#help-33

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proud arch
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And go on from there

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@tawdry rampart

tawdry rampart
proud arch
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Oh I tagged you accidentally

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Sorry

tawdry rampart
#

Np bro

hasty briar
marsh citrusBOT
#

@hasty briar Has your question been resolved?

hasty briar
#

eeeeeeeeeeeeeeeeeeeeee

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<@&286206848099549185>

marsh citrusBOT
#

@hasty briar Has your question been resolved?

hasty briar
#

uhh

limber trellis
# hasty briar how

if u take z = x + iy the remaining part is a constant ( a |z-1|) and 2i

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so for it to be zero

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y must be -2i

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and x= -a|z-1|

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from there u can solve for p and q

hasty briar
limber trellis
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y must be -2 cuz the only other imaginary part 2

hasty briar
limber trellis
#

wdym

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|z| is always a real number its a value

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it cant have an imaginary part

hasty briar
limber trellis
#

it is πŸ—Ώ

limber trellis
limber trellis
#

so it always like a real value

hasty briar
#

okay then yes y = -2

limber trellis
#

ye

hasty briar
#

lemme try it

limber trellis
#

sure

hasty briar
#

how do i calculate the max and min value of a

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like differenciation method?

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@limber trellis

limber trellis
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if u use this u get a quadratic equation in x

hasty briar
#

yes

limber trellis
#

that quadratic eq shld have roots

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so D>= 0

hasty briar
#

but thats dependant on value of a

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wait

limber trellis
#

yes

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if u use b^2-4ac > 0

hasty briar
#

ONG

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RIGHT

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okay

limber trellis
#

then u will get a limit on a

hasty briar
#

jeezzim dum

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yesyes

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i got it

limber trellis
#

lmaoo

hasty briar
#

i did thnk abt the D

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but

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idk i didnt do it

limber trellis
#

isok just try it

hasty briar
#

yes leme

limber trellis
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let me know if u need any help

hasty briar
#

aaaaaa

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im not getting the right ans

limber trellis
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wait

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let me try

hasty briar
#

or u can check my ans

limber trellis
#

sure

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send it

hasty briar
#

instead of doing so much work

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eeeeeee im dum

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dont mind the writing πŸ™

limber trellis
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p it self is

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root over 5/4

hasty briar
#

what

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how

limber trellis
#

cuz that is the maximum value of a

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thats what theyre asking

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try taking p as root 5/4 and q as - root 5/4 and check

hasty briar
#

yes then we get the ans

limber trellis
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oh nice

hasty briar
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but how is a p

limber trellis
#

cuz they said p is max value a

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and a is cannot be more than root 5 /4

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so p is root 5/4

hasty briar
#

OH WAIT

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sory

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right

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i read the ques wroong

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i thought the roots were p and q

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aaaa

limber trellis
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lmao no worries it happens

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😭

hasty briar
#

okayokayy

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thankyou so much

limber trellis
#

your welcome

hasty briar
#

yyeyeyy

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thenksknss

limber trellis
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what grade r u in

limber trellis
hasty briar
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mentally im in 2nd

limber trellis
#

LMFAO

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😭

hasty briar
#

as u mustve figured it out already

limber trellis
#

😭 😭

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i can't 😭

hasty briar
#

stop laughing at me 😭

limber trellis
#

u bought this upon ur self

hasty briar
#

uff

limber trellis
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anyway i gtg now if u have any other doubts let me know

hasty briar
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okayayay

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thank youu

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bye

limber trellis
#

byee

hasty briar
#

.close

marsh citrusBOT
#
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molten ferry
#

how to find torque created by F2 and F3

marsh citrusBOT
molten ferry
hasty briar
#

about which point

molten ferry
hasty briar
molten ferry
#

the distance is diagonal in this case tho

hasty briar
#

axis is perpendicular tothe plane right?

molten ferry
hasty briar
#

it should be perpendicular to the plane only

molten ferry
#

oh the plane as in rectangle

hasty briar
#

so for f3, torque would be f3 x root 10

hasty briar
molten ferry
elfin berryBOT
molten ferry
#

for the net torque about A

hasty briar
#

no idts

molten ferry
#

like the first term is the torque by F1

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the second term is by F2 and third by F3

hasty briar
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and so is f2

molten ferry
#

isnt it only the perpendicular force that matters

hasty briar
#

yes but

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direction is also imp

molten ferry
#

wait would F2 not apply a torque

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it goes through the pivot

hasty briar
#

torque of f2 is in clockwise direction and anticlockwise both

molten ferry
#

they cancel?

hasty briar
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yes

molten ferry
#

alr and is the torque by F1 equal to 2Fsin(45)

hasty briar
#

yess

molten ferry
#

isnt it clockwise

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the torque created by F1

hasty briar
#

yes cw

molten ferry
#

so the net torque is $F-2F\sin45$

elfin berryBOT
hasty briar
#

f root 10

molten ferry
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why sqrt10

hasty briar
#

perpendicular dist of f3 from A

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is root 10

molten ferry
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so r=sqrt10

hasty briar
#

root ( 3^2 + 1^2)

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yes

molten ferry
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F=F

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theta=90

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ohhh i see

molten ferry
elfin berryBOT
hasty briar
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1/root 2

molten ferry
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sin45=sqrt2/2 tho

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and then times 2 is sqrt2

hasty briar
#

ohshit

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yes

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right

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sorry

molten ferry
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alr

molten ferry
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so is it this

marsh citrusBOT
#

@molten ferry Has your question been resolved?

hasty briar
#

@molten ferry wait

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im so sorry 😭

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i wasnt in my right mind

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for 1, torque by f3 would be F only

