help-33

[rare pollen]

/ 72?

[storm fern]

yes

[rare pollen]

72,755,45.06 ?

[storm fern]

approximately that would be the right amount

does the question demand you to find it in integer?

[rare pollen]

dollar amount

rounded 2 decimal places

[storm fern]

isn't it 75k something?

[rare pollen]

75 545.0359

what my raw calculation go

t

[storm fern]

yes

[rare pollen]

how tf did i say 72

[storm fern]

so the rounded 2 decimals would be 04

[rare pollen]

75,545,04

yeah

[storm fern]

you got it

[rare pollen]

sadly it was not correct

wtf

wait

i mistyped

[storm fern]

it's actually quite related to geometric sequences

[rare pollen]

yeah still incorrect

[rare pollen]

this is a finance problem

i do not know about geometric sequences

haha

[storm fern]

ahh

[rare pollen]

but yeah it said the answer is incorrect

75,545.04

is what i put in

[storm fern]

try putting in 03

[rare pollen]

nope

hmm

im not sure if this answer would make sense looking at it normally

how can a payment for a car be over the cars original amount?

or is it 7,000 instead of 75,000

[storm fern]

AHHH

I FORGOT

IT'S (1+0,0605)

[rare pollen]

ahhh

[storm fern]

it's 6.05% right

so it's 6.05/100

[rare pollen]

correct

so

44,300 (1 + 0.0605) ^ 6

[storm fern]

yes!

[rare pollen]

/72

875.256343

[rare pollen]

875.26

[storm fern]

correct

sorry for the slight mistake

[rare pollen]

still wrong.

wtf.

[rare pollen]

np i missed it aswell

did i not round correctly

[storm fern]

eh??

you did

try 25

[rare pollen]

still incorrect

hm

it is 6.05

[storm fern]

uhuh

[rare pollen]

hm

now im even more confused

that seemedl ike it shouldve worked

/12 maybe?

for monthly

instead of 72

nah that wasnt right either

[storm fern]

nahh

the only clue are the apr and the 72 months annuity

to put it in, $\frac {44,300 * (1+0.0605)^6}{72}$

[rare pollen]

hm

[elfin berry]

sho

[rare pollen]

yeah this is what we did

figured it out

728.59

@storm fern

did it a different way

thanks for your help

.close

[marsh citrus]

Channel closed

Closed by @rare pollen

Use .reopen if this was a mistake.

[storm fern]

ah ok

sorry if i couldn't help you fully

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ember flame]

um

im confused

why is ans5 wrong

it's asking for inv of matrix B right?

why do i need a 3x1 matrix?

[marsh citrus]

@ember flame Has your question been resolved?

[slim spire]

it's asking you to solve for x in Bx=y, where your answer will include a B^-1

[ember flame]

Ohh

I see lol

👍👍👍

[marsh citrus]

@ember flame Has your question been resolved?

Channel closed

Closed by @ember flame

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sharp aurora]

Could someone please help me with question 9? I'm stuck.

[marsh citrus]

@sharp aurora Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fierce field]

But the four vertex theroem states that the curvature of an ellipse should be 0 at 4 points

here its only 0 at 3 points

yeah it repeats but i restricted t to be 0<t<2pi cuz thats how the ellipse is drawn

so just kinda curious as to why. and if my understanding of the four vertex theroem is correct

hang on

"two local maxima of curvature, and two local minima of curvature"

so i do have 4 points

nevermind

.close

[marsh citrus]

Channel closed

Closed by @fierce field

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[acoustic acorn]

HOW TF DO I GRAPH this thingy

[acoustic acorn]

im trying to calculate it but its

such a mess

for u(x,1)

its nice they give formula for integral of exp(-x^2)dx but The I(y) is exp(-y^2) and i can't pull it out cuz of the exp from before OR CAN I

nvm i cant

PLZ Hep

plz hep <@&286206848099549185> i just want to know how to start

sure i can set k=1, t=1

but then integral is ??? to compute

[marsh citrus]

@acoustic acorn Has your question been resolved?

Channel closed

Closed by @acoustic acorn

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[winter tinsel]

I was sick during this unit and im tryna catch up on the work
I gotta know what the steps are to get those 2 answers

[crystal lintel]

eh... <@&268886789983436800>

[winter tinsel]

is my username a problem

mb

[tawdry nymph]

huh

[winter tinsel]

I cant set a nickname in here

[tawdry nymph]

uhh

u can request something

and ill do it

[winter tinsel]

Can you change it to just Gaylord?

[tawdry nymph]

okay

[winter tinsel]

thanks

[crystal lintel]

i think i also misinterpreted it being something more offensive than it was

[winter tinsel]

ive been trying to solve it for quite a while and what I have for the equation is this

is this correct?

if it is how do I get x from this

[latent coral]

yeah that's correct, tanx = 13/16, are you allowed a calculator on this?

[quaint elm]

,tex .sohcahtoa

[elfin berry]

hayley!

