#help-33

1 messages · Page 117 of 1

proud zealot
#

how were this coeficients found

#

please tag me if you answer

#

isn't an always 2?

marsh citrusBOT
#

@proud zealot Has your question been resolved?

glass silo
#

From there and comparing, see the sum goes from -infty to -1 only

#

So a(n) is only 2 for strictly negative n

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

next phoenix
marsh citrusBOT
next phoenix
#

In qs 4 why does E1 have 1/6E2 term

#

Shouldn't it be just 1/6 coz that's the probability it will end

#

Bruh

next phoenix
#

<@&286206848099549185>

marsh citrusBOT
#

@next phoenix Has your question been resolved?

next phoenix
#

<@&286206848099549185> pls look at qs above

marsh citrusBOT
#

@next phoenix Has your question been resolved?

next phoenix
#

<@&286206848099549185> <@&286206848099549185> someone

marsh citrusBOT
#

@next phoenix Has your question been resolved?

white breach
#

same reason for E1 to have 2/6 because its E1 and E6

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sterile harness
#

what is trivial solution in linear algebra in matrixes ?

still temple
#

a2x+b2y+c2z=0

#

a3x+b3y+c3z=0

#

x=0,y=0,z=0 is a trivial solution

#

and inorder to have a non trivial solution det of coefficients should be 0

sterile harness
#

so if L2 was like

#

a2x+c2z=0

#

there will be a non trivial solution right ?

marsh citrusBOT
#

@sterile harness Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

vivid wharf
#

what am i doing wrong - solving the 4th no

marsh citrusBOT
vivid wharf
#

logic for ease :
ab = bc(given) so <a = <b = 45 deg .
<h = 90deg and <b = 45deg so <hdb = 45 too, so hd = hb.
ac is root3 so bc is root 3 too bcos <a = <b.
So bd = root3 - 1.
And we here

marsh citrusBOT
#

@vivid wharf Has your question been resolved?

marsh citrusBOT
#

@vivid wharf Has your question been resolved?

vivid wharf
#

.close

marsh citrusBOT
#
Channel closed

Closed by @vivid wharf

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

red minnow
#

Given the bases S = v₁,v₂ and T = w₁, w₂. V = R² with:
v₁ = -3w₁ + 9w₂ and v₂ = 8w₁ - 4w₂
Calculate the determinant of the base change matrix from base S to base T. (Note: Carry out the calculations and provide the result in decimal form with 5 decimal places).

marsh citrusBOT
#

@red minnow Has your question been resolved?

red minnow
#

<@&286206848099549185>

#

.close

marsh citrusBOT
#
Channel closed

Closed by @red minnow

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crisp sigil
#

can someone check if this is right

marsh citrusBOT
undone bane
#

yeah, its correct

broken dome
undone bane
#

idk why you calculated y(1) tho

broken dome
#

You can always check these things with Desmos

crisp sigil
undone bane
crisp sigil
#

oh i di that to see which one is the top and which one is bottom

undone bane
#

ahh

crisp sigil
#

yea bc my teacher doesnt allow us to use calc on test so i do the hw without calc

broken dome
#

you don't have to do that I think

#

you'll just get the negative answer but the absolute value will be the same

crisp sigil
#

this one i need help with

broken dome
#

you should get -72 if you reverse them

#

Ye is good

#

you can use the calculator to check your work is what I meant

crisp sigil
#

oh really? i did it right?

broken dome
#

If the answer is right then the process is usually right too with integrals

#

assuming the formula is correct

#

yes

crisp sigil
#

ok cooll and ik i can use desmos but do u think i should make this graph look better or is this fine

broken dome
#

Depends on what your teacher wants, that sketch is very inaccurate given dimensions, but it's correct in terms of shape

#

They wouldn't intersect at the x axis

crisp sigil
#

@broken dome How’s this?

broken dome
#

Much better

marsh citrusBOT
#

@crisp sigil Has your question been resolved?

crisp sigil
broken dome
#

I mean, if you really wanted to you could mark the points they cross and write which coordinates they are

#

and like hatch the area that you're calculating

#

add axis notation

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

still temple
#

Hello, so I was just wondering if when doing questions like e-i i should take whatever is out of the bracket out of the integration because I saw in a video some rule i dont know when to apply it as he did not give an example. I am pretty sure you dont take it out so could you give me an example of when that rule applies.

limber marsh
#

You can only factor things out if they're constants
E.g. they're unaffected by x

still temple
#

.close

marsh citrusBOT
#
Channel closed

Closed by @marble schooner

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

uneven vector
#

I need help with question 8. d)

marsh citrusBOT
uneven vector
#

i dont know how to go abt it honestly

#

btw the base of the logs is 8

upper timber
elfin berryBOT
uneven vector
#

yes i know this formula

#

hm

upper timber
#

Then the problem tells you that the logs are in an arithmetic sequence

uneven vector
#

yes

upper timber
#

So let their common difference be d

#

Then log(p)-log(27) = log(p/27)=d

#

And same with the rest

#

So p/27 = q/p = 125/q = 8^d

#

See?

uneven vector
#

ohh

#

i see

#

so thats enough for 8 d

#

and now i just solvev for p and q

#

with this

#

p/27 = q/p

#

or wait

marsh citrusBOT
#

@uneven vector Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

finite folio
#

( U+

marsh citrusBOT
#

@finite folio Has your question been resolved?

copper raven
#

V+

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

supple dirge
#

We have a sequence defined by:

Un = ((n-2) / (n)) × Un-1 - ((n-3) / (n(n-1))) × Un-2
U0 = 1 and U1 = 2
how much is the following amount worth:
Sn = (U0 / U1) + (U1 / U2) +...+ (U2023 / U2024)
Thanks

earnest sundial
#

you're missing a ) somewhere. where's that supposed to go?

