help-33

[spark berry]

U made it too much complicated and I don't know where u got the first equation

[unreal oxide]

What exactly are the equations u set up

[spark berry]

The first one should be
R1 + R2 = 18 since this one is series

Then create another system of equation for parallel
1/R1 + 1/R2 = 4

U can use substitution method to get R1 and R2

[spark berry]

@unreal oxide and that is why I was unsatisfied with my equation

Yeah u made it too complicated for urself

At the parallel equation

Just do 1/R1 + 1/R2 = 4

Then use R1 + R2 = 18 to get the answer via substitution

[unreal oxide]

1/R1 + 1/R2 = 1/4

Not 4

[spark berry]

AH yes

Typo

BUt yeah just the same

it says 4 ohms

[marsh citrus]

@bright badge Has your question been resolved?

[bright badge]

no

so whats the value for r1 and r2 ?

im more confused

[spark berry]

Nah first equate something at here

It can be R1 or R2 both works

[spark berry]

Then use it to substitute here

There will be a quadratic equation there

The answer is 12 and 6 basically

[bright badge]

thanks!!!

💯

[spark berry]

Were u able to get the equations?

[bright badge]

im trying right now

[marsh citrus]

@bright badge Has your question been resolved?

[marsh citrus]

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[marsh citrus]

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[marsh citrus]

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[open notch]

id like some help on Julia sets

[open notch]

im creating a research competence about fractals and i finished mandebrot, im now doing Julia sets as they correlate a bit. but im kinda confused about how a Julia set is coloured

[knotty trellis]

Do you know how the black part is generated?

The convergent?

[open notch]

yea, its the same as the mandebrot right?

if it either converges or loops

[knotty trellis]

Not really, different formula

[open notch]

yea

[knotty trellis]

Do you know the formula?

[open notch]

okay

im using the one for the mandelbrot

where Z0 isnt 0

[knotty trellis]

At this formula C is constant, and initial Z, is the complex grid

[open notch]

Z0= to a picked complex number with an r smaller than 1 right?

[open notch]

mhm!

in my school book its talking about the fact that if Z0's modulus is bigger than 1 it will always diverge? but this seems strange to me

i think it is modulus in english

[knotty trellis]

It says that all points outside unit disk (filled unit circle) diverge in julia set

[open notch]

mhm interesting

yea that correlates

so im trying to define julia sets too because i cant really find it. but then can you define them because there are so many?

[knotty trellis]

You can define it

every julia set of mandelbrot, is defined by C in the Z=Z^2+C

[open notch]

okay okay, ill keep looking for that then

yea

i had this for the mandelbrot set

[knotty trellis]

Do you want the formula to generate picture of julia?

[open notch]

now excuse me for mistakes im going to translate

well im only going to talk about the ones made from points of the mandelbrot set

probably

but actually sure

The Mandelbrot set is the set of all C-values from the dynamic Z_(n+1)^2+C for which the trajectory does not diverge to infinity.

and btw the julia set is the ''perimeter'' whilst the fractal itself is the black area right?

😬

[marsh citrus]

@open notch Has your question been resolved?

[open notch]

can anyone help me further?

[knotty trellis]

It's just the "perimeter", idk what you mean by fractal, but the images are usually filled

the filled black area is converging

[open notch]

well you have '' dust something''

they arent filled

if you know what i lean

mean

[knotty trellis]

Fatou dust?

[open notch]

yes!

[knotty trellis]

Seems like my pfp

[open notch]

but this only occurs when u pick a Z0 value outside of your mandelbrot fracal right?

yes!

thats actually a nice example

[knotty trellis]

I think so

[knotty trellis]

replying to this

[open notch]

okay okay

are you cool with me hitting you up with another question if nessecairy?

nescecairy

nescesairy

bro idk how to write that xD

[knotty trellis]

necessary?

[knotty trellis]

Yeah, but I don't know much about it. I just have a lot of experience with generating them using code

[open notch]

ahaaa

like that

okay i c

i dont think i have time to include that

since my deadline for all info is this thursday, i only need to finish the julia sets

i then spoke abt the triangle of sierpinski, romanesco broccoli, snowflake ofc, mandelbrot and Julia sets

and some history definitions etc

anyways

Thank you for the help!!! much apriciated

[marsh citrus]

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[chrome sage]

How would i solve this?

<@&286206848099549185>

[austere heron]

Equate the density formula of A and B

[hollow veldt]

is it coming 4800 g

[chrome sage]

i tried 4800 its saying it is wrong

[chrome sage]

could you ecplain i dont get it

[hollow veldt]

okk

[chrome sage]

<@&286206848099549185>

[austere heron]

Your question seems to be missing smth

Check if the answer is just 6912

Which would technically not be possible

[spark siren]

you calculated a relation between surfaces which is quadratic. mass will be cubic.

[chrome sage]

oh i cropped it out the extra info was 2 similar solids are shown

the solids are made from same material

[austere heron]

No that’s included u didn’t crop out

Anything about the length of additional measurement of the solid

[chrome sage]

that all it says in the question then

[austere heron]

Ah I see

[chrome sage]

no

[austere heron]

And it’s not 6912 grams right

Just checking lmao

[chrome sage]

no just did it

says wrong

[spark siren]

try 4000

[chrome sage]

thank youu

it was right

how did u get that

[spark siren]

as i said before.

[spark siren]

[chrome sage]

Thanks @spark siren

.close

[marsh citrus]

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[timber tundra]

hi, could someone explain how to solve this:
let u = (ac)
and v = (bd)
be non-parallel vectors in the plane.

