#help-28

1 messages · Page 180 of 1

graceful loom
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You are taking delta intervals from a point

ionic zinc
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Whats a delta interval

graceful loom
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And if every point within that interval is less than or equal to the min or max

torn jolt
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open interval

graceful loom
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Yeah

ionic zinc
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oh ok

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so what if a cubic function has two stationary points

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both of equal level

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like, (-2,2) and (2,2)

graceful loom
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Right

torn jolt
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thats not happening

ionic zinc
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what

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why

torn jolt
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cant be equal

ionic zinc
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the y coordinate cannot be equal?

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says who-

torn jolt
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ye

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cuz its increasing or decreasing after the first one

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until the second one

ionic zinc
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oh

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okok

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thanks

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Also also

torn jolt
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ye

ionic zinc
torn jolt
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i gtg

ionic zinc
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oh

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i understood everything uptil the first part

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the second part is where everything went to shit

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like, second image

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@ionic zinc Has your question been resolved?

ionic zinc
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<@&286206848099549185>

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@ionic zinc Has your question been resolved?

ionic zinc
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<@&286206848099549185>

torn jolt
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why

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which part

ionic zinc
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second image

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ion get nothin

ionic zinc
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<@&286206848099549185>

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damn

full forumBOT
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@ionic zinc Has your question been resolved?

ionic zinc
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uhuh

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whats the point tho

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only one derivative value is applicable anyways

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uhuh

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yes

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yes

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ohh

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but like

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is there any case that

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even if we do find a value

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through sigle derivatio

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n

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it may not be the max?

ionic zinc
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.close

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true dagger
#

I've answered ai), how do I go about answering aii)? I don't really understand what it's asking tbh

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ember shadow
#

is it supposed to equal ey? not just e

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wheat seal
#

There's a rectangle with these values:

area=3y
Perimeter=y
Lenght=3x
Width=x+2

I need to find the perimeter using systems of equations (highschool level). Would it be 50?

jolly flint
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im getting ≈57 units

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ember shadow
#

I got 56.84

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wheat seal
#

wait it was actually:

area=3y
Perimeter=y
Lenght=3x
Width=x+5

I put the wrong width. I get to this step but idk where to go from here:

  1. (8x + 10 = y)
  2. (y = x^2 + 5x)
ember shadow
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...

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if you did the arithmetic correct, just solve for x

viral jasper
wheat seal
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8x+10=x^2+5x
3x+10=x^2
=x^2-3x-10
(x-5)(x+2)

so x=5? And then y=50?

ember shadow
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yup

jolly flint
wheat seal
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alr thx 👍

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serene hazel
#

can anyone help me with vectors

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serene hazel
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where do I start

buoyant epoch
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sure

serene hazel
nova sigil
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Post your question

buoyant epoch
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I don't get the notation

nova sigil
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To learn vectors use youtube, to go through questions or understand something specific ask away

serene hazel
serene hazel
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where do i start?

buoyant epoch
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ohh you have to look at it from the top

serene hazel
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yeah I have read the question but still don't know how do I start

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do i need to label the number on given diagram?

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does the image look blurry to see or not

buoyant epoch
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Can you draw a line where 80 degrees is

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I don't really see where the wind is coming from

serene hazel
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I think 80 is already listed

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below 85

buoyant epoch
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That looks more like 90 degrees

serene hazel
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why?

buoyant epoch
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Let's try to put this angle in vectors first

serene hazel
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ok

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also im kinda not sure which side they're asking for

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right from the last sentence

buoyant epoch
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From the N line, the angle is like 170 degrees

serene hazel
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how

buoyant epoch
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because it's 80 degrees from the east line

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If I'm looking at it correctly

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80+90=170

serene hazel
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so you're saying its 90 instead of 80?

buoyant epoch
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No no no

serene hazel
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I don't get where the 90 is coming from

buoyant epoch
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I'm not exactly sure but I'm assuming this is the 80 degree angle we're talking about right?

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or it should be around there

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correct?

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I just want to know whether the wind is coming from that quadrant

serene hazel
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ok

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but they already given us that angle is 80

buoyant epoch
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assuming that's right, we need to add the 90 degrees from where the 85 degree line is so we can think of it like the intersection point is the middle and then we can convert the angle to 90+80=170

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which allows us to get a vector

serene hazel
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I see

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then what you can do after getting your angle?

buoyant epoch
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That would correspond to a vector of (x, y) = (-0.17; -0.98) approximately and we need to flip the vector because the wind is coming from there. so (x, y) = (0.17; 0.98)

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The vector of an angle is (x, y) = (cos(x), sin(x))

serene hazel
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how did you get these "-0.17; -0.98" numbers from?

