help-33

[fierce jewel]

haha

you could watch some khan academy videos on trig substitution for integration on yt

he has explained it pretty well

[fickle shell]

Why are we taking the derivative of 2x=sin(a) instead of the integral of 1/cos(arcsin(2x))

[fickle shell]

Yeah hes great I definatly will

[fierce jewel]

its simply because its easier to do it

what our aim with trig substitution was

to make the question easier

why do we substitute in general during integration

its so that we get a simpler function that we can integrate easily

[fierce jewel]

and we are taking derivative because

we are getting this relation

2dx = cos(a) da

and we had
[1/cos(a)] dx

so replace dx with cos(a) da/2

cos(a) will get cancelled

all you have left is da/2

whose integration is just a/2

[fickle shell]

Aaaaaaaaaaaaaaah

I seeeeeeeee

[fierce jewel]

and we originally said 2x = sin(a)

[fierce jewel]

which means

we can say that

arcsin(2x) = a

[fierce jewel]

so your answer becomes arcsin(2x)/2

[fickle shell]

I get it now

[fierce jewel]

the whole solution , so you can understand it

[fickle shell]

It all came together in my brain right at the end 😂

Thank you so much

[fierce jewel]

lol

[fickle shell]

Youre an amazing teacher and thank you for being so patient with me

[fierce jewel]

no problem

[fickle shell]

I will go do more examples of this in a min but I need a break first hahaha

[fierce jewel]

thank you

[fickle shell]

Thanks again!!

❤️

.close

[marsh citrus]

Channel closed

Closed by @fickle shell

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frosty thicket]

if an object begins at the vanishing point and approaches the camera at constant velocity in real world space, what is the rate at which the object scales in respect to time? That is, how do i model the objects size with respect to t

[fervent idol]

the r scales in linear fashion but since area of the circle is connected with r^2 the object scales in r^2 terms

[frosty thicket]

thank you for the answer. can you simplify what linear fashion means for me?

[fervent idol]

as in "the change in r is constant"

[frosty thicket]

okay, thank you!

and by r, what variable is it?

[fervent idol]

the diameter

[frosty thicket]

thank you

[fervent idol]

*half diameter

[frosty thicket]

so the shape of the camera is a factor?

[fervent idol]

i dont think so

[frosty thicket]

how is the area of the circle related to this?

[fervent idol]

consider this

a sphere is coming from the horizon to the camera in a constant velocity

the radius of the sphere is increasing in a constant manner

but that means the area of the circle coming to you increases with respect to the circle area formula

which is pi * r^2

[frosty thicket]

is it possible to translate this into an equation?

[fervent idol]

lets define the variables then:

• z(t): distance of the object to the camera with respect to t
• S(t): the size of the area of the sphere visible from the camera with respect to t

we can say that z(t) is just the starting distance of the sphere - vt (speed times time) = z_0 - vt

we know that z(t) and S(t) have a negative relation since the less the distance the bigger the sphere, adding the squared notion to the equation there should be a relation like $S(t) \propto \frac{1}{z(t)^2}$

[elfin berry]

Rootsyl
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[fervent idol]

using some geometry, pen and paper one should be able to find the exact equation

but honestly a physics person should be better suited for this kind of question

[frosty thicket]

what's a propto

is that the infinity-like sign

[fervent idol]

it means proportional to

there is a relation

[frosty thicket]

so the main equation is 1/z(t)²?

[fervent idol]

there should be some other parameters but if the radius increases linearly then yes

other parameters like the altitudes, the camera fov, the initial distance

[frosty thicket]

this is just for a sphere?

what if they're 3d objects like a cube, or a prism

[fervent idol]

then you gotta model the increase of a metric of the item

[frosty thicket]

in this context, the camera does not move. it is stationary

[fervent idol]

yea but fov can be changed and it makes the camera see a thinner or broader area

altering the percieved reality to change

[frosty thicket]

would it still be 1/z(t)²?

[fervent idol]

probably not

you need a modeled metric to get a definite equation

a metric of the item that you know how it changes with respect to time

are you just curious on this question or is there a source you found it from?

with more context i could give a more definite answer

[frosty thicket]

im just curious lol

but what you said made a lot of sense

so thank you!

[fervent idol]

sry i couldnt give a definite answer

[frosty thicket]

it was enough to not make me curious anymore anyway since it still made sense so you still did help me

[teal arch]

Omg kanna

[marsh citrus]

@frosty thicket Has your question been resolved?

Channel closed

Closed by @frosty thicket

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[marsh citrus]

Please don't occupy multiple help channels.

[teal arch]

Where u stuck

[sleek swan]

this angle here and the angle d are equal as they are alternate angles (angles in a Z shape)

if you can work out that red angle, then you should be able to work out what d is

[west perch]

is the red angle 73 - 180?

