#help-33

1 messages · Page 7 of 1

cloud topaz
#

What you wrote is not equal to my 3rd line

silk plover
#

Hmm

cloud topaz
silk plover
#

Is it just because DeMorgan's law only works with single complement terms?

cloud topaz
#

Well, it's iterative.

#

So you can use it for infinite compliment terms, but you have to flip the sign every time.

silk plover
#

Okay so with !!(DB) you started with the most internal complement and broke it up, but left the top one alone

cloud topaz
#

(DB)cc = (Dc + Bc)c

#

Yeah

#

You can then break up the next one, but you have to flip the sign again

#

So you get:

silk plover
#

Okay okay and if we did it again it would just undo what we did.

cloud topaz
#

Dcc • Bcc

#

Yep

silk plover
#

Okay. This helps.

cloud topaz
#

I hate writing double compliments. There's not any practical reason to write them. If you see two compliments over the same term, just cancel them and skip the confusing stuff in the middle lol

#

E.g.
(DB)cc = DB

#

Similarly,
Dcc = D

#

Etc.

silk plover
#

Yeah I know I can just use double complement law for sure. But I was worried that if I don't thoroughly understand things I'll be mega confused later

cloud topaz
#

That's fair.

silk plover
#

I always ask why instead of just accepting things for what they are lol

#

Thank you. I appreciate the time that you spent here with me.

cloud topaz
#

No problem. I needed an excuse to avoid my own homework haha

silk plover
#

What are you working on?

cloud topaz
#

Current problem:

silk plover
#

Oh wow it's a chunky problem.

#

What class is this?

#

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marsh citrusBOT
#
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marsh citrusBOT
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pallid agate
#

its so late my brain stop work

marsh citrusBOT
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wet peak
#

How do I factor x^3+5x^2-x-5

marsh citrusBOT
late geode
#

try approaching it with grouping

wet peak
#

how

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I forgot

still creek
#

try grouping it and see if something interesting happens

#

(hint: something interesting should happen)

marsh citrusBOT
#

@wet peak Has your question been resolved?

late geode
#

$$x^3+5x^2-x-5 = \blue{(x^3+5x^2)} + \orange{(-x-5)}$$
can you factor the blue and the orange individually

elfin berryBOT
#

ℝamonov

wet peak
#

nvm

#

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winter parcel
#

Find the largest volume of a cube with the maximum surface area among the cubes
that can be enclosed in a sphere. ( r = 1)

winter parcel
#

i did f(x,y,z)= 2xy+2yz+2xz subject to : x^2+y^2+z^ <= 1

#

but i can't sure this

hidden plaza
#

This just over complicates things

winter parcel
#

then how do i ?

hidden plaza
#

You know the diagonal of the cube must be 2

winter parcel
#

sure

hidden plaza
#

Use Pythagorean theorem

dawn lagoon
#

hello i new

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i have a question

noble nebula
dawn lagoon
#

wait me

hidden plaza
dawn lagoon
hidden plaza
#

?

winter parcel
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hey

dawn lagoon
#

a.b.c>0

winter parcel
#

anyway then it doesn't need to use Lagrange right?

hidden plaza
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No

winter parcel
#

okay

#

let side length of the cube = a

hidden plaza
#

Yes

winter parcel
#

and then use the a^2+b^2= 4

#

??

hidden plaza
#

Do you know Pythagorean theorem in 3D?

winter parcel
#

aha..

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i forgot the z

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then x^2+y^2+z^2 = 4 right?

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f(x,y,z)= 2xy+2yz+2xz subject to: x^2+y^2+z^2 = 4

#

is this a right way ?

hidden plaza
#

Isn’t it r^2

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So 1?

winter parcel
#

i thought r=1, dianoal is 2

hidden plaza
#

Diametre is 2

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r is 1

winter parcel
#

yeah

hidden plaza
#

Equation of a sphere

winter parcel
#

ah

#

i got it

hidden plaza
#

Anyway back to our problem

winter parcel
#

okay

hidden plaza
#

$a^2 + a^2 + a^2 = 4$

elfin berryBOT
hidden plaza
#

By Pythagorean

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a=2/root3

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Use this to find the volume

winter parcel
#

what about a rectangular?

hidden plaza
#

What rectangle

winter parcel
#

if not a cube

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a rectangular then

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do i use x^2+y^2+z^2??

hidden plaza
#

Probably tbh I’m not really sure

winter parcel
#

i've got known the problem is find a rectangular parallelepiped

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not a cube

hidden plaza
#

Then use Lagrange

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Volume is given by 8xyz

winter parcel
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wait

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where did it come from 8?

hidden plaza
#

I’ve got to go very soon

winter parcel
#

not xyz?

hidden plaza
#

2x 2y 2z multiplied together

winter parcel
#

okay thank you

#

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marsh citrusBOT
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random pier
#

What happens when an exponent is a fraction with a numerator greater than one? Like 4^(3/2)

sleek lake
#

it's like (4^3)^(1/2)

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or the other order

crimson frost
random pier
#

Oh ok thanks that makes sense

#

Do I need to type some command to close this problem now?

crimson frost
#

.close

random pier
#

.close

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white willow
#

If a drink containing 40% alcohol is mixed with an equally large drink containing 30% alcohol, what would be the alcohol-percentage in the mixture?

tight furnace
#

we might want a variable for the size of the drink here

marsh citrusBOT
#

@white willow Has your question been resolved?

white willow
#

both of them are 700ml

#

ive been struggling with combining percentages

tight furnace
#

ah

#

so how much alcohol is in each one

white willow
#

First one is 40%, so 40% of 700ml

tight furnace
#

well I suppose there's a shortcut as well

white willow
#

Second one is 30%, so 30% of 700ml

tight furnace
#

since it's the same amount each time you average the percentages

#

The danger is there's some scenarios where this doesn't work

white willow
#

like, alcohol posioning?

tight furnace
#

If I run one mile at 6mph and one mile at 8mph

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my average speed will not be 7mph

tight furnace
white willow
#

Ah I see.

