#help-33

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marsh citrusBOT
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still temple
#

Represent the following numbers as being members of set L: -15, 1, 7, 3, -8, 7, 0,
12, 6, 12

still temple
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I wasn't here at the lesson I was learning this at school so I don't get how to answer this

hazy shard
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Is there anything else to the question?

still temple
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nope

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thats all..

stoic saddle
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{-15, 1, 7, 3, -8, 0, 12, 6}

hazy shard
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{-15, -8, 0, 1, 3, 6, 7, 12}∈L

still temple
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wait how did you get that..

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I lost now..

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I mean I was always lost..

hazy shard
stoic saddle
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you named an entire set of numbers as an element of L

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which it isn't stated to be

still temple
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oh,,

stoic saddle
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@still temple i just listed all your numbers without duplicates and put them in curly braces lmao

hazy shard
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So what, you just write a set and assume the values in it are part of set L?

stoic saddle
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well the problem statement is a little unclear as written

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maybe it had to be translated from a different language so we will never know

still temple
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oh..

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yeah I am in Korea so..

hazy shard
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I assumed L was a set already given and you had to write that the numbers given were part of it

crystal lintel
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maybe {-15, -8, 0, 1, 3, 6, 7, 12} = L

hazy shard
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Not to make the numbers into set L

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That's why I wrote it like that

still temple
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Do I close this after finished..?

hazy shard
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?

royal flicker
crystal lintel
elfin berryBOT
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layla💜

hazy shard
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Ohh

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That makes a lot more sense

still temple
royal flicker
hazy shard
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.close

marsh citrusBOT
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still temple
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.close

marsh citrusBOT
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livid maple
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no

marsh citrusBOT
livid maple
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idk where to start

stoic saddle
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okay well let's see

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what feature can a rational function have at most one of?

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...okay, there are more possible answers to this question than i intended, but maybe thinking about this will spark some thought processes in your head.

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from this, think about how many functions you need in order to satisfy your constraints.

marsh citrusBOT
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@livid maple Has your question been resolved?

marsh citrusBOT
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cold sequoia
#

Guys really basic question. It's a graphing question

f(-1) = -2
f(1)= 2
f(0)=0
lim(x -> infinity) of f(x) =1
lim(x -> negative infinity) of f(x) = -1

cold sequoia
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Like I got all the points and have a general idea but for f(0)=0, would I have to connect those two other graphs or would it just be like a floating point

crystal lintel
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I'd probably connect them

cold sequoia
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yeah but like how

crystal lintel
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it's not very clear exactly

cold sequoia
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Yeah it really aint

crystal lintel
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straight lines or curvy lines or whatever might be fine

cold sequoia
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oh

steep garden
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Hey guys I have three questions that I need help in

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I was wondering if anyone can help me?

cold sequoia
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uh you should ask in a available chat

crystal lintel
steep garden
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Ah thx

cold sequoia
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so yeah, it's literally can be anything -_- I'm overthinking it again

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yeah it's 11 at night. Thanks layla ❤️

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marsh citrusBOT
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crystal lintel
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np ^-^

marsh citrusBOT
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warm obsidian
marsh citrusBOT
warm obsidian
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heres what i got

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<@&286206848099549185>

marsh citrusBOT
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@warm obsidian Has your question been resolved?

warm obsidian
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<@&286206848099549185>

marsh citrusBOT
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@warm obsidian Has your question been resolved?

marsh citrusBOT
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@warm obsidian Has your question been resolved?

wooden oriole
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compare with $\sum_{k=1}^{\infty}\frac{1}{k}$

elfin berryBOT
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秋水

wooden oriole
marsh citrusBOT
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marsh citrusBOT
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sly plume
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Have I multipled the matrices correctly?

marsh citrusBOT
nimble canyon
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no

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oh wait

sly plume
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The top right corner should be -4+y-x

nimble canyon
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nvm

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but

sly plume
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?

nimble canyon
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its a 3 x 2 matrix into2 x 3 matric

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so it should be a 3 x 3 matrix as an answer

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lol

spring tide
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Isn't it supposed to be a 3x3 matrix?

nimble canyon
sly plume
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so what did i miss

nimble canyon
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a whole column and row

sly plume
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Which multiplication did I miss? @nimble canyon

nimble canyon
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everything is wrong

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so

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what you do is

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you take a row

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from the first matrix

spring tide
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You go first row first column first row second column first row third column

nimble canyon
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then multiply corresponding element to each other

sly plume
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Ok

spring tide
sly plume
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.close

marsh citrusBOT
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marsh citrusBOT
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marsh citrusBOT
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fossil crown
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Hello, I found the two demarcation but i don't know how to continue

fossil crown
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I know that i should find this equation but I don't know how to find it

marsh citrusBOT
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@fossil crown Has your question been resolved?

fossil crown
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<@&286206848099549185>

marsh citrusBOT
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@fossil crown Has your question been resolved?

fossil crown
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<@&286206848099549185>

jolly saffron
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Is this supposed to be geometric progression?

