#help-33

1 messages · Page 39 of 1

weary temple
#

Does this set have a name in English. I was interested in reading more about it but I couldn't find anything on it. Perhaps related to p-adic?

stoic saddle
#

"fractions between 0 and 1 with denominator equal to a power of 3"

weary temple
stoic saddle
#

well you could call them triadic fractions by analogy with dyadic fractions ig

weary temple
#

Alrighty well thank you!

#

.close

marsh citrusBOT
#
Channel closed

Closed by @weary temple

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sharp whale
#

Is this sketch correct for the complex plane?

marsh citrusBOT
#

@sharp whale Has your question been resolved?

marsh citrusBOT
#

@sharp whale Has your question been resolved?

sharp whale
#

<@&286206848099549185>

marsh citrusBOT
#

@sharp whale Has your question been resolved?

static orchid
#

@sharp whale Yes it is.

sharp whale
#

thanks

#

so lets say it was just mod(z-i) for example

#

would it be the same circle

#

just with an origin of (1,1) instead right

sharp whale
#

No correction, would be origin (0,1)

#

since you should have a^2 + (b-i)^2 = 1

marsh citrusBOT
#

@sharp whale Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

still temple
#

Is the answer b or a?

marsh citrusBOT
still temple
nova totem
#

We don't give out answers

#

Use geometric mean theorem if you need to

still temple
#

Im not asking for answer i think its a but theres a chance its b too

#

Im asking if b or a is correct

still temple
#

<@&286206848099549185>

velvet cairn
#

R u seeing any similar triangles ?

still temple
#

Whats that mean

#

BDA and CBA?

#

thats one

still temple
#

I think b is right but a might be right too

velvet cairn
#

Yes

still temple
#

its b?

marsh citrusBOT
#

@still temple Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sly thunder
marsh citrusBOT
sly thunder
#

@upper briar

#

The probability is 83,6%

#

Correct?

tribal panther
#

Correct

sly thunder
#

Thanks

#

.close

marsh citrusBOT
#
Channel closed

Closed by @sly thunder

Use .reopen if this was a mistake.

upper briar
#

yay

#

🕊️

sly thunder
#

😆

#

.reopen

marsh citrusBOT
#

sly thunder
#

Wait I show

#

If the r=1,2kohm

#

How calculate probability

#

Do resistance change when mean change?

upper briar
#

did u mean the standard deviation?

#

like are u asking abt 6.4

sly thunder
#

Yes, 6,4

#

Mean of 10k

#

SD of 1,2k

#

Less than 9,8k Ohm
Only 9,6-9,7? Or I wrong

upper briar
#

oh

#

well

#

u kinda repeat the same thing

#

but u find a calculator with normal distribution

#

with mean of 10k, std of 1.2k

#

std is standard deviation

sly thunder
#

Because my friends, they are said I wrong

#

If I only choose 9,6-9,7 for question a

#

I ask but they don't explain

sly thunder
#

I will know all if I know this

upper briar
#

oh

#

6.4 u ignore the stuff previously said

#

it says suppose that it follows normal distribution

#

so all prev stuff is irrelavent

upper briar
#

alternatively use the normal distribution formula

sly thunder
#

Ok

#

Thanks

#

Bye bye and see you soon

#

.close

marsh citrusBOT
#
Channel closed

Closed by @sly thunder

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

void patio
#

Using Linear Equations system, how would I solve this?

Fe^7 + O^2 -> Fe^3 O^2 + S O^2

void patio
#

The answer is (0,0,0)

brave spire
#

Uhm excuse me?

#

This is not maths, its chemistry

drowsy bronze
#

lmaoo

brave spire
#

Cus..like I dont think u can call ur variables Fe

marsh citrusBOT
#

@void patio Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

ornate silo
marsh citrusBOT
brave spire
#

Risolvere means solve ig?

drowsy bronze
#

yeah

#

italian

#

🤔

brave spire
#

@drowsy bronze

drowsy bronze
#

yup

brave spire
#

K

brave spire
ornate silo
#

yeah sorry

#

i did some and got stuck in the middle

brave spire
#

Okay, can u send ur work?

ornate silo
#

yes

brave spire
#

Hmm..Well, just take log(base3)x common (In the numerator)

#

that would become 2/3 * log(base 3) x

#

then transpose 2/3 to the other side

drowsy bronze
#

@brave spire final answer?

brave spire
drowsy bronze
#

i want to confirm

ornate silo
#

let me try one sec

brave spire
drowsy bronze
#

alright

#

😦

ornate silo
#

Like this right ?

brave spire
#

yes

ornate silo
#

got it 27.

