#help-33

1 messages · Page 184 of 1

golden cosmos
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what would the integral of this be

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ignore the bounds

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like i wanna know steps

winged pier
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integration by parts perhaps?

true frigate
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would that just be (e^P^3)/3?

golden cosmos
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wasnt there like

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tabular method or smth

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along those lines

true frigate
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idk

golden cosmos
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how'd you know the answer then

true frigate
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im just thinking along the lines of the derivative of e^p^3 is

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3p^2 x e^p^3

winged pier
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wait my bad

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just do u substitution lol

true frigate
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so i did it in reverse

true frigate
golden cosmos
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yeah you right

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marsh citrusBOT
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winged pier
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du = 3p^2dx

true frigate
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oh

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yeah

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lol

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the derivative of that is 3P^2

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gives the same anser

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sick, ty haha

marsh citrusBOT
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hot drum
#

"Based on the store's purchase data, 40% of customers buy oranges and 33% buy bananas.
How many of the day's 1000 customers buy these fruits (oranges, bananas, or both) in the following cases. Give the answer as a whole number, rounded to the nearest whole number if necessary."

Now I am having trouble in the c section that states

"If buying oranges has no effect on buying bananas."

I can't really grasp the reason on how this affects the outcome and how do I calculate it

Can somebody help?

hot drum
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Okay if buying oranges has no effect on buying bananas, does it mean that those who buy oranges can also potentially buy bananas?

marsh citrusBOT
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@hot drum Has your question been resolved?

hot drum
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<@&286206848099549185>

still temple
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Yes

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?

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?

hot drum
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tranquil ice
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.reopen

marsh citrusBOT
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night lion
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why is it not possible that both are zero is it due to the definiton of cross product?

frank sparrow
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give me one minute

night lion
glacial hedge
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still what?

night lion
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still why isnt it possible that both can be together zero is corss product still defined then?

glacial hedge
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0 x 0 = 0

frank sparrow
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the condition a x b = 0 implies that either a or b must be the zero vector, or both must be parallel (i.e., the angle between them is 0° or 180°). It cannot be the case that both a and b are zero vectors simultaneously.

night lion
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but but is that allowed

frank sparrow
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is what i got

night lion
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nah i dont want chatgpt to answer me gang 😭

frank sparrow
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its not. i just did it.

glacial hedge
night lion
glacial hedge
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you're using trig for the definition?

night lion
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nah like the definiton of cross product is

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A X B= |A||B|sin(theta) unit vector of n [which is given by right hand thumb rule right]

glacial hedge
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most equivalent definitions will let you directly define 0x0 as well

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you just happened to take a def that fails in this case

short sedge
night lion
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makes sense

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fallow furnace
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hi i have this quiz for homework

marsh citrusBOT
fallow furnace
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ive put 1.True 50 2.False 0 3.False 0 4.True 20

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but i only got 5/8 points

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what did i do wrong?

wind sinew
wind sinew
marsh citrusBOT
# wind sinew use chatgpt

Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).

fallow furnace
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<@&286206848099549185>

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pls help

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alpine widget
#

One message removed from a suspended account.

fleet fossil
fervent rampart
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,w LambertW[i*pi]

elfin berryBOT
marsh citrusBOT
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@alpine widget Has your question been resolved?

marsh citrusBOT
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still temple
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how do i do this i have no idea

marsh citrusBOT
azure tusk
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ye ion know either

still temple
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id use chat gpt but i rn out of uploads

azure tusk
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me too

still temple
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fml

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how tf is this gcse maths

azure tusk
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i dont know what u said

marsh citrusBOT
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marsh citrusBOT
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swift olive
marsh citrusBOT
swift olive
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$min= 2l + 3w$

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$l\cdot w=13.5$

elfin berryBOT
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smeagol

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smeagol

swift olive
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I first solved for w

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$l = 13.5w^{-1}$

elfin berryBOT
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smeagol

swift olive
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$27w^{-1}+3w=min$

elfin berryBOT
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smeagol

swift olive
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$-27w^{-2} + 3 = 0$

elfin berryBOT
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smeagol

swift olive
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$w = 3$

elfin berryBOT
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smeagol

swift olive
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then solving for l I got 4.5

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and the answer didn't like 3 or 3000000 (million) what did I do wrong?

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(optimization, system of equations but for calculus)

remote granite
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try 3000 and 4500

swift olive
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oooh ty

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swift scarab
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hey guys, what is going onthumb_rat

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guys, i was solving the hardest math ever in my life:3

marsh citrusBOT
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mint spear
marsh citrusBOT
mint spear
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im trying to find the angle between AP and the lower part of the shape

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obv its vectors

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here's my work

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the alpha angle is 41.41 i alr calculated it

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help :)

marsh citrusBOT
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@mint spear Has your question been resolved?

mint spear
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<@&286206848099549185>

marsh citrusBOT
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@mint spear Has your question been resolved?

marsh citrusBOT
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@mint spear Has your question been resolved?

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wet oriole
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Right or wrong?

