help-28

[hot kernel]

If it is, then how to find the value of "a"?

[onyx glen]

hold on a minute

you understand that your polynomial has four roots not three, right?

it's a quartic, a polynomial of degree 4

[hot kernel]

Oh no 😭

I missed that

Gotta do it again

[onyx glen]

also your division is wrong in the 2nd step i think.

[hot kernel]

But how to do it?

[hot kernel]

Please tell me

[onyx glen]

this 8x^3 - 20x^2 should have been 8x^3 - 20x.

and the way i would do it is

i would write the divisor as 2x^2 + 0x - 5 and then make extra sure that all powers of x are aligned properly during the long division

AND also you should not even bother with any vieta here nor expansion

but rather you will get a remainder in terms of a and b

which you set to 0

and you find a and b from matching coefficients

that's it

no vieta no fancy factorization no expansions even

[hot kernel]

Ohk I get it

I messed up

[echo marsh]

(u can also do this by making two equations using the 2 roots (2x^2 - 5 = 0) and solving them)

[hot kernel]

Gotta do it again

[onyx glen]

mm you could but it's kinda overcomp imo

long division is easier, op just needs to do it properly

[echo marsh]

is it tho

[onyx glen]

and i would say also not waste time doing unnecessary things that make his own life more difficult

[onyx glen]

yeah you need to mess around with surds

or radicals

or whatever else you wanna call them

not worth!

like sure you CAN do it by those means but it's meh

[echo marsh]

well

yeah

you have to be wary of signs

[hot kernel]

My pen is out of ink

Wait a sec

What to do from here?

@onyx glen

@echo marsh

[onyx glen]

what is this 10x^2 - 10x

is it meant to be a multiple of 2x^2-5?

cause it's not

[hot kernel]

Wait wtf I am doing

I am out of mind

[onyx glen]

you're making your own life difficult is what you're doing

by not aligning powers of x properly

and creating for yourself a MINEFIELD for fuckups

[echo marsh]

write it as 2x^2 + 0x - 5

and do it again

[onyx glen]

.

i said it

but it was certainly not taken into account

[hot kernel]

5x+ax+b that's the remainder

[echo marsh]

whenever there is missing power, put 0<power>

to make your life easier

[onyx glen]

nah clearly op wants his life maximally hard

[hot kernel]

5x+ax+b is the remainder of the division

@onyx glen

Should I have to do it again??

Y or N

[onyx glen]

idk where you messed up but this is what it looks like done properly

[onyx glen]

honestly i would not bother

$\polylongdiv{6x^4+8x^3-5x^2-20x-25}{2x^2-5}$

[glossy valve]

Ann

[hot kernel]

Aah I see

[onyx glen]

i also

strongly recommend reading 100% of what i say

and not like 60%

i really don't like it when i tell a helpee to do something only to then see them not do it

[hot kernel]

Hey @onyx glen I am really sorry, if you felt like that

I am all messed up

I am very weak in studies, I am just trying to give my best

[onyx glen]

are you also weak in instruction-following?

[hot kernel]

[onyx glen]

i would write the divisor as 2x^2 + 0x - 5 and then make extra sure that all powers of x are aligned properly during the long division

[hot kernel]

I couldn't understand some of your English words

[onyx glen]

and you didn't think to ask?

[hot kernel]

I am sorry!!

[onyx glen]

if you don't understand some word from me you always can and should ASK "what does <word> mean?"

getting help on here is a 2 way street yknow?

[hot kernel]

I thought you would make fun

That's why

[onyx glen]

well you thought wrong

there are PLENTY of people here who aren't native speakers of English

(myself included)

there are PLENTY of people who struggle with English

helpers on the server don't make fun of them

[hot kernel]

I get it

I will follow your instructions heartedly from now on

[full forum]

@hot kernel Has your question been resolved?

[hot kernel]

Wait a sec*

@onyx glen

I've noted it

Now what should I do?

[onyx glen]

well you want the remainder to be 0 right

[hot kernel]

I think it says remainder is already 0

[onyx glen]

well yes

but you need to find the values of a and b from the info that the remainder is 0

which means you need to set all the coefficients to 0

[hot kernel]

Yeah

[onyx glen]

so do it

a+20 = 0
b+25 = 0
what are a and b?

[hot kernel]

a and b are numbers I think

[hot kernel]

Why? What's the point

[analog sand]

That's what's asked...

[onyx glen]

the question literally asks to find the values of a and b

[hot kernel]

Yeah

a=–20

b=-25

[onyx glen]

the remainder is zero

therefore, all of its coefficients are zero

[hot kernel]

Yeah!!

Ohk it's done ✔️ 🙌

.close

[full forum]

Channel closed

Closed by @hot kernel

Use .reopen if this was a mistake.

[hot kernel]

Thanks for the help @onyx glen

Also @analog sand

[analog sand]

I didnt help

[hot kernel]

Ohh!

No worries

Just accept you did

[analog sand]

[hot kernel]

[onyx glen]

just so you know this would've come across as a little harsh in tone, as if you're giving me an order

i deliberately ignored that since you told me you weren't good at english

but i figured that i should tell you

[hot kernel]

Ohh! is this harsh?

I am sorry if it is

Please let me know, from where it came?

[analog sand]

Better

[hot kernel]

Look I used gpt for the previous sentence 😭

Hey @onyx glen

[onyx glen]

.reopen

[full forum]

✅

[onyx glen]

so... i don't really know what you wanted to get from GPT there. did you want GPT to explain what i meant?

[onyx glen]

that's a better rephase but it is still a little bit broken

"could you tell me where this came from?" is how i would say it (though not the only possible way)

[kindred parcel]

it's just an imperative form to tell someone to do something

[hot kernel]

Oh is it like that!