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Now that I look closer… it appears that the comment was a little late to the party.

fossil crown
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.close

marsh citrusBOT
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wanton pecan
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How can I solve this problem using the method of characteristics?

wanton pecan
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Would applying d'Alembert's formula be considered a solution "by the method of characteristics?" If so, how would I account for the boundary?

marsh citrusBOT
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@wanton pecan Has your question been resolved?

marsh citrusBOT
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viral pilot
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is there an official name for “a quad that has no para lines”

worthy trellis
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not really

viral pilot
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i see

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thats what it seems like too

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even though some people suggest that a trapezium is one

worthy trellis
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that is not atrapezium

gleaming lance
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depends, there are trapezoids that have no parallel sides

worthy trellis
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and trapezium has one pair of parallel sides

viral pilot
gleaming lance
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i dont think there is a specific term for that

upper briar
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fun talk

viral pilot
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oh hey again

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this is the person that got what i meant last time, but shes also in the same boat as me

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we still dunno how to differentiate it lol

viral pilot
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since theres room for discrepancy

gleaming lance
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well if yyou consider kite a shape, then maybe you can call it a kite lol

viral pilot
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and there are already ways to differentiate other higher numbers of parallel sides

gleaming lance
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it is insignificant enough for it to not have a name

viral pilot
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like parallelogram for two, and the supposed trapezium for at least one

viral pilot
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yeah true that, but kites are special tho

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since they have two pairs of equal lengths

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while not all quads with zero parallel sides have pairs of equal lengths

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so a kite wouldnt work

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plus the other properties

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like the circle thing

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gosh

worthy trellis
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why do you think there has to be a name for it?

viral pilot
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self study is addictive

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its 4am already

viral pilot
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like parallelograms

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theyre quads with two pairs of parallel sides

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the next down is one pair, which is apparently a trapezium

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but then theres nothing for zero pairs

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logic whomst?

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darn the greeks or whoever did geometry

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im no experty, but it seems logical that there should be a name for this

upper briar
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well

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thrs a lot of stuff with no sepcific names assigned to them

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as u can easily write it in terms of other stuff already known

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an example would be the set of all ints from 2 onwards

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we just use like $\mathbb{Z}_{\ge 2}$

elfin berryBOT
viral pilot
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yeah true, could u possibly lead the way? im a noob when it comes to this stuff

upper briar
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or similar, thrs a lot of ways to

viral pilot
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i see

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so like

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just find something that shares this kind of property and mix it with quad, or if theres none just translate it into latin and add the suffix -ium to it or smthn?

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lmao

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i feel like a very dumb scientist / mathmentician pioneering in very ingenius things that humanity has completely overlooked for thousands of years

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wooo…

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depressing ngl

worthy trellis
viral pilot
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sigh is there really no better alternative other than going to sleep at this point?

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owndjqjdnkakamda

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im kinda interested in this as well since i got distracted with the quadratic equation

worthy trellis
viral pilot
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yknow, calculus stuff for finding the area

viral pilot
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id be damned if we really called it that

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but then again, its not too far off from the likes of those scientists that coined the term “spaghettification”

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ahahahaha

worthy trellis
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lol

viral pilot
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im sorry, i think my brain aint normal at 4am

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i guess ill revisit this problem another day, or just do as u say:

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just make up a term for it xd

worthy trellis
viral pilot
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lmao yeah fine i concede

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true XD

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aight have a good one mate, thanks for the laughs

worthy trellis
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good day to you

viral pilot
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calling it a night at 4:20am here in nz

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take care!

upper briar
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well

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imma

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bop it

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marsh citrusBOT
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agile yoke
#

Hello Im repeating some stuff about sets. what does "to the power of C mean"

tight furnace
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complement

agile yoke
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thanks

tight furnace
#

np

agile yoke
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.close

marsh citrusBOT
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deft apex
marsh citrusBOT
deft apex
#

is this just asking for the x coord of the maxima and minima of the y curve?

still temple
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Critical points, I guess. $f''(x)=0$.

elfin berryBOT
deft apex
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yeah

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thats what it is asking right

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wait

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isnt it just a single derivative

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and then where it is 0

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cus its a trig function

still temple
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OH damn yeah.

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Sorry for that.

deft apex
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alr ez clap

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just making sure thats what the horizontal stuff is

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wasnt too sure

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.close

marsh citrusBOT
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deft apex
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.reopen

marsh citrusBOT
#

deft apex
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I have no clue how to format this correctly

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oh I forgot the fucking minimum

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.close

marsh citrusBOT
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marsh citrusBOT
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subtle pawn
#

it is right statement right?

marsh citrusBOT
subtle pawn
#

and does anyone know how can i write this kind of statements in wolfram🦆

devout mauve
#

,rotate

elfin berryBOT
devout mauve
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what exactly is w supposed to be?