#

Right.

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So how would that shortcut look like?

lucid hinge
#

moni has obesity, so he runs quite slow

white willow
#

lol

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but i was thinking

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if we take the pure alcohol of both drinks

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and add them together

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then take 700*2

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and divide the amount of alcohol by that?

lucid hinge
white willow
#

that'd be 35

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so the percentage of the final drink would be 35?

tight furnace
#

u get (210+280)/(700*2)

white willow
#

thanks guys

#

we're gonna get fucked

#

!close

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how do I close this

lucid hinge
#

69110 and then close

marsh citrusBOT
#

@white willow Has your question been resolved?

marsh citrusBOT
#
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elder gust
#

At a traffic light, a two-digit display shows the number of seconds before the light turns green. The digits on the display are are shown in Figure 1. Part of the display is obscured by a vehicle (see Figure 2). On the visible part of the screen, the light was the same a second ago. How many different two-digit numbers the display can show now?

elder gust
#

trying to visualize how many types of number there could be

#

considering that the visible portion of the traffic light was the same a second ago

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there is 3 or 2 solution less

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wait

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because this shows the seconds

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the second digit cannot change

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which makes it into this

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what makes it into 3

sleek lake
#

it's just 2?

elder gust
#

why do you think its 2?

sleek lake
#

digit 2 is fixed and digit 1 is two or three

elder gust
#

or 7

sleek lake
#

right my bad

elder gust
#

thanks for the question tho

#

i go close this

#

thanks for joining me btw

#

cya

#

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little schooner
#

There is a team that has 10 members and they clean up weekly, cleaning can be done in 2 hours 48 mins when all 10 members are cleaning how long it takes when 3 members taking free time (not cleaning)?`

little schooner
#

ambulance driving at 80 km/h and arrived at the hospital in 30 mins , if ambulance was driving 100 kmh how quickly he would be arrived to hospital? (only in minute answers)

#

sorry for my english

#

there are the questions im stuck

#

<@&286206848099549185>

marsh citrusBOT
#

@little schooner Has your question been resolved?

little schooner
#

no

marsh citrusBOT
#

@little schooner Has your question been resolved?

marsh citrusBOT
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daring dune
marsh citrusBOT
#

@daring dune Has your question been resolved?

lost apex
#

(-4,4) means x=-4 and y=4. Does that make the given equation true?

marsh citrusBOT
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junior compass
marsh citrusBOT
dry prawn
#

What's giving you issue?

junior compass
#

thats correct so far, right?

dry prawn
#

a looks fine

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b has argument x, not 6

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Actually b is slightly off further, it looks like you constructed f ° g instead of g ° f

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Double actually, why are you asking for help on an exam?

junior compass
#

this is a redo exam and the teacher said i could use any means neccesary

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as long as i go along and learn it

dry prawn
#

Fair enough

junior compass
#

so would i subtract 12-5 then multiply 1/36 by that?

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or multiple 1/36 by 12 then subtract 5

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PEMDAS applies here, right?

dry prawn
#

g(x) is 2x - 5, and you need to multiply f and g

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So which of those do you think is more appropriate?

junior compass
#

well, on the first question, follow pemdas...

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so id multiply 1/36 by 12

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to get 1/3

dry prawn
#

Your pemdas changes if you introduce parentheses

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(1/36)(12-5)

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What would you do now?

junior compass
#

then multiply whatevers in the parentheses

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but i keep the parentheses when i multiply 6 and 2?

dry prawn
#

Yes

junior compass
#

so then the -5 would still be out of it

dry prawn
#

So you clearly understand f*g(6) = f(6)*g(6), which is good

junior compass
#

right

dry prawn
#

However, I think you need to pay a little more attention to the following algebra

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1/36 * 12 doesn't work, because 12 isn't g(6)

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If you compute f(6) and g(6) separately, what are they?

junior compass
#

g(6) is 7

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and f(6) is 1/36

dry prawn
#

So their product must be 7/36

junior compass
#

so its 7 * 1/36?

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ok

dry prawn
#

Perhaps seeing f*g as (f)(g) would help

#

So you naturally include the parentheses needed

junior compass
#

just on my calculator it was different

dry prawn
#

Because (1/36)*12-5 and (1/36)*(12-5) are not equivalent

junior compass
#

ah ok

#

thanks!

#

so then the second one looks fine?

dry prawn
#

No

junior compass
#

actually it should look like this

dry prawn
#

That I agree with

junior compass
#

ok, so whats the first step

dry prawn
#

Well what's 2 * (1/x^2)

junior compass
#

2/x^2?

dry prawn
#

Yep

junior compass
#

so 2/x^2 - 5 is the answer?

