help-28

[lean tangle]

its fine

[spring vigil]

so i got 7 for y

[spring vigil]

is it 7

oh i have to take the derivative of the inverse

[lean tangle]

i got something slightly differnet

well quite a bit different

oh wait nvm me

i thought u were talking about the derivative already

[spring vigil]

i initially wanted to do that

i ended up doing the inverse of f(x) but its the same thing?

[lean tangle]

wdym?

[spring vigil]

i took the inverse of

cube root x +1

isnt it x^3 -1 = y

[lean tangle]

analytically, yes

so u can now take the derivative of this function

[spring vigil]

sooo

so far

1/3 (x + 1 ) ^ -2 /3

[spring vigil]

for deriving the inverse

[lean tangle]

sorry im confused what you are trying to do now

you went back to differentiating the original

im not sure what your intention is now

[spring vigil]

oh no im sorry

i want to take the derivative of

x ^3 - 1 = y not that one

[lean tangle]

yep ok

so what is the derivative then?

[spring vigil]

3x^2

[lean tangle]

mhm mhm good good

do you know what to do now?

[spring vigil]

now plug in 2

[lean tangle]

👍

[spring vigil]

so

its 12

[lean tangle]

looks good to me

[spring vigil]

can u tell me what would ur thought process be

is it

take inverse
take derivative of that inverse
plug in number after taking derivative of inverse

[lean tangle]

if we were to do it ur way, yes

but just make sure u clearly label ur own working out because i feel like u are getting confused between which function to be differentiating

[lean tangle]

there is a faster way but i feel like its not really appropriate for you to consider for now

but for now, this method is good

[spring vigil]

would it yield a diff nuber

[spring vigil]

do you have extra time

i would like to proceed in working out my worksheet

[lean tangle]

it would yield the same thing

[lean tangle]

i may or may not stay and help, im walking in between my lectures in uni currently

[spring vigil]

ohh u wont be able to then appreciate it though!

i got two pages worth

[full forum]

@spring vigil Has your question been resolved?

[normal spoke]

Bro is prepared for studying today 💀

[spring vigil]

yeah

[normal spoke]

Which question you struggle with

[spring vigil]

i wanna go one by one each

so i can understand

better

[normal spoke]

What work do you have so far

[spring vigil]

for the 1st one I did inverse of (x+3)^ 2

if i did it correctly the inverse is sqrt x - 3

[normal spoke]

Should be right

[spring vigil]

ok now im at the part where i have to take the

derivative of

sqrt x - 3

im having trouble recalling how that works

i did

x ^ 1/2 - 3

but how to do it?

ik that -3 is just 0

so i just have to worry about

x^ 1/2

[normal spoke]

Power rule, or limit definition if you’re famcy

[spring vigil]

ive only learned power rule so far

[spring vigil]

so

1/2 x ^ -1/2

[normal spoke]

👍

[spring vigil]

now since its negative ill move the -1/2 to the bottom

1/ 2 times 1/ x ^1/2

1/2 sqrt x

so thats the derivative

now i plug in the 1

ended up with just 1/2

[normal spoke]

👍

[spring vigil]

great GREAT

this is good

i have my work

[spring vigil]

so far for number 2 this is what i have

[normal spoke]

So far so good

[spring vigil]

im stuck on the next step

[normal spoke]

Differentiate again

[spring vigil]

this is through implicit differentiation

right?>

[normal spoke]

I recommend isolating y’ first if you can

[spring vigil]

yeah im trying to figure out which values i can do that for

so i have a (y + xy^1) on the left

and i have a 4cosy y ^1 on the right

[spring vigil]

so can i just put the whole thing y + xy ^ 1 to the right?

[normal spoke]

🤨

y’ = f(x,y) is the form you’d want

[full forum]

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[spring vigil]

do i do power rule on left side

.reopen

[full forum]

✅

[spring vigil]

i dont know i think im lost on this one

[normal spoke]

You should isolate y’

On one side and everything else on the other

[spring vigil]

yeah i understand that part

i know it ends up being a rational y'

but i need some help on the isolating process

[normal spoke]

Hint: factor out 5x^4(y+xy’) first

[spring vigil]

is this even right

[normal spoke]

Looks about right

[onyx glen]

!nogpt

[full forum]

Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).

[spring vigil]

yeah but how did they get tehre

[normal spoke]

Damn I didn’t even realize that was chatgpt

[spring vigil]

deepseek

lol

[normal spoke]

Factoring

[onyx glen]

!nogpt

[full forum]

Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).

[normal spoke]

Like treat y’ as a variable, say y’=a, then it’ll be easier to see

[spring vigil]

the part where

so i get

the 5(xy)^4 ( y + xy')

i dont get where it got the second + 5 (xy)^4

[normal spoke]

A(B+C) = AB + AC

Multiplication

[spring vigil]

and the ^4?

[normal spoke]

What about it

[unique knoll]

You're multiplying both the y and the xy' by 5(xy)^4.