#

thanks a lot. really appreciate.

brave spire
#

Np bud

ornate silo
#

.close

marsh citrusBOT
#
Channel closed

Closed by @ornate silo

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tender ocean
marsh citrusBOT
tender ocean
#

ok so the solution states $\sin \frac {1} {x}$ tends to $\lambda$ as x tends to 0, where lambda is [-1,1]

#

i dont understand how that makes sense

elfin berryBOT
glass silo
#

Do you have the solution as it appears like that?

tender ocean
tender ocean
glass silo
# tender ocean

I don't get what they meant by that tbh, but at least otherwise I can kinda see that... [they divided numerator and denom by x in aim of working out the limits of them both, which can be done]

tender ocean
glass silo
#

Ohhhh alright I get what they're saying now 🥪

#

The sin(1/x) is bounded between -1 and 1, and as x tends to zero, you must have that x * sin(1/x) tends to zero too, as it's sandwiched

#

A weird way of saying that, and the fact that they used lambda in the question as well as the solution thonkHang

tender ocean
glass silo
#

The limit of it doesn't exist by itself no

#

However it is bounded

#

,w plot y = abs(x), y = -abs(x), y = x * sin(1/x)

tender ocean
#

does this work for other trig functions too?

#

what about x tan (1/x) or x cos(1/x)

glass silo
#

For x * cos(1/x), it's a similar picture, cos is bounded between -1 and 1

#

,w plot y = abs(x), y = -abs(x), y = x * cos(1/x)

tender ocean
#

so cos (1/x) x is also zero

glass silo
#

For tan I'm not too sure because it's not necessarily bounded, so you can't really sandwich it

#

,w plot y = abs(x), y = -abs(x), y = x * tan(1/x)

tender ocean
#

interesting

glass silo
#

(as you can see, the bounds I used before for sin and cos don't work, so at the very least you'd need to find new ones, but the image suggests they don't exist...)

#

,w lim x * tan(1/x), x to zero

tender ocean
glass silo
#

It's the boundedness which is the crucial property we're using

tender ocean
glass silo
#

Because sin and cos were bounded, we were able to create "sandwich/squeeze" functions that those products had to be in between

glass silo
#

,w sandwich theorem

glass silo
tender ocean
glass silo
#

Aha, fair enough, well now you've seen an application of it catGiggle weird cause it seems like that's what they're trying to use there thinkies

tender ocean
#

yea got it

#

thanks

#

.close

marsh citrusBOT
#
Channel closed

Closed by @tender ocean

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

fathom hawk
marsh citrusBOT
fathom hawk
#

<@&286206848099549185>

pallid pine
#

!15m

marsh citrusBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

pallid pine
#

then

#

-18 < 3y < 6

#

well acc i dont even know why i typed

#

lmao my brain has just stopped at this part

mystic walrus
# fathom hawk

I personally would calculate the amount of possible values, then see how many can be answered like that?

#

Sorry I'm also really tired so there's probably a much better way to do it KFHS

pallid pine
#

well acc

#

i think i have an idea

fathom hawk
#

what is it

pallid pine
#

since -18 < 3y < 6, and -4<= x < 6

#

they overlap at the numbers

#

where 3y and x are

#

-4 -3 -2 -1 0 1 2 3 4 5

#

and since youre minusing these two together

#

this is almost exactly

#

like when you add two dice rolls together

marsh citrusBOT
#

@fathom hawk Has your question been resolved?

#
Channel closed

Closed by @fathom hawk

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

jagged turret
#

can you translate to english

marsh citrusBOT
jagged turret
#

is the limit the ratio of leading coefficients?

lucid zenith
#

yes

jagged turret
#

what does that mean

lucid zenith
#

that's what is written

#

if you have a function which is the ratio of two polynomial functions of the same degree, the limit as x tends to +- infinity is the ratio of the leading coefficients of the two polynomials

fluid yarrow
#

leading coefficient is the coefficient of the term with the highest degree

jagged turret
#

i understand

#

you take the highest equal coefficients

#

but what does that "ratio" mean?

lucid zenith
#

the two polynomials have to be of the same degree

jagged turret
#

yes

#

understood

knotty trellis
jagged turret
#

a/b is horizontal asymptote not a limit though

lucid zenith
#

then the limit of the function is the limit of a/b (considering a and b to be the coefficients of the terms with the highest power of x in the numerator and denominator, respectively)

knotty trellis
jagged turret
#

thats what

#

we were finding

#

as x aproaches -inf, and +infinity

stoic saddle
jagged turret
#

so its both

#

limit and horizontal asymptote

lucid zenith
#

for example, you have $\lim_{x\to\pm\infty} \frac{4x^2+3x-9}{5x^2+8x-10} = \frac{4}{5}$

jagged turret
#

thought u need a small hole for it to be the limit

elfin berryBOT
#

kheerii

jagged turret
#

ok

#

the limit of that would be whatever equals 0 in the denominator

#

not 4/5?

