#help-33

1 messages · Page 198 of 1

latent coral
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i think bayes theorem actually might be easier here btw

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the way i did it requires you to recognize this

cunning fractal
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Oh okay

latent coral
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actually i'm not sure since bayes would require you to find P(she stopped | last flip heads)

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which doesn't seem all that easier

cunning fractal
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Even then I still feel like the answer is wrong

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Because we're assuming specific sequences like HH or TTT

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But in reality she could do HTTHTHH

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Or something else of the sort

marsh citrusBOT
#

@cunning fractal Has your question been resolved?

marsh citrusBOT
#
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hot slate
#

Hi everyone. I hit my chatgpt and claude limit, so I am coming here to ask something. In this example, on the definition of the set H, H is a direct image right? Even if it was a subset of R(real numbers), within the function definition, there won't be any inverse image, right? So why in this example, it took the direct of the inverse image of H and it was equal to {y:0<=y<=1} ?

whole thorn
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tldr

hot slate
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bruh

hot slate
# whole thorn tldr

it's literally two questions bro i can't sleep if i go to sleep with this question unanswered

quaint elm
whole thorn
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i apologize

quaint elm
whole thorn
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my nitro ran out btw

hot slate
quaint elm
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it will help to start by calculating f-1(H)

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no, not necessarily

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the inverse image of H is all real numbers x such that f(x) is in H

hot slate
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so that means basically all numbers f(x) that is in H would be [0, 1] ?

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that makes sense, because there is no number that will be squared to -1, so we will just take the numbers x that f(x) is in H. Okay got it.

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i forgot the command that closes this channel, anyone?

quaint elm
#

.close

marsh citrusBOT
#
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marsh citrusBOT
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marsh citrusBOT
sacred rivet
#

I found my eigenvalues to be λ= 0, λ = 25, λ = -18

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and the corresponding eigenvectors to be:

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[4/3 0 1]^T

[-3/4 0 1]^T

[0 1 0]^T

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Do I simply normalize these vectors to make P and just use the eigenvalue along the diagonal for D?

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I don't have to perform gram-Schmidt because Each eigenspace has dimension 1, so all we need to do is normalize the eigenvectors?

glass silo
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They're already orthogonal, so you just need to normalise them

sacred rivet
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Well how do we know they are already orthogonal?

glass silo
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Try it SCgoodjob2

valid cape
glass silo
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(last is clearly orthogonal to the first two, the first two you can see it works out happyCat)

sacred rivet
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umm

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then why r we normalizing

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if they are already orthogonal 🙀

glass silo
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Because, weirdly enough, a matrix is orthogonal iff its columns are orthonormal (and not just orthogonal) happyb

sacred rivet
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I'm not getting the first two vectors to be orthogonal

glass silo
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So we need to make sure that those eigenvalues are orthonormal, them being nonzero orthogonal is most of the way there happyCat

sacred rivet
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the dot product is not 0 for the first 2

glass silo
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It's not? How are you doing them?

sacred rivet
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oops!

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it is 😅

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sorry!

glass silo
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Happens to us all OathLove

sacred rivet
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umm i'm still slightly confused

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why we need to normalize

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i understand that

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normalizing makes it orthonormal

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but doesn't the question only want orthogonal?

glass silo
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It wants the matrix to be orthogonal, but you need the columns to be orthonormal for that sadCatThumbsUp

sacred rivet
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ohhh

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OMG

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that makes sense!

glass silo
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catThink good question, I can't remember

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I feel not but I don't have a counterexample to hand for that sadcat

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Actually, if you have all your eigenvalues being distinct, then the corresponding eigenvectors are automatically orthogonal, so then it's just needing to normalise them that would be left SCgoodjob2

sacred rivet
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yaa

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okay thank you!

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wait hmm

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even without normalizing tho

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our matrix P is orthogonal

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so why is normalizing coming into play?

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wait

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nvm

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you are right!

glass silo
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Yep you need them orthonormal, it's an iff nyaTease1

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On a related note, whoever chose the naming should be shot CatShoot

sacred rivet
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hahahahaha

glass silo
#

Anyways, is that all good? OathLove

sacred rivet
#

mhm, thank you so much!

marsh citrusBOT
#

@sacred rivet Has your question been resolved?

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marsh citrusBOT
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weak wind
#

i need help on this question

marsh citrusBOT
weak wind
#

is anyone currently online?

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<@&286206848099549185>

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is anyone online

sand fable
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nope. not a single person

weak wind
#

can someone help

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.close

marsh citrusBOT
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marsh citrusBOT
# weak wind <@&286206848099549185>

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

sand fable
#

i.e. 13/42 - 1/2!, is this less than 0? if yes, then a_2 = 0 and move on to 1/3!. if not, then subtract again, etc

marsh citrusBOT
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steel breach
#

I tried various different methods but I just can't solve this integral.

still temple
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kings rule

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lol

still temple
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and then apply kings rule

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and observe the result

steel breach
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observe the result?

still temple
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what did you get after applying kings rule?

steel breach
still temple
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yes

