#help-33
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I have a quick question about calc 3... My professor said gradient will always be normal to the level curve. (Will it also always be orthogonal/normal to the tangent plane of a surface)?
also gradient does not equal the partial of x y and z right
Nah I do not think so
<a , b ,c> if you had something like this
gradient vector lies inside the tangent plane
would it be equal to a = partial of x, b = partial of y, c = parital derivative of z?
It will not be orthogonal to the plane
oh wait can i share a picture
do you know why this is?
the red vector is the gradient vector btw
yellow plane is the plane and grey surface is the surface
also I noticed there are two ways to solve for a tangent plane
0 = f_x(x1, y1, z1)(x-x1) + f_y(x1,y1,z1)(y-y1) + f_z(x1,y1,z1)(z-z1)
and
z = f(x1,y1) + f_x(x1,y1)(x-x1) + f_y(x1,y1)(y-y1)
in the first one are we treating it as a function with 4 variables?
or 3 inputs
in the 2nd we are treating it like a f(x1,y1) function
but in the first i think we are treating it like f(x1,y1,z1) function
except there is no variable to represent this 3 input function in the 1st formula
@proud ice <@&286206848099549185>
hmm i don't think so since its not a plane
it has creases and stuff
dips and folds
That's the only scenario where I can think of gradient being orthogonal to tangent plane
Also, level surface does not mean "flat plane"
oh
consider the scalar field f(x, y, z)=x²+y²+z²
a level surface would be f(x, y, z)=c for some constant c
Then every level surface would be a sphere centered at the origin with radius sqrt(c)
yes
hmm I think this one is 3 inputs yes
Your level surface is c=x²+y²+z²
In which case, yes, the gradient is orthogonal to this tangent plane
if the formula is this, would this count as a level surface?
partial of x times x values then partial of y etc
because its not explicitly stating an extra variable like
A = x^2 +y^2 +z^2 isn't that also a level surface
where a is a variable
I'm assuming f_x, f_y, f_z are your partial derivatives of f?
yes
Then no, that is not a level surface. That is (I believe) the plane tangent to your level surface
and x1,y1,z1 are the x y and z values of the point
oh okay
wait so if it was 0 = x^2 + y^2 + z^2
would this be a level surface
and f(x, y, z) = x^2 + y^2 + z^2 do you know what the difference is between these?
It would be a level surface of the single point at the origin (a sphere of radius 0)
since the function thinks the 4th variable would be 0? (lets say a = 0)
This is the function of your scalar field. It is not level because f(0, 0, 0) != f(0, 0, 1)
oh
a level surface requires f(x, y, z)=f(x', y', z') for any two points (x, y, z) and (x', y', z') in the surface
(This is equivalent to requiring f(x, y, z) = some constant)
since derivative of 0 is 0
ah okay
Not sure what you mean here
well to be honest, we've been working with 3 variables, and im a bit confused on why f(x,y,z) is coming into the picture when it used to be f(x, y) which is = z
yes
not sure what f(x,y,z) means
you ask good questions
It's hard to grasp at first
f(x, y) is easier to grasp because it can be represented as a surface in 3D space
f(x, y, z) is technically an upscale of that: A hyper surface in 4D space
Not too easy to visualize...
But there are applications for this
f(x, y, z) assign a scalar value to every point in 3D space
wow so is that equation of tangent plane 0 = fx.... a 4D tangent plane?
0 = f_x(x1, y1, z1)(x-x1) + f_y(x1,y1,z1)(y-y1) + f_z(x1,y1,z1)(z-z1)
this one
as a practical application, consider the temperature in a room
Not quite, this is still a plane in 3-space.
If it were w = instead of 0 = , then it is a 4D plane
to help understand scalar fields, imagine f(x, y, z) as saying what the temperature in a room is at a point (x, y, z) in the room
That's the best real-world example I can think of
oh i see, sorry can you explain this sorry for all the questions
he puts it in xyz form
of the function
w=Ax+By+Cz+D is a hyperplane
0=Ax+By+Cz+D is a plane
Difference is the introduction of a new free variable; w
oh but doesn't f(x,y,z) = w?
w=Ax+By+Cz+D has three variables: x, y, and z. They all affect the dependent variable w
okay
0=Ax+By+Cz+D has only two free variables. For example, if x and y are free, then z is dependent on x and y
So two free variables and one dependent give you a 2D plane in 3D space
which makes the 4th variable irrelivant even though its in that form
And three free variables with one dependent will give you a 3D hyperplane in 4D space
ohh okay
Refresh me on your question now. We discussed a lot
basically my question was is the gradient which is < f_x(x1,y1), f_y(x1,y1) > is it orthoganol to the tangent plane of a surface?