#

which is a horizontal asymptote

jagged turret
#

limit wont be 4/5

stoic saddle
#

it will.

#

unless you'd like to tell us it'll be something else

jagged turret
#

limit means

#

it gets close to it

#

but never touches

#

4/5 is an x value

#

that has a y value

#

if i plug in 4/5 it wont be undefined

lucid zenith
#

4/5 is a y value

#

not an x value

jagged turret
#

oh?

lucid zenith
#

x is tending to +-infinity isn't it?

jagged turret
#

how do i find 4/5

#

on calc

#

for y value

lucid zenith
#

what do you mean

jagged turret
#

if i want to confirm

#

its 4/5

#

for limit

lucid zenith
#

,w graph (4x^2+3x-9)/(5x^2+8x-10)

jagged turret
#

where do plug in

#

find y

jagged turret
#

at 4/5

lucid zenith
#

you're calculating the limit as x tends to +- infinity

#

what do you understand from that?

lucid zenith
jagged turret
#

there are two vertical amsmytotes there

#

how do i find

#

limit

#

using calculator

lucid zenith
#

forget the calculator for a moment.

#

forget everything

lucid zenith
jagged turret
#

limit along the domain

#

from - to + infinity

lucid zenith
#

what

#

forget the +-

jagged turret
#

ur finding holes

lucid zenith
#

let's say

#

you have a function

#

f(x)

#

when I ask you what the limit of f(x) is as x tends to +infinity

#

what does that mean?

jagged turret
#

means find if there are any holes in positive infinity f(x)

#

x>0

lucid zenith
#

what do you mean "holes"

jagged turret
#

gaps

#

where x doesnt touch

#

it has to skip over

#

like a constant is 5x

#

but cant equal 1

#

for example

#

then u have a hole

#

at x =1

#

a limit at x=1

#

for example

lucid zenith
#

that is a different kind of limit

#

well

#

not a different kind of limit

#

but

#

it represents a different thing

#

when x tends to infinity, it literally means x tends to infinity.

lucid zenith
jagged turret
#

ohok

#

so

#

a horizontal

#

asymtote

#

needs to be there

#

in order for

#

x-> infinity

lucid zenith
#

yup

jagged turret
#

i dont see it

lucid zenith
#

this graph isn't a great example

jagged turret
#

whats a better one

lucid zenith
#

take sin(x)/x

#

,w graph sin(x)/x for x from -100 to 100

jagged turret
#

looks like an octopus

lucid zenith
#

oh my god

#

wait

lucid zenith
#

yes

#

so

#

do you see how the value of the function approaches 0?

jagged turret
#

it crosses over

#

0

#

many times

lucid zenith
#

yes

#

but

#

as x tends to infinity (as x gets larger)

#

what happens to the value of the function

#

do you see how the waves get closer and closer to 0

#

,w graph sin(x)/x for x from 0 to 1000

lucid zenith
#

notice the downward bend in the graph

jagged turret
#

looks like something else tbh

#

but yes

#

it gets closer

#

to 0

#

can we use

#

a non sin graph

#

im religious

#

i dont sin

lucid zenith
#

take 1/x

#

easiest example

#

,w graph 1/x for x from 0 to 20

jagged turret
#

cool

#

i see that

#

but now

jagged turret
lucid zenith
#

yes

jagged turret
#

ty

lucid zenith
#

that's what the theorem states

#

you can think of it as the lower powers of x "fading away" as x gets larger and larger, leaving only 4x^2/5x^2 inside the limit, which evaluates to 4/5

jagged turret
#

ok

#

makes sense

#

tyvm @lucid zenith

#

.close

marsh citrusBOT
#
Channel closed

Closed by @jagged turret

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

abstract coyote
marsh citrusBOT
abstract coyote
#

I understand how the coordinates for a,b,c,d,and j were fource

#

But how were the coordinates for e,f,g,h determined

#

For example, F is not in the same y position as O is, but how do i know how far to go down to reach F

marsh citrusBOT
#

@abstract coyote Has your question been resolved?

marsh citrusBOT
#

@abstract coyote Has your question been resolved?

marsh citrusBOT
#

@abstract coyote Has your question been resolved?

abstract coyote
#

<@&286206848099549185>

marsh citrusBOT
#

@abstract coyote Has your question been resolved?

marsh citrusBOT
#

@abstract coyote Has your question been resolved?

sand garden
#

<@&286206848099549185>

still temple
#

Hey

#

Whats the question

#

This is @abstract coyote channel

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

still temple
marsh citrusBOT
still temple
#

.close

marsh citrusBOT
#
Channel closed

Closed by @hardy bridge

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

alpine basalt
#

In mathematical logic/proofs, are $\iff$ and $\text{iff}$ interchangeable?

elfin berryBOT
#

normalAtmosphericPa=101,325

stoic saddle
#

yes

alpine basalt
#

i.e., if I use "iff" in my statement to restrict some claim of mine, will I then need to go on to show a proof in both directions?

