#help-33
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@faint coral Has your question been resolved?
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Is this ur question?
yes
I can help. you can easily reach me nbox
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does anyone know the reaoning or can explain why the cross product gives the area of a parreleogram (or half it a traingle in this case)
is the cross product not the normal to a plane made by two vectors
so how is the magnitude of a cross product the area?
but if its too complciated im fine ig
nvm sigh
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I need to show that for n>6, the product of the first n-1 primes is greater than the cube of the nth prime. Could anyone hint me on what to do?
I have tried using bertrand's postulate but it doesn't seem to give me what I want
@untold wyvern Has your question been resolved?
I think that should give you the proof for n>7
Hint
@untold wyvern Has your question been resolved?
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Help
since you have a polynomial here, think of it as a function $$f(x)=(4x^2+x-2)^4(2x^2-x+2)^3=a_0+a_1x+a_2x^2+...+a_nx^n$$
kheerii
then what's the sum you need?
Shld I like take x= 1 in the first part and um and add it with 2 of the second part
what?
Sum of all coefficient with x raised to an even power
But like without expanding it
(condition)
what is that in terms of the notation I introduced?
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how do i add 2 vectors in a triangle if they are not like AB+BC? like if they go like this? in my book i only see how to solve if they are like AB+BC or BC+CA or CA+AB
How else would you be adding them in a triangle??
like AB+BC = AC
but if they are like this idk how to add them
usually the vectors are like this or in reverse
so u have an arrow CA
and another one CB
u move the tail of the arrow CB to the tip of CA
and add them like u normally wud
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just the tip 🎶
.reopen
✅
wait, what if both vectors are going in the same point? like AC+ BC?
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can someone explain this to me?
I have solution here but cant make any sense of it
@gloomy plume Has your question been resolved?
anyone? 🥺
@gloomy plume Has your question been resolved?
@gloomy plume green area is possible, red is impossible
Gray area from original image satisfies the condition
the inequality confuses me a little
why is it -1/2 < y - x < 1/2
like shouldnt every point have both x & y coordinates?
"Given their distance is less than 1/2"
x is a number between 0 and 1.
y is also a number between 0 and 1
So the graph above shows pairs of numbers (x, y) between (0, 0) and (1, 1)
The green area is where the distance condition is satisfied (this is B)
The gray area is where the endpoint condition is satisfied (this is A)
the endpoints are (0,1) and (1,0) ??
The endpoints are just (0, 0) and (1, 1). However, only one of these is the endpoint specified. The solution assumes the endpoint is (0, 0) without loss of generality.
Or more specifically, the endpoint is just 0 or just 1
And both x and y need to be closer to 0 than 1 (if 0 was specified)
so the x & y in the equality are meant to be a point's coordinates right?
ohhh
The graph is about pairs of (x, y) which we put onto a plane
tbh I still dont understand
so the two points have one coordinate bc they're both chosen FROM the unit interval?
andd we're supposed to compare the distance if we put one point on the horizontal and the other on the vertical axis??
So, the two points are independently chosen on the unit interval
We then combine the data from those points to get a single point on the 2d plane
This is only a visualization trick
We compare distances purely 1 dimensionally
And separately
@gloomy plume
and what does A and B stand for here?
A = their distance is less than 1/2
A is the condition "both points are closer to the endpoint selected"
B is the condition "the distance between the points is less than 1/2"
Note here distance between the points refers to the two points on the number line
When we translate this into 2d each pair of points becomes a single point, so the "distance" between them isn't something that makes sense immediately.
But you can come up with an interpretation pretty quick
If we define the line y = x and measure the distance of our pair to this line then we get the distance between the points
In particular the two lines drawn on the solution graph are exactly the points such that the distance between them is exactly 1/2
Between these two lines is the region where the pairs are closer to the line y=x and so their distances between the two points on the number line are less than 1/2
how was the area calculated to get the probability for P(B)
@gloomy plume Has your question been resolved?
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Trying to prove theorem e6.
My attempt (im not sure if it is good enough)
Suppose o(x) and f(x) are not relatively prime. Then there exits some polynomial g(x) that divides both o(x) and f(x). Since o(x) is irreducible, g(x) can either be o(x) or a constant polynomial. If g(x) = o(x), then certainly g(x) does not divide f(x), since o(x) does not f(x) as given; if g(x) = c for some c in F (the field), a polynomial that is not of positive degree. Two polynomials are relatively prime if and only if no polynomial of positive degree divides each of them; so either case leads to a contradiction.
