#help-28

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gleaming turtle
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(ps. sprendinių nėra = no solutions)

tender nacelle
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You use the discriminant, negative discriminant means there are no roots ("solutions")

gleaming turtle
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which means no solutions

tender nacelle
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well because that's asking for ax^2+bx+c > 0

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The D = 0 case means that ax^2+bx+c reaches 0 exactly one

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but if its a downwards parabola, it'll never surpass it

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Hence the "no solutions"

gleaming turtle
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can you explain in laymans terms?

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doesnt the discriminant just determine how the parabola opens

sick vortex
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do you know the quadratic formula?

gleaming turtle
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yes

sick vortex
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,, x_{1,2} = \frac{-b \pm \sqrt{\color{red}b^2 - 4ac}}{2a}

glossy valveBOT
sick vortex
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think about what red = 0, red > 0, or red < 0 means in this case

gleaming turtle
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oh yeah

sick vortex
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u get it now?

gleaming turtle
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yeah but why does it get flipped depending if its ax^2+bx+c>0 or ax^2+bx+c<0

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if its no solutions regardless

sick vortex
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wdym flipped?

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b^2 - 4ac = 0 gives you one solution

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b^2 - 4ac > 0 gives you as you can see tell from the +-

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and b^2 - 4ac < 0 gives you 2 complex solutions

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so no real solutions

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because you'd be dealing with sqrt(negative number)

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owing to that you can draw a horizontal line and make it so that

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it either intersects it twice

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once or never

then you can read off the interval where ax^2 + bx + c > 0

frigid carbon
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here graph is above x axis so no soln for negative value(<0)

gleaming turtle
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ok just to clarify what difference does it make if its y>0 or y<0?

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long helm
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Please don't occupy multiple help channels.

long helm
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oh

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i was just wondering if it would be smart to do u-sub here?

unique perch
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no

long helm
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oh

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what should i do then?

unique perch
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hint: e^2x - 1 = (e^x)^2 - 1

long helm
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ohh

unique perch
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actually nvm u sub works

long helm
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really?

unique perch
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yeah

long helm
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but i am not sure what to do next

unique perch
long helm
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why?

unique perch
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then your u' is e^x

long helm
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oh

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okai

unique perch
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and you dont have to deal with e^2x

long helm
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you are right

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thanks

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i will try that

long helm
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so this is correct?

unique perch
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yea that looks correct

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wait

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where's your du here?

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did it get kidnapped by some cambodian scam center?

long helm
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i forgot it

unique perch
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other than that everything else is correct

long helm
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yayy

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thanks for checking

unique perch
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open another channel

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verbal sky
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sorry didnt see

unique perch
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@long helm if you're done with this question close the channel

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pallid urchin
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why is the quadratic equation positif when the descriminant delta is negative

onyx glen
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what do you mean by "the quadratic equation is positive"

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i think you may be misconceiving something

pallid urchin
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say we have x squared -ax +1

onyx glen
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x^2 - ax + 1

pallid urchin
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yeah

onyx glen
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use ^ for exponents on discord generally

pallid urchin
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say its positif

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ik js count find it

onyx glen
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can you show the full question, just for the record

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i dont want to guess at what your goal was & i wanna make sure we both understand how to say things properly

pallid urchin
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im js tryna affirm an info i used on a test

onyx glen
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the info needs to be cleared up before it can be affirmed or denied

pallid urchin
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then the descriminant is negatif strictly right

onyx glen
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right, but this should be made a bit more precise and general:

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given a quadratic function f(x) = ax^2 + bx + c,

the discriminant D = b^2-4ac is negative if and only if the function f(x) is sign-constant, which itself happens if and only if y=f(x) never touches the x-axis

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"sign-constant" means either always positive, or always negative (based on the sign of a)

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so in your case, a=1 so "sign-constant" means "always positive"

pallid urchin
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hm alr thanks

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cerulean yoke
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help

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cerulean yoke
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HELP

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PLS

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I EG U

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BEG U

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JUST HELP

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THIS ONE I MEAN

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PLEASE

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I BEEN ON THIS FUCKING QUESTOIN 10 TIMES

rough tundra
cerulean yoke
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IM ABOUT TO RIP OFF MY HAIR

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PLEASE

rough tundra
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well for an n-sided polygon the sum of interior angles is (n-2)*180 degrees

cerulean yoke
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SO WHATS THE AANSWE

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ANSWER

low needle
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count the angles

fickle adder
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how many sides are there..

cerulean yoke
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idk

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just say THE ANSWER

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PLEASE

fickle adder
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it literally tells you

cerulean yoke
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LAST QUESTION

low needle
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count the green things

cerulean yoke
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IDK

fickle adder
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no

cerulean yoke
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8?

gritty rose
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uhhh mental breakdown <@&268886789983436800> ?

fickle adder
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its in the damn question this is impressively low amounts of effort man

cerulean yoke
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iS IT 8?

fickle adder
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it is 8

cerulean yoke
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SO IS THE ANSWER 8?

fickle adder
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so if the sum is 180 * (n-2)

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and theres 8 sides.

low needle
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the amount of sides man

cerulean yoke
austere cove
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@cerulean yoke please calm down

low needle
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n = 8 put it in the formula

cerulean yoke
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😭

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I BEEN ON THIS question FOR 1HR

low needle
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only 50 more seconds if you calm it down

cerulean yoke
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have no clue...

austere cove
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and? I've been on the question I'm currently doing for an hour.

