#help-33

1 messages · Page 200 of 1

marsh peak
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No

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Now A11 is the same matrix as the original one except with size (n-1)x(n-1)

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So we can define a sequence a_n with the nth element equal to the determinant of such nxn matrix

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You will have a_1 = 1 and a_{n+1} = 2a_n

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A quick induction shows that a_n = 2^{n-1}

drowsy stirrup
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thank you for the help

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marsh citrusBOT
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obtuse lily
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How to calculate CPI?

marsh citrusBOT
devout mauve
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context?

quaint hill
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like... consumer price index?

marsh citrusBOT
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@obtuse lily Has your question been resolved?

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still temple
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I SPENT AGES ON RHIS AND IT SAYS WRONG I CHECKED IT IDK HOW 😭😭

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Probability

sharp ivy
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I'd say you made a mistake when you divided 96 by 12 to calculate x. Did you get 7, or am I mistaken? x isn't 7...

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The mistake happened when you added 24 insted of 12 in that vertical calculations:
12 24 36 (60?) 72 84 96

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Compute again x=96 : 12, then you'll have to repeat the last part, with the correct x...

marsh citrusBOT
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high spoke
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I have another question

Solve the quadratic trigonometric inequality:

2sin²x - 3sinx+1 < 0

tawdry rampart
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!status

marsh citrusBOT
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What step are you on?
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3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
high spoke
tawdry rampart
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i would say let t=sin(x)

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then it will become a normal quadratic eqn

tawdry rampart
high spoke
tawdry rampart
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correct

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so what exactly is your doubt?

high spoke
tawdry rampart
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ohk

high spoke
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Oh and hey, can I close this channel and reopen it for another question? Or I need to ask in the same ticket?

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@tawdry rampart

tawdry rampart
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!1q

marsh citrusBOT
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It is suggested that you limit yourself to one question per help channel, opening a new one once your original question is answered and your original channel has been closed. This is to make your channel easier to follow for potential helpers and can bring attention to the fact that your question has changed.

tawdry rampart
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you should close this one

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you can reopen this itself or open a new one

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i recommend opening a new one

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!done

marsh citrusBOT
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If you are done with this channel, please mark your problem as solved by typing .close

tawdry rampart
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this is how you close

high spoke
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K

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Thank you

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sinful hinge
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hi! i might just be getting rusty on integration but can anyone tell me why there's a 1 in calculating the area of D?

marsh citrusBOT
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torpid drum
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Hi I need some help, I don't understand how to solve the right equation? e^-4t(t^2 - 9)U(t+3)

torpid drum
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Im not sure how to change the t^2-9 into the form (t-a)u(t-a) as well as how to deal with the e^-4t

marsh citrusBOT
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@torpid drum Has your question been resolved?

torpid drum
main idol
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,w factor t^2-9

main idol
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Yes

torpid drum
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ah so then u replace the (t+3) with t and then use the first shifting theoreom to solve?

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is that right

torpid drum
main idol
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I cannot tell what you're doing

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Where did line 3 come from

main idol
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Why did you replace t+3 with t only in one place

torpid drum
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because the unit step function is u(t+3) right, so u replace the t+3 and leave the t-3, i think at least im not sure

main idol
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Then where did your step function go on line 3

torpid drum
main idol
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Again I don't know why you're selectively changing some t+3 to t

torpid drum
# main idol And not shifting the t in step function

sorry im not very good at this topic, from what i understand the 2nd shifting theorem like if there is the t-a with the unit step function same t-a it will become to t, the first shifting theorom i can understand its just im not sure how to handle when its both at once

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i just really need help to understand how this 2nd shifting theorem works and also how it works in this case with the e^-4t shift as well

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<@&286206848099549185>

torpid drum
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@main idol is this correct? i think the e^-4t was a mistake as there was a misplaced bracket

torpid drum
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lusty furnace
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can someone pls help i dont get how the domain would be somethingi thats not this

stark sandal
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you missed one more condition though

wary kite
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yep

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there is a value of x > 0 that you have to exclude

marsh citrusBOT
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storm flume
marsh citrusBOT
storm flume
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this isnt a proper question but i dont really get what the bracket 0 k means

crystal lagoon
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Have you learnt that yet?

storm flume
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no ;-;

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is a vector a line-?

crystal lagoon
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it can be represented as one technically

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It contains a magnitude and direction

storm flume
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ahh ok, what is the vector trying to say in this case?

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or what is it meant to represent?

storm flume
crystal lagoon
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It bassically translates something to somewhere else, ie moves a body around by the vector

storm flume
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translated means move right?

crystal lagoon
crystal lagoon
storm flume
crystal lagoon
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it moves by
(X)
(Y)

storm flume
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OHHH OK!

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THAT MAKES SENSE!!

