help-33

[still temple]

the relationship of what

[spark berry]

OF THE FUNCTION

[spark berry]

WHAT OTHER RELATIONSHIP DO YOU THINK OTHERWISE?

[still temple]

x and y valuess show the relationship of the function

this is what ur saying?

[spark berry]

YES

[still temple]

HOW DOES THAT EVEN MAKE SENSE

WTF

https://tenor.com/view/oh-my-god-karen-sistas-s4e8-omg-gif-25581197

[spark berry]

For example
X=1, and y=1, what do you think is the relationship between the two?

[still temple]

they both equal 1

[spark berry]

x=2, and y=2

x=3, and y = 3

[still temple]

they both erqual 2

and 3

[spark berry]

So they do have a 1 to 1 ratio

so it's x=y

[still temple]

yes

yes

so what are you trying to tell me

[spark berry]

That you can able to see what function are we using using only the x and y values

[still temple]

YES EXACTLT

i know that

function= relation

ok so f(x)=y

x=1

y=2

f(1)=2

what the hel

so f=2

[spark berry]

Yes

YES

https://tenor.com/view/josuke-gif-26373957

[still temple]

isnt that emma watson

[hollow sparrow]

whoah lmao

[still temple]

ok ill try to understand what u just said

[spark berry]

Yes woah, isn't that just josuke?

[still temple]

relation=output

[spark berry]

Nah, output and input shows the relation

[still temple]

i will write down

why

f(x)=y

[spark berry]

If you have both of those, then you can see the relationship

[still temple]

f(x)= function

y=output

functin= relation

output=relation

[spark berry]

This isn't the function. It's the output also
It would only be a function if there's an equation to the other side
We just call it function of x

f(x) = x -> function

[still temple]

DUDE

[spark berry]

f(x) -> output

[still temple]

WHY DO U KEEP CAHNGING UR ABNSWER

A FEW MINUTES AGO

U TOLD ME F(X)= FUNCTION

[spark berry]

I JUST TOLD YOU EARLIER THAT F(X) IS JUST WHAT WE CALL THE FUNCTION OF X

NOT F(X) = FUNCTION

[still temple]

BEFORE THAT

[spark berry]

SEE

[still temple]

NONO

[spark berry]

LOOK AT THE TIME

[still temple]

ur only getting the ones that say that

[spark berry]

O I forgor we have different time

[nova crescent]

Brahs function is just a machine that gobbles up a values and spits out y values

[still temple]

yes

so the relation

[spark berry]

YES THAT WHAT I SAID EARLIER

[still temple]

and the rewlation

is a equation

[spark berry]

https://tenor.com/view/crying-meme-black-guy-cries-sad-man-thank-god-for-my-reefer-hood-news-gif-24902056

[still temple]

and this guy is telling me that y values is a realtion

relation

[nova crescent]

yeah f(x) is notation for a function

[still temple]

https://tenor.com/view/crying-meme-black-guy-cries-sad-man-thank-god-for-my-reefer-hood-news-gif-24902056

[spark berry]

I NEVER SAID THAT

[still temple]

wtf is a notatio

[still temple]

https://tenor.com/view/stop-the-cap-stop-the-cap-gif-touge-fivem-hashiriya-gif-25151780

[spark berry]

I SAID THAT Y AND X VALUES SHOWS THE RELATION

[nova crescent]

Y value is relation because y is a variable just like x and they are related to each other. For example y = x is a relationship that means y and x are equal

[still temple]

the relation of functions

[spark berry]

You even get it at first

[nova crescent]

Like the way you write something

[spark berry]

LIKE I THOUGHT YOU UNDERSTOOD

[still temple]

so x=2 y =-123232923832

x = y

[spark berry]

BRUH

[nova crescent]

F(x) can often be interpreted as y, but in some cases y can only be described as having a relationship with x, but not a function

[still temple]

I WAS JUST COPYING U

THATS WHYTEHEERE IS A QUESTION MARK

[nova crescent]

Bro what are you smoking guys

I need some of that

[still temple]

ok

so f(x)

is a function

yes?

[nova crescent]

Yes

[still temple]

so function = y values

[nova crescent]

Ye

[still temple]

y=2

function=2

[nova crescent]

Could also be z values, a valued, any other variable values

[nova crescent]

Well the y value of the function is 2, you don't just say function = 2

[still temple]

i dont even know what u are saying anymore

[nova crescent]

Hm

[still temple]

my brain is so fogged up rn

[nova crescent]

I think it's useless to be so strict on the difference between y and f(x)

[still temple]

cause of this guy @spark berry

[nova crescent]

You can just view them as the same thing and in years you will see the difference

[still temple]

so would that mean

[nova crescent]

Before that I doubt school will teach you anything weird

[still temple]

x values are also a function

[nova crescent]

Well

Functions have inputs and outputs. If you're inputting y and outputting x that's possible. To write the function you would write f(y) instead of f(x) since the variable you're inputting is y now, not x

The thing in the parenthesis is just the input of the function

But normally school will only give y values as the output and x as input

It's just the standard

It could be anything tho

[still temple]

hmm

[nova crescent]

Your variables can be a and b

Doesn't matter it's just a notation

[still temple]

ok so

f(x)

and x =1

= f of 1 or f(1)

does that mean y=1?

wait

no

[nova crescent]

f(1) yes

Orally you would say f of 1

[still temple]

no

that wouldnt make sense

[nova crescent]

Well you haven't defined what the function is yet but if the function was f(x) =x AKA y = x, if x is 1 then y is indeed 1

[still temple]

i think imma just take a little break then come back and read what u guys said currently i dont think my brain can process anymore information

[nova crescent]

If it were y=2x AKA f(x) = 2x, your y value at x= 1 would be 2. You would denote that as f(1) = 2

[still temple]

tysm @spark berry and @nova crescent luv u guys for helping me :)

.close

[marsh citrus]

Channel closed

Closed by @covert crypt

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jolly nebula]

How to get the percentage error?