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it doesn't show anything from there

buoyant epoch
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cos(170) and sin(170)

serene hazel
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oh ok

buoyant epoch
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The vector of an angle is (x, y) = (cos(x), sin(x))

serene hazel
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yea I see it now

buoyant epoch
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if the angle is x

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because the vector is going in the opposite direction, we need to flip the vector

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also, we can convert the 60 degree angle and reverse it so we go the long way to get a 300 degree angle

serene hazel
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60+300?

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where does 300 coming from?

buoyant epoch
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yes

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from the 360

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because we're subtracting 360-60

serene hazel
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oh ok

buoyant epoch
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so we're taking the long angle

serene hazel
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the long angle says 380

buoyant epoch
serene hazel
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hmm

buoyant epoch
serene hazel
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right

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can we use sine law or cosine law?

buoyant epoch
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so for the plane's vector, it'd be (x, y) = (cos(300), sin(300)) = (0.866, -0.5)

serene hazel
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ok

buoyant epoch
serene hazel
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can you point me what is the question asking

buoyant epoch
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We can use the speeds and weigh it out

serene hazel
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🫠

buoyant epoch
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The plane is going 380 km/h and the wind is 85km/h
I'm gonna try this
What if we multiply 380 by the planes vector and 85 by the winds vector

serene hazel
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I thought we can't multiple vectors?

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im confused rn

buoyant epoch
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no no no

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380 times the vector

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and add that to 85 times the vector

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but wait actually lemme write it out on paper

serene hazel
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use latex instead but sure

buoyant epoch
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im kinda stuck myself

serene hazel
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its ok

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might wait a little longer until someone else to come

buoyant wadi
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More help needed in here?

serene hazel
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yes

buoyant wadi
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Okay I'm skimming

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So you were trying to translate 380 km/h N60W and 85km/h S80E into cartesian coordinates?

serene hazel
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yep

buoyant wadi
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So S80E is 80 degrees counter-clockwise from direct south, yeah?

serene hazel
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ye

buoyant wadi
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Hmm, so I guess to start we should unify the angles, make N60W and S80E both based on the same axis

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Were you treating due north as 0 degrees? My instinct is to use east since that's pointing right, but it shouldn't matter which one so long as you're consistent

serene hazel
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alright

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but still wondering what side they're asking for

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is there anything to use

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my teacher usually only shows us something like sine and cosine law but I don't have any side except for 380

buoyant wadi
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What do you mean by side?

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Well if we treat due north as 0 degrees and we work counter-clockwise, then N60W becomes 60 degrees right?

serene hazel
buoyant wadi
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Ah okay I think I see what you mean

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Well anyway, still having due north be 0, what angle is due south?

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And from there, what angle is S80E?

serene hazel
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80

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wouldn't this be 80-180

buoyant wadi
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Actually it would be 80+180

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Since south is 180 degrees from north, and S80E is 80 degrees from south

serene hazel
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I see

buoyant wadi
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But anyway, so we have the desired angle being 60 degrees and the wind going at 260 degrees

serene hazel
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where did 260 degrees come from?

buoyant wadi
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260 = 180 + 80

serene hazel
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oh I thought it was 180+60 mb

buoyant wadi
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fair fair

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So lets break the desired angle & velocity into north and west components, 380km/h going 60 degrees

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This is the same as finding the side lengths of a right-angle triangle with hypotenuse 380 and angle 60

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The adjacent side being north and opposite side being west

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Do you think you can figure that out?

serene hazel
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yea

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I can continue with this now

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thanks a lot

buoyant wadi
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No problem!

serene hazel
#

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flat tinsel
#

I need help with this

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flat tinsel
#

I’m plugging my phone in then I’m going to be back to get some help

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@flat tinsel Has your question been resolved?

flat tinsel
#

Yes

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It has

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fleet gulch
#

hi can someone check my answers plz

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Please don't occupy multiple help channels.

fleet gulch
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Please post images (such as PNGs or JPGs) of the question rather than other filetypes such as PDFs which have to be downloaded. Non-image downloads can potentially contain viruses or other security risks.

fleet gulch
#

okay

ember shadow
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nobody's going to download your zip file

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ask a specific question

somber niche
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send a screenshot

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unless you're trying to spy on us.....

fleet gulch
#

sorry im like a nube when it comes to discord

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i use this like once a month max...

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i was hoping if someone could check my answers & see if i did it right

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that way im not jus studying wrong matieral

ember shadow
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I think the first one is wrong. shouldn't N(B) = N(A' n B) + N(A n B)?

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the second page is closer, but N(B) is wrong again

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you wrote N(A' n B)

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@fleet gulch Has your question been resolved?

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@fleet gulch Has your question been resolved?

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thick plinth
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thick plinth
#

CAN ANYONE HELP ME

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srry caps lock

wary lodge
#

U have 3 possible cards and then 2 possible spins, so $3/times2=6$

glossy valveBOT
#

°Jason Parker°

dim violet
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no its 4 possible sums because 5+4 = 6+3 etc

thick plinth
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?

