help-33

[sharp vessel]

Well, there is motivation behind it

You take the right hand side,

and you want to show it equals the left hand side, which has a square root

Therefore by doing that, you "make" a square root appear and you can just continue simplifying the inside until you get (1 - cos(x))/(1 + cos(x))

[chrome thistle]

so the addition of the squr and squ was to make them same to summarize

[sharp vessel]

kinda

[chrome thistle]

okay thanks....

[sharp vessel]

also, this identity is only true for certain values...

kind of a faulty question

[chrome thistle]

what about this one?

i was trying to understand where did 1/2 came to be

[sharp vessel]

look in the red

they write 1/2 * 2

which is just 1, therefore this doesn't change the value again

they do this to add a factor of 2, which lets you use the double angle identity

[chrome thistle]

was it also to make up for the equal they are suppose to be?

Thanks man

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[marsh citrus]

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[sullen ice]

How do I do this

[still temple]

You already have one channel?

[sullen ice]

I deleted the message by accident

[still temple]

Yeah yeah nvm

Go on

[sullen ice]

Well I showed my work for at least how to get a but it says it's wrong so idk

Which means the coefficients for s will be wrong

<@&286206848099549185>

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@sullen ice Has your question been resolved?

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@sullen ice Has your question been resolved?

[sullen ice]

On my way to the bottom 🫡

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[vagrant sky]

this is what i got for my answer but its incorrect

this is my work for my answer

i am using trig sub

[marsh citrus]

@vagrant sky Has your question been resolved?

[vagrant sky]

help

[marsh citrus]

@vagrant sky Has your question been resolved?

[vagrant sky]

anyone good with trig sub integrals

[marsh citrus]

@vagrant sky Has your question been resolved?

[open relic]

Hello!

Mmm it's not really necessary to use trig sub for this one 🤔. Anyway let me check, it should lead to the same answer

Ok I think I see it

[open relic]

secant is √(x²+4)/2. When you substitute that in the final integral, you should get
(√(x²+4)/2)³
= (x²+4)^(3/2) / 2³

Just so you know, the optimal way is probably using sub with u=√(x²+4). Anyway, you know a lot of trig substitution which is important for problems more difficult than this one

[marsh citrus]

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[vagrant sky]

thanks

[marsh citrus]

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[carmine scroll]

how do you solve ii

[olive swift]

Are you familiar with Sum of zeroes, Product of zeroes etc?

Oh you are asking for the 2nd one

Are you there?

[carmine scroll]

yes

[carmine scroll]

what i do now

[olive swift]

take alpha common

[carmine scroll]

factorise

???

beta and gamma equals 12

alpha 3

[olive swift]

how did u get that

i didnt try the sum yet i cant say your answer is right or not

but i know what the procedure is

so maybe show your work

[marsh citrus]

@carmine scroll Has your question been resolved?

[carmine scroll]

done now

[olive swift]

Yep correct till now

Substitute alpha = 3 in the a^2 + b^2 + c^2 = 83

and you know b+c=12

we can convert it into a quadratic again

you will get values of the other roots and done

[carmine scroll]

for y i get

[carmine scroll]

my answer is not correct can you please try it

[olive swift]

uh should i tell you what answer i got?

or explain?

[carmine scroll]

this is answer

[olive swift]

yes a=3, b=7, c=5

actually yeah you dont have to find the roots

[carmine scroll]

what i do now

[olive swift]

?

[carmine scroll]

what i do now

[olive swift]

you know beta + gamma = 12 right

[carmine scroll]

yes

[olive swift]

alpha = 3

yes?

[carmine scroll]

yes

[olive swift]

here substituting alpha = 3 we get beta^2 + gamma^2 = 74?

[carmine scroll]

yes

[olive swift]

now we can put beta = 12 - gamma and substitute that here

or simply do trial and error

we realise that beta = 7 and gamma = 5 works?

49 + 25 = 74
and 7 + 5 = 12?

So now the roots are 3,5,7
And POZ for a cubic equation is -constant term/leading coefficient
which is -r/1 = 3x5x7
hence r = -105

Sry i gtg

[marsh citrus]

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[steep vapor]

dumb question maybe, but where do the 5 and 4 go to?

[restive sun]

they were multiplied into the brackets here

that would definitely be clearer on a separate line by itself

[steep vapor]

thank you!

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[quaint arrow]

in the 3D plane, a geometric object defined by x = (x value) and y = (y value) is a line that goes through the point (x, y, 0) and is parallel to the z plane, right?

[quaint arrow]

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[merry kelp]

anyone able to help me from here?

[marsh citrus]

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[long cape]

32/3 is correct, but B is not

trying to figure out why...

[main idol]

What's x_i?

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[jovial cobalt]

is this saying if two circles have the same center point they are the same

[pale agate]

no

[static quarry]

it's saying that S_3 is the set of all such circles

with the specific center point (0,0)

[jovial cobalt]

im trying to find if the set is pairwise disjoint

[static quarry]

you mean, are every pair of such circles disjoint if they are not the same circle?

