we just call it base
#help-33
novel ice
still temple
I can tell by your questions
novel ice
T-T
novel ice
WAIT
novel ice
so, you don't chop it into a square? just in HALF
still temple
who's area can be easily calculated
jesus christ why square
please tell me why you want a square
still temple
thank you but how is the other rectangle a square đ
novel ice
...it looks like a square
novel ice
novel ice
WAIT
novel ice
yes
still temple
thank you
novel ice
but where would that go?
still temple
finally
novel ice
like which side?
still temple
9*7 is the area of the required rectangle
novel ice
is 7 top or bottom or side?
novel ice
I think so
still temple
god yall have awful terms
novel ice
I think it's breadthing in my brain
novel ice
T-T
still temple
18-11 = 7
novel ice
Americans are obsessed with that here
still temple
get it now?
still temple
Americans are obsessed with that here
clearly
novel ice
interesting
novel ice
WAIT
I THINK I UNDERSTAND, since the blue line equals the whole area of that section
if it's in two rectangles then it's in half
so both of those are 7
still temple
blue LINE IS NOT THE AREA kid
still temple
blue line is 7
novel ice
so the answer is 315?
novel ice
no
still temple
so the answer is 315?
yes
novel ice
interesting
still temple
so easy
marsh citrusBOT
Available help channel!
vapid iris
Is this right? This is integral using u substitution.
marsh citrusBOT
Is this right? This is integral using u substitution.
glossy flint
The du is wrong
vapid iris
The -cos(2x) dx
vapid iris
The integral of sin u is -cos u
glossy flint
The integral of sin u is -cos u
This is correct
vapid iris
Yes
light wharf
how do i find the intercepts of the black and purple lines
vapid iris
Honestly idk , differentiate?
glossy flint
how do i find the intercepts of the black and purple lines
!occupied
marsh citrusBOT
how do i find the intercepts of the black and purple lines
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #âhow-to-get-help for instructions).
glossy flint
Honestly idk , differentiate?
Yeah to find du you have to differentiate
vapid iris
Yeah to find du you have to differentiate
Sir?
glossy flint
Is the final answer is 1/4 (u)^2 + C ?
Nope
The numerator is just du/2
The denominator is u
vapid iris
Oh yea fraction
vapid iris
Also because *du* can't appear in the answer
So will replace the du by its value on numerator?
vapid iris
Also because *du* can't appear in the answer
Is it Ln | u |
Because Du/u is Ln | u |
Thank you sir!
.close
marsh citrusBOT
spark siren
marsh citrusBOT
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jaunty obsidian
marsh citrusBOT
jaunty obsidian
I understand why we have to expand the bracket
to like compare
but like
the rest i dont really understand
why we just use -45? not the b or 4
cobalt sedge
among the 4 options, you have nothing that needs comparison with coefficient 4 to check
And for coeff b, it could be any number, you have no restriction on b, so you cant comment on it to be true or false beyond doubt
jaunty obsidian
among the 4 options, you have nothing that needs comparison with coefficient 4 t...
4 options?
cobalt sedge
A, B, C, D
jaunty obsidian
isnt its just 3?
cobalt sedge
its multiple choice question and you have to choose answers from amongst them
jaunty obsidian
oh thats what u mean
cobalt sedge
those multiple choices A B C D are what I mean
jaunty obsidian
among the 4 options, you have nothing that needs comparison with coefficient 4 t...
wym "nothing that needs comparison with coeeficent 4"
cobalt sedge
coeff 4 compares directly to h, so you can say h = 4, but no one asked about it so we dont care
jaunty obsidian
coeff 4 compares directly to h, so you can say h = 4, but no one asked about it ...
ohh okay
jaunty obsidian
And for coeff b, it could be any number, you have no restriction on b, so you ca...
so this question is -45 because kj = -45 can be rearrange?
frigid lance
As long as the vector is in R^m
jagged relic
No, it means any of the four statements imply the other three
marsh citrusBOT
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unique yarrow
marsh citrusBOT
severe owl
!xy
marsh citrusBOT
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
severe owl
With the given info I am unable to do it. Sorry maybe someone else can help you.
marsh citrusBOT
@unique yarrow Has your question been resolved?
lunar jungle
wooden grotto
Does my solution to this problem:
marsh citrusBOT
Does my solution to this problem:
wooden grotto
check out?
severe owl
Idk the method but what all steps you've done seem correct
marsh citrusBOT
@wooden grotto Has your question been resolved?
