#help-33

1 messages · Page 232 of 1

novel juniper
#

So just to be sure. Here I have to verify that if $A,B$ are normal subgroups of $G$ , then $g(A \cap B) = (A \cap B) g \forall g \in G$

elfin berryBOT
novel juniper
#

The intersection of two subgroups is a subgroup..Let $x \in g(A \cap B)$. The $\exists t \in A \cap B: x= gt$. But as $t \in A,B$ which are both normal,\exists t' \in A\cap B : gt=t'g$. So $x \in (A \cap B)g$. So $g(A \cap B) \subseteq (A \cap B)g$. $(A \cap B) g \subseteq g(A \cap B)$ similarly. So $g(A \cap B) = (A \cap B)g$

devout mauve
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A,B being normal does not mean gt=tg

novel juniper
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gt=t'g\

elfin berryBOT
#

wai

The intersection of two subgroups is a subgroup..Let $x \in g(A \cap B)$. The $\exists t \in A \cap B: x= gt$. But as $t \in A,B$ which are both normal,\exists t' \in A\cap B : gt=t'g$. So $x \in (A \cap B)g$. So $g(A \cap B) \subseteq (A \cap B)g$. $(A \cap B) g \subseteq g(A \cap B)$ similarly. So $g(A \cap B) = (A \cap B)g$
```Compilation error:```! Missing $ inserted.
<inserted text> 
                $
l.1422 ...t \in A,B$ which are both normal,\exists
                                                   t' \in A\cap B : gt=t'g$....
I've inserted a begin-math/end-math symbol since I think
you left one out. Proceed, with fingers crossed.

Preview: Tightpage -1310720 -1310720 1310720 1310720
[1{/usr/local/texlive/2023/texmf-var/fonts/map/pdftex/updmap/pdftex.map}]
(./796939110815629322.aux)```
devout mauve
#

thats also not what it means

novel juniper
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it means gA=Ag

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that's what normality means

devout mauve
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yes

novel juniper
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so how is what I'm saying wrong

devout mauve
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there exists t' in A and t'' in B with gt=t'g=t''g

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nothing says t'=t''

novel juniper
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sure

novel juniper
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I;ll work on this

#

.close

marsh citrusBOT
#
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novel juniper
#

.reopen

marsh citrusBOT
novel juniper
elfin berryBOT
novel juniper
#

does this work

devout mauve
#

yes

novel juniper
#

Cool, thanks!

#

.close

marsh citrusBOT
#
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marsh citrusBOT
#
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rustic crypt
#

what is the difference between the two formats

rustic crypt
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i had a different ticket opened before and i thought i was crazy but in that ticket i used 0 as true while looking at the left table

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if i wrote our the table on the right in using both ttff format and 0011 format would they be Logically equivalent

wary lichen
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Nothing really

rustic crypt
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yes

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ok

wary lichen
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You might get the TF

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In formal logic

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And 01 in Boolean Algebra

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But they are essentially the same

rustic crypt
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i got myself mixed between the two and stared interpreting 0011 as ttff

wary lichen
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Yeah, no, 0011 would be fftt

rustic crypt
#

.close

marsh citrusBOT
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marsh citrusBOT
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subtle flare
#

Integration of sin inverse x whole square

marsh citrusBOT
past thicket
#

,rcw

elfin berryBOT
past thicket
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$\int\arcsin^2(x)\di x$

elfin berryBOT
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𝙸𝚗𝚏𝚒𝚗𝚒𝚞𝚖³

torpid tapir
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what kind of typing is this

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even hebrew is more understandable than this

past thicket
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Dude, if you have nothing to contribute to the problem, don’t say it.

torpid tapir
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i dont even understand the problem

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tell me what is it

past thicket
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Exactly, so don’t even talk about the penmanship.

torpid tapir
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i can solve it but i cant read it

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literally

past thicket
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I wrote it in latex above you.

past thicket
torpid tapir
past thicket
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!nosols

marsh citrusBOT
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As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

winged geode
torpid tapir
winged geode
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bro i think its just you

past thicket
winged geode
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it doesn't matter what the argument is because it's still in respect to the argument inside the sine

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and everything else is understandable perfectly

subtle flare
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And my handwriting isn't that bad 😭

subtle flare
past thicket
winged geode
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i think its a combination of IBP and trig sub

subtle flare
winged geode
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try integrating by parts and then using sine substitution

past thicket
winged geode
#

^

past thicket
elfin berryBOT
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𝙸𝚗𝚏𝚒𝚗𝚒𝚞𝚖³

subtle flare
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Uhh acc to the awnser key

past thicket
torpid tapir
winged geode
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no its not

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stop misleading

torpid tapir
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it is

past thicket
winged geode
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sin^(-1)(x) ≠ (sin(x))^(-1)

subtle flare
torpid tapir
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well it is maybe some diff use of it between us

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but gives the same answer

winged geode
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no it doesnt

past thicket
torpid tapir
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am out

subtle flare
winged geode
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sin^(-1)(x) = arcsin(x)
(sin(x))^(-1) = 1/sin(x) = csc(x)

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not the same

winged geode
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Try applying IBP first

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And then you'll probably get some trig substition there

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u = arcsin²(x) and dv = dx

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try from there

subtle flare
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Why can't I let sin inverse x as theta

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Won't that be easy

winged geode
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you can also go from there right away if you want

subtle flare
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Ok just a sec

winged geode
past thicket
oak oxide
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-# the more messages the faster you become green emojigg_Huh

past thicket
subtle flare
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Wait I think I solved it

past thicket
subtle flare
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Few more mins

past thicket
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okie dokie.

subtle flare
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Yeah I solved it

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Assuming it theta made it easier

past thicket
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Show the work.