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as perpedicular dist is 1

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NOT root 10

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sorrryyyyy

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so sorry

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so for 1, it would be (1-root2)F

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and for 2, it would be 0

marsh citrusBOT
#
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obtuse plume
#

How can I find the normal of y = x + 1, with x being 2

limber hearth
#

When you mean normal, you want to find perpendicular line ?

pulsar trout
#

The slope of a normal is -1/m

obtuse plume
pulsar trout
#

Can you find the point at x=2 first

obtuse plume
#

Well the question asks us "Find the equation for the normal of the line where the point is x = 2. a) y = x + 1

pulsar trout
obtuse plume
#

3

pulsar trout
pulsar trout
# obtuse plume 3

Are you studying calc 1 or precalc
cause the answer to finding the slope would be vary

obtuse plume
#

Current chapter is about derivatives, asymptotes, limits and all that stuff

pulsar trout
#

So you haven't studied derivatives, right?

pulsar trout
obtuse plume
pulsar trout
#

Delta y / delta x is the average rate of change

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dy/dx is the instantaneous rate of change

obtuse plume
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I learned today that instead of finding the limit we can also just use ax^n+bx = anx^n-1+bx^1-1....

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yeah exactly so f(x+Ξ”x)-f(x)/Ξ”x

pulsar trout
#

So the slope of the normal will be -1/1 = -1

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You have a point and the slope
Can you find the normal to the function

obtuse plume
#

Just to confirm, to find the equation for a tangent we can use the derivated function to find a in y = ax+b, and then find b by plugging in (x,y) from the normal function, correct?

obtuse plume
marsh citrusBOT
#

@obtuse plume Has your question been resolved?

marsh citrusBOT
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@obtuse plume Has your question been resolved?

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frozen snow
#

I'm stuck, should I plug 4 and into the u formula and get new parameters? And is my process correct so far

glass silo
#

You could either change the limits for the integral to be in terms of u (and probably really should!), or you could convert the result you found back to the original variables and use that instead...

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Also where is that 1/60 coming from?

frozen snow
frozen snow
glass silo
frozen snow
glass silo
#

Well, you effectively have 100/0.6 that you're dealing with, which you want to simplify, right... catThink

frozen snow
#

why is the 0.6 in the denominator

glass silo
#

Because you have $\dd u = 0.6e^{0.6t} \dd t$ (you forgot the $\dd t$ in yours), which means that $\frac1{0.6e^{0.6t}} \dd u = \dd t$, so replacing the $\dd t$ in the integral you have gets you
[
\frac13 \int_1^4 \frac{100e^{0.6t} }{3 + e^{0.6t}} \dd t = \frac13 \int_{t = 1}^{t = 4} \frac{100 \cancel{e^{0.6t}} }{u} \frac1{0.6 \cancel{e^{0.6t}}} \dd u
]

elfin berryBOT
#

@glass silo

glass silo
#

(note that the limits in the second integral are actually the t values, rather than the u values, and so should be changed really!)

frozen snow
#

Okay I see it

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So 100/0.6 (1/u)

marsh citrusBOT
#

@frozen snow Has your question been resolved?

marsh citrusBOT
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round gorge
#

If you know the period and phase shift of a trigonometric function like sin cos, etc, how do you know what scale to put it in? I am struggling with knowing the best scale to use when plotting the function. For example, the image. The ps is -pi/6 and the period is 4pi. How do I know the scale of the graph

round gorge
#

my best answer is pi/12, but it seems too small

marsh citrusBOT
#

@round gorge Has your question been resolved?

round gorge
#

Any help?

solar heron
#

@round gorge what do you mean by "scale"? Do you mean the marks you want along the x-axis?

round gorge
solar heron
#

Let me think about that for a second

west vault
#

the first coefficent is a scale along y axis, coefficent inside sin is a scale along x axis

solar heron
#

I would think about the full period of your function. For example, this one is $4\pi$. Dividing this by 4 will give you how far you have to move along the x-axis (in this case) to hit the x-intercepts. And dividing by 8, gives placements for the maxes/mins. Not sure if that infor is helpful or not

elfin berryBOT
solar heron
#

So, start at $-\pi/6$, and move $48/8=6$ steps every time to find the important features

elfin berryBOT
round gorge
#

Thats what im confused about, I know how to plot the points if I have the steps labeled

marsh citrusBOT
#

@round gorge Has your question been resolved?

solar heron
round gorge
solar heron
#

ah i see the problem, 52/8 = 13/2

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but every even multiple will "take care" of the weird denominator we would get

round gorge
round gorge
solar heron
round gorge
#

.close

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novel bear
marsh citrusBOT
novel bear
#

I'm missing something and I can't quite figure it out

valid cape
#

the function approaches the same sign as x approaches 2

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so (x-2) should have an even power

#

similarly, the function approaches the opposite sign as x approaches 6, thus (x-2) should have an odd power

novel bear
#

when I put in a power for (x-6) the graph gets wonky

#

for example

valid cape
#

uh, you might want to zoom in a bit btw

novel bear
#

this good?

valid cape
#

try putting in a minus sign before the function

novel bear
#

oh lord

valid cape
#

uhhh

#

i mean the whole function

novel bear
#

ohhh

#

thank god

#

No

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thank 🐏 π“πŸŒΊβ™‘π“‰π’Έπ“‡π‘’π“…π‘’π“ˆ ^.^ πŸŽ€

valid cape
#

and there you go

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rocky nova
#

If I have a group like Z^*_p where p is a prime number is any int 1 to n-1 a generator for the set?

rocky nova
brave marsh
#

No. In general it's not 'easy' to find generators to Z*p.