[still temple]

$\frac{|Experimental-Theoretical|}{|Theoretical|}*100$

[elfin berry]

miky

[jolly nebula]

How can i tell whats experimental and theoretical, sorry getting percent error is new to me

[still temple]

the experimental is the calculated value, the theoretical is the known value (not sure though trying my best to remember)

[jolly nebula]

So based on my given table, the gcal is the experimental while the -9.8 is the theoretical?

[still temple]

from what I understand yeah

[jolly nebula]

Alright thanks

[marsh citrus]

@jolly nebula Has your question been resolved?

[marsh citrus]

@jolly nebula Has your question been resolved?

[marsh citrus]

@jolly nebula Has your question been resolved?

[marsh citrus]

Channel closed

Closed by @jolly nebula

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thin bison]

Hello

[elfin berry]

Basudev

[thin bison]

How is this??

I don't see any way that I can simply

[elfin berry]

Basudev

[stoic saddle]

n! = n * (n-1) * (n-2)!

[thin bison]

Yes

[stoic saddle]

so

$\frac{n \cdot (n-1) \cdot (n-2)!}{2! \cdot (n-2)!}$

[elfin berry]

Ann

[thin bison]

Oh

Thanksn

Got it

.close

[marsh citrus]

Channel closed

Closed by @thin bison

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

Anyone know how to do this?

[marsh citrus]

@still temple Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vivid axle]

Been stuck on this question for a solid 3 days now. Tried using the hint in order to get some sort of log odds to help out with getting the answer...still not entirely sure on how I'd even do it.
3rd year university, Machine Learning, Discriminant Analysis + Bayes Theorem

Anyone able to help me out with this hellish question?
I've managed to get some form of log odds but it doesn't look like I could rearrange it to get the form they've requested in the question.

[vivid axle]

Glad to see someone reacted to this

[placid oak]

you're welcome!

im most sure nobody would help you here

you can try the data science server

[vivid axle]

I'll have a look and hope

[placid oak]

[solid echo]

Show your log odds.

[vivid axle]

Will do
It's pretty messy (and I'm not brilliant at ML so be warned)

This is as far as I’ve got. Feel free to pick through everything and…yeah

[solid echo]

I'm not brilliant either, but I'm telling you to show your work, which will attract more attention to your question

Are you labelling the first term as $\theta_n$?

[elfin berry]

草w

[solid echo]

You want the whole thing as $\theta_0, \dots, \theta_n$

[elfin berry]

草w

[vivid axle]

I thought the first term would be able to get me thetan but there's no x in that term. So in the second image I've converted to use the whole term, combined into just thetan where it's the sum from j = 1 to n of thetaj

[solid echo]

The terms corresponding to independence of $x$ is $\theta_0$

[elfin berry]

草w

[vivid axle]

That makes sense

Mostly from linear regression which we did a fair amount, not all terms have x in them but all but one do. As shown as well with the sigmoid function.
Still wondering how I'd go from what I've got to get the sigmoid which is the main thing confusing me

[marsh citrus]

@vivid axle Has your question been resolved?

[marsh citrus]

@vivid axle Has your question been resolved?

[vivid axle]

<@&286206848099549185>
And of you guys able to assist me?

[marsh citrus]

@vivid axle Has your question been resolved?

[marsh citrus]

@vivid axle Has your question been resolved?

[pale rune]

I Need Help With This

[worthy trellis]

#❓how-to-get-help

[marsh citrus]

@vivid axle Has your question been resolved?

[plush condor]

When I understand it right you have to look at these points, imagine there is a coordinate system and you've learned that no y in a function has two different x points

[pale rune]

Thanks

[still breach]

i’m handicapped

i can’t move my penis

it’s a condition

[vivid axle]

Yes I’m still in need of some help with this question.
Please nobody else just but in and post their own question or random comment.

[shadow relic]

last one

[pale rune]

.close

[shadow relic]

You have (6,5) and (6,-9)

[vivid axle]

Come on guys. Get in a separate channel. Or look in #❓how-to-get-help

[marsh citrus]

@vivid axle Has your question been resolved?

[rough owl]

i calculated i^2, j^2, k^2, ijk but i dont know what to do next

[rough owl]

<@&286206848099549185>

[gentle sierra]

#❓how-to-get-help

[gentle sierra]

post this in #linear-algebra

[rough owl]

Alri

[marsh citrus]

@vivid axle Has your question been resolved?

[olive timber]

i onder

[still temple]

hi

[marsh citrus]

@vivid axle Has your question been resolved?

[lapis cosmos]

so calculate the general form for q

then test the answers to see which is the inverse

ill have paper in a few min

[frail summit]

can someone help me?

