#help-28
1 messages · Page 268 of 1
First off, freak/freaky can be used if someone focuses on the SMALLEST detail. Secondly, you are a freak and you are freaky. Thirdly, if you can't help and still continues to harass me in this channel then I'll have to call the mods
go on
But this method is more efficient
You can factor out x-y here
because they did 4,4,1
instead of 4,4,4
like the answers of each of the equations are not the same
that sucks
But look at this, you can factor out a x-y here
you mean (x - y) but yep
My bad
also I'll tell you in advance that x = y has no solutions
@narrow mica Has your question been resolved?
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Problem 1 (10 points)
Compute the zeros, the vertex, the y-intercept, and the equation of the axis of symmetry for the parabola
y = -x^2 - 4x + 5.
Then draw the parabola in a coordinate system and justify that it is a function.
⸻
Problem 2 (5 points)
Justify that the parabola in Problem 1 is a function.
⸻
Answer to Problem 2
The parabola from Problem 1 is a function because every x-value corresponds to exactly one y-value.
If you draw a vertical line (the vertical line test), it will intersect the parabola at most once for any x-coordinate.
Since no vertical line hits the graph more than once, the graph represents a function.
Why did I only get 5 points for problem 2?
Damn
Huh...
I think it's because it ||does not cover all of the cases|| and ||your explanation is too broad||
Your explanation is too broad and does not go into details
If you draw a vertical line (the vertical line test), it will intersect the parabola at most once for any x-coordinate.
Since no vertical line hits the graph more than once, the graph represents a function….
How is it broad?
As i said, it's too broad
Then how would you word it?
I would use the algebraic method
And show me it
Oh wait nvm
The reason you got 5 points is because the maximum points you can get for the question is 5 
I just noticed that when im trying to explain to ya
Icelandic, huh
Omg I’m so dumb

Omg I have 67 battery
six seven
Fabian, look carefully next time
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y = -x^2-4x+5
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I need some help with this question
okay
so probability of smth
is just
$\frac{\text{The number of cases that satisfies the condition}}{\text{The total of cases}}$
1 divided by 0 equals Infinity
so to figure out the denominator, it's obvious
and to figure out the numerator, you need to count how many cases that satisfies the question
for example, in question c), you would need to count how many even numbers are there in a die
What I did 1/6 *2, giving me 1/3
note that this is only when every possible outcome is equally likely
which is not true in this case
oh...
since we dont know the chance of getting a one
say probability of landing a 1 is p
and the probability of not landing a 1 is 1-p (since those are the only options)
the question has stated that p = 2(1-p)
P(getting a one) = 2 x P(not getting a one)
why 1 is p
I’ll come back to this question since it’s a bit challenging but I want to really understand combinations and permutations
sure
I watched few videos but the concept looks difficult for me to understand
well do you understand the die questions without any modifications
like just finding the probability of rolling an even number on a fair die
that kind of questions
I should be able to
then the next tier would be questions like these
where you have a biased coin or die
it would be easier if you are given the probabilities
Are you referring to the original post
Or getting me to understand combinations/ permutations
I’ll open a new channel because I want to come back to this question
.close
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Hello, can I perform two different operations in gauss elimination in one step?
Is there a higher chance of an error then? Also can I perform two same operations in one step?
As long as the combined effect is equivalent to a sequence of elementary row operations
from experience, you're super likely to make a mistake this way
even though you can mathematically
and these mistakes are also super hard to find yourself
In reality gaussian elimination is multiplying a sequence of elementary matrices like this [
E_kE_{k-1}\cdots E_1A
]
So mathematically nothing changes if you decide on combining some of those matrices together when multiplying
(matrix multiplication is associative)
Yeah this is killing me😭
I genuinely dont know what im doing wrong but I've been trying to get these right fir hours now
Im solving it the correct way (I think) cause in the end my answer IS in standard echelon form but the variables answers just dont match
Just show the problem and your work
Wait up ill solve another one and share it here (if I get the wrong ans again, which is most likely)
?? What am I doing wrong, the last columns value is incorrect :(((( I've been trying
Nvm I wrote 37 instead of 27💀
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C10 + c11 = 2^1
C20 + c21 + c22 = 2^2
And it continues
So u have 2^n/n!
That’s on b
i said only a part
It’s only a part
.
