#help-33

1 messages Β· Page 219 of 1

cunning fiber
#

,w second derivative ln(2t) - sqrt(6t) with respect to t

elfin berryBOT
cunning fiber
#

@drifting goblet this is just straight up wrong

drifting goblet
cunning fiber
#

yes

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see above

drifting goblet
drifting goblet
cunning fiber
#

algebra lol

marsh citrusBOT
#
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haughty zinc
#

Never seen a problem like this sos CastoSob ( can anyone please help?

haughty zinc
void elm
haughty zinc
#

πŸ™‚β€β†”οΈ CastoSob

#

Sadly I do not

void elm
#

so you know how the 1s digit in base 10 corresponds to, well, ones?

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and the tens digit corresponds to tens, the hundreds corresponds to hundreds, etc?

haughty zinc
#

Kinda CastoSob

void elm
#

it turns out that you can write this as a sum

#

for example, the number 123 in base 10 is really $1 \times 100 + 2 \times 10 + 3 \times 1$

elfin berryBOT
#

higher!

void elm
#

you can also write that as $123 = 1 \times 10^2 + 2 \times 10^1 + 3 \times 10^0$

elfin berryBOT
#

higher!

void elm
#

does this make sense so far? pikathink

#

all we're doing is writing 123 as a sum of powers of 10 instead of in its usual way

haughty zinc
#

uhh

void elm
stoic saddle
#

the plan btw is to simply convert these numbers from quaternary and quinary into decimal and then add "as normal"

void elm
#

mhm

haughty zinc
#

lem see rw

void elm
#

but instead of using powers of 10, we're gonna use powers of the base instead

#

for example, the number $101_{\text{two}}$ is the sum [101_{\text{two}} = 1 \times 2^2 + 0 \times 2^1 + 1 \times 2^0 = 4 + 0 + 1 = 5]

elfin berryBOT
#

higher!

void elm
#

as Ann said, we can just turn all our numbers into decimal form via this process and add normally holothink

haughty zinc
#

so like if its 5 like 4,3,2,1,0 as ^4,3,2,1,0

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I think Im kinda stupid at this point

stoic saddle
#

ok here maybe this will jog your memory

#

do the words place value ring a bell

haughty zinc
#

yea

stoic saddle
#

right

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so you know that when writing a number in the ordinary way, going right to left you have a ones place, a tens place, a hundreds place and so on, yeah?

haughty zinc
#

yea

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from 1.

stoic saddle
#

the value of each place is ten times the one before it. that is what makes our number system "base ten".

haughty zinc
#

oh yea

stoic saddle
#

but the fun thing is that you could conceive of numeration systems with another number as the base.

haughty zinc
#

but then if i do that the answer will be over 1000 right?

stoic saddle
#

for example, in base six, you would have a ones place followed by a sixes place, then a thirty-sixes place, and then a two-hundred-sixteens place, and so on. (i am stating these in familiar/decimal terms so it is a bit clunky)

stoic saddle
haughty zinc
#

Alright

stoic saddle
#

for now i want to go over in a bit more detail about how alternative bases work

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so just to show you how the same number looks in two different bases

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the number 176 (decimal)
its decimal representation can be read as:

  • 1 hundred
  • 7 tens
  • 6 ones
    (and in fact this structure is reflected in English number words. "seventy" instead of "seven tens", but still)
haughty zinc
stoic saddle
#

the same number written in base six, however, would look like 452, to be read as:

  • 4 "thirty-sixes"
  • 5 sixes
  • 2 ones
haughty zinc
#

how would it be six?

stoic saddle
#

wdym

haughty zinc
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like why 4" thirty-sixes"

stoic saddle
#

are you asking why we're counting thirtysixes, or are you asking why we got 4 of them

haughty zinc
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why counting thirtysixes

stoic saddle
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it's six times six

haughty zinc
#

oh

stoic saddle
#

a thirty-six is six sixes in the same way as a hundred is ten tens

haughty zinc
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36x36x36= 46656x4?

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oh

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wait

stoic saddle
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omg why are you multiplying these

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no

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(decimal) 4Γ—36 = 144, but 5Γ—36 = 180, which is too much.

haughty zinc
#

oh

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i thought you meant 6^4

stoic saddle
stoic saddle
haughty zinc
#

oh

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hm

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I kinda get it

#

like

#

since its power of 6

stoic saddle
haughty zinc
#

to the 100

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so like 10^2= 100 so 6x6=36 x 4

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and 6^1x5

stoic saddle
#

6**^2** = 36

haughty zinc
#

oop

stoic saddle
#

the "4" in "452_six" means 4Γ—6^2

haughty zinc
#

ye

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cuz of the 100 thingy r so 6^2 x 4

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like 10^2x4 if base was 10?

stoic saddle
#

yes

haughty zinc
#

oki oki

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so the base

#

ohh

#

but then

#

(1x5^3)+ (2x5^2)+(3x5^1) + (4x5^0)

stoic saddle
#

that's 1234(quinary) spelled out, yeah

haughty zinc
#

yea

#

and

#

(1x4^2) +(2x4^1)+ (3x4^0) will be

stoic saddle
#

yeah that's 123(quaternary)

haughty zinc
#

221

#

?

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the answer of problem

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think i get it

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kinda

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using 10^1 as digts etc

stoic saddle
#

yeah it works out to 221

haughty zinc
#

Thank youu

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I think i js didn't know that kinda problem <3

#

thank you for helping <3

marsh citrusBOT
#

@haughty zinc Has your question been resolved?

