#help-28
1 messages · Page 178 of 1
you do
v(0)=2m/s
why is v(0) = 2?
that's what's given
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A point on the edge of a car tire is marked with paint, As the car moves slowly, the marked point on the tire varies in distance from the surface of the road. The height In inches of the point is given by the expression h = -8 cos t+8, where t is the time in seconds. What is the maximum and minimum height above the ground that the point on the tire reaches?
@tall swan Has your question been resolved?
minimum will be 0 and max will be 8
what's the problem u didn't specify it
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Just wanted to check if it is right so I can hit full marks, if not I would like advice on how to fix it
@mortal cargo Has your question been resolved?
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Your first slope is wrong, the rest looks right
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I need help with getting the sum of this cuz I’ve been working on it for awhile but I don’t know how to do it I’ve got the problems down just not getting the sum of this and the assignment is due today this is the last question I need help with
do you have the actual values of a,b,c,d,e?
you know a = -3, and you know b in terms of a so you can substitute to find the value of b
(repeat for the other variables)
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i need some help with precal
factor the denominator
Hii
This is not defined
doesnt exist
that doesn't mean it's not solvable algebraically.......
That's why i asked, i'm kind of surprised at undefined limits like this in precalc
yk what that makes sense i graphed it out it was infinite
not me honors cuz i had to go and excel😭
thank you
my first idea would be to factor out x^2 in the denominator
most likely you see me again in like 3 min Lmao
oh do you still want to solve algebraically?
i was trying to but if it is not defined there is no point
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Hi can someone help me with confidence intervals?
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how do i answer b?
Use periodic property of tangent
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@fast peak the previously channel is claimed but can u help me further here.
how is max{0,5} = 0 and -min{0,5} = 5
its not
I know, my question was asked in #help-25 but it's claimed
u can help me with the question?
Can you explain?
hi is there a mistake here? why is the left side same as the right side. if u take x_j = 5 for example with the right constraint it is still valid
what do you mean by rihgt constraint?
looks fine to me
the constraint x_j^- >= 0
and
x_j^+ >= 0
why not
idea is to represent real number as difference into 2 positive real numbners.
uhh ye I understand that part
This kind of stuff really just means it's a positive reall number.
if it was different it would be allowed ot be negative which is not wanted.
this idk, it seems superfloues to me for everything that comes later
I suppose it is onmly in context.
can I ask 1 more thing, a convex set and convex function are these both different definition like is there any relation between them? I feel like they are totally different things
Sorry; I can't help with this. I am not really sure what is being done here. I would need a lot more context to tell why this is done here.
The idea of splitting reals in 2 parts makes easily sense though.
This I can help with.
Essentially a convex function is just a function such that the set of the form { (x,y) | y > f(x) } ( the points above the function) is convex.
ye I tried to think it as :
if x_j is positive
max{0,x_j} is just x_j and the - min{0,x_j} = -0 which means x_j = x_j + 0 = x_j
if x_j = 0
max{0,x_j} = 0, - min{0,x_j} = 0 x_j = 0 + 0 = 0
if x_j = negative
max{0,x_j} = 0, - min{0,x_j} = x_j so u get x_j = 0 - x_j = -x_j which is also correct
I know what coonvex is graphically for set and for function
but is there any relation between these definitions?
That is what I tried to explain ,aymbe reread it.
I am saying a function is convex exactly if the set { (x,y) | y > f(x) } is convex as a set.
uhh this is a bit hard to understand tbh
so this is a convex function for example
ohh
wait
i get it
so because the whole red part which is the set { (x,y) | y > f(x) } is convex, the function is convex?
yes
wait below the line should that be red marked too?
the connecting line yes.
My f is convex because yellow set is convex
Now it wouldn't be
oh i get it noww so the convex function definition comes from the convex set definition?
yeah, that is probably the origin for the termonology.
do u also know this
this means that the domain is not divided in sub intervals right?
no
it's 1 connecting interval?
well depends
why does it dpend?
I mean it depends on your definition.