Ur far far away from the awnser still with my tips
Do you know a formula for nC2
uh no
but if u could help me derive one ill be sure to remember that
This looks like a low Olympiad question ngl
look at the computed values to get an idea
Not so hard but it’s sketchy
or like just
no its jee mains question
use factorial formula
Whats jee
to get an idea of what
entrance exam for colleges
JEE ahhh, do you even know how we compute nCk w/o caculator
The objective is to get nC2 in terms of n
oh ok
N!/(p!(n-p)!)
so how do we do that
That’s ur ncp formula
why the word "even" here? seems insulting
what prompted that i dont know how to calculate nCk..
It's kind of an expression of how hateful I am for the JEE, but anyway you guys should have known the formula nCk right?
yes. what do i do with that
Compute the values
And see if there’s a progression
bro
And how to converge it
ur giving very general instructions..
It’s not
Compute c22
C32
C42
( I already did it for u just scroll up )
Then u see if there’s a progression that converges
1 + 1/3! + 3/4! + 6/5!....
Yeah
ye so next what
See if it converges
it will obviously converge they wont expect an answer as infinity
Then see how it converges
how do i do that
U should study that topic a bit more for that question
It goes a bit deep into series from my understanding
;/

There's formulae for binomial series.....
Pls share it I’m curious
But that’s calc 2 🤔
Isn’t that a college entrance exam? Or do u guys study that in hs
what is the formula
Search binomial series in google
First thing that pops up
but that is not the series we have here right
Acc I'll need to look into it which i cant rn
for one thing ours starts from 3!
Maybe try writing the general form?
Ignore the first term
The general term of a should be nC2/(n+1)! Right
Now nC2 = (n²-n)/2
So general term will be (n²-n)/(n+1)! Ignoring the 2 in denominator for now
Now spilit the fraction
n²/(n+1)! - n/(n+1)!
Now add and subtract 1
Ig it should work
Simplify
ok i followed till here
add and subtract 1?
(n²-1)/(n+1)! + 1/(n+1)! -(n+1)/(n+1)! + 1/(n+1)!
(n-1)/n! + 2/(n+1)! -1/n!
1/(n-1)! - 2/n! + 2/(n+1)!
Like this
In numerator
I'm pretty sure i did a mistake while writing this, but i think you get what i did
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Hello
we meet again since the last school year
Just send the question
yeah, i need help to understand what did my friend do here
i understand the thing in blue
i have no idea what she did next
or maybe what would you do here cause i dont know what should I do and if i should do the same as her
Hi! If you understand the blue bit, then essentially the strategy is to split up the integral in two, then evaluate each integral. The bottom left portion bit evaluates one integral, so now you have to evaluate the other one.
yeah i figured that
I think your friend was unsuccessful in evaluating the second one - how would you evaluate this integral?
but i dont know how
Hmmmm well
hollup
let me think what i couldve done
ohhhhhhhhhhhhhhh
should i put it into
(fraction)^-1?
oh nono
cause i cant get the derivative out
its 2x+2
I'll leave this hint again: How would you integrate? [ \int \frac{1}{1 + x^2} , dx ]
Redfern Station
its arctan(x)
Perfect :)
Try think about how this integral is related to my hint.
you want me to find an arctan?
Or at least, convert your question into an integral similar to this form.
orz u 
Perfect
Hi Pigeon
Ummm not quite
You split it up right yes,
could you please send a sheet if you know one of integrals of arctan arccos and arcsen?
But you are missing some things
cause i dont know the actual formula on how to get arctan
wait if i split up i can find the roots?
If you don't know trig sub, the one integral that you need to know is this one
Wellll the roots are imaginary, so unless you want to work in the complex field, probably not a good idea.
oh right
You want to try and use this formula in order to evaluate your integral
That means the first thing you actually need to do is rewrite this fraction
yeah i dont even have this formula in spreadsheet my teacher gave me
You need to tell me what exactly the new fraction is
Interesting
i have 1 instead of a, and 1 instead of a^2
Hold on
and it gives arctan(x)
whats that supposed to mean
You specifically need something that is squared
ok
x^2 + 2x + 4 isn't a 'square'
Sure, but its more of an algebraic thing
Remember your denominator is x^2 + 2x + 5
How do we usually turn expressions like these into squares?