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so since x is -

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0

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it doesnt move

crystal lagoon
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for example if the vector is
(1)
(1), that means it goes right once (x axis) and up once (y axis)

storm flume
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but y is K

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so it moves up/down by k units?

crystal lagoon
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Yesss

marsh citrusBOT
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dense wraith
marsh citrusBOT
trim quest
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Bring all the terms to the left side of the equation. This can be factored by grouping

dense wraith
trim quest
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What I mean by factoring in groups is more like

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oh actually, first of all, those terms you brought to the left need to be negative

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You subtracted them from both sides

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so

dense wraith
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oh my bad

trim quest
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But by factoring in groups I meant like:

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$$z^5 - iz^3 + 8z^2 - 8i = 0$$
$$z^3(z^2-i) + 8(z^2 - i) = 0$$

elfin berryBOT
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tatpoj

dense wraith
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oh ok

trim quest
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and then you can factor out z^2-i

marsh citrusBOT
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marsh citrusBOT
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mild needle
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what is the domain of this function

marsh citrusBOT
mild needle
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i said {(x,y) ∈ R^2 | x^2 <2y} and i got false

cunning river
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you cant make the domain with a condition like this x^2 <2y

mild needle
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we were taught to write it like this for example

unborn condor
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you got false because you have more conditions

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y is not a real, it's a strictly positive real

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or if you have to input it on a program, they might want you to write it as 2y>x^2 instead of x^2<2y

unborn condor
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then how did you "get false"?

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!show

marsh citrusBOT
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Show your work, and if possible, explain where you are stuck.

mild needle
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the teacher corrected it and said it was false it was an exam like 3 weeks ago and we got back the correction

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if I remember correctly there was 2 conditions

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one was x^2=2y is excluded and the other is you need 2y>=x^2

unborn condor
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do you have the original question?

mild needle
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yes but it's in french

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the a)

main idol
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,rccw

elfin berryBOT
unborn condor
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okay, you didnt specify that x and y are reals

mild needle
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where would I specify that?

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inside the Df = {}?

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clear basin
marsh citrusBOT
clear basin
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can i use this

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for these questions

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or what would i use

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please help

stray fern
clear basin
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oky ty

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placid gull
#

Im confused what this question is asking and how i would solve it "The parabola has the property of focusing waves, such as light and radio waves, to a single point. A parabolic reflector has a diameter of 4m and a max depth of 1m. How deep is the reflector at 1m from the edge"?

placid gull
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because when i graph it, the obvious answer is 0.75. but idk how to figure that out algebraically (i think thats the correct term)

delicate wharf
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the parabola has a diameter of 4m, and a max depth of 1m which means if you center it on the origin, it should stick out 2 units on either side

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at at each end, it should be at a height of y=1 (depth of 1m)

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if you take the parent parabola, x^2, you need to ask, what do i need to scale it by, so that when i go 2 units to the left or right (x=-2, 2), i get 1 as my output

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and if (2)^2 is 4, but you want the output to be 1, you scale it down by 1/4

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giving you the equation of (x^2)/4

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then, the question asks, how deep is it 1m from the edge?

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since it goes out to 2m, that means that 1m from the edge is at x=1 or -1

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and if you plug in x=1 or -1 to x^2/4, you get 0.25

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and since we defined the parabola as reaching a maximum of 1, 0.25 is going to be 0.75 units from 1

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and thus the parabola is 0.75m deep 1m from the edge

marsh citrusBOT
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primal drift
marsh citrusBOT
primal drift
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i got this to tan^3x+tanx+2=0

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how would i continute the factoring on this

copper jacinth
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you could let u = tan(x) and hope that u^3 + u + 2 is factorable

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sorry i mistyped

primal drift
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ok how would i factor a cubic function

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i like the idea though

copper jacinth
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rational zero theorem

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p/q

primal drift
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that could work so if you take out a value

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the whole thing is divisible by that value

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ok like i use my calculator and got x1 as 0

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and x2 as -0.5

copper jacinth
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for the zeroes of u^3 + u + 2?

primal drift
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yeah

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but how woulld i do it without a calculator

copper jacinth
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0 doesn't sound right

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if you let u = 0 is u^3 + u + 2 =0

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without a calculator is HELL lol

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you use ratioanl zeroes theorem which tells you that if a polynomial has rational zeroes, they are the form of the divisors of the constant over the divisors of the coefficient of the highest power term

copper jacinth
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you basically then guess and check the entire list

primal drift
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oh i got it

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just use remainder theroem

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as u-1 is factor

copper jacinth
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yeah

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is it u-1 or u+1

primal drift
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u-1

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cause if you sub in -1

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it equals 0

copper jacinth
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yeah

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but that tells you it would have to be u + 1

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right

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becuase -1 makes u + 1 = 0

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-1 makes u - 1 = -2

primal drift
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oh right my bad it would u+1 than

copper jacinth
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yeah

primal drift
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oh wait no you are correct U+1 was correct i just messed up my long division the first time

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oh i see the calculation once you factor

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your quadratic become 1+-root7 * i all over 2 which those soloutions are not possible

copper jacinth
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i trust it

primal drift
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so you just get tanx = -1

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have an raa of pi/4

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and between the hits just 3pi/4 and 7pi/4

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yeah i realised i just pressed cubic function on my calculator earlier

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and did a as 1 b as 1 and c as 2 and d as 0

copper jacinth
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ah i see

primal drift
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if i were using a calculator how would i enter it in, may i ask?

