#help-33

1 messages · Page 165 of 1

sleek lake
#

in this case it does make sense, that is basically how "if" works

#

but you don't need to understand that

#

so yeah

ripe glen
#

Thx👍

sleek lake
#

ok i see the problem

#

it's hard to see that "If Bob is at home, it's tuesday" can be true or false

#

it seems like it's some kind of third type of thing

#

like it can be a lie

#

but it can't be a "truth"

#

idk

#

so actually there's no difference between "If Bob is at home, it's tuesday" and "It's wednesday or thursday"

#

it's still a way to say what can't happen

#

so you check the same way, if it's true or false

#

"It's wednesday or thursday"
in reality it's thursday
not a lie!

#

"If Bob is at home, it's tuesday"
in reality bob is at work and it's wednesday

#

not a lie

ripe glen
#

I get it now

sleek lake
#

great

ripe glen
#

Thx

#

.close

marsh citrusBOT
#
Channel closed

Closed by @ripe glen

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

pallid agate
#

Would this question be a yes? because each person on each team has an equally random chance at getting picked?

marsh citrusBOT
#

@pallid agate Has your question been resolved?

trim quest
#

A simple random sample means you put all the people in one big pool, and select the sample at random

#

A stratified random sample means you divide the people into groups first, based on some criteria, and then choose some number from each group at random

pallid agate
#

So that would not satisfy a simple random sample

#

because its divided into smaller groups?

trim quest
#

Right, it's a stratified random sample

#

A simple random sample wouldn't guarantee that you get players from every team

pallid agate
#

ah ok

#

thank you

trim quest
#

no problem 👍

pallid agate
#

so justification would be that it is divided into smaller groups

#

with reason that a simple random sample wouldn't guarantee players from every team

#

would that ^ be a suffice answer?

trim quest
#

yeah that should be fine

pallid agate
#

ok thank you

trim quest
#

np 👍

pallid agate
#

.close

marsh citrusBOT
#
Channel closed

Closed by @pallid agate

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

pallid agate
#

is part c) correct?

marsh citrusBOT
#

@pallid agate Has your question been resolved?

pallid agate
#

.clsoe

#

.close

marsh citrusBOT
#
Channel closed

Closed by @pallid agate

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

gilded ember
marsh citrusBOT
gilded ember
#

where did this GPE come from

fervent rampart
#

anything with mass that is above the ground has gravitational potential energy

gilded ember
#

does KE not account for the GPE

fervent rampart
#

kinetic energy is separate from gravitational potential energy

gilded ember
#

ohh okay

#

so whenever its above the ground i have to add GPE to the final?

fervent rampart
#

you add GPE whenever it is off the ground, whether that is in the initial or the final state

marsh citrusBOT
#

@gilded ember Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

novel juniper
#

Prove that $\lim_{x\to 0} f(x) = \lim_{x\to a} f(x-a)$

elfin berryBOT
#

Veni, vidi, perii

novel juniper
#

So to start

#

the LHS means

#

$\forall \varepsilon>0 \exists \delta>0 st0< |x-0|<\delta \implies |f(x)-f(0)| \leq \varepsilon$

still temple
#

Something is missing

novel juniper
#

huh?

still temple
#

It should be 0 < |x-0| < delta

#

You forgot the 0< part

novel juniper
#

ah

elfin berryBOT
#

Veni, vidi, perii

novel juniper
#

and the RHS is

#

$\forall \epsilon >0 \exists \delta >0 st 0<|(x-a)-a| \implies |f(x-a)-f(0)| \leq \varepsilon$

elfin berryBOT
#

Veni, vidi, perii

novel juniper
#

which feels off

marsh citrusBOT
#

@novel juniper Has your question been resolved?

novel juniper
#

<@&286206848099549185>

torpid plover
#

what happened?

novel juniper
novel juniper
#

It feels off

rugged cobalt
#

you can assume the limit exists and put like L instead of f(0)

novel juniper
#

okie

rugged cobalt
#

and you want to show that L works for both

novel juniper
#

Yes

rugged cobalt
#

did you try anything so far

novel juniper
#

Writing both defns to see if that proves they're equivalent

novel juniper
torpid plover
#

it's no difficult, but I don't have the mathematical rigor to express it.

rugged cobalt
#

apart from some minor typos yea defn looks ifne

novel juniper
#

oops

#

yeah

#

made a few mistakes

#

$\forall \epsilon >0 \exists \delta >0 st 0<|(x-a)-a| \implies |f(x-a)-f(a)| \leq \varepsilon$

elfin berryBOT
#

Veni, vidi, perii

novel juniper
#

$\forall \varepsilon>0 \exists \delta>0 st0< |x-0|<\delta \implies |f(x)-f(0)| \leq \varepsilon$

elfin berryBOT
#

Veni, vidi, perii

novel juniper
#

are what I'm working with

#

I feel this is wrong

delicate prairie
#

tex tip, only wrap the math in dollars so that you can write english cleanly

novel juniper
#

👍

delicate prairie
#

$a$ or $b$

elfin berryBOT
#

RokettoJanpu

torpid plover
#

use sustitucion

novel juniper
#

I haven't proven that substitution works yet

delicate prairie
torpid plover
#

i see

novel juniper
#

so $2a-\delta <x<\delta +2a$

elfin berryBOT
#

Veni, vidi, perii

novel juniper
#

and $-\delta <x<\delta$

elfin berryBOT
#

Veni, vidi, perii

torpid plover
#

so i guess

novel juniper
#

so let $\varepsilon= min(\delta, \delta+2a)$

elfin berryBOT
#

Veni, vidi, perii

torpid plover
#

is something like that and using using triangular inequality

#

triangular inequality that key

novel juniper
#

maybe

#

Why didn't I think of that 😭

#

$\forall \epsilon >0 \exists \delta >0 st 0<|(x-a)| \implies |f(x-a)-f(0)| \leq \varepsilon$

