#help-33
1 messages · Page 218 of 1
the Mohr–Mascheroni theorem states that any geometric construction that can be performed by a compass and straightedge can be performed by a compass alone.
@scarlet wagon Has your question been resolved?
it can be performed by compass only
since the first two points generate the same construction (they're isomorphic)
this doesn't solve much
it says the points have coordinates that are expressible with addition, subtraction, multiplication, division, and square roots
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Hello! I need help solving an ideal gas law equation, I think I may be stuck when it comes to units
#old-network - this server is for math, not sciences
My bad! I thought that it might still be applicable because it's a simple equation uf you take away units
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Can someone please help me
!da2a
No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/
do you have a specific question in mind?
it's not easy to help somebody when you don't know what they need help with 
Yup, send it mate!
Sure!
11,12,13,14
Alright, can be write monthly fee of Karate Klub as x and monthly fee of Kool Karate as y?
Yeah
I meant 25x and 35y, mb
Ahhhhh I'm an idiot, just take x as the number of months, ignore y
X=number of months?
Yes
Ah
So what's the cost for each club if I go there for x months, the total cost
How would you write that as a function?
Wait I'll help you with this one
Thank you
I don’t think we learnt that yet?
Okay then, we'll try another approach, I'm sorry for not confirming this earlier
No no all good! I appoligise for not mentioning!
So basically, we want to know when the prices would be equal
Correct
And total prize of Karate Klub after x months is 200 + 25x, and Kool Karate is 100 + 35x
Would we write it like this 200+25x=100+35x
We collect our like terms
Yes
300=60
Ahhh you made an error
Send me the equation after getting all like terms on one side
Okay, the equation after getting like terms on one side would be?
-10
And subtract 100 from both sides
Yes
I have a paper yep
Alright, subtract 25x and 100 from both sides, you'll get 0 on one side and a number on the other, what would the equation look like?
Unfortunately no
Oh
Okay see, we have 200 + 25x = 100 + 35x
Correct
I subtract 100 from both sides
Wait
200 + 25x - 100 = 100 + 35x - 100
What would this give?
No no
Just subtract the 200 with 100 on left side, and 100 with 100 on right side
What equation does that give you?
100-100=0
Yes
200-100=100
Yes, on the right path
So how would the equation look like now?
200+25=35
You missed the x there
35x and 25x
200-25=175
No no
It's 200 + 25x = 35x
200 won't be affected if we subtract variables
Yes
35-25=10
Write the x too, so you don't get confused
Wait
We subtracted 100 from 200 earlier
So it was 100 + 25x = 35x
So it's 100 = 10x
I missed that, apologies
So what should be x?
You're confusing constants with variables
If we subtract 25x from 100, then it won't affect the 100, because they are not like terms
We got this equation
Wait so
So what should x be?
Bingo!
Okay, and?
No no this is fine
So the number of months are?
Number of months was x, let me remind you
That's correct, you've solved the first part
No no forget y
Ok
David wants to save money, so he'll go to the one that charges lesser after 6 months, no Karate Klub charges 200 + 25x, substitue x with 6, what do you get?
That's great
Now Kool Karate was 100 + 35x, so what would be the total charge there after 6 months?
310
The second one =310
Okay, so David would join that club
In first part?
Yea
Alright, that's the number of months after which the total charge would be equal
Substitute x = 10 in 200 + 25x, you get 450
And x = 10 in 100 + 35x is also 450
So after 10 months, you'd have payed the same amount in both the clubs
Sure, now do the thing you did in second part in third part, just replace x with 12 this time
How would we write that
Just write the equations for each club and replace the x with 12, write in brackets talking x = 12 as the number of months are 12
100+200(12)
Wasn't it 100 + 35x and 200 + 25x?
635
For second one, yes
Wait for 200*25
No no, why would be multiply 200 with 25
Nvm sorry
It's fine
Well that's fine, take your time
So 100 +35+200+25 x 12 would give us 650
Yes, that's the total cost for second one
Ok
And the cost for the first one would be?
It was 100 + 35x
Right
So what would it be, after 12 months
520
520
520 is Kool Karate and 650 is Karate Klub
Alright, so he would join Karate Klub if he was joining for 6 months (second part) and Kool Karate if he was joining for 12 months (third part)
Correct
Okay, you need help with the others?