#

I often don't see people doing so though

devout mauve
#

yes both directions

#

sometimes one direction is obvious

#

or the proof goes the same in both directions

alpine basalt
#

p => q is equivalent to (~p)vq. The implication p=>q is true provided either p is false or q is true.
^^ why is this statement true/?

alpine basalt
#

i.e., "if x=5, then x^2=25", is equivalent to "if x≠5, then x^2=25???"

alpine basalt
#

either (~p) or q is true right?

devout mauve
#

"or" doesnt mean exclusive or

#

if p is false then ~p is true and it doesnt matter what q is

#

if p is true then ~p is false and q has to be true for (~p or q) to be true

alpine basalt
#

I should really comb through a basic proofs book aye

#

I think they contain logic

#

is there a difference between propositional and predicate logic?

marsh citrusBOT
#

@alpine basalt Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

random sphinx
marsh citrusBOT
#

@random sphinx Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

ivory laurel
#

Just to quickly check,suppose in an ODE, the complimentary solution is e^x(sin(x)+cos(x))

still temple
#

yes?

ivory laurel
#

For my particular solution can I use Ae^x as my Ansatz

still temple
#

it depends on the inhomogeneous function

#

i.e. the function on the RHS

#

the complementary solution tells you nothing

ivory laurel
#

Yes the inhomogeneous functions is a linear combination of e^x

still temple
#

show me the problem

ivory laurel
#

I just mean is the Ansatz allowed since if it is then then the problem is solved

still temple
#

If we have a linear combination of $e^x$ on the RHS. That is, $c_1e^{bx} + \hdots + c_re^{rx}$ then the Ansatz is going to be $Ae^{bx} + \hdots + Ne^{rx}$.

elfin berryBOT
lethal shell
#

Yes I believe so, it doesn’t affect the complimentary function you stated hence making it valid

still temple
#

where A, ...., N are coefficients to be discovered

#

(if you are using the method of undetermined coefficients)

marsh citrusBOT
#

@ivory laurel Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

smoky marsh
#

if i had the sum start at n=0 would it then be (-1/8)^n-3?

smoky marsh
#

or n+3

high pine
#

n+3

smoky marsh
#

so as i take away from n, the exponent increases right

devout mauve
#

it might help to make the substitution very explicitly. set $k=n-3$. then $k$ starts at $0$. also $n=k+3$ so you can exchange the exponent using that. so $\sum_{k=0}^\infty (-\frac18)^{k+3}$

elfin berryBOT
#

Denascite

smoky marsh
#

ah yea that makes sense, i tried setting up a formula like that but this one is much neater

#

thanks! .close

#

.close

marsh citrusBOT
#
Channel closed

Closed by @smoky marsh

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

still temple
#

Hey ! I do not understand how this is right.
1 + (yz/(1+yz)) • x = (1 + yz + yx + zx)/(1 +yz)
On the right side of the equality, where do we get the yz from ?

burnt oxide
#

hi

lean flame
#

Which yz?

#

I see many of them

still temple
#

On top

#

In the red square on the bottom

#

In 1 + yz + yx + zx

lean flame
#

Because when we add 1 and .../yz, we take yz as common denominator

#

1+yz as common denominator*

#

So 1 * (1+yz)/(1+yz) + .../(1+yz)

still temple
#

@lean flame oh it get it ! Thank you very much

marsh citrusBOT
#

@still temple Has your question been resolved?

#
Channel closed

Closed by @hearty arch

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

woeful glade
marsh citrusBOT
woeful glade
#

could sm1 help me for IBP

#

for this

#

u=n+3

#

du = 1

#

dv = 1/(-5)^n

#

idk how to get v

#

ik u take the antidervative

#

but how do u take the antidervative of it

marsh citrusBOT
#

@woeful glade Has your question been resolved?

tight furnace
#

first simplify it

woeful glade
#

what

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

tight furnace
#

use exponent laws

#

. reopen

#

.reopen

marsh citrusBOT
#

tight furnace
#

writing 1 as 1^n might help

#

or wait hmmCat

#

tf are they doing bringing a negative to the power of n when n varies across a continuum