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sometimes, you make progress better if you calm down and think things through

cerulean yoke
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?

austere cove
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no one here is going to give you the answer, you're going to need to apply yourself a little.

low needle
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yes and you just calculate it

cerulean yoke
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calculater?

low needle
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idc how just calculate

cerulean yoke
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1080?

austere cove
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you can use a calculator, or a pen and paper, it's up to you.

cerulean yoke
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is 1080

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the answer

austere cove
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it is 1080

low needle
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if youre confidnet you woudnt ask

cerulean yoke
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t IS

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It is

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YAY

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bravo

austere cove
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good job

neon basin
cerulean yoke
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Took me 1hr for it

neon basin
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I'll see myself out

low needle
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Founder of Air france.
Working for Alaska airlines Board of directions.

cerulean yoke
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yay

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ya

cerulean yoke
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u know im 14...

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im practily involved around it

torn sand
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@cerulean yoke Has your question been resolved?

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verbal sky
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verbal sky
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i get all of this

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except

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why is AC = 1/cos(t)

grave elm
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cos(theta) = adjacent / hypotenuse = 1 / AC

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from this, it follows just by rearrangement

verbal sky
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sorry brain fart

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rigid yacht
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I keep getting this instead of -4. Where is the mistake?

gritty rose
#

,rotate

glossy valveBOT
gritty rose
glossy valveBOT
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riemann

rigid yacht
#

Oh I see now that's why it doesn't work.

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fallen ivy
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Until when is algebra 1?

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gritty rose
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wut

iron sand
fallen ivy
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What is the hardest in algebra 1?

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How do to the exam

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@fallen ivy Has your question been resolved?

slate glacier
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You'd have better response at #math-discussion , the help channels are for asking help in solving questions only

fallen ivy
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No1 talks there

slate glacier
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@fallen ivy Has your question been resolved?

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@fallen ivy Has your question been resolved?

warped frost
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unless you have a specific topic you don't get, it's unlikely anyone can give you any specific answers other than to revise and understand the material.

wary condor
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i think algebra 2 starts with complex numbers and polynomial expansions? not very sure.

fallen ivy
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Sure

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.clpse

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hollow timber
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Hey I need help really quick.. I am studying for my test and I am doing a review sheet

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I am confused on

sleek mortar
hollow timber
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Oh, that’s it

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To what?

warped frost
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!occupied, btw

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warped frost
#

it's still not open yet

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coarse flax
#

Hello! I'm a Calculus BC student studying for a test tomorrow that will be 3 questions. I've been working on my homework from yesterday to review for the test but I've been struggling a lot. Can anyone help me understand how to start this problem and how to approach this kind of problem? We're working on real analysis right now and we're writing proofs and tomorrow's test is 3 questions, most likely with at least 2 of them being proofs. Any help is appreciated. Thank you!

hybrid yacht
slate violet
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How are calc BC students doing real analysis?

hybrid yacht
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thats another question on its own

coarse flax
hybrid yacht
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contradiction maybe?

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supposed there is a cauchy sequence that is unbounded

slate violet
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Nah, you just need the maximum of the absolute value of the first N terms

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Then all the other terms are bounded by some max and min

coarse flax
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So far in class we've really only used the N-epsilon definition of sequence convergence, triangle inequality, the max function, and cauchy convergence and since we only do proofs ocassionally I'm not too sure how to do that with a proof by contradiction

hybrid yacht
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ok yeah i think direct might be the move

coarse flax
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By the way the solution key shows this but I don't really understand it

hybrid yacht
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first lets convince ourselves its true

coarse flax
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okay

hybrid yacht
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M is the maximum of specific numbers

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finitely many of them

coarse flax
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Okay

hybrid yacht
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a_m is below one of the numbers in that list

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that means a_m is below M (the maximum)

coarse flax
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okay

hybrid yacht
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and that's for all "big enough" m

coarse flax
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Sorry, what do you mean by "big enough" m? Are you talking about the m'th term?

hybrid yacht
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yeah

coarse flax
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Okay

hybrid yacht
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it says m > N

coarse flax
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And N is some natural number

hybrid yacht
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im trying to strip away the formal language

coarse flax
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Thank you

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English is not my strong suit

hybrid yacht
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so then all the numbers in the sequence are either the first few terms or any of the other ones

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the other ones are all below M

coarse flax
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Okay

hybrid yacht
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the first few are at most M by definition

coarse flax
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Okay

hybrid yacht
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does that help

coarse flax
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Yes, thank you. So would that be part of what is meant by Cauchy?

slate violet
hybrid yacht
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cauchy means that the next term is "almost the same as" the previous term

slate violet
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if it's in the first N terms, we just choose the maximum absolute value

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if it's in the later terms, well, we can set n = N + 1 to show that $|a_{N + 1} - a_m| < \epsilon \implies a_{N + 1} - \epsilon < a_m < a_{N + 1} + \epsilon$ for all $m > N$

coarse flax
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so will it be the max{M, and the other one} for the maximum of that sequence?

