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Represent the following numbers as being members of set L: -15, 1, 7, 3, -8, 7, 0,
12, 6, 12
I wasn't here at the lesson I was learning this at school so I don't get how to answer this
Is there anything else to the question?
{-15, 1, 7, 3, -8, 0, 12, 6}
{-15, -8, 0, 1, 3, 6, 7, 12}∈L
Ah shoot what did I do wrong
oh,,
@still temple i just listed all your numbers without duplicates and put them in curly braces lmao
So what, you just write a set and assume the values in it are part of set L?
ohhhh
well the problem statement is a little unclear as written
maybe it had to be translated from a different language so we will never know
I assumed L was a set already given and you had to write that the numbers given were part of it
maybe {-15, -8, 0, 1, 3, 6, 7, 12} = L
Do I close this after finished..?
?
Yup
maybe ${-15, -8, 0, 1, 3, 6, 7, 12}\subseteq L$ if you wanted to say that?
layla💜
how should I close this..
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no
idk where to start
okay well let's see
what feature can a rational function have at most one of?
...okay, there are more possible answers to this question than i intended, but maybe thinking about this will spark some thought processes in your head.
from this, think about how many functions you need in order to satisfy your constraints.
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Guys really basic question. It's a graphing question
f(-1) = -2
f(1)= 2
f(0)=0
lim(x -> infinity) of f(x) =1
lim(x -> negative infinity) of f(x) = -1
Like I got all the points and have a general idea but for f(0)=0, would I have to connect those two other graphs or would it just be like a floating point
I'd probably connect them
yeah but like how
it's not very clear exactly
Yeah it really aint
straight lines or curvy lines or whatever might be fine
oh
Hey guys I have three questions that I need help in
I was wondering if anyone can help me?
uh you should ask in a available chat
ya, see #❓how-to-get-help 🙂
Ah thx
so yeah, it's literally can be anything -_- I'm overthinking it again
yeah it's 11 at night. Thanks layla ❤️
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np ^-^
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@warm obsidian Has your question been resolved?
<@&286206848099549185>
@warm obsidian Has your question been resolved?
@warm obsidian Has your question been resolved?
compare with $\sum_{k=1}^{\infty}\frac{1}{k}$
秋水
In mathematics, the limit comparison test (LCT) (in contrast with the related direct comparison test) is a method of testing for the convergence of an infinite series.
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Have I multipled the matrices correctly?
The top right corner should be -4+y-x
?
its a 3 x 2 matrix into2 x 3 matric
so it should be a 3 x 3 matrix as an answer
lol
Isn't it supposed to be a 3x3 matrix?
ye
so what did i miss
a whole column and row
Which multiplication did I miss? @nimble canyon
You go first row first column first row second column first row third column
then multiply corresponding element to each other
or that
x 3
Ok
Yup
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Hello, I found the two demarcation but i don't know how to continue
I know that i should find this equation but I don't know how to find it
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@fossil crown Has your question been resolved?
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Is this supposed to be geometric progression?
Now that I look closer… it appears that the comment was a little late to the party.
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How can I solve this problem using the method of characteristics?
Would applying d'Alembert's formula be considered a solution "by the method of characteristics?" If so, how would I account for the boundary?
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is there an official name for “a quad that has no para lines”
not really
i see
thats what it seems like too
even though some people suggest that a trapezium is one
that is not atrapezium
depends, there are trapezoids that have no parallel sides
and trapezium has one pair of parallel sides
i see, what are they called? surely there are ways to differentiate them from the other trapeziums that have at least one pair of parallel sides
i dont think there is a specific term for that
fun talk
oh hey again
this is the person that got what i meant last time, but shes also in the same boat as me
we still dunno how to differentiate it lol
hmmm, there logically should be wouldnt u agree?
since theres room for discrepancy
well if yyou consider kite a shape, then maybe you can call it a kite lol
and there are already ways to differentiate other higher numbers of parallel sides
it is insignificant enough for it to not have a name
like parallelogram for two, and the supposed trapezium for at least one
lmaoo
yeah true that, but kites are special tho
since they have two pairs of equal lengths
while not all quads with zero parallel sides have pairs of equal lengths
so a kite wouldnt work
plus the other properties
like the circle thing
gosh
why do you think there has to be a name for it?
