help-33

[limpid bison]

9 cos squared t + 9 sin squared t = 9

ah

[mystic ledge]

👏

[limpid bison]

ty

.close

[marsh citrus]

Channel closed

Closed by @limpid bison

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worthy harbor]

-x^2 plus -7x is

[worthy harbor]

-8x^2 right?

[vernal forge]

you cannot simplify -x^2 - 7x

[vernal forge]

no that would be if you had -x^2 - 7x^2

[worthy harbor]

So they aren't like terms?

How do I know if it's in standard form yet

[marsh citrus]

@worthy harbor Has your question been resolved?

Channel closed

Closed by @worthy harbor

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lean tangle]

Hi, I could use some help with this problem:

Let $b_{k}\in\mathbb{N}{0}$ be for $k\in\mathbb{N}$ as well as $P{n}:=\prod_{k=1}^{n}\left(2b_{k}+1\right)$

Show using complet induction that for every $n\in\mathbb{N}$ a $\tilde{b}=\tilde{b}\left(n\right)\in\mathbb{N}_0$ exists with $P_n=2\tilde{b}+1$.

[elfin berry]

CreepyShadow

[lean tangle]

sorry if the problem is worded a bit weird, I had to translate it.

I think my main confusion is understanding what exactly is wanted from me

[twilit geyser]

yeah the squiggle over the b is kind of confusing but they just mean that for every n you can find a B such that P_n=2B+1

[lean tangle]

ok, that makes a lot more sense

I think I need to understand the $\tilde{b}$ though to be able to write the proof correctly

[elfin berry]

CreepyShadow

[twilit geyser]

$\tilde b(n)$ is a natural number that depends on n, for instance let's say $b_k = k$ then we would have $P_1 = 21+1$ and so $\tilde b(1)=1$ here. $P_2 = (22+1)(21+1) = 15 = 27+1$ so $\tilde b(2) = 7$

[elfin berry]

Merosity

[twilit geyser]

although I wouldn't worry about determining exactly what the ~b(n) is, I don't think you really need to worry about that for the induction argument asked for here

[lean tangle]

ok, that makes it clearer now

One thing that may just be a language barrier did you assume b_k = k or is that given.

[twilit geyser]

I just picked it as a simple example

to show what ~b(n) was in that case

what you have to prove is more general yeah

[lean tangle]

ok, that's what I thought

[marsh citrus]

@lean tangle Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lean tangle]

.reopen

[marsh citrus]

✅

[lean tangle]

my head is smoking and it's way too late now, gonna try some more tomorrow

[marsh citrus]

@lean tangle Has your question been resolved?

Channel closed

Closed by @lean tangle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wooden shore]

What don't you know

[marsh citrus]

@silent fable Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[storm flume]

ok this is the question and the answer is 3/5 OR 1

idk how to get the 1!!

[still temple]

dont remove the square

if ur gonna do it add absolute value

[storm flume]

wdym?

[still temple]

like |x|

[storm flume]

-sigh- i havent learned that yet

but ill ask my teacher tomorrow

tysm!

❤️

.close

[marsh citrus]

Channel closed

Closed by @storm flume

Use .reopen if this was a mistake.

[still temple]

expand imo

[leaden reef]

Just expand the bracket

(2x-1)(2x-1) = (2-3x)(2-3x)

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fast bramble]

Can someone check my answers

[fast bramble]

Answer check

<@&286206848099549185>

<@&286206848099549185>

[leaden reef]

yeah its good

[fast bramble]

All of them?

[leaden reef]

yes they're fine

[marsh citrus]

@fast bramble Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[night lion]

how to solve e^x sinx integral without by parts since that will make this tedious

[sweet pawn]

hmm]

here's an idea

[night lion]

eulers formula ?

[sweet pawn]

,w sin(x)

[elfin berry]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by the.mr.gamer

[night lion]

?

[sweet pawn]

sin(z) = 1/2 i e^(-i z) - 1/2 i e^(i z)

that's the identity i was looking for

[night lion]

ph write eulers identity right

just a little manipulated

[sweet pawn]

yes

[night lion]

hmm

[marsh citrus]

@night lion Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sand river]

For 22 is that an acceptable way to answer the question?

[covert scarab]

Looks alright

[sand river]

Tysm

[covert scarab]

Well it looks like you have a certain amounts of characters to enter your ans with so if it fits that block you can have some surety, no?

