#help-28

1 messages · Page 268 of 1

slate violet
#

equation 1 - equation 2 is (x + y)(x - y) + 2z(y - x) = 0

delicate torrent
#

First off, freak/freaky can be used if someone focuses on the SMALLEST detail. Secondly, you are a freak and you are freaky. Thirdly, if you can't help and still continues to harass me in this channel then I'll have to call the mods

keen vector
#

go on

narrow mica
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oh

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so i find z in terms of y too

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and then yeah

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i get a equation in terms of y

delicate torrent
narrow mica
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and technically x, y, z can all be interchangeable

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oh wait no

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they cant

delicate torrent
narrow mica
#

because they did 4,4,1

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instead of 4,4,4

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like the answers of each of the equations are not the same

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that sucks

delicate torrent
slate violet
#

you mean (x - y) but yep

delicate torrent
slate violet
#

also I'll tell you in advance that x = y has no solutions

full forumBOT
#

@narrow mica Has your question been resolved?

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cinder terrace
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cinder terrace
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fallen ivy
#

Problem 1 (10 points)

Compute the zeros, the vertex, the y-intercept, and the equation of the axis of symmetry for the parabola

y = -x^2 - 4x + 5.

Then draw the parabola in a coordinate system and justify that it is a function.

Problem 2 (5 points)

Justify that the parabola in Problem 1 is a function.

Answer to Problem 2

The parabola from Problem 1 is a function because every x-value corresponds to exactly one y-value.
If you draw a vertical line (the vertical line test), it will intersect the parabola at most once for any x-coordinate.
Since no vertical line hits the graph more than once, the graph represents a function.

fallen ivy
#

Why did I only get 5 points for problem 2?

delicate torrent
#

Damn

delicate torrent
fallen ivy
#

See

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It only goes through one time

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I mean it touches parabola once

delicate torrent
fallen ivy
#

If you draw a vertical line (the vertical line test), it will intersect the parabola at most once for any x-coordinate.
Since no vertical line hits the graph more than once, the graph represents a function….

#

How is it broad?

delicate torrent
fallen ivy
#

Then how would you word it?

delicate torrent
fallen ivy
#

And show me it

delicate torrent
#

Oh wait nvm

delicate torrent
#

I just noticed that when im trying to explain to ya

slate violet
#

Icelandic, huh

fallen ivy
#

Omg I’m so dumb

delicate torrent
fallen ivy
#

Omg I have 67 battery

delicate torrent
#

six seven

delicate torrent
fallen ivy
#

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fallen ivy
#

y = -x^2-4x+5

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neon rivet
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neon rivet
#

I need some help with this question

delicate torrent
#

okay

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so probability of smth

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is just

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$\frac{\text{The number of cases that satisfies the condition}}{\text{The total of cases}}$

glossy valveBOT
#

1 divided by 0 equals Infinity

delicate torrent
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so to figure out the denominator, it's obvious

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and to figure out the numerator, you need to count how many cases that satisfies the question

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for example, in question c), you would need to count how many even numbers are there in a die

neon rivet
#

What I did 1/6 *2, giving me 1/3

knotty grail
#

which is not true in this case

delicate torrent
#

oh...

knotty grail
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since we dont know the chance of getting a one
say probability of landing a 1 is p
and the probability of not landing a 1 is 1-p (since those are the only options)

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the question has stated that p = 2(1-p)

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P(getting a one) = 2 x P(not getting a one)

neon rivet
#

why 1 is p

knotty grail
#

or just P(dice lands on 1) = p

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P(dice doesnt land on 1) = 1 - p

neon rivet
#

I’ll come back to this question since it’s a bit challenging but I want to really understand combinations and permutations

knotty grail
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sure

neon rivet
#

I watched few videos but the concept looks difficult for me to understand

knotty grail
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well do you understand the die questions without any modifications

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like just finding the probability of rolling an even number on a fair die

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that kind of questions

neon rivet
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I should be able to

knotty grail
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then the next tier would be questions like these

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where you have a biased coin or die

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it would be easier if you are given the probabilities

neon rivet
#

Are you referring to the original post

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Or getting me to understand combinations/ permutations

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I’ll open a new channel because I want to come back to this question

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steep shoal
#

Hello, can I perform two different operations in gauss elimination in one step?

steep shoal
#

Is there a higher chance of an error then? Also can I perform two same operations in one step?

foggy vapor
slate violet
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even though you can mathematically

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and these mistakes are also super hard to find yourself

foggy vapor
#

In reality gaussian elimination is multiplying a sequence of elementary matrices like this [
E_kE_{k-1}\cdots E_1A
]
So mathematically nothing changes if you decide on combining some of those matrices together when multiplying

glossy valveBOT
slate violet
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(matrix multiplication is associative)

steep shoal
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I genuinely dont know what im doing wrong but I've been trying to get these right fir hours now

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Im solving it the correct way (I think) cause in the end my answer IS in standard echelon form but the variables answers just dont match

foggy vapor
#

Just show the problem and your work

steep shoal
#

Wait up ill solve another one and share it here (if I get the wrong ans again, which is most likely)

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?? What am I doing wrong, the last columns value is incorrect :(((( I've been trying

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Nvm I wrote 37 instead of 27💀

#

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sturdy valve
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sturdy valve
#

can someone help w this

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only a part

restive sapphire
#

C10 + c11 = 2^1

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C20 + c21 + c22 = 2^2

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And it continues

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So u have 2^n/n!