molten ferry
how to do second question
marsh citrusBOT
how to do second question
woeful violet
do u have any guesses
molten ferry
do u have any guesses
no
woeful violet
okay
molten ferry
you have that the tail of Y is the tip of X
ye
woeful violet
so if you move in the direction of Y from the tip of X, then you'll eventually land at the midpoint
but how far would you have to move from the tail of Y to its midpoint?
exactly half the length of Y
woeful violet
thus you have a rough procedure "start at the tip of X, then move in the direction of Y at half its length"
yea
molten ferry
Since the tail of Y is the tip of X, you would move an additional Y/2 distance from the tip of X, which is why it lands midway between the tail of Y and the tip of Y
molten ferry
molten ferry
lol i dont know much about coding
the bottom line solves the equation line1[x]=line2[y] for all x and y
molten ferry
no solution
woeful violet
yeah
but it returned a solution right
so they touch at precisely the coordinates given
molten ferry
oh ok
molten ferry
so they touch at precisely the coordinates given
why are they returning differnet coordihnates
oh ok nvm
molten ferry
so they touch at precisely the coordinates given
how do i know what vectors to use
woeful violet
do u know how to test for perpendicularity with the dot product
molten ferry
do u know how to test for perpendicularity with the dot product
ye
if dot product = 0 then its perpendiocualr
woeful violet
great
the trick to this question is
if you have two vectors which are on the same line
molten ferry
do dot products work with 3d vecrtors
molten ferry
why cant u just do {a,b,c}.{d,e,f}=ad+be+cf
woeful violet
well this is how you do the dot product on vectors
but you have to tell whether lines are perpendicular
and how do you compute the dot product between two lines
holy shit i left my stove on brb
woeful violet
and how do you compute the dot product between two lines
it's a trick question, you can't
instead you have to find two vectors which will have the same angle between them as your two lines
molten ferry
instead you have to find two vectors which will have the same angle between them...
wait wdym
like just try out every vector combo and see which one is 0?
woeful violet
nah
ill draw a photo in 2d because 3d would require too much work lol
if you have two vectors that lie on your lines, they'll have the same angle between them as the lines themselves
so if you choose two vectors which are on your lines then compute the angle, it's the same as computing the angle between the lines themselves
and computing the angle between two vectors is easy: just use the dot product
molten ferry
if you have two vectors that lie on your lines, they'll have the same angle betw...
ohhh
molten ferry
so if you choose two vectors which are on your lines then compute the angle, it'...
so u only need to do this for one pair right
and all other pairs will be the same?
woeful violet
yeah
molten ferry
so if you choose two vectors which are on your lines then compute the angle, it'...
1 vector per line right
woeful violet
yeah
of course you have to be careful in the general case
these two vectors have a different angle
that's because two lines intersect at two different angles so you have to make sure you know which angle you're trying to compute
woeful violet
but in the case of a right angle it doesn't matter :)
well in the case of your question
you're working in 3d space
so 3d vectors
2d vectors don't make sense in a 3d environment
woeful violet
well to be fair to me u didnt give me how they defined the line in the above pic, i didnt know you had them
woeful violet
so if you choose two vectors which are on your lines then compute the angle, it'...
but the vectors they used are actually exactly vectors of this form
woeful violet
that doesnt work
molten ferry
why
woeful violet
suppose that blue is the lines, and o is your origin
you found the dot product between these purple vectors
not between the red vectors
even if the red vectors are perpendicular, the purple ones aren't necessarily
molten ferry
ohh
molten ferry
suppose that blue is the lines, and o is your origin
so what would be the actual computation
woeful violet
well you know the purple vectors
you're also given two different points on your line
something like this
molten ferry
you're also given two different points on your line
so i need to add the initial condition?
woeful violet
to get a vector from your point to the tip of the purple vector, you have to subtract them
molten ferry
to get a vector from your point to the tip of the purple vector, you have to sub...
like this?
woeful violet
yeah exactly
molten ferry
yeah exactly
dyk what its getting at here?
idk what viewpoint specification is
ohh its like the cmview thing
woeful violet
sorry i have no clue what this is
i gotta do sum hw of my own so you gotta find someone else if u have more questions sorry
nimble mesa
Hi can you help
brave marsh
If g(x) = 0, they explain that x = -14 or x=t. Since we know (24,0) is a point on the graph, we also know that x is not -14, so we must have x = t = 24.