because its a specific property, one thats already earnt other shapes their names
like parallelograms
theyre quads with two pairs of parallel sides
the next down is one pair, which is apparently a trapezium
but then theres nothing for zero pairs
logic whomst?
darn the greeks or whoever did geometry
im no experty, but it seems logical that there should be a name for this
well
thrs a lot of stuff with no sepcific names assigned to them
as u can easily write it in terms of other stuff already known
an example would be the set of all ints from 2 onwards
we just use like $\mathbb{Z}_{\ge 2}$
yeah true, could u possibly lead the way? im a noob when it comes to this stuff
or similar, thrs a lot of ways to
i see
so like
just find something that shares this kind of property and mix it with quad, or if theres none just translate it into latin and add the suffix -ium to it or smthn?
lmao
i feel like a very dumb scientist / mathmentician pioneering in very ingenius things that humanity has completely overlooked for thousands of years
wooo…
depressing ngl
maybe you could come up with your own name for this if it makes you feel any better lmao
lmao 😭
sigh is there really no better alternative other than going to sleep at this point?
owndjqjdnkakamda
im kinda interested in this as well since i got distracted with the quadratic equation
"okay, construct a owndjqjdnkakamda"
yknow, calculus stuff for finding the area
😂💀
id be damned if we really called it that
but then again, its not too far off from the likes of those scientists that coined the term “spaghettification”
ahahahaha
lol
im sorry, i think my brain aint normal at 4am
i guess ill revisit this problem another day, or just do as u say:
just make up a term for it xd
at least it gives you an idea of what that is, owndjqjdnkakamda on the other hand XD
you place too high of expectations on my interpretation of big words
lmao yeah fine i concede
true XD
aight have a good one mate, thanks for the laughs
good day to you
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Hello Im repeating some stuff about sets. what does "to the power of C mean"
complement
thanks
np
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is this just asking for the x coord of the maxima and minima of the y curve?
Critical points, I guess. $f''(x)=0$.
3317
yeah
thats what it is asking right
wait
isnt it just a single derivative
and then where it is 0
cus its a trig function
alr ez clap
just making sure thats what the horizontal stuff is
wasnt too sure
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✅
I have no clue how to format this correctly
oh I forgot the fucking minimum
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it is right statement right?
and does anyone know how can i write this kind of statements in wolfram🦆
,rotate
whole number 
whole numbers
usually we use Z for that
i mean i think all integers work even negative but i don't need them 🦆
Z is for integers not whole numbers
in what world are integers and whole numbers not the same thing
ok nvm just googled. weird stuff
so you want to say that $i^{4x}=1$ for all $x\in w$
that's it?
Denascite
In Wikipedia
{0,1,2,3,4,5…} = whole numbers
{…-5,-4,-3,-2,-1,0,1,2,3,4,5…} = integers
Yup
if you are gonna quote wikipedia, at least quote everything
what about
i^4x+n = i^n
also correct
Sure
i^4x+n = i^4x×i^n = 1×i^n?
thx 🦆 it wasn't mentioned in the book so i needed to make sure
? 🦆
The Wolfram Language supports logical operators not only for programming, but for mathematical operations as well.
well there is a way
but it's not nice
not sure why you wanna write these statements in wolfram
or do you just mean writing "i^(4x)=1" and wolfram solving to show you x in Z
@subtle pawn Has your question been resolved?
It's ez way to know if somethin is right
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What is the weight of a bowling ball with a diameter of 12 inches given the fact that one with a diameter of 8 inches has a weight of 10 pounds?\
anyone wanna help in this?
we do this by using the density
assuming they share the same density
for a ball we have:
$V=\frac{4}{3} \pi r^{3}$
~Martin
where V is the Volume
density is defined as mass/volume
diameter=8 => radius=4
,calc (4/3)pi*3^3
it weighs 10 pounds
so we get a density of
,calc 10/((4/3)pi*6^3)
Result:
0.011052426603604
to get the mass of the bigger ball we first need the volume
Result:
113.09733552923
sry i got some values wrong
you put it to the power 3 since r is cubed right?