Right. The question, as it stands now, is ill-formed in this context
There are multiple ways you can define "surface"
If you define "surface" as the set of points f(x, y), then no
The gradient will always point in the direction of maximum increase of f(x, y), and will therefore be inside the tangent plane
oh tbh i don't really know the equation of the surface shown
If you defined "surface" as level surface to f(x, y, z), then yes
if its f(x,y) or leveled
oh okay
i will assume its leveled
Based on what you've shown me, you're dealing with level surfaces of f(x, y, z)
You can see an easier example by considering "level curves" to surfaces defined by f(x, y)
These are actually what topographical maps are
Here is an example
oh yeah thats what we did for xy functions
The lines defined sections of constant height (i.e. where f(x, y) is unchanged)
level surfaces are the same idea
They are topographic maps in 3D
oh got it
In these examples, gradient will always be orthogonal to level surface or level curve
ah okay, but not always to tangent planes since the surface could be a non leveled surface
right
Yes. It's important to know what kinds surfaces you are dealing with
you said a leveled surface is f(x,y,z) and has 3 independant and 1 dependant variable
how come here there is only 1 dependant 2 independant, in that equation yet its labeled as f(x,y,z)?
i was thinking since its = 0 it shouldn't even have f(x,y,z) cause 0 = that equation is already a full equation, why are there three = signs?
Maybe he wrote it wrong
anyways thank you for the help @proud ice u really helped me understand that :)
hope u have a great day
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How solve
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how to solve this
@tawdry shard Has your question been resolved?
<@&286206848099549185>
no i dont
any easier way
normally we use this
let a new variable to represent something
<@&286206848099549185>
Try u=(x+8)^3
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Would someone help me on 10th? I can't understand how x is -2.. my solution is 212.5
Can you show your steps on solving this?
It's pretty rough, lemme redo it clearly
Aight take your time
Lmaooo it's fine
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can someone please help me
Have you tried something?
yes
i tried making it into a right angled triangle
with sides of 2km
but that didn't work
to find the distance from start to A, it would be this, no?
the distance is 2km right?
i think thats what you are supposed to do
looking at the picture how many blocks is the base triangle? and how many blocks is the height of the triangle?
yeah
1
for? base or height?
hight
thats correct
so each grid represents 1km. so the base would be 2km and the height would be 1km
what formula would you use to find the hypotenuse?
a^2 + b^2 = c^2
is it square root 5?
square root of 5 is approx 2.24
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how many ways can I represent latitude and longitude, say this one of central park?
40.770071, -73.974952
actually this is more of a google question 😂
i just got it from the internet
There are various ways to represent latitude and longitude coordinates, but some of the most common ones are:
Decimal Degrees: The format you provided, 40.770071, -73.974952, is the decimal degree format, where the latitude and longitude are represented as decimal fractions.
Degrees, Minutes, Seconds (DMS): In this format, the latitude and longitude are expressed as degrees, minutes, and seconds. For example, the coordinates of Central Park in DMS format would be 40°46'12.3"N, 73°58'29.8"W.
Universal Transverse Mercator (UTM): UTM is a coordinate system that divides the earth into a grid and represents locations using easting and northing values. The coordinates of Central Park in UTM format would be 18T 583973mE 4512489mN.
Military Grid Reference System (MGRS): Similar to UTM, MGRS is a coordinate system that divides the earth into a grid and represents locations using a combination of letters and numbers. The coordinates of Central Park in MGRS format would be 18TWL8397301249.
There are also other formats and systems used to represent latitude and longitude coordinates, but these are some of the most common ones.
my goal is to try to reduce the characters counting without losing too much precision. But I believe if I introduce degrees and minutes and seconds, I'd be just adding more characters
thats a very good answer, thank you!
thanks guys
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anyone can help me with solving this question ?
Which one - there are two visible?
question 1 thx
Cool cool, so note how they said that
The sum of the volumes of two spheres is [324pi cm^3]
and also
The radius of the larger sphere is equal to the diameter of the smaller sphere.
Can you use these to form equations?
4/3 pi r³ + 4/3 pi 2r³= 324pi?
