#help-33

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analog sun
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trim saddle
marsh citrusBOT
trim saddle
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I keep getting B

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but the asnwer is E

hybrid plover
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Post your work and we can see where you're going wrong

trim saddle
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ok 👍🏽

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I didn’t even get B😭

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<@&286206848099549185>

marsh citrusBOT
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@trim saddle Has your question been resolved?

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trim saddle
marsh citrusBOT
trim saddle
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I don’t know what to do

marsh citrusBOT
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@trim saddle Has your question been resolved?

marsh citrusBOT
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@trim saddle Has your question been resolved?

marsh citrusBOT
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@trim saddle Has your question been resolved?

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celest frigate
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I have a quick question about calc 3... My professor said gradient will always be normal to the level curve. (Will it also always be orthogonal/normal to the tangent plane of a surface)?

celest frigate
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also gradient does not equal the partial of x y and z right

celest frigate
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<a , b ,c> if you had something like this

proud ice
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gradient vector lies inside the tangent plane

celest frigate
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would it be equal to a = partial of x, b = partial of y, c = parital derivative of z?

proud ice
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It will not be orthogonal to the plane

celest frigate
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oh wait can i share a picture

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do you know why this is?

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the red vector is the gradient vector btw

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yellow plane is the plane and grey surface is the surface

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also I noticed there are two ways to solve for a tangent plane

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0 = f_x(x1, y1, z1)(x-x1) + f_y(x1,y1,z1)(y-y1) + f_z(x1,y1,z1)(z-z1)

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and

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z = f(x1,y1) + f_x(x1,y1)(x-x1) + f_y(x1,y1)(y-y1)

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in the first one are we treating it as a function with 4 variables?

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or 3 inputs

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in the 2nd we are treating it like a f(x1,y1) function

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but in the first i think we are treating it like f(x1,y1,z1) function

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except there is no variable to represent this 3 input function in the 1st formula

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@proud ice <@&286206848099549185>

proud ice
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Is the surface a level surface?

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That is, it is a surface of constant value?

celest frigate
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it has creases and stuff

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dips and folds

proud ice
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That's the only scenario where I can think of gradient being orthogonal to tangent plane

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Also, level surface does not mean "flat plane"

celest frigate
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oh

proud ice
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consider the scalar field f(x, y, z)=x²+y²+z²

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a level surface would be f(x, y, z)=c for some constant c

celest frigate
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but wouldn't that be a plane

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if its a constant

proud ice
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Then every level surface would be a sphere centered at the origin with radius sqrt(c)

celest frigate
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ohh

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its a function with 3 inputs

proud ice
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yes

celest frigate
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hmm I think this one is 3 inputs yes

proud ice
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Your level surface is c=x²+y²+z²

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In which case, yes, the gradient is orthogonal to this tangent plane

celest frigate
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partial of x times x values then partial of y etc

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because its not explicitly stating an extra variable like

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A = x^2 +y^2 +z^2 isn't that also a level surface

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where a is a variable

proud ice
proud ice
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Then no, that is not a level surface. That is (I believe) the plane tangent to your level surface

celest frigate
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and x1,y1,z1 are the x y and z values of the point

celest frigate
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wait so if it was 0 = x^2 + y^2 + z^2

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would this be a level surface

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and f(x, y, z) = x^2 + y^2 + z^2 do you know what the difference is between these?

proud ice
celest frigate
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since the function thinks the 4th variable would be 0? (lets say a = 0)

proud ice
celest frigate
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oh

proud ice
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a level surface requires f(x, y, z)=f(x', y', z') for any two points (x, y, z) and (x', y', z') in the surface

celest frigate
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oh got it

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so basically (0,0,0)

proud ice
celest frigate
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since derivative of 0 is 0

proud ice
celest frigate
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well to be honest, we've been working with 3 variables, and im a bit confused on why f(x,y,z) is coming into the picture when it used to be f(x, y) which is = z

proud ice
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yes

celest frigate
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not sure what f(x,y,z) means

proud ice
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you ask good questions

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It's hard to grasp at first

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f(x, y) is easier to grasp because it can be represented as a surface in 3D space

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f(x, y, z) is technically an upscale of that: A hyper surface in 4D space

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Not too easy to visualize...