#

thats as simple as it gets, right

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cant really evaluate if the variable isnt a number...

dry prawn
#

Unless your teacher wants you to remove the x^2 from the denominator

junior compass
#

ooh right

dry prawn
#

But otherwise yeah it's complete

junior compass
#

likek sovlve for x

dry prawn
#

You can't solve for anything

#

You have an expression only

junior compass
#

right, ok

dry prawn
#

But you could rewrite 2/x^2 to not be a fraction

#

Whether or not it's required is up in the air, but it's an option

junior compass
#

.close

marsh citrusBOT
#
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hollow crater
#

Could anyone explain to me why ln(1+x^2)=2ln(x) +ln(1+1/x^2) please , I feel dumb not understanding this

upper briar
#

2ln(x) = ln(x^2)

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then

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ln(ab) = ln a + ln b

fallen galleon
#

aye aye

#

wassupppp

late geode
#

2ln|x| though

fallen galleon
#

$2ln(x) + ln(1+\frac{1}{x^2})$=$lnx^2 + ln(1+\frac{1}{x^2})$=ln(x^2(1+\frac{1}{x^2}))$

elfin berryBOT
#

Springsskateboard
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

fallen galleon
#

ew

#

nah

#

my latex game sucks

fallen galleon
marsh citrusBOT
#

@hollow crater Has your question been resolved?

marsh citrusBOT
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smoky marsh
#

i feel like im forgetting something but is there a law where it goes something along like 1/x=1/y then x=y

smoky marsh
#

if they have the same numerator can you do something like that

worn nimbus
#

yes

smoky marsh
#

do you know the know the name of the law? i'd like to look more into it

worn nimbus
#

dont know of any law

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respectfully its just basic algebra

pulsar flume
#

It’s commonly referred to as “cross-multiplying”

late geode
#

cross multiplication

smoky marsh
#

you know

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i feel real dumb now

late geode
#

justified algebraically by multiplying both sides by the product of the denominators (or to be more efficient use the lcd)

worn nimbus
#

i get humbled by math every day

smoky marsh
#

me too man me too

worn nimbus
#

its part of the process

smoky marsh
#

part of why i love it so much as well

worn nimbus
#

hahah yeah weirdly yes

smoky marsh
#

thanks for the help !

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glossy adder
#

How to solve this problem on paper?
All I have been told leading up to this problem is this
"If one task can be accomplished in x different ways and, following this task, a second task can be accomplished in y different ways, then the first task followed by the second task can be accomplished in x * y different ways. (This counting principle can be extended to any finite number of tasks.)"

An even number is one whose last digit is a multiple of 2

I have 6 numbers to choose from, for the hundredth place.
I have 5 numbers to choose from, for the 10th place.

The choice for the last digit depends how we chose the first two
Case 1: First two digits are odd
6 x 5 x 3 = 90
Case 2: First two digits are even
6 x 5 x 1(?) = 30 (I have my doubts...but if both are even then we are only left with a single even number innit?)
Case 3: One of the first two digits even only
6 x 5 x 2 = 60

Wrote a python program and the answer is indeed 60, via bruteforce

lst = list(filter(lambda x: x % 2 != 1, range(100, 666)))
# print(len(lst))

count = 0

for i in lst:
    if set(['0', '7', '8', '9']).isdisjoint(set(list(str(i)))):
        if len(list(dict.fromkeys(str(i)))) == 3:
            count += 1

print(count)

I was hoping to gain some insight but..., the program just counted the numbers via brute force.

Also is it coincidence that the arithmetic average of 30, 60, 90 equals 60?

smoky siren
#

A number is even is it ends in a multiple of 2 so that is 3 choose 1. Then you choose 2 numbers for the other digits, which is 5 choose 2, and 2 ways to order those 2 aforementioned digits.

marsh citrusBOT
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glossy adder
#

.reopen

glossy adder
marsh citrusBOT
cloud iron
#

3 choose 1 is the number of ways to pick one element from a set of three

smoky siren
#

The last digit has to be 2 4 or 6. That is 3 choose 1. There are 2 more digits to select among a remaining pool of 5. That is 5 choose 2. Those 2 digits can have any order. (3 choose 1) x (5 choose 2) (2 choose 1) = 3 x 10 x 2 = 60

#

For example, select the 6 to be the last digit (3 choose 1)

#

You can now choose between 1 2 3 4 5. Lets choose 2 and 3 (5 choose 2). So now there is either 236 or 326 (2 choose 1).

glossy adder
#

Thanks!

#

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marsh citrusBOT
dusk coral
#

Because

#

Its not

remote salmon
#

its the reversal property

dusk coral
#

oh right

wraith cobalt
#

no its not

dusk coral
wraith cobalt
#

it is not that, the inequalities are not a<b and b>a, they are a<b and b<a in this case

#

its about the logical definition of if then

stoic saddle
#

"If [false statement] then [WHATEVER]" is always true

wraith cobalt
#

^

stoic saddle
#

or if you speak latin, ex falso sequitur quodlibet

remote salmon
#

ah

nova totem
#

I'm gonna destroy arguments with that

cloud iron
#

Ah that really clears it up

#

Lmao

nova totem
#

But also

#

It's true because if 2 > 3 is false then 3 > 2 is true

#

Something like that

remote salmon
#

oh i completely misread it yeah

wraith cobalt
#

can f and g have the same limit at a?

