#help-33

1 messages · Page 95 of 1

surreal glade
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if i calculate everything i get:

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$\frac{e^{\frac{1}{x}}}{(x+2)^2} \cdot -\frac{x-1}{x^3+2x^2} \cdot e^{\frac{1}{x}}$

elfin berryBOT
surreal glade
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but its so strange in this form

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and there is a way to get this result

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.

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but i dont know how

stoic topaz
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i still don't get it

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are you trying to show that these fractions are equal?

surreal glade
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I have to find a simple result, then make f'(x) > 0

stoic topaz
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you don't get why this works?

surreal glade
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like this is more easy

stoic topaz
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this is just simple fraction manipulation

surreal glade
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can you help me

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pls

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we have to start from here:$\frac{1}{(x+2)^2} \cdot e^{\frac{1}{x}} + \frac{x+1}{x+2} \cdot -\frac{1}{x^2} \cdot e^{\frac{1}{x}}$

elfin berryBOT
surreal glade
stoic topaz
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yeah but make the question clear, what's f(x)? what do you want with f'(x)?

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prove that f'(x)>0?

surreal glade
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I just want to try to simplify what I sent you as easily as possible

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then i will do f'(x) > 0 myself

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:$\frac{1}{(x+2)^2} \cdot e^{\frac{1}{x}} + \frac{x+1}{x+2} \cdot -\frac{1}{x^2} \cdot e^{\frac{1}{x}}$

elfin berryBOT
stoic topaz
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this is correct i think

surreal glade
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yes but i didnt did that

stoic topaz
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just factor e^(1/x)

surreal glade
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i know but how i can do that

surreal glade
stoic topaz
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ok $$e^{1/x}\left(\frac{1}{(x+2)^2}-\frac{x+1}{x^2(x+2)}\right)$$

elfin berryBOT
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moriaritie

stoic topaz
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then make the denominators same

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$$e^{1/x}\left(\frac{x^2}{x^2(x+2)^2}-\frac{(x+1)(x+2)}{x^2(x+2)^2}\right)$$

elfin berryBOT
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moriaritie

stoic topaz
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$$e^{1/x}\left(\frac{x^2-(x+1)(x+2)}{x^2(x+2)^2}\right)$$

elfin berryBOT
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moriaritie

stoic topaz
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$$e^{1/x}\frac{-3x-2}{x^2(x+2)^2}$$

elfin berryBOT
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moriaritie

stoic topaz
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that's what you wanted right?

surreal glade
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yes

stoic topaz
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tell me which step you didn't understand

surreal glade
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let me analyze

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a moment

surreal glade
surreal glade
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can you explain please

stoic topaz
surreal glade
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and why we do that?

stoic topaz
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we can write $\frac{1}{x}=\frac{y}{yx}$

elfin berryBOT
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moriaritie

stoic topaz
surreal glade
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but why you use x^2

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and not x

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for example

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understand

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thanksssss

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👍

stoic topaz
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im glad you got it

surreal glade
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👍

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we can close okay?

stoic topaz
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yeah sure

surreal glade
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.close

marsh citrusBOT
#
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marsh citrusBOT
#
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winged idol
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Is pi make able through e if you consider all the elementary operators i.e. division addition, adding other rationals?

devout mauve
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I am pretty sure we do not know

winged idol
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Oh ok that's pretty interesting

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What if you constrain it to e= a+b*pi

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Where a and b are rationals

devout mauve
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well thats an even harder question

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if you are allowed to do less

winged idol
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Isn't that a subset of the original question?

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Wait no I understand

proper zodiac
marsh citrusBOT
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@winged idol Has your question been resolved?

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static wyvern
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Let $d_b(x,y)=\min(1,|x-y|)$ be a metric on $\mathbb R$. Let $X$ be the set of countable sequences of real numbers and define a metric $\varsigma_b$ on $X$ by $$\varsigma_b((x_n),(y_n))=\sup{d_b(x_n,y_n):n\geq 0}.$$ Let $S\subseteq X$ be the subset of sequences such that $\lim x_n=0$. \textbf{Is $S$ open in $X$?}

elfin berryBOT
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Junojuno

proud ice
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Isn't a sequence countable by definition?

static wyvern
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Thats irrelevant

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Can you help

elfin ivy
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So if I’m reading this right, S is the set of sequences whose terms go to 0?

static wyvern
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Yes

proud ice
elfin ivy
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Do you remember the definition of open for subsets of a metric space

marsh citrusBOT
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@static wyvern Has your question been resolved?

marsh citrusBOT
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marsh citrusBOT
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twin nebula
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i have a questionabout a graph wuick

marsh citrusBOT
twin nebula
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if i have a decreasing velocity function that represents a car breaking

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what is the area under curve represent?

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didtsnce traveled while breaking?

trim quest
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yes, since position is the antiderivative of velocity, it represents the change in position over the given time

marsh citrusBOT
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@twin nebula Has your question been resolved?

twin nebula
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so is it the output of b-a

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of the original function

trim quest
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well it's the output of the antiderivative

twin nebula
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yes

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for what value

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i havent lerned fundamental thereom yet btw

trim quest
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where $F$ is an antiderivative of $f$: $\int_a^b f(x) dx = F(b) - F(a)$

elfin berryBOT
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tatpoj

trim quest
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oh, that pretty much is the fundamental theorem

twin nebula
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oh okay

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that makes sense

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so thats part 2 right

trim quest
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yeah

twin nebula
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can you show me an example with numbers of part 1

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not just the formula

trim quest
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Do you mean like an example of a problem where you might be asked to use it?

