help-33

[deft apex]

if you double the number of starting adult cows, you double your final output

[thorn sparrow]

HAHAHAHAHA

oops replied to myself

[deft apex]

and if you change your minutes its exponential

this is gonna be a differential equation isnt it

[thorn sparrow]

yea it's exonential all right, tho i still think using series is our best bet

[deft apex]

two things that can either increase or decrease

[thorn sparrow]

yea you are probably right

[deft apex]

we should say that we always either run it for 4 minutes or start with 2 cows

to make it easy

or we can try including both

[thorn sparrow]

I have a good lead if you want to hear it

it's not perfect

[deft apex]

yes pls

im having fun here

for once

[thorn sparrow]

but it's a start

ok give me a sec

I divided the two lists and the the longer it gets the closer it gets to two

but the longer it gets the less exact two's I get

If we can get an exact formula or suite converting X baby cows to Y adult cows

then we only have one suite

meaning I can solve the recursive equation

[deft apex]

hmm

ill be honest dude, I have absolutely no idea how to even start this type of q

[thorn sparrow]

thats fine tho still thank you for trying, do you have an Idea of to whom I can ask?

[deft apex]

you can ping helpers

they might know where to start

also maybe re posting your q is a good idea because we kind of clogged the channel

[thorn sparrow]

yea good idea

<@&286206848099549185> Lately I have been interested in converting coding problems into mathematical functions, and this is one of them :
You start with X adult cows and 0 baby cows. Once per minute, for every pair of adult cows, one baby cow will be bred. A baby cow takes 2 minutes to become an adult. So with X starting adult cows, how many of them will there be in Y minutes.
With Z being the final number of adult cows, your equation should only be expressed using X, Y and Z as variables. With f(X, Y) = Z

the code is:

[deft apex]

<@&286206848099549185>

[thorn sparrow]

OOps

[deft apex]

[thorn sparrow]

[main idol]

are these ints? just input your sequence of integers to oeis

[thorn sparrow]

oeis?

[main idol]

https://oeis.org/

[thorn sparrow]

ok let me try this

nope

doesn't work

I THINK I FOUND IT!

@deft apex

this might just work

[deft apex]

👀

?

[thorn sparrow]

@deft apex ok I just came back, let me try it out

[thorn sparrow]

.close

[marsh citrus]

Channel closed

Closed by @thorn sparrow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vapid nexus]

was trying to optimise for this using theta = arctan(15/x) - arctan(4/x) as the equation, then solving for x. but this was incorrect

got 15 cuz 15 = (11 + 9) - 4
got 4 cuz 4 = 8 - 4

[marsh citrus]

@vapid nexus Has your question been resolved?

[trim quest]

@vapid nexus your equation looks correct

But read the directions. The first blank is expecting theta as a function of x

Also, I didn't do the calculation so I'm not exactly sure how you got 35.38, but that number suggests you used degrees. You should be using radians

[marsh citrus]

@vapid nexus Has your question been resolved?

[vapid nexus]

derivative of arctan(15/x)-arctan(4/x) = (see image)

i set this equal to zero and got x = 7.74596

then plugged this into arctan(15/x)-arctan(4/x) and got that number

where did i go wrong?

@trim quest

[trim quest]

If you're going to round to five decimal places, the last digit should actually be 7

But, are you sure you're supposed to round it, instead of the exact value?

[vapid nexus]

not sure

[trim quest]

I'd wager you're meant to use exact values. That's usually the case in a math class unless the directions say otherwise

Do you know what the exact value is?

[vapid nexus]

7.74596669241

[trim quest]

That's not exact either

How did you get that?

I mean specifically, just back up one step. What did you do to get that number

[trim quest]

Yeah, 2sqrt(15) is the exact value

Any decimal is approximate

Do you have a way to input square roots?

[vapid nexus]

yes

[trim quest]

Then 2sqrt(15) should work for the bottom one

[vapid nexus]

ok

[trim quest]

Oh yeah, that's right

[vapid nexus]

and was it correct to sub 2*15^.5 in for x

[trim quest]

There's no reason to do that.

That would get you the angle, but that's not what the first blank is asking for

It wants the function in terms of x

[vapid nexus]

oh

incorrect

[trim quest]

Do you have an actual sqrt symbol you can use?

Like do they provide you with symbols like that?

[vapid nexus]

no

but it should be equivalent

[trim quest]

It is but sometimes programs like this aren't that smart

[vapid nexus]

its worked with this before

[trim quest]

oh

damn

it's not 15 and 4

4 feet is the cow's eye level above the ground

[vapid nexus]

so it'd be 19 and 11

[trim quest]

Nah 15 and 7, it's like this

The cow's eyes are 4 feet above the ground, the bottom of the screen is 11 feet above the ground

And the screen is 8 feet tall

[vapid nexus]

oh i c

plugged in the new values, and worked smoothly

thanks for the help

.closse

.close

[marsh citrus]

Channel closed

Closed by @vapid nexus

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

How do i factor this expression

[celest wyvern]

i believe the question is wrong just leave it or recheck the question

[still temple]

no it is right

[celest wyvern]

or change the 24 to 25

[still temple]

wth bro?

[celest wyvern]

which grade are you in?