(a) Determine the matrix M that maps ex and ey onto u and v, respectively.

[marsh citrus]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[timber tundra]

step 1

[marsh citrus]

@timber tundra Has your question been resolved?

[timber tundra]

<@&286206848099549185>

[marsh citrus]

@timber tundra Has your question been resolved?

[timber tundra]

.close

[marsh citrus]

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[marsh citrus]

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[hazy tapir]

How do i solve this?

[marsh citrus]

@hazy tapir Has your question been resolved?

[marsh citrus]

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[still temple]

Hi need help

[still temple]

Plz

My question is f(x)=1/x

Minimum and maximum value

<@&286206848099549185>

[dense verge]

You mean?

[marsh citrus]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[dense verge]

$$ \text{What is the Minimum and Maximum Values of } F(x) = \frac{1}{x} $$

You mean this?

[elfin berry]

Nerdy_Coder

[dense verge]

@still temple ?

[obsidian shard]

what's the domain?

[dense verge]

@still temple Vertical and Horizantal Asymptotes?

I found them

and also what is the domain and range

If possible give in interval notation

[dense verge]

Why would someone ask a question then leave?

Seriously.....we are trying to help

[devout mauve]

you get used to it

[marsh citrus]

@still temple Has your question been resolved?

[still temple]

Sorry

I’m class

I’m in class

[spark berry]

bruh

[still temple]

Had a quiz English block

[spark berry]

r u using us for ur test?

cause that's a no no here

[still temple]

English and math totally different

Sorry didn’t mean to sound rude

I’m using u guys for an assignment tough

If that’s ok

[spark berry]

That's fine

[marsh citrus]

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[valid lantern]

Why can't I to this

Why do I need IBP if I can just convert 1/C0 S x to sec x

[still temple]

arccos isnt 1/cos

[civic blade]

I hate notation BS, I feel ur pain mukby

[marsh citrus]

@valid lantern Has your question been resolved?

[valid lantern]

How is it not 1/cosx

Secx=1/cosx

(Cosx)^-1=1/cosx

[valid lantern]

No comprende

[civic blade]

the notation here is meant to imply that $\cos^{-1}(x)$ is arccosine function NOT cosine raised to the -1 power which would mean $\frac{1}{\cos(x)}$

[elfin berry]

Jukelyn

[valid lantern]

My god why not just say that

[civic blade]

you're right but $\cos^{-1}(x) \neq (\cos(x))^{-1}$

[elfin berry]

Jukelyn

[civic blade]

they did

[valid lantern]

No not u

That he question

[valid lantern]

Hw

[civic blade]

uh, i'm not sure I get what ur asking

are you asking for the answer to ur hw question?

[valid lantern]

No no I was saying why didn’t they just note “arccos” to not be confused by notation

[civic blade]

they kinda alluded to that

[valid lantern]

I wasn’t like mad at u lol just the way they formatted the question

[civic blade]

I wasn't answering ur question lol, I was just joining u in being mad at the shit notation

yeah

lol

me too !

[valid lantern]

Lol yea

Ty

.close

[marsh citrus]

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[marsh citrus]

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[wispy blaze]

Really bad picture but c is the correct answer right?

[wispy blaze]

Another pic

[still temple]

yeah

wait

i mixed up the letters

no C is not right

[wispy blaze]

Mb

I meant b

[still temple]

oh okay then yeah

seems legit

[wispy blaze]

Can u look at another one for me?

[still temple]

sure

[wispy blaze]

This

Pretty sure I did it right

[wispy blaze]

U there?

[still temple]

uhh

sorry was in other help channels

[still temple]

what do u need help with?

[wispy blaze]

Just to double check

If I got it right

[still temple]

no

u didnt

[wispy blaze]

Both were wrong?

Did I solve it weirdly somehow cause idk what I got wrong

[still temple]

i ignored ur part b because saying "slant asymptote" isnt really an answer

[wispy blaze]

She told me it was either slant or horizontal

So that’s why

She being the teacher mb

[still temple]

i mean i would expect you to show your reasoning behind that conclusion in there as well

not just write two words

[wispy blaze]

Yeah the explanation is basically how I solved a I think

But b is prob wrong since a is

What did I get wrong with a?

[still temple]

first of all 2x^2/x isnt giving you x

thats ur first mistake and u should retrace from there

[wispy blaze]

Wouldn’t it tho cause 2x goes into x 2 times and x times x is 2x^2

Idk I never put 2x^2 into x before so I prob am wrong

[still temple]

no but like

2x^2/x= 2x

not x

[wispy blaze]

Ah

So the answer would be

2x-11=f?

[still temple]

no...

[wispy blaze]

If that’s the only mistake then that should be it no? Cause I put the x which I did wrong on top so replacing it would be 2x-11

[still temple]

No i just did not comment on the rest of your mistakes because they would've been wrong regardless because your first step was a mistake to begin with

So you are better off redoing it instead of trying to salvage it step-by-step

[wispy blaze]

Yeah but I don’t know what other mistakes I made

Cause it looks normal to me

.close

[marsh citrus]

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[solar light]

Could I have some help on B? Not sure where to start

[solar light]

Im seeing some correlation in a where 0 is B-A and 1 is D-C, but im not sure if its relevant or how to apply it

[still temple]

If your answers for a are correct, then you know that v=3(B-A). The 3 variables in that formula are v, B, and A. We're assuming we know v and B already, and are looking for A. How can you find A from this formula?

[marsh citrus]

@solar light Has your question been resolved?

[still temple]

@solar light Uuuuh how am I supposed to interpret this thumbs up emoji?