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Part 1 is like: If $F(x) = \int_a^x f(t) dt$, then $\frac{d}{dx}F(x) = f(x)$

elfin berryBOT
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tatpoj

trim quest
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notice the variable x is one of the bounds of the integral

twin nebula
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so we basivally put x instead of t?

trim quest
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yeah, t is just a 'dummy variable'

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there to make the integral work

twin nebula
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so that could be any variabel

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if i want to take an integral in terms of another variavle

trim quest
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yes, and a could be any constant

twin nebula
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ok

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im learnign this today actually

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so maybe ill uinderstand the use of it

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i had a test today so thats why i asked the question

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i wanna make sure i wrote the write thing even though it wont change anything lol

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thanks tho

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.solved

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solved

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/solved

trim quest
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np 👍

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it's .close, btw

twin nebula
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!solved

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/close

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.close

marsh citrusBOT
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twin nebula
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ok thanks

trim quest
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np 👍

twin nebula
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i would be here all day

marsh citrusBOT
#
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boreal rose
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I just need help finding a closed form expression to solve this q: "Let n be a positive integer. How many different candy bowls can you make if you must include
n pieces of candy, subject to the following conditions:
• The number of Skittles is a multiple of five.
• Any number of peanuts is possible.
• Any number of gummy bears is possible.
• There are at most two Snickers.
• There are at most four KitKat.
• There is at most one chocolate bar.
You answer should be a closed formula."

boreal rose
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I have the generating function btw

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$\frac{1}{1-x^5} * \frac{1}{1-x} * \frac{1}{1-x} * \frac{1-x^3}{1-x} * \frac{1-x^5}{1-x} * \frac{1-x^2}{1-x}$

elfin berryBOT
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nosqldb

boreal rose
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<@&286206848099549185>

sand fable
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i think just simplify this (and partial fractions) then you're good

boreal rose
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for x^n

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😦

sand fable
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ye

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once you get to the partial fractions part you'll see it

boreal rose
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I did partial fractions like in high school 💀

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you have to help me through this

sand fable
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sure

sand fable
sand fable
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nice

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yeah your gf looks right then

boreal rose
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yay

sand fable
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do you know how to factor like (1 - x^3) and (1 - x^2) ?

boreal rose
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or sm like that

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I forgot

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but 1-x^2 is ez

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(1-x)(1+x)

sand fable
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ye square diff

boreal rose
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,w calc (1-x)(1-x+x^2)

sand fable
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(1 - x^3) factors into (1 - x)(1 + x + x^2)

boreal rose
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ah I was pretty close fr

sand fable
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in general, (1 - x^n) factors into (1 - x)(1 + x + x^2 + ... + x^(n - 1))

boreal rose
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mhm

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yeah

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what do I with this info

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tho

sand fable
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there's a lot of things you can factor and/or cancel

boreal rose
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,w simplify \frac{1}{1-x^5} * \frac{1}{1-x} * \frac{1}{1-x} * \frac{1-x^3}{1-x} * \frac{1-x^5}{1-x} * \frac{1-x^2}{1-x}

boreal rose
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pls wolfram

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BOOM

sand fable
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oh nice

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and it gives you the partial fraction decomp

boreal rose
sand fable
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you can extract the coefficients

boreal rose
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I'm a lil lost lol

sand fable
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you can consider each term separately

boreal rose
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yes

boreal rose
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okay so we made progress

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boys

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$\frac{1}{1-x^5} * \frac{1}{1-x} * \frac{1}{1-x} * \frac{1-x^3}{1-x} * \frac{1-x^5}{1-x} * \frac{1-x^2}{1-x}$ = $-\frac{5}{x-1} - \frac{9}{(x-1)^2} - \frac{6}{(x-1)^3} - 1$

elfin berryBOT
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nosqldb

boreal rose
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but now what to do

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oh wait I'm so stupid @sand fable

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why not take derivatives

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.close

marsh citrusBOT
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sand fable
boreal rose
sand fable
#

good on figuring that out. that's pretty much how to continue from there

marsh citrusBOT
#
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boreal rose
#

,w what's the nth derivative of $-\frac{5}{x-1} - \frac{9}{(x-1)^2} - \frac{6}{(x-1)^3} - 1$

marsh citrusBOT
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@boreal rose Has your question been resolved?

marsh citrusBOT
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cursive fiber
#

Is my homework answer key erroneous or did I make several calculation mistakes? We're asked to determine general term of arithmetic sequences:
a. -14, -11, -8, -5, ... has answer key 3n-20 and I got 3n-17
b. 0, -3, -6, -9, ... has answer key -3n+6 and I got -3n+3
c. 4, 0, -4, -8, ... has answer key 12-4n and I got 8-4n

runic temple
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can you send a picture of your homework

cursive fiber
runic temple
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weird

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yeah thats definitely wrong

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kinda funny that one of them is right

cursive fiber
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yeah that was weird like all the other ones are off by 3

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teacher probably accidentally calculated tn=a+(n-2)d or smth

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thanks!

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.close

marsh citrusBOT
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marsh citrusBOT
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upbeat oar
marsh citrusBOT
upbeat oar
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why did they change the integral

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in the second one

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to 0 to pi/3

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and not to the first question? - where they kept the integral the same

marsh citrusBOT
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@upbeat oar Has your question been resolved?

marsh citrusBOT
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@upbeat oar Has your question been resolved?

marsh citrusBOT
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cobalt yacht
#

\begin{figure}[ht]
\centering
\begin{tikzpicture}[node distance={35mm}, thick, main/.style = {draw, circle}]
\node[main] (1) {1};
\node[main] (3) [right of=1] {3};
\node[main] (4) [below right of=3] {4};
\node[main] (2) [below left of=4] {2};
\node[main] (5) [left of=2] {5};

\draw (1) -- (3);
\draw (1) -- (5);
\draw (2) -- (3);
\draw (2) -- (4);
\draw (3) -- (4);
\draw (3) -- (5);
\end{tikzpicture}
\end{figure}
a) Suppose this is an electric circuit in which all edge conductances are unity.
i) By assigning columns/rows to nodes according to the numbering shown, find the graph Laplacian matrix (\mathbold K), the degree matrix (\mathbold D) and the adjacency (\mathbold W).

