#help-28
1 messages · Page 266 of 1
(ps. sprendinių nėra = no solutions)
You use the discriminant, negative discriminant means there are no roots ("solutions")
in the top right where D=0 it says sprendinių nėra
which means no solutions
well because that's asking for ax^2+bx+c > 0
The D = 0 case means that ax^2+bx+c reaches 0 exactly one
but if its a downwards parabola, it'll never surpass it
Hence the "no solutions"
can you explain in laymans terms?
doesnt the discriminant just determine how the parabola opens
do you know the quadratic formula?
yes
,, x_{1,2} = \frac{-b \pm \sqrt{\color{red}b^2 - 4ac}}{2a}
mmmm7
think about what red = 0, red > 0, or red < 0 means in this case
oh yeah
u get it now?
yeah but why does it get flipped depending if its ax^2+bx+c>0 or ax^2+bx+c<0
if its no solutions regardless
wdym flipped?
b^2 - 4ac = 0 gives you one solution
b^2 - 4ac > 0 gives you as you can see tell from the +-
and b^2 - 4ac < 0 gives you 2 complex solutions
so no real solutions
because you'd be dealing with sqrt(negative number)
owing to that you can draw a horizontal line and make it so that
it either intersects it twice
once or never
then you can read off the interval where ax^2 + bx + c > 0
Let y= quadratic if the graph is above y=0 then there is no soln for
quadrtic<0
here graph is above x axis so no soln for negative value(<0)
ok just to clarify what difference does it make if its y>0 or y<0?
@gleaming turtle Has your question been resolved?
Closed by @gleaming turtle
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
no
hint: e^2x - 1 = (e^x)^2 - 1
ohh
actually nvm u sub works
really?
yeah
you should let u = e^x instead
why?
then your u' is e^x
and you dont have to deal with e^2x
yea that looks correct
wait
where's your du here?
did it get kidnapped by some cambodian scam center?
bahahaha
other than that everything else is correct
open another channel
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
sorry didnt see
@long helm if you're done with this question close the channel
ohh okiee
.close
Closed by @long helm
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
why is the quadratic equation positif when the descriminant delta is negative
what do you mean by "the quadratic equation is positive"
i think you may be misconceiving something
say we have x squared -ax +1
x^2 - ax + 1
yeah
use ^ for exponents on discord generally
can you show the full question, just for the record
i dont want to guess at what your goal was & i wanna make sure we both understand how to say things properly
im js tryna affirm an info i used on a test
the info needs to be cleared up before it can be affirmed or denied
if this is strictly positif
then the descriminant is negatif strictly right
right, but this should be made a bit more precise and general:
given a quadratic function f(x) = ax^2 + bx + c,
the discriminant D = b^2-4ac is negative if and only if the function f(x) is sign-constant, which itself happens if and only if y=f(x) never touches the x-axis
"sign-constant" means either always positive, or always negative (based on the sign of a)
so in your case, a=1 so "sign-constant" means "always positive"
Closed by @pallid urchin
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
help
HELP
PLS
I EG U
BEG U
JUST HELP
THIS ONE I MEAN
PLEASE
I BEEN ON THIS FUCKING QUESTOIN 10 TIMES
well for an n-sided polygon the sum of interior angles is (n-2)*180 degrees
count the angles
how many sides are there..
it literally tells you
LAST QUESTION
count the green things
IDK
no
8?
uhhh mental breakdown <@&268886789983436800> ?
its in the damn question this is impressively low amounts of effort man
iS IT 8?
it is 8
SO IS THE ANSWER 8?
the amount of sides man
WHAT DO I DO WITH THAT
@cerulean yoke please calm down
n = 8 put it in the formula
only 50 more seconds if you calm it down
have no clue...
and? I've been on the question I'm currently doing for an hour.
sometimes, you make progress better if you calm down and think things through
no one here is going to give you the answer, you're going to need to apply yourself a little.
yes and you just calculate it
calculater?
idc how just calculate
1080?
you can use a calculator, or a pen and paper, it's up to you.
it is 1080
if youre confidnet you woudnt ask
good job
no, calculate now
Took me 1hr for it
I'll see myself out
Founder of Air france.