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That’s on b

sturdy valve
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i said only a part

restive sapphire
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It’s only a part

sturdy valve
#

.

restive sapphire
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Ur far far away from the awnser still with my tips

sturdy valve
#

i meant i need help only with the (a) summation

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not b

restive sapphire
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C22 = 1

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C32=3

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C42= 6

rapid rain
sturdy valve
#

but if u could help me derive one ill be sure to remember that

restive sapphire
#

This looks like a low Olympiad question ngl

rapid rain
restive sapphire
#

Not so hard but it’s sketchy

rapid rain
#

or like just

sturdy valve
rapid rain
#

use factorial formula

restive sapphire
#

Whats jee

sturdy valve
sturdy valve
rapid rain
#

2C2 = 1, 3C2 = 3, 4C2 = 6...

onyx imp
rapid rain
#

The objective is to get nC2 in terms of n

sturdy valve
restive sapphire
#

N!/(p!(n-p)!)

sturdy valve
#

so how do we do that

restive sapphire
#

That’s ur ncp formula

sturdy valve
restive sapphire
#

It’s not

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He’s trynna see what ur knowledge base is

sturdy valve
#

what prompted that i dont know how to calculate nCk..

onyx imp
sturdy valve
restive sapphire
#

And see if there’s a progression

sturdy valve
#

bro

restive sapphire
#

And how to converge it

sturdy valve
#

ur giving very general instructions..

restive sapphire
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It’s not

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Compute c22

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C32

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C42

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( I already did it for u just scroll up )

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Then u see if there’s a progression that converges

sturdy valve
#

1 + 1/3! + 3/4! + 6/5!....

restive sapphire
#

Yeah

sturdy valve
#

ye so next what

restive sapphire
#

See if it converges

sturdy valve
#

it will obviously converge they wont expect an answer as infinity

restive sapphire
#

Then see how it converges

sturdy valve
#

how do i do that

restive sapphire
#

U should study that topic a bit more for that question

#

It goes a bit deep into series from my understanding

sturdy valve
#

bro

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if that was so it wouldnt appear in the exam

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<@&286206848099549185>

restive sapphire
#

Wym

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Is series not in the tests expected topics ?

sturdy valve
#

;/

restive sapphire
sour shore
#

There's formulae for binomial series.....

restive sapphire
#

But that’s calc 2 🤔

#

Isn’t that a college entrance exam? Or do u guys study that in hs

sturdy valve
restive sapphire
#

First thing that pops up

sturdy valve
#

but that is not the series we have here right

sour shore
#

Acc I'll need to look into it which i cant rn

sturdy valve
#

for one thing ours starts from 3!

sour shore
#

Maybe try writing the general form?

sturdy valve
#

that got me nowhere

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summation r C 2/ (r+1)!

random totem
# sturdy valve

Ignore the first term

The general term of a should be nC2/(n+1)! Right

Now nC2 = (n²-n)/2

So general term will be (n²-n)/(n+1)! Ignoring the 2 in denominator for now

Now spilit the fraction

n²/(n+1)! - n/(n+1)!

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Now add and subtract 1

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Ig it should work

sour shore
sturdy valve
random totem
#

(n²-1)/(n+1)! + 1/(n+1)! -(n+1)/(n+1)! + 1/(n+1)!

(n-1)/n! + 2/(n+1)! -1/n!

1/(n-1)! - 2/n! + 2/(n+1)!

#

Like this

random totem
random totem
sturdy valve
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ohh yes yes

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and then use e^x expansion yes?

random totem
#

Yes

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All terms will be e

sturdy valve
#

okay got it

#

thanks a lot

#

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lost topaz
#

Hello

full forumBOT
lost topaz
#

we meet again since the last school year

sonic stratus
#

Just send the question

lost topaz
#

yeah, i need help to understand what did my friend do here

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i understand the thing in blue

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i have no idea what she did next

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or maybe what would you do here cause i dont know what should I do and if i should do the same as her

forest trail
# lost topaz

Hi! If you understand the blue bit, then essentially the strategy is to split up the integral in two, then evaluate each integral. The bottom left portion bit evaluates one integral, so now you have to evaluate the other one.

lost topaz
#

yeah i figured that

forest trail
lost topaz
#

but i dont know how

forest trail
lost topaz
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hollup

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let me think what i couldve done

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ohhhhhhhhhhhhhhh

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should i put it into

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(fraction)^-1?