#

I know, I'm asking you based on the information in the premises, can f and g have the same limit at a

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(the answer is yes)

#

If f and g were continuous, the result would hold, but allowing for discontinuities allows us to come up with this counterexample where f and g both limit to 0 at 0, but f<g over R

dusk coral
wraith cobalt
#

Well there's nothing saying whether f or g can be discontinuous so there's nothing wrong with choosing discontinuous functions as counterexamples to the statement.

wraith cobalt
#

so yes, it is completely consistent

stoic saddle
marsh citrusBOT
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harsh nova
marsh citrusBOT
harsh nova
#

Can someone help me find the derative of a absolute value

#

Did I set it up correctly

dusk coral
#

I dont want to waste your time(and distract the channel from Rayaans question, any reading about this you'd recommend or the actual concept name?

stoic saddle
#

vacuous truth is what it's called

harsh nova
#

.close

marsh citrusBOT
#
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dusk coral
marsh citrusBOT
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thin bison
#

Hi

marsh citrusBOT
thin bison
#

So actually I a bit confused

#

When do you use "=>" and "<=>" symbol?

hushed egret
#

A => B means "If A then B"

#

A <=> B means (A => B) and (B => A)

#

so "If A then B, and if B then A"

#

so "A if and only if B"

thin bison
#

Oh so

#

I can write like this then

#

2x+2 <=> 2(x+1) right??

stoic saddle
#

no

#

you use => and <=> between statements, not numerical expressions

thin bison
#

Like can you gimme a example??

#

Like 2(x+1)=0 <=> 2x+2=0

#

Likw this??

stoic saddle
#

sure, that works.

#

and because it works both ways, the use of <=> is called for.

thin bison
#

Idk

#

What's the name of <=>??

hushed egret
#

logical equivalence

thin bison
#

Ok

#

Thx

#

.close

marsh citrusBOT
#
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abstract forge
#

what the fuck is this

marsh citrusBOT
abstract forge
#

some ppl say its not a parabola and why does it go in a straight line

#

how the hell does y go -10, -9, -8 ,-7, -6, -5, -4

desert dirge
#

can barely see it

abstract forge
#

it makes 0 sense

#

its f(x) = (x+1) squared - 8

stoic saddle
#

some people say the graph of f(x) = (x+1)^2 - 8 is not a parabola?

#

is that what you are saying?

desert dirge
#

yeah, it is one

abstract forge
#

yes

stoic saddle
#

who is saying that?

abstract forge
#

I was trying 2 get help from other ppl but they say its not a parabola

stoic saddle
#

they're lying to you lmao

abstract forge
#

ok

stoic saddle
#

a parabola this graph very much is

abstract forge
#

what do i do then

#

the vertex is 0, -8

stoic saddle
#

no, the vertex is (-1, -8).

abstract forge
#

but then when u plug in the other numbers its a straight line

stoic saddle
#

also do not omit the parentheses when writing down a point via its coords.

#

also show exactly what you are plugging in and what results you are getting. where is your table of values?

abstract forge
#

I went -1 -2 -3 1 2 3

#

it gave me

#

-10, -9, -8 ,-7, -6, -5, -4

#

also 0

mystic minnow
#

I will bet money you're missing parenthesis

stoic saddle
#

do you have a table of values?

#

this looks very suspicious.

abstract forge
#

x and f(x)

stoic saddle
#

ok then show your table of values.

abstract forge
#

ok

stoic saddle
#

ok let's go through those one by one

abstract forge
#

ok

stoic saddle
#

how did you get -10 for f(-3)?

mystic minnow
#

yup. This is the graph of (x+1)-8 or x + 1^2 -8. you're either missing the square or parenthesis.

abstract forge
stoic saddle
#

but this is not the right formula.

#

f(x) isn't (x+1) - 8, it's (x+1)^2 - 8.

abstract forge
#

ok

#

but even if i did that

#

wouldnt it be the same thing

#

a straight line

desert dirge
#

no

stoic saddle
#

no, it would not!

abstract forge
#

so its

#

(-3+1)^2 - 8

desert dirge
#

yes

abstract forge
#

@stoic saddle is this what i do now

#

ok i think

#

I got it

#

.close

marsh citrusBOT
#
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native anchor
marsh citrusBOT
native anchor
#

Was wondering how i go about solving for C and D

#

<@&286206848099549185>

lost apex
#

I think the right way to think about this kind of question is, "What is the probability that the first letter is a B." Then, "Assuming we got a B for the first letter, what's the probability that the second letter is E" etc

native anchor
#

so like NCR(10,1) *NCR(9,1) etc?

lost apex
#

like 1/10 * 1/10 * ...

native anchor
#

Yep okay, so that is the right for question c just need to divide it by NCR(10, 4)

lost apex
#

why?

#

why do you need to divide it?

#

what does "n choose r" mean

native anchor
#

Because it is a probability so you would have to divide by the total number of possible outcomes

#

like how many combinations

lost apex
#

ok, it's fine to do it that way- then the number of correct out comes is 1 * 1 * 1 * 2

#

and the number of total outcomes is 10^4

#

ncr doesn't get you what you want in this case

native anchor
#

Oh okay, but what about D though, since there isnt any replacement?

lost apex
#

so the total number of outcomes is 10 * 9 * 8 * 7

#

do you see why?

native anchor
#

No not really

#

is it a type of formula you are refering to?

lost apex
#

how many outcomes are there for the first draw?