[still temple]

?????

I need to learn how to do this

this was given to me by the teacher. I can’t leave it out.

[celest wyvern]

u do know how to factorize at all right?

if u can solve the quadratic substitute the x in the general form with k^3

then solving should give you something if any form is fine

[marsh citrus]

@still temple Has your question been resolved?

[still temple]

<@&286206848099549185>

[marsh citrus]

@still temple Has your question been resolved?

[still temple]

<@&286206848099549185>

[still temple]

<@&286206848099549185>

[still temple]

<@&286206848099549185>

[marsh citrus]

@still temple Has your question been resolved?

[still temple]

no

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fleet sierra]

what is the general way of solving these types of (diagonal) determinants?

[devout mauve]

I would try finding a recurrence relation

[fleet sierra]

interesting

but this is material from second semester and i need to solve these without recurrence relation

[devout mauve]

you could try solving the first few by hand and checking if you find a pattern

and in the end, 8 is not that bad, you could do it by hand

with row reducing

[marsh citrus]

@fleet sierra Has your question been resolved?

[fleet sierra]

thanks

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[candid plank]

put 2^x+1

as 2y y being 2^x

then u get 2y=y+16

then isolate and solve for y

[hollow sparrow]

$16 + 2^x = 2^{x+1}\$
$16 = 2^{x+1} - 2^x\$
$16 = 2^x(2 - 1)\$
$16 = 2^x\$

[elfin berry]

MellowDramaLlama

[hollow sparrow]

I think you can get it from there 🙂

[candid plank]

2^x+1=2^x .2

is the same as he did

just i put 2^x as y

how ?

[candid plank]

just isolate y and u get y=16

just the same as llama

[hollow sparrow]

So what he's saying is this:
Let $y = 2^x$. Then $16 + 2^x = 2^{x+1}$ turns into $16 + y = 2y \implies y = 16$. But $y = 2^x$ so $2^x = 16$.

[elfin berry]

MellowDramaLlama

[hollow sparrow]

it's just using substitution to get rid of the 2^x

which sometimes makes it easier to see 🙂

[candid plank]

i cant find the emote i want

😂😂

nvm i got it

[hollow sparrow]

[candid plank]

[marsh citrus]

@untold brook Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

completing the square

[nova totem]

Yeah okay what have you done so far

[still temple]

one sec

sorry I did it with my non. dominant hand

[still temple]

excuse the Messines

I'm wondering do I subtract the two fractions or add them

[ruby marsh]

yh subtract

or u can add but factor -1 out

[marsh citrus]

@still temple Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[spring briar]

hey i need some help with chain rule

[spring briar]

wait nvm

.close

[marsh citrus]

Channel closed

Closed by @spring briar

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[uneven bear]

Why wont I get the lowpoint in sin(bx), with the formula 1/b * 3pi/2 + 2pi* 1/b

[uneven bear]

It isnt the lowPOINT, i know, but it should still give me the x-value. The left side of the plus is the first lowpoint and the right is for the period.

With the k I should be able to decide, which lowpoint I want to get if k is element of Z.

Wait a minute.

.close

[marsh citrus]

Channel closed

Closed by @uneven bear

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[plain notch]

Can anyone help me to solve this equation?

[marsh citrus]

@plain notch Has your question been resolved?

[cobalt sentinel]

Where’s the equation

There’s no equals sign

[marsh citrus]

@plain notch Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pearl zealot]

Need some big help lmao

[unique basin]

Post your question

[pearl zealot]

Im translating it

Nvm it doesnt work somehow but

The questions are

[pliant stream]

Screenshot?

[pearl zealot]

Given is the family of functions fa(x)=3x-a^2*x^3 ( a>0 )
a) Determine the zeros and the extrema of the family depending on a
b) Show that all family functions have a common tangent
t have .
c) determine the locus of high points of the set fa(x)
d) Investigate which family curve fa has a high point with the ordinate y = 4.
e) For which family curve fa applies: The distance from the high point and low point = square root of 5

Its german so yall probably cant read it

[pliant stream]

functions mmmmm

[pearl zealot]

Yep

Cubic function sets

[pliant stream]

I only know a bit

[pearl zealot]

^Well

[pliant stream]

I might be asking this question too yk

[pearl zealot]

lmao

Its fine tho somebdoy hopefully will know something about that topic lmao

[pliant stream]

yeah

[marsh citrus]

@pearl zealot Has your question been resolved?

[marsh citrus]

@pearl zealot Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[spice copper]

I did l'hopital's rule and got e/1. Good?

[eager venture]

yes

[main idol]

,w plot (e^x-e)/log(x) for 0<x<2

[elfin berry]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by riemann#2529

[spice copper]

.close

[marsh citrus]

Channel closed

Closed by @spice copper

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[visual crow]

how did they remove the denominator?

[trim quest]

They just multiplied both sides by both denominators

as in

they multiplied both sides by t(3t^2+100)

[visual crow]

ohh tysm i feel like i should know this but i am so tired rn lol

thanks

[trim quest]

no problem 👍

[visual crow]

.close

[marsh citrus]

Channel closed

Closed by @visual crow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

how do i do this question

[eager venture]

so if $a$ and $b$ are the roots of $f(x) = x^2 - mx + 2$ what does this tell us about how $f(x)$ factors?