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Math is so weird because if I were to multiply the top fraction by the bottom fraction reciprocal, I wouldn’t get the same answer

marsh citrusBOT
wet oriole
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If there is a common factor throughout any part of the complex fraction, can I cancel it?

wet oriole
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If I multiply the top fraction w/ the bottom reciprocal, would I get the same result?

hollow oracle
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like $\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a}{b}\cdot\frac{d}{c}$?

elfin berryBOT
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someone1010

hollow oracle
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if so then yes

hardy kelp
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This would be what would happen, and here the same stuff cancels out

wet oriole
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Ty

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.solved

marsh citrusBOT
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stray raven
marsh citrusBOT
stray raven
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does this look alright?

tepid temple
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does it look right to you?

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because if you look right there's something that should make you think

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@stray raven

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180° + 59 =/= 293

marsh citrusBOT
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@stray raven Has your question been resolved?

stray raven
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are you referring to the decimal

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and saying to round it

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oh wow i just realized for some reason that skipped my mind

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239.4 degrees

marsh citrusBOT
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lilac siren
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brief ana2 Q

marsh citrusBOT
lilac siren
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regarding the definition of a topological space (X, T)

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can for instance
X = R
T = {EmptySet, R, B(0,1)}
?

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where B is the closed ball around the origin with radius 1

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seems to fulfill the conditions

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but I do find it odd as it is also used as an equivalent definition for open sets

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meaning V ⊆ X is open <=> V ∈ T

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but how shall that apply if I can pick any valid T, especially one which contains closed subsets

marsh citrusBOT
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@lilac siren Has your question been resolved?

glass silo
#

“How is a set different from a door?”

lilac siren
lilac siren
glass silo
#

catGiggle I was in the middle of editing AFoxy_Popcorn
was gonna comment that while said closed ball is closed wrt the standard topology (and isn’t open), wrt the new one you just defined, it’s open (but not closed, its complement isn’t in your topology)

lilac siren
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ahh

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topologies are meant to be the guideline for openness

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if T contains all open subsets of X

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then a subset is considered open equivalent to the openness definition with environments

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so it provides the definition for openness itself ok

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ty 🐛

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oak moth
marsh citrusBOT
oak moth
#

stuck and lost

chilly spoke
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do you need to find B(t) or just answer question 14?

marsh citrusBOT
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fickle slate
#

cos(5x) + cos(x) = 2cos(2x)

marsh citrusBOT
fickle slate
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equation

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😭

elfin berryBOT
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riemann

main idol
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Last one with a cleverly chosen x and y

fickle slate
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cos(3x+2x) + cos (3x-2x)

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2cos(3x)cos(2x)

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i need another tip

valid cape
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at what values of x does cos(2x) = 0?

fickle slate
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90

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270

main idol
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cos(2x), not cos(x)

fickle slate
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2cos(3x)cos(2x) = 2cos(2x)

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im heavily tempted to divide by 2cos(2x) but idk if i can

valid cape
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answer my question first

fickle slate
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90, 270

valid cape
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wrong

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cos(2x), not cos(x)

fickle slate
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45, 135

valid cape
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correct, but 2 values arent enough

fickle slate
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225

valid cape
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now given an integer k, can you give the solutions set of x for which cos(2x) = 0?

fickle slate
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45, 135, 225, 315

valid cape
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what about cos(2x)?

fickle slate
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for, cos(2x) = 0 solution set is x = 45k

valid cape
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wrong

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at k = 2, x = 90, but x = 90 isnt a solution to cos(2x) = 0

fickle slate
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tbh i dont know

valid cape
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consider something simple first, like cos(x) = 0

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what is its solution set?

fickle slate
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90 and 270?

valid cape
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correct, but again, im looking for a general solution set

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if its hard, use a unit circle

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,tex .unit circle

elfin berryBOT
valid cape
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at what point on the circle does cos(x) = 0?

fickle slate
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90 and 270

valid cape
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and...?

fickle slate
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360

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no

valid cape
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wrong

fickle slate
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450

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630

valid cape
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remember that you can add 360 to any angle and it still doesnt change

fickle slate
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90, 270, 450, 630 ...

valid cape
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yes

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now take your starting point as 90

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if you observe closely, you can actually add 180 to 90 however times you want

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and cos(x) would still be 0

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can you tell me the solution set of cos(x) now?

fickle slate
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yes

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cos(x) = 0, solution set is 90 + 180k

valid cape
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very good!

