help-33

[mystic gazelle]

My discord crashed

@desert dirge @summer grove

[summer grove]

!noping

[marsh citrus]

Please do not ping individual helpers unprompted.

@mystic gazelle Has your question been resolved?

[marsh citrus]

@mystic gazelle Has your question been resolved?

[marsh citrus]

@mystic gazelle Has your question been resolved?

[marsh citrus]

Channel closed

Closed by @mystic gazelle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[broken bough]

How do i do this i have this as an example but i dont understand

[wary kite]

what is the goal?

the instructions are cut off from the picture

[marsh citrus]

@broken bough Has your question been resolved?

[broken bough]

Ill send it

Youd have to tap on it

[wary kite]

x = 4 is given so all you need is to solve for y

just substitute x = 4 into the top equation

[broken bough]

Okay

Like this?

[wary kite]

exactly

now what does that come out to

[broken bough]

5

[wary kite]

mhm

so y = 5

x = 4

(4, 5)

[broken bough]

Ohh okay thank you so much i have one last help with this one hold on

I dont understand how to put the word equations into an equation

[rotund pike]

What do you mean by putting a word into an equation?

Oh, I get it.

The word problem.

[wary kite]

you don’t have any idea of how to translate it into math?

[broken bough]

Like i just need help in putting it into the equation correctly

[wary kite]

how about this, can you tell me how much it would cost to get two photos from lightning fast foto

[tired monolith]

5 + 0.2p = 7 + 0.1p

[broken bough]

Is that the equation?

[tired monolith]

try solving it first.

[tired monolith]

do you want me to explain it

[broken bough]

Yes please

[tired monolith]

man I'm explaining bullsht

let me redo that sorry

[tired monolith]

okay, what is the question asking?

[broken bough]

Which place is cheaper?

[tired monolith]

not quite

[tired monolith]

it's asking how many photos have to be taken on both sides for the fee to be the same

let me make an equation and I want you to dissect it

5 + 0.2p = 7 + 0.1p
fee fee

both sides are the fee don't pay attention to the variables

well actually the variables do matter

[broken bough]

Okay

Is x 20?

[broken bough]

Is it 20?

What about 2 on this one

[marsh citrus]

@broken bough Has your question been resolved?

Channel closed

Closed by @broken bough

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid urchin]

Was looking to see how you guys would interact w the canceling of these units along with an explination. I know the first two interactions end in multiplication but apperently the last one ends in division which I dont completely understand.

[dry prawn]

What do you mean "ends in division"

[marsh citrus]

@timid urchin Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sharp juniper]

I need help on number 25

[final girder]

someting like f(x) = { 2, -6<= x<= 1
-2, -1<x<= 2
and so on

[sharp juniper]

Oh! I think I understand now

Thankyou

.close

[marsh citrus]

Channel closed

Closed by @sharp juniper

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fallow furnace]

\textbf{Theorem 6.42 (One-sided derivatives of a convex function)}
Let the function ( f ) be convex on an open interval ( I \subseteq \mathbb{R} ). Then ( f ) has finite one-sided derivatives from the left and from the right at every point ( a \in \mathbb{R} ).

[elfin berry]

Slowaq

[fallow furnace]

isnt there a mistake in this theorem

shouldn't a be from I not R?

[marsh citrus]

@fallow furnace Has your question been resolved?

[fallow furnace]

<@&286206848099549185>

.close

[marsh citrus]

Channel closed

Closed by @fallow furnace

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[buoyant jetty]

L1 = L2 = B

a(0,-1,1) + (4,2,1) = b(0,1,2) + (4,-2,-4)

1. 4 = 4
2. -a + 2 = b - 2
3. a + 1 = 2b - 4

3 = 3b -6

3+6 = 3b

3 = b

a+1=6-4

a=6-4-1

a=1

B = a(0,-1,1)+(4,2,1)

B=(0,-1,1)+(4,2,1)

B=(4,1,2)

[buoyant jetty]

AC.AB=0

[marsh citrus]

@buoyant jetty Has your question been resolved?

[buoyant jetty]

B=(4,1,2)

A = (4,2,1)

[outer lodge]

Have you tried subbing in B-A for AB and C-A for AC?

[buoyant jetty]

let me try to see if its perpendicular

B=(4,1,2)

A = (4,2,1)

C = (4,-1,-2)

,w ((4,-1,-2)-(4,2,1))

[elfin berry]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 938c2cc0dcc05f2b68c4287040cfcf71

[buoyant jetty]

,w (4,1,2)-(4,2,1)

[elfin berry]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 938c2cc0dcc05f2b68c4287040cfcf71

[buoyant jetty]

(B-A).(C-A)=0

,w (0,-1,1).(0,-3,-3)

[elfin berry]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 938c2cc0dcc05f2b68c4287040cfcf71

[buoyant jetty]

looks okay tbh

I think is correct

.solved

[marsh citrus]

Channel closed

Closed by @buoyant jetty

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[digital chasm]

Can someone help me understand sine and cosine law

[potent reef]

What do you need help with?

[digital chasm]

Trig

It’s like finding the angle without it being a 90 degree

Angle

[potent reef]

What angle?