[elfin berry]

moonside

[still temple]

uhhh not too sure

[eager venture]

hmm

like if i tell you a polynomial of degree two has roots 1 and 3

can you tell me the polynomial?

[still temple]

yeah

(x -1)(x-3)

[eager venture]

yes

good

now if i tell you a and b are the roots

tell me hte polynomial in terms of a and b

[still temple]

like (x - a)(x - b)

[eager venture]

yes

now foil that out and set it equal to what they tell you the polynomial is

and compare the coefficients

[still temple]

so like x^2 -xb - ab - ax?

[eager venture]

yes can you simplify it a bit more

[still temple]

there arent like terms???

[eager venture]

yes there are

[still temple]

wait hold on

so q = (a + 1/b) (b + 1/a)

so we have ab + 1 + 1 + 1/(ab)

we know that ab = 2

so we have 2 + 1 + 1 + 1/2

4 + 1/2

[eager venture]

yes

[still temple]

so 8/2 + 1/2 = 9/2

[eager venture]

you jumped some steps lol but yeah

[still temple]

wdym

[eager venture]

idk, you went from not understanding how to simplify $(x-a)(x-b) = x^2 -mx + 2$ to solving the problem

[elfin berry]

moonside

[eager venture]

but i guess you only needed that ab = 2

[still temple]

i feel like it was worded overcomplicatedly??

.close

[marsh citrus]

Channel closed

Closed by @flat chasm

Use .reopen if this was a mistake.

[still temple]

.reopen

[marsh citrus]

✅

[still temple]

oh yeah the reason is that

i forgot that the product of 2 roots is -b/ a

so like -b is -m and a is 1

so a + b = m

-m

product of 2 roots is c/a

so 2/1

and then you distributed (a + 1/b) and (b + 1/a)

[eager venture]

uh

[still temple]

and then you blog in your values

plug

.close

[marsh citrus]

Channel closed

Closed by @flat chasm

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[marsh citrus]

@frank breach Has your question been resolved?

[marsh citrus]

@frank breach Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

✅

[marsh citrus]

@frank breach Has your question been resolved?

[marsh citrus]

@frank breach Has your question been resolved?

[marsh citrus]

@frank breach Has your question been resolved?

[marsh citrus]

@frank breach Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

Quick question, but what would you give a geometric interpretation to the pair of equations: $x^2+y^2 = 49, z = x$?

[still temple]

kind of confused on the z = x

[elfin berry]

♡LexQa♡

[still temple]

so it is going to be a circular shape, in the octane z = x

really hard to visualise

but...ellipse?

it cannot have a uniform radius...can it?

oh wait is it like going to be a circle with centre at the origin stretched out diagonally or something?

[still temple]

both of these equations have to be simultaneously true ? or the graphs are to be superimposed

the former

well ig the graph will be of two circles with their planes perpendicular to each other

hm

not sure

apparently the answer is "The ellipse formed by the intersection of the cylinder x^2+y^2=49 and the plane z=x"

not sure how they got to that answer though

oh wait yes that's true

i was imagining x=z to be a line

stupid me

oh dw im still mentally 3 steps behind you with this

and the x^2 + y^2 = 49

will obviously form a cylinder

thought it would be a circle

gotta stay in touch with 3-D

why would it obviously be a cylinder?

because in the x-y plane the eqn will be of a circle but since no info has been given about z therefore the eqn will be true for any value of z the constraints are only on x and y and so you can strech the graph along the y-axis

okay give me a second

visualising 3D is so HARD

so let my ooga booga brain try and understand this, so if we had something of the form x^2+y^2 = 49, z= 3 thats just going to be the plane perpendicular to the z axis at point 3, and it is going to form a circle

now, if you very z with x, meaning z =x, it is not going to be only the plane of z = 3

but multiple planes kind of added up together

because now z can be anything

forget the z=x while visualising the cylinder

i kind of understand why it would be a cylinder

because it is just multiple layers of circles, if u think about it

[still temple]

yes the centre will be (0,0,3)

[still temple]

yes

so that makes sense, but i dont get the ellipse

well we know that since both the equations have to be simultaneously true we'll have to take the common (intersecting) part of both the graphs

intersection point... so the origin?

because z = x is is just some weirdly diagonaled plane and the other is just going to be a cylindar

no it's an ellipse

okay so

i dont really know how to make them simultaneously true in this program

but that looks...funky

also how the hell is that a cylindar haha

you can see the ellipse

it's the common portion

yeah i figured now

3-D diagram yumm

what program is this

i want it

it is math3d.org

just searched like

"3d grapher"

ok thnx

got this

alrighty ty

.close

[marsh citrus]

Channel closed

Closed by @fiery pawn

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[spice sail]

Hi guys I badly need help right now, I didn't get to understand at learn our lesson since I was asleep because i slept late doing so many projects, I'm struggling how do I solve this rational function

[spice sail]

I have examples here but I forgot how sir did it

Lemme show brb

Here

Can someone mind willingly teach me

Please 🙏

[still temple]

what were you ask to do

[still temple]

unclear image

[blazing vortex]

i can help

[spice sail]

Yes please

[spice sail]

We were told to answer

[blazing vortex]

this may sound strange, but i use an analogy to explain this

[spice sail]

This one

[spice sail]

Suree

[blazing vortex]

are you familiar with famous war battles? specifically, the battle at the beach of normandy?