[ripe knoll]

Look

[sleek swan]

almost

[ripe knoll]

from vertically opposite angles we can see that theres also a 73 degree angle on the opposite side of the first one

[sleek swan]

thatd give -107 as the angle but that wouldnt make sense because angles must be positive

[ripe knoll]

we can add both the 73 degree angles and then subtract them from 180 that should give you your final answer

[west perch]

its 107

[marsh citrus]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[lethal bridge]

wait nevermind

i tghought u were someone else

LOL

[ripe knoll]

who pinged

[lethal bridge]

do u have an idea of what to do

[west perch]

nope

i just need answers

[ripe knoll]

i just explained a similar question to you bruh-

[west perch]

my ass gonna get beat if i dont pleu

[lethal bridge]

we cant do it for u

[ripe knoll]

who gonna beat you

[lethal bridge]

we can only show you how to get there

[west perch]

mama

[ripe knoll]

bruh

ok 1 lastt time

ima just tell you

how to do it

alr?

[ripe knoll]

X = 1,2
2.
x=3,4
3.
x= 5,6

now just add both numbers and divide by their frequencies

[west perch]

ok

got it

im so dead

[marsh citrus]

@west perch Has your question been resolved?

[marsh citrus]

@west perch Has your question been resolved?

[jagged oracle]

a is parallelogram and b is kite c is trapezium and d is rectangle

x=65 corresponding angles I think @west perch

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[broken ivy]

What the hells the approach supposed to be to this question?

[jagged oracle]

Listen bro

Do u know sin and cos product series

[broken ivy]

Nope never learnt it

[jagged oracle]

Then it will be tough

Listen bro

[broken ivy]

Damn. It's a differential question. Under what topic is the series supposed to be? Trig? Gp?

[broken ivy]

Yeah

[jagged oracle]

Differential equations?

Na bro

It under trigonometric identities and trig series

[broken ivy]

Yeah it was in my derivative assignment

[jagged oracle]

Oh

Oh

Oh

For real bro

Got it

Listen take log both sides

[broken ivy]

Yeah man

Alright makes sense

[jagged oracle]

Then differentiate u will get the answer

Diff w.r.t to theta

[broken ivy]

Yeah I tried that but I don't get the progression

Like understand it

[jagged oracle]

B

ncotntheta

Listen bro when u take log both sides

It becomes

ln(sin t)+ln(sin(2a+t)+------ so on =ln(sin nt)-ln(2n-1)

Now diff w.r.t t

U get the down series

cot t + cot(2a+t)+------so on =cotnt . N

Using chain rule

@broken ivy

[broken ivy]

Rightt yeah makes sense I did a similar question with a cos and tan series and got that but yeah I just didn't get this series thanks bro

[marsh citrus]

@broken ivy Has your question been resolved?

[jagged oracle]

Welcome

[marsh citrus]

Channel closed

Closed by @broken ivy

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rocky nova]

I get 46 fruits per 1500 seeds. Seeds now come in packs of 1800 but I still want to maintain the same ratio of fruit per seed. How many fruit can I expect?

[rocky nova]

My logic is 46 / 1500 = new_fruit_number / 1800

so then new_fruit_number = (46 / 1500) * 1800

which would be 52.2 is that correct?

I think it is wrong because when I calculate the seed to fruit ratio I get different numbers

old = 46 / 1500 = 0.030666666

new = 52.2 / 1800 = 0.029

how does that make sense?

[humble lintel]

try putting this in your calculator again, you should get 55.2

then checking the ratio, 55.2/1800 = 0.03066666666666 and it works out

[rocky nova]

Ah, yes. I wrote it down wrong, thanks

[humble lintel]

always the little mistakes, good use of logic on the problem though

[rocky nova]

thanks @humble lintel

!close

.close

[marsh citrus]

Channel closed

Closed by @rocky nova

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[near fossil]

Hi

[near fossil]

I need help with slope

What is the slope for this

<@&286206848099549185>

[idle ridge]

Please don't ping Helpers before 15 minutes have passed

[limber hearth]

Take two points on the line and be sure that they are on a square

[near fossil]

Sorry

?

How

[prime cypress]

how is the slope defined?

[near fossil]

Idk

[real crescent]

slope is change in y divided by change in x

[prime cypress]

if you go 1 to the left and 1 up the slope is 1
if you go 1 to the left and 3 up its 3
if you go 5 to the left and 1 up its 1/5

so choose two points on the line and calculate it

[prime cypress]

you get the principle?

[near fossil]

Ye

[prime cypress]

so what would two points be on the line?

[near fossil]

Idk

[real crescent]

you need to look at the graph and decide which 2 points you wanna consider

[prime cypress]

for example is the point (0,0) on the line?