subtle flare
#

Pardon me for my handwriting

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I was in a hurry

winged geode
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good answer

subtle flare
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👍😃

supple junco
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U actually read the manga

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"We are gonna study ethics" or whatever

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I forgot the name

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It's very underrated

subtle flare
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😀

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Thankyou guys

past thicket
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!done

marsh citrusBOT
#

If you are done with this channel, please mark your problem as solved by typing .close

subtle flare
#

.close

marsh citrusBOT
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marsh citrusBOT
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odd agate
#

do you have a question?

marsh citrusBOT
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odd agate
#

cool

supple junco
#

Oh I'm not supposed to chat here

#

Right

supple junco
supple junco
marsh citrusBOT
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faint pewter
#

I have this question with my math work that I've been struggling with-- I understand how to do part a, I just don't understand how to translate the answers from that into the table in part b

fervent tapir
#

maybe it would help if you can share the answers from part a.

wispy stump
faint pewter
fervent tapir
#

you have three screenshots here for two blanks in part a though.

faint pewter
#

the last 2 screenshots was me calculating the interest the way my professor told me to

wispy stump
fervent tapir
#

so screenshot 1 is the monthly payment and ss2-3 are the total interest

wispy stump
faint pewter
wispy stump
marsh citrusBOT
#

@faint pewter Has your question been resolved?

wispy stump
marsh citrusBOT
#

@faint pewter Has your question been resolved?

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blissful summit
#

can anyone help with me question a) and question b)

blissful summit
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the marking key for question a) says indepdent events

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but if its a bernouli, why are we concerned with independent events

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isnt that concern if we are considering if it can be binomial

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heres the markig key

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its very ambiguous

cunning fiber
blissful summit
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isnt bernouli concerned with only 1 trial

blissful summit
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if it changes, cant we define new bernouli for each for those indiviidual trials

blazing pulsar
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I'm not sure what is confusing you here. A binomial distribution is a sequence of bernoulli trials with the same probability of success

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It sounds like you are overthinking the meaning of part (a)

blissful summit
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and saying that the events are independent sounds like its justifying why it can be considered as binomial instead of bernouli

blissful summit
blazing pulsar
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I don't know where you are reading independence in part (a)

blissful summit
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but i dont understand this marking key because it seems to be justifying why it can be considered as binmial instead

blazing pulsar
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If you have two independent coinflips, you can think of it as two bernoulli trials or one binomial depending on your perspective

blissful summit
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this is the marking key

blissful summit
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but why must it be indepedent events, like non constant probability of success

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cant we define new bernouli parameters for each trial

blazing pulsar
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If you have two dependent coinflips there are 4 outcomes not 2

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the marginal distribution is bernoulli but the joint is not

blissful summit
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how is there 4 outcomes

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isnt there only head or tail outcomes

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but the probaiblity are different

blazing pulsar
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I said for two dependent coinflips. There are HT TH HH TT

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At the end of the day it depends on what your random variable is tracking

blissful summit
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we are no longer tracking 1 trial

blazing pulsar
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You asked why can't they be dependent events

blissful summit
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ye they cant be depedent for binomial distrbutions, but how about bernouli

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bernouli context dont even consider whether there are other trials or not, arent bernouli only focused on 1 trial

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wait its okay i think its the question, how thye phrased it
they said why this can be considered a bernouli trial

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but i still dont understand onn how i should solve question b i)

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and the marking key also dont make sense

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the marking key does this and i dont understand why do they this

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and why do they not include the P(X=0) when considering P(Y=3) and missing P(Y=0) for P(X=3) case

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this is question b i)

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cann anyone help

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@tight lance

torpid tapir
blissful summit
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and a big issue is that i dont truly understand what question b i) is actually asking

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anyone helpers online?

marsh citrusBOT
#

@blissful summit Has your question been resolved?

marsh citrusBOT
#
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marsh citrusBOT
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granite dove
#

Is my proof fine?

marsh citrusBOT
still temple
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"only if" part is fine

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"if" i am not quite sure what you are saying, what do you mean by smallest positive real number?

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also the negation of < is $\geq$, just fyi

elfin berryBOT
granite dove
granite dove
still temple
still temple
granite dove
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So |a-b| > epsilon

still temple
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can you find it?

granite dove
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Epsilon

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Is the smallest number

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Like the definition

proud ice
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Nope

still temple
granite dove
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What

still temple
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epsilon by itself is not defined to be anything it's just a placeholder for a set of values which are defined in the problem

still temple
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i am pretty sure this exercise is in abbott

still temple
proud ice
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For starters, you wrote you very first line incorrectly.

still temple
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you are correct to use contradiction though we just need to clarify some concepts

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if epsilon is the smallest positive number then what is epsilon/2?

granite dove
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We need to find some value

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It make forall wrong

granite dove
proud ice
#

What you wanted to write was
$$\forall (a,b\in\bR)(a=b\Leftrightarrow \forall(\varepsilon\in\bR^+)(\abs{a-b}<\varepsilon))$$

elfin berryBOT
granite dove
#

But why i see in books that epsilon is placeholder for ver small value?

