help-33

[proud basin]

hm @"zandaman_4alt_08451"

[wary kite]

way too many 12 year olds come here and think it’s funny to ask what they believe to be a "super hard math question" so they just spam numbers and arithmetic symbols

[jovial osprey]

ok its probably a troll

[quaint valley]

Sounds like diamond to me

[wary kite]

just the older version

[proud ice]

Let's all take a minute to remember best practices: when in doubt, ping <@&268886789983436800> and let them sort it out.

[quaint valley]

Fr 💀

[jovial osprey]

ella got a crush on me or some shit

im catching strays for no reason

[quaint valley]

Only one could hope

blocked message

[wary kite]

why are you reading blocked messages

[jovial osprey]

shes obsessed im blocked and she reads every message i send anyway

[quaint valley]

Someone really wants the biscuit now

[jovial osprey]

😭

[quaint valley]

I can’t help myself and I jsut wanted to know if it was diamond or someone else I didn’t think it was diamond to be honest

[still temple]

weirdos

[quaint valley]

I’ll remember not to

[proud ice]

!redir

[marsh citrus]

This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.

[quaint valley]

Me yes

Lmao

[quaint hill]

i have no clue whats going on here

[brave bluff]

Good bot

[quaint hill]

but regardless

.close

[marsh citrus]

Channel closed

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[quaint hill]

please get a room

[quaint valley]

Lmao

With knife maybe

[proud ice]

Zander likely troll, then de-rail in an attempt to figure out

[quaint valley]

💀

[quaint hill]

i do not care

please just stop shitposting in help channels

[quaint valley]

Fr

Or the test guy @wary kite 😭

[normal moss]

Why are you still talking here?

[normal moss]

You're muted. You can come back in a day.

[marsh citrus]

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[elder crag]

n-degree polynomials have at most n zeroes and can be derived at n times.

for non-polynomials im thinking taylor series but im not sure this always works

i mean you are assuming f is derivable n times, and we can move the center of the taylor series to be inside the desired interval

but im pretty sure this isnt always true

[rose mica]

if f has k+1 roots in (a,b) then f' has atleast k roots, since between any two consecutive roots of f, there must be a local extreme
and similarly f^(k) must have atleast 1 root

[small stream]

Ooh thanks!

[marsh citrus]

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[pliant hedge]

hellooo. i as of current have an integral cos(1/x)/(x^2) dx. im trying to find the antiderivative right, and im setting u = 1/x, but i just end up with

[pliant hedge]

integral cos(u)u^2 dx

where when i do

du = ln|x|, that helps me not at all

[small berry]

That function does not have a standard antiderivative.

[pliant hedge]

OH WAIT nvm i just figured it out. i was doing du wrong

sorry, sdjf

.close

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[plain falcon]

Thanks!

[formal fern]

uhhh

basically

the diamater is equal to the height

is what im getting

it fits perfectly into a 6x6 inch cube

thus the square cross sections

[plain falcon]

yeah i understand that part its just the top is confusing me

the sides would just be 6 x 6 squares right?

[formal fern]

i think its asking for the sides of the diagram

it looks like it has 4 sides

one of them being a circle on the bottom

and then the other 3 are curved sides

[plain falcon]

yeah im just not sure what the sides look like

[formal fern]

OH

i think the top views a circle

[plain falcon]

with radius 3 right

[formal fern]

yah

[plain falcon]

and then the two sides would be squares?

[formal fern]

they look like upside down parabolas to me

no

one would be a parabola

one would be a square

[plain falcon]

oohhh

wait why is one a parabola?

[formal fern]

because the top is bending downwards

if the two sides were both squares itd just be a cylinder

with height 6 in and raidus 3 in

[plain falcon]

OHHH I C

[formal fern]

🙏🙏

[plain falcon]

how would i calculate the measurements of the parabola tho?

[small berry]

There is a formal way to do that. Wait nevermind no there isnt, youre not given the function.

[formal fern]

essentially you need to find a parabola that intersects (-3, -6), (0, 0) and (3, -6)

i think.

oh wait but its also tilted

so youd need to find

a parabola that goes through (-3, -6arctan(6/3))

I might've messed up there

[plain falcon]

ok wait i dont think i have to write the precise coordinates i just need to know wha t it look s like

[formal fern]

phes

phew

[plain falcon]

so drawing an upside down parabola should be fine right...

[small berry]

shuldn't matter no? you just project and the extrema are what you said before

[formal fern]

thats what i would do

[plain falcon]

okay tysm!

[formal fern]

maybe

[formal fern]

of course 🙏

[plain falcon]

so the top is a circle

one is a square

and one is a upside down parabola

ok i can kinda see it now ngl

[formal fern]

seems like it

good luck 🙏🙏🙏

[plain falcon]

ty!