[real crescent]

can you tell me the point where the line passes through y axis

?

nvm, gandhi, take it from here

[prime cypress]

:/

[next apex]

so im guessing (-3; 2) and (-1; 3) are part of the line, right?

you can do it with linear functions, with some triangles, or more simply with the definition of a slope

[near fossil]

Can y’all just give me answer?

[idle ridge]

!noans

[marsh citrus]

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

@near fossil Has your question been resolved?

[half salmon]

right*

[prime cypress]

oh yeah im dumb xD

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pearl gulch]

So, I want to relate the functions to their respective graphs and level curves.

[pearl gulch]

As for the graphs, it is okay for me to do that. But I don't know how to look at a function and relate it to a level curve. I don't know where to start

How can I look at a function (whether exponential, trigonometric, etc.) and get an idea of how its level curve representation would look?

[marsh citrus]

@pearl gulch Has your question been resolved?

[pearl gulch]

<@&286206848099549185>

[limber hearth]

The trig got waves

And for this exponential specially, its the gaussian exponential and his curve in 2d look like a hill

[pearl gulch]

So it's ii - A - III, right?

[limber hearth]

Id say that yeah

[pearl gulch]

but I don't understand why the III look like that

these blank spaces

[limber hearth]

The blank represent relief, more its high,more its blank

In that case

What would it be for other ?

[pearl gulch]

Idk

[pearl gulch]

so they're useless in this case?

[limber hearth]

Theyre not useless, id say that its less understandable.

Compare the graph and the level curve and see what it represent

[pearl gulch]

maybe these "hollows"?

in the graph i mean

[limber hearth]

Yeah, and we need two colors to represent the height difference

Blank for "big" height and Black for "low" height

Its not useless just a different way of representation

[pearl gulch]

Hmm got it

thank you!

.close

[marsh citrus]

Channel closed

Closed by @pearl gulch

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vapid bough]

Can anyone help with this

[brave marsh]

Can you find the period, amplitude and vertical shift from the graph?

Or the points you're given

[vapid bough]

Amplitude would be 3 correct

and period would be 6

and vertical shift is 1 I think im not sure though

[brave marsh]

There is no vertical shift here, so it would be 0. The vertical shift is the average between the highest value and the lowest value.

So (3 + -3)/2 = 0

[vapid bough]

Ohh okay i see

okay then where would i go from that

[brave marsh]

Using this information, you should be able to get a good idea of the formula. In general, $$f(x) = A\sin(\frac{2\pi}{P} (x-h)) + C$$, where $A$ is the amplitude, $P$ is the period, $C$ is the vertical shift and $h$ is a horizontal shift.

[elfin berry]

Azyrashacorki

[brave marsh]

Plug the values you know in there, and use one of the points to find h.

[vapid bough]

Okay let me try it out

3sin(2pi/6(x - h) + C

[brave marsh]

Good. Now try and plug (2,-3) in there, and solve for h

[vapid bough]

Ohh okay so would I plug in 2 for the X, but where would i plug in -3?

[brave marsh]

On the other side. Remember f(x) = 3sin(pi/3(x-h)) and f(2) = -3.

[vapid bough]

ohh okay

f(2) = 3sin(2pi/6(2-h)) -3

[vapid bough]

would it be like that?

[marsh citrus]

@vapid bough Has your question been resolved?

[vapid bough]

.close

[marsh citrus]

Channel closed

Closed by @vapid bough

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mossy kettle]

i am confused with what to do for the last 4 answers in the table, as i was able to solve for the rest and it is right by plugging in the x value but it seems like that does not work for the last 4

[desert dirge]

you sure you did it right

the values dont make sense

[mossy kettle]

i think so?

[desert dirge]

,calc [cos(0.01)-cos(0.06)]/(0.01)^2

[mossy kettle]

i am not 100% sure

[elfin berry]

Result:

[17.494604814611]

[desert dirge]

make sure youre typing right

[mossy kettle]

gimme a sec

weird

[mossy kettle]

if i type that would it work here as well?

[desert dirge]

should do

i think i know the problem

[mossy kettle]

yea?

[desert dirge]

no idea with the 0.01 but the ones after are calculated in degrees

except the last one anyway

thats also random

[mossy kettle]

idk i was using the same calculator

so i thought it would be correct

,calc [cos(0.001)-cos(0.006)]/(0.001)^2

[elfin berry]

Result:

[17.499946041721]

[mossy kettle]

,calc [cos(0.0001)-cos(0.0006)]/(0.0001)^2

[elfin berry]

Result:

[17.499999460657]

[mossy kettle]

,calc [cos(0.00001)-cos(0.00006)]/(0.00001)^2

[elfin berry]

Result:

[17.500000337733]

[mossy kettle]

yea i guess its the problem with the calc i used

[mossy kettle]

because i got those

[desert dirge]

truly odd

[mossy kettle]

maybe it does not have enough brains

like space

or something

[mossy kettle]

thank you

.solved

[marsh citrus]

Channel closed

Closed by @mossy kettle

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[civic path]

can soemone please clarify if my answers are correct

[marsh citrus]

Please don't occupy multiple help channels.

