help-33

[copper basin]

One message removed from a suspended account.

[twilit geyser]

$$\frac{3(-1)(x-c)}{xc(x-c)} = \frac{3(-1)}{xc}$$

[elfin berry]

Merosity

[copper basin]

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

[twilit geyser]

yeah you're welcome

[copper basin]

One message removed from a suspended account.

[marsh citrus]

Channel closed

Closed by @copper basin

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dapper snow]

what

[dapper snow]

at x=0, y is 8.2

at x=4 y is 9

so dont do you like 0.8/4 = 0.2 rate of change

but then it says round to the nearest thousandth

[marsh citrus]

@dapper snow Has your question been resolved?

[dapper snow]

<@&286206848099549185>

[marsh citrus]

@dapper snow Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hallow eagle]

they're asking you to describe the curve you've been given, so plug in 0, 1, 2, 3, 4 and give an answer accordingly

[hallow eagle]

the curve already gives the answer but they want you to use the function here

[marsh citrus]

@hallow eagle Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[split geode]

what ques means ?
1+2+3......+k

[faint narwhal]

sigma (k=1 to 20) [ sigma (i=1 to k) [ i ] ]

[unborn condor]

you're asked the sum of the 20 first integers

[crystal lintel]

sigma

[red nimbus]

you were once too a sigma

[crystal lintel]

i am sigma

[red nimbus]

slayla now it's layla

[split geode]

so using n(n+1)/2 the ans i got is not correct

[split geode]

off topic👾

[cloud field]

that one is 1 + 2 + ... + n

this one you are adding a lot more things

[split geode]

lot more ?

wahat are they

[cloud field]

did you use this and make n = 20?

[split geode]

yes

(20*21)/2

=210

[cloud field]

you need to use that for the inside part

[split geode]

actual ans is 1540

[cloud field]

so its sum (k(k+1)/2) from 1 to 20

[split geode]

i didnt get the sequence

[cloud field]

so you know that 1 + 2 + 3 +... + k is k(k+1) / 2

[split geode]

yes

[cloud field]

then plug it into the sum

so its sum(k(k+1)/2)

[split geode]

but why

[split geode]

ok

so its basically 1+1+2+1+2+3+.....

got it

[cloud field]

yea

[split geode]

thnx

[marsh citrus]

@split geode Has your question been resolved?

Channel closed

Closed by @split geode

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

allo

[sinful thistle]

hello, what is your question

[still temple]

in a square

i saw this triangle

And soo

[sinful thistle]

what... do you mean?

what is the black square? that represents a right angle, aka 90 degrees

[still temple]

i wqnna know if a and b are equal C :

[sinful thistle]

not necessarily

in this diagram that's probably what they meant but we can't definitively say

[fathom sable]

hi am sorry to ask but where can i get help, i'm really just overthinking a small problem

[sinful thistle]

#❓how-to-get-help

[still temple]

@sinful thistle renegade sir

the full context^

"I" think

that theg are

equal

[sinful thistle]

again, not necessarily

[still temple]

🤔 they look the saame and th3y xoming from the same angle

[sinful thistle]

and please do not ping me

[still temple]

aigh sorry

[still temple]

how so

[still temple]

id they meant thwt then they wouldnt name them different variables

bro left on read

me

💀

.close

[marsh citrus]

Channel closed

Closed by @crude fog

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[severe tree]

what have you done

like show me your working process

@stuck geode hello?

[stuck geode]

Hello

[severe tree]

do you have any idea on how to solve this

[stuck geode]

No idea

[severe tree]

or do you need help from the very beginning

you can substitute the denominator

4x²+1 = u

[red nimbus]

apply the same method you would apply on your pfp

[stuck geode]

.close

[marsh citrus]

Channel closed

Closed by @stuck geode

Use .reopen if this was a mistake.

[severe tree]

valid

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hushed dust]

Understanding Eulers:
I'n trying to work with Answer 1's method since my test is in 4 hours but how does the math work for when i square everything

[marsh citrus]

@hushed dust Has your question been resolved?

[hushed dust]

.close

[marsh citrus]

Channel closed

Closed by @hushed dust

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[honest topaz]

.close

[marsh citrus]

Channel closed

Closed by @honest topaz

Use .reopen if this was a mistake.

[honest topaz]

.reopen

[marsh citrus]

✅

[honest topaz]

Ignore the previous screenshot, I need help with this one

Could somebody walk me thru this step by step please?

[main idol]

First factor out a 4

Then do a u substitution

[honest topaz]

Like this?

[granite knot]

yes

[honest topaz]

This one?

This is what I have so far

I don't know where to go from here

.close

[marsh citrus]

Channel closed

Closed by @honest topaz

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[velvet tiger]

Can someone explain how they are manipulating the rhs to get the factorisation?

[pure dagger]

,rotate

[marsh citrus]

@velvet tiger Has your question been resolved?

