#help-33

1 messages · Page 155 of 1

runic temple
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ok, good luck

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do you mind sneding them so i can check them out?

primal drift
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are you not in the course?

runic temple
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no

primal drift
runic temple
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whoa

primal drift
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whoa is right im gonna be spending hours on the next couple

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but hey last day of this course is always exciting

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also for the answer to question 2 was it like 7.2 ish

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@runic temple

runic temple
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should be 6

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remember 26 is the hypotenuse squared

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you need the two legs

primal drift
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with so root 26 times root 8 times 1/2 but that was wrong

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since root 8 is the base of a to B

runic temple
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you can find AC using pythagorean

primal drift
#

I thought BC was the height though

runic temple
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BC is a hypotenuse

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AB and AC are the legs

primal drift
#

well that is my one mistake

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so Ac is height and Ab is base

runic temple
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yeah

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these are cool problems, is this an aops course?

primal drift
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yes it is

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It is called Waterloo Cemc summer course

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it is for problem solving

runic temple
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cool

primal drift
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and I guess you fit the bill by just simplifying the problems

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so you would be perfect for this

runic temple
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i did participate in AMC in high school

primal drift
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Oh that is very cool

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Anyways much appreciate all of your help

#

.close

marsh citrusBOT
#
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marsh citrusBOT
#
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vocal dew
#

can someone help me with this? i dont understand the 1 equation 3 unknown

tired ore
marsh citrusBOT
#

@vocal dew Has your question been resolved?

marsh citrusBOT
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stark trail
marsh citrusBOT
stark trail
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Is this a valid application of the central limit theorem

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I'm just a bit worried because of the sqrt(n) in the denominator in the probability of the last line

broken zealot
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yes

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you need not write the right side of the inequality

stark trail
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How are you sure, sir?

broken zealot
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clt just says that the distribution looks like a normal after sending n to infinity, so that means the cdf will look like a normal's cdf

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just ignore the inequality with the infinity as it is true with probability 1 anyway

stark trail
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No I meant sure about the other thing

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I understand ignoring the infinity side

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like

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CLT would say this is integral from 0.01/(sigma sqrt(n)) to infinity of the standard normal pdf

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but I just replaced the lower bound with 0 because that felt right

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although I'm not sure if it is

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As n to infinity it approaches 0

broken zealot
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oh wait what, no that's not right

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lower bound should be 0.01

stark trail
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I was worried of that

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That also doesn't make sense sir

broken zealot
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why not

stark trail
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you have to get

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(X_nbar - mu)/(sigma/sqrt(n)) in the middle term

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if you do this then you get the left bound as 0.01/(sigma sqrt(n)) not 0.01

broken zealot
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wait you have to also multiply by sqrt(n)? not divide?

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because it's the mean?

stark trail
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Oh

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it lower bound is not0

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i mean

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its infinity

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let me fi

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fix

broken zealot
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wait i think i've done this problem, is this 395

stark trail
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yes

broken zealot
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can you send the original

stark trail
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part (i)

broken zealot
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oh ok then yeah

stark trail
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becomes integral infinity to infinity which is0

broken zealot
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should be i -> 0, ii-> 1/2, iii-> 1

stark trail
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So is this valid fix

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the lower bound is then sqrt(n) * 0.01/sigma which tends to infinity

broken zealot
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yes, since the left side goes to infinity

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right

stark trail
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0.01/sigma sqrt(n) is not a fixed value a

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so I'm just wondering about if pulling the limit inside is fine to make it inf

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the statement is like

broken zealot
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the distribution tends to a normal as n grows large, the actual interval doesn't matter it can still depend on n

stark trail
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for all a,b with -inf <= a <= b <= inf
lim n->inf P( a <= ... <= b) = integrate standard normal pdf from a to b

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but a depends on n

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in the above

broken zealot
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yeah, a and b can depend on n

stark trail
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and we're fine to just bring the limit inside?

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I guess I wonder why

broken zealot
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it's better to think of the clt as saying that the distribution converges to something, not a specific probability statement

stark trail
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yea

broken zealot
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unless a,b oscilate or something

stark trail
#

Okay sir

broken zealot
#

does that seem reasonable

stark trail
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Well it always seemed reasonable to me I just don't want to lose points for applying the theorem in a way that wasn't explicitly written

broken zealot
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yeah i think it is ok

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clt is usually phrased in a stronger way

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or maybe not usually, but often idk

stark trail
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.close

marsh citrusBOT
#
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broken zealot
#

do you have 395 tomorrow?

stark trail
stark trail
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sort of

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can take it whenever

broken zealot
#

oh i see

marsh citrusBOT
#
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native gull
marsh citrusBOT
native gull
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how do i solve this one

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no calculator

naive stump
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if yes, consider rewriting cos10 = cos(2x5)

native gull
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cos^2(5) equals to cos10 + 1 / 2

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right

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cos 10 +1 / 2 - cos 10 / 2

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1/2

wary kite
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🤔

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you should use parentheses

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do you mean cos^2(5)=(cos(10)+1)/2

marsh citrusBOT
#

@native gull Has your question been resolved?

marsh citrusBOT
#
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small stream
#

Let the function ( f(x) ) have the second derivative on ( (0, +\infty) ) and ( f''(x) < 0 ). Let ( u_n = f(n) ), then the sequence ( {u_n} ) diverges is the ( ) of ( u_1 > u_2 ) \
(A) Sufficient and necessary condition\
(B) Sufficient but not necessary condition\
(C) Necessary but not sufficient condition\
(D) Neither sufficient nor necessary condition

small stream
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I'm cooked. No where to start

brittle cliff
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What exactly is the question

small stream
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Ooh lemme modify