copper jacinth
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i've never used a calculator that solves quadratics/polynomials but if you're using RRT you can use the calculator to more easily plug in the roots

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like if you know the possible roots are 1/2,1/3,1

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you can just plug those into the polynomial and see if the polynomial is 0

primal drift
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ooh ok

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anyways thanks for the help

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lean falcon
#

am i right with A here?

marsh citrusBOT
lean falcon
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<@&286206848099549185>

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gloomy oak
#

heres the problem and

marsh citrusBOT
gloomy oak
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(problem 31)

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heres my work im just wondering if its right

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i ignored P because i already cancelled it out before? is that right

main idol
gloomy oak
#

okayy then its probably all fine thank u 😸

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sleek fern
#

count squares

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your name and last name are on the top right btw

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i'd be more careful

teal light
#

Oops sorry

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sleek fern
#

no worries

teal light
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So what do I properly do

sleek fern
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just count the squares

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each square is 1

teal light
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Okay thank you so much

sleek fern
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sure

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i think its one

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i cant see it anymore

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but it looked like it

teal light
#

Okay thank you

marsh citrusBOT
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still temple
#

Need help figuring out some very simple formulas for my coding project ( i cant math )

rancid geode
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yes

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pls send

still temple
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wait

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that was the wrong pic

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do these numbers have a formula? the way that they are increasing

rancid geode
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  • 5,500,000 per round
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no

still temple
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not really

rancid geode
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its inconsistent

still temple
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here is the full table
ignore the green

rancid geode
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as column or row?

still temple
rancid geode
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for row, it's easy

still temple
quick moth
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ye it switches between mutiplying by 1.5

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and 4/3

still temple
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for all of them?

quick moth
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idk why first one doesnt

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from 5.5 to 11

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maybe its just a wrong pattern but

still temple
quick moth
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idk the next 4

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i just did a fraction of them

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and both were 4/3 and 1.5

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after that tho

quaint elm
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plot them on a chart and it'll be easier to see

quick moth
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the pattern seems fine

still temple
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its such a weird pattern

quick moth
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actually pattern breaks

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at the end of first column

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idkl

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from 88 to 110

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its 1.25

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but 88 times 1.5=132

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so

still temple
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we found a formula to a pattern just like this like yesterday or the day before

it looked completaly random at first but we did it, i think we can say the same for this one too, do you want to see the one that we found the formula to ?

quick moth
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idk u got this lock in

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sorry i gotta go sleep

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wish i could help

still temple
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its fine bro

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gn

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<@&286206848099549185>

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If anyone came here to help, ping me so i can get notified that youre here im on another tab

marsh citrusBOT
#

@still temple Has your question been resolved?

marsh citrusBOT
#

@still temple Has your question been resolved?

still temple
#

<@&286206848099549185>

chilly spoke
still temple
#

hmm let me see

chilly spoke
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it changes from +1 to +2 to +4

still temple
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ye, realised that, im looking for a formula to compactly fit that into my code, since i dont know any math, thats why i came here for help

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and its not just that, we got rabbit shrine and coach too

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the shrine one is weirder, not really a balanced pattern

chilly spoke
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if you know when it changes from +1 to +2 and from +2 to +4, then you can program that in

still temple
#

ye it does, but not for time tower, the time tower one has more costs

chilly spoke
still temple
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it has dependensies on prestige too

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just like the one we did 2 days ago

chilly spoke
chilly spoke
still temple
#

it is

chilly spoke
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it's just +500k per prestige

chilly spoke
still temple
# chilly spoke isn't that the original image?

i can code it without a compact formula, but having a formula just like the one we made 2 days ago makes it better,
you plug the prestige and level in, and it gives the cost

also if its not possible dont tire yourself, i can code it without a formula

chilly spoke
#

I mean, I can probably do it
but I don't see a reason to, it'd be less readable than if you do it without

still temple
#

if you have the time to, ill be grateful, and if you dont, ill try to figure it out by myself but it will take much longer, these should be the last formulas of the game as far as im concerned

#

lmao i love python 😂
Coach level increased by 2! New level: 7. Multiplier is now 0.7000000000000001!

chilly spoke
still temple
#

mhm, still tho thank you very much for helping me

#

ill do it myself

chilly spoke
#

for coach, I haven't figured it out yet
I'll be back in 30 or so minutes if someone else hasn't

#

gonna play some modded mc

still temple
#

nice lol

#

hf!

still temple
#

<@&286206848099549185>
what is the formula here?

rapid dirge
#

What do u mean

still temple
#

how does it grow

rapid dirge
#

Aha

#

Let me see

plush gazelle
#

looks geometric

#

ish

#

idk tho

still temple
plush gazelle
#

no

still temple
#

asked coz of the name

cedar stone
#

Where r u getting these values from?