#

1 clearly isn't

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And for instance in $\Z_{11}^*$, $3$ isn't a generator.

elfin berryBOT
#

Azyrashacorki

rocky nova
#

how do you know that so fast though @brave marsh

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for 3 not being a generator

brave marsh
#

It's just a common example.

rocky nova
#

gotcha thank you

#

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heavy blade
#

im confused by both questions...
for part a, from my understanding of a unique solution is that the determinant when u inverse the matrix is 0 but when i found the determinant in this case it was 0... so im not even sure....?

for part b, I converted the matrix to 3 planes and choose 2 planes to find a line by eliminating a variable and i did that twice and both the lines i found where the same so it proves it is consistent but how do i show for the second part of b?

marsh peak
#

What do you mean by "when you inverse the matrix is 0"? Can you name a matrix whose inverse happens to be the zero matrix?

heavy blade
marsh peak
#

You can't invert a matrix with determinant 0

heavy blade
#

oh? so what would i do here?

marsh peak
#

A linear system of n equations and n variables does not have a unique solution iff the determinant of the matrix is 0, so you have already shown part a

heavy blade
marsh peak
#

Yeah

heavy blade
# marsh peak Yeah

ahhh ok i get it, but for part b where it says to show that the general solution can be written as that, if the determinant is 0 how would i show that the general solution is that?

marsh peak
#

Just solve the system, augment the matrix and row reduce or whatever you prefer

heavy blade
#

.close

marsh citrusBOT
#
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golden cosmos
#

is there a difference between line integral of scalar funtions and line integral of a vector field

golden cosmos
#

like in terms of computation

#

cause they seem to be the same

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#

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limber oasis
marsh citrusBOT
limber oasis
#

stared for an hour

faint narwhal
#

||B||

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Let Q approach S

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||Then OQR is 40||, ||and x is 90+40||

limber oasis
#

whered u get 90

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i understand the 40

faint narwhal
#

T’ is tangent to the circle

limber oasis
#

OH

faint narwhal
late geode
#

inscribed angle theorem is simpler

#

consider that inscribed angle <SQR
and central angle <SOR
are subtended by the same arc

marsh citrusBOT
#

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lethal lodge
#

prove by induction that: $10^{n-4} < n!\ \forall n\ge 9$

elfin berryBOT
faint narwhal
#

I mean the left side is always only multiplying 10, and n! After n=9, it is always multiplying 10 and higher, just solve that 10^5 smaller than 9!

lethal lodge
#

but that's not induction

#

you are just taking a case

faint narwhal
#

Oh that isn’t?

#

Oki

lethal lodge
#

oh nvm i done it

#

it was easy af xd

#

.close

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#
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keen gulch
#

I am stuck there: how do I solve that limit without Hopital Theorem?

late geode
#

,rotate

elfin berryBOT
faint narwhal
#

Wt is nim

keen gulch
#

nim?

faint narwhal
#

Nvm

late geode
#

nin?

#

that writing is poor,
is that supposed to be sin

#

or something else

keen gulch
#

I use t cause x tends to pi/4, which is not helpfull for using notable limits

keen gulch
keen gulch
late geode
#

just making sure, it doesn't look anything close to an s
all the other letters looked fine

anyway, after doing that sub, use the compound/difference identities

keen gulch
#

The what?

quaint elm
#

,tex .sum diff trig

keen gulch
#

Like multiplying for (cosX + sinX)?

elfin berryBOT
#

hayley is stateside!!

quaint elm
#

those?

keen gulch
#

Alr but what if i can't?

#

is there any other solution?

late geode
#

what are you expecting

keen gulch
late geode
#

i mean what method are you expecting

keen gulch
#

Notable limits i think

late geode
#

yeh, start with what i mentioned

#

notable limits come after that

keen gulch
late geode
#

did you try starting with conjugates

#

that would be another way to approach it

keen gulch
keen gulch
# keen gulch

That is the way you suggested me to do, and is an approach that i can use but i'd like to know if i can find an other approach

keen gulch
late geode
#

show what you managed to do

keen gulch
#

It's bad written, let me re-write for better understanding

#

(cosx + sinx) is not a problem of the limit cause it's a costant, it's not 0

#

And i think that i have complicated the limit by doing so and not simplified it...

late geode
#

use the sub from earlier

#

or you could use conjugates after doing the sub,
order doesn't really matter

keen gulch
#

where should i use the sub on the limit?
You mean, replace the x with t (so that t tends to 0) and then use the sub equation again?

late geode
#

use the
t = x - pi/4
idea

keen gulch
#

Yeah, but i still have to use the sub equation to solve this exercise.
I was just wondering if there is an other approach other than this and Hoptial

late geode
#

none that i can be bothered thinking about
some trig identities/properties will be involved

keen gulch
#

So, we always talk about goniometric proprieties, right?