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after some manipulation you get
$\int_{-1}^1 \frak{e^x x^2){e^x+1}$

elfin berryBOT
#

Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

still temple
broken zealot
#

,,\int_{-1}^1 \frac{e^x x^2){e^x+1}

elfin berryBOT
#

Bair
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

broken zealot
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bruh

steel breach
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\int_{-1}^1 \frac{e^x x^2}{e^x+1}

still temple
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lol

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anyways

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i suppose you get what i mean

steel breach
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yes

still temple
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do you have one iintegral i.e this

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and other which is the same but with e^x in the numerator

steel breach
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yes

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but how should I get rid of the e^x

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since like I have to sub the I back right?

still temple
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check what happens when you add both the integrals

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since both are the same

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you have 2I = ....

steel breach
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Ahhhhhh

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ok I get it now

still temple
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👁️

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lol

steel breach
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didn't thought of that

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thanks

#

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#
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paper cedar
marsh citrusBOT
amber birch
marsh citrusBOT
# paper cedar
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
paper cedar
#

2

amber birch
paper cedar
#

I have a solution here but it might be wrong

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Can you guide me like from the 1st step

amber birch
#

otherwise I might be telling you things that you already know

paper cedar
#

Alright let me write it again

marsh citrusBOT
#

@paper cedar Has your question been resolved?

marsh citrusBOT
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whole hinge
#

whereis the value of di came from?

marsh citrusBOT
amber birch
marsh citrusBOT
#

@whole hinge Has your question been resolved?

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whole hinge
marsh citrusBOT
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whole hinge
#

the question If the temporary average of the data is 27 million rupiah, then the calculated average of the data (in millions of rupiah) is shown by the formula

whole hinge
#

pendapatan means salary, jumlah means sum, frekuensi means frequency

amber birch
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cause 27 (million) is in the category 25 to 29, so you set that weight to be 0

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it's a very clever method

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,calc 5 * 1 + 8 * 2 * 10 * 3 + 12 * 4 + 7 * 5 + 3 * 6

elfin berryBOT
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Result:

586
amber birch
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hmm

whole hinge
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-3,-2,-1

amber birch
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I'm not too sure actually

whole hinge
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can you solve the problem?

amber birch
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looks like this but different

amber birch
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like what is a temporary average and a calculated average

whole hinge
whole hinge
amber birch
whole hinge
#

oo

amber birch
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unfortunately I don't know why the formula given in the video works

whole hinge
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oo i see , so we have to search the mid point first and after that we hv to reduce mid point and temporary average

amber birch
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and it doesn't help that your teachers are like "shut up and memorise it"

whole hinge
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wwww

amber birch
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which is different I know

elfin berryBOT
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Result:

11.666666666667
whole hinge
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thats the way to search the average

amber birch
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,calc (30 + 270 + 650 + 350)/(3 + 9 + 13 + 5)

elfin berryBOT
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Result:

43.333333333333
whole hinge
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the way to search temporary average is a bit difffrent

amber birch
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yeah so that's the same as (sum of fi di) / (sum of fi)

amber birch
whole hinge
#

yayayaya

amber birch
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but your question is asking for the calculated average right

whole hinge
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yeah

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with known data is temporary average

amber birch
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oh wait what I was doing

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that's rata hitung right

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not rata-rata sementara

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interesting

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but then can't you apply the same method for both

amber birch
whole hinge
#

naahh broo youre right

amber birch
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I just don't know how Indonesian maths works

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maths is maths I know but there are plenty of differences in style and content

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maths isn't super universal

marsh citrusBOT
#

@whole hinge Has your question been resolved?

marsh citrusBOT
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@small stream Has your question been resolved?

marsh citrusBOT
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@small stream Has your question been resolved?

marsh citrusBOT
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flat junco
#

can somebody help me how to calculate eigenvalues by hand? actually its a bonus task for my assignment

fervent rampart
#

could you show the original problem?

marsh citrusBOT
#

@flat junco Has your question been resolved?

flat junco
#

this is just a characteristic polynomial of sample covariance matrix

marsh citrusBOT
#

@flat junco Has your question been resolved?

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rancid glen
marsh citrusBOT
#

Please don't occupy multiple help channels.

modern lintel
rancid glen
#

Solve Derivatives

modern lintel
#

so you want the derivative of that function?

rancid glen
#

Yes please

modern lintel
#

then first, each term on the numerator has a common denominator so try splitting it up into 3 different parts

rancid glen
#

Okay okay

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Everything confused me mind as well start over again

modern lintel
#

yeah oaky so split it into your 3 terms

late geode
#

no need to split

modern lintel
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why not

late geode
#

just apply quotient rule

modern lintel
#

but also depends what level they are at

late geode
#

even if you were to split, you'd need to follow with product rule with neg exponents or quotient rule, so why not just do that directly

marsh citrusBOT
#

@rancid glen Has your question been resolved?

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rancid glen
marsh citrusBOT
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marsh citrusBOT
serene ermine
#

i need a full solution for this

marsh citrusBOT
#

@small stream Has your question been resolved?