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but what about 7+3 and 6+4

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those both euqal

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10

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<@&286206848099549185>

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@scenic thistle

dim violet
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yes

spice orchid
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yeah so go through every card+spinner options and see how many different ones there are

thick plinth
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i did that

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but isnt it two

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cuz of 7+3 and 6+4

dim violet
#

5 + 3 = 8
5 + 4 = 9
6 + 3 = 9
6 + 4 = 10
7 + 3 = 10
7 + 4 = 11
you have 8, 9, 10 and 11 therefore 4 possible sums

thick plinth
#

ok thank you so much

dim violet
#

you can also calculate it with $possible sums = possible cards + possible spins - 1$

glossy valveBOT
#

MinecraftJoe09

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autumn sparrow
#

“In how many ways can you arrange 4 books in math and 3 books in physics in a single shelf so that no two books in physics are next to each other (all the books are different)?”

noble dew
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okay lets try and think about it visually

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one moment please

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we have 7 different spots for our books to occupy

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lets start by fixing our physics books in these specific spots

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how many ways can we arrange these physics books?

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autumn sparrow
#

3!

noble dew
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yep

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and how many ways can we arrange the math books if we placed them in between the physics books?

autumn sparrow
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4!

noble dew
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so your answer is

autumn sparrow
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well its 3! + 4! = 144 ways

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but

noble dew
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its not

autumn sparrow
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damn

noble dew
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notice how i emphasized and earlier

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when dealing with combinatorics, hearing the words and/or should mean something

autumn sparrow
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i have no idea

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i know the formula is supposed to be 3! x 4! x (4c2 + 4c1)

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someone explained it but i dont understand why

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i mean why isnt the answer just 144

noble dew
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Okay, how many ways can I pick 2 apples and 2 bananas

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just as an example

autumn sparrow
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4!

noble dew
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not quite

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hold on let me think for a second

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So when you were figuring out how many ways were possible to arrange the physics books, you said it was 3! right?

autumn sparrow
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yes

noble dew
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do you know why it is?

autumn sparrow
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if we put one book in a specific spot then theres only two spots left where we can put a different book etc etc

noble dew
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yep, so we have 3 choices for one spot, and 2 choices for the next spot, and 1 choice for the last spot

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aka $3\times 2\times 1 = 3!$

glossy valveBOT
#

Cyphercrit

noble dew
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whenever you hear and, you should think about multiplication

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on the contrary, whenever you hear or, you should think addition

noble dew
autumn sparrow
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i understand

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so why isnt it 3! x 4!

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wait wait

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nvm i still dont get why thats not it

noble dew
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do you remember how at the start, i chose where we were going to put the physics books?

autumn sparrow
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yes

noble dew
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we also need to factor in the possibility of other spots being chosen, since the only requirement is that all of the physics books aren't together

autumn sparrow
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how should i do that

noble dew
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one second

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basically, you need to think about the possible arrangements of the physics books such that no one of them is directly next to the other

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first, you can start by arranging the 4 math books, depending on how you arranged them, there would be 5 possible gaps

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one of them being before the first math book, 3 of them being in between consecutive math books, and one of them being after the last math book

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does that make sense?

autumn sparrow
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i dont understand how there are 5 gaps

noble dew
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PMPMPMP is one where you have one before the first math book and after the last math book

autumn sparrow
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shouldnt there be 3 since there are 7 books total

noble dew
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not neccesarily

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MPMPMPM is one where you have 3 gaps in between each math book

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so we have three scenarios really, one where we have an arrangement of some books PMPMPMM, one where we have the arrangement of some books MPMPMPM, and one where have an arrangement of some books MMPMPMP

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if so lets line up these scenarios

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PMPMPMM
MPMPMPM
MMPMPMP

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if we don't double count gaps, how many gaps are there with physics books?

autumn sparrow
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3x3x3?

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not sure

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i have zero idea what the question even is

noble dew
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so the possible gaps are: one gap before the first math book, one gap after the last math book, one gap in between the first two math books, one gap in between the second and third math book, and one gap in between the third and fourth math book

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for a total of 5 gaps

autumn sparrow
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got it

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why do we need to know how many gaps there are

noble dew
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well, we only have 3 physics books, right?