!xy

[marsh citrus]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[summer grove]

,tex .sine law

[elfin berry]

Bonk

[summer grove]

,tex .law of cosine

[digital chasm]

That

[elfin berry]

Bonk

[summer grove]

,tex .double angle

[elfin berry]

Bonk

[summer grove]

,tex .half angle

[elfin berry]

Bonk

[summer grove]

these ones?

[digital chasm]

I think so

[potent reef]

What was the original question?

You either need to show the original question or articulate more clearly what problem you're facing with something.

[digital chasm]

The original question was I need help with understanding sine and cosine

Law

[summer grove]

like, understanding hwo to use them?

[digital chasm]

Yes

Because I was trying watch YouTube videos and I was still confused

[summer grove]

this is what it means

A, B and C are angles

and the ratio of the sine of the angle to the opposite sidelength is equal for all angles and sidelengths

to put it awkwardly into words

[digital chasm]

I get that part

[summer grove]

so what more is there to understand?

here, try solving this one

A is 40, a is 6, b is 8

what is B?

[digital chasm]

Ight I might not get it

So is it 40sine 6 for A right

[summer grove]

no

A is 40 degrees

[elfin berry]

Result:

0.64278760968654

[digital chasm]

So do the side of a go to the bottom

[summer grove]

look at this equation

you have A, a and b

you should be able to get B

[digital chasm]

B 8 right

[summer grove]

no

b is 8

[digital chasm]

What the difference from what I said

[summer grove]

B is the angle

b is the sidelength

big difference

[digital chasm]

Oh

Is the angle A

[summer grove]

yes

A=40 degrees

[summer grove]

x=sin(B)

then solve for B

[digital chasm]

Did I set that right to find b

[summer grove]

yes

well, close enough

[digital chasm]

30.9

[summer grove]

thats not quite right

[potent reef]

damn bro

[digital chasm]

Wouldn’t you cross multiple

[glossy flint]

You just need to multiply everything by 8...

You don't always need to cross-multiply

[digital chasm]

Is it 48

[glossy flint]

Nooo.

[digital chasm]

Yeah am cooked

You there

[marsh citrus]

@digital chasm Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dark oxide]

hi

[dark oxide]

guys

help me

is there somone who understand frensh

[serene briar]

oui

[dark oxide]

est ce que

[dark oxide]

tu peut

explique l integral à paramétre

[serene briar]

le parametre il est sur la borne ou dans l’expression a intégrer ?

[dark oxide]

l expresion

att

[serene briar]

envoie l’exercice

[dark oxide]

ok

https://www.bibmath.net/ressources/index.php?action=affiche&quoi=bde/analyse/integration/foncdefintegrales&type=fexo

si ca

[serene briar]

lequel

[dark oxide]

entrer

à se liebn

le premier

exercice

[serene briar]

tu comprends pas quoi

[dark oxide]

comment

montrer

la continuité

et bien definie

[serene briar]

tu connais le théorème de continue des intégrales à paramètres ?

[dark oxide]

non

si qui

where are u

[serene briar]

bah si tu le connais pas pk tu veux essayer de faire des exercices dessus

[floral prairie]

grosso modo une intégrale à paramètre c'est quand tu intègres une fonction (intégrable) F(x,t) à deux variables sur une des deux variables, par exemple tu intègres F(x,t) sur t, et tu voudrais voir comment varie l'intégrale en fonction de l'autre variable, ici x

Tu as des théorèmes de dominations etc. qui te permettent de déduire rapidement qu'une telle intégrale varie continuement en fonction de x

Mais si tu es pas à l'aise avec les intégrales, c'est peut-être pas à ton niveau, parce que tu as de nombreux théorèmes que tu dois savoir utiliser etc. Genre c'est quoi ton objectif @dark oxide ?

[serene briar]

le vent qu’il te met 😭😭

[floral prairie]

bruh

[serene briar]

grosse force

[floral prairie]

toi t'as des questions? XDDD

[serene briar]

nn ça va j’suis la pr aider mdr

[floral prairie]

bruh je me suis motivé et tout pour une fois bah

bonne chance également à toi XDDDDD

[serene briar]

le giga pavé pour pas avoir de réponse

dur la vie

[floral prairie]

en vrai après avoir bouffé ça en agreg, crois moi je le recite en dormant ce truc XDDD

[serene briar]

carrément t’as l’agreg toi

[floral prairie]

oue

[serene briar]

scuse nous

[floral prairie]

en vrai c'est pas un concours dur genre ca montre juste si tu connais bien ton cours

[serene briar]

MDR mais pardon terence tao

[floral prairie]

nan mais ptdr c'est l'agreg chill

[serene briar]

c’est pas chill les développements

[floral prairie]

blague à part je comptais aider énorméemnt de gens en maths ou autre cette année parce que j'aurais bcp de temps donc hésite pas aussi eh

même pour des trucs que je sais pas on peut y reflechir ensemble etc

[serene briar]

ayi j’suis pas encore chercheur chef 😭

qu’en L2 pr l’instant

[floral prairie]

ça dépend, genre y a des dév qui sont vraiment très durs, genre c'est pas "difficile" c'est surtout qu'il faut vraiment le présenter en speed parce que t'es chronométré, puis t'as des dév qui sont vraiment plus simples typiquement tu pourrais les faire en L2

[serene briar]

Z/pZ cyclique mdr

[floral prairie]

et genre si tu presentes un truc trop dur, les questions que le jury va te poser bah ca va etre hardcore

donc t niké

[floral prairie]

nah ça c'est limite pas dans les questions

par contre

[serene briar]

si jcrois

[floral prairie]

tu peux avoir que le groupe multiplicatif de Fp est cyclique

ça ça tombe

[floral prairie]

jsp c'est quasiment par definition

[serene briar]

bah faut le montrer mdr

[floral prairie]

tous les elements sauf 0 sont générateurs

[serene briar]

preuve ou fake

ah att tiens

l’exercice 6

pour toi l’ordre il compte ?