#

I mean, i was wondering if this exercise could be solved without goniometric proprieties (like a polynomial limit) but i think that it's not possible

#

i have to use goniometric proprieties for sure

#

Alr, thank you for your help and your time : )

#

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#
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zinc heart
#

What makes a function continous and differentiable on a close interval and also what makes it not?

devout mauve
#

it needs to satisfy the relevant definitions

#

tho I feel that will be unsatisfying

#

what kind of answer do you want to hear?

zinc heart
#

I guess just cases where the function wouldn't be continous or differentiable

devout mauve
#

do you mean like visually from the graph?

zinc heart
#

Yeah

#

or in the equation

#

either or

devout mauve
#

its not continuous if there is for example a jump

#

and not differentiable if there is for example a corner (like in |x|)

zinc heart
#

holes in the functions for limits, asymptotes, jumps

#

those are discontinuities?

devout mauve
#

yes

zinc heart
#

what about like sharp points if that makes any sense

zinc heart
#

oh sorry

#

missed that

#

but how come that isnt continious

devout mauve
#

it is continuous

#

but not differentiable

zinc heart
#

How come

devout mauve
#

the slope jumps

zinc heart
#

but like mathematically why

#

and sorry if this is tedious im just trying to get a better understanding of math in general

devout mauve
#

the relevant limit doesnt exist

marsh citrusBOT
#

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marsh citrusBOT
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marsh citrusBOT
#

@cyan pasture Has your question been resolved?

kind ridge
#

looks correct to me

tawdry rampart
#

DOPPELGANGER TYPE SHIT

marsh citrusBOT
#

@cyan pasture Has your question been resolved?

limber trellis
#

😭

tawdry rampart
#

And this are 2 different ppl lol

kind ridge
#

hehe

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#

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@cyan pasture Has your question been resolved?

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sacred leaf
#

I need help in Calculus 3, I dont understand what other points can be min or max:

sacred leaf
#

So if found the max and min for the boundary (max = 5 at (1,0) and min= -7 at (-1,1))

#

<@&286206848099549185>

floral abyss
#

you should get the derivative in the different variable

marsh citrusBOT
#

@sacred leaf Has your question been resolved?

sacred leaf
#

which derivative fx or fy?

floral abyss
#

let me see

floral abyss
#

ok

#

get both partial derivatives

#

respecto to x, and respect to y

#

then make each of them = 0

sacred leaf
#

yeah fx = 15x^2 -4y =0

#

fy = -4x -12y =0

floral abyss
#

you have a system of 2 equations with 2 unknown values, x and y

#

if you divide the 2nd eq by 3 and add it to the first eq

#

you'll get an eq to resolve with the (-b+-sqrt(b^2-4ac)/2a)

#

there you have two potential values for your minimum/maximums in x

#

same with y

sacred leaf
#

They will be the critical points?

floral abyss
#

I've gotten x1=0, x2=-8/90

#

yep

#

let me see with y

#

0and -4/135

#

I think

#

now replace those values in the main function

#

and you'll get your values

sacred leaf
#

it gives -0.019 which is not a minimum no? since I got a min of -7 with the boundary

floral abyss
#

the second value of y doesn't apply

#

is negative

#

there's your function

#

Finding the critical points: Calculate the partial derivatives of the function and set each derivative equal to zero to find the critical points (a, b).

Use the second derivative test: Define the determinant D = βˆ‚Β²f/βˆ‚xΒ² βˆ‚Β²f/βˆ‚yΒ² - (βˆ‚Β²f/βˆ‚xβˆ‚y)Β². Evaluate D and the partial derivatives at the critical points:

If D > 0 and βˆ‚Β²f/βˆ‚xΒ² > 0, then there is a local minimum at (a, b).
If D > 0 and βˆ‚Β²f/βˆ‚xΒ² < 0, then there is a local maximum at (a, b).
If D < 0, there is a saddle point at (a, b).

sacred leaf
#

.close

marsh citrusBOT
#
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sweet quarry
#

Is this right?

marsh citrusBOT
sweet quarry
#

Here’s a better image

#

<@&286206848099549185>

ornate girder
#

I believe you need to convert to radians first

sweet quarry
#

Yea that’s what I did

ornate girder
#

oh, sorry, hard to tell with the picture

sweet quarry
#

60 degrees is pi/3

ornate girder
#

right yeah

sweet quarry
#

Yea it’s kinda messy srry

sweet quarry
#

.close

marsh citrusBOT
#
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red tartan
#

hi guys, In the concavity should I take into account -1 and 2 or should I not? because in the domain doesn't take it into account

marsh citrusBOT
#

@red tartan Has your question been resolved?

red tartan
#

<@&286206848099549185>

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deft hawk
#

My highschool teacher told me to solve this problem by parts, but does anyone know how i could solve it, bec i tried many times

brave marsh
#

I think a substitution first could make it a bit simpler before IBP

amber birch
#

indeed sub in $u = x^2$ first

elfin berryBOT
#

south, just south

amber birch
#

THEN do IBP

marsh citrusBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
vast shoal
#

Oh mb network

marsh citrusBOT
#

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marsh citrusBOT
#
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still parrot
#

i dont understand why this is wrong

marsh citrusBOT
still parrot
#

i plugged in pi over 6 to all the x values

#

and got pi/6 (sqrt3 / 2) - (1/2) over (pi/6)^2

#

so i cancelled one of the pi/6

#

to get (sqrt3 / 2) - (1/2) over (pi/6)

#

then multiplied top and bottom by two

#

to get (sqrt 3) - (1) over (pi/3)

#

and then the final answer

#

what did i do wrong

brave marsh
#

From what you're describing you're going from $\frac{\frac{\pi}{6}\cdot \frac{\sqrt{3}}{2} - \frac{1}{2}}{\frac{\pi^2}{6^2}}$ to $\frac{\frac{\sqrt{3}}{2} - \frac{1}{2}}{\frac{\pi}{6}}$ which you can't do

elfin berryBOT
#

Azyrashacorki

main idol
#

There's no factor of x on the second term

still parrot
brave marsh
#

I'm actually surprised this compiled in one go

still parrot
#

wait then what am i supposed to do

brave marsh
#

You can still simplify both terms a bit, it depends how much the platform you're working on wants things to be simplified to the fullest

still parrot
#

i dont konw anymore

#

13pi (36 sqrt3) - 36 over 2pi^2?

