#help-33

1 messages · Page 186 of 1

faint coral
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im wondering, how hard it is and what are the steps to finding the solutions of a cubic function that has an irrational real root and an irrational complex conjugate, such as 2x^3-7x^2+14x-11

marsh citrusBOT
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@faint coral Has your question been resolved?

faint coral
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<@&286206848099549185>

faint coral
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yes

neat granite
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Ok

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I have no idea how to solve it my bad

vivid wren
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I can help. you can easily reach me nbox

faint coral
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its ok

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marsh citrusBOT
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cosmic veldt
#

does anyone know the reaoning or can explain why the cross product gives the area of a parreleogram (or half it a traingle in this case)
is the cross product not the normal to a plane made by two vectors

cosmic veldt
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so how is the magnitude of a cross product the area?

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but if its too complciated im fine ig

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nvm sigh

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untold wyvern
#

I need to show that for n>6, the product of the first n-1 primes is greater than the cube of the nth prime. Could anyone hint me on what to do?

untold wyvern
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I have tried using bertrand's postulate but it doesn't seem to give me what I want

marsh citrusBOT
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@untold wyvern Has your question been resolved?

fleet fossil
marsh citrusBOT
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@untold wyvern Has your question been resolved?

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manic brook
marsh citrusBOT
manic brook
#

Help

lucid zenith
#

since you have a polynomial here, think of it as a function $$f(x)=(4x^2+x-2)^4(2x^2-x+2)^3=a_0+a_1x+a_2x^2+...+a_nx^n$$

elfin berryBOT
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kheerii

lucid zenith
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then what's the sum you need?

manic brook
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Shld I like take x= 1 in the first part and um and add it with 2 of the second part

lucid zenith
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what?

manic brook
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Idk what I was trying either

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Could u elaborate what u thought of

lucid zenith
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in terms of the coefficients

manic brook
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Sum of all coefficient with x raised to an even power

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But like without expanding it

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(condition)

lucid zenith
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what is that in terms of the notation I introduced?

manic brook
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Huh?

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U mean like expanding the thing?

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marsh citrusBOT
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oblique karma
#

how do i add 2 vectors in a triangle if they are not like AB+BC? like if they go like this? in my book i only see how to solve if they are like AB+BC or BC+CA or CA+AB

junior copper
oblique karma
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but if they are like this idk how to add them

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usually the vectors are like this or in reverse

unreal oxide
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and another one CB

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u move the tail of the arrow CB to the tip of CA

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and add them like u normally wud

oblique karma
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ohh

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thank you

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marsh citrusBOT
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junior copper
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just the tip 🎶

oblique karma
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.reopen

marsh citrusBOT
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oblique karma
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wait, what if both vectors are going in the same point? like AC+ BC?

still temple
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you would still do the same thing

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head to tail

oblique karma
#

ok, thank you

#

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gloomy plume
marsh citrusBOT
gloomy plume
#

can someone explain this to me?

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I have solution here but cant make any sense of it

marsh citrusBOT
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@gloomy plume Has your question been resolved?

gloomy plume
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anyone? 🥺

marsh citrusBOT
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@gloomy plume Has your question been resolved?

quiet anvil
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@gloomy plume green area is possible, red is impossible

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Gray area from original image satisfies the condition

gloomy plume
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why is it -1/2 < y - x < 1/2

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like shouldnt every point have both x & y coordinates?

quiet anvil
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"Given their distance is less than 1/2"

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x is a number between 0 and 1.

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y is also a number between 0 and 1

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So the graph above shows pairs of numbers (x, y) between (0, 0) and (1, 1)

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The green area is where the distance condition is satisfied (this is B)

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The gray area is where the endpoint condition is satisfied (this is A)

gloomy plume
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the endpoints are (0,1) and (1,0) ??

quiet anvil
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The endpoints are just (0, 0) and (1, 1). However, only one of these is the endpoint specified. The solution assumes the endpoint is (0, 0) without loss of generality.

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Or more specifically, the endpoint is just 0 or just 1

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And both x and y need to be closer to 0 than 1 (if 0 was specified)

gloomy plume
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I am still very confused

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I feel very dumb

gloomy plume
# gloomy plume

so the x & y in the equality are meant to be a point's coordinates right?

quiet anvil
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So you have two points, x and y. Each point is just a single value

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Between 0 and 1

gloomy plume
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ohhh

quiet anvil
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The graph is about pairs of (x, y) which we put onto a plane

gloomy plume
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tbh I still dont understand

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so the two points have one coordinate bc they're both chosen FROM the unit interval?

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andd we're supposed to compare the distance if we put one point on the horizontal and the other on the vertical axis??

quiet anvil
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So, the two points are independently chosen on the unit interval

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We then combine the data from those points to get a single point on the 2d plane

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This is only a visualization trick

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We compare distances purely 1 dimensionally

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And separately

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@gloomy plume

gloomy plume
quiet anvil
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A is the condition A from the solution. P(A)

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Similarly with B

gloomy plume
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A = their distance is less than 1/2

quiet anvil
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A is the condition "both points are closer to the endpoint selected"

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B is the condition "the distance between the points is less than 1/2"

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Note here distance between the points refers to the two points on the number line

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When we translate this into 2d each pair of points becomes a single point, so the "distance" between them isn't something that makes sense immediately.