.close

[marsh citrus]

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[marsh citrus]

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[turbid citrus]

how do you pull the 2/g from the square root? i'm using h/4.9 on mine

[marsh citrus]

Please don't occupy multiple help channels.

@turbid citrus Has your question been resolved?

[marsh citrus]

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[north heath]

can anyone help me? teacher didn't teach us about this

[still dome]

Yo this is a phy question

F=ma

[north heath]

physics

yes

pls teach

i was like absent for a week

[still dome]

Ohh

[worn sluice]

Work Energy Theorem?

[still dome]

So find acceleration first

[north heath]

YUP

WORK ENERGY POWER

[still dome]

Yeah you could do that

F.X = change in ke

[north heath]

how do i find the acceleration?

[still dome]

3504=1/22*v^2

[still dome]

That's a lil lengthy ditch that, work energy theorem gives ans in one line

[north heath]

so i'll have to calcu 350 x 4?

or?

[still dome]

Yup that's the work done by the force

Work energy theorem says net work done on object is change in kinetic energy

So just do that and you'll get it

[north heath]

then what do i do with 1/22?

or is 1/2 and 2

1/2 x 2^2?

then ill divide the 2 to 1400?

or? is it 1/2 x 2= 1

then the answer is 1400?

@still dome

[still dome]

It's sqrt1400

You've calculated v^2

[north heath]

oh so only 1400 the answer?

[north heath]

whats v2 for? @still dome

[still dome]

Didn't get you

[north heath]

OH

V^2 is for the velocity?

or?

@still dome

what's the next step

[still dome]

Yep

[still dome]

Look at my solution if you want

[north heath]

after u get the 1400

u just

suqareroot it?

OHH

I SEE

[marsh citrus]

@north heath Has your question been resolved?

[marsh citrus]

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[gloomy fossil]

hi i need help

[gloomy fossil]

pls

[foggy carbon]

whats that?

exponential form?

[hollow parcel]

what do you need to do

find x, y, z?

[gloomy fossil]

yes

[hollow parcel]

you can sub one of the variables to get first eq in terms of 2 variables

like x=8/yz

in first eq

[gloomy fossil]

what do u get after ?

[hollow parcel]

trial and error

for y and z

[gloomy fossil]

any way without trial and error ?

[frosty stag]

I feel like there’s another way to solve that without making it more complicated

I’m trying to figure it out rn 🫠

[gloomy fossil]

its on the lesson for logarithms

so i think loghs

[hollow parcel]

hmm

let me try with logs

[gloomy fossil]

what did u guys see

[hollow parcel]

doesn't seem like logs help here

atleast imo

[gloomy fossil]

so what would be a sufficient solution then

[hollow parcel]

reduce to two unknowns and trial and error ig

[marsh citrus]

@gloomy fossil Has your question been resolved?

[gloomy fossil]

did u get smth

[silent pewter]

what do i have to find

[gloomy fossil]

x y z

[silent pewter]

answer is 2,2,2?

[marsh citrus]

@gloomy fossil Has your question been resolved?

[marsh citrus]

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[cedar siren]

Hi, ive been doing this really long question about vectors and I fear I might have already gone wrong in the first few parts :/

[cedar siren]

also I have no idea why it is useful to have m and n? I feel like I missed the whole point of part a)

<@&286206848099549185> please help…

[novel juniper]

You need your work checked ?

c=ma+nb just means c is a linear combination of those two vectors

[cedar siren]

Yes please, the next part relies on this and I keep getting wrong answers

[novel juniper]

in other words it lies in the span of a and b

[cedar siren]

Ah okay, does it need to get used again?

[novel juniper]

Just looking at the problems. I don't think so

[cedar siren]

Hm okay, I think I’m overthinking it

[novel juniper]

let me check your work

[cedar siren]

And for the next part I actually don’t know how to do it now…

Previously I had some wrong numbers and the RHS of the equation of the plain was 8 instead of 0

[novel juniper]

well part (a) seems right

[cedar siren]

Thanks

[novel juniper]

for (b) you used the cross product , yes?

[cedar siren]

My problem is actually c) ii) at the moment

[cedar siren]

Yes

[novel juniper]

ah

[novel juniper]

so I don't need to check (b)

[cedar siren]

I don’t think so

[novel juniper]

Well, the plane is normal to the vector

what does that mean

[cedar siren]

which vector?

[novel juniper]

b is normal to the plane

is it not?

[cedar siren]

yes

I kinda just took the direction vector (-6, -3, 3) for that but im not sure

[novel juniper]

why

[cedar siren]

uhh

thats a good point

probably because i though I should use part b) to continue

[novel juniper]

hmm

Honestly, I;m not too sure

sorry

I think there should be two such planes

Well, here's another way to solve it

You know that the equation of such a plane is ax+by+cz+d=0

yes?

use that to your advantage

oh, and the direction ratio of the plane is (a,b,c)

[cedar siren]

Yes.