I think you could say a function is convex if it satisfies the convity definition
but it simply not defined in some region
or maybe you just exclude any functions with non-convex domain right away
In mathematics, a real-valued function is called convex if the line segment between any two distinct points on the graph of the function lies above the graph between the two points. Equivalently, a function is convex if its epigraph (the set of points on or above the graph of the function) is a convex set.
In simple terms, a convex function gra...
Wikipedia does exclude it
I don't understand this
can u help me translate it
ye I do understand this
this basically says
they are jsut saying that this convexity definition needs f defined for all intermeidate points
the line has to be above the f(x)
but the question was why is the convex function also having a convex domain right?
oh wait that's what u are saying
so the convexity defintion needs f defined for 1 connecting interval of domain right?
like a convex domain can only be smth like 0 <x < 5 or smth
it can't be x>= 3 and x < = -3 or smth right?
not with WIkipedia's (and probably the most common) definition
theoretically we could jsut say also we ignore points were we cannot check the condition.
For example for contuity it is common to do just that
0=max(0,-5) and 5=-min(0,-5)
but if u take x_j = 5 it is still valid right, x_j^- and x_j^+ are both positive
it is
nobody said it was not
this is if u take x_j = -5
uhh but I am pretty sure the left side says that x_j should be negative
well x_j^+ and x_j^- will obviously depend on x_j
thatÄs a precondition
it's like saying, when milk is out, there will be milk at the supermarket and go buy it there.
This does not mean that if milk is not out
then there will also be no milk at the supermarket
I know that, but basically x_j >=/ 0 should be eequal to the whole right part right
There is always milk at the supermarket (hopefully)
It's just we don't care if we don't need it.
also the x>= 3 and x< = 3 how can that be a convex doomain btw
I don't know the context but I am pretty sure the idea here is that the x_js somehow need oto be positive. If they already are, great, we are happy. If they are not, then we do this decomposition.
if xj>=0 already, then we dont need to care about it
we only need to worry if x_j is not >=0
and only in that case we need to do this replacement step
also can I ask about this too
so the combination of evert vertice(endpoint) can give u every point inside of the endpoints
I can imagine that for a square
like
later the simplex algorithm will assume that all variables are >=0. so thats why we do these things
gotcha, can u help me with this new question too btw
you can imagine it as a sort of weighted average
ye
of the vertices
so for example u got the vertix A and D
then u get the trinagle
as ur
poissible points
right
but I can't realy imagine it if u got 5 end points
whats the difference between 3 or 5 points
i have to go. cya
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this may be a stupid question but
You can not derivate a function to herself
y not btw
yes
herself?
dx/dx = 1
ru assuming it's gender
Ahhahah i guess
How is it possible to derivate a function to itself
are you saying it's impossible to find
d/dx (x)
?
that is a good point ahahaha
but in this case x(t) is a function of t so it only has t variables
which is why im a bit confused
I am thinking of its partials.
x = stuff with t
applying the derivative operator
d/dx (x) = d/dx (stuff with t)
d/dx (x) itself on the left side will be 1
i mean this is kind of abusive notation anyways
but yeah generally in this case u would say d/dx is 1
Actually using the definition of derivative i can't get that result
In the case d/dx x the x is a function y = x
so d/dx y(x)
What is the question?
it's not a question it's just something i came up in my head which i am confused about
lol
The problem should be if the vaqriable of a function can be the function itself
definitely can not
You can derive a function only by the variable on which it depends the function ù
is the question related to taking the derivative, for example d/dx, to a function of t?
question
that doesn't stop you from apply a certain derivative operator
you're implying that given something as simple as
y = x
that you can't determine dy/dx or dx/dy
wait given y(x) dy/dx is well defined but not the second one
well how are you getting dy/dx
and what's the result of that?
y'(x)
what's the result of that for
y= x
that is 1 but ONLY because y depends on x in a linear way
and how did you get 1
regardless the end result is the same
nope you CAN'T derive a function to itself
applying the derivative operator
d/dx (y) = d/dx (x)
applying whatever valid rules you want
d/dx (x) is 1
the left side is irrelevant to that calculation
yes but because y=x the fucking variable is x
so?
