#help-33
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@proud zealot Has your question been resolved?
Coefficient of z^0 is 1, coefficient of z^n for any strictly positive integer n must be zero
From there and comparing, see the sum goes from -infty to -1 only
So a(n) is only 2 for strictly negative n
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In qs 4 why does E1 have 1/6E2 term
Shouldn't it be just 1/6 coz that's the probability it will end
Bruh
@next phoenix Has your question been resolved?
<@&286206848099549185> pls look at qs above
@next phoenix Has your question been resolved?
<@&286206848099549185> <@&286206848099549185> someone
@next phoenix Has your question been resolved?
its actually E5
same reason for E1 to have 2/6 because its E1 and E6
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what is trivial solution in linear algebra in matrixes ?
For 3 sets of questions
a1x+b1y+c1z=0
a2x+b2y+c2z=0
a3x+b3y+c3z=0
x=0,y=0,z=0 is a trivial solution
and inorder to have a non trivial solution det of coefficients should be 0
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what am i doing wrong - solving the 4th no
logic for ease :
ab = bc(given) so <a = <b = 45 deg .
<h = 90deg and <b = 45deg so <hdb = 45 too, so hd = hb.
ac is root3 so bc is root 3 too bcos <a = <b.
So bd = root3 - 1.
And we here
@vivid wharf Has your question been resolved?
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Given the bases S = v₁,v₂ and T = w₁, w₂. V = R² with:
v₁ = -3w₁ + 9w₂ and v₂ = 8w₁ - 4w₂
Calculate the determinant of the base change matrix from base S to base T. (Note: Carry out the calculations and provide the result in decimal form with 5 decimal places).
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can someone check if this is right
yeah, its correct
idk why you calculated y(1) tho
You can always check these things with Desmos
wdym/
oh i di that to see which one is the top and which one is bottom
ahh
yea bc my teacher doesnt allow us to use calc on test so i do the hw without calc
you don't have to do that I think
you'll just get the negative answer but the absolute value will be the same
this one i need help with
you should get -72 if you reverse them
Ye is good
you can use the calculator to check your work is what I meant
oh really? i did it right?
If the answer is right then the process is usually right too with integrals
assuming the formula is correct
yes
ok cooll and ik i can use desmos but do u think i should make this graph look better or is this fine
Depends on what your teacher wants, that sketch is very inaccurate given dimensions, but it's correct in terms of shape
They wouldn't intersect at the x axis
@broken dome How’s this?
Much better
@crisp sigil Has your question been resolved?
could anythig be improvid
I mean, if you really wanted to you could mark the points they cross and write which coordinates they are
and like hatch the area that you're calculating
add axis notation
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Hello, so I was just wondering if when doing questions like e-i i should take whatever is out of the bracket out of the integration because I saw in a video some rule i dont know when to apply it as he did not give an example. I am pretty sure you dont take it out so could you give me an example of when that rule applies.
You can only factor things out if they're constants
E.g. they're unaffected by x
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I need help with question 8. d)
You need to know that $log(ab)=log(a)+log(b)$
coak
Then the problem tells you that the logs are in an arithmetic sequence
yes
So let their common difference be d
Then log(p)-log(27) = log(p/27)=d
And same with the rest
So p/27 = q/p = 125/q = 8^d
See?
ohh
i see
so thats enough for 8 d
and now i just solvev for p and q
with this
p/27 = q/p
or wait
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( U+
V+
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We have a sequence defined by:
Un = ((n-2) / (n)) × Un-1 - ((n-3) / (n(n-1))) × Un-2
U0 = 1 and U1 = 2
how much is the following amount worth:
Sn = (U0 / U1) + (U1 / U2) +...+ (U2023 / U2024)
Thanks
you're missing a ) somewhere. where's that supposed to go?
that's it, thank you
Bob Goldham
what does that ratio equal in the general case?