[solar light]

lol that I understood and am trying it now

Just have one last question where the variable E is introduced as well so Ill give it a try and either close the channel if I get it or ask if not

[still temple]

I'm in multiple channels at once, so I'm looking for whether the channel has a new message, hence I can't see it if you respond by reacting

[solar light]

will do, having some trouble but its a more complicated one so havent been able to come up with an answer yet. Getting closer tho

[still temple]

Ping me if you come back

[solar light]

Task d:
Ive found p'(1) = 3(D-C) and q'(0) = 3(E-D)

I tried to place E alone but since its E = and not a new variable u/w like last question, Im not sure how to do it. x is just a placeholder since I didnt know what to put, and not relevant to the question.
E = (x/3)+D

[still temple]

Hmmm...

Well first setup an equation

(I've been thinking about your question for like 5 minutes before realising the answer was simple)

[solar light]

E = 3(E-D)?

[still temple]

How'd you get that?

[solar light]

Im kind of on deep water just seemed like something that could be right since its the simplified version of the q(t) line when you sub t for 0 because its the only line that contains the E variable

[still temple]

what

[solar light]

basically idk

enlighten me

[still temple]

Anyways I was thinking of 3(D-C)=3(E-D) simply

[solar light]

ohh

that... makes sense

1 sec let me try that

solved it thanks a lot for your help!!

[still temple]

@solar light I'm gonna go now so whether or not you have more questions you should .close this channel

[solar light]

Forgot to close

.close

[marsh citrus]

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[last beacon]

please verify and check that if the answer is

a = 3.739 meters

I made this problem and would like to know if I made it in a way that is understood clearly.

[marsh citrus]

@last beacon Has your question been resolved?

[marsh citrus]

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[still temple]

what's the name of the formula used here?

[still temple]

what is this called

they just expanded the parenthesis

(a-b)^2 = a^2 -2ab + b^2

i guess

[lean flame]

(a-b)^2 = a^2 - 2ab + b^2

I don't know the name 😂

[still temple]

hmm

i forgot the name as well

[bright jay]

Binomial expansion

[still temple]

oh yeah

that stuff

so,w ait

[lean flame]

Square of difference?

[still temple]

so this would be

this

and then they somehow transferred one of the 2s to the 2 that is in front of the root and got 4^3root2

[lean flame]

What is your goal?

[still temple]

to learn math

[lean flame]

No I mean in this question lol

[still temple]

are these the steps they undertook to get 4^3root2

wait

2 x ^3root2 x 2 = 2^3root2 x 2 = 4^3root2

yeah, most likely

[bright jay]

That 2 you wrote under teh root, isn't under the root

[bright jay]

Look here

[still temple]

it's above

bruh

[bright jay]

It's $\sqrt{2} \cdot 2$

[elfin berry]

dldh06

[bright jay]

Hopefully that answers that question

[still temple]

this?

[bright jay]

Yes

[still temple]

yeah, that's what i wrote here

[still temple]

.

it was a little messy tho

[bright jay]

I'm talking about here, you wrote a 2 under the root

[still temple]

ahh, the right one

i did cuz i was thinking in a wrong way

[bright jay]

But this is was was applied because multiplication is commutative

[bright jay]

Yes

[still temple]

cuz root2 * root2 = root2*2

anyways, thx for ur help i appreciate it

.close

[marsh citrus]

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[glossy furnace]

I have this system of equasions. I know how to solve it. I have to verify if this is a subspace of R⁵. How can i verify it?

[still temple]

you need to show that any vector in R^5 can be written as a linear combination of the columns of the matrix

basically

show that all the columns are linearly independent

you are basically trying to find what Col(A) spans

[glossy furnace]

how do i prove it?

[still temple]

row reduce

[glossy furnace]

the rows of this equasions are linearly independent, so it did not reduce anything

I really don't know how to continue @still temple

[still temple]

if the columns are all linearly independent, then the thing spans R^5

[glossy furnace]

so thats it?

It cannot span the whole R⁵ because I have only 4 rows

[still temple]

okay, let me verify, are you trying to find the column span or the row span?

[glossy furnace]

I really don't know for sure what to do, thats why I asked. I have the equastions. I am somehow supposed to verify that it is a subspace of R⁵.

just by looking at it i can say that it is part of R⁵ but i have only 4 rows

so there is no way that i can get the whole R⁵ from that

This is the task, but it is not in english

There is a system of equasions. Find the homogeneous solution of the system, verify that is it a subspace of R⁵. Then find every solution of the equasion.

Thats what is says

[marsh citrus]

@glossy furnace Has your question been resolved?

[glossy furnace]

@still temple any idea?

[marsh citrus]

@glossy furnace Has your question been resolved?

[marsh citrus]

@glossy furnace Has your question been resolved?

[marsh citrus]

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[soft skiff]

Linear Algebra:

[red locust]

aight bro

post work

[soft skiff]

give me a sec

I feel like i missed a step...is e suppose to be 1?

[whole sleet]

I mean it is saying "use a computer algebra system"

[static quarry]

row 2 column 2 should be 8 no?

[soft skiff]

you're right

[static quarry]

yea, i would totally plug this into matlab or some other software

[static quarry]

why are there only 4 rows

you missed the one that starts with 81

[soft skiff]

fixed it

I want to know if the functions are correct. For #1, is
1a + 1b + 1c + 1d + e = 2 correct?

[static quarry]

yea your whiteboard work is right

(after the row 2 col 2 correction)

your last screenshot is almost right except you entered the wrong value for the last column of row 2

should have been 6 instead of 1?

