#help-33
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Hmm
Is it just because DeMorgan's law only works with single complement terms?
Well, it's iterative.
So you can use it for infinite compliment terms, but you have to flip the sign every time.
Okay so with !!(DB) you started with the most internal complement and broke it up, but left the top one alone
(DB)cc = (Dc + Bc)c
Yeah
You can then break up the next one, but you have to flip the sign again
So you get:
Okay okay and if we did it again it would just undo what we did.
Okay. This helps.
I hate writing double compliments. There's not any practical reason to write them. If you see two compliments over the same term, just cancel them and skip the confusing stuff in the middle lol
E.g.
(DB)cc = DB
Similarly,
Dcc = D
Etc.
Yeah I know I can just use double complement law for sure. But I was worried that if I don't thoroughly understand things I'll be mega confused later
That's fair.
I always ask why instead of just accepting things for what they are lol
Thank you. I appreciate the time that you spent here with me.
No problem. I needed an excuse to avoid my own homework haha
What are you working on?
Current problem:
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How do I factor x^3+5x^2-x-5
try approaching it with grouping
try grouping it and see if something interesting happens
(hint: something interesting should happen)
@wet peak Has your question been resolved?
$$x^3+5x^2-x-5 = \blue{(x^3+5x^2)} + \orange{(-x-5)}$$
can you factor the blue and the orange individually
ℝamonov
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Find the largest volume of a cube with the maximum surface area among the cubes
that can be enclosed in a sphere. ( r = 1)
This just over complicates things
then how do i ?
You know the diagonal of the cube must be 2
sure
Use Pythagorean theorem
wait me
Let’s say side length of the cube = a
?
hey
a.b.c>0
No
Yes
aha..
i forgot the z
then x^2+y^2+z^2 = 4 right?
f(x,y,z)= 2xy+2yz+2xz subject to: x^2+y^2+z^2 = 4
is this a right way ?
i thought r=1, dianoal is 2
yeah
Equation of a sphere
Anyway back to our problem
okay
$a^2 + a^2 + a^2 = 4$
Pure
what about a rectangular?
Probably tbh I’m not really sure
I’ve got to go very soon
not xyz?
2x 2y 2z multiplied together
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What happens when an exponent is a fraction with a numerator greater than one? Like 4^(3/2)

Oh ok thanks that makes sense
Do I need to type some command to close this problem now?
.close
.close
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If a drink containing 40% alcohol is mixed with an equally large drink containing 30% alcohol, what would be the alcohol-percentage in the mixture?
we might want a variable for the size of the drink here
@white willow Has your question been resolved?
700ml
both of them are 700ml
ive been struggling with combining percentages
First one is 40%, so 40% of 700ml
well I suppose there's a shortcut as well
Second one is 30%, so 30% of 700ml
since it's the same amount each time you average the percentages
The danger is there's some scenarios where this doesn't work
like, alcohol posioning?
:O
moni has obesity, so he runs quite slow
lol
but i was thinking
if we take the pure alcohol of both drinks
and add them together
then take 700*2
and divide the amount of alcohol by that?
u just average 30 and 40
yeah
u get (210+280)/(700*2)
69110 and then close
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At a traffic light, a two-digit display shows the number of seconds before the light turns green. The digits on the display are are shown in Figure 1. Part of the display is obscured by a vehicle (see Figure 2). On the visible part of the screen, the light was the same a second ago. How many different two-digit numbers the display can show now?
trying to visualize how many types of number there could be
considering that the visible portion of the traffic light was the same a second ago
there is 3 or 2 solution less
wait
because this shows the seconds
the second digit cannot change
which makes it into this
what makes it into 3
it's just 2?
why do you think its 2?
digit 2 is fixed and digit 1 is two or three
or 7
right my bad
thanks for the question tho
i go close this
thanks for joining me btw
cya
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There is a team that has 10 members and they clean up weekly, cleaning can be done in 2 hours 48 mins when all 10 members are cleaning how long it takes when 3 members taking free time (not cleaning)?`
ambulance driving at 80 km/h and arrived at the hospital in 30 mins , if ambulance was driving 100 kmh how quickly he would be arrived to hospital? (only in minute answers)
sorry for my english
there are the questions im stuck
<@&286206848099549185>
@little schooner Has your question been resolved?
no
@little schooner Has your question been resolved?