[marsh citrus]

@dark oxide Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rocky lark]

[
\begin{bmatrix}
1 & 0 & 0 \
2 & 2 & 3 \
-1 & 0 & 2
\end{bmatrix}
]

[elfin berry]

Task Bot

[rocky lark]

I found the diagonalizing matrix P but I don't know if I did it right

I found the eigenvalues ​​$\lambda_{1}=1,\lambda_{2,3}=2$

[elfin berry]

Task Bot
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[rocky lark]

So $\lambda_1$ has arithmetic multiplicity 1 while $\lambda_{2,3}$ has algebraic multiplicity 2

[elfin berry]

Task Bot

[rocky lark]

So since I got 3 distinct eigenvalues ​​I can't say that it is diagonalizable for now

So I went to calculate the geometric multiplicities

And I found that $m_{g}(1)=1$ , so it coincides with the arithmetic one , and also $m_{g}(2)=2$ which corresponds to the arithmetic one

[elfin berry]

Task Bot

[serene briar]

Did you find the 2 eigen space?

[rocky lark]

Yes

[serene briar]

oh its their dimension ?

[rocky lark]

Yes

The dimension would be their geometric multiplicities

In more detail I found that $\vect{V_1={(t,-5t,t)}}$, \vect{V_2={(0,t,s)}}$

Where t and s are parameters

[serene briar]

Write it with « vect » I think it would be better to show the bases

[elfin berry]

Task Bot
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[lucid zenith]

that doesn't look right

[rocky lark]

😦

[lucid zenith]

,w [1, 0, 0
2, 2, 3
-1, 0, 2] * [0
0
1]

[elfin berry]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by kheer257

[lucid zenith]

dude.

[rocky lark]

$\mathbf{V_1} = (t, -5t, t), \quad \mathbf{V_2} = (0, t, s)$

[elfin berry]

Task Bot

[serene briar]

yeah it’s not good

[rocky lark]

Mmm

[lucid zenith]

(0, 0, 1) is not an eigenvector

[rocky lark]

[
\begin{bmatrix}
0 & 0 & 0 \
2 & 1 & 3 \
-1 & 0 & 1
\end{bmatrix}
]

[elfin berry]

Task Bot

[rocky lark]

From here I got V1

Of course I found the ker

This one had rank 2

[serene briar]

for the eigenspace associated with $\lambda=1$, Either $X=(x,y,z)^T$ try to solve $(A-I_3)X=0$ for $x,y,z \in \mathbb{R}$

[elfin berry]

ss

jandro0103

[rocky lark]

Here the rank is 1

So 3 - 1 -> 2 free parameters

[elfin berry]

jandro0103

jandro0103

ss

[wide citrus]

yes

[rocky lark]

Mmm

But if I choose the H= -1

The one on the top left

[wide citrus]

and $\rho(A) = 1$ so 3 - 1 = 2

[elfin berry]

jandro0103

[wide citrus]

2 free variables

[rocky lark]

I don't get x=0,y=t,z=s????

Can't I delete two equations from the system?

[wide citrus]

<@&286206848099549185>

help

[rocky lark]

<@&286206848099549185>

[main idol]

where even is the question

[rocky lark]

I need to find the diagonalizing matrix P

[main idol]

and where's your work

[rocky lark]

Above

[wide citrus]

we are working together btw

[rocky lark]

I can also take a photo but I don't know when it is clear

[main idol]

work to get this

how'd you get those eigenvalues

[rocky lark]

$det(A-\lambda I)$

[elfin berry]

Task Bot

[wide citrus]

take a photo

[main idol]

and where are your eigenvectors

[serene briar]

V1 is correct

[main idol]

how did you get these

[serene briar]

it’s not diagonalizable

[wide citrus]

(sending ...)

[main idol]

are the algebraic multiplicties equal to the geometric multiplicities?

[serene briar]

no

[wide citrus]

yes

[serene briar]

V2=vect(0,0,0)

[main idol]

then yea it's not diagonalizable

[serene briar]

no..

[wide citrus]

it is

explain why

[main idol]

it is what?

what it is "it" in your sentence

[serene briar]

V2=vect(0,1,0) mb

But it’s still not diagonalizable

[rocky lark]

What did I do wrong pls

[serene briar]

the eigenspace dimension associated with 2 is 1

and his multiplicity is 2

[wide citrus]

why the matrix is not diagonalizable

[rocky lark]

I got rank 1

So

I did

dimV_2=3-1=2

[wide citrus]

Since the rank is 1 I have two free variables which are those not present in the chosen minor, in this case I took the minor -1 at the top left

So I have the system x=0, y=t, z=s

[rocky lark]

And therefore they are the same

[main idol]

https://people.math.harvard.edu/~knill/teaching/math22b2019/handouts/lecture16.pdf

[wide citrus]

yes

m_a = m_g

we got 2 = 2

so it is diagonalizable

[serene briar]

no we have 1 bro

[wide citrus]

Since the rank is 1 I have two free variables which are those not present in the chosen minor, in this case I took the minor -1 at the top left

So I have the system x=0, y=t, z=s

[rocky lark]

But the rank is not 2

[wide citrus]

^

indeed

[serene briar]

V2=vect(0,1,0)

x=z=0

[wide citrus]

yes

[elfin berry]

jandro0103

[serene briar]

so dim=1…

[rocky lark]

No

[wide citrus]

x = 0 , 2x + 3z = 0

[serene briar]

yessssss

[rocky lark]

But

[serene briar]

3z=-2x=0 omg

[wide citrus]

the rank is 1 yes ?