Working for Alaska airlines Board of directions.
roblox airlines
u know im 14...
im practily involved around it
if you want to understand why that formula for the sum of interior angles works, consider decomposing your polygon into triangles.
@cerulean yoke Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
cos(theta) = adjacent / hypotenuse = 1 / AC
from this, it follows just by rearrangement
Closed by @verbal sky
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
I keep getting this instead of -4. Where is the mistake?
,rotate
you did $\sqrt{4x^2} = 2x$ but that's only true when $x > 0$
riemann
Why would x have to be positive when (-a)^2 = (a)^2?
Oh I see now that's why it doesn't work.
.close
Closed by @rigid yacht
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Until when is algebra 1?
wut
until you pass the exam 
@fallen ivy Has your question been resolved?
You'd have better response at #math-discussion , the help channels are for asking help in solving questions only
No1 talks there
Maybe try #study-discussion
@fallen ivy Has your question been resolved?
@fallen ivy Has your question been resolved?
unless you have a specific topic you don't get, it's unlikely anyone can give you any specific answers other than to revise and understand the material.
you are currently in algebra 1, nenni.
i think algebra 2 starts with complex numbers and polynomial expansions? not very sure.
Closed by @fallen ivy
Use .reopen if this was a mistake.
Hey I need help really quick.. I am studying for my test and I am doing a review sheet
I am confused on
Simplify
!occupied, btw
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
it's still not open yet
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Hello! I'm a Calculus BC student studying for a test tomorrow that will be 3 questions. I've been working on my homework from yesterday to review for the test but I've been struggling a lot. Can anyone help me understand how to start this problem and how to approach this kind of problem? We're working on real analysis right now and we're writing proofs and tomorrow's test is 3 questions, most likely with at least 2 of them being proofs. Any help is appreciated. Thank you!
are you allowed to prove from scratch those things that you cannot argue
How are calc BC students doing real analysis?
thats another question on its own
I think that I'm not allowed to argue using that even if I were to prove it from scratch
Nah, you just need the maximum of the absolute value of the first N terms
Then all the other terms are bounded by some max and min
So far in class we've really only used the N-epsilon definition of sequence convergence, triangle inequality, the max function, and cauchy convergence and since we only do proofs ocassionally I'm not too sure how to do that with a proof by contradiction
ok yeah i think direct might be the move
By the way the solution key shows this but I don't really understand it
first lets convince ourselves its true
okay
Okay
a_m is below one of the numbers in that list
that means a_m is below M (the maximum)
okay
and that's for all "big enough" m
Sorry, what do you mean by "big enough" m? Are you talking about the m'th term?
yeah
Okay
it says m > N
And N is some natural number
im trying to strip away the formal language
so then all the numbers in the sequence are either the first few terms or any of the other ones
the other ones are all below M
Okay
the first few are at most M by definition
Okay
does that help
Yes, thank you. So would that be part of what is meant by Cauchy?
either the maximum is in the first N terms, or it's in the other terms (N + 1, N + 2, ...)
cauchy means that the next term is "almost the same as" the previous term
if it's in the first N terms, we just choose the maximum absolute value
if it's in the later terms, well, we can set n = N + 1 to show that $|a_{N + 1} - a_m| < \epsilon \implies a_{N + 1} - \epsilon < a_m < a_{N + 1} + \epsilon$ for all $m > N$
so will it be the max{M, and the other one} for the maximum of that sequence?
the other one is below M
okay
you can write that and it will work
south
is this helping out too
Yes, thank you very much
theres only one thing missing
cauchy has for all epsilon > 0
which means it works for any choice
okay
okay
you can use whatever number, but choose a number for this
Do certain values for epsilon make it more convinient later on on the proof?
okay
Does 3/10 work well for most things?