[spring vigil]

then how come there is a single y over here

[tight quest]

btw (x + 3)^2 is not invertible unless you restrict its domain

[spring vigil]

so is my answer wrong?

1/2

[tight quest]

for x >= -3 yes

for x < -3, it'd be a different case

[spring vigil]

what should i change on here

[tight quest]

well

,, x = (y + 3)^2

[glossy valve]

kizzyyy

[tight quest]

if you square root both sides, you're actually left with

,, \sqrt{x} = \sqrt{(y + 3)^2} = |y + 3|

[glossy valve]

kizzyyy

[spring vigil]

ok i can see that

prof so far never had to use that tho

so i dont think theyre expecting it to be in abs value

but i could be wrong lol

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@spring vigil Has your question been resolved?

[spring vigil]

.close

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[low flame]

Guys

[low flame]

I should do A/(x^2+1) + B/(x+2) ?

[tender nacelle]

yes

[low flame]

and then I gotta find A and B?

[rough plaza]

it should be (Ax+B)/(x²+1) + C/(x+2)

and find constants A,B and C

[low flame]

Ohh yeah

Ok thx

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[worldly canopy]

.reopen

like i know what the answer is but i can understahnd the formula
it's 150 * p / 225 = 100
then u solve for p
wat i dont understand is why 150 times p, and why divide by 225
and why 100

[worldly canopy]

like how do u get the equaltion to solve this

this is find the index number

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@worldly canopy Has your question been resolved?

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[formal ridge]

4th question

[formal ridge]

I've stared at it for more than 10 mins but I can't see where I'm going wrong

[hot herald]

you didn't differentiate that correctly

didn't apply chain rule properly

deravtive of (1-pi * r) isn't -1

[formal ridge]

I see it now 😭 sorry

I got the answer, thank you

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[feral dune]

y = f(x^2) , f'(x) = sqrt(5x-1) . Find dy/dx

[feral dune]

😭?

[glacial pasture]

(what have you tried)

[feral dune]

oh

F(x) = 2/3 (5x-1)^3/2

idk if i can do like

[leaden ermine]

also you don't need that

your best friend is chain rule

[feral dune]

This?

[leaden ermine]

2nd line yes

[main trellis]

id suggest doing something like u=x^2

so y=f(u)

then dy/dx will be dy/du *du/dx

[main trellis]

dy/du will be f'(u) = f'(x^2) so replace all the x's in the second eqn here with x^2

du/dx is obviously gonna be 2x

then combine

[feral dune]

oh so that explains the chain rule right

[main trellis]

which as @leaden ermine described is just chain rule

[feral dune]

Oh ok thanks guy

[main trellis]

no worries mate

[feral dune]

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[peak vigil]

help

[grizzled dagger]

!status

[full forum]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[peak vigil]

1

[grizzled dagger]

hmm

what kind of tools are we allowed to use here? are we allowed to work with derivatives?

[peak vigil]

yup

pretty much anything

[grizzled dagger]

hmm

[peak vigil]

i tried visualizing with triangles

[grizzled dagger]

well you have enough information to find the explicit equation for the parabola, right?

[peak vigil]

well yeah

we got all sides equals 2

so its (-1;1) from left to right

[grizzled dagger]

mhm

okay

does this help

a tangent to the circle at P is perpendicular to the radius OP

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@peak vigil Has your question been resolved?

[peak vigil]

hmm

not quite there yet

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[nocturne shard]

Sorry, I'm terribly late

[nocturne shard]

First of all, based on the figure, the parabola goes through (1,2), so the function is y = 2x^2

[modest obsidian]

what's the problem?

nvm i'm kinda

blind

[nocturne shard]

The equation of the circle is x^2 + (y - k)^2 = R^2, in this case we want to find both k and R

yeah this is a bit of a hassle

[modest obsidian]

coordinate bash for parabola

[nocturne shard]

parabola is y=2x^2

[modest obsidian]

let A=(0,0)

fine

then just use tangency condition

[nocturne shard]

oh

wait

i know

i should have thought of this way sooner, use IA = IB

[modest obsidian]

that gives you the entire line

of symmetry

[nocturne shard]

oh?

rip

[modest obsidian]

you won't find k with just that 💔

[nocturne shard]

yeah, ofcourse...

[modest obsidian]

all the points on that line are equidistant

honestly

just find the tangent lines of parabola at A and B

and uh

[nocturne shard]

... then write the equation of perpendicular lines and find their intersections

aha

yep i really should have thought of that LOL

@peak vigil To sum up:

• Write the equation of tangent lines d1, d2 of parabola at A and B
• Write the equation of perpendicular lines l1, l2 of the tangent lines
• Find the intersection of l1 and l2, which is the center of the sphere

wonder if there's a shorter way

I think you can also use the fact that distance from I to the tangent line equals distance IA, by supposing I(0, k)

might be a bit faster there

,w abs(4*0-k-2)/Sqrt[4^2+1^2]=Sqrt[(0-1)^2+(k-2)^2]

[glossy valve]

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[nocturne shard]

yep, it's like, much faster

@peak vigil another ping to keep up

@modest obsidian thx for the help btw

[modest obsidian]

[nocturne shard]

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[shy bane]

what is a^3 + b^3 =?

or (a+b)^3

[vale zealot]

(a+b)(a^2-ab+b^2)

[onyx glen]

use ^ for exponents

[vale zealot]

Alr

[onyx glen]

you can do something with this and a^3 + 1/a^3

[shy bane]

umm

[onyx glen]

in particular the value of a + 1/a is known

[vale zealot]

Uhm?