#

there's going to be complex values involved whenever n isn't an integer

woeful glade
#

we gotta take the intergral test

tight furnace
#

is this your NA then

#

doesn't look like the function is in the realm of what you should be dealing with integrating

woeful glade
#

because it oscillates betweeen neg and positive values?

tight furnace
#

well I mean

#

,w plot 1/(-5)^x

elfin berryBOT
tight furnace
#

complex valued function is the problem

#

it could be integrated still, over the complex numbers

#

but since that isn't in the scope of calc 1 at all I'd say it means not integrable

glass silo
#

It's worth remembering the conditions for integral test tho

#

[could tell that there probably was some other problem behind this lolDog]

tight furnace
#

ah well still

tight furnace
marsh citrusBOT
#

@woeful glade Has your question been resolved?

woeful glade
#

daam what am i doing wrong here

tight furnace
#

did you try just putting NA?

#

or is it the other problems

#

2 of the other answers are also outlined in red

marsh citrusBOT
#

@woeful glade Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dreamy trench
#

does there exist a closed form for the arithmetic geometric mean?

dreamy trench
#

as in not a recurrence

main idol
#

it ain't pretty

dreamy trench
#

hmm

#

this would be ideal but i'm not too sure about using elliptic integrals

still temple
#

what do you mean by "ideal"

dreamy trench
#

i just want something reasonably accurate and computationally simple

still temple
#

what is the original question that you want to answer, before we get too deep into the xy rabbit hole

dreamy trench
#

i want to make a function on my calculator for the agm but it's really slow so i don't want to have to resort to integral expressions

#

so now i'm just wondering how many iterations of the sequence defn are required to be reasonably close (maybe to 3 decimals or so)

still temple
#

I doubt doing the integral numerically would converge much faster than the recursion

#

there's a siam paper for this lmao

main idol
#

SIAM -> NIAM -> NIAP -> PAIN

still temple
#

convergence rates for their computation of pi are pretty good

main idol
#

wow 2788 digits correct just in 10 iterations

marsh citrusBOT
#

@dreamy trench Has your question been resolved?

still temple
#

3 iterations already convinces python

#
a = [np.sqrt(2)]
b = [0.]
p = [2.+np.sqrt(2)]


for i in range(3):
    a.append((a[-1]**.5+a[-1]**-.5 )/2.)
    b.append((a[-2]**.5)* ((b[-1]+1)/(b[-1]+a[-2])))
    p.append(p[-1]*b[-1]*((1+a[-1])/(1+b[-1])))
    print(p[-1], p[-1]==np.pi)```
marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dire dawn
#

tried this a few times and I'm always way off, I don't know what to do.

marsh citrusBOT
#

@dire dawn Has your question been resolved?

dire dawn
#

honestly i had no idea what I was doing and I kept erasing things so it might not all be on there

marsh citrusBOT
#

@dire dawn Has your question been resolved?

dire dawn
#

.close

marsh citrusBOT
#
Channel closed

Closed by @dire dawn

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

long arch
#

yes

#

yes

#

you need to write 512 as a power of 8

#

then you can cancel with the log

#

probably

#

idk my powers of 8

#

write sqrt(125) as a power of 5

#

yes

#

yes

marsh citrusBOT
#

@still temple Has your question been resolved?

#
Channel closed

Closed by @rare agate

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

jagged turret
#

How does the bottom question, answer C make sense

jagged turret
#

Shouldnt it be 415 not 405?

#

it says "interpret A'6 = 405" then it talks about a(7)

#

a(7) if we were to go there, is = 8514

#

a(6) = 8099

#

a(7)-a(6) = 415

#

not 405

#

a'(7) = 425

knotty trellis
#

Interpreting A'(6) like that indeed doesnt make sense. A'(6) means that the instantenous rate of change is 405. But 1 month later it will be greater, so using that you can just aproximate A(7)

jagged turret
#

a'(6)= 404

#

a'(7)-a'(6)=20

jagged turret
#

not "approximately will be"

knotty trellis
#

Yeah, and that's why I think it's incorrect

jagged turret
#

the instantaneous rate of change is 425

#

not 405

#

but yes i agree with you

#

I was told last night though

#

that it made sense

#

something about

#

a'(7)-a'(6) = a'(7-6) * a'(6)

#

or something like that

#

found it

#

is this true

knotty trellis
#

Aproximately

#

so yeah

jagged turret
#

well thats baloney

#

because the question

#

answer c*

#

is saying "it is x value"

#

not "approximately"

knotty trellis
#

thats weird

jagged turret
#

well

#

what would it be

#

then

#

really

#

would i be taking

#

a'(7)-a'(6)

#

or a(7)-a(6)

jagged turret
knotty trellis
#

I feel like none of the answers is correct interpretation of A'(6)=405, C) is a decent approximation

jagged turret
#

ok so just f this problem then

#

thanks mathisalwaysright

#

in this case guess "mathway" isnt always right

#

.close

marsh citrusBOT
#
Channel closed

Closed by @jagged turret

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

rocky pilot
marsh citrusBOT
rocky pilot
#

Did I do these one's right?

marsh citrusBOT
#

@rocky pilot Has your question been resolved?

rocky pilot
#

<@&286206848099549185> ?

marsh citrusBOT
#

@rocky pilot Has your question been resolved?

rocky pilot
#

neat.