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But there are applications for this

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f(x, y, z) assign a scalar value to every point in 3D space

celest frigate
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wow so is that equation of tangent plane 0 = fx.... a 4D tangent plane?

celest frigate
proud ice
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as a practical application, consider the temperature in a room

proud ice
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If it were w = instead of 0 = , then it is a 4D plane

proud ice
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That's the best real-world example I can think of

celest frigate
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he puts it in xyz form

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of the function

proud ice
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0=Ax+By+Cz+D is a plane

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Difference is the introduction of a new free variable; w

celest frigate
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oh but doesn't f(x,y,z) = w?

proud ice
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yes it does

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Right let me fix my terminology

celest frigate
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o then how come it equals

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oh ok

proud ice
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w=Ax+By+Cz+D has three variables: x, y, and z. They all affect the dependent variable w

celest frigate
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okay

proud ice
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0=Ax+By+Cz+D has only two free variables. For example, if x and y are free, then z is dependent on x and y

celest frigate
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true

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i see

proud ice
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So two free variables and one dependent give you a 2D plane in 3D space

celest frigate
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which makes the 4th variable irrelivant even though its in that form

proud ice
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And three free variables with one dependent will give you a 3D hyperplane in 4D space

celest frigate
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ohh okay

proud ice
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Refresh me on your question now. We discussed a lot

celest frigate
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basically my question was is the gradient which is < f_x(x1,y1), f_y(x1,y1) > is it orthoganol to the tangent plane of a surface?

proud ice
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Right. The question, as it stands now, is ill-formed in this context

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There are multiple ways you can define "surface"

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If you define "surface" as the set of points f(x, y), then no

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The gradient will always point in the direction of maximum increase of f(x, y), and will therefore be inside the tangent plane

celest frigate
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oh tbh i don't really know the equation of the surface shown

proud ice
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If you defined "surface" as level surface to f(x, y, z), then yes

celest frigate
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if its f(x,y) or leveled

celest frigate
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i will assume its leveled

proud ice
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Based on what you've shown me, you're dealing with level surfaces of f(x, y, z)

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You can see an easier example by considering "level curves" to surfaces defined by f(x, y)

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These are actually what topographical maps are

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Here is an example

celest frigate
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oh yeah thats what we did for xy functions

proud ice
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The lines defined sections of constant height (i.e. where f(x, y) is unchanged)

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level surfaces are the same idea

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They are topographic maps in 3D

celest frigate
celest frigate
proud ice
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In these examples, gradient will always be orthogonal to level surface or level curve

celest frigate
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ah okay, but not always to tangent planes since the surface could be a non leveled surface

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right

proud ice
celest frigate
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ah got it

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that makes a lot of sense now

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can i ask one last question

celest frigate
# celest frigate

you said a leveled surface is f(x,y,z) and has 3 independant and 1 dependant variable

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how come here there is only 1 dependant 2 independant, in that equation yet its labeled as f(x,y,z)?

celest frigate
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Maybe he wrote it wrong

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anyways thank you for the help @proud ice u really helped me understand that :)

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hope u have a great day

marsh citrusBOT
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@celest frigate Has your question been resolved?

marsh citrusBOT
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gloomy hornet
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How solve

marsh citrusBOT
gloomy hornet
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. Lose

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.close

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tawdry shard
marsh citrusBOT
tawdry shard
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how to solve this

marsh citrusBOT
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@tawdry shard Has your question been resolved?

tawdry shard
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<@&286206848099549185>

main idol
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do you know derivatives

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write the limit as the derivative of a function f(x) at x=2

tawdry shard
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no i dont

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any easier way

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normally we use this

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let a new variable to represent something

tawdry shard
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<@&286206848099549185>

main idol
tawdry shard
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ok

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!close

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/close

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.close

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brave spire
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Would someone help me on 10th? I can't understand how x is -2.. my solution is 212.5

elfin berryBOT
glass kestrel
brave spire
glass kestrel
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Aight take your time

brave spire
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OhhhHHH

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Am dumb

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Sry

glass kestrel
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Lmaooo it's fine

brave spire
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I forgot to multiply x with constant

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Sry

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stoic crag
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can someone please help me

marsh citrusBOT
glass kestrel
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Have you tried something?

stoic crag
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yes

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i tried making it into a right angled triangle

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with sides of 2km

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but that didn't work

glass kestrel
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to find the distance from start to A, it would be this, no?

stoic crag
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the distance is 2km right?

stoic crag
glass kestrel
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looking at the picture how many blocks is the base triangle? and how many blocks is the height of the triangle?

glass kestrel
glass kestrel
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for? base or height?

stoic crag
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hight

glass kestrel
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thats correct

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so each grid represents 1km. so the base would be 2km and the height would be 1km

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what formula would you use to find the hypotenuse?

stoic crag
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a^2 + b^2 = c^2

glass kestrel
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yep

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so what is the answer?

stoic crag
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is it square root 5?

glass kestrel
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yep

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so the distance answer for a is square root of 5

stoic crag
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this is the answer

glass kestrel
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square root of 5 is approx 2.24

stoic crag
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oh yea

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how do we find the angle though?

