help-33

[desert dirge]

is the total resistance the same in each case then?

[wispy ledge]

Uhh no

Wait…

Ohh

Yea ohms law

My bad

Thanks

[desert dirge]

nw

[wispy ledge]

.close

[marsh citrus]

Channel closed

Closed by @wispy ledge

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[runic glacier]

i wrote the answer of this question as c) 2 as its a quadratic but its b)1 in the answer key. why

[still light]

one of them might be extranneous

[stoic slate]

You need to know how is the graph of sqrt

[stoic slate]

It is not a quadratic

Square root is not equal to squared

[dark pagoda]

Hey, I got the answer

I solved with steps, may I send pic

Cuz its hard to type it out

[stoic slate]

!nosols

[marsh citrus]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[calm harbor]

no, keep it

[broken dome]

Desmos says the answer is correct, so I got nothing lol

Oh nvm

lol

I missread

[stoic slate]

Lol

[dark pagoda]

Can we perform squaring on both sides?

[stoic slate]

Depends

[dark pagoda]

In this case?

[stoic slate]

If you know what are you doing yes

[dark pagoda]

Yeah, squaring on both sides gave me answer

[stoic slate]

You don’t need to solve the equation to solve the exercise

[dark pagoda]

Now how the heck I gotta type it all out?

[acoustic bramble]

Write it down and take a picture

[calm harbor]

@runic glacier please ping any of us when you’re back

[calm harbor]

No rush, let’s wait for the OP

[dark pagoda]

Ok

nvm I made a silly mistake anyways

[marsh citrus]

@runic glacier Has your question been resolved?

[dark pagoda]

Actually, I am now getting 2 solutions

The guy who asked question seems to be gone

[lapis shale]

@runic glacier can you send your attempt

[dark pagoda]

I solved again and getting 2 solutions

Can someone check where I am wrong

This is what I did, unable to find any errors in it

[stoic slate]

The error is that sqrt is positive

And you are giving a negative solution

That is why you can’t square both sides if you don’t know what are you doing

You have to set restrictions when doing it

[dark pagoda]

Nah, I can have x= (-1)/3

Because this does not makes any underrot negative

[stoic slate]

You did not understand what I said

What is (-1/3)12 + 1?

[dark pagoda]

My answer is -1/13

So it will be positive anyways

[stoic slate]

Oh 13, still wrong but wait

[dark pagoda]

Yeah, please go through my solution again

Both are correct

Cuz there ain't a negative quantity underroot once

This maybe not correct way to think but it's possible that answer key is wrong

I've experienced this thing many times

[stoic slate]

No, dont worry

I am reading your answer

[dark pagoda]

Ok cool

lmk if you get any catch

[stoic slate]

I found

[dark pagoda]

Hell yeah

[stoic slate]

Just let me write it

I have to check something

[dark pagoda]

kk

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[stoic slate]

5th line

6th

.reopen

[marsh citrus]

✅

[dark pagoda]

Bro, -1/13 is just value of x

If we put this value,

Then there is never a negative quantity in a root

So Samuel, what's the catch?

[stoic slate]

Give me a moment i am doing other stuff brb

[dark pagoda]

Ok

[stoic slate]

Ok im back

[dark pagoda]

Ye

[stoic slate]

Ok so, go to the line

5

[dark pagoda]

Ok

Gone

There

[stoic slate]

You have there 4x-4 correct?

[dark pagoda]

Ye

[stoic slate]

That is equal to a square root right?

[dark pagoda]

Eh

It equals to 4(x-1)

[stoic slate]

4x-4 = sqrt(whatever)

[dark pagoda]

Yeah, now that squaroot comes here to complete square

[stoic slate]

I am reading line 5

No

Wait

You have sqrt() = 4x-4

[dark pagoda]

Okay, yeah

[stoic slate]

This sqrt must give a positive solution

So if u find -1/13 and sub

[dark pagoda]

Hmm

[stoic slate]

U get 4(-1/13)-4

[dark pagoda]

It's positive

[stoic slate]

Which is negative

[dark pagoda]

Oh wait

Lemme do it

Onemin

[stoic slate]

When u do restrictions you have to do not only inside the root but outside

[dark pagoda]

Bro wait

It's positive anyways

[stoic slate]

How is this positive?

[dark pagoda]

There's a +20

Inside root

[stoic slate]

I dont care inside

[stoic slate]

I am talking outside

[dark pagoda]

Okay wait

I got your point

I got it

Man

You just opened my eyes

Good lord

[stoic slate]

No worries, just be sure u make ur restrictions correctly and in every place needed

[dark pagoda]

Hell yeah bro you W

Thanks for clarifying

There's this one guy named

peskyperch2.0

Don't help him out bruh

He literally copies your answers

mb, figure it out yourself

He's like "fuck why and how and tell me the answer"

Anyways, thanks once again

[stoic slate]

.close

[marsh citrus]

Channel closed

Closed by @stoic slate

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Please don't occupy multiple help channels.