#

think about it logically over memorizing a formula

native anchor
#

10 outcomes because it have 10 letters right?

lost apex
#

right! but how many outcomes are there for the second draw?

native anchor
#

9

lost apex
#

ok, i think you understand

native anchor
#

so I do that 4 times because it is 4 letters I need right?

lost apex
#

yeah -on the third draw there will be 8 outcomes

native anchor
#

So how would i write that as a probability then if I know how many outcomes there are?

lost apex
#

how many correct outcomes are there?

native anchor
#

1098*7= 5040

lost apex
#

i think that's the number of total outcomes

#

how many spell barb?

native anchor
#

wait I mis wrote my last question it is 1098*7=5040

lost apex
#

yeah

native anchor
#

I do not know how many spell barb

#

How do I find that

lost apex
#

oh, i was about to say something wrong

#

actually zero

#

right?

#

there's only one b

#

but if we were trying to spell bear, it would be two

native anchor
#

Yeah that is what I was confused about at first but I thought that there had to be a solution that i was not seeing

lost apex
#

because you can use the black r or the white r

#

yeah, i think you were right

#

but now you know how to do this if it asks about something that's actually possible haha

native anchor
#

So wait, sorry to ask again but how do I do C exactly?

lost apex
#

ok, so how many outcomes spell bear?

native anchor
#

1/10*/1/101/103/10

#

since there are 3 r's

#

right?

lost apex
#

yes

#

i think i miscounted earlier

#

i'm a miss

#

mess

native anchor
#

all g so that is how I get the full probability right?

lost apex
#

yes

#

3 correct spellings/ 10000 possible results

native anchor
#

okay and for the other one I would do 1098*7?

#

if it were possible that is

lost apex
#

yeah that would be the denominator

native anchor
#

ah okay so then how would I find the ones that spell BARB?

lost apex
#

well without replacement there are zero outcomes

#

if it were with replacement there would be 3 for the same reason

native anchor
#

okay, tysm for being so patient

#

Have a good one

#

.close

marsh citrusBOT
#
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lost apex
#

you too!

marsh citrusBOT
#
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halcyon rune
#

(solve the question using the formula below) I seriously cant figure out how to do this as my answer always either goes above or way too low

stoic saddle
#

ah yes, the classic "use this formula, except we deliberately give you the wrong formula for your problem!"

halcyon rune
#

i wanna message my teacher to see if it was just a mistake but she doesnt even read my messages 💀😭

stoic saddle
#

then skip this problem tbh

#

like

stoic saddle
#

okay we can assume it's talking about geometric progressions and (a_n) is such a progression

#

even tho that's kind of a big ask

#

without any more context, that is

#

but then like. the formula you've shown gives the SUM of the first n terms of the progression

halcyon rune
#

i mean, yeah considering her who doesnt explain things any further, that might just be the case

stoic saddle
#

and you are asked only for one term

halcyon rune
stoic saddle
#

so... bit of a wtf moment there

halcyon rune
#

well i can just skip this one since i've solved other problems similar to this that i managed to solve but just this one...

stoic saddle
#

well like

#

a_6 = a_1 * r^5

#

but this does not make use of the formula and so might be rejected on those grounds alone

rain leaf
#

what is S_n? is it the sum a_1 + ... + a_n?

halcyon rune
#

sn = the number that came out using the formula

rain leaf
#

so you do know this number?

halcyon rune
#

nope

#

thats what i'm trying to figure it out

rain leaf
#

aren't you asked to figure a_6?

halcyon rune
#

yeah

#

the thing is, i got an answer but its way too far from the answer i got just by computing 4 x 3 again and again

#

the answer that came out using the formula needs to be the same as the one i just computed by doing 4 x 3

rain leaf
#

i kinda don't understand, they want you to figure out S_6 and a_6 at the same time using this single equation?

halcyon rune
#

uh no

#

s6 is the a6

rain leaf
#

can you just isolate a6 then?

a6 = (a1 - a6*r)/(1-r)

#

you know that r=3 and a1=4

halcyon rune
#

i mean, if the formula wasnt necessary and i can just compute it however i want then yeah

#

but sadly the formula provided needs to be used in that way

halcyon rune
lost apex
#

You're asking if the formula provided is appropriate for the question asked, yes?

#

the formula you were given is for the sum

marsh citrusBOT
#

@halcyon rune Has your question been resolved?

marsh citrusBOT
#
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cyan crypt
#

In your own words please define to me the meaning of Interpolation Search Algorithm (Position Probing)

marsh citrusBOT
#

@cyan crypt Has your question been resolved?

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gloomy dome
#

[Statistics newbie]
I don't understand this concept.
Wasn't "sum of squares" the sum of the residuals (i.e. the distances of each data point from the line) squared?
Shouldn't the result be a positive value above 0?

rose torrent
#

Even a kid can solve this

gloomy dome
#

What about my question?KEK

rose torrent
#

No idea

#

Boi

gloomy dome
#

Also in math terms, when they say that an equation Q1 performs worse than a Q2 equation, does it mean that Q1's result r1 is smaller that Q2's result r2?

rose torrent
#

You mean the better one is more accurate

#

That's a result of better modelling

gloomy dome
#

So Q1 is less accurate than Q2 in my example?

rose torrent
#

And by result do you mean value of each equation when put with a specific value in both of them

#

For example when we put x=3 in 3x²+4 we get 3*3²+4= 27+4=31

gloomy dome
#

Uhm, let me get the notes

#

Here, he says that if we would to consider in an analytic context that mouse size is influenced by all of those parameters, they would get reduced to 0.
So this equation wouldn't perform worse than the one on the bottom

rose torrent
#

It's simple

#

You can write 3y³+5y as 3y³+ 0y²+ 5y +0

gloomy dome
#

Yeah but what if one of those parameter was instead multiplied by 1?
Why would you say that the above one performs worse than the bottom one?

rose torrent
gloomy dome
#

Thanks a lot

#

!