hybrid yacht
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the other one is below M

coarse flax
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okay

hybrid yacht
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you can write that and it will work

glossy valveBOT
hybrid yacht
coarse flax
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Yes, thank you very much

hybrid yacht
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theres only one thing missing

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cauchy has for all epsilon > 0

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which means it works for any choice

coarse flax
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okay

hybrid yacht
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which means it works for a specific choice

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and they used 1

coarse flax
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okay

hybrid yacht
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you can use whatever number, but choose a number for this

coarse flax
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Do certain values for epsilon make it more convinient later on on the proof?

hybrid yacht
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usually

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but using convienient numbers sometimes gets you in trouble

coarse flax
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okay

hybrid yacht
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i preferred more annoying numbers for that reason

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my go-to was 3/10

coarse flax
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Does 3/10 work well for most things?

hybrid yacht
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yeah

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problem with 1 is if youre not careful you divide by 0

coarse flax
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Okay

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I think I'm starting to get what each piece of the question means but how do we put it all together? Also how would you go about doing scratch work for this problem?

hybrid yacht
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start by citing the definition of cauchy

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then, pick specific epsilon (a number)

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use the version of triangle inequality that gets the inequality in the right direction

coarse flax
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Okay

hybrid yacht
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you should be able to get that the "far away" terms are bounded

coarse flax
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Yes

hybrid yacht
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thats the hardest part

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the close terms, those are bounded by the maximum among them

coarse flax
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How would I show that the far away terms are bounded?

hybrid yacht
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because the cauchy definition involves pairs of n and m

coarse flax
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Okay

hybrid yacht
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one of them will get you an upper bound

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you will need to play around with that, because there are a bunch of versions of it

coarse flax
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Okay, thank you! I'll try to set up my scratch work based off of that.

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Also, do you have any reccomendations on how to start a proof? Usually the quizzes and tests we have are timed and we only have around 30 minutes in total (I usually lose points because I run out of time). How would I start to think of this and are there key words/key ideas to focus upon?

hybrid yacht
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for questions of this nature, begin by writing down relevant definitions

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before attempting the proof

weary star
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I have a doubt in trigonometric identities

hybrid yacht
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the path tends to become clearer

coarse flax
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Okay, I'll try to review all the definitions in depth

lime ether
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this is ap calculus?

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🤔

hybrid yacht
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so you will need to memorize formal definitions of cauchy, convergence etc

slate violet
coarse flax
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Thank you

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weary star
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!help

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coarse flax
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I think I get it know. Thank you very much

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lime ether
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for a good source of problems you can go use the beginning of carothers real analysis for similar problems

coarse flax
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Oh wait

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.reopen

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coarse flax
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I still have these questions and I don't really get them

lime ether
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have you tried anything here?

coarse flax
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For 5, I don't really have an idea on what to do, I might try restating some definitions. For 6, I think I might be able to start by supposing instead that a doesn't equal b

lime ether
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for 6

coarse flax
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Okay

lime ether
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oh wait

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yea

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they suggested that

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😭

coarse flax
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Should I try to use the definition of sequence convergence and use it on x_n converging to a and x_n converging to b?

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Oh wait they sort of suggested that too

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oops

lime ether
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yea the third one hint is the best one

coarse flax
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Also would I need to use N_1 and N_2 for this?

lime ether
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it doesn't involve assuming a \neq b though 🤔

lime ether
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then take the max

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you don't need to assume a \neq b

coarse flax
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Okay

lime ether
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do you know that if |a| < eps for every eps > 0 then a = 0

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its simple to prove

coarse flax
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I don't know that

lime ether
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try proving it

coarse flax
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Okay

lime ether
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@coarse flax are you stuck or something?

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would you like a hint

coarse flax
lime ether
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nice

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you got it

coarse flax
lime ether
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if a \neq 0 then |a| > 0 so taking eps = |a| gives the contradiction

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use the third hint to arrive at a similar statement

coarse flax
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Okay, I'll try that, thank you

lime ether
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then we will do 5

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i wouldn't do 5 the way they did though

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🤔

coarse flax
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I got until here for the scratch work but I'm not really sure what to do beyond htis

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this

lime ether
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hmm you seem to be missing the third hint

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|a - b| = |(a - x_n) + (x_n - b)|

coarse flax
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Yeah, I'm not really sure how to incorporate it

lime ether
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what inequality can we invoke here?

coarse flax
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Triangle inequality?

lime ether
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perfect

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remember that we have control over |x_n - a| and |x_n - b|

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we should always keep those in the back of our minds

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which is how we come to think of using the triangle inequality here

coarse flax
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would |x_n-a| + |x_n-b| be greater than or equal to |x_n-a+x_n-b|?

lime ether
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yea and that sum is < ?