[velvet tiger]

<@&286206848099549185>

[fervent stratus]

Integrals are not bad woah

[velvet tiger]

I half understand what they did but i cannot follow their method for a similar question with different values for the life of me

Prwtty sure they just did backwards completing the square maybe??

[marsh citrus]

@velvet tiger Has your question been resolved?

[marsh citrus]

@velvet tiger Has your question been resolved?

[velvet tiger]

.close

[marsh citrus]

Channel closed

Closed by @velvet tiger

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[void elm]

how is this proof?

[void elm]

it's a little long winded because I wasn't sure how much detail I should put in, so I decided more was better

the second paragraph feels a little bit on the less rigourous side though

if there's any logical mistakes or typos, please let me know!

[red nimbus]

Do you do such proofs in exams too?

[void elm]

I would put significantly less detail on an exam

just handwave a lot

[red nimbus]

this is worse than gedichtsanalyse

[void elm]

there's also this proof I would like verified

that's all though

just these 2 problems

[red nimbus]

at least your proof writing is neat

[glass perch]

I don't think you can say any open set in [0,2] is an interval

[red nimbus]

it just feels like reading a script 😭

[void elm]

you're right

fml

do I really need to do another double inclusion

[void elm]

I write my proofs in a way that I could read them and understand them without more needed

and since I'm a terrible proof reader, this is the result

[void elm]

actually no I don't

[red nimbus]

i think i am the problem

i dislike reading long ass stuff

[glass perch]

I think so if you want to be extremely rigorous

[void elm]

wait maybe I do

[red nimbus]

but i do it for you higher

cause you are my friend

[void elm]

you're a real one

I appreciate it

[void elm]

okay fine

I'll go do that

[void elm]

how's this proof?

[glass perch]

But it should just be a few lines 🙂

[red nimbus]

😂

you say you are a terrible writer, i am a more terrible reader

[void elm]

no need to delete haha

[void elm]

thanks :)

[glass perch]

For 4b) one might be able to say h(x) = [f(x)+g(x)+|f(x)-g(x)|]/2

[void elm]

does the pasting lemma proof not work?

for reference

[glass perch]

I'm still reading, but your topology knowledge is admittedly on a higher! level than mine

[void elm]

higher!

[void elm]

that's okay, take your time

I'll go try to fix that other proof rn

[red nimbus]

yea i think icannot help on this, this time

[void elm]

no worries

[hushed egret]

oh god the proofs are so long

how have you done this

[void elm]

hey...

I probably write with more words than I need but idk

[void elm]

do you see any problems with this one though, snow?

[red nimbus]

yea it's too long 😭

[void elm]

luckily I don’t write them by hand anymore

[hushed egret]

its just like

[void elm]

my TAs used to have to read stuff like this with my messy handwriting

[hushed egret]

too long to follow

[void elm]

oh no

[hushed egret]

in theory the proof should be quite short

prove that {(x, y) | x <= y} is closed, i.e., {(x, y) | x < y} is open

then {f(x) <= g(x)} is the preimage under (f, g)

and the fact that {(x, y) | x < y} is open should follow directly from constructing an open cover

[void elm]

wdym x < y

is x and y coming from X?

[hushed egret]

well this should be true of any order topology

[void elm]

X isn’t ordered though

[hushed egret]

given an ordered set Y, the set {(x, y) | x < y} in Y x Y is open

[void elm]

ah, I see

I mean, I feel like my proof works, but it’s definitely really long

[hushed egret]

well i feel like what you're doing is shoving all the details of the two steps i outlined into one thing

and my eyes are just falling off the page as i try to read your proof unfortunately

[void elm]

I see

[main idol]

snow can't

[void elm]

[red nimbus]

just like you

[red nimbus]

if snow can't nobody can

maybe riemann but we know he the laziest helper

[hushed egret]

whats going on here

why is a counterexample so long

[void elm]

as I said, I didn’t know how much detail I should’ve put in lol

I could just say that the closure of U is clearly [0,2] and the interior of that is clearly (0,2)

[red nimbus]

wait he said counter example and you wrote proof

[void elm]

I need to prove that it’s a counterexample

[red nimbus]

ah

[hushed egret]

maybe the example is more complicated than you need

[red nimbus]

why not give just one

[hushed egret]

like

[void elm]

I did!

[red nimbus]

i thought you rather tried to prove that it's true not false 😭

[hushed egret]

say you pick the space to be (0, 2) and U = (0, 1) \cap (1, 2)

then clearly the closure of (0, 1) \cap (1, 2) \subseteq (0, 2)

but 1 is also in the closure because any neighbourhood intersects U non-trivially

but U is already open

and thats it

oh i guess you dont need the U is open part

i thought it was Int U \ne Int U bar

[void elm]

wait I don't need why we're done

[hushed egret]

like you've written more than you need

because you've proved things that don't need to be proved

[void elm]

[hushed egret]

like this first paragraph is redundant

[0, 2] is a closed superset of U

so the closure of U must be contained in [0, 2]

by definition

[void elm]

gimme a moment

oh yes, I'm an idiot LOL

alright, I can remove that ig

[hushed egret]

and then you just need to show that 0, 1, 2 are in U for the other containment

these are just checking neighbourhoods intersect non-trivially

[void elm]

I did that, didn't I?