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humble lichen
#

Can someone help me to understand the conclusion of this proof? I understand the intention is to show that we have a homeomorphism from the restriction of p to U, but I don't undestand how Munkres actually... gets to the conclusion

humble lichen
#

I see that he proved surjectivity and I understand that, but he only proved injectivity for the closure so saying the closure is a homeomorphism makes sense to me, but then he just says that the open sets are also fine but how?

indigo nest
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Restriction of a homeomorphism is a homeomorphism still

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So since he's proven it for the closure, he can restrict to the interior

humble lichen
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Okay, that makes sense... I guess I wasn't really thinking about the fact that the closure is bigger

indigo nest
#

Understandable

humble lichen
#

Thanks a bunch

#

.close

marsh citrusBOT
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rugged falcon
#

Can u solve number 35 I got 25 as answer

marsh citrusBOT
wary lichen
#

,rccw

elfin berryBOT
wary lichen
#

show your work prob

rugged falcon
#

I did my work In exam this morning

wary lichen
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Have you at least noted something or somewhat remember your procedure?

rugged falcon
#

Ye

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Lemme type it

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Nvm I will write and send 1 min

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Oh gosh I screwed up so bad

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I did it wrong

wary lichen
#

In fact, well, ill suppose ill guide you back through it
Ill take it as you know your trig basics

rugged falcon
#

K

wary lichen
#

First of all, you know that PQO is an isosceles with two sides = 5, other = 8

rugged falcon
#

K

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Ye

wary lichen
#

For ease of use, we will discard half the diagram and end up with something like this

rugged falcon
#

Kk

wary lichen
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Our isosceles became a rectangular

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with sides 4 and 5 and an unknown height

tiny burrow
#

height is known but not base

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PR ie height is 4

wary lichen
tiny burrow
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base is 3

wary lichen
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Given the nature of the problem, where we asked by the tangent of the circle, we dont really care for the other "side" anyways

Do you know how to find that angle?

rugged falcon
#

How base is 3 guys? My friends told the same

tiny burrow
wary lichen
rugged falcon
#

Wait how u find 5?!

tiny burrow
wary lichen
#

is the radius of the circle, its just info they gave you

tiny burrow
#

i think knowing TR is more important

rugged falcon
#

OHHH

tiny burrow
#

since law of cosines could really help here

wary lichen
rugged falcon
#

So what is TO?

wary lichen
tiny burrow
wary lichen
rugged falcon
#

What's a cosine law πŸ’€ 😭

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I'm 10th grade bro

wary lichen
#

okay you dont know your trig basics then πŸ₯€

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does SOHCAHTOA ring a bell?

silk sable
#

Might be easier to just show they are similar triangles.

rugged falcon
#

DUDE THEY DIDNT TEACH THAT LAW IN SCHOOL

#

Proportionality and similarity that's all lol

wary lichen
#

well, time to show they are similar then

tiny burrow
rugged falcon
#

It's not in my syllabus...

tiny burrow
rugged falcon
calm harbor
wary lichen
rugged falcon
#

Oh yeah

wary lichen
#

Yeah, i was thinking you knew a few more laws about trig, np anyways, it can be solved like this too

rugged falcon
#

Oh okey

wary lichen
#

If you look at it carefully, you can see that you have two right triangles sharing a side, and they have a right angle in common.

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You could take the smaller (the one in the right), rotate it, and find they are similar.

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Still, you will have to find a factor of proportion. Can you see what you need to match?

silk sable
#

AAA proves similarity.

rugged falcon
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So uh

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Can u just tell me the full step

wary lichen
#

You know the bottom side from the small one is 3.
You know the right side of the bigger one is 4, and since those are the sides that are similar, you need to find a number that makes it so:

3 * a = 4

#

Once you find it, you can multiply 5 by it, and youll get the answer

silk sable
#

Similar triangles have corresponding sides. Determine which sides correspond to each other.

rugged falcon
#

So what answer did u get?

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I got 20/3

wary lichen
#

Yeah, thats correct.

rugged falcon
#

O

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Hey can u gimme a piece of advice to get better on math

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I'm only getting 57/80 in this test

silk sable
rugged falcon
#

To get better marks

silk sable
#

Let me ask you this question. What do you think is the purpose of school?

rugged falcon
#

To study

silk sable
#

That's it?

rugged falcon
#

Uh yeah sully

silk sable
#

Public school serves several purposes. One of those purposes is to introduce you to areas of study that you not otherwise have had access to. It's not uncommon for children to go into the same field of work as their parents. This is because parents pass on the knowledge of what they know to their children. Children grow up and go into the same field of work because it is what they are mostly knowledgable about.

rugged falcon
#

Well yeah

silk sable
#

Another purpose is to teach you the skills that you will need to learn on your own. This is an aspect which causes rural students to fail in college. High schools which do not challenge a student enough to force them to develop good studying habits hinder students in college.

rugged falcon
#

O

indigo nest
silk sable
#

You should be learning how to study. Taking notes is a skill that needs to be developed.

rugged falcon
#

So uh what's ur conclusion?

silk sable
#

That's it. Develop your studying skills.

rugged falcon
#

Oh okey

silk sable
#

Everybody has different studying techniques that work for them. I have my own.