#

.close

marsh citrusBOT
#
Channel closed

Closed by @rocky pilot

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

bitter tulip
#

Hello. Any ideas on how to solve this?

marsh citrusBOT
bitter tulip
#

I tried taking ln and then differentiating but I don’t think that gives anything useful

worn nimbus
#

do you need to find the exact value

#

or just converges/diverges

bitter tulip
#

Exact value

#

In terms of x of course

worn nimbus
#

looks very difficult

bitter tulip
#

You’re supposed to solve this in 3 minutes apparently

worn nimbus
#

bruh lmao

marsh citrusBOT
#

@bitter tulip Has your question been resolved?

marsh citrusBOT
#

@bitter tulip Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

austere steppe
#

need help

marsh citrusBOT
austere steppe
#

why is it positioned there

#

i dont get how graphing works

#

y= -2x+1

#

why is it not in 2?

still temple
#

you don't understand how/why the line y = -2x+1 is graphed like that?

#

well the best way to see why is to pick 3 x values, say x = 0, 1, 2 and plot them on the graph

austere steppe
#

yess i think im struggling the teacher didnt provide a video lesson for us anymore 😭 so the handout given is straightforward

still temple
#

and then try to extend the line to infinity

#

so like,

#

lets try it

#

get a piece of paper or something

#

draw the coordinates

austere steppe
#

okey

still temple
#

okay so did u do it

austere steppe
still temple
#

right okay

#

so you have y = -2x+1

austere steppe
#

Yess

still temple
#

lets try taking some x values

#

lets start with x = 0

#

in that equation, what would y be for this x value

austere steppe
#

1??

still temple
#

yep!

#

u got it

#

so you have (0,1)

austere steppe
#

points?

still temple
#

can you try plotting that point in

#

yep

austere steppe
#

Ill plot 0,1

#

?

still temple
#

umm

#

why did u draw the line already? 😅

austere steppe
#

wait what do you mean by plot 😭

#

to test point?

#

OH WAIT

#

SORRY

still temple
#

wait gtg sorry 😭 but just basically try to draw the points and connect them then u will see the patttern of the line

austere steppe
#

is this correct?

#

@still temple

still temple
austere steppe
#

tysm!

#

wait

#

i get it now

#

omg

#

ty

#

ty

#

ty

#

sooo

still temple
austere steppe
#

i have to

still temple
#

okie kinda back

austere steppe
#

create a test point

#

right?

still temple
#

the idea is like

#

plot a few points

#

then connect those dots in a line

#

and then

#

just extend that line

#

forever in both sides

#

thats lke

#

like

#

the easiest way to go about it

austere steppe
#

wait so where did you get

#

0

still temple
#

like

#

it can be anything

marsh citrusBOT
#

@austere steppe Has your question been resolved?

#
Channel closed

Closed by @austere steppe

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

hexed sparrow
#

I am not sure what I did wrong here. Green is what the actual answer is and red is my answer

nimble mason
proper zodiac
hexed sparrow
#

Great to hear gotta review those cause I forgot a lot of them. Ty

#

.close

marsh citrusBOT
#
Channel closed

Closed by @hexed sparrow

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

brittle sun
#

I solved it but am not sure if my way is correct

brittle sun
#

i did 12-x+x/2 = 6

#

then

#

18-x+x/2 = 9

#

then did 9+6 = 15

#

i am not sure if this way is correct tho

sturdy plank
#

im not sure i follow.. this is what i would do:

sturdy plank
trim quest
#

rather than minus

sturdy plank
#

oh the averages, yeah mb

#

he can fix up my calculations xD (yeah 15's correct, you're good JoRe)

marsh citrusBOT
#

@brittle sun Has your question been resolved?

trim quest
marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

barren tangle
#

Any idea what I did wrong?

marsh citrusBOT
#

@barren tangle Has your question been resolved?

marsh citrusBOT
#

@barren tangle Has your question been resolved?

barren tangle
#

.close

marsh citrusBOT
#
Channel closed

Closed by @barren tangle

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dusky turret
marsh citrusBOT
dusky turret
#

i need help finding the interest paid

marsh citrusBOT
#

@dusky turret Has your question been resolved?