Yeah it's fine
Have a good day! Thank you so much again
You too mate🫡
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First did i draw this right and second im confused on if this is a washer or a disk
@keen wyvern Has your question been resolved?
The parabola should extend into Q2 as well.
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im very confused on how to find sample variance and standard deviation, dont know how to use the formulas
welcome to the server!
thanks!
please share a specific question you're stuck on for your problem here
would be better that way
it wants me to find s squared and o squared for a data set of 21, 3, 13, 7, 8. in my notes it says to create a table with two columns but how do i create two columns with five numbers?
(sigma, not o)
could you show the original problem, exactly as stated, please?
that and show what youve got in notes
can i send pictures in here to make it easier?
Yes
picture 4 shows how to make those two columns you need
how do i add it into the equation
what equation? cuz you need to set up the table first (or, if you can hammer out the values you need, you can skip the table)
by the way
idk if the equation in pic 2 is entirely applicable. you may need to make some minor modification to it
what do you mean
you are given the formula for the population standard deviation
however, in your question, you are asked to find the sample standard deviation
the formula is slightly different
i'm not sure if you have learnt about this, and from the mention of s it sounds like you have
but your notes shown here don't show that
if you have, proceed as usual as per picture 4
i cant find any notes on sample standard deviation, how much different is the equation for it?
ohh ok
so would you know how to proceed using picture 4?
no but i can probably figure it out
sure. a quick hint would be to think about how you would enter these scores in something like Excel
for the table?
yes. enter the scores in one column
would you like to keep this open for checking purposes, or are you done with your question?
i think im done with the question
alright. if you're done, please .close the channel or mark it as .solved
and see you around!
.close
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isnt integral 2cosx sinx just sin^2 (x) ?
Why
but then how is -1/2 cos2x equal to sin^2
oh wait the c just differs
yes
why not
isnt dy a change in y
and dx a change in x
wdym
when can i treat dx as a small change in x and when can i not treat it as a factor
because sometimes i ask and people tell me its just a small change in x and i can treat as a factor and in other cases i cant
but i havent understood when i can and when i cant
in substitution
dont we go from u=y => du/dx = dy/dx => du = dy/dx dx
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✅
anyone?
Well, we could cancel, and it would get you the same result (note you'd have N(y) dy instead, but the integral is essentially the same)
The reason this is informal at best and mathematically illegal at worst is precisely because "dy/dx" as a fraction overlooks the property that both dy and dx represent infinitesimially small quantities
While the cancellation here can look legal here, that's more just a result of luck than anything
We want to rely on more than luck; hence the substitution
why can i not treaat it as a factor
and why can i treat it as a factor in other cases
(I think you're confusing the words "factor" and "fraction")
sometimes
(which do you mean)
you can use multiplication of dx
sometimes you cant
when can you and when cant you
$\frac{du}{dx} \ dx = du$ yes, always
south
but this is not to be justified as multiplication
can i like divide by dx/ multiply by it sometimes always or what
it follows from the chain rule
yes, it always gives the same result as the chain rule
if everything is differentiable and so on
Like, these AREN'T fractions (in the strict sense), though, which is the key point
what isnt a fraction
dy/dx
its a division of fractions
(You're confusing yourself again)
It just so HAPPENS that we notate them like so, which leads to the misconception that rules governing fraction arithmetic apply here too
And sometimes they do, but not for the same arithmetic reasons
yes
and the derivative is a limit by definition
it's an infinitesimal
it doesn't mean anything on its own formally speaking
whats the difference
you can think of it as "a tiny, tiny change in x"
if dy/dx
"limit" refers to a point a sequence of points approaches
is the limit of the division change in y and change to x
(You're getting that from the lim-def. of derivatives)
then why isnt it infinitesimal dy /dx
?
We're explicitly telling you that dy and dx are infinitesimals
We can't let either be 0, because that results in a division by 0 problem
So we don't
i dont see how the dy/dx in derivative
We literally let them be "infinitely small" (except "infinity" means "unobtainably massive" usually, so we use "infinitesimal" instead)
is any different than lets say dy * (1/dx)
But I am telling you that the reasons behind them are not the same as the arithmetic examples
to use dy and dx as a fraction
Because these are fokken tiny
if its infinitesimal small isnt it the same as taking the limit
Arithmetic just doesn't function the same; we can't assume these rules to behave
[I recommend you read up on what infinitesimals are; you'll get a better understanding of what I mean by this]
so the difference is
we cant distribute the limit
on a derivative
cause that will result in division by 0
generally yes
what are they
how is it not a real number
But I mean you need to read a short course on this; I'm not gonna write down a whole syllabus here
(by definition it is not a real number)
"because we say so"
I mean tbh you could just try googling this
That's literally what I'm implying he do
Ye
I'm just stating it ig
this looks similar to limit defintion
it's not
the limit definition only uses real numbers
so
in the real numbers, there is no infinitely smallest number
in derivatives
it just doesn't exist
dy and dx arent infinitesemals?