[soft skiff]

good catch

[static quarry]

i did it locally in matlab, that's the only reason i spotted it

[marsh citrus]

@soft skiff Has your question been resolved?

[marsh citrus]

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[austere heron]

Hey guys. I am a bit u clear with this one. Do I just find the inverse of a matrix and multiply with A to show elementary matrix being [1 0][0 1] for 2x2 and [1 0 0][0 1 0][1 0 0] for 3x3?

[devout mauve]

do you know the method of writing down (A | I) and then row reducing the left side until you get ( I | A^(-1)) ?

each row operation corresponds to multiplication by an elementary matrix from the left

so from the row operations that you are doing you can read off the elementary matrices

[marsh citrus]

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[still temple]

Hey, I need Help…

[crisp imp]

[still temple]

Wait, Actually NVM, I Figured It out

Sorry about That

.close

[marsh citrus]

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[polar fable]

matrices and dets

[crisp imp]

Do you know what order of a matrix is

[polar fable]

yes

colums and rows

[crisp imp]

Order = Rows $\times$ Columns

[polar fable]

yeah

[crisp imp]

Yep

So

Lets say

You got

9 elements

In a matrix

How can you arrange those 9 elements

So basically

In how many rows and columns

[polar fable]

ok

[stoic saddle]

"what kind of rectangle can you make out of 18 square blocks"

"and the same question for 19"

[polar fable]

9x2]

[crisp imp]

Yep

And some more

[polar fable]

3x6

6x3

2x9

18x1

1x18

[crisp imp]

Yeah!

[polar fable]

only these

19 how will we arrange>?

[crisp imp]

Find it

How many kinds of rectangles

Of 19 blocks

[polar fable]

1x19

19x1

only

oh so this the ans?

[crisp imp]

Yeah

[polar fable]

thanks i am silly sometimes

[crisp imp]

Nah, its okay.

[polar fable]

.close thanks again'

[marsh citrus]

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[thorny onyx]

what do v and t mean here?

well in this case it would by my min and gal

but for other problems looking for slope of secant line, what would v and t mean?

[spark berry]

Ah r u having trouble with a?

[thorny onyx]

i have not started calculating but for now i want to know what v and t would represent in a different problem

[spark berry]

I mean v is just the volume and t is just time

Can't really sure what ur confused at? just tell me the part where ur having trouble

hello? still there @thorny onyx ?

[thorny onyx]

this is equation for slope of a secant line. in this instance v is gallons and t is minutes. my question would be, what will v and t represent in future problems?

[spark berry]

U mean the questions in a and b?

[thorny onyx]

yes

[spark berry]

My god guy, u just confused my with ur deep english

can't really understand what future problems ur saying there

XD

So anyways

t is just like x and v is just like time

The way I deduced is from the table at the top and the table in question a

From the table at the top, there are intervals with t or time

Usually, u only do that if ur treating a variable as the x or the input

Ah r u going to ask something?

Just ask right away

Smarty u still typing or something?

[thorny onyx]

ya im confused myself

ill have to ponder my orb

.close

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[thorny onyx]

what is supposed to be my v2 and v1? same for t2 and t1

.close

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[night turtle]

help with b) pls

[marsh citrus]

@night turtle Has your question been resolved?

[austere heron]

U mean the Gaussian method right?

[marsh citrus]

@night turtle Has your question been resolved?

[raven olive]

Remind me again what’s the Poisson distribution?

[marsh citrus]

@night turtle Has your question been resolved?

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[safe needle]

e

[marsh citrus]

Please don't occupy multiple help channels.

[safe needle]

.close

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[long cape]

-72 is my best guess but it’s wrong

the entire left side is undefined

any idea how to solve this?

[pallid pine]

maybe x-4 is a factor of the numerator

[static quarry]

the numerator is zero too

[long cape]

Do you mean like this?

[pallid pine]

what?

[long cape]

x-4

[pallid pine]

do you know polynomial long division

[long cape]

oooo

[long cape]

I get this

do I just remove that last term since it's undefined at x=4?

make both piecewise equal, plug in 4, and solve for a?

[pallid pine]

that cant be correct

because the numerator goes to 0 when you put 4 in

there cant be a remainder

[pallid pine]

secondly where tf did the 5 come from

[long cape]

oops

[pallid pine]

it litearlly has to start with 2x^2

[long cape]

my second term is squared not cubed

I think that's correct now

I can plug in (4) for x, make both piecewise equal, and solve for a?

[pallid pine]

yh that should be correct

[pallid pine]

yh

[long cape]

alright i will give that a shot

.close

[marsh citrus]

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[karmic pilot]

It looks like my quiz did not like that I wrote "y =" and thought that was subtraction. Is my answer wrong?

[karmic pilot]

I found the derivative, evaluated it to be 9* sqrt(3). I made that the slope

I then solved y in the formula: y - y1 = m(x-x1)

y-3 = 9*sqrt(3) (x - pi/3)

[mystic minnow]

looks like you entered decimal answers, and it wanted exact answers

[fluid relic]

were you supposed to enter it exactly
things like this usually don't like decimal answers ^
(the exception being of course if it specifically asks for it, or maybe something along the lines of "Estimate...")

theres usually a keypad or whatever on the website to type in math notation

[karmic pilot]

I did not give a decimal answer, my answer is within the red box

This is my answer

This is what it thinks I entered (Notice it thinks I put y - something instead of equals)

[fluid relic]

i mean that still should be the same
it just moved it over to the other side of the equals for some reason

does it say what the correct answer was

[karmic pilot]

No it doesn't, that's why I am asking if it is correct haha.