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now that you got the solution set of cos(x) = 0, can you tell me the solution set of cos(2x) = 0 now?

fickle slate
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cos(2x) = 45 + 90k

valid cape
#

very good!

valid cape
fickle slate
valid cape
#

yes, that is correct

fickle slate
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ok

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2cos(3x)cos(2x) = 2cos(2x)

valid cape
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do you think you can divide both sides by 2cos(2x)?

fickle slate
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well idk the angle so i think not

wary kite
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well cos(2x) could = 0

valid cape
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yes, this is why i asked you to find the values of x in those cases

fickle slate
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so i substract 2cos(2x) from each side

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and take the factors

valid cape
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essentially, you need to consider two cases:

  • when x = 90k + 45
  • when x is not 90k + 45
valid cape
fickle slate
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i did

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2cos(2x)cos(3x) - 2cos(2x) = 0

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2cos(2x) * (cos(3x-1)) = 0

wary kite
fickle slate
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then

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2cos(2x) = 0

cos(3x)-1 = 0

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is that it

valid cape
valid cape
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you found the solution set for the former

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now do it for the latter

fickle slate
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ill be right back, gotta do something quick

marsh citrusBOT
#

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marsh citrusBOT
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rocky nova
#

How is the group of integers under addition cyclic?

rocky nova
#

a single member of G should be able to generate all other members

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1 can generate all positive ints, and -1 can generate all negative ints. but neither can generate all

fervent rampart
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note the "and their inverses"

rocky nova
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I am not looking for a generating set, I am looking for a generator @fervent rampart

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Are you saying that if I have 1 as my generator, that includes its inverse, -1?

fervent rampart
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a cyclic subgroup is generated by a generating set with a single member (the generator)

rocky nova
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I get that

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but shouldn't the subgroup be the actual group itself?

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so not much of a "sub"group

fervent rampart
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a set is a subset of itself, so a group is a subgroup of itself

rocky nova
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I am still not really sure where my understanding is off. Can you just tell me what the generator of the group of ints under addition is?

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As far as I am concerned, there isn't one

fervent rampart
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a generator is just a member of a generating set. so the same rules apply

rocky nova
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you lost me at "generating set"

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well not really

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I am trying to determine if the group is a cyclic group

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a single element in G has to be able to do this (create all members of G)

fervent rampart
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yes, we like to drop the {} and write <g> rather than <{g}> but they mean the same thing. the definition of a generator does not change

rocky nova
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I am not sure why you're mentioning {} that is not what I was confused about, although I am now

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can you please just tell me what the g is?

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I am not sure what the <> denotes either

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is that saying "generator" ?

fervent rampart
#

using additive notation,
<g> = {ng, n in Z}
using multiplicative notation,
<g> = {g^n, n in Z}

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in other words, all elements which can be expressed using a finite number of group operations on g and its inverse

rocky nova
#

in this example what constant is g

fervent rampart
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<g> is the set generated by f

fervent rampart
rocky nova
#

okay

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so how does 1 generate -2 for example?

fervent rampart
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-1 + -1 = -2

rocky nova
fervent rampart
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yes

rocky nova
#

thank you

#

I get it now

#

thank you for your help and patience @fervent rampart

#

/close

#

!close

#

.close

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dense smelt
#

prof accidently put something we havent learned yet on our homework, but insists we do it anyway, which I've only just noticed now, 1.5 hours before its due.

Is anyone able to point me to the relevant reading stuff to solve this problem? Maybe an example? I would like to avoid any stupid mistakes from a hasty google search, and our book is too dense for me to get confident and also do the problem before I have to turn it in.

marsh citrusBOT
#

@dense smelt Has your question been resolved?

brave marsh
#

For a), you want to show linear independence.
That means that you want to see whether a linear combination of p1, p2 and p3 can yield the 0 function without all the coefficients being 0

dense smelt
#

Is this a right approach?

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plan is to do gaussian elimination on these

brave marsh
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That's the right approach.

dense smelt
#

keep in mind I am cooked xdd

brave marsh
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You likely don't need gaussian elimination though

dense smelt
#

alright cool

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yeah probably not

brave marsh
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To have linear independence you need to make sure that the only solution is a1 = a2 = a3 = 0

dense smelt
#

@brave marsh im not rly sure about b though?

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im not rly sure what it means donk

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#
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brave marsh
#

.reopen

marsh citrusBOT
#

brave marsh
#

b) is somewhat similar
You take some generic $\alpha x^2 + \beta x + \gamma$ and you have to show that there are some $a,b,c$ such that $a p_1 + b p_2 + c p_3 = \alpha x^2 + \beta x + \gamma$

elfin berryBOT
#

Azyrashacorki

brave marsh
#

It will look somewhat similar to what you had in a), but the equalities won't be homogeneous (= 0)

dense smelt
#

thank you so much :)

marsh citrusBOT
#

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muted scroll
#

find the biggest n where n³ + 100 is divisible by n + 10

limber hearth
#

n³ + 100 = (n+10)(n² -10n + 100) - 900

#

If n³ + 100 is divisible by n+10, it needs you something else here

sleek lake
#

it means 900 is divisible by n+10

limber hearth
#

Indeed

#

So what is the largest n ?

sleek lake
#

the question becomes how did you factorize it like that

limber hearth
#

I thinked

#

Jk

twilit geyser
#

it's n^3 + 10^2 which wishes to become n^3 + 10^3 🥹

limber hearth
#

Forced factor by n+10

sleek lake
#

the technique that needs to be nerfed badly

still temple
#

where did OP go?

marsh citrusBOT
#

@muted scroll Has your question been resolved?

muted scroll
tawdry rampart
#

Do you know about factor theorem?

