#help-33

1 messages · Page 119 of 1

echo pivot
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semi

sick needle
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semi?

echo pivot
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im not a math girlie, ima bio girlie but i am getting the hang of it

sick needle
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im a math and bio boy

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LMAO

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i love biology

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literally was studying that rn

echo pivot
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im majoring in bio

sick needle
#

ooh

#

noice

echo pivot
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i want to graduate and then come back and get my astrophysics degree

sick needle
#

thats nice

echo pivot
#

yes

sick needle
#

,w tan (157.3)

echo pivot
#

so cool

sick needle
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mf degrees

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,w tan (157.3 degrees)

sick needle
#

there you go, see

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-0.47

echo pivot
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-.418?

sick needle
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wait what

echo pivot
#

thats the result

sick needle
#

oh oh

echo pivot
#

sin are you a computer science major

sick needle
#

oopsie daisy

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,w tan(157.22 degrees)

sick needle
#

there we go

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thats rounded of to -0.42

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same thing

sick needle
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still deciding

echo pivot
sick needle
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Now convert 157.22 degrees to radians

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and you get ur answer

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Hoping you know how to do that

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:D

echo pivot
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🫠

sick needle
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Whatd you get?

echo pivot
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hmm

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well

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9 and 10 go into 180

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but idk about 157

sick needle
#

pi/180

echo pivot
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i did

sick needle
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What did u get?

echo pivot
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i got 157.22pie/180

sick needle
#

that is?

echo pivot
#

but i still need to simplify it down

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idk how to make 157 more simple

sick needle
#

do that

sick needle
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divide 157/180

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and multiply it by pi

echo pivot
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2.74401

sick needle
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theres ur answer

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,w tan(2.74401)

sick needle
#

:D

echo pivot
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ngl that was kinda hard

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made me think about dropping trig tbh

sick needle
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in detail

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because this concept you cant do

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with that just sheets

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its very easy, but you'd have to take baby steps

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there were two unknown concepts for you that you had to do in this which i don;t think you've learned about before

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so i have to explain you that

echo pivot
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i had it explained to me before but i didnt understand it and didnt want to bother my prof over it

sick needle
#

if you can hop on vc

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ill explain it to you in about

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10 mins

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maybe

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well maybe not 10 but a few

echo pivot
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that would be great

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just ping me when youre ready

sick needle
#

lemme add you then

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waitu

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ur not accepting

echo pivot
#

okay

sick needle
#

js add me up

echo pivot
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yeah my friend req are off so im gonna add you

marsh citrusBOT
#

@echo pivot Has your question been resolved?

marsh citrusBOT
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white sun
#

Hi

marsh citrusBOT
white sun
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I’m confused how to set up the integral

true parcel
#

you find the points of intersection of those 2 equations

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then find the area by integration(upper func - lower func)

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and use points of intersection as the limits of the integration

marsh citrusBOT
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lime citrus
#

How do I do this?

marsh citrusBOT
jovial bear
#

dyk how to find out area of a sector

lime citrus
jovial bear
#

have you seen this formula

true parcel
#

(angle/360)pir^2

lime citrus
#

so 60/360)pi r^2

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?

jovial bear
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yep

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where r is the radius

lime citrus
#

got it thanks you two

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tribal frigate
#

let the weight be x

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then

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,tex x - 2 \equiv (mod 5)

elfin berryBOT
#

Nalla Manithan
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

tribal frigate
#

,tex x -5 \equiv (mod 7)

elfin berryBOT
#

Nalla Manithan
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

tribal frigate
#

,tex {\frac {x-2}{5}} = k

whole sleet
#

I think they meant to type:
x = 2 (mod 5)
x = 5 (mod 7)

#

@still temple

#

Chinese Remainder Theorem does apply. Did your class go over that?

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Another alternative is that we can search for numbers that satisfy x = 2 (mod 5) until we also find numbers that satisfy x = 5 (mod 7)

marsh citrusBOT
#

@still temple Has your question been resolved?

marsh citrusBOT
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@still temple Has your question been resolved?

marsh citrusBOT
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@still temple Has your question been resolved?

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wind agate
#

This topic is system of equations in 3 variables and i rlly did try my best to wrapped my head around it, but pls guide me to form the equations 😭

glass silo
#

,rotate

elfin berryBOT
glass silo
#

(only does the last of the pictures it finds)

elfin berryBOT
wind agate
glass silo
marsh citrusBOT
#

@wind agate Has your question been resolved?

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frozen pasture
marsh citrusBOT
frozen pasture
#

the last question pls!!