#

wait

#

this should be the second defn , righ

torpid plover
#

like that

novel juniper
#

That's NOT the triangle inequality for subtraction

torpid plover
#

What is it like?

novel juniper
#

$||g(x)-|h(x)|| \geq |g(x)-h(x)|$

elfin berryBOT
#

Veni, vidi, perii

#

Veni, vidi, perii

novel juniper
#

Ok

#

so just to restate

#

these are my defn

#

$\forall \epsilon >0 \exists \delta >0 st 0<|x-a| \implies |f(x-a)-f(0)| \leq \varepsilon$

#

and

#

oops

elfin berryBOT
#

Veni, vidi, perii

novel juniper
#

$\forall \varepsilon>0 \exists \delta>0 st0< |x-0|<\delta \implies |f(x)-f(0)| \leq \varepsilon$

rugged cobalt
#

consider a translation function g(x)=f(x-a)

elfin berryBOT
#

Veni, vidi, perii

novel juniper
#

I mean sure, but is substitution allowed

torpid plover
#

i ment

torpid plover
rugged cobalt
#

no substituion i what you want to prove i think

#

that you can just write x-a and f(x-a) directly

#

if it works for x and f(x)

novel juniper
#

OK. Let's start from square one

#

$\forall \varepsilon>0 \exists \delta>0 st0< |x-0|<\delta \implies |f(x)-f(0)| \leq \varepsilon$

elfin berryBOT
#

Veni, vidi, perii

novel juniper
#

is the LHS defn

torpid plover
#

but never mind, that's not the point

novel juniper
#

$\forall \varepsilon>0 \exists \delta>0 st0< |x-a|<\delta \implies |f(x-a)-f(0)| \leq \varepsilon$

elfin berryBOT
#

Veni, vidi, perii

delicate prairie
novel juniper
#

That's literally what's given in spivak

delicate prairie
#

its an equation of limits, implicitly assuming beforehand that at least one exists

#

if one of $\lim_{x\to0}f(x)$ or $\lim_{x\to a}f(x-a)$ exists then the other exists, in which case they are equal

elfin berryBOT
#

RokettoJanpu

delicate prairie
#

its a bit more rigorous this way, and in fact it reflects a good strategy for proving equality

novel juniper
#

I don't folllow

delicate prairie
#

take cases

novel juniper
#

what do I have to prove

delicate prairie
#

take the case where the former exists, i.e. $\lim_{x\to0}f(x)=L$ for some $L$, then prove $\lim_{x\to a}f(x-a)=L$

elfin berryBOT
#

RokettoJanpu

delicate prairie
#

the case where the latter exists is handled similarly

delicate prairie
novel juniper
#

Yes

delicate prairie
#

we're writing an equation with limits on both sides. you dont know beforehand whether both limits exist, so the equation doesnt necessarily make sense

novel juniper
#

I get that

#

but how can I assume $\lim_{x\to0}f(x)=L$

elfin berryBOT
#

Veni, vidi, perii

delicate prairie
#

pay attention to my EXACT wording

#

if one of $\lim_{x\to0}f(x)$ or $\lim_{x\to a}f(x-a)$ exists then the other exists, in which case they are equal

elfin berryBOT
#

RokettoJanpu

delicate prairie
#

i said this is what we're really proving

novel juniper
#

What if neither exist

#

ah

#

Let $\lim_{x\to 0} f(x)=L$

elfin berryBOT
#

Veni, vidi, perii

delicate prairie
#

let .. for some L

#

better wording

#

actually i have the wording already

novel juniper
#

Let $\lim_{x\to 0} f(x)=L$ we now attempt to prove $\lim_{x\to a} f(x-a)=L$

elfin berryBOT
#

Veni, vidi, perii

novel juniper
#

so this being L implies

#

$\forall \varepsilon>0 \exists \delta>0 st0< |x-0|<\delta \implies |f(x)-L| \leq \varepsilon$

delicate prairie
#

f(0)?

elfin berryBOT
#

Veni, vidi, perii

novel juniper
#

Now on the right hand side we have

#

$\forall \varepsilon>0 \exists \delta>0 st0< |x-a|<\delta \implies |f(x-a)-L| \leq \varepsilon$

elfin berryBOT
#

Veni, vidi, perii

novel juniper
#

Not too sure how to proceed form here

delicate prairie
#

its a more abstract limit, so you need to think more logically than computationally

delicate prairie
delicate prairie
novel juniper
#

hmm, and no substitutions allowed

#

right

delicate prairie
#

to guide your logic, every epsilon delta proof should go like this

let eps>0
some string of arguments to find suitable delta
let x be such that 0<|x-..|<delta
some string of arguments to show |..-..|<eps

#

ill do the easy bits for you

#

let $\ep>0$

elfin berryBOT
#

RokettoJanpu

novel juniper
#

Hmm

#

okay

delicate prairie
#

since $\lim_{x\to 0} f(x)=L$, there exists $\delta>0$ such that $0<|x|<\delta$ implies $|f(x)-L|<\ep$

elfin berryBOT
#

RokettoJanpu

novel juniper
#

oh, wait

#

$-\delta <x<\delta$

elfin berryBOT
#

Veni, vidi, perii

novel juniper
#

so I have $-a-\delta <x-a<\delta-a$

elfin berryBOT
#

Veni, vidi, perii

novel juniper
#

let $\delta =a+1$

elfin berryBOT
#

Veni, vidi, perii

delicate prairie
#

i need to head out so ill leave some questions associated to epsilon delta proofs, especially abstract ones like this where we have assumed limits:

if im guaranteed a delta from an assumed limit, is that the right delta for another limit? turns out sometimes yes, sometimes no

should i apply an assumed limit directly to epsilon, or is it better to apply it to another positive function of epsilon (eps/2, eps^2 etc)? sometimes just epsilon is enough, sometimes you need a smarter choice

novel juniper
#

hmm

#

have a class now

delicate prairie
#

ill answer these for this problem for you

#

the delta i picked from the assumed limit will work for the limit we need to prove