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what are you trying to say

sage heath
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whole number catGiggle

subtle pawn
devout mauve
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usually we use Z for that

subtle pawn
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i mean i think all integers work even negative but i don't need them 🦆

subtle pawn
devout mauve
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in what world are integers and whole numbers not the same thing

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ok nvm just googled. weird stuff

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so you want to say that $i^{4x}=1$ for all $x\in w$

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that's it?

elfin berryBOT
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Denascite

marsh peak
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Yes i^4 = 1

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So i^4x = 1 as long as x is an integer

subtle pawn
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{0,1,2,3,4,5…} = whole numbers

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{…-5,-4,-3,-2,-1,0,1,2,3,4,5…} = integers

devout mauve
subtle pawn
devout mauve
#

if you are gonna quote wikipedia, at least quote everything

subtle pawn
devout mauve
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also correct

marsh peak
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Sure

subtle pawn
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i^4x+n = i^4x×i^n = 1×i^n?

subtle pawn
devout mauve
#

well there is a way

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but it's not nice

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not sure why you wanna write these statements in wolfram

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or do you just mean writing "i^(4x)=1" and wolfram solving to show you x in Z

marsh citrusBOT
#

@subtle pawn Has your question been resolved?

subtle pawn
marsh citrusBOT
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raven wasp
#

What is the weight of a bowling ball with a diameter of 12 inches given the fact that one with a diameter of 8 inches has a weight of 10 pounds?\

raven wasp
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anyone wanna help in this?

worn nimbus
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33.75 lbs

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(12/8)^3 * 10

eternal tundra
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we do this by using the density

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assuming they share the same density

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for a ball we have:

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$V=\frac{4}{3} \pi r^{3}$

elfin berryBOT
#

~Martin

eternal tundra
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where V is the Volume

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density is defined as mass/volume

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diameter=8 => radius=4

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,calc (4/3)pi*3^3

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it weighs 10 pounds

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so we get a density of

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,calc 10/((4/3)pi*6^3)

elfin berryBOT
#

Result:

0.011052426603604
eternal tundra
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to get the mass of the bigger ball we first need the volume

elfin berryBOT
#

Result:

113.09733552923
eternal tundra
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sry i got some values wrong

raven wasp
eternal tundra
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,calc (4/3)pi*4^3

elfin berryBOT
#

Result:

268.08257310633
eternal tundra
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this this is the volume

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mass is 10 pounds

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density=mass/volume

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,calc 10/((4/3)pi*4^3)

elfin berryBOT
#

Result:

0.037301939787163
eternal tundra
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this is our density

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for the bigger ball we first get the volume

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,calc (4/3)pi*6^3

elfin berryBOT
#

Result:

904.77868423386
eternal tundra
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density=mass/volume
therefore
mass=density*volume

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to get an exact answer, i wont use the result from before but rather the formula used

raven wasp
eternal tundra
#

,calc (10/((4/3)pi4^3))((4/3)pi*6^3)

elfin berryBOT
#

Result:

33.75
eternal tundra
#

and there we have our mass

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otherwise we could also have used the fact that mass and volume are proportional

raven wasp
#

why did you cube it?

eternal tundra
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that is just the formula for a volume of a sphere

worn nimbus
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you dont actually need the volume

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you just need to know how it scales

eternal tundra
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yes, that's correct

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proportionality also works

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i must admit this was a bit overcomplicated haha, but i guess it works as well

worn nimbus
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then now suppose you have a cube with sidelength 2

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how much more volume does the cube with sidelength 2 have

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this doesnt justy hold for cubes

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its for all shapes

worn nimbus
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times 8

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2^3

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volume is 3 dimensional

raven wasp
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yeah

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since the volume of the ball is 3d we would be to times it by 8 right?

worn nimbus
#

well the ratio of the lengths to the third power

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so in this case (12/8)^3

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= 3.375

raven wasp
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ohhhhhh

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makes sense

worn nimbus
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np

raven wasp
#

we then multiply it by 10 since we are trying to find the weight of 12 inch bowling ball compared to the 8 inch one

worn nimbus
#

exactly

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we assume the densities to be equal of course

raven wasp
#

for these type of problems we would do big to small for ratio right?

worn nimbus
#

exactly

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but beware of what ratio you start with

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suppose you start with the ratio of areas

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then you wouldnt cube that ratio to find the ratio of volumes

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usually though the ratio of lengths is where you start

raven wasp
#

ic

raven wasp
worn nimbus
#

well you have 2 dimensional ratio

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so to find the 3 dimensional ratio we would do (2d ratio)^1.5 since 1.5 * 2 = 3

raven wasp
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so square it?