[kindred parcel]

these phrases tend to be softened by rephrasing them as requests

e.g. "please...", "could you... ?"

[hot kernel]

Now if possible please tell me

[onyx glen]

didn't i already tell you

the remainder is 0 => all coefficients in the remainder are 0

[hot kernel]

Coefficient are 0

You did

So it is like that

Now it's clear

Thanks @onyx glen

.close

[full forum]

Channel closed

Closed by @hot kernel

Use .reopen if this was a mistake.

[tight heath]

Wow. I was struggling with pre-calculus and was studying for my final exam with you, I'm now in university, done with calculus 1 and doing calc 2 in the summer, it's crazy how fast time passes, lol. You probably won't know it, but you really helped me that day, thank you 🫶

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[inner hare]

why are W and N used to represent the same thing (subspace)?
Rešitev (in bold) means solution

[gritty rose]

Depends on context. Translate if you want help faster

[inner hare]

is it because one matrix is a mapping so we use W for it whilst we use N for just normal matrices?

[polar pagoda]

I need help

[inner hare]

go to your own channel, no offence

[full forum]

@inner hare Has your question been resolved?

[inner hare]

<@&286206848099549185>

[inner hare]

translation and follow up to original question

[full forum]

@inner hare Has your question been resolved?

[inner hare]

<@&286206848099549185>

.close

[full forum]

Channel closed

Closed by @inner hare

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[onyx glen]

1 or 2?

please dont make us ask you which question you're doing again

it is very annoying to keep doing that every single time

[torpid perch]

1

[torpid perch]

sry

[torpid perch]

if Re(z) > 0

arg(z) is fourth and first quadrant

so arg(z) in between

-pi/2 < arg(z) < pi/2

[onyx glen]

are you asking me a question or just yapping

[torpid perch]

is not yapping, is a fact

[void nova]

Why don't you answer questions?

[void nova]

This requires either a yes or a no as an answer.

[torpid perch]

yes

[void nova]

So which is the question you're asking to Ann?

[onyx glen]

because clearly, answering questions directly is a faux pas.

[full forum]

@torpid perch Has your question been resolved?

[torpid perch]

I was just saying that if Re(z) > 0, then z is either in first or fourth quadrant

but idk what "yapping" is

I'm non native English speaker

but its not asking a question either, was just saying my progress on the question!

[waxen flax]

don't mind the highlight

[torpid perch]

guys, we are derailing

can we go back to the problem

[waxen flax]

Just explaining a word to you
Also you haven't even stated what your problem is yet, there's no question from you directly

[torpid perch]

I am having trouble with 1

[void nova]

!status

[full forum]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[torpid perch]

2

please ping

will be back in a sec

[analog sand]

Half an hour

[torpid perch]

what?

sometimes it takes weeks or months to get help

also, there is no rush

[analog sand]

True

[torpid perch]

I just want to understand complex numbers correctly so I pass my exams

[analog sand]

I'm just a troller like that, dont mind it

[analog sand]

You can stop posting your image in multiple channels, it's counterproductive.

[cedar mirage]

No one’s helping me

[analog sand]

Have patience.

[torpid perch]

welcome to the club (patience is key)

[cedar mirage]

😂

[analog sand]

For people to help you you need to translate the question

[torpid perch]

here is the translation

[full forum]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[brittle parcel]

you called?

[full forum]

@torpid perch Has your question been resolved?

[torpid perch]

I was thinking I saw "faux pas" before I just couldn't remember from where

[torpid perch]

well

other than knowing that z lies in first and fourth quadrant

I am not sure how to proceed

[full forum]

@torpid perch Has your question been resolved?

[gritty flax]

Always good to see such expressions

[full forum]

@torpid perch Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vivid berry]

how do i integrate this

[ember solstice]

u = sin(3x)

[green merlin]

the original expression is sin(6x)

[vivid berry]

how do u know

[ember solstice]

It's a standard double angle identity.

[vivid berry]

unm

umm

[green merlin]

2sin(x)cos(x) = sin(2x)

[vivid berry]

is it in here

[brittle parcel]

or let u=cos(3x)

[vivid berry]

ohh it is

[brittle parcel]

I know a third way lol

[vivid berry]

how

[brittle parcel]

but

u=cos(3x) or u=sin(3x) is the easiest

[vivid berry]

wait how do i do dis way

[brittle parcel]

try it

[vivid berry]

idk how

[carmine minnow]

calculate du/dx

[brittle parcel]

what's d(cos(3x))?

[vivid berry]

-sin(3x)

-3sin(3x)

hi..

[carmine minnow]

looks like the rest of the integrand

[brittle parcel]

or in other words, d(cos(3x))=-3sin(3x)dx

[vivid berry]

yea

[brittle parcel]

the third way i can think of is using Euler's formula, do you know it?

[vivid berry]

whos euler

[brittle parcel]

Leonhard Euler (/ˈɔɪlər/ ⓘ OY-lər;[b] Swiss Standard German: [ˈleːɔnhard ˈɔʏlər]; German: [ˈleːɔnhaʁt ˈɔʏlɐ] ⓘ; 15 April 1707 – 18 September 1783) was a Swiss polymath who was active as a mathematician, physicist, astronomer, logician, geographer, and engineer. He founded the studies of graph theory and topology and made influential discoveries in many other branches of mathematics, such as analytic number theory, complex analysis, and infinitesimal calculus. He also introduced much of modern mathematical terminology and notation, including the notion of a mathematical function.[6] He is known for his work in mechanics, fluid dynamics, optics, astronomy, and music theory.[7] Euler has been called a "universal genius" who "was fully equipped with almost unlimited powers of imagination, intellectual gifts and extraordinary memory".[8] He spent most of his adult life in Saint Petersburg, Russia, and in Berlin, then the capital of Prussia.

lol

[vivid berry]

omg

is he german or swiss

ohh swiss

hey im part swiss

[brittle parcel]

Anway he was a brilliant mathematician who discovered the relationship between e^x and cosx and sinx

you know the imaginary unit i? i^2=-1?