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(-4,4) means x=-4 and y=4. Does that make the given equation true?
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What's giving you issue?
a looks fine
b has argument x, not 6
Actually b is slightly off further, it looks like you constructed f ° g instead of g ° f
Double actually, why are you asking for help on an exam?
this is a redo exam and the teacher said i could use any means neccesary
as long as i go along and learn it
Fair enough
so would i subtract 12-5 then multiply 1/36 by that?
or multiple 1/36 by 12 then subtract 5
PEMDAS applies here, right?
g(x) is 2x - 5, and you need to multiply f and g
So which of those do you think is more appropriate?
well, on the first question, follow pemdas...
so id multiply 1/36 by 12
to get 1/3
Your pemdas changes if you introduce parentheses
(1/36)(12-5)
What would you do now?
then multiply whatevers in the parentheses
but i keep the parentheses when i multiply 6 and 2?
Yes
so then the -5 would still be out of it
So you clearly understand f*g(6) = f(6)*g(6), which is good
right
However, I think you need to pay a little more attention to the following algebra
1/36 * 12 doesn't work, because 12 isn't g(6)
If you compute f(6) and g(6) separately, what are they?
So their product must be 7/36
Perhaps seeing f*g as (f)(g) would help
So you naturally include the parentheses needed
Because (1/36)*12-5 and (1/36)*(12-5) are not equivalent
No
That I agree with
ok, so whats the first step
Well what's 2 * (1/x^2)
2/x^2?
Yep
so 2/x^2 - 5 is the answer?
thats as simple as it gets, right
cant really evaluate if the variable isnt a number...
Unless your teacher wants you to remove the x^2 from the denominator
ooh right
But otherwise yeah it's complete
likek sovlve for x
right, ok
But you could rewrite 2/x^2 to not be a fraction
Whether or not it's required is up in the air, but it's an option
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Could anyone explain to me why ln(1+x^2)=2ln(x) +ln(1+1/x^2) please , I feel dumb not understanding this
2ln|x| though
$2ln(x) + ln(1+\frac{1}{x^2})$=$lnx^2 + ln(1+\frac{1}{x^2})$=ln(x^2(1+\frac{1}{x^2}))$
Springsskateboard
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oh yeyeye^^
@hollow crater Has your question been resolved?
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i feel like im forgetting something but is there a law where it goes something along like 1/x=1/y then x=y
if they have the same numerator can you do something like that
yes
do you know the know the name of the law? i'd like to look more into it
It’s commonly referred to as “cross-multiplying”
cross multiplication
justified algebraically by multiplying both sides by the product of the denominators (or to be more efficient use the lcd)
no dont be like that
i get humbled by math every day
me too man me too
its part of the process
part of why i love it so much as well
hahah yeah weirdly yes
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How to solve this problem on paper?
All I have been told leading up to this problem is this
"If one task can be accomplished in x different ways and, following this task, a second task can be accomplished in y different ways, then the first task followed by the second task can be accomplished in x * y different ways. (This counting principle can be extended to any finite number of tasks.)"
An even number is one whose last digit is a multiple of 2
I have 6 numbers to choose from, for the hundredth place.
I have 5 numbers to choose from, for the 10th place.
The choice for the last digit depends how we chose the first two
Case 1: First two digits are odd
6 x 5 x 3 = 90
Case 2: First two digits are even
6 x 5 x 1(?) = 30 (I have my doubts...but if both are even then we are only left with a single even number innit?)