That's a good attempt
Because you proved it
@silk cave Has your question been resolved?
Thanks a lot
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I’m on theorem e7
My attempt:
let f(x) and g(x) be such polynomials. Supper they are not relatively prime, that is, there exists a polynomial h(x) of positive degree such that h(x) | f(x) and h(x) | g(x). h(x) | f(x) implies h(x) = f(x), since f(x) is irreducible (and h(x) cannot be a constant polynomial since it has positive degree). Similarly, h(x) | g(x) implies h(x) = g(x). This shows f(x) = g(x) = h(x). But g(x) and h(x) are distinct, so this is a contradiction.
Comment:
I think I’m missing something here; I don’t know where to use the monic property of the two polynomials
correct
Although the implication h(x) = f(x) is correct only if you choose h(x) to be monic
In general we only have h(x) = c f(x)
But this is just a small nitpick and it doesn't change much
Ohhh that makes a lot of sense
Tysm again
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can someone help me with this question
I think you show that the catalan recurrence is obyed as far as i know
obyed?
sorry obeyed
idk if you write it like this i am not an english native
but easiest is the bijection to dyck-paths i think
how have you defined the catalan numbers?
the definition is not given in the task, i just googled it
ok cuz you could define the catalan numbers like that
but probably they want you to relate it to the recurrence
yes, its from a combinatorics course
but still i dont really have an idea of how to solve it
i would take this definition:
$$C_0=0, \qquad C_{n}=\sum_{i=1}^n C_{i-1}C_{n-i}\quad n\geqslant 1$$
The Wikipedia page regarding the catalan number should be able to help you a lot better
cosmic
Mostly such questions are done by induction
But choice is yours
You could do this analogically
To the grid problem
yeah i figured that they want you to relate it to the recurrence, which is basically induction
i am not really sure of how i can apply this to the paranthesis part though?
Basically
Assume start with only assuming a
Count cases
Then move onto a,b
Count again
And so on
After certain time you will begin to see the pattern
As cosmic mentioned
This thing
ohh okay got it
Which is the catalan number
then i prove the recurrence by induction
Yet again I urge you to view the Wikipedia page which concerns the same
It is incredible
The insight is amazing
Worth a read in my opinion
They also have a proof exactly through this method
exactly, you have to split up your counting in the right way
great yeah i will check it out in more detail
ping if you need help again but yeah the proof is also just on the wiki page
@pure quail Has your question been resolved?
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Q42
Wants us to find the e area
The area
uh
Anyone
Do we need to use pythagorean
To find the leg
(Height)
any other information given in the question?
@wanton niche Has your question been resolved?
yes
but this seems kinda odd
since we have never seen a question with this many letters in our book
2 letters?
What
no i mean like
when u write the equatiojs
And stuff
It looks like alot
which can confuse (us) ig
im at 9th grade
try doing what you suggested
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I've been trying to solve this maximal flow problem but I'm not sure if this is the optimal network or if i did something wrong
i don;t understand :(
wow there are two numbers for every edge
is it like you can choose a direction, and that changes the weight?
i used ford-fulkerson algorithm in this problem
@modest blade Has your question been resolved?
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@modest blade Has your question been resolved?
@modest blade Has your question been resolved?
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How would I prove that a jump discontinuity is not a removable discontinuity?
if you already know you have a jump, then by definition
whats the definition of jump discontinuity
like lim x->a- f(x) =/= lim x->a+ f(x)?
one sided limits are different / exist
ohh okok
and then for removable it would be like lim x -> a f(x) =/= f(a)
but for lim x -> f(x) to exist, that implies lim x->a- f(x) = lim x->a+ f(x)
which contradicts our definition of jump discontinuity?
is that a valid proof
yeh
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I understand that the factorization goes like this
And plugging in 6 for x yields 5-1 as the first time, making it very easy to show that it's divisible
but how do i get from the first step (i guess 6^n-1) to the factorization?
are you saying you dont know where the factorization comes from?
i guess? i'm not quite sure if i can just slap that into my proof, and how to do so
it does hold true, though. (see attached link, not picture.)