[sand river]

no the box expands as my answer gets longs

[covert scarab]

Ah, evil men

[sand river]

If that’s what u mean?

LOL

[covert scarab]

Format's always the death of me

[sand river]

yeah my teacher wanted one polynomial division done by Dx times q(x) plus remainder

So that’s exactly what I did

But apparently I got put parenthesis around d and q for it to be correct so I lost all points on a question that I got the answer right but the format wrong

Like I guess I’m in the wrong but I wonder how much points he will give me back.. hopefully all

[covert scarab]

Depends on what Dx and q(x) were equal to

[sand river]

D was dividend and a was quotient

[sand river]

Why is 23 not correct…

[covert scarab]

It's an x^4 degree polynomial

So there's 4 roots

[sand river]

Oh ohh like this right

[covert scarab]

Yes

[sand river]

Can u help double check another another thing?

[covert scarab]

Sure

[sand river]

26 and 27 r correct right

[covert scarab]

Doesn't look right

How can an x of 1 give you two different y values in the same quadrant ?

[sand river]

Maybe I don’t understand the question hold on

[covert scarab]

What is the equation of a unit circle

[sand river]

X^2 plus squared equals 1

Y

[covert scarab]

They gave you a y

So you just need to solve for x

Then determine which x lies in the quadrant they gave

[sand river]

For the first one

I got 8/17, -8/17

[covert scarab]

So which would be in quad 4

[sand river]

-8;17

-8/17

[covert scarab]

Yes

Same process for the next question

[sand river]

I did the other one too I got 3 squadron of 5 all over 7

So the ones that’s negative is in the Q4 right

[covert scarab]

Yes

[sand river]

Wait why is wrong LMAO

inout it in and it’s x LMAO

I put it in and it’s wrong

Ohh

[covert scarab]

You said 3sqrt5 /7 right?

[sand river]

Simplify

It

Right

[sand river]

Yes

[covert scarab]

Yeah that's right

[sand river]

For the -8/17 one

It’s wrong

It says

[covert scarab]

-8/17

[sand river]

Yeah

[covert scarab]

do your instructions ask you to round off maybe?

[sand river]

No it doesn’t say that

The positive is the right one

I’m confused now

[covert scarab]

oh yes

it is

I'm clearly up past my bedtime

• is quad 2 and 3

negative

positive is quad 1 and 4

[sand river]

OMG

why did I think it was negative too

omg I’m getting delusional as well

[covert scarab]

passing on my delusions

well same answers just both positive

is the moral of the story

[sand river]

Damn I got 0.25 pts taken off

LOL

[covert scarab]

for the 1 wrong submission?

https://tenor.com/view/the-curse-of-the-black-pearl-pirates-of-the-caribbean-captain-jack-sparrow-johnny-depp-movie-gif-13439093

[sand river]

Yesss like bruhh

[marsh citrus]

@sand river Has your question been resolved?

[proud arch]

What's the question

Or has this been resolved

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[daring herald]

When differentiating that 2 in the fraction vanishes

Am I right?

[sterile pagoda]

Differential of x^4 is 4.x^3

(4.x^3)/2 becomes 2.x^3

[daring herald]

Thanks chaps

I had a mate clear it up for me

.close

[marsh citrus]

Channel closed

Closed by @daring herald

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sand river]

The question asks solve the given inequality graphically?

[sand river]

A little stuck on that

[still temple]

plot (x-1)(x-4)

[marsh citrus]

@sand river Has your question been resolved?

[marsh citrus]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[still temple]

?

he s actually helping that girl

LMAO

[sinful thistle]

LOL who did that

[still temple]

IDK

but its funny

[sinful thistle]

[crystal lintel]

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mortal badger]

how can one see without too much calculation that these generating sets all generate the entire A_5 (the alternating group for n = 5)

[marsh citrus]

@mortal badger Has your question been resolved?

[royal sable]

Those generators don't produce (1,3)(2,4)

Because 1 always goes to 2

[mortal badger]

oh damn

[marsh citrus]

@mortal badger Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dark meadow]

hi! any idea how do I know if delta is negative, positive or equal to zero in a quadratic inequality?

[cunning oak]

is delta the b^2 - 4ac term?

[dark meadow]

yes

[cunning oak]

it depends on what the question wants ; no real roots, D < 0
1 real root D = 0
2 real roots D > 0

[cunning oak]

oh

if its < 0, then it has atleast 2 roots => D > 0

[marsh citrus]

@dark meadow Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[whole notch]

How to evaluate this integration? i already evaluate a) and proof d) the ans show in pic1, pic2 is my step, pic3 is answer from mathematica, pic4 is the answer from the textbook

[glass silo]

The integral from part e)?