[hushed egret]

but the better thing to do is to just choose (0, 2) to be the topological space though

so you yeet everything out of existence

and just deal with 1

[void elm]

I see

I didn't think of that, actually

that's a lot more clever

[hushed egret]

like this first part is also a bit unnecessary

[void elm]

yeah but I put it there for completeness idk

like it's obvious, but I wanted to say it anyways

[hushed egret]

but like

at the end of the day

you probably only need to show that 1 point is in Int U closure

and not in U

so you don't need to compute the whole thing

anyway

i should be doing work

[void elm]

okie dokie

thank you snow

ig the main issue I have is that

I write too much then?

[hushed egret]

probably try to be more concise and to the point

[void elm]

noted, I'll try in the future

thank you snow!

.solved

[marsh citrus]

Channel closed

Closed by @void elm

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[misty mist]

Why is cos(3 -sin x) wrong? The correct answer for the derivative is supposed to be f'(x) = cos(3x cos x)[(-3x sin x) + (3 cos x)]

Er rather where did I go wrong

!flip

how flip

.flip

.help

[marsh citrus]

Commands:

• clopen: .close, .reopen
• consensus: .poll
• factoids: .tag
• help: .help
• version: .version

Type .help <command name> for more info on a command.

[knotty elbow]

your working out doesn't really make much sense, what technique were you trying to use?

[misty mist]

Trying to use the chain rule but I'm not entirely sure how it goes

wow thanks

[knotty elbow]

ok

well you kind of have something in there

[misty mist]

I know im supposed to put the outside derivative multiplying the let side, which is the derivative of u times the inner function

I wrote it badly, I know du is cos[3x cos x] but i got confused after that

[knotty elbow]

ok and what is the derivative of the inner function?

[misty mist]

3 -sin x right

because cos dx is -sin

x

and the derivative of 3x is... 3

3 -sin x?

[knotty elbow]

yes but that isn't the product rule

[misty mist]

o

[knotty elbow]

refer to this where f = 3x and g = cos(x)

[misty mist]

so I should have used the product rule and not the chain rule?

[knotty elbow]

no you have to use both

[misty mist]

oh

[knotty elbow]

first the chain rule because you have a function inside a function

and then you have to use the product rule for differentiaing the stuff inside of sin

[unique basin]

There's like different layers to the functions in this case the first layer was dealing with the composition

So chain rule came first

[knotty elbow]

yeah

[misty mist]

so once I get cos(3x cos x) I use the product rule on the inside...?

okey

[unique basin]

That product rule would be the "derivative of the inner function" part of the chain rule

[misty mist]

so f(x) would be 3x and prime being 3

and g(x) would be cos x and prime being -sin x?

[unique basin]

Yea you can do it that way

[misty mist]

is there a better way ._.

[unique basin]

Then it's an f×g situation

Nooo not necessarily xD

That's perfect

I only mean to suggest there's often many ways to frame the derivative

You could factor the 3 out

And do x*cosx

Then multiply 3 at the end

It's not necessarily better or worse

Just another way

[misty mist]

Like dis

[unique basin]

Yea good

So that entire thing is the "derivative of the inner function"

Finish the chain rule with that in mind

[misty mist]

I can't simplify it or anything, like don't touch it?

[unique basin]

Nah it's usually fine

Unless you need to do more than just find it

Most calc courses I've seen have a low threshold for simplifying

But each professor is different

Many times there's no neat way to simplify

[misty mist]

So then I get cos[(3x)(-sin x) + (cos x)(3)] and thats... like the final answer

[knotty elbow]

as long as you realise what you've shown us isn't the final answer

[misty mist]

o

[unique basin]

It would be

[misty mist]

howd they get this?

[knotty elbow]

forgotten a bit of the chain rule again

[unique basin]

Cos(original inner function)×[derivative of inner]

[knotty elbow]

yeah

[misty mist]

oh

[unique basin]

The first part always keeps the original inner function intact

The derivative you took is just multiplied to the side of that

[misty mist]

So then finally >

[unique basin]

Close the cos on the original g

[misty mist]

or -3x sin x is a different way to write it..

[misty mist]

wym

[unique basin]

Cos(3xcosx) × [product rule]

You're missing a bracket to properly close that cos at the front

You have it

Cos[(3xcosx)

[misty mist]

isnt it the original function times all of that other function?