I could email my professor and tell him I think I got cucked by the system, but I don't want to look like an idiot if my answer is wrong.

I guess technically I shouldn't know the right answer (not that I plan to give it to anyone) but I would like to know if I am wrong before I send an email lol.

I'll show my work in a sec

I think I forgot a +3 now that I did it again.

@fluid relic@mystic minnow So not worth going to my prof probably because it's technically wrong, but other than the + 3 did I do this right? just curious for my own reasons

[mystic minnow]

yes

you could simplify 9root(3)/3 as 3root(3)

[fluid relic]

yeah thats what i came to
you just missed the +3 when calculating the intercept

[fluid relic]

the programs i used weren't too fussy about simplification so long as it was correct
but this is true
try to simplify if you can since you save time typing it in, but if youre faced with something complicated to simplify (but still complete) i wouldn't worry about it unless it asks for the simplest answer @karmic pilot

you can close this by typing .close if finished

[marsh citrus]

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[karmic pilot]

Ok thanks

.close

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[quartz sun]

m-2<-8 or m/8>1

[runic temple]

whats your question

[quartz sun]

it’s to solve compound inequality’s and graph it

teacher didn’t explain it that tell to me

well*

[runic temple]

do you know how to isolate x?

m*

[quartz sun]

nope but on the other half’s it’s also inequalities but i think it’s to do the opposite (?)

so multiply it ?

[runic temple]

sure start with one

what do you get for the one you are talking about

[quartz sun]

it’s 3 other pages that i completed

i’m stuck on compound but for the other ones the way i made the variable alone is by doing the opposite of what it is

so for example m/8 instead of dividing id multiply both sides of it

or is it a different way for compound inequalities

i think i figured it out

m < -6 or m > 8

no solution?

.close

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[jolly sigil]

Is this a legal move in algebra

[jolly sigil]

Since the denom is shared by both sides

[marsh citrus]

@jolly sigil Has your question been resolved?

[jolly sigil]

I've tried multiplying all the way threw too

Now

[leaden solstice]

Yes

[potent shadow]

disagree that cancelling is wack

[jolly sigil]

Oh okay

It didn't work anyway

[jolly sigil]

.close

[marsh citrus]

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[main idol]

show what you're reading that says this

[elfin berry]

xzino

[marsh citrus]

@ivory slate Has your question been resolved?

[marsh citrus]

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[ivory slate]

.close

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[violet cobalt]

I'm trying to graph these two

Equation of the perpendicular line: y=2/3x+4

and

Equation of original line: y=-3/2x+3/2

How do I graph the 1st one when the graph is limited to 5?

I tried inputting this into the system but it said the graph is wrong.

[steel sapphire]

@violet cobalt Try going backwards instead of forwards

[violet cobalt]

I did didn't I? I went down 2 and 3 to the left

[steel sapphire]

Yeah it's correct

[pallid pine]

cant you use desmos?

[steel sapphire]

I think he has to graph as an assignment or smth...

[violet cobalt]

but it still says it's wrong :/

[steel sapphire]

...

[violet cobalt]

it's an online session so nope

it gives me this

but i don't get it lmao

[steel sapphire]

tf

[pallid pine]

lmao

hahaha

wtf

[bright jay]

Your line perpendicular was wrong

[steel sapphire]

how????

[violet cobalt]

the graphing of it? idk. but the equation is correct. the system said it's right

[pallid pine]

yh acc

[bright jay]

The graphing was wrong

[pallid pine]

your perpendicular line

has a gradient

of -1

[bright jay]

Look at the answer given, the actual answer has the line going through x = 1, yours did not

[steel sapphire]

That's such a subtle difference lol

[bright jay]

But it still makes a difference

[violet cobalt]

uhh lemme do another similar example

im lost lmao

This time I did one that can actually fit in the graph but still....

original equation: -3/2x+3/2
perpendicular: 2/3x+3

and it gives me this:

[violet cobalt]

well how do I do this?

[bright jay]

Just count. What does 3/2 mean?

In that equation

[violet cobalt]

it's the y intercept

[bright jay]

And -3/2?

[violet cobalt]

the slope. 3 down and 2 to the right

[bright jay]

So you know the y intercept is 3/2 which is 1.5

[violet cobalt]

yes

[bright jay]

Now go down 3 from that point, what's the new y value there?

[violet cobalt]

-1

wait

[bright jay]

Nope

[violet cobalt]

hmmm

[bright jay]

You start at 1.5 and you go down 3

That can be represented as 1.5 - 3, correct?

[violet cobalt]

ohhh

so y is -1.5

[bright jay]

That's the new y value when you go down 3

Now you need to go right 2

[violet cobalt]

ah I see. thank you. did another example and got it right

.close

[marsh citrus]

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[quartz token]

i know that this is more of a physics question, but in this graph, what would s, m mean?
i know that t, s means time, seconds

[civic blade]

any context?

[quartz token]

oh yeah forgot about that

[civic blade]

position

in meters

[quartz token]

ah

can you help me answer this

[civic blade]

What're you having trouble wit

[quartz token]

this question

[mellow sapphire]

It means distance or displacement

[light frost]

The thing after the comma (m and s) are the units (meters and seconds)
s means position and t means time

[civic blade]

Okay, think about in general what theyu want

[mellow sapphire]

Comes from Latin I think

[civic blade]

those are not the same btw...

[quartz token]

oh god

[mellow sapphire]

Spatium maybe

[nova totem]

s usually refers to position

[quartz token]

so which one would be the correct answer

i kind of want to say that its A

help ;-;

[marsh citrus]

@quartz token Has your question been resolved?