[glass silo]

Also

[whole notch]

pic2

[glass silo]

While cos(pi - x) is -cos(x), remember that cos^2(…) is shorthand for (cos(…))^2

[whole notch]

oh

so it is 1+(cos(x))^2

[glass silo]

At which point you can rearrange to find the original integral on the right hand side, and some multiple of the integral from part (c) also on the RHS

[whole notch]

ok

solved, thanks a lot

btw why mathematica answer is wrong

[glass silo]

Should be x, not pi, no?

[whole notch]

oh 🤣

thx

[marsh citrus]

@whole notch Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cerulean sequoia]

hi, anyone got an idea what function this graph represents?

[valid cape]

this is not a function

[cerulean sequoia]

sorry for my bad drawing skills

can u define it in some way?

[devout mauve]

functions can only have one y value for every x value

you might be interested in sqrt(1-x^2) or -sqrt(1-x^2) which are also semicircles, but rotated

[cerulean sequoia]

yeah that might work as well

thanks

.close

[marsh citrus]

Channel closed

Closed by @cerulean sequoia

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

Am I right in saying that this is an expression for the total impendance?

[marsh citrus]

@still temple Has your question been resolved?

Channel closed

Closed by @hallow bobcat

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[burnt lava]

.reopen

SJBJDBSJAFDAJKSFNS

[burnt lava]

YAY I DID IT

SOMEONE HELP ME

SOS......

[plain violet]

what

[burnt lava]

ok so

I have to find the distance between the point P(8.11) to the line l, the line l is given with 3x+4y-18=0

[dark lotus]

Re arragnge that formula

To its in the form y = mx+c

[burnt lava]

GULP WHAT😭

WHERED THE M COME FROMMMMM

[junior copper]

dude distance formula

[junior copper]

the m is just the coefficient of x

[burnt lava]

oh

[dark lotus]

M is the gradunt

C is the y intercept

[burnt lava]

I don't understand.....

[dark lotus]

Zo it would be y = (3x + 18)/4

Thats the equation of a line

The line u was givin *

[burnt lava]

right

[dark lotus]

So now

[burnt lava]

it told me to find the normal vector before that though, does that have anything to do with it at all

[dark lotus]

Yh do that

[dark lotus]

Can u ss the question for me

[burnt lava]

it's not in english💔

[dark lotus]

Oh

You need to use this formula

[burnt lava]

but I'll do it anyway

[plain violet]

Yes you can also go the "long" way which is basically what this formula does

[plain violet]

but if you chedk out the proof for that formula you will understand everything

[dark lotus]

A in your case would be 3

B would be 4

[burnt lava]

yeah so

[dark lotus]

C is -18

Now sub it in on a calc

[plain violet]

https://brilliant.org/wiki/distance-between-point-and-line/

[burnt lava]

n = (3,4) right

[plain violet]

very good explanaition

[burnt lava]

omg tysm Ily

[elfin berry]

Steel

[burnt lava]

thanks discord people🎀

[marsh citrus]

@burnt lava Has your question been resolved?

[burnt lava]

oh yeah I have to close it

[marsh citrus]

Channel closed

Closed by @burnt lava

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[nova condor]

I've been away for two weeks so there are lots of math ideas ive forgotten.

Here is the problem: Find the equation of the line which passes through point (3,1) and is parallel to the line which passes through (-1,2) and (3,4).

[nova condor]

To be completely honest I have no real idea of what to do besides finding the lines on graph which i did

[junior copper]

Those who know💀

[still temple]

💀

[junior copper]

ok so first what you gotta do is put it into slope point form

wait brain fart

point slope form

[still temple]

So real

[junior copper]

$y-y1=m(x-x1)$

[elfin berry]

Steel

[junior copper]

so its kinda like this

[still temple]

Yo don't u find slope first

And then point slope form

[junior copper]

non linear storytelling

[nova condor]

...lol (idk)

[nova condor]

k

[junior copper]

ok so you have these points(-1,2) and (3,4)

do you know the slope formula

[nova condor]

yes

[nova condor]

no

[still temple]

Hr listed it

[nova condor]

this?