Nope
There's a specific process
That allows us to get squares
Nope
The hint is that your friend actually attempted this strategy
You can see in their working out that they actually used some strategy to get a square.
yeah no idea what are these 1/2 1/2
Dw about that bit, look below
Look at the denominator - how did you friend get that?
ok i see some part of it
she gets the x^2 + 2x + 1 roota
roots
now these roots + 4 = no idea
Wait, wdym by 'roots'?
Perfect, yeah - that's what I meant by finding a square
like simplifying the formula
(x + 1)^2 is a square, and the exact one I am looking for
why
Officially, this method is called 'completing the square', since we are getting a square out of a quadratic
Well because that's what the formula wants!
We need something that is squared.
no wait im talking like
x^2-1=0
x= +1, -1
these things^
Yeah but
We want specifically an expression that has the same roots
So we can write it as (x + a)^2
That specifically is called completing the square
Like when you are solving for the roots, you need to complete the square
omg
so its 1/2*arctg((x+1)/2)+c?
I was going to say, I think this is the method your friend was leading up to
Basically if you didnt know the formula for arctan generally, but you did know that the integral of 1/(1 + x^2) is arctan(x),
You can directly write it in that form
oh
The trick is the factor out 4 from the denominator.
That way you get the first integral at the bottom
Then you just use reverse chain rule
oh
You get the exact same result, just with a little extra steps
My pleasure :)
Unfortunately I only tutor on my own country (which is Australia)! Unless that was just a question out of curiosity :)
are you active here?
Well I come here every once in a while when I get bored so I'd say so yeah
Sometimes I just watch other people solve. It's kind of interesting sometimes
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Hello, is anyone able yo check if i have done part C correct?
Excuse the tipex at tge top, i missed out a step lol
,rccw
Almost: careful here:
This better?
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I was given the equation (x-2)^2 + (y-3)^2 = 9. I have to apply a vertical stretch about the x-axis by a factor of 2 and determine the equation of the conic in standard form. How would I go about doing this?
Try doing the stretch on just the important points of the ellipse
mb i just got the answer while i was waiting for a response lol
thanks for the help
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hi can someone explain this to me
The intuition is that you’re distributing n identical items into m boxes. A multiset selection is the same as deciding how many balls go in each box… That division is done by placing m-1 separators among n+m-1 slots. That’s why the formula is \binom{n+m-1}{m-1}.
Example with n = 7, m = 4:
so we have 7 identical things * to distribute into 4 different boxes.
**|****| |*
This is one such arrangement.
can you please give an example
oh thanks
and where does the countint multiset happens
You can look up a more concrete example by searching stars and bars combinatorics.
thanks
It just represents the number of ways to choose which positions out of n+m-1 total positions will be the bars. We have n stars (the items). We have m-1 bars (the separators). So in total we have n + m - 1 slots to fill. If you choose which m-1 slots contain bars, the rest must be stars.
That is why the given expression is also equal to.
[wrb{binom{n+m-1}{m-1} \overset{\catthink}=binom{n+m-1}n}]
クーリー
but the problem is im stuck on what it means to have those options to choose from
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I only need the profit. 
Please don't repeatedly close and claim a new channel with the exact same question. This erases all previous progress made towards your problem and is confusing for helpers, making it more difficult to help you. Please be patient, even if your channel has not received much attention.
do you know the formula for the profit?
@near jewel
I think it's Profit = total revenue – total cost.
you almost get it right
so yk how to calculate the revenue?
the total revenue
I have no clue that's why I came here lol
If we want to find the Total Revenue first, what is the basic formula for Revenue in any business?
Give it a guess
@near jewel
total Revenue = price per unit × quantity sold
yes
now apply it to profit = tr - tc
you will get the result
@near jewel
now you only need to find the ATC curve and its value
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im here
sorry
i was busy
we can talk more in dms
@near jewel
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yesss thts the name for tht gap method
nice, how do you see dot product in this?
this is a general product a × b, so maybe dot product has the same pattern
i ddont think I've studied thht yet
maybe dot product just has similar name, I don't yet know
so it is multiplication and addition?
eg, v•w has multiplicatoin [v₁w₁, v₂w₂,…]
and addition v₁w₁ + v₂w₂,…
I think the multiplication part has this pattern from the diagram
each v₁w₁, v₂w₂,… is v₁ × w₁, or a × b
and the additions are co-products a + b which have I think the dual drawing, where you reverse all the arrows
yes
look, every arrow is going the other direction for +
welp hvnt studied tht
this is category theory, and these arrows are more abstract/general than functions, they morphisms, or simply arrows
functions are arrows, but not all arrows are functions
as far as I know functions map sets, arrows, morphisms can map all sorts of things,
i hv no idea TT you could ping helpers naybe
@lean rock Has your question been resolved?
what are supposed to show here?
are you given that the diagram commutes and they want you to arrive at that equation?
because if yes then there is nothing to do
use the fact that there are two ways to go from d to a and two ways to go from d to b and the fact that <p,q> is unique
@lean rock Has your question been resolved?
