help-33

[still temple]

i need help with b

[still temple]

<@&286206848099549185>

[green sky]

How many students do rock climbing?

[marsh citrus]

@still temple Has your question been resolved?

[still temple]

sorry i didnt see

35 student do it

[green sky]

Out of which how many are doing bush walkjng

[marsh citrus]

@still temple Has your question been resolved?

[still temple]

.close

[marsh citrus]

Channel closed

Closed by @pulsar hawk

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

i needed to find f(x) and that s what i have so far but i dont know how to find C2

LoL

Is that exp?

yes

So

f'(ln x) = 1 exp 0, when 0< x ≤ 1

?

LoL

What is the Russian?

https://cdn.discordapp.com/attachments/907022703230345237/1107326980329852938/1f1817730bc8f27c.png

Here

"while"

and "and" in the side

Ahhhhh

Okkkkk

AH

I GOT IT

IM STUPID

.close

[marsh citrus]

Channel closed

Closed by @slender moat

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cloud kettle]

Are odd square roots of negative numbers defined?

[lucid zenith]

you mean odd roots

and yes

[cloud kettle]

Alright thanks

That's what I meant

[lucid zenith]

$\sqrt[2n+1]{-k} = -\sqrt[2n+1]{k}$

[elfin berry]

kheerii

[cloud kettle]

I see

.close

[marsh citrus]

Channel closed

Closed by @cloud kettle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[echo jolt]

I'm trynna convert the Cartesian equation to the equation of a line but X=1 stuck what am I supposed to do with x=1 ?

[echo jolt]

is x = 1 + slander 0 ?

.close

[marsh citrus]

Channel closed

Closed by @echo jolt

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lucid zenith]

!status

[marsh citrus]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[lusty scroll]

oh sorry

got it

stupid doubt

.close

[marsh citrus]

Channel closed

Closed by @lusty scroll

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[forest orchid]

what am i doing wrong

[forest orchid]

expanded (y-2)^2

using special products (a-b)^2=a^2-2ab+b^2

idk how they ended up with y^2-4y+4

[frail hinge]

yes

we just have to insert the values

[forest orchid]

why is it not -2

[elfin berry]

Şêro

[forest orchid]

Oh OOPS

I JUST BROUGHT THE WHOLE "-2" WIT ME

its 2

Ur right

ty for clarification

.close

[marsh citrus]

Channel closed

Closed by @forest orchid

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hollow drift]

Is it true that all lines in space of the form x = ay = z lie in the same plane?

[hollow drift]

I believe it is true but I dont know how to prove it

Not rigorous proof, just an example proof

[bleak ibex]

Well, x = z defines a plane

[hollow drift]

Yes

So, since all lines imagined lie in planes with the same normal vector and both pass through the same point, they must lie in the same plane. Therefore, any two lines of the form x = ay = z will lie in the same plane.

Is that a valid reason?

[bleak ibex]

Well, it is simpler. Any point on the line satisfies x = z, and that always lies on the plane x = z

[hollow drift]

True

Thanks, thats an easier explanation

.close

[marsh citrus]

Channel closed

Closed by @hollow drift

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slim quartz]

Hiw do u do this

[stoic saddle]

,rccw

[stoic saddle]

do you know how to solve equations like this in general

[harsh holly]

This is going to be a long-ass solution 🔥

[hollow drift]

Start by factoring

Do you know how to factor

?

[marsh citrus]

@slim quartz Has your question been resolved?

[marsh citrus]

@slim quartz Has your question been resolved?

[marsh citrus]

@slim quartz Has your question been resolved?

[wintry shale]

@slim quartz

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[marsh citrus]

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[eager moat]

does anyone know how to move an ellipse? like the equation, how do you shift it left and right?
im tryna make a line that goes through (-20,0), (-15, 7.5), (-7.5, 9.8)

[echo bough]

if its just shifting

replace the x and y

by (x-a) and (y-b)

[eager moat]

?

wdym

[echo bough]

if you want to shift the ellipse by 3 on the right

replace x by (x-3)

[eager moat]

im fucking stupid

thanks

[marsh citrus]

@eager moat Has your question been resolved?

Channel closed

Closed by @eager moat

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[modest lotus]

shouldn’t the original function of x/2 be x^2/2 where did the 4 come from?

[bright jay]

Fyi x/2 = (1/2)x, where 1/2 is a constant that you can pull out, maybe doing it like that will help you see it

Because you just integrate x

[modest lotus]

sorry m quite dum at math lol could u perhaps show me the steps on a paper/ drawing on paint or smthng

[whole sleet]

Maybe instead, try taking the derivative of x²/2, and show that you don't get x/2

[modest lotus]

umm i saw the correction of this from a vid but the guy just couldn’t explain it properly since its easy for him ig

wait ill write what m talking about im a paper

[whole sleet]

No need, he is probably doing the same thing I am

What is the derivative of x²/2, btw?