youre not going to see where the factorization comes from until you expand it and see how its true
okay by RHS are we talking 6^n-1 or the image
it cant be this, becuase this is not an equation
also, you cannot expand something that is not factored
6^n - 1 is not factored
so you cannot expand it
do you understand
i guess but now i'm at a dead end because i don't see how to expand that giant mess
whats x^(m-1) times x
are you talking about this?
no, i don't see how i can implement it
no, it doesn't
?
consider the following about how belief works
and dont interrupt
in order to use something for a proof, you need to believe that its true first
now see here that, in their proof, they offer these lines to show that its true
however, learning this expansion is not part of your course
therefore its not required to be written
therefore you do not need to believe it to write it
i understand that
additionally
.
if you understood the proof, youd be able to see that one would need to lead to the other
since this is expected to be learned beforehand, you dont really have a choice in doing the same
so you just have to go from one side to the other without any requirement for additional lines to support it
however you are not doing this
which can only come from that you dont believe it enough to use it so tersely
no, it cannot only come from the fact that "i don't believe it enough to use it". it came from my belief that i might have to prove (that the factorization does go like that)
is learning to expand part of your course?
no
thank you
I told you this already
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im so lost
<@&286206848099549185>
guys pls help me ive been trying this problem for 30 minutes and i might crash out 😫 🙏
JD
that should be correct
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Did I do the first problem correct?
it says -infinity
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No, answer is 1
But in the limit you write it as infinity instead of minus infinity
oh is it thank u
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we found the dot product here to be 2.
what does the dot product stand for?
i guess? cuz my textbook gave me a nice formula and a pat on the back
and how to find an angle but
never said what the dot product does
the dot product essentially tells you how much two vectors are aligned
You can think of it in terms of forces
Say a train is held stationary onto a track
It can't go left or right
Only straight
And you apply a force at an angle 45° to the train
So how much of that force gets actually transferred to the train?
That's sort of the intuition here
but
is it normal my etxtbook isnt telling me anything about the use of it
at least
the
dot product itself
they have to tell you what it is early on so they can use it in formulas throughout the book
There's a lot of super cool uses of the dot product
yeah formulas, but not the result of the dot product itself
at least yet
Of the top of my mind I can think of a lot of data science applications
the dot product results in the dot product
there are many formulas which make use of it, but fundamentally the dot product is just an operation that you can perform on two vectors that gives a scalar
ah okay okay
No but do u get what the dot product is actually giving you
Try to get what that scalar is actually is
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The table below gives the selected values for a differentiable function h and its derivative h'. let g be the function with g(2)=0 and the derivative given by g'(x)=xcos(x^2) use the tale to answer question 6-9.
Q9) The point (2,1) lies on the curve in the xy plane given by the equation h(x)=g(x)^2 +xy. what is the value of dy/dx at the point (2,1)? Express your answer as a decimal approximation
,rotate
Does my work look good?
if anyone could double check
I am allowed a calculator but I didnt need one and i got the answer dy/dx= 1.5
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Ur welcome
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How do i approach this?
dy/dx = f
How do you get y?
@rain hare Has your question been resolved?
How do i solve this?
if dy/dx = f
then integrate both sides with respect to x to find y
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for b)
abgle between d and v, where is it exactly?
cuz they dont even have the same starting point
You can do translation
translation?
show the relationship between d and v
one is (1,1,0) and one is (1,1,1) ig?
thats the only way i think i can put it idk tho
so the angle would be when you draw the vectors from the same point
do you understand that?
oh
i need to assum
im starting at same point?
if so yeah i can just product dot
right
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how to proove this? If the function ( f ) is neither bounded above nor bounded below on any punctured neighborhood of the point ( a ), then ( \lim_{x \rightarrow a} f(x) ) does not exist.