[jovial cobalt]

pairwise disjoint if, for all A, B ∈ S, if A ∩ B is inhabited, then A = B

[static quarry]

right

well, do you have any thoughts about whether it's true in this case?

[jovial cobalt]

i think it is true

wait no

what am i saying

different size circles can have the same center points

[jovial cobalt]

i dont think its true?

[static quarry]

can you give an example of two such circles that are not disjoint?

[jovial cobalt]

or wait wouldnt one circle be contained in another

so their intersection is non empty

[jovial cobalt]

they are disjoint

[static quarry]

i don't follow your logic

the goal is to check whether there are two distinct circles C1 and C2, such that their intersection is nonempty, right?

[jovial cobalt]

yes

[static quarry]

can you give an example of two such circles?

[tall night]

think concentric circles

[jovial cobalt]

yes

this will have an inhabited intersection

all the circles

[tall night]

correct, which should be the region of the circle with the smaller radius, if you are only taking two circles into account

[jovial cobalt]

yes

because it excludes the points outside of the smaller circle

but it doesnt mean that the two circles are equal

[tall night]

yeah

they are not necessarily equal

[static quarry]

wdym by this

two circles with different radii and the same center are disjoint

are you maybe thinking of disks instead of circles

[jovial cobalt]

Oh wait bc circles have no are?

Area ?

No wait

Yeah idk the difference between thinking of it as a circle VS disk

[static quarry]

the circle is the boundary, the disk is the region inside the boundary (including or excluding the boundary depending on whether you're talking about the open disk or the closed disk)

that said, people sometimes loosely talk about "circle" when they mean "disk", like "area of the circle is pi times r^2"

so maybe best to determine which is intended in this question

[jovial cobalt]

I think circle

I know circle

[jovial cobalt]

Why

[static quarry]

well let's take two such circles, both with center (0,0), one with radius R1 and the other with radius R2

the first one is the set of points (x,y) such that
x^2 + y^2 = R1^2
the second one is the set of points (x,y) such that
x^2 + y^2 = R2^2
Now, if there was some (x,y) in both of them, then you would have R1^2 = R2^2

hence R1 = R2

hence they are the same circle

[jovial cobalt]

Okay rhat makes complete sense

So I would have to prove with any arbitrary points right

[marsh citrus]

@jovial cobalt Has your question been resolved?

[jovial cobalt]

thank you for clairifying, i know how to prove it now

[marsh citrus]

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[still temple]

what am i doing wrong? i've searched the solutions up on google but it has different answers from what i got from solving both equations + the explanation shown on google is complicated and i want to learn how to solve these types of problems without necessarily searching it up

[zenith escarp]

on the first pic it should be 4x/20

[marble glacier]

x/5 != 5x/20

first line

[still temple]

yes ive tried that

[zenith escarp]

might be why it came out weird

[still temple]

is on the picture

hold on let me check

[marble glacier]

No

[still temple]

its*

[marble glacier]

Im saying

!= is not equal

x/5 is not equal to 5x/20

[still temple]

ohh

[zenith escarp]

try it with the 4x/20 instead

[still temple]

sure but can i have an explanation for that since im a bit slow

[zenith escarp]

yea sure i dont mind dw abt it

[still temple]

thank youu

[zenith escarp]

so yk we have to make common denominators right? becuase you did it. so when you tried to make the denominators 20 you accidently made the x/5 5x/20 when it should be 4x/20 becuase you have to divide the x/5 by 4/4

[still temple]

OHHH

oh my god that was such a weird mistake thank you so much!!

[zenith escarp]

yea dw this kinda stuff happens to me all the time

[still temple]

yeah ty 😭 you're a life saver

[zenith escarp]

yea np

[still temple]

if anyone can walk me through the second pic that would be great ^^

do i have to turn the whole numbers into improper fractions and get common denominator for all of the numbers?

[zenith escarp]

oh lmao thought the second pic was the same problem

lemme look at it

[still temple]

thanks ^^

[zenith escarp]

where did the 15x/3 come from

and the 3x/4

what did you do?

[still temple]

so i asked my friend for help before and she told me that i had to multiply 5x/3 by 3 to isolate the variable

so i did that and multiplied x/4 by 3 as well

[zenith escarp]

yes but not like that

[still temple]

hmm

[zenith escarp]

you have to do it like this 1 sec

3(5/3 - 2) = (x/4 +15)3

[still temple]

so i multiply the entire side?

[zenith escarp]

you have to also multiply the other numbers

[zenith escarp]

yes you have to make it even

[still temple]

ohh okay ty ill try that right now

[zenith escarp]

yea np

ping me when you are finished

[still temple]

kk

excuse my messy handwriting but i think i got it right !! @zenith escarp

[zenith escarp]

lmao you did it again

[still temple]

oh my god

[zenith escarp]

when you were making common denos you didnt do it with the 51

[still temple]

this is gonna be my 13th reason why

ohh right

😕 let me solve it again

[zenith escarp]

okay gl

[still temple]

okay as in making common denominators do you mean i should turn 51 into 612/12

just asking because thats what i interpreted but it doesn't sound right

[zenith escarp]

oh wait ur right

so yes 12 should be the answer i apologize for my stupid moment

[still temple]

oh it's okay 😭

thank you for helping though

🫶

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[long cape]

i got everything correct except for f(x) = sqrt(8+x)

any help or suggestions, would be very much appreciated

should it really be f(x) = √(x+1)?