supple dirge
#

that's it, thank you

earnest sundial
#

well try writing out the general term here

#

$\frac{u_n}{u_{n+1}}=$

elfin berryBOT
#

Bob Goldham

earnest sundial
#

what does that ratio equal in the general case?

supple dirge
#

I doubt it will help us

#

.close

marsh citrusBOT
#
Channel closed

Closed by @supple dirge

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

vivid horizon
#

Can someone help me with either of these questions pls thank u!

vivid horizon
#

how to get started or what rules I need to know

marsh citrusBOT
#

@vivid horizon Has your question been resolved?

marsh citrusBOT
#

@vivid horizon Has your question been resolved?

vivid horizon
#

.close

marsh citrusBOT
#
Channel closed

Closed by @vivid horizon

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

signal nebula
marsh citrusBOT
signal nebula
#

can someone confirm whether the notation is done properly?

#

and I use a lot of steps, which could I omit?

turbid mica
#

lasso notation 😭

signal nebula
#

what is that

turbid mica
#

ur integrals look like a lasso

signal nebula
#

oh 🥺 theyre pretty bad ye

#

ill improve those

elfin berryBOT
#

penguin

turbid mica
#

whats with the 4th line

#

d(2x - 1)

ivory latch
#

why does it say +4c at the end lol

signal nebula
#

the 4 was my c that I miserote

#

miswrote

#

so I put some lines through it

swift wedge
signal nebula
#

its just + c

signal nebula
#

should it not be there at that point?

turbid mica
#

uh if thats how ur teacher wants it ok but that seems weird

signal nebula
#

I dont fully understand the dx syntax to begin with

#

ik d(...) means derivative of whatever is inside

swift wedge
signal nebula
#

but no clue why I can just omit the whole * dx/d() once I start to get the primitive

marsh citrusBOT
#

@signal nebula Has your question been resolved?

#
Channel closed

Closed by @signal nebula

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

chrome swift
#

Small theoric question from me

marsh citrusBOT
chrome swift
#

Say a matrix that has n euginics values.

#

Their eugian values per eugian values form a basis together? or they have to be split from each numbers?

#

For example these three vectors

#

(1,1,1), (-3,0,1) and (1,2,0).

Do they form a basis of R3?

#

Or it's only (1,1,1) that is a basis of R3

obsidian trail
#

yeah they do form a basis of R³

chrome swift
#

Oh, so I have to combine all of them?

obsidian trail
#

yep that's correct

spark otter
#

When your matrix is diagonalizable, you have to combine the vectors of EACH eigenspace

chrome swift
#

So a Matrix of 5x5 that has 5 eugianvalues.

#

All of these vectors together will form a basis.

#

of R5

#

Not only from one.

spark otter
#

1 vector per eigenspace/eigenvalue, yes you will get 5 vectors that form a basis of R5

obsidian trail
#

there can be a 3×3 matrix which is not diagonizable (meaning it doesn't form a basis of R³)

chrome swift
#

Yeah there is a postulate to respect.

#

det(A - kI) =/= 0

spark otter
#

?

#

that's not linked to anything

obsidian trail
#

det(A-kI) is to find eigenvalues

spark otter
#

that just means k is not an eigenvalue

chrome swift
#

Ah woops.

#

Let me recitify

#

Say for a matrix of 2x3

#

if
P(x) = x^2 - (a11 + a22)x + det(A)
can't ever be = 0, then it doesn't have eigenvalues.

spark otter
#

a non-square matrix has no eigenvalues

chrome swift
#

oops

#

I meant 2x2

spark otter
#

no one said it had to be real ones

chrome swift
#

Let's say we stick to the real values

#

since my class stays on the real numbers.

spark otter
#

ok

#

then A (associated to P) is not diagonalizable with real matrices

chrome swift
#

Ok gotcha.

#

Similar question before I finally tackle the diagonalisation.

#

d) is the one I'm looking at.

#

how would I ive a matrix D

#

Hold on let me give you the basis according to a calculator

#

How would I build a matrix with these three vectors?

#

I just place them side by side?

spark otter
chrome swift
#

Oh vous êtes français! Cool.

#

Le problème n'était pas de savoir si c'était une matrice diagonale

#

Mais comment obtenir cette matrice à partir de la base.

#

J'ai l'impression que je pourrais donner n'importe quoi

#

Comme ceci :

spark otter
#

disons que ta base c'est e1 = (1 2 1), e2 = (1 0 1) et e3= (-1 1 0)

#

c'est tes vecteurs propres, aucun problème jusque là?

chrome swift
#

Non, aucun problème.

spark otter
#

ok

chrome swift
#

Ils font une base de R3 ensemble.

spark otter
#

Bon bah D est ta matrice dans la base (e1, e2, e3)

#

Donc chaque colonne de D

chrome swift
#

Ah ok je fais juste les joindre bout à bout?

spark otter
#

c'est les coordonnées de T(ei) dans la nouvelle base

spark otter
#

$D = \begin{pmatrix}a&b&c\d&e&f\g&h&k\end{pmatrix}$

#

elfin berryBOT
#

rafilou2003

spark otter
#

$T(e_1) = ae_1 + de_2 + ge_3$

elfin berryBOT
#

rafilou2003

spark otter
#

$T(e_2) = be_1 + ee_2 + he_3$

elfin berryBOT
#

rafilou2003

spark otter
#

etc...