[vivid berry]

yea

[brittle parcel]

he discovered:

$e^{it}=\cos t + i \sin t$

[glossy valve]

gfauxpas

[vivid berry]

ohh

i did that

[brittle parcel]

so for the integrand, we write:

$e^{3ix}=\cos(3x)+i\sin(3x)$

[glossy valve]

gfauxpas

[brittle parcel]

and multiply it by itself

$e^{3ix}e^{3ix} = (\cos(3x)+i\sin(3x))(\cos(3x)+i\sin(3x))$

see what you get when you finish multiplying

[glossy valve]

gfauxpas

[brittle parcel]

it might be less confusing if you temporarily write $c=\cos(3x), s=\sin(3x)$ just so you dont have to write so many letters

[glossy valve]

gfauxpas

[brittle parcel]

and you analyze (c+is)(c+is)

[green merlin]

[brittle parcel]

and then when you're done replace c with cos(3x) and s with sin(3x) again

[vivid berry]

oh ok

i heard of euler in the hidden figures movie

[green merlin]

complex numbers seem a bit unnecessary in this question to me lah

[green merlin]

what

cool

[brittle parcel]

absolutely, but bum chicken asked me what the third way was

[green merlin]

Oh okay

[vivid berry]

yeah guys im kind of bad at complex numbers

i hate the diagrams

[green merlin]

fr

[brittle parcel]

just multiple (c+is)(c+is) like regular algebra

what do you get

[vivid berry]

um.. 1/6cos6x

[brittle parcel]

that is not right

[vivid berry]

guys i give up im starting chemistry now

[brittle parcel]

$(c+is)(c+is)=c^2 + isc + isc +i^2s^2$

[vivid berry]

wait

can u guys help me with physics

cause im kinda lost

[glossy valve]

gfauxpas

[brittle parcel]

this is just basic algebra my friend

[vivid berry]

ohh

do u know how electromagnetic induction works

[full forum]

@vivid berry Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[marble solstice]

Who needs help?

Okay, I'm assuming you're the main helper?

[full forum]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[surreal vine]

Okay so my problem is to analyze whether that series converges or diverges. I tried to take the limit first? Then relate it to other common series, then tried the integral test which I probably did wrong.

Also I did see two other ways of doing this after sources pointed them out: direct comparison and telescoping series after I did partial fractions

But my main question is what did I do wrong in my work in red?

[surreal vine]

I'm mostly interested in understanding why my execution of the integral test and the following limit led to an incorrect result

Also yes I did forget to write "lim" after the improper integral, my mistake

[glossy valve]

Civil Service Pigeon

[surreal vine]

Oh yeah see I did see that and I thought about somehow redoing the limit but couldn't see how at the time

Or rewriting it actually

So that I could work with it

Hm

So

Was it right to split up the integrals in the first place? And was it right to split up the series into partial fractions in the first place as well?

Which led to the seprate improper integrals?

[robust slate]

Yes

[surreal vine]

Oh that's good to know ty

.close

[full forum]

Channel closed

Closed by @surreal vine

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[orchid charm]

How do i find the domain and range of the open circle line : (

[onyx glen]

can you read off the coordinates of the closed-circle point itself

[orchid charm]

the closed circle is (1,6), but i want to know the open one (1,1)

hello🥹

[cyan walrus]

your question seems to be asking for the domain and range of the entite function,
not each piece

[onyx glen]

oh you wrote "closed" in the original mb

ok well you see how the lower bit of the function goes off to the left and down from the open circle right

presumably off to infinity in both

[cyan walrus]

and the graph is kinda ambiguous,

is that a horizontal asymptote at y = -2?

[onyx glen]

or to -∞ rather?

yeah the graph is ambiguous but it looks like it crosses y=-2

who were you responding 'yes' to :x

[brittle parcel]

by definition horizontal asymptotes are at +infty or -infty wdym

oh you mean OF

not at

nm

[orchid charm]

im sorry i am so tired, but i do see how it curves and goes off to -infin.

or goes off to the left and down

[onyx glen]

so you can write down the contributions of that piece to the domain and range as (-∞, 1) and (-∞, 1) respectively

[orchid charm]

so in this case it would be both? is it because of the type of line that it is?

like it would both be (-infin, 1)

it is also asking me to find f(x)... i found the top one which i think is f(x)= {-x+7 if x (greaterthan/equalto) 3

i am having a hard time finding the f(x) for this one, the domain and the range (which you helped me answer)

[onyx glen]

if you can't type ≥ you should substitute it with >= btw

[orchid charm]

okay thanks

[onyx glen]

also you... don't need f(x) itself

[orchid charm]

okay

[onyx glen]

oh

you do?

huh

like the next part asks you for f(x) itself

[orchid charm]

like lol hold on

[onyx glen]

that lower part looks to me like it might be a cube root function

[orchid charm]

you are a GOD (i still dont know how to find that)

wait

i rearranged it wrong

but that is what it is asking for if it makes it easier to know what i mean

wait

its right i think..

[onyx glen]

the breaking point on x should be 1 btw not 3

you should have cases for x < 1 and for x ≥ 1

[orchid charm]

okayyyy

.close

[full forum]

Channel closed

Closed by @orchid charm

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[boreal helm]

I'm completely lost at how the first answer was 3

Is it because if you insert 2 into the equation -2x+7 you get 3? Or is it maybe because 3 is after 2 in the sequence of whole numbers on the graph?

How exactly do I go about finding the lim x-->2 f(x) = L?