#
Channel closed

Closed by @dusky turret

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

fading plank
#

How would i do this

marsh citrusBOT
#

@fading plank Has your question been resolved?

marsh citrusBOT
#

@fading plank Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

uneven wraith
#

not sure why U turns into and because i thought it turned into or

uneven wraith
worn nimbus
#

x is NOT in A union B

#

$\overline{A \cup B} = \bar{A} \cap \bar{B}$

elfin berryBOT
high pine
#

de Morgan

worn nimbus
#

so $x \in \bar{A} \cap \bar{B} \iff x \notin A \cup B$

elfin berryBOT
whole sleet
#

If x is not in A U B, then it had better be the case that x is not in A, and that x is not in B.

For example, if x were in A, then x would also be in A U B.

uneven wraith
#

so if it was x is not in A intersection B would it turn into x is in A union B?

whole sleet
#

If x is not in A n B

Then x is not in A, or x is not in B.

#

In other words, if x is not in both, then it has to be missing from one of them.

marsh citrusBOT
#

@uneven wraith Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

earnest rain
marsh citrusBOT
#

@earnest rain Has your question been resolved?

earnest rain
#

<@&286206848099549185>

#

Huh?

#

.close

marsh citrusBOT
#
Channel closed

Closed by @earnest rain

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

undone kindle
marsh citrusBOT
undone kindle
#

Pretty sure what I did is illegal

#

Can I get some help on the proper way to do this?

marsh citrusBOT
#

@undone kindle Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

fair cove
#

how can i solve this question with no initial condition

fair cove
#

.close

marsh citrusBOT
#
Channel closed

Closed by @fair cove

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

orchid scarab
#

how do i answerthis?

marsh citrusBOT
willow plinth
orchid scarab
#

yea i just need help w the square

#

idk the approach for it

willow plinth
#

n = 19

#

i = 0

#

you start from 0

#

and end at 19

#

so (0+3)^2 + (1+3)^2 + (2+3)^2 .... (19+3)^2

#

up until the nth term

#

which is 19

orchid scarab
#

yea im doing double summation to make it easier for me doe + brute forcing isnt allowed

#

ik how to do the first summation

#

and teh second i just dk what to do with the square

willow plinth
#

I dont quite udnerstand

#

your question

#

what are you trying to do

orchid scarab
#

double summation

#

using double summation so i dont have to brute force substituting the i values and adding it

pallid pine
#

@orchid scarab wdym by double

#

im pretty sure

#

double summation

#

is when you have two summations with different letters

#

at the same time

#

like this

pallid pine
#

what you can do is

#

expand that bracket

#

then you can use the rules

#

for i^2

#

i

#

and constant

marsh citrusBOT
#

@orchid scarab Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

long cape
marsh citrusBOT
long cape
#

would the second line be equal or am I not allowed to distribute into unequal powers?

#

if I consider - as (-1)^1

#

1 and -1 would not match powers

#

so therefor should I just use (x+3)^-1 instead?

#

converting -(factor) to + (-1)(factor) is like changing the subtraction operator - into a power 1 factor, ya? always power 1

cobalt sentinel
#

Is this wat ur talking about?

elfin berryBOT
#

Stephen

cobalt sentinel
#

Sorry it goes to the next line and looks bad

#

U have a sign error at the end

#

O ur talking abt the powers

long cape
cobalt sentinel
long cape
#

OK

cobalt sentinel
cobalt sentinel
long cape
#

so no issues with this? ^

cobalt sentinel
#

Correct no issues

long cape
#

what I don't get, is when I distribute - into (1/(x+3))

#

top version

#

I can decide on distributing the - into the numerator *or * the denominator

#

but when it's written like (x+3)^-1 I can't distribute the - operator into it at all

#

I may be confusing this with multiplication, not subtraction

#

but same thing applies

#

actually nvm, subtraction too

#

I can change - into + (-1) for subtraction

cobalt sentinel
long cape
#

yeah exactly

#

but if it's written -5(1/(2x+2)) I could make it -5/(2x+2) **or ** 5/(-2x-2)

cobalt sentinel
#

Yes that’s correct

long cape
#

it's like deciding do I want the negative for 5 to be -5/1 or 5/-1

cobalt sentinel
#

Yep

long cape
#

but I lose that ability when the power is negative, right?

cobalt sentinel
#

Example?

long cape
#

-5(2x+2)^-1

cobalt sentinel
#

I mean even if it was -5(2x+2)^2 u couldn’t distribute in

long cape
#

true, but -5(1/(2x+2)) is the same thing as -5(2x+2)^-1, just different notation.. or so I thought

#

so basically, negative exponent can cause issue for stuff like this? .. I guess it depends on what I need to do with them?

cobalt sentinel
cobalt sentinel
#

Could also do something like this

elfin berryBOT
#

Stephen

rugged cobalt
#

its because when you distribute the -1 you are distributing 1/-1

#

which is -1^-1

cobalt sentinel
#

Is that musashi’s friend?