\textcolor{red}{\textit{\textbf{Solution}}} The degree matrix (\mathbold D) is given by a (5\times5) matrix where the (D_{ii}) entry is given by the number of nodes connecting the (i)-th node. Consequently, this is given by
$$
\mathbold D =
\begin{bmatrix}
2&0&0&0&0\
0&2&0&0&0\
0&0&4&0&0\
0&0&0&2&0\
0&0&0&0&2
\end{bmatrix}.
$$
The adjacency (\mathbold W) is given by a (5\times5) matrix where the (\mathbold D_{ij}) entry are (1) if there is an edge between node (i) and (j), and (0) otherwise. Thus, it is given by
$$
\mathbold W =
\begin{bmatrix}
0&0&1&0&1\
0&0&1&1&0\
1&1&0&1&1\
0&1&1&0&0\
1&0&1&0&0
\end{bmatrix}.
$$
The laplacian matrix (\mathbold K) is given by
$$
\mathbold K = \mathbold{D-W} =
\begin{bmatrix}
2&0&-1&0&-1\
0&2&-1&-1&0\
-1&-1&4&-1&-1\
0&-1&-1&2&0\
-1&0&-1&0&2
\end{bmatrix}.
$$

elfin berryBOT
#

Faq
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

cobalt yacht
#

First of all, is this correct?

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And how can I go about calculating the voltages in nodes 3-5 given that the voltage in node 1 is unit and node 2 is grounded?

hidden plaza
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Why did you use \(…\) but $$…$$

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Looks right. And just do KV=b to solve for the voltages. Are you familiar with that?

marsh citrusBOT
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@cobalt yacht Has your question been resolved?

marsh citrusBOT
#

@cobalt yacht Has your question been resolved?

marsh citrusBOT
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spice field
#

hi
i am coding a sort of google map with SDL and C but i run into a problem
i want to make a zoom function (on the cursor)
what i do for now is
scale the image.x + 100
scale the image.y + 100
deplace the image.x according to offset.x
deplace the image.y according to offset.y

mx = mouse position x relative to screen 
my = mouse position x relative to screen
W = constant Width (of the screen)
H = constant Height (of the screen)
Z = constant Zoom factor (100)
d = direction of zoom (1 or -1)

offset_x = mx / W * Z * d
offset_y = my / H * Z * d

is there a better way ?

proud ice
#

You want to learn matrix algebra

spice field
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i've watched some of 3blue1brown videos
do you have any other links ?

marsh citrusBOT
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marsh citrusBOT
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@spice field Has your question been resolved?

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marsh citrusBOT
wheat geyser
#

.close

marsh citrusBOT
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rough trellis
#

thyself need help with math problem

marsh citrusBOT
rough trellis
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Quadrilateral

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No idea what it is supposed to be

quaint elm
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can you answer the rest of the questions? this type of quadrilateral has two pairs of parallel sides.

rough trellis
dire spire
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would be a good idea to learn the basics of quadrilaterals

drowsy crag
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I just dont get why it seems like all of its angles are same. That would mean its a rectangle

rough trellis
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but heres an example

quaint elm
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ohhhh ok i understand what they want now

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ok so um. the capital letters are referring to the points where two sides meet (the corners)

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we call those vertices (plural of vertex)

rough trellis
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Oh

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i didnt knew that vertex has a plural

quaint elm
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yeah you'll sometimes hear people say vertexes and you get to be smug if you know the fancy word

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the lines in the middle of the shape (like the one going from P to N) are called diagonals because, well, they go diagonally

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when we want to talk about a shape as a whole we just list out the vertices in clockwise order, so in that second example the quadrilateral is named ABCD. For yours you can start anywhere, just make sure you go in order clockwise

rough trellis
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Is clockwise is going to right?

quaint elm
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yes

rough trellis
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oh i see then how about the second?

quaint elm
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well the vertices are just the capital letters themselves

rough trellis
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I mean 2) sides

quaint elm
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oh right

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well to name a side (or any line) we just say the endpoints

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so for instance, one of your sides is NM

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or you could say MN, those both refer to the same side

rough trellis
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Oh so its two letters connected to each other?

quaint elm
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yep!

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just like a quadrilateral was 4 letters connected to each other

rough trellis
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Oh i kinda get it now

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Does it always have to be clockwise?

quaint elm
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it doesn't, that's kind of just a standard to make it easier to tell when you're talking about the same one

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it does always have to be in order though, you can't jump around

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but if you went the other way around (anticlockwise) it would be fine

rough trellis
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oh

quaint elm
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the last thing is angles. To name an angle, use this funny symbol ∠ and then three points that define the angle, you need a start point, a vertex, and an end point. so for example this is ∠ONM

quaint elm
elfin berryBOT
#

hayley!

quaint elm
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it's like you're drawing the line that goes from N to M

rough trellis
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o why

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im also confused about that overline part

quaint elm
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to be honest i don't know exactly CH_TeaSip i guess just to remind your reader that N and M are vertices and you're talking about a line, you're not multiplying N by M

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some of this notation goes back to ancient greece

rough trellis
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Oh i guess that does make sense

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anywys opposite sides means Sides of the Opposites so i understand that but Consecutive Sides is the next im still wondering bout

quaint elm
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consecutive means they share a vertex so they're next to each other

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like NM and MP are consecutive sides

rough trellis
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i mean why does it start at A not B

quaint elm
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i think you could start anywhere if i understand your question right, your teacher tried to alphabetize it as much as possible i think

rough trellis
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Oh so i can start anywhere then?