[serene briar]

we only have y

yesssss

[wide citrus]

3 - 1 = 2

[serene briar]

with multiplicity of 2

[wide citrus]

so 2 = 2

ma = mg

[serene briar]

that’s crazy bro

i know how to calculate

[serene briar]

You can use this only if the eigenspaces are in direct sum

but they aren’t

we calculated it and it is vect(0,1,0)

[serene briar]

his dimension is 1

it would be 2 if A was diagonalizable

[rocky lark]

Why was I wrong?

[serene briar]

i don’t know but it’s not diagonalizable

[serene briar]

It is a characterization of diagonalization

[rocky lark]

I wrote that the rank was 1, however, perhaps isn't and I don't know why

[serene briar]

for $X=(x,y,z)^T$, find x,y,z such that $(A-2I_3)X=0$

[elfin berry]

ss

[rocky lark]

Wait

But

[
\begin{bmatrix}
-1 & 0 & 0 \
2 & 0 & 3 \
-1 & 0 & 0
\end{bmatrix}
]

[elfin berry]

Task Bot

[serene briar]

yeah it’s that, now multiply by the matrix X

[rocky lark]

[
\begin{bmatrix}
-1 & 0 \
2 & 3
\end{bmatrix}
]

[elfin berry]

Task Bot

[rocky lark]

Can I consider this minor?

Here the rank is 2

[serene briar]

No, you would lose the y

[serene briar]

do it with this one

[rocky lark]

The first two rows are clearly linearly independent; in terms of minors you can look at the minor formed by rows 1,2 and columns 1,3. In the solution it is written because the rank of this matrix is ​​2

[serene briar]

you’ll lose the 2nd variable

the 3rd *

you solved it ?

[rocky lark]

No

[serene briar]

okay

[rocky lark]

But I'm trying to find the rank

[
\begin{bmatrix}
-1 & 0 & 0 \
2 & 0 & 3 \
-1 & 0 & 0
\end{bmatrix}
]

[elfin berry]

Task Bot

[rocky lark]

Of this

[serene briar]

just solve this and you’ll have the dimension of the eigenspace associated with 2

and if it’s not 2, it is not diagonalizable

[rocky lark]

But the thing I don't understand is why the rank is 2

[serene briar]

even chatgpt says it’s not diagonalizable 😭

[rocky lark]

Indeed

[serene briar]

idk it’s maybe not possible to do this method in this case

[rocky lark]

Mmm

[serene briar]

oh

i’m dumb

rg(A-2I_3)+Ker(A-2I_3)=3

so such that rg is 2, the eigenspace dimension associated with 2 is 1

which is Ker(A-2I_3)

[serene briar]

By the rank theorem

it’s good for you?

[marsh citrus]

@rocky lark Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[karmic plume]

Guys I want to be good at typing math symbols in Discord or Stackoverflow. what's the most popular and common thing called? Is it Latex?

[wheat rover]

you can use alt codes for some small symbols, but most of the times latex gonna help

so yeah if you know some basic latex commands that's gonna help ya

[severe owl]

Watch the yt vid on Latex by freecodecamp

[main idol]

read the resources in #latex-help and #latex-testing

[marsh citrus]

@karmic plume Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vivid parrot]

I have some sequence derived from test these are pretty hard and i wonder how i can tackle them:

These are the sequences in question missing is "?",

16 ,8 ,? ,110 ,-935
6 ,33 ,? ,45 ,46
1 ,40 ,? ,1000 , 625
4 , 2, ? ,-2 , 14

These sequences dont make much sense any way to tackle them?

[late geode]

values seem to random

[vivid parrot]

Right, yet there should be a answer according to this test..

I have broken my head over them, cant figure it out for my life

[late geode]

what class is this from

[vivid parrot]

No class, its an online assessment for a job position, its category is sequence solutions.

I thought I am just stupid, but if math genius levels dont see the answer then atleast i know i am not that stupid i guess

[late geode]

we can't assist with those

.close

[marsh citrus]

Channel closed

Closed by @late geode

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[woven condor]

Difference between bar chart and histograph?
can anyone show in image the example?

[fleet dagger]

guys dont show her anything shes rude and she thinks we r working for her bye

[summer grove]

left is a histogram, right is a bar chart

[woven condor]

Can you shit post in another channel?

[fleet dagger]

girl dont help her she lit said that u dont deserve anything just bc i told her to say can you not (show me an example)

[woven condor]

a bar chart don´t always have multiple bars on one catogory (year this example)

[summer grove]

all histograms are bar charts, but not all bar charts are histograms

[woven condor]

the only difference is the SPACE?