Okay
I think I'm starting to get what each piece of the question means but how do we put it all together? Also how would you go about doing scratch work for this problem?
start by citing the definition of cauchy
then, pick specific epsilon (a number)
use the version of triangle inequality that gets the inequality in the right direction
Okay
you should be able to get that the "far away" terms are bounded
Yes
thats the hardest part
the close terms, those are bounded by the maximum among them
How would I show that the far away terms are bounded?
oh yeah you do need to fix one of n or m to N+1 or something
because the cauchy definition involves pairs of n and m
Okay
triangle inequality
one of them will get you an upper bound
you will need to play around with that, because there are a bunch of versions of it
Okay, thank you! I'll try to set up my scratch work based off of that.
Also, do you have any reccomendations on how to start a proof? Usually the quizzes and tests we have are timed and we only have around 30 minutes in total (I usually lose points because I run out of time). How would I start to think of this and are there key words/key ideas to focus upon?
do more problems
for questions of this nature, begin by writing down relevant definitions
before attempting the proof
I have a doubt in trigonometric identities
the path tends to become clearer
Okay, I'll try to review all the definitions in depth
so you will need to memorize formal definitions of cauchy, convergence etc
!help
Thank you
To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.
!help
To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.
Closed by @coarse flax
Use .reopen if this was a mistake.
for a good source of problems you can go use the beginning of carothers real analysis for similar problems
✅ Original question: #help-28 message
I still have these questions and I don't really get them
have you tried anything here?
For 5, I don't really have an idea on what to do, I might try restating some definitions. For 6, I think I might be able to start by supposing instead that a doesn't equal b
no i wouldn't do that they gave you the suggestion
for 6
Okay
Should I try to use the definition of sequence convergence and use it on x_n converging to a and x_n converging to b?
Oh wait they sort of suggested that too
oops
yea the third one hint is the best one
Also would I need to use N_1 and N_2 for this?
it doesn't involve assuming a \neq b though 🤔
yes
then take the max
you don't need to assume a \neq b
Okay
I don't know that
try proving it
Okay
Sorry I was typing on my computer so it took my a while to figure out how to take a photo
if a \neq 0 then |a| > 0 so taking eps = |a| gives the contradiction
use the third hint to arrive at a similar statement
and use this
Okay, I'll try that, thank you
I got until here for the scratch work but I'm not really sure what to do beyond htis
this
Yeah, I'm not really sure how to incorporate it
what inequality can we invoke here?
Triangle inequality?
perfect
remember that we have control over |x_n - a| and |x_n - b|
we should always keep those in the back of our minds
which is how we come to think of using the triangle inequality here
would |x_n-a| + |x_n-b| be greater than or equal to |x_n-a+x_n-b|?
|a-b|?
we want |a - b| < eps to use the theorem i gave earlier
no
$|a - b| = |(a - x_n) + (x_n - b)| \leq |x_n - a| + |x_n - b| < \dots$
knief
what should the last inequality be
epsilon?
yes
so how can we bounded |x_n - a| and |x_n - b|
so that they sum to be less than epsilon
would |x_n-a|<3/7*epsilon work?
they will
Wouldn't epsilon/2 + epsilon/2 be epsilon?
yes and we have the <
Okay
|x_n - a| + |x_n - b| < eps/2 + eps/2 = eps
Sort of. Would I try to simplify one side of the equation until I get a contradictory statement?
we don't need contradiction here
we are using this
Okay
I think I got it. Thank you
ok
👍
my hint for 5 would be it suffices to show that l = lim(s_n - t_n) <= 0 so try assuming l > 0 and then contradict s_n <= t_n
Okay, thank you very much!
no worries
I'll try to work on the rest of the questions. Thank you for explaning a lot of it
you're welcome
.close
Closed by @coarse flax
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
how are you able to derive this I thought because e^0=1 its not written in an indeterminate form
it's limit to infinity, not to 0
so it would be e^inf/2 = inf
so its inf/inf which is indeterminate
Closed by @odd galleon
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
i have this graph. is it only concave down at (x3, +infinity)? I said this because the derivative of the f’(x) graph (so f’’(x) basically) seems to only decrease here. i believe the right answer had 2 different intervals though so im missing one. did i do this right?
@lucid lily Has your question been resolved?
,rccw
nvm i think its concave down at (x1, x3) u (x3, +inf)
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
What did I do wrong?