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Mbmb

brittle cliff
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You sure it’s ui>uj and not the other way around?

fair kindle
elfin berryBOT
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riyobi

crystal lintel
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it makes sense. the correct option is supposed to go in the ( )

fair kindle
brittle cliff
crystal lintel
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hm maybe

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!original

marsh citrusBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

small stream
crystal lintel
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you should still post the original too

brittle cliff
small stream
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Yes

crystal lintel
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weird question then

fair kindle
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it doesn't look too hard, so I think you will be able to answer it

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always do that by the way, it's a global hint, always try to visualize questions if possible

small stream
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But f(x) is not a f with explicit expression, how to graph it?

fair kindle
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make something up which satisfies given conditions

brittle cliff
small stream
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Let's say f=-x^4

fair kindle
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don't even need to calculate you can imagine it xD

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also the function you wanna come up with doesn't have to be elementary or something you know

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you can just put axes and draw anything random with your pen but make sure it satisfies the conditions

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try drawing multiple ones and ask yourself questions

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can I draw one which diverges satisfying the condition ? can I draw one which diverges without satisfying the condition ? and so on

small stream
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,w plot -e^x

small stream
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Is this one's un diverging?

fair kindle
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clearly diverges

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as you go to infinity

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it blows up to -infinity

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is u1 bigger than u2 here ?

small stream
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Yes

fair kindle
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from this graph. generally if u1 > u2, does your function have to diverge ?

small stream
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Yes

fair kindle
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that's great

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but does it have to be true ?

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is it necessary

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aka can you come up with another example in which it diverges but u1 < u2

fair kindle
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that fits so well

small stream
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Can't think of other examples

fair kindle
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doesn't have to be a sine or a cosine or an e

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just draw something with a pen

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start with a function that has any value

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make it rise

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then keep it's second derivative negative

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anything

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again it doesn't have to have a symbol. or be something you have seen before

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as long as you know what it means for the second derivative to be negative geometrically

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you can just graph something without knowing what it is

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okay how about this, what does it mean for the second derivative to be negative geometrically ?

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like how would you describe it on a graph

small stream
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,w plot -sinx-2cosx

small stream
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,w plot sinx + 2cosx

fair kindle
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okay so for this function for example you just drew

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when is the second derivative positive

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and when is it negative

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and don't use any calculations

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just look at it and tell me

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if you don't know what it means geometrically you can ask by the way this is not an exam

small stream
fair kindle
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it's important

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you won't answer properly if you can't answer it

small stream
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Yes ofc i know

fair kindle
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then tell me

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sinx + 2cosx
when does it have a positive second derivative and when doesn't it, you can name points, you don't have to be too precise

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and make zero calculations

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just tell me from looks

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if f(x) = sinx + 2cosx

what is the sign of f''(0) and f''(pi)

small stream
fair kindle
small stream
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Ooh sorry misread

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It should be the first graph

fair kindle
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okay

small stream
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Anyway, i knew, if idk I'll just ask

fair kindle
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it's true then

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okay so you know that it's related to concavity

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all i'm asking is that you draw a concave down function that has u1 < u2

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and see if you can make it divergent

fair kindle
# elfin berry

non of these work by the way and i'm sure you know why

small stream
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It's not divergent

fair kindle
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no they don't have negative second derivative over (0,inf)

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that's the condition in the original question

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they go concave up in some regions

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you wanna draw something that is always concave down

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but starts rising

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you can draw it using paint or anything , again it doesn't have to be something you would graph on wolframalpha

small stream
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,w plot -(x-1)^2

fair kindle
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that works

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,w plot x(5-x)

elfin berryBOT
fair kindle
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u1 < u2

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it's concave down

small stream
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Yes

fair kindle
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does it diverge ?

small stream
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Yes

fair kindle
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what does that say about the answer to the question

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i will put it here again

small stream
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D

fair kindle
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are you sure

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is it sufficient ?

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like if that condition is true does it make the function diverge ?

small stream
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Yes?

fair kindle
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you tell me xD

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we have established it's not necessary correct ?

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now tell me whether or not it's sufficient and the question is solved

small stream
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Necessary is : u1>u2 implies divergent?

fair kindle
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yes

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wait

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no that's sufficient

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sufficient means the condition is sufficient to make the function diverge

small stream
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😭 it's so hard to remember it correctIy

fair kindle
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necessary means that without it, it's impossible for the function to diverge

fair kindle
#

but just translate it literally

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something that is sufficient means its mere existence is enough to make a statement true but it doesn't have to be there for the statement to be true, if it has to be there then it's necessary

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the existence of rain is sufficient to deduce the sky has clouds, but it's not necessary to have rain in order to have clouds

small stream
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But then we'll need to come up with another example to see if u1>u2 implies non divergent or not. If we can come up with one example, then it's not sufficient

fair kindle
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that's a great note !

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my question is can you come up with an example ?