#

Then my question was solved for now, have a nice day

#

:^)

rose torrent
#

Yes but one thing , you have to use the proper coefficient not any arbitrary number

gloomy dome
#

?
I'll learn what you mean along the way I guess, right now though I'm attending class, sorry to cut our conversation short, if I didn't the bot probably would have eheh

#

.close

marsh citrusBOT
#
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marsh citrusBOT
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gaunt pine
#

the top one

marsh citrusBOT
gaunt pine
#

.close

marsh citrusBOT
#
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fallow compass
#

what is this method of rationalising trigs called?

ruby mulch
#

I don't recall having a name for that technique. Just "multiplying both sides of the fraction with a constant", "expanding the expression", and "Pythagoras theorem"

fallow compass
#

so rationalising trigs is a thing?

#

hadnt seen anything like this except in case of irrational number

upper briar
#

i think its quite specific to this Q

glacial hedge
#

I wouldn't give any generality to this method. Most trig stuff is just about rewriting and since it's an exercise there's got to be a way that works

fallow compass
#

right

ruby mulch
#

It's a thing for basically every rationals ever

fallow compass
#

ahh

#

okay

#

thanks guys

#

.close

marsh citrusBOT
#
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teal isle
#

how would i start this? i think i can make a exact value traingle using x/2

teal isle
upper briar
#

yes

#

then do that

marsh citrusBOT
#

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flat geyser
#

I need help to solve this
If polynomial p(x)= x^3+x^4+x^5+…+x^2021 divided by (x-1)^3 leaves ax^2+bx+c then find the value of 4a+2b+c

marsh citrusBOT
#

@flat geyser Has your question been resolved?

flat geyser
#

<@&286206848099549185>

#

.close

marsh citrusBOT
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signal bronze
#

Find the volume of a quadrangular prism whose base is a triangle with base 4.2 cm and height 3.8 cm and the height of the prism is 10 cm V = ??

stoic saddle
#

@signal bronze channel occupied please move

#

,rccw

elfin berryBOT
stoic saddle
#

@still temple do you know your way around special points on the graph of a function? i.e. ones at which the first or the second derivative is 0

#

yes, dy/dx = 0 gives you stationary points and d^2y/dx^2 = 0 gives you points of inflection

#

blink blink

#

sorry that was a little too word-salady for me and i got thrown off track lmao

marsh citrusBOT
#
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still temple
#

One message removed from a suspended account.

wooden oriole
#

expand it

still temple
#

One message removed from a suspended account.

#

One message removed from a suspended account.

wooden oriole
#

expand $(\vec{x}-\vec{y}) \cdot (\vec{x}-\vec{y})$

still temple
#

One message removed from a suspended account.

elfin berryBOT
#

秋水

wooden oriole
#

$\vec{x}$ and $\vec{y}$ are orthogonal, so $\vec{x}\cdot \vec{y}=0$

elfin berryBOT
#

秋水

still temple
#

One message removed from a suspended account.

wooden oriole
#

so you get the answer

still temple
#

One message removed from a suspended account.

#

One message removed from a suspended account.

#

One message removed from a suspended account.

hushed egret
#

pythagrawr

still temple
wooden oriole
#

The two vectors inside are perpendicular to n.

still temple
#

One message removed from a suspended account.

#

One message removed from a suspended account.

still temple
wooden oriole
#

The two vectors inside the span

#

they are perpendicular to n.

still temple
#

One message removed from a suspended account.

wooden oriole
#

these two vectors are perpendicular to n.

still temple
#

One message removed from a suspended account.

#

One message removed from a suspended account.

wooden oriole
#

1*(-2)+2*a-3*b=0

#

1*c+2*0-3*1=0

still temple
#

One message removed from a suspended account.

#

One message removed from a suspended account.

marsh citrusBOT
#

@still temple Has your question been resolved?

still temple
#

One message removed from a suspended account.

#

One message removed from a suspended account.

wooden oriole
#

Just a suitable set of solutions is okay, you can let a = 1.

wooden oriole
still temple
still temple
wooden oriole
#

The way span is written is not unique

still temple
#

One message removed from a suspended account.

wooden oriole
#

As long as the two vectors inside are linearly independent.

still temple
wooden oriole
#

when a=1, the two vectors are linearly independent, you can check, so you can let a=1

still temple
#

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#

One message removed from a suspended account.

marsh citrusBOT
#
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still temple
#

One message removed from a suspended account.

#

One message removed from a suspended account.

marsh citrusBOT
#

wooden oriole
#

so it's easy to see

still temple
wooden oriole
still temple
#

One message removed from a suspended account.

