#help-33
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and how it says only the forces along the diagonal contribute
i don't understand why
@buoyant pawn Has your question been resolved?
<@&286206848099549185> pls i've been stuck on this for so long
<@&286206848099549185>
@buoyant pawn is there any more information on this?, like a diagram?
I think there is physics's concept for direction of force
the second image is the diagram
FREE SOLUTION: Q40P In Figure, four long straight wires are perpendicula... ✓ step by step explanations ✓ answered by teachers ✓ Vaia Original!
here's the full answer if you want to see more context
it is the component of the force along the diagonal, and in order to get the magnitude of the force along diagonal u take the component of the force vector
but why do we need the force along the diagonal?
force by wire 3 will act diagonally, and by symmetry the sine component for wire 2 and wire 4 will cancel out ( the direction perpendicular to the diagonal direction)
and the component along diagonally of wire 2 and wire 4 will add up so it is 2 times the cos component
i thought wire 4 is placed opposite to wire 1, replace wire 3 with wire 4
is this diagram correct for the forces?
because isn't wire 1 attracted to the other 3
yes it is but you want the force on wire 1
it is the opposite
u need to calculate the force ON wire 1
by others
i saw this in another problem and i don't understand when to use this law
vs sqrt(x^2 + y^2)
that drawing is for the forces on wire 1
i thought
it is the drawing of force exerted by wire 1 on others
that would mean wire 1 was repelling the other 3 though
i thought it was attracted to them
bc their currents are in the same direction
i think you are correct
sorry for the misunderstanding
no worries
i don't think it really matters in the context of this problem anyways because we just want to find the magnitude
yes, your diagram was correct
yes, but in bigger picture our concepts should be accurate( in this case mine)
okay i think i understand it now
i hope you found the reason of diagonal direction
you use the parallelogram law to find the combined vector and then you add that to the other vector
bc they're both in the same direction
yes
i don't know how i've gone through calculus 1 2 3 differential equations and mechanics and i've never heard of this
the reason other component doesnt add cuz they cancel each other
it is more concentrated to vectors unless you studied vector calculus, you wont be seeing vectors that much
but we spent like 2 weeks on vectors and then went into multivariable stuff
and then linear algebra stuff
one component is in the direction of diagonal and other is perpendicular
so the in the perpendicular direction of diagonal force by wire 4 and wire 2 cancels
what does the second drawing represent?
ok now i'm confused again
isn't the angle between F4 and F3 45
and F2 and F3 45
but it's 90 between F4 and F2
so when they add F2 and F4 why do they use cos45 and not cos90
can i do it this way?
Ok so, when you directly add the vectors
That is by using that formula, you use the angle between the vectors
And about the components for the vectors
Yes it is correct
Yeah with these problems, it’s really helpful to split into components
Vector addition is really complicated otherwise
But components of vectors are really helpful and is used in the solution you
Provided
eh
they're not super different imo
E&M is just harder bc you can't really visualize anything
you need to develop a lot of intuition
What’s your major
mechE
ok i think i finally get it
in that solution they split the diagonal vector into 2 and then added those to the horizontal/vertical components
Yes, and since they are equal in magnitude you see 2 F cos45
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how does it go from the original series to the next one
lhopitals rule doesnt do that, deriving it doesnt do that either
What does L’H have to do with anything here?
Start with dividing all terms by n
It's not changing to that second step lol, they're 2 series of exact same degree of n, being compared for the diversion test
It's called comparison test look it up
fml, im braindead 💀
tysm 💛
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Pls help
In the xy-plane, the graph of the equation
y = —x + 9x— 100 intersects the line y = c at
exactly one point. What is the value of c?
is that a parabola?
-x^2
if it is
find the x point that the derivative is 0
and put f(x0) there
its something like this
and if it isn't -x^2 just do y=0 , -x+9x-100=0 , 8x=100 and x =12.5
@final flicker Has your question been resolved?
so what's the answer
first you should said that it's x^2 or x
sec here we just helping you not giving you the answer
this is the solution if its a parabola
wym?
.
