#help-33

1 messages · Page 70 of 1

summer trench
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and also sorry lol, just got to know replying someone with "k" is rude lol

white lion
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wonder how canadians fare in the putnam then

vagrant gull
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well thanks guys

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i think im good now

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lethal basin
marsh citrusBOT
lethal basin
#

help me plz

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i have worked on this for a hour

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and no impact

summer trench
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!status

marsh citrusBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
lethal basin
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1

summer trench
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do you know 2 point form of a line

lethal basin
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nope

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tbf i lit just joined from home school

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to a public

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and this is the hw

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i lit need a awnser lol

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im dyin lol

burnt abyss
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tell your teacher you haven't been taught this

lethal basin
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i tried and he said "well find out"

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i just need help to get the awser lol

simple quiver
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Need help with 6

burnt abyss
lethal basin
#

bro make ur own one

simple quiver
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Oh sorry

lethal basin
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can someone helpplz

simple quiver
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You know slope form

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Y2-Y1/X2-X1

lethal basin
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no

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can i just have a awnser if possible lol

simple quiver
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Basically take two points (x,y)

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In this case I see there’s a point at (1,-1) and (0,4)

lethal basin
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correct

simple quiver
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Now you use the formula m=y2-y1/x2-x1

lethal basin
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whats that

simple quiver
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It doesn’t matter which one is y1 or y2

lethal basin
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ok

simple quiver
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It just matters that you plug it in with the corresponding point for example if you put y2 first your gonna put x2 first on the bottom

lethal basin
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Yes.

simple quiver
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So with our two points (1,-1) and (0,4) you’ll do -1-4/1-0

lapis steppe
simple quiver
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And your answer will be -5/1

lethal basin
simple quiver
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So m=-5

lethal basin
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it says to put it in this form.

simple quiver
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Now that we have m you can put that into the equation y=5x+b

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Now to solve for b your gonna take one of the points

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Either (0,4) or (1,-1) and then solve for b like this 4=-5(0)+b

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And you’ll get b=4

lethal basin
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Alright!

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thanks so much!!!

simple quiver
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So the equation should be y=-5x+4

lapis steppe
lethal basin
simple quiver
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Put in Desmos to make sure it’s correct

lethal basin
lethal basin
simple quiver
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Np

lethal basin
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lemme see if it works rq

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it says incorrect @simple quiver

simple quiver
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?

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I just checked on desmos

lethal basin
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it says incrrect

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for that question

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apparently its wrong

simple quiver
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Is this the question your doing

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Or the other one

lapis steppe
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This isn't the same picture as earlier, though you can follow the same steps to solve it

lethal basin
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as i got the firt wrong,takes me to another

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can we continue in dms if possible @simple quiver

simple quiver
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I checked on desmos and I get the same graph from the first one

lethal basin
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weird

simple quiver
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You sure you typed in the -5x

lapis steppe
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The first solution was correct

lethal basin
simple quiver
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Then idk email your teacher or sum

lethal basin
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yh i will thx bro

simple quiver
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Welcome

lethal basin
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prob asleep lol

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eager rock
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hello

marsh citrusBOT
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eager rock
#

can you help with physics questions

marsh citrusBOT
sleek lake
#

it happens, you can ask and see

eager rock
#

ok

#

solving?

marsh citrusBOT
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high parrot
#

Its due in 5 minutes please help

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high parrot
stark trail
cloud iron
#

What have you tried so far?

marsh citrusBOT
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@high parrot Has your question been resolved?

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oblique inlet
#

Can someone help me?

marsh citrusBOT
oblique inlet
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I need to know what "postulate could be used to prove congruence"

marsh citrusBOT
#

@oblique inlet Has your question been resolved?

bright cloud
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If 2 sides between 1 angle of first triangle are equal to 2 sides between equal angle of another one, so these triangles are congruent. (SAS)

oblique inlet
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Oh

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Gotcha I'll add it to my notes thank you!

bright cloud
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no problem

marsh citrusBOT
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still temple
#

If my asymptote becomes an imaginary number, do I mark it?

marsh citrusBOT
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marsh citrusBOT
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@still temple Has your question been resolved?

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still temple
#

Find the value(s) of k that make x^2 + k(x+7) + 9x +15 a perfect square trinomial

still temple
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how would i go about doing that?