,calc (4/3)pi*4^3
Result:
268.08257310633
this is the volume
mass is 10 pounds
density=mass/volume
,calc 10/((4/3)pi*4^3)
Result:
0.037301939787163
this is our density
for the bigger ball we first get the volume
,calc (4/3)pi*6^3
Result:
904.77868423386
density=mass/volume
therefore
mass=density*volume
to get an exact answer, i wont use the result from before but rather the formula used
@worn nimbus
,calc (10/((4/3)pi4^3))((4/3)pi*6^3)
Result:
33.75
and there we have our mass
otherwise we could also have used the fact that mass and volume are proportional
why did you cube it?
that is just the formula for a volume of a sphere
yes, that's correct
proportionality also works
i must admit this was a bit overcomplicated haha, but i guess it works as well
suppose you have a cube with sidelength one
then now suppose you have a cube with sidelength 2
how much more volume does the cube with sidelength 2 have
this doesnt justy hold for cubes
its for all shapes
times 2
np
we then multiply it by 10 since we are trying to find the weight of 12 inch bowling ball compared to the 8 inch one
for these type of problems we would do big to small for ratio right?
exactly
but beware of what ratio you start with
suppose you start with the ratio of areas
then you wouldnt cube that ratio to find the ratio of volumes
usually though the ratio of lengths is where you start
ic
what would we do then?
well you have 2 dimensional ratio
so to find the 3 dimensional ratio we would do (2d ratio)^1.5 since 1.5 * 2 = 3
no then you would get the 4 dimensional ratio
we care about the 3
since we are dealing with 3d ratio right?
well if you want the 3d ratio you would do that yes
perhaps i overcomplicated it
but i think you understand
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i am having trouble with this
i know that its III
i am having trouble figuring out whether its I or II
@molten venture Has your question been resolved?
I understand that it becomes ln(n+1) - ln(n)
however the only value remained is ln(1)
ln(1)+ln(n+1), bc there will be always a last term that doesn't cancel out
.
Yes
And to test for convergence just take lim as n approaches infinity
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ngl i prefer this over forums
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absolutely anyone who has any say in forums/help channels won't read it here
Wdym?
i imagine at some point one of these will go away
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How do I graph a relation in which the "y" is an absolute value. For example, how would I graph |y|=2x^2
You would graph when y = 2x^2 and -y = 2x^3 simultaneously
Good job Pure
I saw that

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And the question
0,-4
Nope
Look at the information above
It specifically gives you the x-value of the global minimum
That's the minimum as a point, yes
Now, if the equation has the minimum at (3, -4) and is a quadratic, then two things:
Would that make sense
Think about it
Yes the vertex is (3, -4)
But if it's opening down
Yeah no that is not a minimum
This question essentially is checking if you understand parabolic behavior
The vertex is a minimum when the parabola is opening up
The vertex is a maximum when the parabola is opening down
If needed, draw a diagram
But it physically evinces itself
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Can someone explain this graph to me ?
How is it going in the negative side,as:
Cos(-x) = cos(x)
cos (2npi + x) = cos (x)
for all n in Z+
that still lies in the first quadrant right ??
if i take n = 1
cos(2pi + x) = cos(x)
and the value is +ve
so cos -90 = cos 270
does that make sense to you
wait did you learn radians yet
but we can write cos -90 as -cos90 right ?
not sure
bruh
don't think so
isn't cos(-x) = cos(x) ?
yes so how is the graph going in the 2nd and 3rd quads ?
ok going by that too
cox(-x) = cos(x) which again is +ve 💀
what
take this
take what ??
proved
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0 doesn't verify 0(2) = 1. So it's not in Q. Therefore Q isn't a VP
sorry i think i have trouble understanding what a 0 polynomial is then
The constant polynomial equal to 0
It is usual to associate/identify constant polynomials to their value
so there should be a polynomial in every subspace of the set of polynomials where every output is 0?
and because 0(2) != 0 then this 0 polynomial doesnt exist?
