#help-33
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yep it's rude
wonder how canadians fare in the putnam then
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!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
1
do you know 2 point form of a line
nope
tbf i lit just joined from home school
to a public
and this is the hw
i lit need a awnser lol
im dyin lol
tell your teacher you haven't been taught this
Need help with 6
bro make ur own one
Oh sorry
Basically take two points (x,y)
In this case I see there’s a point at (1,-1) and (0,4)
correct
Now you use the formula m=y2-y1/x2-x1
whats that
It doesn’t matter which one is y1 or y2
ok
It just matters that you plug it in with the corresponding point for example if you put y2 first your gonna put x2 first on the bottom
Yes.
So with our two points (1,-1) and (0,4) you’ll do -1-4/1-0
We very specifically do not do that here. Read #rules
And your answer will be -5/1
bro i said that ages ago 💀 , @simple quiver is trying to help me if you dont mind 😄
So m=-5
Now that we have m you can put that into the equation y=5x+b
Now to solve for b your gonna take one of the points
Either (0,4) or (1,-1) and then solve for b like this 4=-5(0)+b
And you’ll get b=4
So the equation should be y=-5x+4
He isn't really helping you no, he's doing the work for you, which he shouldn't be, but that is a different problem. You should still read the rules and respect them.
Thank you mate!
Put in Desmos to make sure it’s correct
mate just dont get invlolbed plz
alr thx
Np
This isn't the same picture as earlier, though you can follow the same steps to solve it
as i got the firt wrong,takes me to another
can we continue in dms if possible @simple quiver
I checked on desmos and I get the same graph from the first one
weird
You sure you typed in the -5x
The first solution was correct
yh
Then idk email your teacher or sum
yh i will thx bro
Welcome
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hello
Please don't occupy multiple help channels.
@eager rock Has your question been resolved?
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can you help with physics questions
it happens, you can ask and see
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Its due in 5 minutes please help
Please don't occupy multiple help channels.
What do i do
Don’t occupy multiple help channels
What have you tried so far?
@high parrot Has your question been resolved?
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Can someone help me?
I need to know what "postulate could be used to prove congruence"
@oblique inlet Has your question been resolved?
If 2 sides between 1 angle of first triangle are equal to 2 sides between equal angle of another one, so these triangles are congruent. (SAS)
no problem
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If my asymptote becomes an imaginary number, do I mark it?
@still temple Has your question been resolved?
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Find the value(s) of k that make x^2 + k(x+7) + 9x +15 a perfect square trinomial
solve for k
how would i go about doing that?
distribute the k(x+7) first
oh yeah i did that
im just stuck after that
lemme do it on paper rq
thanks
btw
thats a binomial
not a trinomial
oh okay
No it's a trinomial
x^2 + k(x+7) + 9x +15
That's trinomial
i did it with python and i got 3 and 7, i didnt check negative numbers though — im just not sure how to do it with math
theres nothing to the 3rd power
Power doesn't not relate to the naming like that
Trinomial means 3 terms, not 3rd power
do you know of any conditions the quadratic must satisfy so that it is a perfect square?
no that was the question
do you know about the discriminant of a quadratic?
yeah
for a perfect square, the discriminant must be 0
ohhh yeah
with this information can you try solving for k?
np
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Can someone confirm if I am correct here, because the tangent lines would be horizontal?
And isn't 1 continuous but not differentiable?
x is differentiable at x=-3
the derivative at x=-3 is just zero
its the first choice
ah
thank you for your help
np
.close lol
.close
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Are the local extremes and relatives the same?
@paper herald Has your question been resolved?
Yes
same steps?
Local extrema and relative extrema?
I'm p sure it's the same thing just different wording
synomym?
yes they are synonyms
a absolute valkue is f(x)?