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distribute the k(x+7) first

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oh yeah i did that

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im just stuck after that

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lemme do it on paper rq

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thanks

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btw

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thats a binomial

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not a trinomial

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oh okay

lone heart
still temple
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You can't solve for trinomial

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you can solve for a binomial tho

lone heart
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x^2 + k(x+7) + 9x +15
That's trinomial

still temple
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i did it with python and i got 3 and 7, i didnt check negative numbers though — im just not sure how to do it with math

still temple
lone heart
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Power doesn't not relate to the naming like that

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Trinomial means 3 terms, not 3rd power

hushed egret
still temple
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no that was the question

hushed egret
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do you know about the discriminant of a quadratic?

still temple
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yeah

hushed egret
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for a perfect square, the discriminant must be 0

still temple
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ohhh yeah

hushed egret
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with this information can you try solving for k?

still temple
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yes

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ty

hushed egret
#

np

still temple
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i think i got it now

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thanks!

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hushed egret
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still temple
#

Can someone confirm if I am correct here, because the tangent lines would be horizontal?

still temple
#

And isn't 1 continuous but not differentiable?

safe badger
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just -2, 0, 1

still temple
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So none of the answer choices would work then.

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Did you mean -3?

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nvm

safe badger
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the derivative at x=-3 is just zero

still temple
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its the first choice

safe badger
#

ah

still temple
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thank you for your help

safe badger
#

np

still temple
#

/close

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/done

safe badger
#

.close lol

still temple
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.close

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paper herald
#

Are the local extremes and relatives the same?

marsh citrusBOT
#

@paper herald Has your question been resolved?

paper herald
safe badger
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Local extrema and relative extrema?

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I'm p sure it's the same thing just different wording

paper herald
#

synomym?

vital sphinx
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yes they are synonyms

paper herald
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a absolute valkue is f(x)?

vital sphinx
#

?

paper herald
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how i can find absolute value

vital sphinx
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absolute value makes any negative number positive

paper herald
#

absulute maxima or minima*

vital sphinx
#

oh

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f(x) = |x| has an absolute minimum at (0, 0)

paper herald
#

(x,y) x=is local and y=anbsolute?

vital sphinx
# paper herald absulute maxima or minima*

to find the absolute maximum or minimum of any function, first find all relative extrema and then you can put those x values into the original function
then the largest value is an absolute maximum and the lowest value is an absolute minimum

paper herald
#

okay thx

vital sphinx
#

no problem

paper herald
#

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dreamy swallow
#

how do i solve this

marsh citrusBOT
#

Please don't occupy multiple help channels.

dreamy swallow
#

i’ve been trying for a while but i don’t get it

#

<@&286206848099549185>

sleek reef
#

So we know that complementary angles add up to 90 degrees. And we know that opposite angles are equal. Given that angle 2 and 3 are equal and 1+2=3+4 we can conclude that 1=4

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sweet pagoda
#

How do I do this

marsh citrusBOT
wet holly
#

U allowed to use trig?

sweet pagoda
wet holly
#

Kool cus law of cosines is necessary

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I guess for starters do u remember anything about opposing angles of a cyclic quadrilateral

wet holly
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Ye

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So u can use that to solve for x

sweet pagoda
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i got x=13

wet holly
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noice

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Next u can draw a line from B to D, and radii from center to B and from center to D

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So if O is the center

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U have triangles ABD and OBD after making those line segmenta

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Oops

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And ye that's where u use law of cosines

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u can figure out <OBD by using <C

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I believe in u catthumbsup

sweet pagoda
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I don’t understand how there is a triangle obd

wet holly
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O B and D are three points

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Ur assuming they're collinear

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If that were the case then angle A would be 90

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cus line OBD would be a diameter of the circle

sweet pagoda
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can you show me how you would draw it

wet holly
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Err just draw the O a bit down so they don't end up in the same line ig

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It'll look like ur O is not at the center of the circle but

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Doesn't really matter :p

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alternatively u can draw D and B closer to A

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That would give u a more accurate picture but I just figured redrawing B and D would be more work bleakkekw

sweet pagoda
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when i draw them closer angle a looks bigger

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like greater than 90

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when it should be 78

wet holly
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oh wait oops ur right

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further then

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And actually I guess getting <DOB from <A would be easier

sweet pagoda
#

Something like this?

wet holly
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Yee

sweet pagoda
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so line bd would be 19.65

wet holly
#

yup

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actually wait why did I say yup

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I didn't do any calculations besides the angle bleakkekw

sweet pagoda
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lol

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where do i go from here

wet holly
#

law of cosines again hype

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but maybe a different triangle

sweet pagoda
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like cbd?