is it inside the limit
Personally I recommend the Iowa one
we have lim Δx/Δy
when we write dy/dx
we cant mean the limit goes to both
cause that identity isnt true here
so what do we mean by dx
This is us literally leveraging infinitesimals
do you know that $\frac{d}{dx} f(x) = \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}$
south
we mean this
we assert the existence of a number infinitely close to 0
and that's not a real number
but inside a limit
dont we say that means the limit is 0
so that's different from what you're saying about dx
this doesn't use any infinitesimals
we get to a point where we can just sub in h = 0 without dividing by 0
yea i dont understand how we can use infinitesimals to represent a limit
how can dy/dx = lim Δy/Δx
one side is a limit
and that's no problem
well then do you have any problems about this then
so left side cant be 0
but there are derivatives that are 0
ok so
define y = 5 , x in R
dy/dx = lim Δy/Δx <=> dy/dx = 0 <=> dy = 0
contradiction
since by defintion dy cant be 0
what went wrong
cause you're not considering the limit
$\lim_{x \to 0} \frac{x}{1} = 0$
south
$\lim_{x \to 0} \frac{x^2}{x} = 0$
south
you cannot conclude dy = 0 if there's a limit
i have a division of infinitesemals = 0
how can this be true if none of them are 0
how can a/b = 0 hold with a,b =/0
just look at this example
lim a/b = 0
there are many functions whose limit is 0
no no
you just told me
that in dy/dx
dy and dx are infinitesemals
and so?
you would need to define a concept of a limit for non-real numbers
that is a valid point
there is no limit
you can define such a concept
this is why arithmetic on infinitesimals doesn't work out then
it doesn't work when you divide them
what does a/b even mean
dy/dx is undefined for dx, dy being infinitesimals
then if its undefined
division doesn't mean anything here
why are we using it to represent derivatives
we shouldn't use infinitesimals to represent dy/dx
that's my point
you're using arithmetic on infinitesimals
do not do that
since one side is infinitesimals and the other a limit
but like dx you can find it inside expressions
if dx is an infinitesimal
and we cant use arethmitic
we're always going back to the limit definition then
then we cant use dx
yes
you have to go back to the chain rule to understand this
it's a historical accident people discovered calculus
before it could be made rigorous
isnt this arithmetic as in a multiplication of a derivative with an infinitesimal
well actually here there might be more confusion
cause the other dx is from the integral
yes, that's also a historical accident
yea icl man
intuitively dx makes sense as the width of the infinitesimal rectangle
im more confused than before i started asking
so
wdym
the whole notation for integrals is wrong ?
and we just dont change it cause we historically used it in the past like this
yeah...
you might want to search up Lebesgue integration
so we can also not do arithmetic with the dx of the integral
the current notation is the one that makes the most intuitive sense
we're technically not manipulating dx when we use the chain rule
then why do some people write int 1 dx as int dx?
My mathematician in highschool said we should write int 1 dx because the dx goes with the integral as symbolisation
but tbf atp idk whats write or wrong
yeah, it comes from treating dx as a kind of number
so technically people shouldn't write that
but the meaning is clear enough
yes
yes
is just a conventional thing
ok thanks
yeah I mean the whole history of calculus and analysis is insane
ok
there's also a concept in linguistics called pragmatics
which states "if I understand what you mean, even if it's technically wrong"
why bother fixing it?