plush gazelle
#

indian

still temple
rapid dirge
#

What’s the question tho

still temple
#

i just need to find the formula so i can easily include it in my code

rapid dirge
#

There’s no stable formula but

still temple
#

i just want to know how are the numbers growing, based on what

rapid dirge
#

You subtract 2

#

Like

#

Here

#

Subtract

#

870,000,000-650,000,000

#

That gives difference

#

And ratios

#

When u do

#

870,000,000/650,000,000

#

Then u get growth pattern

still temple
#

1.33846153846

rapid dirge
#

good

still temple
#

um

#

what do i have to do with 1.33846153846

rapid dirge
#

thats the growth pattern for that one

still temple
#

oh

#

i dont need the paterns one by one

rapid dirge
#

now look

#

Try to multiply one of them

#

And see what u get

still temple
#

multiply one using 1.33846153846?

rapid dirge
#

Multiply like 59,000,000

#

yes

still temple
#

78969230.7692

rapid dirge
#

And what’s the next number

#

On the list

still temple
#

its probably 1.4 instead of 1.33

#

next number after 870m?

rapid dirge
#

No

#

After the 59M

rapid dirge
still temple
#

79m

rapid dirge
#

yup

still temple
#

ye but not exactly 79m

rapid dirge
#

That’s how u do it

still temple
#

i got like 78969230.7692

rapid dirge
#

Round it up

still temple
#

hmm

#

let me try it with the first number

rapid dirge
#

ok

still temple
#

2944615.38461

#

not really the formula

rapid dirge
#

is there like a stable formula

#

I don’t think so

still temple
#

its incostistant

rapid dirge
#

It’s non linear ofc

#

but

#

try to make a code that rounds it up

still temple
#

i will, i got another one that i kinda need to find the formula of

#

if prestige = 2 level =1
outcome = 5.5m

#

thats like how it works

#

ignore the green numbers

rapid dirge
#

Aha

#

U sure that’s math tho

still temple
#

erm

#

we fixed another one like this 2 days ago but it took 8 hours and it seemed random at first

#

this is one for the last one, ye it kinda has a random pattern

still temple
chilly spoke
#

excluding the first one,
it seems like the next value is 1.35*prev_value then rounded to 2 significant digits

#

for the coach one

still temple
still temple
# still temple

this one is the one that id rather find the formula for then code

chilly spoke
#

that's good too
incase you wanna expand it ig

still temple
#

ye

still temple
# still temple

in here we dont have factory 1 because you unlock timetower at factory 2

#

this one seems to be value times first cost, then value times first cost 2 times then 6 times? idk how to do math

chilly spoke
#

yea, so when does it change from +1 to +2 to +4?

#

at what level?

still temple
#

i dont know which one youre reffering to

still temple
#

like 5.5m / 220m?

chilly spoke
#

yea
if you do that for every number, what do you get?

#

just do it for factory 2

#

actually the opposite of that
like 220m/5.5m

still temple
#

40

#

im confused

chilly spoke
#

and then at some point it increases by 4*base

still temple
#

thanks bro

#

love you ❤️

#

(not in a gay way, i just appreciate the time you put in to help me :))

#

.close

marsh citrusBOT
#
Channel closed

Closed by @prisma trellis

Use .reopen if this was a mistake.

marsh citrusBOT
#
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Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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glossy sapphire
#

Check that my Derivation / Proof (not sure which word is appropriate here) that Radical sqrt(1+sqrt(1+sqrt(1+…))) = 1 + 1/(1 + 1/(1 + 1/(1 + …))) is logically consistent and has no errors

glossy sapphire
#

Let ( u = \frac{1}{1 + \frac{1}{1 + \frac{1}{1 + \cdots}}} ).

[\frac{1}{u + 1} = u]
[\frac{1}{u} = u + 1]
[u = \frac{1}{u} - 1]

Derive EQN (1)
[\frac{1}{u} \cdot (u + 1) = (u + 1)^2]
[1 + \frac{1}{u} = (u + 1)^2]
[u + 1 = \sqrt{1 + \frac{1}{u}} \tag{1}]

Derive EQN (2)
[u \cdot \left( \frac{1}{u} + 1 \right) = \left( \frac{1}{u} - 1 \right) \cdot \left( \frac{1}{u} + 1 \right)]
[1 + u = \frac{1}{u^2} - 1]
[\frac{1}{u^2} = 2 + u]
[\frac{1}{u} = \sqrt{2 + u}]
[\frac{1}{u} = \sqrt{1 + (1 + u)}]
[\frac{1}{u} = \sqrt{1 + \frac{1}{u}} \tag{2}]

From EQN(1),
[u + 1 = \sqrt{1 + \frac{1}{u}}]
Since ( \frac{1}{u} = \sqrt{1 + \frac{1}{u}} ) from EQN(2), we can rewrite as:
[
u + 1 = \sqrt{1 + \sqrt{1 + \frac{1}{u}}}
]
We can substitute EQN(2) infinitely to get our required proof.

Thus, we have proved that:
[
1 + \frac{1}{1 + \frac{1}{1 + \cdots}} = \sqrt{1 + \sqrt{1 + \cdots}}.
]

elfin berryBOT
quiet anvil
#

So, the problem with these sorts of expressions is that they aren't well defined.

glossy sapphire
#

Ah…

quiet anvil
#

Nothing is wrong with your work, per se

glossy sapphire
#

So the problem here is the way i mishandled its definition?

quiet anvil
#

Well, the problem is assuming expressions like sqrt(1 + sqrt(1 + ...)) have specific single meanings.