[stiff bear]

@frail summit for what

[hollow kettle]

.close

[vivid axle]

.close

[marsh citrus]

Channel closed

Closed by @vivid axle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[drifting crown]

can anyone help me with the statistics problem

[stoic saddle]

sigma is not 1.2

sigma is unknown

it's the z-score of this particular can you grabbed that is 1.2

[drifting crown]

but it says standard deviation is 1.2

why can’t we use it as sigma

[stoic saddle]

no,

it says

A randomly selected can [...] is 1.2 standard deviations above the mean.

[drifting crown]

i got it

so sigma is 1.67

How can I know the percent xxx

[drifting crown]

Oh

so i search the table A

0.8849

then 1 minus it？

[stoic saddle]

you do not need to know the value of sigma.

you want to know the percentage of values with z-score 1.2 or above

[warped wind]

Anything above 1 standard devatiation from the mean is approx 13.6% + 2.1% + 0.1% ≈ 15.8%. Then because it's 1.2 standard deviation it's a little bit less than this

[stoic saddle]

1 minus this, yes.

[drifting crown]

got it

thanks

and i was also confused with this question

Why D is not right

@stoic saddle 😭

[stoic saddle]

"lower pulse rates than 3/4 of the women" refers to values below the bottom of the box in the women's column

and that doesn't cover half of the men

[marsh citrus]

@drifting crown Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wary bluff]

I was j wonderin but if u have a function (f(x))/(g(x)) and u want the derivative. Instead of quotient rule couldnt u use the extended power rule aswell?

[wary bluff]

so like move g(x) up with and turn the power negative

[devout mauve]

And then product rule, yes

[bleak ibex]

yes, if you don't forget to use the chain rule

and product rule

[devout mauve]

That is how the quotient rule is derived

[wary bluff]

ohh

I see

bet ty

.close

[marsh citrus]

Channel closed

Closed by @wary bluff

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

sin3x+sin(2x+pi/3)=0

i can do 3x+2x+pi/3=0 ?

[twilit arrow]

yes

[still temple]

@twilit arrowthe answer is -pi/15 ?

[twilit arrow]

i don’t believe it’ll give you all solutions though

that’s one solution

[still temple]

how i can get the solution with npi

@twilit arrowhey

[twilit arrow]

i’m not sure

[still temple]

sure of what

[twilit arrow]

how to find all solutions

[still temple]

i have the answer on my werkbook but i dont know how to get it the answer is 2kpi/15 @twilit arrow

wait

.close

[marsh citrus]

Channel closed

Closed by @astral gazelle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gray shale]

when we have sin(arcisin(x)) = ...
we have to verify that x€[-pi/2; pi/2]

but when it's tan(arctan(x)) = ... we don't need to verify an angle right?

[wet zenith]

Huh?

That does not look right

[fallen galleon]

what

sin(arcsin?

[sweet pawn]

,w range of arctan(x

[elfin berry]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Mr. Gamer#6658

[wet zenith]

sin(arcsin(x)), x would be in [-1,1]

But x has to satisfy the arcsin domain

[gray shale]

tan(arctan

[fallen galleon]

damn Mr gamer is truly a gamer

[wet zenith]

tan(arctan(x)), here x can be anything, but i dont understand your question

[sweet pawn]

x can be any real, but its arctangent only returns angles of the right half of the circle

I hope that clears things up

[wet zenith]

tan(arctan(x)) just be simplified to x, same for sin(arcsin(x)), provided that x satisfy the original domain

[gray shale]

no i mean for instance you have to verify that arcsin(2x) - arcsin(xsqrt((3)) = arcsin(x)
then you apply the sin function but since sin is 2pi periodic you have to verify that inside the sin it's between -pi/2 and pi/2

so my question was what the angle when we apply tan

[marsh citrus]

@gray shale Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timber python]

I'm very confused when it comes to JK flip-flop
How can i solve this

[marsh citrus]

@timber python Has your question been resolved?

[timber python]

no

[marsh citrus]

@timber python Has your question been resolved?

[timber python]

<@&286206848099549185>

[marsh citrus]

@timber python Has your question been resolved?

[marsh citrus]

@timber python Has your question been resolved?

[marsh citrus]

@timber python Has your question been resolved?

[silk vector]

Trial and Error. Check if Q=1 satisfies the circuit. If it does not, check 0.

[marsh citrus]

@timber python Has your question been resolved?

[vague vector]

.close

[marsh citrus]

Channel closed

Closed by @vague vector

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[signal ferry]

If U1 = 1 and U2 = 2 and U(n+1) - 2Un + U(n-1) = 1. find U1000 the 1000th term of the sequence .

[signal ferry]

Hey guys which one is the correct answer U1000 = 499501 or U1000 = 1000?

[marsh citrus]

@signal ferry Has your question been resolved?

[wooden oriole]

$$u_{n+1}-2 u_{n}+u_{n-1}=1 \implies (u_{n+1}-u_n)-(u_n-u_{n-1})=1$$

[elfin berry]

秋水

[wooden oriole]

so ${ u_n-u_{n-1}}$ is an arithmetic sequence with common difference $1$, and $u_2- u_1=1$, so $u_n - u_{n-1}=n-1$

[elfin berry]

秋水

[wooden oriole]

$$\begin{aligned}
u_{1000} &= (u_{1000}-u_{999})+(u_{999}-u_{998})+\dots+(u_2-u_1)+u_1\
&=999+998+\dots+1+1 \
& = \frac{1000 \times 999}{2}+1\
& = 499501
\end{aligned}$$

[elfin berry]

秋水

[marsh citrus]

@signal ferry Has your question been resolved?

