#help-33
1 messages · Page 39 of 1
"fractions between 0 and 1 with denominator equal to a power of 3"
So no real name to it? In Dutch triadische getallen was used
well you could call them triadic fractions by analogy with dyadic fractions ig
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Is this sketch correct for the complex plane?
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@sharp whale Has your question been resolved?
@sharp whale Yes it is.
thanks
so lets say it was just mod(z-i) for example
would it be the same circle
just with an origin of (1,1) instead right
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Is the answer b or a?
Im not asking for answer i think its a but theres a chance its b too
Im asking if b or a is correct
R u seeing any similar triangles ?
BDA and CBA
I think b is right but a might be right too
Yes
its b?
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Correct
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✅
Help me the last question
Wait I show
If the r=1,2kohm
How calculate probability
Do resistance change when mean change?
wait wdym r=
did u mean the standard deviation?
like are u asking abt 6.4
oh
well
u kinda repeat the same thing
but u find a calculator with normal distribution
with mean of 10k, std of 1.2k
std is standard deviation
Because my friends, they are said I wrong
If I only choose 9,6-9,7 for question a
I ask but they don't explain
So in question a, which resistor are less than 9,8
I will know all if I know this
oh
6.4 u ignore the stuff previously said
it says suppose that it follows normal distribution
so all prev stuff is irrelavent
so this
alternatively use the normal distribution formula
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Using Linear Equations system, how would I solve this?
Fe^7 + O^2 -> Fe^3 O^2 + S O^2
The answer is (0,0,0)
lmaoo
Cus..like I dont think u can call ur variables Fe
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Risolvere means solve ig?
yup
K
@ornate silo U there?
Okay, can u send ur work?
Hmm..Well, just take log(base3)x common (In the numerator)
that would become 2/3 * log(base 3) x
then transpose 2/3 to the other side
@brave spire final answer?
Let him do the calculation
i want to confirm
let me try one sec
wait pls
yes
Np bud
.close
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ok so the solution states $\sin \frac {1} {x}$ tends to $\lambda$ as x tends to 0, where lambda is [-1,1]
i dont understand how that makes sense
sho
Do you have the solution as it appears like that?
this is the first half of the solution, i left out the rest
I don't get what they meant by that tbh, but at least otherwise I can kinda see that... [they divided numerator and denom by x in aim of working out the limits of them both, which can be done]
they said the "x sin (1/x)" term becomes zero. as its 0 into a finite number. my question was how is sin (1/x) a finite number
Ohhhh alright I get what they're saying now 🥪
The sin(1/x) is bounded between -1 and 1, and as x tends to zero, you must have that x * sin(1/x) tends to zero too, as it's sandwiched
A weird way of saying that, and the fact that they used lambda in the question as well as the solution 
wait so sin (1/x) exists, its not undefined
The limit of it doesn't exist by itself no
However it is bounded
,w plot y = abs(x), y = -abs(x), y = x * sin(1/x)
ok i kind of get it
does this work for other trig functions too?
what about x tan (1/x) or x cos(1/x)
For x * cos(1/x), it's a similar picture, cos is bounded between -1 and 1
,w plot y = abs(x), y = -abs(x), y = x * cos(1/x)
so cos (1/x) x is also zero
For tan I'm not too sure because it's not necessarily bounded, so you can't really sandwich it
,w plot y = abs(x), y = -abs(x), y = x * tan(1/x)
interesting
(as you can see, the bounds I used before for sin and cos don't work, so at the very least you'd need to find new ones, but the image suggests they don't exist...)
,w lim x * tan(1/x), x to zero
so if something that is technically "undefined" gets multiplied by zero, can i assume its equal to zero
It's the boundedness which is the crucial property we're using
is there a specific name for it? i mean i kinda get it, but a video explanation about it would be nice
Because sin and cos were bounded, we were able to create "sandwich/squeeze" functions that those products had to be in between
oh yea i get it
Erm, try sandwich theorem/squeeze theorem, something like that
,w sandwich theorem

yea squeeze theorem sounded familiar i was wondering if this was that. havent learned it tho
Aha, fair enough, well now you've seen an application of it
weird cause it seems like that's what they're trying to use there 
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if -6< y < 2
then
-18 < 3y < 6
well acc i dont even know why i typed
lmao my brain has just stopped at this part
I personally would calculate the amount of possible values, then see how many can be answered like that?