$\x=2\x^2=2^2\
\sqrt{x^2}=\sqrt{2^2}\
x=\pm2\x=2 \text{ or } x=-2\Rightarrow 2=-2 \to \gets$
fort craft 🇵🇸
going backwards instead of forward
Elaborate please.
the process you did is the reverse of solving x^2 = 2^2
and I'll add that we know that x is already positive so how can x be evaluated as negative afterwards ?
So what if I had wrote this:
$\x=a\x^2=a^2\
\sqrt{x^2}=\sqrt{a^2}\
x=\pm a \x=a \text{ or } x=-a\Rightarrow a=-a \to \gets$
fort craft 🇵🇸
given no constraints this falls into we already know that x = a
so how did we find x=-a ?
Don't we get the negative from the plus or minus sign?
I think what qimmah is trying to say is this:
At the last line you have:
"x = a or x = -a"
Which is actually still perfectly fine, but here's the thing - how do you then conclude what x is from this statement?
We can't say "x = -a" just because.
The word "or" here simply means it could be one or the other, or both.
well you don't conclude what x is. a is a non-zero real number. you just write what x is in terms of a.
Well, when you say a = -a, you are certainly concluding what x is.
"you just write what x is in terms of a"
How can you write what something is if you can't conclude what it is inherently?
lmao
I have no idea what you talking about.
I think if x is a then x can't be -a at the same time
unless a = 0
nope. I defined a as a non-zero real number, outruling the possibility of a being 0.
Uh let me put it this way.
When you are solving an equation x^2 = 100, we are essentially asking "for what values of x when squared gives us 100?".
In that case, the answer is both x = -10 or x = 10, which makes sense because both values satisfy the equation.
However, your question is slightly different:
You are saying "Given that x = a, what can we say about x?".
So, we're not trying to find a 'value' for x since we are already given the value of x. That means when you get statements like:
"x = a or x = -a"
You must choose the one that fits the situation best; in that case, it is x = a.
There is nothing in the statement "x = a or x = -a" that implies that x must be both values.
Perfect. Thank you.
.close
Closed by @hard quartz
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
1
Here's a small exercise to help you notice a patern
What is $U_{3}$ in terms of $U_1$ and $V_1$?
Wait sorry
Matcha
@robust fox Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Name three things you are people grateful for today.
- You closing the channel and move this to a discussion channel
- Same as 1
- Same as 2
!redir
This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.
.close not a math question nor any hint at such
Closed by @onyx glen
Use .reopen if this was a mistake.
Wow... your positivness today...
you're posting in the wrong channel mate
for real..
for fake...
You guys… as always are so negative and have bad energy.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
School calculators are sold by one company only in packages of 11 and packages of 15. What is the largest number of calculators you could purchase where it would still be necessary to open a package?
i need help with this question for an extracurricular
That's called the Frobenius number if you want to look it up
it's way more fun if you think about it as McDonald's nuggets though
but yes, that is the proper name of the theorem
We're exploring the world of Chicken Nuggets and Frobenius numbers. 43 has long been a special number in the world of McNugget mathematics, but 11 is also important!
More links & stuff in full description below ↓↓↓
Another video about Frobenius Numbers: https://youtu.be/be8BGCLuC54
This video features Dr James Grime - https://twitter.com...
Could u give me a hand explaining that to me
I don’t get why the largest number isn’t just infinity ( ik it’s not a number I’m just trynna explain what I’m having trouble with lmao)
Ahhh
At this point you can make any number 4+2n or 5+2n by just adding 2
That covers all integers >=4
Gotcha
For 11 and 15 it'll be a lot more, but the same logic applies because they are coprime
@cosmic tusk Has your question been resolved?
thanks guys
Closed by @cosmic tusk
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
I also need help with this question for the same extracurricular: find the number of five-digit numbers less than 40 000 in which the three three-digit numbers formed by consecutive digits are all divisible by either 17 or 23.