Case 3: One of the first two digits even only
6 x 5 x 2 = 60
Wrote a python program and the answer is indeed 60, via bruteforce
lst = list(filter(lambda x: x % 2 != 1, range(100, 666)))
# print(len(lst))
count = 0
for i in lst:
if set(['0', '7', '8', '9']).isdisjoint(set(list(str(i)))):
if len(list(dict.fromkeys(str(i)))) == 3:
count += 1
print(count)
I was hoping to gain some insight but..., the program just counted the numbers via brute force.
Also is it coincidence that the arithmetic average of 30, 60, 90 equals 60?
A number is even is it ends in a multiple of 2 so that is 3 choose 1. Then you choose 2 numbers for the other digits, which is 5 choose 2, and 2 ways to order those 2 aforementioned digits.
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.reopen
I am sorry, what does choose mean?
3 choose 1 is the number of ways to pick one element from a set of three
The last digit has to be 2 4 or 6. That is 3 choose 1. There are 2 more digits to select among a remaining pool of 5. That is 5 choose 2. Those 2 digits can have any order. (3 choose 1) x (5 choose 2) (2 choose 1) = 3 x 10 x 2 = 60
For example, select the 6 to be the last digit (3 choose 1)
You can now choose between 1 2 3 4 5. Lets choose 2 and 3 (5 choose 2). So now there is either 236 or 326 (2 choose 1).
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oh right
no its not

it is not that, the inequalities are not a<b and b>a, they are a<b and b<a in this case
its about the logical definition of if then
"If [false statement] then [WHATEVER]" is always true
^
or if you speak latin, ex falso sequitur quodlibet
ah
Using this
I'm gonna destroy arguments with that
But also
It's true because if 2 > 3 is false then 3 > 2 is true
Something like that
oh i completely misread it yeah
can f and g have the same limit at a?
I know, I'm asking you based on the information in the premises, can f and g have the same limit at a
(the answer is yes)
If f and g were continuous, the result would hold, but allowing for discontinuities allows us to come up with this counterexample where f and g both limit to 0 at 0, but f<g over R
is this a completely consistent rule or are there exceptions
Well there's nothing saying whether f or g can be discontinuous so there's nothing wrong with choosing discontinuous functions as counterexamples to the statement.
In logic, (If A then B) is defined to be false when A is true and B is false, and True for any other truth values of A and B.
so yes, it is completely consistent
there are no exceptions
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So whats the actual logic behind it, if a false statement is true we have no way of disproving another statement?
I dont want to waste your time(and distract the channel from Rayaans question, any reading about this you'd recommend or the actual concept name?
vacuous truth is what it's called
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thanks, also did some reading into the princple of explosion
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Hi
A => B means "If A then B"
A <=> B means (A => B) and (B => A)
so "If A then B, and if B then A"
so "A if and only if B"
logical equivalence
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what the fuck is this
some ppl say its not a parabola and why does it go in a straight line
how the hell does y go -10, -9, -8 ,-7, -6, -5, -4
can barely see it
some people say the graph of f(x) = (x+1)^2 - 8 is not a parabola?
is that what you are saying?
yeah, it is one
yes
who is saying that?
I was trying 2 get help from other ppl but they say its not a parabola
they're lying to you lmao
ok
a parabola this graph very much is
but then when u plug in the other numbers its a straight line
also do not omit the parentheses when writing down a point via its coords.
also show exactly what you are plugging in and what results you are getting. where is your table of values?
I will bet money you're missing parenthesis
ok then show your table of values.
ok let's go through those one by one
ok
how did you get -10 for f(-3)?
yup. This is the graph of (x+1)-8 or x + 1^2 -8. you're either missing the square or parenthesis.
-3 +1 -8
no
no, it would not!
yes
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I think the right way to think about this kind of question is, "What is the probability that the first letter is a B." Then, "Assuming we got a B for the first letter, what's the probability that the second letter is E" etc
so like NCR(10,1) *NCR(9,1) etc?
like 1/10 * 1/10 * ...