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ah

worn nimbus
raven wasp
#

since we are dealing with 3d ratio right?

worn nimbus
#

well if you want the 3d ratio you would do that yes

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perhaps i overcomplicated it

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but i think you understand

raven wasp
#

.close

marsh citrusBOT
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molten venture
marsh citrusBOT
molten venture
#

i am having trouble with this

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i know that its III

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i am having trouble figuring out whether its I or II

marsh citrusBOT
#

@molten venture Has your question been resolved?

molten venture
#

I understand that it becomes ln(n+1) - ln(n)

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however the only value remained is ln(1)

still temple
#

ln(1)+ln(n+1), bc there will be always a last term that doesn't cancel out

molten venture
#

so its 0 + ln(100) for th 99th term

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whats the answer then?

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2ln10?

still temple
#

And to test for convergence just take lim as n approaches infinity

molten venture
#

i see

#

thank you

marsh citrusBOT
#

@molten venture Has your question been resolved?

marsh citrusBOT
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viral pilot
#

ngl i prefer this over forums

marsh citrusBOT
viral pilot
#

.close

marsh citrusBOT
#
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hidden plaza
#

Did you feel the need to open a help channel just to say this. But I agree

main idol
main idol
#

i imagine at some point one of these will go away

marsh citrusBOT
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trail quiver
#

How do I graph a relation in which the "y" is an absolute value. For example, how would I graph |y|=2x^2

nova totem
#

You would graph when y = 2x^2 and -y = 2x^3 simultaneously

#

Good job Pure

#

I saw that

hidden plaza
trail quiver
#

Oh I think I understand. thanks for the help guys

#

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trim matrix
marsh citrusBOT
trim matrix
#

And the question

nova totem
#

It's a quadratic right

#

So what's the minimum expressed as a point

trim matrix
#

-4

#

so

#

thats the y of a vertex

nova totem
#

That's not a point

#

I asked to express the minimum as a point

trim matrix
#

0,-4

nova totem
#

Nope

nova totem
#

It specifically gives you the x-value of the global minimum

trim matrix
#

3,-4

#

is that it ?

nova totem
#

That's the minimum as a point, yes

#

Now, if the equation has the minimum at (3, -4) and is a quadratic, then two things:

  1. Is the parabola concave (opening) up or down?
  2. What is the vertex?
trim matrix
#

uhh

#

its opening down

#

the vertex is 3,-04

#

3,-4*

#

?

nova totem
#

Think about it

#

Yes the vertex is (3, -4)

#

But if it's opening down

#

Yeah no that is not a minimum

#

This question essentially is checking if you understand parabolic behavior

#

The vertex is a minimum when the parabola is opening up

The vertex is a maximum when the parabola is opening down

If needed, draw a diagram

#

But it physically evinces itself

trim matrix
#

Ok i drew it it is opeining up

#

so um

marsh citrusBOT
#

@trim matrix Has your question been resolved?

trim matrix
#

.close

marsh citrusBOT
#
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marsh citrusBOT
#
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languid harness
#

Can someone explain this graph to me ?

marsh citrusBOT
languid harness
#

How is it going in the negative side,as:

Cos(-x) = cos(x)

acoustic cosmos
#

for all n in Z+

languid harness
#

if i take n = 1

cos(2pi + x) = cos(x)

and the value is +ve

acoustic cosmos
#

does that make sense to you

#

wait did you learn radians yet

languid harness
acoustic cosmos
languid harness
#

bruh

acoustic cosmos
#

don't think so

languid harness
#

isn't cos(-x) = cos(x) ?

acoustic cosmos
#

oh yeah it lies in quadrant 4

#

so cosx is positive

languid harness
acoustic cosmos
#

for second quadrant cosx = cos-x

#

for first and third cos-x = -cosx

languid harness
acoustic cosmos
#

you know what

#

go ahead

languid harness
#

what

acoustic cosmos
#

take this

languid harness
#

take what ??

acoustic cosmos
languid harness
#

ummm did u understand my doubt 💀 ??

#

.close

marsh citrusBOT
#
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marsh citrusBOT
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rain wyvern
marsh citrusBOT
rain wyvern
#

for iv, how is there no 0 polynomial?

#

how do we know it doesnt exist in Q?

glacial hedge
rain wyvern
#

sorry i think i have trouble understanding what a 0 polynomial is then

glacial hedge
#

The constant polynomial equal to 0

#

It is usual to associate/identify constant polynomials to their value

rain wyvern
#

so there should be a polynomial in every subspace of the set of polynomials where every output is 0?

#

and because 0(2) != 0 then this 0 polynomial doesnt exist?

glacial hedge
#

A subspace is a vector space, which is a group. It must therefore contain the neutral element, which is 0. Therefore if a set doesn't contain 0 it isn't a VP

glacial hedge
rain wyvern
#

nvm it just wouldnt be in the subspace

rain wyvern
glacial hedge
#

Is not in. Doesn't exist in a set is something we don't say

#

Matter of conventions

rain wyvern
glacial hedge
rain wyvern
#

like if 0 polynomial is a constant how would you input a number into it

glacial hedge
cloud kettle
marsh citrusBOT
#

@rain wyvern Has your question been resolved?