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Can someone help me with either of these questions pls thank u!
how to get started or what rules I need to know
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can someone confirm whether the notation is done properly?
and I use a lot of steps, which could I omit?
lasso notation 😭
what is that
ur integrals look like a lasso
penguin
why does it say +4c at the end lol
In 15 write 1 = n/n to get (1+i)^4/n^4, put inside the other n to get n^5, expand (1+i)^4 using Pascal triangle, you will get 5 terms with coeficients 1,4,6,4,1. Not, use them to get 5 sums, all are basics like \sum i or \sum i^2. Do the limit
its just + c
its to show I substituted
should it not be there at that point?
uh if thats how ur teacher wants it ok but that seems weird
I dont fully understand the dx syntax to begin with
ik d(...) means derivative of whatever is inside
In 4 only evaluate to get 0 - 1 + sin(pi/3) = -1 + sqrt(3)/2 = (sqrt 3 - 2) / 2. You can compute sin(pi/3) using euler identity exp(i x) = cos(x) + i sin(x)
but no clue why I can just omit the whole * dx/d() once I start to get the primitive
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Small theoric question from me
Say a matrix that has n euginics values.
Their eugian values per eugian values form a basis together? or they have to be split from each numbers?
For example these three vectors
(1,1,1), (-3,0,1) and (1,2,0).
Do they form a basis of R3?
Or it's only (1,1,1) that is a basis of R3
yeah they do form a basis of R³
Oh, so I have to combine all of them?
yep that's correct
When your matrix is diagonalizable, you have to combine the vectors of EACH eigenspace
So a Matrix of 5x5 that has 5 eugianvalues.
All of these vectors together will form a basis.
of R5
Not only from one.
1 vector per eigenspace/eigenvalue, yes you will get 5 vectors that form a basis of R5
there can be a 3×3 matrix which is not diagonizable (meaning it doesn't form a basis of R³)
det(A-kI) is to find eigenvalues
that just means k is not an eigenvalue
Ah woops.
Let me recitify
Say for a matrix of 2x3
if
P(x) = x^2 - (a11 + a22)x + det(A)
can't ever be = 0, then it doesn't have eigenvalues.
a non-square matrix has no eigenvalues
it's a polynomial, it always has eigenvalues
no one said it had to be real ones
Ok gotcha.
Similar question before I finally tackle the diagonalisation.
d) is the one I'm looking at.
how would I ive a matrix D
Hold on let me give you the basis according to a calculator
How would I build a matrix with these three vectors?
I just place them side by side?
bon parlons en francais alors
La matrice D est diagonale et contient les valeurs propres associées à chaque vecteur propre de la base sur sa diagonale
Oh vous êtes français! Cool.
Le problème n'était pas de savoir si c'était une matrice diagonale
Mais comment obtenir cette matrice à partir de la base.
J'ai l'impression que je pourrais donner n'importe quoi
Comme ceci :
disons que ta base c'est e1 = (1 2 1), e2 = (1 0 1) et e3= (-1 1 0)
c'est tes vecteurs propres, aucun problème jusque là?
Non, aucun problème.
ok
Ils font une base de R3 ensemble.
Ah ok je fais juste les joindre bout à bout?
c'est les coordonnées de T(ei) dans la nouvelle base
nonon
$D = \begin{pmatrix}a&b&c\d&e&f\g&h&k\end{pmatrix}$
où
rafilou2003
$T(e_1) = ae_1 + de_2 + ge_3$
rafilou2003
$T(e_2) = be_1 + ee_2 + he_3$
rafilou2003
etc...
c'est comme ça que tu es sensé obtenir les coefficients de D
Ce serait hyper long sans indication
mais là coup de bol
Eh boy.
rafilou2003
Ah attend, le A est la matrice associée à la transformation linéaire?
Donc une fonction prenant trois arguments (bu que c'est la base canonique)?
A majuscule c'est la matrice de T dans la base canonique
Genre toute la méga opérations de cette transformation se ferait en résoudant cette matrice
Un peu comme les rotations dans les transformations géométriques?