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so we need to choose only 3 gaps, not 5 of course

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which means we need to choose 3 gaps from 5 possible gaps

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so we need to count the number of ways to choose 3 gaps

autumn sparrow
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so 5x4x3

noble dew
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not quite

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how many ways can we choose 3 elements (gaps) from a set of 5 elements (gaps)?

autumn sparrow
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well i thought it was 5x4x3

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not sure but shouldnt it be just: for the first gap (1/3) i have 5 gaps to choose from, for the second gap (2/3) i have four and for the last gap(3/3) i have three

noble dew
#

$n\choose k$

glossy valveBOT
#

Cyphercrit

autumn sparrow
#

no idea what this is

noble dew
autumn sparrow
#

ohh

#

so combinations and permutations

noble dew
#

yes

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so how many ways can we choose 3 gaps from 5?

autumn sparrow
#

just a sec

noble dew
autumn sparrow
#

so this

noble dew
#

yeah, or just 5 choose 3 or $5\choose 3$

glossy valveBOT
#

Cyphercrit

noble dew
#

so, we have $5\choose 3$ ways to select the gaps, and $3!$ ways to order the physics books, and $4!$ ways to order the math books

glossy valveBOT
#

Cyphercrit

autumn sparrow
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so

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whats the next step

noble dew
#

you tell me

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we're almost done

noble dew
autumn sparrow
#

ohh

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so thats it

noble dew
#

whats the final answer?

autumn sparrow
#

1440

noble dew
#

,w 3! * 4! * (5 choose 3)

noble dew
#

yep

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your teacher would probably prefer that you keep it as 5c3 * 3! * 4! though

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as long as you have the above in it though, it shouldn't matter

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i.e. dont just write down 1440 as an answer and call it a day

autumn sparrow
#

thank you so much tho

noble dew
#

no problem

autumn sparrow
#

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wraith river
#

is my diagram correct?

#

what exactly is a resultant ground velocity

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@knief

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@lime ether

lime ether
#

it’s the velocity relative to the ground

wraith river
#

oh

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so how does that affect my diagram

lime ether
#

no that looks fine

wraith river
#

bc they drew it like this which confuses me

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like why do i see a right angle

lime ether
wraith river
#

It doesnt matter if i draw it like this?

lime ether
#

that looks fine

wraith river
#

i drew mine straight

lime ether
#

the wind pushes it to have that resultant ground velocity

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oh no

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the 430 is greater so it should be higher

wraith river
#

oh

lime ether
#

the magnitude of the 430 is obviously greater than the 400 so the vector should be longer thus it won’t be a straight line

wraith river
#

oh ok

whole compass
#

help pls

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hard mango
#

hi can someone help me get started on this. i don’t exactly understand how the graph should look

hard mango
inland trellis
#

!status

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What step are you on?
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2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
hard mango
#

1 definitely

inland trellis
#

What subject is this?

hard mango
#

pre-calculus

craggy tapir
inland trellis
#

^^

craggy tapir
#

the question is asking for the area from x = 1 to x = 7, so we are going to consider that portion of the graph

#

"with 12 rectangles" means that you need to divide that graph into 12 sections, and draw 12 rectangles side by side, each tangent to that graph

#

somewhat like this

#

and you need to calculate area of each rectangle for an approximation of the area under that curve

#

in more rigorous terms, you are to compute a riemann sum of that curve with 12 terms

hard mango
#

thank you!!

craggy tapir
hard mango
#

🤭👍

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winged jungle
#

hello i am needing to review entire algebra one, i apologize as my english is not too good

astral sinew
#

the ENTIRE algebra one?

#

that sounds like a lot

winged jungle
#

yess

#

very hard haha

#

i do know some things, having trouble remembering

#

i am doing state test, they are making me do it for american school credits

#

very hard 😆

torn jolt
#

idk abt american things so can u tell the portions of algebra one

winged jungle
#

i will get my teacher's curriculm quickly please wait

torn jolt
#

ok

winged jungle
#

Quarter 1
Unit 1: Expressions and Linear Equations
Unit 2: Linear Functions
Quarter 3
Unit 4: Exponents and Radicals
Unit 5: Polynomial Operations
Quarter 2
Unit 2: (continued) Linear Functions
Unit 3: Linear Inequalities
Quarter 4
Unit 6: Investigating Quadratic Functions
Unit 7: Representing and Interpreting Bi-Variate Data

torn jolt
#

i see

#

the last one is basically expresionns in 2 variable ?

winged jungle
#

i believe so

torn jolt
#

ok so ill tell an idea

#

to revise quickly

torn jolt
winged jungle
#

functions , linear equations, expressions, rules, factoring, graphing, exponents, radicals,

#

plotting points

torn jolt
#

do everything other than those

winged jungle
#

i see

#

thank you my friend!

torn jolt
#

so like

#

its algebra

#

hence its connected

#

so if u do smth udk

#

also

#

u get practice on it

winged jungle
#

i am doing khan academy

#

good?

torn jolt
#

yes

#

wonderful

winged jungle
#

okay!😆

torn jolt
#

which class r u in?

winged jungle
#

i do not understand i am sorry

torn jolt
#

which class?

winged jungle
#

i am in the ninth grade
i am in algebra one math class

torn jolt
#

ok

#

idu the american system

#

its complicated

winged jungle
#

that is okay i am learning as well

torn jolt
#

lol

winged jungle
#

i moved to us 8 months ago 😆

torn jolt
#

i see

#

just put a msg when u have a doubt

winged jungle
#

how to graph inequality?