Sorry I stopped responding, I’ll have to continue working on the problem later, not at home anymore

[marsh citrus]

@cedar siren Has your question been resolved?

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[eager plank]

I need help with the topic of Similitudes and system of circles, I need a little bit of Idea with the concept

[eager plank]

@split elm

Hereee

[split elm]

do you have a specific problem?

specific question to help with

[eager plank]

Well, not exactly

[split elm]

uhhhhh

[eager plank]

I was stumbling on the concept

and didn't seem to understand it

[split elm]

well maybe i know the concept by a different name so i dont really know what you're talking about without an example

[eager plank]

Oh alright

This is like the point of intersection of transverse common tangent and direct common tangent apparetnly

[shy shard]

Is this calc bc stuff I don’t know

[marsh citrus]

@eager plank Has your question been resolved?

[eager plank]

It's geometry

Also Please PING if you're helpingg

thank you

[marsh citrus]

@eager plank Has your question been resolved?

[eager plank]

Alright

.close

[marsh citrus]

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[cerulean crag]

quick question but is the number of biconnected components for this graph is 6? and is the graph DAG?
after analyze the options it appears that cycles exist in the graph (e.g., 𝑎 → 𝑏 → 𝑐 → 𝑎 a→b→c→a) and i think its not but i hope someone can confirm

[marsh citrus]

@cerulean crag Has your question been resolved?

[marsh citrus]

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[gaunt lynx]

did i do anything wrong here

and how do i simplify

<@&286206848099549185>

[onyx reef]

Is the problem that you are trying to differentiate $$\frac{72}{7+5e^{-0.5t}}$$?

[elfin berry]

elliot

[gaunt lynx]

no

its 12/1+5e^-0,5t

[onyx reef]

Okay sure

So you want to compute $12 \frac{d}{dt} \left((1 + 5e^{-0.5t})^{-1} \right)$

[elfin berry]

elliot

[onyx reef]

This is of the form $\frac{d}{dt}\left((f(t))^n\right)$

[elfin berry]

elliot

[onyx reef]

And should be fairly routine to compute in this case

[gaunt lynx]

uhh

my main language isnt english

but in this case we dont do product rule right

no

but

did i do it correct

[onyx reef]

I think it looks okay from what I can see

[gaunt lynx]

now how do i simplify that im rly confused

[onyx reef]

Try first bringing all constants out to the front and collecting

[gaunt lynx]

so -1 * -0,5

and the 12 too?

[onyx reef]

and 5 it looks like?

[gaunt lynx]

but that isnt a constant

its 5e

[onyx reef]

5 is a constant, everything is multiplying so we are allowed to bring it to the front as well

[gaunt lynx]

oh

yeah

wait

[marsh citrus]

@gaunt lynx Has your question been resolved?

[marsh citrus]

@gaunt lynx Has your question been resolved?

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[dapper field]

Can someone explain to me why you multiply both sides by 3/4pi

[twilit geyser]

basically the way I was taught is to find the inverse of y=4/3 pi x^3 you swap x and y to make x = 4/3 pi y^3 and then solve for y

so first step I would take is multiply by 3/(4pi) which is same as dividing by (4pi/3)

since dividing by a fraction is the same as multiplying by the reciprocal, if that helps as a reminder

[dapper field]

but why does pi go with it

thats what im confused on

[rotund violet]

no, there is a pi in that

the pi is just a constant for our purposes here

[dapper field]

So its basically a variable?

[proud ice]

Because we seek to isolate x

[proud ice]

No. Pi is a constant. It is unchaging. It is just some well-defined number like any other numbers such as 1, 2, sqrt(2), e, etc.

[stiff wraith]

.

!noanswer

[marsh citrus]

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

[dapper field]

I meant more as in the function of it

[dapper field]

^

[proud ice]

Where is OP asking for the answer?

[dapper field]

?

[proud ice]

function of what?

[dapper field]

I mean the ways it works in relation the fraction in this equation

[proud ice]

$V=\frac43\pi x^3$

[elfin berry]

SWR

[dapper field]

The volume of a sphere is gen by V(x) = $\frac43\π x^3$

[proud ice]

Think of $\frac43\pi$ all as just one number (since it is, in fact, just one number)

[elfin berry]

Blue
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

SWR

[proud ice]

Don't use π, use \pi

[dapper field]

oh alr

im just trying to learn it

[proud ice]

It takes a while

[dapper field]

but also im an idiot i realized what i was doing wrong

thanks though lol

.close

[marsh citrus]

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[opal vector]

any idea of what i did wrong?

[rotund violet]

law of cosines not law of sines

how do you know angles A and B?

they aren't given in the problem

[opal vector]

i used law of sines to find angle B

and angle A is given (48.3)

[rotund violet]

oh wait never mind i apologize

let me check

[opal vector]

all good 👍

[rotund violet]

um assuming you plugged in sin^(-1) into your calculator this should be right?