#

c'est comme ça que tu es sensé obtenir les coefficients de D

#

Ce serait hyper long sans indication

#

mais là coup de bol

chrome swift
#

Eh boy.

spark otter
#

e1, e2 et e3 sont des vecteurs propres

#

$T(e_i) =\lambda_i e_i$

elfin berryBOT
#

rafilou2003

spark otter
#

donc easy peasy

#

(ici lambda_3 = lamdbda_2)

chrome swift
#

Ah attend, le A est la matrice associée à la transformation linéaire?

#

Donc une fonction prenant trois arguments (bu que c'est la base canonique)?

spark otter
chrome swift
#

Genre toute la méga opérations de cette transformation se ferait en résoudant cette matrice

#

Un peu comme les rotations dans les transformations géométriques?

spark otter
#

Oui en fait A décrit intégralement T

chrome swift
#

Aaaah ok.

spark otter
#

Si tu sais comment se comportent les images de chaque vecteur d'une base, alors tu sais comment se comporte la transformation dans son intégralité

#

parce que la transformation est linéaire

chrome swift
#

Ok donc pour résumé

#

On a une fonction qui fait une multiude de opérations à un vecteur quelconque

#

qui peut se résumer à une opération matricielle de vce vecteur avec la matrice A

#

Genre

spark otter
#

oui T(X) = AX

chrome swift
#

T(x,y,z) = des opérations qui se traduisent par la matrice A

#

3 arguments

spark otter
#

si X est le vecteur colonne (x y z) de R^3 alors T(X) se résume à multiplier A avec X

chrome swift
#

R^3 c'est pas supposé être des matrices 3x3?

spark otter
#

R^3 c'est l'ensemble des vecteurs à 3 coordonnées réelles

#

l'ensemble des matrices 3x3 c'est $\mathcal{M}_3(\bR)$

elfin berryBOT
#

rafilou2003

spark otter
#

ou encore $\bR^{3\times 3}$

chrome swift
#

Donc fau tjuste que j'aie une ligne ou une colonne de 3 max

elfin berryBOT
#

rafilou2003

chrome swift
#

Genre 1x3 et 3x1 seraient des vecteurs de R3 aussi.

#

Tout comme 3x3

spark otter
#

3*3 non

#

3*3 si tu comptes ça fait 9 coordonnées

chrome swift
#

Ehh boy va falloir que je corrige cela dans ma tête ahah. merci de cette correction.

#

Ok ce qui est donné dans la fonction fait plus de sens.

spark otter
#

par convention les vecteurs de R^n sont associées au matrices n*1

chrome swift
#

Je donne 3 valeurs à la transformation.

#

Il se passe quelque chose qui es défini par la matrice A

#

qui englobe toutes les opérations effectuées.

#

Jpourrais par exemple avec une rotation avec une dilatation dans cette matrice là.

#

Je commence à faire des liens

#

attends je fais un petit gribouilli

#

Voici ce que la transformation ferait.

#

Et ce quelque chose est dans R3.

#

Ce qui n'est psa intéressant, car ce n,est pas ce que l'on cherche. Mais ça fait beaucoup de sens ou de liens. je comprends mieux la présentation et ce que l'on fait.

#

Puis là on prend la matrice A, et on le décortique avec le polynôme caractéristique, etc.

#

Jusque là, est-ce que je me plante ou je pédale avec 4 roues? 😄

spark otter
#

alors c'est quasiment ça

spark otter
#

C'est AX, pas XA

chrome swift
#

Ah oops.

#

Merci de la correction

#

Ok good

#

Donc là on prend A, et on l'a décomposé pour trouver une base.

#

Revoici l'exemple de tantôt

#

Il se passe quoi ici? Est-ce que l'on obtient un nouvel A plus facile à calculer?

#

Ou encore, prenons la symétrie orthogonale avec X pour une matrice R2

#

Deux vecteurs archi simple.

#

Que serait D dans ce cas super simple.

spark otter
#

tu as pris une matrice déjà diagonale

chrome swift
#

Ah oops. Pasun bon exemple alors.

spark otter
#

ce qui rend le principe de la "diagonalisation".... un peu futile

chrome swift
#

Ça alors?

spark otter
#

oui pourquoi pas

#

et donc tu obtiens une nouvelle matrice D = diag(-1,1)

#

pourquoi on cherche des matrices diagonales ?
Parce que les matrices diagonales ça représente le "scaling" qui est très facile à calculer

#

et ce que la diagonalisation te dit, c'est que ta matrice, si tu la regardes avec la bonne base, bah elle fait juste du scaling

chrome swift
#

Ah je vois

#

Et coment vous avez obtenu diag(-1,1)?

#

Je me souviens que je dois faire T quelque chose.

spark otter
spark otter
#

on sait que T((-1 2)) = -1(-1 2)

#

et T((1 0)) = 1(1 0)

chrome swift
#

Ahh on fait juste plugger les vecteurs propres dans les arguments de la transformation?

spark otter
#

c'est plus que ça

spark otter
#

disons e1 = (-1 2) et e2 = (1 0)

#

et D la matrice de T dans la base (e1, e2)

#

et bien que fait T?

#

elle scale e1 par un facteur -1

#

et elle scale e2 par un facteur 1

#

donc D = diag(-1, 1)

#

on sait que D c'est une matrice diagonale, avec pour coefficients diagonaux les valeurs propres

#

ligne 1 colonne 1, c'est la valeur propre de e1

#

ligne 2 colonne 2, valeur propre de e2

#

etc...

#

et en dehors de la diagonale, des 0

chrome swift
#

Ah ok on fait juste mettre les valeurs propres là-dedans.

#

je m'Excuse d'être un peu têtu à ce sujet, mais ça m'aide à comprendre.

