#help-33
1 messages · Page 119 of 1
semi?
im not a math girlie, ima bio girlie but i am getting the hang of it
im majoring in bio
i want to graduate and then come back and get my astrophysics degree
thats nice
yes
,w tan (157.3)
so cool
-.418?
wait what
thats the result
oh oh
sin are you a computer science major
either that or doctor of medicine
still deciding
yeah that makes sense
Now convert 157.22 degrees to radians
and you get ur answer
Hoping you know how to do that
:D
🫠
Whatd you get?
i did
What did u get?
i got 157.22pie/180
that is?
do that
use a calc
divide 157/180
and multiply it by pi
2.74401
:D
i can explain it to you
in detail
because this concept you cant do
with that just sheets
its very easy, but you'd have to take baby steps
there were two unknown concepts for you that you had to do in this which i don;t think you've learned about before
so i have to explain you that
yeah no i havent
i had it explained to me before but i didnt understand it and didnt want to bother my prof over it
well
if you can hop on vc
ill explain it to you in about
10 mins
maybe
well maybe not 10 but a few
okay
js add me up
yeah my friend req are off so im gonna add you
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Hi
you find the points of intersection of those 2 equations
then find the area by integration(upper func - lower func)
and use points of intersection as the limits of the integration
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How do I do this?
dyk how to find out area of a sector
nah
have you seen this formula
(angle/360)pir^2
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Nalla Manithan
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
,tex x -5 \equiv (mod 7)
Nalla Manithan
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
,tex {\frac {x-2}{5}} = k
I think they meant to type:
x = 2 (mod 5)
x = 5 (mod 7)
@still temple
Chinese Remainder Theorem does apply. Did your class go over that?
Another alternative is that we can search for numbers that satisfy x = 2 (mod 5) until we also find numbers that satisfy x = 5 (mod 7)
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@still temple Has your question been resolved?
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This topic is system of equations in 3 variables and i rlly did try my best to wrapped my head around it, but pls guide me to form the equations 😭
,rotate
(only does the last of the pictures it finds)
thats the answer, our teacher give us the answers and let us try on our own
(I was saying that the rotate command rotates the last picture it spots)
oh okok
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the last question pls!!
i understand solutions until the distance ^2 part
something to do with scalar resolute?
sorry the symbols are not working?
v.v = |v|^2
yep
That hw the got distance^2
oh ok, but where did the n dot n come from?
Is this chegg?
i dont think so
In which part of the solution?
nevermind i got that, now im just lost on their final step
would it not equal to this?
can you simply remove the square, and call it the magnitude?
OHH
Not distance
What course are you taking
University level?
high school
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Someone helpp 😭 the answer i got was math error so pls tell me what i did wrong
i cant read anything its too low-quality, can you send it in a higher quality?
Dont mind the solution for the second picture cuz ik its wrong or maybe not i also dont know
Ok so you put the 4th eq you wrote into 1
yeah thats where it went down
in my opinion and experience
try to simplify the equation as much as possible before putting it in an equation
What did i do wrong again 😭
Ohh okok ill take note of it
mistakes happen
dont let it upset you tho
these mistakes are something that can be fixed with more practice
try to write the square or any kind of power smaller than normal and a bit higher
I GOT ITT
Hope so
Tqq for all the tips and tq sm for guiding me 🫶🏼
You are welcome and good luck on your exam ^^
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What is the average distance for a random point in a 1×1 square to the boundary in a random direction?
This is the correct answer from the Internet, but I don't understand how E(s) is obtained.
@scenic adder Has your question been resolved?
My guess would be start by fixing the arbitrary direction, say for example 37 degrees and try to calculate the answer in that case
Then use an integral to find the average over all the possible angles
@scenic adder Has your question been resolved?
Hmm... I guessed so too, but why does E(s) look like this?
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@scenic adder Has your question been resolved?