[summer grove]

just like both your thumbs are fingers, but not all your fingers are thumbs

make sense?

[summer grove]

no

bar charts are a whole range of graphs

a histogram is just a specific type of bar chart

[ancient copper]

not necessarily

you could interpret a histogram as a more “continuous” representation

[woven condor]

This is my data for histograph

[ancient copper]

but yeah, a histogram, as said before, is a type of bar chart

[woven condor]

is THIS histograph? @summer grove

[ancient copper]

yeah, see how the intervals fit with each other?

[summer grove]

yes

[ancient copper]

*histogram, yes

[woven condor]

isnt each bar supposed to be the range, like

0-4 and the bar up to 11

[summer grove]

wdym?

thats what its doing

[regal coral]

It seems the x labels are placed between the bars

[summer grove]

theyre divided into bins

0-4 bin

5-9 bin

[regal coral]

So I guess that signifies ranges

[summer grove]

etc

[woven condor]

@summer grove

@summer grove

[summer grove]

!noping

[marsh citrus]

Please do not ping individual helpers unprompted.

[ancient copper]

context?

[regal coral]

Seems right

I think the first bin goes all the way up to 4.99

[ancient copper]

methinks

the intervals are different?

[ancient copper]

the graph doesn’t necessarily match with the table “space”-wise

[regal coral]

Oh I see, the graph was made from the table

[ancient copper]

your graph implies that the end interval is closer than it actually is

[regal coral]

Huh?

[woven condor]

@regal coral @ancient copper @summer grove would this be histograph Y/N

[summer grove]

it already is a histogram

???

wdym

[woven condor]

if i mark X axis like this.

BONK.

....

bonk is the sound when people are in bed

😆

[summer grove]

ok

do you want help or not?

[ancient copper]

what the fuck

[ancient copper]

didn’t u ask this question 5 minutes ago

[regal coral]

seems right

actually the first one was fine

[regal coral]

this one

[woven condor]

DUDE.

but these dont have RANGES.

[regal coral]

that's how they look on wikipedia

[summer grove]

wdym?

it does

[woven condor]

this is for example like this

omggsmgs,mdgmsgmsdgjsdgjsjdgjgdsjsdgjhgskhsihugaihusgoqwglqiughqowoihwgheifowifugfoiggfwgoiufgowff

fd

afs

d

ads

asdf

adsf

adfs

dsa

dsf

[summer grove]

this is also a histogram

[woven condor]

what do THE X AXIS NUMBER INDICATE ON THIS ONE?

[regal coral]

so like the first bin would be 0.5 to 1

then 1 to 1.5

because in between 1 and 2 must be 1.5

they all have width 0.5

[woven condor]

do a table for this histograph

i think im talking to ai...

[ancient copper]

no.

i think it’s better not to shitpost and go mentally insane and focus on he question instead

cause, you know, that’s what you asked help for

[ancient copper]

it’s just like you did earlier

[woven condor]

im like studying icelandic rn in the meantime

[ancient copper]

label the endpoints of the bins and approximate the height of the bins

[ancient copper]

so...focus on this, or no?

[summer grove]

!nogpt

[marsh citrus]

Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).

[woven condor]

ok ill talk about this tomorrow.

[summer grove]

!volunteers

[marsh citrus]

Helpers are just people volunteering their time to help you. Be polite and patient.

[woven condor]

.close

[marsh citrus]

Channel closed

Closed by @woven condor

Use .reopen if this was a mistake.

[summer grove]

very important!!!!

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

I will ask again here

[marsh citrus]

Please don't occupy multiple help channels.

[still temple]

no one answered my previous question

[main idol]

close one of your channels

[summer grove]

but you havent even asked your qurstion

[marsh citrus]

@still temple Has your question been resolved?

[rotund pike]

They asked in #help-13.

They wanted to see if their answers were correct.

[still temple]

I chose b, is it correct?

[rotund pike]

You have to close one of the channels you have, because you can't have the same question on two open channels, because that can lead to people not seeing whether you're being helped in the other channel and a duplication of effort.

[rotund pike]

OK, B says that 2 is a prerequisite of 11.

Why do you think that's the case?

[still temple]

wait so im wrong?

[rotund pike]

Maybe.

I'm asking questions to see why you chose B.

[still temple]

Honestly just a educated guess

[rotund pike]

OK, but look at the description they gave. Can you find where they said that 2 is a prerequisite of 11?

[still temple]

I cant

[rotund pike]

OK, so B can't be the answer.

That's one way to work through the problem.

The other way is to draw the graph yourself and see which answer matches yours.

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[still temple]

ok

Can I ask one more question, see if its right?

[rotund pike]

Sure.

.reopen

[marsh citrus]

✅

[still temple]

I chose C

[rotund pike]

OK, what is a bridge?

[still temple]

I forgot

it connects two vertices

i think

[rotund pike]

That's an edge.

A bridge is a special kind of edge.

A bridge is an edge where, if you delete it, the number of graph components increases.

Does that make sense?

[still temple]

yes

[rotund pike]

OK, let's look at C.

How many components do we start with?

[still temple]

not sure

[rotund pike]

OK. What's a component?

[still temple]

?

not sure

[rotund pike]

Well, think of a map with roads on it.

You have cities and roads that connect them.