[unique basin]

No

That part is outside

[misty mist]

yeah and I put the bracket at the end because they both need to be multiplied before cos right?

o

thats confusing

[unique basin]

It's cos(original)

Full stop

Start with that term

[misty mist]

cos(original) * derivation

[unique basin]

Yeaaa

[misty mist]

strange

[unique basin]

Just like that

[misty mist]

gotcha

[unique basin]

It's only weird now cause you didnt practice it enough

[knotty elbow]

chain rule is h(t(x)) = h'(t(x)) * t'(x)

[unique basin]

It's easy once you practice

[misty mist]

I learned all this in the past 2 days tbh

[knotty elbow]

yeah it make a lot of sense after it gets ingrained into your skull

[misty mist]

well I didnt know trigonometry at all

so I had to learn all that

and now I kinda get differentiation and stuff now

[unique basin]

Yea exactly once you do it more you'll think it's easy too

[misty mist]

I got a midterm tomorrow with integrals

[knotty elbow]

good practice drill is to do the 100 differentiations and 100 integrations

[misty mist]

so im like almost there

[unique basin]

You're doing chain rule after integration?

[knotty elbow]

lol

[misty mist]

naw im just really slow in math

im in calc 2 but i didnt know anything so I just caught up from basically beginner trig and now im up to differentiation

I think I can learn integrals before I sleep so I think I can get a good score

[unique basin]

Ohh i see well that takes a lot of work

Respect

[misty mist]

Eh its like a nother operation

[knotty elbow]

if you can do these kind of questions in your head you should be good to go

so good luck

[misty mist]

howd I get up to calc 2 with this knowledge whooo knows, but I hope its enough for the midterm xD

thank yous for all the help

👍

[knotty elbow]

close it

[misty mist]

.close

[marsh citrus]

Channel closed

Closed by @misty mist

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[left geyser]

Is it right or wrong ? please

[left geyser]

my teacher said thats yes but think no ?

[unique basin]

It's true

[wary kite]

why do you think no

also add a $\geq$

[elfin berry]

knief

[wary kite]

a can be zero

[unique basin]

Another way of saying it is

Sqrt(a^2) = | a |

[left geyser]

because

[fervent rampart]

(and the right is the standard definition of absolute value)

[unique basin]

Exactly

[wary kite]

-(-2) = 2

[unique basin]

2 is the negative of the original number in the root, -2

[wary kite]

a here is -2

since a<0 then it’s just -a which is -(-2) = 2

[unique basin]

This happened precisely because -2 < 0

[left geyser]

yes so why it didnt do -2 ?

[left geyser]

.

[wary kite]

^

[left geyser]

no its -2 not -(-2)

[wary kite]

brother

[unique basin]

Sqrt of a positive number is always positive by definition of the radical symbol

[wary kite]

look at your definition

[unique basin]

The radical symbol means "take the positive square root of the number"

Another way to think of that

[left geyser]

so when she mean -a, she mean that the minus (-) is out of the parenthèses ?*

[proud ice]

a is -2, so a<0, so -a is -(-2)

[left geyser]

like this -(a)

[left geyser]

okay thanks

realy

I ve exams tomorow

french teachers are bad ...

[unique basin]

Teachers can be bad anywhere

If that helps xD

[left geyser]

yeah but french system is ...

[tawdry rampart]

Use .close lol

[marsh citrus]

@left geyser Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[fiery valve]

( talking about b ) i understand that 2 theta - 60 = 45 is one solution, i do not understand how to get the other solutions or how to determine how many there are

[glacial knoll]

idk either

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fiery valve]

<@&286206848099549185>

[main idol]

repost your question correctly next time

[main idol]

because you deleted it

[fiery valve]

alr

.close

[marsh citrus]

Channel closed

Closed by @fiery valve

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gloomy salmon]

trying to understand
lim x->0 cosx = 1 (makes sense w unit circle), lim x->0 sinx is NOT = 1? lim x->0 sinx/x = 1 however?

[gloomy salmon]

wait that kind of makes sense bc if lim x->0 sinx = 1 then lim x->0 sinx/x = 1/0

which = 0

[dense hemlock]

squeeze theorem or something idk

no

1/0 isnt 0

[gloomy salmon]

undefined

[dense hemlock]

but limit isn't

look up a video of squeeze theorem

[tranquil mist]

I'm a little confused as to why you can justify the limit of cos(x) with the unit circle but not the sin(x). Isn't sin(x) just the height? Why shouldn't it go to 0?

[dense hemlock]

i honestly forgot how it works but that's why the limit is 0

[gloomy salmon]

yes me too

[dense hemlock]

it does

[tranquil mist]

I mean why do you think it should be 1?

[gloomy salmon]

when x = 0 sin is 1 or -1

on the unit circle

[tranquil mist]

No it isn't.

[gloomy salmon]

wat

[tranquil mist]

sin(0) is 0

[dense hemlock]

im tweaking

[gloomy salmon]

1 sec

[tranquil mist]

x is the angle

[gloomy salmon]

wat

oh

[tranquil mist]

The distance on the x axis is cos(x)

[gloomy salmon]

so to the right would be x = 0

[tranquil mist]

Yep.

[gloomy salmon]

so what would be straight up? lim x->...

pi/2?

[tranquil mist]

Yeah, a quarter turn.

[gloomy salmon]

so lim x->pi/2 sinx = 1

[tranquil mist]

That's correct.