#

For instance, there are two roots to that equation. Phi and -1/phi

glossy sapphire
#

Yep

quiet anvil
#

What does it mean for there to be a second value for this expression?

#

Which one is correct?

glossy sapphire
#

I would argue since it consists only of positive integers, only the solution that is >0 is correct

stoic slate
#

That is why you have to define them correctly

glossy sapphire
#

So i have to use abs()?

quiet anvil
#

You might argue this. But there is a very real sense in which both values are correct.

glossy sapphire
quiet anvil
#

No

glossy sapphire
#

So if you go one out from neg its positive(?)

#

Dang

stoic slate
#

Sqrt doesnt return both

glossy sapphire
#

Hmm, how should i define it better in this case?

quiet anvil
#

You should define it as the limit of a particular sequence

glossy sapphire
#

Oh

#

Ohhhhhh

#

That makes sense

#

Thank you haha

#

I ll get to work on it

quiet anvil
#

Then to start the sequent

#

You need a seed value

glossy sapphire
#

Hmm, i dont think ive learnt that

quiet anvil
#

And the seed value actually affects the result.

glossy sapphire
#

Is there an article anywhere i can read up on regarding that

glossy sapphire
quiet anvil
#

Which is how both can be correct

#

It depends on the starting value

glossy sapphire
#

I see…

#

I ll read up on limits regarding radicals, thank you for the advice 🙏

#

.close

marsh citrusBOT
#
Channel closed

Closed by @glossy sapphire

Use .reopen if this was a mistake.

quiet anvil
#

Where ε is a small value

#

And see if ε grows or shrinks under iteration

#

Essentially you set up, x(1) = c, x(n+1) = 1/(1 + x(n))

#

And choose your c.

#

You still use the substitution to find the limit as you did before

glossy sapphire
#

Ah ok

quiet anvil
#

You'll find one of three behaviors

#

Either the ε will get bigger (this fixed point is unstable), smaller (stable), bigger from one side and smaller from the other (metastable)

#

And also, there will be certain values that will happen to become undefined after a few iterations

#

Due to being undefined.

glossy sapphire
#

Hmm, is it alright for you to provide an example so i can visualise whats going on 😅

quiet anvil
#

Sure

#

.reopen

marsh citrusBOT
#

quiet anvil
#

So the important thing is the seed value.

glossy sapphire
#

.reipen

quiet anvil
#

We can examine a few.

glossy sapphire
#

Oh

quiet anvil
#

Let's start with x(1) = 0

x(2) = 1/(1+0) = 1
x(3) = 1/(1+1) = 1/2
x(4) = 1/(1+1/2) = 2/3

#

And so on

#

We can see this converges to 1/phi eventually

glossy sapphire
#

Yep

quiet anvil
#

What about x(1) = 2?

glossy sapphire
#

X(2) = 1/(1+2)? = 1/3?

quiet anvil
#

x(1) = 2
x(2) = 1/(1+2) = 1/3
x(3) = 1/(1+1/3) = 3/4
x(4) = 1/(1+3/4) = 4/7

This also will converge to 1/phi

glossy sapphire
#

Ohhh

quiet anvil
#

(Lucas sequence)

#

What if we have exactly x(1) = -phi?

x(1) = -phi
x(2) = 1/(1-phi) = -phi
x(3) = 1/(1-phi) = -phi

#

So this also gives us a fixed point, but a different one.

glossy sapphire
#

O dang

quiet anvil
#

x(1) = -2
x(2) = 1/(1-2) = -1
x(3) = 1/(1-1) = 1/0, error

glossy sapphire
#

Ahh…

#

So i have to define x(1) = 0?

quiet anvil
#

No

#

The point is that whatever you define x(1) as, this is a choice

#

And it's a choice that determines what the value of that expression will be

#

! occupied

marsh citrusBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

glossy sapphire
#

Oki

#

Tq @quiet anvil 🙏

#

.choice

#

💀

quiet anvil
#

You're welcome

glossy sapphire
#

.close

marsh citrusBOT
#
Channel closed

Closed by @glossy sapphire

Use .reopen if this was a mistake.

glossy sapphire
#

I misspelled haha

quiet anvil
#

Choice is a new one

glossy sapphire
#

XD

quiet anvil
#

For me anyway

glossy sapphire
#

Adhd kids invent new shit everyday

marsh citrusBOT
#
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marsh citrusBOT
jovial osprey
#

whats the upper bound

#

its so unclear

grand radish
#

+infinity

jovial osprey
#

ah

#

im pretty sure they just did it to make the problem easier

#

its still the same problem

#

0 to infinity

#

is the same thing as

#

0 to 1 than 1 to infinity

#

could be wrong tho

grand radish
#

probably a test

#

convergence or divergence test

#

but I'm not studying this topic so I'm not sure

jovial osprey
#

comparison test works here

#

i believe

#

so does limit comp test

marsh citrusBOT
#
Channel closed

Channel closed due to the original message being deleted.
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as this action is irreversible, and this channel may abruptly lock.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

neon willow
#

,, Tan(60) = \frac {a} {b}

marsh citrusBOT
elfin berryBOT
#

Mirabella

neon willow
#

Can anyone tell me how tan works?

