#help-33
1 messages Β· Page 192 of 1
Yes?
Np bro
how
@hasty briar Has your question been resolved?
@hasty briar Has your question been resolved?
uhh
if u take z = x + iy the remaining part is a constant ( a |z-1|) and 2i
so for it to be zero
y must be -2i
and x= -a|z-1|
from there u can solve for p and q
isnt the value of a |z-1| dependent of z? how is it a constant
i meant real my bad
y must be -2 cuz the only other imaginary part 2
cant a |z-1| have a imaginary part?
no they said a is real and mod of anything is a real number
wdym
|z| is always a real number its a value
it cant have an imaginary part
a is real but if z (complex number) is multiplied wont it become imaginary?
it is πΏ
no mod of z = x+iy, |z| is defined as root x^2 + y^2
okay then yes y = -2
ye
lemme try it
sure
how do i calculate the max and min value of a
like differenciation method?
@limber trellis
@hasty briar
if u use this u get a quadratic equation in x
yes
then u will get a limit on a
lmaoo
isok just try it
yes leme
let me know if u need any help
or u can check my ans
cuz that is the maximum value of a
thats what theyre asking
try taking p as root 5/4 and q as - root 5/4 and check
yes then we get the ans
oh nice
but how is a p
cuz they said p is max value a
and a is cannot be more than root 5 /4
so p is root 5/4
OH WAIT
sory
right
i read the ques wroong
i thought the roots were p and q
aaaa
your welcome
what grade r u in
no worries
mentally im in 2nd
as u mustve figured it out already
stop laughing at me π
u bought this upon ur self
uff
anyway i gtg now if u have any other doubts let me know
byee
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how to find torque created by F2 and F3
about which point
A
force x perpendicular dist
the distance is diagonal in this case tho
axis is perpendicular tothe plane right?
wdym
it should be perpendicular to the plane only
oh the plane as in rectangle
so for f3, torque would be f3 x root 10
yes
so is it $\tau_{net}=-2F\sin45+2F\cos45+F$
Jash
for the net torque about A
no idts
what did i do wrong
like the first term is the torque by F1
the second term is by F2 and third by F3
the for first force, it is being applied in 2 directions
and so is f2
isnt it only the perpendicular force that matters
torque of f2 is in clockwise direction and anticlockwise both
they cancel?
yes
alr and is the torque by F1 equal to 2Fsin(45)
yess
yes cw
so the net torque is $F-2F\sin45$
Jash
f root 10
why sqrt10
so r=sqrt10
so $\tau_{net}=(\sqrt{10}-\sqrt{2})F$
Jash
1/root 2
alr
@molten ferry Has your question been resolved?
@molten ferry wait
im so sorry π
i wasnt in my right mind
for 1, torque by f3 would be F only
as perpedicular dist is 1
NOT root 10
sorrryyyyy
so sorry
so for 1, it would be (1-root2)F
and for 2, it would be 0
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How can I find the normal of y = x + 1, with x being 2
When you mean normal, you want to find perpendicular line ?
You can find the equation of the normal when you have a point and the slope
The slope of a normal is -1/m
Well I have the equation of the tangent which is y = x + 1, the question now asks me to find the normal when x = 2
This is the function itself
Can you find the point at x=2 first
Well the question asks us "Find the equation for the normal of the line where the point is x = 2. a) y = x + 1
Find the value of y when x=2
3
Great so the point in (2,3)
Are you studying calc 1 or precalc
cause the answer to finding the slope would be vary
I'm pretty sure it's precalc, I'm not based in either UK or the US
Current chapter is about derivatives, asymptotes, limits and all that stuff
So you haven't studied derivatives, right?
Oh great that makes explaining easier
I have a bit, from what I know is that f'(x) is the derivative of a function, where delta y / delta x is 'simplified'
Delta y / delta x is the average rate of change
dy/dx is the instantaneous rate of change
I learned today that instead of finding the limit we can also just use ax^n+bx = anx^n-1+bx^1-1....
yeah exactly so f(x+Ξx)-f(x)/Ξx
The slope of the function here is 1 since dy/dx is equal to one
So the slope of the normal will be -1/1 = -1
You have a point and the slope
Can you find the normal to the function
Just to confirm, to find the equation for a tangent we can use the derivated function to find a in y = ax+b, and then find b by plugging in (x,y) from the normal function, correct?
I assume this is because of how we derivate the original expression of y = x + 1?