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if you can then you are right it's not sufficient

small stream
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I can't, but that doesn't mean it's not true because maybe others can🤣

fair kindle
small stream
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Wait how did we prove

fair kindle
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we didn't ... yet xD

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I asked you if it was true or not and you said yes, you didn't provide evidence

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can you prove that it's sufficient

small stream
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Hmmm

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Hints!

fair kindle
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lemme give you an example with a problem associated with it

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you have a function f(x), f(0) = 0 and f'(0) = -1 , its second derivative is always negative, would that function be less or more or intersecting the line y = -x

small stream
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Isn't the f(x) itself y=-x

fair kindle
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the other one has negative

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so it should be falling faster

small stream
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Ooh

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Yea so it's decreasing faster than -x

fair kindle
#

yes

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so it will be always lower than y=-x no ?

small stream
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Yes

fair kindle
#

if you take the sequence y(n) = -n, that will diverge

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well then what of the sequence you get from a function lower than that ?

small stream
#

Due to squeeze thm or something, it'll divergent too

fair kindle
#

not really squeeze theorem but it's a similar idea

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proving the actual thing in your question however is slightly harder

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because we don't have f'(x) but rather we have two points far apart

small stream
fair kindle
#

now check this out xD

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f(1) > f(2)

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a line passing through the points (1,f(1)),(2,f(2)) would have negative slope

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which is f(2)-f(1) / (2-1)

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the mean value theorem tells us the function f(x) has a point c in (1,2) which has exactly that slope

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and since the function has negative second derivative

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then f'(c) > f'(2) since c < 2

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from here, for x > 2 the line passing through the two points must be larger than the function value.

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and since that line is decending at a constant rate, again the sequence taken from it diverges to minus infinity

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hence the sequence taken from the function below it also diverges to - inf

small stream
#

I want to look it up as a reference

fair kindle
#

i'm not really sure if it does, it goes straight back to the definition of limits

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the limit of a sequence an = -inf if for every B you can always find an N such that if n >= N then an < B. if bn < an after some threshould. then if you can find an N to make an < B then you can use the same N to make bn < B since it's lower.

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this would prove by the definition of limits that if bn < an and an goes to -inf, bn must go to -inf as well

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note than N is an integer and B is any real number

marsh citrusBOT
#

@small stream Has your question been resolved?

marsh citrusBOT
#
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frosty bronze
#

can someone help me check if this is the correct answer for this question?

lunar ember
#

30%

naive fox
#

!noans

marsh citrusBOT
#

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

marsh citrusBOT
# lunar ember 30%

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

lunar ember
#

Total density= 0.50

naive fox
#

Welp, wrong one used.

lunar ember
#

Density earning 200-500 is 0.15

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15/50

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3/10

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Which is 30%

frosty bronze
#

0.45 is correct

naive fox
lunar ember
#

What is this density ?

naive fox
#

It is probability density

#

From axiom of probability, the integral for the entire domain must be 1.

lunar ember
#

Ohh

#

My bad

#

First time hearing this kind of density

marsh citrusBOT
#

@frosty bronze Has your question been resolved?

marsh citrusBOT
#
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idle vessel
#

Why do palindromic polynomials with odd degrees necessarily have -1 as a zero?

hollow glen
#

plug in 0 and see what happens, look at the first and last term, second and second last, etc

idle vessel
#

0?

hollow glen
#

oops -1 my bad

idle vessel
#

Ohhhhh

#

P(-1)=-P(-1)

#

.close

marsh citrusBOT
#
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valid kiln
#

Hello everyone, I need help with this one. Is the correct answer for s=1 and t=0 or s=5 and t=-1? And could u explain me how did u get the answer

pallid tapir
#

does (s,t) = (1,0) or (s,t) = (5,-1) yield 1?

valid kiln
pallid tapir
#

uhhh sorry I misunderstood lol

#

does it yield the gcd of the two numbers

valid kiln
pallid tapir
#

yield as in

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give you

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return

#

make the function/expression in question evaluate to

valid kiln
#

i tried checking with the calculator, and both gives 793

pallid tapir
#

great, so they yielded 793

pallid tapir
#

so if 793 is their gcd, then both pairs are fine

valid kiln
#

or can i write + (-1)3172 ? but t is still -1 right?

pallid tapir
#

your task was to find a pair of integers (s,t) satisfying the above. you've found two pairs. -1 is an integer -- there is no problem

valid kiln
#

alright thank you

marsh citrusBOT
#

@valid kiln Has your question been resolved?

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#
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minor nebula
#

help

marsh citrusBOT
late geode
#

!status

marsh citrusBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
minor nebula
#

sorry wrong qs but yes idk where to begin

#

i tried 360-(21x-1 ) to find RSTP

#

wait

#

i think

#

ok nvm

#

.close

marsh citrusBOT
#
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flat meteor
#

can someone help? need to prove

marsh citrusBOT
#

@flat meteor Has your question been resolved?

stoic slate
flat meteor
rustic field
#

just asumme a<b<c WLOG

marsh citrusBOT
#

@flat meteor Has your question been resolved?

marsh citrusBOT
#
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empty compass
#

how do I solve this

marsh citrusBOT
whole thorn
#

any progress or ideas?

empty compass
whole thorn
#

maybe first find the point of intersection???

empty compass
#

ok I'll give it a try

marsh citrusBOT
#

@empty compass Has your question been resolved?

marsh citrusBOT
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wheat moth
#

somone help

marsh citrusBOT
wheat moth
#

help with dis

normal moss
#

Don't ping random people/mods.

wheat moth
#

but like who do i pping for help

normal moss
#

Last warning to stop pinging random users

wheat moth
#

ok alr ill stop

#

but

#

who do i ask for help

normal moss
wheat moth
#

just say it

normal moss
#

I don't care. Find time.

wheat moth
eager tinsel
wheat moth
#

alr

wheat moth
#

heres the sum again

#

someone welp

eager tinsel
#

but only after 15 mins

normal moss
#

It says all this in the first paragraph of the channel I linked.

thorny bison
marsh citrusBOT
#

@wheat moth Has your question been resolved?

thorny bison
# wheat moth

Hint 2 - || in the numerator u get the expression x⁴ +x³ +2x² +1 which can be written as x⁴ + x² +1 + x(x² + x)
Now divide it by the denominator to get two telescopic series ||

thorny bison
marsh citrusBOT
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thorny bison
#

.reopen

sharp peak
#

What level of math do I need to be able to do computer science?