true parcel
#

900 must be divisible by n+10

muted scroll
#

I have (n+10)(n² - 10n + 100) - 900 ≡ 0 (mod n + 10)
since (n+10)(n² - 10n + 100) is divisible by n + 10
also 900 must be divisible by n + 10

tawdry rampart
#

Put -10 in f(n)

true parcel
#

you're looking for the biggest n

#

biggest divisor of 900 is 900

#

so n+10 = 900

muted scroll
#

oh

#

so n is 890

#

thank you

#

.close

marsh citrusBOT
#
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#
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zinc solstice
#

Let $\mathbb{P}$ be a probability on $(\mathbb{R}^n,\mathcal{B}(\mathbb{R}^n))$. Prove that for any $S\in\mathcal{B}(\mathbb{R}^n)$ and $\epsilon>0$, there are an open set $A\supset S$ and a closed set $B\subset S$ such that $\mathbb{P}(A\setminus S)<\epsilon$ and $\mathbb{P}(S\setminus B)<\epsilon$.

elfin berryBOT
#

KOforaf

zinc solstice
#

I am thinking about the construction of $A$ in terms of $S$.

elfin berryBOT
#

KOforaf

marsh citrusBOT
#

@zinc solstice Has your question been resolved?

zinc solstice
#

.close

marsh citrusBOT
#
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sacred epoch
#

if 25% of an amount is $80 then the total amount is

sacred epoch
#

am i just tripping

#

my working out says 320

#

but it sounds wrong

#

idk

#

also the value of 8cos28 correct the four deciaml places is 7.0636 right?

#

<@&286206848099549185>

limpid quartz
#

how do u get cos here?

sacred epoch
#

?

limpid quartz
#

answer is 80 *4

vast sparrow
#

Hence you are correct

sacred epoch
#

alr

#

whats the second one

limpid quartz
#

do u want the workings?

sacred epoch
#

for the firtst one no

#

whats the answer for the second

limpid quartz
#

secons ans is also correct

#

@sacred epoch

sacred epoch
#

ok

#

.close

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#
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oak moth
marsh citrusBOT
oak moth
#

is it D?

#

just checking

amber birch
#

differentiate x + y = K with respect to t

#

dK/dt = 0, the derivative of a constant is always 0

oak moth
#

so B?

#

.close

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#
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oak moth
#

i can use a calc

#

i graphed it

#

not sure what to do

amber birch
#

you have $\frac{d F(s)}{dt} = \frac{d F(s)}{ds} \frac{ds}{dt}$

oak moth
#

i dont get that

amber birch
#

btw, rate means change over time

oak moth
#

right side

amber birch
oak moth
#

no

amber birch
#

this is the same as $\frac{d}{dt} (F(s(t)) = F'(s(t)) \cdot s'(t)$

elfin berryBOT
#

south's secret twin brother

amber birch
#

try watching this for the notation

elfin berryBOT
#

south's secret twin brother

marsh citrusBOT
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hallow gull
#

hello , we have an equation of a circle and we ask us to find the center and the radius

but idk how to do it, can someone learn me how please !

hallow gull
#

the answer is the black one

#

but idk how we get it

amber birch
#

specifically $x^2 - 4x + 4$, $y^2 - 6y + 9$ is already a perfect square

elfin berryBOT
#

south's secret twin brother

amber birch
#

so what must the right hand side now be with x^2 - 4x + 4?

hallow gull
#

+4 ,

#

?

amber birch
#

so now you can get it in the form $(x - h)^2 + (y - k)^2 = r^2$

elfin berryBOT
#

south's secret twin brother

amber birch
#

$(h, k)$ centre and $r$ radius

elfin berryBOT
#

south's secret twin brother

hallow gull
amber birch
elfin berryBOT
#

south's secret twin brother

amber birch
#

and know all of h, k, r

hallow gull
#

oh okay ty @amber birch i understood ! 🫡

#

tysm

#

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wintry gale
marsh citrusBOT
wintry gale
#

Is this possible?

amber birch
wintry gale
#

My book says only option 3 is possible

amber birch
#

oh it might depend on their definition of a recurring decimal then

wintry gale
#

Meaning?

amber birch
#

cause right, 0.2000000... is indeed a recurring decimal

#

but it terminates cause 0.20000... = 0.2

wintry gale
#

Oh

#

Makes sense

#

Ty

amber birch
#

it's really silly I know

wintry gale
#

Yeah

#

Well thanks regardless

#

.close

marsh citrusBOT
#
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amber birch
#

ah yeah that is what recurring means

#

cool that's interesting

marsh citrusBOT
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charred panther
#

Hi, I'd like to ask for some help on finding the equation of a plane

charred panther
#

so in this figure i'm looking for the plane

#

So the edges that make up the tetrahedron is

#

(0,0,0), (1,0,0), (0,2,0),(0,0,3)

#

my idea was to take one point and then subtract two others from there

#

for example (0,0,0)-(1,0,0) and (0,0,0)-(0,2,0)

#

and then use the cross thingy to get a normalvector to the plane

#

but that'd be (0,0,2)?