[still temple]

That's point slope

[junior copper]

uhh

[nova condor]

oh ya i know that

[still temple]

I wrote it wrong

Hel

[nova condor]

oh

[junior copper]

$\frac{y2-y1}{x2-x1}$

[elfin berry]

Steel

[junior copper]

is what i meant

[still temple]

Yeah that

Slopr formula

[nova condor]

k

[junior copper]

using this formula find the slope between the points (-1,2) and (3,4)

for example x1 y1 would be -1 and 2

[nova condor]

so you plug in 2 in where the first y is?

and 4 where the second one is?

same for the x's?

[junior copper]

Yes so it would be like this filled in$\frac{4-2}{3--1}$

[elfin berry]

Steel

[nova condor]

soo

2/2?

[junior copper]

Correct

so the slope you now know is simply 1

[nova condor]

k

[junior copper]

we were told that they were parallel

[nova condor]

yes

[junior copper]

so that means they have the same slope

[nova condor]

yeah

[junior copper]

you are finding the line that passes through point 3, 1

correct?

[nova condor]

yes

the equation of the line

so it would be in y=mx+b form

[junior copper]

yes but to do it with a point you already have you need to use the point slope

mentioned above

then you can convert to y=mx+b

[nova condor]

im following

wait

my solutions says...

$(4-2)/{3-(-1)}=1/2$

[elfin berry]

Rænger

[quick dust]

3 - (-1) = 4

Not 2

[nova condor]

uh

[still temple]

He simplified it

[nova condor]

its 2/4 simplified

i believe

[still temple]

Yea

So ur slope is ½ 😊

[nova condor]

ah hah

[rose heart]

that can be simplified further to 1/2

[nova condor]

yeah

thats what i was saying

[still temple]

Input it now y=mx+b

[nova condor]

y=1/2x+b

x=3

so

y=1/2(3)+b

y=1

[still temple]

Hold on.

💀

[junior copper]

how??

[quick dust]

I was referring to this

[nova condor]

1=1/2(3)+b

[quick dust]

This guy was wrong

[junior copper]

the math was not mathing

[still temple]

Pron typo

[junior copper]

the brain was not braining

[still temple]

Its ok 3-1 is 2 😊 u just forgot -

[junior copper]

i assumed he was correct🤦

[nova condor]

oh yeah its at first 2/4 then 1/2

mbmb my fault

[still temple]

Yessirr

[nova condor]

im a bit slow

[still temple]

No ur not

Everybody slow at one point

💀

[nova condor]

alright

now im here

$1=1/2(3)=b$

[elfin berry]

Rænger

[nova condor]

I need to slove for b to get that number

so multiply 3 to 1/2?

3/2?

[junior copper]

yes

hopefully im not stupiding

im gonna be honest i dont know how you got here

[nova condor]

wait that equation is messed up

well i have (3,1) x=3 and y=1

[junior copper]

$y=\frac{1}{2}x-\frac{1}{2}$

[nova condor]

y=1/2x=b

[elfin berry]

Steel

[junior copper]

you are supposed to get to this

[nova condor]

yeah

thats the answer

how did you get there?

lol

[junior copper]

ok maybe if i do it on my whiteboard

gimme a sec

[nova condor]

1=1/2(3)+b

k

[junior copper]

,calc 1/2 * -3

[elfin berry]

Result:

-1.5

[junior copper]

@nova condor

[nova condor]

kk

[junior copper]

,r

,rotate

[nova condor]

ty lol

ah hah! i got it!

Ive never seen that formula in my math book before

tyty

.close

[marsh citrus]

Channel closed

Closed by @nova condor

Use .reopen if this was a mistake.

[twin olive]

Could someone pls send me the solution of problem 1,2,3,4 and 5

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gilded lava]

Anyone please check my work

I want to solve the problem by general method

So I need some hints only

So that I can feel i will get same result by both methods

General term is :

Sum k=1 to infinity

(-1)^(k+1) (multiplication k=1 to infinity (3k-2))/(5^k k!)

[main idol]

how does 3k-2 = 1 * 4 * 7

[gilded lava]

There must be a multiplication on denominator

[gilded lava]

Do you want me to go MSE for this also?

[main idol]

why are you being a crybaby

[main idol]

this was pointing out your error

[gilded lava]

What about your ultra rudism?

[void elm]

[gilded lava]

And I corrected ☺️

[gilded lava]

You were also wrong few hours ago

a guy corrected you??

[main idol]

.