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oh nono

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cause i cant get the derivative out

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its 2x+2

forest trail
#

I'll leave this hint again: How would you integrate? [ \int \frac{1}{1 + x^2} , dx ]

glossy valveBOT
#

Redfern Station

lost topaz
#

its arctan(x)

forest trail
forest trail
lost topaz
#

you want me to find an arctan?

forest trail
lost topaz
#

so like

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x^2 + 2x +4 +1?

forest trail
forest trail
lost topaz
#

so it gives

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arctan(Sqrt(x^2+2x+4))?

forest trail
forest trail
lost topaz
#

could you please send a sheet if you know one of integrals of arctan arccos and arcsen?

forest trail
#

But you are missing some things

lost topaz
#

cause i dont know the actual formula on how to get arctan

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wait if i split up i can find the roots?

forest trail
forest trail
lost topaz
#

oh right

forest trail
forest trail
lost topaz
forest trail
#

You need to tell me what exactly the new fraction is

lost topaz
forest trail
lost topaz
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and it gives arctan(x)

forest trail
#

x^2 + 2x + 4 isn't a perfect square

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Well

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Yeah, its not a perfect square

lost topaz
#

whats that supposed to mean

forest trail
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You specifically need something that is squared

lost topaz
#

ok

forest trail
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x^2 + 2x + 4 isn't a 'square'

lost topaz
#

oh right 2 is like

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1.4 smth squared

forest trail
#

Sure, but its more of an algebraic thing

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Remember your denominator is x^2 + 2x + 5

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How do we usually turn expressions like these into squares?

lost topaz
#

using sqrt?

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square root

forest trail
#

There's a specific process

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That allows us to get squares

lost topaz
#

so like sqrt(x^2) = x so x^2 is x^2

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nope?

forest trail
#

Nope

forest trail
# lost topaz

The hint is that your friend actually attempted this strategy

#

You can see in their working out that they actually used some strategy to get a square.

lost topaz
#

yeah no idea what are these 1/2 1/2

forest trail
#

Dw about that bit, look below

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Look at the denominator - how did you friend get that?

lost topaz
#

ok i see some part of it

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she gets the x^2 + 2x + 1 roota

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roots

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now these roots + 4 = no idea

forest trail
#

Wait, wdym by 'roots'?

lost topaz
#

(x+1)^2

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arent they called roots in english?

forest trail
#

Perfect, yeah - that's what I meant by finding a square

lost topaz
#

like simplifying the formula

forest trail
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(x + 1)^2 is a square, and the exact one I am looking for

lost topaz
#

why

forest trail
forest trail
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We need something that is squared.

lost topaz
#

x^2-1=0

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x= +1, -1

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these things^

forest trail
#

Yeah but

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We want specifically an expression that has the same roots

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So we can write it as (x + a)^2

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That specifically is called completing the square

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Like when you are solving for the roots, you need to complete the square

lost topaz
#

ohhhhhhh

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SO 4 IS 2^2

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AND 4 IS A?

forest trail
forest trail
#

Thats it

lost topaz
#

omg

forest trail
#

Well

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4 is a^2

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So 2 is a

lost topaz
#

and

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wait

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okay

forest trail
lost topaz
#

so its 1/2*arctg((x+1)/2)+c?

forest trail
#

That's exactly it

lost topaz
#

so she has it wrong in the last part where it is divided by 2?

forest trail
#

Basically

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She was using another strategy

forest trail
# lost topaz

I was going to say, I think this is the method your friend was leading up to

#

Basically if you didnt know the formula for arctan generally, but you did know that the integral of 1/(1 + x^2) is arctan(x),

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You can directly write it in that form

lost topaz
#

oh

forest trail
#

That way you get the first integral at the bottom

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Then you just use reverse chain rule

lost topaz
#

oh

forest trail
lost topaz
#

omg 😮

#

thank you so much

#

im sorry do you do private classes?

forest trail
# lost topaz thank you so much

My pleasure :)
Unfortunately I only tutor on my own country (which is Australia)! Unless that was just a question out of curiosity :)

forest trail
#

Sometimes I just watch other people solve. It's kind of interesting sometimes

lost topaz
#

thank you again so much

#

ig see you sometime

#

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valid spear
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valid spear
#

Hello, is anyone able yo check if i have done part C correct?

#

Excuse the tipex at tge top, i missed out a step lol

restive geyser
#

,rccw

glossy valveBOT
restive geyser
valid spear
#

Ohh, i missed the negative sign

#

,rccw

glossy valveBOT
valid spear
#

This better?

restive geyser
#

ye

valid spear
#

Thanksss

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drifting fog
#

I was given the equation (x-2)^2 + (y-3)^2 = 9. I have to apply a vertical stretch about the x-axis by a factor of 2 and determine the equation of the conic in standard form. How would I go about doing this?

viral jasper
drifting fog
#

thanks for the help

#

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torn jolt
#

hi can someone explain this to me

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maiden vapor
# torn jolt hi can someone explain this to me

The intuition is that you’re distributing n identical items into m boxes. A multiset selection is the same as deciding how many balls go in each box… That division is done by placing m-1 separators among n+m-1 slots. That’s why the formula is \binom{n+m-1}{m-1}.

#

Example with n = 7, m = 4:
so we have 7 identical things * to distribute into 4 different boxes.