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never mind

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thanks

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scenic dagger
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how many ways can I represent latitude and longitude, say this one of central park?
40.770071, -73.974952

sand vigil
scenic dagger
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opencry 😏

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yes you right kevin

dim kestrel
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i just got it from the internet
There are various ways to represent latitude and longitude coordinates, but some of the most common ones are:

Decimal Degrees: The format you provided, 40.770071, -73.974952, is the decimal degree format, where the latitude and longitude are represented as decimal fractions.
Degrees, Minutes, Seconds (DMS): In this format, the latitude and longitude are expressed as degrees, minutes, and seconds. For example, the coordinates of Central Park in DMS format would be 40°46'12.3"N, 73°58'29.8"W.
Universal Transverse Mercator (UTM): UTM is a coordinate system that divides the earth into a grid and represents locations using easting and northing values. The coordinates of Central Park in UTM format would be 18T 583973mE 4512489mN.
Military Grid Reference System (MGRS): Similar to UTM, MGRS is a coordinate system that divides the earth into a grid and represents locations using a combination of letters and numbers. The coordinates of Central Park in MGRS format would be 18TWL8397301249.

There are also other formats and systems used to represent latitude and longitude coordinates, but these are some of the most common ones.

scenic dagger
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my goal is to try to reduce the characters counting without losing too much precision. But I believe if I introduce degrees and minutes and seconds, I'd be just adding more characters

scenic dagger
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thanks guys

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torn sphinx
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anyone can help me with solving this question ?

glass silo
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Which one - there are two visible?

torn sphinx
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question 1 thx

glass silo
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Cool cool, so note how they said that

The sum of the volumes of two spheres is [324pi cm^3]
and also
The radius of the larger sphere is equal to the diameter of the smaller sphere.
Can you use these to form equations?

torn sphinx
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4/3 pi r³ + 4/3 pi 2r³= 324pi?

glass silo
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Need to PARENS that carefully but basically

torn sphinx
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then I'll find the radius of the smaller sphere?

glass silo
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[and from there you can work out everything else they said]

torn sphinx
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can the equation be simplified into 4r³= 324?

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my answer is still different to the actual answer

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<@&286206848099549185>

daring stump
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@torn sphinx

torn sphinx
daring stump
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1st take pi common and it`ll cancel out
then you have to add terms r3

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you`ll get desired outcome

torn sphinx
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4.326....

torn sphinx
daring stump
torn sphinx
daring stump
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r=4.32

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if equation you wrote here is right..! @torn sphinx

daring stump
torn sphinx
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should be 216

daring stump
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yeah you did 1 mistake

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while forming the equation

torn sphinx
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which is?

daring stump
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use r=3 and calculate the things you want to calculate

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tell me if this is wrong

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ill check once again

torn sphinx
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ye it's correct

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288

daring stump
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so the mistake you did was

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they said that the radius of lager sphere is double of the smaller right..?

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then R=2r
R larger sphere radius
r smaller ------
right..?

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till this makes any sense to you...?

torn sphinx
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yew

daring stump
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so when you write the formula for volume its 4/3 pi r^3
this is right for larger sphere which is 4/3 pi R^3
but for smaller one it`ll become 4/3 pi (2r)^3

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got it..?

torn sphinx
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ye

daring stump
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4/3 pi R³ + 4/3 pi 8r³= 324pi

torn sphinx
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ohhhhh

daring stump
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so this is the correct equation
you have to take cube of 2 also in consideration

torn sphinx
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I get it now

daring stump
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glad i could help bro

torn sphinx
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thx so much 🙏

daring stump
torn sphinx
#

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deep gale
marsh citrusBOT
deep gale
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just want to double check

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would I be correct

main idol
deep gale
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would it be that for the 2nd 2 that since they go to infinity and -infinity they get closer to 1

main idol
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yes

deep gale
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gotcha

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I just was not sure which one it would be but it makes sense since it just gets closer

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oak void
#

if

marsh citrusBOT
oak void
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a quadratic have equation $y = 4(1-x)^{2}-2$

elfin berryBOT
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yomiko

oak void
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the the turning point would be (1,-2) right?

hazy lion
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for which class?

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i keep seeing the language turning point

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is that calculus? or are you talking about the max?

oak void
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some call it vertex

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or vortex

hazy lion
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sure

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vertex

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for which class is the question?

oak void
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what do you mean which class

hazy lion
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idk just curious if you can use calculus to discuss it or not

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what you can do is you know a square quantity is squared where it is 0, right

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the squared on a^2 means that a cant be smaller than 0

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so its smallest when its 0

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if thats (1-x)^2 then we want 1-x=0, so x=1

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thats where it will be smallest

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make sense?

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@oak void

oak void
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yeah

hazy lion
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okay

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and yea, i think -2

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so makes sense to me happy

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did you check it

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,w graph 4(1-x)^2-2

hazy lion
oak void
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right ok

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i saw the graph on my question wrong

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i was right lol

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thanks anyways

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🙂

hazy lion
#

you were right

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yea

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np

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tranquil dove
#

turning 2a^-1 + 3b^-2 into a single fraction with positive integers

2/a + 3/b^2 is the first step right

marble glacier
#

mhm

tranquil dove
marsh citrusBOT
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@tranquil dove Has your question been resolved?

