#help-33

1 messages · Page 126 of 1

buoyant pawn
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i don't understand where the cos(45) comes from

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and how it says only the forces along the diagonal contribute

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i don't understand why

marsh citrusBOT
#

@buoyant pawn Has your question been resolved?

buoyant pawn
#

<@&286206848099549185> pls i've been stuck on this for so long

buoyant pawn
#

<@&286206848099549185>

mighty pier
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@buoyant pawn is there any more information on this?, like a diagram?

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I think there is physics's concept for direction of force

buoyant pawn
#

the second image is the diagram

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here's the full answer if you want to see more context

mighty pier
buoyant pawn
mighty pier
#

and the component along diagonally of wire 2 and wire 4 will add up so it is 2 times the cos component

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i thought wire 4 is placed opposite to wire 1, replace wire 3 with wire 4

buoyant pawn
#

is this diagram correct for the forces?

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because isn't wire 1 attracted to the other 3

mighty pier
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yes it is but you want the force on wire 1

mighty pier
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u need to calculate the force ON wire 1

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by others

buoyant pawn
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i saw this in another problem and i don't understand when to use this law

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vs sqrt(x^2 + y^2)

buoyant pawn
#

i thought

mighty pier
#

it is the drawing of force exerted by wire 1 on others

buoyant pawn
#

that would mean wire 1 was repelling the other 3 though

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i thought it was attracted to them

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bc their currents are in the same direction

mighty pier
#

sorry for the misunderstanding

buoyant pawn
#

no worries

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i don't think it really matters in the context of this problem anyways because we just want to find the magnitude

mighty pier
#

yes, your diagram was correct

mighty pier
buoyant pawn
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okay i think i understand it now

mighty pier
#

i hope you found the reason of diagonal direction

buoyant pawn
#

you use the parallelogram law to find the combined vector and then you add that to the other vector

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bc they're both in the same direction

mighty pier
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yes

buoyant pawn
#

i don't know how i've gone through calculus 1 2 3 differential equations and mechanics and i've never heard of this

mighty pier
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the reason other component doesnt add cuz they cancel each other

buoyant pawn
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wdym

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how do they cancel each other

mighty pier
buoyant pawn
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i took vector calculus last semester

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lol

mighty pier
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ah

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wait

buoyant pawn
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but we spent like 2 weeks on vectors and then went into multivariable stuff

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and then linear algebra stuff

mighty pier
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one component is in the direction of diagonal and other is perpendicular

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so the in the perpendicular direction of diagonal force by wire 4 and wire 2 cancels

buoyant pawn
#

what does the second drawing represent?

mighty pier
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Component of forces by wire 4 and wire 2

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The angel is 45

buoyant pawn
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ok now i'm confused again

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isn't the angle between F4 and F3 45

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and F2 and F3 45

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but it's 90 between F4 and F2

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so when they add F2 and F4 why do they use cos45 and not cos90

mighty pier
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Components of vector is different concept

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I will explain in a bit

buoyant pawn
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,rccw

elfin berryBOT
buoyant pawn
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can i do it this way?

mighty pier
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That is by using that formula, you use the angle between the vectors

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And about the components for the vectors

buoyant pawn
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ok i get that

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is the way i did it a correct way though?

mighty pier
maiden trout
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Yeah with these problems, it’s really helpful to split into components

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Vector addition is really complicated otherwise

mighty pier
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But components of vectors are really helpful and is used in the solution you

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Provided

maiden trout
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Out of curiosity, @buoyant pawn are you taking EM

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AP test I mean

buoyant pawn
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no i'm a freshman in college

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my school only offered mechanics

maiden trout
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Ah I see

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I’m also studying em

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It’s really different from mechanics

buoyant pawn
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eh

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they're not super different imo

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E&M is just harder bc you can't really visualize anything

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you need to develop a lot of intuition

maiden trout
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What’s your major

buoyant pawn
#

mechE

buoyant pawn
#

in that solution they split the diagonal vector into 2 and then added those to the horizontal/vertical components

mighty pier
buoyant pawn
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ok that makes sense

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tysm for all the help

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big ups

#

.close

marsh citrusBOT
#
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marsh citrusBOT
#
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weary apex
marsh citrusBOT
weary apex
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how does it go from the original series to the next one

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lhopitals rule doesnt do that, deriving it doesnt do that either

twin girder
twin girder
brittle coral
#

It's called comparison test look it up

weary apex
#

tysm 💛

#

.close

marsh citrusBOT
#
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final flicker
#

Pls help

marsh citrusBOT
final flicker
#

In the xy-plane, the graph of the equation
y = —x + 9x— 100 intersects the line y = c at
exactly one point. What is the value of c?

cedar smelt
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is that a parabola?