-x + 9x
is -x = $-x^2$
Not Scammer
because the problem is wrong if it isn't
no it's not 9/2
so
it is f(9/2) which is -79.75
yes
if it's a linear line than it intersects every y=c line one time
why
how is c y-intercept
y-intercept is a different thing than intercepting every line parallel to the x-axis
does y intersect c every 2 times in parabola
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@cedar smelt @honest quiver i know other way
you get the x coordinate of the vertex
so it's gonna be -b/2a
so you plug in the b and a from the original equation to get the answer of -b/2a
so it's gonna be -(9)/(-1)2
so you get -9/-2 which is also 9/2
that true and also you can B^2-4ac for seeing it gonna intercept x
no
that's for finding the roots of x or x intercepts
why need it
put 9/2 as x of f(x)
and you get -319/4
ph yes
✅
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scemmer
✅
What do you mean?
what happens when a +b + c = 0 in a quadratic function
That’s not a quadratic function
The coefficients you mean?
wait no
Your question still doesn’t make much sense what you mean by “what happens”
f(x)=5x^2-3x-2
Here’s an example of such a quadratic function
What do you want to know about it
like will y = 0 if the x^2 + x + a = 0
What?
Okay so your first step to understanding would be to rewrite the equation as a function of y
Can you do that
make it in the form y=f(x)
byt y is f(x)
Yes that’s why they’re equal
ok so y = 1x^2 +9x-100
Not quite, there’s a small mistake, it should be -1x^2
Unless you made a typo here
y = -1x^2 +9x-100
And you want to know, when is this quadratic function 0?
Or what do you want to know about it
Okay
ok
y = -1x^2 +9x-100
yes
This is a function of x
ok
So, for it to “be 0” that means, you put in an x-value, and the y-value you got out was 0
Does that make sense?
So say you wanted to know, when is it actually 0, then you need to find the x-values that when you plug them in, y=0
Agreed?
no i'm not
i didnt change
it's ax^2 + bx +c =0
so
a= -1
b= 9
c= -y-100
so
No
why not
c=-100
no
Yes
we want y= 0
y=f(x)
so y should be in c
No
Listen I’m not going to argue with you about this
okay
np
we take the y the other side
y=f(x)=-x^2+9x-100
There’s no need to take it to the other side, and that actually makes it incorrect
y=f(x)=-x^2+9x-100
This is what we have
This equals 0 when
0=-x^2+9x-100
So a=-1, b=9, c=-100
Hopefully that helps, but if not I suggest you find a different resource
No
Since it’s incorrect to subtract y over
what's the difference between yand fx
There is no difference
there is
otherwise why need an alternative for it
There is no difference
The reason is because it is more convenient at times to write just “y” than f(x)
Or, sometimes we want to represent two variables, x and y, without them actually being related as functions of eachother
okay
Or, sometimes we just want to look at points on the xy-plane (x,y) without talking about functions
But in this case, there’s no difference
that's what u just said but ok
😭🙏🏻
alrighty
They’re not exactly the same and I’m just trying to give you different ways of seeing it
okay ty
nvm
oh yes 0=y-y
therefore y = 0 when c= -y -100
so the vertex will be (0,0)
or maybe not
bs
No
y = -x^2+9x-100
Both sides are EQUAL they’re the same thing
Exact same thing
If y=0
Then the other side
Also equals 0
0=-x^2+9x-100
what you’re doing, is just subtracting y to the other side
But that isn’t making y=0
i'm opening desmos
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in 2nd problem = no test means tests happens both days so answer should 1-1/3.1/3 ,am i correct or wrong
I think it’s saying that the probability that a test occurs in a given day is 1/3. Since the student is at home, then they must miss the test. So the probability otherwise is 2/3
Does that make sense?
but in ii) we have to find probabilty of atleast one test missed so as given in img but i think i should be 1-1/3.1/3 insted of 1-2/3.2/3
net gain will be 0
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what happens when a quadratic function = 0?
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without the space after $
DJJ
Thanks
i just put C for now, but idk how to do it
my "a" and "b" for both arc length integrals are 0 and 4 respectively, right?
You're right about 6-2x
when i type it in my calculator it lands on none of the choices
Haha it happens
😭
stuff like this
im just wondering if this is my R
and also how would the line of revolution being y=0 affect this
yes
it will give a 3d object that looks like 2 cones smashed on each other
scemmer
the empty space between my area and the line of revolution wont do anything to my final answer?
actually, i should finish the reading for that 😭
mhm, so just the integral of (top-bottom)^2 from a to b would work?
!occupied
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check this
khan explains very well
Too bad too sad, because no one has answered my question yet even though I made my own channel
it doesn't mean you can occupy other channels tho
tag helpers and wait if you need help
in your own channel.