**|****| |*

This is one such arrangement.

torn jolt
#

oh thanks

torn jolt
maiden vapor
#

You can look up a more concrete example by searching stars and bars combinatorics.

maiden vapor
# torn jolt and where does the countint multiset happens

It just represents the number of ways to choose which positions out of n+m-1 total positions will be the bars. We have n stars (the items). We have m-1 bars (the separators). So in total we have n + m - 1 slots to fill. If you choose which m-1 slots contain bars, the rest must be stars.

#

That is why the given expression is also equal to.

#

[wrb{binom{n+m-1}{m-1} \overset{\catthink}=binom{n+m-1}n}]

glossy valveBOT
#

クーリー

torn jolt
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#

@torn jolt Has your question been resolved?

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#
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near jewel
#

I only need the profit. sadcatthumbsup

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#

Please don't repeatedly close and claim a new channel with the exact same question. This erases all previous progress made towards your problem and is confusing for helpers, making it more difficult to help you. Please be patient, even if your channel has not received much attention.

stoic sundial
#

@near jewel

near jewel
#

I think it's Profit = total revenue – total cost.

stoic sundial
stoic sundial
#

the total revenue

near jewel
#

I have no clue that's why I came here lol

stoic sundial
#

Give it a guess

#

@near jewel

near jewel
#

total Revenue = price per unit × quantity sold

stoic sundial
#

now apply it to profit = tr - tc

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you will get the result

#

@near jewel

#

now you only need to find the ATC curve and its value

near jewel
#

What's the total cost?

#

@stoic sundial u still here?

#

??

#

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stoic sundial
#

sorry

#

i was busy

#

we can talk more in dms

#

@near jewel

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lean rock
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sour shore
sour shore
lean rock
lean rock
sour shore
#

i ddont think I've studied thht yet

lean rock
#

maybe dot product just has similar name, I don't yet know

sour shore
#

dot product is scalar product of vectors

#

|A||B|ccosx

lean rock
#

I think the multiplication part has this pattern from the diagram
each v₁w₁, v₂w₂,… is v₁ × w₁, or a × b

#

and the additions are co-products a + b which have I think the dual drawing, where you reverse all the arrows

sour shore
#

no its ntg related to vectors

#

is it functions nd stuff?

lean rock
#

look, every arrow is going the other direction for +

sour shore
#

welp hvnt studied tht

lean rock
# sour shore is it functions nd stuff?

this is category theory, and these arrows are more abstract/general than functions, they morphisms, or simply arrows
functions are arrows, but not all arrows are functions
as far as I know functions map sets, arrows, morphisms can map all sorts of things,

sour shore
#

i hv no idea TT you could ping helpers naybe

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#

@lean rock Has your question been resolved?

grand hatch
#

are you given that the diagram commutes and they want you to arrive at that equation?

#

because if yes then there is nothing to do

#

use the fact that there are two ways to go from d to a and two ways to go from d to b and the fact that <p,q> is unique

full forumBOT
#

@lean rock Has your question been resolved?

lean rock
#

thanks for helping with this @grand hatch

lean rock
#

and the additon part of it

#

oh this isn't

#

because it's first multiply then sum

#

$$
v_1 w_1 \xrightarrow{\iota_1} \bigoplus_i v_i w_i \xleftarrow{\iota_2} v_2 w_2 \quad \dots \quad \xleftarrow{\iota_n} v_n w_n
$$

glossy valveBOT
lean rock
#

v × w ──⊗──► [v₁w₁, v₂w₂,…] ──Σ──► ℝ

stoic sundial
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#

@lean rock Has your question been resolved?

lean rock
stoic sundial
lean rock
#

v × w ──⊗──► [v₁w₁, v₂w₂,…] ──Σ──► ℝ
this is unicode,
and you can create shortcuts with espanso

https://espanso.org/

lean rock
lean rock
stoic sundial
lean rock
stoic sundial
#

yeah seems like it

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thick hedge
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thick hedge
#

I've asked this before, but I'm still sort of confused

#

We have $X= \ln\left(\frac{1}{\sqrt{Y}}\right)$?

onyx glen
#

capital X and capital Y

glossy valveBOT
thick hedge
#

so $0<\ln\left(\frac{1}{\sqrt{y}}\right)< \infty$, right?

glossy valveBOT
thick hedge
#

so $1>√y>0 \implies 1>y>0$?

glossy valveBOT
onyx glen
#

yes

thick hedge
#

okay, so the density function simply is $e^{ln(y) }+ \frac{1}{2} e^{ln(√y)}$

glossy valveBOT
thick hedge
#

which is y+ √y/2

onyx glen
thick hedge
onyx glen
#

find the cdf of X, THEN you can sub in (and even so you need to be careful with inequalities)

fast peak
#

you will have in your script some theorem which tells you exactly the formula to use

thick hedge
fast peak
#

use that

thick hedge
#

this works I suppose

#

y=e^{-2x} is a decreasing function

#

got it

#

tq

#

.close

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golden shore
#

Hello

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golden shore
#

Given y=-4x and y=3^x intersecting at (a,b) then what is the intersection of y=-(x/8) and y=log_9(x)