[modest lotus]

okey i kept sketching and couldn’t see it

[modest lotus]

should be x if m not wrong

[whole sleet]

Right! The derivative is x. The derivative is not x/2

If the derivative of x²/2 is not x/2,

Then the integral of x/2 is not x²/2

.
But we can fix it.
If the derivative of x²/2 is x,

Then we can divide both by 2, and get that the derivative of x²/4 is x/2

Which is what we want, and gives us our integral

We have the integral power rule for this, though. That is, whenever you're integrating x^n, add 1 to the exponent, then divide by the new exponent.

[modest lotus]

jesus m so dum

i get it now

the 2 at first get canceled therefore its just x

my mistake was still writing x/2 even tho the 2 is gone

so x becomes x^2/2

yes that makes total sense

[marsh citrus]

@modest lotus Has your question been resolved?

[modest lotus]

yes thanks guys btw

[marsh citrus]

Channel closed

Closed by @modest lotus

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rugged coral]

Hey I have a question regarding circle geometry

[green sky]

Yes

[rugged coral]

I want to know how to solve this problem I don’t want the answer I just want to know how to start solving it bc I couldn’t grasp the information on how to do it in class today

Here is the problem

[marsh citrus]

@rugged coral Has your question been resolved?

[rugged coral]

<@&286206848099549185>

Sorry I haven’t gotten any help in like 20 mins

[exotic barn]

Can you rotate

Idk how they rotated it

,rotate

[exotic barn]

You can first calculate arc VY

and then calculate arc YX, and the. The rest should be done

Ping me if you need more help

[marsh citrus]

@rugged coral Has your question been resolved?

[stark trail]

Don't click on that link

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

how can i simplify arctan(3)-arctan(1)?

[still temple]

so that it becomes arctan(p(x))

[stoic saddle]

p(x)?

[still temple]

some function

[stoic saddle]

eh?

[still temple]

any function

3

[stoic saddle]

sounds kind of strange even if formally valid

[still temple]

3x^2

[stoic saddle]

there is no x in arctan(3) - arctan(1)

so what is this talk of functions

[still temple]

it says express your answer in the form arctan(p)

[stoic saddle]

show exact problem statement

[still temple]

Find the value of arctan(3)-arctan(1), expressing your answer in the form arctan q, where $q \in Q$

yeah, sorry

q is an integer

[stoic saddle]

did you mean $q \in \bQ$

[elfin berry]

Ann

[still temple]

yeah

[stoic saddle]

Q is not the set of integers, Q is the set of rational numbers

[still temple]

oh

[stoic saddle]

anyway

[still temple]

ok

[stoic saddle]

consider $\tan(\arctan(3) - \arctan(1))$

[elfin berry]

Ann

[still temple]

idk why u can wrap tan around it

that is my problem

[stoic saddle]

do you think you need special permission, signed and notarized in triplicate, to consider the tan of an expression as opposed to an expression itself?

[still temple]

if this were an equation, wouldn't u have to wrap tan on both sides

[stoic saddle]

we will come back to arctan(3)-arctan(1) itself soon enough.

[still temple]

i already know the following steps

[stoic saddle]

you might say we are letting theta := arctan(3) - arctan(1) and considering tan(theta), if that makes things easier for you.

[still temple]

it is an angle identity thing

$\arctan(3) - \arctan(1)=x$

[still temple]

$\tan(\arctan(3) - \arctan(1))=\tan(x)$

[still temple]

shouldn't it become something like this?

[stoic saddle]

yeah sure

same shit

[still temple]

oh is it?

[stoic saddle]

idk about "should" -- are you basing this on some feedback you received from your prof where they rejected a similarly phrased solution?

[still temple]

no, i looked at the answer key

but expressions are weirder than equations tbf

i prefer having something on the other side

.close

[marsh citrus]

Channel closed

Closed by @zealous flint

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[daring dagger]

<@&268886789983436800>

[marsh citrus]

Channel closed

Closed due to the original message being deleted

[daring dagger]

post it in any of these available channel

not here

[marble viper]

oh

[runic temple]

.close

:I

[daring dagger]

bot moment

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

what symbol are these? left one seems to be big delta

what is the right?

[untold wyvern]

capital lambda

what topic is this btw, rarely seen capital lambda being used, especially for angles

[marsh citrus]

@still temple Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

my answer is coming 1/2 while the correct answer is given 1

[main idol]

!show

[marsh citrus]

Show your work, and if possible, explain where you are stuck.

[still temple]

ok

let me download discord on phone

pls wait

[main idol]

show the answer as well

[main idol]

which problem number

[main idol]

is this

[still temple]

4th

[main idol]

that's a mistake. 1/2 is correct

[still temple]

so it means i was right ?

i mean my process is correct ?

[main idol]

i mean yes if you're allowed to use taylor series

[still temple]

thanks

!close

.close

[marsh citrus]

Channel closed

Closed by @gaunt ferry

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worn nimbus]

are you allowed to use LH?

[still temple]

meaning of LH ?