[civic path]

<@&286206848099549185>

[quiet anvil]

!15min

[marsh citrus]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[civic path]

Sorry

[quiet anvil]

!noclopen

[marsh citrus]

Please don't repeatedly close and claim a new channel with the exact same question. This erases all previous progress made towards your problem and is confusing for helpers, making it more difficult to help you. Please be patient, even if your channel has not received much attention.

[quiet anvil]

!show

[marsh citrus]

Show your work, and if possible, explain where you are stuck.

[quiet anvil]

You're asking for if your answers are correct, but you haven't given your answers (in this thread)

[mint galleon]

It's shown in another discussion

Multiposted

[quiet anvil]

I know

[civic path]

I wasn't getting a reply

[quiet anvil]

Yes, but sometimes it takes more than a few minutes

[civic path]

I have been waiting for a proper answer for an hour

Is it possible you could clarify my answers

[quiet anvil]

Your other thread was opened 7 minutes ago, this one 5

[civic path]

I opened another somewhere around 6:15

But I wasn't getting a proper answer

And the helper didn't seem to know the material very well

[quiet anvil]

.

[civic path]

It's ok I'll just figure it out

Thanks for the help

[quiet anvil]

I mean. What do you want me to do exactly?

[mint galleon]

They've already done the problem and want to check their solutions

I suggested plotting the graphs on Desmos to check

[quiet anvil]

I know. And I can go spelunking for their answers in the other thread

But I'm trying to get him to show his work

[mint galleon]

We worked on problem already. Answers were determined ... so

[marsh citrus]

@civic path Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tall sun]

is this correct?

[dusky viper]

yo this is cursed

[tall sun]

i know i know

[dusky viper]

looks correct

[tall sun]

i tried to look it up to confirm and got this hell thing what is even going on here

at first i thought i understood

i did not

[dusky viper]

looks extensive and pointless

[tall sun]

looks like nonsense tbh

[dusky viper]

$\frac{sin^2(\theta)}{1+cos(\theta)} *\frac{1-cos(\theta)}{1-cos(\theta)} = \frac{sin^2(\theta)(1-cos(\theta)}{1-cos^2(\theta)} = \frac{sin^2(\theta)(1-cos(\theta)}{sin^2(\theta)} = 1-cos(\theta)$

[elfin berry]

Galaxy

[marsh citrus]

@tall sun Has your question been resolved?

Channel closed

Closed by @tall sun

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dense lion]

I'm confused on how to start this problem

[sinful thistle]

which part

[dense lion]

part a

i think im overcomplicatingh my thought process

[sinful thistle]

it's an odd question tbh

[dense lion]

would i be something like this

[marsh citrus]

@dense lion Has your question been resolved?

[dense lion]

<@&286206848099549185>

[unique widget]

6.5953?

[marsh citrus]

@dense lion Has your question been resolved?

Channel closed

Closed by @dense lion

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[brisk patrol]

Could anyone explain to me, where did (x^2 + 1 - x) go?

[desert socket]

that was a printing mistake

shoulda been (x^2+1-x^2)

difference of squares

[brisk patrol]

Oh, really, thank you

I just didn't notice it

.close

[marsh citrus]

Channel closed

Closed by @brisk patrol

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[carmine bane]

I need help with

finding 95% confidence interval for population mean

Identifying any potential outliers

Finding IQR

[shadow warren]

do you have a specific question?

[carmine bane]

How do I find it out of data

[shadow warren]

oh god

thats your sample right?

[carmine bane]

Yes

Going up and down is data

Left to right is topic

[shadow warren]

ngl im not that good with google sheets so

im not sure how to quickly do these things

[carmine bane]

How do I do it on paper

[shadow warren]

you need the standard deviation and mean of the sample

we would be using a t interval here since we dont know the population standard dev.

[carmine bane]

I know the mean for items is 6.612

[shadow warren]

okay

now we need the standard deviation

[carmine bane]

How do I find that

[shadow warren]

this but

you can prob find a calculator online for this

this is an awful formula to just plug and chug for

[carmine bane]

Yeah idk how to plug that into a caculaotr

[shadow warren]

https://www.standarddeviationcalculator.io/

here i found this online

put in your data there

and make sure you have it set to sample

[carmine bane]

It says 6.718

[shadow warren]

i mean that makes sense kinda

[shadow warren]

your data is mostly 1's

but then you have a bunch of outliers

[carmine bane]

It’s the numbers that are 1

Or 0 responses

Right?

[shadow warren]

hmm?

its more so like most of your data is 1 or 0

but then you have some that are high

whats your sample size btw

and is this a random sample

[carmine bane]

I believe it’s radome sample

31

[shadow warren]

okay that satisfies one condition

but fails the other

great

[carmine bane]

Radome people filled the survey

[shadow warren]

its fine we can still run the confidence interval

even if one of the conditions arent satisfied

do you know the formula?