[opal vector]

yeah, let me recalculate

i think it might be an issue with rounding precision

[rotund violet]

actually you just need to be more precise in terms of B probably

its almost certainly rounding precision as you need 4 significant digits for the answer but you only have 2 for angle B

[opal vector]

going through the math rn

ok yeah i shouldn't have rounded to 27*

x = 682.8

oh wait i didnt correct angle C

yeah after correcting i got x=682.6885744

so im pretty confused on where my inaccuracy is

rounding x up results in 682.7, no?

[opal vector]

im just going to blame the hw software, thanks for the help

.close

[marsh citrus]

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[slim quartz]

how would i do this

[severe thorn]

calculus 2?

[slim quartz]

1

for revoluating

to find volume

i have this

the height 32-x^2 - x^2

the upper minus the lower

3 to 4 for x = 3 and intersection of the two at 4

but i didnt get the anwser right

so im not sure if i did it correctrly

@severe thorn

[severe thorn]

im more familiar with the washer method

is the shell method radius * height?

[marsh citrus]

@slim quartz Has your question been resolved?

[severe thorn]

if so it would be the integral from 3 to 4 2pi (x)*(32-2x^2) dx

[marsh citrus]

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[soft oar]

Is it possible to solve this

-4 x 5

[cloud iron]

-4 times 5? Yes

[soft oar]

How

[cloud iron]

What have you tried? Any ideas?

[soft oar]

I think it’s -20?

[cloud iron]

It is

[soft oar]

.

Uhhh

[cloud iron]

If it helps, think about it this way. At any time, you can factor a number into some of its factors. Some factors of -4 are -1 and 4 (because -1 times 4 = -4). If you deconstruct the -4 in that way and put that int he expression, you get -1 times 4 times 5

In that context, you can see how 4 times 5 = 20 and then that is mulltiplied by -1

[soft oar]

Oh

Thanks

.close

[marsh citrus]

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[lofty timber]

how do i get to 3sinxcos^2x - sin^3x from 2sinxcos^2x + sinx - 2sin^3x

[lofty timber]

the original proof asks for sin3x = 3sinxcos^2x - sin^3x

[iron bolt]

Could I see more of your process to get to 2sinxcos^2x + sinx - 2sin^3x?

[lofty timber]

yeye

dont mind the first two lines

[iron bolt]

Ic

Use a different identity when ur changing cos(2x)

Use cos(2x) = cos^x-sin^x instead

[lofty timber]

okie lets see

oh my god

that was so obvious

😭

ok tysm

🙏

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[rigid shard]

prove that two matrices have equal row spaces iff after gauss jordan reduction they have the same nonzero rows

[marsh citrus]

@rigid shard Has your question been resolved?

[rigid shard]

<@&286206848099549185>

[marsh citrus]

@rigid shard Has your question been resolved?

[devout hill]

have you learned that gauss jordan elimination is equivalent to multiplying by some invertible matrix?

[rigid shard]

no

[devout hill]

umm what have you learned regarding gauss jordan

[rigid shard]

u do things to a matrix to make it look nicer

[devout hill]

can you be a little bit more specific? because Gauss Jordan preserves certain stuff, and I assume you have covered some

[rigid shard]

idk man

i wanna jump i hate this class

[devout hill]

it is a little bit hard to learn the first time, but maybe reviewing some key concepts of Gaussian jordan elimination will help (idk how specifically ur class went for it, so I need some detail)

but the gist is that every step of a elimination can be viewed as a matrix multiplication

[marsh citrus]

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[rigid shard]

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[marsh citrus]

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[pseudo arrow]

confused as to how this integral is being set up

[rotund violet]

outer integral represents when the basic policy will be set

inner integral represents when the delux policy will be set

if the basic policy is set at time x, we need the deluxe policy, represented by variable y, to happen some time before time x

thus we integrate x from 0 to inifinity, while we integrate y from 0 to x

the quantity we are integrating represents the probability of basic happening at time x and delux happening at time y

[pseudo arrow]

why do we multiply the two variables?

[rotund violet]

because probability is multiplicative

the chance of X happening at x is 1/2e^(-x/2)

the chance of Y happening at y is 1/3e^(-y/3)

multiplying these together we get the chance of X and Y happening at x and y respectively are 1/2e^(-x/2)1/3e^(-y/3)=1/6e^(-x/2-y/3)

by chance i mean relative chance

[pseudo arrow]

oh ok I see

at least I think I see

so we're basically looking at every assignment of (x,y) where x > y

and finding the probability of that happening

and adding it to our total

just want to confirm this intuition is correct @rotund violet

[rotund violet]

yes

[pseudo arrow]

kk

thanks

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[still temple]

hi

[still temple]

Un > 3/2 for all n

[still temple]

i need to calculate the limit of this, i got 1.75

is that right?

my method was saying L = L² - (3/4)

idk whats this method called

question said "suppose that the limit exists and calculate it"

[trail hamlet]

is there a base case for U?