[gilded lava]

riflou

[main idol]

i recommend therapy

for your crybaby

[gilded lava]

Okay fine. I am going to MSE...no time for...shittalks

[main idol]

do that first and save everyone's time

[gilded lava]

Enjoy your behaviour

Open your eyes and read some pictures

[main idol]

.

[gilded lava]

This one has already answer

.close

[marsh citrus]

Channel closed

Closed by @gilded lava

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lavish owl]

how do i do a

The figure below shows the graph of a function f, along with the tangent to the graph at points A and B. Use the figure to find:

[red nimbus]

count squares

[lavish owl]

2/1?

what

[red nimbus]

1 is right 2 is wrong

how long is the green

[lavish owl]

4?

why does it stop at the top point not when it goes further from the graph?

[red nimbus]

ye

[red nimbus]

then it would cross the line which is not what we want

[marsh citrus]

@lavish owl Has your question been resolved?

[lavish owl]

.close

[marsh citrus]

Channel closed

Closed by @lavish owl

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[junior blade]

how to solve this inequality : $1/x \ge -1 $

[main idol]

multiply both sides by x

[junior blade]

here's the original problem

it's to find the domain of this function

[wary kite]

can you divide by zero?

[junior blade]

so I should solve $1+1/x \ge 0$

[elfin berry]

Hamdy Hisham

[junior blade]

zero's out I know

[wary kite]

but can it ever be zero

[junior blade]

but also you can't have a negative number under a square root

[wary kite]

yep

so what’s the issue then

you’ve ruled out x ≠ 0

and established 1 + 1/x >= 0

do what riemann said

[junior blade]

If you solve this you get $x \ge -1$

[elfin berry]

Hamdy Hisham

[junior blade]

right ?

[wary kite]

yes

[junior blade]

but for example if you take x = -1/2

[wary kite]

or no nevermind

[junior blade]

why no

[wary kite]

$1 + \frac{1}{x} \geq 0$

[elfin berry]

knief

[wary kite]

should be less than yea?

[hushed egret]

multiply both sides by x^2

[wary kite]

not greater than

[junior blade]

$\frac{1}{x} \geq -1$

[elfin berry]

Hamdy Hisham

[junior blade]

$1 \geq -x$

[elfin berry]

Hamdy Hisham

[wary kite]

x is negative though

we’re looking at the branch where x isn’t greater than zero yea

because we already know x>0 works

[junior blade]

ohhhhh

yup I get it now

[hushed egret]

multiplying by x^2 avoids all these issues

[junior blade]

I felt stupid as hell

[wary kite]

listen to blake

[hushed egret]

you get $x \ge -x^2$, so $x^2 + x = x(x + 1) \ge 0$

[hushed egret]

classic quadratic inequality

[junior blade]

I see

thnx

[hushed egret]

(so many people still mess these up tho )

[junior blade]

.close

[marsh citrus]

Channel closed

Closed by @junior blade

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wide tundra]

Was able to get b=-1/2 but unsure how to get a=1. Please help.

[marsh citrus]

@wide tundra Has your question been resolved?

[wide tundra]

If someone can explain how to get both a=1, and b=-1/2 that'd be greatly appreciated

[red nimbus]

From the system, can you tell me the solution vector?

[wide tundra]

I plugged in X=[2 0 2] into the equation 1x+ay+bz=1

So 1(2)+a(0)+b(2)=1

b=-1/2

[red nimbus]

ok good

[wide tundra]

Tried doing the same thing for [-1 1 0] but I get 2

Instead of 1

So a lil lost

Any ideas?

[red nimbus]

let me write it down

we can tell z = 3 from the system

y can be a free variable

let's call y = t

[wide tundra]

z=2?

[red nimbus]

yep 2nd row

[wide tundra]

yea im following

[red nimbus]

,, X = \left [ \begin{array}{c} 1-at-2b \ t \ 2 \end{array} \right ] = \left [ \begin{array}{c} 1-2b \ 0 \ 2 \end{array} \right ] + t \left [ \begin{array}{c} -a \ 1 \ 0 \end{array} \right ]

[elfin berry]

bacc (unhelpful)

[red nimbus]

this is the solution vector now you just need to compare

[wide tundra]

im so lost hahahah

[red nimbus]

ok hold still

you know

[wide tundra]

prof didnt even tell us anything about solution vectors ngl

[red nimbus]

,, X = \left [ \begin{array}{c} x \ y \ z \end{array} \right ]

[wide tundra]

then throws this question in the practice midterm

[elfin berry]

bacc (unhelpful)

[red nimbus]

just a fancy name for the solution

[wide tundra]

Kk

I'm following

[red nimbus]

from the system we deduce z=2

[wide tundra]

ok plug that in

[red nimbus]

from the system we can pick y as a free variable

let's call that t

ok?