[carmine bane]

I don’t 😂 my school lost power for 2nd week in a row and I’ve been out sick and missed class

[shadow warren]

oh its all good

$\bar{x}\pm t^{*}\frac{s}{\sqrt{n}}$

[elfin berry]

y0shi

[shadow warren]

x bar is the mean

s is the sample sd

n is the sample size

[carmine bane]

I think I can plug that into the calculator

[shadow warren]

yeah

hold on lemme get t* for you

its 2.042

[carmine bane]

I can’t find the symbol for what’s to the left of x

I mean right

[shadow warren]

oh thats plus or minus

just do plus first for the upper bound

and minus for the lower bound

a confidence interval has two endpoints

[carmine bane]

Mean+t =8.842

[shadow warren]

uhh did you round?

[carmine bane]

No

[shadow warren]

i got 9.076

[carmine bane]

Oh

[shadow warren]

$6.612+(2.042)\frac{6.718}{\sqrt{31}}$?

[elfin berry]

y0shi

[carmine bane]

Oh

I didn’t do () so I think that’s what messed me up

[shadow warren]

oh

all good

[carmine bane]

9.07?

[shadow warren]

yeah

rounded should be 9.08

since its a 5 in the thousandths place

[carmine bane]

Oh

So that’s the confidence interval

[shadow warren]

thats the upper bound

you need to do the minus bit

for the lower

[carmine bane]

It’s the same equation but minus right

[shadow warren]

yes

[carmine bane]

4.14

The. Rounded would be 4.15

[shadow warren]

yep

so our confidence interval is (4.15, 9.08)

do you need a conclusion or no?

[carmine bane]

I don’t think so

[shadow warren]

alright thatll be fine then

now the outliers part

we can use the 1.5*IQR rule

to find these

which means we would need to find the IQR first

[carmine bane]

This will work for stats right?

[shadow warren]

mm? wdym

[carmine bane]

Statistics math

[shadow warren]

well yeah this comes from that

the 1.5 * IQR rule is from stats

im not quite sure what youre asking so mb if im interpreting it wrong

[carmine bane]

Sorry I also haven’t sleep much and been trying to cramp assignments

It works

[shadow warren]

alright

do you know how to find the IQR?

[carmine bane]

It’s doing the median then get two numbers then subtract and divide by to

2

[shadow warren]

so like you find the median

and then you separate that into two piles

numbers under the median

and numbers above

then you find the median of each of those sets

[carmine bane]

Yes from what I remember

[shadow warren]

yeah

thatll give us Q1, lower quartile, and Q3, upper quartile

and subtracting them would be the IQR

[carmine bane]

Oh

Q1: 1 Q3:9.75

Then the IQR is 8.75

[marsh citrus]

@carmine bane Has your question been resolved?

Channel closed

Closed by @carmine bane

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

Is there a way to know how many real roots a polynomial has?

[teal arch]

you can tell how many roots a polynomial has

not sure about real roots

also, imaginary roots always occur in pairs

[still temple]

its highest degree

say x^5-32=0

[teal arch]

it has 5 roots in total

but i think only one is real

[marsh citrus]

@still temple Has your question been resolved?

[still temple]

this one was simple, but how would we really know

[marsh citrus]

@still temple Has your question been resolved?

Channel closed

Closed by @keen edge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[marsh geyser]

https://cdn.discordapp.com/attachments/486841085210132490/1263069178349486155/image.png?ex=6698e456&is=669792d6&hm=4f5ba8a0326fb000a535aa6718b6241b6982eb41fe25c46354bec74a4e05c55d&

[marsh geyser]

i can separate them into 8 determinants

what's the next step?

@devout mauve sorry for pinging. could i get some help with this?

badly stuck

[somber flame]

I'll try to find some determinant properties

[marsh geyser]

the only determinant property i know are the matrix operations

column addition, subtraction

transposing

[somber flame]

It strikes me that we have to do something with (a + b + c) - a, (a + b + c) - b and so on

[marsh geyser]

ooh

i can follow

elaborate

different people are telling me different methods , but no one is getting to the solution

[somber flame]

Honestly I don't really know how to do this either lol sorry to disappoint, but I suspect we use averages somehow

[marsh geyser]

it's okay

@snow juniper

[marsh geyser]

<@&286206848099549185>

[still temple]

Do

U still need help

[somber flame]

Maybe try to work backwards?

From right to left

[marsh geyser]

in determinants

the 2 would only distribute to 1 row or column

right?