?
how i can find absolute value
absolute value makes any negative number positive
absulute maxima or minima*
(x,y) x=is local and y=anbsolute?
to find the absolute maximum or minimum of any function, first find all relative extrema and then you can put those x values into the original function
then the largest value is an absolute maximum and the lowest value is an absolute minimum
okay thx
no problem
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how do i solve this
So we know that complementary angles add up to 90 degrees. And we know that opposite angles are equal. Given that angle 2 and 3 are equal and 1+2=3+4 we can conclude that 1=4
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How do I do this
U allowed to use trig?
yes
Kool cus law of cosines is necessary
I guess for starters do u remember anything about opposing angles of a cyclic quadrilateral
they add up to 180 right?
i got x=13
noice
Next u can draw a line from B to D, and radii from center to B and from center to D
So if O is the center
U have triangles ABD and OBD after making those line segmenta
Oops
And ye that's where u use law of cosines
u can figure out <OBD by using <C
I believe in u 
I don’t understand how there is a triangle obd
O B and D are three points
Ur assuming they're collinear
If that were the case then angle A would be 90
cus line OBD would be a diameter of the circle
can you show me how you would draw it
Err just draw the O a bit down so they don't end up in the same line ig
It'll look like ur O is not at the center of the circle but
Doesn't really matter :p
alternatively u can draw D and B closer to A
That would give u a more accurate picture but I just figured redrawing B and D would be more work 
when i draw them closer angle a looks bigger
like greater than 90
when it should be 78
oh wait oops ur right
further then
And actually I guess getting <DOB from <A would be easier
Something like this?
Yee
so line bd would be 19.65
Result:
19.647748857585
obd?
Ye
but wouldnt i still only have 1 angle 1 side
but the other 2 sides are equal
Result:
386.03403517075
,calc 386/(2(1 - cos(1562pi/360)))*pi
Result:
316.86071513023
Result:
765.47952433335
Yeah
ok i didnt know that bod was supposed to be double bad
thanks a lot for your help i really appreciate it!
Np
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Are these complex limits correct? Ty and advance
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Hi
How is the reciprocal of this ( root 3 - root 2)^x^2-4
Rationalisation
Ok lets start with an easier example
What is the reciprocal of sqrt3 + sqrt 2
@twin robin Has your question been resolved?
root 3 - root 2/ root 3?
you want to make the denominator rational right?
ROOT 3 - ROOT 2/ 3?
remember (a+b)(a-b)= a^2-b^2
I cancelled out 2's idk why i will write it down from next time
anyway its basically the same thing here
so the powers won't really matter in here?
as we do not know the x value
the denominator would be 1^(x^2-4)
Oh
yes because its 1
so in here when i tried to solve it by adding the terms
One could've use made sequence
But i'm confused with sequence
Like 3+2x5
hmm you should think about the perfect squares
oh
but if i do that it will be very calculative
I'm trying to understand the sequence here
OH NVM
I got it
1x3 + 2x5 + 3x7+4x9+...
Thanks!
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im confused on what to do on questions 2.1.2 2.1.3 and 2.1.4 i more or less have evrything else figured out
@still temple Has your question been resolved?
<@&286206848099549185>
For 2.12 just find the height between peak and crest and half it
For range just notice what y values the graph occupies
For period take the distance, horizontal, b/w crest and peak and double it
so for example on 2.12 i take the 3 and half it?
sorry could you give a more indepth explanation
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.close
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hi
im very confused at this question
so when I tried to solve this question myself I got pi(20^2*d)
beacuse why on earth would u square a day?
it says to multiply by day for each day it grows but never mentions squaring
you have to distribute the exponent to eveything in the parenthesis
your radius isnt 20, its 20d
you square the radius and multiply it by pi.
thanks so much
I didnt realize they were connected by the variable as well
forgot to take that in account
thanks so much brother!
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*The Li'enard equation is [
\dnv 2[u]t + \map c u \dv[u]t + \map g u = 0
]
where $g$ satisifes the conditions $\map c u \ge 0, \map g 0 = 0, \map g u> 0\tss{for} 0 < u < k, \map g u < 0 \tss{for} -k < u < 0, u\map g u > 0 \tss{for} u \ne 0 \tss{and} -k<u<k$
\vs{4 mm}
Show that the point $u = 0, \ff{du}{dt} = 0$ is a stable critical point
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shouldn’t a2=(12-30m)/3m instead of (30m-12)/3m
A trick to find acceleration for the syste
is
A = M1(on the surface) times gravity / M1+M2
where m2 is the box on the pulley hanging down
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Both my question and answer are written.
There's no solution given solution, so I wondered if this would be considered correct.