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open plume
marsh citrusBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
open plume
#

1

marsh citrusBOT
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@open plume Has your question been resolved?

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tardy mist
marsh citrusBOT
tardy mist
#

they want me to find the volume between the both functions and i cant find any good variable exchanges that make it work 😦

#

the last integral doesnt end up with the right answer, i dont have the d( θ) because it is wrong somewhere before

#

didnt get that far

#

<@&286206848099549185>

#

tried another method but didnt work either 😦

#

the answer should be about 13,8

#

<@&286206848099549185>

marsh citrusBOT
#

@tardy mist Has your question been resolved?

tardy mist
#

anyone?

marsh citrusBOT
#

@tardy mist Has your question been resolved?

tardy mist
#

.close

marsh citrusBOT
#
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warm plaza
#

A triangular pyramid has a base shaped like an equilateral triangle. The legs of the equilateral triangle are all 13 millimetres long, and the height of the equilateral triangle is 11.3 millimetres. The pyramid's slant height is 18 millimetres. What is its surface area?
'

marsh citrusBOT
#

Please don't occupy multiple help channels.

stark trail
#

Don't occupy more than one channel

#

.close

marsh citrusBOT
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frigid python
#

Hey, this is more of a history of math problem. The proof that there are arbitrarily many composite numbers between prime numbers is quite trivial. For a gap of the size (N-1), create the sequence N!+2, N!+3, N!4, ..., N!+N - each of the terms in this sequence is composite and therefore we've constructed a "gap" of the size N.

However, I have no idea who said this first. Who was the initiator? Does anyone have any idea?

marsh citrusBOT
#

@frigid python Has your question been resolved?

main idol
frigid python
#

Ah, okay 😅 So do you think I can include it into my thesis without citing and referencing?

main idol
#

yes

#

unless you're writing a history paper

marsh citrusBOT
#

@frigid python Has your question been resolved?

marsh citrusBOT
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short jetty
marsh citrusBOT
short jetty
#

for some reason my brain isn't putting together between the factoring and

#

right after I get it all to the same side, the factoring by I'm assuming grouping is throwing me off, why can I just have the x-3 raised to the 4 just go to three and completely eliminate the x-3^3

#

my train of thought is pretty fuzzy on where to go after i isolate everything

wild zodiac
#

you're not understanding the logic behind this step, in particular?

short jetty
#

yes

wild zodiac
#

this is conceptually the same as this factorisation:

5x^2 + 10x

#

= 5x(5x+2)

short jetty
#

yeah

wild zodiac
#

5x here is the common factor

short jetty
#

yeah

wild zodiac
#

in your example, the common factor is (x-3)^3

#

(x-3)^4 / (x-3)^3 = (x-3)

#

-6(x-3)^3 / (x-3)^3 = -6

#

so you are left with (x-3)^3 [ (x-3) + (-6) ]

#

i can write that out in handwriting if notation is hard to understand

short jetty
#

nah youre totally fine

#

so after that i break down the x-3^3 right? but there since its cubed i don't set it to 0 just yet?

wild zodiac
#

what do you mean by 'break down' the (x-3)^3?

short jetty
#

split into (x-3)(x-3)(x-3)

wild zodiac
#

that isn't necessary in order to derive solutions

short jetty
#

so where would you go from there

wild zodiac
#

conceptually you need to know this:

#

if you can rewrite a function as

(x-a)^n * (x-b)^m * (x-c)^k * ... * etc

#

(stop me if i've lost you already)

short jetty
#

youre good

wild zodiac
#

you can derive that there are n-solutions of a, m-solutions of b and k-solutions of c

#

to ground what i just said in an example

#

consider f(x) = (x-3)^2 * (x-2) * (x+1)

#

from this point, we can say for f(x) = 0 we have

#

x=3 or x = 2 or x = -1

#

with x = 3 as a double root

short jetty
#

yeah yeah

wild zodiac
#

so back to your original question

#

you have (x-3)^3 * (x-9) = 0

#

using that concept

#

x=3 (triple root) and x=9 are the only solutions

short jetty
#

ohhhhhhhhhhh damn

#

the (x-3)-6 for some reason totally tripped me up

wild zodiac
#

ah

short jetty
#

I'm always so unaware of when I can remove parentheses

wild zodiac
#

that is only because of one condition

#

(x-3) is (x-3)^1

#

which just means (x-3)

#

parenthesis are only used there to signify that we have factorised a term with (x-3)^3 as a common factor

#

and it has left us with (x-3) by itself

#

if it was, say

(x-3)^2 - 6

#

you couldnt just do (x-9)^2

#

do you understand why?

short jetty
#

because it would be (x-3)(x-3)

#

x^2-6x+9

wild zodiac
#

yeah

#

and if instead you had (x-9)^2
(x-9)(x-9) will expand into something a lot different