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-x^2

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if it is

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find the x point that the derivative is 0

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and put f(x0) there

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its something like this

honest quiver
cedar smelt
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yeah

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but y=0 then no matter what

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and it intersects every y=c line 1 time

marsh citrusBOT
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@final flicker Has your question been resolved?

final flicker
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so what's the answer

cedar smelt
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f(9/2)

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-79.75

honest quiver
cedar smelt
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yeah

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the question is not even understandable

honest quiver
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sec here we just helping you not giving you the answer

cedar smelt
final flicker
elfin berryBOT
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Not Scammer

cedar smelt
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because the problem is wrong if it isn't

final flicker
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it said -x^2 in the q already

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i dont understand what u want

final flicker
honest quiver
cedar smelt
final flicker
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c is -100

honest quiver
cedar smelt
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if it's a linear line than it intersects every y=c line one time

final flicker
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tutor said a(-1x^2) + b(9x) +c(-y-100) = 0

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?

final flicker
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how is c y-intercept

cedar smelt
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i didn't said it was a y-intercept tho

final flicker
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you said intersect every y=c one time

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ok

cedar smelt
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y-intercept is a different thing than intercepting every line parallel to the x-axis

cedar smelt
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this is the sol

final flicker
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does y intersect c every 2 times in parabola

final flicker
#

.close

marsh citrusBOT
#
Channel closed

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final flicker
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@cedar smelt @honest quiver i know other way

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you get the x coordinate of the vertex

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so it's gonna be -b/2a

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so you plug in the b and a from the original equation to get the answer of -b/2a

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so it's gonna be -(9)/(-1)2

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so you get -9/-2 which is also 9/2

honest quiver
final flicker
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that's for finding the roots of x or x intercepts

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why need it

final flicker
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and you get -319/4

honest quiver
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/4

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not 2

final flicker
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yes u can use that for dincing c

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finding*

final flicker
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ok ty bye

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.close

#

.close

#

.reopen

marsh citrusBOT
#

final flicker
#

.close

marsh citrusBOT
#
Channel closed

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Use .reopen if this was a mistake.

desert socket
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scemmer

final flicker
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.close

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.reopen

marsh citrusBOT
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final flicker
#

hwt

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what happens when a quadratic function = 0?

stark trail
final flicker
stark trail
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That’s not a quadratic function

final flicker
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yes

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it's not

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a, b, and c resemble a quadratic f

stark trail
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The coefficients you mean?

final flicker
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wait no

final flicker
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and their xs

stark trail
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Your question still doesn’t make much sense what you mean by “what happens”

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f(x)=5x^2-3x-2

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Here’s an example of such a quadratic function

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What do you want to know about it

final flicker
stark trail
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What?

final flicker
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like this

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-1x^2 +9x -y - 100 = 0

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where is the 0 on graph

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i dont understand

stark trail
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Okay so your first step to understanding would be to rewrite the equation as a function of y

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Can you do that

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make it in the form y=f(x)

final flicker
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byt y is f(x)

stark trail
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Yes that’s why they’re equal

final flicker
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ok so y = 1x^2 +9x-100

stark trail
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Not quite, there’s a small mistake, it should be -1x^2

stark trail
final flicker
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yes

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yes

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-1x^2

stark trail
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y = -1x^2 +9x-100

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And you want to know, when is this quadratic function 0?

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Or what do you want to know about it

final flicker
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yes

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no

stark trail
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Okay

final flicker
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what is 0

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no i dont want to know when it's 0

stark trail
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I think I understand what you’re asking

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How about I try to explain now

final flicker
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ok

stark trail
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y = -1x^2 +9x-100

final flicker
#

yes

stark trail
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This is a function of x

final flicker
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ok

stark trail
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For every input value of x you put in

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You get out an output value of y

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Agreed?

final flicker
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ok

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yes

stark trail
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So, for it to “be 0” that means, you put in an x-value, and the y-value you got out was 0

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Does that make sense?

final flicker
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ok

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yes

stark trail
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So say you wanted to know, when is it actually 0, then you need to find the x-values that when you plug them in, y=0

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Agreed?

final flicker
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y can't be 0

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because y is in c

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becayse

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-1x^2 +9x-y-100=0

stark trail
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You are confusing yourself

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Why change the form of the equation