[worn nimbus]

lhopital

[still temple]

if its also called series expansion / taylor series then yes

[worn nimbus]

lhopital is when you take the derivative of the top and bottom

[still temple]

oh then no

[worn nimbus]

alright

[still temple]

sir said he will teach us in few days so i think this question wont use that method

[worn nimbus]

okay then

so have you tried to use a series yet

[still temple]

yes i have tried to use the sin and cos but how what to put on log(1-x)

[worn nimbus]

do know how to make the taylor series for log(1-x)

you can use that

[still temple]

no

could you please tell ?

[worn nimbus]

it is -x -x^2/2 - x^3/3 etcetera

$\sum_{k = 1}^{\infty} -\frac{x^k}{k}$

[elfin berry]

heavy

[worn nimbus]

for the taylor series at x = 0

[still temple]

ok could you wait till i put this value and check my answer ?

[worn nimbus]

yeah sure

[still temple]

thanks

[still temple]

here in denominator there won't be factorial ?

[worn nimbus]

surprisingly no

[still temple]

ok

What to do next ?

[worn nimbus]

(x/3)/x = 1/3

[still temple]

ok

can you please write and show me what to do next ?

[worn nimbus]

your expression simplifies

to -1/3! - x/4! - 1/3

and you can compute the limit of that

[still temple]

ok

let me try

ya i got the answer i.e -1/2 thanks !!!

[worn nimbus]

nice

[still temple]

very very thanks

.close

[marsh citrus]

Channel closed

Closed by @gaunt ferry

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torpid owl]

is this right?

[torpid owl]

(not a test btw)

circ. is 18

18/2 = 9 = r

H = 8

9^2 * 8 * 3.14 / 3 gave me a decimal

rounded to the tenths.

[odd turret]

you round to the whole number

[proud ice]

The numbers you plugged in look fine

[torpid owl]

I did.

[odd turret]

,calc 9^2 * 8 * 3.14 / 3

[elfin berry]

Result:

678.24

[proud ice]

Oh right the /3

[odd turret]

doesn't look like it

[proud ice]

I missed that too (I haven't slept today)

[torpid owl]

so 678? @odd turret

[odd turret]

,calc 9^2 * 8 * 3.141592653589 / 3

[elfin berry]

Result:

678.58401317522

[odd turret]

3.14 is not pi

no...

[torpid owl]

679?

[proud ice]

This problem is genius.

pi vs 3.14. Very subtle

[torpid owl]

you'd have to input pi into a calc. i'm guessing..

[proud ice]

Most calculators have a specific button for pi

[torpid owl]

i'm using desmos scientific

I should be good right?

[proud ice]

Just type pi

[torpid owl]

yeah I did

also is this right?

[proud ice]

!show

[marsh citrus]

Show your work, and if possible, explain where you are stuck.

[torpid owl]

8 * 12 = 96

96 * 7 / 3

viola

[odd turret]

96 * 7 / 3 = 32?

[proud ice]

Looks like you forgot to *7

[torpid owl]

🤦

224*

good?

[odd turret]

,calc 96 * 7 / 3

[elfin berry]

Result:

224

[odd turret]

[torpid owl]

👍

.close

[marsh citrus]

Channel closed

Closed by @torpid owl

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[winged tree]

Any help is appreciated

[mystic minnow]

what do you have for the definition of probability?

[winged tree]

Im gonna be honest here I have no idea what im doing with this question thats why i am asking for help lmao, so I couldn't tell you

[marsh citrus]

@winged tree Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wary wolf]

I dont know which one is the proportional relationship and ping me if you know this.

[marsh citrus]

@wary wolf Has your question been resolved?

[wary wolf]

<@&286206848099549185>

[peak marten]

What do you know about proportional relationships?

[wary wolf]

if it multiples or add

[peak marten]

Okay, so
If we go back to the definition, a proportional relationship is one where y=kx for some constant, k

[wary wolf]

alr

[peak marten]

Basically, if they’re ‘off’ by a factor

So going back to your problem, which of those fit that definition?

[wary wolf]

y=10/3x+1/3

[peak marten]

So, what is your line of reasoning of selecting that one?

[wary wolf]

it says 10/3x + 1/3 and if you add them up its 3 2/3

[peak marten]

Okay
Let me try and rephrase

Y is proportional to x if y=kx, right?

So for y=10/3x+1/3, that +1/3 doesn’t match with the definition

[wary wolf]

oh

its just for adding

10/3x is for the multiplying

[peak marten]

Yeah, I understand

What I mean is that by adding that, we no longer have a proportional relationship

Does that make sense?

[wary wolf]

yes

so 10/3x + 1/3 is correct

but not incorrect

[peak marten]

All we can say is that y=10/3x+1/3 is not a proportional relationship

[wary wolf]

oh so y=10/3x+1/3 is not a proptional relationship

[peak marten]

Exactly

Now, y=10/3x is a proportional relationship

[wary wolf]

is there still more non proportional relationship

[peak marten]

Well, what do you think?