Yep okay, so that is the right for question c just need to divide it by NCR(10, 4)
Because it is a probability so you would have to divide by the total number of possible outcomes
like how many combinations
ok, it's fine to do it that way- then the number of correct out comes is 1 * 1 * 1 * 2
and the number of total outcomes is 10^4
ncr doesn't get you what you want in this case
Oh okay, but what about D though, since there isnt any replacement?
how many outcomes are there for the first draw?
think about it logically over memorizing a formula
10 outcomes because it have 10 letters right?
right! but how many outcomes are there for the second draw?
9
ok, i think you understand
so I do that 4 times because it is 4 letters I need right?
yeah -on the third draw there will be 8 outcomes
So how would i write that as a probability then if I know how many outcomes there are?
how many correct outcomes are there?
1098*7= 5040
wait I mis wrote my last question it is 1098*7=5040
yeah
oh, i was about to say something wrong
actually zero
right?
there's only one b
but if we were trying to spell bear, it would be two
Yeah that is what I was confused about at first but I thought that there had to be a solution that i was not seeing
because you can use the black r or the white r
yeah, i think you were right
but now you know how to do this if it asks about something that's actually possible haha
So wait, sorry to ask again but how do I do C exactly?
ok, so how many outcomes spell bear?
all g so that is how I get the full probability right?
yeah that would be the denominator
ah okay so then how would I find the ones that spell BARB?
well without replacement there are zero outcomes
if it were with replacement there would be 3 for the same reason
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you too!
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(solve the question using the formula below) I seriously cant figure out how to do this as my answer always either goes above or way too low
ah yes, the classic "use this formula, except we deliberately give you the wrong formula for your problem!"
i was thinking the same thing lmao
i wanna message my teacher to see if it was just a mistake but she doesnt even read my messages 💀😭
so classic
okay we can assume it's talking about geometric progressions and (a_n) is such a progression
even tho that's kind of a big ask
without any more context, that is
but then like. the formula you've shown gives the SUM of the first n terms of the progression
i mean, yeah considering her who doesnt explain things any further, that might just be the case
and you are asked only for one term
yeah that problem exists...
so... bit of a wtf moment there
well i can just skip this one since i've solved other problems similar to this that i managed to solve but just this one...
well like
a_6 = a_1 * r^5
but this does not make use of the formula and so might be rejected on those grounds alone
what is S_n? is it the sum a_1 + ... + a_n?
sn = the number that came out using the formula
so you do know this number?
aren't you asked to figure a_6?
yeah
the thing is, i got an answer but its way too far from the answer i got just by computing 4 x 3 again and again
the answer that came out using the formula needs to be the same as the one i just computed by doing 4 x 3
i kinda don't understand, they want you to figure out S_6 and a_6 at the same time using this single equation?
i mean, if the formula wasnt necessary and i can just compute it however i want then yeah
but sadly the formula provided needs to be used in that way
<@&286206848099549185> is this just wrong or im dumb?
You're asking if the formula provided is appropriate for the question asked, yes?
the formula you were given is for the sum
@halcyon rune Has your question been resolved?
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In your own words please define to me the meaning of Interpolation Search Algorithm (Position Probing)
@cyan crypt Has your question been resolved?
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[Statistics newbie]
I don't understand this concept.
Wasn't "sum of squares" the sum of the residuals (i.e. the distances of each data point from the line) squared?
Shouldn't the result be a positive value above 0?
Is this even a question 😒
Even a kid can solve this
What about my question?
Also in math terms, when they say that an equation Q1 performs worse than a Q2 equation, does it mean that Q1's result r1 is smaller that Q2's result r2?
So Q1 is less accurate than Q2 in my example?
In what context you said q1 is worse ?
And by result do you mean value of each equation when put with a specific value in both of them
For example when we put x=3 in 3x²+4 we get 3*3²+4= 27+4=31
Uhm, let me get the notes
Here, he says that if we would to consider in an analytic context that mouse size is influenced by all of those parameters, they would get reduced to 0.
So this equation wouldn't perform worse than the one on the bottom
.
Because both these equations are exactly the same
It's simple
You can write 3y³+5y as 3y³+ 0y²+ 5y +0
Yeah but what if one of those parameter was instead multiplied by 1?