[quaint elm]

oh that's unfortunate

[whole quiver]

sad

[calm harbor]

You’re getting helped

At #help-25

[quaint elm]

not anymore

[whole quiver]

[calm harbor]

lol

[lucid turret]

that channel corrupted.

[whole quiver]

[calm harbor]

Alr

[lucid turret]

anyways, what's the answer.

[quaint elm]

.close

[marsh citrus]

Channel closed

Closed by @quaint elm

Use .reopen if this was a mistake.

[quaint elm]

I would have left it at an hour to read the rules until they admitted it was a quiz

[calm harbor]

Nah, having them share their idea would definitely take longer than 12min

That’s how I tackle test attendee, ask them to share

[lucid turret]

Do you check every second the state of channels?

[quaint elm]

me? no I'm just bored before work

[lucid turret]

ok

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hearty dust]

if you graph ln(y) against ln(-0.0002384x+0.0007494)
and it turns out to be a linear line
can the relationship between y and x be called logrithmic or approximately logarithmic?

[faint creek]

As in ln(y) = ln(-0.0002384x + 0.0007494) ?

I believe that would simplify to y = -0.0002384x + 0.0007494, making it a linear relationship

[hearty dust]

no like if you graphed y and x normally

would it be a logarithmic relationship

given that, ln(y) against ln(-0.0002384x+0.0007494) made a linear line

[faint creek]

I'm not 100% sure what you mean

If you just try graphing y against -0.0002384x + 0.0007494 you get the same line right?

So the relationship between x and y is linear

[hearty dust]

get the same line as what

[faint creek]

The relationship between ln(x) and y, or between x and ln(y) may be called logarithmic or exponential

[faint creek]

The same line as this relationship

[hearty dust]

why would that also result in a linear relationship?

[faint creek]

Well... the relationship you're starting with is ln(y) = ln(-0.0002384x + 0.0007494) right? From that I can do the following manipulation

ln(y) = ln(-0.0002384x + 0.0007494)
y = e^(ln(-0.0002384x + 0.0007494))
y = -0.0002384x + 0.0007494

Which gives us a linear relationship between x and y

Does that kinda make sense?

[hearty dust]

im getting confused and i hope you can help me

so I started with this equation

I wanted to linearize it and I got:

so if I graph ln(closs) and ln(-0.0002384x + 0.0007494) it will be a linear line as it is in y=mx+b form

so when I ask what the relationship between V and closs it normally

[hearty dust]

how can it be linear if the original equation is this?

@faint creek

[faint creek]

Ah okay I think I see my misunderstanding now

I was treating ln(y) and ln(-0.0002384x+0.0007494) like equations rather than like variables

[hearty dust]

yeah that is what I meant, sorry for not making it clearer

so does closs and v have any relationship? and if so what is it?

[faint creek]

Well from the original equation I would probably call that relationship polynomial or exponential, but that's just my intuition

Is this for a class with specific terminology?

[hearty dust]

im just looking for the mathematical relationship term for it

like u said

polynomial, exponential, etc

but which one is it

I graphed it https://www.desmos.com/calculator/xthnxqnlav

and it looks like this

is this any kind of relationship?

[faint creek]

Well coming from computer science I would call that relationship polynomial since you have a variable raised to an exponent

[hearty dust]

polynomials look like this?

[hearty dust]

but it's also under a square root

so would that still go under polynomial

[faint creek]

Yeah that's why I'm taking a bit to respond

In computer science I would, or more specifically in complexity theory
there a variable raised to a constant exponent is called polynomial while a constant raised to a variable exponent is called exponential

x^(1/2) has more in common with x^2 than it does with 2^x

[hearty dust]

So what would this one be?

[faint creek]

In that terminology it would be polynomial, since V is the variable with it being raised to a constant exponent (With some other constant stuff mixed in)

[hearty dust]

i see tysm

.close

[marsh citrus]

Channel closed

Closed by @hearty dust

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lucid turret]

How to get the result that cos(2x) = cos^2 (x) - sin^2 (x)?

[lucid turret]

I don't need a direct hint.

[lone wharf]

dyk double angle formulas

for sin/cos

[lucid turret]

cos (x+y)?

[lone wharf]

yea

doubling an angle is just cos(x+x)

[lucid turret]

If I knew wouldn't that would've been so easy?

Let us encompass a broader perspective.

cos (x+y)

[lone wharf]

cos(x+y)=cosxcosy-sinxsiny

[lucid turret]

You aren't incorrect.

[velvet cedar]

Interesting choice of words

[iron meadow]

there are direct geometric proofs of the sum formulas

i think if you prove one you can kinda derive the rest from that one

i can try to look one up

[lucid turret]

I like to be unique 🙂

[velvet cedar]

You can also use de moivre to prove the double angle formula

[iron meadow]

it's a bit to parse through but it's just pure geometry that one

[lucid turret]

I will look into it later. Thanks I have to sleep now.

.close

[marsh citrus]

Channel closed

Closed by @lucid turret

Use .reopen if this was a mistake.