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i understand solutions until the distance ^2 part

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something to do with scalar resolute?

wanton ferry
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If v is a vector, $ v \cdot v = |v|^2$

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@frozen pasture

frozen pasture
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sorry the symbols are not working?

wanton ferry
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v.v = |v|^2

frozen pasture
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yep

wanton ferry
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That hw the got distance^2

frozen pasture
#

oh ok, but where did the n dot n come from?

wanton ferry
frozen pasture
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i dont think so

wanton ferry
frozen pasture
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nevermind i got that, now im just lost on their final step

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would it not equal to this?

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can you simply remove the square, and call it the magnitude?

wanton ferry
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Take sqrt

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That expression is distance square

frozen pasture
#

OHH

wanton ferry
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Not distance

frozen pasture
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distance^2 = ( )^2 or distance = ()

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that makes sense noww

wanton ferry
#

What course are you taking

frozen pasture
#

thank you

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specialist maths

wanton ferry
#

University level?

frozen pasture
#

high school

wanton ferry
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Oh

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It looks non standard

frozen pasture
#

it is kind of hell. anyways, thank u for your time 🙂

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wind agate
#

Someone helpp 😭 the answer i got was math error so pls tell me what i did wrong

sour burrow
wind agate
#

Okok sorry2

wind agate
sour burrow
#

Ok so you put the 4th eq you wrote into 1

wind agate
#

Yea

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Is it wrong?

sour burrow
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no its right

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trying to understand this area

wind agate
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U expand the bracket

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Cuz like 84-35 = 49 so (49-y)

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Wait..

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Ill try to redo it

sour burrow
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yeah thats where it went down

wind agate
#

Something is wrong w the expansion

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tqqq

sour burrow
#

in my opinion and experience

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try to simplify the equation as much as possible before putting it in an equation

wind agate
#

What did i do wrong again 😭

sour burrow
#

Ok i see the issue

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you mixed up 35² with 352

wind agate
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OMG

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YAAA

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Im so done w myself atp

sour burrow
#

mistakes happen

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dont let it upset you tho

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these mistakes are something that can be fixed with more practice

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try to write the square or any kind of power smaller than normal and a bit higher

wind agate
#

I GOT ITT

wind agate
sour burrow
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You are welcome and good luck on your exam ^^

wind agate
#

TQQQ

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im gonna cry ur so nice

#

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scenic adder
#

What is the average distance for a random point in a 1×1 square to the boundary in a random direction?

scenic adder
#

This is the correct answer from the Internet, but I don't understand how E(s) is obtained.

marsh citrusBOT
#

@scenic adder Has your question been resolved?

tight furnace
#

My guess would be start by fixing the arbitrary direction, say for example 37 degrees and try to calculate the answer in that case

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Then use an integral to find the average over all the possible angles

marsh citrusBOT
#

@scenic adder Has your question been resolved?

scenic adder
marsh citrusBOT
#

@scenic adder Has your question been resolved?

marsh citrusBOT
#

@scenic adder Has your question been resolved?

marsh citrusBOT
#

@scenic adder Has your question been resolved?

scenic adder
#

<@&286206848099549185>

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vestal elm
#

for this graph there is a question: what is the solution of f(x) < 0 and f(x) > 0 and i understand using the vertex (1,-3) which means x = -1,3 but i dont understand how to get to the answer (f(x) = -1<x<3 and f(x) = x<-1, x>3)

cyan parcel
#

Its pretty easy if u understand how a function works

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f(x) returns a value for each input value of x, we then plug this value f(x) to the y axis

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So we have a graph on OXY plane

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Consider this blue point

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Where x = -2

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Then whats f(-2) = ?

vestal elm
#

how does that help me with inequalities?

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the < and > confuse me

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like i get x = -1,3 but i dont know why -1<x<3

quasi patrol
#

The alligator bites the bigger fish

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The open mouth is to the bigger side

vestal elm
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the solution is x<-1, x>3

quasi patrol
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Yes

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If the alligator chooses to bite f(x)

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Aka f(x) is bigger

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Then x is less than -1 OR x is bigger than 3

vestal elm
#

but if f(x) is > 0 how could x be less than -1?

marsh citrusBOT
#

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silk haven
#

can someone explain why the integral of 1/x dx = ln |x|

silk haven
#

why absolute value?

proud ice
silk haven
#

according to desmos the definite integral of the func of x -3 to 2 is undefined

proud ice
silk haven
proud ice
#

It shouldn't be

silk haven
#

oh

proud ice
#

That's an erroneous calculation if you're getting that

silk haven
#

visually it looks right though

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why isnt it the def integral from -3 to 2 not equal to the def integral from -3 to -2?