sharp peak
#

Like pre calc? Or just algebra 2

dapper ravine
#

Wdym do computer science

#

What specifically do you wanna do

sharp peak
timid merlin
#

Well, u can enter the university with only the high-school math u know

#

It would be nice if u know pre calc

hollow glen
#

a bit of linear algebra too

wheat moth
sharp peak
#

Oh so just regular linear and quadratic formula algebra works for computer science also?

wheat moth
#

what did u gry

dapper ravine
thorny bison
thorny bison
hollow glen
#

oh no linear algebra is much more than just linear polynomials

dapper ravine
#

For general software eng you just need good mathematical reasoning skills, but being good at precalc should give you a leg up

thorny bison
dapper ravine
hollow glen
#

you should know about matrices and how to represent transformations with them and stuff

sharp peak
#

My school learning system is a bit slow

marsh citrusBOT
#

@sharp peak Has your question been resolved?

sharp peak
#

Yes

marsh citrusBOT
#
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alpine wharf
#

I need to solve this using trig identities to prove the equation is true but I'm rlly stuck on the step at the bottom. What do I do next?

brave marsh
#

Just split the fraction here

alpine wharf
#

Oh

#

Like

#

Factor out the cos..?

uncut oasis
#

Recall: (a+b)/c=(a/c)+(b/c)

alpine wharf
#

1/cos - cos^2/cos..?

uncut oasis
#

And what does that equal to?

alpine wharf
#

Ohh sec - cos

#

Thank you!!

uncut oasis
#

There you go

alpine wharf
#

.close

marsh citrusBOT
#
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dusty folio
#

The 3rd question

marsh citrusBOT
dusty folio
#

<@&286206848099549185>

marsh citrusBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

uncut oasis
#

First thing, 1.024 is 1000+24 or 1 +24x10^-3?

#

(just to make sure I get the notation)

dusty folio
#

1.024 × 10^-7

uncut oasis
#

Lemme rephrase my question

uncut oasis
dusty folio
#

Decimals

uncut oasis
#

Alright

#

First thing I'd do: try to write everything in terms of powers of 4

dusty folio
#

May I ask why writing it in terms of power of 4

timid crater
#

because if you write it in terms of the power of 4, its easier to solve it than multiplying all the decimal points of 0.04

uncut oasis
timid crater
#

or smth like that ig

timid crater
uncut oasis
#

4 is a natural number, which is usually the most convenient number set to work with in these kinds of questions

dusty folio
#

Ohh alr

#

So first I should write 4 instead of x .. am I right?

uncut oasis
dusty folio
#

Okay

#

Then what should I do?

uncut oasis
#

Should be pretty straightforward from there

#

Especially if they asked you to deduce it

dusty folio
#

Okay

#

Thankx

#

How to close the channel??

uncut oasis
dusty folio
#

.close

marsh citrusBOT
#
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dusty folio
uncut oasis
#

No problem

marsh citrusBOT
#
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eternal sequoia
#

How in the world do I solve this lol

marsh citrusBOT
night mica
#

$\left( \frac{D^6k^6-2k^{12}}{D^{13}}\right)$

elfin berryBOT
eternal sequoia
#

the t is still stuck to this function of D

#

@night mica oops

night mica
#

maybe Separation of variables could work

eternal sequoia
#

I can't

#

the v is preventing it

#

im wondering if I could try to substitute D for a trig function of some sort

marsh citrusBOT
#

@eternal sequoia Has your question been resolved?

eternal sequoia
#

is it even possible?

marsh citrusBOT
#

@eternal sequoia Has your question been resolved?

#
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spiral plank
#

can someone check my work, i have no idea how to do differential equations

flat meteor
formal spruce
spiral plank
#

omg bruh

#

wow the whole thing is wrong classic

#

ill be back

#

des are literally giving me brain worms

indigo karma
#

seems ok to me idk

spiral plank
#

ok thanks

#

this is the next q, is this a non separable one

formal spruce
formal spruce
#

Is that something specifically intructed?

spiral plank
#

oh wait am i supposed to use substitution for this one where u=x+y

formal spruce
#

You can just

#

Do e^y+x=e^y(e^x)

#

Separate that way

spiral plank
#

ohhh right

#

sorry im bad at exponent rules

#

can someone check this one too please

blazing ferry
#

i think is ok

formal spruce
marsh citrusBOT
#

@spiral plank Has your question been resolved?

#
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spiral plank
#

im back with more questions

marsh citrusBOT
spiral plank
#

this would be a first order de right? does that mean i need to find the integrating constant

pallid tapir
#

isn't the integrating constant like, your initial value thing? that y(0) = 9?

spiral plank
#

um what?

pallid tapir
#

yeah, you meant to say integrating factor

#

I think

spiral plank
#

right i did

pallid tapir
#

then yeah

#

agreed

spiral plank
#

so is the integrating factor just e^(-cost)

pallid tapir
#

sounds real

spiral plank
#

this does not seem corect

#

<@&286206848099549185>

pallid tapir
spiral plank
#

yeah, this is the first one

#

anywayas i figured out the error i didnt divide c by the if

pallid tapir
#

ah, I see it

spiral plank
#

wouls the answer be y=1+8/e

pallid tapir
#

oh I'm late

#

yeah

spiral plank
#

lol i typed in my answers and they were both wrong

#

what am i doing wrong i dont get it

pallid tapir
#

your y in this message is just a constant

spiral plank
#

oh wait

#

no i did not

#

so should the answer for the first one be y=1+ (8/e)/(e^-cost)

pallid tapir
#

I believe it

spiral plank
#

let’s try

pallid tapir
#

which you can simplify to 1+8e^{cos(t) - 1}

spiral plank
#

oh the first one was right the second one wasnt lol

pallid tapir
#

there's another point for the second piece

#

the problem is your initial value thing

#

mainly, 0 is not in the interval [pi, 2pi]

spiral plank
#

ohhh

#

2pi is equal to 0 though right

#

so should i use that instead

#

wait thats literally the same answer

pallid tapir
#

2pi isn't equal to 0 but I know what you mean

#

I still don't think so

#

so you can find two equations y1 and y2 corresponding to the two pieces of g

#

defined on their own respective domains

#

y is just the piecewise definition of y1 and y2, you know

spiral plank
#

right

pallid tapir
#

since y is asked to be continuous, you want these two pieces y1 and y2 to be attached