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But you can come up with an interpretation pretty quick

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If we define the line y = x and measure the distance of our pair to this line then we get the distance between the points

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In particular the two lines drawn on the solution graph are exactly the points such that the distance between them is exactly 1/2

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Between these two lines is the region where the pairs are closer to the line y=x and so their distances between the two points on the number line are less than 1/2

gloomy plume
# quiet anvil

how was the area calculated to get the probability for P(B)

quiet anvil
#

@gloomy plume

marsh citrusBOT
#

@gloomy plume Has your question been resolved?

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silk cave
#

Trying to prove theorem e6.
My attempt (im not sure if it is good enough)

Suppose o(x) and f(x) are not relatively prime. Then there exits some polynomial g(x) that divides both o(x) and f(x). Since o(x) is irreducible, g(x) can either be o(x) or a constant polynomial. If g(x) = o(x), then certainly g(x) does not divide f(x), since o(x) does not f(x) as given; if g(x) = c for some c in F (the field), a polynomial that is not of positive degree. Two polynomials are relatively prime if and only if no polynomial of positive degree divides each of them; so either case leads to a contradiction.

royal sable
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Because you proved it

marsh citrusBOT
#

@silk cave Has your question been resolved?

silk cave
marsh citrusBOT
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silk cave
#

I’m on theorem e7

My attempt:

let f(x) and g(x) be such polynomials. Supper they are not relatively prime, that is, there exists a polynomial h(x) of positive degree such that h(x) | f(x) and h(x) | g(x). h(x) | f(x) implies h(x) = f(x), since f(x) is irreducible (and h(x) cannot be a constant polynomial since it has positive degree). Similarly, h(x) | g(x) implies h(x) = g(x). This shows f(x) = g(x) = h(x). But g(x) and h(x) are distinct, so this is a contradiction.

Comment:
I think I’m missing something here; I don’t know where to use the monic property of the two polynomials

royal sable
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Although the implication h(x) = f(x) is correct only if you choose h(x) to be monic

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In general we only have h(x) = c f(x)

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But this is just a small nitpick and it doesn't change much

silk cave
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Tysm again

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marsh citrusBOT
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marsh citrusBOT
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pure quail
#

can someone help me with this question

marsh citrusBOT
quaint solar
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I think you show that the catalan recurrence is obyed as far as i know

pure quail
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obyed?

quaint solar
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sorry obeyed

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idk if you write it like this i am not an english native

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but easiest is the bijection to dyck-paths i think

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how have you defined the catalan numbers?

pure quail
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the definition is not given in the task, i just googled it

quaint solar
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ok cuz you could define the catalan numbers like that

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but probably they want you to relate it to the recurrence

pure quail
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yes, its from a combinatorics course

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but still i dont really have an idea of how to solve it

proud arch
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Hello

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This a classic proof for the catalan's number

quaint solar
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i would take this definition:
$$C_0=0, \qquad C_{n}=\sum_{i=1}^n C_{i-1}C_{n-i}\quad n\geqslant 1$$

proud arch
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The Wikipedia page regarding the catalan number should be able to help you a lot better

elfin berryBOT
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cosmic

proud arch
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Mostly such questions are done by induction

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But choice is yours

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You could do this analogically

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To the grid problem

quaint solar
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yeah i figured that they want you to relate it to the recurrence, which is basically induction

proud arch
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Whatever works out for you

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Agreed

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@quaint solar

pure quail
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i am not really sure of how i can apply this to the paranthesis part though?

proud arch
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Basically

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Assume start with only assuming a

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Count cases

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Then move onto a,b

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Count again

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And so on

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After certain time you will begin to see the pattern

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As cosmic mentioned

proud arch
pure quail
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ohh okay got it

proud arch
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Which is the catalan number

pure quail
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then i prove the recurrence by induction

proud arch
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Yet again I urge you to view the Wikipedia page which concerns the same

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It is incredible

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The insight is amazing

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Worth a read in my opinion

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They also have a proof exactly through this method

quaint solar
pure quail
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great yeah i will check it out in more detail

quaint solar
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ping if you need help again but yeah the proof is also just on the wiki page

marsh citrusBOT
#

@pure quail Has your question been resolved?

marsh citrusBOT
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wanton niche
marsh citrusBOT
wanton niche
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Q42

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Wants us to find the e area

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The area

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uh

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Anyone

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Do we need to use pythagorean

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To find the leg

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(Height)

sturdy condor
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any other information given in the question?

marsh citrusBOT
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@wanton niche Has your question been resolved?

wanton niche
#

Thats all

tight kite
wanton niche
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but this seems kinda odd

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since we have never seen a question with this many letters in our book

tight kite
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2 letters?

wanton niche
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What

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no i mean like

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when u write the equatiojs

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And stuff

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It looks like alot

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which can confuse (us) ig

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im at 9th grade

tight kite
#

try doing what you suggested

marsh citrusBOT
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modest blade
#

I've been trying to solve this maximal flow problem but I'm not sure if this is the optimal network or if i did something wrong

sleek lake
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i don;t understand :(