Once you have that, you have your equation for g(x) and you can compute g(0).
marsh citrusBOT
@nimble mesa Has your question been resolved?
nimble mesa
Yes tysm
marsh pollen
marsh citrusBOT
onyx lava
Im having trouble with a problem on my algebra homework
marsh citrusBOT
Im having trouble with a problem on my algebra homework
onyx lava
The problem is 2 - 3h = 4 - 7h
leaden monolith
What have you tried?
onyx lava
so i know that you take away the 2 and subtract the 7 by 2
so i have 3h = 4 - 5h
is that correct?
leaden monolith
Not quite
You canât combine the ones with just numbers and the ones with hâs
onyx lava
oh ok
onyx lava
I think i subtract 7h - 3h because 3h is smaller
leaden monolith
The main thing we want to keep in mind for algebra is to âdo the same thing to both sides of the equationâ
Does that make sense to you?
onyx lava
yes
leaden monolith
The problem is 2 - 3h = 4 - 7h
So I guess we want the h by itself
Letâs first try move all the hâs to the left side
(Or right side, it doesnât matter)
How could we âmoveâ all the hâs to the left side?
onyx lava
by subtracting 7h - 3h?
leaden monolith
Remember we need to do the same thing to both sides
leaden monolith
by subtracting 7h - 3h?
This isnât âwrongâ
leaden monolith
But we want to do 2 - 3h +7h = 4 - 7h +7h
See how Iâve âdone the same thingâ to both sides
leaden monolith
But now the -7h and +7h will cancel out
On the right side
Now I have 2 - 3h +7h = 4
onyx lava
so im left with 2 - 10h = 4
leaden monolith
Huh?
onyx lava
mb
onyx lava
oh ok
leaden monolith
How does 2 - 3h +7h = 4 simplify?
onyx lava
-3h + 7h = -4
leaden monolith
No
leaden monolith
How does 2 - 3h **+7h** = 4 simplify?
So what does this become
onyx lava
2 + 4h + 4?
leaden monolith
Equals
onyx lava
i misclicked
leaden monolith
2 + 4h = 4
Yep okay, now letâs deal with the 2
How do you think we should âget ridâ of the 2 from the left side?
leaden monolith
But we want to do 2 - 3h **+7h** = 4 - 7h **+7h**
It will look similar to this
onyx lava
subtract 2 from both sides
onyx lava
4h = 2
leaden monolith
Yep
Now, thereâs still a pesky 4 in front of the h
How could we âget ridâ of that?
onyx lava
by dividing 4 from both sides
onyx lava
2
leaden monolith
Not quite
onyx lava
0?
onyx lava
0.5?
marsh citrusBOT
leaden monolith
đ
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warm root
hey guys i need some help with this problem
marsh citrusBOT
hey guys i need some help with this problem
warm root
$\frac{xx^\frac{-1}{3}}{2x^{5}}\$
elfin berryBOT
Banana2014
warm root
So basically, when I worked it out, I got this let me type it out really quick
$\frac{1}{2x^\frac{13}{3}\}\$
elfin berryBOT
Banana2014
elfin berryBOT
Banana2014
$\frac{1}{2}\x^\frac{-13}{3}\\$
```Compilation error:```! Undefined control sequence.
l.49 $\frac{1}{2}\x
^\frac{-13}{3}\\$
The control sequence at the end of the top line
of your error message was never \def'ed. If you have
misspelled it (e.g., `\hobx'), type `I' and the correct
spelling (e.g., `I\hbox'). Otherwise just continue,
and I'll forget about whatever was undefined.
Underfull \hbox (badness 10000) in paragraph at lines 49--50```
elfin berryBOT
faiyrose
warm root
yes thank you
so basically, my question was
is why is the x raised to a negative, would it be correct if it was on the denominator like i put it?
ohh ok cool thank you
i got this problem from pauls online math notes because im reviewing some basic alegbra/trig before i start calc 1
elfin berryBOT
faiyrose
marsh citrusBOT
marsh citrusBOT
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marsh citrusBOT
can someone pls help me with part b
cunning fiber
marsh citrusBOT
still temple
.close
marsh citrusBOT
Available help channel!
exotic magnet
Would 38 be -1 or 2
marsh citrusBOT
Would 38 be -1 or 2
calm harbor
Would 38 be -1 or 2
-1
velvet elk
marsh citrusBOT
velvet elk
What do I do next?
marsh citrusBOT
@velvet elk Has your question been resolved?
small stream
marsh citrusBOT
cobalt sedge
Any linear combination of solutions of a differential equation is also a solution
use it
small stream
Any linear combination of solutions of a differential equation is also a solutio...