A subspace is a vector space, which is a group. It must therefore contain the neutral element, which is 0. Therefore if a set doesn't contain 0 it isn't a VP
The 0 polynomial does exist. It just isn't in Q. These are 2 very different statements
nvm it just wouldnt be in the subspace
would it be correct in saying that this 0 polynomial doesnt exist in Q?
can you go over how you input a number into a constant number
Because something either exists or it doesn't. We don't want that property to depend on a certain set
like if 0 polynomial is a constant how would you input a number into it
As I said, we associate constant polynomials with their values (and polynomials with their polynomial applications, but that's another topic). So when I wrote 0(2) I mean (x -> 0)(2), which is a (polynomial) function evaluated at 2
5 into (x)^0 I can input any real value of x here, for example
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How do I proceed :/ ?
could you post the whole question?
what i meant is the multiple choices
alright, and what have you tried?
ok, so I suppose limits is available to us?
if not, you can brute force it by just solving for y in terms of x
and then find the domain from there
Limits available as in ? 👀
This is the entire ques
as in, is limit available as a tool for us to use?
Yea u can use whatever u want as long as u r getting the ans
Preferably something which is quick
actually, there is something quicker than that, nvm then
right, so let us rewrite the constraint as 2^y=2-2^x
Pls tell 😈
this is pretty obvious
Yep it sure is
now, since 2^y is strictly positive, this must means that 2-2^x>0
do you follow with this statement?
How did u assume that y is always positive 👀?
i did not assume that y is always positive, I stated that 2^y is always positive
y can be negative, 0 or positive
but 2^y is always positive
this is just the property of exponentiation
Oook got that
right, so it must mean that in order for the equation 2^y=2-2^x to be true for some arbitrary x, then it must mean that 2-2^x>0
for example, take x=2, then 2-2^2=-2, but 2^y=-2 has no real solutions for y
so do you have any question at this point?
What do u exactly mean by real solution of y ??
can you find a value for y such that 2^y=-2?
yes, there is no real values of y such that 2^y=-2
meaning x=2 is not in the domain
Ah ok
but anyway, so as long as 2-2^x>0, meaning as long as the rhs is positive, there always exists a real y that satisfies the equation
so all clear?
Yes understood
right, so all we need to do is to solve for x in 2-2^x>0
Or we can also write it
2>2^x
yes
So from this we can conclude that x = 1 and it has got a real solution?
no
No, how ?
you could also see why it's not true because 2^y=0 has no real solutions too
have you solved inequalities involving with exponential functions before?
Quadratic ones yes
quadratics are polynomials, not exponentials function
But those ones were not strictly increasing or decreasing
Oh sorry
Then no i haven't
alright, nvm all that, if i gave you 2^x<=2, then could you solve for x here?
x = 1 ?
that is one of the solutions
Isn't that the only solution?
again, we are solving an inequality
Oh ok
alright, it seems like you are not very familiar with these types of inequalities, let's solve it with me then
oh nvm
(-infinity,1] ?
yes, (-infty, 1] is the correct solution
now that is 2^x<=2, what about 2^x<2?
(this is just us removing the equal sign, so remove the solution when the equal sign is true)
(-infinity, 1) ?
Wow that so freaking smart
Thanks
Never thought of this ques like this
And yes the ans is also right
Thankkkksss
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hi guys i have a question
what length of tarapulin 3m wide will be requited to make a conical tent of height 8m and base radius 6m? assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm (use pi = 3.14)
pls help
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<@&286206848099549185>
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so as in we just compare surface areas?
then add 20 cm after?
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What should I do to look for the radius and interval of convergence after getting here?
I got stuck
$\sum_{k=1}^{\infty} \frac{2^k}{k² 3^k} x^k$
Herels
with $a_k = \frac{2^k}{k² 3^k}$
Herels
now to find the radius of convergence, you use d'Alembert
why do you want to do that tho
I'll try it out
do you know about d'Alembert tho ?
Yes, ratio
ratio of what
Its the ratio test with the limit
yea but ratio of what
ak+1/ak
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Hey, I am currently searching for a function without condition and defined in R which returns 1 when a number is a solution of n(n+1)/2 et which returns 0 in all the other cases ? Do you have any idea?
$f(x) = 1$ if $\exists n \mid f(x) = \frac{n(n+1)}{2}$
otherwise $f(x) = 0$
Lynox
@river lance Has your question been resolved?
This
U want a polynomial function
?