Channel closed

Closed by @signal ferry

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[boreal summit]

how would i go about solving this?

[devout hatch]

so it is saying x is not a negative number

and that x is smaller than 2 pi

[boreal summit]

how do i begin solving it with this info?

[devout hatch]

just punch it into a calc

no way to do it mentally

x is 0

[boreal summit]

bruh what really

no offense but that cant be right

what have i been learning this whole time 😭

[devout hatch]

x is 0

100%

[wooden oriole]

$$\sin x+\cos x=\sqrt{2}\sin(x+\frac{\pi}{4})$$

[elfin berry]

秋水

[devout hatch]

sin 0 is 0

cos 0 is one

[boreal summit]

i found that x=0, but looking at the answers says that there are 2 other answers, pi/2 and 2pi

[devout hatch]

nono

it says x is = or greater than 0

and less than 2 pi

[boreal summit]

wait am i like actually dumb

lemme check again

i put in cos(0) + sin(0) into my calculator and it comes out as 1

so like yeah x=0

but how did they get the other values?

[devout hatch]

its jsut saying that

0 is the answer

[boreal summit]

im getting so confused rn

[devout hatch]

same

[boreal summit]

so 0 is one of the answers?

[devout hatch]

0 is the only answer

[boreal summit]

💀

[wooden oriole]

the answer is x=0,pi/2,2pi

[boreal summit]

but how

[devout hatch]

WDYM

[boreal summit]

i dont get how

[wooden oriole]

$$$$\sin x+\cos x=\sqrt{2}\sin(x+\frac{\pi}{4})=1$$

[elfin berry]

秋水
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[wooden oriole]

so $\sin(x+\frac{\pi}{4}) = \frac{1}{\sqrt{2}}$, and $x+\frac{\pi}{4} \in [\frac{\pi}{4}, \frac{9 \pi}{4}]$

[elfin berry]

秋水

[boreal summit]

how did you get the root2sin thing?

[devout hatch]

i gtg now

a

[wooden oriole]

so $x+\frac{\pi}{4} = \frac{\pi}{4}, \frac{5 \pi}{4}, \frac{9 \pi}{4}$

[elfin berry]

秋水

[wooden oriole]

https://math.stackexchange.com/questions/4197929/prove-that-sinx-cos-x-sqrt2-sin-leftx-frac-pi4-right

[boreal summit]

could you walk me through this question?

@wooden oriole

[wooden oriole]

$$2 \sin x+3\cos x = \sqrt{13}(x+\arctan \frac{3}{2})$$

[elfin berry]

秋水

[boreal summit]

HOW

wait maybe i remember

hold on

ok where did arctan 3/2 come from?

i get the root 13 part tho

[wooden oriole]

https://en.wikibooks.org/wiki/Trigonometry/Simplifying_a_sin(x)_%2B_b_cos(x)

[marsh citrus]

@boreal summit Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

How would I find the maximum point for this equation?

[still temple]

where e is euler’s number btw

[marble glacier]

honestly plug in a really big and really small number

[still temple]

Wdym?

I have it graphed and can find the point that way but I need the process

[marble glacier]

Plug in a massive number

but thats literally how i would do it

[still temple]

Alr I’ll try

[wind wadi]

You basically have the function f(t) = A(1 - e^(-6t)) - Bt where A & B are constants.
You can find the max by finding critical points using the derivative

[still temple]

Yeah that makes more sense thank you I understand now

I don’t know how to mark as solved lol

.close

[marsh citrus]

Channel closed

Closed by @azure dome

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn veldt]

How should i work out d and e?

[still temple]

first of all

whats 8% of 20,000

[torn veldt]

so 10% is 2000 minus 1% twice which is - 400, so its 1600

is that an okay way to work it out?

[torpid anvil]

Do you have a calculator

[torn veldt]

Well yeah

[torpid anvil]

Use that

[torn veldt]

What should i do on the calculator?

[torpid anvil]

Find what 8% of 20000 is

Or actually forget tha

Just type 20000(1.08)^x until you reach somewhere near 30000

[torn veldt]

so 6 times then its above 30k

[torpid anvil]

Yeah

[torn veldt]

So should i just write 20000*(1.08)^6 power as my working out

[torpid anvil]

Write after six years

Or just six years

[torn veldt]

Okay and for question e?

[torpid anvil]

Bruh

I literally just gave you the equation

[torn veldt]

Ooh okay i think i understand thanks

[torpid anvil]

👍

[torn veldt]

.close

[marsh citrus]

Channel closed

Closed by @torn veldt

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[upper gust]

does every exponential function eventually outscale every linear function

[upper gust]

if the exponent is bigger than 1

[spark otter]

Are you thinking of |exp(a)| > |a| ? depends on the norm you choose

It is generally false as well, just look at an example over the real numbers with a = -1

[spark otter]

this will be false

[wind wadi]

i think they mean linear functions with degree 1 and a > 1

such as a^x > kx + b for x->inf

[marsh citrus]

@upper gust Has your question been resolved?