#
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languid harness
#

How do I proceed :/ ?

marsh citrusBOT
vestal forge
#

could you post the whole question?

languid harness
#

This is the whole ques 💀

#

Its a MCQ

#

Want those ??

vestal forge
#

what i meant is the multiple choices

languid harness
#

Ok wait soory

vestal forge
#

alright, and what have you tried?

languid harness
#

I tried :

x + y = 1

#

Then gave up 💀

#

Can u tell me how do I proceed?

vestal forge
#

ok, so I suppose limits is available to us?

#

if not, you can brute force it by just solving for y in terms of x

#

and then find the domain from there

languid harness
vestal forge
#

as in, is limit available as a tool for us to use?

languid harness
#

Preferably something which is quick

vestal forge
#

actually, there is something quicker than that, nvm then

#

right, so let us rewrite the constraint as 2^y=2-2^x

languid harness
#

Pls tell 😈

vestal forge
#

this is pretty obvious

languid harness
#

Yep it sure is

vestal forge
#

now, since 2^y is strictly positive, this must means that 2-2^x>0

#

do you follow with this statement?

languid harness
vestal forge
#

i did not assume that y is always positive, I stated that 2^y is always positive

#

y can be negative, 0 or positive

#

but 2^y is always positive

#

this is just the property of exponentiation

languid harness
#

Oook got that

vestal forge
#

right, so it must mean that in order for the equation 2^y=2-2^x to be true for some arbitrary x, then it must mean that 2-2^x>0

#

for example, take x=2, then 2-2^2=-2, but 2^y=-2 has no real solutions for y

#

so do you have any question at this point?

languid harness
vestal forge
#

can you find a value for y such that 2^y=-2?

languid harness
#

Ah ok, we cant

#

So that means y hasn't got a real value right ?

vestal forge
#

yes, there is no real values of y such that 2^y=-2

#

meaning x=2 is not in the domain

languid harness
#

Ah ok

vestal forge
#

but anyway, so as long as 2-2^x>0, meaning as long as the rhs is positive, there always exists a real y that satisfies the equation

#

so all clear?

languid harness
#

Yes understood

vestal forge
#

right, so all we need to do is to solve for x in 2-2^x>0

languid harness
#

Or we can also write it
2>2^x

vestal forge
#

yes

languid harness
#

So from this we can conclude that x = 1 and it has got a real solution?

vestal forge
#

no

languid harness
#

No, how ?

vestal forge
#

2>2^x means that 2 is strictly larger than 2^x

#

2>2^1 is not true

languid harness
#

Oh yes it's strictly larger

#

My bad

vestal forge
#

you could also see why it's not true because 2^y=0 has no real solutions too

languid harness
#

Ah yes true

#

So what do I do next ?

vestal forge
#

have you solved inequalities involving with exponential functions before?

languid harness
#

Quadratic ones yes

vestal forge
#

quadratics are polynomials, not exponentials function

languid harness
#

But those ones were not strictly increasing or decreasing

languid harness
vestal forge
#

alright, nvm all that, if i gave you 2^x<=2, then could you solve for x here?

languid harness
#

x = 1 ?

vestal forge
#

that is one of the solutions

languid harness
#

Isn't that the only solution?

vestal forge
#

again, we are solving an inequality

languid harness
vestal forge
#

2^(-1)<=2 is also a true statement

#

1/2 is less than 2

languid harness
#

Oh yes it is

#

-infinity , 1

vestal forge
#

alright, it seems like you are not very familiar with these types of inequalities, let's solve it with me then

#

oh nvm

languid harness
#

(-infinity,1] ?

vestal forge
#

yes, (-infty, 1] is the correct solution

#

now that is 2^x<=2, what about 2^x<2?

#

(this is just us removing the equal sign, so remove the solution when the equal sign is true)

languid harness
vestal forge
#

yes

#

that is now your domain

languid harness
#

Wow that so freaking smart

#

Thanks

#

Never thought of this ques like this

#

And yes the ans is also right

#

Thankkkksss

#

.close

marsh citrusBOT
#
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#
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steady mural
#

hi guys i have a question

marsh citrusBOT
steady mural
#

what length of tarapulin 3m wide will be requited to make a conical tent of height 8m and base radius 6m? assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm (use pi = 3.14)

#

pls help

#

<@&286206848099549185>

marsh citrusBOT
#

@steady mural Has your question been resolved?

steady mural
#

<@&286206848099549185>

marsh citrusBOT
#

@steady mural Has your question been resolved?

marsh citrusBOT
#

@steady mural Has your question been resolved?

upper briar
#

then add 20 cm after?

marsh citrusBOT
#
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harsh tundra
#

What should I do to look for the radius and interval of convergence after getting here?

harsh tundra
#

I got stuck

distant peak
#

$\sum_{k=1}^{\infty} \frac{2^k}{k² 3^k} x^k$

elfin berryBOT
#

Herels

distant peak
#

with $a_k = \frac{2^k}{k² 3^k}$

elfin berryBOT
#

Herels

distant peak
#

now to find the radius of convergence, you use d'Alembert

harsh tundra
#

Why can I take x^k out?