@obtuse plume Has your question been resolved?
@obtuse plume Has your question been resolved?
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I'm stuck, should I plug 4 and into the u formula and get new parameters? And is my process correct so far
You could either change the limits for the integral to be in terms of u (and probably really should!), or you could convert the result you found back to the original variables and use that instead...
Also where is that 1/60 coming from?
I tried to eliminate the 100 and 0.6 in one go
And would that be 3+e^0.6(4) etc.
I don't think you did that right 
Should I change my u and du expressions is there another way to do it
Well, you effectively have 100/0.6 that you're dealing with, which you want to simplify, right... 
why is the 0.6 in the denominator
Because you have $\dd u = 0.6e^{0.6t} \dd t$ (you forgot the $\dd t$ in yours), which means that $\frac1{0.6e^{0.6t}} \dd u = \dd t$, so replacing the $\dd t$ in the integral you have gets you
[
\frac13 \int_1^4 \frac{100e^{0.6t} }{3 + e^{0.6t}} \dd t = \frac13 \int_{t = 1}^{t = 4} \frac{100 \cancel{e^{0.6t}} }{u} \frac1{0.6 \cancel{e^{0.6t}}} \dd u
]
@glass silo
(note that the limits in the second integral are actually the t values, rather than the u values, and so should be changed really!)
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If you know the period and phase shift of a trigonometric function like sin cos, etc, how do you know what scale to put it in? I am struggling with knowing the best scale to use when plotting the function. For example, the image. The ps is -pi/6 and the period is 4pi. How do I know the scale of the graph
my best answer is pi/12, but it seems too small
@round gorge Has your question been resolved?
Any help?
@round gorge what do you mean by "scale"? Do you mean the marks you want along the x-axis?
Yes, I want to make marks and label them. I want to ensure that my main points in my function are on labeled numbers as opposed to not being on the grid
Let me think about that for a second
the first coefficent is a scale along y axis, coefficent inside sin is a scale along x axis
I would think about the full period of your function. For example, this one is $4\pi$. Dividing this by 4 will give you how far you have to move along the x-axis (in this case) to hit the x-intercepts. And dividing by 8, gives placements for the maxes/mins. Not sure if that infor is helpful or not
So, start at $-\pi/6$, and move $48/8=6$ steps every time to find the important features
my question is how do i know what each step is.
Thats what im confused about, I know how to plot the points if I have the steps labeled
and why 48?
@round gorge Has your question been resolved?
A period of 4pi with step size 6, gives 48 steps altogether
so just always make the step size the phase shift? What if the step was a strange number like pi/13. It wouldn't fit in the period nicely
in this case 4 times 13 = 52, so the approach is the same. just more annoying π
ah i see the problem, 52/8 = 13/2
but every even multiple will "take care" of the weird denominator we would get
Sorry can you clarify what you mean by that?
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I'm missing something and I can't quite figure it out
the function approaches the same sign as x approaches 2
so (x-2) should have an even power
similarly, the function approaches the opposite sign as x approaches 6, thus (x-2) should have an odd power
uh, you might want to zoom in a bit btw
because the function is decreasing from -infty to 2
try putting in a minus sign before the function
and there you go
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If I have a group like Z^*_p where p is a prime number is any int 1 to n-1 a generator for the set?
\
No. In general it's not 'easy' to find generators to Z*p.
1 clearly isn't
And for instance in $\Z_{11}^*$, $3$ isn't a generator.
Azyrashacorki
It's just a common example.
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im confused by both questions...
for part a, from my understanding of a unique solution is that the determinant when u inverse the matrix is 0 but when i found the determinant in this case it was 0... so im not even sure....?
for part b, I converted the matrix to 3 planes and choose 2 planes to find a line by eliminating a variable and i did that twice and both the lines i found where the same so it proves it is consistent but how do i show for the second part of b?
What do you mean by "when you inverse the matrix is 0"? Can you name a matrix whose inverse happens to be the zero matrix?
the determinant was 0 when i inversed this matrix
You can't invert a matrix with determinant 0
oh? so what would i do here?
A linear system of n equations and n variables does not have a unique solution iff the determinant of the matrix is 0, so you have already shown part a
oh lol so if there was a unique solution then the determinant would be anything other than a 0?
Yeah
ahhh ok i get it, but for part b where it says to show that the general solution can be written as that, if the determinant is 0 how would i show that the general solution is that?