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remember what our goal is

coarse flax
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|a-b|?

lime ether
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we want |a - b| < eps to use the theorem i gave earlier

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no

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$|a - b| = |(a - x_n) + (x_n - b)| \leq |x_n - a| + |x_n - b| < \dots$

glossy valveBOT
lime ether
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what should the last inequality be

coarse flax
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epsilon?

lime ether
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yes

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so how can we bounded |x_n - a| and |x_n - b|

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so that they sum to be less than epsilon

coarse flax
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would |x_n-a|<3/7*epsilon work?

lime ether
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🤔

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why 3/7

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i mean its fine but why that in particular

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just take eps/2

coarse flax
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Ok

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But don't they need to sum to be less than epsilon?

lime ether
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they will

coarse flax
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Wouldn't epsilon/2 + epsilon/2 be epsilon?

lime ether
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yes and we have the <

coarse flax
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Okay

lime ether
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|x_n - a| + |x_n - b| < eps/2 + eps/2 = eps

coarse flax
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Okay

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Thank you

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Should I try working on the rest of the scratch work?

lime ether
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wdym?

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do you understand the full proof for 6?

coarse flax
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Sort of. Would I try to simplify one side of the equation until I get a contradictory statement?

lime ether
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we don't need contradiction here

lime ether
coarse flax
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Okay

lime ether
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we just got that |a - b| < eps

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for arbitrary eps

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this means |a - b| = 0 so a = b

coarse flax
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Oh okay

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Thank you

lime ether
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should i write it out?

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or do you want to move on to 5

coarse flax
#

I think I got it. Thank you

lime ether
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ok

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👍

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my hint for 5 would be it suffices to show that l = lim(s_n - t_n) <= 0 so try assuming l > 0 and then contradict s_n <= t_n

coarse flax
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Okay, thank you very much!

lime ether
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no worries

coarse flax
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I'll try to work on the rest of the questions. Thank you for explaning a lot of it

lime ether
#

you're welcome

coarse flax
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odd galleon
#

how are you able to derive this I thought because e^0=1 its not written in an indeterminate form

grave elm
#

so it would be e^inf/2 = inf

#

so its inf/inf which is indeterminate

odd galleon
#

ahhh that makes sense

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thank you

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lucid lily
#

i have this graph. is it only concave down at (x3, +infinity)? I said this because the derivative of the f’(x) graph (so f’’(x) basically) seems to only decrease here. i believe the right answer had 2 different intervals though so im missing one. did i do this right?

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twin wolf
#

,rccw

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lucid lily
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hard quartz
#

What did I do wrong?
$\x=2\x^2=2^2\
\sqrt{x^2}=\sqrt{2^2}\
x=\pm2\x=2 \text{ or } x=-2\Rightarrow 2=-2 \to \gets$

glossy valveBOT
#

fort craft 🇵🇸

sudden condor
hard quartz
sudden condor
# hard quartz Elaborate please.

the process you did is the reverse of solving x^2 = 2^2
and I'll add that we know that x is already positive so how can x be evaluated as negative afterwards ?

hard quartz
glossy valveBOT
#

fort craft 🇵🇸

sudden condor
hard quartz
forest trail
#

We can't say "x = -a" just because.

#

The word "or" here simply means it could be one or the other, or both.

hard quartz
forest trail
#

"you just write what x is in terms of a"
How can you write what something is if you can't conclude what it is inherently?

frigid carbon
hard quartz
#

I have no idea what you talking about.

heavy gorge
#

I think if x is a then x can't be -a at the same time

frigid carbon
heavy gorge
#

yeah but that's because 0 = -0

#

a != -a, unless a = 0

hard quartz
forest trail
# hard quartz I have no idea what you talking about.

Uh let me put it this way.
When you are solving an equation x^2 = 100, we are essentially asking "for what values of x when squared gives us 100?".
In that case, the answer is both x = -10 or x = 10, which makes sense because both values satisfy the equation.

However, your question is slightly different:
You are saying "Given that x = a, what can we say about x?".
So, we're not trying to find a 'value' for x since we are already given the value of x. That means when you get statements like:

"x = a or x = -a"
You must choose the one that fits the situation best; in that case, it is x = a.

#

There is nothing in the statement "x = a or x = -a" that implies that x must be both values.

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robust fox
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unreal wren
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!status

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robust fox
#

1

unreal wren
#

What is $U_{3}$ in terms of $U_1$ and $V_1$?

#

Wait sorry

glossy valveBOT
#

Matcha

unreal wren
#

Then figure out V_3 too

#

Also do U_4 and V_4, that will help you notice a pattern

robust fox
#

ic thank u

#

ill try it

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half sorrel
#

Name three things you are people grateful for today.

unique perch
#
  1. You closing the channel and move this to a discussion channel
  2. Same as 1
  3. Same as 2
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onyx glen
#

.close not a math question nor any hint at such

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half sorrel
onyx glen
#

you're posting in the wrong channel mate

fallen ivy
restive geyser
#

for fake...

fallen ivy
#

You guys… as always are so negative and have bad energy.