As-tu juste plugger les valeurs propres là où ya un processus mathématique derrière un peu comme ce que j'avais pensé...?

#

J'arrive juste pas à voir le lien direct entre D et l'espace vectoriel.

#

Le plus proche que je crois avoir c'est ci-dessus.

spark otter
#

on en avait déjà parlé, la multiplication matricielle c'est A * (x y z) et pas l'inverse

#

ensuite

chrome swift
#

éAh j'ai oublié de inverer cela

#

J'avais compris cela j,ai juste pas corrigé sur word.

spark otter
#

quand tu écris T(1,2,1) = col1, col1 refère à quoi selon toi ?

chrome swift
#

col1 refère à la colonne1 que l'on obtiendrait de la matrice D

#

Mais ça ne ferait pas de sens

#

Car je pourrais changer l'ordre de mes "appels de fonction" et chier mon idée.

spark otter
#

col1 c'est pas exactement T(1,2,1), c'est les COORDONNEES de T(1,2,1) dans la base de vecteurs propres

#

bon j'écris (1 2 1) = e1, etc...

#

si T(e1) = a*e1 + b*e2 + c*e3

#

alors sur la première colonne de D, on voit les coeffs a,b,c

#

Or

#

On sait que e1 est vecteur propre

#

donc T(e1) = lambda1*e1

#

donc sur la première colonne de D, on lit "lambda1", puis "0", puis "0"

#

on répète le procédé pour chaque colonne

#

on se rend compte que la matrice est bien diagonale

chrome swift
#

Quelque chose comme ça?

#

Je calcule ça, ça m'intrigue.

spark otter
#

oui

chrome swift
#

Je calcule les autres

#

minute.

#

Revoici les vecteurs propres.

spark otter
#

oui

#

bah effectivement, T(1,2,1) = 5*(1,2,1)

#

c'est du scaling

#

idem pour les autres vecteurs

chrome swift
#

Ah c'est pour ça que ça se multiplie par la valeur propre.

#

Je viens de réaliser.. Est-ce simplement un changement de base ici pour obtenir D?

spark otter
#

Oui techniquement

chrome swift
#

Oh well ça ne semble pas décrire l'obtention d'une matrice unique.

#

Ah attends

#

c'es tplus loin

#

Donc faut prendre la base canonique et la base avec mes vecteurs

#

et faut faire quelque chose avec ça

#

Je crois que je vais reprendre demain. Je suis brûlé. un gros merci d'avoir essayé de me dépogner. J'ai fait beaucoup de lien malgré ce mur actuel.

#

Je suis tellement proche de comprendre je le sens.

#

.close

marsh citrusBOT
#
Channel closed

Closed by @chrome swift

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

rain mirage
#

could someone explain why for L2 we can use (4,0) for the max value but cant use (0,2) for the min value?

quaint elm
#

because f is a quadratic function on L2, and the minimum is at its vertex

rain mirage
quaint elm
#

well, when it's pointing up yes

#

if it's pointing down that's the maximum

rain mirage
quaint elm
#

yes, for quadratics

#

generally you'd just check all three though -- each endpoint as well as the vertex, if it's in the relevant area

rain mirage
#

i see

#

do you think there's any point of finding the "forme canonique" here?

quaint elm
#

quest-ce que le forme canonique? $a(x-h)^2 + k$?

elfin berryBOT
#

هايلي

rain mirage
quaint elm
#

it's not hard to do, so you might as well

#

you need to if you want to find the vertex

rain mirage
#

hmm i found what i assume to be the vertex, which is the (3/2, 7/8) point, by using the second degree equation so i think its not necessary from what i understand

#

anyways

#

thanks a lot

#

.close

marsh citrusBOT
#
Channel closed

Closed by @rain mirage

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

main nest
#

can someone plz help me solve these

marsh citrusBOT
spark swallow
#

this trig?

#

@main nest

indigo talon
#

use cosine rule

spark swallow
#

ye

#

for a

#

you given that the sides are congruent

#

so you know all of the sides

#

and for b

#

i think you would want to try to find the angle adjacent to the one you are solving for

#

and its right angle trig so its not that bad

indigo talon
main nest
indigo talon
main nest
indigo talon
#

no

main nest
#

oh 😭

indigo talon
#

it is true that cos(theta) = a/h but thats not cosine rule

main nest
#

then idk what the rule is

indigo talon
#

use this rule to figure it out

main nest
#

i think i got it now!

indigo talon
#

did u get an answer?

#

i believe its 66.42 degrees from my head

main nest
#

.close

marsh citrusBOT
#
Channel closed

Closed by @main nest

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

chilly mica
marsh citrusBOT
chilly mica
#

im struggling for a), don't really have any ideas on where to start

small vector
chilly mica
#

oh oops meant b)

marsh citrusBOT
#

@chilly mica Has your question been resolved?

#
Channel closed

Closed by @chilly mica

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

thin island
marsh citrusBOT
thin island
#

need help understanding whats going here

#

oohh

#

wait

#

they just got antiderivative?

#

can someone please help explain how

-1/2 *cos(2x) became -1/2 * 1/2 *(sin(2x))
near meteor
#

That’s just how you integrate cosine

#

integration of cos becomes sin, and you divide by the derivative of whatever’s in the cos which is 2

marsh citrusBOT
#

@thin island Has your question been resolved?

thin island
#

isnt cos(2x) antiderivative sin(2x)?

then where is the additional 1/2 from?

#

and what about the -1/2? wouldnt it become (-1/2)x same as the term on the very left?

brazen aspen
near meteor
thin island
#

i see

#

what about the -1/2 then?

near meteor
#

That’s just a constant so it stays the same

thin island
#

how come the 1/2 becomes 1/2(x) ?