[shy bane]

nothing sorry

[vale zealot]

Its ok

[shy bane]

there are two formulas

try remembering the other one

it will be more easier

[shy bane]

.

what is this

[tight quest]

note that $\qty(a + \frac 1a)^3 = a^3 + \frac{1}{a^3} + 3 \qty(a + \frac 1a)$

[vale zealot]

a^3+3a^2b and so on

[glossy valve]

kizzyyy

[vale zealot]

Idk what to put in place of a?..

[royal ledge]

why shouldn't one just calculate a for the given equation

[tight quest]

^

consider that

a + 3 = -1/a so what's a + 1/a

[shy bane]

it is 3ab (a+b)

[analog wraith]

you have to find out the value of a

[vale zealot]

Dont we have to rearrange the given equation in some form😭

[tight quest]

[shy bane]

yes

[tight quest]

do we agree so far?

[royal ledge]

Is that a+3 or 18a +3

[shy bane]

(a+b)^3 = a^3 + b^3 + 3ab(a+b)

[vale zealot]

a+3

[shy bane]

no

[tight quest]

?

[shy bane]

it is wrong

[tight quest]

no it's not

[shy bane]

this is correct

[tight quest]

[shy bane]

??

[analog wraith]

no it's not

[tight quest]

,w true or false (a + 1/a)^3 = a^3 + 1/a^3 + 3(a + 1/a)

[glossy valve]

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[vale zealot]

But i was boutta save it😓

[tight quest]

anyway aroosa, do you agree with what we have above?

[analog wraith]

put b = 1/a in here

[shy bane]

oh yess sorry

[vale zealot]

I am TRYING to get it..

[shy bane]

solve it on your own

[tight quest]

well

[shy bane]

using the formula

[tight quest]

just consider the expansion of (a + b)^3

[shy bane]

yea

[tight quest]

b = 1/a

[tight quest]

and u arrive at this

and then you're done cuz you know what a + 1/a is

from equation 1

by basic rearrangement

[vale zealot]

Alr
Brb

[royal ledge]

put everything on one side so the other side is just zero fr

[tight quest]

because that's a whole lot of work

for something that doesn't require it

[royal ledge]

[vale zealot]

😭😭what is this

[royal ledge]

quadratic's too much for u?

[tight quest]

it's way more effort than what you have to do

[shy bane]

no u don't need to find a

[tight quest]

also the quadratic is not "factorable" so you gotta resort to quadratic formula

,w a^2 + 3a = -1

[analog wraith]

why do you need a quadratic?

[glossy valve]

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[tight quest]

and you're not even done here

do you really want to go that route? lol

[royal ledge]

in spite of greater effort required, it paves the way for certain answer

[tight quest]

[royal ledge]

[vale zealot]

Naw

[tight quest]

didn't follow what was said above frfr

😔

[analog wraith]

uh

[royal ledge]

[analog wraith]

you just ignored everything

[tight quest]

consider (a + 1/a)^3

what do you get

[analog wraith]

woah

[tight quest]

😭 fr

[royal ledge]

oh i get it now

[vale zealot]

Cuz it all flew over my head ngl
Im gonna re read all that

[royal ledge]

i give you back my respect

[tight quest]

have fun cubing those answers and then adding them afterwards

[royal ledge]

thx

[analog wraith]

try to isolate $a^3+\frac{1}{a^3}$

[tight quest]

[vale zealot]

Shit i didnt give yall the MCQs opts

[tight quest]

aroosa 😭

,w a + 3 = -1/a and a^3 + 1/a^3

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[analog wraith]

we don't need options

[vale zealot]

Anywayss😭

[shy bane]

umm?

all ?

[vale zealot]

18

[shy bane]

a + 1/a = -3

do u know why?

[vale zealot]

Hey so can some1 summarise the ans step by step

[analog wraith]

[vale zealot]

Re arrange?

[shy bane]

yes

now which formula will you use

[vale zealot]

Oohhh

But

[shy bane]

to know you can ee what is asked

[vale zealot]

This formula isnt given 💔💔

[shy bane]

like it needs a^3 and 1/a^3 , so u need them

[shy bane]

which?

you know (a+b)^3 right?

[analog wraith]

because it's so basic?