still temple
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in analysis

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but that doesn't mean it's the smallest value

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well, because one doesn't exist

proud ice
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It can be arbitrarily small, but there is no smallest value

still temple
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think of a and b as two points on the real number line and |a - b| as the distance from a to b

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what this definition is saying is that if this distance is arbitrarily small, as SWR said, i.e. for any positive distance you could possibly imagine - think of any insanely small number

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then these two are actually equal

granite dove
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But that mean a-b=0

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If there insanely small number

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Is there a number smallest than it not equal to 0

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Let 0.00000000001

proud ice
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Nope

granite dove
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There 0.000000000000000001 smallest than it

still temple
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it's saying that for any positive distance someone throws at you (which we will define as epsilon), the actual distance is less than that

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and we know that |x| is always 0 or more

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so if it can't be more

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then it must be 0

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but |a - b| is zero IF AND ONLY IF a = b

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which you can and also should prove

proud ice
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Some properties of $\bR$: if $0<x$, then $0<x/2<x$. That is, no matter how small a positive number is, there is always a smaller one

elfin berryBOT
granite dove
still temple
#

yes, that is in the problem statement

granite dove
#

If the statement is
There exist epsilon

proud ice
granite dove
#

Then a=b not necessary

still temple
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a = b is sufficient (but not necessary!) for "there exists eps in R^+ such that |a - b| < eps"

granite dove
still temple
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sure thing

granite dove
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So

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To proof by contradiction

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We need to use some counter example?

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Im wrong?

still temple
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$a = b$ is sufficient (not necessary) for the statement $\exists \epsilon \in \mathbb{R}^+$ and $|a - b| < \epsilon$. For two statements, $A$ is sufficient for $B$ is logically equivalent to $A \implies B$. So $a = b \implies \exists \epsilon \in \mathbb{R}^+$ such that $|a - b| < \epsilon$

elfin berryBOT
still temple
#

your instinct to use contradiction is actually the most elegant approach

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and it is actually the one thing that ties this problem to the "for all" quantifier for positive epsilon

granite dove
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|a-b|=epsilon/2
Is counter example?

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Or wait

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I will re prove it

still temple
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sure

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re formulate it and ping me

granite dove
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What you think? @still temple

proud ice
#

Looks good. Just one question: what is your proof that $x\ne0\to\abs{x}>0$? (That is, is this something you have proven already?)

elfin berryBOT
still temple
#

you can take SWR’s word though if you are in a rush, I am sure he is more qualified than me

still temple
still temple
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Also make sure you understand why you can let eps equal the distance between a and b

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It’s precisely because of what I said before

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This statement holds for all real positive numbers

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So that’s why we can choose epsilon to be |a-b|

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And we don’t even know what it is - just by the virtue of it being non negative and nonzero it is automatically a “candidate” for epsilon

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And if you are done, feel free to type ,close @granite dove

granite dove
granite dove
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And |a-b| > 0 so epsilon can be |a-b|

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For all a,b>0 ,There exist epsilon>0 such that epsilon=|a-b|

granite dove
still temple
granite dove
proud ice
marsh citrusBOT
#

@granite dove Has your question been resolved?

#
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fickle shell
marsh citrusBOT
fickle shell
#

I see what they did but idk why they did it

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How did they decide that r = 3 and the number of elements in X = n

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and the answer was 56

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Normally these questions involve slots and things that go in those slots

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I cant tell what are supposed to be the slots and what are supposed to be the things in the slots

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if that makes sense

elfin cairn
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the number of subsets of size k of a set of size n is (n choose k)

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you choose the elements in the set

gritty vault
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n choose 3 in this case

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$\frac{n!}_{3!(n-3)!}=56$

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$ \frac{n!}_{3!(n-3)!} = 56$

elfin berryBOT
#

Julian
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

fickle shell
#

And the elements are the things that go inside?

gritty vault
#

sure 3 slots

elfin cairn
fickle shell
gritty vault
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if we have n marbles in X

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and 3 slots

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its saying 56 different ways to fill the slots

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but order doesnt matter

fickle shell
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Ok just so that I understand, n choose k, n is always the number of slots and k is always the things i need to pick, right?

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just generally not specifically for this question

gritty vault
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n is the size of X, k is number of slots, and n choose k gives us the amount of unordered ways to fill the slots

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for example if we have the set {1,2,3}

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n=3

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and we want a subset of size 2

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so 2 slots

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we have {1,2}, {2,3}, {1,3} = 3 total subsets or ways to fill the slots

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we dont count {2,1}, {3,2}, {3,1} cuz order doesnt matter

fickle shell
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Ohhh

gritty vault
#

its kinda confusing the first time maybe watch a video with examples

fickle shell
#

Nono I get it now

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Thanks again!

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❤️

#

.close

marsh citrusBOT
#
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mental pike
#

why does this limit equal 1/2?

marsh citrusBOT
mental pike
#

assuming it actually does

elfin cairn
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intuitevly n^2 - n is approximatly n^2 where n is large

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and so your expression is approximately n/(sqrt(n^2) + n) = 1/2

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to do it more formal, divide both numerator and denominator by n

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and then this should simplify nicely to an easy limit

mental pike
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but how do i divide the denominator by n when it has that root

gritty vault
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it goes inside the square root

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cuz

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n = sqrt(n^2)

mental pike
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oh like the root divided by n + n/n?

gritty vault
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so

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sqrt(n^2-n)/n = sqrt(n^2-n)/sqrt(n^2)

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=sqrt((n^2-n)/n^2)=sqrt(1-1/n)

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and 1/n tends to 0

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so its sqrt (1-0)

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=1

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plus the other 1 we have 2 in the denominator

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1 in numerator

mental pike
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oh so you made n sqrt(n^2) to work with the root

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and the division by n is like a standard thing when calculating limits

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i think i understand it now

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thank you

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.close

marsh citrusBOT
#
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mental pike
#

.reopen

marsh citrusBOT
mental pike
#

or uhhh 1-1/n?

earnest belfry
mental pike
earnest belfry
#

Okay so you have an algebraic\manipulative method

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and you have on the other hand L'Hopital's rule

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L'Hopital's rule is applied once you learn derivatives

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But, if that isn't the case for now, we resort to algebraic manipulation

earnest belfry
#

rationalize the denominator

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So, it becomes:
$\frac{n\sqrt{n^{2}-n}}{n^2-n+n}$

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wait . . .