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wow there are two numbers for every edge

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is it like you can choose a direction, and that changes the weight?

modest blade
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i used ford-fulkerson algorithm in this problem

marsh citrusBOT
#

@modest blade Has your question been resolved?

modest blade
#

<@&286206848099549185>

marsh citrusBOT
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@modest blade Has your question been resolved?

marsh citrusBOT
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@modest blade Has your question been resolved?

modest blade
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tulip sundial
#

How would I prove that a jump discontinuity is not a removable discontinuity?

late geode
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if you already know you have a jump, then by definition

tulip sundial
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whats the definition of jump discontinuity

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like lim x->a- f(x) =/= lim x->a+ f(x)?

late geode
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one sided limits are different / exist

tulip sundial
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ohh okok

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and then for removable it would be like lim x -> a f(x) =/= f(a)

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but for lim x -> f(x) to exist, that implies lim x->a- f(x) = lim x->a+ f(x)

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which contradicts our definition of jump discontinuity?

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is that a valid proof

late geode
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yeh

tulip sundial
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alright thanks boss

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torn estuary
#

I understand that the factorization goes like this

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And plugging in 6 for x yields 5-1 as the first time, making it very easy to show that it's divisible

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but how do i get from the first step (i guess 6^n-1) to the factorization?

vital oracle
torn estuary
vital oracle
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you need to learn that

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expand the RHS to see that its true

torn estuary
vital oracle
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youre not going to see where the factorization comes from until you expand it and see how its true

torn estuary
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okay by RHS are we talking 6^n-1 or the image

vital oracle
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it cant be this, becuase this is not an equation

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also, you cannot expand something that is not factored

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6^n - 1 is not factored

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so you cannot expand it

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do you understand

torn estuary
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i guess but now i'm at a dead end because i don't see how to expand that giant mess

vital oracle
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whats x^(m-1) times x

torn estuary
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are you talking about this?

vital oracle
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yes

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you dont believe it

torn estuary
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no, i don't see how i can implement it

vital oracle
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that means

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you dont believe it

torn estuary
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no, it doesn't

vital oracle
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consider the following about how belief works

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and dont interrupt

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in order to use something for a proof, you need to believe that its true first

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now see here that, in their proof, they offer these lines to show that its true

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however, learning this expansion is not part of your course

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therefore its not required to be written

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therefore you do not need to believe it to write it

torn estuary
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i understand that

vital oracle
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additionally

vital oracle
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if you understood the proof, youd be able to see that one would need to lead to the other

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since this is expected to be learned beforehand, you dont really have a choice in doing the same

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so you just have to go from one side to the other without any requirement for additional lines to support it

vital oracle
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which can only come from that you dont believe it enough to use it so tersely

torn estuary
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no, it cannot only come from the fact that "i don't believe it enough to use it". it came from my belief that i might have to prove (that the factorization does go like that)

vital oracle
torn estuary
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no

vital oracle
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you get to skip this

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you get to skip proving it

torn estuary
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thank you

vital oracle
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I told you this already

torn estuary
#

.close

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arctic crow
#

im so lost

marsh citrusBOT
arctic crow
#

<@&286206848099549185>

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guys pls help me ive been trying this problem for 30 minutes and i might crash out 😫 🙏

elfin berryBOT
idle lagoon
#

that should be correct

arctic crow
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omg life saver thank you so much

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shy shard
#

Did I do the first problem correct?

marsh citrusBOT
quick moth
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it says -infinity

shy shard
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Oh

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Negative one then mb

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Thank u

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still temple
#

But in the limit you write it as infinity instead of minus infinity

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lyric kelp
#

we found the dot product here to be 2.

marsh citrusBOT
lyric kelp
#

what does the dot product stand for?

vital frost
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Ur asking what the dot product represents?

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Like fundamentally

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?

lyric kelp
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and how to find an angle but

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never said what the dot product does

vital frost
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the dot product essentially tells you how much two vectors are aligned

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You can think of it in terms of forces

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Say a train is held stationary onto a track

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It can't go left or right

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Only straight

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And you apply a force at an angle 45° to the train

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So how much of that force gets actually transferred to the train?

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That's sort of the intuition here

lyric kelp
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i

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kinda kinda get it

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but yeah ty ill look into it more

lyric kelp
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is it normal my etxtbook isnt telling me anything about the use of it

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at least

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the

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dot product itself

fervent rampart
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they have to tell you what it is early on so they can use it in formulas throughout the book

vital frost
lyric kelp
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at least yet

vital frost
#

Of the top of my mind I can think of a lot of data science applications

fervent rampart
#

the dot product results in the dot product

#

there are many formulas which make use of it, but fundamentally the dot product is just an operation that you can perform on two vectors that gives a scalar

lyric kelp
#

ah okay okay

vital frost
#

No but do u get what the dot product is actually giving you

#

Try to get what that scalar is actually is

lyric kelp
#

im trying to extort that information out of chatgpt

#

.close

marsh citrusBOT
#
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bright sundial
#

The table below gives the selected values for a differentiable function h and its derivative h'. let g be the function with g(2)=0 and the derivative given by g'(x)=xcos(x^2) use the tale to answer question 6-9.