Just solve the system, augment the matrix and row reduce or whatever you prefer
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is there a difference between line integral of scalar funtions and line integral of a vector field
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stared for an hour
what explain
whered u get 90
i understand the 40
OH

inscribed angle theorem is simpler
consider that inscribed angle <SQR
and central angle <SOR
are subtended by the same arc
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prove by induction that: $10^{n-4} < n!\ \forall n\ge 9$
maxy
I mean the left side is always only multiplying 10, and n! After n=9, it is always multiplying 10 and higher, just solve that 10^5 smaller than 9!
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I am stuck there: how do I solve that limit without Hopital Theorem?
,rotate
Wt is nim
nim?
Nvm
I use t cause x tends to pi/4, which is not helpfull for using notable limits
Yeah, what else could it be?
i know i have a bad writing but not that bad xD
Oh, yeah, it's sin
just making sure, it doesn't look anything close to an s
all the other letters looked fine
anyway, after doing that sub, use the compound/difference identities
The what?
,tex .sum diff trig
Like multiplying for (cosX + sinX)?
hayley is stateside!!
those?
Oh
Alr but what if i can't?
is there any other solution?
what are you expecting
i mean what method are you expecting
Notable limits i think
yeah, i mean that i should be able to solve this with ONLY notable limits or tricks, like this one
That is the way you suggested me to do, and is an approach that i can use but i'd like to know if i can find an other approach
That is what i tried to do but wasn't able to get the result
show what you managed to do
It's bad written, let me re-write for better understanding
(cosx + sinx) is not a problem of the limit cause it's a costant, it's not 0
And i think that i have complicated the limit by doing so and not simplified it...
use the sub from earlier
or you could use conjugates after doing the sub,
order doesn't really matter
where should i use the sub on the limit?
You mean, replace the x with t (so that t tends to 0) and then use the sub equation again?
use the
t = x - pi/4
idea
Yeah, but i still have to use the sub equation to solve this exercise.
I was just wondering if there is an other approach other than this and Hoptial
none that i can be bothered thinking about
some trig identities/properties will be involved
So, we always talk about goniometric proprieties, right?
I mean, i was wondering if this exercise could be solved without goniometric proprieties (like a polynomial limit) but i think that it's not possible
i have to use goniometric proprieties for sure
Alr, thank you for your help and your time : )
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What makes a function continous and differentiable on a close interval and also what makes it not?
it needs to satisfy the relevant definitions
tho I feel that will be unsatisfying
what kind of answer do you want to hear?
I guess just cases where the function wouldn't be continous or differentiable
do you mean like visually from the graph?
its not continuous if there is for example a jump
and not differentiable if there is for example a corner (like in |x|)
yes
what about like sharp points if that makes any sense
How come
the slope jumps
but like mathematically why
and sorry if this is tedious im just trying to get a better understanding of math in general
the relevant limit doesnt exist
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@cyan pasture Has your question been resolved?
looks correct to me
DOPPELGANGER TYPE SHIT
@cyan pasture Has your question been resolved?
hehe
@cyan pasture Has your question been resolved?
@cyan pasture Has your question been resolved?
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I need help in Calculus 3, I dont understand what other points can be min or max:
So if found the max and min for the boundary (max = 5 at (1,0) and min= -7 at (-1,1))
<@&286206848099549185>
you should get the derivative in the different variable
@sacred leaf Has your question been resolved?
Can you be more precise?
which derivative fx or fy?
let me see
ok
get both partial derivatives
respecto to x, and respect to y
then make each of them = 0
you have a system of 2 equations with 2 unknown values, x and y
if you divide the 2nd eq by 3 and add it to the first eq
you'll get an eq to resolve with the (-b+-sqrt(b^2-4ac)/2a)
there you have two potential values for your minimum/maximums in x
same with y
They will be the critical points?
I've gotten x1=0, x2=-8/90
yep
let me see with y
0and -4/135
I think
now replace those values in the main function
and you'll get your values
it gives -0.019 which is not a minimum no? since I got a min of -7 with the boundary
the second value of y doesn't apply
is negative
there's your function
Finding the critical points: Calculate the partial derivatives of the function and set each derivative equal to zero to find the critical points (a, b).
Use the second derivative test: Define the determinant D = βΒ²f/βxΒ² βΒ²f/βyΒ² - (βΒ²f/βxβy)Β². Evaluate D and the partial derivatives at the critical points:
If D > 0 and βΒ²f/βxΒ² > 0, then there is a local minimum at (a, b).