[winter tinsel]

yeah

[latent coral]

well okay let me rephrase, arctan(x) != 13/16, but x = arctan(13/16)

[winter tinsel]

can you simplify that a bit
i dont know what arctan means

or what != means

sorry

[latent coral]

okay sorry, arctan is the same thing as tan^-1 or inverse tangent, some people call it arctan cause it's better to type out

[winter tinsel]

ah

thanks

[latent coral]

!= isn't really official symbols (unless you're a programmer) but it's basically not equals

so i was trying to say that based on your triangle, tan(x) = 13/16

look at the soh cah toa diagram above if you don't understand why that's true

so then to isolate for x, you'd apply the inverse operation of tangent to both sides, since arctan(tan(x)) = x

they're inverses so they undo each other

[winter tinsel]

so this is right?

[latent coral]

so aplying arctan to both sides of tan(x) = 13/16 gives x = arctan(13/16)

[latent coral]

yes

[winter tinsel]

thank you

[latent coral]

no problem

[winter tinsel]

so this

and it gives me this?

[latent coral]

correct

[winter tinsel]

thank you so much

[latent coral]

and whatever your calculator gives you for that should be the right answer

depending on what your teacher says, x could be in degrees or radians so that would affect the answer you'd want from your calculator

[winter tinsel]

alright

thank you

how do I close the help thing

[quaint hill]

.close

[marsh citrus]

Channel closed

Closed by @quaint hill

Use .reopen if this was a mistake.

[winter tinsel]

thanks

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sharp mauve]

How am I supposed to proceed further

.rotate

.close

[marsh citrus]

Channel closed

Closed by @sharp mauve

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fallow furnace]

Let $W=\left\langle(1,1,1,2)^T,(1,1,0,-1)^T,(3,1,1,1)^T\right\rangle$ be a subspace of $\mathbb{R}^4$ with the standard scalar product. Express the vector $v=(1,1,-2,0)^T$ as the sum $v=w+u$, where $w$ belongs to $W$ and $u$ belongs to its orthogonal complement $W^{\perp}$.

[elfin berry]

Slowaq

[fallow furnace]

what am i doing wrong?

where <w_1,u> is standart scalar multiplication

[slim spire]

what went wrong? the only thing that might be the issue is the scaling coefficients you put in front of the vectors

[marsh citrus]

@fallow furnace Has your question been resolved?

[fallow furnace]

those two vectors w and u are not perpendiculat as they should

<@&286206848099549185>

[slim spire]

oh it seems like w1 and w3 aren't orthogonal so the formula doesn't work yet, you need to gram-schmidt or something to the subspace vectors first to make it orthonormal

[fallow furnace]

yes it works now thx

[marsh citrus]

@fallow furnace Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sharp mauve]

how did they do a and c?

[sharp mauve]

with b i get (-1)^n (3)^2n / (2n+1)!

with c i got this:

[upbeat sable]

What's the expansion for ln(1+x)?

[sharp mauve]

i know its supossed to be in that form

but idk how to derive it algebraic

ly

@upbeat sable

[upbeat sable]

What does that mean?

[sharp mauve]

this is the answer

[upbeat sable]

Oh you don't know how to derive the expansion for ln(1+x)?

[sharp mauve]

but idk how they get x = 1/3

[sharp mauve]

no idk how they got to the part in orange

[upbeat sable]

What is the expansion for ln(1+x)

Write it in sigma notation

[sharp mauve]

(-1)^n+1 * x^n)/(n)

@upbeat sable

[upbeat sable]

Right

[sharp mauve]

im on a time limit tho

could you explain what steps they took rq

[upbeat sable]

Are you in a test rn?

[sharp mauve]

no i got a test tommorow

see

its just lecture slide

[elfin berry]

smidgin

[sharp mauve]

...

[upbeat sable]

Right

Put x=1/3

[sharp mauve]

there isnt a x

[upbeat sable]

And you get that same thing

...

There won't be after you put x=1/3

[sharp mauve]

did they multiply the equation with 1/3^n?

[upbeat sable]

No

[elfin berry]

smidgin

[sharp mauve]

im lost man

[upbeat sable]

I don't understand why

I have basically given you the solution

[sharp mauve]

I got it in this form

[elfin berry]

smidgin

[sharp mauve]

How could i know x would be 1/3 tho

Oooh

Ahhhh

I get it now

[elfin berry]

smidgin

[sharp mauve]

you just compare the sigma notations with each other

right

[upbeat sable]

Yes

[sharp mauve]

and solve algebraric

thx alot man

https://tenor.com/view/you-didnt-have-to-cut-me-off-meme-you-didnt-have-to-cut-me-off-big-brain-big-brain-meme-gif-26965490

.close

[marsh citrus]

Channel closed

Closed by @sharp mauve

Use .reopen if this was a mistake.