[wary wolf]

I think thats the only one

[peak marten]

Let’s just go through them left to right:
Is the first one a proportional relationship?

[wary wolf]

yes

[peak marten]

Great! What about the second one?

Well, we did that one already, how about the third?

[wary wolf]

proportional

[peak marten]

Nice! And the last one?

[wary wolf]

non

[peak marten]

So how many non-proportional relationships are there?

[wary wolf]

2

[peak marten]

Looks like you got your answer then! Everything make sense?

[wary wolf]

yes

.close

[marsh citrus]

Channel closed

Closed by @wary wolf

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[faint garnet]

is 30b Dne, or des it jump down to the bottom graph

[cunning cobalt]

30b does neither of those things

did you mean a different one?

[faint garnet]

no

30b, since it's coming from the right, does it jump from the graph on the right to the graph on the left?

cause if it does that then the answer is 2

but if it cant jump to the other graph the answer would just be DNE

[cunning cobalt]

well yes, i was just a little confused by the term "jump"

[faint garnet]

u know wht im tryna say

[cunning cobalt]

since this is one function

[faint garnet]

lol im sorry

[cunning cobalt]

all g

yes its 2 then

[faint garnet]

okok

Thxx

.close

[marsh citrus]

Channel closed

Closed by @faint garnet

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[limber condor]

Does the operation max(A) is linear?

I mean, if I define C = [x+y | x ϵ A ^ y ϵ B}, then max(C) = max(A) + max(B)?

[main idol]

What's A? A vector?

[limber condor]

No, a set

[proud ice]

Have you given any consideration to what the answer could be?

You could try to prove using induction

[limber condor]

Uh, but I'm not working with naturals, these are real numbers sets

[proud ice]

Doesn't matter

The sets are finetely sized

[limber condor]

Uh, well I'll try that

.close

[marsh citrus]

Channel closed

Closed by @limber condor

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ivory laurel]

I don’t understand the underlined part, how does it imply |an|r^n tends to 0 shouldn’t it just be anr^n tends to 0 without the absolute sign

[glacial hedge]

an -> 0 <=> |an| -> 0

[ivory laurel]

Oh wait yes this only applies to sequences with limits that are 0 right

[glacial hedge]

Yes

Because then the circle is reduced to a point

(so in general an -> a is stronger than |an| -> |a|)

[marsh citrus]

@ivory laurel Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lapis sable]

I need to find the surface area of this composite figure

[winter meteor]

didn't you ask this question yesterday

[winter meteor]

How many 2D objects can you split the composite figure into?

find the surface area of each of them

Profit

[lapis sable]

2

[lapis sable]

yep, I got help on the other one not this one

[winter meteor]

2???

How many faces does the 3D object have

[twilit grove]

<@&268886789983436800> spam

[still temple]

ban when :/

[glacial hedge]

Legend has it all mods are American and it may be they're all asleep

[still temple]

:// mods really be inactive in this server tho.....there was another fight 2h ago in the help channel

[glacial hedge]

I don't believe it, but it has yet to be proven false since I asked 40 min ago

[cloud kettle]

America 8 21 am now

[glacial hedge]

At the latest, or would that be 9:21 ?

[cloud kettle]

Googled

[lapis sable]

No like there 2 shapes there and the cube has 6 sides

[glacial hedge]

2 solids, which makes for a lot more than 2 faces

[paper raptor]

8:21AM EST is latest, 5:21AM PST is earliest in continental US

[cloud kettle]

Oh

[glacial hedge]

Why P and not W for West ?

[marsh citrus]

@lapis sable Has your question been resolved?

[twilit grove]

Pacific

[marsh citrus]

Channel closed

Closed by @lapis sable

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

why isnt sqrt(a²+b²) simplified to a+b?

[still temple]

what is (a+b)^2

a²+b²

[gloomy crypt]

No

[still temple]

bruh

[gloomy crypt]

Its A^2 + B^2 + 2AB

[paper raptor]

$(a+b)^2=(a+b)(a+b)=a(a+b)+b(a+b)=a^2+ab+ab+b^2=$\fbox{$a^2+2ab+b^2$}. Therefore $(a+b)^2\neq a^2+b^2$ and hence $\sqrt{(a+b)^2}\neq\sqrt{a^2+b^2}\implies a+b\neq\sqrt{a^2+b^2}$

[elfin berry]

XxMrFancyu2xX

[still temple]

so sqrt((a+b)²=a+b

[gloomy crypt]

Yes

[paper raptor]

Yes because square root and square cancel out

[still temple]

am smart

[gloomy crypt]

You surely are

[still temple]

thx

[gloomy crypt]

@still temple Is your problem solved ?_?

If yess then kindly close this by .close

[still temple]

.close

[marsh citrus]

Channel closed

Closed by @haughty elbow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[snow bison]

Would the missing linear value be 65?

If so how so?