#

I know how to calculate it.

#

But I want to know how can it find a side?

#

Based on degrees.

#

60 is degrees.

#

Of an angle

#

But Tan?

#

,, Tan * 60

elfin berryBOT
#

Mirabella

cunning river
#

you need to know either a or b to know the other

neon willow
#

I know.

#

My point is

#

What is Tan?

cunning river
#

its a function

ruby flame
#

tan is sin/cos

runic swan
neon willow
cunning river
neon willow
#

, calc cos^-1 (0,066)

elfin berryBOT
#

The following error occured while calculating:
Error: Parenthesis ) expected (char 10)

neon willow
#

@cunning river

neon willow
#

how can it find the other length

cunning river
ruby flame
neon willow
cunning river
#

see this circle here the radius is 1 so if we want to calculate sinO its the opposite side divided by1

#

right?

neon willow
#

ok,

#

first of all,

#

@cunning river what is 0,179

runic swan
#

thats wrong

elfin berryBOT
#

Mirabella

neon willow
#

Here.

#

@runic swan

runic swan
#

u mean 0/179?

neon willow
#

enter the angle in degrees when

The tangent of the angle is 0,179

runic swan
#

u use a calculator

neon willow
#

ik

runic swan
#

tan^-1(0.179)

neon willow
#

what does 0,179 indicate?

runic swan
#

radians

neon willow
#

is it ,,a/b = 0,179?

runic swan
#

what

elfin berryBOT
#

Mirabella

neon willow
runic swan
#

u know how tangent is opp over hyp

#

so opp over hyp is 0.179

neon willow
#

, calc tan^{-1}(0,354)

elfin berryBOT
#

The following error occured while calculating:
Error: Symbol or string expected as object key (char 6)

runic swan
#

relationship between height and base of the triangle

neon willow
runic swan
#

$\frac{opp}{hyp}$

elfin berryBOT
#

jackeylove

runic swan
#

u use tan^-1 to find the angle

neon willow
#

thats wrong...

#

$tan = \frac{a}{b}$

elfin berryBOT
#

Mirabella

$tan = \frac{a}{b}$
runic swan
#

a is sin b is cos

#

bruh what

elfin berryBOT
#

Mirabella

runic swan
#

yes

#

oppy over adj

#

my bad

elfin berryBOT
#

Mirabella

runic swan
#

write 0.179 as a fraction

#

idk what ur trying to do here

#

what r u trying to find

#

whats ur question

neon willow
#

find the angle in degrees when

The tangent of the angle is 0.179 0.354 0.839 1.437 11.43

runic swan
#

are you allowed to use a calculator

neon willow
#

ik

#

im trying to

#

understand what these are

#

okay sure, i know how to use the formula

#

however i want to LEARN

#

the math

#

i can use pythagoras theorem for example and use it, however i dont know what is it unless i know that if you add square of a and aquare of b it is square c

runic swan
neon willow
#

@runic swan omg why r u difficult

#

<@&286206848099549185> give me a video explaining trigonometry, not how to calculate it but how it works. Definition MEANING.

merry pivot
#

What do U need help with

grand radish
#

khan acadedmy

merry pivot
#

I bet this is sum troll account

#

Nun wanna LEARN trig

#

🙏😭

marsh citrusBOT
#

@neon willow Has your question been resolved?

neon willow
#

<@&286206848099549185> Help me!

thin cairn
#

Leave this young lady alone she’s lovely

neon willow
#

Ik!

merry pivot
#

💀💀💀😭😭

neon willow
#

Out

merry pivot
#

Dis aint even the hard trig yet

#

😭🙏

#

If ur being fr I will help you but I’m actually convinced bro is js

#

Trolling

cedar stone
#

tan(x) = sin(x)/cos(x)

#

ig by 0,179, they mean that in degrees, the period of tan(x) is 180, so tan(0) = tan(180), so they are saying all number from 0 to 180 excluding 180

neon willow
#

Sir, I’m not trolling.

neon willow
cedar stone
neon willow
grand radish
#

3/5

elfin berryBOT
#

Mirabella

neon willow
#

And we have the ratio

#

, calc 4 / 5

elfin berryBOT
#

Result:

0.8
neon willow
#

0,8 is the ratio

#

Let’s say c was 75

elfin berryBOT
#

Mirabella

#

Mirabella

neon willow
#

So ultimately, Sin A is a ratio between b/c @cedar stone

cedar stone
#

sin a = 3/5

#

not 4/5

neon willow
#

So sin a tell the RATIO between two lengths?