if it ain't broke don't fix it mentality
think of the millions of students for whom calculus already doesn't make sense
and you could force the 'proper' notation on them
but they wouldn't understand anything
so this is a choice so that students learn what calculus is, then question every assumption about what they've learned later
that's how we can service all the engineers, physicists, and basically everyone who isn't a pure maths person
bro is offending me now
otherwise you'd have to teach every 11th grade student what a measure is (in measure theory)
i see how it is i cant study math because im going into engineering
and a million more abstract concepts to learn something so useful
you can
yea ik just jk
but pure maths and engineering are two completely different mindsets
uni hasnt started yet
but i was told in electrical engineering some stuff we write wrong
and we make a lot of conventions
yes
thats gonna piss me off fr
there are certain subfields of engineering which are particularly egregious
for example
on the differential equation for like metal moving with exponential function it doesnt go to 0 ever but we agree its 0 after some point
its I - e^r/L ... or some like that
i think its supposed to mean something like the sum of tiny rectangular areas in a cartesian graph
and has asymptotic line y=0
anyways yea
@amber birch thanks a lot i understand it now
no worries!
one argues that in physics, if two things are less than a certain constant (dim: length) apart, then they're actually the same thing
so yeah the foundations of calculus are the real numbers
that's why it's called real analysis
very roughly anyways
and then the real numbers are very very nice as a mathematical structure, so we can do a lot of cool things with them
like calculus
legend for answering to me doubting everything
i was getting mad of my own questions at some point
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How do I even sketch that curve to begin with I know y=e^(x) but not that one
you could isolate y in that eq
Y=1/x²
I'm not sure, maybe use intercepts from there to find 2 points
Does that work
@autumn vault Has your question been resolved?
@autumn vault Has your question been resolved?
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I’m really confused because this does not give me enough info. It does not give me an interest rate or time line besides 10 years.
,rccw
And now I’m really confused because for the next one I’m getting the same number I started with
4 million over 10 years is 400,000 per year, I'm not sure if they want you to do anything else, it doesn't seem like it?
I have to use one of these equations
I'd imagine if the interest is not specified it's just 1?
I don't do financial math often, so I'm not really sure what to do here
Kk no worries
The problem I’m running into is I either done have enough info or my equation gives me the same number I put in
RoR is just percent increase in value right
I don’t know…
The problem is my finance teacher is a history teacher he doesn’t know how to teach math
But I don’t understand at all why Everytime I have been able to do a equation it equals the same thing I put in
in cuemath we trust
anyway so
initial value is 4m
final is 8m
theres no discussion to be had now
The problem is my teacher said to only use the two formulas he gave us
Is my teacher just wrong? Like I won’t be surprised he’s a history teacher teaching personal finance …
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Guys I don't understand when a function is neither increasing nor decreasing
Well look at something like f(x) = x²
It's decreasing when x is negative and increasing when x is positive
Overall it's neither
What if I'm given a condition x ≥ 0
Then u can do e.g. sinx
It goes up then down then back up then down...
Wait I have a sum
For example this sun
The answer is neither
I don't understand why
The f'(x) is (-6+2x)/(x+2)^3
When is this positive? When is it negative
I don't understand that
From what I know
if f'(x) is positive
It's increasing
And vice versa
And what if both happen in the same domain
I'm sorry I don't understand
Do you think this function is increasing or decreasing or neither for x in (-inf,inf)
Yes because there's a part where it's decreasing and part where it's increasing right
Yes
So if f(x) is both increasing or decreasing
No matter the function?
You can't call it an increasing or decreasing function
Yes
So in the end it all comes down to the condition
Yes
Ok but what about this one
The condition is same here but the function is increasing
I think you misunderstood
If the function is only increasing for the given domain
Then it's an increasing function
If the function is only decreasing for the given domain
It's a decreasing function
And if it does both it's neither
I'm sorry but what do u mean by the domain
x>=0
Oh I understand it now
Thank you man
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hwkp
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Can I cancel these (x-5) and (x-3) without losing solutions?
And if not, I'm wondering how I'd go about solving this
it's not that you lose solutions but rather that you risk gaining some
namely x=5 and x=3
whichever ones happen to be solutions afterwards
and indeed the one solution you got, x=3, must therefore be discarded as extraneous
Sorry how are solutions gained by doing that? Is it because x=3 wouldn't normally work because x-3 would be on the denominator if I hadn't canceled?
yes, same logic for x=5
Ok that makes sense!
What if I was doing a bunch of algebra to solve something, and midway through I had for example (x-7) on the denominator of an equation, but only because I did algebra to put it there. Would x=7 still be excluded as a solution? What if I removed the (x-7) afterward without cancelling it?
if you put it there by algebra then it means you would have divided by (x-7) at some point
as in, divided both sides by (x-7)
this risks losing x=7 as a sol
it's a risk. i can cook up an example where you're lucky and it is not lost.
but the best way to mitigate this risk is to just account for x=7 explicitly before doing it
I would appreciate that if you feel like doing it!