#

this is the case for any (x-3)^n where n isn't 1

#

e.g (x-3)(x-3)(x-3) wouldnt be = to (x-9)(x-9)(x-9) and so on so forth

#

but with (x-3)^1 specifically

#

(x-3)^1 = (x-3) = x - 3

#

there is no operation happening upon the '(x-3)' here

#

so anything outside it, like the -9, can freely interact

#

i.e, we can remove the parenthesis

short jetty
#

yeah thats wild

#

something in me wants to just set the (x-3) = 0 and then get x = -3

#

even though its being subtracted from 6

wild zodiac
#

i can get that since when you see brackets its tempting

short jetty
#

6 subtracting etc

wild zodiac
#

you can infact do that for the (x-3)^3 straight away

short jetty
#

and have them just = 3 triple root?

wild zodiac
#

if you have f(x) = (x-3)^3 * (literally any function of (x))

#

like, say

#

f(x) = (x-3)^3 * (arctan(5/13^(15x)))

#

you would still have the solution

#

x=3 (triple root)

#

(and some other wild solution for whatever is on the other side, there)

short jetty
#

yeeah yeah

wild zodiac
#

the important distinction here is the multiplication

short jetty
#

may i ask another question

wild zodiac
#

sure thing

short jetty
#

excuse the mess above lmfao

#

so when i see this

#

my first thought is to grab common etc

#

and i first imagined itd be the x(x-2) ?

#

to give me this?

wild zodiac
#

small mistake here-

#

oh you just corrected it there

#

oh

#

no you didnt

short jetty
#

oh yeah the stuff above the line that i poorly seperated is bad

wild zodiac
#

well

#

the solutions to this from step 2 you can see will be

#

[x^2] = 0

#

[(x-2)] = 0

#

[(x-2)^3 - 1] = 0

#

the first two should be trivial

short jetty
#

the first one isn't a double root?

#

that was kind of driving my crazy

#

x^2?

wild zodiac
#

[x^2]=0 => x=0 (double root)
[(x-2)]=0 => x=2

#

the first one is a double root

#

again thou gh

short jetty
#

yeah that's what is figured, but they dont give me the option for that

wild zodiac
#

noticing that things are double roots are only important graphically

#

do you understand what i mean?

short jetty
#

yeah i think

#

to square root zero for the sake wouldnt really do anything

wild zodiac
#

well rather

short jetty
#

im not sure

wild zodiac
#

if your questions is 'What are all the possible solutions for x?'

#

you would just write 'x=0'

short jetty
#

it's just solve, and since i didn;t see double root there i freaked

wild zodiac
#

'double root' just means that, in a graph, the function passes through 0 'twice' at the same spot

short jetty
#

yeah yeah that part i got

wild zodiac
#

the last part of the question is to solve [(x-2)^3 - 1] = 0

short jetty
#

but wait

#

on this part, am i approaching this correctly step wise?

wild zodiac
short jetty
#

oh wait

wild zodiac
#

you were right to factor out a common factor, yes

short jetty
#

i saw yours, okay so thats the right factor

wild zodiac
#

for the last brackets, we expand for

expand out for (x-2)(x-2)(x-2) - 1 = 0
(x^3-6x^2+12x-8) - 1 = 0
x^3 -6x^2 + 12x - 9 = 0

#

using factor thrm notice x=3 is a factor

short jetty
#

ohhhh i got it, the first part for why thats factored the way it is

wild zodiac
#

=> (x-3)(x^2 -3x +3)=0

#

use quadratic formula for the one on the right

short jetty
#

on the last bit?

wild zodiac
#

for (x^2 -3x +3)

short jetty
#

ahhhhh i think im mentally flooded a second

wild zodiac
#

but tbh, you probably don't want complex answers...

#

let me just triple check i've not made any mistake

short jetty
#

yeah nah not yet

wild zodiac
#

weird that they'd give you this question, then

wild zodiac
short jetty
#

yeah those are the choices

#

im surprised double root for zero isnt there

#

that really messed with me mentally

wild zodiac
#

right they probably just want you to say:

"ah, this sqrt( ) has a - in it, i should disregard it completely"

short jetty
#

the (x-2)(x-2)(x-2)-1

#

how should i approach that again?

wild zodiac
#

have you done something called polynomial division at your stage?

short jetty
#

not in depth we're going back over it in a few units

#

all of the video lessons on this dont have it being done on these

wild zodiac
#

you can not approach (x-2)(x-2)(x-2)-1=0

#

without knowing how to compute this

#

(at least, i dont think so)

short jetty
#

id have to review that, we did it a while ago but it wasnt used to solve any of these up until this point

#

mostly factoring by grouping and differences of squares

wild zodiac
#

i can remind you how you would do it if it'd help

#

i was only hesitant because what you're doing could be a few grades behind what this is

short jetty
#

yeah im actually returning to school, way later

wild zodiac
#

polynomial division is where you know (x-3) * (something) = (x^3 -6x^2 + 12x - 9)