I’m so confused

[rocky veldt]

Ok do you know general equation of a linear form

$y = ax + b$

[elfin berry]

Encrpyt

[rocky veldt]

Yes, this is the correct answer

[snow bison]

yes i do

[snow bison]

Yeah but can you explain how it would be 65 ? i need some reassurance

[rocky veldt]

Ok, so, now we insert the first value, that is x=0, y=5, what will be equation in that case

[snow bison]

oh

hm

not sue w

sure wouldn’t it be like this

[snow bison]

^

[rocky veldt]

ok, if we insert y=5 and x=0
then we get 5 = a(0) + b
b = 5

did you get this

[snow bison]

oh

yes i see

[rocky veldt]

Now, we got equation as $y = ax + 5$

[elfin berry]

Encrpyt

[rocky veldt]

Now, can you insert y=125 and x=2, find what is 'a'.

[marsh citrus]

@snow bison Has your question been resolved?

[snow bison]

ohh

60

omggg

125=(60)(2)+5

[rocky veldt]

Great, now can you tell me value of y when x=1 in the equation y=60x +5

[snow bison]

65 ?

[rocky veldt]

Yes you got it!

[snow bison]

tysm!

.close

[marsh citrus]

Channel closed

Closed by @snow bison

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slender junco]

just need help rearranging an equation

[slender junco]

T = 2π * √(I / (m * g * d^2))

so rearranging for my g = 4π^2 * (I / (m * s))

where s is slope

Where slope is Delta_T^2/Delta_d

[marsh citrus]

@slender junco Has your question been resolved?

[slender junco]

<@&286206848099549185>

<@&286206848099549185>

[twilit grove]

what are you asking here?

[marsh citrus]

@slender junco Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[native tapir]

how is the answer d?

[marsh citrus]

@native tapir Has your question been resolved?

[native tapir]

.close

[marsh citrus]

Channel closed

Closed by @native tapir

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[marsh citrus]

@still temple Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

Why is he ticking the equation on the left?

[still temple]

2 < 3 is not in the triangle.

and why is he putting a big X on sections (he said something wont be there) but idk why he crossed it.

[bright jay]

He used the point (1, 2) in the first equation

[still temple]

Yes

I understand

But why is he ticking it.

What is the point of that equation

[bright jay]

Because he's plugging in that coordinate, and confirmed it for the first inequality that (1, 2) satisfies it but for the others, it doesn't work

[still temple]

satisfies what

???????????????????????????????

[bright jay]

The inequality

[still temple]

How do ik if it satisfies the inequality

[bright jay]

If it's a true statement

[still temple]

How do ik if its a true statement

Oh

OH

[bright jay]

If it satisfies the inequality

[still temple]

2 is less than 3

is that the statement

[bright jay]

Yes

[still temple]

Alr

[bright jay]

Plug in the coordinates (1, 2) into the first inequality

[still temple]

And then why is he crossing out the other regions and sides

[bright jay]

You have 2 < 2(1) + 1 which is 2 < 3, that's true so (1, 2) satisfies the inequality

[bright jay]

You're picking a point from each region and plugging it into each given inequality

[still temple]

Mhm

OHH

So like

[bright jay]

If it fails at least 1 inequality then that region does not satisfy all three regions

[still temple]

If i picked -4, 4

Do i put it through each inequality

[bright jay]

If it fails at least 1 inequality

You plug it into each inequality, and the first one that fails, you can stop

Because if it fails one then that region does not satisfy all three inequality

[still temple]

it failed it

why shouldnt it satisfy all 3 regions

i picked one region

I picked that region

[bright jay]

Typo

Meant to say inequality

Because if it fails one then that region does not satisfy all three inequality

[still temple]

yeah so?

Wait huh

My regions are

[bright jay]

Your goal is to find the region that satisfies all 3 inequalities

[still temple]

Is this one region

So it has to be somewhere in the blue?

[bright jay]

You did (-4, 4) first, because it failed the first inequality, that means that region will not satisfy all three inequalities

[bright jay]

No

[bright jay]

No

[still temple]

Bruh i dont know which region is which

How do ik the regions

[bright jay]

The region is the area encompassed by the lines

The lines are the borders

[still temple]

wdym encompassed

[bright jay]

Google it

[still temple]

Which regions bro

[bright jay]

The lines are the borders

[still temple]

Is that all 3 regions

[bright jay]

No

[still temple]

Then tell me where.

[bright jay]

lines are the borders

Follow along the lines

That encompass a region

[still temple]

Thats 4 regions

[bright jay]

Yes that's 4 of the many existing regions

[still temple]

But theres 3 inequalitys

So shouldnt it be 3 invalid?

[bright jay]

No

[still temple]

<@&286206848099549185>

[bright jay]

You can have as many regions as you want

[still temple]

I need someone to better explain.

[bright jay]

There's not a set limit

[still temple]

No offence your explanation is confusing as hell to understand.

[bright jay]

Then understand it, it's not complex

[still temple]

Your doing everything but answering my question

[bright jay]

You asked

So shouldnt it be 3 invalid?

