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I’m confused as to how they get the geometric sequence
are you confused on how they concluded it was a geometric sequence or the (1/(1- 1/10^k))?
How they concluded the recurring part can be factored into the two things
@ivory laurel Has your question been resolved?
oops, sorry, i was afk for a while...
if you still need the answer:
terribly sorry :(
@ivory laurel Has your question been resolved?
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hi
can anyone help
post question
ok
wait
i. 135 and 225
ii. 196 and 38220
iii. 867 and 255
tell
Show your work
Your work? Your progress along with where you are stuck?
ok
so deol you can see, from the question 225 is greater than 135. Therefore, by Euclid’s division algorithm, we have,
225 = 135 × 1 + 90
Now, remainder 90 ≠ 0, thus again using division lemma for 90, we get,
135 = 90 × 1 + 45
Again, 45 ≠ 0, repeating the above step for 45, we get,
90 = 45 × 2 + 0
The remainder is now zero, so our method stops here. Since, in the last step, the divisor is 45, therefore, HCF (225,135) = HCF (135, 90) = HCF (90, 45) = 45.
Hence, the HCF of 225 and 135 is 45.
is my answer correct??
i want to just confirm
It’s correct
lets gooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo
thanksssssssssssssssssssssssssssssss
That was so elaborate lol
deolllllllll
Ye?
Lol
He is from Pakistan
okkkkkkkkkkkkkkk
sharukh
You
Lol how so?
ok
I am Indian
India lost today lol
bro i am in 10th
yes
Thanks to Dinesh Karthik
HEHE?
6 runs 15 ball
?
Why not sunny?
euclid is nub'
Lmao close the channel if you’re done
i need to read his algrothim everyday
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ok
Everyday?
@worthy trellis are you married?
It’s not even in the cbse syllabus?
?
hey
It’s not
ch-1 real numbers
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1st question is that
wtf
Deleted portion I think
ok
This is Ariana grande 💀

HUH
Pure is from India

Gujarat
Is there a reason this channel still open lmao?
Main bhi bhartiya
lmao
for a fuking math question
ok
How you feel India lost
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Bro
not good
What r u in about
Pure is from gujurat
ok ok
Mera Naam mery hai
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Grade 9 maths but I need help here
@late valley Has your question been resolved?
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✅
.
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This is not solvable 🥲
Remember the discriminant
And now you can go through a few cases. b can be 0 to 5 and then that gives you only a few options for a,c
If you don't count 0 as a natural number then it can be 1 to 5
(I'm not saying that 1 actually works. Just that it is a case to consider)
Yeah right so if b is 1.. a and c will have to be 0 because b squared is greater than 4ac
Yes
Yupp that was my next question. So one doesn't work right
Yes
Perfect
So the next case that can be considered is 3
And for 3, a can be 1, 2 and even c so four pairs found
Wait do you count 0 as a natural number or not
No i dont
Ok
I think I have got the hang of it
Thanks so much i was stuck on it since hours overthinking about zeros of polynomials and coefficients not thinking about discriminants
i wonder if this can be solved using generating functions
What's that?
it's a method of solving counting problems, i learned about from 3Blue1Brown video. I don't really know how they fully work so idk if they are really applicable here
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Hello, is drawing such a function realistically possible without using a utility?
Also can I have some tips for D please?
I dunno if drawing a function like that without a utility is super realistic
As for part D, remember that a graph has horizontal tangent lines where the derivative = 0
(Haven't worked it out, but judging from the x^3 and y^3, I think it means for you to use either the quadratic formula or factoring to find those 0s)
I have two variables in y’ 💀
?
sorry I had a brainfart
So since y' is a fraction, you'd only need to solve the numerator for 0
(although do keep in mind where the denominator = 0, as those points would be undefined)
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Ty
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Hello, i need help with this problem "One day 12 746 people visited an amusement park, on average a person spent 300kr with standard deviation of 60kr, how many people spent less than 200kr that day?".
I cant solve it, the only thing i came to was 318, which is wrong
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Can someone explain to me that if Aω are constants, why don’t they fall away when we take the derivative?
Because we multiply and not add
Oh of course. If there’s an addition of a constant then it falls away?
Yes
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How do I do part e?
write out $\begin{pmatrix}1&1\0&1\end{pmatrix}\begin{pmatrix}a&b\c&d\end{pmatrix}$
Toby
then write it out for the other way round, then equate
equate how?
compare each entry
so would that just be {(a+c, c) , (b+d, d)}
$\begin{pmatrix}(a+c)&(b+d)\c&d\end{pmatrix}$
classic truedough
just this?