#

for all points in the interior of the domain of y1 and y2, the corresponding piece, hence the function, is continuous at that point

#

it gets dodgy at the endpoints, in particular the place where y1 ends and y2 begins

#

that's what gives you your initial value condition for the second piece

spiral plank
#

so like, the intial value information given can only be used to solve the first de for the interval from 0 to pi

#

and i shuold make my answer for y2 equal my ansewr for y1 when t=pi cause thats when the piecewise connects them?

pallid tapir
#

exactly

spiral plank
#

ok

#

that makes complete sense

#

gimme a mintue

pallid tapir
#

technically it's more like, the limit as x approaches pi from the right (coming from the domain of y2) should equal y1(pi)

#

but it's all the same really

spiral plank
#

but instead of -1 at the front i should change it to reflect continuity?

pallid tapir
#

I think the constant is the thing that ought to change right?

spiral plank
#

wdym

pallid tapir
#

all of the DE shenanigans should still work up to this point, with arbitrary constant C

#

using your new initial value premise that y2(pi) = y1(pi) should give you a value for c that's probably different from 10/e

spiral plank
#

ive made them so theyy are continuous at pi

pallid tapir
#

nice

spiral plank
#

so youre saying i keep the -1 and change the c value only

#

i have 8+2e^2 / e

pallid tapir
#

I literally did the same thing btw

#

just now

#

and yeah, I agree with your choice of c

spiral plank
#

wowww ok

#

ii will try

#

hopefully its right lol last chance

#

YAY

#

it was correct!

pallid tapir
#

very cool

spiral plank
#

ive reverse my math brainrot by like 20% just now

#

tysm for the help

pallid tapir
spiral plank
#

yes very

#

have a splendid day

pallid tapir
#

you as well

spiral plank
#

.close

marsh citrusBOT
#
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past atlas
#

Hi, I was wondering how you would turn this problem into a function:

past atlas
#

I am struggling with how to translate what is being explained into math

I imagine 27 is the y-value.

pallid tapir
#

you mean how do you generalize its solution?

past atlas
#

yeah if that is the correct terminology

#

I guess that sounds right because really I am wondering about any problem like this

#

particurarly if you had n amount of workers

#

but honestly just a function for this specific problem would probably help me understand how to think about this better

pallid tapir
#

right, it's like the difficulty of modeling and generalizing something, sure

past atlas
#

i have trouble deciding what the speed of the workers should be and what difference it makes that the workers are not working on the same dress

#

yeah i suppose that is what you'd call it

pallid tapir
#

it's probably a lot uglier to assume that there isn't any kind of linear collaboration going on, if you will

#

like, all but one person could be done and have nothing to do

devout pebble
pallid tapir
#

we can always describe the i'th worker's productivity as being a rate of r_i products per time unit

#

which turns out to be the actually useful thing

past atlas
#

$D(t) = \frac{r_i}{t}$ ?? idk how to turn it into math at all lol

elfin berryBOT
past atlas
#

I genuinely can't remember how to model even basic things

pallid tapir
#

so assume there is $s$ total product to be made and there are $n$ workers making the product, for which the $i$'th worker makes product at a rate of $r_i$ product per second, say. assuming productivity scales linearly, then the amount of time it takes to make $s$ product, $t$, satisfies $$r_1t+\ldots+r_nt=(r_1+\ldots+r_n)t=s,$$ yielding a time of $t=\frac s{r_1+\ldots+r_n}$

elfin berryBOT
past atlas
#

sorry I'm having trouble understand the i'th worker, is the i'th worked the sum of all the n workers?

#

the rate of all the n workers?

pallid tapir
#

I'm not immediately sure how you'd do this if s were a positive integer and each worker can only work on at most one item at a time

past atlas
#

ah that's okay to be honest just understanding this in of itself would be very helpful

pallid tapir
#

nah, if I name my employees w_1, w_2, ..., w_n, then I'm saying that w_i works at a rate of r_i

past atlas
#

but i am interesting in learning how that works too, that only one worker can work on an item at a time

#

oh okay so r is the rate

#

and r_n is the rate for that n worker?

pallid tapir
#

I think it'd have to do with determining the first person to have nothing to do on their own, then hijacking the slowest worker's project if they're faster

#

then keep going like that

pallid tapir
#

n is a reserved character denoting the number of workers, so we can't use that as an index

past atlas
#

man im lost, but have i at least understood things right that the r in r_n is the rate for the n'th worker?

pallid tapir
#

instead of exhaustively saying the first worker works at a rate of r_1, the second works at a rate of r_2, and so on, I just say that the i'th worker has a rate of r_i

past atlas
#

since there are many different workers?