[gloomy salmon]

so now it makes sense why lim x->0 sinx = 0

ok thanks :D

.close

[marsh citrus]

Channel closed

Closed by @gloomy salmon

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[charred abyss]

Hello

[charred abyss]

How do I show that $$ \frac{a}{a-1}= 1+ \frac{1}{a-1}$$ ?

[elfin berry]

aguirre27

[runic temple]

write 1 as (a-1)/(a-1)

this makes a common denominator

[charred abyss]

Right, start from the end

$$ \frac{a}{a-1}= 1+ \frac{1}{a-1}= \frac{a-1}{a-1} + \frac{1}{a-1} = \frac{a}{a-1}$$

[elfin berry]

aguirre27

[charred abyss]

That will do

.close

[marsh citrus]

Channel closed

Closed by @charred abyss

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tight pebble]

How many bit strings of length 10 containing at least 5
consecutive 0’s or at least 5 consecutive 1’s are there?

[broken magnet]

full disclosure i might not be the most qualified to answer this problem but i'll try anyway

my general strategy is to use PIE:
count number with at least 5 consecutive 0's
count number with at least 5 consecutive 1's
add them together, and subtract count where there are at least 5 consecutive 0's AND at least 5 consecutive 1's

Let's count the case with there are at least 5 consecutive 0's

At the top of my head, there are two ways to count it:

• Complementary Counting / Recursion
• Casework

[broken magnet]

What have you tried?

[marsh citrus]

@tight pebble Has your question been resolved?

[tight pebble]

I've tried focusing on solely the 0's. at least 5 consecutive would be equal to exactly 5 + exactly 6 + ... + exactly 10.
for exactly 5 you could have 2(2^4) + 3(2^3) different outcomes but i dont think this is the most efficient way to calculate it

I do agree that inclusion exclusion is a good idea

[broken magnet]

do you know recursion?

just wondering

[tight pebble]

I haven't tried putting the problem into code, i was hoping to get an equation to represent the problem

[broken magnet]

Yeah, recursion isn't just for code tho

Anyway recursion might be nasty

I think we can casework based on the "leftmost 0" of the chain

does that make sense?

[tight pebble]

im not sure im familiar with casework? do you mean just going through each scenario?

[broken magnet]

Yeah, like you did here

[tight pebble]

ok I think that is possible, since I got 2(2^4) + 3(2^3) for exactly 5 0's. My reasoning for this is that 2^4 is for both cases when the 0s are on the left or right edge of the string, leaving a 1 as a buffer and then the final 4 bits are 0s or 1s. 2^3 is for the 3 cases where the 0's are not in the center and need a 1 bit buffer on both ends, leaving 3 bits as 1s or 0s

If that makes sense

[broken magnet]

instead of exactly 5 + exactly 6 + ... + exactly 10, i think it might be better to casework on the where the left most digit of the consecutive zeros is

so instead we will do

00000...
100000...
_100000...
__100000...

does that make sense?

it's hard to explain what i mean

[tight pebble]

i think i understand, where _ can either be 0 or 1

[broken magnet]

yeah

so for 00000...

we can have any of the following

000001____
0000001___
00000001__
000000001_
0000000001

How many possibilities are there?

[tight pebble]

2^4+2^3+2^2+2^1+2^0?

[broken magnet]

Yep!

How about this case?

1000001___
10000001__

and so on

wait oops

the first digit must be 1

[tight pebble]

it would be 2^3+2^2+...+2^0?

so the pattern would just keep removing the highest power until the final case 0000000000 would just be 2^0

[broken magnet]

Well the next case would be

_100000___
_1000000__
_10000000_
_100000000

Each time, we are moving the 00000... one to the right

[tight pebble]

wouldnt the final case of 10 0s be missing?

[broken magnet]

you're right i'm sorry

000001____
0000001___
00000001__
000000001_
0000000001
0000000000

This should have been the first case

1000001___
10000001__
100000001_
1000000001
1000000000

this is the second case

_1000001__
_10000001_
_100000001
_100000000

this is the third case

instead of determining its length and then position,

we determine its position and then its length

[tight pebble]

i see, ty. I have to run for the night but if the chat doesnt close ill send my solution. thank you for your help, ive been stuck on this problem for a couple days!

[broken magnet]

alr before you leave

[broken magnet]

honestly now that i think about it this way might be easier

[tight pebble]

😆

[broken magnet]

sorry about that

2(2^4)+3(2^3) for length 5

[tight pebble]

all good! your way helped explain it for me

[broken magnet]

2(2^3)+3(2^2) for length 6

yeah and then

for the white ones

its symmetric

and then finally you subtract 2 for the cases where both are true

[tight pebble]

and then the overlap would just be 2: 1111100000 0000011111

yep!

thank you so much!

[broken magnet]

np!

[marsh citrus]

@tight pebble Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lyric laurel]

what can help me to select variation of parameters, reduction of order, or indeterminate coefficients to solve an ODE

[marsh citrus]

@lyric laurel Has your question been resolved?