#

and 0*(x-x0)+0(y-y0)+2(z-0) = 0

#

doesn't really uh..

#

produce something that i think is correct

#

so where did I go wrong ;P

#

ah it should be end point vs start point

#

but even then does that really change a lot?

#

(1,0,0) and (0,2,0)

#

still gives (0,0,2)

#

and then we get 2z = 0 as the normal equation for the plane

#

or would I have to select coordinates that aren't 0?

#

like (1,0,0)-(0,5, 0,5, 0,5) and (0,2,0)-(0,5, 0,5, 0,5) from which we get (0,5, -0,5 , -0,5) and (-0,5, 1,5, -0,5)

#

(0,25-(-0,75), 0,25-(-0,25), 0,75-(0,25)) = (1, 0,5, 0,5) and plugging back our values we get 1(x-0,5) + 0,5(y-0,5) + 0,5(z-0,5) = 0

x-0,5+0,5y-0,25+0,5z-0,25 = 0
x +0,5y + 0,5z = 0,5+0,25+0,25
2x+y+z-2=0

which ain't it :/

#

ah wait im completely gone

#

XD

#

-1,2,0
-1,0,3

6, 3, 2

#

6(x-1) + 3(y-0) + 2(z-0) = 0

#

6x + 3y + 2z - 6 = 0

#

yeah

#

idk what i was thinking

#

.close

marsh citrusBOT
#
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marsh citrusBOT
#
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spare badger
#

ive been stuck on this problem for awhile now

still temple
#

y=mx+b

spare badger
#

im new to this so i dont rlly understand it all

spare badger
still temple
#

Okay so

#

Are u familiar with rise over run?

spare badger
#

ive seen tht to and i dont understand it

pliant willow
#

the slope of the curve is determined by the coefficient of x

#

called m

still temple
pliant willow
#

and you find that coefficient taking two points of the curve

pliant willow
spare badger
#

what does slope mean?

still temple
#

State ur points which is ob the graph

crude wadi
#

the ratio of rise to run. How much a line increases in height for every one unit is moves across

still temple
#

So like

#

(-2,24) and (2,8)

#

Label them if u want to make it easier to read

#

X1 y1 x2 y2

crude wadi
#

that's a ratio of -2/1, so the line has a slope (or gradient) of -2

#

the intercept is where the line crosses the y-axis

spare badger
#

how do i get the equation

pliant willow
crude wadi
#

a line is always in the form:
y=ax+b

pliant willow
#

use the form y = mx+p

crude wadi
#

a is the slope, and b is the intercept

pliant willow
#

with the slope you find the val of m

still temple
pliant willow
#

ok lets use a and b

crude wadi
crude wadi
# still temple

okay, so from there, you can choose one point to be (x1,y1) and the other to be (x2,y2)

#

Either point can be (x1,y1) and vice versa, it'll give you the same answer

#

Which one do you want to do?

spare badger
#

the points are the dots right

crude wadi
#

Yes the ones on the corners of the triangle

#

And then those points are written out on the sides there

#

as (-2,24) and (2,8)

spare badger
#

im trying to understand

#

is there any tut i can use or something

crude wadi
#

probably

#

chuck "what is slope intercept form" into youtube and something will come up

#

but i'll give it one more go

#

from the top

#

So, the slope intercept form of a line is in the form:
y=ax+b,
where a is a number that represents the slope (or gradient), and b is a number that represents the y-intercept

#

Do you know how to find the y-intercept?

spare badger
#

where the line crosses the y axis?

crude wadi
#

Exactly

#

Can you tell me where that happens

spare badger
#

8

crude wadi
#

Not quite

#

the y-axis is the vertical one

spare badger
#

oh

#

2

#

im suppposed to be looking at the red line rii?

crude wadi
#

Yes, when the red line crosses over the y-axis

still temple
spare badger
#

24

crude wadi
#

Not quite

#

This black line is the y-axis

spare badger
#

oh then its 16

crude wadi
#

Yeah!

still temple
#

YEAH

#

So

spare badger
#

i was looking at the blue one

crude wadi
#

And another way of saying that is that the red line intercepts the y-axis at the point (0, 16)

still temple
#

y=mx+b your slope is gonna be -4 your y int (b) is 16

#

Put it into the equation

spare badger
#

yes

crude wadi
#

Cool

#

okay we're getting somewhere

#

And now the only other thing we need to find is the slope

spare badger
#

so b is 16?

crude wadi
#

To find that, you can pick any two points on that red line

spare badger
#

and -4 is y?

crude wadi
crude wadi
#

Oh do you mean the y in
y=ax+b?

spare badger
#

which one do i use

still temple
#

A

spare badger
#

urs?

still temple
#

Ok it's honestly the same thing

#

Just different letter

crude wadi
#

Yeah they're just different letters that mean the same thing

#

Just up to personal preference

#

What do you prefer

spare badger
#

ill use the a one

crude wadi
#

Okay

still temple
#

Okok

crude wadi
#

In the equation y=ax+b, we leave the y and x as is

spare badger
#

so b is 16 how would i get a and y

crude wadi
#

So we're only needing to find a and b. Since we've found b, we just need a

crude wadi
# spare badger so b is 16 how would i get a and y

You don't need it. When we have a and b, (I'll just give the example that a is 2 and b is 3):

then our equation would be: y= 2x+3.