Need to
that carefully but basically
then I'll find the radius of the smaller sphere?
[and from there you can work out everything else they said]
can the equation be simplified into 4r³= 324?
my answer is still different to the actual answer
<@&286206848099549185>
which equation you want to simplify..?
@torn sphinx
this
yes you can convert
1st take pi common and it`ll cancel out
then you have to add terms r3
you`ll get desired outcome
4.326....
but still I can't get the desired outcome of the larger spehre's volume which is 288
you trying to find value of r right..?
ye and it's this if my calculations aren't wrong
wait i`m considering that this equation is correct
then r = cuberoot of 81
r=4.32
if equation you wrote here is right..! @torn sphinx
what`s the ans
should be 216
which is?
use r=3 and calculate the things you want to calculate
tell me if this is wrong
ill check once again
so the mistake you did was
they said that the radius of lager sphere is double of the smaller right..?
then R=2r
R larger sphere radius
r smaller ------
right..?
till this makes any sense to you...?
yew
so when you write the formula for volume its 4/3 pi r^3
this is right for larger sphere which is 4/3 pi R^3
but for smaller one it`ll become 4/3 pi (2r)^3
got it..?
ye
4/3 pi R³ + 4/3 pi 8r³= 324pi
ohhhhh
so this is the correct equation
you have to take cube of 2 also in consideration
I get it now
glad i could help bro
thx so much 🙏
anytime brother
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first one's right. 2nd and 3rd are wrong
would it be that for the 2nd 2 that since they go to infinity and -infinity they get closer to 1
yes
gotcha
I just was not sure which one it would be but it makes sense since it just gets closer
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if
a quadratic have equation $y = 4(1-x)^{2}-2$
yomiko
the the turning point would be (1,-2) right?
for which class?
i keep seeing the language turning point
is that calculus? or are you talking about the max?
what do you mean which class
idk just curious if you can use calculus to discuss it or not
what you can do is you know a square quantity is squared where it is 0, right
the squared on a^2 means that a cant be smaller than 0
so its smallest when its 0
if thats (1-x)^2 then we want 1-x=0, so x=1
thats where it will be smallest
make sense?
@oak void
yeah
okay
and yea, i think -2
so makes sense to me 
did you check it
,w graph 4(1-x)^2-2

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turning 2a^-1 + 3b^-2 into a single fraction with positive integers
2/a + 3/b^2 is the first step right
mhm

Yes
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What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
1
@open plume Has your question been resolved?
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they want me to find the volume between the both functions and i cant find any good variable exchanges that make it work 😦
the last integral doesnt end up with the right answer, i dont have the d( θ) because it is wrong somewhere before
didnt get that far
<@&286206848099549185>
tried another method but didnt work either 😦
the answer should be about 13,8
<@&286206848099549185>
@tardy mist Has your question been resolved?
anyone?
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A triangular pyramid has a base shaped like an equilateral triangle. The legs of the equilateral triangle are all 13 millimetres long, and the height of the equilateral triangle is 11.3 millimetres. The pyramid's slant height is 18 millimetres. What is its surface area?
'
Please don't occupy multiple help channels.
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Hey, this is more of a history of math problem. The proof that there are arbitrarily many composite numbers between prime numbers is quite trivial. For a gap of the size (N-1), create the sequence N!+2, N!+3, N!4, ..., N!+N - each of the terms in this sequence is composite and therefore we've constructed a "gap" of the size N.
However, I have no idea who said this first. Who was the initiator? Does anyone have any idea?
@frigid python Has your question been resolved?
This isn't really well known in math since it's not a big result
Ah, okay 😅 So do you think I can include it into my thesis without citing and referencing?
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for some reason my brain isn't putting together between the factoring and
right after I get it all to the same side, the factoring by I'm assuming grouping is throwing me off, why can I just have the x-3 raised to the 4 just go to three and completely eliminate the x-3^3
my train of thought is pretty fuzzy on where to go after i isolate everything
you're not understanding the logic behind this step, in particular?
yes
yeah
5x here is the common factor
yeah
in your example, the common factor is (x-3)^3
(x-3)^4 / (x-3)^3 = (x-3)
-6(x-3)^3 / (x-3)^3 = -6
so you are left with (x-3)^3 [ (x-3) + (-6) ]
i can write that out in handwriting if notation is hard to understand
nah youre totally fine
so after that i break down the x-3^3 right? but there since its cubed i don't set it to 0 just yet?