Could you elaborate a bit?
cobalt sedge
2*y1 + 3*y2 is also a solution
so, you can find any such similar combination that satisfies the initial conditions, and that would be your answer
small stream
Yes i know, but how can i find the one that satisfied the condition?
cobalt sedge
put x = 0 in it and calculate y(0) and y'(0) for them
and check if they match the initial conditions
small stream
I know, I mean, how can I find the combination
cobalt sedge
?
y is the solution
so the linear combination you get IS y
just as y1 is y and y2 is also y
small stream
If we don't even know y then how can we plug 0 into it and calculate y(0) and y'(0)?
cobalt sedge
bruh
you have 3 solutions to y as y1 y2 and y3
they are all y
and also functions of x
so you put x = 0 and calculate the values
for y(0) is same as y(x=0) since x is the only thing in its domain
marsh citrusBOT
@small stream Has your question been resolved?
cobalt sedge
suppose for example, I took y = y1 + y2, then:
y(0) = x + e^x = 0 + 1 = 1
y'(0) = 1 + e^x = 1 + 1 = 2
And x + e^x is also a solution to the differential equation, as you can check yourself
so, if your problem was find solution such that y(0) = 1 and y'(0) = 2, the solution would have been y = x + e^x
small stream
so we can find many linear combination( y) like this that meets the conditions?
cobalt sedge
any one is fine
small stream
Does that mean we have to try all possible linear combinations to find the one that meets the conditions y(0)=y'(0)=3?
like, we need to suppose y=c1y1+c2y2 and plug in to find c1 c2 which satisfy the conditions
small stream
y=c1y1+c2y2+c3y3
but we only have two condition y(0)=3 y'(0)=3
two equation, three vars
cobalt sedge
any one is fine
.
marsh citrusBOT
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clear nacelle
Hey guys, i'm a philosophy student but I have a class on prop logic also (which isn't in english), so forgive me if the terminology or methods I use aren't familiar.
We were basically taught two methods (pic related) to check if an argument is 'truth preserving', which means checking whether if an argument has true premises, the conclusion is also true or not. 'Truth preserving' seems to be a term mostly used in philosophy from cursory google searches. The first method works by breaking down the propositions, the second by using a table.
as you can see the starting argument in the 'breaking down' example includes the propositions split by a comma, where in the table example the premise is just one proposition.
My question is, can you also solve an argument that's presented with commas separating the different propositions using the table method? Is it possible to convert a comma-separated series of propositions into a single one, to solve with the table method?
The reason I ask is on one of the mock exams one of the questions asks to find out if an argument is truth preserving using two different methods, but the argument itself is one where the propositions are separated using commas. the only way I would be able solve this is by actually working out the argument, since if you can work out the argument it must be truth preserving also.
marsh citrusBOT
Hey guys, i'm a philosophy student but I have a class on prop logic also (which ...
knotty trellis
Hey guys, i'm a philosophy student but I have a class on prop logic also (which ...
You could probably just join those comma seperated premises with ands
assuming there are finitely many
or just treat the comma like a conjuction
clear nacelle
makes sense i think, i'll try solving some using both methods and comparing the results. ty!
.close
marsh citrusBOT
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near elbow
hi guys how do i solve this?
marsh citrusBOT
hi guys how do i solve this?
near elbow
i tried multiplying the whole equation by (x+2)(x+3), and got x^2-5x+26=0 as a linear equation but i can't factorise it
raw hawk
Wouldn't the minus multiply all the terms of (x+2)(x+3)
marsh citrusBOT
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Available help channel!
turbid trout
Yelp
proud basin
!da2a
marsh citrusBOT
No need to ask âCan I askâŚ?â or âDoes anyone know aboutâŚ?ââitâs faster for everyone if you just ask your question! See https://dontasktoask.com/
turbid trout
So
Our school introduced a new method for factorisation and I don get a single bit
It's x^3-2x^2-x+2
Without out long division
weary karma
it isnt really a method
weary karma
taking x^2 common in the first two terms and -1 in the next 2 right?
turbid trout
It's the question
weary karma
No it's not a method it the question
oh
turbid trout
Without long division
weary karma
taking x^2 common in the first two terms and -1 in the next 2 right?
this is how to
without long division
proud basin
why use long division when you can use syntethic ^_^
turbid trout
They taught us to find a factor like (x+1) and then do something and then splitting the middle term
turbid trout
why use long division when you can use syntethic ^_^
We need to use that method only
weary karma
They taught us to find a factor like (x+1) and then do something and then splitt...