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but then i only have 1 side 1 angle

wet holly
#

,calc 14^2 + 17^2 - 21417cos(782*pi/360)

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Oh

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It uses radians I think

elfin berryBOT
#

Result:

19.647748857585
wet holly
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Not cbd

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u wanna solve for r or r^2

sweet pagoda
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obd?

wet holly
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Ye

sweet pagoda
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but wouldnt i still only have 1 angle 1 side

wet holly
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but the other 2 sides are equal

sweet pagoda
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oh right

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i got r=15.61 and area = 765.54 but thats not an answer choice

wet holly
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hmm lemme check

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,calc 14^2 + 17^2 - 21417cos(782*(pi)/360)

elfin berryBOT
#

Result:

386.03403517075
wet holly
#

,calc 386/(2(1 - cos(1562pi/360)))*pi

elfin berryBOT
#

Result:

316.86071513023
wet holly
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idk how u got 765 🤷‍♂️

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,calc 386/(2(1 - cos(782pi/360)))*pi

elfin berryBOT
#

Result:

765.47952433335
wet holly
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Oh

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U got angle BOD wrong

sweet pagoda
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oh

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i was using 78

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should it be 156

wet holly
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Yeah

sweet pagoda
#

ok i didnt know that bod was supposed to be double bad

sweet pagoda
wet holly
#

Np

sweet pagoda
#

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toxic flame
#

Are these complex limits correct? Ty and advance

toxic flame
marsh citrusBOT
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@toxic flame Has your question been resolved?

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@toxic flame Has your question been resolved?

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twin robin
#

Hi

marsh citrusBOT
twin robin
#

How is the reciprocal of this ( root 3 - root 2)^x^2-4

night turtle
#

Rationalisation

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Ok lets start with an easier example

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What is the reciprocal of sqrt3 + sqrt 2

marsh citrusBOT
#

@twin robin Has your question been resolved?

twin robin
night turtle
#

you want to make the denominator rational right?

twin robin
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Yes

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OH MB

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It must be 3 not root 3

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right?

twin robin
night turtle
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( sqrt3 + sqrt2 )(sqrt 3 -sqrt2 )

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= 3 - 2 =1

twin robin
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OH SHIT

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Right

night turtle
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remember (a+b)(a-b)= a^2-b^2

twin robin
#

I cancelled out 2's idk why i will write it down from next time

night turtle
twin robin
#

as we do not know the x value

night turtle
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the denominator would be 1^(x^2-4)

twin robin
#

Oh

night turtle
twin robin
#

aight thank you!

#

also there's one more question

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do i ask here or

night turtle
#

sure

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ask here

twin robin
#

so in here when i tried to solve it by adding the terms

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One could've use made sequence

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But i'm confused with sequence

twin robin
night turtle
#

hmm you should think about the perfect squares

twin robin
#

Yes

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i did thats the did i get

night turtle
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oh

twin robin
#

but if i do that it will be very calculative

twin robin
#

OH NVM

#

I got it

#

1x3 + 2x5 + 3x7+4x9+...

#

Thanks!

#

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still temple
#

im confused on what to do on questions 2.1.2 2.1.3 and 2.1.4 i more or less have evrything else figured out

marsh citrusBOT
#

@still temple Has your question been resolved?

still temple
#

<@&286206848099549185>

blazing robin
#

For range just notice what y values the graph occupies

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For period take the distance, horizontal, b/w crest and peak and double it

still temple
still temple
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still temple
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.close

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boreal bramble
#

hi

marsh citrusBOT
boreal bramble
#

im very confused at this question

#

so when I tried to solve this question myself I got pi(20^2*d)

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beacuse why on earth would u square a day?

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it says to multiply by day for each day it grows but never mentions squaring

still temple
#

your radius isnt 20, its 20d
you square the radius and multiply it by pi.

boreal bramble
#

OHH

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thats very true

boreal bramble
#

I didnt realize they were connected by the variable as well

#

forgot to take that in account

#

thanks so much brother!

still temple
#

np

#

if you don't need further help send ".close"

boreal bramble
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.close

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still temple
#

*The Li'enard equation is [
\dnv 2[u]t + \map c u \dv[u]t + \map g u = 0
]
where $g$ satisifes the conditions $\map c u \ge 0, \map g 0 = 0, \map g u> 0\tss{for} 0 < u < k, \map g u < 0 \tss{for} -k < u < 0, u\map g u > 0 \tss{for} u \ne 0 \tss{and} -k<u<k$

\vs{4 mm}
Show that the point $u = 0, \ff{du}{dt} = 0$ is a stable critical point

elfin berryBOT
still temple
#

i was able to determine its a critical point

#

idk how to determine its stable tho

marsh citrusBOT
#

@still temple Has your question been resolved?