[somber flame]

Yes

[marsh geyser]

YES. PLEASE

[marsh geyser]

i don't think i'm skilled enough to work backwards

[still temple]

lemme think

[marsh geyser]

please do = )

[still temple]

whats the question

do u wanna see if it is true

pr solve it

or

bc it is true

hello

[still temple]

u thee

there

[marsh geyser]

yes

[marsh geyser]

i want to solve it

it's telling me to solve for the left side, and prove that it equals the right side

.close

[marsh citrus]

Channel closed

Closed by @marsh geyser

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[valid hinge]

Any shortest way?

Amswer is 12

[devout mauve]

draw graphs, area of triangles

[valid hinge]

Why area?

Because of mod sign?

||

[devout mauve]

integral <-> area

[valid hinge]

Yeah but

Sometimes we substrates also

If they don't ask about area

[devout mauve]

well if its below the x axis

[valid hinge]

Ohh i see

[devout mauve]

but the graphs here arent

[valid hinge]

Above x axis

Yes

If graph was left side of y axis?

Any effect?

[devout mauve]

no

[valid hinge]

I see

Let me find it tq tq😋🥰

Wonderful 🥰

.close

[marsh citrus]

Channel closed

Closed by @valid hinge

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[desert wolf]

Can I get help with question 14
ABCD is a rectangle
FE||BD
I need to prove AC halves FE

[pliant inlet]

BD // EF ??

[desert wolf]

Parallel to

[pliant inlet]

then AC halves BD?

[desert wolf]

That’s what I need to prove

[pliant inlet]

I think that's the basic theory of rectangle

no?

[desert wolf]

Nah idk

Don’t think so

[pliant inlet]

okay. then lets call that point O

okay?

[desert wolf]

This point?

[pliant inlet]

not, but BD and AC

[desert wolf]

Ok

So I’ll call it G

[pliant inlet]

if then the angle of CDG = GDA

right?

[desert wolf]

Right

Then

?

[marsh citrus]

@desert wolf Has your question been resolved?

Channel closed

Closed by @desert wolf

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fresh copper]

kinda stuck again

how do i simplify this further

[alpine basalt]

expand brackets

[fresh copper]

okay

[alpine basalt]

-2cosx/e^x

dependning on what you need it for, it should be enough

[fresh copper]

oh is there no trig identity here

[alpine basalt]

what is this from

[fresh copper]

calculus and vectsor

[alpine basalt]

no i mean like

are you integrating this

[fresh copper]

2nd derivative

this is the 2nd derivative

of an equation

[alpine basalt]

ok

then no simpler form

[fresh copper]

thank you

[alpine basalt]

unless you did something wrong in an earlier step

[fresh copper]

i think i ddint

this seems right

i was just wondering if it had a trig identity

cuz i forgot them

.solved

[marsh citrus]

Channel closed

Closed by @fresh copper

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pliant maple]

should be ln(x) + c

[lucid zenith]

Yeah, this is correct

What are you having trouble with?

[terse dove]

How do I find y

I have to eliminate the ln

[lucid zenith]

$-\ln y=\ln x+\ln c$

[elfin berry]

kheerii

[terse dove]

Yes

[lucid zenith]

What’s $\ln x+\ln c$?

[elfin berry]

kheerii

[terse dove]

Lnxc

[lucid zenith]

$-\ln y=\ln cx$

[elfin berry]

kheerii

[lucid zenith]

$\ln y=-\ln cx$

[terse dove]

-y = cx?

[elfin berry]

kheerii

[lucid zenith]

No

Whats -ln(cx)?

[terse dove]

Ln(1/cx)?

[lucid zenith]

Yes

$\ln y=\ln\left(\frac1{cx}\right)$

[elfin berry]

kheerii

[lucid zenith]

So now, what’s y?

[terse dove]

1/cx

Wth is this then

@lucid zenith

[lucid zenith]

It’s the same thing

$y=\frac1{cx}\implies xy=\frac1{c}$

[elfin berry]

kheerii

[lucid zenith]

1/c is just another constant

So you can replace it with c

If you wish to match the given answer

[terse dove]

Oh

Ok

Thx

.close

[marsh citrus]

Channel closed

Closed by @terse dove

Use .reopen if this was a mistake.

[terse dove]

Example 5 last line

What does it mean by the 'fixed distance'

<@&286206848099549185>

[lucid turret]

!15min

[marsh citrus]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[terse dove]

THIRTEEN MINUTES

14 now

[lucid turret]

13<15

14<15

[terse dove]

Consider a sufficiently large margin of error

[lucid zenith]

It’s alright the helper role means nothing anymore anyway

Almost nobody actually replies to helper pings because there are just so many

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[muted warren]

how do i do a local offset? i have a vector (3d) and want to offset it by another vector locally

[muted warren]

online i saw something about global transformation matrixes or something but idk what that is

[lucid turret]

no but how can the time increase? you sent the message at 11:00 p.m., which is fixed. You don't have a time-dialation machine!

[muted warren]

what...