[velvet cedar]

The only proof I've seen(besides the one you sent) for double angle used a rectangle

[iron meadow]

neat

[lone wharf]

oh when I learned it I saw a different diagram

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[severe obsidian]

hello! im working on this inequality question 3x-1/x+6 >= 3x+4/x-12, and I've understood the steps up until making the interval chart. I'm a bit confused as to why -59x-12 has turned to -59x+12 in the interval chart, when the simplified equation is -59x-12/(x+6)(x-12). I know what's in the interval chart is correct as I graphed it in Desmos but I'd like to understand why the sign changes for the constant here

[cunning fiber]

that's a typo

note that they're considering x = -12/59

that makes -59x - 12 = 0, not -59x + 12

[severe obsidian]

ahh i seee, thanks for getting back to me!

[cunning fiber]

[severe obsidian]

.close

[marsh citrus]

Channel closed

Closed by @severe obsidian

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tall sun]

how do these look?

[broken dome]

The formatting has seen better days

[tall sun]

yeah you right im lazy

[tall sun]

hows the content though? legible even w bad formatting? correct?

[broken dome]

I'm checking don't rush me

[iron meadow]

i don't see what's so bad about the formatting? looks clean to me

[tall sun]

oops not trying to rush you, thought i confused you with "how does it look"

[tall sun]

for word yeah, but the fractions aren't looking like fractions with one thing on top one on bottom

[tall sun]

at least thats what i think she means

[iron meadow]

so what? i assume you're probably in high school? it's not like you're expected to know how to do mathematical type scripting in high school

[tall sun]

true so it won't make or break anything, esp bc this isnt rlly graded, it's just a note ig

[velvet cedar]

a, b and c all seem right

Haven't checked d

[tall sun]

yoooo c i was nervous about c

[broken dome]

d seems fishy ngl

[velvet cedar]

Yh

[tall sun]

oh no

[broken dome]

d should have 6 solutions

for some reason

wait

holup

either desmos is drunk

or I am

[tall sun]

uh

ok i was gonna say

that i was being stupid

bc it should just be pi/6 +1/3

and not both of those

but 6???

[iron meadow]

d seems correct to me

🤷‍♂️

[tall sun]

ok 2 say yes one say no

i say kind of

[velvet cedar]

Look at the range

[broken dome]

You guys seeing this?

[velvet cedar]

cos(3x - 1) = 0

cos(t) = 0 -1 < t < 6pi - 1

[broken dome]

This look sane to yall?

[tall sun]

oh

[iron meadow]

@tall sun yeah so you found the solutions for when the input of the cos = pi/2 or 3pi/2, which are correct, but also check other possible values for the input of the cos since you might still have 0 <= theta <= 2pi because of the transformations inside, so check -pi/2 -3pi/2, 5pi/2 ... etc until theta is no longer in the correct domain

[tall sun]

oh so there are 6??

[iron meadow]

or another way to think about it: plug in the endpoints of your domain, 0 and 2pi into 3x -1 and you get [-1, 6pi-1] now think of all the values in that interval, which is being plugged into cos that give 0

[tall sun]

oh great heaven

alr lemme try

[broken dome]

proof by exhaustion, my third favourite

right after proof by hindsight and proof by intimidation

[tall sun]

my favorite is proof by yeast

idk what you are talking about

[vernal mantle]

Pol pot ahh proof

[broken dome]

lmao what?

[velvet cedar]

https://en.m.wikipedia.org/wiki/Pol_Pot

Sorry about the ping

[vernal mantle]

Communist dictator proof

[broken dome]

Ah yes, a man of culture proof, exactly

[vernal mantle]

Bro didn't even fully understand communism 😭

[broken dome]

There are 2 kinds of people on this earth, those who want communism and those who understand it

[marsh citrus]

@tall sun Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[potent burrow]

hello

[lone wharf]

hi

[marsh citrus]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

@potent burrow Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[spiral plank]

can someone let me know why my answers are wrong

[marsh citrus]

@spiral plank Has your question been resolved?

[spiral plank]

@fluid mica

wait sorry

<@&286206848099549185>

[uncut oasis]

Pretty sure you didn't integrate the series back

[glass silo]

c1 is the coefficient of x^1, c2 the coefficient of x^2, etc presumably?

[glass silo]

She did

[uncut oasis]

Also, I'm not really that familiar with series, but are you sure 1/1-x^2= the series of x^2n?

[uncut oasis]

She multiplied the x there

(or so I think)

Nvm, she did integrate it

Just didn't see it, hm

[glass silo]

Nonetheless-

[marsh citrus]

@spiral plank Has your question been resolved?

[spiral plank]

ohhhh i think youre right chartbit

ill try doing 0 for the terms with no x power

omg you were right chartbit so smart

tyyyy

.close

[marsh citrus]

Channel closed

Closed by @spiral plank

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[drifting wyvern]

Does this correlate with the negative and positive planes, like uh

This

Would it go off of this, or is it only for reference questions

[marsh citrus]

@drifting wyvern Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[twin tapir]

can sum1 help me w this question

[tired ore]

you know that the sum of angles in a triangle are 180 degrees so you can set up an equation to solve for x, and plug it back in

[twin tapir]

can i just (5x - 12) + (4x + 8) = 180˚???

nvm i don think that works

[tired ore]

its almost correct, just remember what isosceles means

[twin tapir]

isosceles have two equal sides?