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#

@still temple Has your question been resolved?

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@still temple Has your question been resolved?

marsh citrusBOT
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molten ferry
marsh citrusBOT
molten ferry
#

shouldn’t a2=(12-30m)/3m instead of (30m-12)/3m

still temple
#

A trick to find acceleration for the syste

#

is

#

A = M1(on the surface) times gravity / M1+M2

#

where m2 is the box on the pulley hanging down

molten ferry
#

i’m just confused on why it’s 12-30M and not 30M-12

#

.close

marsh citrusBOT
#
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somber iris
marsh citrusBOT
somber iris
#

Both my question and answer are written.
There's no solution given solution, so I wondered if this would be considered correct.

Do note that this was a basic exercise in an introductory book to analysis, so I'm not sure how rigorous I'm supposed to be

sleek lake
#

you could just prove that the average would work for z

#

that it's not equal to x, or less than x or equal to y or more than y

silver gazelle
#

Please

#

ITS KILLING ME

#

PLEASEEEEEE SAVE ME

graceful pewter
#

find another channel

sleek lake
#

also delet please

#

i don't know if yours is wrong, but proofs are never like this

#

like it reads to me like you stated the same thing

graceful pewter
somber iris
#

yeah I'm pretty new to the whole proof thing, so I'm not really sure how I should go at it.

How would I prove it for the average?

sleek lake
#

like
(x+y)/2 ? y
x + y ? y + y

#

what i want to say is that proofs can ask you for obvious things, but they don't expect you to state it right back

#

you gotta like do induction, or construct something

graceful pewter
#

yeah nvm x < y => existence of an open interval containing elements between x and y is just restating the same thing but using the definition of an interval

somber iris
#

so for this one I basically just have to say that for those given x and y, if you add them up and divide by 2, you'll get a number which is bigger than x and smaller than y (basically just the average)

Would that be it, like would that be considered correct?

sleek lake
#

it would be correct

#

it's convincing

graceful pewter
#

also mention why the average is in R

sleek lake
#

but ideally you have to do guess what's intended to be the answer 🙂

somber iris
#

to mention why the average is also in R, would it suffice to say that any 2 numbers in R added and divided by another number in R (except 0) is going to end up being another real number, or is there some other thing I'm not aware of?

graceful pewter
#

yeah thats it

somber iris
#

ait dope, thanks for the help, proofs are really confusing

#

.close

marsh citrusBOT
#
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silver gazelle
#

PLEASEEEEE

marsh citrusBOT
#

Please don't occupy multiple help channels.

desert dirge
#

gotta calm down
what have you done

silver gazelle
#

Help

#

Me

#

P

#

P

#

Please

desert dirge
#

tell me what youve done, or what you dont understand, then i can help

silver gazelle
#

Its so many numbers

desert dirge
#

theres only two numbers in that question

silver gazelle
#

Wait

desert dirge
#

ig the main thing is converting 2.67kg to grams, but after that, just use the given formula

silver gazelle
#

I love u

desert dirge
#

thanks

silver gazelle
#

Ok well now im def stuck

#

Like i thought

#

And now im just straight tripping on air

desert dirge
#

what did you try for (a)

silver gazelle
#

I got it wrong

#

I forgot what i put but what i did was

#

I multiplied 1.67 x 10-24 but 3

#

then added it w the nitrogen

desert dirge
#

and got?

silver gazelle
#

7.33 x 10-47

#

I think i might know

#

Where i went wrong

#

But B confuses me most

desert dirge
desert dirge
#

oh

#

you do not just add the exponents

silver gazelle
#

Ye

#

I clocked it now

#

I gotta make it into -23

desert dirge
#

whats your new answer

#

the 7.33 is wrong too

silver gazelle
#

Ye

#

Wait

#

52.42x10-23

desert dirge
#

no

silver gazelle
#

Fuck sake

#

Idk what my guy is setting me bro

#

He doesnt teach me dis

desert dirge
#

$3(1.67\times 10^{-24})+2.32\times 10^{-23}$

elfin berryBOT
#

AℤØ

desert dirge
#

is all you need to calculate

silver gazelle
#

Yup cheers

#

Step closer now

desert dirge
#

as for b, you know how many grams a single molecule is (a), so how would you find how many are in 1 gram

marsh citrusBOT
#

@silver gazelle Has your question been resolved?

marsh citrusBOT
#
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bitter turtle
#

Hello! I'd like to ask about linear algebra.

bitter turtle
#

That's the question (the second one)

#

So far, I have used Holder inequality to get

#

$$\max_{i\in{1, \dots, m}}|a_i|_q$$

elfin berryBOT
#

Memiya#9800

bitter turtle
#

Not sure how to type norms

#

But it's basically the largest q-norm of the row vectors

#

But now I need to show that this is equal to the norm

#

It is more or equal to it

#

I was advised to use the equality condition of the Holder inequality to find an x vector that selects that largest row.