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cosmic tusk
#

School calculators are sold by one company only in packages of 11 and packages of 15. What is the largest number of calculators you could purchase where it would still be necessary to open a package?

cosmic tusk
#

i need help with this question for an extracurricular

queen crater
#

That's called the Frobenius number if you want to look it up

slate violet
#

it's way more fun if you think about it as McDonald's nuggets though

#

but yes, that is the proper name of the theorem

restive sapphire
#

I don’t get why the largest number isn’t just infinity ( ik it’s not a number I’m just trynna explain what I’m having trouble with lmao)

queen crater
#

Take 2 and 5

#

You can't make 3, but you can make 4 = 2+2, and 5

restive sapphire
#

Ahhh

queen crater
#

At this point you can make any number 4+2n or 5+2n by just adding 2

#

That covers all integers >=4

restive sapphire
#

Gotcha

queen crater
#

For 11 and 15 it'll be a lot more, but the same logic applies because they are coprime

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cosmic tusk
#

thanks guys

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cosmic tusk
#

I also need help with this question for the same extracurricular: find the number of five-digit numbers less than 40 000 in which the three three-digit numbers formed by consecutive digits are all divisible by either 17 or 23.

onyx glen
#

!status

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onyx glen
#

got a feeling like this might not have any more sophisticated solution than simply listing out all possible sequences of 3 digits and then looking at how they fit together if at all

#
102 115 119 136 138 153 161 170 184 187 
204 207 221 230 238 253 255 272 276 289 299 
306 322 323 340 345 357 368 374 391 
408 414 425 437 442 459 460 476 483 493 
506 510 527 529 544 552 561 575 578 595 598 
612 621 629 644 646 663 667 680 690 697 
713 714 731 736 748 759 765 782 799 
805 816 828 833 850 851 867 874 884 897 
901 918 920 935 943 952 966 969 986 989 
#

and ig you also have 017 023 034 046 051 068 069 085

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fallow ridge
#

Cam anyone up here help me in this question. Professer tried to explain it but i didnt get it

gritty rose
#

this is the standard explanation

copper tangle
#

Honestly this is partially a history question, because you need to know what Euclid's proof is.

#

Actually it's not stated correctly

#

Well, cuz it's false...

#

nvm

fallow ridge
#

some questions -

#

let me write them

covert heath
#

linked it cuz its fun

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marsh vault
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fallow ridge
#
  1. how can he say that there exists at least one additional prime number not included in the list? 2) Why have he added one into the product of all prime number? 3) What is he actually trying to do or prove?
queen gull
#

Euclied is trying to prove there are infinitly many primes

#

To do that, he assumes there is a finite number of them and he labels them

#

So this finite list includes all prime numbers

#

This number N is not divisable by any of the primes in the list

#

So it has a prime factor which is not in the list

restive geyser
#

For which there are two options (for N, or if you're reading from Riemann's citation, for q):

#

one - it does have a prime factor that isn't in this list - which is a contradiction, because we assumed this list were complete

#

two - it itself is prime - but then it should've been in the list, so again a contradiction

queen gull
#

In both cases it has a prime factor

restive geyser
#

The question as phrased isn't true, because that's only the second option, not the first one

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@fallow ridge Has your question been resolved?

fallow ridge
#

how?

restive geyser
#

where did I say q

restive geyser
fallow ridge
restive geyser
#

The name of the new number is not important

fallow ridge
#

then what is?

restive geyser
#

What it represents is

restive geyser
restive geyser
fallow ridge
restive geyser
#

Both are contradictions

#

But BOTH are needed for the proof

#

Because that's the whole point of a proof by contradiction

fallow ridge
restive geyser
#

"because we assumed this list were complete"

restive geyser
#

Might I recommend revising what proof by contradiction entails:
e.g. https://youtu.be/MfTmjQnGOA8

Link to Bicen Maths Award video: https://youtu.be/Cd7JFkhMp6Q?si=PWWm5CaXFmfY_NDG

Use this as quick revision, to summarise a playlist, and/or to check that you are ready to tackle exam questions. (Remember you can change playback speed on YouTube if you're in a rush!)

PDF available in the Google Drive here: https://drive.google.com/drive/folde...

▶ Play video
fallow ridge
# queen gull This number N is not divisable by any of the primes in the list

hmmm @restive geyser we assumed a prime number "q" in which we added 1. so isn't there possibility that when we added 1 it would have maybe became a non-prime number? or even if it is a prime number so it will not have a number which is factor of it. right? but what do i get to know by getting the conclusion that q have no prime factor within list?

restive geyser
#

No, you've misunderstood what q is

restive geyser
fallow ridge
#

i mean q is sum of all prime numbers + 1

restive geyser
#

No, you've still misunderstood it

fallow ridge
restive geyser
#

sum ≠ product

fallow ridge
#

ok i understand

restive geyser
#

That product already can't be prime (if that list has at least 2 numbers) because we can write it as a product of prime factors

#

But we're not examining this product specifically - we're looking at the number one more than it

#

The cited example of the proof calls this q = P + 1; your original question calls this number N

#

Either way, its nature is contradictory

#

Either it is prime - CONTR. because it then should have been in our list of primes that we thought was complete

#

Or it has a prime factor not in our list - CONTR. because then we still have some prime number not in our list

restive geyser
fallow ridge
#

ok so second case is wrong or you can say not asked in the question. And about the first case - if q is a prime number P+1 so in this scenraio if its a prime number than it should have been within the finite set

#

that means there is no finite rather infinite prime numbers

fallow ridge
restive geyser
#

I've finished an undergraduate degree in mathematics, yes

fallow ridge
#

appreciated everyones concern

#

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noble citrus
#

dy = sinx/cos^2x dx

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rough tundra
#

and you have to solve for y(x)?