[spice sail]

I'm not oof

But I can listen

[blazing vortex]

d-day, world war 2? it's the opening battle for the movie Saving Private Ryan

[spice sail]

Yes

I did

[blazing vortex]

okdoke, great

so during that battle, the germans had the land, and the allies were attacking from sea. the germans had the domain

they had the beach

[spice sail]

I bet this will sound interesting

[blazing vortex]

the germans had their machine guns and mortars and whatnot as their ranged attacks, trying to take out the allies as the allies tried to land on the beach

[spice sail]

Go on, i can sleep late tonight since it's about me learning the math

Right

[blazing vortex]

well, when you think of the cartesian coordinate, the domain is the left and right directions, like how you'd see a beach. the range is how far you can see or reach

you follow that so far?

[spice sail]

Wait, is the land and the domain are the same?

[blazing vortex]

yep

[spice sail]

Rightt

[blazing vortex]

so we can look to verify the domain of the first question, B(x) in your assignment

[spice sail]

Wait also, you mind telling me what Cartesian coordinate is? Maybe Im familiar with it but not exactly that i know it

[spice sail]

Alright alright

[blazing vortex]

the left and right are the domain, the up and down are the range

[spice sail]

Oh yessss I know that

Righttt go on

[blazing vortex]

ah, ok, sorry, wanted to make sure i wasn't missing anything

[spice sail]

No no it's fine, it's actually cool coz Its way easier to understand

[blazing vortex]

so what i like to do first is find the domain. to do that, we're basically verifying if there are any specific numbers that we might plug in for x that won't give a valid number as output

[spice sail]

output is the domain right?

then range was the input???

Oh wait

[blazing vortex]

the value of the output would be the range

[spice sail]

Oh yess

I forgot that the y intercept depends on the x

[blazing vortex]

it's like putting a mortar shell in and firing it

[spice sail]

Ohhh

[blazing vortex]

you put in the input, and after it's fired and landed, you can see the range

[spice sail]

Ohhh

Yeaaa i get it now

[blazing vortex]

so for the first problem, B(x), the key thing that i like to keep in mind is that we cannot divide by zero

i do that for all problems like this

[spice sail]

right!

[blazing vortex]

we can't even do 0/0

so is there any number that we could plug in for x that would cause us to be dividing by zero?

[spice sail]

1?

Wait

Ohhh

It's 6?

Positive 6?

[spice sail]

oh wait

Yes

Oh wait

12

It's 12?

[blazing vortex]

nice!

[spice sail]

😁

Am I correct????

[blazing vortex]

yep

[spice sail]

EUIRIEKDKK RIGHT

[blazing vortex]

that means that our domain is restricted, 12 is not within our domain

[spice sail]

Because i remember sir saying about the LCD

Right!

Also while we're discussing do you mind helping me like teaching me whole showing how the illustration of the solution looks like?

[blazing vortex]

that's why your notes have the "find the domain" bit

[spice sail]

They turned off the light so I'm gonna just right it here lol and gonna copy it tomorrow

[spice sail]

Right

Oh right! I get it

B(x) = x+12
(-12) (-12)
x = -12?

[spice sail]

Ohh Soo B(x) = x+12
(-12) (-12)
x = -12?

[blazing vortex]

that's how we find where our domain is restricted

you'll see that your notes have something similar:

[spice sail]

Ohh so therefore -12 is the restricted value?

[spice sail]

yeaaa right rightt

{x|x≠-12}?

[blazing vortex]

that bit at the bottom is basically saying that the domain can be any value of x except the restricted value

yep!

[spice sail]

OMG

So are we moving on the finding the y intercept?

[blazing vortex]

if you're ready 🙂

[spice sail]

YEP I AM

[blazing vortex]

ok, remember that cartesian coordinate pic i uploaded?

[spice sail]

Yep

[blazing vortex]

see where the red line passes through the y-axis?

[spice sail]

B(x) = x-6/x+12, let x = 0?

B(0) = 0-6/0+12 ?

[spice sail]

Yep

[blazing vortex]

yep! i was going to say, you may notice that where the red line passes through the y-axis, x is equal to zero

[spice sail]

Ohhh

[blazing vortex]

this is how you find the y-intercept. you just plug in 0 for x

[spice sail]

Ohhhhhh

OMG

It's so cool that what you're teaching me is what I actually can somehow understand 😁

Alsoo what's next about the 0-6/0+12?

[blazing vortex]

you're doing the hard part, the learning 🙂 it's good effort!

[spice sail]

Also about the 0-6 do I have to put like parenthesis?

[spice sail]

Thanks! 😁

[spice sail]

Oh rightt

[blazing vortex]

can you see how we can simplify this fraction?

[spice sail]

6/12?

[blazing vortex]

yep!

[spice sail]

😁

[blazing vortex]

and we can even simplify it further

[spice sail]

Hmm

I suck at turning something into a mixed fraction

3/14?