#

and its enough to apply the assumed limit to just epsilon

#

there are no smart choices required here. you just need to think very logically through the proof structure

delicate prairie
#

and the proof is much simpler than you think. no clever inequality tricks needed. just decent logic

marsh citrusBOT
#

@novel juniper Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

pure current
marsh citrusBOT
pure current
#

For question 3

#

I got 11

#

Should be 7 thou but idk how

#

.close

marsh citrusBOT
#
Channel closed

Closed by @pure current

Use .reopen if this was a mistake.

calm harbor
#

2^2 + 3^2 = (2+3)^2
Just check this out to see if it’s correct

pure current
dreamy pollen
#

This will help

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

steady juniper
#

i want to use euler identity of split complex number but argument of hyperbola only defind in the blue area i wonder how can i write it in polar form

steady juniper
#

i try this but it only defind in the blue area

#

i try switch x and y term but its wrong if i do the power of 2

#

even tho 1+3j or anything outside the blue area exist but how can i even write it in polar form

steady juniper
thorny bison
steady juniper
#

it look like this in split complex number

thorny bison
#

catscream mb i can't answer this then

steady juniper
#

wait it should be hyperbolic sine i misspelling

#

im fk up rn

#

i think about it all day

marsh citrusBOT
#

@steady juniper Has your question been resolved?

marsh citrusBOT
#

@steady juniper Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

smoky widget
marsh citrusBOT
cunning oak
#

!status

marsh citrusBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
raw hawk
# smoky widget

Do you know sum of first n terms of an arithmetic progression

cunning oak
raw hawk
smoky widget
#

yes

#

a+(n-1)d

raw hawk
#

Next

#

You have a simultaneous equation

#

6=a

#

12=a+(5-1)d

#

Solve for common difference

smoky widget
#

i'll get 1.5

raw hawk
#

Correct

smoky widget
#

then?

raw hawk
#

Next
$S_n = \frac{n}{2} [a+a+(n-1)d]$

elfin berryBOT
raw hawk
#

In this case S_n =90

raw hawk
smoky widget
#

i'll get a quadratic equation

#

thanks alot brother

raw hawk
raw hawk
#

Note

#

The number of terms should be positive

smoky widget
#

ok

raw hawk
#

Type . close if you are done

smoky widget
#

.close

marsh citrusBOT
#
Channel closed

Closed by @smoky widget

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

smoky widget
#

Q3

marsh citrusBOT
smoky widget
glass silo
#

,rccw

elfin berryBOT
lucid turret
#

so

#

let a be the first erm

#

and common difference = d

#

I don't want to make this slow

smoky widget
#

Ok

lucid turret
#

first term = a
second term = a+d

smoky widget
#

Yeah

lucid turret
#

atq a(first term) = 5
a+d = 9
so d = 4

smoky widget
#

Yea

lucid turret
#

now let the last term be of the form a+nd = 5+4n = 4n + 4 + 1
Now equate 4+1+4n and 500
4n = 495
n = 123.75

now since n must be an integer
we need to add 1 to 500 to make 501
So 5+4n = 501
4n = 496
n = 124

#

substitute this value in 5+4n to find the term (the last one)

smoky widget
#

Tha ks alo

#

Thanks

#

Alot

#

.close

marsh citrusBOT
#
Channel closed

Closed by @smoky widget

Use .reopen if this was a mistake.

lucid turret
#

welcome

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

livid falcon
#

is it alright if someone could explain the process for this? im really confused

livid falcon
#

you can pick which ever question !!

lucid turret
#

ok

#

so 15.(a)

livid falcon
#

yup

worthy obsidian
#

X^4 = 16 it is asking which number when multiplied 4 times has its ans as 16 so to solve these kind of questions you should find all prime factors of 16

lucid turret
#

x^4 = 16
x^4 - 16 = 0
(x^2+4)(x^2-4) = 0
either x^2 + 4 = 0 or x^2 - 4 = 0
for x^2 + 4 = 0
x^2 = -4
x = -2i or 2i

For x^2 - 4 = 0
x = -2 or +2

livid falcon
livid falcon
#

wait whys it either negative or positive

worthy obsidian
worthy obsidian
livid falcon
#

it's real nice

worthy obsidian
#

-4 x -4 = +16

lucid turret
#

(-2)(-2) = 4

#

so (-2)^2 = (-1)^2 * 2^2 = 1 * 4 = 4
so this also satisfies

livid falcon
#

aight got it

#

i've written stuff down from this thanks a lot

#

.close

marsh citrusBOT
#
Channel closed

Closed by @livid falcon

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

velvet root
#

I’m so stuck on Part D, how do I do it? I can’t find any examples like this online

torpid plover
#

Are you still stuck?

#

@velvet root

velvet root
torpid plover
#

Ok, one sec

#

now you need to use it in the firs expression

#

this one

wooden bloom
#

hola, hablas español cierto?

torpid plover
#

replacing by dx

torpid plover
#

what happened?

wooden bloom
#

necesito ayuda con las funciones

#

tengo prueba y aun no las entiendo bien

#

funciones cuadraticas

velvet root
# torpid plover

wait so what did you find, that is that the integral of (1-4x^2)^2/3?

torpid plover
wooden bloom
#

tengo que analizar funciones y describirlas ? sin realizar los calculos, saber si tiene un maximo o un minimo, si pasa por el inicio o no, o cual es su vertice

torpid plover
#

i though that that was your confusion

torpid plover
wooden bloom
torpid plover
#

?

wooden bloom
torpid plover
#

pero te la dan graficada?

wooden bloom
#

tambien debo saber si crece o decrece

wooden bloom
torpid plover
#

No te puedo ayudar, porque no se que sabes y que no. Por lo que me decis estas medio en la nada. Yo te puedo responder una duda puntual. Pero explicarte todo no jajaaj

wooden bloom
#

me ayudas con las formulas del vertice y eje de simetria?

velvet root
#

So what is the way to solve this integral? You find the integral of the denominator first?