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because -2 to 0 and 0 to 2 cancel out

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even though they cant be calculated

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but why is the absolute value there in the first place

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why isnt it just undefined

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if integration is inverse derivative, then it should pass the horiziontal line test

proud ice
silk haven
proud ice
#

Whatever calculator you are using is probably assuming that you were doing an improper integral, in which case it would cancel out

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But for a proper integral, it will always be undefined

silk haven
#

oh ig

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my calculator is desmos 💀

proud ice
#

Yeah it's probably assuming improper integral then

proud ice
#

Because we still need to calculate integral of 1/x for when x is negative

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And when $x<0$, you would find $\int \frac{1}{x}=\ln(-x)$

elfin berryBOT
silk haven
#

why isnt it just undefined

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ln isnt defined for neg numbers

proud ice
proud ice
silk haven
proud ice
#

If x<0, then -x>0, so ln(-x) is defined

silk haven
#

but the derivative is ln(x) not ln (-x)

proud ice
silk haven
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i meant the derivative of ln x = 1/x

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we never heard or anything saying ln -x

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oh wait i see how

proud ice
silk haven
#

the derivative of ln -x is -(-1/x)

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k i get it ty

proud ice
#

Exactly right

silk haven
#

.close

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boreal heath
#

A car slows down from 28m/s to rest in a distance of 88m. What was its acceleration,assumed constant?

boreal heath
#

my answer was -4.72

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can someone double check that

#

ah nvm

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ebon depot
#

Determine the point (x,y) on the ellipse $\frac{x^2}{a^2}+\frac{y^2}{b^2} = 1$ for which the area of the triangle with the corners $(0,-b), (x,y)$ and $(0,y)$ get the biggest area

elfin berryBOT
#

Merineth

ebon depot
#

I have an idea on what i'm supposed to do

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It has something to do with derivatives to find the maxima

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However i'm not entirely sure how to proceed

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I know that the area of a triangle is $0.5bh$ where the base is the length from $(0,y)$ to $(0,-b)$ and the height is $(0,y)$ to $(x,y)$

elfin berryBOT
#

Merineth

cobalt sentinel
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is the answer in terms of a and b

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(the point (x,y))

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i got (0.5a*(sqrt3), 0.5b) using lagrange mutlipliers, but i have no clue if i did it right lol

ebon depot
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I'm not sure what you mean but afaik i'm supposed to find the point(x,y) which maximizes the area withing the ellipse

cobalt sentinel
#

yea it makes sense if the answer is in terms of a and b

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otherwise it wouldn't vary with ellipse size

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are u familiar with lagrange mutlipliers

ebon depot
#

No i'm not

cobalt sentinel
#

do you know gradient? $\nabla$

elfin berryBOT
#

Stephen

ebon depot
#

Yes

cobalt sentinel
#

hmm

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what class is this for

ebon depot
#

Calc 3

cobalt sentinel
#

ok

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are u allowed to use topics u havent learned yet

ebon depot
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I'd rather not

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This questions specifically is around derivatives

cobalt sentinel
#

Ok, I understand.

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I'm not too sure on how to do the problem otherwise, I always just use L.M. for optimization

ebon depot
#

Well the Area is defined by the length between the points.
And since i'm given the equation for the ellipse. Couldn't i insert the area of the triangle into the ellipse equation?

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Derive it for ciritcal points

cobalt sentinel
#

yea sure why not

ebon depot
#

I'm not sure but that'd be my guess

cobalt sentinel
#

try that and see what u get

ebon depot
#

<@&286206848099549185>

grizzled needle
marsh citrusBOT
#

@ebon depot Has your question been resolved?

ebon depot
#

☹️

#

I’m hated

#

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cobalt sentinel
marsh citrusBOT
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sour pivot
marsh citrusBOT
sour pivot
#

why is the lim to 5^- undefined but 5^+ does not?

#

is this bcs in the LHL if we put 5 in the root it becomes root - 10?

turbid mica
#

since thats not on the domain of real numbers for the root function it is undefined

sour pivot
#

but he cross on this

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does 5^- means -5

#

?

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so he doesnt cross the left one

turbid mica
#

the - and + sign means approaching from that side

sour pivot
#

ohh

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so -1 -2 -3 counts

turbid mica
#

5^- would be from the left, so you would go from -inf to 4.999999999 ... and 5 - 4.999999999 is negative

sour pivot
#

to approach 5

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ok i see

#

thanks

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prime junco
#

what does part b mean?

marsh citrusBOT
prime junco
#

i know the DE is exact but im not sure what its asking by the geometric or physical description of the solution

#

same here

#

for 4a I got y = 1/3 sin3x

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and the graph is just a regular sin graph

#

so is the physical decription just that its wavy idk

marsh citrusBOT
#

@prime junco Has your question been resolved?

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@prime junco Has your question been resolved?

marsh citrusBOT
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@prime junco Has your question been resolved?

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severe pewter
#

I've seen a few memes about something with d and dx (in relation to integrals i think), but what do they mean? I kinda understand what integrals are, but not what they have to do with d and dx.

whole sleet
#

tl;dr it's a notation for "variable we're integrating with respect to".

There's a plethora of vague reasons we write this.