what do you mean by 'break down' the (x-3)^3?
split into (x-3)(x-3)(x-3)
that isn't necessary in order to derive solutions
so where would you go from there
conceptually you need to know this:
if you can rewrite a function as
(x-a)^n * (x-b)^m * (x-c)^k * ... * etc
(stop me if i've lost you already)
youre good
you can derive that there are n-solutions of a, m-solutions of b and k-solutions of c
to ground what i just said in an example
consider f(x) = (x-3)^2 * (x-2) * (x+1)
from this point, we can say for f(x) = 0 we have
x=3 or x = 2 or x = -1
with x = 3 as a double root
yeah yeah
note: for x=0, that is
so back to your original question
you have (x-3)^3 * (x-9) = 0
using that concept
x=3 (triple root) and x=9 are the only solutions
ah
I'm always so unaware of when I can remove parentheses
that is only because of one condition
(x-3) is (x-3)^1
which just means (x-3)
parenthesis are only used there to signify that we have factorised a term with (x-3)^3 as a common factor
and it has left us with (x-3) by itself
if it was, say
(x-3)^2 - 6
you couldnt just do (x-9)^2
do you understand why?
yeah
and if instead you had (x-9)^2
(x-9)(x-9) will expand into something a lot different
this is the case for any (x-3)^n where n isn't 1
e.g (x-3)(x-3)(x-3) wouldnt be = to (x-9)(x-9)(x-9) and so on so forth
but with (x-3)^1 specifically
(x-3)^1 = (x-3) = x - 3
there is no operation happening upon the '(x-3)' here
so anything outside it, like the -9, can freely interact
i.e, we can remove the parenthesis
yeah thats wild
something in me wants to just set the (x-3) = 0 and then get x = -3
even though its being subtracted from 6
i can get that since when you see brackets its tempting
6 subtracting etc
you can infact do that for the (x-3)^3 straight away
and have them just = 3 triple root?
if you have f(x) = (x-3)^3 * (literally any function of (x))
like, say
f(x) = (x-3)^3 * (arctan(5/13^(15x)))
you would still have the solution
x=3 (triple root)
(and some other wild solution for whatever is on the other side, there)
yeeah yeah
the important distinction here is the multiplication
may i ask another question
sure thing
excuse the mess above lmfao
so when i see this
my first thought is to grab common etc
and i first imagined itd be the x(x-2) ?
to give me this?
oh yeah the stuff above the line that i poorly seperated is bad
well
the solutions to this from step 2 you can see will be
[x^2] = 0
[(x-2)] = 0
[(x-2)^3 - 1] = 0
the first two should be trivial
[x^2]=0 => x=0 (double root)
[(x-2)]=0 => x=2
the first one is a double root
again thou gh
yeah that's what is figured, but they dont give me the option for that
noticing that things are double roots are only important graphically
do you understand what i mean?
well rather
im not sure
if your questions is 'What are all the possible solutions for x?'
you would just write 'x=0'
'double root' just means that, in a graph, the function passes through 0 'twice' at the same spot
yeah yeah that part i got
the last part of the question is to solve [(x-2)^3 - 1] = 0
here?
oh wait
you were right to factor out a common factor, yes
i saw yours, okay so thats the right factor
for the last brackets, we expand for
expand out for (x-2)(x-2)(x-2) - 1 = 0
(x^3-6x^2+12x-8) - 1 = 0
x^3 -6x^2 + 12x - 9 = 0
using factor thrm notice x=3 is a factor
ohhhh i got it, the first part for why thats factored the way it is
on the last bit?
for (x^2 -3x +3)
ahhhhh i think im mentally flooded a second
but tbh, you probably don't want complex answers...
let me just triple check i've not made any mistake
yeah nah not yet
weird that they'd give you this question, then
this is the answer they want?
yeah those are the choices
im surprised double root for zero isnt there
that really messed with me mentally
right they probably just want you to say:
"ah, this sqrt( ) has a - in it, i should disregard it completely"
have you done something called polynomial division at your stage?
not in depth we're going back over it in a few units
all of the video lessons on this dont have it being done on these
you can not approach (x-2)(x-2)(x-2)-1=0
without knowing how to compute this
(at least, i dont think so)
id have to review that, we did it a while ago but it wasnt used to solve any of these up until this point
mostly factoring by grouping and differences of squares
i can remind you how you would do it if it'd help
i was only hesitant because what you're doing could be a few grades behind what this is
yeah im actually returning to school, way later
polynomial division is where you know (x-3) * (something) = (x^3 -6x^2 + 12x - 9)
and you want to factor out the (x-3)
to get the (something)
and rewrite it as (x-3) * (something)
x^2 + 2x + 4 i think something like that
wdym?