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?

final flicker
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no i'm not

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i didnt change

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it's ax^2 + bx +c =0

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so

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a= -1

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b= 9

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c= -y-100

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so

stark trail
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No

final flicker
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why not

stark trail
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c=-100

final flicker
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no

stark trail
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Yes

final flicker
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we want y= 0

stark trail
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y=f(x)

final flicker
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so y should be in c

stark trail
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No

final flicker
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STOP

stark trail
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Listen I’m not going to argue with you about this

final flicker
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okay

stark trail
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I’m not sure how else to explain it besides that

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Y is a function of x

final flicker
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np

stark trail
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we represent that as y=f(x)

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And in this case

final flicker
stark trail
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y=f(x)=-x^2+9x-100

final flicker
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so f(x)=0

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lol

stark trail
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There’s no need to take it to the other side, and that actually makes it incorrect

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y=f(x)=-x^2+9x-100
This is what we have
This equals 0 when
0=-x^2+9x-100

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So a=-1, b=9, c=-100

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Hopefully that helps, but if not I suggest you find a different resource

final flicker
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No

stark trail
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Since it’s incorrect to subtract y over

final flicker
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what's the difference between yand fx

stark trail
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There is no difference

final flicker
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otherwise why need an alternative for it

stark trail
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There is no difference

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The reason is because it is more convenient at times to write just “y” than f(x)

final flicker
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hm

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okay

stark trail
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Or, sometimes we want to represent two variables, x and y, without them actually being related as functions of eachother

final flicker
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okay

stark trail
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Or, sometimes we just want to look at points on the xy-plane (x,y) without talking about functions

final flicker
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oh yes

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makes sense now

stark trail
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But in this case, there’s no difference

final flicker
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😭🙏🏻

final flicker
stark trail
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They’re not exactly the same and I’m just trying to give you different ways of seeing it

final flicker
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nvm

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oh yes 0=y-y

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therefore y = 0 when c= -y -100

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so the vertex will be (0,0)

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or maybe not

final flicker
stark trail
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No

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y = -x^2+9x-100

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Both sides are EQUAL they’re the same thing

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Exact same thing

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If y=0

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Then the other side

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Also equals 0

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0=-x^2+9x-100

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what you’re doing, is just subtracting y to the other side

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But that isn’t making y=0

final flicker
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i'm opening desmos

stark trail
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That’s making -x^2+9x-y-100=0

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that’s not the same as y

marsh citrusBOT
#

@final flicker Has your question been resolved?

marsh citrusBOT
#
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vital nymph
#

in 2nd problem = no test means tests happens both days so answer should 1-1/3.1/3 ,am i correct or wrong

stuck pollen
#

Does that make sense?

vital nymph
sour yew
#

<@&286206848099549185>

halcyon viper
#

net gain will be 0

marsh citrusBOT
#

@vital nymph Has your question been resolved?

#
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still temple
#

what happens when a quadratic function = 0?

marsh citrusBOT
still temple
#

.close

marsh citrusBOT
#
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marsh citrusBOT
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Send your question here to claim the channel.

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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
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dusk moth
marsh citrusBOT
dusk moth
#

how?

#

i do this and its completely wrong

foggy pier
#

$\int^b_a \sqrt{1+ (y')^2} dx$

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That's the right formula

urban shard
#

without the space after $

elfin berryBOT
foggy pier
#

Thanks

dusk moth
#

i just put C for now, but idk how to do it

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my "a" and "b" for both arc length integrals are 0 and 4 respectively, right?

foggy pier
#

Yes

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Have you got some working?

dusk moth
#

and y'_1 is 2x i believe

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and the other y' is 6-2x from what i see

foggy pier
#

You're right about 6-2x

dusk moth
foggy pier
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But not the 2x

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Derivative of 1/2x^2 is x

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1/2 * 2 = 1

dusk moth
#

...

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ahem

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oops

foggy pier
#

Haha it happens

dusk moth
#

woah

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would u look at that

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I guessed right

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😭

foggy pier
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😭

dusk moth
#

can you help me review 1 more thing tho?