[upper gust]

my question is if
lim x-> to inf
(e^x)/ax with a > 0 goes to infinity

and

lim x-> to inf
ax/e^x with a > 0 goes to 0

or in other words if every exponential function as x approaches infinity will surpass every increasing linear function

sry wasnt clear enough

.close

[marsh citrus]

Channel closed

Closed by @upper gust

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fringe prairie]

The quadratic equation ax² + bx + a =0 with b>2a>0 has

(A) two equal roots;
(B) two roots that are opposite each other;
(C) two roots that are inverse to each other;
(D) two roots with opposite sign and different absolute value;
(E) no real roots.

[still temple]

Well, to see what it would be, let's try and set a, and b to two numbers that satisfy the inequality

So assume we have b = 5 and a = 2

This would give you 5 > 4 > 0 for the inequality

Now knowing that, can you substitute those values into the Discriminant of a quadratic and see what it would get you?

[fringe prairie]

i think i know the outcome now

[fringe prairie]

D= 9

[still temple]

right, this should tell u what the answer should be

[fringe prairie]

yeah its C

can u help me with another question if u want to?

[still temple]

I have a class right this second but good luck !

[fringe prairie]

alr ty for the help

.close

.close

[marsh citrus]

Channel closed

Closed by @fringe prairie

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[brazen oriole]

Hi there i need some help with the following question: Given isosceles trapezoid.
Given that: the smallest base is 3 cm, the largest base is 9 cm, and
The stems are 5 cm

[brazen oriole]

1. I need to find the hight of the isosceles trapezoid

2. I need to find the space of it

I know that the angles of the biggest base are congruent

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

@tacit fjord

[tacit fjord]

1. #❓how-to-get-help and the bot message is clear. Don't spam ping helpers - max every 15 mins

2. wtf are u pinging me for

[brazen oriole]

By Accident sorry

Sorry

.close

[marsh citrus]

Channel closed

Closed by @brazen oriole

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fluid river]

I have:

M = {{0, {1}, 2}, {{1}, 2, 3}, {{1}, 2, {3, 4}}}
N = {{0,{1}},{{1},2,3},{1,{3,4}},{{1},2}}

What is ∪{M,N} and ∩{M,N}

[marsh citrus]

@fluid river Has your question been resolved?

[marsh citrus]

@fluid river Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[languid elm]

Hi, I was wondering on how to solve this paticular part of this trignometry question

[languid elm]

I know that I have to convert from tan(-120) to cot

but how do i do so#

[teal arch]

Tan(-x)=-tan x

The use tan (90+theta) formula to convert to cot theta

Put in the value and voila

[marsh citrus]

@languid elm Has your question been resolved?

Channel closed

Closed by @languid elm

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[unkempt osprey]

does this work

[unkempt osprey]

I've found the slope -3/(2^9) at x = 16, but having difficulty finding tangent

[high pine]

slope is ok

now just use equation of the tangent line

y = m(x-x1) + y1

[unkempt osprey]

So far I have $$y = -3/(2^9) * (x - 16) + 1/8$$

[high pine]

correct, simplify and you're done

[unkempt osprey]

I get the wrong answer

[proper zodiac]

lost the minus on slope

[high pine]

aaaa, actually

[elfin berry]

studying lang calculus

[unkempt osprey]

$$-\frac{3}{2^9}x + \frac{3}{2^5} + \frac{1}{2^3}$$

[proper zodiac]

16=2^4

[unkempt osprey]

oh lol

[elfin berry]

studying lang calculus

[unkempt osprey]

That was the issue

thanks @high pine@proper zodiac

.close

[marsh citrus]

Channel closed

Closed by @unkempt osprey

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

is this right?

[unkempt osprey]

Is the red line y = x - 1?

[distant peak]

of course no

[unkempt osprey]

So he's just asking for question b) only

[still temple]

y = 7-x

[still temple]

yes

[unkempt osprey]

If you draw y = x - 1 it might help

[worthy trellis]

They aren’t showing their work. That’s just the question

[still temple]

yh i did but i put in those co ordinates n it said im wrong

am i ? vuz i think im right

[unkempt osprey]

ah okay

[marsh citrus]

@still temple Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[manic widget]

the function: F(x) = the integral of f(x,t)dt, can someone give me an example where F(x) is non continuous

[manic widget]

but defined

[crystal lintel]

question feels a little unclear

but sorry i gtg anyway actually

[manic widget]

whats unclear?

its parametric integrals

[manic widget]

alright

[tardy bluff]

yo some one help me

some who know what thales euclid and pythagoras did

[marsh citrus]

@manic widget Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine chasm]

Im so lost help please :)

[leaden minnow]

so for part a, its just asking which image shows the locus of points (also known as the set of points) such that they are 6cm away from Q or less
do you have a guess for what the answer might be?

[alpine chasm]

b?

[leaden minnow]

yup

because anything outside of that green circle would be more than 6cm away from Q

[alpine chasm]

i see but i dont really get how the colours correlate

[leaden minnow]

the green is what the problem refers to as the shaded region
so the green is whatever satisfies the condition in the problem, which in this case was being less than 6cm away from point Q

that means that every point in that shaded green circle is less than 6cm away from Q

once you enter the non shaded region (in this case white), your condition is no longer satisfied

[alpine chasm]

right so would question b be a?