<@&286206848099549185> sorry to ping, just need to answer this one final question for tonight

it's my last chance, have already used 2/3 tries

(WebWork)

I'm pretty sure it's f(x) = sqrt(x+1) but just want to double check before locking it in

https://tenor.com/view/who-wants-to-be-a-millionaire-john-carpenter-life-lines-stinking-life-lines-gif-3471636

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[vernal sentinel]

how can i find if f is continuous from a piecewise function in a time efficient way?

[vernal sentinel]

https://gyazo.com/6181c17f5ece38040733080a7c7674a7

[marsh citrus]

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@vernal sentinel Has your question been resolved?

[tiny bear]

What do you usually do?

[marsh citrus]

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[stable fox]

Need help with this I keep messing up the second part, and I have one attempt left at this assignment

the answer I was able to reach is 0.9772215716s

it seems right, but I gotta check

this is the way I tried to solve it

[marsh citrus]

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[still temple]

Is there any difference between these two ?$$ 2n! $$ and $$(2n)!$$

[elfin berry]

What should I do

[teal bramble]

yes

[devout mauve]

the image quite clearly shows the difference

without needing a graph

2*4! is 2*24

(2*4)! is 8!

[desert saddle]

does anyone know remainder theoram

[still temple]

yes

[still temple]

If the remainder of dividing a polynominal by another polynomial is zero

[desert saddle]

can complete a or b

without long division method

[still temple]

then the polynomial you divided by is a zero factor

I advise you to never use long division

Synthetic division is way easier

[desert saddle]

ok

but its not mentioned in my book

[still temple]

google or look it up on youtube

get a better book

[teal bramble]

in math, never is a bad word

u can use long division

[still temple]

You can also stand in the middle of the highway

not good ideas

[desert saddle]

\

[teal bramble]

bro

hahaha

[flint jolt]

But why u need to divide

Its only asking for remr.

[teal bramble]

thats the task

[still temple]

They have to divide to find the remainder

[flint jolt]

No just use remr theorem

[still temple]

dividing is easier than evaluating the function

anyways

My question has been answered

[flint jolt]

Small values here

[still temple]

TY

[teal bramble]

and also

[still temple]

.close

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[autumn hinge]

am i crazy? I feel like this should be really easy

.close

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[chilly nova]

I need help

[chilly nova]

How do i do these 2 questions

[marsh citrus]

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[wheat haven]

I just need some clarification of what this problem is asking

[wheat haven]

Specifically the second part

The first part I showed and I do not believe I have any errors since I found what was being asked. The second part I am having issues with since I am not sure how I am supposed to end up with (a+b)/2

[proper zodiac]

Youre misremembering how the moment generating function can give you the expectation

[wheat haven]

Should I turn that into a regular f(x)?

I do have in my notes about the Inversion formula that I could use. Then once I have a standard function, I could create the integral to find E(X)

[proper zodiac]

No there is a direct formula relating φ and E[X]

It's similar to what you've done you're just missing something

And I think its important that you realise what it is yourself

[wheat haven]

Of course! I will keep looking in my notes to see if I can find it!
Thank you!

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[lyric bay]

.Hello

[still temple]

Is there a better way of solving this problem?

[marsh citrus]

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[marsh citrus]

@spice depot Has your question been resolved?

[spice depot]

<@&286206848099549185>

[crystal sand]

Hint: Try calculating f(1-x).

[spice depot]

(3^(1-2x))/(3^(1-2x)+1)

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[crystal sand]

.

Write that in form of powers of 9.

Also, doesn't seem like you did it correctly.

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[quaint arrow]

any equation of y = A where A is some real number will always be a plane that is perpendicular to the z axis in a 3d coordinate plane, right?

[quaint arrow]

.close

[marsh citrus]

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[static quarry]

!status

[marsh citrus]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[humble crescent]

1

[static quarry]

do you know how to find a line that is perpendicular to those two?

[humble crescent]

No

[static quarry]

do you know about cross products?

[humble crescent]

I just googled it

Cross product is zero vector if perpendicular

[humble crescent]

This is not true

<@&286206848099549185>

[marsh citrus]

@humble crescent Has your question been resolved?

[humble crescent]

<@&286206848099549185>

[humble crescent]

<@&286206848099549185>

https://media.discordapp.net/attachments/540211747613704221/1154887704555827311/image0.jpg

[static quarry]

so far so good, now what are you going to do with (-2,2,-1)?