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for this graph there is a question: what is the solution of f(x) < 0 and f(x) > 0 and i understand using the vertex (1,-3) which means x = -1,3 but i dont understand how to get to the answer (f(x) = -1<x<3 and f(x) = x<-1, x>3)
Its pretty easy if u understand how a function works
f(x) returns a value for each input value of x, we then plug this value f(x) to the y axis
So we have a graph on OXY plane
Consider this blue point
Where x = -2
Then whats f(-2) = ?
how does that help me with inequalities?
the < and > confuse me
like i get x = -1,3 but i dont know why -1<x<3
what about for f(x) > 0
the solution is x<-1, x>3
Yes
If the alligator chooses to bite f(x)
Aka f(x) is bigger
Then x is less than -1 OR x is bigger than 3
but if f(x) is > 0 how could x be less than -1?
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can someone explain why the integral of 1/x dx = ln |x|
why absolute value?
Because you must consider integral of 1/x when x is negative
why isnt it undefined when x is negative
according to desmos the definite integral of the func of x -3 to 2 is undefined
This is undefined because you are crossing 0, where the integral is not defined
then why is it 0 when it's -2 to 2
It shouldn't be
oh
That's an erroneous calculation if you're getting that
visually it looks right though
why isnt it the def integral from -3 to 2 not equal to the def integral from -3 to -2?
because -2 to 0 and 0 to 2 cancel out
even though they cant be calculated
but why is the absolute value there in the first place
why isnt it just undefined
if integration is inverse derivative, then it should pass the horiziontal line test
They do not
?
Whatever calculator you are using is probably assuming that you were doing an improper integral, in which case it would cancel out
But for a proper integral, it will always be undefined
Yeah it's probably assuming improper integral then
Now for this question
Because we still need to calculate integral of 1/x for when x is negative
And when $x<0$, you would find $\int \frac{1}{x}=\ln(-x)$
SWR
why cant it just be undefined
why isnt it just undefined
ln isnt defined for neg numbers
It's not undefined because it is definable
You are correct. It is not.
why is it definable though
If x<0, then -x>0, so ln(-x) is defined
but the derivative is ln(x) not ln (-x)
Inverse? Wdym?
i meant the derivative of ln x = 1/x
we never heard or anything saying ln -x
oh wait i see how
You can use chain rule
Exactly right
.close
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A car slows down from 28m/s to rest in a distance of 88m. What was its acceleration,assumed constant?
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Determine the point (x,y) on the ellipse $\frac{x^2}{a^2}+\frac{y^2}{b^2} = 1$ for which the area of the triangle with the corners $(0,-b), (x,y)$ and $(0,y)$ get the biggest area
Merineth
I have an idea on what i'm supposed to do
It has something to do with derivatives to find the maxima
However i'm not entirely sure how to proceed
I know that the area of a triangle is $0.5bh$ where the base is the length from $(0,y)$ to $(0,-b)$ and the height is $(0,y)$ to $(x,y)$
Merineth
is the answer in terms of a and b
(the point (x,y))
i got (0.5a*(sqrt3), 0.5b) using lagrange mutlipliers, but i have no clue if i did it right lol
I'm not sure what you mean but afaik i'm supposed to find the point(x,y) which maximizes the area withing the ellipse
yea it makes sense if the answer is in terms of a and b
otherwise it wouldn't vary with ellipse size
are u familiar with lagrange mutlipliers
No i'm not
do you know gradient? $\nabla$
Stephen
Yes
Calc 3
Ok, I understand.
I'm not too sure on how to do the problem otherwise, I always just use L.M. for optimization
Well the Area is defined by the length between the points.
And since i'm given the equation for the ellipse. Couldn't i insert the area of the triangle into the ellipse equation?
Derive it for ciritcal points
yea sure why not
I'm not sure but that'd be my guess
try that and see what u get
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Everyone died
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?