#

But I don't really know how to approach that part

#

Some kind of ratio...

#

But that's not the part of Holder inequality I used for the first inequality

marsh citrusBOT
#

@bitter turtle Has your question been resolved?

marsh citrusBOT
#

@bitter turtle Has your question been resolved?

marsh citrusBOT
#

@bitter turtle Has your question been resolved?

marsh citrusBOT
#

@bitter turtle Has your question been resolved?

marsh citrusBOT
#

@bitter turtle Has your question been resolved?

marsh citrusBOT
#

@bitter turtle Has your question been resolved?

bitter turtle
#

. close

#

.close

marsh citrusBOT
#
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marsh citrusBOT
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sudden cape
sudden cape
#

ill translate if you need help with translation

vernal forge
#

just send screenshots

sudden cape
#

k

#

ill translate it

#

If one of the roots of the equation is 5, then the other result is
a: a prime number
b : a perfect cube
c : divisor of 48
d: a perfect square
e : a multiple of 3

vernal forge
#

okay

#

do you know what the sum and the product of roots equal to?

sudden cape
#

yh

vernal forge
#

what are they equal to?

#

assume the other root is x. thus, what are 5x and x+5 equal to?

sudden cape
#

i dont get it

#

like

vernal forge
#

do you know vieta's theorem?

sudden cape
#

i dont

vernal forge
#

idk what it's called in your school

#

but it basically says that if you have an equation x^2+bx+c=0, then the roots x_1 and x_2 create this system:
x_1+x_2 = -b
x_1*x_2 = c

#

your x_1 is 5

#

what are your b and c?

sudden cape
#

i know this theorem

vernal forge
#

good

sudden cape
#

x and a

vernal forge
#

that's okay

#

just let a be some number and do the same operations as you would've done with regular numbers

sudden cape
#

the b would be 2 and the c would be 11 then

vernal forge
#

nope

#

but close

sudden cape
#

hm

vernal forge
#

you are solving this equation with respect to x. that means that you don't care about the value of a (yet) and treat it as a constant

vernal forge
sudden cape
#

b would be -a

vernal forge
#

yes

#

correct

sudden cape
#

but how come the c is 2a+11

vernal forge
#

a quadratic equation has 3 coefficients: one in front of the x^2 term, one in front of the x term, and one constant

sudden cape
#

oh i get it

vernal forge
#

awesome

sudden cape
#

the c is more "flexible"

vernal forge
#

yes

#

therefore, you have:
5+x = a
5x = 2a+11

#

you should be able to solve this system

sudden cape
#

quick question, what does * mean

vernal forge
#

where do you see it?

#

multiplication, most likely

sudden cape
#

here

vernal forge
#

ah

#

yes, multiplication

sudden cape
#

k

vernal forge
#

$x_1 x_2 = -b$

elfin berryBOT
#

artemetra

sudden cape
#

a is 12

#

so

#

its a prime number

vernal forge
#

yes

#

correct

sudden cape
#

hooray

#

thanks

vernal forge
#

np

sudden cape
#

can i get more help?

vernal forge
#

okay

sudden cape
#

the sheet i sent that is unavailable has content of the next year (for me)

#

thats why im having trouble

#

The numeric value of this expression, for x = 999 equates to

vernal forge
#

factor both numerator and denominator

sudden cape
#

k

#

(x-1)(x+1)
x(x+2) + 1

#

i kinda forgot how to do that

#

properly

vernal forge
#

hint

#

(a+b)^2 = a^2 + 2ab + b^2

sudden cape
#

(x+1)^2

#

(the denominator)

#

so i substitute the x for 999?

vernal forge
vernal forge
sudden cape
#

k

vernal forge
#

notice that you have $\frac{(x-1)(x+1)}{(x+1)^2}$

elfin berryBOT
#

artemetra

vernal forge
#

can you cancel anything?

sudden cape
#

i can cut the (x+1) on the numerator

#

(x-1)/(x+1)

vernal forge
#

yes

#

now sub 999

#

and you are done

sudden cape
#

998/1000= 0,998

#

tysm

#

this is the next one
X is the smallest natural number that makes the square root 1080 times x have an exact value
X is a
a: prime number
b : multiple of 15
c : divisor of 100
d : perfect square
e : perfect cube

is there a way to solve this without "brute forcing" ?