#

Wont I get to the same place I was?

distant peak
#

why do you want to do that tho

harsh tundra
#

I'll try it out

distant peak
#

do you know about d'Alembert tho ?

harsh tundra
#

Yes, ratio

distant peak
harsh tundra
#

Its the ratio test with the limit

distant peak
#

yea but ratio of what

harsh tundra
#

ak+1/ak

marsh citrusBOT
#

@harsh tundra Has your question been resolved?

marsh citrusBOT
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river lance
#

Hey, I am currently searching for a function without condition and defined in R which returns 1 when a number is a solution of n(n+1)/2 et which returns 0 in all the other cases ? Do you have any idea?

river lance
#

$f(x) = 1$ if $\exists n \mid f(x) = \frac{n(n+1)}{2}$
otherwise $f(x) = 0$

elfin berryBOT
marsh citrusBOT
#

@river lance Has your question been resolved?

steel basin
#

This

#

U want a polynomial function

#

?

#

I don think polynomial function exist for this

devout mauve
#

they don't

#

the function described is clearly not continuous so you can't get it with polynomials or something like that

steel basin
#

Yeah

devout mauve
#

you could do some weird stuff like $f(x) = 1 - \left(\ceil{\frac 12 (\sqrt{8x+1}-1)} - \floor{\frac 12 (\sqrt{8x+1}-1)}\right)$

elfin berryBOT
#

Denascite

steel basin
#

How?

devout mauve
#

if x=n(n+1)/2, then n=1/2 (sqrt(8x+1)-1)

steel basin
#

Oh

#

I am dumb sorry

devout mauve
#

if n is an integer, then ceil(n)=floor(n)=n, so ceil(n)-floor(n)=0 and f(x)=1

#

but if n is not an integer the ceil(n)=floor(n)+1 and so ceil(n)-floor(n)=1 and f(x)=0

#

or you could probably find a lot of other functions which are 0 if input is integer and 1 otherwise

marsh citrusBOT
#

@river lance Has your question been resolved?

marsh citrusBOT
#
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worn fractal
#

i need help on these two geometry questions

marsh citrusBOT
#

@worn fractal Has your question been resolved?

rose tiger
#

for 10

#

the two angles are supplementary

marsh citrusBOT
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fallow lynx
#

Please explain to me the step by step process on this

fallow lynx
#

I'm particularly confused how there is a +2 and how -1 was added in 4cos theta

wet zenith
fallow lynx
#

Ohhh

#

Aight thanks, got confused and thought you factor cos theta to all

#

thanks

#

.close

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#
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glad tundra
#

Which poligon has 35 diagonals? i'd need the steps and the result so i can see how to solf in the future, thank you!

glad tundra
#

polygon*

hidden plaza
#

In any n-sided polygon, each vertex can be connected to n-3 other vertices (not itself or its adjacent vertices.) Can you come up with the formula for the number of diagonals for an n-sided polygon (careful with over counting.)

glad tundra
#

yeah i know the formula for that, its n*(n-3) divided by 2

#

but im getting stuck on how to calculate the n when im given the number of diagonals

hidden plaza
#

$\frac{n(n-3)}{2} = 35$

elfin berryBOT
hidden plaza
#

This is just a quadratic

glad tundra
#

so

#

n(n-3)=d/2?

#

oh wait no

#

it would be d*2

#

so now im on n^2 - 3n = 70

#

what now

marsh citrusBOT
#

@glad tundra Has your question been resolved?

glad tundra
#

Hello?

#

@hidden plaza

hidden plaza
#

Do you know how to solve quadratic equations

glad tundra
#

sort of, but i'm having problems on this one
can i just get the formula for n so i can have it for future refrence, i am very lost currently

merry terrace
glad tundra
#

yes, i would like the formula to solve for n

merry terrace
#

n=+and-√67

#

Wait

#

Shit

#

What I am doing

glad tundra
merry terrace
#

That's what I am talking about

#

It would be the quadratic formula

#

n²-3n-70=0

glad tundra
#

ooh right

merry terrace
#

Yupp you can solve it form here?

glad tundra
#

yeah thank youu

merry terrace
#

Welcome 🫂

marsh citrusBOT
#

@glad tundra Has your question been resolved?

#
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fleet sierra
marsh citrusBOT
fleet sierra
#

How is it supposed to solve this problem? I mean which formula should i use

#

I tried different things but can't solve this

upper briar
#

wait

trim quest
#

it means arctan

upper briar
#

werent u here awhile ago

#

we were talkin abt pyrawr triples

fleet sierra
#

Nope, not for the triples

#

Yep

upper briar
#

like

#

draw the unit triangle

fleet sierra
#

Yes i can derive arctg12/5 from the triangle

#

W what am i supposed to do catThink

#

Ok, I'll get arccos +arccos. Is there a formula for addition of two arccos?