[tired ore]

yep

[twin tapir]

ohh wait.

so (5x - 12) + (5x - 12) + (4x + 8) = 180˚??

[tired ore]

yeah

[twin tapir]

ohhh

thank youu

.close

[marsh citrus]

Channel closed

Closed by @twin tapir

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[whole berry]

can anyone explain why the gradient of the product of a matrix(A) and x(a vector I suppose), is equal to the transpose of A, as for the other statement I don't understand anything of it if someone could explain what is the gradient of a matrix referencing, and what does the x^T mean sorry if I'm asking for too much

[marsh citrus]

@whole berry Has your question been resolved?

[whole berry]

<@&286206848099549185>

[lofty gyro]

i wish i can help, but im workin in 5mins
the hint will be expand the expressions, also A is matrix with constants only

and x^T is the transpose of column vector x

[whole berry]

does the product of a matrix and a vector change depending on the shape of a vector?

just answer that brief question, I'm still trying to figure out everything else

[marsh citrus]

@whole berry Has your question been resolved?

[whole berry]

where did he go 😭

[odd crest]

to work

i'm guessing you know what $\vec{x}$ means

[elfin berry]

Katharine

[odd crest]

$\begin{pmatrix} x \ y \ z \end{pmatrix}$

[elfin berry]

Katharine

[odd crest]

$\vec{x}^{T} = \begin{pmatrix} x & y & z \end{pmatrix}$

[elfin berry]

Katharine

[odd crest]

try to think of it as some matrix that you transpose

but instead of being 3x3 or 2x4 or something like that

it's Nx1 and the transpose is a 1xN

[marsh citrus]

@whole berry Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[steel iris]

A B, ,C and D are points on a straight line so that AB= BC = CD. Also, BPQC is a parallelogram. If BP BC = 2 , prove that PD is perpendicular to AQ

[steel iris]

.close

[marsh citrus]

Channel closed

Closed by @steel iris

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

Why do we need a homogenous and particular solution for a ODE with forcing?

[marsh citrus]

@still temple Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tall sun]

did i get these right?

[dusky viper]

first one is incorrect

[glossy flint]

It's correct, isn't it?

[dusky viper]

ah yes it is

didnt read the domain

[glossy flint]

Yeah at first I didn't too 😅

[tall sun]

oh phew

5 is ok, how about 4 and 1? im pretty confident tbh but if i mess up at one of these i need to know before my test on friday

[dusky viper]

others look fine

[tall sun]

yayyy

thanks!

.close

[marsh citrus]

Channel closed

Closed by @tall sun

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sterile matrix]

for this question if they ask how much interest this persons paid is there a way to figure that out using sequences

Cause I’m using the sequences app on a classpad and I have no idea how to solve for that

[marsh citrus]

@sterile matrix Has your question been resolved?

Channel closed

Closed by @sterile matrix

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cosmic veldt]

any1 help pls, for

[cosmic veldt]

for this

derivative hits x axis at 2.31 whatever which is the 1st

like 'maximum'

why isnt anything after it considered

i.e. when blue hits a 2nd maxiumum later on?

answer is

[devout mauve]

well before that the population turns negative

which is an indicator that the model stops working

and shouldnt be followed anymore

[cosmic veldt]

oh

true

thanks

.close

[marsh citrus]

Channel closed

Closed by @cosmic veldt

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[oblique field]

help how do i solve these

[oblique field]

im pretty sure the answer to this is 3/5

[whole quiver]

substitute x=4

[oblique field]

and this one is the last option

[whole quiver]

and it's 3/5

[whole quiver]

open the whole square

add it with 8 and tell me the eqn

[oblique field]

XER
(x-4)^2 > 0
(x-4)^2 + 8 > 8

= {Y E R, Y>8}

[whole quiver]

uh

what did you do

[oblique field]

idk tbh

i graphed it at 4,8 and then did it

im confused

[oblique field]

is it 8, infinite

[whole quiver]

no like

see

y = (x-4)²+8
y = x²+16-8x+8
therefore
y = x²-8x+24

[oblique field]

oh

and then what

[whole quiver]

now there are 2 possible methods to solve it

[oblique field]

vertex form?

[whole quiver]

yeah

[oblique field]

I know how to do that you get 8,∞

Im just confused on which option to select

[whole quiver]

a range of quadratic reqn

is determined by

(-D/4a, infinity) if

a > 0

D = discriminant

[oblique field]

ohhh

[whole quiver]

yes

and for a < 0

it's

(-infinite, -D/4a)

[oblique field]

mhmm

i see

Okay then

what about this question

so using the vlt

it would be the second graph

[whole quiver]

tbh i am poor at graphs

but i think 2

[oblique field]

Yes it was correct

lol

[whole quiver]

yea

[oblique field]

thank you:>

[whole quiver]

np

[oblique field]

thats all

[whole quiver]

you can close it using: .close

[oblique field]

Okay!

.close

[marsh citrus]

Channel closed

Closed by @oblique field

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tall sun]

i only get pi/2 but thats not an option is what i have selected right and also why??