  • It kinda looks like Riemann sums!
  • It makes u-sub easier
  • It cancels with a derivative in the integral

But none of that is like a "mathematical necessity"

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main garnet
marsh citrusBOT
main garnet
#

why did the randomly just switch

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*they

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from f(z_n) > y to f(z_n) => y

devout mauve
#

cause they want to use it in the next line?

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to get whatever somewhere after that?

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its not like using f(z_n) >= y is wrong

main garnet
#

cz the proof involves

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saying

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soemthing >= y and something <= y and therefore it is = to y

#

however in this case we know f(c) > y but since earlier in the proof we also showed f(c) <= y wouldnt that be wrong

main garnet
devout mauve
#

even if f(z_n) > y, that wouldnt translate to the limit

main garnet
#

why not

devout mauve
#

for example if z_n = 1/n > 0, then still lim z_n = 0

main garnet
#

ohhh

#

yeahh i forgor about that

devout mauve
#

in general if a_n > b, then still lim a_n >=b only

main garnet
#

tyty

#

.close

marsh citrusBOT
#
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true basin
#

Need help with b part

marsh citrusBOT
true basin
#

The question states: find the moment of area about y-axis for the part of surface generated by the line x=4 (red line)

#

I'm so confused,

#

Btw the whole shape is rotating around the x-axis

marsh citrusBOT
#

@true basin Has your question been resolved?

marsh citrusBOT
#

@true basin Has your question been resolved?

marsh citrusBOT
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edgy elk
#

On this I have to set e^y = y^2-7

#

and then solve for y

#

but I have no idea how to do that

marsh citrusBOT
#
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edgy elk
marsh citrusBOT
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scenic birch
marsh citrusBOT
scenic birch
#

The answer is E but I can’t figure out how to get it

upper timber
#

I see you have the region sketched out already

#

Imagine rotating it around the y axis

#

How would you cut it up into circles? What would the radii of the circles be?

scenic birch
#

They would need to be horizontal

#

I think the bound is right but I don’t know

upper timber
#

So you should integrate with respect to y

scenic birch
#

And it is disk method right?

still temple
#

Why did you square y^3?

scenic birch
#

Cus I was just throwing stuff in my calculator and it would be the value of X

upper timber
#

Don’t worry about that yet we have bigger problems to fix

#

If you’re integrating with y your bounds should be from 0 to 2

#

Then you find the radii in terms of y

scenic birch
#

Ok

marsh citrusBOT
#

@scenic birch Has your question been resolved?

#
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still temple
marsh citrusBOT
still temple
#

How do i do this? Is there a trig identity for this?

stoic slate
#

Use subtitution

#

To get in the denominator something u must recall

#

From the derivative of arctan

still temple
#

I cant find that one

stoic slate
#

I said derivative

still temple
#

o

stoic slate
#

U know derivative of arctan

still temple
#

Not off the top of my head

stoic slate
#

It is 1/(x^2+1)

still temple
#

ohh

stoic slate
#

Ok so use subtitution to get that denominator or something similar

still temple
#

im stuck

void trail
#

.

stoic slate
#

What sub u did

still temple
#

u = x ?

#

wait no

#

hmm

stoic slate
#

That doesnt make too much sense

still temple
#

yeah lol oops

#

u = x^2 - 4

#

then its 1 / (1 * sqrt(u) )

stoic slate
#

No

#

If u do that sub it should be…

still temple
#

this looks closer to the question

stoic slate
#

1/4 integral 1/(sqrtu(u+4)) du

still temple
#

wait so what was u

stoic slate
#

U Chose it to be x^4-4 no?

#

Oh no u did x^2

#

Why x^2-4

still temple
#

oh i meant x^4

#

my bad

#

sorry

stoic slate
#

Ok so if u do that sub

stoic slate
still temple
#

or you meant that?

stoic slate
#

None

#

Sqrt(u)(u+4)

still temple
stoic slate
#

Parenthesis

#

For (u+4)

still temple
stoic slate
#

U are suppose to know how to do this steps btw

#

If u cant, you should try easier exercises with subtitutions

#

Now u need another sub

#

I tell u the sub and u do it

still temple
#

ok

stoic slate
#

v=sqrt(u)/2

#

Now i have to leave so, wait for other to make the correction

still temple
#

il just watch youtube

#

.close

marsh citrusBOT
#
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open dune
#

A math class consists of 24 engineering majors, 12 science majors, and 6 business majors. 8 of the engineering students, 6 of the science majors, and 3 of the business majors are female.

What is the probability that a student selected at random is a business major given the student is a male?

knotty frost
#

Do you know bayes rule?

open dune
#

was wondering if this is just 6-3/42

open dune
knotty frost
#

Can you show your work

#

Are you just doing # of business majors who are male / number of men

open dune
#

yes trying to find what the probability that a student selected at random is a business major given the student is a male

knotty frost
#

Then no ur answer is incorrect sadly

#

You are doing # of male business majors / total number of students

open dune
#

oh

#

how would you do it then?

knotty frost
#

Do you know how to count the number of total men?