I don’t understand the steps

torpid plover
#

porque son funciones pares

wooden bloom
wooden bloom
#

como puedo saber donde estan las intersecciones con el eje x y el eje y en una funcion cuadratica?

wooden bloom
#

luego?

velvet root
#

Solve for x that will give you the intersecciones con el eje y

torpid plover
#

u understand the steps now?

velvet root
torpid plover
#

yes, everything in time, first it is important that you understand the steps.

#

is it clear to u?

velvet root
#

Like dx is on top why are you multiplying it with the denom

torpid plover
#

note that I subtract the powers by using properties

torpid plover
#

u can put it on top like a number, and is better couse if u are lazy and don't want to write 1 and then dx, just write dx on top

#

it doesn't matter, but smart people do it

#

an example

marsh citrusBOT
#

@velvet root Has your question been resolved?

velvet root
marsh citrusBOT
#
Channel closed

Closed by @velvet root

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

real lichen
marsh citrusBOT
proud portal
#

Rep

real lichen
#

Do I just use the points on red line with y is 2 and for blue y is 2

proud portal
#

Thanks @real lichen

#

There's no reps

real lichen
#

Huh?

proud portal
#

Thank you @real lichen

real lichen
#

I'm confused

valid cape
proud portal
#

Thanks @valid cape

#

Oh

#

Nvm sorry

#

Carry on

real lichen
valid cape
#

you are on the right track

real lichen
#

Red (2,2)

#

Blue 2,-2

#

Or

torpid plover
real lichen
#

Is it the 2nd point they have

valid cape
marsh citrusBOT
# torpid plover 0 is the answer

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

valid cape
#

generally when you add two functions, you add the y-value of each function at every x

real lichen
#

Ohh

valid cape
#

so when they are asking you (f + g)(2), it means "combine f + g into one function, then find the value of that function at x = 2"

real lichen
#

So it's like I draw a vertical line at 2

#

And every point there for each corresponding line

#

I would use that point

valid cape
#

yes

real lichen
#

And then I just add the x toghter and they y together

#

Or do I just add everything together

proud portal
#

So like what do u gain from helping others

proud portal
#

Oh shit sorry

valid cape
#

you do not add the x

real lichen
#

Ok

#

Just the y

#

Ok now 2nd question

#

Same thing but with 4

#

I do same thing as the first one?

#

Ok i got that one

#

Now it f - g(6)

valid cape
real lichen
#

Do I add the negative symbol to the term

#

Or

#

Nvm

#

Ik

#

Wait

#

So would it be -2-(-6)

real lichen
marsh citrusBOT
#

@real lichen Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

solid solstice
marsh citrusBOT
#

Please don't occupy multiple help channels.

gaunt gate
# solid solstice D

multiply both sides by 30, it should be easier to do the equation after this

gaunt gate
#

so will be left no fractions

solid solstice
#

oh

#

thx

gaunt gate
#

you're welcome

solid solstice
#

@gaunt gate do i put the x's at one side b4 multiplying or after

gaunt gate
#

you can multiply first

#

then isolate the x's

solid solstice
#

alright

#

If 3a + 2b = 7 and 2a + 3b = 13 , find a + b

#

how do u solve this

meager badger
#

System of equations

#

I’d use elimination method

solid solstice
meager badger
#

So we have this so far right and then I’m gonna choose a variable to cancel

solid solstice
#

ohh

#

alright

#

i rmbr it now

#

tysm

meager badger
#

👍

solid solstice
#

.close

marsh citrusBOT
#
Channel closed

Closed by @solid solstice

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

idle vessel
#

What does it mean by (A, B; C, D)?

marsh citrusBOT
#

Please don't occupy multiple help channels.

fervent rampart
#

they seem to be defining (A, B; C, D) to be the cross ratio of the points A, B, C, D

idle vessel
#

Is it because ; is a cdot with a comma 💀

fervent rampart
#

well the ; seems to sort them in to two distinct groupings of AB and CD

#

there seem to be a lot of different notations for this (wolfram mathworld has completely different notation), this is just the one that wikipedia went with

If a, b, c, and d are points in the extended complex plane C^*, their cross ratio, also called the cross-ratio (Courant and Robbins 1996, p. 172; Durell 1928, p. 73), anharmonic ratio, and anharmonic section (Casey 1888), is defined by [a,b,c,d]=((a-b)(c-d))/((a-d)(c-b)). (1) Here if a=d, the result is infinity, and if one of a, b, c, or d i...

marsh citrusBOT
#

@idle vessel Has your question been resolved?

#
Channel closed

Closed by @idle vessel

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

fringe thistle
#

i need assistance with polynomial functions

lucid bridge
#

!justask

fringe thistle
#

yes

lucid bridge
#

!da2a

marsh citrusBOT
#

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

glass silo
#

What exactly do you need help with? Do you have a literal question?

fringe thistle
#

i have some yes

#

an example being (4x²-8x-2):(2x-1)

#

mainly i want to understand both the subtractions and additions of the polynomial functions

main idol
fringe thistle
main idol
fringe thistle
#

now could you explain the multiplication and division of the polynomial function?

marsh citrusBOT
#

@fringe thistle Has your question been resolved?