noble citrus
#

i need to do the swirly thingy to both sides

#

i need to find the antiderivivate

rough tundra
#

yes integration

noble citrus
#

how do i do it

#

cuz i dont have any rules for this

rough tundra
#

have you learned how to do integration?

noble citrus
#

i know the power rule for the integration

#

thats it

#

i know all my derivitave rules tho

#

and anti derivitaves are like the exact oppsite

#

im js like confused on how to start

ivory cairn
#

it's a trig identity
sin x / cos x = tan x
1 / cos x = sec x

rough tundra
#

you sure you haven't done anything like this before?

ivory cairn
#

then you probably know a function whose derivative is that....

noble citrus
#

my teacher said its like a puzzle

fathom saddle
#

It's actually pretty reasonable to guess the integral here. You want to think of a function whose derivative is sin(x)/cos²(x)

forest trail
ivory cairn
#

they don't know u-sub yet.

fathom saddle
#

OP, double check to see if you can use u-sub haha

hot herald
noble citrus
#

so i like split the denominator

forest trail
hot herald
#

they mentioned they know the common derivatives

#

thus knowing the integral of that is implied

forest trail
#

I also agree - this is kind of unreasonable as the first ever integration question even if there is a known integral/derivative for it. So would it not be better to route to u-sub, which is a fundamental process for integration?

noble citrus
#

is the answer sec x

hot herald
#

yes

noble citrus
#

it makes like sense

ivory cairn
noble citrus
#

but like

#

how do i know to split the demoinator

hot herald
#

practice, recognition of common derivatives

noble citrus
#

wait is dy/dx = sinx/cos^2x

#

the same as dy=sinx/cos^2x dx

hot herald
#

pretty much, yeh

hot herald
noble citrus
#

sec x +c

#

ok that is all

#

thank you

#

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neon rivet
#

σ
x

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neon rivet
#

why is there a subscript x in population sd?

#

(\sigma )_n

glossy valveBOT
#

h
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

neon rivet
#

also Im not sure why I got this wrong

#

I used this method

#

and if we can use our calc to find population SD, whhy are we given this?

slate violet
neon rivet
#

yea if the calc is doing for me, why are we learning how to do it by hand

#

from the slides shown

#

because in the exam we will also use calculators

slate violet
#

that's not our problem then.....

onyx glen
#

i mean you DO need to know the process for it right

#

cause otherwise this entire SD thing is just gonna be a completely black box to you

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ocean crescent
#

Four million 500-kilowatt windmills in the states listed in the table could generate 91% of the total electrical use. If this were done, how many windmills would be in North Dakota? (Hint: It is not 11% of 4 million.

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turbid tide
#

Im trying to find the first and second derivative, am I doing the first one right?

gritty rose
#

,w diff x*sqrt(x^2+16)

unreal wren
turbid tide
unreal wren
#

Oh yesh

onyx glen
unreal wren
#

I'm so sorry, it's correct

#

Well now @turbid tide you can try taking the second derivative

turbid tide
turbid tide
#

And then i need to find the critical points of the second derivative

unreal wren
turbid tide
#

Yes

unreal wren
#

We actually use the first derivative to compute it

#

So, do you mind showing the original question?

turbid tide
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#

@turbid tide Has your question been resolved?

onyx glen
#

gonna say you need to assemble these into one fraction at least

#

with denom (x^2+16)^(3/2)

turbid tide
onyx glen
#

,rccw

glossy valveBOT
turbid tide
#

I made a mistake

onyx glen
#

was about to fix that

#

uhh ok let's see

#

,w d^2/dx^2 (x * sqrt(x^2+16))

onyx glen
#

ok looks like your 2nd derivative is also correct but unsimplified

wide crag
#

.reopen

#

guys

#

whos onli,e

turbid tide
#

Wait i think I got the critical numbers
But now I need to find the derivative of this

wide crag
#

what's 5.NBT.1 - 5.NBT.7

#

all the units

#

just wanna learn a little

turbid tide
#

?

onyx glen
#

!occupied also

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#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

wide crag
#

oh mb

#

ill go

#

gl

onyx glen
#

!xy though

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#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

onyx glen
#

ill be busy soon tho

turbid tide
#

That's ok thanks of your help so far

onyx glen
#

no instructions for how many decimal places to go for...

#

wait

#

hold on a bit. what am i saying

#

5^(-x) * ln(5) = 1

#

divide both sides by ln(5)

#

get 5^(-x) = 1/ln(5) = log_5(e)

#

you're not cooked at all

#

1/log_a(b) = log_b(a)

turbid tide
#

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tired blade
#

why is the angle between Y' and W 20 degrees

tired blade
#

can someone explain the geometry applied here

green badge
#

This uses similar triangles

umbral dome
#

,tikz \draw[->] (0,0) coordinate(O) -- (2,0) coordinate(X) node[right]{$x$};
\draw[->] (O) -- (0,2) coordinate(Y) node[above]{$y$};
{[rotate=20]
\draw[->] (0,0) coordinate(O) -- (2,0) coordinate(X') node[right]{$x'$};
\draw[->] (O) -- (0,2) coordinate(Y') node[above]{$y'$};
}
\draw pic[draw, angle radius=5]{right angle=X--O--Y} pic[draw, angle radius=7]{right angle=X'--O--Y'} pic[draw, "\ang{20}", angle eccentricity = 2.3]{angle=X--O--X'} pic[draw, "?", angle eccentricity = 2]{angle=Y--O--Y'};

glossy valveBOT
#

cloud ☁

green badge
#

^^

umbral dome
#

you have the original x and y axes, the new x' and y' axes, the 20 degree angle, and the right angles between x and y and between x' and y'