#

You were able to find the number of male business majors, so try doing that with all the majors

open dune
#

25 total men

knotty frost
#

So what should your answer be?

open dune
#

is it 6/25?

knotty frost
#

No

#

Now you’re doing # of man + woman business majors / number of male business majors

open dune
#

3/25

#

?

knotty frost
#

Yes

#

Do you understand why?

open dune
#

is it because they are asking to find the chance that out of the total men what would be the chance that they would be in business?

#

.close

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still temple
marsh citrusBOT
still temple
#

is it correct!

leaden monolith
#

No idea what I’m looking at

still temple
#

😭

still temple
leaden monolith
#

Yeah you should post the question first lol

still temple
#

lmao

#

😅 lmao

marsh citrusBOT
#

@still temple Has your question been resolved?

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light sentinel
marsh citrusBOT
leaden monolith
#

What have you tried

light sentinel
#

well idrk where to start

#

i did a similar question earlier but this one is harder

#

this is the other one i did:

leaden monolith
#

Well here’s what I’m thinking, if a line intersects a parabola only at 1 point, it’s either a vertical line, or it’s tangent to the parabola

#

Does that make sense?

light sentinel
#

yeah the question says tangent

leaden monolith
#

Right, and if I write my line like y = mx + b

#

Do you agree that this is a line but not a vertical one?

light sentinel
#

yeah

leaden monolith
#

Now if I tell you my line mx + b intersects the parabola x²

#

How would you find where they intersect?

light sentinel
#

using discriminant formula?

leaden monolith
#

(Your answer will be in terms of m and b as they are constants I haven’t given you)

leaden monolith
#

If a point (r, s) lies on the line y = x²

#

That means s = r²

#

If a point (r, s) lies on the line y = mx + b

#

That means s = mr + b

#

If this (r, s) point lies on both the curves then surely r² = s = mr + b

light sentinel
#

ohh i see

leaden monolith
#

The idea here is that the points of intersection between x² and mx + b will be when x² - mx - b = 0

#

Ah but this means in general we will have 2 intersections

leaden monolith
#

Rather we want only 1 intersection

#

Here’s where the discriminant comes in

marsh citrusBOT
#

@light sentinel Has your question been resolved?

light sentinel
#

hey ive been trying to figure out how do it even after all he help u gave me i ant figure it out

#

could u help a bit more pls

leaden monolith
#

We can “force” it to have 1 solution by making the discriminant of x² - mx - b to be = 0

#

We lastly also need to use the fact that our line y = mx + b has to go through the point (1, -2)

#

This means whatever m and b we have, it needs to satisfy -2 = m(1) + b

#

This is what it means for (1, -2) to lie on the line y = mx + b

#

We have 2 unknowns m and b, and here

leaden monolith
#

2 equations, so we just need to solve for the solutions here

light sentinel
#

k ty

marsh citrusBOT
#

@light sentinel Has your question been resolved?

marsh citrusBOT
#
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calm stump
#

Doing basic calc, my answer to this question is 3x^2 * ex + x^3 * ex. The answer is different according to my lecturers mark scheme, just want to confirm if I am right or wrong and how their answer is right (if it is).

calm stump
heady lark
#

do you have to darivate it ?

calm stump
#

yeah its a differentiation question

#

should have said sry

heady lark
#

use this formula

#

d(uv)/dx = udv/dx+vdu/dx

#

substitute xcube and e power x

fervent rampart
# calm stump

that's the same thing but factoring out x^2 e^x afterward

calm stump
#

ah ok

heady lark
#

an easy way to remeber this formula is left d right d

#

mark uv as u is left and v is right

calm stump
#

gotcha

#

ok thanks guys

heady lark
#

k

calm stump
#

.close

marsh citrusBOT
#
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novel juniper
#

$\lim_{x\rightarrow0}\frac{\left(\tan\left(x\right)-\sin\left(x\right)\right)}{\sin^3\left(x\right)}$

elfin berryBOT
#

ƒ(Why am. I here)=I don't know

novel juniper
#

I'm aware l'hopital and series expansions will work here

#

but what else?

still temple
#

taylor

#

B)

novel juniper
#

lol

calm vortex
#

you can factor out 1 - cos x

novel juniper
#

hmm

#

1-cos(x)?