#

its just all wrong

still parrot
#

cause its just pi/6 over (pi/6)^2 isnt it

brave marsh
#

Because pi/6 is only a factor of the first term in the numerator, not the second

still parrot
#

oh

#

ohh

#

thank you

brave marsh
#

Nw

still parrot
#

i still have no idea what the answer is tho

#

i cant tell if this website is wack or

marsh citrusBOT
#

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#
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gusty patio
#

I don't know how to even start this

marsh citrusBOT
meager acorn
#

e^x expansion?

#

Or maybe u can simply use L-Hospital also

red nimbus
#

sin(x) β‰ˆ x linear approximation around x = 0

gusty patio
#

Don't I need inf/inf or 0/0? I get here (1-inf)/0

#

Nvm I'm stupid, its 1-1/0

meager acorn
#

Mhm

gusty patio
#

$(e^{sinx})'=e^{cosx}*e^{sinx}$?

elfin berryBOT
meager acorn
#

Nop

red nimbus
#

Kind of

meager acorn
gusty patio
red nimbus
#

If you use the linear approximation you have the form 0/xΒ² = 0 remember x approaches 0 but never is

meager acorn
#

Not e^cosx

#

Just cosx

gusty patio
#

cosx*e^(sinx)?

meager acorn
#

Yes

gusty patio
#

Can you explain why? Bc I don't get it

red nimbus
#

chain rule

meager acorn
#

Ok so

#

Chain rule yes

#

Consider t=sinx

#

So then

#

e^sinx = e^t

#

Differentiate wrt to x

#

Ull get

#

dy/dx = e^t*dt/dx

#

dt/dx is cosx

gusty patio
#

Ok, now I get it thanks

#

$\lim_{x\to 0}\frac{e^x-e^{sinx}}{x^2} = \lim_{x\to 0}\frac{e^x-e^{sinx}cosx}{2x} = \lim_{x\to 0}\frac{e^x-e^{sinx}(cosx)^2+e^{sinx}*sinx}{2}$

elfin berryBOT
gusty patio
#

Is this correct?

#

$=\frac{1-11+10}{2}=0$

elfin berryBOT
marsh citrusBOT
#

@gusty patio Has your question been resolved?

marsh citrusBOT
#
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limpid beacon
#

How do I find the distance between C' and D'?
I tried using the pythagorean theorem but it gave me sqrt(45)

limpid beacon
#

I get sqrt(45) if I scale it to 3. If I don't, I get sqrt(5) instead. Which is useless?
Khan Academy says the distance is 6 for the scaled version. And I get sqrt(45) which is approximately 6,708203932

late geode
#

C' seems to refer to the point vertically below D'

#

the point you considered is E'

limpid beacon
#

oh shit

#

how tf did I not see that

#

oops sorry guys

#

brain fart moment

night blade
#

Can you like
Label which point is which better

#

Cuz rn, the way I see it is line C'D' just a vertical line

limpid beacon
#

yeah my bad I confused it with E'

#

sorry again guys

#

.close

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#
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night blade
#

And if that is the case, their distance is just 2 and line CD would be 6

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#
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still temple
marsh citrusBOT
still temple
#

Helloo!! I need help with the Honey Comb!!

#

It is difficult for me blobsweat

#

Thank you!!

marsh citrusBOT
#

@still temple Has your question been resolved?

still temple
#

<@&286206848099549185> Hello? blobsweat

#

Yes please :3

still temple
#

<@&286206848099549185>

#

It's okay!!

#

<@&286206848099549185> Hello???

wheat pond
#

Hi

#

how can I help you?

still temple
#

Yess

#

I've been looking for a helper in ages

still temple
#

What?

#

Is that for all letters??

#

Which one is letter a b and c?

#

SO C IS THE ONLY INCORRECT THING I DID

#

DG ITTT

#

Wait...

#

We might be both wrong

#

<@&286206848099549185>

#

My answer was only 15/2

#

I didn't make it to a decimal

#

I mean for letter a 😭

#

What did you do in letter c?

#

YEAH

#

I used arithmetic sequence, arithmetic series and geometric series

#

Eh sure

marsh citrusBOT
#

@still temple Has your question been resolved?

marsh citrusBOT
#
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limpid olive
marsh citrusBOT
tight kite
#

what is that

limpid olive
#

That is a code :))

tight kite
#

what do you need help with

sharp elk
#

may i have some help

marsh citrusBOT
#

@limpid olive Has your question been resolved?

full flume
#

idk wth that is lmao but transcribed for posterity

910 80,x2:0, 3'8x1-0, (=) Β±20, 72() 262(=)
1(=) Β±1 (=) 72 910 80,x2;0,
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#
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dull slate
#

Trying to apply function of $\sqrt{\sum_{i=1}^{dimensions} ((Start_i+t(End_i-Start_i)-Other_i)^2)}$ to a line. So far as I have seen, form is like $\int_C f(...) ds$ to $\int_0^1 f(...) \sqrt{x'(t)+y'(t)... to dimensions}$. I keep getting like just one distance, what am I doing wrong? X E.

dull slate
#

How do I translate that to ds instead of dt?

#

This is for a straight line in 3+D. X E.

#

I should be getting like a sum of distances right?

elfin berryBOT
#

maybeJosiah

dull slate
#

<@&286206848099549185> No answer yet, is this not simple enough? In case it helps, I am trying to average a function over a line. X E.

spark siren
#

maybe your question isnt clear enough.

dull slate
#

How could I be more clear?

spark siren
#

!original

marsh citrusBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

dull slate
#

I am getting average of all distances from another point to a line segment and I do not know how to set up an integral for it. X E.