Do note that this was a basic exercise in an introductory book to analysis, so I'm not sure how rigorous I'm supposed to be
you could just prove that the average would work for z
that it's not equal to x, or less than x or equal to y or more than y
find another channel
also delet please
i don't know if yours is wrong, but proofs are never like this
like it reads to me like you stated the same thing
conceptually it's correct I think, but if it asks you to show that something exists, just showing that one such element exists (like the average as was pointed out) is enough.
yeah I'm pretty new to the whole proof thing, so I'm not really sure how I should go at it.
How would I prove it for the average?
like
(x+y)/2 ? y
x + y ? y + y
what i want to say is that proofs can ask you for obvious things, but they don't expect you to state it right back
you gotta like do induction, or construct something
yeah nvm x < y => existence of an open interval containing elements between x and y is just restating the same thing but using the definition of an interval
so for this one I basically just have to say that for those given x and y, if you add them up and divide by 2, you'll get a number which is bigger than x and smaller than y (basically just the average)
Would that be it, like would that be considered correct?
also mention why the average is in R
but ideally you have to do guess what's intended to be the answer 🙂
to mention why the average is also in R, would it suffice to say that any 2 numbers in R added and divided by another number in R (except 0) is going to end up being another real number, or is there some other thing I'm not aware of?
yeah thats it
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PLEASEEEEE
gotta calm down
what have you done
tell me what youve done, or what you dont understand, then i can help
Its so many numbers
theres only two numbers in that question
Wait
ig the main thing is converting 2.67kg to grams, but after that, just use the given formula
I love u
thanks
Ok well now im def stuck
Like i thought
And now im just straight tripping on air
what did you try for (a)
I got it wrong
I forgot what i put but what i did was
I multiplied 1.67 x 10-24 but 3
then added it w the nitrogen
and got?
yeah this is wildly off
what you described here is right but idk what youve done in practice
oh
you do not just add the exponents
no
$3(1.67\times 10^{-24})+2.32\times 10^{-23}$
AℤØ
is all you need to calculate
as for b, you know how many grams a single molecule is (a), so how would you find how many are in 1 gram
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Hello! I'd like to ask about linear algebra.
That's the question (the second one)
So far, I have used Holder inequality to get
$$\max_{i\in{1, \dots, m}}|a_i|_q$$
Memiya#9800
Not sure how to type norms
But it's basically the largest q-norm of the row vectors
But now I need to show that this is equal to the norm
It is more or equal to it
I was advised to use the equality condition of the Holder inequality to find an x vector that selects that largest row.
But I don't really know how to approach that part
Some kind of ratio...
But that's not the part of Holder inequality I used for the first inequality
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Can someone help me with the exercises on this sheet https://moodle.colband.com.br/mod/resource/view.php?id=268495
ill translate if you need help with translation
it's unavailable
just send screenshots
k
ill translate it
If one of the roots of the equation is 5, then the other result is
a: a prime number
b : a perfect cube
c : divisor of 48
d: a perfect square
e : a multiple of 3
yh
what are they equal to?
assume the other root is x. thus, what are 5x and x+5 equal to?
do you know vieta's theorem?
i dont
idk what it's called in your school
but it basically says that if you have an equation x^2+bx+c=0, then the roots x_1 and x_2 create this system:
x_1+x_2 = -b
x_1*x_2 = c
your x_1 is 5
what are your b and c?
i know this theorem
good
that's okay
just let a be some number and do the same operations as you would've done with regular numbers
the b would be 2 and the c would be 11 then
hm
you are solving this equation with respect to x. that means that you don't care about the value of a (yet) and treat it as a constant
hint: ||c = 2a+11. what's b?||
b would be -a
but how come the c is 2a+11
a quadratic equation has 3 coefficients: one in front of the x^2 term, one in front of the x term, and one constant
oh i get it
awesome
the c is more "flexible"
yes
therefore, you have:
5+x = a
5x = 2a+11
you should be able to solve this system
quick question, what does * mean
k
$x_1 x_2 = -b$
artemetra
np
can i get more help?
okay
the sheet i sent that is unavailable has content of the next year (for me)
thats why im having trouble
The numeric value of this expression, for x = 999 equates to
factor both numerator and denominator
yes
not yet
k
notice that you have $\frac{(x-1)(x+1)}{(x+1)^2}$
artemetra
can you cancel anything?