pretty lenghty method tbh
proud basin
pretty lenghty method tbh
i think they want to guess roots lmao thats my best understanding of their schools method
lucid turret
â: .･. o(â§â˝âŚ)o .･.:â
weary karma
oh ;-;
lucid turret
( ŕ° ŕľ ŕ° )ďž
hazy narwhal
wait i did somethign wrong
hazy narwhal
whoopsiedoodles
lucid turret
!original
marsh citrusBOT
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
lucid turret
what's the question bro?
weary karma
what ;-;
velvet cedar
seems like skill issue was right
weary karma
oh its the guessing one
weary karma
seems like skill issue was right
yea
turbid trout
oh its the guessing one
?
proud basin
seems like skill issue was right
real
weary karma
long division?
turbid trout
Our teachers told us that after substitution and proving a factor of that we need to do something to have 6 terms and 3 Pairs of thise
That isn't the correct answer even
turbid trout
long division?
Not allowed in our school
weary karma
Our teachers told us that after substitution and proving a factor of that we nee...
goofy method
turbid trout
Indeed
And even our teachers told us that to having 6 terms we need Brian storm smth or what forbidden method
Alr y'all can close ill check it on later thanks
still temple
its your help channel
velvet cedar
The method is similar to factorizing quadratics
If you have, $x^2 + 5x + 6$ and you know that $(x + 3)$ is a factor, you can rewrite the $x$ term so $(x + 3)$ is easily seen.
$$\begin{align*}
x^2 + 5x + 6 = x^2 + 3x + 2x + 6 \
= x(x + 3) + 2(x + 3) \
= (x + 3) (x + 2) \
\end{align*}$$
With the cubic, it's not too different.
$$\begin{align*}
x^3 - 2x^2 - x + 2 \
\end{align*}$$
We know $(x - 1)$ is a factor so to factor out $(x - 1)$ from $x^3$, we need an $-x^2$ term.
That can be taken from $-2x^2$term
$$\begin{align*}
x^3 - x^2 - x^2 - x + 2 = x^2 (x - 1) - x^2 - x + 2 \
\end{align*}$$
That quadratic expression at the end $-x^2 - x + 2$ also has $(x - 1)$ as a factor so we can apply the same steps as we did for earlier quadratic
elfin berryBOT
StrangeQuarkAL
Compile Error! Click the 
reaction for more information.
(You may edit your message to recompile.)
marsh citrusBOT
@turbid trout Has your question been resolved?
low mica
marsh citrusBOT
low mica
how to do 10b
whole thorn
same way you did 10a
low mica
i havent done cases thats the thing, its so unfamiliar to me for some reason
we were never taught it
weary karma
Over here
Critical points are -4 and 5/2
They determine
If the modulus will be positive or negative
If it's greater than 5/2
All will be positive
weary karma
Oh đ
weary karma
No problem lmao
low mica
đ i wont bother myself then with learning that
thank you anyway
but i see what u were getting at
null factor law
for each modulus
sorta
but yes thank you
have a good night
.close
flint onyx
What's up guys, I have a quiz today and I have some problems on the practice and I think it's over for me
marsh citrusBOT
What's up guys, I have a quiz today and I have some problems on the practice and...
pseudo badger
!status
marsh citrusBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
1
pseudo badger
what question are you on?
flint onyx
2(P + W)
pseudo badger
do you understand that L = 2W from the question?
flint onyx
I think so
pseudo badger
then just substiute L in the formula and youre done
pseudo badger
yeah
flint onyx
Last night I actually couldn't get that to click đ thank you
pseudo badger
!done
marsh citrusBOT
If you are done with this channel, please mark your problem as solved by typing .close
flint onyx
.close
marsh citrusBOT
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Available help channel!
charred panther
marsh citrusBOT
charred panther
Find all X that solve the equation
So my idea was to do the following
and i think this gives me sin(2x-30) = sqrt(2)/2?
and then my idea was that we get sqrt(2)/2 at pi/4, so add 30 degrees and then x is half of that, but clearly not the case :P
fervent umbra
i think they intended for u to use that
charred panther
tried that originally but to no avail
and then i know there's some method where you essentially "pull" the equation back onto the unit circle which is what i tried to do here
eager tinsel
and i think this gives me sin(2x-30) = sqrt(2)/2?