[sharp mauve]

.reopen

[marsh citrus]

✅

[sharp mauve]

@upbeat sable

so how did they do c

i get the (-1)^n in the denumartor

@upbeat sable pls

[upbeat sable]

Write down the series for ln(1-x) and ln(1+x)

[sharp mauve]

is (-1)^n * s (-1)^n equal just 1?

they maybe i got it

then *

i want to cancel out the (-1)^n it seems in the denumarotr

i got 2^n in the form of sqrt2)^2n

then doing the antiderivatve

just the (-1)^n in the denum throws me off

[elfin berry]

smidgin

[sharp mauve]

no

arent you supossed to do the sigma of the arctan(x)??

[upbeat sable]

Oh yes use that

You will get your value for x

[elfin berry]

smidgin

[upbeat sable]

Now compare the sums

[marsh citrus]

@sharp mauve Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tall sun]

math says yes,, internet to check says nothing

thoughts?

[paper relic]

0.03407811

[marsh citrus]

@tall sun Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vale ruin]

Why is sin2theta = positive and negative 1/2, instead of just positive 1/2?

[vale ruin]

Im supposed to be finding the points of intersection

[worn plank]

to be honest idk

[marsh citrus]

@vale ruin Has your question been resolved?

[marsh citrus]

@vale ruin Has your question been resolved?

[marsh citrus]

@vale ruin Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lapis knoll]

Anyone can find the idea how to solve this? Been stuck

[marsh citrus]

@lapis knoll Has your question been resolved?

[lapis knoll]

<@&286206848099549185>

[cunning fiber]

Use the formula $$1+2+3+\cdots+n=\frac{n(n+1)}{2}$$

[elfin berry]

Civil Service Pigeon

[cunning fiber]

then telescope w/ partial fractions

[lapis knoll]

I use that formula

But I can't telescope it

Wait, when to use partisl fractions?

[cunning fiber]

$\frac{1}{n(n+1)}=\frac{1}{n}-\frac{1}{n+1}$

[elfin berry]

Civil Service Pigeon

[cunning fiber]

https://brilliant.org/wiki/partial-fractions/

[lapis knoll]

Ooo I see, thanks man!

.close

[marsh citrus]

Channel closed

Closed by @lapis knoll

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[digital zodiac]

Can anyone tell me what am I supposed to do here?
O

[digital zodiac]

I'm guessing I have to use the Gaussian-Jordan matrix to solve this but yeah I really don't have an idea how to start (Subject is Linear Algebra)

[marsh citrus]

@digital zodiac Has your question been resolved?

[marsh citrus]

@digital zodiac Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jagged bay]

I was tasked with proving that for three non-negative real numbers x, y and z, the following is true:
xy/z + xz/y + yz/x >= x+y+z.
I want to know if my proof, which follows, is correct. And if there's something I should improve.

xy/z + xz/y + yz/x >= x+y+z
<-> (xy)^2 + (xz)^2 + (yz)^2 >= xyz(x+y+z)
<-> (xy)^2 + (xz)^2 + (yz)^2 >= (x^2)yz + (y^2)xz + (z^2)xy
Let a=xy, b=xz and c=yz.
a^2 + b^2 + c^2 >= ab + ac + bc
(should I make it more clear why the above is true, specifically for the right side??)
<-> a^2 - ab + b^2 - bc + c^2 - ac >= 0
<-> ((a-b)^2 + (b-c)^2 + (a-c)^2)/2 >= 0
(should I make it more clear why the above is true??)
<-> (a-b)^2 + (b-c)^2 + (a-c)^2 >= 0

[zenith knoll]

yeh i think you should mention when you multiplied both sides by 2

but its true 👍

[jagged bay]

((a-b)^2 + (b-c)^2 + (a-c)^2)/2 >= 0
<-> (a-b)^2 + (b-c)^2 + (a-c)^2 >= 0

is imo very easy to understand

but

a^2 - ab + b^2 - bc + c^2 - ac >= 0
<-> ((a-b)^2 + (b-c)^2 + (a-c)^2)/2 >= 0

is a lot less obvious

should I explain more for the latter?

[zenith knoll]

mhm not really

if its a teacher who is reading this

it doesnt really matter

she/he should understand

[jagged bay]

the presentation is being graded

like how well it's written

So it should be easy to understand

[marsh citrus]

@jagged bay Has your question been resolved?

[marsh citrus]

@jagged bay Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[limpid bison]

I forgot how to do B

Like i got ebverything

except the angle ABD

halppp

[lone hare]

angle sum of triangle is 180 degrees, does that help?

[marsh citrus]

@limpid bison Has your question been resolved?

[limpid bison]

Ok i mean idk any angles in the ABC triangle

all i know is that it is icosseles

But i rly need the angle ABD

[lone hare]

you found ACB right

then you can get DCB, and since the triangle DCB is isosceles you can get ABD

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[limpid bison]

wait is AD a straight line?

idk how im meant to get ACB

also can you ping me if u dont mind xd

if u respond

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lone hare]

oh yikes can’t believe I just made that assumption

[limpid bison]

hahahaha

its fine i thought it too

[lone hare]

what is the bot doing

[limpid bison]

idk bro

[lone hare]

I think you’re supposed to make that assumption because nothing else works

[marsh citrus]

@lone hare Has your question been resolved?