I don think polynomial function exist for this
they don't
the function described is clearly not continuous so you can't get it with polynomials or something like that
Yeah
you could do some weird stuff like $f(x) = 1 - \left(\ceil{\frac 12 (\sqrt{8x+1}-1)} - \floor{\frac 12 (\sqrt{8x+1}-1)}\right)$
Denascite
How?
if x=n(n+1)/2, then n=1/2 (sqrt(8x+1)-1)
if n is an integer, then ceil(n)=floor(n)=n, so ceil(n)-floor(n)=0 and f(x)=1
but if n is not an integer the ceil(n)=floor(n)+1 and so ceil(n)-floor(n)=1 and f(x)=0
or you could probably find a lot of other functions which are 0 if input is integer and 1 otherwise
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i need help on these two geometry questions
@worn fractal Has your question been resolved?
9: 14x-1 = 12x+17
for 10
the two angles are supplementary
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Please explain to me the step by step process on this
I'm particularly confused how there is a +2 and how -1 was added in 4cos theta
cos theta factored from first two terms, 2 factored from the last two terms
Ohhh
Aight thanks, got confused and thought you factor cos theta to all
thanks
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Which poligon has 35 diagonals? i'd need the steps and the result so i can see how to solf in the future, thank you!
polygon*
In any n-sided polygon, each vertex can be connected to n-3 other vertices (not itself or its adjacent vertices.) Can you come up with the formula for the number of diagonals for an n-sided polygon (careful with over counting.)
yeah i know the formula for that, its n*(n-3) divided by 2
but im getting stuck on how to calculate the n when im given the number of diagonals
$\frac{n(n-3)}{2} = 35$
Pure
This is just a quadratic
so
n(n-3)=d/2?
oh wait no
it would be d*2
so now im on n^2 - 3n = 70
what now
@glad tundra Has your question been resolved?
Do you know how to solve quadratic equations
sort of, but i'm having problems on this one
can i just get the formula for n so i can have it for future refrence, i am very lost currently
@glad tundra is this your questions ?
yes, i would like the formula to solve for n
Oh ok
n²-3=70
n=+and-√67
Wait
Shit
What I am doing
waut hold on wouldnt it be n^2 - 3n =70?
Yeah
That's what I am talking about
It would be the quadratic formula
n²-3n-70=0
ooh right
Yupp you can solve it form here?
yeah thank youu
Welcome 🫂
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How is it supposed to solve this problem? I mean which formula should i use
I tried different things but can't solve this
wait
it means arctan
Yes i can derive arctg12/5 from the triangle
W what am i supposed to do 
Ok, I'll get arccos +arccos. Is there a formula for addition of two arccos?
Thank you
Where can I find those formulas?
like
you shouldve calculated the sin and the cosine
of the angles
as was suggested
@fleet sierra Has your question been resolved?
,w sin(arccos(12/13) + 2arctan(5))
,w cos(arccos(12/13) + 2arctan(5))
hence the top angle is -pi
repeat for bottom one
,w sin(arcsin(8/17) + 2arctan(4))
,w cos(arcsin(8/17) + 2arctan(4))
hence the bottom angle is also -pi
so you're just evaluating arctan(-pi/-pi) = arctan(1) = pi/4
yes
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hello guys, im a bit confused with the question, it says
find value of dy/dx at point (1,-2) which lies on curve 2x^2 +3y^2-6xy=26
what does this question mean? to first input the points to the curve then find dy/dx?
or to first find the dy/dx then then input the points?
if you inpt the points first, then you'll now have a number, and can't differentiate the function anymore
asit is no longer in terms of vriables
yess
so differentiate first
it would be the ratio of change in distance in the y direction to the change in the x direction, if you took a small step in the x direction
what do you mean? hehe
so, assume you move a very small distance $\Delta x$ in the x direction on the given curve, then if $dy/dx = a$, it means you will move $a \cdot \Delta x$ distance in the y direction to stay on the curve
Sharl Eclair
is this correct?