Why would you say that the above one performs worse than the bottom one?
If those parameters really have got something to do with mouse weight, multiplying by a coefficient would give you a more accurate answer .
If those parameters are of no use , multiplying by a coeff gives you a less accurate aka a worser result
Yes but one thing , you have to use the proper coefficient not any arbitrary number
?
I'll learn what you mean along the way I guess, right now though I'm attending class, sorry to cut our conversation short, if I didn't the bot probably would have eheh
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the top one
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what is this method of rationalising trigs called?
I don't recall having a name for that technique. Just "multiplying both sides of the fraction with a constant", "expanding the expression", and "Pythagoras theorem"
so rationalising trigs is a thing?
hadnt seen anything like this except in case of irrational number
i think its quite specific to this Q
I wouldn't give any generality to this method. Most trig stuff is just about rewriting and since it's an exercise there's got to be a way that works
right
It's a thing for basically every rationals ever
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how would i start this? i think i can make a exact value traingle using x/2
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I need help to solve this
If polynomial p(x)= x^3+x^4+x^5+…+x^2021 divided by (x-1)^3 leaves ax^2+bx+c then find the value of 4a+2b+c
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Find the volume of a quadrangular prism whose base is a triangle with base 4.2 cm and height 3.8 cm and the height of the prism is 10 cm V = ??
@still temple do you know your way around special points on the graph of a function? i.e. ones at which the first or the second derivative is 0
yes, dy/dx = 0 gives you stationary points and d^2y/dx^2 = 0 gives you points of inflection
blink blink
sorry that was a little too word-salady for me and i got thrown off track lmao
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expand it
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expand $(\vec{x}-\vec{y}) \cdot (\vec{x}-\vec{y})$
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秋水
$\vec{x}$ and $\vec{y}$ are orthogonal, so $\vec{x}\cdot \vec{y}=0$
秋水
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so you get the answer
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pythagrawr
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The two vectors inside are perpendicular to n.
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@still temple Has your question been resolved?
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Just a suitable set of solutions is okay, you can let a = 1.
the other is 1*c+2*0-3*1=0, you can get c straightly
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The way span is written is not unique
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As long as the two vectors inside are linearly independent.
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when a=1, the two vectors are linearly independent, you can check, so you can let a=1
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✅
vector a and b are linearly independent if a≠mb (m≠0)
so it's easy to see
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that's from the definition
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the plane equation is
$\vec{n} \cdot (\vec{x}-\vec{p})=0$
秋水
just calculate it
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$\vec{x} = (x,y,z)$
秋水
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what do you mean?
$\vec{n}=(1,2,1)$,$\vec{p}=(1,0,1)$
$\vec{x}-\vec{p} = (x-1,0,z-1)$
秋水
$\vec{n} \cdot (\vec{x}-\vec{p})=(1,2,1) \cdot (x-1,0,z-1)=x-1+(z-1)=0$
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I need help to solve an exercise about functions and function limits.
First of all you can simplify (x^3 - 2x^2 + x - 2)/(x - 2)
okk
so one moment I write down
ok this is the simplification
Now I can delete x-2
define x=2 separately
If it was zero, it wouldn't be as simple as to just cancel out
exactly what is being done in f lol
ok, this is clear, so remains
x^2 + 1
ye find the turing pts of it
So the range of outputs on [-1, 3] is the same as the range of outs puts of x^2 + 1 on [-1, 2)U(2, 3] united with {a}
wait im drunk LOL
so I have to write
[-1, 2) U (2, 3] U a
No
oh sorry I didn't understand this passage
(range of x^2 + 1 for x in [-1, 2)U(2, 3]) U {a}
aaah okkk
ok and now how can I proceed?
That's not it but okay forget it
Just find the range of x^2 + 1 on [-1, 2)U(2, 3] first
i like to draw it
I know the scription is uncorrect
okk I try
,w graph y=x^2+1
omg bad scale
Post your question in an available help channel
ohh okay okay
sorry but it's my turn. Wait a minute please
AH sorry i just joined i didnt know
In x = 2 the function doesn't exist
no problem :D
👽
ty!!
thus that circle
So I have to find the range separately?