Oui en fait A décrit intégralement T
Aaaah ok.
Si tu sais comment se comportent les images de chaque vecteur d'une base, alors tu sais comment se comporte la transformation dans son intégralité
parce que la transformation est linéaire
Ok donc pour résumé
On a une fonction qui fait une multiude de opérations à un vecteur quelconque
qui peut se résumer à une opération matricielle de vce vecteur avec la matrice A
Genre
oui T(X) = AX
si X est le vecteur colonne (x y z) de R^3 alors T(X) se résume à multiplier A avec X
R^3 c'est pas supposé être des matrices 3x3?
R^3 c'est l'ensemble des vecteurs à 3 coordonnées réelles
l'ensemble des matrices 3x3 c'est $\mathcal{M}_3(\bR)$
rafilou2003
ou encore $\bR^{3\times 3}$
Donc fau tjuste que j'aie une ligne ou une colonne de 3 max
rafilou2003
Ehh boy va falloir que je corrige cela dans ma tête ahah. merci de cette correction.
Ok ce qui est donné dans la fonction fait plus de sens.
par convention les vecteurs de R^n sont associées au matrices n*1
Je donne 3 valeurs à la transformation.
Il se passe quelque chose qui es défini par la matrice A
qui englobe toutes les opérations effectuées.
Jpourrais par exemple avec une rotation avec une dilatation dans cette matrice là.
Je commence à faire des liens
attends je fais un petit gribouilli
Voici ce que la transformation ferait.
Et ce quelque chose est dans R3.
Ce qui n'est psa intéressant, car ce n,est pas ce que l'on cherche. Mais ça fait beaucoup de sens ou de liens. je comprends mieux la présentation et ce que l'on fait.
Puis là on prend la matrice A, et on le décortique avec le polynôme caractéristique, etc.
Jusque là, est-ce que je me plante ou je pédale avec 4 roues? 😄
alors c'est quasiment ça
Ah oops.
Merci de la correction
Ok good
Donc là on prend A, et on l'a décomposé pour trouver une base.
Revoici l'exemple de tantôt
Il se passe quoi ici? Est-ce que l'on obtient un nouvel A plus facile à calculer?
Ou encore, prenons la symétrie orthogonale avec X pour une matrice R2
Deux vecteurs archi simple.
Que serait D dans ce cas super simple.
en fait D est la même matrice
tu as pris une matrice déjà diagonale
Ah oops. Pasun bon exemple alors.
ce qui rend le principe de la "diagonalisation".... un peu futile
oui pourquoi pas
et donc tu obtiens une nouvelle matrice D = diag(-1,1)
pourquoi on cherche des matrices diagonales ?
Parce que les matrices diagonales ça représente le "scaling" qui est très facile à calculer
et ce que la diagonalisation te dit, c'est que ta matrice, si tu la regardes avec la bonne base, bah elle fait juste du scaling
Ah je vois
Et coment vous avez obtenu diag(-1,1)?
Je me souviens que je dois faire T quelque chose.
en fait théoriquement il faut passer par là
mais ayant une base de vecteurs propres
on sait que T((-1 2)) = -1(-1 2)
et T((1 0)) = 1(1 0)
Ahh on fait juste plugger les vecteurs propres dans les arguments de la transformation?
c'est plus que ça
quand on regarde la transformation T avec la nouvelle base de vecteurs propres
disons e1 = (-1 2) et e2 = (1 0)
et D la matrice de T dans la base (e1, e2)
et bien que fait T?
elle scale e1 par un facteur -1
et elle scale e2 par un facteur 1
donc D = diag(-1, 1)
on sait que D c'est une matrice diagonale, avec pour coefficients diagonaux les valeurs propres
ligne 1 colonne 1, c'est la valeur propre de e1
ligne 2 colonne 2, valeur propre de e2
etc...
et en dehors de la diagonale, des 0
Ah ok on fait juste mettre les valeurs propres là-dedans.
je m'Excuse d'être un peu têtu à ce sujet, mais ça m'aide à comprendre.