(x-7)^5 = 8(x-7)^4
Like account for it by subbing it in and seeing what happens?
dividing by just (x-7) gives (x-7)^4 = 8(x-7)^3
yeah exactly
So 15 and 7 are both valid answers here, and we can know 7 is valid by testing it before we divide (x-7)?
yes
We also could have lost a soln in this example if we immediately divide both sides by (x-7)^4 without accounting for x=7
Anyways I think I get it! Thanks so much @stoic saddle I really appreciate the help! 😄
@delicate prairie thank you as well for your help!

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hi
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
okay
and the eigenvectors to go with them
Aren’t the eighenvectors orthogonal ?
You just need to normalize them and you’re done
and the ones op just gave are.
"eigenvector" has no h btw
My bad
wonderful now just normalize these as shakigras said
and youll have yourself a diagonalization
which really is all that the question asks for
i still dont understand what O and D are
ok do you know how diagonalization works
like $A = PDP^{-1}$ where $D$ is a diagonal matrix that holds the eigenvalues of $A$ and $P$ is the matrix whose cols are the corresponding eigenvectors
Ann
and here is O the P? but here it's the transpose?
waiit
oh ok
why do we normalize O?
why do we normalize
if the cols of P are orthonormal then P is orthogonal
Because the matrix O is supposed to be orthogonal. Which means all its vectors need to be normalized
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im stuck.
i have 0 clue what to do further
i looked at it again and i think theres nothing more to do? its solved?
Consider a k such that x_k = k^2 + k
Then x_(k+1) = (k^2 + k) + 2k + 2 = k^2 + 3k + 2 = (k+1)(k+2) = (k+1)(k+1 + 1) = (k+1)^2 + (k+1)
Hence the relation between the serial number and the value of x for that serial number holds for the serial number k + 1 if it holds for the serial number k.
x_n = n^2 + n holds for n = 1 and hence it holds for n = 2 and so on.
I understood that but did i do it correctly or was there something missing? can i just write that x_n = n^2 + n is the same as (k+1)^2 + (k+1)?
because i proved that its the same if u input 1, 2, 3 ,4 ?
oh wait they are legit the same...
<@&286206848099549185>
i dont know the exact meaning of mathematical induction
but i can help you solve this problem
a proof technique to show a statement is true for all natural numbers
ok i think i can do that
u kinda need mathematical induction to solve this haha
You don't need but you are required to use it here.
so its given that x_n+1=x_n+2n+2
consider x_n= x_n-1+ 2(n-1) + 2
and all terms all the way to x_2 = x_1 + 2 + 2
now define a sum S = x_1+x_2+x_3... x_n+1
and add all the equations till here
that will give the value of x_n in terms of n, numbers, and x1
after a bit of simplification that is
lmk if you dont understand any of this
ill write it down on paper and send it here
hm i solved it and then checked this 😅
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I think a plane is just a line but it is also infinitely thick
So I'm kinda imagining this as two pieces of paper, one higher up that the other
and they are at the same slant
but I have no clue where to go from there
Also tried just doing 23.52 - -18.11 but that's wrong
the correct answer is 5.622 btw
BTW I can't really graph this, my calc only supports 2d on the grapher
desmos
note that the planes are slanted, so this doesn't work
since the planes are parallel, ||I'd pick a point on one plane and use the formula for the distance from a point to a plane||
Not really sure how to go about that
whats that formula?
this formula
Ok, and to pick a point I'm gussing I just assign random value to x, y, then solve for z?
yes that right
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I have a graphing calc and can also write programs to perform calculations
to actually find that full value directly is impossible, just returns infinity on my calc
I also graphed 2017^x and looked at the table, but I couldn't find any patterns with the first 5 numbers
oh yeah I just typed in python shell, returned 3906579...
How could I do this generally?
modular arithemtic!
Read the question again
and what do I do with that value?
... no
$2017^{2017}=((2017)^2)^{1008} * 2017$
ExpertEsquieESQUIE
Read it again, slowly
i'm interested to find consecutive powers of 10 that it lies between
ok I understnad that, just splitting up the exponents
ye
mb @leaden peak
is it possible without python then?