[humble crescent]

Still thinking

[solid echo]

@humble crescent What does it mean for (\mathcal{L}_1) to be defined by (\mathbf{X} = \lambda(1,1,0) + (0,0,2))?

[elfin berry]

Watson

[humble crescent]

X is a column vector

Lambda a scalar

It’s an equation for generating every point on the line by scaling and adding vector s

[solid echo]

Okay that's a good answer

Not quite what I'm looking for

What I'm looking for is, the equation of a line is the set of all points in R^3 that lie on the line.

So ((0,0,2)) lies on the line, because in that case we have (\lambda = 0) for the line for ((0,0,2))

[elfin berry]

Watson

[solid echo]

And so on

This is the same for L_2

In other words

If #linear-algebra message
there is a point L_1 intersects L_2, this point must satisfy both equations of L_1 and L_2. Can you write this down algebraically?

@humble crescent

[humble crescent]

P1 = p2

[solid echo]

What is P1 and what is p2?

[humble crescent]

I’m hardstuck Watson

[solid echo]

Look at notes or find notes

Look into what is a system of linear equations

Go into R^2 if possible

There's not much that is happening at R^1 so you cannot do that

[marsh citrus]

@humble crescent Has your question been resolved?

[humble crescent]

i need hints and help

link me up alright?

[humble crescent]

<@&286206848099549185>

[hardy axle]

What

Huhh

[hardy axle]

.

[quaint hill]

anyway yeah, pls dont ping helpers multiple times, but also pls dont send off-topic messages in help channels

[hardy axle]

.

[quaint hill]

i am aware, theyve already been told off about it

[hardy axle]

I didn’t send offtopic messages. I was just asking her why pinging

and also asking her what she wants.

So clearly its not offtopic

[quaint hill]

read the convo?

[idle ridge]

They want help with their math problem; if you keep posting non-helpful messages in here, you will be muted.

[idle ridge]

Have you found a line that satisfies i)?

[hardy axle]

I don’t have time to scroll all the way up so they should’ve told me.

[static quarry]

he/him, actually

[hardy axle]

I got other people to help.

[hardy axle]

Its not even a he or she

[idle ridge]

(They have the any pronouns role)

[static quarry]

ohh, missed that part

[hardy axle]

@idle ridge srry for the ping but I am trynna understand?

[static quarry]

@humble crescent so you're trying to find the intersection of two lines that are given parametrically

is that correct?

namely, $\lambda(1,1,0) + (0,0,2)$ and $\lambda(0,-1,-2) + (1,-2,-4)$

[hardy axle]

The mods aint modding

[elfin berry]

Bungo

[idle ridge]

Please stop posting here without helping

[humble crescent]

Yes

[hardy axle]

Ok pls turn of the ping when u reply to me. Thank you. Bye.

[static quarry]

do you have any ideas about how to do that?

[humble crescent]

Yes i think

[static quarry]

iirc, you found a normal vector

you can use that to define a line that meets all three conditions

all you need is to specify a point in the plane that it should pass through

and since you want it to intersect both L1 and L2, that point should be the point of intersection of L1 and L2

i've been vaguely following this here and in #linear-algebra and I think you're aware of all of the above?

[humble crescent]

Ok

What point doe

[marsh citrus]

@humble crescent Has your question been resolved?

[marsh citrus]

@humble crescent Has your question been resolved?

[marsh citrus]

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[green geyser]

Is there any property for this? I cant seem to find it on the internet

[tender sparrow]

https://youtu.be/KEDoXFvvpHw?si=3hsHhAX2VhnvbHm1

this might help

[marsh citrus]

@green geyser Has your question been resolved?

[left whale]

Think about another way to express 4 that might help you

[marsh citrus]

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[tender mantle]

I tried to differentiate

[stark trail]

@tender mantle n

[tender mantle]

Split the limit?

[brave spire]

Nvm

[brave spire]

What did you get

[stark trail]

unhonne hamaare rainkon mein ghusapaith kee hai. kisee par bharosa nahin. ab se hamaara sanchaar keval hindee mein hona chaahie. main ain kee madad se padhaee kar raha hoon. yadi aavashyak ho to krpaya meree hindee sudhaaren. ham is mahaan yuddh mein vijayee honge.

[brave spire]

Yk mujhe Hindi aati hai

[stark trail]

kya tum hamamen se ek ho?

ya kya aapako erik jaison se sahaanubhooti hai?

[brave spire]

Erik jaison kon hai

[brave spire]

Me sirf apni side pr hu

Mujhe kisi se sahaanubhooti mhi hai

[stark trail]

aap ya to hamaare paksh mein hain ya hamaare viruddh hain. madadagaar aapake gambheer vishvaasaghaat ko nahin bhoolenge

[brave spire]

Show work

[brave spire]

Itni Hindi nhi aati bhai 💀

Vishvaasaghat kya Hota Hai??