#

I have ran into some contradiction

#

I dk where I did wrong

#

Do not be shy

#

It is a easy one

#

Just some manipulation of logarithm

knotty grail
#

its invalid substituting x = -1/4 3^x

#

thats only true at (a, b)

#

not for all x

golden shore
#

It is math operation

knotty grail
#

you can substitute like that either if its an identity or you're solving for an intersection point where that graph is involved too

golden shore
#

(a,b) is an intersection point

#

It is a movable intersection point

knotty grail
#

no its not

frigid carbon
knotty grail
#

both graphs intersect at a fixed point

golden shore
#

Could you explain

frigid carbon
golden shore
#

Ohhh

knotty grail
#

not at the point you need to find

golden shore
#

I’m so bad at it.

knotty grail
#

you equate them both only when you need to find their intersection point

golden shore
#

I did not notice (a,b) can be found

#

I feel so bad

knotty grail
#

it cant be found

golden shore
#

.close

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knotty grail
#

its a very weird point

golden shore
#

I’m too sad

knotty grail
#

you probably need to find the new point in terms of (a, b)

frigid carbon
#

better not be found

golden shore
#

.reopen

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knotty grail
#

id suggest doing 9^ for the second eqn

golden shore
#

I just have to make it legal

#

I have to operate legally

#

I’m no longer in Mexico

frigid carbon
#

lmao wym

golden shore
#

Okay

#

That’s legal

neon basin
knotty grail
# golden shore

ok please just dont try involving both sets of equations together

frigid carbon
golden shore
frigid carbon
frigid carbon
golden shore
golden shore
#

To find relation

frigid carbon
golden shore
#

Is there anything special about this one

frigid carbon
#

the point of intersection is not same

golden shore
knotty grail
#

just say

#

the first two equations they gave and the other two

#

please do not involve them together

#

whenever you equate two equations you indirectly find intersection points in questions like these

#

so the first two and the next two are two separate sets

#

the question setter on the other hand just wants you to find some clever way of representing the second set of equations such that it resembles the first set of equations

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@golden shore Has your question been resolved?

golden shore
#

I will try this way

kind prism
#

!done

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dim gyro
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dim gyro
#

so is this.... like | |x| - |y| |

thats the norm of x - norm of y right lets call it z

then |z| is the abs value?

dim gyro
#

this is an old book and they dont use notation im used too

#

thanks

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.close

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plush socket
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static bramble
plush socket
#

<@&286206848099549185>

brittle sun
#

Dude you literally got asked smth, at least answer that

plush socket
#

Bruh I didn’t know if that was me or not

#

I can’t even try. I’m so stuck on this concept I have no idea what to do

gritty rose
plush socket
#

My boyfriend helped me with that before he had to hang up. From what I understood, basically since -3,0 was plotted it was negative.

Idk I barley understood 😭😭

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tulip kettle
#

i dont understand this

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unreal wren
tulip kettle
#

4

unreal wren
#

Hm

#

So which of the 4 options represent a point in the 4th quadrant?

tulip kettle
#

B?

#

ohhh

#

okay

#

thank you

#

uhh

#

can someone also help with this

gritty rose
#

Can you find similar triangles

tulip kettle
#

yes

gritty rose
#

What do you get from similar side lengths

tulip kettle
#

im not really sure

gritty rose
#

Do you see the proportions of side lengths are equal

tulip kettle
#

oh yes

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@tulip kettle Has your question been resolved?

gritty rose
tulip kettle
#

the answers are in fractions

#

so i just dont get that

frigid carbon
#

Ratio of sides is constant

gritty rose
glossy valveBOT
#

Result:

0.375
gritty rose
#

,calc 8/3

glossy valveBOT
#

Result:

2.6666666666667
gritty rose
#

,calc 4/5

glossy valveBOT
#

Result:

0.8
gritty rose
#

You should be comfortable converting fractions to decimals

tulip kettle
#

i think the answers 8/3

gritty rose
burnt turret
#

8/3

#

use similarity of triangles

#

3/(3+2) = 4/(4+x)

#

Then solve for x

burnt turret
burnt turret
#

Don't go to decimal

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forest quail
#

Why do i have to found some weird find x looks like this:

forest quail
#

...