We can then find what y would be equal to by inputting any number for x

#

For example, if we set x to 1, we would have

2x1 +3
so y would be equal to 5 in that case

#

but y isn't always equal to 5, so we need to keep it as just y to make sure we can find all the other values it could take

#

if that makes sense

spare badger
#

mk

#

so how do i get a

crude wadi
#

Probably the easiest way is the rise over run formula

spare badger
#

can u teach me rise run?

crude wadi
#

Yeah I'll give it a go

#

So we want to see how fast the line goes upwards compared to outwards

#

If a line goes up as fast as it goes across, then its gradient is 1

#

This is a 45° line

#

The formula you use to find the gradient is:

#

You need to pick two points that are on the red line

#

And they can be any points, so don't worry about having to pick specific ones

#

They will always give you the same answer

#

Did you want to pick two points on the line?

spare badger
#

i dont understand the points part

#

i just pick a point for x?

crude wadi
#

okay

#

So that red dot there is the point (-2, 22)

spare badger
#

mk

crude wadi
#

you can pick that point to help you find the slope, because it lies on the line

#

the yellow dot is the point (1, 12)

#

does that point lie on the line?

spare badger
#

yes

crude wadi
#

so we could also use that point to calculate the slope

#

but we aren't limited to using only those two points

#

we could use the corners of the triangle

#

or we could use the y intercept and a corner

#

there's infinite possibilities

#

but you can't use the green dot

#

because it doesn't lie on the line

spare badger
#

how will the point calculate the slope?

crude wadi
#

because it will show us how fast the line has spread both vertically and horizontally

#

Can you tell me what point that brown dot is?

spare badger
#

4,3

crude wadi
#

very close

#

you've just switched the y and x around

spare badger
#

so 3,4

crude wadi
#

That's it

#

Okay, so we'll use that point

#

Now pick any other point on the line

spare badger
#

-1,20?

crude wadi
#

Okay yeah we can do that

#

So, to use the formula, we need to substitute one of our points for x2 and y2, and the other for x1 and y1

spare badger
#

can u explain the x2 y2 stuff a bit more

crude wadi
#

I'm drawing something up

spare badger
#

mk

crude wadi
#

So the y1, y2, x1, and x2 are all just placeholders

#

You put the numbers from your points in their place, and then you can solve the formula

spare badger
#

ok so 3 is x and y is 4

crude wadi
#

x2 is 3 and y2 is 4, yeah

#

but you can swap them around if you'd like

#

it wouldn't make a difference

spare badger
#

i think x1 3 and y1 4 would be better for me

crude wadi
#

okay then lets do that

spare badger
#

ok so what now?

crude wadi
#

So all we have to do now is swap those numbers into the formula

#

so in place of x1, put 3

#

and in place of y1, put 4

#

make sure to be careful of the minus 1!

crude wadi
spare badger
#

20-4?

crude wadi
#

yes that's the top

#

and the bottom would beee?

spare badger
#

1-3

crude wadi
#

very close

#

it's a minus one

spare badger
#

oh ye

#

so -1-3

crude wadi
#

yep

#

so what would that be altogether

spare badger
#

wdym

#

like add the top n bottom

crude wadi
#

it's a fraction, so you have to divide them

#

what's 20-4?

spare badger
#

16

crude wadi
#

awesome

#

and what's -1 -3?

spare badger
#

-4

crude wadi
#

awesome

#

and then what's 16 divided by -4?

spare badger
#

-4

crude wadi
#

yep!

#

so that's your slope

spare badger
#

a is -4 and b is 16?

crude wadi
#

what that number tells you is, your line moves down four spaces before it moves one space to the right

#

sure is

crude wadi
spare badger
#

oh my gosh tysm😭

crude wadi
#

that's okay man

#

got one more thing

#

now that we've gone through it once, tell me how you'd figure out the equation for this line

spare badger
#

is it ok if i go back and read?

crude wadi
#

that's okay, it would be good to see how much you can remember

#

i can ask you prodding questions if you'd like?

spare badger
#

whats that mean?

crude wadi
#

like for example

#

i'd ask you, what is the equation of a line ?

#

or, what form does it come in?

spare badger
#

what other forms are there?

crude wadi
#

only one

#

but what does the equation of a line look like?

spare badger
#

y=mx+b

crude wadi
#

yes

#

and what do we need to find?

spare badger
#

m and b

crude wadi
#

what does b mean?

spare badger
#

y intercept

crude wadi
#

and can you tell me what that is on this line?

spare badger
#

where the line crosses the y axis

crude wadi
#

yes hahah, what number does that happen at?

spare badger
#

3?

crude wadi
#

yeah!

spare badger
#

but i dont see 3

crude wadi
#

that's okay

spare badger
#

oh its still there

#

i understand

crude wadi
#

that's right

spare badger
#

so b is 3

crude wadi
#

yep!