I think maybe the point is to show the universal arrow exists
from given the outer arrows show there is the dashed arrow commutes with h
given f∘h and g∘h, there is this common <f,g>∘h, I guess
thanks for helping with this @grand hatch
also @grand hatch do you know by any chance if this is the product pattern of the multiplication part of dot product? I tried to draw it
and the additon part of it
oh this isn't
because it's first multiply then sum
$$
v_1 w_1 \xrightarrow{\iota_1} \bigoplus_i v_i w_i \xleftarrow{\iota_2} v_2 w_2 \quad \dots \quad \xleftarrow{\iota_n} v_n w_n
$$
kytsu
v × w ──⊗──► [v₁w₁, v₂w₂,…] ──Σ──► ℝ
how do you even type these symbols
@lean rock Has your question been resolved?
wit TikZ, and Latex https://tikz.dev/
thanks
and computer agent
v × w ──⊗──► [v₁w₁, v₂w₂,…] ──Σ──► ℝ
this is unicode,
and you can create shortcuts with espanso
also, computer agent writes stuff when you copy its message it is formatted latex
interesting
yes
yeah seems like it
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I've asked this before, but I'm still sort of confused
We have $X= \ln\left(\frac{1}{\sqrt{Y}}\right)$?
capital X and capital Y
wai
so $0<\ln\left(\frac{1}{\sqrt{y}}\right)< \infty$, right?
wai
so $1>√y>0 \implies 1>y>0$?
wai
yes
okay, so the density function simply is $e^{ln(y) }+ \frac{1}{2} e^{ln(√y)}$
wai
which is y+ √y/2
incorrect and also 2 counts of badtex
don't I simply sub into the original pdf now
find the cdf of X, THEN you can sub in (and even so you need to be careful with inequalities)
you will have in your script some theorem which tells you exactly the formula to use
I find the cdf, sub in and then differentiate
use that
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Hello
Given y=-4x and y=3^x intersecting at (a,b) then what is the intersection of y=-(x/8) and y=log_9(x)
I have ran into some contradiction
I dk where I did wrong
Do not be shy
It is a easy one
Just some manipulation of logarithm
i think you loved the idea of substitution a bit too much
its invalid substituting x = -1/4 3^x
thats only true at (a, b)
not for all x
For real. Why
It is math operation
you can substitute like that either if its an identity or you're solving for an intersection point where that graph is involved too
no its not
domain of log matters here
both graphs intersect at a fixed point
Why I can do what I did
Could you explain
a and b are constants
thats only true at a single point that has been given to you
not at the point you need to find
I’m so bad at it.
you equate them both only when you need to find their intersection point
it cant be found
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its a very weird point
I’m too sad
you probably need to find the new point in terms of (a, b)
.reopen
✅ Original question: #help-28 message
id suggest doing 9^ for the second eqn
lmao wym
an*
ok please just dont try involving both sets of equations together
still illegal
Why
try not to use substitution
I have to my best to follow the law of logarithm
not every time
How do you tell
Is there anything special about this one
the point of intersection is not same
Got u
just say
the first two equations they gave and the other two
please do not involve them together
whenever you equate two equations you indirectly find intersection points in questions like these
so the first two and the next two are two separate sets
the question setter on the other hand just wants you to find some clever way of representing the second set of equations such that it resembles the first set of equations
@golden shore Has your question been resolved?
That helps a lot
I will try this way
!done
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so is this.... like | |x| - |y| |
thats the norm of x - norm of y right lets call it z
then |z| is the abs value?
I think so
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<@&286206848099549185>
Dude you literally got asked smth, at least answer that
Bruh I didn’t know if that was me or not
I can’t even try. I’m so stuck on this concept I have no idea what to do
What do you think f(-1) means in words?
My boyfriend helped me with that before he had to hang up. From what I understood, basically since -3,0 was plotted it was negative.