If D > 0 and βΒ²f/βxΒ² < 0, then there is a local maximum at (a, b).
If D < 0, there is a saddle point at (a, b).
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Is this right?
I believe you need to convert to radians first
Yea thatβs what I did
oh, sorry, hard to tell with the picture
60 degrees is pi/3
right yeah
Yea itβs kinda messy srry
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hi guys, In the concavity should I take into account -1 and 2 or should I not? because in the domain doesn't take it into account
@red tartan Has your question been resolved?
<@&286206848099549185>
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My highschool teacher told me to solve this problem by parts, but does anyone know how i could solve it, bec i tried many times
I think a substitution first could make it a bit simpler before IBP
indeed sub in $u = x^2$ first
south, just south
THEN do IBP
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
Oh mb network
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i dont understand why this is wrong
i plugged in pi over 6 to all the x values
and got pi/6 (sqrt3 / 2) - (1/2) over (pi/6)^2
so i cancelled one of the pi/6
to get (sqrt3 / 2) - (1/2) over (pi/6)
then multiplied top and bottom by two
to get (sqrt 3) - (1) over (pi/3)
and then the final answer
what did i do wrong
From what you're describing you're going from $\frac{\frac{\pi}{6}\cdot \frac{\sqrt{3}}{2} - \frac{1}{2}}{\frac{\pi^2}{6^2}}$ to $\frac{\frac{\sqrt{3}}{2} - \frac{1}{2}}{\frac{\pi}{6}}$ which you can't do
Azyrashacorki
There's no factor of x on the second term
oh
I'm actually surprised this compiled in one go
wait then what am i supposed to do
You can still simplify both terms a bit, it depends how much the platform you're working on wants things to be simplified to the fullest
wait can i know why you cant do that?
cause its just pi/6 over (pi/6)^2 isnt it
Because pi/6 is only a factor of the first term in the numerator, not the second
Nw
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I don't know how to even start this
sin(x) β x linear approximation around x = 0
Mhm
$(e^{sinx})'=e^{cosx}*e^{sinx}$?
Falco
Nop
Just cosx
wdym?
If you use the linear approximation you have the form 0/xΒ² = 0 remember x approaches 0 but never is
cosx*e^(sinx)?
Yes
Can you explain why? Bc I don't get it
chain rule
Ok so
Chain rule yes
Consider t=sinx
So then
e^sinx = e^t
Differentiate wrt to x
Ull get
dy/dx = e^t*dt/dx
dt/dx is cosx
Ok, now I get it thanks
$\lim_{x\to 0}\frac{e^x-e^{sinx}}{x^2} = \lim_{x\to 0}\frac{e^x-e^{sinx}cosx}{2x} = \lim_{x\to 0}\frac{e^x-e^{sinx}(cosx)^2+e^{sinx}*sinx}{2}$
Falco
Falco
@gusty patio Has your question been resolved?
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How do I find the distance between C' and D'?
I tried using the pythagorean theorem but it gave me sqrt(45)
I get sqrt(45) if I scale it to 3. If I don't, I get sqrt(5) instead. Which is useless?
Khan Academy says the distance is 6 for the scaled version. And I get sqrt(45) which is approximately 6,708203932
Can you like
Label which point is which better
Cuz rn, the way I see it is line C'D' just a vertical line
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And if that is the case, their distance is just 2 and line CD would be 6
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@still temple Has your question been resolved?
I am quite confused on what to do with the honey comb
What?
Is that for all letters??
Which one is letter a b and c?
SO C IS THE ONLY INCORRECT THING I DID
DG ITTT
Wait...
We might be both wrong
<@&286206848099549185>
My answer was only 15/2
I didn't make it to a decimal
I mean for letter a π
What did you do in letter c?
YEAH
I used arithmetic sequence, arithmetic series and geometric series
Eh sure
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what is that
That is a code :))
what do you need help with
may i have some help
@limpid olive Has your question been resolved?
idk wth that is lmao but transcribed for posterity
910 80,x2:0, 3'8x1-0, (=) Β±20, 72() 262(=)
1(=) Β±1 (=) 72 910 80,x2;0,
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Trying to apply function of $\sqrt{\sum_{i=1}^{dimensions} ((Start_i+t(End_i-Start_i)-Other_i)^2)}$ to a line. So far as I have seen, form is like $\int_C f(...) ds$ to $\int_0^1 f(...) \sqrt{x'(t)+y'(t)... to dimensions}$. I keep getting like just one distance, what am I doing wrong? X E.