#

and you chose i arbitrarily or is that convention if n is already being used for something else?

pallid tapir
#

ah, sorry, that's conventional. if I declare n items and say that the i'th item has attribute r_i, it's implied that i is like, a dummy index, that I use to quickly declare the n attributes. by context, the dummy variable i will take on integer values between 1 and n as I define each of the n attributes

#

if you like programming, it's like saying R = [r_i for i in range(1, n)]

past atlas
#

i think maybe im being unclear

#

basically think of me as a high school student who is bad at math

#

i barely understand any of the terminology used on here but i am slowly learning

#

i somehow got into uni despite this

#

I am also Swedish so I don't know what range means

#

I think it has something to do with the number line or sets

pallid tapir
#

ah word, my bad lol

past atlas
#

I know domain is also related

#

Nah you're all good man

pallid tapir
past atlas
#

R are the real numbers?

pallid tapir
#

I also wrote that to just be a different R, I'm sorry lol

past atlas
#

no that's alright, i'm probably just out of my depth even with this question

pallid tapir
#

I think we should ignore that example lol

past atlas
#

maybe this would be better

#

actually no it wouldnt be

#

damn I suck at math

#

i will get back to you when i can at least formulate a question in some manner

#

thanks for trying to help

#

.close

marsh citrusBOT
#
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marsh citrusBOT
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slim summit
#

hey, I'm trying to understand the relationship of this trig identity:
C_1cos(theta*t) + C_2sin(theta*t) = C_3cos(theta*t+ϕ)
but I don't really see how Acos(theta*t+ϕ) is a sum of these two vectors? I know that A = sqrt(A^2 + B^2) and that phi = arctan(B/A)
but when I try doing measurements it doesn't add up am I doing something wrong?

slim summit
#

for context, it's for differential equations for Dampened harmonic motion

marsh citrusBOT
#

@slim summit Has your question been resolved?

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quaint kettle
#

can anyone tell me a very logic reason why am i bad at math and why the others is really simple to solve math equations?. Give me tips too to improve more

pallid tapir
next raft
#

go study

late geode
#

what are examples of things you're struggling with?
it may be an issue of how you're being taught things

quaint kettle
#

like the mindset tho, like math is just stressful subject and i dont wanna learn about it

#

and u get humiliated sometimes

late geode
#

that's gonna be an issue

next raft
#

sounds like a bad learning environment u are in

quaint kettle
#

yups

leaden monolith
#

math is a skill and as with all skills it comes with practice and experience

#

you're only bad at math because you haven't been exposed to it enough

next raft
#

study with your friends and classmates

quaint kettle
#

can u like give me a good mindset how should i picture math

leaden monolith
#

can you ride a unicycle

next raft
#

so abstract lol

quaint kettle
#

just bike

#

ohhh so u need to balance and move so u can keep move forward and solve

next raft
#

i think u just learn it slowly using the method of your choice

#

dont think too much about this

marsh citrusBOT
#

@quaint kettle Has your question been resolved?

#
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simple kayak
#

Hello i'm having trouble in trying to visualize this box fractal and i can't determine what the number of self-similar pieces are

simple kayak
#

I assume the scaling factor is 1/3 so all i got for now is

D= log(n)/log(s)
D= log(???)/log 3

When i try drawing the box, it ends up looking like a cross and i'm not sure if that's correct

wheat moth
#

i tried this

marsh citrusBOT
#

@simple kayak Has your question been resolved?

marsh citrusBOT
#

@simple kayak Has your question been resolved?

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small stream
#

Let the function ( f(x) ) be once differentiable on the interval [0,1], and ( f(0) = 0 ), ( f(1) = 3 ), and ( \int_{0}^{1} f(x) e^x , dx = e ). Prove that: (1) There exists a ( c \in (0,1) ) such that ( f(c) = c^{2} + 2c ). (2) There exist distinct ( c_1, c_2 \in (0,1) ) such that ( f'(c_1) - f'(c_2) = 1 ).\
Any hints

elfin berryBOT
#

riyobi

marsh citrusBOT
#

@small stream Has your question been resolved?

marsh citrusBOT
#

@small stream Has your question been resolved?

fair kindle
#

@small stream Insane question by the way xD

#

I would give you a hint but, this style of hints is a bit too advanced compared to questions we have done before.

#

consider the function $g(x)=f(x) - x^2 - 2x$

elfin berryBOT
#

Mohamed Mohsen

fair kindle
#

this would be my hint

#

explore this function a bit and see if you can relate it to your question

small stream
#

I'm really fed up with this kind of mean value theorem problem😭

#

g(0) = f(0) - 0^2 - 2(0) = f(0) = 0
g(1) = f(1) - 1^2 - 2(1) = 3 - 1 - 2 = 0

fair kindle
#

this problem is very neat though

fair kindle
#

keep going

#

what more can you deduce ?

#

what does this function look like ?

small stream
#

hmnn

#

The exact shape of g(x) depends on the properties of f(x) so we dont know

#

[\int_0^1 f(x) e^x , dx = \int_0^1 \left( g(x) + x^2 + 2x \right) e^x , dx ] \Expanding this: [ \int_0^1 f(x) e^x , dx = \int_0^1 g(x) e^x , dx + \int_0^1 x^2 e^x , dx + \int_0^1 2x e^x , dx ]
[\int_0^1 x^2 e^x , dx = \left( 2 + e \right)]
[\int_0^1 2x e^x , dx = \left( e + 1 \right)] [e = \int_0^1 g(x) e^x , dx + (2 + e) + (e + 1)]
[\int_0^1 g(x) e^x , dx = -2e - 3]

elfin berryBOT
#

riyobi

fair kindle
#

how did you calculate the x^2e^x integral

#

you are on the right track, I just think the calculation is not correct

#

you forgot the slash

#

at the end

#

[\int x^2 e^x , dx = x^2 e^x - \left( 2x e^x - 2 e^x \right) ]

small stream
#

[\int x^2 e^x , dx = x^2 e^x - \left( 2x e^x - 2 e^x \right) ]

fair kindle
#

oh yea it doesnt xD

elfin berryBOT
#

riyobi

fair kindle
#

when you put 1

#

you have e

#

when you put 0, you get 2

#

but then you need to subtract not add

#

so it's e - 2

#

wait how

small stream
#

Nvm, mb🥲

fair kindle
#

it's okay

#

for the other one

#

it's $2xe^x - 2e^x$

elfin berryBOT
#

Mohamed Mohsen

small stream
#

0(x=1)

fair kindle
#

yes

#

so add both up and you get ?