Slowaq
you can construct a sequence for which f diverges to infinity or -infinity
then f(x) must be in some neighbbut i need to prove that it doesnt exists not that it diverges to infinity
you can construct two sequences that for the first diverges to infinity and the other diverges to -infinity
then if by absurd lim(f(x)) when x-> a existed, the limit of all sequences that converge to a must be that limit
can i just say that let limit exist and is equal to L iff for all epsilon>0 exist delta >0 that for all x in punctured delta neighbourhood of a f(x) in epsilon neighbourhood of L and that is in contradiction with my assumption that f(x) isnt bounded thus limit doesnt exist?
what is an epsilon neighborhood of L if L is an infinite limit
well in that case the definition of limit is this
and that is also in contradiction with my assumption
@fallow furnace Has your question been resolved?
that's + infinity limit
you will also have -infinity limit with a different definition
so suppose by absurd the limit exists
show that it can neither be finite, + infinity nor -infinity
Let us prove by contradiction. Assume that ( \lim_{x\to a} f(x) = L \in \overline{\mathbb{R}} ) and ( a \in \overline{\mathbb{R}} ). Since ( f(x) ) is not bounded on any punctured neighborhood of ( a ), we can consider two sequences
[
{x_n} \text{ such that } x_n \rightarrow a \text{ and } f(x_n) \rightarrow +\infty
]
[
{y_n} \text{ such that } y_n \rightarrow a \text{ and } f(y_n) \rightarrow -\infty
]
For ( \lim_{x\to a} f(x) = L ) to exist, it must hold that for all sequences converging to ( a ), their function values under ( f ) must converge to ( L ). However, this contradicts the existence of the sequences ( {x_n} ) and ( {y_n} ).
Slowaq
is this valid?
I think the closing argument, rather than "this contradicts the existence of ..." which is a little vague, would better be 'Then L = +infinity and L = -infinity, which is absurd'
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hi can someone help with this? I need to find AOB
can you find bcd
just find as many angles as you can
you can also find them in terms of x
thankss, i will try
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Let a and b be some constants satisfying 0<a<π/2<b<π. How can you show that the equation cos(x) = (x^4- a^4) (X²-b²) sin(x²) has at least two real solutions? Can you help me?
what have you tried
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I solved
$$(4x^{7})^{8} \times 4x^{11}=$$
$$4^{8}x^{56}\times4x^{11}=$$
$$4^9x^{67}$$
In the answers in the book I use it says the answer is $2^{18}x^{67}$
I know my answer is correct but their is simplified into prime numbers
$$(2^{2})^9x^67 = 2^{18}x^{67}$$
I just want to ask is there any reason for me to simplify it into prime numbers if I haven't been asked to?
𝕿𝖆𝖘𝖐
no ig
well it depends
ask your teacher in which form (s)he wants his/her answers
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Hello, I am a 9th grade student on a fast paced math track (algebra 2), I enjoy more advanced level math (calculus) and often self study. My question is: Is there a limit definition for integrals?
If so, how do I implement it for integrals
it is called the riemann sum
In this section we will formally define the definite integral, give many of its properties and discuss a couple of interpretations of the definite integral. We will also look at the first part of the Fundamental Theorem of Calculus which shows the very close relationship between derivatives and integrals.
thanks so much!
presumably you were introduced to integrals by taking rectangles and making them smaller and smaller
riemann sums are just that but precise
I am solving derivates using the limit def, and getting into integrals but I found that there was no universal rule available
if you do even more maths, it'll turn out in the future that the definition of the Riemann integral is actually quite bad and doesn't satisfy a lot of the properties you want it to satisfy
once u study measure theory, you'll find that the Lebesgue integral is a better way to define the integral
anyway that's something u can also read about once ur comfortable with the defn of the Riemann integral
while its a classic exercise to compute derivative with the limit def, you very rarely do that for integrals
strictly speaking for the riemann integral we need the limit of every possible riemann sum to converge to the same value. but if it does show up as an exercise in some calculus classes, usually you just calculate the limit of one riemann sum
thanks!
How is it possible for me to help other people in this server?
just go in their channel and help
👍
look in the other help channels or #1021175428326633542 for questions that seem interesting, then just start helping. there is a bit of guidance in #helpers-info
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I'm trying to remember this, some case I had come across ...
That,
√(2)² can only be +2
And, √4 can be ±2
Is that correct?
no
alr
It was this lol just searched up
When we want to evaluate the square root of a number, say 36, the answer is just positive 6. It is a common math mistake for students to say the answer is both positive 6 and negative 6. It is both positive and negative 6 when we want to solve the quadratic equation x^=36
Shop my math t-shirts & hoodies on Amazon: 👉 https://amzn.to/3qBeuw6
----...
well it can be explained by calculus
if u take the function f(x) = sqrt(x) youll that its positive
so it will have a positive outcome
x is a positive number, and sqrt(x) is also positive
W bprp
Kinda getting the feel of it
x is positive not negative
Thanks man later
W
np
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✅
√x is a real function and x² isn't?