As-tu juste plugger les valeurs propres là où ya un processus mathématique derrière un peu comme ce que j'avais pensé...?
J'arrive juste pas à voir le lien direct entre D et l'espace vectoriel.
Le plus proche que je crois avoir c'est ci-dessus.
attends déjà plusieurs problèmes
on en avait déjà parlé, la multiplication matricielle c'est A * (x y z) et pas l'inverse
ensuite
éAh j'ai oublié de inverer cela
J'avais compris cela j,ai juste pas corrigé sur word.
quand tu écris T(1,2,1) = col1, col1 refère à quoi selon toi ?
col1 refère à la colonne1 que l'on obtiendrait de la matrice D
Mais ça ne ferait pas de sens
Car je pourrais changer l'ordre de mes "appels de fonction" et chier mon idée.
col1 c'est pas exactement T(1,2,1), c'est les COORDONNEES de T(1,2,1) dans la base de vecteurs propres
bon j'écris (1 2 1) = e1, etc...
si T(e1) = a*e1 + b*e2 + c*e3
alors sur la première colonne de D, on voit les coeffs a,b,c
Or
On sait que e1 est vecteur propre
donc T(e1) = lambda1*e1
donc sur la première colonne de D, on lit "lambda1", puis "0", puis "0"
on répète le procédé pour chaque colonne
on se rend compte que la matrice est bien diagonale
oui
oui
bah effectivement, T(1,2,1) = 5*(1,2,1)
c'est du scaling
idem pour les autres vecteurs
Ah c'est pour ça que ça se multiplie par la valeur propre.
Je viens de réaliser.. Est-ce simplement un changement de base ici pour obtenir D?
Oui techniquement
Oh well ça ne semble pas décrire l'obtention d'une matrice unique.
Ah attends
c'es tplus loin
Donc faut prendre la base canonique et la base avec mes vecteurs
et faut faire quelque chose avec ça
Je crois que je vais reprendre demain. Je suis brûlé. un gros merci d'avoir essayé de me dépogner. J'ai fait beaucoup de lien malgré ce mur actuel.
Je suis tellement proche de comprendre je le sens.
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could someone explain why for L2 we can use (4,0) for the max value but cant use (0,2) for the min value?
because f is a quadratic function on L2, and the minimum is at its vertex
alright so when there's a second degree equation, the min will always be found by -b/2a?
so there's always either one of the two points that i can directly use to calculate one of the values right?
yes, for quadratics
generally you'd just check all three though -- each endpoint as well as the vertex, if it's in the relevant area
quest-ce que le forme canonique? $a(x-h)^2 + k$?
هايلي
oui c'est celui-là

it's not hard to do, so you might as well
you need to if you want to find the vertex
hmm i found what i assume to be the vertex, which is the (3/2, 7/8) point, by using the second degree equation so i think its not necessary from what i understand
anyways
thanks a lot
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can someone plz help me solve these
use cosine rule
ye
for a
you given that the sides are congruent
so you know all of the sides
and for b
i think you would want to try to find the angle adjacent to the one you are solving for
and its right angle trig so its not that bad
yeah find the adjacent angle to be 180 - theta and use tan to find it
but how do you know which one is the adjacent and hypotenuse in this?
do you know what cosine rule is?
isnt it a/h?
no
oh 😭
it is true that cos(theta) = a/h but thats not cosine rule
then idk what the rule is
use this rule to figure it out
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im struggling for a), don't really have any ideas on where to start
here's a visual on how p^a rotates you around the unit circle as you vary a
https://www.geogebra.org/calculator/mgsgcu6f
oh oops meant b)
@chilly mica Has your question been resolved?