i think is the answer to that, idk
it's a good guess in that
you know the (something) will likely be a quadratic
because the biggest term of the product function is x^3
so you'd need an x^2 at most to get from x to x^3
but unfortunately, we need to be very exact
and the rest of it (+2x+4) isn't correct
so we can't just guess, we need to follow a division algorithm a little like long division
oh yeah i wasn't writing it down or anything, i actually think i found out how they want me to do it
i think they want me to factor an (x-2) out of the (x-2)^3
this?
yeah
yeah youre right
(you would get (0)(0)^2 - 1 = 0, -1=0 which isnt right
the answers to your question are
x=0,x=2,x=3, & x=3/2 +/- i sqrt(3)/2
you can ignore the 4th and 5th, however
as they are complex
x=0, x=2 and x=3 are the answers
no double root?
the last test i took marked it wrong because i didn't
is it not a usual convention?
well, i can say that to me it personally isn't as a college student in the field
if your teacher is asking for it though then i would just out of habit
if they are specifically saying, no, x=0 is a single root, not a double root
then they are wrong
it is a double root
okay gotha
so for the sake of the answer then, and in general, in this context, x^2 = 0
of this specific problem
(x^2) * (x-2) * [this last function we're working on] = 0
solution 1:
(x^2) = 0
=> x = 0
solution 2:
(x-2) = 0
=> x=2
solution 3 is what we're working on righ tnow
solution 3 will be the case:
(x-2)^3 -1 = 0
without using polynomial divison or the quadratic formula, how would you approach that
you couldn't
at all
well
you could find (x-3)
but
you couldn't say 'I am certain that the quadratic that occurs when I factor out (x-3) will give me real solutions'
real meaning 'not-complex'
so really you'd have to approach it in full
so i cant solve this without either of those
which requires polynomial division
we havent used that in this unit
i don't think so, no
i think i can use the difference of two cubes here actually
(x-2)^3 - 1
(x-2)^2 + (x-2) + 1
yesss
so from here you have x=3 as solution as required
and you would just show the discriminant test for the quadratic to show it has no solutions in the reals
yeah yeah
they didn't want me messing with anything complex in this yet
ahh youre the best, big time thanks
the parentheses getting removed and the double root thing tripped me up majorly
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hello
So,
I calculated the fourth derivative to be 6/x
but then I get n = 100(1000x^3)^1/3 / x
which can't be right
so i'm a little lost
i basically simplified to
1/(3X10^6n^4) < 1/3X10^17
oh
nvm
i'm so slow
i didn't plug in my lower limit
lool
this channel can be closed
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how would i slove (2x^3y^2z^4)^3 x (2z^2)^3 ??
Bad notation here. Simplify, and is the x in between the multiplication symbol
Use like • or "times"
Looks like a third term of x
so would i dispute the 3?
You want to distribute the 3 to every number/variable inside the parentheses
try solving it and ill tell you if youre right
bc doesnt 2^3 = 6?
2^3=8
but how?
$2^3=222$
CrEpasPmkinPie
how?
bc i went 2x3, 2x3, 2x3
that doesn't even equal 12 lol
ohhh
$222$
CrEpasPmkinPie
$2*2=4$
CrEpasPmkinPie
$4*2=8$
CrEpasPmkinPie
So what do you get for the question now?
lemme see
wait
(2z^2)^3
it also be 8 if i did it with the 2 and 3?
the two exponets
;-;
CrEpasPmkinPie
CrEpasPmkinPie
uhhuh
CrEpasPmkinPie
geez
its chonky
yes!!

$8x^9y^6z^{12}*(2z^2)^3$
CrEpasPmkinPie
and i still have to simpily ?
simplify the right term
the one with the ()?
yes
o ok
but here's the rule on the exponents and parentheses
what is it?/
$(x^a)^b=x^{ab}$
CrEpasPmkinPie
thats what
?
what is this?
thats the rule for exponentd and parentheses
np
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How to solve?