[leaden minnow]

this one asks for all points closer to P than Q
if A is the answer, then your claim is all the points in the green circle are closer to P than to Q, which is true
BUTTTT there are other points that satisfy the condition that lie outside of the green circle that are closer to P than to Q so answer A is not quite right

for example consider the right corner of A, the points in that area are closer to P than to Q, but they are not in the green shaded region

[alpine chasm]

im so lost im srry

[leaden minnow]

its okie, its a bit hard to explain over text since this is so visual
let me see if i can show you it another way

[alpine chasm]

ok thank you

[leaden minnow]

okay, look at A where ive drawn a red point and a blue point

so for part b we want the locus of points that are closer to P than to Q

now the question is, does the red point satisfy that locus (aka is the red point closer to P than to Q)

[alpine chasm]

yes p is closer than q

[leaden minnow]

yes 🙂

now the next question is, does the blue point satisfy that locus (aka is the blue point closer to P than to Q)

[alpine chasm]

no its further from p than q

[leaden minnow]

good 🙂

okay now the question is, what region will have points where the points are closer to P than to Q?

so think about all the different red points i could draw where theyd be closer to P than to Q

(that will give you your answer because it will be one of the answer choices)

here ive drawn some more red and blue points to help you see it better

as you can see, all the red points are closer to P than to Q

while all the red points are NOT closer to P than to Q

so if i painted every possible red and blue point, which answer choice would that look like?

[alpine chasm]

im not too sure im still really confused

i thought i understood then i got lost

[leaden minnow]

hmm, how about you try part c and then come back to part b

[alpine chasm]

would that be d? im just guessing.

[leaden minnow]

no not quite, because you have points in the green region that are NOT more than 6cm from P

for example, some points near P are less than 6cm from P

[alpine chasm]

ill just ask my teacher tmrw to help me with this i think its better in real life srry for wasting your time

[leaden minnow]

its alright, hopefully youll understand it with your teacher

[alpine chasm]

ok ty

.close

[marsh citrus]

Channel closed

Closed by @alpine chasm

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[minor yew]

Not sure how to solve this, I’m assuming initial velocity isn’t 0 for this then?

[marsh citrus]

@minor yew Has your question been resolved?

Channel closed

Closed by @minor yew

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lofty shoal]

can someone please explain the question?

<@&286206848099549185>

[marsh citrus]

@lofty shoal Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[halcyon trail]

.close

[marsh citrus]

Channel closed

Closed by @halcyon trail

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[median rose]

idk how to begin doing this

[desert dirge]

if theyre perpendicular then the gradients are negative reciprocals of eachother

so m1 = -1/m2

[median rose]

oh

i get it now thank you

.close

[marsh citrus]

Channel closed

Closed by @median rose

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[agile tree]

hi

[agile tree]

i need help

for this question

do i 6-12

or 6+12

because

i subtracted the y to make it one variable

then i did 4-2

2x

[glacial hedge]

That's not how signs work

[agile tree]

?

[glacial hedge]

You subtract -2x

[agile tree]

yes

[glacial hedge]

So it's actually adding 2x

[agile tree]

because i multiplied it by -1?

[glacial hedge]

Because - negative = + positive

[agile tree]

ok

[glacial hedge]

Yes

[agile tree]

so 9i would 6-12

right

[glacial hedge]

0 = 6x - 6 yes

[marsh citrus]

@agile tree Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

Need help

[still temple]

Need some help with double integrals and polar coordinates, I think I have written in the right way but i don't get the correct result:

,rotate

[still temple]

Should be 2 I think

.

[marsh citrus]

@still temple Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

Anyone?

[still temple]

.reopen

Pretty sure this is simple and I'm not seeing what's wrong...

[marsh citrus]

@still temple Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[north lily]

hello, i want to solve the equation d(x,y) =< d(x,z) +d(z,y) could you help me please ?

[north lily]

i tried to appear what is d(x,z) + d(z,y) but i don't know how to expose it

[marsh citrus]

@north lily Has your question been resolved?

[north lily]

<@&286206848099549185>

[north lily]

<@&286206848099549185>

[marsh citrus]

@north lily Has your question been resolved?

[marsh citrus]

@north lily Has your question been resolved?

[north lily]

.CLOSE

.close

[marsh citrus]

Channel closed

Closed by @north lily

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

is correct?

[mystic minnow]

no

why'd you chnage back to x after integrating and then use the bounds for u?

[still temple]

int of 1 is x

or not?

[mystic minnow]

after you've substituted and changed the variables to u, the integral of 1 is u

[still temple]

integral of 1 is u?

how?

[mystic minnow]

your variable is u

so when you integrate 1, you get your variable, u

you're integrating with respect to u

[still temple]

you meaning this part?

[mystic minnow]

yes

[still temple]

i stil dont get it

[mystic minnow]

$\int 1\ du = u$\
$\int 1\ dx = x$ \
$\int 1\ dv = v$

[elfin berry]

Zybikron

[mystic minnow]

+C

[still temple]

oh

you are right

[mystic minnow]

once you have changed all of your variables over to u, you are integrating with respect to u
so the integral of 1 is u

[still temple]

something like this

@mystic minnow

in this, i should take x as u or sen(2x)

or instead, do integration by parts

[mystic minnow]

you still changed your bounds again. The 0,2 bound is on u, the 0,1 bound is on x

[still temple]

you mean this?

.close

[marsh citrus]

Channel closed

Closed by @mortal peak

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fading echo]

How do I figure out the 3 bigger solutions

Forgot how

[high pine]

basically it's sin(x) = 0.92
hence
x = arcsin(0.92) + 2πn or x = π - arcsin(0.92) + 2πn

manipulate with value of n to get next three solutions

and next solution won't be 2 btw

[fading echo]

Nani..