it is supposed to be sin(30-2x)
charred panther
ahhhhhhh
fervent umbra
@charred panther ok the thing is with these questions is that they usualy want u to turn the sin cos and tan into one function
But if ur method works then its fine
eager tinsel
yeah ig
charred panther
since we're adding 15 to get to 45 degrees? xd?
but this is the solution
which doesn't really feel like what i wrote here ngl
x = - 180 / 24
nvm
that is -7,5
well probably get some points for that :')
eager tinsel
since we're adding 15 to get to 45 degrees? xd?
should have used the general solution form instead of pi/4
charred panther
which is?
eager tinsel
well probably get some points for that :')
lol
charred panther
pi / 4 + 2kpi?
eager tinsel
erm
mortal cipher
marsh citrusBOT
mortal cipher
could someone please explain what Iâm supposed to do in f)
eager tinsel
could someone please explain what Iâm supposed to do in f)
you have to write the equation of asymptotes
I think by increasing order they meant from most negative to most positive thing
hazy dragon
how is this a proof for $\exists f'(0)$?
marsh citrusBOT
how is this a proof for $\exists f'(0)$?
elfin berryBOT
Ayanokoji (ALWAYS PING ME)
hollow glen
try it out, what is $\frac{f(x)-f(0)}{x-0}-1$ for a rational and for an irrational x?
elfin berryBOT
rbit
marsh citrusBOT
@hazy dragon Has your question been resolved?
hollow glen
the rest is just squeeze theorem and definition of derivatives
unborn axle
Just trying to make sure this is correct.
Just started Calc I and weâre doing an algebra review unit. My professor is like a 60 year old chick and talks faster than Iâve ever heard in my life; flies through the lecture without hardly any examples or anything and then ends class 40 minutes early.
Weâre reviewing trig functions and one of the questions on the HW was finding cos and tan from sin and the quadrant.
Did I do this right? Iâd probably be fine if sheâd have talked for more than 2 minutes on it.
Itâs regarding finding all 6 functions from sin(x)+cos(x)=1 given sin=-1/2 and Q3.
marsh citrusBOT
Just trying to make sure this is correct.
Just started Calc I and weâre doing a...
unborn axle
I donât think itâs right because I keep getting a negative root in the denominator but that may just be how it is. Idfk.
May also just be an algebra misunderstanding. Everything looks correct to me but maybe Iâm missing something.
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marsh citrusBOT
marsh citrusBOT
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charred panther
Hi
charred panther
So I want to find the smallest value for k such that the following inequality always is true
my idea was to move sin and cos to a single side and the constants to the other
and then "pull" back the LHS into the unit circle
so i took 1^2 + 2^2 = z^2 to find how "far out" we are and then factor that out
but now I'm kinda stuck.. Is this the completely wrong approach or should there be a way to evaluate the rad for arccos(1/sqrt(5))?
magic hare
so first of all do you know the highest and the lowest values these trig functions can have?
magic hare
good good
magic hare
oh yeah
charred panther
^^
magic hare
i thought you meant just cosx
charred panther
nah
magic hare
ok so lets approach the first problem logically
charred panther
but I'm thinking that i want to turn this into a sqrt(5) * sin(rad + x) <= k-3 situation
magic hare
here since it asks for the lowest value of k then you want cos and sin to be the lowest right?
charred panther
that's the approach i took in the past and sadly i failed that exam ;D
going through all old exams and don't remember exactly what the method of solving was..
but we have f(x) and g(x) and we want f(x) <= g(x) for all x
magic hare
um
you dont always plug -1 as the lowest for a function
but in this case it is the true method
for example if i give you k+3>= sinx-cosx and ask you the lowest value of k then here you would want sin to be the lowest and cos to be the highest because cosx is with a negative sign so if you plug in a negative value it will turn positive meanwhile if you plug in a positive a value like 1 thn you will get the lowest value that you can get. so sinx=-1 and cox=1 in this case gives k+3>= -1-(+1), k>=-5 which is the lowest value for k would be -5
charred panther
so what would your final answer be with that method?
magic hare
so what would your final answer be with that method?