Q9) The point (2,1) lies on the curve in the xy plane given by the equation h(x)=g(x)^2 +xy. what is the value of dy/dx at the point (2,1)? Express your answer as a decimal approximation

bright sundial
#

,rotate

elfin berryBOT
bright sundial
#

Does my work look good?

#

if anyone could double check

#

I am allowed a calculator but I didnt need one and i got the answer dy/dx= 1.5

proud arch
#

Hello @bright sundial

#

Their seem to be a few errors in your work

proud arch
#

1+ 2 y'

#

Is not 3 y'

#

So y'= -3/2

#

Rest seems to be correct

marsh citrusBOT
#

@bright sundial Has your question been resolved?

bright sundial
#

thank you!

marsh citrusBOT
#
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proud arch
#

Ur welcome

marsh citrusBOT
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rain hare
#

How do i approach this?

marsh citrusBOT
modern sedge
marsh citrusBOT
#

@rain hare Has your question been resolved?

rain hare
#

How do i solve this?

modern sedge
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lyric kelp
#

for b)

marsh citrusBOT
lyric kelp
#

abgle between d and v, where is it exactly?

#

cuz they dont even have the same starting point

limber hearth
#

You can do translation

lyric kelp
#

translation?

still temple
#

show the relationship between d and v

lyric kelp
#

one is (1,1,0) and one is (1,1,1) ig?

#

thats the only way i think i can put it idk tho

still temple
#

so the angle would be when you draw the vectors from the same point

#

do you understand that?

lyric kelp
#

i need to assum

#

im starting at same point?

#

if so yeah i can just product dot

still temple
#

right

lyric kelp
#

it

#

and find

#

angle with cos

#

okok tyyt

#

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fallow furnace
#

how to proove this? If the function ( f ) is neither bounded above nor bounded below on any punctured neighborhood of the point ( a ), then ( \lim_{x \rightarrow a} f(x) ) does not exist.

elfin berryBOT
#

Slowaq

fallow furnace
#

can i jus tdo it by contradiction

#

lets assume that it exists

night mica
#

you can construct a sequence for which f diverges to infinity or -infinity

fallow furnace
spark otter
#

then if by absurd lim(f(x)) when x-> a existed, the limit of all sequences that converge to a must be that limit

fallow furnace
spark otter
fallow furnace
#

well in that case the definition of limit is this

#

and that is also in contradiction with my assumption

marsh citrusBOT
#

@fallow furnace Has your question been resolved?

spark otter
#

you will also have -infinity limit with a different definition

#

so suppose by absurd the limit exists

#

show that it can neither be finite, + infinity nor -infinity

fallow furnace
# spark otter that's + infinity limit

Let us prove by contradiction. Assume that ( \lim_{x\to a} f(x) = L \in \overline{\mathbb{R}} ) and ( a \in \overline{\mathbb{R}} ). Since ( f(x) ) is not bounded on any punctured neighborhood of ( a ), we can consider two sequences
[
{x_n} \text{ such that } x_n \rightarrow a \text{ and } f(x_n) \rightarrow +\infty
]
[
{y_n} \text{ such that } y_n \rightarrow a \text{ and } f(y_n) \rightarrow -\infty
]
For ( \lim_{x\to a} f(x) = L ) to exist, it must hold that for all sequences converging to ( a ), their function values under ( f ) must converge to ( L ). However, this contradicts the existence of the sequences ( {x_n} ) and ( {y_n} ).

elfin berryBOT
#

Slowaq

fallow furnace
#

is this valid?

spark otter
marsh citrusBOT
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covert falcon
#

hi can someone help with this? I need to find AOB

whole thorn
#

just find as many angles as you can

#

you can also find them in terms of x

covert falcon
#

thankss, i will try

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cinder pilot
#

Let a and b be some constants satisfying 0<a<π/2<b<π. How can you show that the equation cos(x) = (x^4- a^4) (X²-b²) sin(x²) has at least two real solutions? Can you help me?

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gray crystal
#

I solved
$$(4x^{7})^{8} \times 4x^{11}=$$
$$4^{8}x^{56}\times4x^{11}=$$
$$4^9x^{67}$$
In the answers in the book I use it says the answer is $2^{18}x^{67}$
I know my answer is correct but their is simplified into prime numbers
$$(2^{2})^9x^67 = 2^{18}x^{67}$$
I just want to ask is there any reason for me to simplify it into prime numbers if I haven't been asked to?

elfin berryBOT
#

𝕿𝖆𝖘𝖐

pliant willow
#

no ig

#

well it depends

#

ask your teacher in which form (s)he wants his/her answers

gray crystal
#

hmm ok

#

thx

#

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quick raft
#

Hello, I am a 9th grade student on a fast paced math track (algebra 2), I enjoy more advanced level math (calculus) and often self study. My question is: Is there a limit definition for integrals?

quick raft
#

If so, how do I implement it for integrals

fervent rampart
#

it is called the riemann sum

quick raft
devout mauve
#

presumably you were introduced to integrals by taking rectangles and making them smaller and smaller