[vale zealot]

This

[tight quest]

that's applying (a + b)^3

the one u ticked

where b = 1/a

[shy bane]

yea

[vale zealot]

Ohk

[shy bane]

algebraic - 5th 1row

anf the one you ticked

[vale zealot]

Yea i see

[shy bane]

you can take 3ab common from that

formula

$3a^2b + 3ab^2 = 3ab (a+b)$

[glossy valve]

lizzie250

[analog wraith]

so you have $(a+b)^3 = a^3+b^3+3ab (a+b)$

[shy bane]

exactly

[vale zealot]

Yep

[shy bane]

and since b = 1/a

[analog wraith]

now put 1/a in place of b

and see what you get

[shy bane]

$(a+1/a)^3 = a^3+1/a^3+3ab (a+1/a)$

[glossy valve]

lizzie250

[vale zealot]

Alr
Thanku sm y’all
(And now my grandma is calling me🫡)

[shy bane]

.

lol

[analog wraith]

eh

one b is left

[shy bane]

sorry forgot to replace one of the b

[analog wraith]

yeah

[shy bane]

lol

[analog wraith]

[vale zealot]

So its final now ryt?

[tight quest]

also how'd you do 16

Lol

,w a^2 + b^2= 29 and a + b = 7

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[tight quest]

2 -5 = -3
5 - 2 = 3

well okay since it's mcq

still silly

[vale zealot]

Formula

Jus that lol

Do yall get a formula sheet?

[tight quest]

it's not that helpful

you just put it on a pedestal

[royal ledge]

what?

[vale zealot]

Cuz i get the one i sent

For exams n tests

[analog wraith]

$a^2+b^2=(a\pm b)^2\mp 2ab$

[vale zealot]

Fax

[royal ledge]

formula sheet is w

[shy bane]

did u get ur ans? i go it

[analog wraith]

y'all so lucky

you get formula sheet

[shy bane]

ikr

[royal ledge]

you don't?

[tight quest]

how is it being lucky?

[vale zealot]

Send 🙂

[analog wraith]

nope, we have to remember every one of them

[shy bane]

can we do that lol

[tight quest]

u just are already expected to know it

seems like a waste of time

maybe they want you to look at it

[shy bane]

true still

[royal ledge]

and that's high school?

[tight quest]

and waste time

[shy bane]

during exam

[royal ledge]

or uni

[shy bane]

high school

[analog wraith]

high school

[vale zealot]

Yea

Cuz the students were crying that it aint even that helpful

The difficult formulas arent given n stuff

Im happy w/ it ngl

[royal ledge]

It's not that tough to remember all the formulas, but I believe all should get used to these sheets

[analog wraith]

not those basic ones

[royal ledge]

which tough formulas for instance?

[vale zealot]

Ask them lol
Cuz even ion know

[analog wraith]

like some complicated ones used in calculus and trigonometry

[vale zealot]

They arent even used

[royal ledge]

it depends

[vale zealot]

They jus gotta rant about everything

[analog wraith]

just remember binomial theorem

[vale zealot]

Ok i do to
But not in everything

[royal ledge]

for most of the time in case of extended maths, just a formula is useless if you don't know how to apply it, which is what should be expected and not memorisation of formulas tbh

[royal ledge]

ok that's one horrible formula

you got me

[analog wraith]

ok but what about trigonometry where you have to memorize everything

[analog wraith]

is it?

[royal ledge]

You don't have them listed?

[analog wraith]

ig I don't have an argument, i have to remember every single one of them cause we don't get a formula sheet

[analog wraith]

nope

I had to remember like 70 formulas and values of some weird angles in the beginning

[royal ledge]

You're doing tasks from all fields and you don't get the sheet?

there's no way

[analog wraith]

we don't :(

[royal ledge]

ok i feel you now bro

[vale zealot]

Thats sad tbh
Straight up slavery

[royal ledge]

I understand it now

I didn't think it was that bad

[analog wraith]

i wouldn't say so, cause there's a really good benefit, you can solve questions like this without even thinking

[vale zealot]

In conclusion every1 should get a formula sheet😓

[analog wraith]

nah I'm good without it

[royal ledge]

🤝

[analog wraith]

recalling it from memory is faster than looking it up imo

[vale zealot]

It takes like 2 secs to look up the formula from sheet
But point ig

[analog wraith]

you can save those 2 secs and maybe skip multiple steps with enough practice

[royal ledge]

It has its benefits for sure

[vale zealot]

Yep cuz they said u gotta solve MCQs in secs
So ur right

[royal ledge]

It's just that there's some formulas you hardly ever use, which sometimes are found in those sheets

[analog wraith]

but I would say, remembering all the formulas from physics, maths and chemistry is a pain

[royal ledge]

yep

[shy bane]

not when u have 30+ trigo formulas

[royal ledge]

don't even mention it

[shy bane]

ikr

[royal ledge]

fr

[analog wraith]

@shy bane

[shy bane]

like i remember them by heart now cause i have done it for the whole year

[analog wraith]

of trigonometry

[shy bane]

omg wtf

[shy bane]

damn

[tight quest]

you've done trig for a whole year?