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if u dont mind

dusk moth
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stuff like this

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im just wondering if this is my R

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and also how would the line of revolution being y=0 affect this

cedar smelt
cedar smelt
desert socket
#

scemmer

dusk moth
#

actually, i should finish the reading for that 😭

cedar smelt
#

it will be sums of little circles

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you need to find where does those functions meet

dusk moth
#

mhm, so just the integral of (top-bottom)^2 from a to b would work?

sour yew
cedar smelt
#

!occupied

marsh citrusBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

sour yew
# cedar smelt !occupied

Too bad too sad, because no one has answered my question yet even though I made my own channel

cedar smelt
#

it doesn't mean you can occupy other channels tho

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tag helpers and wait if you need help

sour yew
#

Ight

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<@&286206848099549185>

#

Done

cedar smelt
#

in your own channel.

sour yew
#

This is my own channel

cedar smelt
#

its not

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its ajiba's

dusk moth
#

plug stuff in and viola

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wait i spelled that wrong

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but u get the point

sour yew
dusk moth
dusk moth
dusk moth
#

well, better image to understand since it labels it, but same formula

sour yew
dusk moth
#

.326 cents rounds to .33

sour yew
#

So the answer would be .33?

dusk moth
dusk moth
dusk moth
#

the 28k

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the 6% interest

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and the 10 year length of time

sour yew
#

I don't know how to do anything 😔 I just wanted the answer solved

dusk moth
#

😭

#

thats what photomath and other stuff is for

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do you have a calculator

sour yew
#

Ye photomath gave me incorrect answers

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Ok I know it's 50,979.36 or 50,978.80 or 51,019.36

sour yew
dusk moth
sour yew
#

But it's confusing

dusk moth
sour yew
#

Ye it's either those 3 numbers

sour yew
dusk moth
sour yew
#

Are u able to do it for me

dusk moth
#

i just did, but u should do it too

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or else you're cooked on your test on this

sour yew
#

Wait so what's the final answer u got?

dusk moth
#

u tell me what u got first lol

sour yew
#

Alright 💀

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Imma try

dusk moth
#

ping me when ur back

sour yew
#

I got 50,019.32

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I might be wrong though

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@dusk moth

dusk moth
#

Can you screenshot what you typed for me?

sour yew
#

I typed that into the calculator

dusk moth
#

That looks suspiciously similar to chat gpt

sour yew
#

Nah I just type it out lol

dusk moth
#

And last time I checked... my calculator doesn't talk to me, it just gives me numbers 👀

sour yew
#

I used online calculator

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👀

dusk moth
#

Use your phone calculator

sour yew
#

I did

dusk moth
#

Are u android or apple

sour yew
#

Android

dusk moth
sour yew
#

Btw what answer you came up with

dusk moth
#

...

sour yew
#

😭

dusk moth
#

Yeah I'm gonna go back to homework

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💀

sour yew
#

Aw come on

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Was my answer close to yours?

dusk moth
#

Yes it was

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Off by like 1k

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But close enough

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Well technically not

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But it's close

dusk moth
#

If u type EXACTLY that and THEN press "6" you will get my answer

sour yew
dusk moth
#

Maybe

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Or maybe it's off by 1k in the other direction

sour yew
#

Type what in?

dusk moth
#

This put the number 6

sour yew
#

so 0.6?

dusk moth
#

I'm scared that you're suffering from C.I.S.

dusk moth
dusk moth
#

I used to have it... and I got like a 20 on 3 homeworks in a row... and then I was borderline failing... then I WAS failing... buuuut I clutched

sour yew
dusk moth
#

U forgot a 0

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28,000

sour yew
#

Huh?

#

oh

dusk moth
#

OK

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NOW we can round to the nearest cent

sour yew
#

I probably need to round of to the nearest cent now I think

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Ye how do I do that

dusk moth
#

3 decimal places then round

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.326

sour yew
#

Do I type that in the computer?

dusk moth
#

Cents goes to only 2 places so we need to look at the 3rd one to determine if we round up

dusk moth
dusk moth
#

Is 6 greater than or less than 5

sour yew
#

So 36?

dusk moth
#

Nope

sour yew
#

51019.326?

dusk moth
sour yew
dusk moth
#

Good

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If it's greater than or equal to 5, then we can round up by 1

#

So 32.6 cents rounds to 33 cents

sour yew
#

Ahh because it's closer to 30

dusk moth
#

When considering rounding, compare the digit in the next place to 5

sour yew
#

But I thought it would be 51019.30 in that case

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Since 32 is closer to 30

dusk moth
#

Well

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Correct and incorrect

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IF you were told to round to the neatest 10 cents, or to the nearest dime, then that's correct

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BUT

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You were told to round to the nearest cent, or the nearest penny

sour yew
#

Ohh

dusk moth
#

And you have 32.6 cents

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You can't have 0.6 of a penny