#

and then what do we do to find m?

spare badger
#

thats the one i forgot

crude wadi
#

that's okay, you can look at the formula

spare badger
#

wait

#

so id have to do the y 2 and y1 stuff rii

crude wadi
#

yep

#

and what do you have to do before you can use the formula?

spare badger
#

im lost again

crude wadi
#

why's that?

#

what's got you confused

spare badger
#

the formula is y=mx=b rii

#

+*

crude wadi
#

that's the equation of a line

#

the formula im talking about is the formula you use to find out what m is

spare badger
#

oh

crude wadi
#

we're thinking about the same thing

spare badger
#

can 1 7 be a point?

crude wadi
#

yep!

spare badger
#

so

#

x1 1

crude wadi
#

yeah you can do that

spare badger
#

then x2 2

crude wadi
#

and then what else do you need

spare badger
#

y1 n

#

2

crude wadi
#

and what are they

spare badger
#

y1 is 7 and y2 is 11

crude wadi
#

there you go

#

now plug them into the formula and tell me what you get

spare badger
#

1 divided by 4 right?

#

wait

#

is m 4?

crude wadi
#

put it all together?

spare badger
#

y=4x+3

crude wadi
#

you got it

spare badger
#

man your a life saver

crude wadi
#

is it making sense? are you getting the hang of it?

spare badger
#

yes

crude wadi
#

that's very good

#

do you want to do one more?

spare badger
#

yes pls

crude wadi
#

and i don't ask you anything, but you tell me everything that you're doing

spare badger
#

ok

crude wadi
#

so that i can point things out if you make mistakes?

crude wadi
# spare badger wait

i also think it's very good that you figured out where you went wrong here by yourself

spare badger
#

ye i put the xs on top

crude wadi
#

hahaha everyone's been there at least once

#

okay, here's a new line

spare badger
#

b is 5

#

then for the points i go 1 2

#

could i do 0 5?

crude wadi
#

yep!

spare badger
#

x1 1

#

and x2 0

#

y1 2 y2 5

#

2-1 1

#

wait

#

itd be 0-1

#

so -1

#

5-2 is 3

#

3 divided by -1

#

-3

#

so

#

y=-3x+5

#

?

crude wadi
#

you're too good

spare badger
#

thanks to u

crude wadi
#

hahaha

spare badger
#

fr tho thx i was stuck for like 2 hours

crude wadi
# spare badger 2-1 1

my only recommendation is: it's very normal for people to write down the formula first and then put all their numbers in

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just to make sure they get the right answer

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are you writing this on paper?

spare badger
#

no i was using my head

crude wadi
#

well that's some talent

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i recommend having a go solving some of these on paper

spare badger
#

im good at math when i understand it

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ty tho again ima close this now

crude wadi
#

that's okay! just one more thing too

spare badger
#

?

crude wadi
#

make sure to practice

spare badger
#

i will ill look up some

crude wadi
#

you're very good at it right now, but when you move on to other topics later, it might not come as easily then

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so make sure to do a couple questions here and there to make sure you've still got it

spare badger
#

ok ty for the advice

crude wadi
#

all good man

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good job on all of those

spare badger
#

also do yk any books i could read im tryna get some reading in and cant find any?

crude wadi
#

i probably wouldn't know. if i recommended anything, it might not fit exactly what they're teaching you at school

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i recommend searching it up on youtube, there's some very good maths youtubers out there

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and also just ask your teacher if they have any recommendations

spare badger
#

homeschooled

crude wadi
#

they might be able to loan you a textbook

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ohhh

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well there you go

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yeah have a go on youtube!

spare badger
#

mk ty

crude wadi
#

you're welcome to dm if you get stuck

spare badger
#

will do

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.close

marsh citrusBOT
#
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marsh citrusBOT
#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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sly hare
#

Is it possible to take the infimum (or min) or a multivariable function subject to only one of the variables, like for example trying to get infimum of f(x,y) subject to only x? If so, how is that defined?

past maple
#

Yes, it is possible

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In the example, for each y, you get a function f_y(x) = f(x,y) which depends only on x

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So you can take the inf as usual

sly hare
elfin berryBOT
past maple
#

You get a different result for each y

sly hare
#

so essentially for all values of y, the infimum of f(x,y) based on x should be an appropriate lower bound

devout mauve
#

for each fixed y you get a different thing

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so for example for y=2 you get the infimum of f(x,2)

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for y=3 you get the inf of f(x,3)

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and so on

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that defines a new function g(y) = inf_x f(x,y)

past maple
devout mauve
#

for each value y you want, you can plug it into this and get some new value g(y)

sly hare
past maple
#

Not for the whole function

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For example, take f(x,y) = x^2+y^2

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I will find the inf in x when y = 4

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The functions becomes x^2 + 16 and the inf is 16

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So g(4) = 16

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But 16 is not the infimum of f, as it is 0

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16 is the infimum of the function f(x,4)

sly hare
#

Soo if you have something like $\max_{y} \inf_{x} f(x,y)$ you take the max first to figure out what the inner y should be?

elfin berryBOT
past maple
#

No, you take the inf first

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And get a function g(y)

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And then find the max of that new function g

sly hare
#

yeah I mean that's what I was thinking

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idk i'll go see if I confused myself somehow

#

.close

marsh citrusBOT
#
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marsh citrusBOT
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sharp sedge
marsh citrusBOT
sharp sedge
#

why is the person working out coeffecient of x^2

#

why not x^3

sharp sedge
# sharp sedge

my working out will be expand out (3+bx)^3 so u get bx^2 which u then multiply by -x to make x^3 and mutiply x^3 by 2 and then do equation

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but this isnt the case

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how do i do this???????????