[still temple]

U0 > 3/2

[trail hamlet]

if U0 > 3/2, the function goes to infinity

i think it should be U0 < 3/2

[still temple]

well the question said "suppose" that it has a limit

[still temple]

<@&286206848099549185>

[devout mauve]

if you assume that it has a limit, then you can take the limit on both sides and indeed end up with L=L^2-3/4

[still temple]

yeah so... is this true?

is it 1.75 or did i mess smth up

[devout mauve]

,w L=L^2-3/4

[elfin berry]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by denascite

[devout mauve]

you fucked up

[still temple]

lmao its alright

thanks, i didnt know i can use wolfram for this

[devout mauve]

wa can solve all basic equations

[still temple]

good to know, thanks again

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[marsh citrus]

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[novel juniper]

If $sup(A) < inf(B)$ for sets $A,B$, there exists a $ c \in \R$ satisfying $a<c<b$ for all $a\in A$ and $b\in B$
\
Counterexample:$ B:(0,\sqrt{2}] A = (1,1.1)$

[elfin berry]

ƒ(Why am. I here)=I don't Know

[spark otter]

sup(A) >= inf(B) so there's no counterexample

[novel juniper]

what do you mean

oops

bad example

right

[novel juniper]

So there is no counter example

I suppose a proof by counterexample would be the way to go then?

[spark otter]

are you still supposing the statement is false?

[novel juniper]

NO, now I suppose the statement is true

but I;m proving it by contradiction

[spark otter]

then there is no counterexample if the statement is true

i would prove the statement directly

[novel juniper]

hmm

oh

that works

[spark otter]

I can even express such a c in terms of sup A and inf B

[novel juniper]

take the mean of the sup and inf

[spark otter]

yes

[novel juniper]

We chose $c = \frac{\inf{B} + \sup{A}}{2}$

[elfin berry]

ƒ(Why am. I here)=I don't Know

[novel juniper]

We're done

Thanks!

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[somber vault]

am i doing this right?

[somber vault]

wait do I not change the bounds?

just plug in x after I integrate to use the bounds set for in terms of x

[somber vault]

I think you meant to post this on a math help channel

[silent pewter]

Yes

[somber vault]

oh ok

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[fresh wind]

posted but no help yet

[marsh citrus]

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[distant girder]

Solve the task without a digital tool.

Two children and seven adults sit in a cinema. Before the film starts, another amount of people arrive.

Then the relationship becomes 3/4 between the amount of children and the amount of adults.

How many people were added, if there were as many adults as children?

[distant girder]

I don't even know how to set up the equation

Like, how do I separate the previous amount from the following amount?

[onyx reef]

We are saying that children and adults are added by the same amount, so call this x. The initial ratio is 2/7, right?

[distant girder]

Yes

[onyx reef]

What is the new ratio in terms of x?

[distant girder]

(2+x)/(7+x)

[onyx reef]

Exactly

[distant girder]

is it (2+x)/(7+x)=3x/4?

[onyx reef]

I don’t think you need the x on the right, you just want it to be 3/4

[distant girder]

Why is that?

Why do we put 3/4 on the right side?

[onyx reef]

It’s saying we want 3/4 to be the ratio of children/adults when we add them in

[distant girder]

Ooh, right

Thanks for your help

And have a good day!

.close

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[distant girder]

A group of bacteria increases all the time by the same percentage.

Write an equation for how many bacterias we have after x hours if they increased 100 times in the first 8 hours.

[distant girder]

Wait, I think I know how to solve this.

First, we need to find out how much it increases per hour.
$x^8=100$

[elfin berry]

Elliot Pixel

[winged pier]

What does that equation represent

[distant girder]

$x=\pm \sqrt[8]{100}$

[elfin berry]

Elliot Pixel

[distant girder]

The factor of change per hour

[winged pier]

Hmmm

[distant girder]

We can eliminate the +-.
$x^{\sqrt[8]{100}}$

[elfin berry]

Elliot Pixel

[winged pier]

Yes

Oops

[distant girder]

wait noo

$\sqrt[8]{100}^{x}$

[elfin berry]

Elliot Pixel

[distant girder]

Okay, nice. I actually solved it.

[winged pier]

What is the starting amount of the bacteria

[distant girder]

No value

[winged pier]

Real

[distant girder]

Which is the same as

$\sqrt[4]{10}^{x}$

[elfin berry]

Elliot Pixel

[distant girder]

Damn, that was tricky

Anyway, thanks for your attempt to help lol

Cya

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[slender lichen]

help me, I don't know how to solve it

[vast magnet]

do it from the inside out

[slender lichen]

wait, lemme try

[vast magnet]

start from sqrt81

[slender lichen]

is the result 3?