It's dumb question I get it but
Depends on how you define them
Most of the time, you can assume both are real
I was scouring the net, and "Saying √4 is ±2 wouldn't make sqrt a real function, as gives off more than one real numbers" statement popped up
What does that mean exactly
Welp, first of all
How would you define a real function?
That's a real and real valued application, but you're still lacking something
If you're saying what I think you're saying then yeah
You can imagine a function as something that relates a set to another
Btw I like how you guys do it here, explaining through interactions and not just stating the right facts!
There's one thing real functions always satisfy though
Assume we've got two sets A={a,b,c,d} and B={e,f,g,h}
A function f:A->B will relate each element of A with, at most, one element of B
In other words, for any element of A, a_i, f(a_i) will give only one output, which will be in B
For real and real valued functions(the most common type) the only difference is that both sets, A and B, are the reals
Going back to the square root now
We know(or at least in most cases assume) it is a real valued function
So if a belongs to R, the square root of a can, at most, be one number
As to why it's the positive one, it's more of a definition thing, but there's why the square root of any real number(over the reals) is both unique and positive
Wdym?
Idk if it's what you're asking but it's a non-surjective non-injective function
Yeah what i was thinking was all over the place but I get it thanks
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I just need a fast explenation about something.
im studying logarithms and im encountering log3(1/9)
the "1/9" became 3^-2.
why? and how did it transform a fraction into a power?
yes
So what is 1/3^2?
Yes
But we are trying to rewrite it
Do you recall how to rewrite a reciprocal like above into a power?
List the powers of 3
3, 9, 27, 81, ...
notice that each term you're multiplying by 3, so 3×9 = 27, 3×27 = 81, etc
If you go backwards you can say that any term is a third of the next
so 81/3 = 27, 27/3 = 9, etc.
we know 3¹ = 3, how would we find 3⁰? well, to get the previous term, divide by 3, so 3⁰ = 3¹/3 = 1 so 3⁰ = 1.
What about 3 to the minus one? you know 3⁰ is 1 so if you divide by 3 again you get 1/3, so 3 to the minus one is 1/3, and this goes on, so 3 to the negative k is 1/3^k
hmm
Yup!
oh so i just remove the 1, then 3^2 becomes 3^-2
Yes
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Hi, could anyone give me some pointers for this problem? Our professor likes to take each of these roots and "substitute" for them (So it becomes An-Bn/Cn-Dn where n is like the index of the set).
He then went on to do lim An/n = 1, same for BCD and that is easy to understand. What isn't simple, though, is everything else.
I don't expect anyone to solve this with steps, neither do I need the answer (which is -1 for those interested), but I would really appreciate some help.
ummmmm, I don't think I'm catching on? :d
My question might make more sense if I send the notes from my tablet I think
from green to blue you can factor out the n^x from under the radical
for example, take the first term in the numerator from the original function
you can factor out n^3 to get
cube-root(n^3(1+1/n^3))
then just take the cube root of n^3 to output n
the term becomes n*cube-root(1+1/n^3)
you can repeat this process for the remaining 3 terms to obtain what i wrote in the blue
does that make sense?
as a side note, i should really learn latex 😂
Yep, we get n from all the roots there, ye
or wtv bot this server uses
That far I understood
but after that, the professor just went rogue - I really think I need to send the SS so it makes sense
do you know how i went from green to blue though?
Yes
okay so from there, the n's cancel out right?
All of the roots behave "almost" like n for large enough n
yep
okay mb
This is what we've done. The top half makes sense, but the lim n to the fifth over n to the fourth A-B is where I am completely lost)
im blind bruh
from here im also a little stumped
but i can tell how i reasoned it
don't have a rigorous scientific explanation though
so for the numerator, for any n>0 the second term will always be greater than the first
in the denominator, for any n>0 the first term will always be greater than the second
thus the numerator evalutes to a tiny negative value, and the denominator a small positive value
and the magnitudes of the values are the same so as n->infinity it becomes -1
I appreciate your help - I'll look into it more and hopefully get that eureka moment.
<@&286206848099549185> would any of you understand the "6th line"? Where we take the limit of (A-B), but multiply it first?