#

Thank you

#

Where can I find those formulas?

hushed egret
#

like

#

you shouldve calculated the sin and the cosine

#

of the angles

#

as was suggested

marsh citrusBOT
#

@fleet sierra Has your question been resolved?

elfin berryBOT
fleet sierra
#

Why zero??

#

I get п/4 as an answer @hushed egret

hushed egret
#

,w sin(arccos(12/13) + 2arctan(5))

hushed egret
#

,w cos(arccos(12/13) + 2arctan(5))

hushed egret
#

hence the top angle is -pi

#

repeat for bottom one

#

,w sin(arcsin(8/17) + 2arctan(4))

hushed egret
#

,w cos(arcsin(8/17) + 2arctan(4))

hushed egret
#

hence the bottom angle is also -pi

#

so you're just evaluating arctan(-pi/-pi) = arctan(1) = pi/4

fleet sierra
#

So yes, the final answer should be п/4 right?

#

Like that

#

@hushed egret

hushed egret
#

yes

marsh citrusBOT
#
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silver matrix
#

hello guys, im a bit confused with the question, it says

silver matrix
#

find value of dy/dx at point (1,-2) which lies on curve 2x^2 +3y^2-6xy=26

#

what does this question mean? to first input the points to the curve then find dy/dx?

#

or to first find the dy/dx then then input the points?

ripe rock
silver matrix
ripe rock
#

asit is no longer in terms of vriables

ripe rock
#

so differentiate first

silver matrix
#

if i differentiate first

#

then the dy/dx would be a slope?

#

right?

ripe rock
#

it would be the ratio of change in distance in the y direction to the change in the x direction, if you took a small step in the x direction

ripe rock
#

so, assume you move a very small distance $\Delta x$ in the x direction on the given curve, then if $dy/dx = a$, it means you will move $a \cdot \Delta x$ distance in the y direction to stay on the curve

elfin berryBOT
#

Sharl Eclair

silver matrix
#

dy/dx will be my answer

marsh citrusBOT
#

@silver matrix Has your question been resolved?

marsh citrusBOT
#

@silver matrix Has your question been resolved?

marsh citrusBOT
#
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fleet beacon
#

Every natural number from 1 to 15 (incl) is written down on a cardboard card, where each cardboard card has a number on it and none repeat. Four cardboards are drawn at random. What is the probability that among four cards drawn 8 is the lowest number OR 12 is the highest number?

fleet beacon
#

combinatorics got me good

#

So 15 choose 4 is what we divide by a

#

And I have a sneaking suspicion its gonna be 7 choose 3 divided over it + 11 choose 3 divided over it again

#

at the same time something feels a bit off about it like I have to divide possible all combinations of 8 by only the ones i need

sleek lake
#

i would do
7c3 + 11c3 − 4c2

fleet beacon
#

why the 4c2

sleek lake
#

there's overlap
(it's 3c2 my bad)

fleet beacon
#

ah right makes sense

#

wowzers again not so difficult once you see the answer 🤣🤣

#

thanks mate

fleet beacon
#

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fleet beacon
sleek lake
#

4c2 was a mistake yes

fleet beacon
#

Right

sleek lake
#

i wrote the numbers to see the sizes

fleet beacon
#

Thats super calm then

#

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fleet beacon
#

Little something from class why is 11/36 added again isnt the 11/36 counting both die and the potential swapping in their positions

fleet beacon
#

Is it all possibilities with 3 and then same for 6 ?

lean flame
#

,rccw

elfin berryBOT
fleet beacon
#

then I get the vibe that | 3 | 6 | combinations overlap 🤔

marsh citrusBOT
#

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@fleet beacon Has your question been resolved?

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zealous flame
#

Hi can someone help?

marsh citrusBOT
zealous flame
#

15th question

trim quest
#

What's the question?

zealous flame
#

wants the answer

#

it is about matrices

trim quest
#

This is just a matrix with an unknown exponent

#

There must be something else. What do the directions say? There is no question here

zealous flame
#

Find multiplication of matrices

fleet beacon
#

Matrix calculators show step by step solutions

zealous flame
#

how can i find it

#

i try symbolab one

#

Matrix unsupported power

marsh citrusBOT
#

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#

@zealous flame Has your question been resolved?