Idk I barley understood 😭😭
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i dont understand this
In the picture, the intersection of the two lines are in which quadrant?
4
Can you find similar triangles
yes
What do you get from similar side lengths
im not really sure
It'll be something like this
https://www.gcse.com/maths/images/similar.gif
Do you see the proportions of side lengths are equal
oh yes
@tulip kettle Has your question been resolved?
What are you stuck on still
You know similar triangles?
Ratio of sides is constant
Yes
Use this
,calc 3/8
Result:
0.375
,calc 8/3
Result:
2.6666666666667
,calc 4/5
Result:
0.8
You should be comfortable converting fractions to decimals
i think the answers 8/3
Explain
If the answers are in fractions, then try to solve in fractions
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Why do i have to found some weird find x looks like this:
Whts the zero before the comma..?
Are those coordinates or smth
typo maybe
I imagine it’s 1/5 in decimal
It's 0.2
ye
Serbia uses , for decimals
Oh
If I assumed this is in Serbia!
did you come here to complain or do you need help solving this
!1q
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i need help solving this
Well I see two unrelated questions
ok so do you want the equation first, or the angle thing first
the equation
Eat soup with a fork instead of a knife
do you know how to work with ratios generally? @forest quail
my suggestion will be to simplify the ratio 0.2 : (1 1/5) as your first step
Simplify the mixed fraction
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(9. Find value/s of ‘a’ such that the linear system: 2x + 5y = 16; 3x + ay = 11, has unique solution.
10. Consider each of the following systems in unknowns x, y, z:
i) x – 2y = 1, x – y + az = 2, ay + 9z = b.
ii) x + 2y + 2z = 1, x + ay + 3z = 3, x + 11y + az = b.
iii) x + y + az = 1, x + ay + z = 4, ax + y + z = b.
A) For what values of a does the system have a unique solution, and for which pairs of value (a, b) does the system have more than one solution?
B) The value of b does not have any effect on whether the system has a unique solution. Justify.
11. Solve the following system of equations and interpret it geometrically.
i) x + y = 3, 2x – y = 5
ii) x + y = 3, 4x + 4y = 12
iii) x + y = 3, x + y = 5
iv) x + y + z = 6, 2x + y + z = 9
v) x + 2y + 3z = 0, 2x + 3y + 4z = 0, 4x + 7y + 10z = 0
vi) x + 2z = 0, y + z = 0)
let's start at the top with 9
okay
we have a linear system:
2x + 5y = 16
3x + ay = 11
they ask you to find value(s) of a such that there is only 1 pair of x and y that makes this true.
ohh okay
If you want to solve such a system, disregarding the variable a, what steps would you take?
matrix?
yes AX=B
How i would tackle it is to try to make a single formula out of it. As we don't know what a is, we can multiply the first formula by 3 and the second formula by 2 and get
6x + 15y = 48
6x + 2ay = 22
Can you do something with this?
@spiral parcel a matrix would also be good, do you know how you would put these values in one?
its only good for bigger equations or more equations
i dont think its feasible to do it in smaller equations
it's also fine for smaller equations. You just have a small matrix to find the reduced echelon form of.
true
its easier to do in this method then
technically this is exactly that but without formatting it in a proper matrix ^.^
why a matrix for this one
fr 😭
a linear eq can only have 1 unique sol, no sols or inf sols
why do you need a matrix 😭😭😭
not saying it's the best way, but it is a reliable way
and if you're comfortable with a method that works all the time, even if it's not the best method, it's worth it to use it in my opinion.
Alr
I would love to hear how you think it should be solved though, i'm here to learn after all. (though this is not my help channel, might have to move to discussion)
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I may be having a brainfart here, but can I have a hint
this is the method I'm using
soay, so X=U;V=X+2Y
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In linear algebra, when solving a system of differential equations, we can use the eigenvalue method, thus finding the eigenvalues, eigenvectors and then find the general solution for the system. However, often I notice that my approach looks like the answer, but is not 100% alike.
In the book for example, they used this approach where they didn't multiply the first row with (1/2). This causes my free variables in my general solution to not be 100% alike, does this matter, or is the solution still correct?
This is the solution of the book, while my solution was
[x;y] = (3/5) * [2;-3] * exp(4t) + (4/5) * (1;1) * exp(-t)
So each free variable, it doesn't matter what we set it as, the solution is still the same?