#

isnt that also a constant

near meteor
#

You can take the 1/2 out of the integral

#

So it would become 1/2 * integral of 1-cos(2x)

thin island
#

ok so like this?

#

then you multiply each one by half right?

brazen aspen
#

why is the integral there you already got the antiderivative

thin island
#

.close

marsh citrusBOT
#
Channel closed

Closed by @thin island

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

main nest
#

anyone know how to solve this plz?

marsh citrusBOT
sleek lake
#

this is pythagoras theorem

#

you know how to solve it

main nest
#

like for the diagonal one i would assume the hypotenuse is 3.6cm?

#

so the elevation/angle is 45 degrees

#

but what side would i solve for?

#

if that makes sense 😭

#

then after i get that i would add with the original 3.6

#

i just dont know which one to do idk if that makes sense

sleek lake
#

you;re right, it's 2 different answers

#

straight or 2 steps added

#

i don't know

#

i would probably guess the shorter one, where you go straight

main nest
#

omg wait i got it

#

i just realised

#

the other side would also be 3.6

#

so u would just to phythag

#

and that answer you would add with the original 3.6

sleek lake
#

no

#

i would do the other way wghere you get a smaller answer

#

i would know i'm guessing

#

and it could be wrong

main nest
#

isnt it 8.69cm?

sleek lake
#

8.69 is the larger one, i would say 8.05

main nest
#

thanks fr ur help

#

.close

marsh citrusBOT
#
Channel closed

Closed by @main nest

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

still temple
#

Is there a way to find out how I can make 3819 using only 5 digits and multiplying by 3

still temple
#

using math

#

or no

limber marsh
#

Not entirely sure what you're asking

still temple
#

i need to

limber marsh
#

Are you asking if there are integers a,b,c,d,e such that
abcde*3 =3819?

still temple
#

not exactly

#

More like

limber marsh
still temple
#

didn't know you could answer that

#

but

#

its more like

#

the integers are 3, 6, 4, 7, 0

#

and the only mathematical operation you can use

#

is multiplying by 3.

#

you can set up the numbers in any way

#

like

#

you can start with 36

#

then do 36*3 which gives

#

,calc 36*3

elfin berryBOT
#

Result:

108
still temple
#

108

#

and then you can add any integer at the end

#

lets say 0,

#

so it becomes 1080

#

i'll make a video hold on

#

so its easier to visualize

#

if that makes sense

cyan parcel
#

Its pretty easy if u reverse engineering it

#

@still temple

still temple
#

i guess you can do like

#

3819/3

#

to get 1273

#

and then try to get 1273

#

from there

#

but its still pretty hard trying to get 1273 unless theres a way to find numbers that cant give 3 in the ones position when multiplied by 3

cyan parcel
#

1273 is not divisible by 3

#

But we have 7 and 3

still temple
#

wait

#

omg

#

4*3

cyan parcel
#

So 12 (73)

still temple
#

then u add on 7 and 3

cyan parcel
#

12 = 4 * 3

still temple
#

yooo

#

tysm ^-^

cyan parcel
#

👍

still temple
#

.close

marsh citrusBOT
#
Channel closed

Closed by @quick sun

Use .reopen if this was a mistake.

still temple
#

great help brother

cyan parcel
#

lmao

still temple
#

waittt wa

#

.reopen

marsh citrusBOT
#

limber marsh
#

Do you still have a question?

still temple
#

is reverse engineering/ figuring out how you get 3819 using only the number 1, and the mathematical operations +7 and *3 possible

#

yep

cyan parcel
#

Should be

still temple
#

okay, the only rule is you can only input 20 things

#

as in like 1 sec i'll make a gif

limber marsh
#

Since both functions increase the number,
There's a finite amount of things you can do anyways

still temple
#

right

cyan parcel
#

Is this a game

#

😭

still temple
#

kind of LOOl

#

i'm not that good with math i'm only up to like

#

maybe completing the square

#

i assume you still need to get 1273 here

#

actually

#

3819
3819/3
1273
1273-7
1266
1266/3
422
maybe

limber marsh
#

Here's one way I think

#

That's 15 moves or so

cyan parcel
#

@still temple What happen for negative

#

Do 1; then - 7

#

What do we get

#

-6?

still temple
#

negatives don't exist

#

i found the solution i'll share it with you guys

limber marsh
#

You can't subtract 7 though

still temple
cyan parcel
#

So -1 become 1

still temple
#

i think this was the solution

limber marsh
still temple
#

howd 10 become 101?

#

i'll share my solution hold on

#

here cuz discord messes it up

limber marsh
still temple
#

ohh

limber marsh
#

There's a lot of ways you can do this one

still temple
#

Yeah that'd work

#

im trying to bruteforce this one now

#

i guess it was a little easier before because it was only plus and division

#

now

#

you have to find 3819 using +201, +234, and -141

#

you start off at 0

still temple
#

so you can't just add 201 19 times

#

nvm solved it

#

okay i'm stuck

#

is there a way to reverse engineer getting 3819 from;

+1
*2
+3

where you can multiply by 2 eight times
and you have a maximum of 18 turns

#

figured it out ^-^

marsh citrusBOT
#

@still temple Has your question been resolved?

still temple
#

sorrey .

#

how would you go by finding 1410535

#

starting with 1

#

where you can multiply by 2 variables

#

the variables value both start at 1 and can be increased only by adding one onto another

#

so, lets say you have 2 variables, a and b

#

both are = 1

#

increasing the value of a means adding b onto a

#

so a + b (1 + 1) = 2 which means a = 2 now

#

then u can add a onto b so on and so forth

#

til you get 1410535

#

but liek idk how.