[lucid turret]

The channel got disabled while I was trying to send this message earlier... so...

[muted warren]

should have sent it sooner...

💀

[limber hearth]

Computer science ?

[muted warren]

well i need it for programming yes

its not homework

i need it for implementation

its ran 20 times a second so efficiency is only somewhat important

tho i would prefer no trig

[limber hearth]

Fair

But i cant help with it sorry, try to ask in https://discord.com/channels/268882317391429632/326138793650421760

[muted warren]

ah okay

[limber hearth]

Maybe they could help you with it

[muted warren]

didnt ask in there because it always looks like nobody gets any answers there ;-;

or should i ask in linear algebra

cuz it is also linear algebra

i feel like it fits better in there

i asked it

[limber hearth]

Hope you get an answer

[marsh citrus]

@muted warren Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tall sun]

is this correct?

[rocky lark]

No

[tall sun]

oh?

[rocky lark]

Can I see how you did it?

[tall sun]

oh you are right wait

A's result was negative

i used a calculator to calculate -sqrt2+sqrt6/4

and compared it to sin(-15)

-0.2588190451 deg

[rocky lark]

The problem is that it comes with +

It should be with the -

[rocky lark]

.

[tall sun]

yeah

but i just did the rest

none of them are positive

[rocky lark]

The right answer must be with the -

[rocky lark]

.

[rocky lark]

.

[terse dove]

actually, im messaging you from space and my aircraft is moving at an astonishing speed of 0.963c, thats why time is shorter for you because youre an observer from Earth.

[lucid turret]

that's good but I think you're not understanding my point.

[tall sun]

what

[tall sun]

then that is A..

[rocky lark]

Nope

The answer A Is positive

[tall sun]

then what am I doing..

[rocky lark]

Nice

[tall sun]

ok

final answer

B

[rocky lark]

Yep

[tall sun]

im going to blame brackets and protect my peace and ego

ty

.close

[marsh citrus]

Channel closed

Closed by @tall sun

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[marsh citrus]

@calm vessel Has your question been resolved?

[calm vessel]

<@&286206848099549185>

[primal kelp]

Yess

What the proj

Prob*

Bro in which year youre

[calm vessel]

What

[marsh citrus]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wary bluff]

wait shit im slow

.close

[marsh citrus]

Channel closed

Closed by @wary bluff

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[keen stump]

cbrt(81) = 3cbrt(3)

is this true?

[mystic minnow]

yes

[keen stump]

thank you

.close

[marsh citrus]

Channel closed

Closed by @keen stump

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[marsh citrus]

@regal barn Has your question been resolved?

[regal barn]

.close

[marsh citrus]

Channel closed

Closed by @regal barn

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lyric bay]

How did they get the right expression from?

[desert dirge]

its just a factorised form like a quadratic can be written a(x-b)(x-c) with b and c as the roots

same thing, just with a cubic

[grizzled cobalt]

Well they just used the complex roots, and the fact that p(z) has the leading coefficent of 3 🙂

Like p(z)=3(z-r1)(z-r2)(z-r3) where r's are the roots.

[lyric bay]

OHHHH

I understand

Thank you both

[marsh citrus]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lyric bay]

Hello

[lyric bay]

Can someone explain why a, b is wrong and d is correct

[spark otter]

the dot refers to the dot product?

[lyric bay]

Yes

[limber hearth]

Take example for a)

[spark otter]

ok so

x = (0,1)

y = (1,0)

what is x . y?

[lyric bay]

Isn't 0 vector mean that all entries are 0?

[spark otter]

yep

[lyric bay]

0

[spark otter]

yep

is x = 0 or y=0 (0 vector)?

[lyric bay]

If a or b is all 0

How would it not result 0

[lyric bay]

No

[spark otter]

huh? that's not what we're sayin

[lyric bay]

[0, 0, 0] = 0 vector, no?

[spark otter]

yes

[lyric bay]

[0, 0, 0] • [a, b, c] = 0 vector

[spark otter]

we're not saying "x = 0 or y = 0 => x.y = 0" is false

we're saying "x.y = 0 => x = 0 or y = 0" is false

[lyric bay]

Oh shit I'm bad at discrete math

[spark otter]

and the dot product doesn't result in a vector, it results in a scalar

[0, 0, 0] • [a, b, c] = 0 scalar

but

[lyric bay]

But this implication is correct, right?

[spark otter]

yes

[lyric bay]

Since this is not always, it is incorrect

[spark otter]

but is this what a) is about?

[spark otter]

there we go

[lyric bay]

icic

What about beee

[spark otter]

well try

x = y = (1,0)

and z = (-1,0)

[lyric bay]

Oh wait

b) is easy

But I don't understand c)

[spark otter]

do you think c is correct or incorrect?

[lyric bay]

Incorrect

Scalar ≠ Vector

[spark otter]

no that's not what they wrote

they're saying

||x|| refers to the magnitude of vector x right?