[wide tundra]

Don't get that part

Why is y a free variable

[red nimbus]

you can pick actually decide between x and y

because z is taken

and we have one zero row

[wide tundra]

Ok so wouldnt that mean a could be any real number

[red nimbus]

we will get to a soon

we pick a free variable first

[wide tundra]

kk

[red nimbus]

ok so

[elfin berry]

bacc (unhelpful)

[red nimbus]

we can find x in terms of y

looking at the first row

[elfin berry]

bacc (unhelpful)

[red nimbus]

y is more conventient to choose as free variable otherwise you would have to divide by a and stuff

so instead we just move everything to the other side that is not x

[elfin berry]

bacc (unhelpful)

bacc (unhelpful)

[wide tundra]

Ahh okay

[red nimbus]

now do the same

[elfin berry]

bacc (unhelpful)

[wide tundra]

so if we choose y as a free variable it just becomes 0 on the solution matrix?

[red nimbus]

no

it's basically

0y = 0

y can be anything here then

[wide tundra]

i feel like an idiot

why are we multiplying y by 0

[red nimbus]

it's the 3rd row basically

you basically have 0 = 0

since we chose y as a free variable you can also write 0*y = 0

[wide tundra]

ok i see

[red nimbus]

to say that no matter the value of y it doesnt affect this equation

[wide tundra]

same thing as what we did to 1(z)=2

[red nimbus]

yes

and with x

first row

so now you simply compare

,, \left [ \begin{array}{c} 1-2b \ 0 \ 2 \end{array} \right ] + y \left [ \begin{array}{c} -a \ 1 \ 0 \end{array} \right ] = \left [ \begin{array}{c} 2 \ 0 \ 2 \end{array} \right ] + t \left [ \begin{array}{c} -1 \ 1 \ 0 \end{array} \right ]

[elfin berry]

bacc (unhelpful)

[wide tundra]

Also so sorry

[red nimbus]

1-2b = 2 and -a = -1

the thing is i wanted to choose y as t so it would be more intuitive

[red nimbus]

since both are parameters

[wide tundra]

where does the +y... come from

[red nimbus]

i pulled y out

[wide tundra]

[red nimbus]

ok let me write it down

[wide tundra]

I'm so sorry haha

[red nimbus]

it's ok

[elfin berry]

bacc (unhelpful)

[red nimbus]

like the first step was to split the vector into two vectors where we separate y from the "non-y" stuff

and then I pulled out y

[wide tundra]

OH OKAY I SEE IT

[red nimbus]

ok good, was about to use colors

[wide tundra]

BAHAHA

[red nimbus]

so back

[elfin berry]

bacc (unhelpful)

[red nimbus]

aside from the parameter

[wide tundra]

I just don't get how you pulled the y out

ok nvm i lied

[red nimbus]

it's like a scalar

[wide tundra]

i see it

yep

[red nimbus]

common factor

0 = 0y

[red nimbus]

so here you just need to compare the components

1-2b = 2 and -a = -1

[wide tundra]

I see

[red nimbus]

and again

if you chose x as a free variable instead, it would have worked out too but it would be uglier

in terms of terms

[wide tundra]

Is there not an easier way to find a?

Like the method I used to find b?

Or is doing this just more reliable

Cause I was looking at the solution the practice test had and it came out with

[red nimbus]

well it isn't that bad

[wide tundra]

−1+a⋅1+b⋅0=0

[red nimbus]

takes you at most 1 min

[wide tundra]

It did this

[red nimbus]

it just too awhile cause i explained it to you

[wide tundra]

Nice way to call me slow

[red nimbus]

no

there is no shame

[wide tundra]

this just confused me

[red nimbus]

nobody wins if i just skip steps

[wide tundra]

why do they expect us to solve it like this

[red nimbus]

Ok so you have [x = 1-at-2b ]

[elfin berry]

bacc (unhelpful)

[wide tundra]

so real

[red nimbus]

x would be 2-t from the what they gave us

[elfin berry]

bacc (unhelpful)

[red nimbus]

Now

you could do the following

[elfin berry]

bacc (unhelpful)

[red nimbus]

compare

2 = 1-2b
-t = -at

so a = 1

b = -1/2

basically this is called coefficient comparison

i compare the terms with t well with t

and the terms not with t with the term not with t

[wide tundra]

how is x=2-t?