Sorry I'm also really tired so there's probably a much better way to do it KFHS
what is it
since -18 < 3y < 6, and -4<= x < 6
they overlap at the numbers
where 3y and x are
-4 -3 -2 -1 0 1 2 3 4 5
and since youre minusing these two together
this is almost exactly
like when you add two dice rolls together
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can you translate to english
is the limit the ratio of leading coefficients?
yes
what does that mean
that's what is written
if you have a function which is the ratio of two polynomial functions of the same degree, the limit as x tends to +- infinity is the ratio of the leading coefficients of the two polynomials
leading coefficient is the coefficient of the term with the highest degree
i understand
you take the highest equal coefficients
but what does that "ratio" mean?
the two polynomials have to be of the same degree
Ratio of a and b means a/b
a/b is horizontal asymptote not a limit though
then the limit of the function is the limit of a/b (considering a and b to be the coefficients of the terms with the highest power of x in the numerator and denominator, respectively)
horizontal asymptote is the limit as x approaches infinity
the horizontal asymptote('s y-coordinate) is the limit at infinity (of your function).
for example, you have $\lim_{x\to\pm\infty} \frac{4x^2+3x-9}{5x^2+8x-10} = \frac{4}{5}$
thought u need a small hole for it to be the limit
kheerii
ok
the limit of that would be whatever equals 0 in the denominator
not 4/5?
which is a horizontal asymptote
limit means
it gets close to it
but never touches
4/5 is an x value
that has a y value
if i plug in 4/5 it wont be undefined
oh?
x is tending to +-infinity isn't it?
what do you mean
,w graph (4x^2+3x-9)/(5x^2+8x-10)
at 4/5
you're calculating the limit as x tends to +- infinity
what do you understand from that?
in relation to this graph
.
ur finding holes
let's say
you have a function
f(x)
when I ask you what the limit of f(x) is as x tends to +infinity
what does that mean?
what do you mean "holes"
gaps
where x doesnt touch
it has to skip over
like a constant is 5x
but cant equal 1
for example
then u have a hole
at x =1
a limit at x=1
for example
that is a different kind of limit
well
not a different kind of limit
but
it represents a different thing
when x tends to infinity, it literally means x tends to infinity.
i.e this means "what value does f(x) approach as the value of x gets larger and larger?"
ohok
so
a horizontal
asymtote
needs to be there
in order for
x-> infinity
yup
this graph isn't a great example
whats a better one
looks like an octopus
yes
but
as x tends to infinity (as x gets larger)
what happens to the value of the function
do you see how the waves get closer and closer to 0
,w graph sin(x)/x for x from 0 to 1000
notice the downward bend in the graph
looks like something else tbh
but yes
it gets closer
to 0
can we use
a non sin graph
im religious
i dont sin
4/5 is the limit? not 0?
yes
ty
that's what the theorem states
you can think of it as the lower powers of x "fading away" as x gets larger and larger, leaving only 4x^2/5x^2 inside the limit, which evaluates to 4/5
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I understand how the coordinates for a,b,c,d,and j were fource
But how were the coordinates for e,f,g,h determined
For example, F is not in the same y position as O is, but how do i know how far to go down to reach F
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Using trigonimetry
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In mathematical logic/proofs, are $\iff$ and $\text{iff}$ interchangeable?
normalAtmosphericPa=101,325
yes
so does "if and only if" always mean a two directional implication?
i.e., if I use "iff" in my statement to restrict some claim of mine, will I then need to go on to show a proof in both directions?
I often don't see people doing so though
yes both directions
sometimes one direction is obvious
or the proof goes the same in both directions
thank you!
p => q is equivalent to (~p)vq. The implication p=>q is true provided either p is false or q is true.
^^ why is this statement true/?
yes it does
i.e., "if x=5, then x^2=25", is equivalent to "if x≠5, then x^2=25???"
no
either (~p) or q is true right?