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serene ermine
#

.end

marsh citrusBOT
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muted grail
#

how can i show that this series is a cauchy series?

amber birch
#

<@&268886789983436800>

amber birch
elfin berryBOT
#

southlander!

amber birch
#

since a_n is always positive

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oh yeah if $n \ge m$ ofc

elfin berryBOT
#

southlander!

amber birch
#

we can assume this condition without loss of generality

muted grail
#

ok

amber birch
muted grail
#

so we need to show that the sum of all the terms 1/k^2 from k = m to k = n can be as small as we want it to

amber birch
#

ah can't you bound $|a_n - a_m|$ above by $(m - n + 1) \frac{1}{n^2}$

elfin berryBOT
#

southlander!

amber birch
#

basically if we have 1/4^2 + 1/5^2 + ... + 1/10^2 for example

bound this above by 1/4^2 + 1/4^2 + ... + 1/4^2

muted grail
#

i might be wrong can we maybe use the fact that n>=m>=N_e and say that 1/n^2=<1/m^2 =< 1/N^2

amber birch
#

and there will be 10 - 4 + 1 or m - n + 1 terms

muted grail
#

yeah i have that right now

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like smt similar

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lemme send it

amber birch
#

the experts are coming great

hushed egret
#

,, \sum_{k=m}^n \f 1 {k^2} \le \sum_{k=m}^n \f 1 {k(k-1)}

elfin berryBOT
hushed egret
#

🔭

muted grail
#

but i need to use cauchy crit

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does that make any sense?

hushed egret
#

your bound doesn't work because n is unbounded

hushed egret
muted grail
#

your saying compare it w a telescopic series right?

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ohh or use it as a bound

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?

marsh citrusBOT
#

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muted grail
#

.reopen

marsh citrusBOT
#

muted grail
#

@hushed egret hey so

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I understood what you meant

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but I'm stuck again

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<@&286206848099549185>

marsh citrusBOT
#

@muted grail Has your question been resolved?

muted grail
#

.close

marsh citrusBOT
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gray iron
marsh citrusBOT
gray iron
#

How do I get second solution?

#

I'm not sure how to start on that

terse basin
#

to find the second solu you do pi -x

amber birch
#

cause sin(u) = sin(pi - u) for all real u

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,w pi - arcsin(-0.45)

amber birch
#

oh and then add 1

gray iron
#

Sorry if my notation is messy

#

This seems correct

#

Thanks guys I really appreciate the help :)

#

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gloomy merlin
#

Are the Fourier coefficients of a scalar the scalar itself?

gloomy merlin
#

my book says the following, but how do you justify it using the mathematical representation of the Fourier coefficient series

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#

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royal sable
elfin berryBOT
#

EQUENOS

marsh citrusBOT
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wicked ridge
#

How do you do newtons cooling with changing environmental temperature

wicked ridge
#

Like a block heated to 100 degrees C is placed into water that is 18 degrees C

#

when will the temperature stabilize

marsh citrusBOT
#

@wicked ridge Has your question been resolved?

wicked ridge
#

Sorry it wouldnt be newtons cooling

#

The mass of the water isnt enough to keep its temperature constant

#

How would we come up with a coupled differential to solve this

marsh citrusBOT
#

@wicked ridge Has your question been resolved?

unborn condor
#

!original

marsh citrusBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

marsh citrusBOT
#

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median flare
#

Hello, I need some help with converting units of measuerement

median flare
#

So I have 0.00001pm³ and I need to convert it to Tm³

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Now I understand I have to use division because pm is a smaller unit than Tm and that I have to do it 3 times because it's ^3

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But like... how do I calculate it?? What numbers do I put in

main idol
#

Do you know how many pm equals 1 Tm?

median flare
#

I don't, I don't really understand that part. I just have this table and I know that pm=10^-12 and that Tm=10^12

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But what do I do with that information?

main idol
#

1 pm = 10^(-12) m

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1 Tm = 10^12 m

median flare
#

Yeah

main idol
main idol
#

1 Tm = ? pm

median flare
#

I got 1×10^31m

main idol
median flare
main idol
#

? pm^3 = 1 m^3

#

How many pm^3

median flare
#

10^-12?

main idol
#

No

median flare
#

What do you mean by both sides?

main idol
#

Then cube both sides if you want to solve for pm^3 in terms of m^3

#

like 2.4cm = 1in. Multiply both sides to get 1 foot = 12*2.4cm

median flare
#

How did you get 12 in 12×2.4

main idol
#

What

#

1 foot = 12 inches

#

I assumed this was common knowledge

median flare
#

Hahahahaha I know it probably is but I never used American measurements in my life

main idol
#

"multiplying both sides" by a number should not be a new concept

median flare
#

I don't know what to multiply with

#

what number

#

I thought it was maybe first about converting pm to m and then m to Tm

main idol
#

I specifically said 10^12

median flare
#

Is 1Tm=10^12m?

main idol
#

This is the first half of what you said

main idol
median flare
#

I guess we have different ways of solving because I dont know what it means

#

Let me tell you an easy one I solved

#

For example when I wanted to convert 0.5cm² to m²

#

I just did 0.5÷100÷100

main idol
median flare
#

And got 5×10^-5m²

#

Which is correct and I understand that

#

So I used the same logic for every other task but when I came to these weirder measurements it stopped working

#

that is it probably still works but I don't understand those measurements how to convert them since I never heard of them up until now

marsh citrusBOT
#

@median flare Has your question been resolved?

median flare
#

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keen echo
#

GUYS WHATA 9!

marsh citrusBOT
keen echo
#

WHAT ARE !

still temple
#

Seems like a question you can Google

#

That too

grizzled sonnet
elfin berryBOT
marsh citrusBOT
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buoyant jetty
marsh citrusBOT
buoyant jetty
marsh citrusBOT
#