$\begin{pmatrix}a&a+b\c&c+d\end{pmatrix}$
classic truedough
yup
all of these columns look linearly independent
what does the c in the bottom lest being the same mean
if you equate the bottom left, then c=c which doesnt tell us much
try equating the other entries
so i got that d=a (from b+d = b+a) and c=0(from c+d=0)
making the matrix $\begin{pmatrix}a&b\0&a\end{pmatrix}$ ?
classic truedough
yup, thats correct
now find a basis (of two matrices) that generates all matrices of that form
so would that just be {(a, 0) , (b, a)}
no
its a matrix subspace
so the generators should be matrices
they also shouldn't have variables in them
$\begin{pmatrix}1&0\0&0\end{pmatrix}\begin{pmatrix}0&1\0&1\end{pmatrix}$
classic truedough
Toby
i dont understand how you would find a basis that generates that matrix
its the same process as finding a basis of vectors in linear algebra
$\begin{pmatrix}a&b\0&a\end{pmatrix}=\begin{pmatrix}a&0\0&a\end{pmatrix}+\begin{pmatrix}0&b\0&0\end{pmatrix}=a\begin{pmatrix}1&0\0&1\end{pmatrix}+b\begin{pmatrix}0&1\0&0\end{pmatrix}$
Toby
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Whenever the graph is below x axis
@ripe kite Has your question been resolved?
which of the choices would that be
Visva, you can figure that out by looking at where the graph is below the x-axis
Here's some help
oh so when x doesnt equal 4
No, notice it's positive when x is 0 too
yeah
Do you understand intervals
nope 😦
If we projected that onto the x axis this is what we have
oh so its b
Yes
what if the qeustion asks for range
Does it make sense how to arrive at that answer?
If you want to know the range, you project every value onto the y-axis
👍
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Can somebody please explain the second row? Thanks
with the second row you mean "if zx then x = 0, ..."?
or the 4th row where f(x,y) = 1?
@wise minnow
Wdym
do you mean the row where f(x,y) = 1?
So you have two 16-bit inputs x & y. The two 1's for zx & zy mean they get zeroed out, so x = y = 0 now. Then because nx & ny are set on they are inverted which means x = 1111... and y = 1111..., since the function f is also set to 1, you get the sum x+y = 11111...0 (the last bit will be 0 after completing the binary addition).
Lastly, since no=1, the result, which is 1111...0, is inverted -> 0000...1, so out = 1.
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i've narrowed this problem down to B and C.
Well, you mean your answer is option b and c?
yeah, I eliminated A D and E
AAA can also be used I guess so far
AAA isn't a postulate that exists sadly
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thank you btw
.
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are you sure cos B is -sqrt(119)/12?
ya
12 is r and -sqrt 119 is the x value
i used the pythagorean theorem to calculate the x
all g
ok all values for sin a, sin b, cos a, and cos b are correct
k good
so cos(a+b) = cos a x cos b - sin a x sin b
ye ye i have that down
the cos(a+b) part is correct
well except for the end product which I don't have
nah just leave it like that
i can't or else it will mark it incorrect
it will be (-4 x sqrt(119) - 15)/60
there is no way to simplify it further though
idk what to tell u
hmmm
i mean for the question it says "use radicals as needed, use integers or fractions for any numbers in the expression"
ya but it's savvas 😢
i feel like the culprit is the 15
like if there was no 15 then it would be easy
umm which 15?
15/60
oh.. yea
here's what i mean
well i think the square root 119 messes it up so the answer is "not as tidy"
if there was just a radical in the numerator on one of the fractions... and a regular number in the other... then it would be easy as u would just do it like radical - number / 60
but yea u can't necessarily simplify -4 x sqrt(119) - 15
yea yea
hmmm idk man
slightly weird question tho
u think anyone else here would know what to do?
bc ik for a fact that it won't accept that answer
@honest perch Has your question been resolved?
i mean, i expect anyone to write it using the square root thing
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Draw a figure of all possible complex numbers that satisfies the following rule:
$$
\begin{cases}
\mid z - 3 \mid < 1, \text{if Im}z > 0 \
\mid z + 1 \mid \le 5, \text{if Im}z \le 0 \
\end{cases}
$$
-(𝕂eloτ)-
How would you go on about solving that question?