998/1000= 0,998
tysm
this is the next one
X is the smallest natural number that makes the square root 1080 times x have an exact value
X is a
a: prime number
b : multiple of 15
c : divisor of 100
d : perfect square
e : perfect cube
is there a way to solve this without "brute forcing" ?
nvm i got it
i need help with this one
translating:
Elevating by cube both sides of the equation and developing it correctly, we reach the conclusion that x^2 + 1/2^2 equals
a : -1
b: 2
c : -2
d: 1
e: 3
x^3 + 1/x^3
youre asking me to simplify this?
or this
3x
hm
maybe the question has a typo
and they meant square both sides
if they meant square both sides, the question makes more sense but idk
and the answer would be d) 1
the answer sheet says its b) 2
ill skip this one
the next one has geometry content that i haven't learned still
but i do have knowledge about basic operations with rectangle triangles
the triangle ABC is rectangular on A, if BH = 9 cm and the area of the triangle ABH is 54 square cms, the area of the triangle ABC is
300 square cm
150 square cm
96 square cm
144 square cm
192 square cm
(x+1/x)^2=x^2+2+1/x^2
4-2=x^2+1/x^2
No need to cube
Just square
i see
weird it says "cube"
glad you found the solution, ty
im familiar with these formulas
and the pythagoras theorem
nvm i manage to do it
all i had to do was 54 = 9.m/2
didnt realize
Can someone help me find the area of this circle
Each square has 16 centimeters
@sudden cape Has your question been resolved?
for this
yea
ok so what u have to do is take TO as r(radius of circle)
and the point from O to the point on line EF will become 16-r
also OE will be equal to r
i see
i dont understand this part
why is that so
let me show it on drawing
k
ok ok
how am i supposed to do the Pythagoras theorem now tho
i have EP^2 + (16-r)^2 = r^2
i dont know either ep or pf
only op and oe
nvm i do know
ep/pf = 8
Thanks for the help
Does anyone know how to calculate the area of a parallelogram with different sides?
All I have to do is calculate the area of the blackened part
But the sides have different sides (2, 7, 9, 6 centimeters)
I tried dividing the parallelogram into 2 triangles
Then calculating the area of each, then adding them up
But it didn’t work
@sudden cape Has your question been resolved?
Can u pls share the question
nvm i already did it
@sudden cape Has your question been resolved?
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Okay
oops mb
nah i did
you already have this thread, don't move
Ok
So I'm stuck on this proof , in the case where n is prime it follows by theorem however when n is not prime I can't seem to find any manipulations to show it
This is my new line of thought
But u have already expanded modulo and tried setting out the definitions to desried result
I
I wonder then if it's false as that's a possibility
For the q
And requires a counter exmp
you can try going from the definition of mod
if n divides b(a-b), then either the RHS is 0 or a multiple of n
Yes that's true
so you must have either n divides b or n divides (b-a) right
Yeah makes sense otherwise the number u get would not be an integar which was the assumption ,okay nice and if itsbthe other case where RHS =0 then it would amount to n |0 which is true
Thanks Elliot
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mean value theorem kicking my butt again. is this just asking for what f'(c) is equal to?
HELP
HELP
e^(iπ) - 30 + 208x - 2 + 4x (2x) + (9x) ∫₀ˣ dx = x - x²/2 + x³/3 - x⁴/4 + 4 + (-1)ⁿ xⁿ⁺¹ / (n + 1) + 8 x 2
...
!occupied
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
um.
wgat
i just need help with this question
i dont understand it
Yes, specifically the f'(c) given by the mean value theorem
okay thank youu
You can open a channel of your own by the way
thanksa
for this one, how would i approach this?
@last cliff Has your question been resolved?
@last cliff Has your question been resolved?
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Hi, can anyone help me with this vector question. Im congused as to how the two lines can be contained in the plane, as they don't have the same direction. Should I just do cross product? Thx
lines dont have to be parallel to be in the same plane
but doing the cross product of the direction vectors will get you the normal vector of the plane yeah
oh yh, now that i think about it, ig it makes sense
what about this one, idk how to find the point of intersection
why do you mark the first one =
because it was the right cross product
ok so intesection of 2 planes its ofetn a line
now a line is given by a starting point and a direction vector
the direction vector is the solution of this linear system
you can do elementary row operation to simplify the system and get the solution
@elder wolf Has your question been resolved?