#

i am confused on how to take from equation to proper graph

torn jolt
#

so if its linear

#

take 2 points

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tribal heron
#

Hi guys I just wanted someone to double check if my steps are correct in finding the partial derivative dz/dx

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raven mauve
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raven mauve
#

Can someone help please

flint crane
#

drawing it out would be helpful

raven mauve
#

Here

flint crane
#

yes

#

but its asking for bearing

#

so it would be clockwise direction

raven mauve
flint crane
#

so 360-that angle

#

cuz bearing always starts at 0 degrees and ends at 360 degrees

raven mauve
#

307.57 approx

flint crane
#

yeah

raven mauve
#

How about this one

#

Can u give me 3 min to solve

#

See if I’m right

flint crane
#

ok

raven mauve
#

I done a

#

For b is it just Pythagoras?

#

So b is 1.7

#

I don’t know how to do c tho

#

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cobalt spruce
#

When it comes to sinusodial functions how does a cercle affect the horizontal translation (H)

cobalt spruce
#

If the equation at a is 16sin(10(x)) + 19

#

At b why isn’t it (x-90)

#

It’s (x-27)

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hardy magnet
#

i am a little confused but if am correct is it 7/12, can someone inform me?

robust slate
#

,w 210/360

glossy valveBOT
hardy magnet
#

oh

#

its my calculator giving me a different input than others really weird

#

thanks

#

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fluid prawn
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fluid prawn
#

How do I do this

lofty vine
#

since they dont ask for a rigorous method, you can reduce the numerator and denominator to the highest power term

lime ether
#

yea sqrt (9x^2+… is going to about 3x

fluid prawn
lime ether
#

then just compare coefficients

lofty vine
fluid prawn
#

Ok so I have 4x/sqrt9x^2

lofty vine
#

yep

fluid prawn
#

And if I plug in infinite it’s infinite/infinite

lofty vine
#

the x's cancel

#

sqrt(9x^2) = 3x

#

so the limit is 4x/(3x) = 4/3

fluid prawn
#

Oh

#

How about lim as x->0 (e^x-1-x)/x^2

#

Do I deriv both top and bottom

lime ether
#

lhopital

lofty vine
#

L'hopital or power series

#

just by inspection i can see it is 1/2

fluid prawn
#

Answer is 1/2

fluid prawn
lofty vine
#

$e^x=1+x+\frac{x^2}{2!}+...$

glossy valveBOT
#

Obotron

lofty vine
#

replace e^x with it's taylor series and evaluate

fluid prawn
#

Idk that

lofty vine
#

but you know lhopital's rule?

fluid prawn
#

Yes I got 1/2

lofty vine
#

that's so weird. L'hopital's rule should definitely be taught after Taylor series

#

but ok

fluid prawn
#

Bruh these r so confusing

#

@lofty vine How u do this

#

Is it also l hospital

lofty vine
#

l'hopital is the way

static forge
#

no need for l'hopital, just divide and multiply by 2 to get the square root inside

fluid prawn
#

It looks like it goes on forever

static forge
#

no like without using l'hopital

#

just divide and multiply by 2

#

youll get 2ln(sqrt(x))/sqrt(x)

fluid prawn
static forge
#

ln(x)/sqrt(x) is just 2 * 1/2 * ln(x)/sqrt(x)

lofty vine
#

i know its something that we take for granted

#

but it's kinda hard to prove

static forge
fluid prawn
#

I still don’t get it

lofty vine
#

its true, but i cant just assume it and give the answer

fluid prawn
static forge
#

well you cant assume l'hopital either

lofty vine
static forge
static forge
lofty vine
#

l'hopital is a formula thats explicitly given, most calc courses dont explicitly state the relative growth rates of functions

#

they might tell you that e^x grows faster than x etc but that's not an explicit formula

static forge
#

l'hopital is given in high school?

lofty vine
#

whether it's high school or college is irrelevant. if u are studying limits you will probably learn l'hopitals rule

static forge
#

youll probably learn ln(x)/x goes to 0 as well when x goes to infinity then

lofty vine
#

true, but if it's a quesiton asked to u in an exam you wont just write 0 and say that 'x grows faster than lnx'

static forge
#

if its taught no need to elaborate, you just have to point out that you have a limit that's written in the form ln(X)/X with X -> +infinity

lofty vine
#

so that means if my teacher does a question in class: $lim_{x \to \infty}\frac{x^2}{x^2+x+1} = 1$ then i get the same question in an exam i can say that my teacher taught me this limit = 1 so i dont need to show it

glossy valveBOT
#

Obotron

static forge
#

something as specific as that will not be taught in class by your teacher and will not be in the books as a "proposition" or "corollary" or whatever

#

ln(X)/X is more general and can be applied to many cases

#

same as e^X/X

#

ln(X + 1)/X ln(X)/X-1

#

etc...

lofty vine
#

that's fair enough, this example was very specific. But lnx/x at infinity is not as much of a standard limit as say sinx/x at 0. And since it can be so readily proven, why not just do it., instead of risking losing marks for not proving it

static forge
#

ok this just depends on what type of exam it is in the us, either multiple choice, or free answers, in both cases im still wondering if l'hopital is taught and the standard limits of ln are not?