This is my own channel
100%-20%-20%-20%=40% 40% of 70k is 28000
plug stuff in and viola
wait i spelled that wrong
but u get the point
I know the first part is 2800 (thank you) but the next part is to find out how much it will be in 10 years then rounding off to the nearest cent
ty for that, ill watch it rn bc my test is in a few days and im running outta time 😭
this one is better
well, better image to understand since it labels it, but same formula
Rounding off to the nearest cent is the hardest part
.326 cents rounds to .33
So the answer would be .33?
no, i left out the dollar amount here and just gave u the rounded cents
plug ur numbers in here
I don't know how to do anything 😔 I just wanted the answer solved
Ye photomath gave me incorrect answers
Ok I know it's 50,979.36 or 50,978.80 or 51,019.36
Nah
But it's confusing
which part
Ye it's either those 3 numbers
This part
if you go here and plug the numbers in youll get the real answer
Are u able to do it for me
Wait so what's the final answer u got?
u tell me what u got first lol
ping me when ur back
Can you screenshot what you typed for me?
I typed that into the calculator
That looks suspiciously similar to chat gpt
Nah I just type it out lol
And last time I checked... my calculator doesn't talk to me, it just gives me numbers 👀
Use your phone calculator
I did
Android
Btw what answer you came up with
...
😭
U see that setup?
If u type EXACTLY that and THEN press "6" you will get my answer
So basically 51,019.32?
Type that in
Type what in?
so 0.6?
I'm scared that you're suffering from C.I.S.
Yeah instead of 0.0 u put 0.6
CIS = calculator illiteracy syndrome, aka "chat gpt is close enough" 👀
I used to have it... and I got like a 20 on 3 homeworks in a row... and then I was borderline failing... then I WAS failing... buuuut I clutched
Do I type that in the computer?
Cents goes to only 2 places so we need to look at the 3rd one to determine if we round up
No do it manually
The third digit is 6
Is 6 greater than or less than 5
So 36?
Nope
51019.326?
ANSWER MY PROMPTS PLS 😭
Greater
Good
If it's greater than or equal to 5, then we can round up by 1
So 32.6 cents rounds to 33 cents
Ahh because it's closer to 30
When considering rounding, compare the digit in the next place to 5
Well
Correct and incorrect
IF you were told to round to the neatest 10 cents, or to the nearest dime, then that's correct
BUT
You were told to round to the nearest cent, or the nearest penny
Ohh
And you have 32.6 cents
You can't have 0.6 of a penny
So you found up at 33 pennies or 33 cents
Np
Well partially the rounding off still gets me a bit confused
Oh make sense
X=4logx, how do I go about solving this?
So it's always the third digit that you round off from?
And not the second
?
Nope
U said they asked for nearest CENT
That's the 3rd digit
If they asked for the nearest DOLLAR
You would round to 51019
Since now ur considering the .3
And 3 is less than 5 so don't round up
Log base of what?
Kk I appreciate the help
Np
10 or e
Base 10,
Really im trying to figure out how to@compare algorithms (log base 2) but I completely forgot how@to@work with logs, last time@I used them was over 10 years ago
I even tried to ask chat gpt and it doesn’t give me an answer
Wait is it 8 or 4
Here u put 4
4 is fine, it’s more about trying what identity I need to use
I don’t care about the actual answer but the method I need to use
Tbh I got no clue
Yeah, I can’t find any help for this problem online
I don’t even know what I would call it
Are you familiar with the lambert w function?
i think i got something
i need like 5 more mins
This is a complete mess
Thank you!
Wait what is this even for
I'm asking bc it doesn't look like any normal problem 😭
I am reading about algorithms, and was trying to compare a n and log n algorithm. My questions was “at what n does one algorithm become faster than the other” so I thought, easy just solve for n.
Apparently not easy lol,
well
i got that as an n
which is equal to that or...
@graceful prawn thats the work if u want but idk if its very helpful 😭
W(ue^u)=u
helpful for setups like W(xe^x) because the output is x
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Hey
How can I find the area of a circle without knowing the size
What do you know
NOTHING else???
Man. It's dumb. I should contact my teacher lmao
Can u send a picture of the problem
I can't take screenshots like that on mobile
Is it possible to type it out/copy paste
But there's no photo. It says find the area of the 2d circle
Should there be a photo?
Does it give diameter, radius, circumference?
No it only tells me to find the area of a 2d circle
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yea bro I want that
do they give you the value of d at least? 😭
the question is so broad looool
😭😭😭
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Got it correct my guy @dusk moth
@sour yew Has your question been resolved?
wot
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Real quick how is this function odd
what is the definition of an odd function
uh f(-x) = -f(x) ?