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Please I’m stuck on it for two hours
i recommend reading up on concave/convex and when it changes https://tutorial.math.lamar.edu/Classes/CalcI/ShapeofGraphPtII.aspx
In this section we will discuss what the second derivative of a function can tell us about the graph of a function. The second derivative will allow us to determine where the graph of a function is concave up and concave down. The second derivative will also allow us to identify any inflection points (i.e. where concavity changes) that a funct...
especially example 1
So when it opens up
So that’s what I did
It starts going up at -1
Then starts going down at 1
you're not thinking of the definition of concavity correctly
Wait wtf
It can concave up down going down
Okay so I know which is which but how does that tell me the inflection points
read to find out
A bowl can be facing up or down. In both cases u can either trace ur finger up or down the bowl
It doesn’t talk about inflection points
Unless I’m blind
Here
Im a bit rusty on vocab, is inflection point just the point where the bowl starts facing the otther way?
On the side there is even the definition of inflection point
That’s what I’m trying to understand 😭
Yep
can i introduce you to ctrl + f
WAIT ITS THE IN BETWEEN THEM???
The huh? In between the bowls? Sure
So 0,0???
Nah
U gotta find where the next “bowl” begins
This location is where the slope suddenly changes direction
The bowl is just an analogy for concavity
The first bowl still ends
The start of a bowl, if there is one, is the end of another
If u wana think of it like that
My brain
I understand none of this
And reading doesn’t help me understand it
I understand by doing it and by seeing someone do it
I know you guys are trying to make me understand it myself but I don’t
It makes 0 sense
This is the point between the two bowls
Here in my graph it’s 0,0
But it’s wrong
So I don’t get it
Yes two graphs
Maybe this vid can help? https://youtu.be/dkoJWBhx8CA?feature=shared
This video provides an example of how to find the interval where a function is increasing or decreasing, and concave up or concave down. The relative extrema and points of inflection are also found.
Site: http://mathispower4u.com
Weird, id assume it would be that point as well based on ur graph
Wdym its infinite?
To the sides there is no other bump
Isnt the other bump shown here?
Or is that another graph
No sorry
Two bumps
One graph
But then the point in the middle is the thing you sent before
Seems like it
Weird
Whats the whole question? Can i see it plz?
The hell
🥲🥲
Lmao yeah its the origin
No clue y its wrong
Try the peaks
Just to f around
Also
Maybe this is the “first bowl”
Check by seeing if the slope decides to change direction
In the red, the slope seems to get more negative and negative until it decides to turn around and start increasing to make the new bowl
@mellow frigate Has your question been resolved?
😫😫😫
@mellow frigate Has your question been resolved?
Was it not this? @mellow frigate
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i would like to know
what would you like to know? 
they are the same formula, just rewitten with trig identities
i meanbt like the
left and right
they the matrix here combined
two orthogonal projections
you will get the orthogonal projection of any vector $\begin{bmatrix} x \ y \end{bmatrix}$ by mulitplying by the given matrix
cloud
ok ty thats what i meant
it's quite powerful because it means we can represent a pretty large class of transformations (what we like to call functions that turn vectors into other vectors) as just multiplying by a particular matrix
@lyric kelp Has your question been resolved?
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if i undertsnad
we would get the same result for any scalar multiple of a, yes
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we want to find the maximum area of BCDF
i’m confused what “maximum area” even means lol
didn’t they already define a trapezoid? there’s only one area
is there not?

heyy
yes
Maximum area of that thingo?
the full question is to show that the maximum area > 37
but that part is irrelevant
so i was just talking about the maximum area of that thing
yes
no
But usually for these question they give a maximum perimeter and want you to use a quadratic equation to find the maximum area for it
But this doesn’t have anything else so I just need to clarify
What about the FD line
yeah cuz you have the bias that this is an optimization question
when it doesn’t have to be 😭
anyway this is a geometry problem
now that i think about it
B, F, and D have no restrictions on them
well other than the most obvious ones
but they can move around in their respective line segments
and u have to maximize the area of whatever formed
the side lengths of the triangle can all be computed 

Yeah so
Would that not just be
The area of the whole shape?
what

B probably can’t be A
Wait
for example
also if you make the trapezoid a triangle, you’re deforming the topology of the trapezoid
it’s not four sided anymore

and it says maximum area of BCDF so you can’t decay it into BCD or BCF, for example
So you can’t have a 3 sided shape?
that doesn’t affect the topology of the trapezoid
Ok got it
No I think I get what she’s tryna say
You can’t have a 3 sided shape right?
i mean the english definition of topology
not the math one 
Ok wait what’s the answer for this?
i’m still not 100% sure what the question is. you can put B and D anywhere so long as BF and CD are parallel?