[stark trail]

betrayal

[brave spire]

Achha

Theek hai

[tender mantle]

Tum mere bio me jake mera server join kar lo ya vha ek Hindi ka bada server hain discord par...religion/political conflict k chalte me banned hu vha se

[stark trail]

main nahin kar sakata unhen mera naam pata hoga. main antararaashtreey star par vibhinn hindee samoohon mein vaanchhit hoon.

[tender mantle]

विश्वासघात

[tender mantle]

Tum kar sakte ho

Tujme vo bat hain

[stark trail]

⚔️

[brave spire]

Tujhe Prashna ke uttar mein dilchaspi hai bhi ya nhi @tender mantle

[stark trail]

main kabhee bhee dakshin bhaarat mein kadam nahin rakh sakata.

[marsh citrus]

@tender mantle Has your question been resolved?

[tender mantle]

Ek minute dost

[tender mantle]

Noooo mujhe dhaksin pasand h mujhe vha hi jana h ek din

[marsh citrus]

@tender mantle Has your question been resolved?

[tender mantle]

a cos/xsinx + b/x^2 =1/3
-a sinx/(sinx+xcosx) + b/2x

-a cosx/(cosx+cosx-xsinx) + b/2 = 1/3

-a/2+b/2 = 1/3

-a+b = 2/3@brave spire

[desert socket]

words ka choosing dekh ke saaf saaf lg rha Austin translator use kr rha

[tender mantle]

Ha Austin the translator

[marsh citrus]

@tender mantle Has your question been resolved?

[tender mantle]

.close

[marsh citrus]

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[north gull]

how to do this?

[lethal bridge]

🪵arithm

[still temple]

you don't really have to

[desert socket]

,tex .exp rules

[elfin berry]

B-eard

[north gull]

what does that mean

[still temple]

try to transform 10^x into 10^(x/2 +1) by a series of algebraic operations on both sides of the equation

[summer trench]

logs😭

[desert socket]

we don't need logs here

[inner narwhal]

x = log(64)

[north gull]

I haven't studied that

😅

[still temple]

specifically, make use of the "power of power" and "product rule" properties of exponents that are listed here

[desert socket]

Hint:|| 10^(x/2+1)=10^(x/2)*10^(1)||

[north gull]

I still don't understand

oh wait nvm

[granite trench]

[north gull]

the answer is 80 right

yeah

[granite trench]

yea

[north gull]

thank

you

[marsh citrus]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[granite trench]

No problem

[terse turtle]

based gpt

[granite trench]

More to solve using apps (which are possible) than to solve without apps, which takes a little longer.

[stoic saddle]

GPT???

[terse turtle]

what

[marsh citrus]

@north gull Has your question been resolved?

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[marsh citrus]

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[marsh citrus]

Channel closed

Closed due to the original message being deleted

[frank orbit]

.reopen

...

.close

[marsh citrus]

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[marsh citrus]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[foggy hazel]

1

[foggy hazel]

1

[marsh citrus]

@foggy hazel Has your question been resolved?

[marsh citrus]

@foggy hazel Has your question been resolved?

[plush willow]

do you know what is a common denominator?

[foggy hazel]

Yea

[plush willow]

what is common denominator in this case?

[foggy hazel]

X^2-15x+50 // factoring it

I want to say x^2 is (x ) (x )

15 and 50 is -10 and -5

Because -10*-5 is 50

And -10+-5 is -15

Is that right?

So (x-5)(x-10)

[marsh citrus]

@foggy hazel Has your question been resolved?

[marsh citrus]

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[violet prairie]

which of these would be 13pi/4?

[bright jay]

Just take 13pi/4 and subtract pi until you get a number that's between 0 and 2pi

[violet prairie]

im sorry i dont understand what u mean

[bright jay]

Take 13pi/4, subtract pi from it

Keep doing that until the number appears on the unit circle

[violet prairie]

ahh okok ty

.close

[marsh citrus]

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[hollow dew]

i need to find a rectangualr prism, with all three sides being whole numbers, and the volume needs to be 850, and being as close to a cube as possible, i also want to know how do you get the result

[hollow dew]

ping me if someone comes, ty

also if its not too difficult, how do i find a solution closest to a cube in range from n, being 850 in this case to n+m%, lets say n+5% (meaning we can go up, not down)

[snow orchid]

not at all:)

tan is periodic by 1pi

$ \tan{ \frac{13\pi}{4}} = \tan{ \frac{\pi}{4}} $

anyways idk why latex isnt working but it should be the same as tan(pi/4)

@hollow dew

[hollow dew]

ok, ill take a look

[snow orchid]

it helps if you look at how tangent looks:)

or imagine it on the unit circle

[hollow dew]

ok

oh, i think there was a mistake, you ansvered the previous question

but dont worry, everyone makes mistakes

[snow orchid]

OH XD

I'm just tired af xD

[marsh citrus]

@hollow dew Has your question been resolved?

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[exotic magnet]

Could someone please check this?

[lapis wraith]

I need help with Algebra

[exotic magnet]

<@&286206848099549185>

[lapis wraith]

Oh wait a second.

[exotic magnet]

I’m sorry but this channel is occupied please find a different one

[lapis wraith]

Okay.