#

riemann sums are just that but precise

quick raft
#

I am solving derivates using the limit def, and getting into integrals but I found that there was no universal rule available

mellow crag
#

if you do even more maths, it'll turn out in the future that the definition of the Riemann integral is actually quite bad and doesn't satisfy a lot of the properties you want it to satisfy

#

once u study measure theory, you'll find that the Lebesgue integral is a better way to define the integral

#

anyway that's something u can also read about once ur comfortable with the defn of the Riemann integral

devout mauve
#

while its a classic exercise to compute derivative with the limit def, you very rarely do that for integrals

fervent rampart
#

strictly speaking for the riemann integral we need the limit of every possible riemann sum to converge to the same value. but if it does show up as an exercise in some calculus classes, usually you just calculate the limit of one riemann sum

quick raft
devout mauve
#

just go in their channel and help

quick raft
fervent rampart
quick raft
#

👍

#

.close

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inland hill
#

I'm trying to remember this, some case I had come across ...

That,
√(2)² can only be +2
And, √4 can be ±2

inland hill
#

Is that correct?

hidden dawn
#

no

inland hill
#

Just wait a se

#

Sec

hidden dawn
#

alr

inland hill
#

It was this lol just searched up

https://youtu.be/NBOlK_rSsm4?si=5MhJ9u8PqE5zwXBk

When we want to evaluate the square root of a number, say 36, the answer is just positive 6. It is a common math mistake for students to say the answer is both positive 6 and negative 6. It is both positive and negative 6 when we want to solve the quadratic equation x^=36

Shop my math t-shirts & hoodies on Amazon: 👉 https://amzn.to/3qBeuw6
----...

▶ Play video
hidden dawn
#

well it can be explained by calculus

#

if u take the function f(x) = sqrt(x) youll that its positive

#

so it will have a positive outcome

#

x is a positive number, and sqrt(x) is also positive

hidden dawn
#

(speaking of real numbers ofc)

#

wait no i messed it up

inland hill
hidden dawn
#

x is positive not negative

inland hill
#

Thanks man later

inland hill
hidden dawn
#

np

inland hill
#

.close

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#
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inland hill
#

.reopen

#

.reopen

marsh citrusBOT
#

inland hill
#

It's dumb question I get it but

uncut oasis
#

Most of the time, you can assume both are real

inland hill
#

I was scouring the net, and "Saying √4 is ±2 wouldn't make sqrt a real function, as gives off more than one real numbers" statement popped up

#

What does that mean exactly

uncut oasis
#

How would you define a real function?

inland hill
#

Well how would?

#

Domain is real and so is range

uncut oasis
inland hill
#

What would that be

#

Ohh

#

Pairs?

uncut oasis
#

You can imagine a function as something that relates a set to another

inland hill
#

Btw I like how you guys do it here, explaining through interactions and not just stating the right facts!

uncut oasis
#

Assume we've got two sets A={a,b,c,d} and B={e,f,g,h}

#

A function f:A->B will relate each element of A with, at most, one element of B

#

In other words, for any element of A, a_i, f(a_i) will give only one output, which will be in B

#

For real and real valued functions(the most common type) the only difference is that both sets, A and B, are the reals

inland hill
#

Yuo

#

Yup

uncut oasis
#

Going back to the square root now

#

We know(or at least in most cases assume) it is a real valued function

#

So if a belongs to R, the square root of a can, at most, be one number

#

As to why it's the positive one, it's more of a definition thing, but there's why the square root of any real number(over the reals) is both unique and positive

inland hill
#

👍

#

So what we say x² a kind of function is?

uncut oasis
inland hill
#

What kind of function x² be

#

No no sorry I get it lol

#

Later mate thanks 👍

uncut oasis
inland hill
#

.close

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#
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maiden relic
#

I just need a fast explenation about something.
im studying logarithms and im encountering log3(1/9)
the "1/9" became 3^-2.
why? and how did it transform a fraction into a power?

nimble prairie
#

You can rewrite 9 as 3^2

#

Do u agree?

maiden relic
#

yes

nimble prairie
#

So what is 1/3^2?

maiden relic
#

uhh

#

its still 1/9

nimble prairie
#

Yes

#

But we are trying to rewrite it

#

Do you recall how to rewrite a reciprocal like above into a power?

maiden relic
#

ye 1/x = x^-1

#

oh

tight kite
#

List the powers of 3

3, 9, 27, 81, ...

notice that each term you're multiplying by 3, so 3×9 = 27, 3×27 = 81, etc

If you go backwards you can say that any term is a third of the next

so 81/3 = 27, 27/3 = 9, etc.

we know 3¹ = 3, how would we find 3⁰? well, to get the previous term, divide by 3, so 3⁰ = 3¹/3 = 1 so 3⁰ = 1.

What about 3 to the minus one? you know 3⁰ is 1 so if you divide by 3 again you get 1/3, so 3 to the minus one is 1/3, and this goes on, so 3 to the negative k is 1/3^k

maiden relic
#

hmm

nimble prairie
maiden relic
#

oh so i just remove the 1, then 3^2 becomes 3^-2

nimble prairie
#

Yes

maiden relic
#

ahhh

#

alr tysm

#

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fallow holly
#

Hi, could anyone give me some pointers for this problem? Our professor likes to take each of these roots and "substitute" for them (So it becomes An-Bn/Cn-Dn where n is like the index of the set).