3/14*?

[blazing vortex]

it's not a mixed fraction, don't worry

[spice sail]

3/4*?

Oh

[blazing vortex]

is there a number that can go into 6 and also go into 12?

[spice sail]

3?

Or 2.

?*

3/6?

[blazing vortex]

that works, yeah. but you can simplify it even further 🙂

[spice sail]

X_X

[blazing vortex]

what number goes into both 3 and 6?

[spice sail]

12?

Or 6?

[blazing vortex]

naw, but here, it may help if i provide a visual way to see it

[spice sail]

Alright

[blazing vortex]

see how that makes sense?

[spice sail]

Oh it's a negative

[blazing vortex]

or, actually, a better way might be:

[spice sail]

2x2x3=12?

I get it :D

[spice sail]

I prefer this one 😁

[blazing vortex]

lol, okdoke

[spice sail]

Sooo 0-6/0+12 = -6/12 = - 2x3/2x2x3

[blazing vortex]

negative sign, but yeah

[spice sail]

Oh right

[blazing vortex]

but here we can reduce the fraction

[spice sail]

Alrightt

[blazing vortex]

see how there's a 2 in the numerator and a 2 in the denominator?

[spice sail]

LCD?

Is it because of their LCD?

Or?

[blazing vortex]

LCD is lowest common denominator, which is something different, but i think you're thinking the right idea, just using the wrong words

[spice sail]

Ohhh

I forgot what it's called

[blazing vortex]

since there's a 2 in both the numerator and a 2 in the denominator, we can just cross each one of those out:

[spice sail]

3/6??

[blazing vortex]

you may notice that this means we can also do this with the 3 in the numerator and the 3 in the denominator

[spice sail]

Yee

[blazing vortex]

so we do it with those

[spice sail]

Ohhhhh

Wait I'm a bit confused kskdkskxkd

[spice sail]

OH

1/2????

[blazing vortex]

negative sign 🙂

[spice sail]

-1/2*

😅

[blazing vortex]

yep! and remember that graph i posted above, with the red line?

[spice sail]

After the -1/1x2 do i have to put -1/2 at last or i can turn it -1/2 immediately instead of -1/1x2?

[spice sail]

Yeaa

[blazing vortex]

you can just turn it to -1/2

[spice sail]

Alrighttt

[blazing vortex]

if you look at where the red line crosses the y-axis of that graph, what is the value of y?

[spice sail]

KSKKSKDKSKKDKEKDJ I'm so happy I managed to understand lol

[spice sail]

Wait lemme check again

1/2?

[blazing vortex]

negative sign 🙂

[spice sail]

0 1/2 1 1 1/2 2

-1/2

[blazing vortex]

yep!

[spice sail]

😅😅

AHAHKGAJGLGAGAPJGAU

OMG

[blazing vortex]

you wanna try the g(x) in your assignment?

[spice sail]

Alsoo about this one, if LCD was not the right name, do you mind telling me what is it?

[blazing vortex]

greatest common factor

[spice sail]

So that i could easily explain it to my classmates because, I'm gonna try answering it at the board

OH RIGHT

[blazing vortex]

it's the largest number that can go into each number

[spice sail]

Gcf

Righttt

OMG

Now for the other one, I'm gonna do it but can you check if I was right?

[blazing vortex]

i'd love to 🙂

[spice sail]

OMG

Alright

Lemme look at it again skkfkdkd

Okay Soo there's g(x) = x-2/2x+1

2x+1
(-2) (-2)
x=-2?

Am I right that -2 is the restriction?

[blazing vortex]

i'm afraid not, but it's okay

[spice sail]

Actually, I'm still a bit confused how did they solved it

[blazing vortex]

so in this case, the denominator is what?

[spice sail]

2x+1

[blazing vortex]

and we want to get x by itself, so that we can see what x is equal to, yeah?

[spice sail]

Can you also tell me how did they manage to solve like what was in my notes?

0 rifht

I forgot

Is it 0?

2x+1 = 0

[blazing vortex]

that's the right first step 🙂

[spice sail]

Ohh right

[blazing vortex]

so what can we do now?

[spice sail]

Then (-2) and (-2)?

[blazing vortex]

what do you mean, "Then (-2) and (-2)"?

[spice sail]

To be honest im confused how did they solve that in that arrow arrow thing in my notes

[blazing vortex]

it's okay, i can explain what they did

[spice sail]

I'm referring to my notes 😅

[spice sail]

Yes please

[blazing vortex]

i'll use the problem in your notes to explain it

[spice sail]

Alrightt

I'll be waiting 😁

[spice sail]

Wait

Soo in the current problem that i am going to solve, i subtract 1 with the (-2)?

[blazing vortex]

in the notes, the (-5) and (-5) is where the person was subtracting 5 from both sides

[spice sail]

Yea

Since my problem is 2x+1, because of the 2 is positive so I'm gonna turn it into negative right?

[spice sail]

Ah yesyes

[blazing vortex]

so in your case, what number are we going to subtract from both sides?

[spice sail]

2x+1
(-2)(-2)

[blazing vortex]

nope

[spice sail]

Aw

2 -2? 1-2?