[royal ledge]

like that formula for the field of a triagle using the radius of the inside circle

[analog wraith]

only relations and identifies, leave inverse trigonometry and equations

[royal ledge]

I was randomly reminded of it like a month ago

[shy bane]

well to be exact 2 years but this year was kinda bad cause so many new formulas

[vale zealot]

Every1 gotta byheart the special angles values?🥹

[tight quest]

that's just 1/2 bh applied three times and relating it to the semiperimeter

[shy bane]

yea brooo sureeeee whole year lol

[analog wraith]

we'll use it for the next 1.5 years

[tight quest]

sad

[shy bane]

yes

for me whole 1 year

and new formulas from next grade

[royal ledge]

something about that yeah

[tight quest]

how is that hard to remember?

[analog wraith]

im talking about angles like sin 15°, tan 22.5°, tan 67.5°, cos 36° stuff like that

[shy bane]

i swear to god....i love love love maths but don't like trigo (can't say hate)

[shy bane]

i don't have that oheww

[royal ledge]

I haven't used it for so long I forgot it existed

nothing else

[vale zealot]

😬😬

[tight quest]

A = 1/2 (a * r) + 1/2 (b * r) + 1/2 (c * r)

A = 1/2r (a + b + c) = 1/2 r p where p is the perimeter and so p/2 = semiperimeter

thus A = rs

[royal ledge]

oh hell no

[analog wraith]

lemme introduce trigonometric equations, solution of triangle and inverse trigonometry

[tight quest]

just derive it if you can't memorize lol

[analog wraith]

someone I still remember each of them 💀

[royal ledge]

Right there we go

[tight quest]

A = rs is a cute formula

hard to forget

[analog wraith]

waste 5 mins deriving when u get 2 mins per question

[royal ledge]

I thought you were talking about equality of fields

[analog wraith]

nuh

[tight quest]

well don't do competition math then

it's pointless

[royal ledge]

yep

[tight quest]

that's not how binom theorem works

[royal ledge]

pretty cute one

[analog wraith]

subjective

[tight quest]

oh nvm i misread

[analog wraith]

congrats

[vale zealot]

💔😓

[vale zealot]

Lol

[royal ledge]

Congrats mira

[tight quest]

[royal ledge]

I guess I learned something from you guys here

[vale zealot]

Mira= mirror guys😭
Aroosa**

[analog wraith]

blud stole my emoji

[tight quest]

you're in hwh right? i remember helping u

[analog wraith]

give it back

[royal ledge]

srry aroosa 😭

[vale zealot]

Yessir

[vale zealot]

Theres a book on my name💅🏼in my native language

[tight quest]

[royal ledge]

spill the beans

[vale zealot]

Well my name’s meaning is lowkey embarrassing🥹😭

Aroosa=bride😭

[royal ledge]

🙏

[analog wraith]

[royal ledge]

Subtle foreshadowing

[vale zealot]

Book name: Mira tul Aroos= Bride’s mirror

[vale zealot]

But i like my name tho

[royal ledge]

so you've got this name off of a book title?

[vale zealot]

Nop…it jus a common name in here

[royal ledge]

that would be the last thing I could expect

[vale zealot]

Lol

[analog wraith]

i thought it was cool before you told what it means

[tight quest]

so you're from Pakistan?

[royal ledge]

it still sounds kinda cold

[vale zealot]

The cutting lmao
Yep

[royal ledge]

Very well

[vale zealot]

🥹

It does not mean a literal bride

It means to cherish urself, dress up n all dat

[analog wraith]

no bride?

sed

[vale zealot]

(My teacher told me that..cuz we had to read the book in class)

[vale zealot]

Lol

[vale zealot]

And obv every1 was looking at me😭😭😭

[royal ledge]

💔

[vale zealot]

To lower the embarrassment scale😓

[vale zealot]

Word meaning=bride

Still a bride then

[royal ledge]

No need to mate

we cool

[analog wraith]

yeah

[vale zealot]

Yep (😓)

[tight quest]

no need to what

oh

[royal ledge]

?

That's a nice chit chat

[vale zealot]

U canged pfp ryt?
And i thought there was another kizzy lol

[tight quest]

[vale zealot]

Hmm

[vale zealot]

I didnt get scolded !

(That much lol)

[royal ledge]

Why would you???

[vale zealot]

I always get scolded

[royal ledge]

For what

[vale zealot]

Cuz im stupid🥹

In meth

[royal ledge]

You're not bruv

[royal ledge]

https://tenor.com/view/breaking-bad-chemistry-experiment-scientific-walter-white-gif-17820266

[vale zealot]

1 time i walked up to my teacher

And asked this ome question

[royal ledge]

ye

[vale zealot]

She held her head in both hands and heaved a sigh

😭😭😭

[royal ledge]

😭

we ain't even do nun

[vale zealot]

And also yesterday she got in front of the class

And said Aroosa did u prep the test

That too in front of the whole class

(I didnt cuz history is better)

[royal ledge]

you like history?