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translation?
i thought you are having a sleep for your chem test
you were lying this whole time
sleep didn't arrive
lel
😭
@heavy escarp Has your question been resolved?
before translating, first state which question it is you need help with, I suppose
there are like 7 questions here, subquestions not included
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actually nvm thx guys
Oh a malay one
!done
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can someone explain why rank(A) of a matrix A is the order of the biggest none 0 sub-determinant
$$\text{rank}(A) = \text{dimension of the column space of } A = \text{dimension of the row space of } A$$
Steven0925
@thin lark
This means $\text{rank}(A)$ is the maximum number of linearly independent columns (or rows) in the matrix $A$.
Steven0925
this is the definition no?
rank(A) is the maximum number of linearly independent columns
thats how my professor ddefined it in his notes
let me see
8.1.1 is the def
and 8.1.3 is the sub- determinant
its in greek
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kind of confused here
like unsure of how to setup the bounds
It's the region bound by y=x^2 and 1≤x+y≤2?
because the bounds are quite weird
are you allowed to graph the regions?
@thick hedge Has your question been resolved?
I did
non-integer intersection point is from x^2 = 1 - x
your integral just needs to be in this shaded region
@thick hedge
Yea, I just thought the bounds were weird
liks surds
what intersection point did you get
(1,1) and ((√5-1)/2, (3-√5/2)
you can see why I thought that's werid
like really strange coords for something to be done by hand
then again there arent very many integer coordinates that are usable here
fair enough
every integer coordinate the region intersects with has already been used
tq
np
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Let (F,+, x ) be a (commutative) field and V an F-Vectorspace and U a subspace of V and T a subspace of U.
Denote by V/U the factorspace, that is the set of equivalence classes of v in V w.r.t. U. We call v equiv to w, w.r.t. U , for v,w in V iff v-w is in U. Denote this by v~w
now I want to show that (V/T) / (U/T) is isomorphic to (V/U).
In principal I know how isomorphisms work and what equivalance classes and factor structures are, mainly from graph theory. But here I heavily lack intuition and have no real clue what such an isomorphism could look like.
Does anyone have hints or thoughts that could be useful?
my main problem is that I have no good image of these two structures in my head, ig
pick a basis for T, extend to basis for U and then basis for V
then think about what happens with all of those basis vectors in all of the various spaces
thanks a lot, I will try to check this out, though I should probably mention that we havent been introduced to the basis of a vectorspace yet. Only very basic stuff
well its not needed here
just gives some intuition
but quotient spaces before basis is certainly a decision
@tame bobcat Has your question been resolved?
lol
yeah the course structure is quite interesting
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the rhs is the ques
you have to solve the integral? sorry I didn't get what you mean by rhs is the ques its very "vague" haha
gotcha, I understand that, but you want to prove the equality yes? that the lhs = rhs?
yep
i dunno wot to do
good ideas on there, but $sin^2x + cos^2x = 1$ you can set that, from there, solve the straight forward integral of $cos2x$
do u think there might be smthn wrong with the question
PinkPurpleBlue
and then that should be like sin2x/2 = 2sinxcosx/2 and then keep simplifying, wait let me actually try on paper
the rhs is -(cot x + tan x) or is that a multiplication/
that is right
its a sum?
yep
gotcha I'm trying it, essentially its proving that sin2x/2 is equal to -(cotx + tanx) by moving things around, idk even if its true I'm trying it out
aah okay $sin2x/2 = sinxcosx$ however,$-(cotx + tanx) = -(1/(sinx cosx))$ they are not equal
PinkPurpleBlue
yeah -1/(RHS) should be the correct one where RHS means the current RHS
see $$(cotx + tanx) = \frac{cosx}{sinx} + \frac{sinx}{cosx} = \frac{sin^2x + cos^2x}{sinx cosx} = 1/sinxcosx$$ hence $$-(cotx + tanx) = \frac{-1}{sinxcosx}$$ but the integral simplifies to $$\frac{sin2x}{2} = sinx cosx$$
PinkPurpleBlue
do you understand why the itnegral simplifies to that?
Indeed.
yep
cool
thanks
you're welcome
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can someone explain chain rule for derivatives to me?
i dont get it at all
How to use it or what do you want to know
i study derivatives using chatgpt -ik not the best decision but i dont have much time and i need simple calc- and it says
if
f(x)=g(h(x)),
then
f′(x)=g′(h(x))⋅h′(x)
but here how are we supposed to calculate the g(h(x)) one
i didnt understand anything abt the rule tbh
bc like here we would need to do it again and again so it'd go forever no?