A component of that would be a bunch of cities where you can use the roads to get from one of the cities in that component to any other city in that component.

If you have two cities and there's no way to take some roads from one to another, they're not in the same component.

Does that make sense?

Like the cities in Hawaii wouldn't be in the same component as the continental United States.

[still temple]

ok

[rotund pike]

Not only that, but the cities on different islands of Hawaii wouldn't be in the same component as each other.

[still temple]

Hey man I will stop asking questions, just tell me if my answer is correct

[rotund pike]

Sorry, it's not.

[still temple]

ok bte

[marsh citrus]

@torn sinew Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[magic heron]

Currently learning about logs and its rules/laws. I'm curious if there was anything special about multiplying 2 logs, like the same way you can simplify 2 logs being added together/subtracted.

I concluded there wasn't much to take away from it

[proud basin]

dont think so

[blazing pulsar]

You have that alog(b) = log(b^a), so if a is a log and b is the appropriate base, there is some cancellation.

[magic heron]

I'm assuming you're referring to the end of my second line, which should cancel out to 12log_2(2) = 12

[magic heron]

ahh I see, thanks

.close

[marsh citrus]

Channel closed

Closed by @magic heron

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[true leaf]

need help with 15-26

[marsh citrus]

@true leaf Has your question been resolved?

[marsh citrus]

@true leaf Has your question been resolved?

[marsh citrus]

@true leaf Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[carmine rivet]

Review of Calc 1 in Calc 2,
What did I miss in my work, my final answer ended up being wrong

[proud ice]

$\cos 0\ne 0$

[elfin berry]

SWR

[limpid pond]

cos(0) is not 0 nor e^0

[carmine rivet]

oh lmao thanks

yep
9e^pi/2 - 15

got it right

.close

[marsh citrus]

Channel closed

Closed by @carmine rivet

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[merry hinge]

the answer is 1007^2

but how

[marsh citrus]

@merry hinge Has your question been resolved?

[severe owl]

2012 = 2¹⁰+2⁹+2⁸+2⁷+2⁶+2⁴+2³+2²

[merry hinge]

but

thats just one solution

[severe owl]

This gives you the starting point to find other solutions

[merry hinge]

i did sum of 1+1+2+4+...1024=2048

for 2012 i need to remove 36 from this

[merry hinge]

ngl im really lost here

[severe owl]

2¹⁰ = 2⁹+2⁹

2⁸ = 2⁷+2⁷

Like that

[merry hinge]

i understand this but... do you not think thats a lot of manual work?

[severe owl]

Idk wth i typed !

[severe owl]

See the edited text

[severe owl]

There may be a simpler way !

[merry hinge]

yeah it was wrong but i understood that

[merry hinge]

ikik

[severe owl]

We have restrictions like

There are 3, 2^x

[merry hinge]

wdym

[severe owl]

We have 3 cards with the same power of 2 right ?

[merry hinge]

yep

3 sets of 2,4,...1024

also any number of cards can be chosen

[severe owl]

I meant if you break 2^10, then we can't introduce any more 2^9

But that's making the sum a lot more complicated!

[merry hinge]

exactly!

i did sum of 1+1+2+4+...1024=2048
for 2012 i need to remove 36 from this

but couldnt get anywhere from here

maybe no. of ways to get 36 from powers of 2 taken any in number

[marsh citrus]

@merry hinge Has your question been resolved?

[merry hinge]

<@&286206848099549185> 😭

[merry hinge]

this was the solution given

but its still unclear

[merry hinge]

@severe owl did you get anywhere?

ive spent 2 hrs on this and have made 0 progress

[marsh citrus]

@merry hinge Has your question been resolved?

[severe owl]

Hey i was busy !

I will try this later ! And will DM you if it gets solved !

[merry hinge]

Cool thanks

.close

[marsh citrus]

Channel closed

Closed by @merry hinge

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[spring tree]

how is $\angle APQ=\angle BCA$ where AQXP is a parallelogram?

[elfin berry]

babario

[serene briar]

what is the condition for $ABCD$, for example, to be a parallelogram?

[elfin berry]

ss

[spring tree]

D is just altitude

ABC is any acute tri

[serene briar]

In terms of distance

[spring tree]

oh and BPX~XQC

[serene briar]

what’s that?

[spring tree]

similar

$\Delta BPX \sim \Delta XQC$

[elfin berry]

babario

[serene briar]

oh ok so in my example , $ABCD$ is a parallelogram $\iff AB=DC$

[elfin berry]

ss

[serene briar]

so for you it’s $AP=QX$

[elfin berry]

ss

[spring tree]

.close

[marsh citrus]

Channel closed

Closed by @spring tree

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dreamy harness]

Can someone help me with this question my math isn’t very good

[proud basin]

your allowed yo use calculators right?

[dreamy harness]

ye

[proud basin]

do you know soh cah toa (or some alternate acronyms)?

[long sundial]

i showed u the way

i hope it is easier to understand 🙂

[dreamy harness]

ty i will work on it

[dreamy harness]

yep i know

[proud basin]

yeah basically this

[dreamy harness]

so pythagoras and trig

[long sundial]

ye

[dreamy harness]

this was so much easier than i thought i was just overthnking

thanks guys for help[

[pliant coral]

yes this easier

wait what

[marsh citrus]

@dreamy harness Has your question been resolved?