who's writing y(y)
d/dx x
if x doesn't depends on x the derivative is 0
but if y= x then d/dx y(x) = 1
derivative is 1 because d/dx (x) is 1
whether x can be expressed on terms of another variable is irrelevant
I mean it's pretty important when applying chain rule and doing stuff like implicit differentiation
when you use chain rule or whatever the function depends on x and you are deriving on x
wait a minute
given f(x,y,z) how is it defined d/df f ?
as the single variable simply
u mean x,y,z are functions of t?
note that the variable to which you derive indicates the direction in which you are defining the change ratio of a function
yes
x, y, z are generally the variable of the function
yes
It's strange to imply that you can't take the derivative with respect to y, just because y can be expressed in terms of x.
@cold sail Has your question been resolved?
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I used conditional exchange on step 1 then demorgans on step 4 so far but i dont know where to go from there
@haughty moat Has your question been resolved?
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How do I do question 2
integration is area under the curve
Yh
But like I’m not really sure about the x lines
And also there is no y axis which I think is needed for the last 2 parts
They give you the values of each area
yes
Do I need to do anything with that info it gave about the lines of x
@hybrid zephyr
yes?
This
the question itself is 'you will not be able to find one of these'
which do u have difficulty in finding
?
iii and vi
the 3rd one
u can get the 3 out of integral
now it is 3integral
6 also same
get -1 out
What about all that about the function be hounded
and how were u able o do v?
Bounded
I haven’t done all of it yet just tryna figure out if I can or not
??
Yh if u read it
It talks about x= 2(n-1) and x =2n
yes
integral 4to6 f(x) is?
dude no
@rotund shore
Oh I’m tripping
I don’t think that’s a question
It’s just defining the domain of the function
what?
The x equations are just saying the Rn function is only valid over the values shown in the graph
None of them have 4 to 6
what is R3?
yes
24
which is from what value of x to what?
4 to 6
thats what u need right?
Well Yh but it says 3(fx)
um
u dont know what f(-x) is going to be
multiply
....
no
f(-x) is not -f(x) everytime
for example cosx
or x^2
here f(-x) = f(x)
and for x^2 - x it is not both
so we cant say
Oh
yep
yes
np
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May I know actually how to get the S_n?
I know it should be geometric series, but I can’t see how it becomes that formula
ok so assume u have general gp
which is a, ar, ar^2, ...
let Sn = a + ar + ar^2 + ... + ar^n-1
rSn = ar + ar^2 + .... + ar^n
subtract both
Sn(r-1) = ar^n - a (as other terms will get canceled)
so Sn = a(r^n - 1)/r-1
@slim folio
@slim folio Has your question been resolved?
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not sure how to get started
@strong merlin Has your question been resolved?
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Can someone explain to me how this works?
I am trying to domy assingments but I have no idea how it works, it just gets me confuse
@naive sandal Has your question been resolved?
just focus and understanding the notation and being able t construct truth tables. I would recommend you refer to Discrete Maths by Susanna E.P.. Solutions can be found on quizlet.com. Only mistake in the logic section of the textbook is "and" has higher precedence than "or"
@naive sandal Has your question been resolved?
I kinda get it now but there is a huge problem here
I must be tripping but look at this question
HOW AM I SUPPOSE TO GET THE ANSWER
It doesn't even follow the logic
or am I wrong?
I had to resequence the arrangment of the question
Here is the table can someone pls help, I am stress out rn
Wait unlesss it is not valid....
This is the original statement
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i have a question shouldnt it be 15 + 2?
because the integral of v(t) from 3 to 0 is S(3) - S(0) and S(0) is -2
so 15 + 2
s(0) + (s(3) - s(0)) = s(3)
s(0) is -2
s(3) - s(0) is your integral, 15
@peak dome
so -2 + 15 should be the answer
@peak dome Has your question been resolved?
i dont understand
isnt s(0) = -2
so - (-2) = 2
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How do I do b
Do you know differentiation?
And how to calculate whether the function is increasing or decreasing from that?