Channel closed

Closed by @lone hare

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[midnight estuary]

Is it possible to solve this without multivariate optimization?

[proud ice]

f is increasing radially, so the maximum value must be at the boundary somewhere

[midnight estuary]

hmm maybe the intersection point?

[proud ice]

Not a guarantee

Maybe, but not certain

[midnight estuary]

Because that's farthest from centre

[proud ice]

the parabolic curve is what makes it uncertain

But with straight lines, yeah you can do just the intersection points

[midnight estuary]

Alright

[marsh citrus]

@midnight estuary Has your question been resolved?

[marsh citrus]

@midnight estuary Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[high bison]

Please someone help

I got 76

360-256

180-104

[rigid veldt]

ure correct

[high bison]

The website tells me im wrong

[rigid veldt]

wait which website

[high bison]

ive just realised i had to put the 0 before it

[high bison]

sparx

[rigid veldt]

oh damn

is it right now

[high bison]

ye lol

.close

[marsh citrus]

Channel closed

Closed by @high bison

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[broken flare]

Hello! How are you? Could someone help me with this fraction multiplication? The answer should be 37/5 = 7.4, but instead, I get 74.

[left wadi]

where this 10 came from?

you hade 43/30 before and now you wrote 43/10/30 from nowhere

ok i see

its 4,3/30

i dont see the problem

maybe your initial formula is wrong?

for h

in calculator its also 74

[broken flare]

Yeah, right?

There is the formula

[left wadi]

its 74 then

[broken flare]

Okay, thank you for the help! I suppose the note might be wrong.

.close

[marsh citrus]

Channel closed

Closed by @broken flare

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vivid pier]

guys can you help me what is this

[verbal ibex]

fractions?

[vivid pier]

yea

[verbal ibex]

yea that’s what it is

[vivid pier]

yea but i dont understand where the answer got like the big numbers

[verbal ibex]

as in the 8/3?

[vivid pier]

might be

[verbal ibex]

wym might be it’s a yes or no

[vivid pier]

like the 2 and 1 what is that for

[verbal ibex]

they’re whole numbers

You add them to the fraction by multiplying the denominator (bottom number) by the whole number then adding it to the numerator (top number)

Eg if you have 1 and 2/5 you’d do 5x1+2 to get 7/5

[vivid pier]

yea

[verbal ibex]

yea

so all good now?

[vivid pier]

alr thanks

[vivid pier]

yup

[marsh citrus]

@vivid pier Has your question been resolved?

Channel closed

Closed by @vivid pier

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fossil adder]

For some reason that answer is wrong? is my input syntax invalid?

[runic temple]

s(0)

[fossil adder]

why?

[runic temple]

they gove you a value for s(0)

[fossil adder]

so sub and find C ?

[runic temple]

yes

[fossil adder]

ah ok

[nova tree]

that’s so weird why anti derivative why not integral

[fossil adder]

anti deriviate of velocity gives displacement

oh wait

you mean the wording

[nova tree]

mhm

[fossil adder]

idk thats how they teach it at unsw

weird

[nova tree]

weirdddd

[fossil adder]

thank you btw!!

.clsoe

.close

[marsh citrus]

Channel closed

Closed by @fossil adder

Use .reopen if this was a mistake.

[nova tree]

It’s like instead of saying plus saying anti minus lol

[fossil adder]

haha

true

its ok tho

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slim mist]

can anyone help me in my stats homework? kinda confused with the question

[slim mist]

Express the probability distribution of the random variable of the sum of the outcomes on rolling two dices.The sample space of the discrete random variable for the sum of the outcomes on rolling two dice is 6. (just incase my handwriting can’t be read)

[opal parcel]

i am not gonna make the table but i can tell you what to do

basically you just have to calculate the probability of each sum possible

like firstly, the sum is 2

this only happens when the first dice rolls 1 and the second dice rolls so individually its 1/6 and 1/6

and together it is 1/36

[slim mist]

wait, I made a table. can you check if its right?

[opal parcel]

sure

[slim mist]

am i horribly far from the right answer

[opal parcel]

yes

this is not what the problem is asking you to do at all

the table will look something like this :

[slim mist]

damn

[opal parcel]

$\text{Let X represent the sum while P represents probability} \newline X = 2 \newline P = \frac{1}{36}$

[elfin berry]

Barbie

[opal parcel]

and the table will move in this order

[slim mist]

so theres 36 outcomes right? since theres 2 dices

[opal parcel]

no

the possible outcome is 1 in 36

[slim mist]

ohh

[opal parcel]

what grade are you in?

[slim mist]

11th

[opal parcel]

i see

[opal parcel]

try understanding this and then construct the table

[slim mist]

ill try

okay im having a slightly hard time

[opal parcel]

think about it

it's easy

[slim mist]

do i make two tables?

[marsh citrus]

@slim mist Has your question been resolved?

[marsh citrus]

@slim mist Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[marsh citrus]

@fringe flame Has your question been resolved?