[naive fox]

because it is not only pi/2

[bitter terrace]

did you cross out the cos?

[spark otter]

if you "crossed" out the cos, then you forgot what operation happened when you do that

[tall sun]

yes well I am more likely to be wrong than the thing but I do not know what my error was so

[bitter terrace]

did you like

just say sintheta=1

you should have a value for your costheta as well

if you divided them, youve lost an answer

[naive fox]

yeah, because sin(x) = 1 will only yield you one solution

you can look at the period of the function to also find that there will be 2 intersections

because cot(x) has period of pi and cos(x) has period of 2pi

[tall sun]

ughhh this is weird why do calculators make the same mistake

[spark otter]

well before "simplifying" you need to make sure the thing you're simplifying by is not 0

[tall sun]

yeah true

well i guess i got halfway there

[tall sun]

pi/2 is still one of the correct ones though right

[bitter terrace]

yep

[tall sun]

ayy 50 percent

thanks all that was kind of embarassing

.close

[marsh citrus]

Channel closed

Closed by @tall sun

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[near elbow]

guys, how to do completing the square for y = -4x^2+16x-7?

[near elbow]

for negative equations

[glossy flint]

Factor out a minus sign

[sacred idol]

take - common

-(4x^2 - 16x + 7)

or just the entire -4 for that part

-4(x^2 - 4x) - 7
= -4(x^2 - 4x + 4 - 4) - 7
= -4(x^2 - 4x + 4) + 16 - 7
= -4(x-2)^2 + 9

= (3 - 2(x-2))(3 + 2(x-2))

and so on

if youre interested in factoring that is

[near elbow]

ooohh

guys i thought a quadratic number should not be pulled out

like we shouldn’t make -4 outside the bracket

[sacred idol]

where is it mentioned so?

[near elbow]

i was told like that 😂

[sacred idol]

by who 🤔

oops

[near elbow]

i think it’s for (ax+b)^2 + c

btw guys, if an equation is like this
-(2x-4)^2 + 9

can we not take 4 and 9 as the turning point coordinate?

[sacred idol]

wdym 4 and 9?

(4, 9)?

[near elbow]

yes

[near elbow]

yes

[sacred idol]

nope; turning point coordinate is $(\frac{-b}{2a}, \frac{-D}{4a})$, where D is the discriminant $(b^2 - 4ac)$

[near elbow]

ooohh

okk thank you so much

[near elbow]

thank youu

[marsh citrus]

@near elbow Has your question been resolved?

[near elbow]

.close

[marsh citrus]

Channel closed

Closed by @near elbow

Use .reopen if this was a mistake.

Channel closed

Closed by @near elbow

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[charred venture]

could someone help me with this please

[charred venture]

what is a discriminant and how do I find it

[red cloud]

the root term in the quadratic formula

[charred venture]

what is a root term

[red cloud]

like an equation in a square root

[charred venture]

okay so whats my first step 💔

[red cloud]

do you know the quadratic formula?

[charred venture]

nope

MY BAD

[red cloud]

how are you doing quadratic equation without that formula...

[charred venture]

online grade 11 math

[red cloud]

this one

[charred venture]

okay

[mighty gyro]

💀💀

[charred venture]

not funny

[mighty gyro]

I think they teach that in 9th??

[red cloud]

so like the term in the square root is the discriminant!

[red cloud]

probably the system is different for them

[mighty gyro]

Maybe

[charred venture]

I hate canada

[mighty gyro]

Hmm

[red cloud]

you get this?

[charred venture]

not really idk what the term in the square root is

guys I got a 51 in math last year

[eager tinsel]

ig, you should revise/learn about quadratic equations a bit, before diving right into questions

[charred venture]

well this is the math class im taking so I dont have to do math ever again

ill watch quadratic youtubes vids or smt

💔

Akka ur a real one

[red cloud]

and if you need help, feel free to message!

[charred venture]

.close

[marsh citrus]

Channel closed

Closed by @charred venture

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tall sun]

sqrt2+sqrt6/4

[tall sun]

,w cos(-15)

[elfin berry]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by cattdog

[tall sun]

hm

is the exact value sqrt2+sqrt5/4?

[jagged relic]

Why sqrt5?

[tall sun]

oop

[tall sun]

meant sqrt6

misstype

[jagged relic]

Then it's (sqrt2+sqrt6)/4, yes

[tall sun]

yayyy

thanks!

.close

[marsh citrus]

Channel closed

Closed by @tall sun

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hot dock]

does this contain the zero polynomial?

[marsh citrus]

@hot dock Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tall sun]

is this right? fixed it earlier but i wasnt sure then and im not sure now

[marsh citrus]

@tall sun Has your question been resolved?

[tall sun]

<@&286206848099549185>

[tall sun]

.close

[marsh citrus]

Channel closed

Closed by @tall sun

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tall sun]

is B correct?

[shadow thicket]

technically both b and c is correct

[whole quiver]

I mean it's not wrong

yea

but do c

it's safer option

[tall sun]

oh?

how can both be right?