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@fluid prawn Has your question been resolved?

lofty vine
# static forge ok this just depends on what type of exam it is in the us, either multiple choic...

most calc students have an understanding of relative growth rates that allows them to calculate standard limits like lnx/x, x/e^x etc. However, this does not mean they can assume the values of said limits in exam just because they are intuitive/well-known. The main 'standard' limits that can be taken as given are trig limits whose proofs require methods outside the course (sinx/x requires the squeeze theorem/geometry) etc. In those cases, the limits are explicitly given in questions (at least that's true in the UK)

#

or for example the limit defintion of e

static forge
#

that confuses me because ln(X)/X also uses the same principle (squeeze theorem)

#

or the basic definition of the limit iirc

lofty vine
#

u cant prove sinx/x using L'hopitals rule or taylor series without circular reasoning

#

u cant prove the limit definition of e for the same reasons

static forge
#

okay thanks for the insight

#

but where has the original poster of the question gone @fluid prawn

lofty vine
#

we stole their channel lol

static forge
#

oops

lofty vine
#

sorry @fluid prawn

static forge
#

yeah sorry

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swift star
#

Find the standard deviation and mean for a normally distributed x, if 1.1% of the data are less than 7.84 and 50.8% of the data are less than 17.08

swift star
#

<@&286206848099549185>

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@swift star Has your question been resolved?

swift star
#

<@&286206848099549185>

void echo
#

i have done that question but i dont remember rn, i will have to check the book

#

do you knnow about normal ditribution curve? @swift star

swift star
#

yes

#

i just need to know what the process is

void echo
#

z=x-(mean)/SD

#

it says 1.1% of the data are less than 7.84

#

so the area from 0 to 1.1

#

is z

void echo
#

similarly from 0 to 50.8% area is equal to z

void echo
#

@swift star do you understand it?

swift star
#

yea

#

but i need the mean and SD

#

i found them by trail and error but dont know any method that is more mathematical

#

the equation im stuck at is 17.08-x/SD=0.02

#

and the other one being 7.84-x/SD=-2.29

#

i got z by cross referencing a zscore table

void echo
#

oh

#

since you have the equations

#

2 equations 2 variables

#

solve them

swift star
#

i havent gotten to that in school yet, so im clueless

void echo
swift star
void echo
#

ok so

#

you find the value of one variable in terms of other from any equation

#

now you put the value of that variable in other equation ( which will have only one variable)

#

in this case

#

multiply both side by sd

#

you will have have $17.08-x =0.02SD$
and $7.84-x=2.29SD$

glossy valveBOT
#

Kyanite

void echo
#

find the value of x from any of the equation that is only x in LHS or RHS and other terms on the other side

#

and put the value of x in next equation

swift star
#

okay sure

#

ill go try tha

#

thanks

#

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past obsidian
#

Im trying to understand the working out for the integration of this -could someone show theirs

hybrid zephyr
#

Prolly use t=lnx

#

And do byparts?

past obsidian
#

do you m,ind showing

#

pls

hybrid zephyr
#

I dont have paper with me rn

#

Ill try

past obsidian
#

ah its ok sorry

#

oh thnakyouj

granite torrent
past obsidian
#

kind of

#

im practisisng it

#

im trying to get better but dont really get it

hybrid zephyr
#

Do by parts for this and ull get it

past obsidian
#

sorry i dont get it

hybrid zephyr
#

Can't help then

past obsidian
#

i am getting -lnxcosx + (integrate)cosx/x

hybrid zephyr
#

What did u do dude

#

By oarts the e^tsint one

#

Ull get

past obsidian
#

sinx differnitates to cosx

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wooden orchid
#

can anybody see the steps they did here to get to the second matrice?

ivory cairn
#

-5/2 row2 + row3 -> replace row3

wooden orchid
#

ahh i thought that the h would also go into a fraction then

#

but you ignore that oke

#

thanksss

#

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calm jewel
#

if A / 5 has the rest 2 and b/5 has the rest 4 what is a + b /5 rest

calm jewel
#

rest = remainder

torn jolt
#

because even u can do it simple math

#

if

#

A/5 = 2

calm jewel
#

no remainder

#

like a/5 = x + 2

torn jolt
#

Where di x come from 😭

calm jewel
#

like 15 / 5 = 3

#

right

torn jolt
#

ye

calm jewel
#

17 / 5 = 3

#

but it doesnt even out

#

the remainder is 2

torn jolt
#

oh u mean that

#

annh

viral jasper
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# torn jolt 6

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

torn jolt
#

but i think i ddi ti wrong aswell

#

cuz i thought a/5 = 2

viral jasper
#

Have the student work through the problem themselves and guide them along the way.