Do you know how to take the complex absolute value
YouTube
Is mostly how I learned
It’s not the best
$$
| z | = sqrt{a^{2} + b^{2}}
$$
So I suggest
-(𝕂eloτ)-
Try out a few complex numbers
And i am aware that the absolute value = the distance from 0,0 to complex point
And see if they satisfy the conditions
No problem
Fyi \sqrt is the latex command for square root
ik, missed it and thought that it was too late to replace
Why was that pasted as one \
-(𝕂eloτ)-
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
Easier in vim because I have snippets and whatnot
Ok
Forgot another step for the 9
What do you mean by this?
Is your profile picture black or is my discord tripping?
Only seeing your name
Huh, weird..
OH
Sorry
No worries 😉
where did you get that from?
Just
An example
You can then write
B as b>6-a^2
And then
You can graph that
We can already do something similar what I had sent earlier
It looks a little weird though
Something like this:
Ya
Just put in numbers?
Not like that
You can add 8
Flip the inequality
And multiple by -1
And take the square root
Lol messed up the a
Just about to say that
Correct
And also
B is positive because
It said the imaginary value is greater then 0
So the sqrt on that side is *
Sqrt
I think you forgot a 1
Yup
Would that work in desmos? Because geogebra tripped
Let me try
1st: b > \sqrt{a^{2} - 6a + 8}
2nd: b \ge \sqrt{-a^{2} - 2a + 24}
$$
b > \sqrt{a^{2} - 6a + 8}
$$
-(𝕂eloτ)-
$$
b \ge \sqrt{-a^{2} - 2a + 24}
$$
-(𝕂eloτ)-
Which?
Most likely, wonder where
What had I missed?
I think the signs got flipped
Oh
Take your time 🙂
This is what I did
And it seemed to graph it right
I switched the variables so
That it graphs it correctly
You got to type in all the steps for it to show the figure?
Want latex?
This is fine
Alright 👍
🙏
Mine is worse, don't worry! 🙂
I think I flipped the signs because it should be Imz < 0
Which one
Draw a figure of all possible complex numbers that satisfies the following rule:
$$
\begin{cases}
\mid z - 3 \mid < 1, \text{if Im}z > 0
\mid z + 1 \mid \le 5, \text{if Im}z \le 0 \
\end{cases}
$$
-(𝕂eloτ)-
Also
Oh, how?
Idk how geogebra works
no graph, even if true
my computer cant run it
It usually graphs things and has good functions but sometimes it's dumb
Oh
Hmm
Nothing
I think I graphed it wrong
Still nothing
change a to x
Oh
and b to y
Interesting enough switching a & b to x & y worked in geogebra too
Both are dumb.. lol
They are not recognizing anything past x and y as variables
That was geogebra with no extra steps
Line looks odd though
It's a butchered circle
Cannot get second function to work though
Desmos is better
Interface sucks though
Mine was a newbie's graph 😂
Yeah that looks about right
So trail + error is the only approach here or is there a better way to get all the values?
Me too, but I wonder how it would look like
Yep, because the graph looks like the solution
≤ 5
Ok
I think
what you can do for these questions
is because the imaginary value
never mind
I appreciate your help mate!
If someone with better algebra knowledge than me, please do help me solve the question algebraically
let me go search it up
Much appreciated! 🙂
repost the question
Where?
Oh
I think that
I tried wolframalpha with the complex variable and it said no step-by-step solutions available
Do tell!
Ok
Well when we solved for b
we got two equations b>= something
and b<something
so we can sort of smoosh b in between
OH
and the something
can have a in it
https://www.universalclass.com/articles/math/algebra/solving-systems-of-linear-inequalities.htm - this website taught me lol
you just do 3 > x > 2 ?
Oh ok
I'll show it with a graph
its still processing
sorry
5 years later
the purble
is x>2
Divide by two and you get the limit between the two
-2<x<3
I know that algebra 😉
lol
so bascially if they are
the same way
then just pick the one
that contains both directions
Will keep that in mind!
At least we got somewhere
AHA
not closed
thanks
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uhmmm
quick quiz
from the table, do you know what is the value of f^-1(1)
do you know how to differentate f^-1 
yeah, what you get is sort of like this, right?
3_n
Compile Error! Click the
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(You may edit your message to recompile.)
so now you basically know whats in the brackets
it's just evaluating f^-1's derivative
are you trying to say this 
because i doubt so
yes
well this is how i understand chain rule (but kind of cursed and idk if its mathematically right to write it this way)
XD but it's kind of cursed (physics student
)
anyways it's just the df^-1/dx bothering you right
so do you want the formula to be thrown to you or you want some sort of explanation?
lolll kk
so we know that f(f^-1(x))=x right?
do implicit differentation wrt x
ohhhh uhm
it's just taking derivative of both sides of the equation at its core
uhmmm this is misleading
use the cursed way
we know the first derivative: it's f'(f^-1(x))
divide both sides by that and viola
im not familiar with function notations as i mostly use d/dx, but i think they're the same?