quaint elm
#

yeah it's common to start in the top left though

rough trellis
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like CD & DA, CB & BA

quaint elm
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yep

#

this exercise seems like practice in writing the same 4 letters as many ways as possible Giggle

rough trellis
#

Oh i just understood on why the overlining now

#

its like a symbol like when looking for angles u put an angle

#

I think i understand it now tyvm

#

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quaint elm
#

there's a symbol for triangles as well (it's just a small triangle)

marsh citrusBOT
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surreal glade
#

ni

marsh citrusBOT
surreal glade
#

hi

marsh citrusBOT
surreal glade
#

i have a problem with graph

#

i will wait to send other pics

#

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manic peak
#

is gaussian elimination the quickest way of solving 3 variable system of equations?

void elm
#

do you mean for a human or for a computer?

manic peak
void elm
#

I think for most people, it will be the fastest method

#

for me personally though, I find substitution quicker for most nice systems

manic peak
elfin berryBOT
manic peak
#

$2x+y+6z=0 \$
$-y-2z=-4 \$
$(\alpha -10)z=\beta -16$

#

This is what I have from gaussian elimination

elfin berryBOT
serene basalt
#

You know when you get no solution ??

manic peak
#

i forgot

#

when there are no intersection points between the 3 equations

#

i dont have a graphic calculator tho

#

I got a=10 and B doesnt equal 16 for the no solution

#

idk if this is correct

serene basalt
#

You know matrix form of it

#

Like putting in a matrix

#

You get no solution if your last row is like [0 0 0 b]

manic peak
#

no

#

idk

#

canu show me in texit

serene basalt
#

See there is no solution if coff. Of you last equation is 0

#

And after equal part is non zero

manic peak
serene basalt
#

Ya this is right

#

Answer right

marsh citrusBOT
#

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stoic drum
#

i am making a weighted average calculator for my bio class, did i use the correct weight for each unit
what i did is i took 32% of each unit and put it in the row with the the blue label that matched the unit name. then i took 48% of each unit and put it in the row with the purple label that matched the unit name

then i took 20% of each unit (in total 16%) and added it to the final exam row with the red label. i added 20% to that 16%, because the final is worth 20%

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#

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limber star
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pearl granite
#

hi

marsh citrusBOT
pearl granite
marsh citrusBOT
pearl granite
#

Need help with this

#

So for this question to figure out the work do I need to calculate the force first?

static quarry
#

you could do it using potential energy, if you know about that

pearl granite
#

well this is calc 2

pearl granite
static quarry
#

ah ok

restive sun
#

can't you use work = force * distance (to avoid explictly using energy calculations)

#

and force is mass * gravity (I don't know what this is in imperial units)

marsh citrusBOT
#

@pearl granite Has your question been resolved?

pearl granite
#

that what I thought initally but wasnt sure

restive sun
#

times gravitational acceleration

#

1500 isn't force, it's mass

pearl granite
#

what gravitational acceleration?

restive sun
#

google the number, I don't know it for imperial

#

it's 9.81 in SI

pearl granite
#

our formula in class was just W = (F)(d)

#

f is force and d is distance

restive sun
#

yes, it's the same formula

#

but you need force

#

you don't have force, you have mass

#

so use F=ma to find force

pearl granite
#

and F = kx

#

k is spring constant

#

and x is displacement

restive sun
#

we're not working with springs

pearl granite
#

so i think if I just do 1,500 times 40 I should get it

restive sun
#

no

#

work is force times distance

#

you do not have force

#

you have a mass

pearl granite
#

thats all I needed to do

#

now I am not sure how to do this

marsh citrusBOT
#

@pearl granite Has your question been resolved?

pearl granite
#

nvm got that question

#

may need help with another one

marsh citrusBOT
#

@pearl granite Has your question been resolved?

pearl granite
#

Need help with this

#

why is number one wrong

marsh citrusBOT
#
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trail flint
marsh citrusBOT
trail flint
#

felt like this one should be simple but can't seem to get it done

#

I tried solving for y and got y = 12 - 6x

#

then because its rotated about the y-axis I solved it in terms of x and got y -12 = -6x so (y-12)/-6 = x

#

then since I knew that for the volume of a solid region I needed to do PI * integral from a-b of [R(x)]^2

#

I took the (y-12)/-6 and squared it to get

#

Then I solved for the zero of the function, which is given by setting y to 0, so 0 = 12 - 6x so -6x = -12 so x = 2

#

And so if x = 0 is a bound and y = 0 is a bound and x = 2 is our zero, we can integrate from 0 to 2

#

Leaving us with 61/9

#

But the PI on the outside needs to be remembered, so 61*PI/9

#

Can anyone help me with this? Where is my logic wrong?

still temple
#

hey uhm

#

if you graph the 3 funcs

#

you get a triangle

trail flint
#

It's not three functions

#

Oh I see what you mean

#

nvm

#

Sorry I misinterpreted

#

Yeah you get a triangle

still temple
#

use it to find its volume

trail flint
#

Yeah but I am not meant to do it by the triangle

#

I am supposed to integrate, that's what will be on my test

still temple
#

oh

#

hmmm

#

isnt this like finding the area between two curves?

trail flint
#

pretty much the same, except with volume now you use the volume equation, so PI * integral of [R(x)]^2 where R(x) is your function that creates the graph

#

In the case of 2 functions creating a region in between them, it's [R(x)]^2 - [r(x)]^2 where R(x) is the function on top and r(x) is the function that lies below

still temple
#

im thinking we should get the area of the triangle and multiply by 2pi

#

other than that im stumped :/

you gotta wait for someone else to come help you im sorry

drowsy crag
#

Just use the formula for area of a cone

trail flint
drowsy crag
#

Why?

trail flint
#

It's a requirement that I integrate

drowsy crag
#

Oh

late geode
#

bounds are wrong

#

you're rotating around the y-axis with disk's, / integrating wrt y
the bounds should be the y-coords

trail flint
#

like 0 to 12

#

?