#

@cedar stone

#

Am I right?

cedar stone
neon willow
#

,Calc asin(/frac {3}{5}

elfin berryBOT
#

The following error occured while calculating:
Error: Value expected (char 6)

neon willow
#

,Calc asin(/frac {3}{5})

elfin berryBOT
#

The following error occured while calculating:
Error: Value expected (char 6)

amber birch
amber birch
#

oh but this answer is in radians

neon willow
#

I want in degrees

amber birch
#

,calc 0.6435 * 180/pi

elfin berryBOT
#

Result:

36.869834116668
amber birch
#

converted

#

,w arcsin(3/5) in degrees

neon willow
#

I’m actually confused what does -1 do?

amber birch
#

so $f^{-1} (x)$ is the inverse function of $f(x)$

neon willow
#

When do you use it?

elfin berryBOT
#

southlander!

amber birch
#

this means $f(f^{-1} (x)) = x, f^{-1} (f(x)) = x$

elfin berryBOT
#

southlander!

amber birch
#

if you apply the inverse then the original function in any order, you get back your original number

amber birch
#

and you want to find x of course

#

you apply the inverse functions, sin^(-1) or cos^(-1) to both sides

#

so x = sin^(-1) (0.5) and x = cos^(-1) 0.7

neon willow
#

Let’s say

elfin berryBOT
#

Mirabella

neon willow
#

@amber birch How to add degrees?

amber birch
elfin berryBOT
#

southlander!

neon willow
#

,, \sin(50^{\circ}) ≠ \sin(50) ??

amber birch
#

sin(50) can mean sin(50 radians)

neon willow
#

,text $\sin(50^{\circ})$ ≠ $\sin(50)$ ??

elfin berryBOT
#

Mirabella
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

amber birch
#

but you can tell from the context usually

neon willow
#

wtf why isn’t ≠ put there

amber birch
neon willow
#

,, \sin(50^{\circ})

elfin berryBOT
#

Mirabella

neon willow
#

,,Sin * 50°

amber birch
#

sin is a function!

#

you can put some number into the function

#

but $sin + 2, sin - 2, sin \cdot 2, sin \div 2$ make zero sense

elfin berryBOT
#

southlander!

neon willow
#

Can you tell me other thing as a function?

amber birch
neon willow
amber birch
neon willow
#

I want to know what a function is

#

Cuz surely it’s not a formula or number

amber birch
#

a function is a machine

#

you put one number in

#

you apply some rule

#

and you get another number out

neon willow
#

So it’s all a generative?

#

It’s like a script?

amber birch
#

yeah if you know programming or coding

neon willow
#

Without a calculator no one knows what sin is?

amber birch
#

we can only figure out special values of sin

neon willow
amber birch
#

like sin 0, sin 30, sin 60, sin 45

amber birch
neon willow
amber birch
#

long story short, if you have sin(k degrees) where k is a fraction or a whole number

neon willow
#

I just barely know sin cos tan

amber birch
#

then x = sin(k degrees) into some polynomial

neon willow
#

What’s radians?

amber birch
#

such as $2x^5 - 3x^3 + 2x^2 - x + 7$ or something, when you put that $x$ in

elfin berryBOT
#

southlander!

amber birch
#

gives you zero

amber birch
neon willow
#

Haven’t learned it…

amber birch
neon willow
#

Can you also give me an image on how to calculate circumference of a circle?

amber birch
#

for a sector you just do this

neon willow
neon willow
#

Yeah diameter = 2*r

#

And how to calculate circumference?

amber birch
neon willow
#

Why 2 pi?

amber birch
#

pi = circumference/diameter

#

so circumference = diameter * pi

amber birch
neon willow
#

So circumference is as well as pi * diameter?

#

@amber birch

neon willow
#

Pi is a specific point or?

amber birch
#

pi = 3.1415.............

neon willow
#

How many decimals is best to remember pi?

#

3.14 only?

amber birch
#

(and how do we get that number? try drawing a circle
now use some string and try to wrap it around your circle
then straighten out the string and you have found the circumference length)

amber birch
amber birch
neon willow
#

Do I need to learn contangus as a beginner?

amber birch
neon willow
#

I feel like it’s just skipped

amber birch
#

it's really not that hard

#

cotangent = 1/tan

#

cosecant = 1/sin

#

secant = 1/cos

neon willow
#

And how to divide 1 with cos?

#

@amber birch

amber birch
#

I mean 1/cos(x)

#

sorry about that

neon willow
#

x is an angle?

#

@amber birch

amber birch
neon willow
#

Cos(x) tell the ratio between b/c?

#

Right?

#

Am I having this correct

#

Way of thinking

amber birch
neon willow
#

Ok ok

#

Also tell me

amber birch
neon willow
#

@amber birch If I attended 344 classes out of 365 all possible classes, it’s 94,24% right. Now how much more classes do I need to attend to get 95% of attendance?

neon willow
amber birch
neon willow
#

Do I need to know that?

amber birch
neon willow
#

43 classes more to go.