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So you found up at 33 pennies or 33 cents

sour yew
#

this makes cents now

#

Sense*

#

Thank you

dusk moth
#

Np

sour yew
#

Well partially the rounding off still gets me a bit confused

dusk moth
#

You'll get used to it

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With some more practice

#

Alright I gtg now

#

Byee

sour yew
#

How did u know it was 326 though when rounding off

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And not just 32

dusk moth
sour yew
#

Oh make sense

graceful prawn
#

X=4logx, how do I go about solving this?

sour yew
#

And not the second

#

?

dusk moth
#

U said they asked for nearest CENT

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That's the 3rd digit

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If they asked for the nearest DOLLAR

dusk moth
#

Since now ur considering the .3

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And 3 is less than 5 so don't round up

dusk moth
sour yew
#

Kk I appreciate the help

dusk moth
#

Np

dusk moth
graceful prawn
#

Base 10,

#

Really im trying to figure out how to@compare algorithms (log base 2) but I completely forgot how@to@work with logs, last time@I used them was over 10 years ago

#

I even tried to ask chat gpt and it doesn’t give me an answer

dusk moth
#

Wait is it 8 or 4

dusk moth
graceful prawn
#

4 is fine, it’s more about trying what identity I need to use

#

I don’t care about the actual answer but the method I need to use

dusk moth
#

Tbh I got no clue

graceful prawn
#

Yeah, I can’t find any help for this problem online

#

I don’t even know what I would call it

dusk moth
#

Are you familiar with the lambert w function?

graceful prawn
#

No

#

Looks interesting though

dusk moth
#

i need like 5 more mins

#

This is a complete mess

graceful prawn
#

Thank you!

dusk moth
#

Wait what is this even for

dusk moth
graceful prawn
#

I am reading about algorithms, and was trying to compare a n and log n algorithm. My questions was “at what n does one algorithm become faster than the other” so I thought, easy just solve for n.

#

Apparently not easy lol,

dusk moth
#

well

#

i got that as an n

#

which is equal to that or...

#

@graceful prawn thats the work if u want but idk if its very helpful 😭

#

W(ue^u)=u

#

helpful for setups like W(xe^x) because the output is x

#

.close

marsh citrusBOT
#
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graceful prawn
#

Thank you

marsh citrusBOT
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still temple
#

Hey

marsh citrusBOT
still temple
#

How can I find the area of a circle without knowing the size

dusk moth
#

What do you know

still temple
#

That's all

dusk moth
#

NOTHING else???

still temple
#

Man. It's dumb. I should contact my teacher lmao

dusk moth
#

Can u send a picture of the problem

still temple
#

I can't take screenshots like that on mobile

dusk moth
#

Is it possible to type it out/copy paste

still temple
#

But there's no photo. It says find the area of the 2d circle

#

Should there be a photo?

dusk moth
#

Does it give diameter, radius, circumference?

still temple
#

No it only tells me to find the area of a 2d circle

dusk moth
#

Just put pi r^2

#

Maybe it's just asking for the formula

marsh citrusBOT
#

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final flicker
marsh citrusBOT
final flicker
#

the question is so broad looool

#

😭😭😭

marsh citrusBOT
#

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sour yew
marsh citrusBOT
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@sour yew Has your question been resolved?

final flicker
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frigid marsh
#

Real quick how is this function odd

marsh citrusBOT
twilit grove
#

what is the definition of an odd function

frigid marsh
#

uh f(-x) = -f(x) ?

twilit grove
#

yes

#

so substitute -x into the equation

#

see what you get

frigid marsh
#

Nah

#

1-cos(x)/-x != cos(x)+1/-x ??

twilit grove
#

Substitute -x everywhere you see x

frigid marsh
#

cos(-x) = cos(x) so i did

still temple
marsh citrusBOT
#

@frigid marsh Has your question been resolved?

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pure quail
#

when solving the part (a) is it correct to say "since each point in the triangle is equally likely to be chosen, the joint density function is uniform and we find the value of density, which is constant over the area of the triangle."

dry prawn
#

the joint density function is uniform
yes

#

and we find the value of density, which is constant over the area of the triangle.
well you have to actually provide the density, as well as the bounds

pure quail
#

how do i do that

dry prawn
#

how do you normally find density functions?