torn jolt
#

kk

#

ty

#

i hate construction help i beg lmaoo

calm jewel
#

but does anyone know how to solve it

#

?

torn jolt
#

what chapter

calm jewel
#

what

#

i dont have the same book as you

#

problem solving

#

so very general

torn jolt
calm jewel
#

i dont really know

#

becaus i havent gotten forward from just understanding the question

torn jolt
#

A/5 = x + 2
B/5 = x + 4
A + B/5 = ??

calm jewel
#

B/5 = another numerical like y + 4

torn jolt
#

Ye ye

iron cairn
#

the number a could also be written like 5 * m + 2 and b could be written as 5 * n + 4

calm jewel
#

yes thank you

iron cairn
#

if you add them it would be 5m + 2 + 5n +4

calm jewel
#

yes

iron cairn
#

which would be the same as 5(m + n + 1) + 1

calm jewel
#

yes

iron cairn
#

if you would divide that with 5 what would the remainder be...?

calm jewel
#

m+n + 1 + 1

#

m+n + 2

#

nvm

#

m + n +1 + 0.2

#

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slender pond
#

How do I answer this?

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shrewd hamlet
#

What have u tried

slender pond
#

I tried the log rules

#

I got log 36 (abc) = 1

#

To get 36 = abc

#

But I idk what to do next

#

@shrewd hamlet

shrewd hamlet
#

@slender pond why not?

#

just find a,b,c such that a<b<c and abc = 36

#

and that u get positive probabilities

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flat prawn
#

I think its time for me to learn proportionality, anyone know how to do this?

graceful loom
#

Is this a part of a homework?

#

Or an assignment?

#

It literally wrote "Assignment"

lime ether
#

nah it’s just an assignment looks like an ap classroom progress check

graceful loom
#

On the website link

#

Oh

lime ether
#

is this for calc

#

ap exam ended?

graceful loom
earnest anvil
#

guys can you help me understand equations😭

graceful loom
#

No

flat prawn
#

Yeah just

graceful loom
#

Open a new channel

#

Not here

#

Thx

flat prawn
#

Ok so

#

The rate of change of the salt in the tank is

#

6-0.02A

#

With A being the amount currently in it

earnest anvil
flat prawn
#

So let me get an initial condition

#

Oh it says

#

At 10 mins its 50

#

So i should do

#

50 + integral between 10-12 right

#

Oh but i need to find a tangent line

#

So y = mx + b

#

m i can get by plugging in

#

Which is 5

#

But what is the y intercept

#

Poooh

#

What if i dont need a y intercept

#

What if I just started from 10

#

5(x-10)+50

#

Thats gotta be the answer to the first questiob

#

Ok i need help again

#

.close

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zealous wasp
#

Does anyone have an intuitive way of understanding ODE particular solutions?

zealous wasp
#

Im a bit confused when he says the growth factor or growth time is t-s

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When s in an interval and t is the current time

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dense cove
#

Help

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dense cove
#

I sorry het the notes but need help making sense of taking away

#

Like the -400

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Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

quaint prawn
#

are you allowed help on this quiz? Also you might want to blur your profs name and class name next time

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for privacy

dense cove
#

Sorry

quaint prawn
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no need to apologize

dense cove
#

It’s after the quize and allowed help with fixing the questions

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I just don’t get the -400 how it gets solved

ember shadow
#

not sure what you're asking, but 400 gets subtracted because that is the monthly payment

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dense cove
#

I got it sorted out I just didn’t understand how to solve it

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torn jolt
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torn jolt
#

where do i start?

ember shadow
#

first plug in x = 2, y = -6

devout valley
#

What do these mean?
[edit: the first one has been done for you, when x = 2, then y = -6, what about the second one?]

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proper summit
#

Hi, I'm having trouble understanding some examples of a topological manifold, particularly with coordinate charts. The first example are graphs of continuous functions. If $U \subset \mathbb{R}$ is an open subset and $f: U \to \mathbb{R}^k$ is a contiuous function, then the graph of $f$ is defined as the subset of $\mathbb{R}^k \times \mathbb{R}^k$: $$\Gamma(f) := {(x,y) \in \mathbb{R}^n \times \mathbb{R}^k : x \in U \quad \text{and} \quad y = f(x)}$$ on the subspace topology

glossy valveBOT
#

Zorich

#

Zorich

proper summit
#

what does this mean?