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need help understanding whats going here
oohh
wait
they just got antiderivative?
can someone please help explain how
-1/2 *cos(2x) became -1/2 * 1/2 *(sin(2x))
That’s just how you integrate cosine
integration of cos becomes sin, and you divide by the derivative of whatever’s in the cos which is 2
@thin island Has your question been resolved?
im still abit confused
isnt cos(2x) antiderivative sin(2x)?
then where is the additional 1/2 from?
and what about the -1/2? wouldnt it become (-1/2)x same as the term on the very left?
no antiderivative of cos(kx) where k is a constant is sinx/k
You need to divide by the derivative of what’s inside the function
That’s just a constant so it stays the same
You can take the 1/2 out of the integral
So it would become 1/2 * integral of 1-cos(2x)
why is the integral there you already got the antiderivative
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anyone know how to solve this plz?
ik but which one would you use
like for the diagonal one i would assume the hypotenuse is 3.6cm?
so the elevation/angle is 45 degrees
but what side would i solve for?
if that makes sense 😭
then after i get that i would add with the original 3.6
i just dont know which one to do idk if that makes sense
you;re right, it's 2 different answers
straight or 2 steps added
i don't know
i would probably guess the shorter one, where you go straight
omg wait i got it
i just realised
the other side would also be 3.6
so u would just to phythag
and that answer you would add with the original 3.6
no
i would do the other way wghere you get a smaller answer
i would know i'm guessing
and it could be wrong
isnt it 8.69cm?
8.69 is the larger one, i would say 8.05
ohh ok thx
thanks fr ur help
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Is there a way to find out how I can make 3819 using only 5 digits and multiplying by 3
Not entirely sure what you're asking
sorry if the question seems confusing
i need to
Are you asking if there are integers a,b,c,d,e such that
abcde*3 =3819?
Answer to that is yes btw
didn't know you could answer that
but
its more like
the integers are 3, 6, 4, 7, 0
and the only mathematical operation you can use
is multiplying by 3.
you can set up the numbers in any way
like
you can start with 36
then do 36*3 which gives
,calc 36*3
Result:
108
108
and then you can add any integer at the end
lets say 0,
so it becomes 1080
i'll make a video hold on
so its easier to visualize
if that makes sense
yea
i guess you can do like
3819/3
to get 1273
and then try to get 1273
from there
but its still pretty hard trying to get 1273 unless theres a way to find numbers that cant give 3 in the ones position when multiplied by 3
So 12 (73)
then u add on 7 and 3
12 = 4 * 3
👍
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great help brother
lmao
✅
Do you still have a question?
is reverse engineering/ figuring out how you get 3819 using only the number 1, and the mathematical operations +7 and *3 possible
yep
Should be
okay, the only rule is you can only input 20 things
as in like 1 sec i'll make a gif
Since both functions increase the number,
There's a finite amount of things you can do anyways
kind of LOOl
i'm not that good with math i'm only up to like
maybe completing the square
i assume you still need to get 1273 here
actually
3819
3819/3
1273
1273-7
1266
1266/3
422
maybe
You can't subtract 7 though
wait
So -1 become 1
i think this was the solution
This works
howd 10 become 101?
i'll share my solution hold on
here cuz discord messes it up
You use the 1 button to add it at the end?
ohh
There's a lot of ways you can do this one
Yeah that'd work
im trying to bruteforce this one now
i guess it was a little easier before because it was only plus and division
now
you have to find 3819 using +201, +234, and -141
you start off at 0
in strictly 24 moves
so you can't just add 201 19 times
nvm solved it
okay i'm stuck
is there a way to reverse engineer getting 3819 from;
+1
*2
+3
where you can multiply by 2 eight times
and you have a maximum of 18 turns
figured it out ^-^
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sorrey .
how would you go by finding 1410535
starting with 1
where you can multiply by 2 variables
the variables value both start at 1 and can be increased only by adding one onto another
so, lets say you have 2 variables, a and b
both are = 1
increasing the value of a means adding b onto a
so a + b (1 + 1) = 2 which means a = 2 now
then u can add a onto b so on and so forth
til you get 1410535
but liek idk how.