How do I translate that to ds instead of dt?
This is for a straight line in 3+D. X E.
I should be getting like a sum of distances right?
maybeJosiah
<@&286206848099549185> No answer yet, is this not simple enough? In case it helps, I am trying to average a function over a line. X E.
maybe your question isnt clear enough.
How could I be more clear?
!original
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
I am getting average of all distances from another point to a line segment and I do not know how to set up an integral for it. X E.
There is no original problem except as I stated. X E.
you are starting your question with "trying to ..." so you describe what you do. maybe you should describe the goal you want to achieve.
This is goal. X E.
Beyond that, I am trying to compare average distances of shapes but that is not important much. X E.
Like we have point P, try to get average of all distances from a line segment AB defined by points A and B. X E.
Trying and failing to integrate a function over a straight line. All lines are straight in this case. What form should I use? X E.
sorry, i still dont get it. can you show a sketch for a simple case?
Does this help?
Do you have one point and many line segments or one line segment and many points?
One line segment and one point. X E.
Where is the average then?
one line and one point gives one distance.
Even if you had finitely many things there would be no need for integrating so I'm assuming one of these two collections must be infinite?
Uh, comparing distances of all lines from each point on line segment to other point. X E.
"All lines from each point" what is our collection of points and what is our collection of lines here?
A line can be considered any number of points depending how many intermediates you define. X E.
Great, but we need to know BOTH what our collection of lines are and what our collection of points are to even begin talking about distances between objects in these sets.
Collection of points is on original line segment, collection of lines is from collection of points to other point to compare with. X E.
Okay so we start with a single fixed line segment and some fixed separate collection of points?
A single line segment that contains a set of points and another point. X E.
Okay, if we start with a fixed line segment we're already talking about a set of points. Line segments are sets of points.
If we have only one extra point outside the segment, typically people call the distance from the point to the line the length of the segment connecting the point and line perpendicularly
Since that's the smallest distance between the two.
There's only one such distance...
So then you mean
But I am looking for average, not minimum. X E.
We have a point and a line segment and you want the average of the distance between the point and every point on the line segment?
Correct. X E.
Okay, this is just the average value of a function I think?
In calculus, and especially multivariable calculus, the mean of a function is loosely defined as the average value of the function over its domain. In one variable, the mean of a function f(x) over the interval (a,b) is defined by:
f
Β―
...
This mf
The idea generalizes to n dimensions
Yeah but I can't get applying to a line correct, it keeps having just like one distance, not a sum over what number of set is. X E.
Here your function is just the distance function between your fixed point and points on your line.
Tried, I think that is a fail. X E.
It is a single integral, that is about all I know. X E.
I'm fairly certain this works and is exactly the quantity you want. Whether or not you can evaluate it or set it up is a different issue to do with your own skill (and also tbh how hard the problem is).
In n dim this should be an iterated integral rather than a single one I think.
it will work.
Form then?
Like if you have a function f(x,y,z) you would have a triple integral iirc?
iirc?
Okay, yeah. X E.
If nothing else you should have the basic idea of your problem a little more clear here. You have a fixed point and line segment you wanna know the average distance between the fixed point and all points on your segment.
Actually wtf is the volume of the region of integration here?
express every point C on AB as A+t(B-A), where 0<=t<=1 calculate the distance PC as a function of t.
Why not a single integral instead? sqrt is hard to do multiple times. X E.
Are you trying to reduce this to a single integral this way?
Tried, what is integral form?
It might be reducible to one?
Yes. X E.
Not you
Okay. X E.
i again dont get your question. i showed you haw to make a distance function, dootdooter showed you how to calc the mean of a function.
do it.
You would integrate from 0 to 1 the distance from your fixed point to A+t(B-A) basically
So $\int_0^1 f(t) dt$ as with original? Tried, fails. X E.
maybeJosiah
I don't think this fails theoretically josiah
You should be careful to understand WHY things fail.
True. X E.
It's kinda misleading to say it fails without telling ppl why because then ppl can't address that part of the issue
its more or less senseless if you repeat permanently "tried, fails". it works. if you fail, you made a mistake.
Iirc the integral calculation was too hard and approximation wasn't so great either
For them
For any line it is not a sum though as it seems it should be. It is like one distance. That one that was too hard was polygons. X E.