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Every natural number from 1 to 15 (incl) is written down on a cardboard card, where each cardboard card has a number on it and none repeat. Four cardboards are drawn at random. What is the probability that among four cards drawn 8 is the lowest number OR 12 is the highest number?
combinatorics got me good
So 15 choose 4 is what we divide by a
And I have a sneaking suspicion its gonna be 7 choose 3 divided over it + 11 choose 3 divided over it again
at the same time something feels a bit off about it like I have to divide possible all combinations of 8 by only the ones i need
i would do
7c3 + 11c3 − 4c2
why the 4c2
there's overlap
(it's 3c2 my bad)
ah right makes sense
wowzers again not so difficult once you see the answer 🤣🤣
thanks mate
if you ever have the hearthstone quest do let me know I will do my best to log in an play a friendly game 😝
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Boss how do you go about determining size of overlap at first glance it seems 3c2 cause if 8 and 12 are fixed that leaves 3 numbers between 2 slots?
4c2 was a mistake yes
Right
i wrote the numbers to see the sizes
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Little something from class why is 11/36 added again isnt the 11/36 counting both die and the potential swapping in their positions
Is it all possibilities with 3 and then same for 6 ?
,rccw
then I get the vibe that | 3 | 6 | combinations overlap 🤔
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Hi can someone help?
15th question
What's the question?
This is just a matrix with an unknown exponent
There must be something else. What do the directions say? There is no question here
Find multiplication of matrices
Matrix calculators show step by step solutions
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help please
Idk what to do for this
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here again 😭 dont know how to do any of this
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Obtain the differential equation by eliminating the arbitrary constants
y=Ae^(-3x)-Be^(2x)+Cx^3
I tried getting up to the 3rd derivative, but i don't know what to do next
@wide wind Has your question been resolved?
Looks like a linear algebra problem now
yeah, i also tried doing this method, but because of the x variable beside c, i can't add the equations
Oh hmm I'm stumped then
and i can't move the x variable outside since the last equation only has 6C
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<@&286206848099549185> help🥺
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the derivative of arctan(x) is 1/(x^2+1) there is not supposed to be any sine in there
too bad you shouldnt have trusted photomath then
cuz i tried like 8 times beforehand and got it wronmg every time
try to do it by hand

have you learnt implicit differentiation?
ye
if you are finding it too ugly to differentiate, try taking tangent on both sides first and then differentiate
one sec lemme do it again and ill send my work
okay
oh ignore the first bit
that was my last try
im nmot sure whats wrong abt it
you didnt distribute correctly
if you wanted to distribute 1/(1+whateverishere) into 1-x/sqrt(1+x^2), it should have been $\frac{1}{1+(x+\sqrt{1+x^2})^2}-\frac{1}{1+(x+\sqrt{1+x^2})^2}\cdot\frac{x}{\sqrt{1+x^2}$ instead
and bot is dead
wonderful
basically, you didnt distribute correctly, the fraction should have been multiplied to x/sqrt(1+x^2) as well
but there was no need for you to distribute, just leave it as is
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How can you solve this with Wolfram?
,w {{-4,-2,4},{8,4,-10},{2,1,-4}} * {{x},{y},{z}} = {{6},{-12},{-3}}
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what's a preimage
use gugle
given a map f: X -> Y and a subset B ⊆ Y, the preimage of B by f is denoted f^-1(B) and is defined as f^-1(B) := {x ∈ X : f(x) ∈ B}
omg! why didn't I think of that earlier!
ah
thanks
(well tbf you do find the answer with google)
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Is that right?
Looks right to me

should have f(x) instead of f(3) in that main first line
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Question no. 6 please
,rotate
Bit of a cheat method, but they could be 1x1 matrices
Let B be a square matrix such that det(B) = 1 and 2A + B = B^T - A^T. Find det(A+B).
@sly plume
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✅
What matrices do u have in mind?
Yes that's the question
Well, if A is 1x1 it is just a real number a, and it's determinant and transpose are equal to a as well
This makes the equations really easy
@sly plume
tell the numbers u have in mind then
B is already 1
A = 0?
Also works if B is 2x2 identity matrix, but I gtg
Probably, I dont like this as well
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How can I find the term 2015 of the fibonacci sequence?
I doubt it's possible for humans
Unless your allowed to use a computer that is

I thought there would be a formula in which I could use
Nope nothing like that u have to find 2014 th and 2013th term manually..
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Hey I need help with matrices
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[h = \sqrt{15277^{2} -(4153)^{2}}]
[h \approx 14701.67746]
dopediscorduser