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And how is it a homeomorphism?

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@proper summit Has your question been resolved?

neat bay
proper summit
neat bay
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Why did you write R^n and R^k

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Shouldn’t it all be R^k

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I’m confused

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Sorry

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@proper summit

proper summit
glossy valveBOT
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Zorich

proper summit
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But I'm not sure, which is why I am asking

neat bay
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The function f is from R -> R^k basically

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So its graph should be a subset of R x R^k

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Unless you’ve written U subset R wrong

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Did you mean U subset R^n

proper summit
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no, $U$ is a subset of $\mathbb{R}$

glossy valveBOT
#

Zorich

proper summit
#

however, it has a function that maps it to $\mathbb{R}^k$

glossy valveBOT
#

Zorich

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@proper summit Has your question been resolved?

neat bay
#

Three different things lol

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@proper summit Has your question been resolved?

timber cape
#

The graph of a continuous function is a common example used to illustrate topological manifolds. Essentially, it's a way of visualizing how the function maps points from one space to another. In this case, given an open subset ( U ) of ( \mathbb{R} ) and a continuous function ( f: U \to \mathbb{R}^k ), the graph of ( f ) is defined as the set of points ( (x, y) ) in ( \mathbb{R}^n \times \mathbb{R}^k ), where ( x ) comes from ( U ) and ( y ) is the output of ( f ) for that input ( x ). This definition allows us to study the properties of the function and its mapping visually. What specific aspect or detail are you having trouble with regarding this example?

glossy valveBOT
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tawdry roost
#

Hi, I would like assistance in using desmos graphing to have a similar graph as to the one above? If any values or numbers are needed I can attempt to provide them

tawdry roost
#

I'm sorry if the image is blurry, I can't get another screenshot of it

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tawdry roost
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<@&286206848099549185>

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onyx inlet
#

Parallel vectors yeah

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onyx inlet
#

How do I know how to establish the relationship when they are parallel

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An example, it says 6i+8j is parallel to vector OP

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I know you can do the magnitude of one is directly proportional to the magnitude of another

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But when I use the magnitude of 6i+8j = k * magnitude of OP ( 80 )

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10 = k * 80

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And k = 1/8

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It says I'm wrong

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And it's 80 = 10 * k

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And I = 8

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K*

void echo
#

is there any question?

unborn cliff
void echo
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your concept it not wrong but it depends on the context

onyx inlet
void echo
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also it is not the magnitude that is proportional

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it is the vector

onyx inlet
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I was told both

void echo
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since it also includes direction

onyx inlet
#

Huh

void echo
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vector a =k times vector b

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you dont know the vector OP

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but you know that vector 6i+8j is parallel to op

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so k times vector (6i+8j) = OP vector

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and from this you will equate their mangnitude

onyx inlet
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Oh

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So it's always the unknown one is equated to the constant * the known one

void echo
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yes because in this question u need that vecrot in terms of i and j, since you will multiply the factor k to them

onyx inlet
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Oh I get it now

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Thank you

void echo
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like u got 1/8

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that is correct but

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it is 8i-6j = 1/8(xi+yj)

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xi+yj is vector OP

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since youdont know the value , i used the variable x and y,
when you will multiply by 8 on the know vector

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the factor will become 8

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not 1/8

onyx inlet
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Ohh

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So either way

void echo
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you can solve howver you want

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but you will have to answer in the way question asks

onyx inlet
#

So if I ever get something around that fraction form all I need to do is express it in the x y form to see if I got the constant correct

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past obsidian
#

Hello, on this quesrtion i was able to expand the first fraction with one on top, but im dont know how to get to the second number - thanks

willow sedge
#

timtom

past obsidian
#

yes?

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anyone?

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.close

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hard mango
#

hi can someone help me start the equation for the left hand rectangle

hard mango
#

here’s an example because my teacher makes it so confusing:

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vivid berry
#

am i doimg this right

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vivid berry
void echo
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hi bum chicken

vivid berry
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hi

void echo
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for intersection

vivid berry
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yes

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wait

void echo
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just equate both the function

vivid berry
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oh

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ok and then i

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move to one side

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and then find the roots?

void echo
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yes

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because

vivid berry
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so there is multiple points of intersection?

thick hedge
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yes

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maybe

void echo
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assume x is a number say 2 or 4 or anything but we are putting x, if for some x in functon f is equal to the same x in g function then they will be equal

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so we are equation the two functions

void echo
vivid berry
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i did this

void echo
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now to check, you can put these values in both the functions

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if they give equal values then they intersect

vivid berry
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all of them?

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to find the y of each one, do i plug them into one of the equations?

void echo
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yea

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you need coordinates

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you already have x

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find y by putting them in any one function

vivid berry
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liek dis

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wait

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dis looks wrong

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brb

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ok nvm i get the jist moving onto the next question