#

One message removed from a suspended account.

wooden oriole
#

the plane equation is
$\vec{n} \cdot (\vec{x}-\vec{p})=0$

elfin berryBOT
#

秋水

wooden oriole
#

just calculate it

still temple
#

One message removed from a suspended account.

wooden oriole
#

$\vec{x} = (x,y,z)$

elfin berryBOT
#

秋水

still temple
#

One message removed from a suspended account.

still temple
wooden oriole
#

what do you mean?

#

$\vec{n}=(1,2,1)$,$\vec{p}=(1,0,1)$

#

$\vec{x}-\vec{p} = (x-1,0,z-1)$

elfin berryBOT
#

秋水

wooden oriole
#

$\vec{n} \cdot (\vec{x}-\vec{p})=(1,2,1) \cdot (x-1,0,z-1)=x-1+(z-1)=0$

elfin berryBOT
#

秋水

#

秋水

marsh citrusBOT
#

@still temple Has your question been resolved?

#
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still temple
#

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marsh citrusBOT
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bright hedge
#

I need help to solve an exercise about functions and function limits.

marsh peak
#

First of all you can simplify (x^3 - 2x^2 + x - 2)/(x - 2)

bright hedge
#

okk

#

so one moment I write down

#

ok this is the simplification

#

Now I can delete x-2

marsh peak
#

Yes, also note that you can simplify x-2 because x isn't 2

#

So x-2 can't be 0

upper briar
#

define x=2 separately

marsh peak
#

If it was zero, it wouldn't be as simple as to just cancel out

upper briar
#

exactly what is being done in f lol

bright hedge
#

ok, this is clear, so remains

x^2 + 1

upper briar
#

ye find the turing pts of it

marsh peak
#

So the range of outputs on [-1, 3] is the same as the range of outs puts of x^2 + 1 on [-1, 2)U(2, 3] united with {a}

upper briar
#

wait im drunk LOL

bright hedge
marsh peak
#

No

bright hedge
#

oh sorry I didn't understand this passage

marsh peak
#

(range of x^2 + 1 for x in [-1, 2)U(2, 3]) U {a}

bright hedge
#

aaah okkk

bright hedge
#

ok and now how can I proceed?

marsh peak
#

That's not it but okay forget it

#

Just find the range of x^2 + 1 on [-1, 2)U(2, 3] first

upper briar
#

i like to draw it

bright hedge
bright hedge
upper briar
#

,w graph y=x^2+1

upper briar
#

omg bad scale

wise dove
#

im gr8

#

pls help 😭

marsh peak
#

Post your question in an available help channel

wise dove
#

ohh okay okay

bright hedge
upper briar
wise dove
upper briar
bright hedge
bright hedge
upper briar
#

👽

wise dove
upper briar
bright hedge
#

So I have to find the range separately?

1 ≤ x^2 + 1 < 2

and

2 < x^2 + 1 ≤ 3

upper briar
#

well

upper briar
bright hedge
#

and what 'bout "a"? How can I insert this parameter in a range?

upper briar
#

a shld fill in that gap

bright hedge
#

yes this is clear but how?

Sorry if I seem stupid, but I really am ahaha.

So these are the ranges:

1 ≤ x ≤ 2 and
2 < x ≤ 3

upper briar
#

those r the domain

#

idk

#

trivially just put f(x) as x->2

#

would always work as polynomials are cont

bright hedge
#

lim f(x)
x->2

#

Theorically I understand, but I can't solve it algebrically

#

MAYBE I DID IT

#

So

#

if I put:

bright hedge
upper briar
#

yes

#

kinda

#

i would write

#

a = lim... = 2^2+1 = 5

#

but urs works too ig

marsh citrusBOT
#

@bright hedge Has your question been resolved?

bright hedge
#

for your time

upper briar
#

np

#

💕

bright hedge
#

and for your help

#

😘

marsh citrusBOT
#
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still temple
marsh citrusBOT
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still temple
marsh citrusBOT
still temple
#

Can anybody help me with d, Im not sure what the question meant

hidden hollow
# marsh citrus

Question . Im trying to convert -225 into radians. I got -5pi/4 . I know that its going to be -225 * pi/180. I broke down 225(45 x 5) and 180 (45 x4), after canceling everything I ended up with -5pi/4. I looked up the answer and its -37pi/30......where did I go wrong? @marsh citrus <@&286206848099549185>

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@still temple Has your question been resolved?

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unique mural
#

$(1 + i)^{12}$

marsh citrusBOT
elfin berryBOT
#

ahmed349

unique mural
#

Is binomial theorem the only way to do this

smoky siren
#

You would usually write 1+i in polar coordinates instead

unique mural
#

Polar coordinates?

trim quest
#

Like $re^{i\theta}$ form

elfin berryBOT
#

tatpoj

unique mural
#

Ah not familiar with that unfortunately

trim quest
#

You can imagine a complex number as a point on the complex plane, sort of like a vector.

#

It has a magnitude r and a direction theta

#

Then re^(i*theta) is equal to that complex number

#

1+i is like the vector [1,1]

#

Do you know what its magnitude and direction are?

#

from the origin

unique mural
#

What's re though

#

Nvm

trim quest
#

r is the magnitude, e is euler's number

unique mural
#

I haven't learnt about Euler's yet

trim quest
#

Hm

#

Then for now, I guess I would just use the binomial theorem

unique mural
#

This is like a prelude excercise to Euler's

#

Alright

trim quest
#

Oh, okay. Then you'll probably learn what I'm talking about soon

unique mural
#

Alright, I will stick to binomial for now, thanks, I will keep the above formula in mind

marsh citrusBOT
#

@unique mural Has your question been resolved?