trail flint
#

or am I imagining things

late geode
#

yes

trail flint
#

ok

#

you are 100% right

#

I didn't realize that

#

I only flipped the function

#

not the bounds lol

#

ty

#

I still get it wrong lol

#

I get -4 doing it from 0 to 12

#

And then I multiplied it by PI to get -4PI

#

but it's not correct

late geode
#

can you take a pic of your work on paper

marsh citrusBOT
#

@trail flint Has your question been resolved?

trail flint
#

ok here

#

That's the work

late geode
#

work on paper seems fine
you plugged your bounds into the integrand instead of the antiderivative in mathway

trail flint
#

Oh I see I plugged it in wrong

#

my work was right I worked it out by hand and got 16 * PI and it was accepted

#

ok one last question it's of the same type

#

I am guessing I messed up along the way somewhere again

#

I will post work

#

This feels good to me

#

But I'm not sure

trail flint
#

is this right?

marsh citrusBOT
#

@trail flint Has your question been resolved?

trail flint
#

anybody here who can help

#

I still can't figure it out

trail flint
#

<@&286206848099549185>

#

This question is plaguing me

#

I can post my work so far

#

I only have 2 trains of thought for it

nova solstice
#

Yes that looks alright to me

nova solstice
nova solstice
# trail flint

this ones start and stops are still in terms of x and need to change to terms of y

trail flint
#

so 0-32?

nova solstice
#

yeah

trail flint
#

ok so 0-32 I tried both 0-32 and 2-6 but neither worked for me

#

I got (-32^2)/2+36(32) so 640

#

and * PI

#

so 640*PI

#

but it was not accepted

nova solstice
#

What if you multiplied the pi and 640? does it typically want pi left byitself?

trail flint
#

It is 640

#

but...

#

-4(32)

nova solstice
#

?

trail flint
#

Because the bounds are x = 2 and x = 6, but we rotate around x = 0

#

so we don't want from x = 0 to x = 2

#

therefore we subtract x = 2 function from the given function

nova solstice
#

ah, yeah. right minus left

trail flint
#

Cool I got it now

#

thanks

#

I can finally sleep

#

😵‍💫

marsh citrusBOT
#

@trail flint Has your question been resolved?

#
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marsh citrusBOT
#

Please don't occupy multiple help channels.

late geode
#

.close

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pure pagoda
marsh citrusBOT
pure pagoda
#

in this form of u substitution, the sub taken is 3-x. How is that affecting the x in the original equation if the u sub is 3-x and not just x. If this is some kind of rule, can someone explain how it works?

still temple
#

just solve for x in u = 3 - x

#

,align
u &=3-x\ x&={???}

elfin berryBOT
pure pagoda
#

right i get this, but should this be done in every situation of x? for example, if there was another x somewhere in the qeuation somehow would i do it then to? do i do it to every x every time?

still temple
#

so you should always accordingly change every x to be in terms of u yes

lone heart
pure pagoda
#

ok, i understand, thank you

#

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dense oriole
#

Suppose that you want to have a $39,000 retirement fund after 39 years. How much will you need to deposit now if you can obtain an APR of 11.3%, compounded daily? Assume that no additional deposits are to be made to the account.

$472.47

$639.14

$475.80

$411.67

None of the above.

dry ibex
#

Since irl nobody would tell you which angle is the right angle, how to identify the hypotenuse, opposite and adjacent without knowing the right angle? What if the theta is placed on right angle and the hypotenuse is oppositing the theta?

marsh citrusBOT
#

@dense oriole Has your question been resolved?

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sturdy cradle
marsh citrusBOT
hazy lion
#

What have you tried?

lavish kernel
# sturdy cradle

Identify the possible outcomes when two dice are rolled to get a sum of 7.

sturdy cradle
#

my work

sturdy cradle
hazy lion
# sturdy cradle

Tutorial on how to calculate conditional probability (Bayes Theorem) for two events P(A), P(B), P(B|A) with two examples using

Playlist on Probability
http://www.youtube.com/course?list=EC482E6C6B5F0A30E7

http://www.facebook.com/PartyMoreStudyLess

Created by David Longstreet, Professor of the Universe, MyBookSucks
http://www.linkedin.com/in/...

▶ Play video
lavish kernel
hazy lion
#

oh, sorry, you posted work

#

dont mind me happy

sturdy cradle
#

😁

#

.close

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scarlet rune
#

Can I have some help?

marsh citrusBOT
scarlet rune
#

.reopen

#

Reopen

lethal bridge
#

its already opened

#

?

scarlet rune
#

Oh

lethal bridge
#

just ask ur question

muted narwhal
#

ITS YOU

lethal bridge
#

?

muted narwhal
#

waddup

lethal bridge
#

hello

#

did you leave the server and come back today lol

scarlet rune
#

If x² - 2ax + a²=0, find the value of x
-
a

lavish kernel
#

Is it x/a

#

@scarlet rune

scarlet rune
#

Yes

muted narwhal
#

I realised I forgot all my maths which isn't good, so revising it all again hahaa....

lavish kernel
elfin berryBOT
#

David K.

marsh citrusBOT
#

@scarlet rune Has your question been resolved?

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#
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inland patio
#

I have tried converting the x denominator into x*sinx/sinx and put it in the exponent, I just got ln(1+sinx)^sinx and sat like a duck, the answer is supposed to be 1 but I kept getting 0

inland patio
#

I honestly thought there'd be a form of some sort for ln(1+x)^x, but nope, it is always x and 1/x and vice versa

novel juniper
#

Hvae you tried l'hopital's rule

#

alternatively multiply and divide by sin(x)

inland patio
inland patio
novel juniper
#

you want to use the result (1+sin(x))/sin(x) at 0 is 1

inland patio
#

Ohhhhh, and I disect x and sin x and place eachother accordingly.