[fringe flame]

<@&286206848099549185>

.close

[marsh citrus]

Channel closed

Closed by @fringe flame

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[manic basin]

Book says solution is 1/3, am i not seeing something or did they accidentally use the limit of x approaches 0 instead of infinity?

[manic basin]

Because sinx/x; x->inf goes to zero, but it just seems highly likel they used the wrong limit

Idk tho

[normal warren]

nope, they used the right limit
you can solve this limit by either using l'hospitals rule or by using taylor series

[manic basin]

No, theres a method without these

[normal warren]

ah sorry then I can only think of those 2

[manic basin]

Even here sinx/x as x goes to inf it says its 1

[worn plank]

maybe there's a way using this limit honestly IDK

[manic basin]

Oh wait im stupid

[manic basin]

1/3x as x-> inf goes to 0

So its just lim x->0 sinx/x

[worn plank]

ok im helping you

[manic basin]

Yeah thx

.close

[marsh citrus]

Channel closed

Closed by @manic basin

Use .reopen if this was a mistake.

[worn plank]

you still have that 1/3 there

you can again use subtitution or the other limit

sin(ax)/x

whatever you want

[manic basin]

.close

.close

.reopen

[marsh citrus]

✅

[manic basin]

.close

[marsh citrus]

Channel closed

Closed by @manic basin

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mystic basin]

I need help with proof by induction (screenshots following)

[mystic basin]

This is the homework i have to do with some hints

As of right now i have proven the base case for both formulas and started with the inductive step but tbh i dont really know how to continue here

[marsh citrus]

@mystic basin Has your question been resolved?

[marsh citrus]

@mystic basin Has your question been resolved?

[marsh citrus]

@mystic basin Has your question been resolved?

[mystic basin]

ive started over again and got this for the inductive step right now but i dont know how to continue

(ive proven the base case already)

can any <@&286206848099549185> help? :)

[marsh citrus]

@mystic basin Has your question been resolved?

[marsh citrus]

@mystic basin Has your question been resolved?

[marsh citrus]

@mystic basin Has your question been resolved?

Channel closed

Closed by @mystic basin

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[past shard]

Does anyone mind explaining how the two equations after (2x)(2y) are equivalent to each other?

[elder glacier]

y was probably equal to sqrt(1-x^2/4)

[past shard]

Yes. That is correct.

How did you figure they are equal to each other?

[elder glacier]

because thats the only substitution that would give you the equation, or are you asking about something else?

[past shard]

No. I am asking about the same equation; I just can't figure out how 4x(√1 - x^2/4) equals 2x(√4 - x^2)

@elder glacier

[elder glacier]

take 1/4 as a common factor

which is gonna be half outside the root

[past shard]

1/4? Doesn't 1/4 × 4x = x? (The problem simplifies to 2x. . .etc.)

[elder glacier]

inside the root

hold on]

ill show you what i mean

is that what you were havin trouble with?

[marsh citrus]

@past shard Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[swift lion]

I have a trigonometry question. I have the answer of 14.36, although my exam is asking to write the sum of how I got that answer. They have given the formula of 1.08/14x3240/2 but nothing else..

[still temple]

is this an exam?

[swift lion]

i have finished the exam

but this question is a bonus one for us to try

and i can’t figure it out

[pseudo jackal]

I don't understand what the question is

[dim schooner]

,rotate

[swift lion]

Question number 1.35

[dim schooner]

sorry i forgot how to calculate sounds, like all of it

i just wanted to help everyone by using the bot to turn the picture

[marsh citrus]

@swift lion Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ruby axle]

Hi there

[marsh citrus]

Please don't occupy multiple help channels.

[vagrant gull]

bro use one channel

[marsh citrus]

@ruby axle Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mossy widget]

surely y can be anything no???

not just 0

this is the question we r doing f(z)

.close

[marsh citrus]

Channel closed

Closed by @mossy widget

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

1. isn't 5! 125

oh wait

so you can actually effectively simplify it to G1, G2, G3, G4, G5 and B1, B2, B3, B4, B5, right?

however G1 can't sit in B1...

so G1 must sit in B2, B3, B4, or B5, so that's 4, then, if she sits in B2, G2 has 4 choices, but if she sits anywhere else, G2 has 3 choices

so your current number of choices is 4+3*3 = 13 for the first 2 girls

now repeat this for the next 3

yeah

but we're simplifying the problem and renaming the girls and chairs

G3 -> G1, G4 -> G2... and B1 -> B1, B4 -> B2...

[marsh citrus]

@still temple Has your question been resolved?

[still temple]

<@&286206848099549185>

[lethal eagle]

B1,B4,B5,B6,B7 are left for G3,G4,G5,G6,G7 so if G3 sits in B1 there is a perfect case for derangement so 9 possibilities , next for any other girl sitting on B1 , we get a number telling different combos which is same for all those 4 girls..... so lets take G4 occupying B1 then if G3 takes B4 then by derangement we get 2 combos but if not then assuming G3 taking one of B5,B6,B7 then by counting we get 3 for each selection so final answer is: A=9+4(2+3(3))=53

[marsh citrus]

Channel closed

Closed by @candid basin

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[halcyon current]

can I get help for part c?