"or" doesnt mean exclusive or
if p is false then ~p is true and it doesnt matter what q is
if p is true then ~p is false and q has to be true for (~p or q) to be true
I should really comb through a basic proofs book aye
I think they contain logic
is there a difference between propositional and predicate logic?
thank you=
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Just to quickly check,suppose in an ODE, the complimentary solution is e^x(sin(x)+cos(x))
yes?
For my particular solution can I use Ae^x as my Ansatz
it depends on the inhomogeneous function
i.e. the function on the RHS
the complementary solution tells you nothing
Yes the inhomogeneous functions is a linear combination of e^x
show me the problem
I just mean is the Ansatz allowed since if it is then then the problem is solved
If we have a linear combination of $e^x$ on the RHS. That is, $c_1e^{bx} + \hdots + c_re^{rx}$ then the Ansatz is going to be $Ae^{bx} + \hdots + Ne^{rx}$.
Nika
Yes I believe so, it doesn’t affect the complimentary function you stated hence making it valid
where A, ...., N are coefficients to be discovered
(if you are using the method of undetermined coefficients)
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if i had the sum start at n=0 would it then be (-1/8)^n-3?
or n+3
n+3
so as i take away from n, the exponent increases right
it might help to make the substitution very explicitly. set $k=n-3$. then $k$ starts at $0$. also $n=k+3$ so you can exchange the exponent using that. so $\sum_{k=0}^\infty (-\frac18)^{k+3}$
Denascite
ah yea that makes sense, i tried setting up a formula like that but this one is much neater
thanks! .close
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Hey ! I do not understand how this is right.
1 + (yz/(1+yz)) • x = (1 + yz + yx + zx)/(1 +yz)
On the right side of the equality, where do we get the yz from ?
hi
Because when we add 1 and .../yz, we take yz as common denominator
1+yz as common denominator*
So 1 * (1+yz)/(1+yz) + .../(1+yz)
@lean flame oh it get it ! Thank you very much
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could sm1 help me for IBP
for this
u=n+3
du = 1
dv = 1/(-5)^n
idk how to get v
ik u take the antidervative
but how do u take the antidervative of it
@woeful glade Has your question been resolved?
first simplify it
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✅
writing 1 as 1^n might help
or wait 
tf are they doing bringing a negative to the power of n when n varies across a continuum
there's going to be complex values involved whenever n isn't an integer
is this your NA then
doesn't look like the function is in the realm of what you should be dealing with integrating
how is it Na?
because it oscillates betweeen neg and positive values?
complex valued function is the problem
it could be integrated still, over the complex numbers
but since that isn't in the scope of calc 1 at all I'd say it means not integrable
It's worth remembering the conditions for integral test tho
[could tell that there probably was some other problem behind this
]
calc 2
ah well still
Yeah the dn should have tipped me off lol
@woeful glade Has your question been resolved?
daam what am i doing wrong here
did you try just putting NA?
or is it the other problems
2 of the other answers are also outlined in red
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does there exist a closed form for the arithmetic geometric mean?
as in not a recurrence
what do you mean by "ideal"
i just want something reasonably accurate and computationally simple
what is the original question that you want to answer, before we get too deep into the xy rabbit hole
i want to make a function on my calculator for the agm but it's really slow so i don't want to have to resort to integral expressions
so now i'm just wondering how many iterations of the sequence defn are required to be reasonably close (maybe to 3 decimals or so)
I doubt doing the integral numerically would converge much faster than the recursion
https://en.wikipedia.org/wiki/Arithmetic–geometric_mean#Example
The number of digits in which an and gn agree (underlined) approximately doubles with each iteration.
there's a siam paper for this lmao
SIAM -> NIAM -> NIAP -> PAIN
seems like they give some error bounds there
convergence rates for their computation of pi are pretty good

wow 2788 digits correct just in 10 iterations
@dreamy trench Has your question been resolved?
damn
3 iterations already convinces python
a = [np.sqrt(2)]
b = [0.]
p = [2.+np.sqrt(2)]
for i in range(3):
a.append((a[-1]**.5+a[-1]**-.5 )/2.)
b.append((a[-2]**.5)* ((b[-1]+1)/(b[-1]+a[-2])))
p.append(p[-1]*b[-1]*((1+a[-1])/(1+b[-1])))
print(p[-1], p[-1]==np.pi)```
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tried this a few times and I'm always way off, I don't know what to do.