I am new to this server.

[exotic magnet]

.close

[marsh citrus]

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[still temple]

i got the derivative

but idk what to do when tangent line is vertical

i only know what to do when its horizontal (x=0)

<@&286206848099549185>

[marsh citrus]

@still temple Has your question been resolved?

[still temple]

<@&286206848099549185>

.close

[marsh citrus]

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[red pecan]

hey wondering about this statement and if my definition of parallel carries onto 3-space properly

[red pecan]

"Two lines parallel to a plane are parallel"

i would say no

believing that the definition of parallel is that these lines would be equidistant throughout space

is this accurate?

okay this is right

.close

[marsh citrus]

Channel closed

Closed by @red pecan

Use .reopen if this was a mistake.

[red pecan]

what

how is this not true

[bright jay]

Btw

It means your channel will close soon @red pecan

[red pecan]

.reopen

[marsh citrus]

✅

[terse turtle]

which one, 4 or 6?

[red pecan]

okay so

i don't imagine two lines parallel to a plane must to parallel

because they can be offset, right?

they dont have to be equidistant throughout space

but can remain parallel to the plane, right?

so i don't see how this must be true (for 6)

this is all for 3-space btw

[terse turtle]

is it that the answer says it's true?

[red pecan]

sorry, i mean apparently some of these are wrong

i am 76% right

in the answers you see now

[terse turtle]

i see

[red pecan]

yea just wondering if anyone has any hints

what i'm taking for granted

[terse turtle]

i think 9 should be false, by the way

i could be wrong

[red pecan]

i don't see how that's possible

what do you think of that you could see it as false?

OH

WAIT

YOURE RIGHT

thanks for that

this is actually driving me CRAZY

<@&286206848099549185> ❤️

apparently 82% of this is correct

and i am so sad that i don't see the 2 remaining that must be wrong

[tight nymph]

Think of a cube

[red pecan]

right so that corrected 9 for me, i think

er um

wait

i have been thinking of a cube

but not well enough apparently

😦

okay 7 must be false

one down

one of the answers i have now are untrue

<@&286206848099549185> one of these are incorrect as i have them now. i have been thinking of a cube which while likely great advice is not enough for my smol brain

i am asking for another hint

pretty please

[zinc socket]

Sorry, I read "planes" instead of line

[red pecan]

😛

thanks for playing lol

[zinc socket]

well

I don't know where you're wrong 😅

[red pecan]

me neither

and it hurts

so much

we just have to put our heads together and think of a cube

[zinc socket]

😂 have you verified there isn't some problem when typing the answer ?

[red pecan]

or at the very least you can get me out of the cube i have become trapped inside

[zinc socket]

do you have unlimited answer ?

[red pecan]

i have 1 attempt left

[zinc socket]

ouch

[red pecan]

i think it will just request a reorganized version

[zinc socket]

that's problematic

[red pecan]

it's funny when i first saw this i thought "wow this is gonna be easy"

so flew through it

[zinc socket]

there are two possibilities :

1. we're stupid

2. answers given are wrong

[red pecan]

i am well aware that i am stupid

i am reminded every day in fact

so humbling

[zinc socket]

tragic life

sorry, but I think I can't help you more than that

[red pecan]

hey man it's okay. i appreciate it.

[zinc socket]

one thing you could do, is just to submit your answer

then see where we were wrong

[red pecan]

nah. it will just request a new version without showing me 😛

[zinc socket]

oh

how unfortunate

[red pecan]

i really want to know

i have become emotionally invested in this

[tight nymph]

Think of a cube and a corner of the cube

[zinc socket]

OH

[red pecan]

lmfao

WAIT

DO YOU SEE IT

[zinc socket]

yes

[red pecan]

wait give me a sec im slow

[zinc socket]

check the statement with orthogonality

[red pecan]

9 right?

[zinc socket]

nah

[red pecan]

oh yea

no that must be f

yea i don't see it

[zinc socket]

check the 2

[red pecan]

when they said cube the corner was the first thing i was thinking of

im stupid

wow

[zinc socket]

every day you're reminded of it

[red pecan]

thank you guys

ima go 2 bed

.close

[marsh citrus]

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[oak dragon]

hello, i am learning about combinations and permutations in class and i am having a little trouble wrapping my mind around what the question is asking, could anybody walk me through what they mean by exactly 1 non conforming part and at least, and what this means mathematically?

[twin mesa]

question basically says

1. there is 13 parts produced
2. 3 of the parts are nonconforming or in simple terms "broken"
3. out of the 13, the inspector picks out 2 randomly

[oak dragon]

so is this a problem where i have to use the combination formulas at all?

n! / r!(n-r)!