He then went on to do lim An/n = 1, same for BCD and that is easy to understand. What isn't simple, though, is everything else.

I don't expect anyone to solve this with steps, neither do I need the answer (which is -1 for those interested), but I would really appreciate some help.

still temple
fallow holly
#

ummmmm, I don't think I'm catching on? :d

#

My question might make more sense if I send the notes from my tablet I think

still temple
#

from green to blue you can factor out the n^x from under the radical

#

for example, take the first term in the numerator from the original function

#

you can factor out n^3 to get

#

cube-root(n^3(1+1/n^3))

#

then just take the cube root of n^3 to output n

#

the term becomes n*cube-root(1+1/n^3)

#

you can repeat this process for the remaining 3 terms to obtain what i wrote in the blue

#

does that make sense?

#

as a side note, i should really learn latex 😂

fallow holly
#

Yep, we get n from all the roots there, ye

still temple
#

or wtv bot this server uses

fallow holly
#

That far I understood

#

but after that, the professor just went rogue - I really think I need to send the SS so it makes sense

still temple
#

do you know how i went from green to blue though?

fallow holly
#

Yes

still temple
#

okay so from there, the n's cancel out right?

fallow holly
#

All of the roots behave "almost" like n for large enough n

still temple
#

okay mb

fallow holly
#

This is what we've done. The top half makes sense, but the lim n to the fifth over n to the fourth A-B is where I am completely lost)

still temple
#

im blind bruh

#

from here im also a little stumped

#

but i can tell how i reasoned it

#

don't have a rigorous scientific explanation though

#

so for the numerator, for any n>0 the second term will always be greater than the first

#

in the denominator, for any n>0 the first term will always be greater than the second

#

thus the numerator evalutes to a tiny negative value, and the denominator a small positive value

#

and the magnitudes of the values are the same so as n->infinity it becomes -1

fallow holly
#

I appreciate your help - I'll look into it more and hopefully get that eureka moment.

#

<@&286206848099549185> would any of you understand the "6th line"? Where we take the limit of (A-B), but multiply it first?

#

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mellow frigate
#

Please I’m stuck on it for two hours

marsh citrusBOT
main idol
#

i recommend reading up on concave/convex and when it changes https://tutorial.math.lamar.edu/Classes/CalcI/ShapeofGraphPtII.aspx

#

especially example 1

mellow frigate
#

So that’s what I did

#

It starts going up at -1

#

Then starts going down at 1

main idol
mellow frigate
#

Wait wtf

#

It can concave up down going down

#

Okay so I know which is which but how does that tell me the inflection points

kind shadow
mellow frigate
#

Unless I’m blind

red nimbus
mellow frigate
#

I meant

kind shadow
#

Im a bit rusty on vocab, is inflection point just the point where the bowl starts facing the otther way?

red nimbus
mellow frigate
main idol
mellow frigate
#

WAIT ITS THE IN BETWEEN THEM???

kind shadow
mellow frigate
#

So 0,0???

kind shadow
#

Nah

#

U gotta find where the next “bowl” begins

#

This location is where the slope suddenly changes direction

mellow frigate
#

It’s infinite

#

There is no next bowl

kind shadow
#

The bowl is just an analogy for concavity

mellow frigate
#

Yea

#

There is no another one

#

It’s infinitely flat

kind shadow
#

The first bowl still ends

#

The start of a bowl, if there is one, is the end of another

#

If u wana think of it like that

mellow frigate
#

My brain

#

I understand none of this

#

And reading doesn’t help me understand it

#

I understand by doing it and by seeing someone do it

#

I know you guys are trying to make me understand it myself but I don’t

#

It makes 0 sense

mellow frigate
#

Here in my graph it’s 0,0

#

But it’s wrong

#

So I don’t get it

mellow frigate
kind shadow
kind shadow
kind shadow
mellow frigate
kind shadow
#

Or is that another graph

mellow frigate
#

No sorry

#

Two bumps

#

One graph

#

But then the point in the middle is the thing you sent before

kind shadow
#

Seems like it

mellow frigate
#

0,0

#

It’s wrong tho

kind shadow
#

Weird

mellow frigate
#

Stupid question

#

Last question on the hw

#

3 hours

kind shadow
#

Whats the whole question? Can i see it plz?

mellow frigate
#

Literally just to find the inflection points

kind shadow
#

The hell

mellow frigate
#

🥲🥲

kind shadow
#

Lmao yeah its the origin

#

No clue y its wrong

#

Try the peaks

#

Just to f around

#

Also

#

Maybe this is the “first bowl”

#

Check by seeing if the slope decides to change direction

#

In the red, the slope seems to get more negative and negative until it decides to turn around and start increasing to make the new bowl

marsh citrusBOT
#

@mellow frigate Has your question been resolved?

mellow frigate
#

😫😫😫

marsh citrusBOT
#

@mellow frigate Has your question been resolved?