#

someone help me

sour shore
#

Are those coordinates or smth

frigid carbon
eternal terrace
#

I imagine it’s 1/5 in decimal

neon basin
#

It's 0.2

forest quail
#

ye

neon basin
#

Serbia uses , for decimals

sour shore
neon basin
#

If I assumed this is in Serbia!

onyx glen
#

!1q

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It is suggested that you limit yourself to one question per help channel, opening a new one once your original question is answered and your original channel has been closed. This is to make your channel easier to follow for potential helpers and can bring attention to the fact that your question has changed.

forest quail
#

i need help solving this

neon basin
#

Well I see two unrelated questions

onyx glen
#

ok so do you want the equation first, or the angle thing first

forest quail
#

the equation

eternal terrace
#

Change : to division first

#

Rewrite the question with / instead of :

neon basin
#

Eat soup with a fork instead of a knife

onyx glen
#

do you know how to work with ratios generally? @forest quail

#

my suggestion will be to simplify the ratio 0.2 : (1 1/5) as your first step

sour shore
#

Simplify the mixed fraction

onyx glen
#

oh yeah sure that too

#

let's wait for op to respond though

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spiral parcel
#

(9. Find value/s of ‘a’ such that the linear system: 2x + 5y = 16; 3x + ay = 11, has unique solution.
10. Consider each of the following systems in unknowns x, y, z:
i) x – 2y = 1, x – y + az = 2, ay + 9z = b.
ii) x + 2y + 2z = 1, x + ay + 3z = 3, x + 11y + az = b.
iii) x + y + az = 1, x + ay + z = 4, ax + y + z = b.
A) For what values of a does the system have a unique solution, and for which pairs of value (a, b) does the system have more than one solution?
B) The value of b does not have any effect on whether the system has a unique solution. Justify.
11. Solve the following system of equations and interpret it geometrically.
i) x + y = 3, 2x – y = 5
ii) x + y = 3, 4x + 4y = 12
iii) x + y = 3, x + y = 5
iv) x + y + z = 6, 2x + y + z = 9
v) x + 2y + 3z = 0, 2x + 3y + 4z = 0, 4x + 7y + 10z = 0
vi) x + 2z = 0, y + z = 0)

spiral parcel
#

any one knows ho to solve these

#

how*

sinful prism
#

let's start at the top with 9

spiral parcel
#

okay

sinful prism
#

we have a linear system:

2x + 5y = 16
3x + ay = 11

#

they ask you to find value(s) of a such that there is only 1 pair of x and y that makes this true.

spiral parcel
#

ohh okay

sinful prism
#

If you want to solve such a system, disregarding the variable a, what steps would you take?

spiral parcel
#

matrix?

unborn ore
sinful prism
#

How i would tackle it is to try to make a single formula out of it. As we don't know what a is, we can multiply the first formula by 3 and the second formula by 2 and get

6x + 15y = 48
6x + 2ay = 22

Can you do something with this?

#

@spiral parcel a matrix would also be good, do you know how you would put these values in one?

unborn ore
#

i dont think its feasible to do it in smaller equations

sinful prism
unborn ore
sinful prism
delicate torrent
delicate torrent
delicate torrent
sinful prism
#

and if you're comfortable with a method that works all the time, even if it's not the best method, it's worth it to use it in my opinion.

sinful prism
#

I would love to hear how you think it should be solved though, i'm here to learn after all. (though this is not my help channel, might have to move to discussion)

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thick hedge
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#

Please don't occupy multiple help channels.

thick hedge
#

I may be having a brainfart here, but can I have a hint

#

this is the method I'm using

#

soay, so X=U;V=X+2Y

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shadow furnace
#

In linear algebra, when solving a system of differential equations, we can use the eigenvalue method, thus finding the eigenvalues, eigenvectors and then find the general solution for the system. However, often I notice that my approach looks like the answer, but is not 100% alike.

In the book for example, they used this approach where they didn't multiply the first row with (1/2). This causes my free variables in my general solution to not be 100% alike, does this matter, or is the solution still correct?

shadow furnace
#

This is the solution of the book, while my solution was

[x;y] = (3/5) * [2;-3] * exp(4t) + (4/5) * (1;1) * exp(-t)

astral sinew
#

Yeah...

#

4/5 (1,1) = 2/5 (2,2)

shadow furnace
#

So each free variable, it doesn't matter what we set it as, the solution is still the same?

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heavy escarp
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sour shore
#

translation?

delicate torrent
#

you were lying this whole time

sour shore
#

sleep didn't arrive

delicate torrent
#

lel

sour shore
#

😭

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@heavy escarp Has your question been resolved?

full whale
#

before translating, first state which question it is you need help with, I suppose
there are like 7 questions here, subquestions not included

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heavy escarp
#

actually nvm thx guys

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full whale
#

you reopened the channell

#

if you have nothing else, you can close it back

delicate imp
warped frost
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heavy escarp
#

!done

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heavy escarp
#

.close

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thin lark
#

can someone explain why rank(A) of a matrix A is the order of the biggest none 0 sub-determinant

kind prism
#

$$\text{rank}(A) = \text{dimension of the column space of } A = \text{dimension of the row space of } A$$

glossy valveBOT
#

Steven0925

kind prism
#

@thin lark

#

This means $\text{rank}(A)$ is the maximum number of linearly independent columns (or rows) in the matrix $A$.

glossy valveBOT
#

Steven0925

thin lark
#

rank(A) is the maximum number of linearly independent columns

#

thats how my professor ddefined it in his notes

kind prism
#

let me see

thin lark
#

8.1.1 is the def

#

and 8.1.3 is the sub- determinant

#

its in greek

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thick hedge
#

kind of confused here

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thick hedge
#

like unsure of how to setup the bounds

#

It's the region bound by y=x^2 and 1≤x+y≤2?