Part of the context here is them trying to do graphics stuff where things can be generally correct but not so viable for their application.
Which thing do you think should be a sum?
The integral we're discussing shouldn't just be a sum
Riemann sum approximations will be literal sums.
Integral of f(t) dt. X E.
Yeah that shouldn't be a sum?
Should be some integral of a square root of a sum I guess.
Not the same as just a sum
True it is not just a sum but it should somehow be like divide by length of line to get average over line. That does not work. X E.
That triple integral would be volume seemingly, not trying for that. X E.
In this case the division by length ends up being trivial
If you parameterize in a way that your integral has bounds 0 to 1 that length is just 1.
Which is what Thm suggested.
You can think of their approach as transforming the problem so that the segment lies on an axis
We don'f care about where the pt and segment actually lie
Just their relative distances
On a polygon I have to divide by area, I am still unsure considering I use 1 to 0 on that too. X E.
I also tried using from start x to end x values, still same non-sum. X E.
The 1 to 0 thing works here because we have control over how we parameterize the line. If we had our line written as the vector equation y=mt+b (here y,m,b are vectors and t is a scalar) with t ranging from 2,4 for ex we could just scale t by the distance 4-2 and change our bounds to get an equation that traces the same segment with parameter ranging between 0 and 1
I could be off by a factor or so on the scaling point
But that general trick allows us to choose our bounds for tracing the segment.
There are multiple ways to parameterize a curve usually.
What would be sum on line form then?
Maybe 0 to length of line?
I tried form of integral over dx with others relative to x in case that helps. Still no sum over line. X E.
Like what would give sum of all distances of points on line segment?
I think what ThM suggested does basically that.
It's gonna be their suggestion up to like a scalar multiple.
Which is formulated how?
This was basically their idea
And it is not sum form, it is single distance form. X E.
Take your fixed point as C and r(t) as the equation of your line segment parameterized from 0 to 1 like they suggested. f(t)=dist(C,r(t)) integrate for t from 0 to 1.
The integral replaces the sum here.
We can use a sum if we have only finitely many points. But we don't have that now.
Hence the integral.
If you mean the sum in the distance formula, that's just part of f(t).
By sum form I mean like you divide by segment length to get average. X E.
And the integration is?
So that was $\int_{Line} f(t) dr$?
maybeJosiah
Code stuff. X E.
The bounds would just be 0 to 1 with this approach
From Wolfram Alpha, results of integration. X E.
True but it is not sum form as I was saying. X E.
That is JS. X E.
Could it be Wolfram is just bugging or there is a different solution for from 1 to 0 instead of indefinite integral usage?
All you're talking about afaict is the difference between the average or the integral here. You can figure out this from the average value integral in the one var case I mentioned.
Where?
integral is the sum form for the infinitesimal case.
It should be but it is not coming out to that. X E.
you stlll claiming things without any argument. my solution gives you an integral.
why shold i run this in a browser?
It gives you a sense of how wrong current solution you are suggesting is. X E.
JS can only be run in browsers. X E.
Feel free not to. X E.
You could also run in some online tool. X E.
only in the case if we believe that this code gives an idea for a correct result. this is to prove.
so its up to you to explain why this code should give the right result.
i wont do it this way.
Shall I give you a screenshot then?
well, i think we should agree to disagree. you do not accept my solution, so why should we continue the discussion?
Here are results. First line is like should be supposedly. X E.
155/588 is not even close to range of possible values. X E.
This is for a line 100 or more out in each direction. X E.
First line is result, ignore next 2, then next line, first is length of line, others are lengths on line from point to consider against. Last is center to point, others are ends to point. X E.
It is on bottom right. X E.
you are showing that your code doesnt give you the result you expect. well, ok. and whats my part to this code?
It is an implementation exactly as you suggested for math and it does not work. X E.
A better one with what values, first and second are line points, other is to compare with. X E.
in which line i can see the integral i suggested?
Where last result-= or last return in first function. X E.
That was result from a sumation like sqrt(A+Bt+Ft^2) where each coordinate is part of those letters. X E.
That sqrt being f. X E.
its still your implemetation. not my suggestion. anyway. from myside everthing is said.
this.
Full code, sorry. X E.
if you wanna have a mathematical discussion write f(t) in a mathematical notation, solve the integral in a mathematical notation, and then we can look if there is a mistake. maybe.