[twin mesa]

not really i think

[oak dragon]

so do i just multiply the probability of it being broken times the subset the inspector is picking out

2/13 * 3/13

[twin mesa]

i dont think so

personally for (a) i would have taken
3/13 * 10/12 + 10/13 + 3/12

[oak dragon]

can you walk me through why you think thats the answer

or what those numbers mean

[twin mesa]

to me i would have split it into 2 cases when he picked it out.

case 1: the first part he picked out is broken, second one is not

case 2: first part he picked out is fine, second one is broken

in probability terms

3/13 * 10/12 for case 1

[oak dragon]

ohhhhhhh

[twin mesa]

at least thats how i view it

[oak dragon]

i see

okay let me think this through with that logic ill get back to you

[twin mesa]

sure

[oak dragon]

i think this is still a combination problem actually

im kinda tired tho so im gonna try it tmrw with a fresh brain, ty for your help

.close

[marsh citrus]

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[red pecan]

trying to play catchup. i'm not sure what they're asking for here. for b

[red pecan]

here is my work so far:

everthing seems to have worked out nicely so i tink i did it right. maybe this is more of a technical question that might be more obvious to those familiar with ODE's

okay so they wanted du/dx + (-1/x) for the second part

but what would "u" be then for the third part if it can't be 1/y?

.close

[marsh citrus]

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[marsh citrus]

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[unreal bridge]

Is this a correct proof?

[desert socket]

no

a^b^c≠a^(b*c)

[unreal bridge]

Oh

Well nvm then thanks

.close

[marsh citrus]

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[clear onyx]

does anyone know how to complete p test and ctt for this

[marsh citrus]

@clear onyx Has your question been resolved?

[clear onyx]

<@&286206848099549185>

[marsh citrus]

@clear onyx Has your question been resolved?

[marsh citrus]

@clear onyx Has your question been resolved?

[marsh citrus]

@clear onyx Has your question been resolved?

[fast pumice]

Write down as $\int_1^\infty \frac{x}{x^2 + 5^x} , dx + \int_1^\infty \frac{3^x}{x^2 + 5^x} , dx + \int_1^\infty \frac{2}{x^2 + 5^x} , dx.$ With $\frac{1}{x^p}$ which term can you compare the integrals for each integral?

[elfin berry]

adzetto

[clear onyx]

in this case is it x?

the first integral

[slender cipher]

Ohhh compare them you then it would converge. I am sorry I wasn't any help. I never seen a problem where you have to split the integrals like that.

[marsh citrus]

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[split oasis]

y - 5 = 2/3 (x-3)

[remote barn]

what's the question

[split oasis]

they just gave that😭

[still temple]

Surely there is some context to this

[split oasis]

but my other friend said first it will be y = 2/3 (x-3) +y

[still temple]

they wouldn't have just dumped a random equation in your face with no instructions

[remote barn]

Uh, not really

[split oasis]

no my friend is giving 10 dollars for someone who solves it that's why

[remote barn]

Is it transform from this form to slope-intercept form

[remote barn]

Well it's a line

[proper zodiac]

there is nothing to solve if your friend doesn't tell you what they want you to do with it

[split oasis]

Multiply, multiply, transpose, multiply

[still temple]

???

[remote barn]

yes, if I were you, you SHOULD bet 10 dollars for this question: p=np

[waxen dust]

A lot of work!

[still temple]

If you don't have a clear question we cannot help you. We are not clairvoyant

[proper zodiac]

who is she??

[split oasis]

Polynomial

related to polynomial

[proper zodiac]

ask your friend exactly this: "what exactly do you want me to do with this equation?"

and do not take "solve" for an answer as that's nonsense

[marsh citrus]

@split oasis Has your question been resolved?

[split oasis]

Slope equation

Anyone?😭

I forgot how to do this

[marsh citrus]

@split oasis Has your question been resolved?

[marsh citrus]

@split oasis Has your question been resolved?

[marsh citrus]

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[marsh citrus]

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[sudden pier]

What if a z score is 5

[waxen dust]

What?

[wise jackal]

Statistics?

[sudden pier]

yes

[leaden monolith]

!original

[marsh citrus]

Please show the original problem, exactly as it was stated to you. A picture or screenshot is best.

If the original problem is not in English, then post it anyway! The additional context might still help helpers help you. Do your best to translate.

[wise jackal]

it would just mean you are 5 standard deviations from the mean ig?

[sudden pier]

so

how do i show that process

that a z-score

is a 5

and its zero

[leaden monolith]

Well

200 = 100+5*20

Or you can use the formula

(200-100)/20 = 5

That’s the (X-mu)/σ

[sudden pier]

also

how do u get the z score in a calculator

[marsh citrus]

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[marsh citrus]

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[marsh citrus]

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[long granite]

Im not sure if I did the graph right, could someone check if im on the right track please?

[long granite]

Actually I think the graph is this

[marsh citrus]

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[tardy vessel]

How do you determine the next term in a sequence using mathematical induction?

[tardy vessel]

like how do i find the next term from (2k-1)

[high pine]

You rather meant to prove it by mathematical induction

[tardy vessel]

yes

i mean like when doing induction proof

sorry

[high pine]

What step are you in or what have you done so far?