calm vortex
#

writ e tan as sin/cos

#

then the sin's cancel leaving sin^2 on the bottom

novel juniper
#

yeah

calm vortex
#

then you can convert the bottom sin^2 to 1 - cos^2

novel juniper
#

can't believe I missed that lol

#

thanks

calm vortex
#

np

novel juniper
#

$\lim_{x\rightarrow0}\left(\frac{\left(1^x+2^x+3^x...n^x\right)}{n}\right)^{\frac{a}{x}}$

elfin berryBOT
#

ƒ(Why am. I here)=I don't know

novel juniper
#

so here

#

what series am I looking at

#

I suspect something factorial

#

hmm

#

Let me ignore the 1/x for now

#

that's just 1 in the bracket

#

so let the limit be L

#

$\lim_{x\rightarrow0}\left(\frac{\left(1^x+2^x+3^x...n^x\right)}{n}\right)^{\frac{a}{x}}=L$

elfin berryBOT
#

ƒ(Why am. I here)=I don't know

novel juniper
#

$\frac{a}{x}\ln\left(\lim_{x\rightarrow0}\left(\frac{\left(1^x+2^x+3^x...n^x\right)}{n}\right)\left(\right)=\ln\left(L\right)\right)$

elfin berryBOT
#

ƒ(Why am. I here)=I don't know

novel juniper
#

hmm

#

now I l'hopital i I guess

#

I feel that would turn messy real fast though

#

$\frac{a\left(\ln\left(2\right)2^x+\ln\left(3\right)3^x........\right)}{\lim_{a\rightarrow\infty}\sum_{a=1}^na^x}$

elfin berryBOT
#

ƒ(Why am. I here)=I don't know

novel juniper
#

hmm

still temple
#

the hell

novel juniper
#

I know lol

#

It's a a fun problem though ngl

#

I think I almost got it

#

nah, I'm getting an e blobcry

calm vortex
#

do you have any guess if what it is?

still temple
novel juniper
still temple
#

my brain hurts to go your way

novel juniper
#

is it $(n!)^\frac{a}{n}$

elfin berryBOT
#

ƒ(Why am. I here)=I don't know

calm vortex
#

yea

novel juniper
#

hmm

#

what did I do wronf

calm vortex
novel juniper
#

wdym

#

I used l'hopital's rule

calm vortex
#

idk what you did but your expressions are kinda fishy

novel juniper
#

Let me re-write them

calm vortex
calm vortex
#

using l'hopital's rule is correct but something weird's going on with your limits

novel juniper
#

$\left(\lim_{x\rightarrow0}\left(\frac{a}{x}\right)\ln\left(\frac{\left(1^x+2^x+3^x...n^x\right)}{n}\right)\right)$

elfin berryBOT
#

ƒ(Why am. I here)=misery

novel juniper
#

Now I apply L'hopital's rule

calm vortex
#

take the a out, it doesnt matter, and to make it look a bit simpler, write ln(fraction stuff) as ln(1^x + ...) - ln n

novel juniper
#

$\left(\lim_{x\rightarrow0}\left(a\right)\left(\frac{\left(\ln\left(1\right)1^x+\ln\left(2\right)2^x....\ln\left(n\right)n^x\right)}{\frac{\left(1^x+2^x+3^x....n^x\right)}{n}}\right)\right)$

elfin berryBOT
#

ƒ(Why am. I here)=misery

novel juniper
#

this is ln(L)

calm vortex
#

1/n on the numerator went missing

novel juniper
#

oj

#

right

#

wait

#

which 1/n

calm vortex
#

it should be $\lim_{x\rightarrow0}\left(a\right)\left(\frac{\frac{1}{n}\left(\ln\left(1\right)1^x+\ln\left(2\right)2^x....\ln\left(n\right)n^x\right)}{\frac{\left(1^x+2^x+3^x....n^x\right)}{n}}\right)$

elfin berryBOT
novel juniper
#

where did the 1/n in the num come from

calm vortex
#

the numerator is from differentiating the inside of ln

#

and originally it has 1/n

novel juniper
#

wait, what

#

it's 1^x+2^x...n^x/n

#

right

calm vortex
novel juniper
#

don't get it

#

the differential of ln(1^x+2^x+3^x...)

#

is

#

$\frac{1^x\ln\left(1\right)+2^x\ln\left(2\right)+3^x\ln\left(3\right).....}{1^x+2^x+3^x...n^x}$

#

right?

elfin berryBOT
#

ƒ(Why am. I here)=misery

calm vortex
#

yea

novel juniper
#

so where did the 1/n come from

#

$\frac{n\left(1^x\ln\left(1\right)+2^x\ln\left(2\right)+3^x\ln\left(3\right).....\right)}{1^x+2^x+3^x...n^x}$

#

wait

elfin berryBOT
#

ƒ(Why am. I here)=misery

novel juniper
#

it shoudl be this

calm vortex
#

that sill looks wong

calm vortex
novel juniper
#

hmm

novel juniper
#

right

calm vortex
#

no

novel juniper
#

why not

calm vortex
#

wait, lemme write it

#

you agree?