@buoyant jetty Has your question been resolved?

buoyant jetty
#

<@&286206848099549185>

wary lichen
#

the z values for the first condition are

z = 1, z = -1, z = i, z = -i

sooo, in easier terms, the powers of i

#

we both speak spanish, lol

#

bueno, cuestion, no hay ningún argumento que corresponda a los argumentos de las potencias de i

#

esos son arg(z) = 0, π/2, π, and 3π/2

#

la unica que cumple con las condiciones es z_3 = i, que tiene parte imaginaria mayor a uno, pero su argumento no tiene nada que ver

elfin berryBOT
#

zzz0nnn

wary lichen
#

si entendes que las soluciones de z^n a una de estas ecuaciones forman un poligono de n lados, entonces resulta en que las aristas del "cuadrado" equivalen a las potencias de i

marsh citrusBOT
#

@buoyant jetty Has your question been resolved?

buoyant jetty
#

well

#

answer key says 5pi/8 and pi/8 bro

wary lichen
wary lichen
buoyant jetty
#

ye, I think I will try it again tomorrow bro ded is too late today

#

or maybe I will leave it open idk

#

like there is some argument properties that we can use directly

#

no need to use demoivre mayhaps

#

idk

craggy terrace
solar heron
#

@buoyant jetty the first thing that we did was evaluate $(1+i)^{10} = 32i$. Once we had that, then we knew that we had to divide the argument of this complex number by $4$ to obtain the first positive solution of $\pi/8$. There are definitely four solutions to the problem, but only two of the angles have $Im(z)>0$, so the other solution must be $5\pi/8$

elfin berryBOT
marsh citrusBOT
#

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marsh citrusBOT
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wispy ledge
marsh citrusBOT
wispy ledge
#

Is ii right?

crystal lintel
#

,rotate

elfin berryBOT
marsh citrusBOT
#

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ruby matrix
#

hi i dont understand how the bottom inequality is achieved

vocal rune
#

How many fractions are there in the middle?

#

And can you find an easy lower and upper bound for these fractions.

ruby matrix
#

i tried doing this

#

but i dont see why it can be generalized

vocal rune
#

From 2^n to 2^(n+1) - 1, there are 2^n numbers, so you have 2^n fractions in the middle. Do you agree?

ruby matrix
#

yep

vocal rune
#

Each fraction in the summation gets smaller, so 1/(2^n) > 1/(2^n + 1) > ... > 1/(2^(n+1) - 1)

#

An upper bound for all these fractions is 1/(2^n), so the sum is at most 2^n * 1/(2^n) = 1

#

Because we have n>1,, we have at least 1 fraction smaller than 1/(2^n), so the sum is strictly lower than 1.

#

A lower bound for these fraction is 1/(2^(n+1)), so their sum is bigger than 2^n * 1/(2^(n+1)) = 1/2

ruby matrix
#

hmm let me digest this first

#

thanks so much

marsh citrusBOT
#

@ruby matrix Has your question been resolved?

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cunning oak
#

suppose we write down all the permutations of all the arrangements in the letters in MATHEMATICS, and rearrange that in alphabetical order. what would be the 92nd permutation?

cunning oak
#

not sure what to do

marsh citrusBOT
#

@cunning oak Has your question been resolved?

cunning oak
#

<@&286206848099549185>

#

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devout mauve
#

divide num and denominator by x

#

if you then "plug in" x=0 you would have number/0 which doesnt exist unless the number is 0

small stream
#

Ooh I guess that I understand

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small stream
#

Why is it 0?

marsh citrusBOT
glass silo
#

How do you have o(x^3) defined? pikathink

small stream
glass silo
#

At which point, dividing both numerator and denominator terms by x^3, the numerator still goes to 0, the denominator goes to -25/2, which is nonzero nyaTease1

marsh citrusBOT
#

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small stream
#

Thanks charbit!

marsh citrusBOT
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full arrow
marsh citrusBOT
full arrow
#

i tried this and got sinxcosx + 1

#

not sure how to do this one

late geode
#

can you show your attempt

full arrow
full arrow
late geode
#

it might be better to start from the more complicated right side

valid wing
#

have you tried making a2-b2?

full arrow
full arrow
#

not any closer sadly

valid wing
valid wing
#

no wait nvm

full arrow
valid wing
#

it won’t work anyway so its ok

clear basin
# full arrow how

i'd let tan = sinx/cosx and i'd let secx = 1/cosx and then substitute

#

then you should get a big RHS, you can then simplify it down and get the answer, i just did it @full arrow

#

let me know if you need help

full arrow
#

ill give it a try.

#

so to clarify, the general good approach in sums like these would be to tackle the trickier side right

#

as its easier to simplify

clear basin
#

but from what i've learned that's the case

marsh citrusBOT
#

@full arrow Has your question been resolved?

full arrow
#

giving it a try right now!

clear basin
#

because i might not see

full arrow
#

i reach here

#

@clear basin

#

how do i simplify furhter?

full arrow
clear basin
#

i combined the two photos without realising

#

im sorry 💀

full arrow
#

haha all good

#

😭

#

hopefully someone else can figure it out

grand radish
#

@full arrow Still need help?

grand radish
#

^RHS

#

in numerator

marsh citrusBOT
#

@full arrow Has your question been resolved?

marsh citrusBOT
#
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timid mesa
#

$\int_{0}^{\frac{1}{2}}\int_{0}^{x}\frac{1}{x}\times \frac{1}{1-y}dydx$

elfin berryBOT
timid mesa
#

Can I get an explanation on how to evaluate this?