[lyric laurel]

<@&286206848099549185>

.close

[marsh citrus]

Channel closed

Closed by @lyric laurel

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[buoyant cave]

help in iv

[glass silo]

How did you get the coordinates of C and D, from your diagram?

Anyways, you have the coordinates of A and B given to you, if you call the point C (-c, 0) and the point D (0, d), then...

[glass silo]

Ping

[marsh citrus]

@buoyant cave Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[buoyant cave]

sorry was afk

[buoyant cave]

is this correct

[glass silo]

Lemme read through it

[glass silo]

Careful, while OC is 16/3, remember that the point C has negative x coordinate, so C is the point (-16/3, 0) and so your denominator is 0 - (-16/3)

[buoyant cave]

oh

[glass silo]

(also notice that CD has positive gradient from the diagram too, so you should get a positive answer)

But if you fix that, I'm happy with the gradient +27/16

[buoyant cave]

so just the signs are incorrect right

[glass silo]

Yep the signs in certain places

[buoyant cave]

then the final eqn is just the same just pos

[glass silo]

Yep, y = +27x/16 + 9 it is

[buoyant cave]

alright! thanks so much !

[glass silo]

Have a good one

[buoyant cave]

.close

[marsh citrus]

Channel closed

Closed by @buoyant cave

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sand beacon]

Thank you in advance if someone gets it!

[mystic minnow]

Hint: Remainder theorem says when a polynomial p(x) is divided by x-a, the remainder is p(a).

[marsh citrus]

@sand beacon Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[swift bronze]

i keep getting this question wrong 😭

so for this i tried to get the derivative then found the derivative of that

i ended up with (y+2-y-2)/x^2

for double derivattive

[deep sequoia]

what's the first derivative

of RHS

[swift bronze]

(y+2)/x

[main idol]

Use product rule

And chain rule

[swift bronze]

wait chain rule?

[main idol]

Might be easier to see if you substitute y=f(x)

,tex .diff rules

[elfin berry]

riemann

[glass silo]

(you're forgetting some negatives, if you're claiming that this is dy/dx)

[swift bronze]

wait huhhhh

[main idol]

Do this

[swift bronze]

okay i got 2-(x dy/dx +y) for first derivative

[glass silo]

That's equal to 0

[swift bronze]

yeahh

and then i found the derivative of that

which is [x(dy/dx)-(y+2)]/x^2

right ? 😭

and then i just plugged dy/dx back in

[glass silo]

For the first derivative, you've claimed that $2 - \qty(x\dv{y}{x} + y) = 0$, which is correct - what is $\dv{y}{x}$ equal to from that?

[elfin berry]

@glass silo

[glass silo]

hint: not this

[swift bronze]

OHHH

oops

i forgot to distribute 💀

okay so derivative is (y-2)/-x

yea i think i get it now

thanks 🙏

[lethal bridge]

https://tenor.com/view/cat-kiss-alydn-gif-26454084

[glass silo]

https://tenor.com/view/tiktok-cat-silly-funny-goofy-gif-2522193369795121953

[lethal bridge]

https://tenor.com/view/hug-gif-13595007150059080982

[swift bronze]

https://tenor.com/view/cat-watermelon-eating-eats-eat-gif-25258999

[lethal bridge]

cstbittttttttttttttttttttttttttttttttttttttttttttttttttttttt

[marsh citrus]

@swift bronze Has your question been resolved?

Channel closed

Closed by @swift bronze

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fast bramble]

Is it Cl6?

If it isn’t 1/

[fervent rampart]

each little clump of atoms is a separate molecule

[deep sequoia]

you are aware that this is mathematics?

[main idol]

He is, he just doesn't care

[fast bramble]

So why isn’t it CL12

[main idol]

<@&268886789983436800>

[quaint elm]

.close

[marsh citrus]

Channel closed

Closed by @quaint elm

Use .reopen if this was a mistake.

[quaint elm]

go to the chem server

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fresh oyster]

we must find a 2x2 so that ker(T)=col(T)

[fresh oyster]

i think there is no such T, how could elements transformed to 0 even be a basis of the column space?

but the problem makes it sound like there must be one, so i need to know if im just being silly

[fervent rampart]

it is definitely possible

[fresh oyster]

okay, one sec

oh i see, so like nilpotent T

ty

.close

[marsh citrus]

Channel closed

Closed by @fresh oyster

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[naive stump]

$\int_{0}^{\frac{\pi}{2}} \frac{ \sqrt{cos(x)}}{1+cos^{2}(x) }dx$

[elfin berry]

Dootud

[naive stump]

scope highschool math, currently i have about not a lot (zero) ideas where to go with this

[orchid igloo]

take cosx as t squared.

differentiate and then resubstitute

change limits ofcourse.

[orchid igloo]

try the ones ive mentioned if u got no clue come over to dms.

[naive stump]

ive tried the sub u suggested already

it doesnt work out very nicely

[orchid igloo]

what happened.