With a decent calculator, yes
i found $10^{6665} < 2017^{2017} < 10^{6666}$
Axe
That just tells you it has 6666 digits
I mean, Python is being run on my calc so
It's just the actual calculator app doesn't return the value
then i think you want $\lfloor 2017^{2017} / 10^{6661}\rfloor$
Axe
$2017^{2017} = 10^{2017 \cdot \log_{10}(2017)} = 10^{\lfloor 2017 \cdot \log_{10}(2017) \rfloor} \cdot 10^{{2017 \cdot \log_{10}(2017)}}$
i got 39065
Nel
All you need is the first 5 digits of $10^{{2017 \cdot \log_{10}(2017)}}$
Nel
(where {x} is the fractional part)
that's slightly different than what i did, but that also gives 39065
that's a good sign
(you only need the first 5 digits of {2017 log_10(2017)})
can anyone explain what this stuff means or how to get it?
oh I think its just log properties
yeah mostly log properties
$n=\lfloor n\rfloor + { n}$ for any n
$x = \lfloor x \rfloor + {x}$
Axe
wait what does curly brace mean?
.
oh yeah that makes sense
so ${n}=n-\lfloor n \rfloor$
why are the brackets not visible
The integer part doesn't contribute since it just ends up doing powers of 10
You need to write \{ and \}
Curly braces make groups in LaTeX
UCYT5040
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could someone explain the diagonal set definition? i dont get it
im p sure pi is treated like a permutation of S, so like for example {5,2,3,1,4}
what does pi(i) mean?
a permutation of S can be thought of as a bijection from S to S
so (5,1,2,3,4) example could be phrased as a function pi(1) = 5, pi(2) = 1,...
? what else could it be?
isnt that the default view?
well that's the underlying definition but you don't have to write it in function notation
ah ,gotcha
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need help
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A printing house must print a novel in two formats. This novel will be produced in at least 5000 copies but at most 8000. The number of pocket format novels must be less than the number of standard format novels, but must be at least 2000 copies. The pocket format novels cost $8 to print and will sell for $13, while the standard format novels cost $11 to print and will sell for $15. Knowing that the production costs amount to $1350 for printing, what maximum profit can this printing house expect?
x: number of pocket format novels
y: number of standard novels
x+y >= 5000
x + y =< 8000
x =< y
x >= 2000
i got troubles with this part
A printing house must print a novel in two formats. This novel will be produced in at least 5000 copies but at most 8000. The number of pocket format novels must be less than the number of standard format novels, but must be at least 2000 copies. The pocket format novels cost $8 to print and will sell for $13, while the standard format novels cost $11 to print and will sell for $15. Knowing that the production costs amount to $1350 for printing, what maximum profit can this printing house expect?
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3000
Then the coordinate is (2000,3000)
got it
Do same with 8000 line
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why tis not 2
Its asking you to find the function f(t)
you see it looks like a parabola shifted downwards
yah i got it now i didn't know it want the function
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Btw insane that parabolicinsanity is answering a parabola question
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excuse me, i'm trying to solve this question but i'm not really sure which direction to take. the decimals seem out of place where i am so far and i'm not sure if i'm taking the right approach. i'm doing this problem for fun so i may not have written my explanation in the best way 😓
i got stuck after 5.4 and i genuinely have no idea where to go after this or if calculating DE was even in the right direction 😭😭
BD = DC is incorrect
!help
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how do i not occupy it
oh really??
uhhhh yes
The ratio is 3
So 4*A(BED) = A(DCA)
3 to 9
OHH okay i get that
Do you get this one too ?
I skipped some steps
i've been trying to understand it but where'd the 4 come from
Ok let me write on a paper it’s hard to type
OKSY SURE!! thanx
.rotate
So if you keep going you’ll find : ED = 4 and BD = 5
@woven chasm
,rccw
Thank you
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thanks
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i found x y u and v, where to go from here?
i also notice that u=v^2 looks similar to x=y^2, but they are different variables in different dimensions no? how do i use this hint?
Ngl, this so much more convoluted than it really needs to be, ill try to tackle it
a and b are my lagrange multipliers btw
This can be easily solved by differentiating regular f(x) functions tbh
Anyways, gimme a sec
as in, just recreate the problem to be easier
takes a little bit of geometry to come up with an answer, and tbh, i havent been able to get much progress on the method the problem asks for
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What’s wrong with my working?
@drifting goblet Has your question been resolved?