[still temple]

Anyways ill wait for someone else go have some tea.

[bright jay]

I'm saying no because you can have 10 regions if you wanted

And only certain ones will work

[still temple]

.close

[marsh citrus]

Channel closed

Closed by @wise moth

Use .reopen if this was a mistake.

[bright jay]

.reopen

[marsh citrus]

✅

[bright jay]

Don't be a prick

https://www.youtube.com/watch?v=5Lr96TAhUck&ab_channel=TheGCSEMathsTutor

[bright jay]

If you look at the video, notice this, there are 7 regions, but only one region satisfies all three inequalities, the green shaded part

[main idol]

if you're confused, ask a question and explain what you don't understand. saying this is not useful

[still temple]

I already started watching the video before u linked it m8

stop reopening this ticket its solved.

.close

[marsh citrus]

Channel closed

Closed by @wise moth

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[blazing mist]

can anyone explain squaring the ceiling function? Do I just square the inner terms?

[main idol]

think of it as two operations in one

ceiling(3.1) = 4

[blazing mist]

ok so a composition

[main idol]

4^2 = 16

[blazing mist]

so in this case it'd be, take the ceiling value and square it ?

thank you!

.close

[marsh citrus]

Channel closed

Closed by @blazing mist

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ripe oasis]

hey so apparently you can raise both sides of an equation to the power of 2

[ripe oasis]

why does this work?

and is it related to applying the exp function?

[main idol]

you're asking why x = y implies x^2 = y^2 ?

[ripe oasis]

yeah

oh well

now it's obvious

hm

but does this mean you can only raise to power of 2 if x > 0 and y > 0?

[main idol]

no

x = y = -3

what's x^2 ?

[ripe oasis]

9

ahh

[ebon smelt]

x=y => x²=y²
but x²=y² does not imply x = y

[elfin berry]

madmike

[ripe oasis]

so uhh wolframalpha says the real solutions are this

I am not sure how to get there

because I'd assume xy = 0 is true if either x=0 or y=0

but then why not x < 0

or y < 0

[ebon smelt]

you're squaring the above equation so you're getting more solutions then you're supposed to have for the original equation
y=0 and x<0 won't satisfy above equation because the output of sqrt function is positive

same is true for y<0

[ripe oasis]

ah yeah I see ...

how do you catch stuff like this?

I had no idea

thought I just need to solve for xy and then I'd get the solution

[ebon smelt]

Please note that sqrt(x²)=|x| (look at my about ^_^)
And hence putting y = 0 gives |x|=x which is true only for x>0

[ripe oasis]

ohhhh

[ebon smelt]

I wouldn't have caught it either if I was giving some test my marks would've been deducted because of that lol
But since you asked it why it isn't true I had to obviously use my mind

[ripe oasis]

ok tricky question then l0l

hm

tbh this rly confuses me

so squaring both sides is not a safe operation l0l

[ebon smelt]

No, because x² is an not an injective function

you'll have to check all the solutions manually after getting to the answer

[ripe oasis]

ahhhh that makes sense

not injective means one input can be mapped to multiple outputs so when we square we will get some solutions that might not work

[ebon smelt]

Yes

[ripe oasis]

thanks a lot

.close

[marsh citrus]

Channel closed

Closed by @ripe oasis

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

draw a triangle

[loud hamlet]

But somehow I didn’t get the right answer

[still temple]

!show

[marsh citrus]

Show your work, and if possible, explain where you are stuck.

[loud hamlet]

So.. I got sin = 5/rad34

[still temple]

how did you get that

[loud hamlet]

Sin = o/h

3 I mean

[still temple]

cos = a/h

not o/a

[loud hamlet]

Isn’t it sin?

Ooo

[still temple]

sec is 1/cos

[loud hamlet]

Tysm

.close

[marsh citrus]

Channel closed

Closed by @loud hamlet

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

Hi

[still temple]

I’m so confused

<@&286206848099549185>

[marsh citrus]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[still temple]

<@&286206848099549185>

[desert socket]

Draw a diagram and send a labelled pic

[still temple]

Ladder and wall are thee

There

[young owl]

nope, 3m is the length of the ladder

[still temple]

I know

[young owl]

not the height that the ladder reaches when tilted

[still temple]

Wait what

ohh

What’s the length

Ah thank you

[young owl]

the distance between the two extremities of an object

[still temple]

damn I’m not that smart I’m only year 9

[inner kernel]

my pleasure'

[still temple]

Your very smart

[inner kernel]

thanks.............

[desert socket]

!nosols

[marsh citrus]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[inner kernel]

ohk great didnt knew

[still temple]

Fuck off you stupid bot

[desert socket]

Also probably a ' ChatGPT answer '

[inner kernel]

damn you sure 9

hey on this app just saying can we play among us like .......