kind shadow
marsh citrusBOT
#
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lyric kelp
#

i would like to know

marsh citrusBOT
void elm
#

what would you like to know? catthimc

lyric kelp
#

im finding a way to word it catthimc

#

the formula here

#

is one for y and one for x

fervent rampart
#

they are the same formula, just rewitten with trig identities

lyric kelp
#

i meanbt like the

#

left and right

#

they the matrix here combined

#

two orthogonal projections

fervent rampart
#

you will get the orthogonal projection of any vector $\begin{bmatrix} x \ y \end{bmatrix}$ by mulitplying by the given matrix

elfin berryBOT
lyric kelp
#

ok ty thats what i meant

fervent rampart
#

it's quite powerful because it means we can represent a pretty large class of transformations (what we like to call functions that turn vectors into other vectors) as just multiplying by a particular matrix

marsh citrusBOT
#

@lyric kelp Has your question been resolved?

marsh citrusBOT
#
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lunar sedge
#

.help

marsh citrusBOT
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lunar sedge
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.reopen

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.help

marsh citrusBOT
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lunar sedge
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.reopen

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.help reopen

marsh citrusBOT
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lyric kelp
#

if i undertsnad

marsh citrusBOT
lyric kelp
#

well

#

a here

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doesnt matter the manitude

#

whats important is the direction

#

right?

fervent rampart
#

we would get the same result for any scalar multiple of a, yes

lyric kelp
#

ok ty

#

.close

marsh citrusBOT
#
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honest creek
marsh citrusBOT
honest creek
#

we want to find the maximum area of BCDF

#

i’m confused what “maximum area” even means lol

#

didn’t they already define a trapezoid? there’s only one area

#

is there not?

crystal lintel
ornate heath
#

Uh

#

Is that the full question

honest creek
honest creek
ornate heath
#

Maximum area of that thingo?

honest creek
#

the full question is to show that the maximum area > 37

#

but that part is irrelevant

#

so i was just talking about the maximum area of that thing

#

yes

ornate heath
#

Huh

#

They don’t give any other criteria?

honest creek
#

no

ornate heath
#

Like max perimeter of the shop?

#

Shape

honest creek
#

you can already infer that

#

CE = 15 and AC = 10

ornate heath
#

But usually for these question they give a maximum perimeter and want you to use a quadratic equation to find the maximum area for it

#

But this doesn’t have anything else so I just need to clarify

#

What about the FD line

honest creek
#

yeah cuz you have the bias that this is an optimization question

#

when it doesn’t have to be 😭

ornate heath
#

Mhm true

#

It’s just when I see maximum area I think of those questions lmao

honest creek
#

anyway this is a geometry problem

#

now that i think about it

#

B, F, and D have no restrictions on them

#

well other than the most obvious ones

#

but they can move around in their respective line segments

#

and u have to maximize the area of whatever formed

crystal lintel
ornate heath
#

Would that not just be

#

The area of the whole shape?

honest creek
#

what

ornate heath
#

Am I tweaking or what

#

I think I am

crystal lintel
honest creek
#

B probably can’t be A

ornate heath
#

Wait

honest creek
#

for example

#

also if you make the trapezoid a triangle, you’re deforming the topology of the trapezoid

#

it’s not four sided anymore

#

and it says maximum area of BCDF so you can’t decay it into BCD or BCF, for example

ornate heath
#

So you can’t have a 3 sided shape?

crystal lintel
#

that doesn’t affect the topology of the trapezoid

ornate heath
#

Ok got it

ornate heath
#

You can’t have a 3 sided shape right?

honest creek
#

not the math one ded

ornate heath
#

Ok wait what’s the answer for this?

crystal lintel
#

i’m still not 100% sure what the question is. you can put B and D anywhere so long as BF and CD are parallel?

ornate heath
honest creek
#

i think

#

tbh i don’t know either

#

hence my question

crystal lintel
#

what about F? anywhere as well?

honest creek
#

yes

ornate heath
#

Bruh

honest creek
#

not on A or E though

#

but answer inside the line segment

ornate heath
honest creek
#

the provided solution is something something rectangle maximizes the area

#

that makes no sense

honest creek
#

the annotation is a hint towards the actual solution

ornate heath
#

Wait

crystal lintel
#

you can just choose F and B close to A and D close to E and get arbitrarily close to the area of the whole triangle?

ornate heath
#

Rectangles don’t maximize area squares do

#

wtf

#

Witchcraft

honest creek
#

i’m lost as well

#

that’s literally all there is to the question

#

also wait

#

meh okay the angle 105

ornate heath
honest creek
#

can be preserved too while doing that

ornate heath
#

But it can’t possibly be that

crystal lintel
#

so F is fixed

ornate heath
#

How did we arrive to this conclusion

honest creek
#

the question posted is all info there is

#

uhm the chances of the question being posed weirdly is also high

#

so you won’t be wrong in saying the question is bad or smth

crystal lintel
#

idfk. is it supposed to be whatever point makes that angle 105 degrees?

ornate heath
#

the question is absoluetly terrible

honest creek
#

the line segment connecting F and D

ornate heath
#

wait is there and actual like

#

numerical answer?

honest creek
#

has to be at a 105 degree angle (my guess)

ornate heath
#

or does it just say whatever you said back there

honest creek
ornate heath
#

bruh

crystal lintel
#

well ms mmmm7 idk what to say anymore

ornate heath
#

does it say less than any number?

honest creek
#

thank you for being here

crystal lintel
ornate heath
#

no wait we gotta get to the bottom of this

honest creek
#

u have to show the maximum area > 37

ornate heath
#

.