rugged falcon
#

Btw can I ask smth?

silk sable
#

Yes.

rugged falcon
#

What do you do? Or what's ur ambition

#

I mean u sound rlly smart

silk sable
#

I was a web developer. In college, I had my own difficultiies related to my previous comment about rural schools. It took quite some time for me to understand why I was failing. At some point, I took a philosophy class that taught me how to ask questions. A well-thought out question gives you well-thought out answers.

rugged falcon
#

Oh that's rlly cool

#

I wanna study law in canada in fact my dad knows a person who can arrange me for it and my seat git confirmed

#

My dad studied law too so I'm doing it too

silk sable
#

My one tip for learning math well. As you are solving a math problem, write out your thought process as you are solving the problem. Those notes to yourself are useful when it comes to studying. If the notes don't make sense when you re-read them, redo the notes so they do make sense.

#

If you need to use a formula, write out the formula. Repetition makes things easier to remember.

rugged falcon
#

Oh okey but I need to tell u some harsh truths abt me

silk sable
#

Ok.

rugged falcon
#

I'm so lethargic and I don't write and study

#

Only in maths

tropic minnow
silk sable
#

That's something you will have to correct. If concentrating is problematic for you, eliminate distractions. If you have a study area, get a big cardboard box and make a wall in front of you.

tropic minnow
#

no one really cares unless it makes them feel good

rugged falcon
tropic minnow
rugged falcon
rugged falcon
#

U sound u unalive every distractions in ur life jeez lol

#

But I will try

tiny burrow
tropic minnow
# rugged falcon Idk

suffer because you tried
or suffer because you didn't try
the second option mostly leads to a net positive happiness

tiny burrow
#

anyways i think this is drifting off topic

rugged falcon
#

I don't get the mood to study in my home lol but in tution I have big fire in me lol

tiny burrow
#

it doesn't matter if you like it or not you absolutely have to

#

delete every single game that you might be using too much

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or app

rugged falcon
#

Ye your right

tiny burrow
#

i did that

rugged falcon
#

Oh

tiny burrow
#

lets close this help sections and head to discussion

#

since its no longer on topic

rugged falcon
#

Okey

#

Yeah

tiny burrow
#

use .close

rugged falcon
#

Anyways thx I guess

#

.close

marsh citrusBOT
#
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Remember:
β€’ Ask your math question in a clear, concise manner.
β€’ Show your work, and if possible, explain where you are stuck.
β€’ After 15 minutes, feel free to ping <@&286206848099549185>.
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β€’ Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

ornate leaf
#

hello there a reason general form isnt used ?

ornate leaf
#

is it not true for y' = f(at,by)

stoic saddle
#

wdym general form

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what's the point of writing f(at, by)?

ornate leaf
stoic saddle
#

i think you misunderstand

ornate leaf
#

on the previous page it covered this form

stoic saddle
#

f(t,y) already just means any function of t and y

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of two variables mind you!

ornate leaf
#

what

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oh wait nvm

stoic saddle
#

adding those extra a and b simply introduces more moving parts that are completely unnecessary

ornate leaf
#

so couldnt be f(at,y)

fervent rampart
#

y ' = G(ax + by) is a very specific form of ode which is not "the most general form an ode can take"

ornate leaf
#

t isnt a function is it ?

fervent rampart
#

y' = f(t,y) is just the most generic form you can write a first order ode in, where t is understood to be the independent variable and y is the dependent variable

ornate leaf
fervent rampart
#

yes, because the theorem is intended to apply to all first order odes

ornate leaf
#

in other words is there a unique solution to a first order ode if and only if those conditions are met

fervent rampart
#

no

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the partial derivative being continuous is actually a stronger condition than strictly necessary

ornate leaf
#

ok so

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wait no so yea what i said is correct

fervent rampart
#

the less strong condition than f_y being continuous is lipschitz continuity in y. but you aren't expected to know what that means yet so they chose a condition which implies that instead

ornate leaf
#

ok so if df/dy isnt continious

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there can still be a unique solution

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nvm read that wrong

ornate leaf
fervent rampart
#

yes. it's likely that it will fail to exist or be unique but not necessarily guaranteed

marsh citrusBOT
#
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Available help channel!

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Remember:
β€’ Ask your math question in a clear, concise manner.
β€’ Show your work, and if possible, explain where you are stuck.
β€’ After 15 minutes, feel free to ping <@&286206848099549185>.
β€’ Type the command .close to free the channel when you're done.
β€’ Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

midnight flower
#

hhi

marsh citrusBOT
past thicket
#

Hi!

midnight flower
#

i need help

past thicket
#

you can post your question

midnight flower
#

ill send

hard lantern
#

Post question first so bot can pin it.

midnight flower
#

q19

calm harbor
#

,rccw

hard lantern
#

,rccw

elfin berryBOT
calm harbor
midnight flower
#

q19

#

in diagram only 110 is there

#

rest is pencil markings i did

calm harbor
midnight flower
#

anyone here

#

?

elfin stone
#

or both

#

lemme rephrase my problem: What's your current progress?

#

Please ping me when you're back.

midnight flower
#

😭

#

its pinned

elfin stone
midnight flower
#

q19

midnight flower
#

it came in exam

#

today

elfin stone
midnight flower
#

i did

#

ik its wrong

#

so im here

#

i wrote 70 and 70 (i was in time hurry)

elfin stone
midnight flower
#

only 110 is there

elfin stone
#

Your x is correct

midnight flower
#

and bcd is 80 in question

midnight flower
#

half of the total

elfin stone
midnight flower
#

hmm

elfin stone
#

yeah, your y is incorrect

midnight flower
#

whats the ans

elfin stone
#

y is apparently half of ADC

midnight flower
#

?