[tardy vessel]

i havnt done that problem i am just wondering in general how do i find like the next term for the last term in what ever sequence. like 1+2+3+4+...+n=n(n+1)/2 the next term from n is n+1. but how do this when the last term is (2k-1) or n^2+1 or somthing where the next term is not +1 rather +2 or +5 etc how do i find the formula for the next term for the last term

english isnt my first language so i have hard time trying to formulate

[high pine]

First of all in the sequence 1, 3, 5, 7, ..., (2k-1)

The general term is given by (2k-1)

I mean it can be any term you want for the given k

In terms of k next term after 2k - 1 is 2k - 1 + 2 = 2k + 1

because it's arithmetic sequence and we see (according to the first few terms) that common difference is just 2

[devout mauve]

you plug n+1 in for n

so n^2 becomes (n+1)^2

[tardy vessel]

what if i dont have the sequence stated? do i just k + (next term) and plug in k+1 for whatever k is

oh ok

[devout mauve]

2n-1 becomes 2(n+1)-1

[tardy vessel]

okay i think i got it now thank you

.close

[marsh citrus]

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[stiff shuttle]

I’m not understanding how to get the displacement in this physics question: a hiker walks 25.5 km from her base camp at 35° south of east. On the second day she walks 41.0 km in a direction 65° north of east. Determine the total displacement of the hiker.

[pale agate]

draw a diagram

[stiff shuttle]

I did

I’m trying to find Theta 1

[pale agate]

youve got 2 parallel lines on this diagram

and a line crossing them

[stiff shuttle]

I’m still not understanding how I can find theta 1? Srry

[pale agate]

alternate angles

[stiff shuttle]

I don’t think it alternative angles would work thou

[pale agate]

why

[stiff shuttle]

But it still won’t give me theta 1

[pale agate]

thats not alternate angles

[stiff shuttle]

?

[pale agate]

those are vertical

[stiff shuttle]

Ok I’m still not understanding how to find theta 1 thou. Srry

[pale agate]

https://en.m.wikipedia.org/wiki/File:Paralelni_transverzala_alt.svg

these are alternate angles

[stiff shuttle]

Gotcha but how would that help me thou ?

[pale agate]

youve got two parallel lines

[stiff shuttle]

Yea

[pale agate]

a line crossing them

and one of the alternate angles

[stiff shuttle]

?

[pale agate]

what?

[stiff shuttle]

I’m still not understanding

[pale agate]

what exactly

what line is crossing the parallel ones?

[stiff shuttle]

How to find theta 1

[pale agate]

.

[stiff shuttle]

I see it but how would that help me thou

I don’t have theta 2 either

Nvm got it

Thx

[pale agate]

you dont need theta2

[stiff shuttle]

.close

[marsh citrus]

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[glossy wind]

Not quite sure well, really how to simplifiy

[mental panther]

thats really weird

is there some extra constraint on omega

[glossy wind]

no :p im not sure if its complex or an argument

[mental panther]

in general, $\frac{\omega^2 + 1}{\omega ^2 + 9} \ne \frac 15$, which is what it wants to be the case

[elfin berry]

Frog_Man

[bleak ibex]

Is the delta a function or just a variable?

[glossy wind]

id assume the actual delta function

[mental panther]

that explains alot mb

think about what happens when $\omega \ne 1$

[glossy wind]

this might be silly but

[elfin berry]

Frog_Man

[glossy wind]

do i just plug in -1 into every omega besides the delta function

so then i get the value of whatever those are at delta

[mental panther]

as it happens that gives the right answer, but it should be plugging in omega = 1

because when omega is not 1, the delta function gives 0

[glossy wind]

right

[mental panther]

so we only care about the case when omega = 1

[glossy wind]

alrighty that makes sense

time to take a peak at b

this is just indetermient at omega = 0 hey

so then you gotta use LH rule

which gets me that

ah yes yes 'tis correct

wait, actually is it?

is the derivative of sin(kw)delta(w) = kcos(kw)delta(w)?

[mental panther]

you have a sin(kw)delta ' (w) term as well

[glossy wind]

what is delta'(w)

wouldent that just be 0?

[mental panther]

yes

so it ends up being correct

but you should include it for correctness when doing lhopital

[glossy wind]

i see, yeah totally

thanks alot

[mental panther]

np

[glossy wind]

ima keep this open incase i have more questions for the later problens

*problems

[marsh citrus]

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[tacit fjord]

might get a faster response in #calculus

!show

[marsh citrus]

Show your work, and if possible, explain where you are stuck.

[tacit fjord]

also this.

[marsh citrus]

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[trail cove]

I have to copy the chatgpt proof but im not supposed to use words so how am i supposed to split up the union?

[runic temple]

what

the

FUCK

Who the hell assigned a chatGPT proof

[tacit fjord]

What school is this?

highschool? college? uni?

and if you don't mind, which country (don't have to share if u dont want)

like this is absolutely awful standards of teaching.

[trail cove]

uni

[tacit fjord]

im. at a loss for words.

[crystal lintel]

what's so bad about it