#

There is no original problem except as I stated. X E.

spark siren
#

you are starting your question with "trying to ..." so you describe what you do. maybe you should describe the goal you want to achieve.

dull slate
#

Beyond that, I am trying to compare average distances of shapes but that is not important much. X E.

#

Like we have point P, try to get average of all distances from a line segment AB defined by points A and B. X E.

dull slate
spark siren
#

sorry, i still dont get it. can you show a sketch for a simple case?

dull slate
#

Does this help?

normal moss
#

Do you have one point and many line segments or one line segment and many points?

dull slate
#

One line segment and one point. X E.

normal moss
#

Where is the average then?

spark siren
#

one line and one point gives one distance.

normal moss
#

Even if you had finitely many things there would be no need for integrating so I'm assuming one of these two collections must be infinite?

dull slate
normal moss
#

"All lines from each point" what is our collection of points and what is our collection of lines here?

dull slate
normal moss
#

Great, but we need to know BOTH what our collection of lines are and what our collection of points are to even begin talking about distances between objects in these sets.

dull slate
normal moss
#

Okay so we start with a single fixed line segment and some fixed separate collection of points?

dull slate
normal moss
#

Okay, if we start with a fixed line segment we're already talking about a set of points. Line segments are sets of points.

#

If we have only one extra point outside the segment, typically people call the distance from the point to the line the length of the segment connecting the point and line perpendicularly

#

Since that's the smallest distance between the two.

#

There's only one such distance...

#

So then you mean

dull slate
#

But I am looking for average, not minimum. X E.

normal moss
#

We have a point and a line segment and you want the average of the distance between the point and every point on the line segment?

dull slate
#

Correct. X E.

normal moss
#

Okay, this is just the average value of a function I think?

#

This mf

#

The idea generalizes to n dimensions

dull slate
#

Yeah but I can't get applying to a line correct, it keeps having just like one distance, not a sum over what number of set is. X E.

normal moss
#

Here your function is just the distance function between your fixed point and points on your line.

dull slate
#

Tried, I think that is a fail. X E.

#

It is a single integral, that is about all I know. X E.

normal moss
#

I'm fairly certain this works and is exactly the quantity you want. Whether or not you can evaluate it or set it up is a different issue to do with your own skill (and also tbh how hard the problem is).

#

In n dim this should be an iterated integral rather than a single one I think.

spark siren
dull slate
#

Form then?

normal moss
#

Like if you have a function f(x,y,z) you would have a triple integral iirc?

dull slate
#

iirc?

normal moss
#

If I remember correctly

#

My bad

dull slate
#

Okay, yeah. X E.

normal moss
#

If nothing else you should have the basic idea of your problem a little more clear here. You have a fixed point and line segment you wanna know the average distance between the fixed point and all points on your segment.

#

Actually wtf is the volume of the region of integration here?

spark siren
#

express every point C on AB as A+t(B-A), where 0<=t<=1 calculate the distance PC as a function of t.

dull slate
#

Why not a single integral instead? sqrt is hard to do multiple times. X E.

normal moss
normal moss
#

It might be reducible to one?

normal moss
#

Not you

dull slate
#

Okay. X E.

spark siren
#

do it.

normal moss
dull slate
#

So $\int_0^1 f(t) dt$ as with original? Tried, fails. X E.

elfin berryBOT
#

maybeJosiah

normal moss
#

I don't think this fails theoretically josiah

#

You should be careful to understand WHY things fail.

dull slate
#

True. X E.

normal moss
#

It's kinda misleading to say it fails without telling ppl why because then ppl can't address that part of the issue

spark siren
#

its more or less senseless if you repeat permanently "tried, fails". it works. if you fail, you made a mistake.

normal moss
#

Iirc the integral calculation was too hard and approximation wasn't so great either

#

For them

dull slate
#

For any line it is not a sum though as it seems it should be. It is like one distance. That one that was too hard was polygons. X E.

normal moss
normal moss
#

The integral we're discussing shouldn't just be a sum

#

Riemann sum approximations will be literal sums.

dull slate
normal moss
#

Yeah that shouldn't be a sum?

#

Should be some integral of a square root of a sum I guess.

#

Not the same as just a sum

dull slate
#

True it is not just a sum but it should somehow be like divide by length of line to get average over line. That does not work. X E.

#

That triple integral would be volume seemingly, not trying for that. X E.

normal moss
#

If you parameterize in a way that your integral has bounds 0 to 1 that length is just 1.

#

Which is what Thm suggested.

dull slate
#

Oh, okay. X E.

#

It still seems weird. X E.

normal moss
#

You can think of their approach as transforming the problem so that the segment lies on an axis

#

We don'f care about where the pt and segment actually lie

#

Just their relative distances

dull slate
#

On a polygon I have to divide by area, I am still unsure considering I use 1 to 0 on that too. X E.

#

I also tried using from start x to end x values, still same non-sum. X E.

normal moss
#

The 1 to 0 thing works here because we have control over how we parameterize the line. If we had our line written as the vector equation y=mt+b (here y,m,b are vectors and t is a scalar) with t ranging from 2,4 for ex we could just scale t by the distance 4-2 and change our bounds to get an equation that traces the same segment with parameter ranging between 0 and 1

#

I could be off by a factor or so on the scaling point

#

But that general trick allows us to choose our bounds for tracing the segment.

#

There are multiple ways to parameterize a curve usually.

dull slate
#

What would be sum on line form then?

#

Maybe 0 to length of line?