[quartz token]

no lmao

.close

[marsh citrus]

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[twilit ginkgo]

how do i do part b?

do i take moments ?

if so where abouts

my diagram:

[still temple]

kmg should be horizontal right?

You have to equate moments here

[marsh citrus]

@twilit ginkgo Has your question been resolved?

[twilit ginkgo]

ahh

yeah i just saw

how would i equate the moments tho ?

[twilit ginkgo]

<@&286206848099549185>

[marsh citrus]

@twilit ginkgo Has your question been resolved?

[marsh citrus]

@twilit ginkgo Has your question been resolved?

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[hoary wolf]

An SME produces three products, A, B and C, with a benefit of 2, 5 and 3 monetary units, respectively. The firm's annual fixed costs are 15,000 units, and the manufacturing costs of each unit of A, B, and C are 1, 3, and 2 currency units, respectively. The goal for next year is to produce and sell a total of 5,260 units of the three products, obtaining a total benefit of 16,160 monetary units. If the total costs are to be 25060 currency units, how many units of each of the products must be manufactured the following year?

[marsh citrus]

@hoary wolf Has your question been resolved?

[hoary wolf]

<@&286206848099549185>

[hoary wolf]

Someone?

[hoary wolf]

<@&286206848099549185>

[tender verge]

.

[hoary wolf]

Hello!

[uncut gust]

hm? @hoary wolf

[hoary wolf]

Hi!

[uncut gust]

Oh nvm I see it

[hoary wolf]

If you could help me, it would really appreciate it

[uncut gust]

Do you only want the answer ?

[hoary wolf]

If you could explain to me even in a simple way the process, it would be better

[uncut gust]

give me 2 mins

[hoary wolf]

Take your time

[uncut gust]

Let's call the number of units of product A, B, and C that the SME should produce as x, y, and z, respectively.

From the problem statement, we know the following:

Benefit of product A = 2 monetary units
Benefit of product B = 5 monetary units
Benefit of product C = 3 monetary units
Therefore, the total benefit of x units of A, y units of B, and z units of C is:

2x + 5y + 3z

The total benefit for the year is given as 16,160 monetary units. Hence, we have:

2x + 5y + 3z = 16,160

Manufacturing cost of product A = 1 currency unit
Manufacturing cost of product B = 3 currency units
Manufacturing cost of product C = 2 currency units
The total manufacturing cost of x units of A, y units of B, and z units of C is:

x + 3y + 2z

The annual fixed cost is 15,000 currency units.
The total cost for the year is given as 25,060 currency units. Hence, we have:

x + 3y + 2z + 15,000 = 25,060

Simplifying the above equation, we get:

x + 3y + 2z = 10,060

We also know that the SME should produce and sell a total of 5,260 units of the three products. Hence, we have:

x + y + z = 5,260

We now have three equations with three unknowns:

2x + 5y + 3z = 16,160
x + 3y + 2z = 10,060
x + y + z = 5,260

We can solve these equations using any method of our choice, such as substitution or elimination. Here, we will use substitution.

From the third equation, we have:

x = 5,260 - y - z

Substituting this into the first two equations, we get:

2(5,260 - y - z) + 5y + 3z = 16,160
(5,260 - y - z) + 3y + 2z = 10,060

Simplifying the above equations, we get:

y + z = 2,240 (equation 4)
2y + z = 3,440 (equation 5)
Subtracting equation 4 from equation 5, we get:

y = 1,200

Substituting this value of y into equation 4, we get:

z = 1,040

Substituting the values of y and z into equation 3, we get:

x = 3,020

Therefore, the SME should produce 3,020 units of product A, 1,200 units of product B, and 1,040 units of product C to achieve its goals.

(Not mine) lol

[hoary wolf]

Where have you found it?

[uncut gust]

AIA

AI*

Its best for this kinds of problems

[hoary wolf]

Which AI have you used?

[uncut gust]

Secret, but well the AI will get most of the answer wrong.. and you need to double or triple check it xd

(and know what its doing)

[tender verge]

They do 😦

[hoary wolf]

Perfect, so once you have checked it, tell me please

[uncut gust]

Already did it, its... 96 % good

Hopefully

.-.

[hoary wolf]

I have a problem

These are the solutions for each unit

Ignore that it is in spanish

@uncut gust

[uncut gust]

Spenish

Wait

A = 2,060
B = 2,000
C = 1200

@hoary wolf

[hoary wolf]

Why?

Incorrect, it was A=1300
B=840
C=3120

[marsh citrus]

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[vale pumice]

I have two questions.

1. How is an empty set a subset of all sets?
2. Is ∅ an element of all sets? Why or why not?

[green scaffold]

I might miss something but from my understanding a subset has the property that
Lets say we have a set S and a subset T of S
then T is a subset iff
T u S = S
and thats true for the empty set

[marsh peak]

And the answer to the second question is no

Consider A = {1, 2, pi}

Do you see ∅ anywhere in it as an element?

[green scaffold]

And empty set should not be an element of every set.
Lets say S = {1,2,3} then we would need something like S = {1, 2,3 , {} } so that empty set would be an element of S

ye same what A lonely bean said

[vale pumice]

Sorry, I forgot to mention. I'm very new to Discrete Math so I don't really know much about what T u S means.