[naive stump]

you yield $-\int_{0}^{1} \frac{2t^{2}}{(1+t^{2})(\sqrt{1-t^{6}})}dt$

[elfin berry]

Dootud

[orchid igloo]

well, my bad.

[naive stump]

no worries

[orchid igloo]

kings rule?

[naive stump]

so far ive tried:

application of symmetry for definite integrals (didnt work)
subs for u^{2} = cosx
u=-x

[orchid igloo]

ok but what if were going to assume cosx is some u

[naive stump]

by parts (100% a no)

[orchid igloo]

no differentiation of course

just letting it

and then letting u as some z squared

[naive stump]

this is no different to t^2 = cosx sub that was suggested earlier

i dont think subs like this will work for this integral

[orchid igloo]

try diving by cos square x

[naive stump]

whats the motivation behind that though

[orchid igloo]

ill try and lyk

[naive stump]

aight

[orchid igloo]

im not sure bout this one

were just letting

nvm

we still have to replace dx

oh wow

i was right

divide by cos squared x

@naive stump

[naive stump]

what does that do to the integrla tho

[orchid igloo]

wait no nvm.

[orchid igloo]

it wont change the limits.

just division

[naive stump]

yeah as in like

whats the goal after that

just gonna ping helpers as well

<@&286206848099549185>

[orchid igloo]

u can if it has been 15 mins

[naive stump]

$\int_{0}^{\frac{\pi}{2}} \frac{ \sqrt{cos(x)}}{1+cos^{2}(x) }dx$
(reposted for convenience)

[elfin berry]

Dootud

[naive stump]

is this another trig sub

[orchid igloo]

no clue.

[zinc tinsel]

so ugly

[orchid igloo]

i think ive kinda got it.

divide by cos squared x and then the denomiator would be sec squared x + 1 which is 2+ tan squared x

tan pie / 2 is ugly

[naive stump]

your numeratour is sitll (secx)^{3/2}

[orchid igloo]

3/2?

cos^2x inside the root becomes cos^4x

[naive stump]

did u not divide by cos^2{(x)

[orchid igloo]

cosx/cos power 4x is sec cube x

[naive stump]

u did ur algebra wong

*wrong

[orchid igloo]

wait 1 second.

why wouldnt it be power 4?

[orchid igloo]

no ur correct but u do get 1/(cos^3x)^1/2

even then

[naive stump]

which is (secx)^3/2

[orchid igloo]

i got the value inside the root.

[orchid igloo]

yes

correct.

finally

[naive stump]

which is what i said above

ur nuemrator is (secx)^3/2

[orchid igloo]

yes

my bad.

[naive stump]

all good

[orchid igloo]

so split it

sec^2x

and then sec^[-1/2]. x

oh nvm

@naive stump

split it as under root sec squared x and under root sec x

works right?

then divide and multiply by under root secx u shud end up taking another variable

[naive stump]

but like where are u going with this

[orchid igloo]

jus let me cook

[naive stump]

aight

[orchid igloo]

if its wrong its wrong i mean

u ride by the ship u die by it

anyway.

do that rn.

u shud end up here.

assume tanx as t

root secx would be root 1 + tan squared x

[orchid igloo]

tiny error.

uh u get root sec ^2 x into root sec^x into root sec^x

so the numerator would be sec^2x

[naive stump]

oh nvm solved it

[orchid igloo]

ok.

was i helpful?

[naive stump]

my sub ended up being let $cosx = tan(\frac{u}{2})$

[elfin berry]

Dootud

[naive stump]

i appreciated the help

[orchid igloo]

ok

[orchid igloo]

ok.

[naive stump]

.close

[marsh citrus]

Channel closed

Closed by @naive stump

Use .reopen if this was a mistake.

[orchid igloo]

u gotta use partial at the end by my method

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[raven sky]

can someone recommend me some good material to learn episilon - delta limits and stuff?

[raven sky]

im new to those and i dont understand anything :c

[cobalt yacht]

Probably something on YouTube

[sinful thistle]

blackpenredpen

top tier

[main idol]

just do example problems until you get stuck

[raven sky]

k , ty ❤️

ty all

.close

[marsh citrus]

Channel closed

Closed by @raven sky

Use .reopen if this was a mistake.

[sinful thistle]

nw

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[raven sky]

resuming my last question , do u have any good epsilon - delta questions?

[raven sky]

tho let them be easy ish , so i can do them

[crystal lintel]

what kind?

[sinful thistle]

like i said

blackpenredpen

he has like 15 videos on the topic

[raven sky]

reimann said it would be best if i solved them

[raven sky]

like starter type questions , new to them

[sinful thistle]

you can always pause the videos and try for yourself

[crystal lintel]

but like limits or something else?

[raven sky]

what are the use for epsilon delta limits?

is it just to proof the limit we found is correct or not?

[sinful thistle]

formal proofs of limits, yes

[raven sky]

ye , epsilon delta proof for limits

[crystal lintel]

uhh no not really

[raven sky]

then what are they used for?

will they be useful in future calculus?