pure quail
#

well it depends on the random variables, if they are discrete or continious

dry prawn
#

it should hopefully be clear which of those two you're working with

pure quail
#

yes continious

dry prawn
#

if the density is uniform, then the density function is just some constant

pure quail
dry prawn
#

yes

pure quail
#

aha okay then it is 2

dry prawn
#

provide the correct bounds

pure quail
#

0≤x≤1

#

and do i say the same for y or 0≤y≤1−x

dry prawn
#

saying the same for y would make your bounds a square

pure quail
#

right okay, so i must say 0≤x≤1 and 0≤y≤1−x

dry prawn
#

you must

pure quail
#

thank you so much ))

marsh citrusBOT
#

@pure quail Has your question been resolved?

frigid marsh
#

.reopen

marsh citrusBOT
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short agate
#

Jeff has taken out a loan for college. He started paying off the loan with a first payment of $175. Each month he pays, he wants to pay back 1.4 times as the amount he paid the month before. Show Jeff how to represent his first 36 payments in sigma notation, either using the equation editor or uploading a picture of your written notation. Then explain how to find the sum of his first 36 payments, using complete sentences. Find the sum and explain why this series is convergent or divergent. (10 points)

short agate
#

need help w this word problem

#

im just learning sigma notation

marsh citrusBOT
#

@short agate Has your question been resolved?

short agate
#

.closer

#

.close

marsh citrusBOT
#
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marsh citrusBOT
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strong apex
#

hi! so i was looking to answer what percentage of engineering respondents work in europe but im a bit confused. naturally, i divided the number of engineers by the number of respondents in europe but that ended up with 93% which wasnt an answer choice. what would be the best way to approach this?

silk bobcat
#

find percentage of each and multiply

strong apex
silk bobcat
#

percentage of european with respect to the whole
multiplied by number of engineers

#

it's like estimate right

#

not derive a specific answer?

strong apex
#

also, to further add onto the info, i added all the departments together and the regions together but they dont equal the same number so im not sure if that has an affect on the answer

#

the choices are cannot say, 17%, 22%, 46%, and 8%!

silk bobcat
strong apex
#

or i guess, the reasoning behind the estimate would be a better question

silk bobcat
#

so it's 1210/the sum of all of them so 6967

strong apex
#

.close

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pure quail
#

im trying to do the part (b) but im not sure of my solution i did it as integrating the joint density function over possible values of x for a given y, is that correct

marsh citrusBOT
#

@pure quail Has your question been resolved?

marsh citrusBOT
#

@pure quail Has your question been resolved?

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fallow quiver
#

i got n=10 and k=1

marsh citrusBOT
cedar smelt
#

seems like n=10

#

but

#

it should be 45x^2 shouldn't it?

broken magnet
fallow quiver
#

yup

cedar smelt
#

wait

broken magnet
#

Well, by the binomial theorem, k * (n choose 1) = 10, right?

fallow quiver
#

i dont get it

#

pls articulate

broken magnet
#

if we expand (1-kx)^n

#

what do we get

cedar smelt
#

If I'm not wrong,

fallow quiver
broken magnet
fallow quiver
#

the second term is nx

cedar smelt
#

yep

broken magnet
#

Yeah, but x in this case is technically -kx

#

so it would be

fallow quiver
#

oh

cedar smelt
#

nkx = -10x

fallow quiver
#

yra

#

got it

broken magnet
#

1 + n(-kx) + n(n-1)/2! (-kx)^2

fallow quiver
cedar smelt
#

m2 in my first take

fallow quiver
#

i compared it with the (1-x) one

cedar smelt
#

but doesn't matter.

#

yeah

fallow quiver
#

ok thx i got it

#

.close

marsh citrusBOT
#
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marsh citrusBOT
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steep knoll
marsh citrusBOT
long yew
#

On the first one, -(x+1) turns into -x-1 so overall 2-x-1=-x+1

#

on the second one its the reverse thing, you put it back in the bracket

steep knoll
#

I'm sorry I dont understand. Where does the 2 go?

long yew
#

try opening the brackets

steep knoll
#

ah

#

duh

#

thank you

#

.close

marsh citrusBOT
#
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marsh citrusBOT
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sinful sparrow
marsh citrusBOT
stark trail
#

Don't close and reopen a new channel just to post the same question

dusky viper
#

dont close and reopen it if ur not getting answers

#

I can help u solve the mathematics but im not here to fill in gaps of content you don't know.

sinful sparrow
#

i looked through my textbook and there isn’t any formula idk y

dusky viper
#

what textbook is this in?

sinful sparrow
#

chemistry fourth canadian edition john a.olmsted

dusky viper
#

yeah they would've made the assumption that u know a certain level of maths

#

do u know the volume of a sphere?

sinful sparrow
#

no

#

why should i know that

dusky viper
#

because ur doing chemistry?