#

In ur pfp

rugged cobalt
#

yes lol

#

'friend'

cobalt sentinel
#

yea

#

Controversial take: I’m happy the author went on hiatus (hope they feel better tho or whatever happened)

#

Cuz I didn’t want kojiro and him to fight

rugged cobalt
#

yea same i think that was the reason he stopped

#

cant remember though

cobalt sentinel
#

ah

marsh citrusBOT
#

@long cape Has your question been resolved?

marsh citrusBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

white brook
#

Stuck on:

marsh citrusBOT
white brook
#

What I've tried

marsh citrusBOT
#

@white brook Has your question been resolved?

marsh citrusBOT
#

@white brook Has your question been resolved?

#
Channel closed

Closed by @white brook

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

fallow arrow
marsh citrusBOT
#

Please don't occupy multiple help channels.

fallow arrow
#

does anyone k what they mean by this thing

#

why would u ever subtract the omitted term from the 8th term

#

usually you would ifnd the summation of 8 terms and subtract and add the 9th

pallid pine
#

i just

#

googled

#

what the alternating series error term is

fallow arrow
#

it might be a bit difficult tho

#

because this is a complicated question since ur using the partial sum notation to get it

pallid pine
#

remember that the error cannot be bigger than the next term of the series

#

so if we choose S8

#

the error cant be bigger than a9

fallow arrow
#

the error is always the omitted term

pallid pine
#

and since a9 = S9 - S8

fallow arrow
#

how does a9=S9-S8

pallid pine
#

remember

fallow arrow
#

i didnt understand that part

pallid pine
#

back

#

to when

#

found out that

#

an = Sn - Sn-1

#

substitute n = 9

fallow arrow
#

no way 💀

#

it connects

marsh citrusBOT
#

@fallow arrow Has your question been resolved?

#
Channel closed

Closed by @fallow arrow

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

paper venture
#

A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and other features. The distribution of the number of months in service for the fleet of cars is bell-shaped and has a mean of 43 months and a standard deviation of 8 months. Using the 68-95-99.7 rule, what is the approximate percentage of cars that remain in service between 19 and 27 months?

whole hazel
#

!status

marsh citrusBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
paper venture
#

i dont know how to solve this problem ive never done it before

#

1

whole hazel
#

Do you know how to use the 68 95 99.7 rule

paper venture
#

no this is my first time coming across a problem like this and I am stuck

#

i have no idea what I am supposed to do

whole hazel
#

what does the 68 mean

#

Do you know what the numbers mean

pallid pine
#

@paper venture how far is 19 months interms of standard deviation

#

from the mean

paper venture
#

2.35%?

pallid pine
#

@paper venture is that your final answer

paper venture
#

i think so

#

tbh I dont know how to read the graph image you posted

pallid pine
#

@paper venture it shows you the %

#

for areas

#

that are certain standard deviation

#

from the mean

paper venture
#

oh ok

#

so would it be 43-19?

#

the mean minus 19?

pallid pine
#

so how much is that

#

interms of standard deviation

paper venture
#

since the standard deviation is 8 months it would be 3 standard deviations correct?

pallid pine
#

how much is 27

#

away from the mean

#

interms of standard deviation

paper venture
#

like 3.2/3.2 interms of standard deviation since 3 interms is 24 right

#

3.2/3.3

paper venture
#

ir would be 2 standard deviations

#

it

pallid pine
#

yh

#

so from 2 to 3 standard deviations below the mean

#

what is the probability

#

using the graph

#

i sent

paper venture
#

95% is 2 standard deviations and 99.7% is 3 standard deviations

pallid pine
#

from both ends

#

you only want to go less than

#

so half it

paper venture
#

so o.475?

#

0.475

pallid pine
paper venture
#

you said half of 95%

pallid pine
#

find, half of 95%

#

you also use

paper venture
#

sorry😓

pallid pine
#

half of 99.7%

paper venture
#

ok

pallid pine
#

and then take them away from each other

#

or

#

you could skip all that

#

and

#

just

#

use

#

the

#

graph

paper venture
#

so its 2.35%

pallid pine
#

yh

paper venture
#

ok so that is the percentage of cars that have remained in service between 19 and 27 months