Integrate[Sqrt[A+B t+F t^2],{t,0,1}], Well, Wolfram always exceeds computation time for this so I guess I am stuck. X E.
Alright, let us calculate using this then?
And also, it is like before, $(x+t(x1-x)-P)^2$ so $(x-P)(x-P)+2t(x-P)(x1-x)+(t(x1-x))^2$ per dimension. X E.
maybeJosiah
maybeJosiah
Actually, we can consider it to be sum per dimension, not just that one thing per variable. X E.
I could continue but why? I already implemented this in JS as up there. X E.
I can't solve with definite integral but indefinite integral definitely should work. X E.
Well, I guess I am going with this is accurate though it might not be. If I can't make it work then I guess I come back. X E.
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hello
can anyone explain this to me?
this is linear algebra null space / column space
im confused about why we needed to find the solution of null space here and what information it gives.
im also wondering how they knew to choose that kind of matrix like what the line of thought behind it was
pls help!
this xbar is in the null space of A
How this happens when we increase one quantity by 2 and other decreases by 2
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oh right
wait
so it says there is more than one solution to xbar
that means x is not trivial
but im stuck there
how do i go from there?
i don't know what you're stuck on
i just dont know how to solve the problem
ohhh
no i have no idea
one dimensional i think means that the basis has one vector?
but i dont know how to connect that to a matrix
thank you ill watch this video
i think i understand now
so for an easy example, i could choose a matrix with dimension 1, rank 1, and 2 columns
then, i can find the column space of the matrix i make
for A, the column space is (1,0).
im really lost
what does this line mean?
the zero vector won't ever contribute to the span. it's just adding linear combinations of zeros
why did they add the linear combinations of zeros?
wait the span S is talking about the column space of A right?
how did they get the null space to be (0,1)
π
why is it right to say the null space is not in the span so every vector in Rm cannot belong to S? how did they connect those two ideas?
pls elp!
@sterile rivet Has your question been resolved?
@sterile rivet Has your question been resolved?
@sterile rivet Has your question been resolved?
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I wasn't entirely sure how to deal with the negative in part b, and I'm wondering where the faults in my progression were. Is it the derivative of x? Was I supposed to implement the -1 some other way? I'm curious.

????
,w differentiate -1/(x+8)^2
hang on
lol, i see
So I've got a separate integral, I'm wondering how the -1/2 will be implemented
wait, got it
.close
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Can every even number except 2 be expressed as the sum of two prime numbers ?
probably idk
That question should not be posted here
Ahh it's dumb
I just searched and realised there's already a conjecture like this to be proven
.close
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for c, if the correct graph is C in (b), would it be A?
this problem took me forever
Is it to your right or to the graph's right?
I think if it is the latter it should be B, if it is the former then it is C
did you get part b right
whatβs the order of the 5 number summary btw
so the blue lil line on the left is the min, the start of the blue box is q1, the median is the black line in the mid of blue box, the end of the blue box is q2, and the end of blue line on right is max
they r in order
The middle line in the box corresponds to your middle datapoint, which is quite far to the left of your biggest data point but quite close to your smallest data point
positive skew would be correct i'm pretty sure; the terminology is confusing
so shouldn't it be B? Can you explain your reasoning?
yea so if you did the 5 number summary right then part b is correct and you should be able to tell its skewed right
"right skew" means there's some outliers to the far right of your middle
ya but i think the symmetry within the box
means its A
if the box had more fat on the right side of the median
no, consider the tail end
it'd be skewed right
yes
it is skewed right
itβs clumped towards the left which means the tail is on the right
^
"When the median is in the middle of the box and the whiskers are roughly equal on each side, the distribution is symmetrical (or βnoβ skew)."
i think im right
with A
WAIUDGHAUDGAWYD
but then
ur explanation also makes sense
like mf huh
If I was a teacher I'd accept either answer
frrr LOL
itβs clear, look at the whisker
the right whisker is much longer
Ya ima just go with ur answer
skewed right
if its wrong ill have to question my prof
so confusing
this site even states its up to the whiskers
i mean they literally exaggerated how short the left whisker was for this reason
you canβt even see the left whisker
Your friend is wrong
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How to solve linear equations?
I donβt get it
give me an example
Ok try to transfer (1/2)(x) to the left hand side
Manipulate the equation so that one side have all the x, and the other side have all the variable, so you can simplify it
You want all the terms with a variable on one side of the equals sign and everything else on the other side
@lunar walrus Has your question been resolved?
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how u do this