#

that is enough to determine the angle between y and y' using a bit of algebra

tired blade
umbral dome
#

yes

tired blade
umbral dome
#

no

#

the 60 degree angle is between P and the y axis

tired blade
umbral dome
#

P does not point along the y' axis

tired blade
#

oh shoot

#

right

umbral dome
#

that is an artefact of you drawing all diagonal lines at a 45 degree angle regardless of their actual direction

tired blade
#

yeah my mistake

#

I didn't notice 🤦‍♂️

#

thanks

tired blade
umbral dome
#

it's a rotated coordinate system

tired blade
umbral dome
#

yes

tired blade
#

i want to know how you can justify this with similar triangles

#

wait do we consider y and x equal in magnitude

full forumBOT
#

@tired blade Has your question been resolved?

full forumBOT
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gentle hollow
#

hi, is this even right, or are there better ways to do this

unreal wren
#

You could just use the chain rule honestly

#

Doing the derivative this way will be quite simple but the expanding and simplifying will take ages

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full forumBOT
#

Please don't occupy multiple help channels.

sacred yarrow
#

.solved

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warped spire
full forumBOT
#

Please stick to your channel.

sacred yarrow
#

yeah, just stick to your channel, Ann is trying to help you rn

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warm temple
#

someone please help 🙏

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#

@warm temple Has your question been resolved?

restive geyser
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# warm temple someone please help 🙏
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
warm temple
#

1

#

i really dont understand the concept of transversals

#

and cant seem to find much info online

restive geyser
#

A transversal point of an equivalence class would be a singular point in that class

#

A transversal would be a set where each of its elements belongs to exactly one of these classes

#

It helps first to figure out what this equivalence class actually looks like

#

Graphically, can you describe this equivalence relation?

warm temple
#

well it would be straight lines going out of the center point

restive geyser
#

ye

#

Let's take each line and collapse it onto a single point that can define that class

warm temple
#

and the equivalent classes from what i understand are either (-p, q) (p, -q) or (p, q)

#

since if theyre both negative it just goes into k

restive geyser
#

I'll give one for free: (x, y) where x² + y² = 1, and y > 0

warm temple
#

so an upper semicircle?

restive geyser
#

yee

warm temple
#

ok wait let me see if i understand this right

restive geyser
#

(noting also that we haven't included the y=0 relation, but we can just add that point to the set)

warm temple
#

or did i not get this right at all

restive geyser
#

(-p, q) for one is where (p, q) reflects to on the y-axis

restive geyser
#

(-p, q) isn't even on the same line as (p, q)

warm temple
restive geyser
#

Yes, but since when was it on the same "straight [line] going out of the center point" as (p, q)?

restive geyser
warm temple
#

i tried to draw the different cases

restive geyser
#

What different cases?

warm temple
#

equivalent classes of
[(m, n)]
[(-p, q)]
[(l, -o)]

restive geyser
#

each blue line (and the highlighted red line also) is a singular equivalence relation

#

We can uniquely define each one of these with a point on each line; for the sake of normalising, we can have those points be a distance 1 away from the origin (hence the x^2 + y^2 = 1 condition I set)

warm temple
#

oh i see

#

so no matter what each of the equivalent class graphically straight lines reach positive y

restive geyser
#

Now if I only have that condition, then I'm gonna have two points for each class

#

For every (x,y) point I have there, I'm gonna get (-x, -y) there too

#

So I can further restrict that y > 0, i.e. the second condition I set

warm temple
#

that makes sense

#

what about the quotient set? how do i find that

#

i know its the set of every equivalance class but how do i write that?

restive geyser
#

Well, the difference between the quotient set and a traversal is just what elements it contains

#

A transversal contains exactly one point from each class

#

A quotient set contains each class

#

It suffices then that if we can write each class using the defined point, we should be done

restive geyser
warm temple
restive geyser
#

(x,y) being from the transversal we've just defined

warm temple
#

so [(x,y)] from x^2 + y^2=1 y>0?

restive geyser
#

yes (you should know how to define a set, right?)