sorry if it's confusing ^-^
you can only multiply once
for each variable
no fuck th question actually
the question just asks for
xy = 1410535
the answer is 1055 and 1337
the problem is
how would you get 1055 and 1337 using only adding x and y togethr
that's a lot of messages
plez help .
holy
i still need help
😭
dw
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finding the solutions is simple
but as there are infinitely many of them, writing them down might not be so easy
especially given that z^2 = 1 is probably the best way to describe them
are you supposed to put them on graph?
hmm okay
what do they mean by solve?
in what form do they want the solutons
there are infinitely many of them
i guess you could say if $z = a+bi$ then $\sqrt{a^2 + b^2} = 1$
alright
b
oh wait
ye thats right
it has no complex solutions
or no complex solutions that arent real
because z=1 is complex itself
it has just those 2 solutions
you can factorize it like this
z^2 = 1
z^2 - 1 = 0
(z-1)(z+1) = 0
so z=-1 or z=1
the imaginary component is 0
yep
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help
first rewrite equation in vertex form which will be
g(x) = A(x + h)^2 + k
then substitue given vertex into the equation
g(x) = A(x - (-2))^2 + d
and the equation also passes through point 2.183,-5 so we can also substitue that into equation
-5 = A(2.183 - (-2))^2 + d
and do the same for point N which is x,-5
-5 = A(x - (-2))^2 + d
since we need the Y coordinate of -5 for point N this means we have the same equation as for point M so they are on the same parabolic curve and then solve for A and d using the equation we used for point M
-5 = A(2.183 + 2)^2 + d
since both points are on the same parabola and have the same y coordinate of -5 their x coordinates will be about the vertex which is -2
so this means that if the distance between M and the vertex is 4.183 units (2.183-(-2)=4.183) then the x coordinate of point n will be
x = -2 - 4.183
which is -6.183
so the value of x for when the y coordinate is -5 will be -6.183
(-6.183 , -5 )
:0
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Cross product
cross product of position vector of (a,b,c) and (x,y,z) ?
a(x-x0) + b(y-y0) + c(z-z0) = 0
This formula finds something but what is it?
The cross product is also considered the normal vector right? Does that mean the cross product always has a length of 1?
you mean magnitude not length right?
oh maybe
yes we get a vector with cross product
I thought they kinda mean the same thing length and magnitude and distance
this formula is for a,b,c vector perpendicular to a plane where x0,y0,z0 is a point on the plane
wait
they both are same but yes mostly in vectors it is termed magnitude
Cross prod always has a magnitude of 1?
We always call cross product the n vector?
n as in norm
So what sort of question would I use this formula for? How would the question be worded
nope only the maginitude of cross product of unit vector is 1
Ah OK
yes because cross product is normal to the plane formed by two vectors
for example there are two vectors one along x and other along y
And to find norm of vector I divide each entry by magnitude of the vector? Sqrt(a^2+b^2+c^2)
then their cross product has the direction in +z is X cross Y or -z if Y cross X
“Normal” vector is different in this context? Not referring to magnitude of 1?
well you use this to like find a vector in the direction of a,b,c or you can say normal to the given plane
\ normal as in perpendicular
So there is normal as in perpendicular
And there is norm as in magnitude of 1
Both are different terms
I should not get them confused
no norm means magnitude or length of a vector
If it said find the unit vector then you may want to find the vector in that direction with magnitude/length = 1
To find the unit vector you divide by the norm right
yes that is correct
Tyty
Sorry still confused what a question might ask where I need to use this formula? Is the formula finding a plane? Values that you plug in after? A vector? A scalar? A point?
a plane.
And what would the question be asking
Where I should use this formula
Given only a point and a vector
Find the plane?
Plane where point passes through
Plane of the vector I guess?
question will ask you to find a plane passing through (x0,y0,z0) and then in the direction of a vector n which is (a,b,c)
Oh wow
What does direction mean in this question?