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why is the lim to 5^- undefined but 5^+ does not?
is this bcs in the LHL if we put 5 in the root it becomes root - 10?
the root is negative
since thats not on the domain of real numbers for the root function it is undefined
the - and + sign means approaching from that side
5^- would be from the left, so you would go from -inf to 4.999999999 ... and 5 - 4.999999999 is negative
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what does part b mean?
i know the DE is exact but im not sure what its asking by the geometric or physical description of the solution
same here
for 4a I got y = 1/3 sin3x
and the graph is just a regular sin graph
so is the physical decription just that its wavy idk
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I've seen a few memes about something with d and dx (in relation to integrals i think), but what do they mean? I kinda understand what integrals are, but not what they have to do with d and dx.
tl;dr it's a notation for "variable we're integrating with respect to".
There's a plethora of vague reasons we write this.
- It kinda looks like Riemann sums!
- It makes u-sub easier
- It cancels with a derivative in the integral
But none of that is like a "mathematical necessity"
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cause they want to use it in the next line?
to get whatever somewhere after that?
its not like using f(z_n) >= y is wrong
it is when u look at the entire proof tho
cz the proof involves
saying
soemthing >= y and something <= y and therefore it is = to y
however in this case we know f(c) > y but since earlier in the proof we also showed f(c) <= y wouldnt that be wrong
the whole proof if u wanna see
even if f(z_n) > y, that wouldnt translate to the limit
why not
for example if z_n = 1/n > 0, then still lim z_n = 0
in general if a_n > b, then still lim a_n >=b only
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Need help with b part
The question states: find the moment of area about y-axis for the part of surface generated by the line x=4 (red line)
I'm so confused,
Btw the whole shape is rotating around the x-axis
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On this I have to set e^y = y^2-7
and then solve for y
but I have no idea how to do that
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The answer is E but I can’t figure out how to get it
I see you have the region sketched out already
Imagine rotating it around the y axis
How would you cut it up into circles? What would the radii of the circles be?
No, precisely because they’re horizontal
So you should integrate with respect to y
And it is disk method right?
Why did you square y^3?
Cus I was just throwing stuff in my calculator and it would be the value of X
Don’t worry about that yet we have bigger problems to fix
If you’re integrating with y your bounds should be from 0 to 2
Then you find the radii in terms of y
Ok
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How do i do this? Is there a trig identity for this?
Use subtitution
To get in the denominator something u must recall
From the derivative of arctan
I said derivative
o
U know derivative of arctan
Not off the top of my head
It is 1/(x^2+1)
Ok so use subtitution to get that denominator or something similar
im stuck
.
What sub u did
That doesnt make too much sense
this looks closer to the question
1/4 integral 1/(sqrtu(u+4)) du
wait so what was u
Ok so if u do that sub
U get this
U are suppose to know how to do this steps btw
If u cant, you should try easier exercises with subtitutions
Now u need another sub
I tell u the sub and u do it
ok
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A math class consists of 24 engineering majors, 12 science majors, and 6 business majors. 8 of the engineering students, 6 of the science majors, and 3 of the business majors are female.
What is the probability that a student selected at random is a business major given the student is a male?
Do you know bayes rule?
was wondering if this is just 6-3/42
no
Can you show your work
Are you just doing # of business majors who are male / number of men
yes trying to find what the probability that a student selected at random is a business major given the student is a male
Then no ur answer is incorrect sadly
You are doing # of male business majors / total number of students
Do you know how to count the number of total men?
You were able to find the number of male business majors, so try doing that with all the majors
25 total men
So what should your answer be?
is it 6/25?
No
Now you’re doing # of man + woman business majors / number of male business majors
is it because they are asking to find the chance that out of the total men what would be the chance that they would be in business?
.close
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is it correct!