#

(Like, with set-builder notation)

warm temple
#

uhh i think so
X/~ = {[(x,y)] : x^2 + y^2=1 y>0}

#

is that fine?

restive geyser
#

yee

#

(but a comma after the 1 there, else it's unclear)

warm temple
#

dude genuinely thank you so much

restive geyser
#

(and also)

restive geyser
warm temple
#

y=0 relation like [(x, 0)]?

restive geyser
#

ye

#

0 isn't greater than 0, so atm we haven't included it yet

#

But it is in our relation

warm temple
#

x² + y² = 1, y=>0 perhaps?

restive geyser
#

again, though, we can use set-builder notation just to union a singleton set as an add-on to the sets we've made, so this should be the easy part

restive geyser
#

We only need one of them

warm temple
#

ah

restive geyser
#

We can just add it

#

[you should be familiar with the union operator for sets too]

warm temple
#

the U looking thing right

restive geyser
#

ye

warm temple
#

X/~ = {[(x,y)] : (x^2 + y^2=1 y>0) U [(x, 0)] }

#

would that be right?

restive geyser
#

Almost

#

[(x,0)] isn't clear - you need a class that's generated by a defined, not undefined, point

#

Think of it like, the point we use acts as the class's nametag

warm temple
#

since our radius is 1 we can just do [(1,0)]?

restive geyser
#

ye

warm temple
#

i see

#

T = {(x,y) : (x^2 + y^2=1 y>0) and (1, 0) } right?

restive geyser
#

Your "unioning" doesn't look right

restive geyser
warm temple
warm temple
restive geyser
#

What's the set that contains just the point (1,0)?

warm temple
#

ohhh

#

it should be ... U {1, 0}

#

right?

restive geyser
#

What's the set that contains the number 23?

warm temple
#

{23}

restive geyser
#

Good

#

You just add the curly brackets in

#

Now what's the set that contains the point (1,0)?

warm temple
#

{1, 0}?

#

i mean

restive geyser
#

No you're replacing the brackets there

warm temple
#

{(1, 0)}

restive geyser
#

YEE

#

Now this is a set

warm temple
#

okay okay

restive geyser
#

Union this with the other set

warm temple
#

X/~ = {[(x,y)] : (x^2 + y^2=1 y>0) U {[(1, 0)]} }

restive geyser
#

waiiit

#

{[(x,y)] : x^2 + y^2=1, y>0**}**

#

This is one set

#

{(1,0)} is the other set

warm temple
#

ohhh ok

restive geyser
#

{set 1} union {set 2} needs the braces in the same places

warm temple
#

X/~ = {[(x,y)] : (x^2 + y^2=1 y>0) } U {[(1, 0)]}

restive geyser
#

{set 1} U {set 2}

restive geyser
warm temple
#

oh wait

#

an equivalent class is just a set

#

X/~ = {[(x,y)] : (x^2 + y^2=1 y>0) } U [(1, 0)]

#

but for the transversal it would be
T = {(x,y) : (x^2 + y^2=1 y>0) } U {(1,0)}?

restive geyser
#

Also, both of these are sets, but of different things

#

T is a subset of X, i.e. comprised of elements of X

#

X/~ is a subset of the powerset of X, i.e. it is comprised of subsets of X

#

To this end, the only difference between the traversal and the quotient set is the []s

warm temple
#

i see

#

i think i understand it now

warm temple
warm temple
#

ok so the strategy for finding traversals is imagining the equivalent classes and it as a graph of sorts?

restive geyser
#

Well, the idea behind understanding an equivalence relation is precisely to understand what an equivalence class looks like

#

A transversal is just a set defined by collapsing each class to a single elements and then collecting those elements up

#

In this case, this was done by projecting each class onto a unit circle (and then making adjustments, like taking y>0, and then adding an extra point)

#

This is gonna have to come with practice, ultimately

warm temple
#

do you have any recommendations of where to practice?

restive geyser
#

Not really lol

#

I suppose just Google some questions/examples

warm temple
#

why is this subject so hard to study 😭

#

well thank you so much for all the help

#

o/

#

.close

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#
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full forumBOT
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digital nymph
#

what's up with this

full forumBOT
digital nymph
#

if i solve according to this board

#

then i get

#

i ask chatgpt and it tells me yp is this instead

#

but the final solution isn't even the same as the one in my textbook

mental junco
#

Bro help me in my maths

#

I failed the subject

umbral dome
umbral dome
mental junco
#

Help me in maths

#

Help me in math

umbral dome
full forumBOT
#

@digital nymph Has your question been resolved?

digital nymph
#

what now

umbral dome
#

well that means your guess was wrong

digital nymph
#

okay?

#

then what

umbral dome
#

so make a different guess. in particular, if you have (some polynomial) * e^(ax) then you should always guess (polynomial of same degree) * e^(ax)

digital nymph
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@digital nymph Has your question been resolved?

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heavy gulch
#

Uh I don't even know how Part A is supposed to help me with part B. Am I dumb?

heavy gulch
#

is it staring at me?

#

the creature..

hallow walrus
heavy gulch
#

I didn't feel like moving my pencil sorry

kindred grove
# heavy gulch

looks good, now the idea is to plug in that matrix^n from part A in the series

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delicate torrent
#

How can I prove that OI, NQ and MP all meet at H? ABCD ise an inscribed quadrilateral where AC is perpendicular with BD at I. M, N, P, Q are midpoints of AB, BC, CD, DAA

delicate torrent
#

Note that I am working with Euclidean geometry, not some coordinated geometry

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#

@delicate torrent Has your question been resolved?

delicate torrent
#

<@&286206848099549185>

hot frigate
#

Let's see

hoary ember
#

with some angle chasing you can see yhat MNPQ form a rectangle and H is the center of it, but not sure where this comes into pkay