#

yes

#

then?

#

value?

elfin stone
#

You can figure it out, right??
You already got DCB = 80

midnight flower
#

topper of class said x is 30

midnight flower
elfin stone
midnight flower
#

and i thought "wtf?"

elfin stone
#

πŸ₯²

midnight flower
#

πŸ’”

elfin stone
midnight flower
#

they were discussing

#

i was eavesdropping

elfin stone
#

nah, you'll get half of the marks for this question

hard lantern
#

,rccw

elfin berryBOT
midnight flower
#

first sub q

#

i think i did it wrong

hard lantern
#

What did you even try

elfin stone
# elfin stone

y is simply 50, because DCB is 80 so the other angle must be 100, divde by 2 = 50

midnight flower
elfin stone
#

If you're curious

calm harbor
midnight flower
#

bro

#

anyone solved?

elfin stone
#

No, you're supposed to share your work in the first place

#

That's not how things work in this server

midnight flower
#

can i whiteboard

elfin stone
#

you mean activity? No, it's been disabled

midnight flower
#

hmm

#

i added triangle pmx such that sp=px and pm bisects angle m

#

then sas

#

thats all

marsh citrusBOT
#

@midnight flower Has your question been resolved?

fathom cypress
# elfin berry

have you solved this? (you can ping me if you still need help. if you have done, pls close ts channel)

midnight flower
#

@fathom cypress i need help

#

i dont know what to do

fathom cypress
#

what is the question again

midnight flower
#

23a

fathom cypress
#

alright

#

what can you inferred if sr is parallel to pq (im referring to angles)

midnight flower
#

wdym

fathom cypress
#

so we have sr parallel to pq right?

#

what do we know abt the angles if sr is parallel to pq?

midnight flower
#

that makes no sense

midnight flower
midnight flower
fathom cypress
#

no:’)

midnight flower
#

πŸ’”

fathom cypress
#

since i cant actually get a question for u right, ima say it

#

we have srm congruent to rmq by alternate interior angles

#

and bc MR bisects QRS, we have SRM congruent to MRQ

#

since SRM= RMQ, and QR= SRM,
we have RMQ =QRM

midnight flower
#

we have to prove pm = sp

fathom cypress
#

i understand that

midnight flower
#

and?

fathom cypress
#

then we have isoceles triangle qrm

fathom cypress
#

u have to be patient tho

#

we are almost there

midnight flower
#

ok?

fathom cypress
midnight flower
#

nop

#

e

fathom cypress
#

where?

midnight flower
#

how is it isoceles

fathom cypress
midnight flower
#

oh

#

mb

#

i didt see that

fathom cypress
#

then qrm isoceles by property

midnight flower
#

continue

fathom cypress
#

ok

#

we have mq=mp bc m is midpoint of pq and ps=qr right

#

and qrm isoceles, so mq=qr

#

then we have mp=mq=qr=ps

#

does ts make sense to u, if not, why?

marsh citrusBOT
#

@midnight flower Has your question been resolved?

marsh citrusBOT
#
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Available help channel!

Send your question here to claim the channel.

Remember:
β€’ Ask your math question in a clear, concise manner.
β€’ Show your work, and if possible, explain where you are stuck.
β€’ After 15 minutes, feel free to ping <@&286206848099549185>.
β€’ Type the command .close to free the channel when you're done.
β€’ Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

ocean helm
marsh citrusBOT
ocean helm
#

what concept am I learning here

#

the prof has a thick accent, his slides are incoherent and he doesnt post book chapters

#

I just need to know what am I learning to know what im supposed to look up in the book and youtube

#

I wish there were other sections with different prof;-;

loud temple
#

First you use the formula for average value

#

Ur learning integral calculus I think

ocean helm
#

imma look that up

ocean helm
#

but this specific thing that im just trying to find out

#

and the c seems to just be a label

#

im not sure

#

hm, seems that average value is the thing

#

thanks

#

.close

marsh citrusBOT
#
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paper raptor
#

(\exists c\in[a,b]:f(c)(a-b)=\int_a^bf(x)dx)

elfin berryBOT
#

PajamaMamaLlama

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
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finite forum
marsh citrusBOT
finite forum
#

Idk what to do next

wet holly
#

Use cos(2theta) = 1 -2sin^2(theta) to rewrite sin^2(2theta) in terms of cos(4theta)

zinc heart
zinc heart
#

and then distribute

lavish pelican
#

no

zinc heart
#

yeah he cano

wet holly
zinc heart
#

reduction identity

lavish pelican
#

πŸ’€

#

do u know the reduction identity

#

by heart

wet holly
#

what's the reduction identity? Google just says it's the same one I said and then you'd just end up with a cos^2 term after expanding the sin^4 term

ebon geyser
zinc heart
#

I'm not gonna do it

#

cause im lazy

#

but its possible

#

you'll get the same answer if you use my way

wet holly
#

oic

lavish pelican
#

obviously

#

its just that its the worst way possible

#

best if u like wasting ur time

zinc heart
#

whateva

#

bunch of haters

marsh citrusBOT
#

@finite forum Has your question been resolved?

finite forum
finite forum
#

.close

marsh citrusBOT
#
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#
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native minnow
#

Hello great math fellows, I need some help regarding understand the following proposition from a paper I'm reading.

native minnow
#

If we take a non-continuous bijective additive mapping f : R β†’ R, the natural extension g: C β†’ C, g(Ξ± + iΞ²) = f(Ξ±) + if(Ξ²) is an additive bijection preserving orthogonality in both directions. We shall see next that this counterexample can only occur when the inner product space in the domain is one–dimensional.