Like derivative of sin(2x) would be derivative of sin(2x)* derivative of (2x)
Okay so what they mean is that if you have a composition of functions
ex could be cos(2x+1) The chain rule tells you how to deffirentiate it
So here sin function is f(x) and 2x is g(x), so derivative of f(g(x)) is f'(g(x))*g'(x)
chatgpt gave these examples
how is the exponiental one have 2 functions? or the ln one?
Do you know you can apply chain rule in normal derivative too
Like derivative of e^x is derivative of e^x* derivative of x (which is just 1 so we ignore it)
So what's shown is, you have f(g(x)) as e^(3x + 5), and g(x) as (3x + 5), so when you differentiate it, you firstly differentiate it like normal (like e^(3x + 5) is just e^(3x + 5)), but then you multiply the derivative of g(x) to it too
so e is another function?
now g'(x) is 3, so we simply multiply 3 to the derivative of our original function
yes e^x is the "outer" function
Yes basically, e is a separate function and (3x + 5) is another function
then why do we have another rule for exponiental if we have chain rule?
for x^3x+5 for example
which rule am i supposed to do?
the exp. one or the chain rule?
both are quite different
IG you can do this by chain rule too, what's the exponential rule again?
Oh this cannot be done like that, it has x in power
but we have e here in the example and why do we use chain rule?
isnt it the same
its an unknown anyways like
i feel like ur judging me so much on the inside rn 😭
sorry if my questions dont make any sense
No see there's a difference, you can't compare x^x and e^x, in cases of x^x it is entirely different and we use a more complex version of the power rule
I'm not
So in cases like e^g(x), log(g(x)), sin(g(x)), etc, we use chain rule
In cases of x^(any constant), we use power rule
whats the special thing with e? what function is that
In cases of x^(g(x)), we use an advanced version of the power rule which you shouldn't be taught yet
didnt take calc in hs. did pre calc. took a gap year then. now im an econ major. so yeah i suck at it 🥲
exponential function, e is euler's number
oh
e is kinda known because e^x is among the only functions out there whose derivative is the same as the original function (e^x), so you encounter it a lot in calculus
you can look up like a cheat sheat of diffrent derivatives.
here is an example
But it is generally a good idea to get an understanding of these derivatives
I get that it is hard to remember but learning the ideas behind something is always better than just remembering everything
Yes, initially it feels like a chore but once you get the idea it all starts feeling basic
when we do the chain rule we do like this. now if you look at the highlighted part we must redo the chain rule over and over and over again based on the formula
im not asking this for e but for like other examples
like for me to calculate the derivative of f(g(x)) i must find the derivative of f(g(x))?
no
how is that supposed to work
but it has 2 functions so dont we use chain rule?
isnt d/dx ( f(g(x)) the same as that
so d/dx = f'(g(x))*g'(x) that is the chain rule
So you would differentiate f(x) and g(x) seperatly and insert g(x) into f'(x)
well for those functions the composite would be
3(5x+6)+4=15x+20 so you wouldn't use the chain rule
we use chain rule for e and ln only?
gpt says we use chain rule when we got 2 functions but here u say we dont use it
for this question
We can use it for any composite function that cant be reduced too a simpler term
so the example you gave you can reduce to a linear equation which is easier
e^(2x+4) can be reduced to be easier
yes
if it can be reduced to be easier then we cant use it for chain rule
but we just did
its proberlly the best rule their is
damn
how would you reduce e^(2x+4)
.
well mb then
oh it was a typo?
what i ment was in that case you would use the chain rule cause it can't be reduced
by can't be reduced what kind of things are included in it? like functions with x^2 ? are they included?
3x^2+3x+5
lets say
What is the composite functions
for that you would use the power rule and the addition rule (not sure if thats the english name)
alr thx
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If $A$ is open or closed, show $\partial int(A)= \varnothing$
AT LAST
$\partial A = \bar{A} \backslash \mathrm{int}(A)$
wai
ExpertEsquieESQUIE
that's a different question from what you wrote
I realised I kept making typos 😭
your ordering just isn't true
but anyway
if A is open, then int(A) = A
so del(A) = clos(A) \ A
suppose this is nonempty so there is some open set U in the boundary
then look at the neighbourhoods of all the points of U
I'm typing an answer