[shadow thicket]

bruh

wait

[cloud thistle]

3 choose 0 = 3 choose 3 and 3 choose 1 = 3 choose 2

[elfin berry]

r02

[shadow thicket]

i was trying to send this

[tall sun]

ah

so you agree c is the better option?

[shadow thicket]

yeah

[tall sun]

why didnt they just say "best option" instead of correct

[blazing ferry]

I think that only one is correct, because when solving with the binomial theorem, one of the terms remains as the first and the other as the second, although the result is the same, the process is different.

[tall sun]

oh

[cloud thistle]

they are both right and none is better but id guess whoever was making the wrong answers made a mistake

[tall sun]

hhhhhh that's so stupid this is a practice test

[shadow thicket]

they are both right

[cloud thistle]

but since addition is commutative both work just fine.

[tall sun]

like its ungraded but it's literally a reused test

[whole quiver]

go on with c, in text books they generally starts with x³

[tall sun]

yeah I guess so

thanks guys

.close

[marsh citrus]

Channel closed

Closed by @tall sun

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vestal rock]

if triangle abc sides are b=13.5 and c=8.9 and angle A is 29 deg is side a 7.2?

[shadow thicket]

you can use law of cosines to find

and can you send image of triangle

[vestal rock]

um no image

i did use law im just trying to check

i was looking for side A and got 7.2

[shadow thicket]

it is ~7.16 so yeah

[vestal rock]

close enough ig?

is that a neg sign??

[shadow thicket]

no

length cannot be negative

~ = approximately

it would be better if i used ≈

[vestal rock]

oh i just cant see

its not - its ~

ok so i'm all good?

[shadow thicket]

if you say 7.2 is close enough, you are good

[vestal rock]

yeah ig

thanks!
.close

.close

[marsh citrus]

Channel closed

Closed by @vestal rock

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vestal rock]

A small town holds a raffle once a week in which the winner gets $1000. Every one of the 100 residents have an equal chance of winning the prize each week.

After 12 weeks, what is the probability that a town resident will win the raffle once?

[vestal rock]

0.11 chance?

[daring cradle]

Assuming that each week there is always a winner

And it’s exactly once in 12 weeks

It’s 12c1 .99^11*.01

[vestal rock]

c1?

well that is nearly 0.11

[daring cradle]

12 choose 1

=12

Its combinatorics

[vestal rock]

ah yes

its been like a month i forgot

sorry

yeah basically 0.11

thanks!

[daring cradle]

👌

[vestal rock]

.close

[marsh citrus]

Channel closed

Closed by @vestal rock

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wary bluff]

We want to construct a 95% CI for the length of iron rods produced by a certain factory. We know that these rods range in length from about 0.96m to about 1.04m. If we want the entire width of the confidence interval to be equal to 0.05m, what is the required sample size?

[wary bluff]

WHat I have done so far:

s.d = range/4 = 1.04-0.96 / 4 = 0.08/4 = 0.02
zstar for 95% = 1.96

0.05 = ( (1.96 * 0.02)/sqrt(n))
n = ( (1.96 * 0.02)/0.05))^2

is this correct?

[daring cradle]

Ur assuming sizes r uniformly distributed

But it doesn’t say so

At the same time

If u don’t assume it then I don’t see how this q is solvable

[wary bluff]

how would u have solved this q

[daring cradle]

I can’t

Without assuming uniform lol

If u do

[wary bluff]

alr with assuming uniform how would u

[daring cradle]

Then use the var formula

For it

Your var formula is wrong

[wary bluff]

whats wrong with it

[daring cradle]

It’s (b-a)^2/12

You divide by 4

Instead of by root12

[wary bluff]

thats what it said in the lec slides one sec

I thought I was suppose to use this

this is like 3 slides before the question

[daring cradle]

Ok then I guess you use that approximation then

Since it doesn’t say uniform

[wary bluff]

so my soln would be considered correct?

[daring cradle]

Ye

[wary bluff]

coz I also asked gpt and it gave something similiar but instead it multiplied rhs by 2

[daring cradle]

Wait no

You need to divide

0.05 by 2

[wary bluff]

oh

[daring cradle]

Cuz it’s entire width

Not halfwidth

[wary bluff]

I see

tysm

.close

[marsh citrus]

Channel closed

Closed by @wary bluff

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[polar dragon]

Finn wants to know the length of a large pond on his property. He places a stake 30 m from
one end of the pond at an angle of 15 degrees. The stake is 50 m from the other end of the pond. To
the nearest metre, how long is the pond? Who can solve this pls using the cosine law so I could compare between my answer and his

[marsh citrus]

@polar dragon Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[polar dragon]

.reopen

[marsh citrus]

✅

[polar dragon]

<@&286206848099549185>

[proud ice]

angle of 15 degrees measured from what?

[marsh citrus]

@polar dragon Has your question been resolved?