#

@amber birch

amber birch
#

365 + 43 = 408 classes

#

,calc 408 * 95/100

elfin berryBOT
#

Result:

387.6
amber birch
#

,calc 387.6 - 344

neon willow
#

388

elfin berryBOT
#

Result:

43.6
amber birch
#

so you need to attend 44 classes or more

neon willow
#

bruh so i need to attend all of them to get 95%

amber birch
#

even if you attended all of them you would not get 95% attendance

neon willow
#

why

amber birch
#

,calc (344 + 43)/(365 + 43)

elfin berryBOT
#

Result:

0.94852941176471
amber birch
#

your percentage is still lower than 95%

neon willow
#

bruvvvv

#

thats so close

amber birch
#

yeah I made the same mistake at uni

#

Canvas the online platform miscalculated the predicted grade when I didn't submit an assignment

neon willow
#

,calc 0.99 *408

elfin berryBOT
#

Result:

403.92
amber birch
#

so I couldn't get a distinction

#

even if I got 100% on the remaining assignments

neon willow
#

wow, so you can only skip 4 classes to have 99% attendance

#

thats sooo few

#

its either way not the actual attendanec

#

94% is if we count the sick and free days

#

i have 100% meaning i didnt skip one class

#

but 94% is for all sick days + approve abscence

#

@amber birch do u kbnow what i mean

amber birch
#

unlucky

amber birch
#

or it doesn't

neon willow
#

yes

amber birch
neon willow
#

that 6% is how much i didnt attend becsuse of sickness and free days

amber birch
neon willow
#

i have 100%, meaning i didnt skip any class
94% because i went sick and free days

amber birch
#

I know

#

what is the 95% then

neon willow
#

its all here

#

@amber birch

amber birch
#

excluding sick + approved but still

neon willow
#

ikr

#

i had 100% in sick approved in first half of the semester

#

but then i had to go to the capital city

#

do u also use canvas??? @amber birch

#

well this is inna

neon willow
#

hiow does it look like

amber birch
#

I don't care honestly

neon willow
#

@amber birch Can you check my homework?

#

One equation.

#

Cause when I was here.

#

A person told me an answer

#

And chatgpt too (the same answer as him)

#

However my answer was different.

#

Can you take 7 mins?

amber birch
#

someone else will answer don't worry

neon willow
#

sure.

#

.close.

#

.clos

#

.close.

prime ivy
#

@neon willow

#

close the channel

#

with .close

neon willow
#

.close

#

ty

marsh citrusBOT
#
Channel closed

Closed by @neon willow

Use .reopen if this was a mistake.

marsh citrusBOT
#
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Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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gaunt gate
#

translation: does exist a number n divisible by 103 such that happens?

gaunt gate
#

idk if it's right but i found that if it's the case (exists such n multiple of 103), then n should be multiple of 51 by fermat little theorem and then n should be multiple of 4? and then it's absurd because LHS is gonna be divisible by 4 so not congruent to 2 mod 4

#

<@&286206848099549185>

ruby mulch
#

Wait, I almost found the solution

#

I guess, you're right.

gaunt gate
#

did you find the same?

marsh citrusBOT
#

@gaunt gate Has your question been resolved?

marsh citrusBOT
#

@gaunt gate Has your question been resolved?

ruby mulch
#

Yes, I found the same.

narrow oak
#

oh it's mod n, i'm sry it's not correct

marsh citrusBOT
#
Channel closed

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marsh citrusBOT
#
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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inland patio
#

So I'm curious how does the substitution work here

inland patio
#

So, du is 2xdx, so dx is du/2x?

#

Or just du/2

#

Like, I wonder what happened with the x in the du sub and why can't I write it if du is 2xdx strictly, it feels and it is right, but I'm not sure how

strong dagger
#

because that means you can now replace your xdx in your problem with du/2

#

and then you can factor out the 1/2

inland patio
#

Ohh yes it makes sense!

#

Since I got x there

strong dagger
#

yeah

inland patio
#

I guess I lacked perspective

#

Thanks for the short help! Have a good day or night

strong dagger
#

you too

inland patio
#

.close

marsh citrusBOT
#
Channel closed

Closed by @inland patio

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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arctic flame
#

Hi.

marsh citrusBOT
stark sandal
#

!nohello

#

!nohi

#

sigh

arctic flame
#

How are you? @stark sandal

stark sandal
#

i'll do it manually

arctic flame
#

Is Sin and Cos always <1?

stark sandal
#

no.

#

$\leq$, yes.

elfin berryBOT
arctic flame
#

whats < and _

stark sandal
#

,wolf leq meaning

arctic flame
#

what

stark sandal
#

ok fuck

#

it just means less than or equal to

#

how did you get into trig without knowing math notation

arctic flame
#

so sin and cos are 1 or less?

rocky lark
#

No

#

they are also greater than or equal to -1

arctic flame
#

uh yesss

#

so theyre 1 or 0,9... 0,8 etcc

#

the height of triangle is always 90 degrees? @stark sandal

hollow snow
#

Both sin and cos, can be any number between -1 and 1 including -1 and 1

#

[-1,1] in simple terms

arctic flame
#

but tan?

#

the height of triangle is always 90 degrees? @Percy

hollow snow
#

Well tan is just sin/cos

hollow snow
#

Right side triangles always have 90 degree angle

arctic flame
#

ok then

#

.close

marsh citrusBOT
#
Channel closed

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marsh citrusBOT
#
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Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dim wasp
#

graphing sin(e^x)

marsh citrusBOT
dim wasp
#

it looks like this but could anyone give me some genuine tips on how to approach this

proud ice
dim wasp
#

sketching

#

sin(e^x)

#

i know the individual graphs

#

and how sin is periodic and has max and min at 1 and -1