So can you show me how it isn't 2 @high pine

Still kinda confused

[high pine]

let n = 0
then:
x = arcsin(0.92) (solution provided in the sheet) or x = π - arcsin(0.92)

,w π - arcsin(0.92)

[elfin berry]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Modus#7591

[high pine]

it's close to 2, but it's not 2

[fading echo]

Oh ok

Thanks

So to get the next bigger number what would I do?

[high pine]

let n = 1 and check

[fading echo]

Ok

Thanks

What about the next smaller solution

[high pine]

smaller that x = arcsin(0.92) ?

let n = -1 basically

[fading echo]

Oh ok lmao

Thanks

[marsh citrus]

@fading echo Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fresh oriole]

back at this cus it makes no sense

answer please

[spice verge]

You have similar triangles

TVS and UVR

Use the ratio of side lengths that you know and call UV x

Or whatever variable you like

@fresh oriole does this help at all?

[fresh oriole]

everything did until i had to do ratio sides

[spice verge]

So basically due to having similar triangles their sides have a common ratio that changes the side length from one of the triangles to the other

[fresh oriole]

right yeah

so like 4 will go into 2?

[spice verge]

No

4 goes to 6

For the side you know

[fresh oriole]

OHH

OKAY i get it now

[spice verge]

Nice

[fresh oriole]

thank u thank uuu

.close

[marsh citrus]

Channel closed

Closed by @fresh oriole

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still temple]

confused

[earnest kettle]

what are you confused about?

[still temple]

when u do the substitution, r u changing the equation?

how do u use the oddness and evenness so to speak

i dont get the process, where do they change the limit from x to u

how do they go back to du to dx

dont u needa resubstitute

what's the point then

[earnest kettle]

the point is to cancel out both sides

in an odd function f(x) = - f(-x)

so the area cancel out

the area on the right cancels with area on the left side

this image is kinda bad

[still temple]

i get that it cancels out

but

couldnt u do this to any func and take it out this way

does subbing in u=-x change the expression itself

[earnest kettle]

it does not change

the integral is the same

but instead of being integrated by x, is integrated by u

[still temple]

?

how does it use the property of odd-ness

[earnest kettle]

what do you mean?

[still temple]

f(-x)=-f(x)

but at what point do they put a -

how does the substitution make use of the property

[earnest kettle]

see the second line

[still temple]

what am i supposed to see blood

[earnest kettle]

f(-u(x)) = -f(u(x))

[still temple]

i see

i get it now

thx

oops lol

can i ask another q

[earnest kettle]

sure

[still temple]

how do u decide the limits here

why is it -1 to -2 now

[earnest kettle]

lower limit: u(a) = 0
upper limit: u(b) = 3

[high pine]

look on the right

[earnest kettle]

then find a and b

[still temple]

nah look

at how it's +-1 and +-2

• OR -

that's what's trippy to me

[earnest kettle]

a is either 1 or -1
and b is either 2 or -2

but sqrt(x² -1) says that x²-1 >= 0
x² >= 1
x>= 1 or x <= -1

[still temple]

where does the correspondence for b come from then

like

-1 and -2

not -1 and 2

[earnest kettle]

x cannot be between -1 and 1

so the integral from -1 to 2 cannot exist

[still temple]

oooh that's smort

thank u

[marsh citrus]

@still temple Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fallen stump]

calculator recomondstions?

[lunar tree]

what is your intended major or what classes are you planning on taking

?

[fallen stump]

i’m only in hs i’m taking calc next sem

[lunar tree]

I would look into finding a calculator that

• can make a graph (so you can graph functions)

• and has an ability to solve finite integrals (so that you can check your answers)

so that would be the TI-83 or TI-84

I would strongly recommend you to get a used calculator and then clean it up.

The best calculator from Texas Instruments is the TI-Nspire (there are multiple models with differing features)

I got a used one for a steal of $70 at a Pawn Shop. So I would look at local places to see if someone is selling a calculator

[marsh citrus]

@fallen stump Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hexed rain]

Hi, am converting a equation of the parabola into vertex form

[hexed rain]

Wondering if this looks correct so far

I have to relearn that factoring method which is why I didn't finish lol

[raven bear]

complete the square

you make the expression into a perfect square

of the form

a^2 + 2ab + b^2

[hexed rain]

is it correct so far though?

[raven bear]

so you can factor it into (a+b)^2

[hexed rain]

yeah, I just have to look up how to factor with that 2x^2

I'm used to just X^2

[raven bear]

you can divide by 2 as well

[hexed rain]

I can simplify that before factoring?

how does that rule work?

actually nvm

but good to know

here so far

am trying to find a number that works atm

I don't think there is one..

<@&286206848099549185>

.close

[marsh citrus]

Channel closed

Closed by @hexed rain

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stone merlin]

how 😦

[trim quest]

What did you do for the first one?

[stone merlin]

guessed im ngl

[trim quest]

Critical numbers are values of t that make h'(t)=0

So, take the derivative, then find where it's equal to 0

[stone merlin]

gachu

i dont know how to factor it

once i get to the first derivative @trim quest

[trim quest]

What'd you get for the derivative?

[stone merlin]

3/4t^-1/4-1.5t^-3/4

[trim quest]

Maybe it would help if we made a substitution?

like a = t^-1/4

if we let $a=t^{-\frac{1}{4}}$, then we have $\frac{3}{4}a-\frac{3}{2}a^3 = 0$

[elfin berry]

tatpoj

[stone merlin]

im stuck now

so basically

3/4(3/4+3/2)?