#

first, why the map f must be non-continuous?

#

Also the "natural extension" of f which is g. is it something dedicated to complex spaces?

marsh citrusBOT
#

@native minnow Has your question been resolved?

main idol
#

probably need the actual context of the paper to answer your question

#

a couple sentences usually isn't enough

marsh citrusBOT
#

@native minnow Has your question been resolved?

marsh citrusBOT
#
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violet jasper
#

This the question

marsh citrusBOT
elfin stone
violet jasper
#

Ya

elfin stone
#

So what seems to be the problem?

violet jasper
#

Now done, it's clear

elfin stone
#

ALright

#

alright

violet jasper
#

Ty

elfin stone
#

Don't forget to close the channel before leaving

#

have a good one

violet jasper
#

Kk

calm harbor
#

.solved

marsh citrusBOT
#
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timber imp
marsh citrusBOT
timber imp
#

,rccw

elfin berryBOT
cunning fiber
#

Intuition tells me to ||rotate triangle ADE about A onto AB so D' = B||

timber imp
#

idk everything with x just cancels out and doesnt make sense

lavish pelican
#

in terms of 45 and x

timber imp
#

so 115-x?

lavish pelican
#

yeah but ur right it is cancelling

silk sable
#

There are quadrilaterls ABFE and AFCE. That may help.

lavish pelican
timber imp
#

oh yeah

timber imp
cunning fiber
silk sable
#

There are four inner quadrilaterals. You could make a system of equations, me thinks. πŸ€”

#

Or maybe not. I haven't done the mental gymnastics yet.

timber imp
#

im stuck and theres everything is just cancelling so idk what to do

#

😭

silk sable
#

Give me a moment.

timber imp
cunning fiber
#

everything else is trivial from then on out

#

aka you basically solved the question by doing 1 thing

timber imp
#

so like make an isosceles triangle

cunning fiber
#

where is isosceles coming from

cunning fiber
timber imp
#

you moved ad to ab

#

and its a square

#

oh wait

#

thats the worng line

timber imp
cunning fiber
#

you're doing a rotation

#

what do you know about rotations

timber imp
#

i meant after the rotation

cunning fiber
#

I'm aware of that

timber imp
cunning fiber
#

lemme rephrase

#

what do rotations preserve

#

you can use your intuition based on moving things around to answer this if you want to

timber imp
#

the lengths and angles of the shape?

cunning fiber
#

correct

#

so you can actually fill in some more information now

#

fill in what you can and send a picture of what you have after that

timber imp
cunning fiber
#

angles are fine

#

what happened to labeling the lengths

#

also maybe draw a nicer diagram without the scribbles because that will be helpful in not getting confused

timber imp
#

its a rough sketch i can fix next time

cunning fiber
#

ok

timber imp
timber imp
cunning fiber
#

how is this 1

#

the hypotenuse is always the longest side

timber imp
#

o wait oops

cunning fiber
#

also you can use variables or tickmarks to label equalities that you don't have concrete numerical values for

#

so that you can actually label everything

timber imp
#

@cunning fiber

cunning fiber
timber imp
#

do u mean like extra variables

cunning fiber
#

sure

#

ex. you can label both of these a

timber imp
cunning fiber
#

you tell me

timber imp
#

idk what to do

cunning fiber
#

you can take some time to make observations

#

I don't expect you to get it instantly

cunning fiber
cunning fiber
#

(observe the time gap)

cunning fiber
#

and don't worry if your observations feel "too obvious"

#

that's how you gain intuition/acclimate yourself (source: personal experience)

timber imp
#

with the new angles formed

cunning fiber
#

you're talking about this one right

timber imp
#

the 25 20 and 45

cunning fiber
#

oh yes

#

I see what you're getting at now

#

ok

timber imp
#

thats all i hav found rn

cunning fiber
#

that's fine

#

I have like 13 minutes before I need to leave anyway

#

and I'm just killing time lol

timber imp
cunning fiber
#

idt you need them

#

your first observation is already pretty good if you state it from a different perspective

timber imp
#

what perspective would it be? im still stuck 😭

#

@cunning fiber πŸ™

cunning fiber
#

90 = 45 + 45

timber imp
cunning fiber
#

Oh is that what you’re doing

#

Yeah uh

#

Don’t try to find x

timber imp
cunning fiber
#

Yeah but don’t try to get to x immediately

timber imp
#

or the 2 1s

#

@cunning fiber

silk sable
#

Don't feel bad. It took me a while to figure out what Pigeon was doing.

timber imp
silk sable
#

Here's a better drawing.

#

Think about which segments have the same length.

#

The caveat here is that one segment will be looked at twice.

silk sable
#

No.

#

Pigeon had you move the triangle up to the top and it formed another triangle.

timber imp
silk sable
#

Yes.

timber imp
#

is it AF?

silk sable
#

What about AF?

timber imp
#

the segment thats looked at twice

silk sable
#

Yes.