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So, it becomes:
$\frac{n(\sqrt{n^{2}-n}-n)}{n^2-n+n}$

elfin cairn
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still not

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its n^2 - n - n^2

earnest belfry
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oh yes

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So, it becomes:
$\frac{n(\sqrt{n^{2}-n}-n)}{n^2-n+n^2}$

elfin cairn
#

and all of this leaves you with something ugly

earnest belfry
#

My math isn't mathing, nvm

elfin cairn
#

what I suggested at the beginning is good

silk sable
#

Perhaps factor out n^2 from the radicand.

elfin cairn
elfin berryBOT
#

ExpertEsquieESQUIE

elfin cairn
#

is this what you don't understand?

mental pike
#

i think i missed the mention of how 1/n is going to 0

#

so its 1-0 under the root right?

elfin cairn
#

yes

mental pike
#

yeah sorry im scatterbrained

elfin cairn
#

all good

mental pike
#

anyway thanks again

#

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marsh citrusBOT
#
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lyric kelp
#

i did a proof by case here. to show if x is rational, all the following statements are also rational. however when it comes to x being irrational, idk how to prove (ii) and (iii) to be irrational too

wary kite
mellow kraken
#

you'll need to show four things

  1. if (i) is true, then (ii) is true
  2. if (ii) is true, then (i) is true
  3. if (i) is true, then (iii) is true
  4. if (iii) is true, then (i) is true
void elm
#

(technically, you don’t need to show four, only three, but four is probably easier here)

mellow kraken
#

yeah, technically 3

#
  1. if (i) is true, then (ii) is true
  2. if (ii) is true, then (iii) is true
  3. if (iii) is true, then (i) is true
#

basically, you need to set up some chain of implications such that any statemeny implies any other statement.

lyric kelp
#

oh yeah i can just do a contrapositive of a biconditional oh... normally for p <--> q we have to prove p-->q and q-->p, here we just prove neg p-->neg q and reverse?

#

okay yeah i forgot i can just do that ty

#

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mellow kraken
#

¬p -> ¬q is the same statement as q -> p.

marsh citrusBOT
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twilit kindle
marsh citrusBOT
twilit kindle
#

Okay so how he got a-x after observing

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wheat trench
#

Which version do y'all prefer?

marsh citrusBOT
wheat trench
#

The underlined one feels a little redundant, but also kinda sounds better.

night relic
#

"$\in \mathbb{G}$" and "is a member of $\mathbb{G}$" are pretty much the same. both are accurate and widely used \
personally, though, i think you may want to go with "$a,b,c$ be members of $\mathbb{G}$" if you'd like to keep that text

elfin berryBOT
#

ηασιβ ♥

wheat trench
#

To understand what you mean: Are you saying, either keep the text or remove it, but don't have both? like, don't have " in G be members of G" . Or are saying that its fine in any combination?

night relic
#

it is fine in any combination, because it's understood what the elements are, and what the bigger set is. that's really all that matters.
however, "in G be members of G" is technically redundant, so if we're being really specific, i would go for only one of them

#

my personal process is this: the "natural" thing to put inside of a group is an element, so if you say $g \in G,$ that's going to be unequivocally understood as an element of a group. if, however, i thought there might be ambiguity, i might say "let $(gh)^2j^{-1}$ be an element of $G$", so it's clear what $\in$ is doing here

elfin berryBOT
#

ηασιβ ♥

wheat trench
#

I initially had the first one, just "Let 𝔾 be a group and 𝖺, 𝖻, 𝖼 ∈𝔾.", but it almost sounds like the sentence cuts off, when I read it in my mind. But, if it seems ok to have that, then I'm gonna go for this version.

#

I was just concerned that it might have been "wrong" in some type of way.

#

Thanks for the feedback. I appreciate it.

#

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chilly fable
#

i mean seems like you've already done it then?

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#

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hazy fox
marsh citrusBOT
hazy fox
#

This is under chapter differentiability so ig its gonna use that topic

marsh citrusBOT
#

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7. None of the above
cunning fiber
# hazy fox Q3

Let $f(x)=x 2^y + y2^{-x}-x-y$ and note that $f(0)=0$ (which means the two sides are equal when $x=0$)

elfin berryBOT
#

Civil Service Pigeon

cunning fiber
#

you should see from this that ||it suffices to show f is never zero again||

#

Further hint: ||is f decreasing? increasing?||

marsh citrusBOT
#

@hazy fox Has your question been resolved?

hazy fox
sage nova
# hazy fox Yes so how do i show this part

Couldn't you take the derivative to show if it is decreaing or increasing, and then from that show that f will never equal zero again, and hence the two sides will not be equal?

restive coral
#

Hello

sage nova
#

I am taking Differential Equations next semester, but that is just my guess

restive coral
#

Est ce que une application peut etre non injective ni surjective ou bijective

#

?

#

Donner moi un reponse

sage nova
#

!occupied

marsh citrusBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

restive coral
#

@marsh citrus est ce que une application peut etre non injective ni sujective ou bijective

sage nova
#

I thought that works

hazy fox
#

Its not in our syllabus either

sage nova
#

Try that

#

That’s just my guess

hazy fox
#

Oooh is that so

marsh citrusBOT
#

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elfin onyx
#

how to solve (X+3)^3 + 64?

marsh citrusBOT
elfin onyx
#

i mean how to factorize it

weak surge
elfin onyx
#

yea but like

#

what do i do after it

weak surge
elfin onyx
weak surge
elfin onyx
#

(a+b)(a^2-ab+b^2)

weak surge
#

You're done then

#

Can you finish?