[crystal lintel]

if that means analysis then sure

[raven sky]

different things?

[main idol]

https://en.wikipedia.org/wiki/Functional_analysis

go read

and go find problems

don't ask for them here

[raven sky]

ok

[main idol]

nobody knows what you know or don't know

[raven sky]

(i havent studied those , im just in calc 1 :c)

tho ty for the help , ill research furture

.close

[marsh citrus]

Channel closed

Closed by @raven sky

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[queen prairie]

,rotate

[queen prairie]

to rationalize them

I 3)

3 / cbrt 3

[sinful thistle]

hi you

[queen prairie]

hi

again

[sinful thistle]

3^(2/3)

or cbrt 9

[queen prairie]

i believe the third time today

[sinful thistle]

no, second?

[queen prairie]

second only?

[sinful thistle]

unless i'm going mad

yeah i think so

[queen prairie]

then it was yesterday also

[queen prairie]

thats a bit straight forward

i thought of putting it all to ^3

which will give directly

27 / 3

[sinful thistle]

and then simplify and cbrt

that's the same thing

[queen prairie]

yea

[queen prairie]

how did u get cbrt 9

[sinful thistle]

because you cubed it all

so you need to apply a cbrt to cancel it out

[queen prairie]

a yera

[sinful thistle]

is that a 9

[queen prairie]

looks like 9

i believe

[sinful thistle]

i guess

that's fairly easy i take it you know what it'll be

[queen prairie]

1^9/ 32 ?

[sinful thistle]

uhhhh

i guess?

[queen prairie]

i guess not

[sinful thistle]

or

[queen prairie]

or

?

[sinful thistle]

just see that

[elfin berry]

ren

[sinful thistle]

then simply negate the exp

[queen prairie]

how tho

[elfin berry]

ren

[queen prairie]

quotient rule i guess

we could take 1 as 2&0

2^0

[sinful thistle]

no...

[queen prairie]

..

[sinful thistle]

negative exponent

well yeah that's derived via quotient

but the one above that should be the first thing you think to apply

[sinful thistle]

actually just use this from now
lmk if you need any assistance tho

[queen prairie]

aight

aint it just 2^-(5/9) ?

[sinful thistle]

mhm

[queen prairie]

now for this one

we just multiply by msqrtm + n sqrt n

we get 2 formulas

one up one down

(m sqrtm + n sqrt n) ^ 2 / (msqrtm)^2 - (n sqrt n)^2

[sinful thistle]

mhm

simplify the bottom

and expand the top

[queen prairie]

aight

damn thats a long one

[sinful thistle]

not really but sure i guess

defo longer than the rest

[queen prairie]

(m^3 + 2mnsqrt(mn)+n^3 ) / (m^3 - n^3)

[sinful thistle]

uhhhhh
yeah checks out

[queen prairie]

this one is to calculate it

same shit ig

firsto ne we use sqrt 2 + 2

we get them like at the last one

the next one same thing

for the last one just sqrt 2

[sinful thistle]

mhm

[queen prairie]

for the first one

we get -3 - 2sqrt 2

[sinful thistle]

yeah

[queen prairie]

second one is 3 - 2 sqrt 2

[sinful thistle]

yeah

you can cancel the twos and add the sqrt 2 - terms btw

[queen prairie]

last one 2 + 3 sqrt 2

[queen prairie]

wym

[sinful thistle]

simplify -3 - 2 sqrt 2 + 3 - 2 sqrt 2 - (2 + 3 sqrt 2)

[queen prairie]

-2 + sqrt 2

[sinful thistle]

yeah!

wait no-

check again

the -2 is correct

@queen prairie u there my guy

[marsh citrus]

@queen prairie Has your question been resolved?

Channel closed

Closed by @queen prairie

Use .reopen if this was a mistake.

[queen prairie]

mb i went to take a shower

yea thx a lot

[sinful thistle]

LMAO

okay

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[marsh citrus]

Please don't occupy multiple help channels.

[humble river]

so sirry

Ok so

487 kj to J right

would be 4.87x10^5J/mol photons

but how do i find wavelength if im not given frequency (V)

[cold pecan]

.

[humble river]

sry i close

d

[cold pecan]

Nah

Previous one is now closed

All good

[runic temple]

what are the two equations that you do know

[humble river]

not the one in the middle

Oh

[still temple]

well you dont have v explicitly, but you can write v in terms of something else

[humble river]

i need to think harder...

[cold pecan]

Interconnect the given formulas whenever possible

[runic temple]

use the outer two

[humble river]

v can be something else?

[runic temple]

isolate v then plug into the other equation

[humble river]

OH

so v=c/wavelength

[runic temple]

so E=?

[humble river]

Oh

2 fractions in 1?

da heck

[runic temple]

uhh

what are you getting

[humble river]

Oh oh

i just realized

E= hc/wavelength

[runic temple]

boom

you dont need frequency

[humble river]

ohh

Wait

[runic temple]

but you can still solve for it if you want lol