0
charred panther
i think -5 is what i had too when i did the exam
if i remember correctly..
but it seems like my original idea was the right approach
or well, what the professors intended*
clever spade
for example if i give you k+3>= sinx-cosx and ask you the lowest value of k then...
isn't that looking for the largest value of k
clever spade
So I want to find the smallest value for k such that the following inequality al...
if we are finding smallest value it would be different
charred panther
only thing is that they never solve for theta which is what I got stuck on
clever spade
actually nvm
charred panther
they just say that there is an angle theta such that the condition is satisfied and rewrite it as sin(x + theta) -_-
magic hare
flipped the signs
clever spade
they just say that there is an angle theta such that the condition is satisfied ...
can you send the working out?
charred panther
that they did?
it's in swedish but sure
you have the numbers in there at least ;D
writing it out myself, can show in a sec what i think is the way to do it
magic hare
basically taking everything to one side
charred panther
but that's the entire thing i think
yeah i got stuck on the part where i was trying to calculate arcsin(1/sqrt(5))
but they just don't calculate it
:'))
oh well, would've just went with it on the exam day so it's fine
magic hare
sorting it to get acosx+bsinx format and then truning it to r.sin(x+theta)
charred panther
yap
clever spade
đ
marsh citrusBOT
magic hare
good luck on your exam
charred panther
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marsh citrusBOT
marsh citrusBOT
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marsh citrusBOT
marsh citrusBOT
compact crescent
Thatâs a common question
Would you wish a helping hand from a servant of Mickey Mouse
Blind, ignorant, and self serving people, could you see the truth
Could you penetrate the facade
Could you see the truth from the sheet
The sheet of the truth
marsh citrusBOT
compact crescent
Youâre biased. It is mere a flaw of your very being human
Do you know how to solve it from the graph
tawdry nymph
ty
real stirrup
he just asked in a different help channel if his answer is correct đ
compact crescent
he just asked in a different help channel if his answer is correct đ
Iâm skeptical about everything
real stirrup
Iâm skeptical about everything
ah yes
compact crescent
I did
But I like to double check
Iâm just trying to sound Shakespeare
Iâm by no means to offend you
compact crescent
I luv you đśđąđŚđťđŻđŚ
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fallow kelp
marsh citrusBOT
fallow kelp
For 552 I'm not sure how to find the answers
For the parallel sides
All I know is that the diagonals will go through the points between the segments of 8 3 and 8
The only "work" I have is a bunch of drawings of trapozoids
hidden dawn
fallow kelp
None of these drawings are accurate to the question though
Other than the midline is 19
This one is the closest
marsh citrusBOT
@fallow kelp Has your question been resolved?
fallow kelp
<@&286206848099549185>
coral path
<@&286206848099549185>
hi
fallow kelp
Hey
coral path
whatâs the question
fallow kelp
552
Asking about the parallel sides of the trapozoid
I need to know the lengths of the parallel sides
coral path
canât you find the parallel sides using pythagorean theorem?
fallow kelp
Not really
coral path
Not really
wouldnât the midline make another trapezoid
cuz itâs in the middle and would be parallel, the 3 would make it another trap?
what I got so far sorry for the messy handwriting
MLine=19
wait @fallow kelp is this geometry?
it looks like it but I donât remember this at all đđđ
marsh citrusBOT
@fallow kelp Has your question been resolved?
devout pebble
Isnt there something that says the length of the midline is the average of the lengths of parallel sides
still temple
$36u^2-81v^2= 9(4u^2-9v^2)=9(4u-9v)(4u+9v)$
marsh citrusBOT
$36u^2-81v^2= 9(4u^2-9v^2)=9(4u-9v)(4u+9v)$
elfin berryBOT
Tchaikovsky
still temple
is this wrong
late geode
yes
marsh citrusBOT
still temple
.reopen
marsh citrusBOT
â
still temple
$36u^2-81v^2= 9(4u^2-9v^2)=9(2u-3v)(2u+3v)$
elfin berryBOT
Tchaikovsky
still temple
so the 9 in the last equation is only distributed into the first algebraic difference
2u-3v not into 2u+3v
nvm
late geode
you can distribute the 9 once to one of the other factors
still temple
because of the associative law it doesnt matter which order the 3 are multiplied?
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marsh citrusBOT
late geode
commutative law here actually
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Available help channel!