#

Yeah I got it, 1*1

#

Morning limits. haha. Thanks for the help!

#

.close

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cunning heath
#

Hello

marsh citrusBOT
cunning heath
#

is there any theorem saying

#

how to quickly find roots of a polynomial

#

(write as a product of polynomials)

late geode
#

approach with rational root theorem i suppose

cunning heath
#

what is it

late geode
#

way of searching for candidates for rational roots

cunning heath
#

moreover, what does it say? like how can i use it

late geode
#

it'll be easier for you to look it up

cunning heath
#

i did

late geode
#

try applying it here

#

after you find one of the roots, you can use long division
then repeat as needed

cunning heath
#

oh i see

#

i get it

marsh citrusBOT
#

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limpid bison
marsh citrusBOT
limpid bison
#

Is n+1,n+2,n+3 also correct?

vital oracle
#

yes

#

not really as common because n wouldnt be one of the integers

limpid bison
#

right ty

vital oracle
#

np

limpid bison
#

Do i have to state the root 11 thing

#

or is it implied

#

I never seen this before 😵‍💫

vital oracle
#

do you know why the root thing works?

limpid bison
#

nope

vital oracle
#

say you needed the factors of 100

#

you usually have a small number * a big number = 100

#

you meet in the middle with 10 * 10 = 100

#

then have a big number * a small number = 100

#

when you go through the factors in order

#

1 * 100 = 100
2 * 50 = 100
...
10 * 10 = 100
...
50 * 2 = 100
100 * 1 = 100

#

youll notice the big * small part of the list is just a repeat of the small * big part of the list

#

you already went through all the factors on the small side

#

so they have to reappear on the big side

#

that means the big side is redundant

#

the separation between them is that 10 * 10 = 100, where both are equal

#

and so you can stop after √100 = 10

limpid bison
#

ah ok u explained that rly well

#

thanks

#

🙏

#

/close

vital oracle
#

.close

limpid bison
#

.quit

vital oracle
#

np

limpid bison
#

.close

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#
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void cove
#

i don't know how to start this, the method i used was to try and isolate R and then take the partial derivative of r1 but I got stuck when I saw dr/dr1 on both sides

void cove
#

nvm got it sorted!

#

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fast needle
#

I don't know where to exactly start for b

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hoary timber
marsh citrusBOT
hoary timber
#

can somone explain why as x goes to infinite

#

it became ln 4

#

from what i see its should jsut be ln(1) as infinite cancel out

novel juniper
#

Try writting L=ln(f(x) )so e^L=f(x)

#

Evaluate it now

#

And then Take the log of both sides

hoary timber
#

ok

glass silo
#

Seeing the second is equivalent, may be easier to see if you write
[
\ln\qty( \frac{2x^2 + 3}{(x + 1)^2 } ) = \ln\qty( \frac{2x^2 + 3}{x^2 + 2x + 1} ) = \ln\qty( \frac{2 + \frac3{x^2}}{1 + \frac2x + \frac1{x^2}} )
]

elfin berryBOT
#

@glass silo

hoary timber
#

that make more sense

#

cause what i done was infinite +3 =infinite

tacit fractal
#

yes exactly

hoary timber
#

so top bottom both becames infinite

#

but it actully 3/infinite

#

so it becames 0

#

yeah

#

thgat make so much sense

tacit fractal
#

but it does not matter

glass silo
hoary timber
#

yeah

#

thank

tacit fractal
#

whatever that was nice

hoary timber
#

thank

#

end

#

emm

#

how do i end this

#

.close

marsh citrusBOT
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gilded sierra
#

I have been stuck on this problem for a few hours and found an online solution that I think is wrong. I've transcribed it out to make it easier to read.

marsh citrusBOT
#

@gilded sierra Has your question been resolved?

gilded sierra
#

<@&286206848099549185>

marsh citrusBOT
#

@gilded sierra Has your question been resolved?

marsh citrusBOT
#

@gilded sierra Has your question been resolved?

marsh citrusBOT
#

@gilded sierra Has your question been resolved?

marsh citrusBOT
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robust notch
#

Why 2xy=12

marsh citrusBOT
robust notch
#

=

#

Y=6/x

#

How do you get to that

static quarry
#

divide both sides by 2x? (assuming x is not zero)

robust notch
#

Ah ok

#

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tulip marsh
#

im not sure

marsh citrusBOT
still temple
#

Are you familiar with the fundemental theorem of calculus

tulip marsh
#

well

next ravine
#

This is FTOC Part 1

tulip marsh
#

i know them but i dont konw how to apply them. i just learn the steps to solve problems

still temple
#

FTC and chain rule

#

so first of all we establish FTC

#

,, \dv x\int_a^x \m ft \dd t = \m fx

tulip marsh
#

for reference this is what i learned

elfin berryBOT
still temple
tulip marsh
#

(supposed to have learned)

#

hum

still temple
#

this is the basis you need

tulip marsh
#

when do you use the second one?

still temple
#

the second one is basically the first in disguise

next ravine
still temple
#

,, \int_{\m hx}^{\m gx} \m ft \dd t = \int_{\m hx}^a \m ft \dd t+ \int_a^{\m gx} \m ft \dd t = -\int_{a}^{\m hx} \m ft \dd t + \int_a^{\m gx} \m ft \dd t

elfin berryBOT
tulip marsh
#

im not good at understandn letter notation. it seems like the first intergral n's should be a to a.

#

since it goes from

a to hx and then gx to a

#

oh

#

i read it wrong

#

yes

#

it makes sense

tulip marsh
# next ravine Yes! Use this first one here

i dont understand how to apply it. or rather, i dont understand what tells us to apply it. what part in the problem indicates to us we should use this theorem. what should i look for to know to use this

#

anyone??