when i put z to 0, to solve x and y, it doesnt give me the values I want for x and z
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where does the +1/3 come from?
ohh of course I was so hell bend on why it was positive I totally missed the -
ok yeah simple answer thanks
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where does the -12 come from? i get +12 when intergrating
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Need help understanding why my answer doesn’t match the real answer
I think that
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can someone help me check my work on part 1a
I think the answer is {b,c,d,e,g,h}
but im not sure what proper set notation is
or if the answer is even correct
to which question
it actually means "all the elements not in (A intersect B)"
if that is what you meant
so did you find A intersect B?
yes there you go
lol missed a value
but the issue i have is
proper set notation
im not sure how thats supposed to look
any ideas?
what do you mean by proper set notation?
this looks like a perfectly normal set to me
(use curly brackets)
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i need to prove that f'(pi)+f'(0)=0
Expand the integral
I expanded and did parts on both terms
It might be easier to show your work so we can find if there's a problem
derivative of cos(x) is...
-sin(x)
yes
Oh i made a mistake with the signs?
thankyouuu 🙂
you most likely did -1 -1 instead of -1 -(-1)
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i just finished these problems, can someone check it for me please!
Do you have reason to believe you’re wrong?
uhh for all of 1, i just wanted to double check
for 2 its because im not very confident
like at all lol
2’s correct
But if I’m pedantic I’d say A = 1, 2, 3 is not a set
Missing curly brackets from the question
Looks good as well
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I have having some trouble finding this limit
mh... do you want the exact value of that series ?
$|n^2+i^n|>|n^2|-|i^n|=n^2-1$
everg
hence $\frac{1}{|n^2+i^n|}<\frac{1}{n^2-1}$
but yeah ok
not true, these are complex numbers
fafilou do you know morphism between algebraic varieties ?
no I don't
yeah you need to add module
ok ok ... just study the absolute convergence (that imply convergence )
everg
(don't mean to be aggressive I think it's important to make things like this as explicit as possible when trying to teach to avoid questions about notation and make it clearer what our potential goal is)
whotao ...everyone are writing except you xD
yes you' re right
Don't think I could help you, my understanding is pretty vague
i am a little bit tired
ah ok thanks np ... i very tough subject
I am trying to see, if I can use this
you want to prove convergence ... now we're going to prove something stronger, which is absolute convergence
so now the problem becomes $\sum \frac{1}{|n^2+i^n|}$
everg
by that inequality you get that
$$\sum \frac{1}{|n^2+i^n|}<\sum \frac{1}{n^2-1}$$ where the last series is convergent
everg
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ive asked like 4 people
and none could help but
realized we only add max once so it should be 3 + 3.75
nvm i just solved it lmao
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sry i close
Do i have to plug in points
To graph like this one
like -2 -1 0 1 2
If you plug in a really big number into x^2, what do you expect to get?
like
this would not help you btw
In terms of like big, small, negative, positive
oh
But part of the question they want the graph
but i will get positive number
big positive number]
infinity
-1000^2
their product is negative surely
You should use part a to eliminate options
All the questions you've been asking, applies the same concept
yes it just get harder
Describing the end behavior and graphing
If you can figure out part a, you use part a for part b
So this concept
I will never need to know what graph look like
I can just do the first part and im good
yes have that big U shape
But ideally yes
Ok perfect thnxs
@humble river Has your question been resolved?
hi
i did the elimination method but this time it is a different scenario i ask in new channel since this 1 inactive
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Pretty sure i did this correctly can anyone double check
can you show work
Yeah
F'(-1)=11(2)-(5)=17
what's the stuff before that
11(-1)^10 h(-1) + (-1)^11 h^1 (-1)
seems alright
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please help with if that's correct and where to go from here
determine slope at the specified point
how do I do that?
slope at a given point x = a is f'(a)
recall the relation between derivatives and slope, (why you're even taking the derivative in the first place)
idk is this right?
work is unfinished, missing value at the very end
why do you have
y = 3x + [blank space]
oh y=3x+1?
yes
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I dont get this simplification at all
this is the full answer to the question on proving by induction for Fibonacci:
can anyone help me?
$2^{(n-1)/2}2 = 2^1*2^{(n-1)/2} = 2^{1+(\frac{n-1}{2})}) \geq 2^{\frac{n+1}{2}}$