[red nimbus]

x resembles the first component of X

which is if you sum up

2+(-1)t = 2-t

[wide tundra]

ok i see now

thank you so much

was looking through all my lecture notes and this kind of question did not pop up at all

.close

[marsh citrus]

Channel closed

Closed by @wide tundra

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wise oxide]

Did I do anything correct

[agile ice]

It isn't absolutely convergent, because it fails the p-series test

It's conditionally convergent though

[wise oxide]

R any of my steps actually correct

[main idol]

this is correct

[agile ice]

The limit of 1/sqrt(n) = 0 is correct for alternating series test, but it doesn't show absolute convergence

Only conditional

[wise oxide]

So how was I suppose to solve the other part

Without the abs value

[agile ice]

You disprove absolute convergence by showing that the exponent in the denominator is less than or equal to 1 (p-series test)

[rocky lark]

try using the Leibniz criterion

[marsh citrus]

@wise oxide Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cosmic shuttle]

I need help with these questions

[marsh citrus]

@cosmic shuttle Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[blissful zenith]

good idea

what have you done so far?

[marsh citrus]

@sacred rivet Has your question been resolved?

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[west raft]

https://media.discordapp.net/attachments/1301346463430873089/1301346463934316626/IMG_2415.jpg?ex=672424d6&is=6722d356&hm=88088c1f2ed93edf3d794a6cbb7860b705c8627de77d5f68d6779a9589da30d4& how do i even start #25

[marsh citrus]

@west raft Has your question been resolved?

[kind shadow]

you are given the angular vel vs time graph

the area between the curve and the x axis represents the angular position incrememnt

the reason why is that multipying the height with width on the graph is the same as multiplying the speed times time

which gives displacement

did you draw the axes of your angular pos vs time graph at least?

[marsh citrus]

@west raft Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[copper basin]

One message removed from a suspended account.

[copper basin]

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

[tight kite]

you don't need to

just take derivatives of the options and check if it matches

[copper basin]

One message removed from a suspended account.

[tight kite]

except for c

[copper basin]

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

[tight kite]

wym

if D matches then its the answer

[copper basin]

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

[quick moth]

well well well 😭🙏🙏

look who we have here

[copper basin]

One message removed from a suspended account.

One message removed from a suspended account.

[tight kite]

if D is incorrect and the derivative of B matches D, then B is also incorrect

[copper basin]

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

[marsh citrus]

Channel closed

Closed by @copper basin

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[copper basin]

One message removed from a suspended account.

[copper basin]

One message removed from a suspended account.

[wary kite]

get out

!occupied

[marsh citrus]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[copper basin]

One message removed from a suspended account.

One message removed from a suspended account.

[wary kite]

what are the two points

substitute those x and y values

and solve for y’

[copper basin]

One message removed from a suspended account.

[wary kite]

subtract 2y then factor y’

[copper basin]

One message removed from a suspended account.

[wary kite]

then divide by the remaining expression

to isolate y’

[copper basin]

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

[wary kite]

yep

[copper basin]

One message removed from a suspended account.

One message removed from a suspended account.

[marsh citrus]

Channel closed

Closed by @copper basin

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[marsh citrus]

Please don't occupy multiple help channels.

[fast bramble]

Need help on

Starting these

[rancid geode]

what do u notice

about these graphs

[fast bramble]

This was wrong only got one answer left

[final skiff]

Why (x-4) in denominator

[amber birch]

yeah should be (x - 3)^2

you clearly understand the concept though

so just sub x = 0 in again to find your new value of k (not -1.2)

[fast bramble]

Got it

[fast bramble]

X into what I have

So plug in 0 into the X?

[amber birch]

yes, start over and remove the -1.2 also

[fast bramble]

Got it

[amber birch]

so you have $y = k \frac{(x - 2)^2}{(x + 1)(x - 3)^2}$

[elfin berry]

south's secret twin brother

[amber birch]

and $x = 0, y = -0.3$

[elfin berry]

south's secret twin brother

[fast bramble]

I got 0

How did you get that

@amber birch

[amber birch]

you shouldn't get 0

[fast bramble]

So it’s this?

[amber birch]

no

[amber birch]

what do you get if you sub in x = 0 into the RHS?

[fast bramble]

Into the numerator and denominator?

[amber birch]

yes

[fast bramble]

-0.45?