#

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#
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brazen flame
marsh citrusBOT
brazen flame
#

can someone explain me why 1/1 * 2 + 1/2 * 3 is equal to 1/1 - 1/2 + 1/2 - 1/3 + 1/3

vernal forge
#

work backwards

brazen flame
#

hmm?

marsh citrusBOT
#

@brazen flame Has your question been resolved?

vernal forge
# brazen flame hmm?

$\frac{1}{2} - \frac{1}{3} = \frac{3}{2\cdot 3} - \frac{2}{2\cdot 3} = \frac{3-2}{2\cdot 3} = \frac{1}{2\cdot 3}$

elfin berryBOT
#

artemetra

marsh citrusBOT
#
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harsh vigil
#

how do you do this problem?

marsh citrusBOT
still temple
#

split it up first

harsh vigil
#

idk how to apply this to this problem

still temple
#

,, \sum_{k=1}^n a_k + b_k = \sum_{k=1}^n a_k + \sum_{k=1}^n b_k

elfin berryBOT
still temple
still temple
harsh vigil
#

no 😦 so i got n(n+1)(2n+1)/6 + 5n(n+1)/2 + 8(n) so far but idk what the next step is

still temple
#

okay so you do know how to do it since you implicitly did exactly that

#

anyways that's correct

#

the rest is just algebra

harsh vigil
#

ok yayy

#

like for the next part i see that they got 9n^2+9n and 24n and idk what number they mulitiplied it by?

still temple
harsh vigil
#

ive had several attempts at this question and they want the answer to be in the same 1/3n(n^2+...+...) form

still temple
harsh vigil
#

yes

#

i havent taken math for the long time so my memory is little foggy 😦

still temple
#

ok so you have [
\f{n(n+1)(2n+1)}6+5\cd\f{n(n+1)}2 + 8n
]
you want to get rid of the fractions. To do that, you can multiply and divide by the least common factor between 6 and 2 (the denominators)

elfin berryBOT
harsh vigil
#

sooo im multiplying by 2...?

still temple
#

that's not the LCM

harsh vigil
#

oh is it 6

still temple
#

yeah

#

so like now

#

[
\f{n(n+1)(2n+1)}6+5\cd\f{n(n+1)}2 + 8n = \c b{\f66\cd}\bs{\f{n(n+1)(2n+1)}6+5\cd\f{n(n+1)}2 + 8n}
]

elfin berryBOT
still temple
#

try distributing in like, that 6 in the numerator while keeping out the 1/6

zealous lava
#

keep the 1/6

#

or keep it in mind and divide by 6 later

#

whichever's better

harsh vigil
#

so 1/6[2n^3+3n^2+n]+(30n^2+30n)+48n ... ?

zealous lava
#

keep it undistributed

#

it's simpler

still temple
#

uh no

#

starting from the right, where did the n go for the 48?