#

And there is a reason why the top-right point is called E'.

timber imp
silk sable
#

What can you say about those two lengths?

timber imp
#

they are equal

silk sable
#

Do you see the two triangles that extend from point A?

timber imp
#

AFE and AFE'?

silk sable
#

Yes.

#

Note that the angles from A are both 45 degrees.

timber imp
silk sable
#

Have you taken geometry?

#

Or are you currently taking geometry?

timber imp
silk sable
#

What do you know about triangles that have equal SAS?

timber imp
#

oh they are congruent right

silk sable
#

Yes.

#

And these two triangles are a reflection about AF.

timber imp
#

so x should be 65 degrees

silk sable
#

Yes. I've taken geometry many moons ago and I would not have figured this out on my own either. πŸ™‚

#

It's an interesting trick to see. I'm not sure I'd recognize to do it again if I came across a similar problem.

timber imp
silk sable
#

Without using trigonometry, I don't know.

marsh citrusBOT
#

@timber imp Has your question been resolved?

timber imp
#

o wait nvm with trig its easy

silk sable
timber imp
#

<@&286206848099549185> any ideas for part b :)

silk sable
#

AI is so wild for this explanation. It took some finessing and several corrections but it came up with a solution.

#

You have already seen that triangle AEF and triangle AFD' are congruent triangles.

#

From triangle AFE', you can show that EF is equal to FE' which is just DE + BF. This is a long-winded way of saying that EF is equal to DE + BF.

timber imp
timber imp
#

kinda

#

oh wait ef not e'f

silk sable
#

The point here is that you can reframe the length of EF in terms of DE and BF.

#

EF = DE + BF.

timber imp
#

wait

#

did u get perimeter as 2

silk sable
#

Yes.

timber imp
#

i did x+y+1-x+1-y

silk sable
#

Yes.

timber imp
#

ohhh i get it now

silk sable
#

Or more formally.
EF = DE + BF
EC = 1 - DE
CF = 1 - BF
P(ECF) = EF+EC+CF

#

I wonder what type of psycho originally figured this one out. πŸ˜„

timber imp
silk sable
#

That whole shifting triangle ADE, I would have never thought of it.

timber imp
#

im surprised pigeon found that out

silk sable
#

Pigeon has probably seen this type of problem before.

timber imp
#

ill try keep like a mental note of those types but i highy doubt ill find answers for them

silk sable
#

Well ... we both learned something today. πŸ™‚

timber imp
#

tysm for helping to explain to me it was kinda hard to understand

silk sable
#

yw

timber imp
#

.close

marsh citrusBOT
#
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young mantle
#

can i have help being walked through how to answer these questions? i think the answer is unsure without proof but im not sure and im not exactly sure how id explain it

main idol
#

just identify which of the sets contain [0, 4]

young mantle
#

so, none of them?

#

or wait

#

question 14 could contain it, right?

#

if y starts at 4 then moves up 1

main idol
#

draw [0, 4] and [1, 5] on a number line and see

#

A set S "contains [0, 4]" means every number in [0, 4] is also in set S

#

in other words, [0, 4] is a subset of S

young mantle
#

but the question says i shouldn’t use a number line, right?

#

i also dont remember how to write those on a number line

main idol
#

where does it say that

young mantle
#

well it says only use the knowledge provided so i thought i couldn’t do anything else but think

main idol
#

i mean it should be obvious without a number line that 0 is in [0, 4] but not in [1, 5]

#

i was just suggesting using a number for you to convince yourself

young mantle
#

well yeah i know that

queen sun
#

The problem is asking which of these intervals contains [0,4] basically

main idol
queen sun
#

So make sure every number from 0 to 4 is included

young mantle
#

let me draw something so you understand how im thinking of this hold on

#

i only learned functions a few hours ago so bare with me i appreciate your patience thank you

#

i apologize im not that bright when it comes to math

queen sun
#

Not really sure what the question is asking exactly

marsh citrusBOT
#

@young mantle Has your question been resolved?

young mantle
marsh citrusBOT
#

@young mantle Has your question been resolved?

marsh citrusBOT
#
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marsh citrusBOT
#
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finite forum
#

yo

marsh citrusBOT
finite forum
#

what does the 2 lines after an answer mean

#

something line this

keen mist
#

just underlining it maybe?

tiny burrow
#

probably means something was a little incorrect or sm

#

in my country at least

wary lichen
#

Where have you gotten this from to start with

finite forum
#

this guy

#

does it

junior copper
#

its not anything deep or mathematical

marsh citrusBOT
#
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bleak ledge
#

Some use boxes

#

some just write Q.E.D.

#

Its doesn't mean much aside from end of your problem

vernal mantle
#

I do this but it looks more like a #

violet folio
#

Where do i ask for help

finite forum
glossy flint
marsh citrusBOT
#
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willow rampart
#

Pls help with 11

marsh citrusBOT
past thicket
#

What have you tried?