Yes
I think I just don’t understand the question
What they are asking is h(X)
Which is distance between fx and gx
So fx-gx
Is h(X)
I know you're not asking about it but how did you find B?
Now differentiaten this and put X=0.5
They are asking vertical distance meaning, distance at same x
Graphing calc
Cause it’s calc active question
How’s it the distance between that?
Like see the graph
Vertical distance
Is f(X)-g(X)
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<@&286206848099549185>
@quartz scroll Has your question been resolved?
lol, i was tryna figure out cause i love the organic chem vids
This statistics video tutorial provides a basic introduction into the mean absolute deviation.
Introduction to Statistics: https://www.youtube.com/watch?v=XZo4xyJXCak
Arithmetic, Geometric, & Harmonic Mean:
https://www.youtube.com/watch?v=6G6i8vSa8Zs
Cumulative Relative Frequency Table:
https://www.y...
this could help
for examples
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hi can anyone help me with some algebra?
i need some help with the second grade systems
u should just post it
oh ok ty
it seems easy at the beginning
but after i try doing it i get stuck
heres my process
it should result
how does 3 become -3
changing him place
3 is already on the rhs side n positive
you r only transposing positive 2y
which when brought to rhs becomes negative 2y
im not getting it sorry
hmm fine ill go slow
ty
for the 3
i changed it place so after i get all the numbers without an y i can easly calculate the solution and bring it to the other side
here 3 is already on the right side
ye
hm now we r trying to get the value of x
so that
we can substitute it in the first eq
like
so wt i mean by saying that we r bringing 2y on the other side
is
subtracting 2y on both sides
x+2y-2y = 3-2y
we do this
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$V=l_{1}l_{2}l_{3}$ so
$V+\Delta{V}=V(1+\lambda\Delta{T})=l_{1}(1+\lambda\Delta{T})l_{2}(1+\lambda\Delta{T})l_{3}(1+\lambda\Delta{T})$
BobTheBuilder
I don't understand why this can be written this way
for example if I had V=324 and that my $(1+\lambda\Delta{T})=(1+2)$
then it would be $V*(1+2)=(324)(1+2)=3(1+2)2(1+2)4(1+2)\neq $72
BobTheBuilder
y would u multiply (1+2) thrice when u have it only once?
wdym
(324)(1+2) is not equal to 3(1+2)21+2)4(1+2)
i know
but
$V+\Delta{V}=V(1+\lambda\Delta{T})=l{1}*(1+\lambda\Delta{T})l{2}(1+\lambda\Delta{T})l{3}(1+\lambda\Delta{T})$
BobTheBuilder
i think the flaw here
the coeffecient of linear expansion isnt same as cubic expansion
like the lambda in v(1+lambda delta t ) is not same as in the l on rhs
if u get what im saying?
mmm no
$V+\Delta{V}=V(1+\gamma\Delta{T})=l{1}(1+\lambda\Delta{T})l{2}(1+\lambda\Delta{T})l{3}*(1+\lambda\Delta{T})$
Shi Tensai
it cant be lambda on both sides unless lambda is 0
BobTheBuilder
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@clever turret Has your question been resolved?
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need help
need help
I need help solving a word problem that required higher knowledge of sigma notation
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I feel stupid for not knowing how to do this
Calculus 1 btw
I thought I could just find the integral of the equation and plug in t but that did not work
uhh maybe I just used wolfram alpha and I need to actually know how to do it
nvm its just this right?
cus chain rule
but that doesnt exactly help with the answer
that's the derivative
I honestly forget how to do this
you forgot how to integrate this?
yes
try a u-sub
even if I set this up right (which I probably didnt) I dont know how to continue
then you need to review how u-subs are done
can you help me?
i am helping you
ok so can you kind of explain where to continue?
if you don't know how to continue, then you need to review your material on u-substitutions
I mean I could do that, but im already here with you, who knows how to do u substitution, and since I have done u substitution in the past I would probably be able to get it done with some of your guidance
so you could go back and do the review yourself, but you'd rather have me do it for you
thats correct
this is also right.
well yea I was just asking for guidance with the u substitution because I clearly showed where I was stuck at
ok
so I got (20/0.02)e^0.02(5), which gives 1105 which is not an answer choice
the equation itself was (20/0.02)e^0.02(t), which seems right to me but it appears as though it's wrong. Where did I go wrong?
yea this is defniitely the integral but I genuinely dont know why when I plug in 5 for t, it just doesnt give a reasonable answer
@placid kayak Has your question been resolved?