#

nvm i got it

#

i need help with this one
translating:
Elevating by cube both sides of the equation and developing it correctly, we reach the conclusion that x^2 + 1/2^2 equals
a : -1
b: 2
c : -2
d: 1
e: 3

vernal forge
#

well, cube x+1/x

#

what do you get?

sudden cape
#

x^3 + 1/x^3

vernal forge
#

no

#

use this

#

a = x, b = 1/x

sudden cape
#

that's new for me, ill try

vernal forge
#

simplify

#

3x^2 * 1/x

sudden cape
#

how do i simplify that

#

wait

sudden cape
sudden cape
sudden cape
sudden cape
#

wait a sec

vernal forge
#

hm

#

maybe the question has a typo

#

and they meant square both sides

#

if they meant square both sides, the question makes more sense but idk

#

and the answer would be d) 1

sudden cape
#

the answer sheet says its b) 2

vernal forge
#

huh

#

okay

sudden cape
#

ill skip this one

#

the next one has geometry content that i haven't learned still
but i do have knowledge about basic operations with rectangle triangles

#

the triangle ABC is rectangular on A, if BH = 9 cm and the area of the triangle ABH is 54 square cms, the area of the triangle ABC is
300 square cm
150 square cm
96 square cm
144 square cm
192 square cm

fleet fossil
#

No need to cube

#

Just square

sudden cape
#

weird it says "cube"

#

glad you found the solution, ty

sudden cape
#

and the pythagoras theorem

#

nvm i manage to do it

#

all i had to do was 54 = 9.m/2

#

didnt realize

#

Can someone help me find the area of this circle

Each square has 16 centimeters

marsh citrusBOT
#

@sudden cape Has your question been resolved?

sudden cape
#

need help

grim void
#

is the ans 100pi

#

?

sudden cape
#

yea

grim void
#

ok so what u have to do is take TO as r(radius of circle)

#

and the point from O to the point on line EF will become 16-r

#

also OE will be equal to r

sudden cape
#

i see

grim void
#

and EF will be equal to 16

#

use pythagoras and u get r

sudden cape
#

why is that so

grim void
#

let me show it on drawing

sudden cape
#

k

grim void
#

here

sudden cape
#

ok ok

#

how am i supposed to do the Pythagoras theorem now tho

#

i have EP^2 + (16-r)^2 = r^2

#

i dont know either ep or pf

#

only op and oe

#

nvm i do know

#

ep/pf = 8

#

Thanks for the help

#

Does anyone know how to calculate the area of a parallelogram with different sides?

#

All I have to do is calculate the area of the blackened part

#

But the sides have different sides (2, 7, 9, 6 centimeters)

#

I tried dividing the parallelogram into 2 triangles

#

Then calculating the area of each, then adding them up

#

But it didn’t work

marsh citrusBOT
#

@sudden cape Has your question been resolved?

grim void
#

Can u pls share the question

sudden cape
#

nvm i already did it

marsh citrusBOT
#

@sudden cape Has your question been resolved?

marsh citrusBOT
#
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wide summit
marsh citrusBOT
wide summit
#

Okay

late salmon
#

oops mb

wide summit
#

Then

#

No

#

Problem

#

I'll move

late salmon
#

nah i did

hollow sparrow
#

you already have this thread, don't move

wide summit
#

Ok

#

So I'm stuck on this proof , in the case where n is prime it follows by theorem however when n is not prime I can't seem to find any manipulations to show it

#

This is my new line of thought

#

But u have already expanded modulo and tried setting out the definitions to desried result

#

I

#

I wonder then if it's false as that's a possibility

#

For the q

#

And requires a counter exmp

vernal forge
#

you can try going from the definition of mod

onyx reef
#

if n divides b(a-b), then either the RHS is 0 or a multiple of n

onyx reef
#

so you must have either n divides b or n divides (b-a) right

wide summit
#

Thanks Elliot

marsh citrusBOT
#

@wide summit Has your question been resolved?