[still temple]

I’m not 9

I’m 14

I’m year 9 Uk

[inner kernel]

ok i still dont recommend you using less of those words you know it makes your personality less likable by people

no dont sorry

[still temple]

nobody likes me anyway

Doesn’t really matter

[inner kernel]

well umm can we play among us together

like here

[still temple]

Don’t have it

[inner kernel]

oh great

[marsh citrus]

@still temple Has your question been resolved?

Channel closed

Closed by @shut plover

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cyan radish]

This will probably be a hard one to explain (abstract set theory)
So we have classes that are sets and classes that aren't sets right? (I'm talking about ZFC here) There are classes that aren't sets like the sets of all sets or the sets of all tiny sets that are known to create paradoxes if one consider them a set. But are all classes that are not sets create paradoxes? If we can't answer the question, to what other question in math the provlem equivalent to?

[cyan radish]

Bro I already opened it. I dont know the answer to your question but feel free to move it to another place

[main idol]

delete your message please

[wise minnow]

We posted at the same time

I didn't know you had posted

Sorry...

[marsh citrus]

@cyan radish Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ocean marsh]

What do I do now

[main idol]

there's no question

[ocean marsh]

No

I am stuck at a step

I was dividing

And got stuck

[main idol]

dividing what ? your handwriting is all over

[ocean marsh]

(4x³-5x²-kx+32)÷ 4x-1

Is it possible to do this by division

[main idol]

what are you solving for?

it'd be a lot faster if you just showed the question with instructions

instead of going back and forth asking clarifying question

[ocean marsh]

I am literally

Just

Dividing

That's the question you know

[main idol]

no i don't know

[main idol]

this question doesn't make sense on its own

[ocean marsh]

It's not a question

Its just my query

[marsh citrus]

@ocean marsh Has your question been resolved?

Channel closed

Closed by @ocean marsh

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[urban grail]

Türk biri çözse daha iyi olur

[marsh citrus]

@urban grail Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

Quite easy little thing yet I am paranoid

[still temple]

Did I do everything correct

Basically task is to say if these logical operations have no contradictions

It has no contradictions right?

Oh wait

[raven olive]

What about A/B?

[still temple]

I am mega stupid

Yes

2 is not supposed to not exist

How stupid is that

Close

.close

[marsh citrus]

Channel closed

Closed by @visual tartan

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[graceful nacelle]

is this not 7pi/6

[still temple]

what makes you think that?

[graceful nacelle]

because A is pi/6

and B is just pi radians ahead of A

so pi+pi/6=7pi/6

[still temple]

I do not see any evidence for that in the image you've given

[graceful nacelle]

wdym

[still temple]

and B is just pi radians ahead of A

where are you getting this information?

[graceful nacelle]

thats true

i just looked at the line between the points and it went through the middle of the circle

so how do i advance

[still temple]

if you are 100% sure of this, then ask your teacher

[graceful nacelle]

no teacher, khan academy

[still temple]

then this is not true

each part is unrelated

choose the angle in the correct eighth

[graceful nacelle]

wdym

[still temple]

split the unit circle into eighths

figure out which of the four angles lies in the eighth containing B

[graceful nacelle]

it is in 5/8

[still temple]

5/8 isnt a choice

but yes, it is in the fifth eigth

[graceful nacelle]

i mean it is in number 5 of the 8

[still temple]

yes

[graceful nacelle]

7pi/8

that makes sense thanks

what

[still temple]

yeah you are right

[graceful nacelle]

yeah

it was correct

[still temple]

nice

[graceful nacelle]

.close

[marsh citrus]

Channel closed

Closed by @graceful nacelle

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cloud kettle]

If a function is defined wrongly, that is I get $$Range \nsubseteq Codomain$$, is it still a function?

[elfin berry]

Calamity

[still temple]

no

[cloud kettle]

Alright, thankyou!

[still temple]

if an object doesn't satisfy the function definition, it is not a function

[cloud kettle]

Oh okay!

.close

[marsh citrus]

Channel closed

Closed by @cloud kettle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[barren lance]

so I will explain the context first, he called it the magical square and u basically need to make a square where every row column and diagonal sums up to 15 and he did it by the making the set of sets which has the numbers that sums up to 15 and the question was to fill in the magical square

[barren lance]

he said the letter e has 4 lines through it so there must be a number in the sets of set which occurs 4 times and after that he did 1 I also understood that because that must be a nubmer that occurs 2 times

then he went to the number 8 and it needs to occur 3 times but also it has to be within a set of the number 1

and I don't understand why it had to be in the set of number 1

[marsh citrus]

@barren lance Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[storm imp]

Need help

[quasi minnow]

AM>=GM

[storm imp]

BRO CHATGPT ANSWER IS NOT IN MCQd

mcqs

Someone helppp

[twilit grove]

do not use chatgpt, it cannot do math

[storm imp]

k

[fathom ridge]

You're better off asking a monkey for math help

[brittle delta]

AM - GM is for all positive numbers not just integers

[fathom ridge]

Are integers not numbers

[brittle delta]

not just integers

[fathom ridge]

I still fail to understand the point

[brittle delta]

the answer that AM GM gives is third root of 144

[storm imp]

the solution key came in clutch

it came as 75

[fathom ridge]

You can just take the integral part of the third root

[brittle delta]

all of them need to be integers

[fathom ridge]

The AM-GM inequality will just give you a bound lol

[marsh citrus]

@storm imp Has your question been resolved?