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
got a feeling like this might not have any more sophisticated solution than simply listing out all possible sequences of 3 digits and then looking at how they fit together if at all
102 115 119 136 138 153 161 170 184 187
204 207 221 230 238 253 255 272 276 289 299
306 322 323 340 345 357 368 374 391
408 414 425 437 442 459 460 476 483 493
506 510 527 529 544 552 561 575 578 595 598
612 621 629 644 646 663 667 680 690 697
713 714 731 736 748 759 765 782 799
805 816 828 833 850 851 867 874 884 897
901 918 920 935 943 952 966 969 986 989
and ig you also have 017 023 034 046 051 068 069 085
@cosmic tusk Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Cam anyone up here help me in this question. Professer tried to explain it but i didnt get it
what is this bruh?
this is the standard explanation
Honestly this is partially a history question, because you need to know what Euclid's proof is.
Actually it's not stated correctly
Well, cuz it's false...
nvm
ok lemme see
some questions -
let me write them
@fallow ridge 3b1b does a casual explanation here
This was done as part of an event by Matt Parker (@standupmaths ) "An Evening of Unnecessary Detail". Many thanks to Tim Blais (@acapellascience) for joining, and for the Bell House in Brooklyn for housing the event.
linked it cuz its fun
@fallow ridge Has your question been resolved?
Hopefully that has been explained in class; otherwise it would be a bit of a mean question.
@fallow ridge Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
- how can he say that there exists at least one additional prime number not included in the list? 2) Why have he added one into the product of all prime number? 3) What is he actually trying to do or prove?
Euclied is trying to prove there are infinitly many primes
To do that, he assumes there is a finite number of them and he labels them
So this finite list includes all prime numbers
This number N is not divisable by any of the primes in the list
So it has a prime factor which is not in the list
For which there are two options (for N, or if you're reading from Riemann's citation, for q):
one - it does have a prime factor that isn't in this list - which is a contradiction, because we assumed this list were complete
two - it itself is prime - but then it should've been in the list, so again a contradiction
In both cases it has a prime factor
The question as phrased isn't true, because that's only the second option, not the first one
@fallow ridge Has your question been resolved?
meaning q is a prime number?
how?
where did I say q
Is up to this point clear to you, first off?
in solution euclid have assumed q
The name of the new number is not important
then what is?
What it represents is
But you've not mentioned q before here, and since i haven't got what you're reading here, I have no context for whatever's being defined as q
Though... Do you mean the q here?
here is the solution by euclid
Then read from here
Both are contradictions
But BOTH are needed for the proof
Because that's the whole point of a proof by contradiction
why cant it have prime factor within list?
"because we assumed this list were complete"
Literally the first step here
Might I recommend revising what proof by contradiction entails:
e.g. https://youtu.be/MfTmjQnGOA8
Link to Bicen Maths Award video: https://youtu.be/Cd7JFkhMp6Q?si=PWWm5CaXFmfY_NDG
Use this as quick revision, to summarise a playlist, and/or to check that you are ready to tackle exam questions. (Remember you can change playback speed on YouTube if you're in a rush!)
PDF available in the Google Drive here: https://drive.google.com/drive/folde...
hmmm @restive geyser we assumed a prime number "q" in which we added 1. so isn't there possibility that when we added 1 it would have maybe became a non-prime number? or even if it is a prime number so it will not have a number which is factor of it. right? but what do i get to know by getting the conclusion that q have no prime factor within list?
alright
No, you've misunderstood what q is
I reclaim my time and re-ask you this
i mean q is sum of all prime numbers + 1
No, you've still misunderstood it
thats what i am asking. my question is part of the first point
That product already can't be prime (if that list has at least 2 numbers) because we can write it as a product of prime factors
But we're not examining this product specifically - we're looking at the number one more than it
The cited example of the proof calls this q = P + 1; your original question calls this number N
Either way, its nature is contradictory
Either it is prime - CONTR. because it then should have been in our list of primes that we thought was complete
Or it has a prime factor not in our list - CONTR. because then we still have some prime number not in our list
The question as stated here says only the first part (that this new number N is prime), but neglects the second case, hence the answer being "False"
ok so second case is wrong or you can say not asked in the question. And about the first case - if q is a prime number P+1 so in this scenraio if its a prime number than it should have been within the finite set
that means there is no finite rather infinite prime numbers
are you in universty man by the way?