elfin onyx
#

i think i can

#

okay thanks

weak surge
#

Good

#

Np

elfin onyx
#

.close

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steel plinth
#

Need help understand the expression I marked up in the red box

steel plinth
#

How does subtracting two points and dividing them by their distance=x²? (Aka 3²)

devout mauve
#

A(3.001) is the area from 0 all the way to the second of those two red lines

#

and A(3) is the area up to the first of them

#

so A(3.001)-A(3) is the small area between them

#

the one in yellow

#

this area is approximately a rectangle

#

with height 3^2 and base 0.001

#

so if you divide its area by 0.001 you get 3^2

steel plinth
#

Ok thank you
Really fast explanation

#

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#
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faint grove
#

The data A has 4 elements and the average is 5,the standard 편차 (표준편차) is 2

And the data B has 6 elements and the average is 5, the standard편차(표준편차) is 3

Then what is the standard편차 of both sets of data A and B?

wispy stump
faint grove
#

What the heck?

desert dirge
#

<@&268886789983436800>

wispy stump
#

Irrelevant bro delete

faint grove
wispy stump
wispy stump
faint grove
#

I have no idea whether the average of combination of both datas will still be 5 or not if it is a variable

wispy stump
#

We compare overall mean no matter what their individual values

faint grove
#

The average of combination of data A and B

wispy stump
smoky parrot
#

average of both datas will be $$\frac{\sum n_i x_i}{\sum n_i}$$ , x_i being the averages and n_i being the number of averages of each dataset

elfin berryBOT
#

RadMeerkat62445
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

smoky parrot
#

so 5

wispy stump
#

It’ll be the same

faint grove
#

There is a chance of either data A or B containing something lower than. 0

wispy stump
#

It’ll be the same mate

#

When it says average is 5, then it is 5 no matter what numbers you use

wispy stump
faint grove
#

I think it was true

wispy stump
#

The thing i said or the thing you said?

faint grove
#

Maybe the thing that you said

wispy stump
#

So now we have combined mean 5 right

#

So use combined variance formula for combined mean

smoky parrot
# faint grove The average of combination of data A and B

Let us say we have a dataset of m elements $(a_1, a_2, .. a_m)$ and of n elements $(b_1, b_2, .., b_n)$.
Then, the average of the dataset of m elements can be denoted A and is given by $\frac{a_1+a_2+...+a_m}{m} $ and that of the dataset with n elements can be denoted B and is given by $\frac{b_1+b_2+...+b_n}{n}$. But now $mA = a_1+a_2+...+a_m$ and $nB = b_1+b_2+...+b_n$.
We want to find the average of the combined dataset $(a_1, b_1, a_2, b_2, ... a_m, ... b_n)$.
We remember that the average is the sum of all observations (i.e., the sum of all elements $(a_1, b_1, a_2, b_2, ... a_m, ... b_n)$ divided by the number of observations. In our case, we have m observations from the first dataset and n observations from the second dataset, so we have m+n observations.
Then, the combined average C is $\frac{a_1+b+1+a_2+b_2+...+a_m+...+b_n}{m+n}$. But from above, $mA = a_1+a_2+...+a_m$ and $nB = b_1+b_2+...+b_n$. Hence C = $\frac{mA+nB}{m+n}$.

elfin berryBOT
#

RadMeerkat62445

marsh citrusBOT
#

@faint grove Has your question been resolved?

wispy stump
#

@faint grove You dont know the formula for combined variance?

faint grove
#

I don't know

wispy stump
wispy stump
#

@faint grove You get it now?

#

Lmk if you want me to explain it with our question

faint grove
#

Yes

wispy stump
#

So n1 = 4

#

With standard deviation 2

#

So square of standard deviation is variance

#

So sigma1^2 =2^2

#

Can you try for n2 and sigma2^2? @faint grove

faint grove
#

( 4 * 2 * 2 + 6 * 3 * 3 ) / 10 then?

wispy stump
#

Then what you’ll get is variance

#

And sqrt of variance is standard deviation

#

Its done

#

@faint grove Got it?

faint grove
#

Yes

wispy stump
#

Lmk your answer so can verify

faint grove
#

7

wispy stump
#

Yeah thats the variance

#

Now find standard deviation

wispy stump
marsh citrusBOT
#

@faint grove Has your question been resolved?

marsh citrusBOT
#
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hazy fox
#

Question 9

marsh citrusBOT
hazy fox
#

My thought process yet
Use rolles theorem so there exists a c for which f'(c) and f''(c)=0 for some c€(a,b)
Trying to define a function on which i can use imvt but i cant put my hands on that part

elfin cairn
#

you are close

#

the two c's that you get from rolle's theorem are not the same necessarily

#

and yes, try to think what can you use IVT on

#

also I think your function needs to be continuously second differentiable

hazy fox
elfin cairn
#

the function in the equation catcothink

hazy fox
#

I dont have any info about f'''

elfin cairn
#

the function in the equation is
f'' - lambda (f')^2

hazy fox
#

Yes but rolles theorem is f'(c)= 0

elfin cairn
#

yes

hazy fox
#

The derivstive of that equation will give me f'''

marsh citrusBOT
#

@hazy fox Has your question been resolved?

neat grove
#

lol

#

hey

#

bro

#

this is NOT highschool math

#

@hazy fox

#

dont we have to use

#

rolles theorem

marsh citrusBOT
#

@hazy fox Has your question been resolved?

hazy fox
#

So technically pre uni :😭

hazy fox
vagrant raft
hazy fox
#

f'(c)= f(b)- f(a)/ b-a

vagrant raft
#

We don't know is f''' even exists

hazy fox
#

/what to do

neat grove
#

@cunning fiber help him out bro😪

vagrant raft
hazy fox
vagrant raft
#

so you need to find a point where f''+ alpha f'^2 >=0 and another where it is <= 0

#

for that you can look at points where f' = 0

marsh citrusBOT
#

@hazy fox Has your question been resolved?