[pliant coral]

(I think I did it wrong)

[dreamy harness]

I understand it now

To get AB we need to use 100 x tan41

86.9 cm

[pliant coral]

I got 35.6

nevernevermind my answers wrong

[dreamy harness]

o

DC is 100 x sin32.4

53.6

And BD is just Pythagoras so it’s 100 squares + 86.9 squared

[pliant coral]

yes

[dreamy harness]

Which is square root of 17,551.61

132.5 cm

Is that right?

[pliant coral]

let me check

[dreamy harness]

Ok

[pliant coral]

yes

it's correct

[dreamy harness]

yay we did it

thx

[marsh citrus]

Channel closed

Closed by @dreamy harness

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[onyx venture]

i have no understanding of how to solve this except ik the equations for the area of a sector, the length of an arc, and the cosine and sine rules

otherwise i have absolutely no clue what to do here

the only idea i MIGHT have is to make lines from the left point up and make them touch the places where the two circles meet to find THAT sector area

but otherwise im at a loss

[onyx venture]

but there's an issue here

i dont have the angle in between the two radii (which are going in almost opposite directions)

i assume i can use the cosine rule to find it but even then, how?

oh wait

i understand it now, i need to use the diameter

to make it like a triangle first and then use the angle to find the sector area

oh wait, that doesn't work though

because the two intersections are not completely opposite of each other

can someone help i have no idea what Im doing

[onyx venture]

yeah that's what i was just starting to come up with

that's actually extremely helpful, thanks a lot owen

[marsh citrus]

@onyx venture Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[buoyant jetty]

\textbf{P3.} The carts A and B in the figure are connected by an ideal rope, which passes over a fixed (also ideal) pulley. A force $F = 25$ N pulls cart B parallel to the inclined plane downward. Cart A has a mass of $2$ kg, cart B has a mass of $3$ kg, and all frictional forces are neglected.

\textbf{P3.a.} Calculate the acceleration of the system.

\textbf{P3.b.} Calculate the tension in the rope.

[elfin berry]

938c2cc0dcc05f2b68c4287040cfcf71

[marsh citrus]

@buoyant jetty Has your question been resolved?

[sacred idol]

and where are you stuck?

you almost finished the problem

only step left is to write the force equations for both blocks

[buoyant jetty]

?

[buoyant jetty]

how

[sacred idol]

take cart A

say it moves with acceleration a in the horizontal direction

now the only horizontal force is tension

use Newton's second law to write the relation

F = ma

what would you get then?

[buoyant jetty]

F = 2a

[sacred idol]

here F is T

T = 2a

can you say what acceleration of B is then?

[buoyant jetty]

no

[buoyant jetty]

its inclined

[sacred idol]

wouldn't matter

B moves along with A

both are connected by a taut rope

[buoyant jetty]

wdym Moves along?

[sacred idol]

if I move B by some distance d

A should also move by d

if B has velocity v

A should also have velocity v

same goes for acceleration

this is true for movement of any two particles connected by a tight rope

[buoyant jetty]

hmmkay

seems like hard to understand

what about sum of Forces of B

how do I figure out the tension

[sacred idol]

tension is same everywhere along an ideal rope

so tension force on B is also T

[buoyant jetty]

?

what about the sum of forces in B

in B is tricky because normal is not the same as the weight

[sacred idol]

do you know how to resolve vectors into two?

[buoyant jetty]

into x and y components?

[sacred idol]

somewhat like that

[buoyant jetty]

no

[buoyant jetty]

can i get some tips

[sacred idol]

a vector can be resolved into one along x axis and other along y axis

say the vector makes angle $\theta$ with the x axis

[sacred idol]

then the component along the x axis is $F\cos \theta$ and the component perpendicular to the x axis is $F \sin \theta$

[buoyant jetty]

which vector are we talking about doe

[buoyant jetty]

which vector we talking about doe

[sacred idol]

every force in the diagram you showed is a vector

forces are vectors

[buoyant jetty]

for Wb

how do I find the weight

mass of B is 3

but idk

how do I find the normal of B

F = 25 sin(37)

what about normal weight and tension

[still temple]

weight is a force which is given by mass*acceleration (here acceleration is "acceleration due to gravity" often denoted by "g")

So W_B = M_B * g

[still temple]

You further need to resolve W_B and on resolving you will find that the normal of B will cancel out with a component of W_B ...so you don't have to bother about normal of B

Here we are hence only bothered about the component of W_B along F (or inclined plane)

[buoyant jetty]

how do I find Wb

should I watch a video or no

[still temple]

You should

[still temple]

. this is how you find wb

[buoyant jetty]

Wb = 3a

problem is at an angle

a = g

[still temple]

ya right

[still temple]

yes for that you need to learn resolution of vectors

specifically resolution of vectors on inclined plane

[still temple]

At last on finding resolution of wb...you will get another equation to finally get Tension and Acceleration ....this equation would be given by : T= F + Wb_along_F

[marsh citrus]

@buoyant jetty Has your question been resolved?