#
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last cliff
#

mean value theorem kicking my butt again. is this just asking for what f'(c) is equal to?

crisp mortar
#

HELP

#

HELP

#

e^(iπ) - 30 + 208x - 2 + 4x (2x) + (9x) ∫₀ˣ dx = x - x²/2 + x³/3 - x⁴/4 + 4 + (-1)ⁿ xⁿ⁺¹ / (n + 1) + 8 x 2

still vortex
#

...

crisp mortar
#

pleas e

#

i beg you

trim quest
marsh citrusBOT
last cliff
#

um.

crisp mortar
#

i just need help with this question

#

i dont understand it

still vortex
crisp mortar
#

fuckin help dawg

#

i need help

last cliff
#

okay thank youu

trim quest
#

@crisp mortar Stop spamming other peoples' channels

still vortex
crisp mortar
last cliff
#

for this one, how would i approach this?

marsh citrusBOT
#

@last cliff Has your question been resolved?

last cliff
#

<@&286206848099549185> !

#

sorry for the ping

marsh citrusBOT
#

@last cliff Has your question been resolved?

#
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elder wolf
#

Hi, can anyone help me with this vector question. Im congused as to how the two lines can be contained in the plane, as they don't have the same direction. Should I just do cross product? Thx

desert dirge
#

lines dont have to be parallel to be in the same plane

#

but doing the cross product of the direction vectors will get you the normal vector of the plane yeah

elder wolf
#

oh yh, now that i think about it, ig it makes sense

#

what about this one, idk how to find the point of intersection

night mica
#

why do you mark the first one =

elder wolf
#

because it was the right cross product

night mica
#

ok so intesection of 2 planes its ofetn a line

#

now a line is given by a starting point and a direction vector

#

the direction vector is the solution of this linear system

#

you can do elementary row operation to simplify the system and get the solution

marsh citrusBOT
#

@elder wolf Has your question been resolved?

elder wolf
#

when i put z to 0, to solve x and y, it doesnt give me the values I want for x and z

marsh citrusBOT
#
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kindred obsidian
#

where does the +1/3 come from?

marsh citrusBOT
desert dirge
#

the lower limit was 1

#

(upper)-(-1/3)

#

(upper)+1/3

kindred obsidian
#

ohh of course I was so hell bend on why it was positive I totally missed the -

#

ok yeah simple answer thanks

#

.close

marsh citrusBOT
#
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sharp mauve
#

where does the -12 come from? i get +12 when intergrating

sharp mauve
#

.close

marsh citrusBOT
#
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past flicker
marsh citrusBOT
past flicker
#

Need help understanding why my answer doesn’t match the real answer

past flicker
#

I don’t think that works

#

This is probably a geometric series

dapper hollow
#

I see. but 3 < 13^(1/2)

#

you can use a = 1 and r = 3/sqrt(13)

past flicker
#

Ah okay

#

That worked

#

Thank you

#

.close

marsh citrusBOT
#
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shy urchin
marsh citrusBOT
shy urchin
#

can someone help me check my work on part 1a

#

I think the answer is {b,c,d,e,g,h}

#

but im not sure what proper set notation is

#

or if the answer is even correct

spark otter
shy urchin
#

1a

#

sorry lol

#

i know the symbol means A does not intersect B

#

i think

spark otter
#

if that is what you meant

shy urchin
#

yeah

#

{b, c, d, e, f, g, h}

spark otter
#

so did you find A intersect B?

spark otter
shy urchin
#

lol missed a value

#

but the issue i have is

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proper set notation

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im not sure how thats supposed to look

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any ideas?

spark otter
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what do you mean by proper set notation?

long osprey
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It clarifies in the question

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separate with commas, don't list things twice

spark otter
long osprey
#

(use curly brackets)

shy urchin
#

ohhh ok got it

#

thanks guys! i appreciate it!

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clever raven
marsh citrusBOT
clever raven
#

i need to prove that f'(pi)+f'(0)=0

still temple
#

Expand the integral

clever raven
#

I expanded and did parts on both terms

spark otter
#

It might be easier to show your work so we can find if there's a problem

clever raven
#

Sry for the caligraphy im an ape

spark otter
#

derivative of cos(x) is...

clever raven
#

-sin(x)

spark otter
#

yes

clever raven
#

Oh i made a mistake with the signs?

spark otter
#

yes most likely

#

there shouldn't be a -2int(...) it should be 0

clever raven
#

thankyouuu 🙂

spark otter
#

you most likely did -1 -1 instead of -1 -(-1)

clever raven
#

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shy urchin
#

i just finished these problems, can someone check it for me please!

shy urchin
leaden monolith
#

Do you have reason to believe you’re wrong?

shy urchin
#

uhh for all of 1, i just wanted to double check

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for 2 its because im not very confident

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like at all lol

leaden monolith
#

2’s correct

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But if I’m pedantic I’d say A = 1, 2, 3 is not a set

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Missing curly brackets from the question

shy urchin
#

oh gotcha!