[marsh peak]

It means the union of T and S

All the elements from T and S collected together into a single set

[green scaffold]

Yeah imagine it like this maybe
S = {1,2,3} and T = {2,3,4}
then S u T = {1,2,3,4}

its not actually a letter u inbetween its supposed to be this symbol

$\cup$

[elfin berry]

barış

[green scaffold]

so in this special case T wouldnt be a subset of S

[still temple]

look at the definition of subset, for all x, x element in A -> x element in B

x cant be an element of the empty set because it has no elements by definition

so the conditional is always true

[green scaffold]

I think that would also require a basic understanding of the implication semantics

could be a bit confusing if you have never dealt with taht

but yeah also a good point

[green scaffold]

if your question is resolved close the channel

[vale pumice]

Will do, thanks! I'll read your responses first. :>

[green scaffold]

alright , dont hesitate to ask if its still unclear

[vale pumice]

Yeah, I don't think I know anything about "implication semantics" yet.

[green scaffold]

I could explain it to you real quick if you wnat to

[vale pumice]

I think I'm starting to get what you mean here.

If I replace T with ∅ in your example, it's like ∅ U S = S.
If S = {1, 2, 3, 4} and I combine it with ∅ , S would still be {1, 2, 3, 4} because ∅ is empty.

I still don't think I get it entirely, though. Like, how does ∅ U S = S being true prove that ∅ is a subset of S? I think I get it in my head, but I can't verbalize it properly, so I don't think I understand it very deeply yet. Hopefully I would as I go further into my studies.

[vale pumice]

Really? I would love to hear about it. Thanks!

[twilit arrow]

x in A u B means x is in A or x is in B

think about how we define an element to be a subset, and how that works with the equality A u B = A

in particular, if A u B = A, then by definition A is a subset of A u B. so x in A implies x is in A or x is in B

[green scaffold]

So I wrote
T is a subset of S iff T u S = S
meaning if and only if.
You could try to prove this for both directions.
Or in short :
If T U S = S then T is a subset of S :
T U S = S means there are no elements in T that are not in S.
So every element in T is in S (if T does not contain any element this is true by default, implication thing, will explain it in a sec)
So in this case T has to be a subset of S

If T U S not = S then T is not a subset of S:
T U S not = S means there has to be an element in T that S does not contain.
So T can certainly not be a subset of S by definition.
(because the empty set has no elements it cant contain any element that S does not contain, it cant hurt the requirement)

I hope this does not confuse you even further, if so then just ignore

I think the main point is
T is a subset of S if and only if T does not contain any element that S does not contain. This would be an alternative defintion

And as mentioned, the empty set can certainly not go against this because it has no elements at all, so als none that are not in S

[marsh citrus]

@vale pumice Has your question been resolved?

[green scaffold]

Sure :
I will try to explain it the way I understood it best so the implication consists of two parts, the premisse and the conclusion. Lets just call them A and B for simplicity.
All the implication requires is that whenver A is a true statement then B must be a true statement too. If A is not true in the first place then the implication doesnt care, it lets you do what you want, its always true.
So A and B dont need to be related. Its just that you cant first state something that is not true and then state something that is true. The implication will in this case rebell and tell you "Hold on it doesnt work like this"
So remember the implication is cool as long as both statements are true ones or A is false.
Example:
Today is sunday -> 3 is an odd number

Both statements are true therefore the implication is content and tell you ok cool 1
If you said :
Today is Monday -> 3 is an even number
then the implication would still be ok with that. A was false already so it doesnt care about B , it says 1

Only time you'll get in trouble is if you say something true and then something false
3 is an odd number -> "a" is a capital letter
that not cool

Also in short :
Whenever you have two statements A and B the implication is fulfilled if either A is not true or B is true and A is also true.
The important point is that A and B dont have to have any relation whatsoever.

So for the Set thing

T is a subset of S if and only if
For every element t in the set T :
t in T -> t in S

so concluding from the semantics of the implication either t is not an element of T , then it will say, "yeah do whatever you want" meaning , t can be in S or not , its irrelevant.
Or t is indeed in T then it must be in S otherwise T would not be a subset of S

and whenever you check for something thats empty or not there the implication is also directly true for the same reason.

I'll stop now, just spend some time thinking about it, if there are certain points that I didnt explain well and you have a question about just ask. Most of the time it also helps to accept things and some time in the future it clicks. Works very often for me

[vale pumice]

Wow, that's a lot! I appreciate your time and effort into writing and explaining.

Unfortunately, it's late where I live and I have to sleep now. I might not be able to digest this right now. I'll come back to this tomorrow, though! Thank you! ❤️

Can this query stay open for any longer or should I close this now?

[green scaffold]

you should close it. Otherwise it will timeout after 30mins.
You can later on look it up by just searching in the search bar or remembering the channel number

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[green scaffold]

timedout already lmao

[vale pumice]

Alright! I'll close it now. Thank you so much and have a nice day! ❤️

.close

[green scaffold]

thakns, you too good night then

[marsh citrus]

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[hybrid flame]

how do i go about this problem

.close

[marsh citrus]

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[proven cairn]

(gonna take me a sec to type everything out so pls bare with)

[proven cairn]

i'm using matlab; above, i've created an array/vector/whatever, and as seen i've given the output of said vector

i need to multiply this vector by a scalar that is a fraction

multiplying it by 2 gives me the following output:

everything works fine, yay

multiplying it by 1/2 gives me this:

?????

i cannot for the life of me figure out why it's doing this

for reference, this is the code:

(multiplied by 2)

(multiplied by 1/2)

i've tried parenthesis, i've tried making it a decimal

neither work

i'm at a loss

that's the end of my question explanation

[hollow veldt]

i dont get this but maybe parenthesis around 1/2 might work like(1/2)

[proven cairn]

^

didn't work

idk y

[hollow veldt]

okk

[marsh citrus]

@proven cairn Has your question been resolved?