No idea what I’m looking at
Yeah you should post the question first lol
i summarized it on top of the problem i was solving
lmao
😅 lmao
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What have you tried
well idrk where to start
i did a similar question earlier but this one is harder
this is the other one i did:
Well here’s what I’m thinking, if a line intersects a parabola only at 1 point, it’s either a vertical line, or it’s tangent to the parabola
Does that make sense?
yeah the question says tangent
Right, and if I write my line like y = mx + b
Do you agree that this is a line but not a vertical one?
yeah
Now if I tell you my line mx + b intersects the parabola x²
How would you find where they intersect?
using discriminant formula?
(Your answer will be in terms of m and b as they are constants I haven’t given you)
Not quite, I want to find when are 2 lines intersecting
If a point (r, s) lies on the line y = x²
That means s = r²
If a point (r, s) lies on the line y = mx + b
That means s = mr + b
If this (r, s) point lies on both the curves then surely r² = s = mr + b
ohh i see
The idea here is that the points of intersection between x² and mx + b will be when x² - mx - b = 0
Ah but this means in general we will have 2 intersections
Ok but we note from here that we dont want 2 intersections
Rather we want only 1 intersection
Here’s where the discriminant comes in
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hey ive been trying to figure out how do it even after all he help u gave me i ant figure it out
could u help a bit more pls
Alright, so when this equation x² - mx - b = 0 has 1 solution only, our line touches the parabola only at 1 point, aka is tangent to the parabola
We can “force” it to have 1 solution by making the discriminant of x² - mx - b to be = 0
We lastly also need to use the fact that our line y = mx + b has to go through the point (1, -2)
This means whatever m and b we have, it needs to satisfy -2 = m(1) + b
This is what it means for (1, -2) to lie on the line y = mx + b
We have 2 unknowns m and b, and here
1
2
2 equations, so we just need to solve for the solutions here
k ty
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Doing basic calc, my answer to this question is 3x^2 * ex + x^3 * ex. The answer is different according to my lecturers mark scheme, just want to confirm if I am right or wrong and how their answer is right (if it is).
do you have to darivate it ?
that's the same thing but factoring out x^2 e^x afterward
ah ok
an easy way to remeber this formula is left d right d
mark uv as u is left and v is right
k
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$\lim_{x\rightarrow0}\frac{\left(\tan\left(x\right)-\sin\left(x\right)\right)}{\sin^3\left(x\right)}$
ƒ(Why am. I here)=I don't know
you can factor out 1 - cos x
yeah
then you can convert the bottom sin^2 to 1 - cos^2
np
$\lim_{x\rightarrow0}\left(\frac{\left(1^x+2^x+3^x...n^x\right)}{n}\right)^{\frac{a}{x}}$
ƒ(Why am. I here)=I don't know
so here
what series am I looking at
I suspect something factorial
hmm
Let me ignore the 1/x for now
that's just 1 in the bracket
so let the limit be L
$\lim_{x\rightarrow0}\left(\frac{\left(1^x+2^x+3^x...n^x\right)}{n}\right)^{\frac{a}{x}}=L$
ƒ(Why am. I here)=I don't know
$\frac{a}{x}\ln\left(\lim_{x\rightarrow0}\left(\frac{\left(1^x+2^x+3^x...n^x\right)}{n}\right)\left(\right)=\ln\left(L\right)\right)$
ƒ(Why am. I here)=I don't know
hmm
now I l'hopital i I guess
I feel that would turn messy real fast though

$\frac{a\left(\ln\left(2\right)2^x+\ln\left(3\right)3^x........\right)}{\lim_{a\rightarrow\infty}\sum_{a=1}^na^x}$
ƒ(Why am. I here)=I don't know
hmm
the hell
I know lol
It's a a fun problem though ngl
I think I almost got it
nah, I'm getting an e 
do you have any guess if what it is?
what if you take n common from num?