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any input on 1?

leaden monolith
#

Looks good as well

shy urchin
#

awesome! thank you so much for your help! I really appreciate it

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thorny jungle
marsh citrusBOT
thorny jungle
#

I have having some trouble finding this limit

night mica
#

mh... do you want the exact value of that series ?

thorny jungle
#

Oh no.

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I just wanna see if this converges or diverges

night mica
#

$|n^2+i^n|>|n^2|-|i^n|=n^2-1$

elfin berryBOT
night mica
#

hence $\frac{1}{|n^2+i^n|}<\frac{1}{n^2-1}$

thorny jungle
#

let me think

spark otter
#

but yeah ok

long osprey
night mica
#

fafilou do you know morphism between algebraic varieties ?

spark otter
night mica
#

ok ok ... just study the absolute convergence (that imply convergence )

elfin berryBOT
long osprey
#

(don't mean to be aggressive I think it's important to make things like this as explicit as possible when trying to teach to avoid questions about notation and make it clearer what our potential goal is)

night mica
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whotao ...everyone are writing except you xD

spark otter
night mica
#

i am a little bit tired

night mica
thorny jungle
night mica
#

you want to prove convergence ... now we're going to prove something stronger, which is absolute convergence

#

so now the problem becomes $\sum \frac{1}{|n^2+i^n|}$

elfin berryBOT
night mica
#

$$\sum \frac{1}{|n^2+i^n|}<\sum \frac{1}{n^2-1}$$ where the last series is convergent

elfin berryBOT
thorny jungle
#

I see.

#

I got it, thanks.

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marsh citrusBOT
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gloomy salmon
marsh citrusBOT
gloomy salmon
#

ive asked like 4 people

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and none could help but

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realized we only add max once so it should be 3 + 3.75

#

nvm i just solved it lmao

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humble river
marsh citrusBOT
#

Please don't occupy multiple help channels.

humble river
#

sry i close

#

Do i have to plug in points

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To graph like this one

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like -2 -1 0 1 2

brave marsh
#

If you plug in a really big number into x^2, what do you expect to get?

humble river
#

like

stoic saddle
brave marsh
#

In terms of like big, small, negative, positive

humble river
#

oh

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But part of the question they want the graph

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but i will get positive number

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big positive number]

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infinity

stoic saddle
#

you sure?

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-x^2 is negative and x^2 - 9 is positive

humble river
#

-1000^2

stoic saddle
#

their product is negative surely

humble river
#

ohhhhh

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-(5)^2

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like thjat

#

okkkk

lone heart
humble river
#

oh soo same thing

#

Ok

lone heart
#

All the questions you've been asking, applies the same concept

humble river
#

yes it just get harder

lone heart
#

Describing the end behavior and graphing

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If you can figure out part a, you use part a for part b

humble river
#

So this concept

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I will never need to know what graph look like

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I can just do the first part and im good

lone heart
#

You should know the general shape too

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Like a quadratic vs x^4 graph

humble river
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yes have that big U shape

lone heart
humble river
#

Ok perfect thnxs

marsh citrusBOT
#

@humble river Has your question been resolved?

humble river
#

hi

#

i did the elimination method but this time it is a different scenario i ask in new channel since this 1 inactive

#

.close

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fair pagoda
#

Pretty sure i did this correctly can anyone double check

late geode
#

can you show work

fair pagoda
fair pagoda
late geode
#

what's the stuff before that

fair pagoda
late geode
#

seems alright

fair pagoda
#

Ty

#

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hexed veldt
#

please help with if that's correct and where to go from here

late geode
#

determine slope at the specified point

hexed veldt
#

how do I do that?

fervent rampart
#

slope at a given point x = a is f'(a)

late geode
#

recall the relation between derivatives and slope, (why you're even taking the derivative in the first place)

hexed veldt
#

idk is this right?

late geode
#

work is unfinished, missing value at the very end

#

why do you have
y = 3x + [blank space]

hexed veldt
#

oh y=3x+1?

late geode
#

yes

hexed veldt
#

thank u so much!!

#

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obtuse mural
#

I dont get this simplification at all

marsh citrusBOT
obtuse mural
#

this is the full answer to the question on proving by induction for Fibonacci:

#

can anyone help me?

earnest sundial
#

$2^{(n-1)/2}2 = 2^1*2^{(n-1)/2} = 2^{1+(\frac{n-1}{2})}) \geq 2^{\frac{n+1}{2}}$