#

I tried form of integral over dx with others relative to x in case that helps. Still no sum over line. X E.

normal moss
#

I don't know what you're asking

#

Sum on line form?

dull slate
#

Like what would give sum of all distances of points on line segment?

normal moss
#

I think what ThM suggested does basically that.

dull slate
#

Thanks for talking. X E.

normal moss
#

It's gonna be their suggestion up to like a scalar multiple.

dull slate
#

Which is formulated how?

normal moss
dull slate
#

And it is not sum form, it is single distance form. X E.

normal moss
#

Take your fixed point as C and r(t) as the equation of your line segment parameterized from 0 to 1 like they suggested. f(t)=dist(C,r(t)) integrate for t from 0 to 1.

normal moss
#

We can use a sum if we have only finitely many points. But we don't have that now.

#

Hence the integral.

#

If you mean the sum in the distance formula, that's just part of f(t).

dull slate
#

By sum form I mean like you divide by segment length to get average. X E.

dull slate
#

So that was $\int_{Line} f(t) dr$?

elfin berryBOT
#

maybeJosiah

dull slate
normal moss
#

The bounds would just be 0 to 1 with this approach

dull slate
#

From Wolfram Alpha, results of integration. X E.

dull slate
#

That is JS. X E.

#

Could it be Wolfram is just bugging or there is a different solution for from 1 to 0 instead of indefinite integral usage?

normal moss
#

All you're talking about afaict is the difference between the average or the integral here. You can figure out this from the average value integral in the one var case I mentioned.

spark siren
dull slate
#

It should be but it is not coming out to that. X E.

spark siren
#

you stlll claiming things without any argument. my solution gives you an integral.

dull slate
#

Or fix it, I don't know. X E.

spark siren
#

why shold i run this in a browser?

dull slate
#

It gives you a sense of how wrong current solution you are suggesting is. X E.

#

JS can only be run in browsers. X E.

#

Feel free not to. X E.

#

You could also run in some online tool. X E.

spark siren
#

only in the case if we believe that this code gives an idea for a correct result. this is to prove.

#

so its up to you to explain why this code should give the right result.

#

i wont do it this way.

dull slate
#

Shall I give you a screenshot then?

spark siren
#

well, i think we should agree to disagree. you do not accept my solution, so why should we continue the discussion?

dull slate
#

Here are results. First line is like should be supposedly. X E.

#

155/588 is not even close to range of possible values. X E.

#

This is for a line 100 or more out in each direction. X E.

#

First line is result, ignore next 2, then next line, first is length of line, others are lengths on line from point to consider against. Last is center to point, others are ends to point. X E.

#

It is on bottom right. X E.

spark siren
#

you are showing that your code doesnt give you the result you expect. well, ok. and whats my part to this code?

dull slate
#

It is an implementation exactly as you suggested for math and it does not work. X E.

#

A better one with what values, first and second are line points, other is to compare with. X E.

spark siren
#

in which line i can see the integral i suggested?

dull slate
#

That was result from a sumation like sqrt(A+Bt+Ft^2) where each coordinate is part of those letters. X E.

#

That sqrt being f. X E.

spark siren
#

its still your implemetation. not my suggestion. anyway. from myside everthing is said.

dull slate
spark siren
#

if you wanna have a mathematical discussion write f(t) in a mathematical notation, solve the integral in a mathematical notation, and then we can look if there is a mistake. maybe.

dull slate
#

Integrate[Sqrt[A+B t+F t^2],{t,0,1}], Well, Wolfram always exceeds computation time for this so I guess I am stuck. X E.

#

Alright, let us calculate using this then?

#

And also, it is like before, $(x+t(x1-x)-P)^2$ so $(x-P)(x-P)+2t(x-P)(x1-x)+(t(x1-x))^2$ per dimension. X E.

elfin berryBOT
#

maybeJosiah

dull slate
#

Correct so far?

#

$A=(x-P)(x-P)$, $B=2(x-P)(x1-x)$, $F=(x1-x)^2$. X E.

elfin berryBOT
#

maybeJosiah

dull slate
#

Actually, we can consider it to be sum per dimension, not just that one thing per variable. X E.

#

I could continue but why? I already implemented this in JS as up there. X E.

#

I can't solve with definite integral but indefinite integral definitely should work. X E.

#

Well, I guess I am going with this is accurate though it might not be. If I can't make it work then I guess I come back. X E.

#

.close

marsh citrusBOT
#
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marsh citrusBOT
#
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sterile rivet
#

hello

marsh citrusBOT
sterile rivet
#

can anyone explain this to me?

#

this is linear algebra null space / column space

#

im confused about why we needed to find the solution of null space here and what information it gives.

#

im also wondering how they knew to choose that kind of matrix like what the line of thought behind it was

#

pls help!

main idol
#

this xbar is in the null space of A

still palm
#

How this happens when we increase one quantity by 2 and other decreases by 2

marsh citrusBOT
sterile rivet
#

oh right

#

wait

#

so it says there is more than one solution to xbar

#

that means x is not trivial

#

but im stuck there

#

how do i go from there?

main idol
#

i don't know what you're stuck on

sterile rivet
#

i just dont know how to solve the problem

main idol
#

did you understand this 2x2 matrix?

#

And how it has 1 dim null space

sterile rivet
#

ohhh

#

no i have no idea

#

one dimensional i think means that the basis has one vector?

#

but i dont know how to connect that to a matrix

sterile rivet
#

thank you ill watch this video

#

i think i understand now

#

so for an easy example, i could choose a matrix with dimension 1, rank 1, and 2 columns

#

then, i can find the column space of the matrix i make

#

for A, the column space is (1,0).