Channel closed

Closed by @storm imp

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[distant peak]

I'm having a brain fart, I forgot how to bound this type of integral :
$\int_a ^b x^{\alpha -1} e^{-x} \lvert \phi_n (x) - \phi(x) \rvert dx$ with $\phi_n \to \phi$ uniformely

[elfin berry]

Herels

[distant peak]

if someone can help me remember

[marsh citrus]

@distant peak Has your question been resolved?

[azure pier]

are a and b positive ?

whatever that doesn't matter (though if [a, b] contains 0 then it's better to have alpha < 0)

[distant peak]

yes they are

[distant peak]

it doesnt contain 0

[azure pier]

alright

then I guess you can say $$\int_a^b x^{\alpha -1} e^{-x} \lvert \phi_n (x) - \phi(x) \rvert dx \leq ||\phi_n - \phi||_{\infty} \int_a^b x^{\alpha-1} e^{-x} dx$$

[elfin berry]

Gio'

[distant peak]

oh 🤔

I thought there would be (b-a) ||phi_n - phi||

[azure pier]

you mean an extra (b - a) factor?

[distant peak]

yea

[azure pier]

here we're still integrating something which is not 1 so it doesn't appear

[distant peak]

Since you would need to bound gamma(alpha) there too nah ?

[azure pier]

we're just using the fact that if f <= g then \int_a^b f <= \int_a^b g

[distant peak]

hmm

wait its not gamma

[azure pier]

it is gamma

[distant peak]

the bound

it goes from 0 to inf

to be gamma

[azure pier]

yes of course but we can bound this by gamma(alpha) since x^alpha-1 e^-x is positive

[distant peak]

ah yes true

I've reduced the bounds to a and b cuz I wanted to bound an integral from 0 to inf

so I made the supposition that we work on a compact set

[azure pier]

hmm right

well if the integral converges then this rule also applies (the limit preserves large inequalities)

[distant peak]

okk thx

.close

[marsh citrus]

Channel closed

Closed by @distant peak

Use .reopen if this was a mistake.

[azure pier]

np :)

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[smoky terrace]

is there something like peano's axioms but for rationals or maybe even reals?

[still temple]

maybe try asking in#foundations

[smoky terrace]

Ok

.close

[marsh citrus]

Channel closed

Closed by @smoky terrace

Use .reopen if this was a mistake.

[smoky terrace]

the channel is closed for me

[still temple]

follow instructions in #get-advanced-access

[smoky terrace]

ok

thanks

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mellow willow]

How do I become an expert at integrals, I know I need to practice so Im wondering whether someone has a file that has a list of integrals from easy to hard and any tips are appreciated

[distant peak]

Bluepenredpen video marathon

[mellow willow]

Where do I find that

[distant peak]

youtube

[mellow willow]

Oh this 5 hour one

[distant peak]

https://youtu.be/dgm4-3-Iv3s

have fun

[mellow willow]

This is perfect

Thank you

.close

[marsh citrus]

Channel closed

Closed by @mellow willow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bitter tulip]

Let $f: \mathbb{R}\to\mathbb{R}$ be a function as $f(x) = (x-1)(x+2)(x-3)(x-6)-100$. If $g(x)$ is a polynomial of degree $\le 3$ such that $\int \frac{g(x)}{f(x)} dx$ does not contain any logarithm function and $g(-2) = 10$. Then the minimum value of $f(x)$ is

[elfin berry]

lmaowhat

[bitter tulip]

All I was able to do till now was factorize it

$$t = (x-1)(x-3) = x^2-4x+3$$
Then $$(x-1)(x+2)(x-3)(x-6)-100 = t(t-15)-100 = t^2-15t-100$$
$$= (t-20)(t+5) = (x^2-4x-17)(x^2-4x+8)$$

[elfin berry]

lmaowhat

[bitter tulip]

Now what?

I can't seem to use the information provided in the question

[marsh citrus]

@bitter tulip Has your question been resolved?

[bitter tulip]

<@&286206848099549185>

[marsh citrus]

@bitter tulip Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[marble glacier]

https://gyazo.com/387ee9c8abbcb57fd77f9928e9f77af8

[marble glacier]

https://gyazo.com/fdd694e6b0361daeb611a5bdf1732a7c

why is the bounds in polar coords pi/2 ?

[marsh citrus]

@marble glacier Has your question been resolved?

Channel closed

Closed by @marble glacier

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[round magnet]

I don't understand how my teacher rewrites the expressions, such as:
3 - 2 * ( 8 - 2 * 3 ) = -1 * 8 + 3 * 3
and the rest

[round magnet]

generally just how he rewrites all the expressions

[amber ruin]

lol isn't it wrong