#

anyways its (4/3)pi*r^3

#

$\frac{4}{3}\pi r^3$

elfin berryBOT
#

Galaxy

sinful sparrow
#

but how is this the same as atom and nucleus

#

are we just using the sphere equation because it’s sphere shaped i guess

dusky viper
#

if its spherical then yes

#

but idk about the shapes of atoms so idk

maiden trout
#

If this is a math question

#

Certain simplifications are needed

dusky viper
maiden trout
#

A nucleus can be roughly modeled as a sphere I suppose

sinful sparrow
#

so let’s asking to compute typical atomic and nuclear volumes and i don’t have a formula in my textbook so do i assume it’s the e sphere one @maiden trout

maiden trout
#

Yeah I’m not sure it depends on the level of chemistry you’re studying

sinful sparrow
#

it’s just first year

#

but i don’t remember doing the sphere equation for anything in hs

#

that’s y i’m confused

#

also i just assumed the formula would be in the textbook

maiden trout
#

Yeah if i had to guess it seems to be a simple application of spherical volume

marsh citrusBOT
#

@sinful sparrow Has your question been resolved?

#
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sinful sparrow
#

i got it

marsh citrusBOT
#
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worldly crypt
#

A bit confused on how to approach this question

worldly crypt
#

1a) as of rn

#

wait I got it

mighty pier
#

nice

worldly crypt
#

.close

marsh citrusBOT
#
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worldly crypt
#

.reopen

marsh citrusBOT
#

worldly crypt
#

I have the answers but I'm not exactly sure if my reasoning is correct

mighty pier
worldly crypt
#

fair enough

#

it'll be fine

#

I'll just think about it

worn vale
#

Can anyone help me to find the inverse of the Matrix

#

?

marsh citrusBOT
#

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sleek lake
marsh citrusBOT
sleek lake
#

is this wrong or what?
there's 8000 from below and there's 1000 from the gravity, why not 70 m/s²?

sand fable
#

70 seems... legit

sand fable
#

it says "during lift-off"

sleek lake
#

but it would be true in space right?

whole compass
dapper badge
#

could mean lift off from a planet that happens to have a gravity defying lack of gravity

whole compass
sleek lake
#

ok

sleek lake
#

thank you all

dapper badge
#

assume the elephant is a sphere

whole compass
#

Actually they myt not thought that much

#

Just use F=ma here

sleek lake
#

.close

marsh citrusBOT
#
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void elm
marsh citrusBOT
#
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leaden monolith
#

I was learning some vector calc and encountered a vector field where there's a hole, and somehow it turned out very very similar to the residue theorem from CA, i was wondering about the connection that there were 1/2ipi factors coming out and also 2pi factors coming out in the vector calc version

stark trail
#

yes there's a connection

#

do you have a more specific question about it

marsh citrusBOT
#

@leaden monolith Has your question been resolved?

leaden monolith
#

i dont know what the specific question i want to ask is

#

it just looks really similar

#

😭

#

is it possible to perhaps recover one of them from the other?

#

or is there some sort of direct translation of how such a vector calc problem can be rewritten in CA as a contour integral instead

stark trail
#

I can send you a few resources

#

one sec

leaden monolith
#

it was the last part here

stark trail
leaden monolith
#

when the singularity (1, -1) was inside the interior we could shrink any simple closed curve into that small loop around the singularity

#

very similar to what you do in CA

#

OOHHH

#

when you identify the C -> C functions has R^2 -> R^2

#

you have a 2d vector field

stark trail
#

🔠

leaden monolith
#

so where did the i come from in the residue theorem again

#

is that the parametrisation being e^{ix} where x goes from 0 to 2pi but the integral of that guy spits out an i

#

you get ie^{ix} as the primitive so when you do the limits there's a i left over

stark trail
#

it comes from the cauchy integral formula

leaden monolith
#

but in the real case you dont get the i because your components are in terms of the 1st and 2nd entries

#

which just ends up being sin^2 and cos^2

#

hmmmmm

stark trail
#

can I just refer you to S&S? XD

leaden monolith
#

yeah im thinking that the specific part that gives us that i is the parametrisation

#

the part where we need to call our parametrisation e^{ix}

#

so when we integrate that guy we get an i out the front

leaden monolith
#

that's why the real version just has 2pi but the complex analogy has an i out the front