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honestly i had no idea what I was doing and I kept erasing things so it might not all be on there
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yes
yes
you need to write 512 as a power of 8
then you can cancel with the log
probably
idk my powers of 8
write sqrt(125) as a power of 5
yes
yes
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How does the bottom question, answer C make sense
Shouldnt it be 415 not 405?
it says "interpret A'6 = 405" then it talks about a(7)
a(7) if we were to go there, is = 8514
a(6) = 8099
a(7)-a(6) = 415
not 405
a'(7) = 425
Interpreting A'(6) like that indeed doesnt make sense. A'(6) means that the instantenous rate of change is 405. But 1 month later it will be greater, so using that you can just aproximate A(7)
it says "it will be"
not "approximately will be"
Yeah, and that's why I think it's incorrect
the instantaneous rate of change is 425
not 405
but yes i agree with you
I was told last night though
that it made sense
something about
a'(7)-a'(6) = a'(7-6) * a'(6)
or something like that
found it
is this true
well thats baloney
because the question
answer c*
is saying "it is x value"
not "approximately"
thats weird
well
what would it be
then
really
would i be taking
a'(7)-a'(6)
or a(7)-a(6)
here, down
I feel like none of the answers is correct interpretation of A'(6)=405, C) is a decent approximation
ok so just f this problem then
thanks mathisalwaysright
in this case guess "mathway" isnt always right
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Did I do these one's right?
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<@&286206848099549185> ?
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Hello. Any ideas on how to solve this?
I tried taking ln and then differentiating but I don’t think that gives anything useful
looks very difficult
You’re supposed to solve this in 3 minutes apparently
bruh lmao
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need help
why is it positioned there
i dont get how graphing works
y= -2x+1
why is it not in 2?
you don't understand how/why the line y = -2x+1 is graphed like that?
well the best way to see why is to pick 3 x values, say x = 0, 1, 2 and plot them on the graph
yess i think im struggling the teacher didnt provide a video lesson for us anymore 😭 so the handout given is straightforward
and then try to extend the line to infinity
so like,
lets try it
get a piece of paper or something
draw the coordinates
okey
okay so did u do it
Yess
lets try taking some x values
lets start with x = 0
in that equation, what would y be for this x value
1??
points?
wait gtg sorry 😭 but just basically try to draw the points and connect them then u will see the patttern of the line
okie
yepp
yaaaaaay
i have to
okie kinda back
the idea is like
plot a few points
then connect those dots in a line
and then
just extend that line
forever in both sides
thats lke
like
the easiest way to go about it
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I am not sure what I did wrong here. Green is what the actual answer is and red is my answer
The answers are the same, use log rules
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I solved it but am not sure if my way is correct
i did 12-x+x/2 = 6
then
18-x+x/2 = 9
then did 9+6 = 15
i am not sure if this way is correct tho
im not sure i follow.. this is what i would do:
@brittle sun (forgot to enable ping)
shouldn't the midpoints be (D+C)/2 and (B+A)/2 ?
rather than minus
oh the averages, yeah mb
he can fix up my calculations xD (yeah 15's correct, you're good JoRe)
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Yeah 15 is right but I don't quite understand what you did here to get it
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Any idea what I did wrong?
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i need help finding the interest paid
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How would i do this
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not sure why U turns into and because i thought it turned into or
heavy
de Morgan
so $x \in \bar{A} \cap \bar{B} \iff x \notin A \cup B$
heavy
If x is not in A U B, then it had better be the case that x is not in A, and that x is not in B.
For example, if x were in A, then x would also be in A U B.
so if it was x is not in A intersection B would it turn into x is in A union B?
If x is not in A n B
Then x is not in A, or x is not in B.
In other words, if x is not in both, then it has to be missing from one of them.
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Pretty sure what I did is illegal
Can I get some help on the proper way to do this?
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how can i solve this question with no initial condition
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how do i answerthis?