marsh citrusBOT
#
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foggy sphinx
#

Need help with quadratic equations

marsh citrusBOT
stoic saddle
#

send your question(s) here

foggy sphinx
#

K

#

It’s multiple questions btw

#

I just don’t understand how this works

stoic saddle
#

looking at this graph can you scribble over it to pinpoint where the vertex is

#

(or if you feel up for it, name the coords right away -- but a visual will do fine)

foggy sphinx
umbral oasis
#

What are its coordinates?

foggy sphinx
#

I honestly do not know I don’t know what I’m supposed to be looking at

stoic saddle
#

right, would've liked a more precise reading

#

tho you are in the right ish place

#

gimme a sec

umbral oasis
#

You see it's derivative there is 0

stoic saddle
fervent tapir
#

OP, maybe it helps to think of the vertex of a parabola as the "tip" of the parabola.

stoic saddle
foggy sphinx
#

I see that’s 8 right

umbral oasis
#

That's not the point of what I'm talking about

umbral oasis
stoic saddle
#

8 is its y-coordinate

umbral oasis
#

So what is the tuple

stoic saddle
#

given he is just studying quadratics atp

fervent tapir
#

not sure if we should also use the word "tuple" here too, given the same thing.

foggy sphinx
#

Wouldn’t X be -3

stoic saddle
#

also yes i would ask for coords

stoic saddle
#

what should its x coord be

#

(also dont confuse this point with other pts of interest on the parabola)

foggy sphinx
#

So what should I be looking at for the X cord

stoic saddle
#

@umbral oasis i think my point is quite clear, your explanation is overengineered to the point of not connecting with op's knowledge. simple as that.

stoic saddle
#

this doesnt require you to know anything about parabolas specifically

#

just reading coordinates from an xy grid

umbral oasis
#

It's not overengineered. I literally used the word derivative once. If he doesn't understand it he can choose to completely ignore that part of my "explanation"

#

Or ignore my explanation entirely

foggy sphinx
#

10?

stoic saddle
foggy sphinx
#

Idk what I’m supposed to be looking at to find the x cord

stoic saddle
#

you're not supposed to be like, "finding" the x-coord by means of a formula

#

are you OK with us going over some basics of coordinates real quick

foggy sphinx
#

Yes

stoic saddle
#

ok right

sacred idol
#

can you see the y-coord of the vertex now

stoic saddle
sacred idol
#

oh okk

stoic saddle
#

op already said the y coord is 8./

#

anyway

foggy sphinx
stoic saddle
#

you know the point where the x and y axes meet?

#

this point has a special name

#

do you knwow this na-

#

augh.

#

well, i can't really continue my explanation if other people are going to talk over me, i think.

#

@foggy sphinx the point where the x and y axes cross each other is special enough to have its own name. do you know what it is called?

stoic saddle
#

it is called the origin.

#

does that ring a bell?

foggy sphinx
#

A lil

stoic saddle
#

does it ring enough of a bell that you can tell me what the coordinates of the origin are?

#

(again, forget about parabolas, we're just going over coordinate grid basics)

foggy sphinx
#

I feel like it’s zero

stoic saddle
#

a point on the plane has two coordinates, written in brackets (obligatory, you can't drop them, ever) and with a comma in between.

foggy sphinx
#

Huh?

stoic saddle
#

it takes two numbers to tell where a point is

#

an x and a y

#

they are written as follows: (x,y)
i was also emphasizing that dropping the brackets and writing x,y is wrong.

#

go give this a watch tbh

foggy sphinx
#

K

marsh citrusBOT
#

@foggy sphinx Has your question been resolved?

marsh citrusBOT
#

@foggy sphinx Has your question been resolved?

#
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fervent rampart
#

looks like a calligraphic C, $\mathcal{C}$

elfin berryBOT
#

κλαουντ ☁ (cloud)

fervent rampart
#

they don't look exactly the same because they are in different fonts (the C in that message appears to be from the ams euler calligraphic font)

marsh citrusBOT
#

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upper star
#

please help me solve. i don't even know how to start solving this

stoic saddle
#

do you know how to find intersections of straight lines on a coordinate plane?

upper star
#

no.

stoic saddle
#

mmm

#

aight gonna be tricky then

upper star
#

🙁

restive sparrow
#

What topic are you doing right now?

upper star
#

this is the bonus problem of my alg homework

stoic saddle
#

actually wait let's go further back

#

if they asked for the length of AB, would you know how to find that

upper star
#

yes

#

pythag. thoerem

stoic saddle
#

ok

upper star
#

sqrt(58)

#

is the length of ab

#

i think.

stoic saddle
#

58?

restive sparrow
stoic saddle
#

that doesn't sound right

#

anyway

#

triangles CEF and DEB are similar

upper star
#

ohhh

#

ok.

wise lance
stoic saddle
#
  • i am tracing a horizontal thru C
upper star
knotty trellis
#

<@&268886789983436800>

upper star
#

WHAT

inland frigate
#

<@&268886789983436800> SPAMMER

charred silo
#

Yikes. Has been muted and presumably banned

stoic saddle
#

yuck

lean cedar
#

did someone @ me?

upper star
#

jeez.

#

what even...