[polar dragon]

\

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[polar dragon]

.reopen

[marsh citrus]

✅

[polar dragon]

<@&286206848099549185>

[mighty gyro]

What did u try

[polar dragon]

yes, but first of all, could it even be calculated by law of cosines. It seems to be incorrect

[mighty gyro]

Yes u can

Ig

[polar dragon]

if so I calculated it to be 22 cm thoughI had an answer key that got it 77 cm since they used the law of sines, thats y Im asking

so I thought maybe It couldn't even be solved by the cosine law

have any clue?

[marsh citrus]

@polar dragon Has your question been resolved?

[mighty gyro]

Idk man

[marsh citrus]

@polar dragon Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[brave spire]

$$ \frac{d^{\ell + m}}{dx^{\ell + m}} (\sin^{\ell}(\theta)) $$

[elfin berry]

rak³en

[brave spire]

How would one evaluate this using cauchy;s formula for differentiation?

I think U here is the entire complex plane

because my function sin^l(theta) remains defined for all complex numbers

and iirc z_0 is the singularity

but sin doesnt have a singularity iirc

sooo all thats left is determining r

which is determined by gamma ig?

[hushed egret]

this seems like a pretty terrible way to compute the derivative

[brave spire]

i wouldnt try use that

[hushed egret]

also your variables don't match

[brave spire]

generalised chain rule formula

[brave spire]

wdym?

[hushed egret]

d/dx and then sin(theta)

[brave spire]

oh right mb should be theta

sorry sorry

[hushed egret]

like evaluating the contour integral is arguably worse

[sleek birch]

How can

i make a avaliable channel

[limber hearth]

https://discord.com/channels/268882317391429632/488120190538743810

[marsh citrus]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[brave spire]

hmm

well i dont understand the generalised chain rule

[hushed egret]

typically you actually have access to the derivatives prior to even attempting to compute the contour integrals

[brave spire]

i definitely have a better (but still very bad) understand of this

[hushed egret]

because contour integrals are usually computed using the residue theorem

[brave spire]

ah 🤔

[brave spire]

ah yes the residue theorem, another thing i have yet to learn

[hushed egret]

i'm not sure reading this off wikipedia counts as learning but you do you

[brave spire]

this is why i dont like the generalized chain rule

[hushed egret]

well that's just ridiculous

[brave spire]

i am watching a course on complex analysis. i just reached countour integration yesterday, so no I am not reading things off of wikipedia

[brave spire]

this whole shenanigan is for trying to solve a MSE problem (its alr solved I am looking for aliters)

[hushed egret]

okay well it seems like you're overcomplicating the problem

[brave spire]

i shouldnt have xyed 🤦‍♂️

this is the integral I want to evaluate

I thought IBP, but thats just gonna give me a reduction formula

I dont think I can find a solution for it

[hushed egret]

a to b?

[brave spire]

i was tempted to see if differentiating under the integral sign gives something cool, but my inution says it wont work

[brave spire]

real constants in [0, pi]

[hushed egret]

any random a to b?

that's just messy

[brave spire]

well, cant really do nothing about it

[hushed egret]

if a and b were on the end points you could at least IBP for free

but now you get a huge mess

[brave spire]

oh and yeah maybe the indef integral is easier to evaluate

[brave spire]

well, thats what the problem asks for

[jagged oracle]

Here for help

[red nimbus]

lol did you lose helpful

[jagged oracle]

;-;

I saw it now

But how

I was only here to help 🙂

[red nimbus]

hmm weird, did you say something in hlounge

[jagged oracle]

No

I ping people often for their help

Like I help them

And then ping

That's why I feel i got timed out

[marsh citrus]

@brave spire Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[grand pawn]

pls help i have no idea how to do it

nope

i dont understand tangents and stuff

ok

@remote parcel plsss help

<@&286206848099549185>

[viral jacinth]

Don't ping helpers repeatedly

[grand pawn]

oop sorry

[viral jacinth]

Np

[silver heath]

hi

sup

[grand pawn]

hi

can u help plss

[silver heath]

yea

send problem

[grand pawn]

i don't get tangents

[silver heath]

can u wait for

like 10 mins

or 20?

[grand pawn]

umm

i have to go soon

[silver heath]

some guy is askin rn

[grand pawn]

oh

wait

can i dm u the question

and solve it like tmr or smth

cuz its late for me rn

[silver heath]

sup

ill do now

[grand pawn]

ok

ty

[silver heath]

so uh

u are sayin

no tangents will come?

[grand pawn]

no

i have the diagram

but idk how to prove

like idk what reasoning

[silver heath]

okay

so take a white paper

[grand pawn]

ye

[silver heath]

Draw a line through X perpendicular to IX (the radius of K at X). This line is the tangent to K at X.

[grand pawn]

whats IX

[silver heath]

l is line

u mentioned

[grand pawn]

oh

[silver heath]

X is pt on L

[grand pawn]

ye

[silver heath]

YEAH

did u draw

[grand pawn]

ye

[silver heath]

ok now

this line

is tangent to K

at x

[grand pawn]

ye

like it touches k at once at x?

[silver heath]

yeah

[grand pawn]

ok

i get that part

i just dk how to prove

[silver heath]

now listen

[grand pawn]

mhm

[silver heath]

draw line thru Y perpendicular to LY too

both are on same circle right?