#

Lemme just write it in LaTeX

willow rampart
#

i divided whole equation by 2

past thicket
#

I’m not seeing what that does here

willow rampart
#

u misunderstood i came for 11

past thicket
#

shit

#

sorry

willow rampart
#

no worries

elfin berryBOT
#

π™Έπš—πšπš’πš—πš’πšžπš–Β³

willow rampart
#

yes

willow rampart
#

@past thicket ?

past thicket
#

No I just wrote it in latex so. I could see it without having to look at the paper

willow rampart
#

oh well now pls help me further

past thicket
#

Yep just lemme think about this…

#

use substituion

#

let π‘₯ = 2𝐴 and 𝑦 = 2𝐡

willow rampart
#

ohk

#

hell why didnt i got that idea

#

substitution

past thicket
#

so now we have $\sqrt{3}\sin(x)=\sin(y)$

elfin berryBOT
#

π™Έπš—πšπš’πš—πš’πšžπš–Β³

willow rampart
#

its still same but yea it still helped to reduce my effects in writing

past thicket
#

We can use the identity sinΒ²(π‘₯) = (1-cos 2π‘₯)/2 to transform

√3 β€’ (1-cos π‘₯)/2 + (1-cos 𝑦)/2 = (-1+√3)/2
Multiply by 2 on both sides
√3 (1-cos π‘₯) + (1-cos 𝑦) = -1 + √3

willow rampart
#

ig now ill do it

#

.close

marsh citrusBOT
#
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willow rampart
#

thank you

marsh citrusBOT
#
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finite forum
#

hey

marsh citrusBOT
finite forum
#

can someone tell me where i went wrong

#

sending pics 1 sec

#

this is the answer

quick kindle
#

why is it 3(x-4) rather than just x - 4

stark sandal
quick kindle
#

also why not do partial fractions from the start

#

like why r u doing a substitution

finite forum
finite forum
#

so i assumed i needed a sub

stark sandal
#

its not like the sub helped opencry

obtuse umbra
limpid pond
finite forum
#

thanks

#

.close

marsh citrusBOT
#
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marsh citrusBOT
#
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hard laurel
#

Can anyone tell me a short method without calculator?

obtuse umbra
#

for question 13

#

a number is divisible by 6 when it's divisible by 3 and 2

#

if a number is divisible by 2

#

it's obvious to see

#

if a number is divisible by 3

#

then the sum of its digit is divisible by 3

#

(this can be proven btw)

trim owl
obtuse umbra
#

and i don't see what i can do to 12

hard laurel
#

I'm only asking for 12

obtuse umbra
#

well i don't see how

hard laurel
#

πŸ˜‡

obtuse umbra
#

i mean, that's literally why they asked you to round to 2 decimal places lol

sick walrus
#

those numbers don't look friendly enough for a short method without using a calculator.

marsh citrusBOT
#

@hard laurel Has your question been resolved?

#
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chrome ether
#

We know that ||A+xb ||^2 = ||A ||^2 + x^2 ||B || ^2 +2x Aβ€§B. So We know that ||A+xB||^2 - x^2||B||^2 = ||A||^2 2x Aβ€§B. Then we can see that ||A+xB|| > ||A||.||A+xB || = ||A|| iff x = 0 and Aβ€§B = 0. But you can't still write something that is > as >=. This leads to my issue since we know that it can only equal if the dot product is 0 but you can rewrite the inequality sign to have the equality

copper raven
stark sandal
#

i was like everyone i go i see silksong spoilers

#

then realised im not in obsidian opencry

copper raven
#

A+xB that's such a spoiler

chrome ether
#

do you guys have any suggestions on how to resolve this?

copper raven
#

you're doing a or b ?

#

@chrome ether

chrome ether
#

b

#

but I am a bit iffy on a too

vagrant raft
#

I'd do b by showing the contrapositive I think

chrome ether
#

but don't you get the same issue with the inequalities sign if you try to show the contrapositive?

vagrant raft
#

wdym

chrome ether
#

by this I mean this statement only has equality if x = 0 and Aβ€§B = 0.

vagrant raft
#

I didn't get this

||A+xB|| > ||A||.||A+xB || = ||A|| iff x = 0 and Aβ€§B = 0

#

even if x = 0 and A.B = 0, |A|.|A+xB | = |A|^2 no?

chrome ether
#

ok so we can show that||A+xB||^2 - x^2||B||^2 = ||A||^2 2x Aβ€§B. so if we take away the - x^2||B||^2 . we get ||A+xB||^2 > ||A||^2 2x Aβ€§B

vagrant raft
#

also

|A+xB|^2 - x^2|B|^2 = |A|^2 2x Aβ€§B.

did you mean

|A+xB|^2 - x^2|B|^2 = |A|^2 + 2x Aβ€§B.

chrome ether
#

yes sorry

chrome ether
vagrant raft
#

but you wrote |A| instead of |A|^2

#

anyways

chrome ether
#

don't we sqrt both sides?

vagrant raft
#

how do you get |A+xB| > |A|.|A+xB |

#

you didn't sqrt the left side

#

oh I get it

#

you didn't write the sqrt

chrome ether
#

from what I understand the equation simplifies to ||A+xB|| > ||A||. if the dot product is 0

#

wait do you think we can start from the top. because I think im confusing myself

vagrant raft
#

let me see if I understand:

you're saying that $|A+xB|^2 - x^2|B|^2 = |A|^2 + 2x Aβ€§B$ thus $|A+xB|^2 \geq |A|^2 + 2x Aβ€§B \geq |A|^2$ with equality iff x = 0 and A.B = 0 \
And at the same time, $|A+xB| \geq |A|$