harsh vigil
#

oh sorry im really lost cat_happycry

elfin berryBOT
#

Gamer Sans The Gamer Skeleton

it's $\frac{1}[6} \cdot n(n+1)(2n+1) + 15 \cdot n(n+1) + 48n$

if im not stoobid
```Compilation error:```! Extra }, or forgotten $.
l.49 it's $\frac{1}[6}
                       \cdot n(n+1)(2n+1) + 15 \cdot n(n+1) + 48n$
I've deleted a group-closing symbol because it seems to be
spurious, as in `$x}$'. But perhaps the } is legitimate and
you forgot something else, as in `\hbox{$x}'. In such cases
the way to recover is to insert both the forgotten and the
deleted material, e.g., by typing `I$}'.

Preview: Tightpage -1310720 -1310720 1310720 1310720
[1{/usr/local/texlive/2023/texmf-var/fonts/map/pdftex/updmap/pdftex.map}{/usr/l```
zealous lava
#

i am stoobid with latex

#

$\frac{1}{6} \cdot [n(n+1)(2n+1) + 15 \cdot n(n+1) + 48n]$

elfin berryBOT
#

Gamer Sans The Gamer Skeleton

still temple
#

,align
\f{n(n+1)(2n+1)}6+5\cd\f{n(n+1)}2 + 8n &= \c b{\f66\cd}\bs{\f{n(n+1)(2n+1)}6+5\cd\f{n(n+1)}2 + 8n}\
&=\f16\bs{6\cd\f{n(n+1)(2n+1)}6+6\cd5\cd\f{n(n+1)}2 + 6\cd8n}

elfin berryBOT
still temple
# elfin berry

@harsh vigil this is what you have currently. Do you agree yes or no?

harsh vigil
#

yes

still temple
#

okay, so for now, don't distribute the parentheses

#

simplify the numbers only

#

what do you get?

harsh vigil
#

1/6[6n(n+1)(2n+1)/6 + 30n(n+1)/2 + 48n] ??

still temple
#

yeah sure

#

but like

#

whats 30 divided by 2

harsh vigil
#

oh 15

still temple
#

yeah

#

What's 6 divided by 6

harsh vigil
#

1

still temple
#

so, your updated version?

harsh vigil
#

1/6[1n(n+1)(2n+1) + 15n(n+1) + 48n] ?

still temple
#

yeah great

#

now, distribute out 15n(n+1)

#

what do you get

harsh vigil
#

15n^2+15

still temple
#

nuh uh

harsh vigil
#

no?? wait lmao

#

oh wait 15n^2+15n?

still temple
#

yeah

harsh vigil
#

okk

still temple
#

so, your updated version now?

harsh vigil
#

1/6[n(n+1)(2n+1) + 15n^2+15n + 48n]

still temple
#

yeah

#

you can simplify 15n + 48n

#

what does that become

harsh vigil
#

1/6[n(n+1)(2n+1) + 15n^2+63n]

still temple
#

yeah

#

so now going to the left

#

distribute out all three parentheses

#

or do you want me to guide you with that?

harsh vigil
#

wait so do i multiply (n+1)(2n+1) by n first then 1/6?

still temple
#

just ignore 1/6

#

pretend like it doesnt even exist

harsh vigil
#

ok ok ill try just give me a sec

#

am i supposed to get 3n^2+n^2

still temple
#

nope

#

well

#

for what exactly?

harsh vigil
#

n(n^2+n)(2n^2+n)...

still temple
#

pause

harsh vigil
#

oh wait

#

yea

still temple
#

why is it that ?

#

you have n(n+1)(2n+1) remember

harsh vigil
#

i think i got it messed up somewhere let me look at it

#

yea

#

(n^2+1n)(2n^2+n)

still temple
#

no

#

that's wrong

#

like

harsh vigil
#

isnt 1n = n??

still temple
#

n goes only once

harsh vigil
#

oh what

still temple
#

,, a(b\cd c) \c r{\ne} ab \cd ac

elfin berryBOT
harsh vigil
#

im sorry how do u distribute it then? i forgot most of my algebra

still temple
#

like

#

just once

#

,, a\cd b \cd c = (a\cd b) \cd c = a\cd (b\cd c)

elfin berryBOT
still temple
#

so like

still temple
harsh vigil
#

n^2+n...?

still temple
#

yeah

#

so

#

(n^2+n)(2n+1)

#

distribute this now

harsh vigil
#

ohhhh thats what you meant

still temple
#

yes

harsh vigil
#

i thought the n goes into both parenthesis

still temple
#

no like

#

for multiplication its only once

#

you are confusong it with addition

#

for addition yes it does distribute

#

a(b+c) = ab + ac
a(b*c) != ab * ac

#

!= means not equal to

harsh vigil
#

ohh ok

still temple
#

whatcha get

harsh vigil
#

2n^3+3n^2+n

still temple
#

congratss

#

ok

harsh vigil
#

FINALLY

still temple
#

so your updated version?

still temple
#

we are not done yet, but almost

harsh vigil
#

1/6[(2n^3+3n^2+n)+15n^2+63n]

still temple
#

yeah

#

so like now

#

n + 63n simplifies

#

what is it

harsh vigil
#

64n?

still temple
#

yeah

#

3n^2 + 15n^2 simplify

#

what do you get

harsh vigil
#

18n^2

still temple
#

and, at last, your updated final version is?

harsh vigil
#

1/6(2n^3+18n^2+64n)

still temple
#

oh actually

#

just kidding

#

there is one more step joyspin

harsh vigil
#

lmaoo were almost there at least

still temple
#

what's the greatest common factor between 2n^3, 18n^2 and 64n

harsh vigil
#

2?

still temple
#

i mean, yeah, but you are missing something

harsh vigil
#

2n

still temple
#

yeah

#

so

#

factor out that bad boy

#

what do you get

harsh vigil
#

1/6 2n(n^2+9n+32)

still temple
#

yess and whats 2 divided by 6 (in fraction)

harsh vigil
#

1/3

still temple
#

yeppie

#

and we are done

harsh vigil
#

so 1/3n(n^2+9n+32) ?!!?!?!

still temple
#

so your last thing is[
\f n3(n^2 +9n +32)
]

elfin berryBOT
still temple
harsh vigil
still temple
#

i mean

#

we can check for you lol

#

let's see

#

,w sum of i^2 + 5i + 8 from 1 to n =n/3(n^2+9n+32)

harsh vigil
#

does this look right

#

oh yeah huh

#

FINALLY GOT IT!!!! TYSM

still temple
#

seems like it

#

ayeee

harsh vigil
#

lifesaver fr fr

still temple
#

lmao

#

anyways do u have anything else to ask @harsh vigil

harsh vigil
#

nope! that was the only question i got wrong on hw

#

thank youu

still temple
#

okay have a great day!

#

.close

marsh citrusBOT
#
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loud pagoda
#

.close

marsh citrusBOT
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hardy smelt
marsh citrusBOT
hardy smelt
#

I just want to understand the part why it can assume lambda to be an specific thing, and then prove the unequally for all lambda in R

#

It’s in spanish but ill explain the important parts:

It is trying to prove the cauchy inequality

Starting with the square of the norm of x+lambda * y, which is always > 0 because its an square

#

And then, it choses that one specific lambda, which will be enough to make everything work out and prove the inequality

#

My question is that

#

If you chose that one specific lambda, does it mean that the inequality will only work if the lambda is only the one you chose?

devout mauve
#

well the first inequality is valid for all lambdas

#

the actual inequality you want to prove doesnt depend on lambda at all

hardy smelt
#

I see

#

So it does work

#

Now if there was a lambda in the inequality (like the cauchy one)

#

We shouldn’t assume it works for all lambdas in R?

devout mauve
#

well depends on the statement of the inequality

#

it could be "for all lambda this inequality holds"

#

or "there exists a lambda for which the inequality holds"

hardy smelt
#

I see

#

Sorry for my english but by hold you mean “this thing works”?

devout mauve
#

the inequality is true

hardy smelt
#

Alright tyty

#

Have a good day!

#

.close

marsh citrusBOT
#
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minor verge
marsh citrusBOT
minor verge
#

help pls

#

ive done a and c

#

im so lost on d

bitter solstice
#

Can you not use the same tehod you used for a and c?

#

Here's a hint that may or may not help (depends on what method you use), there's one eigenvector you can kind of tell by inspection

marsh citrusBOT
#

@minor verge Has your question been resolved?

minor verge
bitter solstice
#

Whats the method you've been taught to use?

minor verge
bitter solstice
#

yeah so can't you do the same here? find the characteristic polynomial?

#

,w characteristic polynomial of {{0,1,1},{1,0,1},{1,1,0}}