[unreal wren]

If you check the equation it's x < 2 and x>2 there's no equation for x=2

But look at the graph

Limit is just "where the point should be"

[boreal helm]

Should the point be at (2,0)?

[unreal wren]

No

Just look at the graph, and think "to make this function simple what can I make f(2) equal to"

Or ask urself "how to make this function continuous? "

Does that make sense lol

I'm making it so shady

Sus math but I hope it makes sense, I think limits are pretty intuitive

[boreal helm]

I assume that entails making the point (2,4) included so that that section is continuous

Because (2,4) on the graph is not included, it's discontinuous

[unreal wren]

Yes

[boreal helm]

Oh wait, sorry 2,3

that's the point I'm talking about

[unreal wren]

Oh ok

Well basically limit is just making it "continuous"

[unreal wren]

But, things get complicated for limits at 0

[boreal helm]

Okay, but could you explain why L = 3?

Is it because of that specific point?

And its y value?

[unreal wren]

Because it makes the function continuous

Idk how to explain it rigorously and the rigorous explanation of limit probably isn't that helpful

[boreal helm]

So the objective of this question is to determine how to make the x value 2 continuous on the graph?

That sounds really stupid now that I read that back

I mean that like, rather than focus on the whole equation, I'm trying to make that specifc section of the graph continuous

.close

[full forum]

Channel closed

Closed by @boreal helm

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[indigo minnow]

This was the problem in one of my high school exams and to this day I dont know the answer

[woeful pasture]

First

What is the condition for f(x) to be non-differentiable at p

[indigo minnow]

Well the f(x) has the form of | function(x) | so you tell me because the absolute value function in its own form is only non-differentiable at x=0

[woeful pasture]

So we know it’s (maybe) undifferentiable where the inside is 0

[indigo minnow]

Yessir

[woeful pasture]

The next condition

The derivative there mustn’t match

[indigo minnow]

Which derivative

f?

[woeful pasture]

f(x)

Left and right shouldn’t match

[indigo minnow]

Yes indeed

Essentially it's saying get me the g(a) that outputs the possible smallest k that keeps the count of non-differentiable points on f to one

[sonic stratus]

mb for interrupting, but i catched interest on the problem, and i think i can maybe explain on simpler terms

what you are being asked, is to find the smallest k such that you have a single value "p"

this directly means that the function inside of the absolute value has to have a single root.

[woeful pasture]

What is g(a)

[indigo minnow]

That is the exact problem

[woeful pasture]

It should only have one p

[indigo minnow]

We have to construct g

[woeful pasture]

Cuz e^kx will cross ax^2 only once

Or positive k and a

[sonic stratus]

both functions can cross either 1 or 3 times

[woeful pasture]

Ye

Mb

Or twice

[indigo minnow]

That is how I remebered it last time I tried to tackle it

[woeful pasture]

How 3 times tho

Another thing I’m trying to do is to interpret f(x) as the distance between e^kx and bx^2

[sonic stratus]

its pretty obvious to see that they cross on the negative x side of the graph
i like to see it as "ax^2" having a faster influence, meaning it grows larger quicker

and under certain a's, it will also grow larger on the positive side at first, but e^kx will eventually catch up being an exponent function

[indigo minnow]

Also, I checked my last note on this problem, which also at some point directly is referencing the solution of the problem which I forgot (which is why now I am asking this here)

It's this

[woeful pasture]

So 2 times?

[sonic stratus]

2 times at the positive side, yeah

well, actually they can cross only once on the positive side, that will be basically your minimum value
infinitemasilly lesser than that, anyways

[woeful pasture]

Huh

[sonic stratus]

you can see that ax^2 gets closer to e^kx, when they cross once on x>0, theres two values "p"
so you have to use something smaller than that

[woeful pasture]

I think I’m stepping out now. I will think about this question again soon

[indigo minnow]

💡 ‼️

That pretty much is the point yeah

So that the non differentiability associating with the absolute value function with a nest is a bit more fancy way to talk about intersecting points between two formulas

[sonic stratus]

you can prob just set up an equation with a e^kx>ax^2 and then pull out the a with a cieling or something on those lines

if you observe the intersections, they line up with the 0's (and as so, non-differentiable points)

you basically have to analyze the rightside cause, for a positive a and k, you will always have the x<0 intersection

[indigo minnow]

I see

I have no idea how to visualize of those graphs as k keeps changing in order to intuitively see when exactly does it have 3 p's and when it only has 1 p

[indigo minnow]

Problematically enough, I dont even know how I came up with making this h function and why would it play an important role in this problem

[sonic stratus]

ill make a new gif

mostly, as a or k grows, both graphs get "squished" to the center

so, if k is bigger, the corresponding a will also be

you already seen the a one, heres for k, you can think of the "x" increasing faster, so all values will be higher for each x

which, visually, makes it squished to the left

[indigo minnow]

Ohhh my lord

[sonic stratus]

rn im working on how to solve e^xk-ax^2=0

first of all, xk-lna-2lnx is a graph derivated from that, which makes the 0 more "visible"

[carmine minnow]

probably W
But what you are looking for is the extreme case where the two graphs touch right

[sonic stratus]

mostly cause we need a value a that is just a bit smaller than that

[indigo minnow]

When k should be the minimum value of satisfying that we only get one p,

e^(kx) = ax^2 ends up implying e^2 = ax^2

Also under the same condition, by differentiating the both sides of e^(kx) = ax^2 we get ke^kx = 2ax = kax^2 (the last identity is derivable from right above fact)

[sonic stratus]

e^2?

[indigo minnow]

I have no idea how did I get those. I searched up for more and this was also one of the notes I left. Presumably, there were some more things to be done before getting to this part.

[sonic stratus]

wrong from me, sadly

that idea was wrong- lmao

[indigo minnow]

Why is it??