#
Channel closed

Closed by @fringe thistle

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

still temple
#

Just wanted to check my answer

The curve C1 is given by the following equation

$$e^{xy} + \ln(y^2) + e^y = 1 + e$$

Determine the gradient at point (0, 1)

elfin berryBOT
#

Edmund Cloudsley

still temple
#

For this particular question, we would have to utilise implicit differntiation

#

$$\frac{d}{dx} e^{xy} + \frac{d}{dx} \ln (y^2) + \frac{d}{dx}e^y = 0$$
$$ = e^{xy} (xy)^\prime + \frac{2}{y} \frac{dy}{dx} + e^{y} \frac{dy}{dx} = 0$$
$$\frac{dy}{dx} = \frac{-ye^{xy}}{\frac{2}{y} + xe^{xy} + e^y}$$

#

and if we substitute the mentioned value of x and y

#

we should get

#

$$\frac{dy}{dx} = -1/(2+e)$$

elfin berryBOT
#

Edmund Cloudsley

still temple
#

I am unsure if the implicit differentiation of $e^{xy}$ is correct in my case

elfin berryBOT
#

Edmund Cloudsley

still temple
#

and let's say if I have somethign like the derivative of $\tan(xy)$

would it be:

$$(xy)^\prime \sec^2{xy}$$

elfin berryBOT
#

Edmund Cloudsley

#

Edmund Cloudsley

gilded cedar
still temple
sharp vessel
#

You need the partial derivatives for the gradient, do you not?

gilded cedar
still temple
sharp vessel
#

Idk maybe I'm wrong

still temple
still temple
#

partial derivative is the same as total derivative here as there is only one variable

still temple
#

I will look into partial derivatives

#

I remember doing them 2 months ago for something else not related to maths 😓

#

and I don't remember a thing

#

thanks anyways guys

#

.close

marsh citrusBOT
#
Channel closed

Closed by @small nymph

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dusty stump
marsh citrusBOT
dusty stump
#

Cant figure out where I keep on going wrong

stoic slate
#

!show

marsh citrusBOT
#

Show your work, and if possible, explain where you are stuck.

meager badger
#

U need long division

dusty stump
#

thanks

#

.close

marsh citrusBOT
#
Channel closed

Closed by @dusty stump

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

final badger
#

can yall explain how to do sine/cosine rule i watched yotube videos i still dont understand

glossy flint
#

What does sine rule tell?

glossy flint
#

Usually you'd better label all sides and angles, unless you are savvy with the topic

limber hearth
#

Oh it was on two channel

marsh citrusBOT
#

@final badger Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

neon adder
#

is there a more efficient way of solving this problem?

paper raptor
#

Yes, generating functions:

$G(x)=G_X(x)*G_Y(x)=(2x+x^2+x^3+x^4+x^5)(x^2+x^3+x^4+x^5+2x^6)$

elfin berryBOT
#

PajamaMamaLlama

paper raptor
#

,w (2x+x^2+x^3+x^4+x^5)(x^2+x^3+x^4+x^5+2x^6)

paper raptor
#

2x^11+3x^10 (11,10 are higher than 9), sum the coefficients to get 5

#

or 5/36 odds to get a combination higher than 9

marsh citrusBOT
#

@neon adder Has your question been resolved?

#
Channel closed

Closed by @neon adder

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

vernal granite
#

Hi, I have to proof that the sequence {a_n}, where a_n is that summatory Σ 1/k^3 is a cauchy sequence, I did this, but I arrive at point where I don't know what to do :(

vernal granite
#

!status

marsh citrusBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
vernal granite
#

2

marsh citrusBOT
#

@vernal granite Has your question been resolved?

vernal granite
#

<@&286206848099549185>

marsh citrusBOT
#

@vernal granite Has your question been resolved?

main idol
#

from here, did you learn that $\sum_{k=1}^{\y} \frac{1}{k^2} = \frac{\pi^2}{6}$?

elfin berryBOT
#

riemann

vernal granite
#

eeh nop :(

main idol
#

what about just the convergence of the left side?

#

using p-test or integral test

vernal granite
#

oh so this exercise needs theory of integrals

#

thank you <3

#

.close

marsh citrusBOT
#
Channel closed

Closed by @vernal granite

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cobalt swan
#

does anyone know where I went wrong? The answer is -2 but I put 2 because of the boundary change ( 0 to 1 ).

cobalt swan
digital robin
#

is this given there ∫35sin⁴(x)cos²(x)dx

#

or is that a 3

cobalt swan
#

3 sorry for my handwriting

main idol
#

,w 35 * int pi/2 to pi sin^4(x) * cos^3(x) dx

main idol
#

-2 was right, not sure why you changed it to 2

cobalt swan
#

i put it on 2 because i have the boundary from 0 to 1 because i wanted to stay on u instead of going back to sin x

#

and when it’s from small to big or something you swap the sign

#

if i remember properly 😭

main idol
#

and when it’s from small to big or something you swap the sign
this is not a rule

#

$[7 (0) - 5 (0)] - [7 (1) - 5(1)] = 0 - (2) = -2$

elfin berryBOT
#

riemann

cobalt swan
#

my life is a lie 😭

main idol
#

that's it, no other "small to big swap the sign" business needed

cobalt swan
#

i swear that was a thing in calc 1

#

let me go cry 😭

#

but tysm!

fervent rampart
#

we have it that [ \int_1^0 f(x) \odif x = -\int_0^1 f(x) \odif x ] but that's the same as saying [ F(0) - F(1) = -[F(1) - F(0)] ]

elfin berryBOT
marsh citrusBOT
#

@cobalt swan Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

marsh citrusBOT
static quarry
#

define critical point, to start with

lilac siren
#

extrema? roots? ...?

iron orbit
#

sorry my friend replied to me and helped me but thank you guys @static quarry @lilac siren

marsh citrusBOT
#
Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

glass crest
#

I just started limits in AP Calc AB and I have no idea how to solve this problem: lim x-> pi/4 (2cos^2x-1)/(cosx-sinx)

glass crest
#

So I know that 2cos^2x-1 = cos2x

#

So I'm guessing I get lim x-> pi/4 (cos2x/(cosx-sinx) but what happens then or am I going in the wrong direction?

dry prawn
#

sure that works

#

do you know of another identity that also gets you cos2x?

glass crest
#

I know there are 3 but in this case I would guess you use the cos^2x-sin^2x

dry prawn
#

that's a good guess

#

you want cos^2x-sin^2x, and in the denominator you have cosx-sinx... perhaps there's something there

wraith sun
glass crest
#

So now I just cancel the square to get lim x -> pi/4 cosx-sinx

dry prawn
#

no you certainly do not

glass crest
#

wait you don't

dry prawn
#

that would be implying cos^2x-sin^2x = (cosx-sinx)^2

wraith sun
#

Cancel correctly 😅

glass crest
#

cosx+sinx

marsh citrusBOT
#

@glass crest Has your question been resolved?