#

and you want to factor out the (x-3)

#

to get the (something)

#

and rewrite it as (x-3) * (something)

short jetty
#

x^2 + 2x + 4 i think something like that

wild zodiac
#

wdym?

short jetty
#

i think is the answer to that, idk

wild zodiac
#

it's a good guess in that

#

you know the (something) will likely be a quadratic

#

because the biggest term of the product function is x^3

#

so you'd need an x^2 at most to get from x to x^3

#

but unfortunately, we need to be very exact

#

and the rest of it (+2x+4) isn't correct

#

so we can't just guess, we need to follow a division algorithm a little like long division

short jetty
#

oh yeah i wasn't writing it down or anything, i actually think i found out how they want me to do it

#

i think they want me to factor an (x-2) out of the (x-2)^3

wild zodiac
short jetty
#

yeah

wild zodiac
#

i'm unsure how that'd help solve it

#

you couldn't just say 'x=2' from that

short jetty
#

yeah youre right

wild zodiac
#

(you would get (0)(0)^2 - 1 = 0, -1=0 which isnt right

short jetty
#

so the answer choices there are wrong in that there isn't a double root for x^2

#

?

wild zodiac
#

the answers to your question are

x=0,x=2,x=3, & x=3/2 +/- i sqrt(3)/2

#

you can ignore the 4th and 5th, however

#

as they are complex

#

x=0, x=2 and x=3 are the answers

short jetty
#

no double root?

wild zodiac
#

it is a double root

#

you just don't tend to write that

short jetty
#

the last test i took marked it wrong because i didn't

wild zodiac
#

this is the double root

short jetty
#

is it not a usual convention?

wild zodiac
#

well, i can say that to me it personally isn't as a college student in the field

#

if your teacher is asking for it though then i would just out of habit

#

if they are specifically saying, no, x=0 is a single root, not a double root

#

then they are wrong

#

it is a double root

short jetty
#

okay gotha

#

so for the sake of the answer then, and in general, in this context, x^2 = 0

#

of this specific problem

wild zodiac
#

(x^2) * (x-2) * [this last function we're working on] = 0

#

solution 1:
(x^2) = 0
=> x = 0

#

solution 2:
(x-2) = 0
=> x=2

#

solution 3 is what we're working on righ tnow

short jetty
#

yes yes

#

excellent

#

i understood all of that

#

now the (x-2)^3-1

wild zodiac
#

solution 3 will be the case:

(x-2)^3 -1 = 0

short jetty
#

without using polynomial divison or the quadratic formula, how would you approach that

wild zodiac
#

you couldn't

short jetty
#

at all

wild zodiac
#

well

#

you could find (x-3)

#

but

#

you couldn't say 'I am certain that the quadratic that occurs when I factor out (x-3) will give me real solutions'

#

real meaning 'not-complex'

#

so really you'd have to approach it in full

short jetty
#

so i cant solve this without either of those

wild zodiac
#

which requires polynomial division

short jetty
#

we havent used that in this unit

wild zodiac
#

i don't think so, no

short jetty
#

i think i can use the difference of two cubes here actually

#

(x-2)^3 - 1

#

(x-2)^2 + (x-2) + 1

wild zodiac
#

TIL that difference of two cubes is a thing o_o

#

yeah that works plenty

short jetty
#

yesss

wild zodiac
#

so from here you have x=3 as solution as required

#

and you would just show the discriminant test for the quadratic to show it has no solutions in the reals

short jetty
#

yeah yeah

#

they didn't want me messing with anything complex in this yet

#

ahh youre the best, big time thanks

#

the parentheses getting removed and the double root thing tripped me up majorly

#

.close

marsh citrusBOT
#
Channel closed

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#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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simple briar
#

hello

marsh citrusBOT
simple briar
#

So,

#

I calculated the fourth derivative to be 6/x

#

but then I get n = 100(1000x^3)^1/3 / x

#

which can't be right

#

so i'm a little lost

#

i basically simplified to

#

1/(3X10^6n^4) < 1/3X10^17

#

oh

#

nvm

#

i'm so slow

#

i didn't plug in my lower limit

#

lool

#

this channel can be closed

marsh citrusBOT
#

@simple briar Has your question been resolved?