[buoyant jetty]

Wb = mg = 3g = 30N

[buoyant jetty]

Wb = hypotenuse

hyp = mg = 3.g

Wbx = mg sin (37)

Wby = mg cos (37)

Soh Cah Toa

Sin(x) = op/hyp
Cos(x) = adj/hyp
Tan(x) = op/adj

Wb = hyp = mg = 3g

sin(37) . hyp = op

hyp = 3g

(3g)sin(37) = op

op = Wbx

Wbx = 3g sin(37)

Wby = 3g cos(37)

T = F + Wb_along_F
T = F + Wbx
T = F + 3g sin(37)

T = 25 + 30sin(37)

,w T = 25 + 30sin(37°)

[elfin berry]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 938c2cc0dcc05f2b68c4287040cfcf71

[buoyant jetty]

T ≈ 43 N

no its not

we need to find the acceleration first

Wbx = 3g sin(37)

Wby = 3g cos(37)

Wbx = 30 sin(37)

Wby = 30 cos(37)

,w 30cos(37)

Wbx = 30 sin(37) ≈ 18N

[elfin berry]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 938c2cc0dcc05f2b68c4287040cfcf71

[buoyant jetty]

Wbx = 30 sin(37) ≈ 18N
Wby = 30 cos(37) ≈ 24N

a_x = a_y because they are connected by a rope

T = 2a

T = 25 + Wbx = 2a

43 = 2a

T = 25 + (3a)sin(37)

T = 2a

2a = 25 + 3a sin(37°)

2a - 3a sin(37°) = 25

a(2 - 3sin(37°)) = 25

a = 25/(2 - 3sin(37°))

,w a = 25/(2 - 3sin(37°))

[elfin berry]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 938c2cc0dcc05f2b68c4287040cfcf71

[buoyant jetty]

,, a = \frac{\sum \text{Forces}}{\sum \text{Mass}}

[elfin berry]

938c2cc0dcc05f2b68c4287040cfcf71

[buoyant jetty]

sum of masses = (3+2) = 5kg

3a = Wbx + 25

3a = 18N + 25N

,calc (18+25)/5

,, a = \frac{18N + 25N}{3kg + 2kg}

[elfin berry]

938c2cc0dcc05f2b68c4287040cfcf71

Result:

8.6

[buoyant jetty]

because they are connected by a rope

they have same acceleration

in this case sum of forces in x

in this case the free body diagram of B

indicates that the force F = 25N pulling the body B downhill is in the x axis

we are given Wb = 3 x g = 30 N

but we need to find Wb x axis component

Wbx = 30 sin (37°)

,w 30 sin(37°)

[elfin berry]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 938c2cc0dcc05f2b68c4287040cfcf71

[buoyant jetty]

Wbx ≈ 18 N

[buoyant jetty]

like T ≈ a . 2 ≈ (8.6).2

,w (8.6)*2

[elfin berry]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 938c2cc0dcc05f2b68c4287040cfcf71

[buoyant jetty]

T ≈ 17.2 N

a ≈ 8.6 m/s^2

fnet in x

Wbx + 25N - T = Mb . a

T = M_A . a

Wbx + 25N -(M_A . a) = M_B . a

Wbx + 25N = (M_B . a) + (M_A . a)
Wbx + 25N = a(M_B + M_A)

(Wbx + 25N)/(M_B + M_A) = a

I think I got it broo

I like physics I like it

I am liking it bro

.solved

[marsh citrus]

Channel closed

Closed by @buoyant jetty

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ripe sun]

Hi

[ripe sun]

x^2 -4x =10

How do I even begin

<@&286206848099549185>

[slow sand]

do u know how to factorise

[main idol]

!15m

[marsh citrus]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[ripe sun]

Oh sorry

[ripe sun]

Idk

Prolly

[limber hearth]

Do you know completing the square ?

[ripe sun]

No

That’s what we’re supposed to do

[vernal mantle]

Oh nvm

[slow sand]

what does the question ask for?

[ripe sun]

Target 2: Complete the Square

[main idol]

,tex .cts

[vernal mantle]

I read the 10 as a 0

[elfin berry]

riemann

[ripe sun]

Bro what

Holy shit im failing

[main idol]

x^2 -4x - 10 = x^2 + bx + c

[main idol]

identify b and c. the bottom two equations tell you what to add to complete the square

[vernal mantle]

Have you seen the graphical explanation before

[ripe sun]

No

Can we go step by step pls

[vernal mantle]

https://youtu.be/T0HyWIFbsHQ?si=-2pJ3POrRGr9NrVs

[ripe sun]

Lemme watch dat

[marsh citrus]

@ripe sun Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dawn grotto]

When are you allowed to switch integral and sums?

[dawn grotto]

as in their places?

As in something like this

[summer grove]

im pretty sure the conditions are quite complex, but most of the time (esp when working in some type of real world applications) you can swap them

[spark otter]

If all f_n are non-negative no problem

[dawn grotto]

Yeah but why?

[static quarry]

there are several sufficient conditions depending on whether this is riemann or lebesgue integration

[spark otter]

because you can prove it

[summer grove]

ah wait, this is real analysis right?

[dawn grotto]

How do I prove that?

[spark otter]

this is lebesgue integration i think

[static quarry]

look up monotone convergence theorem

[spark otter]

yeah it's monotone convergence theorem

[static quarry]

for functions that are not necessarily positive, the dominated convergence theorem is the usual tool

[spark otter]

otherwise you would require $\sum_n \int_\Omega |f_n|d\mu < \infty$ or $\int_\Omega \sum_n |f_n|d\mu < \infty$

[elfin berry]

rafilou is not not born in 2003