I've finished an undergraduate degree in mathematics, yes
ok. Thanks for helping
appreciated everyones concern
.closed
.close
Closed by @fallow ridge
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
dy = sinx/cos^2x dx
and you have to solve for y(x)?
yes integration
have you learned how to do integration?
i know the power rule for the integration
thats it
i know all my derivitave rules tho
and anti derivitaves are like the exact oppsite
im js like confused on how to start
it's a trig identity
sin x / cos x = tan x
1 / cos x = sec x
you sure you haven't done anything like this before?
then you probably know a function whose derivative is that....
my teacher said its like a puzzle
It's actually pretty reasonable to guess the integral here. You want to think of a function whose derivative is sin(x)/cos²(x)
Isn't this a little overkill? Why not just ||use u-substitution?||
they don't know u-sub yet.
OP, double check to see if you can use u-sub haha
no, usub is more complex here
oo
so i like split the denominator
Well I mean what are the chances that tan(x)sec(x) is not in OP's derivative list? It's not a standard integral where I come from
they mentioned they know the common derivatives
thus knowing the integral of that is implied
I also agree - this is kind of unreasonable as the first ever integration question even if there is a known integral/derivative for it. So would it not be better to route to u-sub, which is a fundamental process for integration?
is the answer sec x
yes
it makes like sense
it's a standard derivative of a typical trig function.
It's not beneficial to jump to u-sub if they don't know that method yet.
practice, recognition of common derivatives
pretty much, yeh
also don't forget the constant of integration
oh shoot
sec x +c
ok that is all
thank you
.close
Closed by @noble citrus
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
σ
x
h
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
also Im not sure why I got this wrong
I used this method
and if we can use our calc to find population SD, whhy are we given this?
cause your calc is automatically doing these steps for you
yea if the calc is doing for me, why are we learning how to do it by hand
from the slides shown
because in the exam we will also use calculators
that's not our problem then.....
i mean you DO need to know the process for it right
cause otherwise this entire SD thing is just gonna be a completely black box to you
@neon rivet Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Four million 500-kilowatt windmills in the states listed in the table could generate 91% of the total electrical use. If this were done, how many windmills would be in North Dakota? (Hint: It is not 11% of 4 million.
Please don't occupy multiple help channels.
.close
Closed by @gritty rose
Use .reopen if this was a mistake.
.close
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Im trying to find the first and second derivative, am I doing the first one right?
,w diff x*sqrt(x^2+16)
Do you know the product and chain rule?
Cause this is wrong
Oh yesh
this actually equals op's answer does it not
I'm so sorry, it's correct
Well now @turbid tide you can try taking the second derivative

Ohhh I see I just needed to simplify
And then i need to find the critical points of the second derivative
You mean "finding the critical points of f(x) using it's second derivative" right?

Yes
Well recall the definition of a critical point
We actually use the first derivative to compute it
So, do you mind showing the original question?

@turbid tide Has your question been resolved?
this form you've got it in is definitely not that great for finding concavity, even if correct
gonna say you need to assemble these into one fraction at least
with denom (x^2+16)^(3/2)
Okay
,rccw
ok looks like your 2nd derivative is also correct but unsimplified
Wait i think I got the critical numbers
But now I need to find the derivative of this
?
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
i think you're cooked here as far as an exact value goes
!xy though
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
ill be busy soon tho
no instructions for how many decimal places to go for...