[blazing vortex]

the 2 is "attached" to the x

[spice sail]

2x-2*

[blazing vortex]

just like the 3 is "attached" to the x in the notes

[spice sail]

Sooo

[blazing vortex]

but what isn't attached to the x?

[spice sail]

Ohh

Wait

I forgot cancelling out

[spice sail]

1

[blazing vortex]

yep, just like the 5 isn't attached to the x in the problem in the notes

[spice sail]

I subtract 2x-2 right Soo it's gonna be only x

[blazing vortex]

nope

[spice sail]

Aw

But am I right that the number I subtract is 2?

[blazing vortex]

in the notes, we basically "moved" the 5 over to the other side, yeah?

[blazing vortex]

i'm afraid not

[spice sail]

Wait lemme check

Awss

That's why

What should be the number?

Is it -1?

-2 and -1?

[blazing vortex]

we're moving the number that isn't attached to the x to the other side

[spice sail]

2x+1 = 0

Wait

Please don't be mad but I'm confused 😵

[blazing vortex]

no worries 🙂

[spice sail]

I'm still confused x_x

I'm trying to understand the arrow arrow thing

[blazing vortex]

in the 3x + 5 = 0, which number isn't attached to the x?

[spice sail]

5

[blazing vortex]

yep!

[spice sail]

Where do we move it??

[blazing vortex]

so let's move that to the other side. to do that, we subtract it from both sides

[spice sail]

Oh

[spice sail]

3x+5=0
(-5)(-5)?

Soo I'm gonna left the 3x?

+5-5 = 0

0-5 = -5

[blazing vortex]

notice that it was a positive 5 on the left, yeah? so we have to do the opposite function, therefore, subtracting it from both sides

yep!

[spice sail]

Righttt

[spice sail]

Ohhhhh

Wait so in my case

2x+1-1=0-1 ?

[blazing vortex]

perfect!

[spice sail]

2x=-1????

[blazing vortex]

excellent work 🙂

[spice sail]

OMG

Lol sorry that took time for me to understand

[blazing vortex]

no worries at all, i've done this before, i had to learn it once, too

[spice sail]

Aleightt

Oh

Alright sooo

[blazing vortex]

so now we want to get that x by itself still, yeah?

[spice sail]

Oh right

[spice sail]

Wait

Oh ye

[blazing vortex]

but there's a 3 attached to it

[spice sail]

What am I gonna do next?

[blazing vortex]

the function that's happening between the 3 and the x is multiplication, yeah?

[spice sail]

Yea

[blazing vortex]

it's "3 times x is equal to -5"

[spice sail]

Yee

[blazing vortex]

so we need to do the "opposite" of multiplication with that 3

what's the reverse of multiplication?

[spice sail]

Ohh sooo that's when I start the
(-2) (-2) in my case?

Or still wrong?

[spice sail]

Subtract?

[blazing vortex]

yeah, still not quite right

naw, the reverse of multiplication is division

[spice sail]

Ohhhhh right

I suck at division

😵

[blazing vortex]

one way to get better!

[spice sail]

Let me know dkkdkdkkd

[blazing vortex]

lol, to practice

[spice sail]

Right right MMDMDKKDKDKS

I just kept forgotting it

Alright soo

What are we gonna do now?

We're gonna use division??

[blazing vortex]

yep

and we're trying to get move what number?

[spice sail]

2x?

-1*?

[blazing vortex]

are you guessing?

[spice sail]

I mean -1

[blazing vortex]

guessing isn't effort 😉

[spice sail]

😅

Was it the -1?

Like, lately we moved it right,

Then it becomes 2x=-1

Oh

Are we gonna move 2x?

To make it like 2x-1?

Am I still wrong?

[blazing vortex]

one sec, in a meeting

[spice sail]

Oh sorry sure sure take your time

I think I slowly get it

2x=-1 = 2x/2 = -1/2 ?

2x/2 = x

-1/2 = 1?

{x|x≠1}?

[blazing vortex]

you had it right up to here

[blazing vortex]

this is where you made your mistake

[spice sail]

Ohhhhh it's correct??

Aw

what should it be?

Do i divide it to 1?

[spice sail]

OHHH

It's still 1/2

[blazing vortex]

not just 1/2

[spice sail]

• 1/2

Ohhh I was wrong because of the sign????

Was i close??? 😁

[blazing vortex]

yep!

[spice sail]

ALRIGHT so therefore, {x|x≠-½}

[blazing vortex]

negative sign

[spice sail]

AH I FORGOT

FDKGDGDGDHLDDDH

Now for the y Intercept, g(x)= x-2/2x+1, let x = 0

Soo 0-2/2(0)+1?

[blazing vortex]

yep!

be right back, gotta bring some paperwork to another office

[spice sail]

Alright! OMG I'm sorry for disturbing you

Now for the y Intercept, g(x)= x-2/2x+1, let x = 0

Soo 0-2/2(0)+1 = 2/2+1 = 2/3?

Or 2/2? Or 2/4?

Which one is correct?

You seem to be busy x_x i guess this will end here

[blazing vortex]

sorry, ya, at work, this is what i do for a hobby when i'm not busy

[spice sail]

OH NO IT'S NP lol

SGGKGKGSSGKSSGI

[spice sail]

OMG, You still tryna help me even when you're busy

Thank you very much!