small stream
#

-2

fair kindle
#

yea it's -2 at zero

#

don't forget that

#

so when you use the fundamental theorem of calc

#

it's 2

#

because you subtract the second bound

#

adding the two integrals is adding e - 2 + 2

#

what is that ?

small stream
#

[e = \int_0^1 g(x) e^x , dx + e ]

elfin berryBOT
#

riyobi

fair kindle
#

conclusion

#

wait what

#

yes the bounds are zero

#

and what of the integral ?

small stream
#

Uhh wait what's the antiderivative of g(x)ex

fair kindle
#

bro xD

fair kindle
small stream
#

Or we can get g(x)ex is odd function

fair kindle
#

what is the integral of g * e^x

#

i'm confused, you already solved it

#

why did we go back

small stream
fair kindle
#

yes

#

that's it

small stream
#

But what can we derive things from it

fair kindle
#

oh boy you can derive alot from that

#

we have a function that has g(0) = g(1) = 0

#

and its integration times a positive function ( e^x in that case) is also zero

#

this must have one of two meanings

#

either the function g(x) = 0 or it has a zero in the interval (0,1)

#

tell me why

small stream
#

Hmmmmm

#

Maybe some thm

#

MVT

fair kindle
#

maybe some intuition

#

how can an integral equal zero ?

small stream
#

Symmetry

fair kindle
#

the function inside can't be fully positive or fully negative

#

yes

#

there must have been some ... not really symmetry but you need to have the function be positive in places and negative in places

#

or you need the entire function to be zero itself

#

but you know our function is differentiable and that means it's continuous

#

ofc so is g because you just added a polynomial to f

#

this means by the intermediate value theorem, there must be c inside (0,1) such that g(c) = 0

small stream
fair kindle
#

forget about the theorem xD you can't get there without your understanding

#

you understand what you are doing then you write it using proper theorems

#

i wasn't thinking ivt when i got this idea

#

i was thinking the integral can't be zero if g had a singular polarity

small stream
#

I understand now

fair kindle
#

great and what does it mean for g(c) to be equal zero ?

small stream
#

(1) is proven

fair kindle
#

exactly

#

now think about part 2 and tell me what you think

#

I think it's easy so give it a shot now after you got part 1

#

part 1 was the hard work

small stream
#

Since g(0)=g(1)=0, we know there's a c s.t. g'(c1)=0

fair kindle
#

okay keep going

small stream
#

And since (1) we know that there's g'(c2)=0 ?

fair kindle
#

where does that lead though

#

even if that is true

small stream
#

g"(m)=0 , umm wrong direction ig

fair kindle
#

i think it's a good practice to avoid naming the second derivative at all since the question mentioned a differentiable function only so it doesn't have to have a second derivative

small stream
#

[ f'(c) = \frac{f(b) - f(a)}{b - a} ] [ f'(c) = \frac{f(1) - f(0)}{1 - 0} = \frac{3 - 0}{1} = 3 ]

elfin berryBOT
#

riyobi

small stream
#

Seems like I need a little hint

fair kindle
#

you are on the write track just using wrong points

#

you have 0,c,1 and we got c from part one, you can use those to make two points

small stream
#

[ f'(c_1) = \frac{f(c) - f(0)}{c - 0} = \frac{c^2 + 2c - 0}{c} = c + 2, ] [ f'(c_2) = \frac{f(1) - f(c)}{1 - c} = \frac{3 - (c^2 + 2c)}{1 - c}. ]
[ f'(c_1) - f'(c_2) = \left( c + 2 \right) - \frac{3 - (c^2 + 2c)}{1 - c}. ]

elfin berryBOT
#

riyobi

small stream
#

I guess this will result in 1

#

Yes it is

#

Wow, this question is not that difficult as I imagine

#

Thank you so much🙏💕

#

.close

marsh citrusBOT
#
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fair kindle
marsh citrusBOT
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misty plume
#

Can anyone explain me what is mod 6

marsh citrusBOT
cloud field
#

remainder after division by 6

misty plume
#

Ummm ok got it thanks

#

.closw

#

.close

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dull mesa
#

Hello all 😊

This is more of a theoretical question, but - We can obtain the amount of possible combinations of k elements from a set of n total elements with repetition allowed using the binomial coefficient (n + k - 1, k).

However, do we have a method / algorithm for obtaining the actual combinations?

For permutations, one could "itemwise" iterate over all possible options until all are obtained, but how could this be done for combinations?