Yeah tbh I’m also confused abt that
yes
i think
tbh i don’t know either
hence my question
what about F? anywhere as well?
yes
Bruh
Is there a provided solution or answer
the provided solution is something something rectangle maximizes the area
that makes no sense
Huh
the annotation is a hint towards the actual solution
Wait
you can just choose F and B close to A and D close to E and get arbitrarily close to the area of the whole triangle?
😭that’s true
i’m lost as well
that’s literally all there is to the question
also wait
meh okay the angle 105
That’s exactly what I was thinking
can be preserved too while doing that
But it can’t possibly be that
so F is fixed
not that i know of
the question posted is all info there is
uhm the chances of the question being posed weirdly is also high
so you won’t be wrong in saying the question is bad or smth
idfk. is it supposed to be whatever point makes that angle 105 degrees?
ok well
the question is absoluetly terrible
😭yesss i think so
the line segment connecting F and D
has to be at a 105 degree angle (my guess)
or does it just say whatever you said back there
it’s greater than 37 always
bruh
well ms mmmm7 idk what to say anymore
does it say less than any number?
it’s okay
thank you for being here

no wait we gotta get to the bottom of this
remember the exercise i posted above
u have to show the maximum area > 37
if we move the sines as close to the triangle's edges as possible then technically its always less than the triangle's area is it not?
bruh
of course
is F the midpoint

no
that’s an annotation
the printed stuff should say something
the one on red is just writing
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How would you notate a probability density function?
Say I have a particular probability function p(x) with equations:
how would I notate these equations to represent the probability function p(x)? Note that I've used f(x) as a placeholder
U can use the notation of piece wise functions
how would I do that exactly?
I'm not sure how to do piecewise notation in google docs
One sec I’ll show you
$$P(X = x) =
\begin{cases}
\frac{4}{143} x - \frac{92}{143} & \text{if } 23 \leq x \leq 28.5 \
-\frac{4}{195} x + \frac{48}{65} & \text{if } 28.5 < x \leq 36 \
0 & \text{otherwise}
\end{cases}
$$
also, do I need to capitalise the X in any place considering this is a random variable?
Edmund Cloudsley
Yeah
alright, thanks! Just wondering if there's any way to notate this in google docs
Are u righting a maths paper or smth?
If so, I highly recommend Overleaf
similar
Over google docs
Okay then
It might be a good idea to use #latex-testing to create your screenshots using latex
And put that into google docs
Cause maths with google docs is really frustrating (one of the reasons I learnt overleaf :))
overleaf is a good place to do latex
Also if you want more privacy, you want more privacy
Like if it’s a confidential paper or smth
You can create your own server
And put latex bot there
@elfin berry
This one ⬆️
alright!
Ciao
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how do we find x
without a calculator (this is supposed to be done quickly)
answer is (-2(1+i) , 1)
do the matrix multiplication
alright, let me try
neon
the det = 0, i cant inverse it
Yeah well
Carry out the multiplication
on the left side
And then match the entries on either side
?
You can multiply the two matrices on the left
Normally
You'll get a column vector, equate each component of that vector to 0
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how can i rigorouosly proove that $\lim_{x \to 0 }\sin\left(\frac{1}{x}\right)$ doesnt exist
Slowaq
@fallow furnace Has your question been resolved?
think about $lim_{y\rightarrow \infty}sin(y)$?
ThM
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hi
Can we say y=2e^t+ce^(-t) or did I do smth wrong ?
No
why it is wrong tho ?
you'd have take the reciprocal of the whole side
not whatever you want in any order you want
if z = x + y we can't say z-1 = x-1 + y-1
we have 1/( 2e^(-t)+ce^t )
we can take stuff with the opposite pow, right
oh wait
we have to take the whole expression right ?
like ( )^-1
Yeah
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hi i am confused by R ∘ R⁻¹
shouldnt aRb in R and bRa in R-1 lead to the final pair (a,a), thus (a, b) and (b, a) should not be included
@ruby matrix Has your question been resolved?
@ruby matrix Has your question been resolved?
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