[trim quest]

?

Hang on, let's try something else

[trim quest]

This is good

$\frac{3}{4}t^{-\frac{1}{4}} - \frac{3}{2}t^{-\frac{3}{4}}=0$

[elfin berry]

tatpoj

[trim quest]

This is what you want to solve

You can get rid of the negative exponents by multiplying both sides by t^(3/4)

[stone merlin]

uh

ok

so

3/4t-3/2t=0

ye?

[marsh citrus]

@stone merlin Has your question been resolved?

[marsh citrus]

@stone merlin Has your question been resolved?

[marsh citrus]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[marsh citrus]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frail zenith]

would this be the same as e^1 = (x+3/2x+1)

[mystic minnow]

yes

[frail zenith]

thanks

.close

[marsh citrus]

Channel closed

Closed by @frail zenith

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thorn sparrow]

Lately I have been interested in converting coding problems into mathematical functions, and this is one of them :
You start with X adult cows and 0 baby cows. Once per minute, for every pair of adult cows, one baby cow will be bred. A baby cow takes 2 minutes to become an adult. So with X starting adult cows, how many of them will there be in Y minutes.
With Z being the final number of adult cows, your equation should only be expressed using X, Y and Z as variables. With f(X, Y) = Z

[thorn sparrow]

the code is

The first thing I taught of is using series

and i'm stuck on that right now

[marsh citrus]

@thorn sparrow Has your question been resolved?

[marsh citrus]

@thorn sparrow Has your question been resolved?

[young owl]

Idk if append is what you want here
I would do something like that:
babycow is a vector [a, b] where a is the number of baby cow born the minute before and b the number of babycow born this minute
then at each minute, adultcows += babycow[0]
babycow[0] = babycow[1]
babycow[1] = int(adultcows/2)

[deft apex]

did u work out an expected total adult cow value for 4 minutes and starting with 2 adult cows?

Im getting a logic error of 5 total adults by the end when I think it should be 4

[thorn sparrow]

guys give me a minute to read before I respond I usually do this in french

[deft apex]

ja habite eccosse

[thorn sparrow]

hahaha

[deft apex]

did that work

[thorn sparrow]

bien essaye

[young owl]

j'ai vécu en France

[thorn sparrow]

you were close

you would have to say :

[deft apex]

ohhh merdeeee

[thorn sparrow]

j'habie en écosse

[deft apex]

jai adore le fromage

[thorn sparrow]

that works

it mean i liked the cheese

tho it's written like this: j'ai adoré le fromage

ok let me read the reply

[thorn sparrow]

that would work too but i kept adding it so I could print the progression of numbers

[deft apex]

wait

I might have it

omg

this works for my specific set case

not tried it with any other numbers

def cowCalc(x,y) :
  minutes = x 
  adult_cows = y
  newbabies = [[] , []]


  for minute in range(minutes) :
    newbabies[0].append(adult_cows//2)
    newbabies[1].append(minute)
    print(newbabies[0])
    print(newbabies[1])

    for x in range(len(newbabies[0])) :
        if len(newbabies[0]) > 2 :
            if newbabies[1][x] == newbabies[1][minute-2] :
                newbabies[0][minute] -= newbabies[1][x]
                adult_cows += newbabies[0][minute-2]
                
        else : 
            pass

  return adult_cows
    
print(cowCalc(4,2))

it returns 4 adults

which is what my flow chart got

[thorn sparrow]

you're kinda losing me with your code tho lets start with the problem you mentioned

[thorn sparrow]

what did you mean by that

i have no errors running my code

[deft apex]

noo I was coding mine from scratch

I was speaking about mine, don't think I was tracking the values correctly

uses a 2D array to track the amount of new babies and the minute they were born at

[thorn sparrow]

ahh ok so your keeping track of the results If i understand

[deft apex]

oui

[thorn sparrow]

ok well this is what i get

[deft apex]

if we track the minute they are born at we can compare it

if newbabies[1][x] == newbabies[1][minute-2] :

this is the age checker

x is looping through the entire array of values

and seeing if its 2 minutes old yet

and if it is it adds it and removes it from the total of babies

[thorn sparrow]

i get this

[deft apex]

what are the params?

[thorn sparrow]

calling this minecraftCowConundrum(2, 15)

[deft apex]

ok

so 15 minutes as 2 starting cows

can you try 2 starting cows and 4 minutes

to see what you get

ah ok

I have logic error in my code still

[thorn sparrow]

it'll be the same list but shorter

[deft apex]

oh I see what you're doing

[thorn sparrow]

2 starting cows and 4 minutes

the baby array is on top

[deft apex]

yep

nice

[thorn sparrow]

and the adult one is on the bottom

[deft apex]

you should do a flow chart of like 2 adults and 5 minutes and see if it matches your code

[thorn sparrow]

i'm trying to find a relation to convert this into a math equation

[deft apex]

emm

hmm

[thorn sparrow]

I thought about using series

[deft apex]

I would start with a table of values

[thorn sparrow]

but the thing is i'm using 2 right now if you think about it

my end goal once I find the solution to this is to be able to apply it to eaven bigger functions

[deft apex]

ok im getting somewhere

[thorn sparrow]

Really!?