#
Channel closed

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After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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glass needle
#

how would i slove (2x^3y^2z^4)^3 x (2z^2)^3 ??

keen stump
#

theres no equals sign

#

can't be solved for what I know

#

simplify?

nova totem
#

Use like • or "times"

glass needle
nova totem
#

Looks like a third term of x

glass needle
#

so would i dispute the 3?

keen stump
#

You want to distribute the 3 to every number/variable inside the parentheses

glass needle
#

ohh okay

#

so what would it be?

keen stump
#

try solving it and ill tell you if youre right

glass needle
#

bc doesnt 2^3 = 6?

keen stump
#

2^3=8

glass needle
#

but how?

keen stump
#

$2^3=222$

elfin berryBOT
#

CrEpasPmkinPie

glass needle
#

but i got 12 doing that

#

not 8?

keen stump
#

how?

glass needle
#

bc i went 2x3, 2x3, 2x3

keen stump
#

that doesn't even equal 12 lol

glass needle
#

idk 😭

#

2x2 2x2 2x2

#

is what i did

keen stump
#

ohhh

glass needle
#

yeah

#

but idk how u got 8 and i got 12

keen stump
#

$222$

elfin berryBOT
#

CrEpasPmkinPie

keen stump
#

$2*2=4$

elfin berryBOT
#

CrEpasPmkinPie

keen stump
#

$4*2=8$

elfin berryBOT
#

CrEpasPmkinPie

glass needle
#

OHHHH

#

okayy

keen stump
#

So what do you get for the question now?

glass needle
#

lemme see

#

wait

#

(2z^2)^3

#

it also be 8 if i did it with the 2 and 3?

#

the two exponets

keen stump
#

yes

#

but don't forget to do the exponents to the variables

glass needle
#

so its not differant?

#

ok

#

so

#

would it be

#

(8x^27y^8z^64) x (8z^8)?

keen stump
#

well

#

n o

#

lets see

glass needle
#

;-;

keen stump
#

if I told you to do

#

$(x^4)^3$

elfin berryBOT
#

CrEpasPmkinPie

keen stump
#

that would be same as saying

#

$(xxx*x)^3$

elfin berryBOT
#

CrEpasPmkinPie

glass needle
#

uhhuh

keen stump
#

and then if you expand that out

#

$(xxxx)(xxxx)(xxx*x)$

elfin berryBOT
#

CrEpasPmkinPie

glass needle
#

geez

keen stump
#

its chonky

glass needle
#

so then would it be

#

8x^9y^6z^12 x (2z^2)^3?

keen stump
#

yes!!

glass needle
keen stump
#

$8x^9y^6z^{12}*(2z^2)^3$

elfin berryBOT
#

CrEpasPmkinPie

glass needle
#

and i still have to simpily ?

keen stump
#

simplify the right term

glass needle
#

the one with the ()?

keen stump
#

yes

glass needle
#

ok

#

8z^6

keen stump
#

yes

#

now multiply those two terms together

glass needle
#

ohhh

#

so its:

#

64x^9y^6z^18??

keen stump
#

yes

#

and that's your answer

glass needle
#

o ok

keen stump
#

but here's the rule on the exponents and parentheses

glass needle
#

what is it?/

keen stump
#

$(x^a)^b=x^{ab}$

elfin berryBOT
#

CrEpasPmkinPie

glass needle
#

thats what

keen stump
#

?

glass needle
keen stump
#

thats the rule for exponentd and parentheses

glass needle
#

o ok

#

anyways ty

keen stump
#

np

glass needle
#

.close

marsh citrusBOT
#
Channel closed

Closed by @glass needle

Use .reopen if this was a mistake.

marsh citrusBOT
#
Available help channel!

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Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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rancid saffron
#

How to solve?

marsh citrusBOT
nova totem
#

Take the natural log of both sides

#

Your erased work is fine

rancid saffron
#

Ok!

#

Then how do I find the answer?

nova totem
#

Your work was fine

#

Your answer of ln(21) is correct

rancid saffron
#

It requires a decimal number as the answer

nova totem
#

,w ln(21)

elfin berryBOT
nova totem
#

There

#

You have to use a calculator to get that

#

Note that wolfram treats log as ln

rancid saffron
#

Ohhh I see

#

Thank you

#

Have a nice day

#

God bless

#

.close

marsh citrusBOT
#
Channel closed

Closed by @rancid saffron

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Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

still temple
#

Hi

marsh citrusBOT
#

Please don't occupy multiple help channels.

still temple
#

I have a question

mellow isle
still temple
stoic saddle
#

i closed the other one

still temple
#

How do they get the X values @mellow isle

#

Or just in general

#

they just picked them

#

Cause I assume that they got the y values then multiplied by -1

#

Yeah I know

#

It’s a reflection off the X axis correct?

#

idk what question you are referring to

#

D

#

the sheet just looks like its practicing graphing equations

#

Yea, but the y values are correct, but the X values are incorrect

#

Why tho

#

whats f(x)

#

Wouldn’t the equation be x=2X+4

#

Cause I found the y values, and that’s correct

#

The x values are incorrect

#

can u show what f(x) is

#

Idk @

#

what

#

Idk what you’re asking me

#

send a picture of the function

#

or graph associated with it

#

It’s the very top one

#

On the left

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You just need to translate it

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i can barely see it

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The points are

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(-2,0), 0,-2, 6,1

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I understand how to get the Y values

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Not the x tho

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I dont understand you question, you want to know how to translate the graph ?