wait
hold on a bit. what am i saying
5^(-x) * ln(5) = 1
divide both sides by ln(5)
get 5^(-x) = 1/ln(5) = log_5(e)
you're not cooked at all
1/log_a(b) = log_b(a)
.close
Closed by @turbid tide
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
why is the angle between Y' and W 20 degrees
can someone explain the geometry applied here
This uses similar triangles
,tikz \draw[->] (0,0) coordinate(O) -- (2,0) coordinate(X) node[right]{$x$};
\draw[->] (O) -- (0,2) coordinate(Y) node[above]{$y$};
{[rotate=20]
\draw[->] (0,0) coordinate(O) -- (2,0) coordinate(X') node[right]{$x'$};
\draw[->] (O) -- (0,2) coordinate(Y') node[above]{$y'$};
}
\draw pic[draw, angle radius=5]{right angle=X--O--Y} pic[draw, angle radius=7]{right angle=X'--O--Y'} pic[draw, "\ang{20}", angle eccentricity = 2.3]{angle=X--O--X'} pic[draw, "?", angle eccentricity = 2]{angle=Y--O--Y'};
cloud ☁
^^
sorry I can't decipher this
you have the original x and y axes, the new x' and y' axes, the 20 degree angle, and the right angles between x and y and between x' and y'
that is enough to determine the angle between y and y' using a bit of algebra
okay thank you
is this angle 60 right? I'm trying to decompose the P vector onto the y' and x' axis
yes
so can I say that x' component of P is Psin60
it makes sense to me though, the opposite is the component along the x', so this gotta be sin
P does not point along the y' axis
that is an artefact of you drawing all diagonal lines at a 45 degree angle regardless of their actual direction
btw does this pattern have a name because I come across it a lot and I don't want to waste time doing this geometry every single time
it's a rotated coordinate system
oh like this one? the angle between y and y' is the same as theta?
yes
are the two triangles formed by x-y and x'-y' congruent
i want to know how you can justify this with similar triangles
wait do we consider y and x equal in magnitude
@tired blade Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
hi, is this even right, or are there better ways to do this
You could just use the chain rule honestly
Doing the derivative this way will be quite simple but the expanding and simplifying will take ages
@gentle hollow Has your question been resolved?
Closed by @gentle hollow
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
.solved
Closed by @sacred yarrow
Use .reopen if this was a mistake.
Please stick to your channel.
yeah, just stick to your channel, Ann is trying to help you rn
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
someone please help 🙏
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
1
i really dont understand the concept of transversals
and cant seem to find much info online
A transversal point of an equivalence class would be a singular point in that class
A transversal would be a set where each of its elements belongs to exactly one of these classes
It helps first to figure out what this equivalence class actually looks like
Graphically, can you describe this equivalence relation?
well it would be straight lines going out of the center point
ye
Let's take each line and collapse it onto a single point that can define that class
and the equivalent classes from what i understand are either (-p, q) (p, -q) or (p, q)
since if theyre both negative it just goes into k
I'll give one for free: (x, y) where x² + y² = 1, and y > 0
so an upper semicircle?
yee
ok wait let me see if i understand this right
(noting also that we haven't included the y=0 relation, but we can just add that point to the set)
where would p, -q go? if the semi circle is for y>0
or did i not get this right at all
No I don't think this is quite right
(-p, q) for one is where (p, q) reflects to on the y-axis
But for two, you'd already said this here
(-p, q) isn't even on the same line as (p, q)
wouldnt (-p, q) just be negative x axis but positive y?
Yes, but since when was it on the same "straight [line] going out of the center point" as (p, q)?
You've even drawn these on different lines: these points are not in the same equivalence class
i tried to draw the different cases
What different cases?
equivalent classes of
[(m, n)]
[(-p, q)]
[(l, -o)]
each blue line (and the highlighted red line also) is a singular equivalence relation
We can uniquely define each one of these with a point on each line; for the sake of normalising, we can have those points be a distance 1 away from the origin (hence the x^2 + y^2 = 1 condition I set)
oh i see
so no matter what each of the equivalent class graphically straight lines reach positive y
Now if I only have that condition, then I'm gonna have two points for each class
For every (x,y) point I have there, I'm gonna get (-x, -y) there too
So I can further restrict that y > 0, i.e. the second condition I set
that makes sense
what about the quotient set? how do i find that
i know its the set of every equivalance class but how do i write that?
Well, the difference between the quotient set and a traversal is just what elements it contains
A transversal contains exactly one point from each class
A quotient set contains each class
It suffices then that if we can write each class using the defined point, we should be done
And seeing this, I think you should already have the notation down
so would [(x,y)] (x,y) being from R x R work?
(x,y) being from the transversal we've just defined
so [(x,y)] from x^2 + y^2=1 y>0?
yes (you should know how to define a set, right?)