[grand pawn]

ye

[silver heath]

yeAH

so

line is tangent to k at y

[grand pawn]

ok i give up

[silver heath]

lol

i wish i could send

but im on pc

[grand pawn]

ohh

[silver heath]

wait

ill try

[grand pawn]

oki

[silver heath]

i should ask ma fiend

[grand pawn]

lol

can i dm u later

[silver heath]

ok

[grand pawn]

cuz i rlly gtg

sorry

but ty for trying to help

[silver heath]

ok

[grand pawn]

.close

[marsh citrus]

Channel closed

Closed by @grand pawn

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[velvet elk]

So a questionare asked for the range of the following domain (-1,0,1,2) and I had to plugin them to y²=x²+1 and got y = ±√2 y = ±1 y = ±√2 and y = ±√5

Is it a function or mere relation?

[sacred idol]

based on the definition of a function, it is a mere relation

since one input (0 for example) has two outputs (+1 and -1) mapped to it

[velvet elk]

If I were to draw a box

it would be like this

x -1 0 1 2
y ±√2 ±1 ± √2 ±√5

Or {(-1,±√2),(0,±1),(1, ±√2),(2,±√5)}

[lean vortex]

Hey

[lean vortex]

we need to check if each input (x-value) corresponds to exactly one output (y-value).
In this case, the given relation is y² = x² + 1.
By analyzing

• x = -1: y² = (-1)² + 1 = 2 => y = ±√2 (two outputs)
• x = 0: y² = 0² + 1 = 1 => y = ±1 (two outputs)
• x = 1: y² = 1² + 1 = 2 => y = ±√2 (two outputs)
• x = 2: y² = 2² + 1 = 5 => y = ±√5 (two outputs)
  Since each input corresponds to two outputs, this relation is not a function. It's a mere relation.
  In a function, each input must correspond to exactly one output. Here, each input corresponds to two outputs, so it doesn't meet the criteria for a function.

[velvet elk]

Okay thank you

.close

[lean vortex]

Ye close

[marsh citrus]

Channel closed

Closed by @velvet elk

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vagrant granite]

,w Integrate x/(4+x^2)^1/2

[elfin berry]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by integrateseverything

[vagrant granite]

Can I use trig sub for this

I supposed x = 4Tantheta

[lean vortex]

Is the doubt yet clarified?

What's the doubt womp

[vagrant granite]

Can I use trig substitution bro

[vagrant granite]

And why am I getting a different answer from this

[uncut oasis]

You probably could but it's kind of an overkill

Just use u=4+x^2

Since you've got that x up there

[marsh citrus]

@vagrant granite Has your question been resolved?

[vagrant granite]

Okas

Gracias

.close

[marsh citrus]

Channel closed

Closed by @vagrant granite

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frosty minnow]

a coin is tossed 8 times, what is probability that head appears exactly 3 times

[frosty minnow]

what i understand is, 3 heads have 8 places to arrange themselves on

[sacred idol]

you can use binomial distribution if you know what that is

[frosty minnow]

i know

explain me how to apply it

[sacred idol]

you know that x = 3 and n = 8

[frosty minnow]

wait

[sacred idol]

im assuming youre saying that you know the formula below

[frosty minnow]

yes I know

is there only binomial formula to solve this

[sacred idol]

not really

but its the easiest

[frosty minnow]

can it be done with basic probability

[sacred idol]

yeah

it would indirectly use this anyways

[frosty minnow]

I'm getting confused where to apply which method. I was thinking about which method to use and binomial didn't come to mind

because just saying "exactly 3 heads in 8 throws" sounds like a simple question

[sacred idol]

any formula which involves a number of trials and a definite chance of succeeding/failing is suitable for applying BD

here you toss a coin 8 times and the probability of succeeding is 0.5

and you need only 3 heads

that is exactly 3 success cases

[frosty minnow]

.close

[marsh citrus]

Channel closed

Closed by @frosty minnow

Use .reopen if this was a mistake.

[sacred idol]

or you can just reason it out

[frosty minnow]

oh god

[sacred idol]

nCx ways of distributing heads

oh

[frosty minnow]

i didn't know your were typing and i closed it

[sacred idol]

its alr

[frosty minnow]

.close

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[compact ether]

Can anyone help me with this question please? "The side of a square is x cm long. The length of a rectangle is 5 cm longer than the side of the square and the width is 5 cm shorter. What is the area of the rectangle? Which has the greater area the square or the rectangle?

My teacher gave me this homework but didnt teach me how to solve it so im confused. I tried researching but i still can't get it

[midnight heron]

Comparing the areas x^2 is greater than x^2 -25

So area of square should be greater than the area of reacangle

[whole quiver]

,rotate

[whole quiver]

yea proceed, what you were typing

[past estuary]

Okay

So look at it like three different scenarios

Either the rectangle is bigger or smaller or the same

And you already have formulas for both

Let's start with assumptions their the same

So set both equations equal to eachother

And then you can simplify

[midnight heron]

By comparing the 2 areas we can say that x^1/2 >x^1/2 -25

Also as we are reducing 5 cm from the side we should consider values of x from more than 5