#

because the bounds are quite weird

spice knot
#

are you allowed to graph the regions?

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@thick hedge Has your question been resolved?

thick hedge
spice knot
#

non-integer intersection point is from x^2 = 1 - x

#

your integral just needs to be in this shaded region

#

@thick hedge

thick hedge
#

liks surds

spice knot
#

what intersection point did you get

thick hedge
#

(1,1) and ((√5-1)/2, (3-√5/2)

spice knot
#

are you sure on that y-coordinate?

#

nvm its correct

thick hedge
#

you can see why I thought that's werid

#

like really strange coords for something to be done by hand

spice knot
#

then again there arent very many integer coordinates that are usable here

thick hedge
#

fair enough

spice knot
#

every integer coordinate the region intersects with has already been used

thick hedge
#

tq

spice knot
#

np

thick hedge
#

I'll close this jow

#

*now

#

.close

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tame bobcat
#

Let (F,+, x ) be a (commutative) field and V an F-Vectorspace and U a subspace of V and T a subspace of U.
Denote by V/U the factorspace, that is the set of equivalence classes of v in V w.r.t. U. We call v equiv to w, w.r.t. U , for v,w in V iff v-w is in U. Denote this by v~w

now I want to show that (V/T) / (U/T) is isomorphic to (V/U).

In principal I know how isomorphisms work and what equivalance classes and factor structures are, mainly from graph theory. But here I heavily lack intuition and have no real clue what such an isomorphism could look like.

Does anyone have hints or thoughts that could be useful?

tame bobcat
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my main problem is that I have no good image of these two structures in my head, ig

fast peak
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pick a basis for T, extend to basis for U and then basis for V

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then think about what happens with all of those basis vectors in all of the various spaces

tame bobcat
fast peak
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well its not needed here

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just gives some intuition

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but quotient spaces before basis is certainly a decision

full forumBOT
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@tame bobcat Has your question been resolved?

tame bobcat
#

yeah the course structure is quite interesting

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livid rapids
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livid rapids
#

the rhs is the ques

unique cloud
#

you have to solve the integral? sorry I didn't get what you mean by rhs is the ques its very "vague" haha

livid rapids
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haha

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yeah

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rhs like

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right hand side

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wrt to the equals to

unique cloud
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gotcha, I understand that, but you want to prove the equality yes? that the lhs = rhs?

livid rapids
unique cloud
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good ideas on there, but $sin^2x + cos^2x = 1$ you can set that, from there, solve the straight forward integral of $cos2x$

livid rapids
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do u think there might be smthn wrong with the question

glossy valveBOT
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PinkPurpleBlue

livid rapids
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yeah but will i get the answer

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lemme try

unique cloud
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and then that should be like sin2x/2 = 2sinxcosx/2 and then keep simplifying, wait let me actually try on paper

livid rapids
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yea

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pls do

unique cloud
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the rhs is -(cot x + tan x) or is that a multiplication/

livid rapids
unique cloud
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its a sum?

livid rapids
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yep

unique cloud
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gotcha I'm trying it, essentially its proving that sin2x/2 is equal to -(cotx + tanx) by moving things around, idk even if its true I'm trying it out

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aah okay $sin2x/2 = sinxcosx$ however,$-(cotx + tanx) = -(1/(sinx cosx))$ they are not equal

glossy valveBOT
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PinkPurpleBlue

livid rapids
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could there be a mistake perhaps

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in the question

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a frnd of mine is saying that

unique cloud
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yeah -1/(RHS) should be the correct one where RHS means the current RHS

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see $$(cotx + tanx) = \frac{cosx}{sinx} + \frac{sinx}{cosx} = \frac{sin^2x + cos^2x}{sinx cosx} = 1/sinxcosx$$ hence $$-(cotx + tanx) = \frac{-1}{sinxcosx}$$ but the integral simplifies to $$\frac{sin2x}{2} = sinx cosx$$

glossy valveBOT
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PinkPurpleBlue

livid rapids
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yea

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the ques might be a bit wrong then

unique cloud
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do you understand why the itnegral simplifies to that?

unique cloud
livid rapids
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yep

unique cloud
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cool

livid rapids
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thanks

unique cloud
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you're welcome

full forumBOT
#

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#
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white roost
#

can someone explain chain rule for derivatives to me?

white roost
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i dont get it at all

peak shale
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How to use it or what do you want to know

white roost
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i study derivatives using chatgpt -ik not the best decision but i dont have much time and i need simple calc- and it says

if
f(x)=g(h(x)),
then
f′(x)=g′(h(x))⋅h′(x)

but here how are we supposed to calculate the g(h(x)) one

white roost
white roost
slate glacier
#

Like derivative of sin(2x) would be derivative of sin(2x)* derivative of (2x)

peak shale
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Okay so what they mean is that if you have a composition of functions
ex could be cos(2x+1) The chain rule tells you how to deffirentiate it

slate glacier
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So here sin function is f(x) and 2x is g(x), so derivative of f(g(x)) is f'(g(x))*g'(x)

white roost
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chatgpt gave these examples