#

sorry if it's confusing ^-^

still temple
#

for each variable

still temple
#

no fuck th question actually

#

the question just asks for

#

xy = 1410535

#

the answer is 1055 and 1337

#

the problem is

#

how would you get 1055 and 1337 using only adding x and y togethr

sick needle
#

that's a lot of messages

still temple
sick needle
#

holy

still temple
#

i still need help

sick needle
#

oh

#

lmfao i didnt even look at ur question

still temple
#

😭

sick needle
#

dw

marsh citrusBOT
#

@still temple Has your question been resolved?

marsh citrusBOT
#

@still temple Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

knotty trellis
#

finding the solutions is simple

#

but as there are infinitely many of them, writing them down might not be so easy

#

especially given that z^2 = 1 is probably the best way to describe them

#

are you supposed to put them on graph?

#

hmm okay

#

what do they mean by solve?

#

in what form do they want the solutons

#

there are infinitely many of them

small vector
#

i guess you could say if $z = a+bi$ then $\sqrt{a^2 + b^2} = 1$

knotty trellis
#

alright

elfin berryBOT
knotty trellis
#

oh wait

#

ye thats right

#

it has no complex solutions

#

or no complex solutions that arent real

#

because z=1 is complex itself

#

it has just those 2 solutions

#

you can factorize it like this

#

z^2 = 1
z^2 - 1 = 0
(z-1)(z+1) = 0

#

so z=-1 or z=1

#

the imaginary component is 0

#

yep

marsh citrusBOT
#

@still temple Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

white plover
#

help

marsh citrusBOT
white plover
#

I don't know where to begin

warm cargo
#

first rewrite equation in vertex form which will be
g(x) = A(x + h)^2 + k

#

then substitue given vertex into the equation
g(x) = A(x - (-2))^2 + d

#

and the equation also passes through point 2.183,-5 so we can also substitue that into equation
-5 = A(2.183 - (-2))^2 + d

#

and do the same for point N which is x,-5
-5 = A(x - (-2))^2 + d

#

since we need the Y coordinate of -5 for point N this means we have the same equation as for point M so they are on the same parabolic curve and then solve for A and d using the equation we used for point M
-5 = A(2.183 + 2)^2 + d

#

since both points are on the same parabola and have the same y coordinate of -5 their x coordinates will be about the vertex which is -2

#

so this means that if the distance between M and the vertex is 4.183 units (2.183-(-2)=4.183) then the x coordinate of point n will be
x = -2 - 4.183

#

which is -6.183

#

so the value of x for when the y coordinate is -5 will be -6.183

#

(-6.183 , -5 )

white plover
#

:0

marsh citrusBOT
#

@white plover Has your question been resolved?

#
Channel closed

Closed by @white plover

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#
Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

dusty forum
#

.close

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

long cape
#

Cross product

marsh citrusBOT
long cape
#

<a,b,c>

#

Point (x0,y0,z0)

#

What does the following formula find?

dapper socket
long cape
#

a(x-x0) + b(y-y0) + c(z-z0) = 0

#

This formula finds something but what is it?

#

The cross product is also considered the normal vector right? Does that mean the cross product always has a length of 1?

dapper socket
long cape
#

oh maybe

dapper socket
#

yes we get a vector with cross product

long cape
#

I thought they kinda mean the same thing length and magnitude and distance

dapper socket
dapper socket
#

they both are same but yes mostly in vectors it is termed magnitude

long cape
#

Cross prod always has a magnitude of 1?

#

We always call cross product the n vector?

#

n as in norm

long cape
dapper socket
long cape
#

Ah OK

dapper socket
#

for example there are two vectors one along x and other along y

long cape
#

And to find norm of vector I divide each entry by magnitude of the vector? Sqrt(a^2+b^2+c^2)

dapper socket
#

then their cross product has the direction in +z is X cross Y or -z if Y cross X

long cape
dapper socket
dapper socket
long cape
#

So there is normal as in perpendicular

And there is norm as in magnitude of 1

#

Both are different terms

#

I should not get them confused

dapper socket
long cape
#

Huh?

#

“Find the norm”

dapper socket
#

yes it means

#

find the magnitude

#

or length

#

or distance

#

:D

long cape
#

Ohhhh

#

But not necessarily 1

#

Right right

#

That’s called the unit vector

dapper socket
long cape
#

To find the unit vector you divide by the norm right

dapper socket
long cape
# long cape a(x-x0) + b(y-y0) + c(z-z0) = 0

Tyty
Sorry still confused what a question might ask where I need to use this formula? Is the formula finding a plane? Values that you plug in after? A vector? A scalar? A point?

long cape
#

It feels like a plane equation to me

#

Is my intuition correct?

dapper socket
#

yes

#

sorry

#

a plane

long cape
#

And what would the question be asking

#

Where I should use this formula

#

Given only a point and a vector

#

Find the plane?

#

Plane where point passes through

#

Plane of the vector I guess?

dapper socket
#

question will ask you to find a plane passing through (x0,y0,z0) and then in the direction of a vector n which is (a,b,c)

long cape
#

Oh wow

long cape
#

How do you know the vector is a cross product vector to begin with?