#

alright thank you sir austin

#

❤️

#

.close

marsh citrusBOT
#
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stark trail
marsh citrusBOT
#
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elfin surge
#

hi

marsh citrusBOT
elfin surge
#

someone please help me out

onyx flume
#

hello there

#

sure

elfin surge
#

I wanna know how to solve 12 and 13

low ruin
#

Find the midpoint

#

The gradient perpendicular to the line is -1/m

elfin surge
#

can you help me solve it I am stuck

low ruin
#

So the first step would be to determine where you are stuck

elfin surge
#

no clue how to answer

low ruin
#

Find the midpoint

elfin surge
#

what is it/

#

?

low ruin
#

If you have two coordinates (x1, y1), (x2, y2) taking average of the coordinates will give you the midpoint

elfin surge
#

ok then?

low ruin
#

First find it

#

So the midpoint will be ((x1+x2)/2, (y1+y2)/2)

elfin surge
#

then wha tdo we do?

low ruin
#

The gradient perpendicular to the line is -1/m

elfin surge
#

please tell everything inn once sentence

#

Im getting confused

low ruin
#

from there use m(x-x1) = y - y1

elfin surge
#

PLEASE tell in one sentence

#

full

low ruin
#

I would prefer if you performed the actual steps first before asking about subsequent steps

elfin surge
#

I wanna know just how to do it....

low ruin
#

You are not listening to me

elfin surge
#

im

low ruin
#

Find the midpoint

elfin surge
#

idk what that is..

low ruin
#

I gave you definition earlier

#

I am done. I would recommend you refer to some YouTube video starting with how to find midpoint

mighty pier
#

@elfin surge do you not know what is a midpoint?

#

what is the mid point of 2 and 4

marsh citrusBOT
#

@elfin surge Has your question been resolved?

marsh citrusBOT
#
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low mica
marsh citrusBOT
low mica
#

The answer would just be {2, 3, 4, 5}

#

which is just "A"

#

because "B" and "C" have nothing in common

dapper badge
#

yep

low mica
#

(-4, -2] U (1, 5] $.$

elfin berryBOT
low mica
#

right?

#

union

#

so its 'x' OR 'y'

#

this is question btw

dapper badge
#

U is union, v is or

#

so i think it would be asking for (-4, -2] v (1, 5]

#

kind of a weird question tbh

honest quiver
low mica
#

i haven't heard of 'v'

dapper badge
#

they arent the same thing though

low mica
honest quiver
#

ok

low mica
#

i'll worry about 'v' later when I'm taught about it

#

or when I have free time to teach myself

#

although i'd prob focus on calculus then

#

i know this content, im just making sure of my knowledge cause I haven't done these topics in months

#

have an exam coming soon sooo

dapper badge
#

If you did union instead, it would mean that you are combining the two into a set

#

or means you are choosing between the two

#

although based on the question, it looks like you would want union, not or

low mica
#

well yeah wouldn't that be describing the subsets

low mica
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i didnt even know it had its own separate thing

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ill be more careful next time with my wording

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for this one, would we quite literally just dot those coordinates down

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and connect them

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and it'll make a graph

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then we can use the vertical line test to see if its a function or not

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if that's how its done then I wont waste my time doing this, seems really simple

low mica
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is this notation supposed to mean 0 is mapped to 1, 0 is mapped to 2, etc?

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if so, one disqualifier for being a function is when you have an element in the domain being mapped to more than one element in the codomain

low mica
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so like

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(0,1) and (0,2)

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right?

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or is that fine

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however, you can have 2 different elements in the domain being mapped to one element in the codomain (such as (-2)^2 = 4 = (2)^2)

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low mica
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yeah and (b) in the image i sent

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is a function

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yeah thats fine

low mica
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yeah ill skip over that then

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ima send images of 6 graphs in a bit

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and ill attach the domain and range for them

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is it fine if u check my answers

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if im still up lol

low mica
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Domain: [-2, infinity)

Range: [-4, infinity)

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Domain: [-2, infinity)

Range: [1, infinity)

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Domain: (negative infinity, 4)

Range: (-16, infinity)

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Domain & and range: all real numbers (infinity, infinity)

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Domain: (negative infinity, 3)

Range: (negative infinity, 16)

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Domaine: [-4, infinity)

Range: (negative ifnity, 2]

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aren't all these just (negative infinity, infinity)

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D?

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still two <--> arrows

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so

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still all real numbers

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anyway

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so

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i have an answer

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let me try use latex rq

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yeah ok idk how to use latex

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but

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first equation: $50$, $x \leq 400$ $\ \$ Second equation: $0.30x$, $\text{idk domain}$