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edgy flint
#

ax^2+bx+ma+nb=0 where n^2+m<0, a,b,m,n real numbers, a not equal 0, find what kind of solutions does this equation have

tardy monolith
#

look at the discriminant

edgy flint
#

b^2-4(a^2)m-4abn

upper briar
#

errr

#

thats a weird equation

edgy flint
#

it is

#

i guess i need to rearrange the terms in the discriminant

#

idk how?

marsh citrusBOT
#

@edgy flint Has your question been resolved?

edgy flint
#

<@&286206848099549185>

marsh citrusBOT
#

@edgy flint Has your question been resolved?

marsh citrusBOT
#
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bleak reef
marsh citrusBOT
still temple
#

plz help

bleak reef
#

GET OUT MY CHANNEL 😈

bleak reef
hidden plaza
#

Makes no sense or at least I don’t know how to interpret that. Seems just like an abuse of notation.

#

But if you really had to do it, you could argue dx is just an infinitesimally small amount

hidden plaza
#

That is $$\int \lim_{h \to 0} x^h dx = x+c$$

#

But this just makes no sense

elfin berryBOT
bleak reef
#

ya alright, ty pure, I guess it was just a silly question. somebody asked me it 🤷‍♂️

#

.close

marsh citrusBOT
#
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marsh citrusBOT
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tardy canyon
#

I kinda forgot where else to go from here, do I bring down the 3 when I solve the denominator?

lean flame
#

If I'm understanding you are looking for 3a^2 + 12a - a - 4

#

Caca??

tardy canyon
#

I think i see now, is the answer then (3a-1)(a+4) which makes the zeros 4 and 1/3

#

-4

lean flame
#

You got it bro

tardy canyon
#

my homework question says that it is incorrect however

#

Oh wait

#

I’m slow nvm

#

.close

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#
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marsh citrusBOT
still temple
#

I have two quesitons about the solution

#

I got to

daring wadi
#

its 3

#

the answer is 3

elfin berryBOT
#

umadbruh

#

umadbruh

still temple
#

but in the answer it says $(x-4)^n$ instead of $(\frac{x-4}{4})^n$

elfin berryBOT
#

umadbruh

still temple
#

and also how do they know it's $2^{1-2n}$?

elfin berryBOT
#

umadbruh

still temple
marsh citrusBOT
#

@still temple Has your question been resolved?

still temple
#

<@&286206848099549185>

#

oh wait

#

I see why it's x-4

#

it's because it's at a =4

still temple
#

<@&286206848099549185>

still temple
#

<@&286206848099549185>

still temple
#

<@&286206848099549185>

#

never mind

#

I figured it out

#

.close

marsh citrusBOT
#
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long fjord
#

Can someone help with 53c I have done a and b but don’t understand c

marsh citrusBOT
#

@long fjord Has your question been resolved?

long fjord
#

<@&286206848099549185>

marsh citrusBOT
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@long fjord Has your question been resolved?

long fjord
#

.close

marsh citrusBOT
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vernal coral
marsh citrusBOT
vernal coral
#

im so confuse on this logic diagram

proper cove
#

lol

#

this is math help not cs help

obsidian bone
#

Some@people

vernal coral
chrome silo
#

@vernal coral Just make a truth table with the inputs and outputs and go through the diagram

chrome silo
#

what are you confused by?

vernal coral
#

how to get c amd d values

chrome silo
#

ok

#

do you know the gates on the diagram?

vernal coral
#

yes

#

it so hard to keep track of what is going on

#

to much gates

#

too

chrome silo
#

then get out a paper

#

and go through a possible input

#

if you write it down its not too difficult

vernal coral
#

yeah i have the a nd b set up

chrome silo
#

ok then lets go through a case

#

lets have a = 0 and b = 0

#

what are the outputs of these three gates then?

vernal coral
#

the first one would be 1

chrome silo
#

which one is the first one?

vernal coral
#

the other two would be 0

chrome silo
#

the middle?

vernal coral
#

yes

chrome silo
#

the middle gate would recieve two 0 inputs

#

and since its a nand gate, it would output 1

vernal coral
#

agree

chrome silo
#

ok what does the top gate output

#

?

vernal coral
#

the top would be a 0 beccause there is a 1 going thorug itfrom a\

chrome silo
#

what are the two inputs for the top gate?

vernal coral
#

input is 1 and a 0

chrome silo
#

yes

#

what is the output then?

vernal coral
#

oh so it would be 1

chrome silo
#

yes

vernal coral
#

i got confuse with and

chrome silo
#

The bottom would output 1 as well, since it also has inputs 0 and 1

#

right?

vernal coral
#

yes

chrome silo
#

what should the last gate output then?

vernal coral
#

oh so c woul;d be 0 then?

chrome silo
#

yes

#

and what would D be?

vernal coral
#

it would be 0 because 1 is going throug a not gate

chrome silo
#

Yes

vernal coral
#

ahhh i see thanks so much ,am

chrome silo
#

np

vernal coral
#

.close

marsh citrusBOT
#
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livid maple
marsh citrusBOT
stoic saddle
#

@livid maple have you made progress thus far?

marsh citrusBOT
#

@livid maple Has your question been resolved?