#

The question stated that?

dapper socket
dapper socket
long cape
#

Oh ok

dapper socket
#

tbh this formula is quite useful in many scenarios let me try to list some

#

to make it more clear

long cape
#

Tyvm

dapper socket
#
  1. Determining the equation of a plane passing through a specific point with a given normal vector

  2. Finding the intersection of two planes

  3. Defining the orientation of a plane in 3D space relative to a reference point

#

do you have some exercise book with questions? if yes then maybe try seeing the ones that uses this formula since it can be used in too many ways

long cape
#

Yeah, thank you

#

I will keep that In mind

#

Tyvm!

dapper socket
#

see the vector passing through (a,b,c) can be any vector

#

a cross product of two vectors

#

simply a normal vector to a plane

#

both are possible

#

since when you cross product two vectors you also kind of visualize the resultant vector to be perpendicular to the plane formed by those two vectors in the space

dapper socket
long cape
#

.close

marsh citrusBOT
#
Channel closed

Closed by @long cape

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

buoyant blade
#

if x=2^1/3 -2^-1/3 then 2x^3 + 6x =?

marsh citrusBOT
serene spoke
#

Hii

late geode
#

!status

marsh citrusBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
serene spoke
#

(a-b)³ = a³ - b³ -3ab(a-b)

#

Use this and simplify

buoyant blade
#

i used

#

i got -6^1/3 -6^-1/3 (2^1/3 - 2^-1/3) + 6(2^1/3 - 2^-1/3)

buoyant blade
late geode
#

wheres base of 6 coming from

#

do you have a pic of your work on paper

buoyant blade
late geode
#

you're violating the order of operations in the third line in multiple ways

#

you're seem to be trying to do
a(b+c)^n→(ab + ac)^n
which is invalid since exponentiation takes priority
and then also
pq^n → (pq)^n
which again is invalid for the same reason

buoyant blade
#

yeah i bro i need a clear explanation how exponents work with addition subractiona multiplication division cuz i just completed 10th

late geode
#

its a bit more convenient to use the cubic expansion identity with the $-$ \
$$(a-b)^3 = a^3 - b^3 -3ab(a-b)$$
here your
$$a = 2^{\frac13}, b = 2^{-\frac13}$$

elfin berryBOT
#

ℝαμΩℕωⅤ

late geode
#

do you have access to a list of exponent laws

marsh citrusBOT
#

@buoyant blade Has your question been resolved?

#
Channel closed

Closed by @buoyant blade

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wanton shale
marsh citrusBOT
wanton shale
#

can someone tell me why we need to find A'(t) and not simply A(t). I know it's the right answer but it doesn't make sense to me that l(t) and w(t) multiply to give A(t) but we need to find A'(t). isn't the first derivative only taken to find the speed of a rate of change?

broken dome
#

You need to find the rate at which it is increasing

#

Not the ammount it is

#

A(t) is the function of the area in a given moment with unit cm

#

A'(t) is the rate of change of the area in a given moment with unit cm/s

#

You are given the rate of change of the sides

#

So you are given l'(t) = 5 cm/s and w'(t) = 4 cm/s

#

They don't multiply to A'(t) however

#

A'(t) should come out to be l'(t) * w(t) + w'(t) * l(t)

#

Where w(t) is width in a moment and l(t) length in a moment

wanton shale
#

thanks that makes things clear. i'm also curious as to why they assumed we should find A'(t) at t=0 when it wasn't explicitly stated in the question.

is it because the equations of l(t) = 12+5t and w(t) = 10+4t are based on when the time is zero?

broken dome
#

I don't have the full question sheet, so I don't know, in this case you're not given the time, you're given the dimension, so you need to find the moment in time from the given dimensions, but since the rate of change is constant it doesn't matter anyway

#

If the rate of change is constant then it doesn't change with time, hence t doesn't matter

marsh citrusBOT
#

@wanton shale Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

exotic wolf
#

Hello. I have a question about Partial Fraction Decomposion

exotic wolf
#

So here they did the following method

#

but if we set x=2, then we divide with 0

frosty linden
#

? Where

#

No it sets x= 2 on A so no problem for B WE have x= 3

exotic wolf
#

I dont understand what you mean

#

if we put x = 2

#

then Q(x) = 0

#

so we divide with 0

frosty linden
#

What is Q(x)

exotic wolf
#

(x-2)(x-3)

frosty linden
#

Ok what is P(x)

exotic wolf
#

x+4

frosty linden
#

I didn't get that for me when you have your expression multiply both side by your denominator and evaluate on the roots

#

And you get your A and B

exotic wolf
#

i dont understand

frosty linden
#

You will have like x+4 = A(x-3) + B(x-2)

#

And you evaluate on Roots which are 3 and 2 to get A and B

exotic wolf
#

oh yeah, i get it now

#

thanks

#

.close

marsh citrusBOT
#
Channel closed

Closed by @exotic wolf

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

toxic lily
#

Anyone know how to prove this

marsh citrusBOT
toxic lily
#

Tried induction for a while did not reach far

marsh citrusBOT
#

@toxic lily Has your question been resolved?

marsh citrusBOT
#

@toxic lily Has your question been resolved?

toxic lily
#

.close

marsh citrusBOT
#
Channel closed

Closed by @toxic lily

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

modern heron
#

can u help me if its okay? i had to check the uniform convergence

marsh citrusBOT
#

@modern heron Has your question been resolved?

modern heron
#

<@&286206848099549185>

marsh citrusBOT
#

@modern heron Has your question been resolved?

marsh citrusBOT
#

@modern heron Has your question been resolved?

marsh citrusBOT
#

@modern heron Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

rain hare
#

How do i interpret and solve this?