How do you know the vector is a cross product vector to begin with?
The question stated that?
direction of a vector?
the vector doesn't need to be a cross product
Oh ok
tbh this formula is quite useful in many scenarios let me try to list some
to make it more clear
Tyvm
-
Determining the equation of a plane passing through a specific point with a given normal vector
-
Finding the intersection of two planes
-
Defining the orientation of a plane in 3D space relative to a reference point
do you have some exercise book with questions? if yes then maybe try seeing the ones that uses this formula since it can be used in too many ways
see the vector passing through (a,b,c) can be any vector
a cross product of two vectors
simply a normal vector to a plane
both are possible
since when you cross product two vectors you also kind of visualize the resultant vector to be perpendicular to the plane formed by those two vectors in the space
you're most welcome
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if x=2^1/3 -2^-1/3 then 2x^3 + 6x =?
Hii
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
.
you're violating the order of operations in the third line in multiple ways
you're seem to be trying to do
a(b+c)^n→(ab + ac)^n
which is invalid since exponentiation takes priority
and then also
pq^n → (pq)^n
which again is invalid for the same reason
yeah i bro i need a clear explanation how exponents work with addition subractiona multiplication division cuz i just completed 10th
so
its a bit more convenient to use the cubic expansion identity with the $-$ \
$$(a-b)^3 = a^3 - b^3 -3ab(a-b)$$
here your
$$a = 2^{\frac13}, b = 2^{-\frac13}$$
ℝαμΩℕωⅤ
do you have access to a list of exponent laws
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can someone tell me why we need to find A'(t) and not simply A(t). I know it's the right answer but it doesn't make sense to me that l(t) and w(t) multiply to give A(t) but we need to find A'(t). isn't the first derivative only taken to find the speed of a rate of change?
You need to find the rate at which it is increasing
Not the ammount it is
A(t) is the function of the area in a given moment with unit cm
A'(t) is the rate of change of the area in a given moment with unit cm/s
You are given the rate of change of the sides
So you are given l'(t) = 5 cm/s and w'(t) = 4 cm/s
They don't multiply to A'(t) however
A'(t) should come out to be l'(t) * w(t) + w'(t) * l(t)
Where w(t) is width in a moment and l(t) length in a moment
thanks that makes things clear. i'm also curious as to why they assumed we should find A'(t) at t=0 when it wasn't explicitly stated in the question.
is it because the equations of l(t) = 12+5t and w(t) = 10+4t are based on when the time is zero?
I don't have the full question sheet, so I don't know, in this case you're not given the time, you're given the dimension, so you need to find the moment in time from the given dimensions, but since the rate of change is constant it doesn't matter anyway
If the rate of change is constant then it doesn't change with time, hence t doesn't matter
Given those functions, yes
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Hello. I have a question about Partial Fraction Decomposion
I dont understand what you mean
if we put x = 2
then Q(x) = 0
so we divide with 0
What is Q(x)
(x-2)(x-3)
Ok what is P(x)
x+4
I didn't get that for me when you have your expression multiply both side by your denominator and evaluate on the roots
And you get your A and B
i dont understand
You will have like x+4 = A(x-3) + B(x-2)
And you evaluate on Roots which are 3 and 2 to get A and B
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Anyone know how to prove this
Tried induction for a while did not reach far
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can u help me if its okay? i had to check the uniform convergence
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How do i interpret and solve this?
try drawing a table
follow the same theme for the other 2 equations
u should have an equation for lead and an equation for manganese
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The part that's been bothering me for this question is the text in the 2nd picture
B is a random variable for the mass of each biscuit
P1 is a random variable for the mass of each packet containing 25 biscuits
P2 is a random variable for the mass of each packet containing 26 biscuits
X is a random variable for the mass of each box filled with packets containing 25 biscuits
The problem I'm dealing with is interpreting the text in the 2nd pic
I thought it was P(P1>P2) but when I calculated it out it was not the right answer
The answer is actually 0.0385
How do you interpret this text as is to get the probability?