[vast magnet]

,w 1/3sqrt(9 * sqrt(9 * sqrt(9 * sqrt(81))))

[elfin berry]

Results provided by WolframAlpha

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Requested by shriihan

[slender lichen]

thanks man🙏🏻🙏🏻🙏🏻

🤝🤝🤝

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[upbeat needle]

can someone help me review derivatives in 10 minutes i didnt study the entire semester but i did calc ab and got a 4 two years ago
i have finals in 2 hours

[main idol]

just do problems

help channels are for specific questions

if you have a problem or theorem you want to understand, post it here

[upbeat needle]

can u tell me the topics i look out for also i just cheated my way through the course cause its online and i had chatgpt so i dont rember anything

also i have anoher final and got 1 hr of sleep last nigh cause i was studying for that one so

[main idol]

again, not specific enough to help you

https://tutorial.math.lamar.edu/Classes/CalcI/DerivativeIntro.aspx

try reading that

[upbeat needle]

ok will read in like 1 hour cuz i mtired af

[marsh citrus]

@upbeat needle Has your question been resolved?

[marsh citrus]

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[merry terrace]

Should I start by using the coordinate form of tangent of an ellipse

And use the thing where the equation of tangent of ellipse from the centre of the circle is equal to the radius

Like this ?

Nvm I solved it

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[gusty birch]

how to calculate bandwidth for this graph

[gusty birch]

no graph people here?

[marsh citrus]

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[surreal blade]

hey all! wondering if i can get some help with an odd physics problem?

[surreal blade]

im not seeing how im supposed to get a numerical answer, ill post the problem in just a moment

ok so given this

we're evaluating the energy to bring a -2q charge from infinity to a distance a = 3cm

but when we do this, does it not just result in infinite energy required?

like

[main idol]

show the original question and full work up to this point

[surreal blade]

its written on paper

ill type it

If the electric field within a solid sphere conductor is E = k5qr/a^2, where a is a, k and q are constant and r is the changing variable, calculate:

the electric potential voltage that results from this field and

calculate the energy needed to bring a -2q charge from infinity to a distance a = 3cm, where q = (1*10^-9) C

i know part A is correct

if i have no idea how im supposed to get a numeric answer for part B

unless i’m not supposed to integrate along the bounds and just plug 0.03m into the voltage equation before plugging them into the energy equation?

am i just meant to assume that voltage = 0 at a distance r -> inf? thats the only logical explanation i can think of

[main idol]

that's a physics question not a math question

since this diverges, you probably made a mistake earlier

[surreal blade]

so you see why im confused right

i dont think im meant to take the integral at all tbh

because the original part A integration is correct

[surreal blade]

xact reason i came here lol thats abt it

[main idol]

#old-network for physics server

[midnight kraken]

is there any physics server?

[surreal blade]

.close

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[rancid crane]

How to find ABC angle?

[midnight kraken]

is that a rectangle?

[rancid crane]

Omfg

In quadrilateral ABCD, sides AB, CD, and DA are equal in length, and angle BCD measures 131°. The diagonal AC divides the quadrilateral into an equilateral triangle and an isosceles triangle (see the diagram).

Assess the truth of the given sentences. Select T if the sentence is true or F if it is false.

The angle ABC measures 60°.
T
F

[midnight kraken]

oy can you help me to slove this problem?

if A:B=3:4 and B:C=2:3 then what is the answer ofA:B:C.

[rancid crane]

360 - 131 - 131

It has 98°

The angle DAB is 98°.

P
F

<@&286206848099549185>

[neat granite]

R u in grade 9th ?

[midnight kraken]

i don't think so

[vagrant cosmos]

she said no

[rancid crane]

R u in 2nd?

[neat granite]

No girl I’m in nursery 😭

[rancid crane]

And ur failing that

[main idol]

neither angle B nor D is greater than 90 degrees

[neat granite]

I love ur he she we vibes

[rancid crane]

what

[main idol]

The diagonal AC divides the quadrilateral into an equilateral triangle
do you know what the vertices of the equilateral triangle are?

[rancid crane]

60 degrees

I know it dog

[main idol]

that gives you angle D

[rancid crane]

Okay then

Dawg

.cllse

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[rancid crane]

@neat granite and you don’t act smart

Boywoman

[still temple]

is the diagram to scale ?

[neat granite]

Girl stfu u thought u ate that

[still temple]

oh mb didnt see riemann answering

[marsh citrus]

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[hallow pier]

In order to find the area of this, can I just use absolute value?

[still temple]

yes.. you gotta split it up and use absulute values

[marsh citrus]

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[fickle rover]

what does the highlighted part mean

[fickle rover]

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[versed hinge]

My y outputs are wrong. How do i find the correct y outputs if those are the x inputs?