Is there a more efficient / straightforward approach than generating all permutations and sorting + filtering out already existing combinations?

hollow glen
#

i think because order does not matter, one could just make up some order for these n elements and list up only the sorted combinations, which would then look like regular counting, just that whenever a digit wraps around, it has to start from the value of its left neightbor (after it has been incremented), for example
1 ... 1 1 1
1 ... 1 1 2
...
1 ... 1 1 n
1 ... 1 2 2
1 ... 1 2 3
...
1 ... 1 2 n
1 ... 1 3 3
...
1 ... 1 n n
1 ... 2 2 2

sleek lake
#

yeah you "iterate" the binomial coefficient

marsh citrusBOT
#

@dull mesa Has your question been resolved?

sleek lake
#

i don't know exactly how, it's not that easy, here's python's "combinations" for example

marsh citrusBOT
#
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blissful terrace
#

I throw defective die 10 times, probabilty of even face occuring 5 times is twice of even face occuring four times , probabilty of even face occuring?

blissful terrace
#

so what i did is

#

let p of even throw is x

#

So

#

(x)⁵(1-x)⁵ = 2(x)⁴(1-x)⁶

#

But its wrong

#

Idgt

tired knoll
#

Hello, can you please provide a picture of the question you're working on

marsh citrusBOT
#

@blissful terrace Has your question been resolved?

marsh citrusBOT
#
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blissful terrace
marsh citrusBOT
blissful terrace
#

how do i start

marsh citrusBOT
#

@blissful terrace Has your question been resolved?

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dawn pendant
marsh citrusBOT
dawn pendant
#

can you go another channel im already here

viral wyvern
#

oh mb

#

i think i sent it to the wrong channel

#

sorry

dawn pendant
#

alg

#

someone check my work for question 2 its kinda sketchy and idk if its right

marsh citrusBOT
#

@dawn pendant Has your question been resolved?

marsh citrusBOT
#

@dawn pendant Has your question been resolved?

marsh citrusBOT
#

@dawn pendant Has your question been resolved?

wheat moth
#

bruh

dawn pendant
#

?

wheat moth
marsh citrusBOT
#

@dawn pendant Has your question been resolved?

round furnace
# dawn pendant

Sketchy yes but mathematically it seems to check out, your conclusion also seems valid

#

But sketchy can be said about the entire exercise because never have I ever seen a simple mass spring damper system ma+cv+kx=0 being written in such a cursed way with momentum p🤮🤮

marsh citrusBOT
#

@dawn pendant Has your question been resolved?

versed niche
#

Money money money

dawn pendant
#

.close

marsh citrusBOT
#
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#
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timid prairie
#

Hello does anyone know how this equation is formed?

timid prairie
shadow ibex
#

2a + 2pi*(b/2) = 400

#

...

#

🤔

#

We need some excuse to express b in terms of a

#

Oh, maximized area

#

No 💩

#

A = ab + pi*(b/2)^2

shadow ibex
#

b = 2(200 - a)/pi

shadow ibex
wheat moth
#

hm

timid prairie
#

<@&286206848099549185>

still temple
# timid prairie

I am not a calculus expert, but try to do 2 divided by 3.14 which is pi in number

timid prairie
#

.close

marsh citrusBOT
#
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wary bluff
#

How is this hint useful?

marsh citrusBOT
wary bluff
#

|p(k+1)| = |p(k) U p(k+1)| ?

#

acc nah idk

#

ngl I was thinking of something like this

Inductive step: WTS p(k+1) = T(k+1)

T(k+1) = T(k-2) + T(k-4) - T(k-7)

and by inductive hypothesis we know:

p(k-2) = T(k-2), p(k-4) = T(k-4), p(k-7) = T(k-7)

#

or maybe for p(k+1)

let A = p(k-2) and B = p(k-4) and then A n B = p(k-7) somehow?

#

ye shit idk

#

<@&286206848099549185>

marsh citrusBOT
#

@wary bluff Has your question been resolved?

marsh citrusBOT
#

@wary bluff Has your question been resolved?

wary bluff
#

<@&286206848099549185>

marsh citrusBOT
#

@wary bluff Has your question been resolved?

vestal forge
#

I'm not quite sure how to formally do this but if you look at the two sets:
\begin{align*}
A={(a,b)\in\mathbb{N}^2|3a+5b=k-2} = {(a,b)\in\mathbb{N}^2|3(a+1)+5b=k+1}\
B={(a,b)\in\mathbb{N}^2|3a+5b=k-4} = {(a,b)\in\mathbb{N}^2|3a+5(b+1)=k+1}
\end{align*}

elfin berryBOT
vestal forge
#

Notice that if you take any solution (a,b) from set A, and 'transform' it to (a+1,b), you gain a solution to the (k+1)-cent problem where you must use a 3-cent stamp. That is a solution that has at least one 3-cent stamp.

So essentially, for every element in A, you would be able to build a solution for the problem "create a postage of (k+1) cents using at least one 3-cent stamp and some arbitrary amount of 5-cent stamp".
Similarly for the set B, taking any elements from set B, you would be able to build a solution for the problem "create a postage of (k+1) cents using at least one 5-cent stamp and some arbitrary amount of 3-cent stamp".

#

and if you now consider the union of A and B. Using any element from this set you can build a solution to the problem "create a postage of (k+1) cents using at least one 3-cent stamp or at least one 5-cent stamp". Which is equivalent to using either 3-cent stamp or 5-cent stamp to make a postage of (k+1) cents.

Which means that card(AUB) = p(k+1).

elfin berryBOT
vestal forge
#

So you can now prove that p(k+1) = p(k-2)+p(k-4)-p(k-7) using this and the hint given.
Though a problem is this is still very crude and I'm not sure what would be a more fomal way to represent it

marsh citrusBOT
#
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still temple
#

.pf

#

.pdf

#

!pdf

quasi gust
#

yea wait mb

still temple
#

yea whatever

marsh citrusBOT
#
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still temple
#

u didnt have to delete it 😭

#

now open a new channel

quasi gust
#

Oh

#

No idea on how to do last 2 questions.

still temple
quasi gust
still temple
#

this channel will get closed

#

soon

quasi gust
#

oh thanks.

#

.close

still temple
#

its already closed

#

nvm u just put that question in a new channel

quasi gust
#

done