[vale zealot]

I gave my shy ass smile and shook my head
Humiliated the duck outta me😭💔

[vale zealot]

Well better than meth

[royal ledge]

Fr I love it

[vale zealot]

And everyone says history over geography

But..uhm

[royal ledge]

It's a great springboard from all these numbers

[vale zealot]

Idk I studied geography better this time prolly

[vale zealot]

Springboard?

[royal ledge]

What do you extend then?

[royal ledge]

It was thinking a literal translation is all it takes, i meant an alternative, something to get my mind off the usual stuff

[vale zealot]

Aha

Ohk ohk

[royal ledge]

So that's the way to spend the time off

[royal ledge]

what do u extend?

which classes

[vale zealot]

Equal mostly

Maths probably

[royal ledge]

Splendid mate

[vale zealot]

And sci subjects

I got 8 in total

[royal ledge]

We are united by cult of nunbers

8??

[vale zealot]

Eng

Urdu

Meth
Bio
Phys
Chem
Pakistan studies…h and g
Islamiyat

Lol

[royal ledge]

there is NO way

[analog wraith]

islamiyat 💀

[royal ledge]

im outta here

[analog wraith]

real

[vale zealot]

Yes islamiyat branches into 2 other subjects so like 3😭

Formula sheet pretty reasonable?🥹

[analog wraith]

which grade btw

[vale zealot]

9th

[analog wraith]

huh

we had like 8 subjects till 8th grade

then its 6 since 9th

[vale zealot]

In 8th did u have separate sci subjects?

Like phys, chem and bio

[analog wraith]

no, we get to choose in 11th

[vale zealot]

Cuz here they are 1 subject..sci till 8th

[analog wraith]

have to study everything till 10th

[vale zealot]

And get Separated in 9th

[analog wraith]

there are different teachers and different books, but we give only 1 exam

science

[vale zealot]

Ohk
Thats a better strategy imo

[vale zealot]

U wish to be a cat?

Whys there a dog on ur pfp then😼

[analog wraith]

[analog wraith]

now you know that you need to get glasses

[vale zealot]

Ayo

On the idk avatar/banner or whatever

[analog wraith]

ow you talking about the avatar decoration?

[vale zealot]

Yep

[analog wraith]

hexagon thingy

yes it's a dog

mb

[vale zealot]

Car betrayer💔

[analog wraith]

the pfp is cat

[vale zealot]

Am wearing them😭

[analog wraith]

irony is that I have a dog

[vale zealot]

💀

[analog wraith]

get yo focal length adjusted

[vale zealot]

No car?

[vale zealot]

I wasnt wrong tho😓

[analog wraith]

no cat

[vale zealot]

What do i make out of dis?😭

Ngl i like cars more than dogs

Gonna have one once i ger older

[analog wraith]

same

[vale zealot]

Why do u have a dog instead of a cat tho?

[analog wraith]

cause dogs are cool

[vale zealot]

Love-hate relationship

Who is the side chic man? Cats or dogs?

[analog wraith]

what?

[vale zealot]

U see theres one main (cat/dog) who u love more

and theres a side chick (cat/dog)

[analog wraith]

I'm loyal 💀

[vale zealot]

To both?😭

[analog wraith]

no?

[vale zealot]

Loyal to cat or dog then?😭

[analog wraith]

I don't remember saying I like cats

[vale zealot]

💀

Brain rot final boss

[analog wraith]

btw close this channel ig

[vale zealot]

Yea i forgot
n open book atp

.close

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[gritty rose]

,rotate

[tropic lion]

I got 2 for x

It ask for square

[tropic lion]

Should it be 4 for the answer then

Sry this question

Not the other one

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[tropic lion]

.close

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[shut pelican]

anyone mind helping me pls?

[viral jasper]

Does it want you to estimate with a calculator?

[shut pelican]

yes

for g(1) i set it up like G(3)-G(1) = the integral from 1 to 3 of squareroot(x^3 + 2)

and then i pluged the integral into my calc

and got like 6,58

then I knew that g(3) is just 5

so i subtracted that from both sides

and got 1.58

then i took the negative of the right side to make g(1) positive

then i got g(1) is -1.58

but i feel like its wrong

oh i got it

the answer is on the bottom

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[slate parrot]

can someone explain me how to find angle alpha?

[leaden cloak]

Lami's theorem

Oh wait, that only works when the sum of forces is 0

Nevermind

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[lime sinew]

hey! I'm reading the James Stewart, but I'm stuck in the section about work. So I understand the defintions, but can never apply them correctly, can someone help approach these problems?

[full forum]

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[lime sinew]

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[stuck fiber]

I drew what I thought would be asymptotes on the graph

Its this graph but p = 8 (yes im XYing but my question is about something else)

Apparently only the aqua blue vertical line and red oblique line are asymptotes

How come the gold and dark blue lines aren't asymptotes?