1 ≤ x^2 + 1 < 2
and
2 < x^2 + 1 ≤ 3
well
i kinda alr gave it to u
and what 'bout "a"? How can I insert this parameter in a range?
yes this is clear but how?
Sorry if I seem stupid, but I really am ahaha.
So these are the ranges:
1 ≤ x ≤ 2 and
2 < x ≤ 3
those r the domain
idk
trivially just put f(x) as x->2
would always work as polynomials are cont
lim f(x)
x->2
Theorically I understand, but I can't solve it algebrically
MAYBE I DID IT
So
if I put:
do u think that this M.O. might be correct?
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Can anybody help me with d, Im not sure what the question meant
Question . Im trying to convert -225 into radians. I got -5pi/4 . I know that its going to be -225 * pi/180. I broke down 225(45 x 5) and 180 (45 x4), after canceling everything I ended up with -5pi/4. I looked up the answer and its -37pi/30......where did I go wrong? @marsh citrus <@&286206848099549185>
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$(1 + i)^{12}$
ahmed349
Is binomial theorem the only way to do this
You would usually write 1+i in polar coordinates instead
Polar coordinates?
Like $re^{i\theta}$ form
tatpoj
Ah not familiar with that unfortunately
You can imagine a complex number as a point on the complex plane, sort of like a vector.
It has a magnitude r and a direction theta
Then re^(i*theta) is equal to that complex number
1+i is like the vector [1,1]
Do you know what its magnitude and direction are?
from the origin
No?
What's re though
Nvm
r is the magnitude, e is euler's number
I haven't learnt about Euler's yet
Oh, okay. Then you'll probably learn what I'm talking about soon
Alright, I will stick to binomial for now, thanks, I will keep the above formula in mind
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ax^2+bx+ma+nb=0 where n^2+m<0, a,b,m,n real numbers, a not equal 0, find what kind of solutions does this equation have
look at the discriminant
b^2-4(a^2)m-4abn
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plz help
still need help?
GET OUT MY CHANNEL 😈
wtf is this
Makes no sense or at least I don’t know how to interpret that. Seems just like an abuse of notation.
But if you really had to do it, you could argue dx is just an infinitesimally small amount
ye that's what I thought
Pure
ya alright, ty pure, I guess it was just a silly question. somebody asked me it 🤷♂️
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I kinda forgot where else to go from here, do I bring down the 3 when I solve the denominator?
I think i see now, is the answer then (3a-1)(a+4) which makes the zeros 4 and 1/3
-4
You got it bro
my homework question says that it is incorrect however
Oh wait
I’m slow nvm
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but in the answer it says $(x-4)^n$ instead of $(\frac{x-4}{4})^n$
umadbruh
and also how do they know it's $2^{1-2n}$?
umadbruh
heisenburger
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<@&286206848099549185>
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Can someone help with 53c I have done a and b but don’t understand c
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im so confuse on this logic diagram
Some@people

@vernal coral Just make a truth table with the inputs and outputs and go through the diagram
im confuse on this
what are you confused by?
how to get c amd d values
then get out a paper
and go through a possible input
if you write it down its not too difficult
yeah i have the a nd b set up
ok then lets go through a case
lets have a = 0 and b = 0
what are the outputs of these three gates then?
the first one would be 1
which one is the first one?
the other two would be 0
the middle?
yes
the middle gate would recieve two 0 inputs
and since its a nand gate, it would output 1
agree
the top would be a 0 beccause there is a 1 going thorug itfrom a\
what are the two inputs for the top gate?
input is 1 and a 0
oh so it would be 1
yes
i got confuse with and
yes
oh so c woul;d be 0 then?
it would be 0 because 1 is going throug a not gate
Yes
ahhh i see thanks so much ,am
np
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@livid maple have you made progress thus far?
@livid maple Has your question been resolved?