#

I'm not really sure where to start.

#

Oh also it's like the first or the second time using this bot so correct me for wrong uses

lucid zenith
#

Also use \dd{x} for differentials

timid mesa
lucid zenith
#

$\int_0^\frac1{2}\int_0^x\frac{\dd{y}\dd{x}}{x(1-y)}$

elfin berryBOT
#

kheerii

lucid zenith
#

Anyways you can write this as an iterated integral

timid mesa
#

I haven't heard of it, is it about the notation or how to go about solving it?
would like to hear more about it or get related resources either way.

lucid zenith
#

The inner integral can be worked out easily because it's just in terms of y

elfin berryBOT
#

kheerii

timid mesa
elfin berryBOT
timid mesa
#

like this?

marsh citrusBOT
#

@timid mesa Has your question been resolved?

marsh citrusBOT
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light cloak
#

does anyone know why we combined (2) and the first two equations in (3) and not just all three equations in (3)?

wheat carbon
#

where do u see that

gloomy merlin
#

Including it would be redundant in that sense

light cloak
#

oh damn great observation

#

thank you

#

.close

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sinful hinge
#

Hi! I'm supposed to prove inequalities like these using the Mean Value Theorem, but am stuck on what to pick for f(x). Does anyone know how to pick an appropriate f(x) to go off of?

marsh citrusBOT
#

@sinful hinge Has your question been resolved?

proud ice
#

@sinful hinge choose any two integers that surround r

sinful hinge
#

what do you mean by that??

#

Maybe I didn't word it right, but my professor solves it by making a function f(t). I'm just trying to figure out how to decide on what it would be

proud ice
#

If i recall, bernoullis inequality is just $1+nx\le (1+x)^n$ for $n\in\bN$, right?

elfin berryBOT
sinful hinge
#

yes

#

wait it mightve been n > 1

proud ice
#

Naw it still works for n=1

sinful hinge
#

oo okay

proud ice
#

Okay now let's consider $r$. We are given $r>1$. So if $r$ is an integer, then $r\in\bN$, and we just have bernoulli inequality. So now let's consider when $r$ is not an integer. I forget the name of the identity, but we know that there exists an $n\in\bN$ such that $n-1<r<n$

elfin berryBOT
proud ice
#

Hmm

sinful hinge
#

okay?? i'm sorry if im not seeing the big picture here but i dont really get it right now

proud ice
#

This might not lead where i wanted it to lead

sinful hinge
#

😢

#

i was supposed to solve it using mvt!! if that helps a little

#

i dont know if wht you were doing leads to that

proud ice
#

These are easy to prove with Taylor series but yeah mvt is baffling

sinful hinge
#

😢

proud ice
#

Yeah i was trying to use mvt, and the idea i had i thought would work, but it doesn't really use the "1+rx" part

#

Damn

sinful hinge
#

if you want i can show you how my professor did it 😭 though i'm more so wondering how to get the thought process of solving inequalities like these myself

proud ice
#

Yeah what did your prof do

sinful hinge
#

so she does this (continuation is her doing it for the (iii) part, too)

#

i just wondered why she picked f(t)=(1+t)^r for this case, but for an example question she ended up using f(z) = z - sin z

#

like based on what do we pick an f(t)? is kind of the root of my question i guess

#

the rest of it i can draw conclusions on why she'd do it, but its just that specific part that confuses me

#

do we pick just pick any function thats differentiable on (a,b) and continuous on [a,b] (did i say it right?)?

proud ice
#

I'm still here. I'm just reading it through

#

I think i see the idea, but i must be sure

sinful hinge
proud ice
#

Okay i see what she did for the proof to a)

sinful hinge
#

ive tried watching so many videos but nobody really explains how they come up with their functions 😢

proud ice
#

It'll take a bit of writing to explain, and i am on mobile right now, so I'll have to wait until i get to my pc

sinful hinge
proud ice
#

I also have to bake some pies today for thanksgiving, so permit me some time to get back to you for a proper response

sinful hinge
#

i might close this channel if nobody else decides to answer. its getting a bit late here 😞 but i really appreciate you trying to help!!

proud ice
#

@sinful hinge okay here's what I can figure out

#

For part a, you prof broke down into three cases, the x=0 case, I imagine you do not need help with

proud ice
#

so let's look at her $x\in(0, 1)$ case

elfin berryBOT
sinful hinge
#

yess

proud ice
#

She's going to use MVT in the interval $[x, 0]$. For this, she is chosing any $c\in(x, 0)$ (it will be important to us later to rememberthat this means $x<c<0$, so just keepo that in mind)

elfin berryBOT
proud ice
#

Oops: correction, she is not "choosing" a $c\in(x, 0)$

elfin berryBOT
proud ice
#

She is saying that a specific $c\in(x, 0)$ $\textbf{exists}$ such that it satisfies the MVT condition $\frac{f(0)-f(x)}{0-x}=f'(c)$

elfin berryBOT
proud ice
#

We recall that $f(x)=(1+x)^r$, and we can thus calculate $f(0)=1$ and $f'(c)=r(1+c)^{r-1}$.