This will all end here now, thank you so much really! Now i need to sleep lol it's already 12:44 am, önce again thank you!

And also! I hope you'll have a great day! Like always!

Cya!

[blazing vortex]

have a great day!

[marsh citrus]

@spice sail Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[smoky marsh]

can someone help me find polar form of (1+sqrt(3)i)^10

[smoky marsh]

so first we get R=2 and tan o=sqrt(3) or o = pi/3

[still temple]

R=2^10

[smoky marsh]

1024

wait, i got a question

[still temple]

(1024)e^(ipi/3)

[smoky marsh]

to find the angle, we say tano= sqrt(3)/1 which is sqrt(3) but how do we get pi/3 from that

[still temple]

bruh trigonometry

[smoky marsh]

bruh im dumb as hell, gimme bread crumbs

im staring at the unit circle

[still temple]

what is sin(pi/3)

[smoky marsh]

sqrt(3)/2

[still temple]

not like what is but do you know how do you get that

[smoky marsh]

no I dont really remember learning that but i might be forgetting.

[still temple]

what is sinx

what does sinx signify

[smoky marsh]

opp/hypo

[still temple]

yes

i hope you know pi/3 = 60 in degrees

[smoky marsh]

yea i get that

but I guess my question is why is tan sqrt(3)/1 = pi/3. i know that tan is sinx/cosx but i feel like im missing something

[still temple]

tan(pi/3) is sqrt(3)

[smoky marsh]

so is it just memorization

if so how do you recommend memorizing it

[smoky marsh]

thats a neat picture, just gotta burn it into my mind

[still temple]

@smoky marsh
https://www.youtube.com/watch?v=zfUs6iV455o
watch this video before it

[still temple]

and remember tanx = sinx/cosx , you will only be required to remember sinx and cosx values the rest would take seconds to figure out if you know the identities

[smoky marsh]

alright much thanks!

.close

[marsh citrus]

Channel closed

Closed by @smoky marsh

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[kindred void]

Hello, very general question that I want to confirm.

[kindred void]

Let A = the set of x where f_1(x) > c, let B = the set of x where f_2(x) > c, A - B = A interset B complement, what would thislook like?

ultimately im trying to get that f_1(x) > f_2(x)

idk if subtracting the two sets would be the way to go

[sleek lake]

how is this a general question

[kindred void]

?

[sleek lake]

it doesn't matter just, it's a regular question I was expecting something "general"

[kindred void]

sorry for the confusion then

i just dont know that the correct operation would be

[still temple]

$\begin{aligned}A=\left{ x,f_{1}\left( x\right) >C\right} ;B=\left{ x,f_{2}\left( x\right) >C\right} \ A-B=A\cap \overline{B}=A\backslash B\ A\cap \overline{B}=\left{ x,f_{1}\left( x\right) >C ,and, f_{2}\left( x\right) \leq C\right} \end{aligned}$

[elfin berry]

Zamarus

[still temple]

So it's interesting if f1 is always >c and f2 always <=c for other cases we don't know if f1>f2

If the set is empty then f2>f1 so maybe it's better to consider B-A and check if it's empty for f1>f2 but it doesn't looks like a good idea in the first place

[marsh citrus]

@kindred void Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[oak bough]

Can i have some help with this

[deft apex]

c looks pretty tasty to me

[oak bough]

reallu

why is that then

i would appreciate an elaboration lol

[deft apex]

so negative gradient on f(x) translates to under the graph for f'(x) to me, and it will approach the same thingy majigy

[oak bough]

okok

nice

[deft apex]

im unclear on it myself

would be good for someone else to have an input

[oak bough]

ikr

[deft apex]

red is f(x) , blue is f'(x)

[lavish crescent]

Help please 🥺🥺🥺

[oak bough]

dude

[deft apex]

you see how positive f(x) gradient means above the graph

right

also stationary points become roots

so

[oak bough]

dude this is my chat

[oak bough]

ok

[deft apex]

so thats why I think C

[oak bough]

k

interesting

just reposting for someone else

<@&286206848099549185> can you help me please

[marsh citrus]

@oak bough Has your question been resolved?

[oak bough]

<@&286206848099549185> please help me on this

[marsh citrus]

@oak bough Has your question been resolved?

[marsh citrus]

@oak bough Has your question been resolved?

[still temple]

at this point the gradient is negative, because it is going down

[oak bough]

K

[still temple]

that means the asnwer has to be C or D, they are the only two graphs with negative gradients at that point

[oak bough]

Ok

Or D?

[still temple]

yes sorry

C or D

[oak bough]

K

But its y = -1/x so its C

Not D

[still temple]

at this point the slop is going up, therefore the gradient must be positive

[still temple]

correct

i mean i dont think the graph is actually -1/x

but youre right that the answer is C

[oak bough]

Its similar tho

I think

[still temple]

yeah i get what you mean

[oak bough]

Yh

[still temple]

at that region its similar enough that the graident would work the same

[oak bough]

Ok

Can you explain the last part above the positive x axis

[still temple]

this region?