[amber birch]

don't round, it's just 4/9

so we have $-\frac{3}{10} = k \cdot \frac{4}{9}$

[elfin berry]

south's secret twin brother

[fast bramble]

So this

[amber birch]

no

[fast bramble]

Then what

[amber birch]

we need to solve for k cause the only thing we don't know is k

[fast bramble]

Okay so

What next

[amber birch]

literally

[fast bramble]

We divide by 4/9

@amber birch

[amber birch]

yeah

[fast bramble]

So -27/40

[amber birch]

yeah

I'm wondering what you did to get -1.2 before?

cause it's the same steps, just with a different function

[fast bramble]

So that’s the final answer

[amber birch]

yeah

[amber birch]

.

[fast bramble]

What about question 9

21 minutes till it’s due

[amber birch]

not my responsibility to manage your time for you

[fast bramble]

I got this so far @amber birch

[amber birch]

I'm not interested ok

[fast bramble]

Wdym?

[wary kite]

he doesn’t feel like helping you

[amber birch]

I'm not helping you with your question 9

[fast bramble]

Do you got me no neck

[wary kite]

no neck?

wild

💀💀

[fast bramble]

No neck Jay

[wary kite]

OH

😭😭😭

[fast bramble]

Help a brother out

Question 9 is all I need

[wary kite]

ever try the video

[fast bramble]

Yea shit wasn’t helpful there off topic lol

[wary kite]

they’re?

[fast bramble]

Yes

[wary kite]

is there a zero at x = 0?

[fast bramble]

Yea

[wary kite]

so why tf isn’t it in your function

⁉️⁉️

[fast bramble]

Where do I put it

Numerator

Or denominator

Do u do

I*

X-0

[wary kite]

x-0 is unnecessary sir

[fast bramble]

So just X

[wary kite]

it’s the same as x

[fast bramble]

Okau so we got that

@wary kite

[wary kite]

looks like a horizontal asymptote too though

at y = -2

[fast bramble]

That’s why I have X-2

On top

[wary kite]

nah you did that for the zero

look at the horizontal line

[fast bramble]

Ohhh

[fast bramble]

So where do I start it this

On top as well?

@wary kite

[wary kite]

what’s this?

is that supposed to be there

it’s in a lighter color

[wary kite]

ahh i see

there’s the piece below

ok

makes sense

[fast bramble]

Yup that’s why I have it to the power of 2

Cause it’s smaller

How much more we got @wary kite

It’s due in 7 min

[wary kite]

ok then your functions wrong

get rid of the square

[fast bramble]

What I gotta do

Got it

Let’s make it work

[wary kite]

and

now we need the horizontal asymptote at y = -2

so we need

[fast bramble]

Ok so what we do

[wary kite]

the limit x -> -inf to be -2

and

lim x -> inf to be -2

[fast bramble]

So what we gotta do

[wary kite]

well

what do you know about horizontal asymptotes

you have a few minutes

is this the last question

consider the case when the numerator and denominator have the same degree

which is the case we have

what does the horizontal asymptote =

it’s y = …

what is it

[fast bramble]

Yes

[wary kite]

how do we find it

[fast bramble]

Set X to 0 to find Y

[wary kite]

yea that’s good ig just make sure it’s typed correctly

[fast bramble]

Do got it

[wary kite]

$\frac{-2(x)(x-2)}{(x+3)(x-5)}$

[elfin berry]

knief

[fast bramble]

Got it

Let’s go

[wary kite]

my goat

[fast bramble]

🫡 my boy

.close

[marsh citrus]

Channel closed

Closed by @fast bramble

Use .reopen if this was a mistake.

[fast bramble]

@wary kite

Tell moderators

@fervent rock tried to charge me money in dms

[wary kite]

LOL

he’s the same guy that said he’d help someone in 20 minutes

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wary kite]

<@&268886789983436800>

[wary kite]

what do y’all do about that

[fast bramble]

Tell mods

[wary kite]

^

[fast bramble]

Bros a scammer

[delicate prairie]

can you send a screenshot to @viscid flame

[fast bramble]

I asked for free he said no little money

[wary kite]

what about after

you approached him tbh

[fast bramble]

He wouldn’t answer

[fast bramble]

Yea for free not money

He deleted something lol

He messaged first

He’s slick

[wary kite]

it would be different if he sent you a dm though

.close

[marsh citrus]

Channel closed

Closed by @wary kite

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.