#
Channel closed

Closed by @glass crest

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

hearty wasp
#

how do i find the line on this graph

marsh citrusBOT
paper raptor
#

intercept-intercept form

#

$\frac{x}{a}+\frac{y}{b}=1$ where $a$ is the x intercept and $b$ is the y intercept

elfin berryBOT
#

PajamaMamaLlama

paper raptor
#

$y=-\frac{b}{a}(x-a)$

elfin berryBOT
#

PajamaMamaLlama

hearty wasp
#

i already got 2/1

paper raptor
#

where does the line touch the x-axis?

hearty wasp
#

1

paper raptor
#

and the y-axis?

hearty wasp
#

2

paper raptor
#

therefore b=2, and a=1

#

above the formula for the line given two intercepts :)

#

done

hearty wasp
#

so i this case it will be 2/1 x-1

paper raptor
#

parentheses are important

#

so are negative signs

#

you need to distribute the -2 to both the x and the -1

hearty wasp
#

im sorry but where did the negative 2 and -1 come from?

#

.close

marsh citrusBOT
#
Channel closed

Closed by @hearty wasp

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

strange fable
#

I need help with a show that question

marsh citrusBOT
strange fable
#

Question 2

#

i’ll get the original in a sec

dire mirage
#

How many T would you expect at equilibrium if you repeated the experiment, starting with 1000
H and 0 T and using a probability of 99.9% that a collision turns H into T? I am really confused is this like a trick question.

#

heads and tails

strange fable
#

can u delete ur question and post in a new thread plz

#

.close

marsh citrusBOT
#
Channel closed

Closed by @strange fable

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

zenith lily
#

c

marsh citrusBOT
#

Please don't occupy multiple help channels.

austere glacier
#

Hello

zenith lily
#

hello i asked this earlier, but incorrectly

austere glacier
#

Oh I was just saying hellosully

zenith lily
#

oh hello lol

pallid tapir
zenith lily
#

I just realized it cropped incorrectly. If an and b are real numbers. Then if a^2 + ab + b^2 >=0

pallid tapir
#

and we're using trig to do it?

zenith lily
#

Yeah just trying. I have other proofs

pallid tapir
#

what you have is chicken scratch so it isn't a proof, but there may be something there

zenith lily
#

Oh yeah it’s scratchwork lol my bad. I’m wondering if showing this relationship is correct though

pallid tapir
#

you want to argue that for this arbitrary a,b pair, there is an angle x for which you can do this representation

#

but what concerns me is that it isn't true if a=b=0 so you need a separate case

zenith lily
#

Yes

pallid tapir
#

sorry, you need to address that particular case separately

#

so we must assume at least one of a,b are nonzero

zenith lily
#

Okay, so because

#

This relationship idea doesn’t work to satisfy sin theta = cos theta = 0

#

Correct? Like there’s not a theta to satisfy this

pallid tapir
#

yeah like, to me you're constructing a circle of radius sqrt(a^2+b^2)

#

that's radius 0 if a=b=0

zenith lily
#

Ah okay. Are we “allowed to say”
A=b=0 then a^2+ab+b^2 >= 0
Which satisfies what we need to prove.

And say for like “in the case that an and b are both non zero” and use this proof ?

pallid tapir
#

no, not both nonzero

#

I will return shortly brb

zenith lily
#

Okay, the reason I said nonzero is because I saw cases such as a=0 and b≠0
Or
a≠0 and b=0 as quick cases that simplify to a^2 >= 0 and b^2 >= 0 respectively

#

So case 3 would be
a and b are both non zero and then go onto the trigonometric proof

pallid tapir
#

the trig argument still works as long as at least one of a or b are nonzero

zenith lily
#

Okay that’s cool (just exploring if these ideas are “valid”)

#

Thank you mate

pallid tapir
#

well it isn't exactly valid in my opinion because you still have to assume you have a rigorous construction of trig functions

zenith lily
#

Oh okay

pallid tapir
#

we're assuming that you're asked to prove this inequality in an introductory real analysis course where you're only given that the real numbers is a field with an ordering

zenith lily
#

Nah. It’s just an intro to discrete math class. This is the question from the first day of class a week ago

pallid tapir
#

they're still introductory so ok

#

it's cute to invoke trig functions but not rigorous enough because you're just invoking a higher power

zenith lily
#

The prof really liked a proof with inflection points. I think the prof is just trying to get people’s brains turning , yk?

pallid tapir
#

yeah

#

it's good that you're thinking about this stuff, people like creative proofs

zenith lily
#

I’m not in the class , it’s my friend who is. I completed the course but we just been having fun talking about different proofs for it

pallid tapir
#

oh word

zenith lily
#

im on a gap semester currently. Im really liking math but want to be a software engineer for the money

#

I completed the course during the month of June. (Accelerated summer class) and I feel like I didn’t get to have the full experience because of it. And that I’m probably worse at proof writing than others who completed it at a normal pace

#

I’m thinking of just starting real analysis though (I kinda already did) like last week
With understanding analysis although I’d like to go through 2 books concurrently

pallid tapir
#

so in constructing a circle of radius $r=\sqrt{a^2+b^2}>0$, we identify that there is some angle $\theta\in[0,2\pi)$ for which $r\cos\theta=a$ and $c\sin\theta=b$, and we argue that $$a^2+b^2+ab\geq 0\ \ \ \iff\ \ \ \frac{1}{c^2}\left(\cos^2\theta+\sin^2\theta+\sin\theta\cos\theta\right)\geq 0$$

elfin berryBOT
pallid tapir
#

the rightmost component of the iff is equivalent to dropping the 1/c^2 because it's positive

zenith lily
#

Shi looks so clean like this

#

Tryna get like you

pallid tapir
zenith lily
#

Yeah fosho. Need to get through understanding analysis

#

I’d like to get through the book and partially a second book before my analysis course starts next semester

pallid tapir
#

self-study is hard, so you'd probably benefit from making a schedule for it, and a study group or some other incentive for reading and doing exercises