[late geode]

you're not taking the absolute value

you're treating this as though you had
y = 2(x-1)

[marsh citrus]

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[versed hinge]

.reopen

[marsh citrus]

✅

[versed hinge]

right. so how do i do it?

[late geode]

take the absolute value

[versed hinge]

which is x-1

[late geode]

|x-1| isn't the same as x-1

[versed hinge]

may you pls explain the difference

ik what x-1 is but its the |x-1|

what does the 2 things at the side mean

rules for it?

[late geode]

look up absolute value

[versed hinge]

non-negative value of x

so that means all my inputs should be positive

what abt the 2 in the equation?

[late geode]

what resource are you looking at

[late geode]

input can be negative,
outut will be positive or 0

$|\text{this}| = \begin{cases} \text{this}\ &\text{if } \text{this} > 0 \
-\text{this} \ &\text{if\ } \text{this}\leq 0 \end{cases}$

[elfin berry]

ℝαμOmeganato5

[late geode]

applying the above
|-5| = -(-5) = 5

whether |x-1| is (x-1) or -(x-1) depends on the sign of x-1

for simplicity, you can first plug in the value, then simplify the abs value of the number you get

the 2 on the outside is just being multiplied

[versed hinge]

if y=|0-1| then y=1 ?

[late geode]

yes

[versed hinge]

but i do not get when y=2|-1-1|

i got 4

oh hold up

its right im sure

✅ or ❌

[next ravine]

y = 2 |-1 -1| = 2 |-2| = 2 * 2 = 4

[versed hinge]

yes thank you both

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[humble lichen]

Hey yall, I'm working on an integer programming problem where I have a bunch of restraints and I'm trying to figure out how I write done one in which

[humble lichen]

my decision variables Xi are binary so either one or zero and I have a specific condition that's saying if X2 is 1, then X19 is also 1 and I'm not sure how to turn that into an actual condition

I'm thinking that X2 + X19 must be either 0 or 2 but struggling to figure out how to turn that into a condition in an integer program

nvm it just struck me, I can just have a condition where they're equal to each other

.close

[marsh citrus]

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[still temple]

anyone have any gud math book for calculus?

[still temple]

early college? highschool?

highschool

i think its better to ask in #book-recommendations

oh okk

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[ruby torrent]

Guys how many cm in one foot cuz some sources say 30.48 and some say 25

[latent coral]

i don't know why sources would differ when there's just an objectively correct answer

there's exactly 2.54 cm in an inch, and 12 inches in a foot

[ruby torrent]

Yeah i was looking at my height and apparently i was either 5.9 or 5.11 and im so confused

[latent coral]

well it's 30.48 cm per foot

[ruby torrent]

im 181cm

[latent coral]

181 / 30.48 is 5.938 ft

note that that's not the same as 5'9

[marsh citrus]

@ruby torrent Has your question been resolved?

[quaint valley]

2.54 cm is equal to 1 inch

$12(\frac{2.54}{1})$

[elfin berry]

ℰ𝓁𝓁𝒶

[quaint valley]

,calc 12(2.54)

[elfin berry]

Result:

30.48

[quaint valley]

Does that help?

[marsh citrus]

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[lethal bridge]

We found two different answers for the integral $\int_{ }^{ }\sin^{4}\left(\theta\right)\cos^{2}\left(\theta\right)d\theta$.

[elfin berry]

water beam

water beam

[lethal bridge]

i dont know how to start

one of the answers were found using the sine reduction formula and the other with just using half angle identities but i dont know how if im supposed to use that here somehow

[marsh citrus]

@lethal bridge Has your question been resolved?

[marsh citrus]

@lethal bridge Has your question been resolved?

[lethal bridge]

@glass silo catbittttttttttt

[sudden panther]

use double angle first for sin^3(2x)

And double angle again for sin(4x)

[dusky viper]

lock in bro

[marsh citrus]

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[median stag]

How to do this

[hard gull]

find number of 5 digit numbers that is divisible by 3 (which is M)

find number of 5digit number that is divisbile by 4 (which will be N) and then find M/N ig

[median stag]

how to do this?

[hard gull]

just consider the numbers which add up to a multiple of 3

like

[median stag]

there are 10^5 numbers

how can u check all

[hard gull]

no like
10248 all add to multiple of 3 so divisible by 3

[median stag]

case 1- 3 is there

Case 2- 3 sing there

isn't

like this

5 digit number case 1- 2,3,4,7,8

case 2- 2,0,4,7,8

?

[hard gull]

yeah that works , but there will be more

let me think something else wait

[median stag]

like

i don't think there will be more since none of them is a factor of 3

if u calculate this u get case 1= 5!= 120

and case 2- 4*4! = 96 ig

[hard gull]

im pretty sure u should get all these

all these would be divisible by 3 , cuz the digits add upo to multiple of 3

[median stag]

oh

how did u find these

by hit and trial?