[sonic stratus]

that would be only correct if they were at the same height on x=0

here the derivatives cross, while the functions dont

[indigo minnow]

I'm so sorry but can you test this

I just kept scrolling the memo of mine and eventually in a lot of walls of pens there was this

g(a) = 2*root(a)/e

I'm concerned if that is the answer

Still wouldnt make me happy because I am left as having no fucking idea how to derive that

[sonic stratus]

yeah it is

[indigo minnow]

Okay

[sonic stratus]

i think i can kinda see where it comes from, but ill check

[indigo minnow]

PLEASE do thank you so much bro

[sonic stratus]

ill prob come up to you tomorrow

[indigo minnow]

Then Ill just maybe close this one for now
If anybody also stumbles on above convo and has their own ideas they can dm me

.close

[full forum]

Channel closed

Closed by @indigo minnow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[inner hare]

For this task, I've figured that I dont fully understand what a base is? Like if we have a standard base, could we only pass i, j and k through the mapping f or can we pass any vector?
I know what a base is theoretically but I dont understand it practically when it comes to mappings.

[full forum]

@inner hare Has your question been resolved?

[inner hare]

Also could anyone offer tutoring in the next 0-10 hours? I can pay up. I need help on understanding mapping in linear algebra.

[inner hare]

is there any way you could explain this as if I was 5 years old? beacuse I have no clue what I just read

[leaden ermine]

No

I don't think I can

You need to get familar with the coordinate vectors, bases, linear combination in order to understand these topics

[inner hare]

I have thats the problem

I know what all of these are and understand them to some level but not in terms of mapping, at least practically

I know a basis is just a set of linearly independent vectors that form a span with their linear combination

mappings are my kryptonite though

[leaden ermine]

Maybe watch this
https://youtu.be/k8xJx80yCh0?si=DN0-SYtNwO1rUL2p

[inner hare]

on it

ok so lets say we have a vector (2,3) in a space with standard base i, j. We then have a space with its base vectors being something entirely different. Is (2,3) from the space with the standard base also (2,3) in the space with some different base vectors or is it 2*x different base vector + 3*y base different vector

[inner hare]

I think this is my main confusion

[inner hare]

does my question make sense or no?

[leaden ermine]

It's not the same

[inner hare]

so its not (2,3) in the different (non standard) base?

[leaden ermine]

It will have different coordinates in the new basis

[inner hare]

oh my

ok that makes a lot more sense

[leaden ermine]

You can view it as transforming the coordinate system

You can do a drawing

[inner hare]

ok I get this

[leaden ermine]

Gimme a sec

[inner hare]

no wait I think I dont need it

but now I dont understand, if I have a mapping f right

so f: R^3 -> R^3

it can have a different base, how is this possible

wait oh my I think I understand

so the base is just the base, where the operations that you preform inside f use different base vectors with different bases

dus mapping to different coordinates

HOLY F*%KING S#IT I THINK I UNDERSTAND

[inner hare]

is my line of thinking correct @leaden ermine ?

[leaden ermine]

all a base does is represent the same thing differently

[inner hare]

so here youre showing what (1,0) would be in the different bases?

[leaden ermine]

Yes

[waxen flax]

Isn't it called a basis (singular)?

[leaden ermine]

See the orange as a new coordinate system

[inner hare]

I'm not sure how you got 1/2,1/2

[leaden ermine]

A matrix that transform (1,0) from B to C can be interpreted as a rotation or translation for example

[leaden ermine]

I solve the system

1 = λ_1 + λ_2 and 0 = λ_1 - λ_2

If you add both you get 1 = 2λ_1 and so on

But thats not the point, you should know how to solve linear systems

[inner hare]

ok I understand kind of, I'll look into it a bit more, thanks

[leaden ermine]

Notice that the coordinate vector is practically the vector with the new coordinates in the new bases

And you will need these to construct the new transformarion matrix A in order to map vectors from the old basis to the new basis

[inner hare]

actually I'm confused on this, the notation throws me of a little

[leaden ermine]

Read the rows component wise

[inner hare]

how did we get 1/2,1/2 when this would be (1,1), no?

[inner hare]

oh

what would these be called, the vectors in our column space?

wait whaat but here in this video she says that we get the same vector https://youtu.be/Qp96zg5YZ_8?si=bu1bXe8mhO2O6uLZ&t=349

whilst you said we get different ones

[leaden ermine]

.

I was referring to the coordinates in the new basis

[inner hare]

yea exactly

[inner hare]

but isnt she implying here that the coordinates stay the same?

[leaden ermine]

No

She is saying (2,3) can have different representations in different basis

Thats totally different from actually changing (2,3) for example you rotate it in the same basis!

[inner hare]

is it possible that I hop in a call with you?

[leaden ermine]

All I am saying is the vector (1,0) has a different representation in the basis C from B

[leaden ermine]

Nah

I am also not home too

[inner hare]

aka. different coordinates

[leaden ermine]

Yes, thats literally whats inside the coordinate vector

Last thing I suggest is to really try to understand the proofs of these concepts, because then I think it makes more sense as to why something works out

[inner hare]

ok, thank you for the help

.close

[full forum]

Channel closed

Closed by @inner hare

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hot gyro]

Given:

Given:
a and b are two consecutive numbers, with b > a,
x and y are also consecutive numbers, with y > x,
and b^2 - a^2 + y^2 - x^2 \neq 0

What is the value of the following expression?
\frac{b + x}{b^2 - a^2 + y^2 - x^2}

What is the value of the following expression?
\frac{b + x}{b^2 - a^2 + y^2 - x^2}

I have this q that has to be solved in under a min the books way was to solve it like this Given values for substitution (mentioned in the explanation):
y = b=2
x = a = 1

Substitution and Simplification:

\frac{b + x}{b^2 - a^2 + y^2 - x^2}
= \frac{2 + 1}{2^2 - 1^2 + 2^2 - 1^2}
= \frac{3}{4 - 1 + 4 - 1}
= \frac{3}{6}
= \frac{1}{2}

So my problem is can we assume that x=a and b=y ? I understand it’s a possibility but still how can we assume it to get an answer

[analog sand]

Forgot the $

[hot gyro]

lol

Nvm the teacher replied

So ig

.close

[full forum]

Channel closed

Closed by @hot gyro

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fair barn]

I have not the foggiest clue how to solve htis

[analog sand]

Expand

[fair barn]

ya

9=k^2+2ki-36i

[analog sand]

Compare real and img parts after expanding

[fair barn]

how does one do that

[indigo ore]

Observation

[analog sand]

the parts with i on one side are equal to the parts with i on the other

for img

[fair barn]

ohhh

[onyx glen]

im not sure this expansion is correct

[indigo ore]

12ki right

and dont shift them around

[fair barn]

36-12ki-k^2=27-36i

[indigo ore]

whats the imaginary part in rhs

and lhs

[fair barn]

-12ki and -36i?

so k=3?

wait that makes sense

thanks

.close

[full forum]

Channel closed

Closed by @fair barn

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[meager garnet]

i don't understand this

[meager garnet]

pls ping after reply

[remote zealot]

beginning from the expression on the left side

at the last radical, u factorize 2⁸, u get 2⁸(1 +....) inside of that square root

@meager garnet

[sharp vine]

Imagine replacing each square root with a power of 1/2, so that every nested square root becomes an exponentiation. Then, under each root, you factor out a power of 2^(2^n)) starting from 2^8 (which is the last term shown in the image).
So first, you have (2^8)^(1/2) = 2^4
Next, you factor out (2^4)^(1/2) = 2^2
Then, you factor out (2^2)^(1/2) = 2
Eventually, at the very outermost root, you’re left with 2^(1/2) which is exactly what you started with in the first radical.

This is why it simplifies to the form shown on the right hand side.

[full forum]

@meager garnet Has your question been resolved?

[glossy valve]

Modus

[sharp vine]

And so on...

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[meager garnet]

thank you both @sharp vine @remote zealot

[meager garnet]

.close

[full forum]

Channel closed

Closed by @meager garnet

Use .reopen if this was a mistake.

[meager garnet]

.reopen

[full forum]

✅

[meager garnet]

@sharp vine this would be the same if the it was a different base or exponent right?
but it follows the same general pattern

[sharp vine]

Yes, it could be for example 3^(3^n) and then cube root

[meager garnet]

would square root of that work

[meager garnet]

this would be cube root(3(1+sqrt1 ... )

[sharp vine]

Not exactly, I mean we wouldn't get that 1(1+(1+...))) for such a case

[sharp vine]

Yes

[meager garnet]

when it is in the form x^x^n
this would result in the (1+1(1+...)))

is this correct

[sharp vine]

Yes, but I think we also need n-th degree root

[full forum]

@meager garnet Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[full forum]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[hearty holly]

1,2,3 combined

but mostly 1

[robust slate]

What have you deduced so far

[hearty holly]

if AB =0, then det(AB)=0 right

[robust slate]

Yes

[hearty holly]

so either det(A)=0 or det(B)=0

if both are 0 then infinite

else unique soln

if det(A)=0, then must det(B) necessarily be non zero?

in that case B is invertible, but then if we take det(B) = 0, then B isn't invertible

[robust slate]

You have the right idea of doing casework based on the determinants

If B is invertible, then consider what happens if you multiply AB=O by the inverse of B

[hearty holly]

A=0?

oh so then, if det(B) is non zero, then A=0 and vice versa

but now what

det(A) not 0 implies B=0, and det(B) not 0 implies A=0

so are we left with the only case being det(A)=0 and det(B)=0?

[robust slate]

Yes

[hearty holly]

so infinite solutions?

let me check the key

its right, thanks 🫶

.close

[full forum]

Channel closed

Closed by @hearty holly

Use .reopen if this was a mistake.

[robust slate]

👍 In the future, please say what you’ve deduced so far when you ask the question before being prompted - it saves everyone’s time,

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

@wraith vessel Has your question been resolved?

[full forum]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shrewd meadow]

How do I simplify this algebraically? I am currently struggling to make sense to what I need to do to manipulate the problem to get a trig identity. Could someone break down the steps please?

[unique wagon]

sin(4x)/sin(17x)?

[narrow path]

are you trying to prove its true

[woeful pasture]

Is this

Originally a limit question

At x -> 0

[unique wagon]

one can express it as a Chebyshev polynomial of the second kind.

[unique wagon]

maybe it is just this

!xy

[full forum]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[shrewd meadow]

Yes this is for a limit

[analog sand]

Use small angle approx

[unique wagon]

sin x = x

+some negligible stuff

[rapid rain]

if you do "wavy hands" that's the idea

if you have to do it rigorously, you will use that $\lim_{X\to 0}\frac{\sin(X)}{X} = 1$

[glossy valve]

rafilou is not not born in 2003

[analog sand]

Mhm

[rapid rain]

and make some relevant "X"s appear

[unique wagon]

i mean i think using the taylor series would be just as rigorous

[unique wagon]

which is this

[analog sand]

Series expansion gang

[shrewd meadow]

Thanks everyone ^^

[full forum]

Channel closed

Closed by @shrewd meadow

Use .reopen if this was a mistake.

[urban jacinth]

Ain’t no way you doing series expansion on this

[analog sand]

Ik lol

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ripe halo]

How do I go about approaching this? I've tried writing it as a Telescoping but failed in the attempt.

[sudden cove]

Okay so what was your first step?

[ripe halo]

I tried writing the numerator as a difference of the terms in the denominator. Atp, I think that it can't be written as a Telescoping. I'm stuck.