why won't this work though
my brain hurts to go your way
is it $(n!)^\frac{a}{n}$
ƒ(Why am. I here)=I don't know
yea
did you take x out of the limit
idk what you did but your expressions are kinda fishy
Let me re-write them
in this, the x is outside of the limit
and suddenly its a -> infinity not x -> 0
using l'hopital's rule is correct but something weird's going on with your limits
$\left(\lim_{x\rightarrow0}\left(\frac{a}{x}\right)\ln\left(\frac{\left(1^x+2^x+3^x...n^x\right)}{n}\right)\right)$
ƒ(Why am. I here)=misery
Now I apply L'hopital's rule
take the a out, it doesnt matter, and to make it look a bit simpler, write ln(fraction stuff) as ln(1^x + ...) - ln n
$\left(\lim_{x\rightarrow0}\left(a\right)\left(\frac{\left(\ln\left(1\right)1^x+\ln\left(2\right)2^x....\ln\left(n\right)n^x\right)}{\frac{\left(1^x+2^x+3^x....n^x\right)}{n}}\right)\right)$
ƒ(Why am. I here)=misery
this is ln(L)
1/n on the numerator went missing
it should be $\lim_{x\rightarrow0}\left(a\right)\left(\frac{\frac{1}{n}\left(\ln\left(1\right)1^x+\ln\left(2\right)2^x....\ln\left(n\right)n^x\right)}{\frac{\left(1^x+2^x+3^x....n^x\right)}{n}}\right)$
Ham
where did the 1/n in the num come from
so when you differentiate that there will still be 1/n multiplying the whole thing
don't get it
the differential of ln(1^x+2^x+3^x...)
is
$\frac{1^x\ln\left(1\right)+2^x\ln\left(2\right)+3^x\ln\left(3\right).....}{1^x+2^x+3^x...n^x}$
right?
ƒ(Why am. I here)=misery
yea
so where did the 1/n come from
$\frac{n\left(1^x\ln\left(1\right)+2^x\ln\left(2\right)+3^x\ln\left(3\right).....\right)}{1^x+2^x+3^x...n^x}$
wait
ƒ(Why am. I here)=misery
it shoudl be this
that sill looks wong
you were differentiating ln((1^x+2^x+3^x...)/n) not ln(1^x+2^2+...)
hmm
no
why not
which n
the one in the denominator here
ah, that's $x$ ok
ƒ(Why am. I here)=misery
it's still there in the denominator
then plugging in x = 0 wouldn't cause any issues
np
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can someone help me on this
do you have the
eqn
in 1st one
ax^3+bx^2+cx+d=0
-d/a = product of roots
c/a = sum of product of roots taken 2 at a time
c/a divided by -d/a
or c/-d
thats your answer
(of the eqn in 1st answer)
do u want the equation?
nah
it is 2u^3 + 12u^2 + 27u +25
-27/25
how do u do it in simpler terms
more pls 
like can u show me on whtieboard or paper
maybe on paint
im on a laptop
you gotta wait for a while
go read this
and also realise if u subbed x=u+2
a (alpha) = some value of u + 2
if for a the eqn in x = 0
then for a-2 eqn in u =0
i thought it would be -1/6 as its a sum
no wtf
like adding all the terms and i had a new equation
nawww
could you help me on this other one while we wait
i guess
hmm wait
you must be getting u*root(u) + 5u + 7
now sqaure that
fully
i think*
gtg
ok
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what is the domain of this function
the answer says (-infinity, -1) U (1, infinity)
but i got (-infinity, -(1/3)) U (1/3, infinity)
show work/reasoning
you didn't copy down the expression correctly
x can’t be 0
you sqrt changed
1 or -1
oh thanks!
Yeah you can’t take stuff out of root
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In general, for proving existence questions of the type "prove that there exists ... with properties/restrictions ...", can I first assume the properties/restrictions, then work backwards to construct the object?
Take for example question b) here. Can I first assume that $U=im \pi$ and $\pi^2-\pi$ to find such a linear transformation $\pi$?