Do you know what a summation is
You plug in 0 for i
n = 19
i = 0
you start from 0
and end at 19
so (0+3)^2 + (1+3)^2 + (2+3)^2 .... (19+3)^2
up until the nth term
which is 19
yea im doing double summation to make it easier for me doe + brute forcing isnt allowed
ik how to do the first summation
and teh second i just dk what to do with the square
double summation
using double summation so i dont have to brute force substituting the i values and adding it
@orchid scarab wdym by double
im pretty sure
double summation
is when you have two summations with different letters
at the same time
like this
for your one
what you can do is
expand that bracket
then you can use the rules
for i^2
i
and constant
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would the second line be equal or am I not allowed to distribute into unequal powers?
if I consider - as (-1)^1
1 and -1 would not match powers
so therefor should I just use (x+3)^-1 instead?
converting -(factor) to + (-1)(factor) is like changing the subtraction operator - into a power 1 factor, ya? always power 1
Is this wat ur talking about?
Stephen
Sorry it goes to the next line and looks bad
U have a sign error at the end
O ur talking abt the powers
ya, the powers
I think what ur saying here is correct
OK
Looks better
But this is still correct
Correct no issues
what I don't get, is when I distribute - into (1/(x+3))
top version
I can decide on distributing the - into the numerator *or * the denominator
but when it's written like (x+3)^-1 I can't distribute the - operator into it at all
I may be confusing this with multiplication, not subtraction
but same thing applies
actually nvm, subtraction too
I can change - into + (-1) for subtraction
So like if we had -5(2x+2)^-1 it wouldn’t be (-10x -10)^-1 right? That’s what ur saying?
yeah exactly
but if it's written -5(1/(2x+2)) I could make it -5/(2x+2) **or ** 5/(-2x-2)
Yes that’s correct
it's like deciding do I want the negative for 5 to be -5/1 or 5/-1
Yep
but I lose that ability when the power is negative, right?
Example?
-5(2x+2)^-1
I mean even if it was -5(2x+2)^2 u couldn’t distribute in
true, but -5(1/(2x+2)) is the same thing as -5(2x+2)^-1, just different notation.. or so I thought
so basically, negative exponent can cause issue for stuff like this? .. I guess it depends on what I need to do with them?
Yea same just different notation
I guess
Could also do something like this
Stephen
Lol yea I was legit about to say this
Is that musashi’s friend?
In ur pfp
yea
Controversial take: I’m happy the author went on hiatus (hope they feel better tho or whatever happened)
Cuz I didn’t want kojiro and him to fight
ah
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Stuck on:
What I've tried
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does anyone k what they mean by this thing
why would u ever subtract the omitted term from the 8th term
usually you would ifnd the summation of 8 terms and subtract and add the 9th
it might be a bit difficult tho
because this is a complicated question since ur using the partial sum notation to get it
remember that the error cannot be bigger than the next term of the series
so if we choose S8
the error cant be bigger than a9
the error is always the omitted term
and since a9 = S9 - S8
how does a9=S9-S8
remember
i didnt understand that part
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A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and other features. The distribution of the number of months in service for the fleet of cars is bell-shaped and has a mean of 43 months and a standard deviation of 8 months. Using the 68-95-99.7 rule, what is the approximate percentage of cars that remain in service between 19 and 27 months?
!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
Do you know how to use the 68 95 99.7 rule
no this is my first time coming across a problem like this and I am stuck
i have no idea what I am supposed to do
2.35%?
@paper venture is that your final answer
@paper venture it shows you the %
for areas
that are certain standard deviation
from the mean
yh
so how much is that
interms of standard deviation
since the standard deviation is 8 months it would be 3 standard deviations correct?
yh
how much is 27
away from the mean
interms of standard deviation
what is 43 - 27
yh
so from 2 to 3 standard deviations below the mean
what is the probability
using the graph
i sent
95% is 2 standard deviations and 99.7% is 3 standard deviations
well those are
from both ends
you only want to go less than
so half it
?
you said half of 95%
sorry😓
half of 99.7%
ok
and then take them away from each other
or
you could skip all that
and
just
use
the
graph
so its 2.35%
yh
ok so that is the percentage of cars that have remained in service between 19 and 27 months