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sum1 tell me step by step please

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<@&286206848099549185>

vernal yoke
sharp sedge
#

how do i do this

sharp sedge
vernal yoke
sharp sedge
#

im so stupid might aswell

#

fck this server

#

.close

marsh citrusBOT
#
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leaden depot
#

I am doing this question and I am quite confused about the use of Advisory and the use of probability that if a Advisory can distinguish two codes. This is the question:

Suppose MAC is the tag-generation algorithm for a secure Message Authentication Code. Define a new tag-generation algorithm MAC′ as
MAC′(k, m) = MAC(k, m)∥MAC(k, m),
where k ← {0, 1}n is a fully uniform key string of length n. Does MAC′ also yield a secure Message Authentication Code? Prove your answer. You may assume that for both MAC and MAC′, the corresponding Key Generation algorithms take as input the security parameter 1n and output a uniform key k of length n. Here, by secure we mean that the Message Authentication code is existentially unforgeable under an adaptive chosen-message attack.

And my attempt is as follow:
Let the adversary receive any valid message-tag pair (m, t∥t) where t = MAC(k,m)
The adversary can verify that the tag consists of two identical halves
And accept only if both halves are identical (t = t')
Hence Pr[𝙼𝚊𝚌-𝚏𝚘𝚛𝚐𝚎𝒜,Π(𝑛) = 1] > 1/2
Hence MAC' does not yield a secure message authentication code

sharp sedge
#

cba to read all that

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use chat gpt

sharp sedge
marsh citrusBOT
#

@leaden depot Has your question been resolved?

marsh citrusBOT
#
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charred panther
marsh citrusBOT
charred panther
#

How do we get to -2 sinh(1)??

#

like how is it the case that sin(1) - sin(1) doesn't cancel each other to begin with? o_O

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and shouldn't e^-1 - e^1 be 1?

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like in my head this is = 1

main idol
elfin berryBOT
#

Result:

-2.3504023872876
main idol
#

no

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$a^{-1} = \frac{1}{a}$

elfin berryBOT
#

riemann

charred panther
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ah wait i see

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what i did wrong

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kek

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or now im confused

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1/e - e/1

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1/e - e^2/e

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ah no it probably checks out

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but nonetheless how do we get to -2sinh(1)?

fervent rampart
#

,, \sinh x = \frac{e^x - e^{-x}}2

charred panther
#

or ah it flips it

elfin berryBOT
charred panther
#

yeah ok and we have 1-e^2/e

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or we had e^-1-e^1 to begin with before i started doing this stuff

fervent rampart
#

use that original one j think

charred panther
#

so then you can say 2(sinh(1))?

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ah no its -

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since it's the wrong order

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ok i see what they did then

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thank you!

#

felt so lost for a second there..

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have a nice evening/day!

#

.close

marsh citrusBOT
#
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marsh citrusBOT
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still temple
#

Let’s say i have a pizza and cut it up into 8 equal pieces. Is there a difference in the fraction 8/8 and 0/8

still temple
#

Yeah

red nimbus
#

explain

still temple
#

Because you are counting all 8 right

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In 8/8

red nimbus
#

yea

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how many do you count with 0/8

still temple
#

7

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Im just kidding

#

Thanks man. I just got confused for a second

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And im trash at math

#

And i always imagine there is a secret rule i dont know about

#

.close

marsh citrusBOT
#
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limpid bison
marsh citrusBOT
limpid bison
#

completely lost on how to do c

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the circle is ez pz

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but idk what they did here

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😱

mystic ledge
#

you get the inspiration from the pythagoras theorem

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in the equation of circle there is sum of two squares as in pythagoras theorem

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and also sin^2+cos^2=1

limpid bison
#

oh its not a right angle triangle there tho

mystic ledge
#

what is not right angle triangle

limpid bison
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ah im lost

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oh wait

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i think i get it

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u make a right angle out of this right?

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so then 3 cos t squared plus 3 sin t squared = 3

mystic ledge
#

no no i mean we have equation of circle like this:
(x-4)^2+(y-3)^2=9

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it's like pythagoras theorem right?

limpid bison
#

yea

mystic ledge
#

can you see where the parametric equations come from?

limpid bison
#

omg

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wait no

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if u sub in that stuff

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u get 3 cos ^2 + 3 sin^2 t = 9

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oh shit yeah thats right