novel juniper
#

hmm, why is there an n in the dnominator too

#

outside the log

calm vortex
#

which n

novel juniper
#

the one in the denominator here

calm vortex
#

before l'h

#

ignoring a

novel juniper
#

ah, that's $x$ ok

elfin berryBOT
#

ƒ(Why am. I here)=misery

novel juniper
#

thanks

#

yeah

#

please continue

calm vortex
#

it'd be this

novel juniper
#

yeah

#

that makes sense

#

what happened to 1^x+2^x...n^x though

calm vortex
#

it's still there in the denominator

novel juniper
#

hmm

#

ok

#

yeah

#

now what

calm vortex
#

then plugging in x = 0 wouldn't cause any issues

novel juniper
#

hmm

#

that gives ln(L)=aln(n!)/n

#

oh

#

I see

#

yeah

#

makes sense now

#

thanks

calm vortex
#

np

novel juniper
#

.close

marsh citrusBOT
#
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marsh citrusBOT
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remote drift
#

can someone help me on this

marsh citrusBOT
remote drift
#

done part i i need help on (ii)#

violet badger
#

do you have the

#

eqn

#

in 1st one

#

ax^3+bx^2+cx+d=0
-d/a = product of roots
c/a = sum of product of roots taken 2 at a time

#

c/a divided by -d/a

#

or c/-d

#

thats your answer

#

(of the eqn in 1st answer)

remote drift
#

do u want the equation?

violet badger
#

nah

remote drift
#

it is 2u^3 + 12u^2 + 27u +25

violet badger
#

-25/27

#

thats yo answer

#

i think

#

check

remote drift
#

-27/25

violet badger
#

oh mb

#

mb

#

i typo'd

violet badger
#

easssy

remote drift
#

how do u do it in simpler terms

violet badger
#

😎

#

how more simple you want it to be

remote drift
#

more pls opencry

violet badger
#

😭

#

its just

#

basic property

remote drift
#

like can u show me on whtieboard or paper

violet badger
#

alr wait

#

wait i dont have aphone

remote drift
#

maybe on paint

violet badger
#

im on a laptop

#

you gotta wait for a while

#

go read this

#

and also realise if u subbed x=u+2

a (alpha) = some value of u + 2

#

if for a the eqn in x = 0
then for a-2 eqn in u =0

remote drift
#

i thought it would be -1/6 as its a sum

violet badger
#

no wtf

remote drift
#

like adding all the terms and i had a new equation

violet badger
#

nawww

remote drift
#

i will have to wait a bit for the working out

#

i still dont understnad :/

violet badger
#

😦

#

sorry then

remote drift
#

could you help me on this other one while we wait

violet badger
#

i guess

remote drift
#

i subbed it in and the equation was wrong that i got

violet badger
#

hmm wait

#

you must be getting u*root(u) + 5u + 7

#

now sqaure that

#

fully

#

i think*

#

gtg

remote drift
#

ok

marsh citrusBOT
#

@remote drift Has your question been resolved?

marsh citrusBOT
#
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cinder mason
#

what is the domain of this function

marsh citrusBOT
cinder mason
#

the answer says (-infinity, -1) U (1, infinity)

#

but i got (-infinity, -(1/3)) U (1/3, infinity)

late geode
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show work/reasoning

cinder mason
late geode
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you didn't copy down the expression correctly

fallen spade
#

x can’t be 0

late geode
#

you sqrt changed

fallen spade
#

1 or -1

cinder mason
fallen spade
#

Yeah you can’t take stuff out of root

cinder mason
#

i didnt see that -1 is in the root

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.close

marsh citrusBOT
#
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frail lodge
#

In general, for proving existence questions of the type "prove that there exists ... with properties/restrictions ...", can I first assume the properties/restrictions, then work backwards to construct the object?
Take for example question b) here. Can I first assume that $U=im \pi$ and $\pi^2-\pi$ to find such a linear transformation $\pi$?

elfin berryBOT
#

Kakaka

frail lodge
marsh citrusBOT
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main mica
#

There are A and B cities. And we have Two buses when the first one entered B.the second one was 1/5 of the full road away from B. Need to find the first bus speed if he is 20km/h faster then the second

cyan parcel
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Pretty easy if u just assign unknown value as a variable

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Then try to make the variable cancle themselve out

main mica
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well how?