[oak bough]

Yea

[still temple]

the graph value is increasing, so the gradient must be positive, at the gradient is slowly getting steeper, so the gradient must be getting larger

[oak bough]

Ah ok

[still temple]

As a general rule, if the graph is going down its a negative gradient and if its going up its a positive gradient, and the steeper the graph the larger the gradient would be (think rise over run)

[oak bough]

Tysm for that tip

[still temple]

all good :)

[marsh citrus]

@oak bough Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[median aspen]

Event = ✅ or ❌
Outcomes = 10
Example:
✅❌❌✅✅❌✅✅✅❌ [Fail]
✅✅✅✅✅✅✅✅✅✅ [Win]

The probabilities of win are:

1/(10^2) also 1/100
or?
10/2

and i want to get it in percentage so

[median aspen]

"and i want to get it in percentage so":

%0.01
or?
%5

[marsh citrus]

@median aspen Has your question been resolved?

[marsh citrus]

@median aspen Has your question been resolved?

[main idol]

percentage = 100 * probability

[marsh citrus]

@median aspen Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bitter crystal]

"A car is worth 180000 and drops by 12% each year" how would you graph this?

[bitter crystal]

Norwegian numbers so the value of the car might be bit weird to you

[still temple]

It's a linear function

[bitter crystal]

It's supposed to be an exponential

[still temple]

Oh it compounds ig

[sleek lake]

it's exponential

[still temple]

Makes sense

[bitter crystal]

Any suggestions?

[still temple]

I would think something like 180000(1-3/25)^t

Just graph it as any exponential decay Function with intercept at 180000 ig

[bitter crystal]

ok, thanks. Seems right!

.close

[marsh citrus]

Channel closed

Closed by @bitter crystal

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quiet quartz]

How did they get this answer? did they Divide? Multiply? Subtract? add?

[bleak reef]

just isolate a

multiply and divide

is what they did

[molten smelt]

yes

they just did basic multiplication and division to isolate a (make it the new subject)

@quiet quartz do you understand now?

[quiet quartz]

Like this?

[quiet quartz]

Do i Multiply the Sin20?

[quiet quartz]

Am i doing it correctly?

[molten smelt]

let me see

remember you want to have the a on top of the fraction

[bleak reef]

no

[molten smelt]

you want a/1

[bleak reef]

you divided by sin 20 on the left side, and multipliedon the right side

you have to do the same thing to both sides to keep the equality

[molten smelt]

yes

so you'd have to divide by sin20 on both sides@quiet quartz

do it correct and show me

[quiet quartz]

if this is correct, then how come the answer has the denominator and numerator reversed?

Am i wrong?

.close

[marsh citrus]

Channel closed

Closed by @quiet quartz

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tired ore]

Hello, i have trouble with a geometry problem about areas, it is known that BD/CD=CE/EA, I am to prove that Area[EPDC]=Area[ABP]

[dry spindle]

all i can really think of is you just do a lot of similarities between triangles

then derive their area factor as k²

then play with the areas

id probsbly need some paper for this

[marsh citrus]

@tired ore Has your question been resolved?

[tired ore]

I cant find any similar triangles without adding new segments and that seems to make it more complicated

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fickle sable]

How can I solve #17

[fickle sable]

I took the derivative and got -1, but im not sure what to do after that

[still temple]

you also have to check the endpoints because the function does not have a derivative at those points

[fickle sable]

What do you mean how do I check that

[wise jackal]

plug in -1 and 2 into the equation

and you'll have your abs max and min

[fickle sable]

Ok

Thanks

.close

[marsh citrus]

Channel closed

Closed by @fickle sable

Use .reopen if this was a mistake.

[still temple]

Can someone help

@wise jackal

Can u help with parallelograms

[wise jackal]

you have to create your own help channel

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[limber void]

whats wrong with using n = 2k + 1 for any n integer n adding it twice

since an odd is usually represent by 2k + 1 for e.g.

why is there k n l here?

[sage gale]

you wanna show it holds for any odd integers. if you just add n to itself it doesnt necessarily hold for all odd numbers

[twin girder]

Meaning if you use the same letter, say k for both integers

They are the same integer

You can’t have say 3= 2 * k+1 and 5 = 2 * k+1

k can’t be 1 and 2 at the same time

[marsh citrus]

@limber void Has your question been resolved?

[limber void]

oh right thanks

how doi know when to use contra+ or contradiction in a proof q?

or can i use any types of proof?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thick elk]

NightHorn — Today at 22:20
Q. Sets of data are summarised by the information given. For each set of information find the standard deviation.
a) i) Σ(x - x̄)^2 = 42.9 n = 10

[thick elk]

I have no clue where to start any help is parriciated

.close

[marsh citrus]

Channel closed

Closed by @thick elk

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[solar nimbus]

A mouse wheel is 16cm in diameter and the base of the wheel is 2cm off the ground. If the hamster spins the wheel 4 times each second, determine the cosine function that describes the movement of the wheel if it starts at lowest point

[solar nimbus]

Anyone please

Been working on this for a week now

Seems like no one knows the answer or how to solve it

[fallen galleon]

well

uhhhh

[marsh citrus]

@solar nimbus Has your question been resolved?

[solar nimbus]

Anyone know?