[marsh citrus]

Please don't occupy multiple help channels.

[sinful thistle]

please close one of your channels

@halcyon current

[halcyon current]

how do I/

?

[sinful thistle]

.close

[marsh citrus]

Channel closed

Closed by @sinful thistle

Use .reopen if this was a mistake.

[sinful thistle]

there

:D

[halcyon current]

thx

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[velvet elk]

A group of 6 boys and 3 girls wants to take a photograph. Find the number of
ways that the group members can be arranged in a row if the three girls sit next
to each other?
A. 3P3 x 7P7 C. 3P3 x 6P6
B. 3P3 x 7P7 x 2P2 D. 3P3 x 6P6 x 2P2

Not really sure but D?

[marsh citrus]

@velvet elk Has your question been resolved?

[sleek lake]

it's c

no okay

d

no

a

d would work if the boys had to stay together too

then you have 2 ways to arrange the groups, boys first or girls first

but there's 7 ways: 0 boys before girls, 1 boy, 2... 6 boys

so 3p3 × 7 × 6p6 = 3p3 × 7p7

[velvet elk]

I already changed my mind with a earlier but thanks for confirming it

Cuz I was doubting too xd

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stray nest]

How to proceed?

[knotty frost]

Hold on one moment. Let me contact my sir. @stark trail help us please.

[stark trail]

what is the trig function in the denominator? Sine?

I suggest you cancel the common factor of x^3 from the numerator and denominator

then recall that trig functions such as sine and cosine are bounded between -1 and 1

[stray nest]

yep

[knotty frost]

Hint: $\lim_{x\to 0} \frac{x}{\sin(x)} = 1$

[elfin berry]

Ultimate Chad

[stark trail]

x do be limiting to infinity doe

[knotty frost]

Yeah it was harder then I thought

You get 3/infinity * 0

[stark trail]

there's a substitution that trivializes it

I will let my sir @knotty frost figure it out though

[knotty frost]

My thought was to cancel the x^3 then multiply by something to get 1/x/sin(1/x) and use that limit

[stray nest]

But there's nothing much to do with this because X goes to infinity, isn't it?

[teal arch]

can we do lim (1/x) tends to 0 if lim x tends to infinity? (just curious, i dont know it myself)

[knotty frost]

But 1/x goes to 0

[knotty frost]

Yes exactly

This is what I’m using

[stray nest]

0*infinity is undefined

[teal arch]

not sure 👾 i will let more experienced ppl handle this

[stray nest]

A hint?

[knotty frost]

His hint was u = 1/x

[marsh citrus]

@stray nest Has your question been resolved?

[knotty frost]

?

[stray nest]

I'm still trying to solve it using u=1/x

[knotty frost]

Where r u getting stuck?

[stray nest]

everywhere right after I cancel x^3

[knotty frost]

@stark trail my friend here needs help

[stray nest]

I'm pretty sure it's wrong, ahsdhasdhas

But that's where I've arrived

[knotty frost]

Yes that’s good

Now multiply top and bottom by u

[stray nest]

I tried putting the u^2 in evidence so I could get to the fundamental limit

But I ended up with 3/u/1

[knotty frost]

You picked up a u somewhere

Ended up with an extra

[stray nest]

Was it after I switched to u or when I factorise u^2?

[knotty frost]

When you went from the first line to the second

[stray nest]

Ah

Got it

Finally got it

thank you so much!

Really helpful! Hope you have a nice day/night/whatever over there!

:)

.close

[marsh citrus]

Channel closed

Closed by @stray nest

Use .reopen if this was a mistake.

[knotty frost]

👍u2

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vagrant gull]

is this test?

[marsh citrus]

@crude mango Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[copper lodge]

how can i find the angle of an n sided shape

[copper lodge]

i forgot the formula

a regular shape

okay its 180(n-2)/n

.close

[marsh citrus]

Channel closed

Closed by @copper lodge

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[surreal glade]

What is the definition of a system of generators of a vector subspace?

[marsh citrus]

@surreal glade Has your question been resolved?

[surreal glade]

<@&286206848099549185>

[marsh citrus]

@surreal glade Has your question been resolved?

Channel closed

Closed by @surreal glade

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

If 10^2x = 25, then 10^-x is equal to?

[marsh citrus]

Please don't occupy multiple help channels.

[dusk coral]

what have you tried?

[stoic slate]

Dont use multiple channels

You have another channel with the same question, stick to that one

[next raft]

let q=10^x

[still temple]

I'm gonna just give up 🙃

Anyways, have a good day guys

[marsh citrus]

@still temple Has your question been resolved?

[lilac siren]

but

I've shown you the steps before

(...)^1/2

then (...)^-1

and you get 10^-x = 1/sqrt(25)

[marsh citrus]

@still temple Has your question been resolved?