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<@&286206848099549185>

lucid bridge
main mica
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what part?

lucid bridge
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illustrate point A and B on a line

main mica
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ohh

severe dawn
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the question itself

main mica
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Ill phrase it better

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Wait

lucid bridge
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i think your explanation is sufficient, im only asking you to draw so you can understand better

main mica
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ok

lucid bridge
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after you have drawn, point out how much distance first and second bus have travelled from the starting point

main mica
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Something like this?

lucid bridge
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compare their speeds

#

yeah

main mica
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ok i need a equation now right?

lucid bridge
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if you call the entire path 5x then you wont need to deal with fractions btw

lucid bridge
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you can call first bus' speed whatever you want

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i would prefer letting speed of first bus be 5v

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in this case, try to find out speed of second bus

main mica
#

v

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?

lucid bridge
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nah

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first bus went 5x units while second one went 4x units

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first one has speed 5v so what should other have

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using the equation x= v.t

#

they travelled these distances at the same time so they have the same time value

main mica
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ok so t is the same

lucid bridge
main mica
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4v is the seconds speed?

lucid bridge
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4v speed yeah

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now read the question again

main mica
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ok so now i need a euqtion

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5v=4v+20?

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thats it?

lucid bridge
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its almost over yeah

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what did the question want from you

main mica
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firs busses speed

lucid bridge
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you know the v value, you also called speed of first bus 5v

main mica
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yea 100

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but could this equation also work?

lucid bridge
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100 what tho

main mica
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x=4/5x-20

main mica
severe dawn
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(V+20) t = 5x
Vt = x
(V+20)t = 5Vt
V+20 = 5V

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isnt that how it goes

lucid bridge
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it seems like you called speed of first bus v here

main mica
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soo 100km/h is the answer

lucid bridge
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then you get a different value for v

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and still solve the equation

lucid bridge
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you can do the question as many times as you want, by setting up your own custom unknown for first bus speed

main mica
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Ok got it thank

#

Btw are you good at pyramid problems i solved one but just need to confirm that my answer is right

severe dawn
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send it

main mica
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got a pyramid with a equalavent triangle as a base the the cercumscribed circles radius at the base is 20 the side hight is 26 need the volume

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Got 2400sqrt3 need to confirm if its right

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So first we need the base triangles side

severe dawn
main mica
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Then we find the inscribed circles radius to set up pyth to find the hight

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And then 1/3 *areabase * h

main mica
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Can’t rn

lucid bridge
main mica
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What did you get?

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@lucid bridge

lucid bridge
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2600sqrt3

main mica
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Ok take me thro what you did

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Step by step

#

@lucid bridge

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What did you get as the base triangles side length ?

lucid bridge
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use 30 60 90 triangle

main mica
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Dude

#

What did you get as the side length of the base

#

.close

marsh citrusBOT
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real token
#

Hello

marsh citrusBOT
real token
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6c please!!!

#

<@&286206848099549185>

crude mango
brittle coral
#

Hello, do you know all the log rules

real token
brittle coral
#

Try to apply rule 2 on that expression

crude mango
elfin berryBOT
brittle coral
#

Then that yeah

real token
#

Thank you!!

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severe wing
#

Needs explanation. I have tried this question by equating the Transpose of the Matrix to it's Inverse, also tried using the fact that the product of the Transpose of the matrix with itself is the Identity Matrix. Can this be done in a concise manner?

copper raven
#

there's another characterization of orthogonal matrices which will help you reduce the number of equations you're dealing with

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what conditions should the columns of an orthogonal matrix satisfy ? @severe wing

marsh citrusBOT
#

@severe wing Has your question been resolved?

severe wing
copper raven
#

exactly

#

@severe wing

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did you solve the question or no ?

copper raven
severe wing
#

yes, I have solved it now. I got two equations by taking the product of column 3 with other two products and taking the norm of column 3. Then I solved for the quations.

copper raven
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alright

severe wing
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I'll check whether the solutions yield the orthogonal matrix by. I just checked if the solutions for a, b, and c atisfy the equality A*transpose(A) = I. Surely they satisfy.

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severe wing
#

.close

marsh citrusBOT
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placid gate
#

hi just now learning how to solve this stuff and im not sure if its correct i was wondering if someone could double check my work,

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@placid gate Has your question been resolved?

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@placid gate Has your question been resolved?

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half karma
#

The first three make sense but can someone pls explain why no.4 converges and 5 depends on G(u)? I cant think of an example

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still temple
#

how many odd whole numbers less than 3000 can be formed using the digits 0 through 5 with repetition?

still temple
#

This problem confuses me so much, like what is it even asking

stray fern
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it's asking how many odd numbers are there from 1 to 2999 that can be formed with just {0,1,2,3,4,5}
for example 25, or 2543

novel juniper
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you are given the numbers 0,1,2,3,4,5

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you have to form odd numbers less that 3000 using these digits

still temple
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hmm

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but only odd numbers can be used right so i cant use 2 or 4 right

stray fern
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even digits can be used but it has to be an odd number

true parcel
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no, its asking to form odd numbers

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not that u have to use odd digits from 0 to 5

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for ex 1235 is odd

lilac siren
still temple
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2?

lilac siren
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0,1,2 => 3

still temple
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oh

lilac siren
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Consider "00001"