marsh citrusBOT
next raft
#

try drawing a table

dusky viper
#

follow the same theme for the other 2 equations

#

u should have an equation for lead and an equation for manganese

marsh citrusBOT
#

@rain hare Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

hasty wasp
#

The part that's been bothering me for this question is the text in the 2nd picture

hasty wasp
#

B is a random variable for the mass of each biscuit

P1 is a random variable for the mass of each packet containing 25 biscuits

P2 is a random variable for the mass of each packet containing 26 biscuits

X is a random variable for the mass of each box filled with packets containing 25 biscuits

#

The problem I'm dealing with is interpreting the text in the 2nd pic

#

I thought it was P(P1>P2) but when I calculated it out it was not the right answer

#

The answer is actually 0.0385

#

How do you interpret this text as is to get the probability?

marsh citrusBOT
#

@hasty wasp Has your question been resolved?

hasty wasp
#

<@&286206848099549185>

hasty wasp
#

<@&286206848099549185>

marsh citrusBOT
#

@hasty wasp Has your question been resolved?

hasty wasp
#

<@&286206848099549185>

hasty wasp
#

<@&286206848099549185> this is urgent btw I don't wanna wait on this forever

ivory sundial
#

Divide the variance by 25

elfin berryBOT
hasty wasp
ivory sundial
#

If you do a hypothesis test:

Suppose in one test you sample 100 items.

And in another you sample just 25 items.

Clearly the bigger sample is more significant, but without changing the variance you would get the same probabilities out for equal sample means.

#

Decreasing the variance by a factor of n just accounts for that.

hasty wasp
#

This is about probability ditributions not sampling and estimations

#

If my knowledge in that is void (which it is) how would I've known it in the first place when confronting the question

#

<@&286206848099549185>

#

<@&286206848099549185>

#

<@&286206848099549185> urgent but is there another way to do this question in its own concept

sick needle
#

No idea

hasty wasp
#

Might as well ping for every 10 mins then

#

<@&286206848099549185>

next phoenix
#

Bruh

hasty wasp
#

<@&286206848099549185>

indigo talon
#

it seems to be a sampling proportions question

hasty wasp
#

All of these are involving random variables and probability distributions

#

Even the previous chapters were about probabilities

#

The next chapter is sampling and estimation

#

How would I know a thing that is without no preview of the next chapter?

#

@indigo talon

indigo talon
#

alr ill talk a look at the problem

#

its been a bit since ive done normal distributions and stuff so give me sum time

hasty wasp
#

Kewl

indigo talon
#

so we have to find the distribution of the total mass of biscuits

#

what do u think the mean of this new distribution is gonna be

#

@hasty wasp

hasty wasp
#

Did that

indigo talon
hasty wasp
#

I'm only posting pics of the questions as a whole just fyi

#

The ones I've written saying "Confused by subquestion/part of question" is what I struggled finding with

#

I mean if someone took time to look around sure they'd catch on

#

<@&286206848099549185>

#

<@&286206848099549185>

hasty wasp
#

<@&286206848099549185>

#

<@&286206848099549185>

#

<@&286206848099549185>

#

<@&286206848099549185> just one question PLEASE
Thank me that I havent gotten unhinged today

fallow roost
#

why are you spaminh

#

stop

sleek shadow
#

you’ve phoned helpers like 34 times bro

fallow roost
#

yes

#

my notification is full of your massages

#

pls

#

pls

#

stop

sleek shadow
#

try again later in a couple hours

#

just… it’s very early for NA

hasty wasp
#

Its been 4 hours

#

It was evening

#

Its night

hasty wasp
sleek shadow
still temple
#

is this the question u need to answer?

#

for the first question (the 598g to 606g)

#

Since the sample is random the masses of the 25 biscuits will be independent of each other

#

the distribution of the total mass willl be normal

still temple
#

ah

hasty wasp
#

Some say it is a sampling question

still temple
#

is that the second question of 26? the "ten packets of biscuits are placed in a box" one?

hasty wasp
still temple
#

ahh ok

hasty wasp
#

This

still temple
#

so

#

If X is the mass of the biscuit in packet containing 25 buiscuits then we already know that X is

#

N(600,90.25)

molten moss
still temple
#

If we say Y is the mass of buiscut in a packet containing 26 buiscuits then Y is normally distributed with mean 26 x24=624g and variance 26 x 1.9^2=93.86

molten moss
#

i haven't looked up the values but i'm wondering why the result is so high

still temple
#

the difference Y-X is normally distributed with mean = equalling 624-600

#

or 24 g

#

variance is 184.11

#

and standard dev is 13.57

molten moss
#

0.2236 is the answer that you came up with, right? just intuitively that sounds crazy high, so maybe something went wrong with selecting that Z-value 0.760

still temple
#

thus z=(0-24)/(13.57)=-1.769

#

hence the probability is 1-0.9615

#

aka 0.0385

#

i think that is the best any1 can help u here

#

people arent always jumping to help u so be patient

#

this may not always be the quickest most efficient method of answer finding

#

or even help finding at that

molten moss
#

ye just a thought, i was scared of even starting this question b/c there were like 200 messages after the original question

still temple
#

FR!

molten moss
#

it can help to restate what the actual question is at that point, b/c it looks like maybe there's already been some progress

#

tho i guess in this case there wasn't necessarily

still temple
#

i open discord and instantly get compounded with 200+ messages

#

anyways i gtg i have school 😭, just a few days till middle school is over 4 me

hasty wasp
#

Not used to waiting 4 hours for a question I want to be answered before I sleep and have to reopen

still temple
#

np! i got you

hasty wasp
#

I guess I'll evolve to being patient so yeah

still temple
#

that would help...

hasty wasp
#

Sorry for the pings too

still temple
#

np for me.. cant say the same for every1 else

hasty wasp
#

True

still temple
#

well if that answers ur questions ill be on my way

hasty wasp
#

It does