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Yes

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what part are you stuck with

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The x values

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okay

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do you know what f(cx) does to the coords?

#

like lets say f(x) gives you a point (a, b)

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what does f(cx) give you

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and similarly what does f(x+d) give you

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Wouldn’t it be x= 2X+4

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Then you put the points into X

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what

still temple
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Not sure @still temple

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if f(x) gives some some point (a, b)

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Compress

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then f(cx) gives you (a/c, b)

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f(x+d) gives you (a-d, b)

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apply that to the points

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How would you write the equation

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what equation

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Like how would I find the x points

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okay so you have the point

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(-2, 0)

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transform it

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Yes

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How?

still temple
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How do I transform the x points

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Can you explain in simpler terms

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I don’t get what you’re telling me

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f(x) gives (10, 10)

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f(2x) gives (5, 10)

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How

still temple
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The equation is 2X+4

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okay

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2(-2)+4??

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what

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okay

still temple
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No

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what part dont you understand

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What it means

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if you have a function

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f(x)

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and transform it by some constant c

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such that

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f(cx) is ur new function

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then a point (a,b) will turn into a point (a/c, b)

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Yeah I get that, but how do they get the x values transformed

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bro

still temple
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(a,b) turns into (a/c, b)

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c is the constant you transformed by

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Can you show me how to get the first x point

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okay

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lets say

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f(x) gives you some point (10, 10)

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then f(2x) gives you (10/2, 10)

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do you get that ?

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10 divided by 2?

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yes

still temple
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Why are you dividing

still temple
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You divide the x values?

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yes

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If the original point is (-2,0) then what the transformed point of x for 2X+4

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lets say you have f(x)

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which gives a point (100, 100)

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what does f(10x) give you

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what point ?

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10

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give the whole point

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10,100

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okay

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what about f(x+1)

still temple
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Idk

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f(x+d) gives you (a-d, b)

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you have (100, 100)

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what does f(x+1) give you

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Not sure

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-1?

still temple
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d is just some constant

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so f(x+d) means like f(x + SOME NUMBER)

still temple
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Just some number

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whats the number specifically

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f(x+1)

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what is d

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100

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f(x+d)

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you have

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f(x+1)

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what is d

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1

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okay

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f(x) gives you (a, b)

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f(x+d) gives you (a-d, b)

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if f(x) gives you (100, 100)

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what does f(x+1) give you

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101

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no, your answer is meant to be a point

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and either way its a-d not a+d

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okay I'm going to sleep maybe someone else can help

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Okay

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Can someone else help me please

marsh citrusBOT
#

@still temple Has your question been resolved?

#
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still temple
#

.close

raw coral
#

How do u do this?

marsh citrusBOT
static quarry
#

what needs to be true in general for a function to be continuous at a point?

raw coral
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left and right sides must equal each other

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but there are 2 variables

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so doing that wont work

static quarry
#

no

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only x is a variable

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a and b are constants that you have to determine

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there may be more than one pair of (a,b) that work

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which is why they say "find all numbers a and b.."

raw coral
#

how would $a/x-1$ be continious on 1?

elfin berryBOT
raw coral
#

there is a va at 1

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can you tell me the answer

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i legit dont have any idea

static quarry
#

there's exactly one value of a that will give a/(x-1) a finite limit as x->1

raw coral
#

woundn't that be 0?

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otherwise it's just +-infinity

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@static quarry

#

bruh

#

wtf

#

.close

marsh citrusBOT
#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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white brook
#

This is my problem

marsh citrusBOT
white brook
#

This is what I've tried

#

In my head it seems correct, so I'm not entirely sure what it's flagging, whether it's a calculation issue, or a syntax issue.

flat raft
#

you wrote x in there when the variable is clearly t

white brook
#

Yeah I saw that

#

I started a new problem but am having a similar issue (I think)

#

.close

marsh citrusBOT
#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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sterile mango
marsh citrusBOT
sterile mango
#

hi this question is about shoes so the only thing i dont understand here is 1/7 of the GST inclusive price

marsh citrusBOT
#

@sterile mango Has your question been resolved?

limber star
sterile mango
#

so its just 158.50 x 1/7?

marsh citrusBOT
#
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fervent turtle
#

How would I find inverse tan of -7/5 in degrees

fervent turtle
#

(Without calculator)

edgy jungle
fervent turtle
#

Oh y’a

#

.close

marsh citrusBOT
#
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fervent turtle
#

.reopen

marsh citrusBOT
#

fervent turtle
#

How would I determine if it is Q2 or 4 based on a given tan or will it not matter

stoic saddle
#

arctan only gives outputs between -90° and +90°, so only Q4 and Q1

marsh citrusBOT
#

@fervent turtle Has your question been resolved?

marsh citrusBOT
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hollow pelican
#

Work on the right. What did I do wrong?

marsh citrusBOT
#

@hollow pelican Has your question been resolved?

marsh citrusBOT
#
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