Substitute -x everywhere you see x
cos(-x) = cos(x) so i did
They gave the words 2d circle lmao
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when solving the part (a) is it correct to say "since each point in the triangle is equally likely to be chosen, the joint density function is uniform and we find the value of density, which is constant over the area of the triangle."
the joint density function is uniform
yes
and we find the value of density, which is constant over the area of the triangle.
well you have to actually provide the density, as well as the bounds
how do i do that
how do you normally find density functions?
well it depends on the random variables, if they are discrete or continious
it should hopefully be clear which of those two you're working with
yes continious
if the density is uniform, then the density function is just some constant
yes. okay but then it should be constant over the area of the triangle?
yes
aha okay then it is 2
provide the correct bounds
saying the same for y would make your bounds a square
right okay, so i must say 0≤x≤1 and 0≤y≤1−x
you must
thank you so much ))
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Jeff has taken out a loan for college. He started paying off the loan with a first payment of $175. Each month he pays, he wants to pay back 1.4 times as the amount he paid the month before. Show Jeff how to represent his first 36 payments in sigma notation, either using the equation editor or uploading a picture of your written notation. Then explain how to find the sum of his first 36 payments, using complete sentences. Find the sum and explain why this series is convergent or divergent. (10 points)
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hi! so i was looking to answer what percentage of engineering respondents work in europe but im a bit confused. naturally, i divided the number of engineers by the number of respondents in europe but that ended up with 93% which wasnt an answer choice. what would be the best way to approach this?
find percentage of each and multiply
could you further explain that? percentage of what exactly should i be calculating
percentage of european with respect to the whole
multiplied by number of engineers
it's like estimate right
not derive a specific answer?
also, to further add onto the info, i added all the departments together and the regions together but they dont equal the same number so im not sure if that has an affect on the answer
the choices are cannot say, 17%, 22%, 46%, and 8%!
a good estimate would be 17%
But if it's asking for an exact value it's probably not possible
may i ask how that was estimated?
or i guess, the reasoning behind the estimate would be a better question
it's just the general probability of European
In theory should be the same across all subsets
so it's 1210/the sum of all of them so 6967
this makes sense, thank you so much!
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im trying to do the part (b) but im not sure of my solution i did it as integrating the joint density function over possible values of x for a given y, is that correct
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i got n=10 and k=1
Do you know binomial theorem?
yup
wait
Well, by the binomial theorem, k * (n choose 1) = 10, right?
i compared nx with 10x
It should be nk=10
yep
oh
nkx = -10x
1 + n(-kx) + n(n-1)/2! (-kx)^2
i didnt take the negatuive tho
m2 in my first take
i compared it with the (1-x) one
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On the first one, -(x+1) turns into -x-1 so overall 2-x-1=-x+1
on the second one its the reverse thing, you put it back in the bracket
I'm sorry I dont understand. Where does the 2 go?
try opening the brackets
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Don't close and reopen a new channel just to post the same question
dont close and reopen it if ur not getting answers
I can help u solve the mathematics but im not here to fill in gaps of content you don't know.
i looked through my textbook and there isn’t any formula idk y
what textbook is this in?
chemistry fourth canadian edition john a.olmsted
yeah they would've made the assumption that u know a certain level of maths
do u know the volume of a sphere?
Galaxy
but how is this the same as atom and nucleus
are we just using the sphere equation because it’s sphere shaped i guess
i mean its from a chemistry textbook, but i'd still say this applies
A nucleus can be roughly modeled as a sphere I suppose
so let’s asking to compute typical atomic and nuclear volumes and i don’t have a formula in my textbook so do i assume it’s the e sphere one @maiden trout
Yeah I’m not sure it depends on the level of chemistry you’re studying
it’s just first year
but i don’t remember doing the sphere equation for anything in hs
that’s y i’m confused
also i just assumed the formula would be in the textbook
Yeah if i had to guess it seems to be a simple application of spherical volume
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A bit confused on how to approach this question
nice
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wait do you by chance know why c is how it is
I have the answers but I'm not exactly sure if my reasoning is correct
Not really, I have seen the proof, and results from other relations but never paid much attention to it nor does it stick in my mind
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is this wrong or what?
there's 8000 from below and there's 1000 from the gravity, why not 70 m/s²?
70 seems... legit
Might be in space
it says "during lift-off"
but it would be true in space right?