It requires a decimal number as the answer
,w ln(21)
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Hi
I have a question
ask it
i closed the other one
How do they get the X values @mellow isle
Or just in general
they just picked them
Cause I assume that they got the y values then multiplied by -1
Yeah I know
It’s a reflection off the X axis correct?
idk what question you are referring to
D
the sheet just looks like its practicing graphing equations
Yea, but the y values are correct, but the X values are incorrect
Why tho
whats f(x)
Wouldn’t the equation be x=2X+4
Cause I found the y values, and that’s correct
The x values are incorrect
can u show what f(x) is
Idk @
what
Idk what you’re asking me
send a picture of the function
or graph associated with it
It’s the very top one
On the left
You just need to translate it
i can barely see it
The points are
(-2,0), 0,-2, 6,1
I understand how to get the Y values
Not the x tho
I dont understand you question, you want to know how to translate the graph ?
Yes
what part are you stuck with
The x values
okay
do you know what f(cx) does to the coords?
like lets say f(x) gives you a point (a, b)
what does f(cx) give you
and similarly what does f(x+d) give you
Wouldn’t it be x= 2X+4
Then you put the points into X
what
what does this give you
Not sure @still temple
if f(x) gives some some point (a, b)
Compress
then f(cx) gives you (a/c, b)
f(x+d) gives you (a-d, b)
apply that to the points
How would you write the equation
what equation
Like how would I find the x points
okay so you have the point
(-2, 0)
transform it
Yes
How?
.
How do I transform the x points
Can you explain in simpler terms
I don’t get what you’re telling me
f(x) gives (10, 10)
f(2x) gives (5, 10)
How
.
The equation is 2X+4
okay
2(-2)+4??
what
okay
do you understand this?
No
what part dont you understand
What it means
if you have a function
f(x)
and transform it by some constant c
such that
f(cx) is ur new function
then a point (a,b) will turn into a point (a/c, b)
Yeah I get that, but how do they get the x values transformed
bro
.
(a,b) turns into (a/c, b)
c is the constant you transformed by
Can you show me how to get the first x point
okay
lets say
f(x) gives you some point (10, 10)
then f(2x) gives you (10/2, 10)
do you get that ?
10 divided by 2?
yes
.
Why are you dividing
.
You divide the x values?
yes
If the original point is (-2,0) then what the transformed point of x for 2X+4
lets say you have f(x)
which gives a point (100, 100)
what does f(10x) give you
what point ?
10
give the whole point
10,100
okay
what about f(x+1)
use this
Idk
f(x+d) gives you (a-d, b)
you have (100, 100)
what does f(x+1) give you
Not sure
-1?
do you know what this means
d is just some constant
so f(x+d) means like f(x + SOME NUMBER)
what is d in the case of f(x+1) ?
Just some number
whats the number specifically
f(x+1)
what is d
100
f(x+d)
you have
f(x+1)
what is d
1
okay
f(x) gives you (a, b)
f(x+d) gives you (a-d, b)
if f(x) gives you (100, 100)
what does f(x+1) give you
101
no, your answer is meant to be a point
and either way its a-d not a+d
okay I'm going to sleep maybe someone else can help
Okay
Can someone else help me please
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How do u do this?
what needs to be true in general for a function to be continuous at a point?
left and right sides must equal each other
but there are 2 variables
so doing that wont work
no
only x is a variable
a and b are constants that you have to determine
there may be more than one pair of (a,b) that work
which is why they say "find all numbers a and b.."
how would $a/x-1$ be continious on 1?
Dracu
there's exactly one value of a that will give a/(x-1) a finite limit as x->1
woundn't that be 0?
otherwise it's just +-infinity
@static quarry
bruh
wtf
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This is my problem
This is what I've tried
In my head it seems correct, so I'm not entirely sure what it's flagging, whether it's a calculation issue, or a syntax issue.
you wrote x in there when the variable is clearly t
Yeah I saw that
I started a new problem but am having a similar issue (I think)
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hi this question is about shoes so the only thing i dont understand here is 1/7 of the GST inclusive price
@sterile mango Has your question been resolved?
discount of 1/7 of the GST inclusive price means that the price of the shoes including GST is discounted by 1/7
so its just 158.50 x 1/7?
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How would I find inverse tan of -7/5 in degrees
(Without calculator)
Use right triangle and quadrants
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✅
How would I determine if it is Q2 or 4 based on a given tan or will it not matter
arctan only gives outputs between -90° and +90°, so only Q4 and Q1
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Work on the right. What did I do wrong?
@hollow pelican Has your question been resolved?
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😏