#

make your own due dates for responses to book exercises or problems, or give your friends a lecture on what you worked on

#

the friends should hopefully be willing to hear you lol

#

choose people who encourage you

zenith lily
#

Noted, me and my roomate are trying to learn from different sources and have a white board to write down interesting problems .
He’s using Spivak and tao analysis

I’m using understanding analysis and to be determined

#

Love the idea of hard, I think of math as an intellectual navy seal training boot camp for my brain

pallid tapir
#

sounds fun

zenith lily
#

Even if they do not correlate directly. I think a degree in math will benefit “everything” cognitively
Plus I like math 😎

#

Haha

pallid tapir
#

some treatments of real analysis feature a careful and frankly long-winded construction of the real numbers (in two ways) from the peano axioms

zenith lily
#

I have read this (as in, I am on the screen activity waiting for messages to let you know I’m here)

pallid tapir
#

lots of equivalence classes to rise from one number system to another

zenith lily
#

I remember what equivalence classes are, but I know I’m not amazing on the topic right now

pallid tapir
#

other treatments assume we're already at the finish line and that we have the real numbers, which is a totally-ordered field

#

an equivalence class is a formal lumping-together of things that are considered equivalent to some element under some (equivalence) relation

#

every equivalence relation begets a partitioning of your set (the equivalence classes are what makes the partitioning), and every partitioning of your set begets an equivalence relation

#

they can be very pretty

zenith lily
#

Googling begets

#

Okay context clues definition of begets ≈google’s definition

pallid tapir
#

this is good

zenith lily
#

Al this is mentally noted and screenshotted , thank you

pallid tapir
#

sure thing

#

also in case you don't know latex already, you should experiment with it

#

I used it for every college assignment I had once I learned the basics

#

so you should consider using latex to write up your proofs, just to give yourself non-obvious editorial and presentation problems to solve lol

#

super super helpful

#

for example I took a graph theory course and used it as an excuse to learn tikz, a latex package for creating graphs and other wacky pictures

#

it's very important to learn latex especially if you want to write papers, because a lot of journals don't even accept papers written in other editors

#

and also because it of course makes for nice presentations

marsh citrusBOT
#

@zenith lily Has your question been resolved?

zenith lily
#

.close

marsh citrusBOT
#
Channel closed

Closed by @zenith lily

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

still temple
#

I just had a question on the bi nominal

marsh citrusBOT
still temple
#

I wanted to know what the difference it when it asks me to find the sum/difference and when it asks me to find the product?

#

Sorry if that questions a lil dumb

terse relic
#

the sum/difference is just adding the polynomials, the product is multiplying them
i.e. the sum/difference uses the process you have there, the product uses FOIL

without variables, 2 + 3 = 5, 2 x 3 = 6
with variables, its (2x^2 + 5) + (3x^2 + 3) = 5x^2 + 8, (2x^2 + 5)(3x^2 + 3) = 5x^4 + 21x^2 + 15

still temple
#

What is FOIL? Is that a math acronym?

pallid tapir
elfin berryBOT
pallid tapir
#

ac is the product of the 'first' terms, ad the product of the 'outer' terms, bc the product of the 'inner' terms, and bd the product of the 'last' terms

#

you never need to remember this acronym if you understand it's nothing more than distribution done twice

still temple
#

Thank you!

#

I also wanted to know if anyone could check my math

#

For 13, 19 and 21 if that’s okay

#

I have assignment regarding the solve the equation in full formula and full explanation and the title is translations

pallid tapir
still temple
#

Thank you! I really appreciate the help from everyone!!

pallid tapir
# still temple

19 in particular has a shortcut: $$(6b^2-6)(4b^2-4)=6(b^2-1)4(b^2-1)=(6\cdot 4)(b^2-1)^2$$

elfin berryBOT
still temple
#

Oh wow thank you!

#

I had no idea I could do it that way

#

I’ll write that down too

#

I appreciate the shortcut and explanation, I’ll use it for class tomorrow 😼 I hope u guys have a good night!

#

.close

marsh citrusBOT
#
Channel closed

Closed by @weary berry

Use .reopen if this was a mistake.

still temple
#

. reopen

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

outer ravine
#

Find me two numbers such that when they are added together, they make as much as the cube of the lesser added to the product of its triple with the square of the greater; and the cube of the greater added to its triple times the square of the lesser makes 64
more than the sum of these two numbers.

marsh citrusBOT
#

@outer ravine Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

honest topaz
marsh citrusBOT
honest topaz
#

I'm trying to show that this is a tautology without using truth tables

#

But I get stuck

#

when using logical equivalencies

devout mauve
#

use the distributive property

honest topaz
#

like i thought you needed 3 seperate variables

#

not p counts as one?

slate yarrow
honest topaz
#

Does this look good?

slate yarrow
#

yeah

#

it is true

honest topaz
#

.close

marsh citrusBOT
#
Channel closed

Closed by @honest topaz

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

honest topaz
marsh citrusBOT
honest topaz
#

Using logical equivalencies, how would I proceed?

pallid tapir
#

distribution maybe?