Kakaka
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There are A and B cities. And we have Two buses when the first one entered B.the second one was 1/5 of the full road away from B. Need to find the first bus speed if he is 20km/h faster then the second
Pretty easy if u just assign unknown value as a variable
Then try to make the variable cancle themselve out
can you illustrate this by drawing for a better understanding
what part?
illustrate point A and B on a line
ohh
the question itself
i think your explanation is sufficient, im only asking you to draw so you can understand better
ok
after you have drawn, point out how much distance first and second bus have travelled from the starting point
Something like this?
ok i need a equation now right?
if you call the entire path 5x then you wont need to deal with fractions btw
since first bus travelled 1/5 of the path more than the second bus, you can compare their speed actually
you can call first bus' speed whatever you want
i would prefer letting speed of first bus be 5v
in this case, try to find out speed of second bus
nah
first bus went 5x units while second one went 4x units
first one has speed 5v so what should other have
using the equation x= v.t
they travelled these distances at the same time so they have the same time value
ok so t is the same
if you know this, you are two steps away from the answer
4v is the seconds speed?
firs busses speed
you know the v value, you also called speed of first bus 5v
100 what tho
x=4/5x-20
km/h
did you mean to type plus 20 instead of minus?
it seems like you called speed of first bus v here
yes
soo 100km/h is the answer
then you found speed of second bus as 4v/5
then you get a different value for v
and still solve the equation
yeah
you can do the question as many times as you want, by setting up your own custom unknown for first bus speed
Ok got it thank
Btw are you good at pyramid problems i solved one but just need to confirm that my answer is right
send it
got a pyramid with a equalavent triangle as a base the the cercumscribed circles radius at the base is 20 the side hight is 26 need the volume
Got 2400sqrt3 need to confirm if its right
So first we need the base triangles side
can you draw it
Then we find the inscribed circles radius to set up pyth to find the hight
And then 1/3 *areabase * h
how did you get this?
2600sqrt3
Ok take me thro what you did
Step by step
@lucid bridge
What did you get as the base triangles side length ?
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Hello
break up the log
Hello, do you know all the log rules
No😭 please tell me by steps
$\log x^y=y\log x$
mXd
Then that yeah
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Needs explanation. I have tried this question by equating the Transpose of the Matrix to it's Inverse, also tried using the fact that the product of the Transpose of the matrix with itself is the Identity Matrix. Can this be done in a concise manner?
there's another characterization of orthogonal matrices which will help you reduce the number of equations you're dealing with
what conditions should the columns of an orthogonal matrix satisfy ? @severe wing
@severe wing Has your question been resolved?
If we consider the matrix as a rectangular arrangement of column vectors then the dot product between columns have to be zero, and every column must have a norm of 1?
if not, then look at what this says about a b c specifically
yes, I have solved it now. I got two equations by taking the product of column 3 with other two products and taking the norm of column 3. Then I solved for the quations.
alright
I'll check whether the solutions yield the orthogonal matrix by. I just checked if the solutions for a, b, and c atisfy the equality A*transpose(A) = I. Surely they satisfy.
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Thank You for the help. This is my first time ever using a forum to clarify my doubts.
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hi just now learning how to solve this stuff and im not sure if its correct i was wondering if someone could double check my work,
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The first three make sense but can someone pls explain why no.4 converges and 5 depends on G(u)? I cant think of an example
number 4 try conjugating
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how many odd whole numbers less than 3000 can be formed using the digits 0 through 5 with repetition?
This problem confuses me so much, like what is it even asking
it's asking how many odd numbers are there from 1 to 2999 that can be formed with just {0,1,2,3,4,5}
for example 25, or 2543
you are given the numbers 0,1,2,3,4,5
you have to form odd numbers less that 3000 using these digits
even digits can be used but it has to be an odd number
no, its asking to form odd numbers
not that u have to use odd digits from 0 to 5
for ex 1235 is odd
How many options do you have for the first digit
2?
0,1,2 => 3
oh
Consider "00001"