#

I think that working with the contrapositive of statement b) is easier

elfin berryBOT
#

bloubbloub
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

vagrant raft
#

i.e. assume A and B are not orthogonal and find x such that |A+xB| < |A|

chrome ether
vagrant raft
#

for the contrapositive you only need to show that there exists one

#

negation of "for all" is "there exists"

chrome ether
#

Ok I see

marsh citrusBOT
#

@chrome ether Has your question been resolved?

marsh citrusBOT
#
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molten quiver
#

i have to simplify and use conditions of existence but I'm not sure how to

molten quiver
#

(the red thing is the result im supposed to get btw)

elfin cairn
#

find a common denominator

molten quiver
elfin cairn
#

are you saying the common denominator is 2?

molten quiver
#

yeah

elfin cairn
#

a common denominator will be a multiple of both other denominators, 2 is not what you are looking for here

molten quiver
#

oh

elfin cairn
#

naturally a common denominator will be something like (x^2-2x)(x^2+2x) but there is a more reduced version. Can you see it?

molten quiver
#

a more reduced version in what sense? (sorry I'm bad at math)

#

so im not sure what your referring to

elfin cairn
#

a common denominator of smaller degree

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specifically of degree 3

molten quiver
elfin cairn
#

ok

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then lets ignore that

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for now

molten quiver
#

aight

elfin cairn
molten quiver
#

plus im not sure what ^ is supposed to be in this case

sick walrus
#

^ denotes an exponent.

elfin cairn
#

x^2 is x squared

molten quiver
#

ohh

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oh wait nvm

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i think i understand

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so just write everything together?

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but does that include the upper part or just the lower part?

elfin cairn
#

if you multiply the denominator by something you have to multiply the numerator by the same thing to preserve the value of the fraction

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$\frac{a}{b} + \frac{c}{d} = \frac{ad}{bd} + \frac{bc}{bd} = \frac{ad+cb}{bd}$

elfin berryBOT
#

ExpertEsquieESQUIE

molten quiver
#

so I have to multiply the first one with x^2+2x

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and the second one with

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x^2-2x

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right?

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(including the top part)

elfin cairn
#

yes

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try to do it now

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on paper preferably

molten quiver
#

ohh nice okay

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sure

queen sun
#

It would be easier if you factorised these quadratics first

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Then you can see what is needed to create a common denominator

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As long as you multiply the numerator and denominator by the same thing even a polynomial like x+2/x+2 it will still be the same, so try to use that

molten quiver
#

now what?

elfin cairn
#

what did you end up with

molten quiver
molten quiver
molten quiver
queen sun
molten quiver
#

yk C.E

queen sun
elfin cairn
queen sun
#

Also I don’t see why you can’t factorise first

molten quiver
queen sun
#

$x^{2}-2x=x*(x-2)$

elfin berryBOT
#

BBMaths

queen sun
#

Maybe factorize in us spelling

molten quiver
elfin cairn
#

they have the same denominator

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so just add the numerators and keep that denominator

elfin cairn
molten quiver
#

ohhh

molten quiver
elfin cairn
#

close

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one small mistake with your simplification of the numerator

molten quiver
elfin cairn
#

||it should be times 2||

molten quiver
queen sun
#

No*

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Both the numerator and denominator can be divided by x^2

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Simplifying

molten quiver
#

uhh

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guys slow down 😭

queen sun
#

So a fraction like 12/8 can be simplified to 3/2

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The same applies to these polynomials

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Polynomials is like x^2-2x

queen sun
molten quiver
elfin cairn
elfin cairn
queen sun
elfin cairn
#

you did (x^2 + 2x) + (x^2-2x)=x^2 but its actually 2x^2

queen sun
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$\frac{2x^{2}}{(x^{2}-2x)(x^{2}+2x)}$

elfin berryBOT
#

BBMaths

molten quiver
#

like this guys?

queen sun
#

No

molten quiver
#

oh nvm the bottom dosent need the extra ^2 right

queen sun
#

The denominator was fine

molten quiver
#

ohh ok

queen sun
#

Do you know how to factorise x^2-2x?

molten quiver
#

nope

queen sun
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Okay so do you know how to distribute like $(x+2)(x-1)=x^2+x-2$

elfin berryBOT
#

BBMaths

molten quiver
queen sun
#

This is* just an example not related to the problem or do you mean in the example?

molten quiver
queen sun
#

Wait I’m confused now do you know distribution?

molten quiver
queen sun
#

This question seems hard to do without knowing distribution or factorisation

elfin cairn
#

the law of distribution tells you x(y+z)=xy+xz

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so in the example above:

molten quiver
#

Ohh im just supposed to multiply

elfin cairn
#

yes

molten quiver
#

nevermind

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sorry im not familiar with math lingo

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so i get confused a lot

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okay after i use distribution then what?

queen sun
#

We want to do the opposite of distribution here

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Factorisation is doing this in reverse

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$x^2+2x \rightarrow x(x+2)$

elfin berryBOT
#

BBMaths

queen sun
#

There we go

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We need to do this to x^2+2x and x^2-2x

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Then the denominator will be fully factorised (usually better that way)

molten quiver
queen sun
#

Yes

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Do you see how to get rid of x^2 now

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$x^2=x*x$

elfin berryBOT
#

BBMaths

molten quiver
#

yes

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ok what's the next step?

queen sun
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Cancel them out

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On numerator and denominator

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If they share a factor they can go

molten quiver
#

like this?

molten quiver