nocturne dune
#

Help

proud ice
marsh citrusBOT
elfin berryBOT
proud ice
elfin berryBOT
proud ice
#

Does all of that jive with you so far, @sinful hinge?

sinful hinge
#

yess

#

Here's the continuation by the way, in which I'm honestly starting to not understand why she does certain things

sinful hinge
#

as in why show r(1+c)^{r-1} < r, and the entirety of what's below 'Then,'

proud ice
#

We can multiply both sides by $-x$, giving us $1-(1+x)^r=-rx(1+c)^{r-1}$. Then we can rearrange some terms to get $$1+rx(1+c)^{r-1}=(1+x)^r$$

elfin berryBOT
proud ice
#

That's just some simple algebra, so I hope that at least that much is easy to understand right now

sinful hinge
#

oh my god i see it

#

youre right 😭 i understand the entire bottom part now!!! thank you

#

just a tiiny little question.. whats the reason behind choosing the interval [x,0]? i'd understand it for part (iii) where she's looking at x>0, as in that the interval would (hopefully...) be [0,x], but i'd had thought this one would have something to do with the -1

#

to be entirely honest, i'm really sleepy so i might just overlook something really obvious right now so im sorry if its a really dumb question

#

as in i thought the interval would be [-1,x]

proud ice
sinful hinge
#

i think i'll just have to bombard my professor with alot of questions this time

#

😞 MVT.... my enemy

#

Thank you so much for helping me, though @proud ice. I appreciated it alot!! But I think I'm going to dip for tonight and rest up

#

.close

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buoyant jetty
#

The tangent line to the graph of ( f(x) = (ax + 2)e^{ax} ) at the point ( (0, 2) ) is given by ( y = 6x + 2 ). Then ( a ) is:

[
\boxed{2} \quad \boxed{-2} \quad \boxed{-4} \quad \boxed{4}
]

elfin berryBOT
#

Renato Chavez

buoyant jetty
#

the tangent line at a point (0, 2) is the first degree taylor polynomial centered around zero

#

y = f(x_0) + f'(x_0)(x-x_0)

#

y = 6x + 2 = f(0) + f'(0)(x-0)

#

y = 6x + 2 = f(0) + xf'(0)

#

f(0) = 2

#

f'(0) = 6

odd crest
#

if you take the derivative of f

#

and then fill in x = 0

#

is there an a left?

buoyant jetty
#

product rule + chain rule

#

,, f'(x) = ae^{ax} + a(ax+2)e^{ax}

elfin berryBOT
#

Renato Chavez

buoyant jetty
#

,, f'(0) = a + 2a

elfin berryBOT
#

Renato Chavez

odd crest
#

yes

#

and so now you know y

#

f(0)

buoyant jetty
#

a = 3

odd crest
#

and have an expression for f'(0)

buoyant jetty
#

hmm

#

I am trying

#

6 = 3a

#

6/3 = a

#

,calc 6/3

elfin berryBOT
#

Result:

2
buoyant jetty
#

a = 2

#

ty kat

buoyant jetty
#

I guess this is it

#

.close

marsh citrusBOT
#
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hoary lake
#

hi I don't understand what they did to get this particular line

hoary lake
#

just for some background im going into physics fresh and don't know the arithmetic

#

specifically this part

distant peak
hoary lake
distant peak
#

all the things that are written before the equation you underlined in red

hoary lake
#

can you write out the equation for me

#

Im not sure I understand

distant peak
#

0.3 × 380 (T_f - 80) + 0.2 × 4200 (T_f - 20) = 0

hoary lake
#

like what was added to get 9120 and 16800

#

give me a second to read that

hoary lake
#

not the whole line

#

I get that 114 is from 0.3*380

distant peak
#

114 T_f - 9120

#

not T_f - 9120

hoary lake
copper raven
elfin berryBOT
#

Result:

-9120
copper raven
#

,calc0.2 * 4200 * -20

elfin berryBOT
#

Result:

-16800
hoary lake
distant peak
#

expanding

#

0.3 × 380 (T_f - 80) = 0.3 × 380 T_f - 0.3 × 380 × (-80)

hoary lake
#

so you distributed the values from the first two sets of brackets into the third?

distant peak
#

well yea

#

a(b+c) = ab+ac

hoary lake
#

why don't you distribute the 3rd into the second and change that value

distant peak
#

3rd what

hoary lake
#

is there a good article or video I can use to refresh my memory on this

distant peak
#

look for algebra course on khan academy I guess

hoary lake
#

expanding?

distant peak
#

algebraic expression

hoary lake
#

damn 6th grade math I feel like a late french person

#

alright Ill look into that

#

oh i already know this

#

the reason why im so confused is because somehow the tf is now outside the bracket

#

and now it's minus some other number that's from multiplying two other numbers

#

so why isn't tf affected why is it still tf

copper raven
hoary lake
#

so why is it next line there is only one tf instead of two

copper raven
#

with the 954 you mean ?

hoary lake
#

what with the 954?

copper raven
#

the line starting with 954

#

when you say "next line"

hoary lake
#

oh yeah that one

copper raven
#

yeah well they just rounded up all the Tf's they got

#

114 Tf's + 840 Tf's

#

,calc 114+840

elfin berryBOT
#

Result:

954
copper raven
#

that's 954 Tf's

hoary lake
copper raven
#

well the goal is to get Tf alone

#

then we know it's value

#

that's why they're doing all of this

#

to find what Tf is

hoary lake
#

wait a second

#

Recall, both Tf values will be the same because the mixture of water and brass will come to an equilibrium temperature.

copper raven
#

yea

hoary lake
#

okay I get it more

#

give me a second to think

#

why is it (114)(tf) and not 114tf

copper raven
#

weird formatting on their part idk

hoary lake
#

do you mind if I complete it on my own and then close the ticket

copper raven
#

I guess it's confusing if you remove the parentheses and keep the units

#

114 J/°CTf now it's barely readable

copper raven
#

there's no time limit as long as you speak a bit in the channel

hoary lake
#

ok

#

I got it but ill keep it open for a second just in case

#

but close it soon

marsh citrusBOT
#

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versed agate
#

I don’t understand equations of a line with a curve

versed agate
#

I don’t know how to write the the equation

wary inlet
#

need an example

marsh citrusBOT
#

@versed agate Has your question been resolved?

weary condor
#

Cant really find the equation of a curve can you

#

Unless maybe its a sin wave or logarithmic or something like that but also you cant be sure

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void iron
#

so im on the circled step, however i'm not sure how the hell you get to the next few

wary inlet
#

25-25 =0

#

then divide h cause it’s in the numerator and denominator

#

then plug in 0 for h to evaluate the limit

void iron
#

so im actually just clueless

#

my god

wary inlet
#

😭😭

void iron
#

😭

wary inlet
void iron
#

alright i appreciate the support lol

wary inlet
#

all g

void iron
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sonic palm
#

would this be correct?

marsh citrusBOT
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mild hearth
#

Let $\omega$ be the principal root of $z^7=1$ \newline Find the exact value of the following: \newline $(1+\omega+\omega^2)^7+(1+\omega)^7(1+\omega^2)^7$

elfin berryBOT
mild hearth
#

is there a trick to do this without letting w=e^i(2pi/7) ?

#

cos the answer is just 0

mild hearth
elfin berryBOT
marsh citrusBOT
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@mild hearth Has your question been resolved?

cunning fiber
# mild hearth is there a trick to do this without letting w=e^i(2pi/7) ?

Using geometric series, this is the same as $$\frac{1}{(\omega-1)^7} [(\omega^3 - 1)^7+(\omega^4 -1)^7]$$ $$=\frac{1}{(\omega-1)^7} \left[ \left(\omega^3-1 \right)^7+\left(\frac{1}{\omega^3} -1 \right)^7 \right]$$ By symmetry, this is the same as $$\frac{1}{(\omega^5-1)^7} \left[(\omega-1)^7+\left(\frac{1}{\omega}-1 \right)^7 \right]$$

elfin berryBOT
#

Civil Service Pigeon

cunning fiber
#

See if you can finish it from here

marsh citrusBOT
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mild hearth
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latent whale
#

@mild hearth I can't speak for the person above but I didn't need to use geometric series for this

latent whale
#

I would also mention that with some substitution and factoring I was able to get a form of (F1 (w)) * (F2 (w)) where F1 and F2 are polynomials with respect to w, and you can show that one of them must reduce to 0 so the whole thing is 0

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drowsy stirrup
#

if A is a matrix is 3A = A3 true?

marsh citrusBOT
drowsy stirrup
#

ty

#

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amber birch
#

it's just matrix multiplication where changing the order would give you a different answer

drowsy stirrup
#

.reopen

marsh citrusBOT
#

drowsy stirrup
#

wait so if its like matrix multiplication then 3A =/= A3

drowsy stirrup
amber birch
#

otherwise yeah that multiplication is impossible

#

this is the rule btw

drowsy stirrup
#

ok i get it

#

thanks man

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faint birch
#

Im supposed to use either direct comparison or limit comparison. Every graph ive thought of for comparison felt like i was getting an inconclusive result. For #21

faint birch
#

I know that if the bigger expression converges, then the smaller one if its the original one converges too.

I know that if the smaller one diverges, and the original one is bigger, it diverges too

#

I guess i could try limit comparison maybe? I think if i use 1/n, i could use lhospitals rule?

#

This is what AI said lol

quaint hill
#

.close

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simple pollen
#

How can I solve this question? The ramps height is sin(10) * 3.5m = 0.6077686m

simple pollen
#

the energy gained by the box is mgh = 9.81m/s^2 * 10kg * 0.6077686m = 59.6221018 Joules

#

I would try W = F * d = 200N * 3.5m but that doesn't seem right

#

200N * 3.5m * sin(10) gives 121.553724 Joules, which would give an efficiency of 49.05%, but I am not sure if that is correct

#

the normal force on the box should push with a force of 10kg * 9.81m/s^2 * sin(10) = 17.0348862N down the ramp

rocky lark
#

How did you find the height of the ramp?

simple pollen
rocky lark
#

What does that 30 in the figure represent

simple pollen
rocky lark
#

Ah

#

The box starts from the bottom, right?

simple pollen
#

yes

rocky lark
#

Is there no friction?

simple pollen
#

there is no friction on this ramp, there is the normal force from gravity

rocky lark
#

What do you have to find?