[lyric bay]

Yes

[spark otter]

so what they're assessing is

"if x and y have same magnitude, then x = y"

[lyric bay]

Yeah so this

Magnitude = Scalar

[spark otter]

that still doesn't say anything?

[spark otter]

sure but we're not saying magnitude = vector

we're saying

if magnitude1 = magnitude2 (scalar = scalar)

then vector1 = vector2 (vector = vector)

[lyric bay]

Which are not equal

[spark otter]

why?

[lyric bay]

Because vector has points and direction

Direction mainly

[spark otter]

ok we're making progress

[lyric bay]

Yay

[spark otter]

to make a vector you need magnitude AND direction

so, if you only know the magnitudes are equal

we would ALSO need to know the directions are equal

to be able to say the vectors are equal

so

[lyric bay]

True

[spark otter]

do you have a counterexample?

[spark otter]

to this?

[spark otter]

knowing what we just said

[lyric bay]

1, 2, 3

-1, -2, -3

[spark otter]

exactly

(1,2,3) and (-1,-2,-3) have same amplitude

[lyric bay]

amplitude?

[spark otter]

magnitude/amplitude

anyways

they have same magnitude

[lyric bay]

Yes

[spark otter]

but clearly not equal

[lyric bay]

I get c...

I feel like linear algebra is harder than multivar calc and discrete math

What about d)?

[spark otter]

well

d is just distributive property

you know, (a+b)c = ac + bc with real numbers and multiplication

well... (u+v).w = u.w + v.w with dot product

so knowing this, compute (x-y).z

[lyric bay]

x•z - y•z?

[spark otter]

yeah, with the correct notations?

yes (x-y)•z = x•z - y•z

[lyric bay]

How do we know this equals to 0

[spark otter]

well what info are we given...

huh?

no z is a vector of R^n

[lyric bay]

Oh right

x•z = y•z

We can cancel z

Which makes x = y

[spark otter]

?

[spark otter]

noooooooo

you can't do that

not with dot product

[lyric bay]

What does that tell us T.T

[spark otter]

nothing more than

[spark otter]

look at this

[spark otter]

and look at this

if you just squint enough

[lyric bay]

x•y - y•z = 0

Oh

You're genius

Thank you so much

.close

[marsh citrus]

Channel closed

Closed by @lyric bay

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[night hearth]

No idea when to start for #1

[marsh citrus]

@night hearth Has your question been resolved?

[marsh citrus]

@night hearth Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tulip fulcrum]

How do I continue this

[tulip fulcrum]

I tried like 4 differnt ways

Non worked

[brave marsh]

Try and multiply numerator and denominator by cot^2(x)

[tulip fulcrum]

I did

Didnt work

[brave marsh]

You should be able to integrate it by parts from there

[tulip fulcrum]

Hm this I didnt try

[brave marsh]

From the multiplication you get $\int_\frac{\pi}{4}^\frac{\pi}{2} \frac{\cot^2(x)}{\cot(x) + x}$, and you can split this into $\cot^2(x)$ and $\frac{1}{\cot(x) + x}.$

[tulip fulcrum]

Mhm

[elfin berry]

Azyrashacorki

[tulip fulcrum]

Nope

Same thing as expanding cot²x to csc²x-1

Which I tried

[brave marsh]

It does work though

[tulip fulcrum]

Extra negative one for some reason

[brave marsh]

Let u = x + cot(x).

[tulip fulcrum]

Tried aswell

Hmmm actually one sec

Nice

Ugly boundries

Jeez what an integral

Thanks for the help mate

.close

[marsh citrus]

Channel closed

Closed by @tulip fulcrum

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lyric bay]

Hello

[lyric bay]

Why can there be multiple orthogonal unit vectors for this problem?

[still light]

Any vector has lots of orthogonal unit vectors

[lyric bay]

How

[still light]

You can picture a vector as a line segment kinda. And there are lots of other line segments that are perpendicular to that line segment

[lyric bay]

Can you use vector OP or OQ to find the orthogonal unit vector too?

Instead of dot producting PQ

[still light]

Idts

or maybe there is but using dot product with PQ would be easier

[lyric bay]

But like they would still be on the same plane

OP, OQ and PQ

[still light]

Oh right. I guess you can take the cross product

[lyric bay]

Thanks for helping!

.close

[marsh citrus]

Channel closed

Closed by @lyric bay

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[terse gazelle]

can someone please tell me what the answers do here for question b? i simply dont get how they got a series already given that it is x/sqrt(x^2+1)

[terse gazelle]

it seems like they pulled a series out of arctanx formula im guessing? but what about the x on the numerator?

[brave marsh]

They're just taking the derivative termwise

[terse gazelle]

yeah if i took the derivative step by strep it would take forever

how do i get the series?