[marsh citrus]

@proven cairn Has your question been resolved?

[flat raft]

you should type out a minimal reproducible example

paste code that generates a vector, does operations to it, and then explain why the result is not what you expect

there's always a chance that the issue is not what you think it is

[marsh citrus]

@proven cairn Has your question been resolved?

[marsh citrus]

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[paper herald]

why it is 1/4-h

[main idol]

did you plug $(-4 + h)$ into $f(x)$?

[elfin berry]

riemann

[main idol]

i.e. evaluate $f(-4+h)$

[elfin berry]

riemann

[paper herald]

1/4-h

?

i don't understand why h convert to negative

[main idol]

yes

just missing parentheses

[main idol]

where do they do what you're asking?

there's no h in the image

[paper herald]

imagines y is h

[main idol]

if they get the same answer as you, why does it matter how?

just understand what you're doing

[paper herald]

I know it is evaluated but I don't know why h becomes negative into faction

[main idol]

do you now know how you got 1/(4-h)?

[paper herald]

no

can tell me how

[main idol]

$f(-4+h) = -\frac{1}{-4+h}$

[elfin berry]

riemann

[main idol]

can you get that far ?

[paper herald]

soo thx

.close

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[wispy goblet]

Hello! I'm struggling trying to find a way to preserve a property in a proof.

If x is an even number, is there a way to perform integer division with the divisor >1 and ensure that both the quotient remains even and no information is lost?

[brittle vessel]

what information

[wispy goblet]

Well, the remainder, I suppose. Let's say we have 16 and trying to divide by 3. So you'd get 5. Multiplying by 5, you get 15.

Hmm, I do realize how strange the question sounds. It's for a correctness proof, and I'm not sure if modulo has some property that could be taken advantage of to not lose the remainder

Thanks anyway

.close

[marsh citrus]

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[marsh citrus]

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[cunning echo]

Fuck math

[cobalt sentinel]

Hey if u got a question, post it, otherwise close the channel

[cunning echo]

oki doki schoki mocki

[pallid pine]

with lube?

[cunning echo]

lol

Fortnite for ever

[deft apex]

.close

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[signal comet]

I need to solve the area of the colored area

<@&286206848099549185>

[marsh citrus]

@signal comet Has your question been resolved?

[marsh citrus]

@signal comet Has your question been resolved?

[marsh citrus]

@signal comet Has your question been resolved?

[marsh citrus]

@signal comet Has your question been resolved?

[marsh citrus]

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[stable path]

how come the formula can not be rewritten as

Vf / V i x A

i just did that and did not get 5 seconds for time

[marsh citrus]

@stable path Has your question been resolved?

[nova totem]

My guy addition is not multiplication

A + B ≠ AB

[stable path]

okok thats true

so i could do

vf - a / vi

right?

[ornate ginkgo]

what are you trying to solve for?

[stable path]

wait no i cant, hmmm

[ornate ginkgo]

time?

[stable path]

nah im just trying to brush up on equation rearranging

but yes time

[ornate ginkgo]

then there's not much you can do except what you've shown here

[stable path]

because of the addition sign?

[ornate ginkgo]

yes

[stable path]

ahhh

[ornate ginkgo]

yeah

whenever you see addition, you basically have to think of the entire thing

or like, lump it as one term

[stable path]

ok so what smaller steps did they take when changing the formula

they seem to have skipped a lot of shifting around

because by my current understanding ,i should be able to switch T and Vf without changing the addition

but thats not correct

if it has to remain a LUMP. how does acceleration drop down

[ornate ginkgo]

so

we can create different lumps

[stable path]

ok

[ornate ginkgo]

$v_f = v_i + at \implies v_f - v_i = at$

[elfin berry]

blanket

[ornate ginkgo]

and then we divide by a on both sides to obtain

[stable path]

hmm ok so thats what they moved first

velocity

[ornate ginkgo]

$\frac{v_f - v_i}{a} = t$

[elfin berry]

blanket

[ornate ginkgo]

yep

[stable path]

ok thats all i was wondering, a lot of resources skip the small steps

thank u very much

[ornate ginkgo]

yeah nw

you should look up resources on some basic equation solving/rearranging terms

that sorta stuff gets overlooked because its just algebra

[stable path]

yea i just did that, thought i was good at it

[ornate ginkgo]

but it can get kinda tough when there's lots of confusing terms

[stable path]

i guess i get confused on where the addition sign gets stuck to the whole way through

just to clarify, in ur example

when Vi crosses over

why does it carry the addition sign with it

(that turns to negative)

is the addition sign not attached to AT

[ornate ginkgo]

we are subtracting the quantity v_i from both sides

[stable path]

ahhhhh

[ornate ginkgo]

v_i - v_i is 0

but we now have a subtracted v_i on the left side

[stable path]

so the addition sign is technically still infront of AT

[ornate ginkgo]

so its $v_f - v_i$

[stable path]

just not needed

[elfin berry]

blanket

[ornate ginkgo]

yeah

[stable path]

i see i see

[ornate ginkgo]

when there's no negative sign in front of terms, we assume they're safely positive

[stable path]

lastly

[ornate ginkgo]

for example, we read $1 + 2$ as positive 1 plus a 2

[elfin berry]

blanket

[stable path]

why is Vi minus rather than divided

i would have assumed based on this all that A should have been subtracted instead

[ornate ginkgo]

we perform the operation opposite to what we see

so when we read the right hand side that is "positive v_i plus the quantity of a times t"

so we subtract a positive

and divide the multiplied a

[stable path]

hmm i must have missed that part