#

uh

honest creek
#

the lower bound is 37

#

which is never attained

#

(according to them)

ornate heath
#

if we move the sines as close to the triangle's edges as possible then technically its always less than the triangle's area is it not?

ornate heath
ornate heath
#

is F the midpoint

honest creek
#

no

#

that’s an annotation

#

the printed stuff should say something

#

the one on red is just writing

ornate heath
#

so thats just like

#

an assumption or smth

#

not given

honest creek
#

it’s okay

#

thanks for trying

#

i’m p sure the question can’t be solved

#

.close

marsh citrusBOT
#
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clever spade
#

How would you notate a probability density function?

clever spade
#

Say I have a particular probability function p(x) with equations:

#

how would I notate these equations to represent the probability function p(x)? Note that I've used f(x) as a placeholder

still temple
#

U can use the notation of piece wise functions

clever spade
#

I'm not sure how to do piecewise notation in google docs

still temple
#

One sec I’ll show you

#

$$P(X = x) =
\begin{cases}
\frac{4}{143} x - \frac{92}{143} & \text{if } 23 \leq x \leq 28.5 \
-\frac{4}{195} x + \frac{48}{65} & \text{if } 28.5 < x \leq 36 \
0 & \text{otherwise}
\end{cases}
$$

clever spade
#

also, do I need to capitalise the X in any place considering this is a random variable?

elfin berryBOT
#

Edmund Cloudsley

clever spade
#

alright, thanks! Just wondering if there's any way to notate this in google docs

still temple
#

If so, I highly recommend Overleaf

clever spade
still temple
#

Over google docs

clever spade
#

unfortunately can only use google docs

#

but I could import screenshots

still temple
#

Okay then

#

It might be a good idea to use #latex-testing to create your screenshots using latex

#

And put that into google docs

#

Cause maths with google docs is really frustrating (one of the reasons I learnt overleaf :))

weak surge
#

overleaf is a good place to do latex

still temple
#

Also if you want more privacy, you want more privacy

#

Like if it’s a confidential paper or smth

#

You can create your own server

#

And put latex bot there

#

@elfin berry

#

This one ⬆️

clever spade
#

alright!

still temple
#

Ciao

clever spade
#

I'll keep it in mind and see what I can do

#

thank you

#

.close

marsh citrusBOT
#
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marsh citrusBOT
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runic crag
marsh citrusBOT
runic crag
#

how do we find x

#

without a calculator (this is supposed to be done quickly)

#

answer is (-2(1+i) , 1)

fathom ridge
#

inverse

#

there's a trick to inverting a 2x2 matrix

runic crag
#

once inverted, how does that help ?

#

nvm

fathom ridge
#

do the matrix multiplication

runic crag
#

alright, let me try

elfin berryBOT
fathom ridge
#

hmm

#

weird formatting

runic crag
#

yea dont worry i get it

#

thanks for your help :)

runic crag
fathom ridge
#

oof

#

I forgot what the implication was for that

runic crag
#

isnt there any other way ?

#

teacher went from here to

#

x1=-2(1+i)x2

fathom ridge
#

Yeah well

runic crag
#

then

#

(-2(1+i) , 1)

fathom ridge
#

Carry out the multiplication

#

on the left side

#

And then match the entries on either side

runic crag
#

?

fathom ridge
#

You can multiply the two matrices on the left

#

Normally

#

You'll get a column vector, equate each component of that vector to 0

runic crag
#

ok let me try

#

ok i understand now

#

thanks alot

#

.close

marsh citrusBOT
#
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marsh citrusBOT
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fallow furnace
#

how can i rigorouosly proove that $\lim_{x \to 0 }\sin\left(\frac{1}{x}\right)$ doesnt exist

elfin berryBOT
#

Slowaq

marsh citrusBOT
#

@fallow furnace Has your question been resolved?

spark siren
#

think about $lim_{y\rightarrow \infty}sin(y)$?

elfin berryBOT
marsh citrusBOT
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restive silo
#

hi

marsh citrusBOT
restive silo
#

Can we say y=2e^t+ce^(-t) or did I do smth wrong ?

cerulean prairie
#

No

restive silo
late geode
#

you'd have take the reciprocal of the whole side
not whatever you want in any order you want

cerulean prairie
#

if z = x + y we can't say z-1 = x-1 + y-1

restive silo
#

oh wait

#

we have to take the whole expression right ?

#

like ( )^-1

cerulean prairie
#

Yeah

restive silo
#

I see...

#

Thanks alot

#

.close

marsh citrusBOT
#
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marsh citrusBOT
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ruby matrix
#

hi i am confused by R ∘ R⁻¹

marsh citrusBOT
ruby matrix
#

shouldnt aRb in R and bRa in R-1 lead to the final pair (a,a), thus (a, b) and (b, a) should not be included

marsh citrusBOT
#

@ruby matrix Has your question been resolved?

marsh citrusBOT
#

@ruby matrix Has your question been resolved?

marsh citrusBOT
#
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