There is a point where the graph comes close but doesnt touch, right? Isnt that the definition of an asymptote?

[gritty rose]

what even is your question

[stuck fiber]

How come the gold and blue lines arent asymptotes

[gritty rose]

why should they be

[stuck fiber]

There is a point where the graph comes close but doesnt touch, right? Isnt that the definition of an asymptote?

[gritty rose]

no that's not the definition of asymptote

[stuck fiber]

Ok..... thanks...........

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[proper edge]

Is my trapezoidal rule setup correct here?

the bounds is 2 to -1 btw I didn’t see that I cut it off

[onyx glen]

nope

your x values cover the range [0, 3]...

not the [-1, 2] that they're supposed to

also why do you write Δx = 1/4 ?

you use it correctly as 1/2 afterwards, but that claim of Δx = 1/4 is there fsr

[cursive condor]

They probably meant the fraction before all the brackets.

[proper edge]

so I wrote delta x = 1/2 which is (b-a)/n right and then I had to multiply that by 1/2 again bc that’s what the trapezoidal rule states

[onyx glen]

well then that's $\frac{\Delta x}{2}$ not just $\Delta x$ ...

[glossy valve]

Ann

[onyx glen]

anyway the other issue i pointed out still stands

[proper edge]

so you’re saying my x intervals are for 0 , 3 and not -1 to 2 right? so instead I need to incorporate -1 as -2/2 all the way to 4/2?

Or is that not it either

[cursive condor]

What is the upper bound?

It's cut off.

[proper edge]

yeah it's 2 sorry about that

[onyx glen]

so instead I need to incorporate -1 as -2/2 all the way to 4/2?
yes

though the writing of -1 as -2/2 is hardly obligatory

[proper edge]

i just like it to emphasize the intervals idk why

ight let me write that rq

[proper edge]

better?

[onyx glen]

yes seems correct now except that those "intervals" aren't called that

those are endpoints

an interval is a stretch on the number line not a single point

[proper edge]

idk maybe thats why my understanding is weird cuz my professor wrote it on the board that way

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[golden shore]

Inscribe a triangle in a circle, what is the probability that the triangle encloses the center of the circle.

[golden shore]

That’s my answer

But it is incorrect

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[crude jackal]

Any electronics guy?

[austere cove]

Hi what's up?

For this problem I would use the mesh circuit analysis method

[quick grove]

Might need to supermesh because of the current source?

[austere cove]

That fair, I completely forgot that super mesh is distinct from mesh

[full forum]

@crude jackal Has your question been resolved?

[crude jackal]

That current symbol is confusing me

I mean, what does that arrow mark mean? Does it mean there is 3A extra current other than the current from battery?

[austere cove]

Think of it as a voltage source that creates enough voltage to cause a 3A current in the direction indicated

But we don't know how much voltage that is

[crude jackal]

Oh....hm....

Oh!

So u mean there is some voltage around that 3A

[austere cove]

3A

[crude jackal]

Ya ya

Hm...

[austere cove]

Yes there is a voltage difference

[crude jackal]

Does it also have some resistance then?

[austere cove]

No, like the 12V source on the far right, it is assumed ideal, 0 internal resistance

[crude jackal]

Hm... Damn my head is spinning now

If the resistance is 0 then how is current not infinite there

And before u say it, I do suck in electronics

[austere cove]

If the resistance is 0 how is the current not infinite across the 12V source?

[crude jackal]

Oh...hm....

[austere cove]

The answer is there are no paths back around to them without encountering a resistor

[crude jackal]

I never thought of that

Hm....

[austere cove]

If there were then it would be a short circuit and yes, infinite current in theory

[crude jackal]

So, so should the voltage be 12V accross the 3A?

[austere cove]

No

[crude jackal]

Simply multiply 3 times 4?

[crude jackal]

Oh

[austere cove]

It's some voltage that is sufficient to induce a 3A current

But we don't know what that is

Yet

[crude jackal]

So how to find that voltage then

[austere cove]

Mesh

Or super mesh I guess

[crude jackal]

What's that

Damn

[austere cove]

Using Kirchoff's rules make a loop in each of the three cells

[crude jackal]

hm... okay

[austere cove]

https://en.wikipedia.org/wiki/Mesh_analysis

[crude jackal]

Is this good?

Please tell me

Is the answer 24 volts?

Please

Come on

[austere cove]

@crude jackal patience please, I am not only in this channel

[austere cove]

This looks good to me

[crude jackal]

Oh,... sorry

Can u please check urself as an expert too?

[austere cove]

I have not tried to figure out this problem yet, so I do not know

[austere cove]

I can check your work if you show it

Oh good!

[crude jackal]

so....looks good?

[austere cove]

I don't know yet

Give me a moment

[crude jackal]

Okay 👍

Thanks for sticking for this long

I am really thankful

[austere cove]

,w Solve[{12 - 3x - 8(x-y) == 0, 8(x-y) - 2y + 3 == 0}, {x, y}]

[crude jackal]

Oh shit

I fked up the math

[austere cove]

No I did

[crude jackal]

66+24 I wrote 100

[glossy valve]

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Requested by omnipotententity

[crude jackal]

Hm....