#

im really lost

#

what does this line mean?

full flume
#

the zero vector won't ever contribute to the span. it's just adding linear combinations of zeros

sterile rivet
#

why did they add the linear combinations of zeros?

#

wait the span S is talking about the column space of A right?

#

how did they get the null space to be (0,1)

#

😭

#

why is it right to say the null space is not in the span so every vector in Rm cannot belong to S? how did they connect those two ideas?

#

pls elp!

marsh citrusBOT
#

@sterile rivet Has your question been resolved?

marsh citrusBOT
#

@sterile rivet Has your question been resolved?

marsh citrusBOT
#

@sterile rivet Has your question been resolved?

marsh citrusBOT
#
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#
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vestal drum
#

I wasn't entirely sure how to deal with the negative in part b, and I'm wondering where the faults in my progression were. Is it the derivative of x? Was I supposed to implement the -1 some other way? I'm curious.

stoic slate
cunning fiber
#

????

#

,w differentiate -1/(x+8)^2

elfin berryBOT
vestal drum
#

hang on

#

lol, i see

#

So I've got a separate integral, I'm wondering how the -1/2 will be implemented

#

wait, got it

#

.close

marsh citrusBOT
#
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marsh citrusBOT
#
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velvet cairn
#

Can every even number except 2 be expressed as the sum of two prime numbers ?

gilded sage
#

probably idk

stoic slate
#

That question should not be posted here

velvet cairn
#

Ahh it's dumb
I just searched and realised there's already a conjecture like this to be proven

#

.close

marsh citrusBOT
#
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marsh citrusBOT
#
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lime shuttle
#

for c, if the correct graph is C in (b), would it be A?

lime shuttle
#

this problem took me forever

glacial chasm
#

Is it to your right or to the graph's right?

#

I think if it is the latter it should be B, if it is the former then it is C

lime shuttle
#

def not c

#

its A or B with 10000x certainty

#

i think its A

wary kite
#

did you get part b right

lime shuttle
#

ya im 99% sure

#

part a took forever

wary kite
#

what’s the order of the 5 number summary btw

lime shuttle
#

so the blue lil line on the left is the min, the start of the blue box is q1, the median is the black line in the mid of blue box, the end of the blue box is q2, and the end of blue line on right is max

#

they r in order

kindred vigil
# lime shuttle ya im 99% sure

The middle line in the box corresponds to your middle datapoint, which is quite far to the left of your biggest data point but quite close to your smallest data point

#

positive skew would be correct i'm pretty sure; the terminology is confusing

glacial chasm
wary kite
#

yea so if you did the 5 number summary right then part b is correct and you should be able to tell its skewed right

kindred vigil
#

"right skew" means there's some outliers to the far right of your middle

lime shuttle
#

ya but i think the symmetry within the box

#

means its A

#

if the box had more fat on the right side of the median

wary kite
#

no, consider the tail end

lime shuttle
#

it'd be skewed right

wary kite
#

it is skewed right

#

it’s clumped towards the left which means the tail is on the right

wary kite
lime shuttle
#

"When the median is in the middle of the box and the whiskers are roughly equal on each side, the distribution is symmetrical (or β€œno” skew)."

#

i think im right

#

with A

#

WAIUDGHAUDGAWYD

#

but then

#

ur explanation also makes sense

#

like mf huh

kindred vigil
#

If I was a teacher I'd accept either answer

lime shuttle
#

frrr LOL

kindred vigil
#

no skew sounds best

#

It's probably no skew with an outlier but no general trend

wary kite
#

the right whisker is much longer

lime shuttle
#

Ya ima just go with ur answer

#

skewed right

#

if its wrong ill have to question my prof

#

so confusing

#

this site even states its up to the whiskers

wary kite
#

i mean they literally exaggerated how short the left whisker was for this reason

#

you can’t even see the left whisker

lime shuttle
#

my friend said

#

for part b its C

#

mfs are confusing me

kindred vigil
#

Your friend is wrong

lime shuttle
#

im going with C for B and B for c

#

πŸ™πŸ»

#

yall smarter

#

so fuck it we ball

kindred vigil
#

A/B is interpretation

#

C/D is just there to pad out the multiple choice answers

lime shuttle
#

ya

#

i appreciate yalls help ❀️

#

.close

marsh citrusBOT
#
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wary kite
marsh citrusBOT
#
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lunar walrus
#

How to solve linear equations?

marsh citrusBOT
lunar walrus
#

I don’t get it

glacial chasm
#

give me an example

lunar walrus
#

This

#

All I see when I look at this is a jumble of nothing

glacial chasm
#

Ok try to transfer (1/2)(x) to the left hand side

lunar walrus
#

Huh what does that do

#

Like how do you figure out that’s what u need to do?

glacial chasm
#

Manipulate the equation so that one side have all the x, and the other side have all the variable, so you can simplify it

lone heart
lunar walrus
#

Oh

#

Think I got it

marsh citrusBOT
#

@lunar walrus Has your question been resolved?

marsh citrusBOT
#

@lunar walrus Has your question been resolved?

marsh citrusBOT
#
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#
Available help channel!

Send your question here to claim the channel.

Remember:
β€’ Ask your math question in a clear, concise manner.
β€’ Show your work, and if possible, explain where you are stuck.
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still temple
#

how u do this

marsh citrusBOT
still temple
#

help

sinful thistle
#

factorize 54

#

expand it

#

and use the laws of exponents

still temple
#

i got it till 2*3^x+5=2

#

Idk what to do after

sinful thistle
#

good

#

divide by 2. what do you get?