#

$(x\land y)\lor z\equiv (x\lor z)\land (y\lor z)$

elfin berryBOT
honest topaz
#

like what do i look for

pallid tapir
#

to attack the $(p\land\neg q)\lor(q\land\neg r)$

elfin berryBOT
pallid tapir
#

maybe it brings joy, idk

honest topaz
#

so i would treat (p and not q) as p and distribute it to (q and not r)?

pallid tapir
#

that is how that'd work yeah

#

it's at least something to do lol

honest topaz
#

Great

#

now i have even more gibberish

#

do i have to distribute again

#

and twice

pallid tapir
#

it looks like there's a little more joy from that yeah

honest topaz
#

no joy to be found

pallid tapir
#

you find a -q or q, which is nice

honest topaz
#

only suffering

#

be back in 3 mins

pallid tapir
#

best of luck

honest topaz
honest topaz
#

that i can distribute again

pallid tapir
#

well you can

#

you'll find another tautology in (-p or r or -r or p)

honest topaz
#

?

#

i dont see it

#

am i even doing this correctly

#

like i dont see what to do next

#

<@&286206848099549185>

#

.close

marsh citrusBOT
#
Channel closed

Closed by @honest topaz

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lyric kelp
#

for gaussian

marsh citrusBOT
lyric kelp
#

.close

marsh citrusBOT
#
Channel closed

Closed by @lyric kelp

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

unique timber
#

hey guys wanna join a minecraft server pls dm me

open seal
#

this is not math

still temple
#

let's talk about the maths behind procedural generation

cobalt sedge
#

L fractal noises

marsh citrusBOT
#

@unique timber Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

restive ledge
marsh citrusBOT
night mica
#

$ln 5x= lnx+ln4x$ can you go on?

elfin berryBOT
restive ledge
#

I I think you made a mistake

night mica
#

could be

restive ledge
#

lnx + ln5 ?

#

ln(ab) = lna + lnb

night mica
#

ohh right

restive ledge
#

I did that and got an integral with lnx in denominator

#

let me show

#

Wrong pic

#

I tried lnx = u but it didn't help

#

I also tried graphing to see if I could gain something

still temple
#

you sure it is not sine?

restive ledge
#

yeah pretty sure

#

,w integrate log(5x)/log(x) from 0 to pi

still temple
#

then the question is simply wrong, because it does not exist

restive ledge
grave dove
#

no matter what you do, you wouldnt be able to find the antiderivative of that function, cuz it has ln(x) in the denominator

#

this is called a non-elementary integral

grave dove
#

and you are integrating from 0 to π

#

including x=1

#

boom!

restive ledge
grave dove
#

still

restive ledge
#

So the question is wrong

#

thanks

#

I'll be able to sleep peacfully

grave dove
#

yeah, most likely

#

i tried an online integral calculator and it failed

restive ledge
still temple
# restive ledge

it seems like someone haphazardly remove the s from sin though

restive ledge
#

Oh yeah it does look like sin without s

#

😅

grave dove
#

lol plot twist

restive ledge
#

Then it'll be easy I think

#

expand sin(5x) by the sum formula

#

thanks again

#

I'm gonna close this

#

.close

marsh citrusBOT
#
Channel closed

Closed by @restive ledge

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

restive venture
#

idk how to interpret this situation and fit it into the formula

restive venture
#

like is only 2 ft of water moving up?

marsh citrusBOT
#

@restive venture Has your question been resolved?

restive venture
#

<@&286206848099549185>

marsh citrusBOT
#

@restive venture Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

vernal granite
#

Let {a_n} be a sequence of non-zero real numbers such that (image), Proof that a_n converge to zero. I don't know how to solve it, I tried using the definition of converge, |a_n+1/a_n - L | < e
-e < a_n+1/a_n - L < e
L - e/a_n+1 < a_n < L + e/ a_n+1, but doesn't feel that it help me with something :c

vernal granite
#

!status

marsh citrusBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
vernal granite
#

1

marsh citrusBOT
#

@vernal granite Has your question been resolved?

vernal granite
#

<@&286206848099549185>

glass silo
#

Have you happened to cover series, by any chance? pikathink

marsh citrusBOT
#

@vernal granite Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

past hamlet
#

can anyone help me with this

marsh citrusBOT
wraith cobalt
#

Have you done anything so far?

past hamlet
#

nah Im confused 😭

wraith cobalt
#

Generally if you have a fraction and something added together, and you want to express it as a single fraction

#

a good start is to write both things with a common denominator

#

since then you can add the two into one fraction

#

in this case, you could write 4x with the same denominator as x/(1-x) by multiplying and dividing it (which is ok because those two things cancel out) by (1-x)

marsh citrusBOT
#

@past hamlet Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

marsh citrusBOT
static quarry
#

pls at least use brackets so we can tell what is grouped with what

#

do you have a screenshot or a photo, you could just paste that

#

ok

#

well first thing i notice is that 7 x 3 is not 27

#

oh i see

#

it's fine, i'll read it as 21

#

lemme see if there are other issues

#

your answer is right, the key is wrong

marsh citrusBOT
#
Channel closed

Closed by @nocturne phoenix

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

mighty barn
#

I don't understand what I'm doing wrong. I multiplied the top one by 2 and the bottom one by 5 and found 4/5 for k but shouldn't h NOT be 5/4? why is it not working?

lucid zenith
#

I think you mean h should not be equal to 5/2

mighty barn
#

that worked but HOW

#

ohhhhhhhhh

#

wait ok i get it thank you so much

#

i had messed up

#

.close

marsh citrusBOT
#
Channel closed

Closed by @mighty barn

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

opal vector
#

hi, im stuck trying to fin sin(t)

marsh citrusBOT
dreamy pollen
opal vector
#

i think im messing up when squaring cos

dreamy pollen
#

tan(t) = sin(t) / cos(t) isn't it?

opal vector
#

yeah

#

let me try doin that

#

.close

marsh citrusBOT
#
Channel closed

Closed by @opal vector

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lean zodiac
marsh citrusBOT
lean zodiac
#

a discontinuity like this is not removable right

night lion
wraith sun
#

It is removable

lean zodiac
#

oh

#

thanks

#

.close

marsh citrusBOT
#
Channel closed

Closed by @lean zodiac

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.