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hybrid belfry
#

help please

marsh citrusBOT
hybrid belfry
#

Idk what to do for this

marsh citrusBOT
#

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still temple
#

here again 😭 dont know how to do any of this

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#

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still temple
#

bruh

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wide wind
#

Obtain the differential equation by eliminating the arbitrary constants

y=Ae^(-3x)-Be^(2x)+Cx^3

I tried getting up to the 3rd derivative, but i don't know what to do next

marsh citrusBOT
#

@wide wind Has your question been resolved?

main idol
#

Looks like a linear algebra problem now

wide wind
#

yeah, i also tried doing this method, but because of the x variable beside c, i can't add the equations

main idol
#

Oh hmm I'm stumped then

wide wind
#

and i can't move the x variable outside since the last equation only has 6C

marsh citrusBOT
#

@wide wind Has your question been resolved?

wide wind
#

<@&286206848099549185> help🥺

marsh citrusBOT
#

@wide wind Has your question been resolved?

wide wind
#

. close

#

.close

marsh citrusBOT
#
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marsh citrusBOT
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half onyx
marsh citrusBOT
half onyx
#

why is this wrong lol

vestal forge
#

the derivative of arctan(x) is 1/(x^2+1) there is not supposed to be any sine in there

half onyx
#

hm

#

thats what photomath gave me

vestal forge
#

too bad you shouldnt have trusted photomath then

half onyx
#

cuz i tried like 8 times beforehand and got it wronmg every time

vestal forge
#

try to do it by hand

half onyx
vestal forge
#

have you learnt implicit differentiation?

half onyx
#

ye

vestal forge
#

if you are finding it too ugly to differentiate, try taking tangent on both sides first and then differentiate

half onyx
#

one sec lemme do it again and ill send my work

#

okay

#

oh ignore the first bit

#

that was my last try

vestal forge
#

this is correct

#

the line below that is not

half onyx
#

im nmot sure whats wrong abt it

vestal forge
#

you didnt distribute correctly

half onyx
#

can you tell me what exactly is wrong tho

#

because i have no idea

vestal forge
#

if you wanted to distribute 1/(1+whateverishere) into 1-x/sqrt(1+x^2), it should have been $\frac{1}{1+(x+\sqrt{1+x^2})^2}-\frac{1}{1+(x+\sqrt{1+x^2})^2}\cdot\frac{x}{\sqrt{1+x^2}$ instead

#

and bot is dead

#

wonderful

#

basically, you didnt distribute correctly, the fraction should have been multiplied to x/sqrt(1+x^2) as well

#

but there was no need for you to distribute, just leave it as is

half onyx
#

okAY

#

thanks

#

.close

marsh citrusBOT
#
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marsh citrusBOT
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still temple
#

How can you solve this with Wolfram?

marsh citrusBOT
stoic saddle
#

,w {{-4,-2,4},{8,4,-10},{2,1,-4}} * {{x},{y},{z}} = {{6},{-12},{-3}}

marsh citrusBOT
#

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swift cypress
#

what's a preimage

marsh citrusBOT
celest wyvern
#

use gugle

stoic saddle
#

given a map f: X -> Y and a subset B ⊆ Y, the preimage of B by f is denoted f^-1(B) and is defined as f^-1(B) := {x ∈ X : f(x) ∈ B}

swift cypress
devout mauve
#

(well tbf you do find the answer with google)

swift cypress
#

lmao fair

#

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modest idol
marsh citrusBOT
modest idol
#

Is that right?

cloud iron
#

Looks right to me

hidden plaza
late geode
#

should have f(x) instead of f(3) in that main first line

cloud iron
#

^

#

Didn't even notice that I tunnel visioned lol

marsh citrusBOT
#

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modest idol
#

Thank you

marsh citrusBOT
#
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sly plume
#

Question no. 6 please

marsh citrusBOT
sly plume
#

,rotate

elfin berryBOT
bleak ibex
#

Bit of a cheat method, but they could be 1x1 matrices

stoic saddle
#
Let B be a square matrix such that det(B) = 1 and 2A + B = B^T - A^T. Find det(A+B).
bleak ibex
#

@sly plume

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#

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sly plume
#

.reopen

marsh citrusBOT
#

sly plume
bleak ibex
#

Well, if A is 1x1 it is just a real number a, and it's determinant and transpose are equal to a as well

#

This makes the equations really easy

#

@sly plume

sly plume
#

tell the numbers u have in mind then

bleak ibex
#

Well |A| = 1 so A = 1

#

Sry, B

#

Not A

sly plume
#

B is already 1

bleak ibex
#

A = 0?

sly plume
#

Oh nvm yh that makes sense ig

#

but there should a elegant method

bleak ibex
#

Also works if B is 2x2 identity matrix, but I gtg

bleak ibex
sly plume
#

.close

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#
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still temple
#

How can I find the term 2015 of the fibonacci sequence?

sly plume
#

Unless your allowed to use a computer that is

still temple
#

I thought there would be a formula in which I could use

sly plume
still temple
#

Wow

#

Really impossible

#

@sly plume thank you for the answer

#

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lime coral
#

Hey I need help with matrices

marsh citrusBOT
lime coral
#

Part b)

alpine imp
#

Hey I am doing a survey for maths and I am kindly asking if you could fill these out

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#

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ionic owl
#

[h = \sqrt{15277^{2} -(4153)^{2}}]
[h \approx 14701.67746]

elfin berryBOT
#

dopediscorduser

ionic owl
#

What am I doing wrong here?

proper lantern
#

round to the nearest thousandth

#

That's a hundreth

ionic owl
#

Now I'm confused