could mean lift off from a planet that happens to have a gravity defying lack of gravity
Yes
ok
sO true
thank you all
assume the elephant is a sphere
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I was learning some vector calc and encountered a vector field where there's a hole, and somehow it turned out very very similar to the residue theorem from CA, i was wondering about the connection that there were 1/2ipi factors coming out and also 2pi factors coming out in the vector calc version
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i dont know what the specific question i want to ask is
it just looks really similar
😭
is it possible to perhaps recover one of them from the other?
or is there some sort of direct translation of how such a vector calc problem can be rewritten in CA as a contour integral instead
what kind of vector calc problem
I can send you a few resources
one sec
it was the last part here
when the singularity (1, -1) was inside the interior we could shrink any simple closed curve into that small loop around the singularity
very similar to what you do in CA
OOHHH
when you identify the C -> C functions has R^2 -> R^2
you have a 2d vector field
🔠
so where did the i come from in the residue theorem again
is that the parametrisation being e^{ix} where x goes from 0 to 2pi but the integral of that guy spits out an i
you get ie^{ix} as the primitive so when you do the limits there's a i left over
it comes from the cauchy integral formula
but in the real case you dont get the i because your components are in terms of the 1st and 2nd entries
which just ends up being sin^2 and cos^2
hmmmmm
yeah im thinking that the specific part that gives us that i is the parametrisation
the part where we need to call our parametrisation e^{ix}
so when we integrate that guy we get an i out the front
i understand the cauchy integral formula but in the derivation of that we get the i through this i think
that's why the real version just has 2pi but the complex analogy has an i out the front
alright thank you sir austin
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hi
someone please help me out
I wanna know how to solve 12 and 13
can you help me solve it I am stuck
So the first step would be to determine where you are stuck
no clue how to answer
Find the midpoint
If you have two coordinates (x1, y1), (x2, y2) taking average of the coordinates will give you the midpoint
ok then?
then wha tdo we do?
The gradient perpendicular to the line is -1/m
from there use m(x-x1) = y - y1
I would prefer if you performed the actual steps first before asking about subsequent steps
I wanna know just how to do it....
You are not listening to me
im
Find the midpoint
idk what that is..
I gave you definition earlier
I am done. I would recommend you refer to some YouTube video starting with how to find midpoint
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The answer would just be {2, 3, 4, 5}
which is just "A"
because "B" and "C" have nothing in common
yep
pixel
U is union, v is or
so i think it would be asking for (-4, -2] v (1, 5]
kind of a weird question tbh
But how do you know (c,d,e or f) are not equal to 4,5,6,7.
union is the same thing as or, no?
i haven't heard of 'v'
they arent the same thing though
im going through the basics of my topic since I am revising so I can tell you for sure that it isn't that complex
ok
mm but its still union in my question regardless
i'll worry about 'v' later when I'm taught about it
or when I have free time to teach myself
although i'd prob focus on calculus then
i know this content, im just making sure of my knowledge cause I haven't done these topics in months
have an exam coming soon sooo
If you did union instead, it would mean that you are combining the two into a set
or means you are choosing between the two
although based on the question, it looks like you would want union, not or
well yeah wouldn't that be describing the subsets
yeah that was my bad, i didn't mean to use 'or'
i didnt even know it had its own separate thing
ill be more careful next time with my wording
f
for this one, would we quite literally just dot those coordinates down
and connect them
and it'll make a graph
then we can use the vertical line test to see if its a function or not
if that's how its done then I wont waste my time doing this, seems really simple
(the vertical line test is where we draw a vertical line anywhere in the graph, if there are two intercepts then its not a function --> circle wouldn't be a function)
is this notation supposed to mean 0 is mapped to 1, 0 is mapped to 2, etc?
if so, one disqualifier for being a function is when you have an element in the domain being mapped to more than one element in the codomain
however, you can have 2 different elements in the domain being mapped to one element in the codomain (such as (-2)^2 = 4 = (2)^2)
precisely
yeah thats fine
yeah ill skip over that then
ima send images of 6 graphs in a bit
and ill attach the domain and range for them
is it fine if u check my answers
if im still up lol
Domain: [-2, infinity)
Range: [-4, infinity)
Domain: [-2, infinity)
Range: [1, infinity)
Domain: (negative infinity, 4)
Range: (-16, infinity)
Domain & and range: all real numbers (infinity, infinity)
Domain: (negative infinity, 3)
Range: (negative infinity, 16)
Domaine: [-4, infinity)
Range: (negative ifnity, 2]
aren't all these just (negative infinity, infinity)
D?
still two <--> arrows
so
still all real numbers
anyway
so
i have an answer
let me try use latex rq
yeah ok idk how to use latex
but
first equation: $50$, $x \leq 400$ $\ \$ Second equation: $0.30x$, $\text{idk domain}$