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how is the exponiental one have 2 functions? or the ln one?

slate glacier
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Do you know you can apply chain rule in normal derivative too

white roost
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tbh idk anything abt derivatives at all 🥲

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im just learning it for my exam

slate glacier
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Like derivative of e^x is derivative of e^x* derivative of x (which is just 1 so we ignore it)

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So what's shown is, you have f(g(x)) as e^(3x + 5), and g(x) as (3x + 5), so when you differentiate it, you firstly differentiate it like normal (like e^(3x + 5) is just e^(3x + 5)), but then you multiply the derivative of g(x) to it too

white roost
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so e is another function?

slate glacier
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now g'(x) is 3, so we simply multiply 3 to the derivative of our original function

peak shale
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yes e^x is the "outer" function

slate glacier
white roost
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then why do we have another rule for exponiental if we have chain rule?

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for x^3x+5 for example

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which rule am i supposed to do?

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the exp. one or the chain rule?

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both are quite different

slate glacier
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IG you can do this by chain rule too, what's the exponential rule again?

white roost
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power rule like

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x^3 -> 3x^2

slate glacier
white roost
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but we have e here in the example and why do we use chain rule?

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isnt it the same

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its an unknown anyways like

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i feel like ur judging me so much on the inside rn 😭

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sorry if my questions dont make any sense

slate glacier
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No see there's a difference, you can't compare x^x and e^x, in cases of x^x it is entirely different and we use a more complex version of the power rule

peak shale
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Calculus is hard

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Its okay to not understand at first

slate glacier
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So in cases like e^g(x), log(g(x)), sin(g(x)), etc, we use chain rule

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In cases of x^(any constant), we use power rule

white roost
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whats the special thing with e? what function is that

slate glacier
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In cases of x^(g(x)), we use an advanced version of the power rule which you shouldn't be taught yet

white roost
slate glacier
white roost
slate glacier
#

e is kinda known because e^x is among the only functions out there whose derivative is the same as the original function (e^x), so you encounter it a lot in calculus

peak shale
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you can look up like a cheat sheat of diffrent derivatives.
here is an example

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But it is generally a good idea to get an understanding of these derivatives

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I get that it is hard to remember but learning the ideas behind something is always better than just remembering everything

slate glacier
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Yes, initially it feels like a chore but once you get the idea it all starts feeling basic

white roost
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when we do the chain rule we do like this. now if you look at the highlighted part we must redo the chain rule over and over and over again based on the formula

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im not asking this for e but for like other examples

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like for me to calculate the derivative of f(g(x)) i must find the derivative of f(g(x))?

peak shale
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no

white roost
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how is that supposed to work

peak shale
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you would find the derivative f'(x)

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and insert g(x)

white roost
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but it has 2 functions so dont we use chain rule?

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isnt d/dx ( f(g(x)) the same as that

peak shale
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so d/dx = f'(g(x))*g'(x) that is the chain rule

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So you would differentiate f(x) and g(x) seperatly and insert g(x) into f'(x)

white roost
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for f 3x+4 and g 5x+6 how would you do that?

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im trying to see how it works

peak shale
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well for those functions the composite would be
3(5x+6)+4=15x+20 so you wouldn't use the chain rule

white roost
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we use chain rule for e and ln only?

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gpt says we use chain rule when we got 2 functions but here u say we dont use it

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for this question

peak shale
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We can use it for any composite function that cant be reduced too a simpler term

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so the example you gave you can reduce to a linear equation which is easier

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e^(2x+4) can be reduced to be easier

white roost
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do we use it a lot in calc?

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chain rule

peak shale
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yes

white roost
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but we just did

peak shale
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its proberlly the best rule their is

white roost
peak shale
white roost
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idk

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u said so

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so i trusted u

white roost
peak shale
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well mb then

white roost
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oh it was a typo?

peak shale
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what i ment was in that case you would use the chain rule cause it can't be reduced

white roost
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by can't be reduced what kind of things are included in it? like functions with x^2 ? are they included?

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3x^2+3x+5

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lets say

peak shale
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What is the composite functions

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for that you would use the power rule and the addition rule (not sure if thats the english name)

full forumBOT
#

@white roost Has your question been resolved?

#
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thick hedge
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If $A$ is open or closed, show $\partial int(A)= \varnothing$

queen gull
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you just woke up

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on the grind

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xD

thick hedge
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AT LAST

queen gull
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$\partial A = \bar{A} \backslash \mathrm{int}(A)$

glossy valveBOT
thick hedge
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=ykw

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one min

glossy valveBOT
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ExpertEsquieESQUIE

thick hedge
thick hedge
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that's better

split swift
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that's a different question from what you wrote

thick hedge
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I realised I kept making typos 😭

split swift
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your ordering just isn't true

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but anyway

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if A is open, then int(A) = A

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so del(A) = clos(A) \ A

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suppose this is nonempty so there is some open set U in the boundary

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then look at the neighbourhoods of all the points of U

thick hedge
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I'm typing an answer