stoic saddle
lean cedar
#

lol

stoic saddle
#

might wanna change your nick

inland frigate
#

i MENT MODERATORS

#

BUT I ACCIDENTALY PINGED YOU

upper star
#

i'm very afraid rn

stoic saddle
upper star
#

i was looking for help with math...

stoic saddle
#

you're fine

upper star
#

ok

sleek nimbus
#

I was thinking about setting axis and finding the equation of the lines ab and dc and then find the point e as their intersection

stoic saddle
#

but op said he doesn't know how to proceed from that

upper star
#

i just started alg

#

barely passed pre alg...

#

so

knotty trellis
#

this could also work if u know what i mean by that

upper star
#

i can do that

knotty trellis
sleek nimbus
#

if you know how to find line equations then finding the intersection is a very simple idea

knotty trellis
#

can u notice sth with this pic

upper star
#

the distances between the blue lines is

#

1

knotty trellis
upper star
#

also they are all parallel

knotty trellis
#

what's the proportion of (red+orange) : yellow

upper star
#

1:1

knotty trellis
#

sorry, (red+orange) : yellow

upper star
#

2:1

knotty trellis
#

yeah, and can you find the total length of the colored segment?

#

i.e. red+orange+yellow?

upper star
#

1+sqrt(2)

knotty trellis
#

hmm not really

#

how did u get that?

#

notice that the endpoints lie on the grid

#

so u can just pythagoras it

upper star
#

yes

knotty trellis
#

i think u did ur pythagoras wrongly then

upper star
#

oh

#

lemme try again lol

#

sqrt(5)

#

ok.

knotty trellis
#

can u now find the distance from the left endpoint of red to E?

upper star
#

yes!

#

tysm

#

😄

knotty trellis
#

np

upper star
#

.close

marsh citrusBOT
#
Channel closed

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marsh citrusBOT
#
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slim ginkgo
#

Linear transforms

marsh citrusBOT
jagged relic
#

What's your question / what have you tried?

sleek nimbus
#

!status

marsh citrusBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
slim ginkgo
#

.close

marsh citrusBOT
#
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marsh citrusBOT
#
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safe cloud
#

Sorry for the amount of questions I’m asking but I’m trying to solve for #17 b.

safe cloud
#

and im at the point where im finding the limits

#

based on what ive done for the cusp im tryna do the same to see if theres a vertical tan line but

#

would that mean i would have to find the limits for all 3 critical points

#

or is there some shortcut i can take/ are there steps that im doing wrong

faint creek
#

Is 6 a critical point? Is it not just 0 and 12?

safe cloud
#

3(2x - 12) = 0

#

would be x = 6

faint creek
#

Yes but that's a 0 in the numerator

#

Ah nvm I had my definition wrong

safe cloud
#

i think it would still be able to be factored out though

#

ah alr

faint creek
#

But anyway, since f'(6) = 0, we can tell that it's going to be flat rather than a cusp or vertical tan

safe cloud
#

i see

#

cant the same be said for the other 2?

faint creek
#

Well the other two have f'(c) approaching +- infinity, which implies a cusp or vertical tan

safe cloud
#

OH

#

okay yes im following

faint creek
#

A cusp is what you have in (a) right? Where the function makes a sort of spike shape?

safe cloud
#

yeah i didnt solve it on the paper but its a cusp on a

#

i was doing it in my notebook, im still a little iffy on it but i do get it

faint creek
#

Yeah, so if you remember how the way a curve tilts up/down relates to the positiveness/negativeness of the derivative

#

You can see how the critical point in (a) is a cusp because f' goes to negative infinity from the left (So it's going down), while it goes to positive infinity from the right (so it's going up)

#

While if you had a vertical tan, it would have to be approaching either negative or positive infinity from both sides

#

So once you've found either a cusp or vertical tan, you can tell the difference by analyzing the sign of the derivative

#

Does that make sense at all?

safe cloud
faint creek
#

Sure thing

#

How about looking at this graph of your work from (a)

#

The blue line is your original function, while the green one is the derivative

#

You can see that the derivative is going to -infinity from the left, so the curve is going down really fast

safe cloud
#

oh my god this visualization actually just simplified it so much

#

😭 thank you anyways yes continue

faint creek
#

While it's going to +infinity from the right, so it's going up really fast!

#

Lmao no problem, graphing a problem is often a great idea if you're having trouble understanding it :)

#

So a cusp is when the derivative is going to +infinity from one side and -infinity from the other, causing that sort of spike shape

#

While with a tangent line the derivative will go to one of -infinity or +infinity from both sides, since the curve won't be changing direction as it goes through the critical point

#

Remember, positive derivative means it's going up, negative derivative means it's going down

safe cloud
#

alright i see it now

#

thank you so much this helped alot

#

truly i appreciate it 🙏

faint creek
#

Glad I could help!

#

Do you have more questions or are you done?

safe cloud
#

that'll be it thank you

faint creek
#

Cool, can you use .close to free the channel then?

safe cloud
#

.close

marsh citrusBOT
#
Channel closed

Closed by @safe cloud

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marsh citrusBOT
#
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dusty bone
#

How do I solve question (ii)

marsh citrusBOT
late geode
#

use the slope and y-intercept in the y-intercept form and you'll have your equation

dusty bone
#

Is the equation y=1/2x

#

I found that c=0

late geode
#

yes

dusty bone
#

Thanks

#

.close

marsh citrusBOT
#
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marsh citrusBOT
#
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chilly fable
#

😋

marsh citrusBOT
calm harbor
#

How are you today? Anything we can help?