#

@simple pollen

simple pollen
#

how effiecient is the ramp to lift the box

#

output-energy / input-energy

rocky lark
#

But does the box have to reach up to the top?

simple pollen
#

yes, it will travel ramps length of 3.5 meters

rocky lark
#

But here we assume v_0=0?

#

@simple pollen

simple pollen
#

I doubt velocity is relevant

#

same with acceleration

#

how do i calculate the efficiecny of the ramp?

rocky lark
#

You had to calculate the work of the applied force and that of the weight force

simple pollen
rocky lark
#

along the ramp

#

d

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#

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rigid lodge
#

Hi, I need a little (lot) of help here. I'm reading Bartle's book on Lebesgue Integration so Phi and Psi are simple functions

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#

@rigid lodge Has your question been resolved?

devout mauve
#

you need to be more specific about what you need help with

#

have you done a sketch of these functions?

rigid lodge
marsh citrusBOT
#

@rigid lodge Has your question been resolved?

static quarry
#

note that the representation for phi + psi is not necessarily the standard one

marsh citrusBOT
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haughty token
#

hi

marsh citrusBOT
haughty token
#

whats the easiest out of these?

rugged spindle
#

the easiest ones are definitely trigonometry, applied statistics (assuming it's not calc based, still would be rather easy if it was), then calculus 1 and 2

haughty token
#

i should go for calc 2 next? is the the easiest?

rugged spindle
#

then probably calc 2 or linear algebra, but probably calc 2 first

#

unless linear algebra is a proof-based course (some colleges have their introductory linear algebra courses be proof-based, other have theirs computation based), then it might be pretty much same level as discrete math

haughty token
#

what about numerical analysis

rugged spindle
#

i'm not sure what exactly it is by that name

#

if it's supposed real analysis, then it's far more difficult than calc 2

still temple
#

I think "numerical analysis" is when you study computational methods for doing integration, solving ODEs/PDEs, and so forth

So yea probably on the more advanced side

haughty token
#

alright

#

calc 2 then ig

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still temple
#

please ive tried these problems all day and i dont know how to do it. i just want some extra credits😭

amber birch
elfin berryBOT
#

southlander!

still temple
#

no i have no idea what his mean or how to start

amber birch
#

or your textbook

still temple
#

okk i will try this

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gentle owl
marsh citrusBOT
gentle owl
#

I have no clue what this means

#

Can someone send resources for me to understand?

#

Like 0 clue where to even begin this

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light crown
#

having trouble integrating after i substiute w

wraith elm
#

trig sub?

#

w = 7 sin theta

#

dw = 7 cos theta (dtheta)

#

so then its (98 * 7 cos theta d theta)/(7 sin theta)^2 * sqrt(49-(7sintheta)^2))

#

you can simplify the radical into 7 cos theta

#

and then cross out with the top and then 98/49 = 2

light crown
#

i managed to reduce to 2 intgrl 1/sin^2 theta

wraith elm
#

oh okay that's right

#

then you get 2csc^2theta

light crown
#

and yea i used trig sub

wraith elm
#

do you know integral of csc^2theta

light crown
#

no

#

thats where im stuck

#

is it -cotx?

wraith elm
#

yeah

#

u can usub to prove it

#

but its helpful to just memorize unless u need to profve it for somethign

light crown
#

thank you king

#

i like ur pfp

#

.solved

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modest scarab
#

In the formula
P (X = k) = ( nk ) ⋅ p^k ⋅ (1 – p)^n – k, (nk) means n! / k! * (n - k)!
Why can ( nk ) be used to calclulate how many paths there are for k, I understood why the other stuff makes sense just not the ( nk )

modest scarab
#

ohhhhh

#

I wondered where this help channel was, It was just closees so I thought none was created

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.close

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still temple
#

There are 100 patients in a hospital. Some (an even number) are one-legged but wearing shoes. One-half of the remainder are barefooted. How many shoes are being worn?

cunning oak
#

sorry, but does this imply half of the remainer wears shoes?

#

never learnt this

still temple
#

umm

#

Ig the remainder the question says are all those except one-legged + wearing shoes?

cunning oak
#

well the remainder could be wearing one shoe also

still temple
#

wait I got 100

#

bruh

#

it's 100 shoes?

#

is it really 100 and why do they mention even number? It shouldn't make a difference, right?

weary thistle
#

Because if it’s odd then there is odd number of two leg patients remaining and half of that would be a decimal

still temple
#

x + 2 . (100-x)/2 is 100 regardless of x being odd or even though but yea

weary thistle
#

It is it’s just the example wouldn’t make sense if the number of one legs wasn’t even

still temple
#

ok

#

ty

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robust mountain
#

could someone verify if i have done these correctly ? particuloarly part ii and iv

robust mountain
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abstract hull
#

`perimeter of triangle is 10m if one side is 4m what are the other 2 sides of the triangle for its maximum area

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abstract hull
#

<@&286206848099549185>

crystal lagoon
#

Because we know that equilateral triangles have the most area per perimeter, followed by isosceles

#

Unless I'm wrong on the isosceles one then it's just both 3/3

abstract hull
crystal lagoon
#

x+y=6 then do simultaneous with heron's formula

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fickle shell