still temple
$\frac{32r^2\times25p}{35q\times24r}=\frac{4r\times5p}{7q\times3}$
marsh citrusBOT
$\frac{32r^2\times25p}{35q\times24r}=\frac{4r\times5p}{7q\times3}$
elfin berryBOT
Tchaikovsky
still temple
how do you go from step 1 to 2 using cancellation
$\frac{32r^2\times25p}{35q\times24r}=\frac{32r^2}{24r}\times\frac{25p}{35q}$
elfin berryBOT
Tchaikovsky
still temple
is this true
$\frac{32r^2}{35q}\times\frac{25p}{24r}=\frac{32r^2\times25p}{35q\times24r}=\frac{32r^2}{24r}\times\frac{25p}{35q}$
elfin berryBOT
Tchaikovsky
still temple
true or false
proud basin
true
elfin berryBOT
Tchaikovsky
still temple
whats the intuition behind this
late geode
shifting the dp forward/back is multiplication/division by 10
respectively
still temple
how does it stay equal if you are multiplying one factor and dividing the other
late geode
they shifted one back (dividing by 10)
shifted one forward (multiplying by 10)
effectively multiplying by 1 (since 1/10 * 10 = 1)
which doesn't change the value of the overall expression
gilded ember
marsh citrusBOT
spark otter
how am i supposed to do this tech free
if you're given f, f' and f", which of those is the easiest that tells you about the concavity of f?
gilded ember
i thought u could only get concavity using f''
spark otter
not exactly but
it's the easiest
so
how does f'' tell us when f is concave up and concave down?
gilded ember
how does f'' tell us when f is concave up and concave down?
u find inflection points using f''(x)=0
i think im using the wrong method
sorry i was trying to find something
spark otter
u find inflection points using f''(x)=0
you don't want inflection points
you want concave up parts (and concave down)
so it's not f"(x) equal to 0 you're trying to solve for
marsh citrusBOT
@gilded ember Has your question been resolved?
marsh citrusBOT
gilded ember
.reopen
marsh citrusBOT
â
gilded ember
you want concave up parts (and concave down)
so how do i do that
i got taught through a table method
like this
@sharp wing
<@&286206848099549185>
limber hearth
You need the sign of f'' which depends only on the polynomial
x^2 -4x +2
So f'' => 0
<==> x^2 -4x+2 => 0
To get where it is concave up
And the parts of the domain, where it is not concave up, it will be concave down
marsh citrusBOT
@gilded ember Has your question been resolved?
marsh citrusBOT
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Available help channel!
forest dune
guys can someone tell how to solve
marsh citrusBOT
guys can someone tell how to solve
forest dune
using am and gm
marsh citrusBOT
@forest dune Has your question been resolved?
marsh citrusBOT
@forest dune Has your question been resolved?
forest dune
@everyone can yall help đ
forest dune
how
queen quartz
Do as if it were 1 function of a
So be is a fixed unkown
a works like an x
So f(a) =...
Derivate
Dont forget
b is constant here
forest dune
huh
queen quartz
That then gives you a function in b
forest dune
how can you tell
forest dune
hmm
queen quartz
how can you tell
Tell what ?
Sorry @forest dune
I forgot 1 step
No nvm it still works
What i said works
forest dune
i gotta complete the square first?
forest dune
bro there must be some hidden trick, its from a gems book, no question in it takes so much solving, its all trick questions
queen quartz
Try specific cases
Maybe a or b being 0 could help
You can solve it in 30s
Solution
A=0 b=-1
Its the lowest option
Since you reach it, none of the other are correct
forest dune
no, a=0 and b=+1 is the lowest
forest dune
Since you reach it, none of the other are correct
real
silent pewter
.open
I need help with
"if 1A Ă A = 9A, A equals to?"
(Answer is 6 in answersheet but i just dont get it how)
marsh citrusBOT
I need help with
"if 1A Ă A = 9A, A equals to?"
(Answer is 6 in answersheet but ...
storm meadow
so a^2=9a?
candid remnant
lim cosx/log(x-180/2+1)
x-180/2
knotty trellis
I need help with
"if 1A Ă A = 9A, A equals to?"
(Answer is 6 in answersheet but ...
is A a matrix or sth? Or is it just a variable? Why did you use uppercase
silent pewter
is A a matrix or sth? Or is it just a variable? Why did you use uppercase
Variable(i guess)
candid remnant
.open
lim cosx/log(x-180/2+1)
x-180/2
knotty trellis
then 6 isn't a correct answer
knotty trellis
.open
lim cosx/log(x-180/2+1)
x-180/2
hey, this channel is occupied, read #âhow-to-get-help and open your own channel
silent pewter
then 6 isn't a correct answer
Look i amnt very smart, its from class 8 book, chapter playing with number.
I amnt sure if its variable or not
knotty trellis
if it's from class 8, it surely is
if you want to get the correct solution, then subtract 9a from both sides and factor out a
silent pewter
if you want to get the correct solution, then subtract 9a from both sides and fa...
I dont get the correct answer like this, the answersheet says its 6
knotty trellis
I dont get the correct answer like this, the answersheet says its 6
but 6 is not the correct answer
can you get a photo of the question?