indigo nest
#

Given that they just joined and that username, I feel confident saying they're a bot

ruby mulch
#

.close I don't think there is any real question here.

marsh citrusBOT
#
Channel closed

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Use .reopen if this was a mistake.

#
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
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hard laurel
#

an is absolutely convergent and bn is convergent series then their multiplication anbn will be convergent?

hard laurel
#

I am looking for examples so that i can be sure

sick charm
#

What kind of examples are you looking for? Do you have examples for absolutely convergent series?

stoic saddle
#

i can give a deliberately un-enlightening example

#

$b_n=\frac{1}{2^n}, a_n=0$

elfin berryBOT
hard laurel
#

So it will be convergent??

#

anbn=0+0+0..

stoic saddle
#

the zero series is in fact convergent, yes

hard laurel
#

I was looking for such examples where it fails if does

static quarry
#

you do some manipulations and at some point you say, "it would be nice if b_n were a ____ sequence"

sick charm
#

at some point, |anbn| would be smaller than |an|.

hard laurel
#

we have |an|,bn

#

And looking for |an|bn

#

.closd

#

.close

marsh citrusBOT
#
Channel closed

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calm harbor
hard laurel
#

Hey?

calm harbor
#

hello

marsh citrusBOT
#
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Show your work, and if possible, explain where you are stuck.
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sacred idol
#

Let ${\delta_1, \delta_2, ..., \delta_k}$ be the set of determinants formed by the set of 9 real and non-zero numbers ${a_1, a_2, a_3, ..., a_9}$.\\
what is the value of k?

elfin berryBOT
sacred idol
#

it is definitely not 9!

#

as a website i saw online says

sick charm
#

What is a determinate for a set of numbers?

sacred idol
#

nah its okay

#

just consider if 9!/18 would be correct

#

im not sure what the answer is

indigo nest
#

We can't help you with the question if you don't clarify what the question says

stoic saddle
sacred idol
#

mb

#

determinant with the you know

lavish pelican
#

so can the question be rephrased like
How many determinants can be formed by the set of 9 real non zero numbers

sacred idol
#

matrices

#

that one

sacred idol
#

uhh wait nvm distinct is not given

#

but how would you do it if it was distinct

lavish pelican
#

if its distinct it should be 9! right

sacred idol
#

if its not distinct

lavish pelican
#

that makes it a little tougher

#

i dont know

#

cause there are too many combinations

indigo nest
marsh citrusBOT
#

@sacred idol Has your question been resolved?

marsh citrusBOT
#

@sacred idol Has your question been resolved?

faint creek
#

Hmm... what if we look at 2x2 matrices first? So just {a1,a2,a3,a4} ?

#

Or rather {a,b,c,d}

#

I think the maximum number of determinants made from 4 values would be 6, from

ab-cd
ab-dc
ac-bd
ac-db
ad-bc
ad-cb
#

Or... actually 12 because we would need the negatives of all of those

vagrant raft
#

Do negatives count though

sacred idol
#

duh??

faint creek
#

Well 1 =/= -1 so I assume so

vagrant raft
#

Since we chose a1... a9 and not -a1... -a9
Actually it doesn't matter since we can get the opposite determinant by swapping columns

faint creek
#

"... by swapping columns" that's what I meant by the negatives

vagrant raft
faint creek
#

No! This has all the duplicates taken out

#

I just also took out the negatives by accident

#

Or....... No wait I'm dumb????

#

Too much screwy algebra, I forgot cd=dc lol

vagrant raft
#

Why isn't ad-cd equal to ad-dc

faint creek
#

Yeah I know

#

lol

sacred idol
#

i would say

faint creek
#

Anyway, so take out my doubled half and add in the negatives and we get back to 6

sacred idol
#

for a given matrix

#

either a transpose is performed

#

or/and one of these two choices

  • swap rows AND columns
  • do nothing
#

which gives 2 x 2 = 4 matrices in a group with same det

#

so 24/4 = 6

faint creek
#

Well there's only 1 way to do a row + column swap isn't there?

#

I think these 4 matrices should have the same det

[a b]
[c d]

[d c]
[b a]

[a c]
[b d]

[d b]
[c a]
sacred idol
#

and the other one is to do nothing

faint creek
#

Those last 2 matrices can't be gotten from the first 2 by row/column operations

sacred idol
#

two exclusive choices

#

hmm

vagrant raft
faint creek
#

Ah true!

#

Then are those all of them?

vagrant raft
#

So for the 3x3 case we would have at most 9! possible configuration divided by 433 : even number of row operation and column operation, odd number of row and column operations, and twice that number for transpose?

faint creek
#

So if it's transpose and double operations... we have 2 * |S_3|^2/2 = 36 redundant permutations?

vagrant raft
#

I got the same

faint creek
#

Hell yeah

faint creek
#

But that's assuming we've got them all

sacred idol
#

ill try with an example

faint creek
#

All the ways of making a redundant permutation I mean

sacred idol
#

we should get 10080

faint creek
#

That's a lot of cases to check

vagrant raft
#

I think we can choose 9 transcendent numbers and that will make sure that we can't get the same det with different formulas

#

Actually square roots of prime numbers should work

faint creek
#

Just use numbers of sufficiently different size?

#

1, 100, 10000, 100000, ...

sacred idol
#

its not going smoothly

#

im either getting too many or too less cases

marsh citrusBOT
#

@sacred idol Has your question been resolved?

marsh citrusBOT
#

@sacred idol Has your question been resolved?

vagrant raft
#

Wdym

marsh citrusBOT
#

@sacred idol Has your question been resolved?

sacred idol
#

uhh nvm