Channel closed

Closed by @granite karma

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[modern lake]

I need help

[modern lake]

<@&286206848099549185>

[pliant tangle]

AC and CB are equal so Angle ABC and angle CAB will be equal

[modern lake]

I need to rush to school in an hour can someone help me with these two questions?

[modern lake]

Then?

[pliant tangle]

AOB is twice of ACB

Because subtended by chord AB at centre and circumference, respectively

[pliant tangle]

Which means angle ABC (given that AOB is twice of it) and Angle ACB are equal

[modern lake]

So?

[pliant tangle]

Which makes all the angles in triangle ABC equal

Therefore Angle BAC is 60

[modern lake]

So what will be the BDC?

[pliant tangle]

Angle BDC + Angle BAC = 180 becuz cyclic quadri

[modern lake]

I'm getting late for school

Yeah question is asking me angle BDC

[pliant tangle]

It’s 180-60

[modern lake]

120 right?

So the answer is option A basically

[pliant tangle]

Yeah

[modern lake]

Can you solve this one also, please?

@pliant tangle hey, helper are u there?

[spark siren]

!nosols

[marsh citrus]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[spark siren]

you wont get solutions here.

[modern lake]

I'm getting late for school

Its just one question

He might help me

Okay someone please help me to reach conclusion

[spark siren]

youre cheating. that violates the rules of this server.

[modern lake]

.close

[marsh citrus]

Channel closed

Closed by @modern lake

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[open kayak]

Find all possible natural numbers with the following properties: \begin{enumerate} \item One of the digits is a 0 and all the other ones nonzero \item The last digit is 5 \item If we remove the zero-digit, then the number becomess 9 times smaller \end{enumerate}

[open kayak]

How do we approach this?

We had modulo before this, so maybe with that?

[marsh citrus]

@open kayak Has your question been resolved?

[open kayak]

.close

[marsh citrus]

Channel closed

Closed by @open kayak

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

Hello
I need someone to explain to me how to solve these problem as I have a slight confusion

[pliant tangle]

You have to find area of white region?

Or coloured

[still temple]

I have to find the area of the shaded region ( that’s the question )

So I’m assuming it’s the coloured ?

[pliant tangle]

Find the area of whole shape, and subtract the area of the white region from it

[still temple]

Just a question do we always subtract the small from the biggest or it can be the opposite ?

[pliant tangle]

Small from big

Can’t be done opposite

[still temple]

Alright it worked with me just one error in one of the questions

I did 240 minus 19.21 and it says wrong

Would you please tell me where I went wrong ?

[pliant tangle]

How did you get 19.21?

[next raft]

how did you get 240

[still temple]

I found hypotenuse

[still temple]

10 times 24

[next raft]

that is not relevant to the area

[pliant tangle]

That not the area tho

Find area of the big triangle

Or you could find the small triangle individually and add them

[still temple]

A = b x h x 0.5

Area equals to 15 times 12 times 0.5? Since we divide the 24 by 2?

[pliant tangle]

No need to divide it by 2

0.5 x base x height

For the blue triangle at top, base is 24 and height is 15

With same formula find the area of those two small triangle at the side

And then add all three

[still temple]

So it will be 25 plus 25 plus 180 equals to 230

240 minus 230?

[pliant tangle]

No need to minus

[still temple]

But I though we do this ^

[pliant tangle]

230 is the total area of blue region

[pliant tangle]

.

[pliant tangle]

That can be done, but you can also just find the areas of the individual blue regions

[still temple]

Wait so then what is the next step ?

since we got the 230

Mb it’s just that I’m slightly confused

[pliant tangle]

This is the final answer

[still temple]

It’s telling me it’s wrong answer

Maybe there is an error with the survey

This bring one last question

How did you know that you didn’t need to minus?

[pliant tangle]

Oh

Well try finding the area of the whole triangle itself, then subtract the area of rectangle from it

[still temple]

Alright man thank you a lot for you help really appreciate it
Have a good day ahead !

[pliant tangle]

Should be 185

Try that

[still temple]

YESSSIR IT WORKED

[marsh citrus]

@still temple Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[visual crag]

if you did that area would come lesser than zero, like a negative number which is not possible

[marsh citrus]

@visual crag Has your question been resolved?

Channel closed

Closed by @visual crag

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[inner nexus]

How do i prove this sss similarity theorem with statements and reasons?

[still temple]

a two-column proof i guess right?

well if u want a hint, XY and ST are parallel to each other

what can u say about the relation between angles RXY and RST?

[inner nexus]

They're parallel segments???