[sudden cove]

Well the first thing I would do is sub in 3/4

What do you get in that case?

[ripe halo]

No luck

I tried that

[sudden cove]

^^^

[ripe halo]

$$f\left(\frac{3}{4}\right)=\frac{1}{2}\sum_{r=0}^{\infty}\frac{1}{\left(\frac{3}{4}+r\right)\left(\frac{1}{4}+r\right)}$$

[glossy valve]

Will

[sudden cove]

Looks good

What's your next step?

@ripe halo

And ghosted

[full forum]

@ripe halo Has your question been resolved?

[ripe halo]

$$\sum\limits_{r=1}^{\infty}\left(\frac{1}{r-\frac{3}{4}}-\frac{1}{r-\frac{1}{4}}\right)$$

[glossy valve]

Will

[ripe halo]

Changed limits for convenience

[sudden cove]

I'm not sure that's particularly convenient tbh

What's it like without?

[ripe halo]

It's the same Ig because the sum is till infinity? I'm just used to starting the limits from 1 😭

[sudden cove]

You can't just change it at will

[ripe halo]

$$\sum\limits_{r=0}^{\infty}\left(\frac{1}{r+\frac{1}{4}}-\frac{1}{r+\frac{3}{4}}\right)$$

[glossy valve]

Will

[ripe halo]

Doesn't lead me anywhere either ways

[sudden cove]

It does

So if we write out a few terms of this, what do we get?

@ripe halo

(Btw, you can change it like that if you want to. I didn't realise you'd done it properly)

[ripe halo]

Alright wait

[ripe halo]

Using this

Brb

$$T_1=\frac{4}{1}-\frac{4}{3}$$
$$T_2=\frac{4}{5}-\frac{4}{7}$$
$$T_3=\frac{4}{9}-\frac{4}{11}$$

[glossy valve]

Will

[carmine minnow]

looks like something well known

[ripe halo]

Why do I not see it

😭

[carmine minnow]

its a pretty famous formula

[ripe halo]

What is it

[carmine minnow]

But if you cant see it yet, you can try expanding the power series for arctan

[unique perch]

it is equal to pi iirc

[ripe halo]

Idk what that it's like

[ripe halo]

Oh

What

[stone meteor]

arctan taylor series

i think to derive it

[carmine minnow]

Yeah

[ripe halo]

https://en.m.wikipedia.org/wiki/Leibniz_formula_for_π

Good lord

[stone meteor]

lol

[ripe halo]

I didn't know this existed

Ty guys 😭

[sudden cove]

The Maclaurin Series for arctan(x) is x - x^3/3 + x^5/5 - x^7/7 + ...

[stone meteor]

there are like way too many of these

including infinite products

that result in pi or something related

[ripe halo]

Nice

[carmine minnow]

But its not so hard because the derivative for arctan is $(1+x^2)^{-1}$ and you can expand with generalized binomial theorem

[glossy valve]

Element118

[ripe halo]

This was actually a part of a Physics problem I was stuck at

[stone meteor]

its much easier than that

[ripe halo]

Oh

[stone meteor]

just note the geometric series formula

1/1-r

and make r = -x^2

[ripe halo]

So the answer is just π?

[sudden cove]

Yep

[carmine minnow]

It's exactly the same idea lol

[ripe halo]

Ty

[stone meteor]

oh

[sudden cove]

The answer is 4 arctan(1)

= π

[carmine minnow]

Though you may want to work through the derivation

[ripe halo]

Does it require Calculus

I haven't done Calculus outside of Physics

[carmine minnow]

Pretty basic, just need to know how to differentiate arctan and how to integrate polynomials

[stone meteor]

1/(1+x^2) = 1 -x^2 +x^4 - x^6 +...

then integrate both sides

plug in 1 for x

and ur done

[ripe halo]

Damn

Ty you all

[carmine minnow]

Need some theory on power series for why plugging in 1 is fine since its that the edge of the range of convergence

[ripe halo]

.close

[full forum]

Channel closed

Closed by @ripe halo

Use .reopen if this was a mistake.

[stone meteor]

yo help me in my channel if u can

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[inner hare]

so I got something entirely different then the solution. Chatgpt and deepseek agree with me and not the maker of the notebook

Can someone check to see if I did an oopsie anywhere please. I tripple checked and found nothing

[void nova]

Could you send the original task? Cause I feel the translator has done something weird

[inner hare]

based on the standard base yea

if there is anything else confusing please lmk

[void nova]

I don't get the steps you did here

If I understand correctly, you wanted to compute the inverse of S in two ways, right? With the cofactors and with row-reduction?

[inner hare]

yes

[void nova]

Awesome

[inner hare]

the second one (lower) is the one that most ai's agree with

[void nova]

Which is the wrong one lol

[inner hare]

bruh

oh wait mb, its the first one xD

[void nova]

The one you found above with co-factors method is correct

[void nova]

Oh ok then I agree too

[inner hare]

but why does it not match with the solution?

I guess they made a mistake?

[void nova]

Because you still haven't finished 😅

[void nova]

No no (even though they don't show what the inverse turns out to be)

[mighty totem]

Hey guys what 1+1?

I really can't find the answer

[void nova]

<@&268886789983436800>

And also...

[void nova]

!occupied

[full forum]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[inner hare]

but look at the difference

[inner hare]

they did

[keen vector]

can we have a rule specifically for 1+1

[void nova]

What's the problem?

[inner hare]

the inverses are not the saem

same

[void nova]

!occupied

[full forum]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[void nova]

Where do you see it? 🤔

[inner hare]

I put them in the red squares

[void nova]

But I don't see what the inverse turns out to be in their solution

There's only written "inverse of S"

[inner hare]

its in the left image in the red squre

[inner hare]

yea

oh wait im stupid

[void nova]

Then how can you say it's different from yours?