[hard gull]

Yeah

Guess

[median stag]

any tricks/ shortcuts?

bcz this is too lengthy

[hard gull]

Not really , I can't think of any

[median stag]

oh ok

what about the one for 4?

[hard gull]

Last 2 digits should be divisible by 4

So ig guess those numbers as well xD

[median stag]

oh

this is easier

[hard gull]

Yeah

Good luck

[median stag]

thanks for ur help

.close

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[stiff ledge]

Can someone check if I did this right?

I got radius of circle is 0.27 and side of equilateral triangle is 16.10146 feet

[late geode]

show your work

[stiff ledge]

Ok, handwriting is a bit messy

[late geode]

that shoud be +, not *

[stiff ledge]

Ah I see

Thank you!

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[night sluice]

i know how use long division but still cant understand this

[odd orchid]

well do long division then

[sharp ivy]

after division, you get a simple polynomial with degree 2. Use quadratic formula to find roots of it.

[marsh citrus]

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[vague vale]

i dont get it

is angle at centre

half 126?

i mean double

so 252

degrees but idk what to do after that

[odd orchid]

mo and lk arent parallel though

you can find mqj using angle at the centre theorem

[sharp ivy]

calculate measure of short arcs MJ and LJ from the given angles. calculate arc ML. find angle x.

[vague vale]

bro what

how am i meant to find the lengths

[sharp ivy]

lengths? the arcs have measures. An arc is a portion of the circle.

[vague vale]

yh so its 252

whats a measure

an angle

?

so Moj is 252

how do u work our OJL

angle

[sharp ivy]

maybe you are familiar with a theorem saying...measure of arc NJ is double the measure of the angle NLJ, for example. with that theorem, you can compute the measures of the arcs I mentioned.

[vague vale]

whats a measure tho

like the angle between n and j

[sharp ivy]

'size of the angle'? a measure is expressed in degrees?

You likely studied measure of arcs, if you have this exercise to solve. might need to look over theory again...

oops wrong link

[buoyant pond]

52?

[vague vale]

oh

yh

how tho

[vague vale]

howd u get 160-x

for JOL

[buoyant pond]

2* angle MNL = angle MOJ

MOL = x so LOJ = 160-x

[vague vale]

uh

i dont get it

but ok

how do i close

[buoyant pond]

let me send a better solution

one sec

[vague vale]

its ok

[buoyant pond]

.close

[vague vale]

ok yh but how is that side 160

because

angles around a point

= 360

so 360- 126x2

108

[buoyant pond]

yeah so LOJ is 108

LOJ reflex is 252 i didnt extend that angle all the way

[vague vale]

ohhhhh

cuz

80 x 2

= 160

ok i get it

thanks

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[buoyant pond]

i mean yeah thtas for MOJ not LOJ

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[echo scaffold]

These are equivalent right?

[void elm]

yes

,, \sqrt{2^3} = (\sqrt{2})^3 = 2^{\frac{3}{2}}

[elfin berry]

higher!

[echo scaffold]

Ok ty it was on a test and I have extra time to finish. I was just second guessing myself. I was also kinda sick so

[void elm]

[echo scaffold]

Even if it was with differnt numbers but that’s some style it would still be equivalent right? So if it was the third root instead

[void elm]

you're writing a test right now?

[echo scaffold]

No I had a test yesterday I get extra time to finish

But I was sick

Not sick

Some mystery tjign

So I’m justifying this

By me being sick

For example o was so dizzy I kept mixing elements of certain problems and mixing them together. I thought one problem and a square root when the problem below had one. And stuff like that

[void elm]

in general, $\sqrt[n]{a^m} = \left(\sqrt[n]{a}\right)^m = a^{\frac{m}{n}}$

[elfin berry]

higher!

[echo scaffold]

Ty!

[mortal obsidian]

Yeah, I like to imagine sqrt(a) just as a^1/2

So if you have sqrt(a^3), it’s just a^3*1/2, which would just be a^3/2

In case your tryna to understand it in terms of logical reasoning

[marsh citrus]

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[marsh citrus]

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[wind sonnet]

Hello does this seem correct so far?

did it again and got that\

something is wrong, please help

.closwe

.close

[marsh citrus]

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[gusty wasp]

can someone explain the last part

where the denomanator gets converted into 3tan(thetat) instead of 3tan^2(theta)

[frosty thicket]

reread the last line of text

[gusty wasp]

omg i read it, im so dumb

thanks

[frosty thicket]

youre welcome

[marsh citrus]

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[tacit elm]

Find all solutions to tan(x)=sec(x) that lie in the domain [0, 2).

I'm studying for midterms and this was one of my practice problems. The answer key said there was no solution but I came up with the solution of pi/2.

[tacit elm]

Can anyone explain why?

open

oops

[odd orchid]

tan pi/2 is undefined

[tacit elm]

Ohhhhh

Damn

Im stupid