[still temple]

they are angles

we are not considering lines

[inner nexus]

Ohh

Sorry my math teacher literally rushed our lesson

Grasping them was pretty pressuring so i didn't really get to understand the lesson much

[still temple]

thats ok

[inner nexus]

What can i do to prove them

[still temple]

well there are some steps and im trying to guide u towards that

[still temple]

i need u to answer this at least

[inner nexus]

I kind of proven to draw a line xy then replace the seg st

[still temple]

i dont understand what u mean by that soz

[inner nexus]

We're gonna try using corollary 60.1 to prove them

[still temple]

i dont know what corollary 60.1 is

[inner nexus]

Argh

We prove them like this way

[still temple]

Yes i know you are expected to do two column proofs

[inner nexus]

Rhhh

[still temple]

for the third time, can you please try and answer this

the construction of your triangle tells you that XY and ST are parallel, so knowing that, what can you say about the relationship between angles RSY and RST?

Are they equal for example?

[inner nexus]

Rxy is smaller than Rst, made a mistake in my writing sorry

[still temple]

they are not meant to be

they are corresponding angles so they are in fact equal

[inner nexus]

I see

[inner nexus]

Apologies for the trouble there

[still temple]

its like 2 and 6 here

i think you call them transversals

well anyways

do you know AA theorem? @inner nexus

[inner nexus]

Sadly no

[still temple]

aight

sorry i dont know how to help you then. I would suggest studying some of those similarity theorems

SAS, SSS, AA, so on

you can use AA here at least

[inner nexus]

I see, thank you about that

[marsh citrus]

@inner nexus Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[surreal linden]

1 sec

if for example

AC and AB are tangents from point A to the circle

and AD is angle bisector.

can u say ED is a diameter?

as if two tangents from the same point are connected with a line from the center of the circle, the line is bisector to the angle between the two tangents.

and a diameter is a chord that passes through the center

[iron meadow]

yea it should be

[surreal linden]

can u say that " if a line connected to the point where two tangents to the circle meet, which bisects the angle between the tangents, the line comes from the center"?

[surreal linden]

yeah i thought so too

[iron meadow]

one easy argument you can make: you draw the 2 tangents, then connect the tangent points to the center of the circle (the tangent lines and radii of the circle make 90 degree anglex). now connect center of circle with the original point to the left. so you have 2 right triangles with two equal sides (1 is shared and the 2nd is both radii) so the triangles are congruent. so the angles at the left are congruent, so the line you drew from the center to the point bisects the angle

[marsh citrus]

@surreal linden Has your question been resolved?

Channel closed

Closed by @surreal linden

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[winter flicker]

how do i get started with this

[marsh citrus]

@winter flicker Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wispy robin]

Hey, im making an investigation and need help modeling the parabolas of the macdonald's logo to get the area of the "m" in the red square, could somebody help me make the equations that form the "m", I have tried to model it with a system of equations and desmos but the parabola doesn't match. Please help!!!!

[marsh citrus]

@wispy robin Has your question been resolved?

[wispy robin]

<@&286206848099549185>

[twilit arrow]

i am inclined to say that those aren't parabolas

[slim spire]

for real life archways the equation is cosh(x)

[twilit arrow]

you can approximate the shape with parabolas, but if you found a parabola that passes through 3 the other curve's points and it doesn't match, then the other curve is not a parabola

[marsh citrus]

@wispy robin Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[main bough]

one sec gonna post a solution

idk if its right or not

so is it concave down

[marsh citrus]

@main bough Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[earnest hound]

for 1b, what am i doing wrong?

[earnest hound]

the answer's
-11
4
12

[lone heart]

The second row is -3 1 0

Wait sorry I'm trying to find the mistake still

Right here actually, why did you flip all the signs on the right when you did R1 = -R1?

[marsh citrus]

@earnest hound Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sick dawn]

Someone pls help me with this

[void elm]

,rotate

[void elm]

,rotate

[void elm]

,rotate

[sick dawn]

Am i heading in thw right direction?

@void elm doyk?

[potent fog]

you're on the right track yeah

[sick dawn]

My exam’s in like an hour and im in a bus could u help me

With working

@potent fog

[potent fog]

sure

you figured out we want to use 2theta to find the area of the unshaded region in the quadrilateral

so what are the areas of those two unshaded regions of the circles

[sick dawn]

Ye 2pi-thera

Then thetar^2/2

X2

Then add it with the shaded area in the middle

But how to find the middel one

On either side

Area pf rhombus-the sectors?

[potent fog]

yup

[sick dawn]

I forgot area of rhombus form

[potent fog]

well

we dont need to find the area of the rhombus necessarily

we can see some triangles in the diagram you drew right?

[sick dawn]

Oh ye

We could do triangle

[potent fog]

right

[sick dawn]

I remember that thing i did

(Basexheight/2 - area of sector) x 4

Then add everything up

1:shaded

[potent fog]

mhm

[potent fog]

well not 1:shaded

[sick dawn]

This is gonna be the ratio?

[potent fog]

shaded:area of the large circle
right

[sick dawn]

But since the shaded part is inside the circle wouldnt we take it as 1

I mean prwcious time i did take it as pir^2

[potent fog]

[sick dawn]

But u feel like it should be 1

[potent fog]

is the area of the large circle pir^2?

how did you define r

[sick dawn]

oh sorry 2x squared

[potent fog]

right

[sick dawn]

Oh