[inner hare]

HAHAHAHAHHA

AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA

oh my

yea mb, im blind

[void nova]

It happens sometimes 😂

Don't worry

[inner hare]

.close

[full forum]

Channel closed

Closed by @inner hare

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[inner hare]

Another one. I went wrong somewhere, but I cant put a finger on where exactly...

And this time chatgpt actually agrees with me

[vast fossil]

You are correct

[inner hare]

so the teacher made an oopsie?

[vast fossil]

Yeah

[full forum]

@inner hare Has your question been resolved?

[inner hare]

thank you : )

.close

[full forum]

Channel closed

Closed by @inner hare

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[karmic helm]

Thats my question.
I have done a and its just using the Thales theorem and

the Angle bisector theorem

then idk how to solve b

FG is a straight line

[unique perch]

DE is a mid-segment so DE = 1/2 BC

so you can find the ratio AB/BC then GA/GC subsequently

[karmic helm]

ok now what do i do?

im fucking bad at geometry

[unique perch]

AB = DE so AB/BC = DE/(2*DE) = 1/2

[karmic helm]

ty solved it

[full forum]

If you are done with this channel, please mark your problem as solved by typing .close

[karmic helm]

.close

[full forum]

Channel closed

Closed by @karmic helm

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[final wing]

2b

[final wing]

Why do you even want to work to P[exp[-(t/theta)²) > some boundary) ???

what does that have to do with P(X>t) = exp(-(t/theta)²) cuz this is just a 1- cdf

[wide sundial]

The bottom looks like it’s a chi squares by the given identity

[final wing]

ye so they did this:

[wide sundial]

So it cancels or something idk

[final wing]

but why like we dont even use that P(X>t) part

[full forum]

@final wing Has your question been resolved?

[full forum]

@final wing Has your question been resolved?

[final wing]

.close

[full forum]

Channel closed

Closed by @final wing

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lapis merlin]

do is have to fivid 70 by 2 to get the perimeter of the shape for 4 rectangels?

[drowsy notch]

yeah

[lapis merlin]

but then how do i work out the area of the 8 sided shape?

[echo marsh]

length is 7cm longer than width

[lapis merlin]

?

[echo marsh]

so if width = x, then length = x+7

7+x*

[rugged tapir]

yes ofc mb

[echo marsh]

and u have perimeter of the shape

so write it in terms of x

and equate

[lapis merlin]

dose not make sense

[echo marsh]

why?

[lapis merlin]

how to find the x?

do i divide by 4?

[echo marsh]

why

[lapis merlin]

.close

[full forum]

Channel closed

Closed by @lapis merlin

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cedar flint]

I know how to solve this (by drawing a venn diagram) but my work is so messy it's hard to keep track

[cedar flint]

I also don't know how to do certain steps

[grim bridge]

3 dozen pies right?

so 36 pies

[cedar flint]

i already know that

[grim bridge]

if a third of the 36 pies were chocolate, you do 36/3, which equals twelve

so 12 chocolate pies

[cedar flint]

broski

there could be multiple ingredients in a pie

[grim bridge]

oh right

[cedar flint]

please only help if you only know how to solve it

[strange basalt]

Show us your steps so we could help maybe?

Or show us your venn diagram

[left bone]

its true, but you want the smallest number of pies that had none of these ingredients, so assuming no overlap of ingredients provides the smallest number of non-ingredients

[cedar flint]

yes i know that but i also want to solve it through venn diagram

because i am not too good at that

[left bone]

there is no venn diagram needed, it would just be 4 non-overlapping circles

(in a big circle if you want a circle for all the pies)

[cedar flint]

oh okay

thanks

.close

[full forum]

Channel closed

Closed by @cedar flint

Use .reopen if this was a mistake.

[left bone]

you want to solve for blue here

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[storm flint]

What are the generalized binomial koefficients defined by

[full forum]

@storm flint Has your question been resolved?

[full forum]

@storm flint Has your question been resolved?

[full forum]

Channel closed

Closed by @storm flint

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rotund tinsel]

Bruh

Why is this wrong

[robust slate]

Same idea for c

[analog sand]

Why 5,6

Yuh

[rotund tinsel]

Oh shit mb I wasn’t reading

Thought it ended it at x = 6 lmao

[analog sand]

E

[rotund tinsel]

So if I change it to 7 it should be good?

[robust slate]

Yes

[rotund tinsel]

Lifesaver ty 🙏

[full forum]

If you are done with this channel, please mark your problem as solved by typing .close

[analog sand]

Sullied the guy

[full forum]

@rotund tinsel Has your question been resolved?

Channel closed

Closed by @rotund tinsel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[calm depot]

which question

and can you give me english tranlation of these questions

[gritty flax]

It asks for the limit of the expression in +inf

[calm depot]

15 no

[gritty flax]

Yeah 15

[calm depot]

ok

[gritty flax]

Globalement ln(x)/x c'est 0

Et les ln² tu peux faire une identité remarquable

Et trouver quelque simplification avec les propriétés du logarithme

[analog sand]

Idts thats even needed

[gritty flax]

How would you do it

[analog sand]

ln^2(x+1) is greater than ln^2 x when x approaches infinity

Unless you werent saying apply logarithm properties

in which case my mistake

[gritty flax]

Yeah i mean both are working but depends on the justification they are waiting for

If they only want algebraic

Or some analysis

[analog sand]

True, if its written then go for log properties

[gritty flax]

Nothing written about the method tho

[full forum]

@wary badge Has your question been resolved?

[calm depot]

is its ans c

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[woeful pasture]

hello gang

[woeful pasture]

how should i go about this

for context

U_n is a set of elements of Z_n that has multiplicative inverse mod n