@hasty wasp Has your question been resolved?
<@&286206848099549185>
<@&286206848099549185>
@hasty wasp Has your question been resolved?
<@&286206848099549185>
<@&286206848099549185> this is urgent btw I don't wanna wait on this forever
Divide the variance by 25
Max
Why
If you do a hypothesis test:
Suppose in one test you sample 100 items.
And in another you sample just 25 items.
Clearly the bigger sample is more significant, but without changing the variance you would get the same probabilities out for equal sample means.
Decreasing the variance by a factor of n just accounts for that.
This is about probability ditributions not sampling and estimations
If my knowledge in that is void (which it is) how would I've known it in the first place when confronting the question
<@&286206848099549185>
<@&286206848099549185>
<@&286206848099549185> urgent but is there another way to do this question in its own concept
No idea
Bruh
are you sure?
it seems to be a sampling proportions question
I mean
All of these are involving random variables and probability distributions
Even the previous chapters were about probabilities
The next chapter is sampling and estimation
How would I know a thing that is without no preview of the next chapter?
@indigo talon
alr ill talk a look at the problem
its been a bit since ive done normal distributions and stuff so give me sum time
Kewl
so we have to find the distribution of the total mass of biscuits
what do u think the mean of this new distribution is gonna be
@hasty wasp
Reference
are we solving this question here?
Question in the 2nd pic
I'm only posting pics of the questions as a whole just fyi
The ones I've written saying "Confused by subquestion/part of question" is what I struggled finding with
I mean if someone took time to look around sure they'd catch on
<@&286206848099549185>
<@&286206848099549185>
<@&286206848099549185>
<@&286206848099549185>
<@&286206848099549185>
<@&286206848099549185> just one question PLEASE
Thank me that I havent gotten unhinged today
you’ve phoned helpers like 34 times bro
Maybe if someone were to actually solve my question then sure I wouldnt get cranky
everyone in america was sleeping
is this the question u need to answer?
for the first question (the 598g to 606g)
Since the sample is random the masses of the 25 biscuits will be independent of each other
the distribution of the total mass willl be normal
2nd pic
2nd pic
ah
Some say it is a sampling question
is that the second question of 26? the "ten packets of biscuits are placed in a box" one?
ahh ok
This
so
If X is the mass of the biscuit in packet containing 25 buiscuits then we already know that X is
N(600,90.25)
ye i think a lot of the basic work has already been done correctly in the third screenshot here
I'd call it P1 but yeah
If we say Y is the mass of buiscut in a packet containing 26 buiscuits then Y is normally distributed with mean 26 x24=624g and variance 26 x 1.9^2=93.86
i haven't looked up the values but i'm wondering why the result is so high
man im helping u and that is enough so pls
the difference Y-X is normally distributed with mean = equalling 624-600
or 24 g
variance is 184.11
and standard dev is 13.57
0.2236 is the answer that you came up with, right? just intuitively that sounds crazy high, so maybe something went wrong with selecting that Z-value 0.760
thus z=(0-24)/(13.57)=-1.769
hence the probability is 1-0.9615
aka 0.0385
i think that is the best any1 can help u here
people arent always jumping to help u so be patient
this may not always be the quickest most efficient method of answer finding
or even help finding at that
ye just a thought, i was scared of even starting this question b/c there were like 200 messages after the original question
FR!
it can help to restate what the actual question is at that point, b/c it looks like maybe there's already been some progress
tho i guess in this case there wasn't necessarily
i open discord and instantly get compounded with 200+ messages
anyways i gtg i have school 😭, just a few days till middle school is over 4 me
omg thank you so much
Not used to waiting 4 hours for a question I want to be answered before I sleep and have to reopen
np! i got you
I guess I'll evolve to being patient so yeah
that would help...
Sorry for the pings too
np for me.. cant say the same for every1 else
True
well if that answers ur questions ill be on my way
It does