I just finished my exam on this chapter in my math course XD
from what we have i think we can sub everything in? 

if im correct
nonoon f^-1 is not 1/f 
if it's confusing you, use something like g
are you sure 
but he is saying f^-1'(y)
not f^-1'(x)

yes
since f'(3)=-4
so 1/f'(3) = -1/4?
and the whole thing is 1/3 * -1/4
soooo -1/12?
what is the circled item in this picture

it'd be funny if i am wrong

-0.083 is 2sf/3dp?
I forget all the roundings XD
btw rmbr to close when you're done with channel XD
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the circles represent certain characterstics
where circles intersect, the people have the characteristics of the intersecting circles
i dont get it
i get venn diagrams but for euler diagrams
and predicates
i am lost
Like look at D
You can see that it is a part of the diagram, but it only intersects C and B
So that means some elements or characteristics are not included at D
so A B C
are all intersect together
D only intersect C & b
but how would you make a formula
At 1st question (Farmers), two portions are included
1?
The one that intersects A and C; and the other one that intersects A,B and C
ok i see
P(x) and R(x)
will be in the formula
A and C
A and C intersection is true right?
The second is clearly false, No blonde farmer can't have blue eyes, it's at circle D and it doesn't even touch the intersection of A and B
how would you make this into a formula before knowing if its false or true
i need to use propositional variables
so P,Q,R,S
A is P
BTW The last part is also false, since there is no intersection at A and D
doesnt the last one
include A C
and D
so the first one is true?
Yeah, but it tries to relate statement A and B to be true to prove the last statement is true
Is this the thing you're talking about?
how did you interpret without creating formula?
This is my answer for the first 1, I think?
Oh my bad
I don't really know since I never encountered these symbols, but I think there should be an Implied symbol at the last question
thanks for the help 👍
<@&286206848099549185> if anyone has really good knowledge in predicates i'd appreciate help
to be clear by the way
this was euler and not venn
so it might be different
i believe euler can have own seperate sets inside a set
@whole umbra Has your question been resolved?
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Hey there
hello
What I have here is ABC being an isosceles triangle
with r the radius of the circle
I also have that L = AH + HC
and that L/r ratio is equal to:
I need to find the measurement of the alpha angle
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<@&286206848099549185>
anything?
I couldn't think of anything though
Because I always end up in loops
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.reopen
✅
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@novel rune Has your question been resolved?
Not yet
lol
.close
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How is infinity/infinity the same as (1/infinity) / (1/infinity)? I am forgetting a fundamental concept here
In the context of L'Hopital's rule
That's not what l'hopital says
What you're saying sounds like just algebra
Yes, sorry I wasn't clear enough
I am just wondering why this one is the case
(1/x)/(1/y)=y/x
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maybe do something like (-3/8)^2 + cos^2x=1?
but im not quite sure what to do after
ping me if someone responds
yeah calculate cosx first using sin^2x+cos^2x=1, then use sin(a+b), cos(a+b), tan(a+b) formulas
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how can i find the devirative of ((\root(3)(6x-4))) by using the definition
$((\root(3)(6x-4)))$
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lenme take a pic
SlowBrosRUs
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cube root of function can be written as
function ^1/3
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brilliant
wait no
the definition...
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I think you can use $(a-b)*(a^2+ab+b^2) =a^3-b^3$
asuasu
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how do I even find the solution?
You know that tanx is sinx/cosx
you don't actually need to
you have four numbers and you are asked to say how many of THEM are solutions
Every value that doesnt make Cosx = 0 (Since dividing by 0 is bad)
you can accomplish this by simply pluging each one in
and checking
and then reporting how many successes you get
@supple spindle
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@stoic saddle SORRY I LITERALLY FELL ASLEEP
ok yeah that makes sense
sorry lmao
and thanks
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AC=CB
S(AC) - symmetrical bisector
Why does angle CO1Q=angle CAB
I think they might be similar triangles, since CQ=1/2 AC
CQO1=90 degrees
but so far there's a side, and an angle that are proportional and equal
what's that CO1 line?
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how do i do this
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how do i estimate square root 34 number
: ( no one answered
?
and 5 and 6 is the answer right
ye depending on what ur cher wants