(Like, with set-builder notation)
dude genuinely thank you so much
(and also)
You need to tweak the answer to deal with this class too
y=0 relation like [(x, 0)]?
ye
0 isn't greater than 0, so atm we haven't included it yet
But it is in our relation
x² + y² = 1, y=>0 perhaps?
again, though, we can use set-builder notation just to union a singleton set as an add-on to the sets we've made, so this should be the easy part
Now that would make both (-1,0) and (1,0) in the transversal
We only need one of them
ah
the U looking thing right
ye
Almost
[(x,0)] isn't clear - you need a class that's generated by a defined, not undefined, point
Think of it like, the point we use acts as the class's nametag
since our radius is 1 we can just do [(1,0)]?
ye
Your "unioning" doesn't look right
And similarly here btw
well (1, 0) isnt a group
oh i see
What's the set that contains just the point (1,0)?
What's the set that contains the number 23?
{23}
Good
You just add the curly brackets in
Now what's the set that contains the point (1,0)?
No you're replacing the brackets there
{(1, 0)}
okay okay
Union this with the other set
X/~ = {[(x,y)] : (x^2 + y^2=1 y>0) U {[(1, 0)]} }
waiiit
{[(x,y)] : x^2 + y^2=1, y>0**}**
This is one set
{(1,0)} is the other set
ohhh ok
{set 1} union {set 2} needs the braces in the same places
X/~ = {[(x,y)] : (x^2 + y^2=1 y>0) } U {[(1, 0)]}
{set 1} U {set 2}
Check the formatting here
oh wait
an equivalent class is just a set
X/~ = {[(x,y)] : (x^2 + y^2=1 y>0) } U [(1, 0)]
but for the transversal it would be
T = {(x,y) : (x^2 + y^2=1 y>0) } U {(1,0)}?
By this I mean, your way of writing the conditions is off
Also, both of these are sets, but of different things
T is a subset of X, i.e. comprised of elements of X
X/~ is a subset of the powerset of X, i.e. it is comprised of subsets of X
To this end, the only difference between the traversal and the quotient set is the []s
is it like this in every case? where the quotient set is just the traversal set but with equivalent classes?
Well, yh - see here
ok so the strategy for finding traversals is imagining the equivalent classes and it as a graph of sorts?
Well, the idea behind understanding an equivalence relation is precisely to understand what an equivalence class looks like
A transversal is just a set defined by collapsing each class to a single elements and then collecting those elements up
In this case, this was done by projecting each class onto a unit circle (and then making adjustments, like taking y>0, and then adding an extra point)
This is gonna have to come with practice, ultimately
do you have any recommendations of where to practice?
why is this subject so hard to study 😭
well thank you so much for all the help
o/
.close
Closed by @warm temple
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
what's up with this
if i solve according to this board
then i get
i ask chatgpt and it tells me yp is this instead
but the final solution isn't even the same as the one in my textbook
you did not use the product rule when differentiating yp
this channel is currently occupied. pleas open your own (see #❓how-to-get-help )
again, this is not your channel. please open your own #❓how-to-get-help
@digital nymph Has your question been resolved?
ok, i put it in the original equation. now i got 2Ax-2A=xe^-x
what now
well that means your guess was wrong
so make a different guess. in particular, if you have (some polynomial) * e^(ax) then you should always guess (polynomial of same degree) * e^(ax)
ok, so it is this then
@digital nymph Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Uh I don't even know how Part A is supposed to help me with part B. Am I dumb?
What did you get for part A
looks good, now the idea is to plug in that matrix^n from part A in the series
@heavy gulch Has your question been resolved?
Closed by @heavy gulch
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
How can I prove that OI, NQ and MP all meet at H? ABCD ise an inscribed quadrilateral where AC is perpendicular with BD at I. M, N, P, Q are midpoints of AB, BC, CD, DAA
Note that I am working with Euclidean geometry, not some coordinated geometry
@delicate torrent Has your question been resolved?
<@&286206848099549185>
Let's see
with some angle chasing you can see yhat MNPQ form a rectangle and H is the center of it, but not sure where this comes into pkay