[austere cove]

,w (72/23 - 129/46)*8

[glossy valve]

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[austere cove]

According to this it should be 2 volts. Let's see if this makes sense with the rest of the circuit

[crude jackal]

But is my initial assumptions current tho....

I mean, all those initial foundations

[austere cove]

I don't understand?

[crude jackal]

Nah, Nevermind.

Hm...

The guy who gave the question said 9.6

9.6V

[austere cove]

That might be correct

[crude jackal]

Oh shit.

[austere cove]

I may have made a typo

Don't just take my word for it.

I can make mistakes too

[crude jackal]

I for some reason am find voltage accross 4 ohm resistor

But the question asks 8 ohms

[crude jackal]

At least u will know what mistake u did unlike me walking in the shadows clueless

[austere cove]

,w Solve[{12 - 3x - 8(x-y) == 0, 8(x-y) - 2y - z == 0, z - 4(y-3) == 0}, {x, y}]

[glossy valve]

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[austere cove]

There we go, my bad.

,w 8*(44/15-38/15)

[glossy valve]

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[austere cove]

3.2 according to this

[full forum]

@crude jackal Has your question been resolved?

[crude jackal]

Ya, I got same

Thank you very much

I guess I am done

[crude jackal]

Yes

.close

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[naive sparrow]

I managed to work through a and b, working through c atm but my answer doesn't align with the answer sheet for some reason

[naive sparrow]

Pr(1 job in total) from part b was given to be 0.352

so Pr(2 jobs total) should just be = Pr(1 job total) + Pr(A2B0) + Pr(A0B2) + Pr(A1B1)

using part A, Pr(exactly x job) = 0.6^x * 0.4

Pr(2 jobs total) should be = 0.352 + 2 * (0.6^2 * 0.4 * 0.6^0 * 0.4) + (0.6 * 0.4)^2 = 0.5248

wait nvm I'm just bad at simple multiplication

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[oblique kraken]

I would like to know if I got any of the questions wrong. I don't know how t-test works and just based off my guts.

Also, how do you know if you should reject the null hypothesis or not?

[drifting ferry]

How do you think the t test works

[oblique kraken]

Just substituting based on the formula

Idk what's the difference between the population standard deviation and sample standard deviation though. It looks the same in the questions

[inland moth]

population is the whole

sample is a small part

so population standard deviation is the standard deviation for the WHOLE population

sample standard deviation is the standard deviation from your drawn sample

[oblique kraken]

I tried looking up videos online but I get confused about the greater than, less than, equal to, not equal to, yknow those signs. Were the signs I used in my alternative hypothesis even correct? Because somehow in some videos even if the alternative is less than the null, they still make it not equal to instead of just using the less than sign

[inland moth]

yeah it looks right

[oblique kraken]

Thanks! : )

You reject the null hypothesis if it's inside the rejection region that's inside the critical value/alpha value right?

In #2, I wanted to answer that the null hypothesis is accepted/not rejected since my Z is higher than the critical value

Would that be correct?

[inland moth]

firstly, its not z

its t

you're using a t-test

second, are you sure that the test statistic is less than the critical region?

[oblique kraken]

I'm not actually:((

[inland moth]

your test statistic is 2.53

[oblique kraken]

We were taught to use z test if the sample is greater than or equal to 30

[inland moth]

if the sample is greater or equal to 30 AND you know the population standard deviation

[inland moth]

anyways, your test statistic is 2.53 and critical value is 2.33

is 2.53 greater than 2.33?

[oblique kraken]

...yeh? 😢

I'm confused rn

[inland moth]

so 2.53 is in the rejection region correct?

[oblique kraken]

OH

OHHHHHHHHH

Omg you're right

I was looking at the values and thinking if Z or T is higher that means it's accept if it's lower it's reject

That actually solved the entire issue for me, thanks!

[inland moth]

theres two values you need to look

the value you get from the significance value

and the value you get from using the z/t formula

if the value you get from the z/t formula is greater than (right tail) or less than (left tail) the value you get from the significance value, you reject

[oblique kraken]

I see🤔🤔🤔🤔

[inland moth]

for two tailed if its either less than -z(alpha/2) or greater than z(alpha/2) you reject

[oblique kraken]

So I have to redo my previous answers ye? I looked up another yt tutorial earlier and found out I forgot to use the t-table

[inland moth]

also applies to t test

so your conclusion on 2 is?

[oblique kraken]

Got it! I'll keep those in mind

My conclusion is I'll reject the null hypothesis

As it's inside the rejection region

[inland moth]

good

[oblique kraken]

Wait I'm gonna resolve 3 and 4

[inland moth]

also you shouldn't write z(alpha/2) if you aren't doing a two tailed test

you are not dividing the significance by 2

[full forum]

@oblique kraken Has your question been resolved?