<@&286206848099549185>
make it similar to this
I got this (20/0.02)e^0.02(t)
and yeah it's the integral, but when I plug in 5 for t I get some fraud answer thats like 1105
wym
u sub
so the way that I got the integral already is wrong?
no but if you want it easier do u-sub
you're computing $\int_0^5 20e^{0.02t} \dd t$
yes
Steakanator
you've antidifferentiated, but you don't just plug in 5
OHHH
right I gotta subtract it from 0
so I even though I already have the antiderivative which is (20/0.02)e^0.02(t)
I have to take it for t=5, then subtract it by t=0
so then the answer would be 105
right?
]
if that's what your computation gives you
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can someone teach me what this means?
Have you done any kind of vector addition before?
It's an opposing force that balances the forces acting on an object
so if I'm pushing on something with 5N, the equilibrant would be an opposing force of 5N which would nullify my action
I assume this is a statics problem?
Wow lol
well let the x axis be east west and y axis be north south
You can write the first vector as (5, 0) right?
Its 5 + 12 ?
nooo
wait
yes
to get the magnitude of the vector
the vector itself is (5, 12)
you get the magnitude with the pythagorean theorem
now what vector would balance this one?
a vector with which, when this one is added together, gives (0, 0)
the equilibriant?
well it would have magnitude 13 acting in the opposite direction
to be more precise, it would be (-5, -12)
if you applied pythagorean to it you'd get 13
this is because the magnitude of a vector doesn't tell us about it's direction, unless we accept some convention
so the vector notation is more precise
ohh ok
Now do part b on your own
okay okay
holy crap
why did i think 9^2 is 36 ?????? im braindead..
That was just me figuring out how to add a vector thats tail to tail
Ye so here you have (-9, 0) + (0, -12) = (-9, -12)
and so the equilibrant is (9, 12)
ooh ok
so the eqb is the positive of the resultant?
do yk how i can answer htis question?
It's essentially the opposite sign
so if the force is (a, b)
the equilibrant is (-a, -b)
umm for question 6 you are not given any information about the angles under which the forces act
this is what my teavher did
technically, all of those forces could produce equilibrium when put under the right angles....
oh
nvm
I dont understand what they mean by could produce equilibrium
How do I know if they can
if they can be the sides of a triangle
essentially
yeah c couldn't, my bad
wait
actually
hold on
yeah
because the sum of 2 sides has to be greater than the third
so c doesn't make a triangle
and therefore there are no angles under which they'll make equilibrium
can i pick any two sides or why is it specifically the third
nvm i unerstand
sorry i just made you help me with 2 homework questions 😭
have to be greater than the third
So let's have our force act on the baseline
as in
the x axis
for example
then f1 can be written as (6, 0)
assuming the second force is acting at a positive angle
we can write it to be (8 * cos(60°), 8 * sin(60°))
now just do the usual
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How would you approach this?
what do you mean
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help
do u do financial maths?
4th time today
"the nearest cent" 
do you have a finance calc?
Sorry, I don't know this, someone else might
alr
Can you solve part a?
Okay, do you know how to use the “payment” or ‘pmt’ function?
yea
just not sure if we are solving for fv or pmt
for ii
i have the answers of that will help
just not sure how to get there
Is it not the same as b.i ?
They don’t use the geometric mean for their interest rates smh… though I’m not sure where these last 43 cents are coming from… I suspect it has to do with the ‘as close to the regular payment as possible’
yea its a tough one
How did you find a.i ?
Right but that’s the same as the number they gave… is a.i different?
Yeah, but in a they give 5253.39 and a.i is asking for final pmt, so is it the same or different?
These are the answers
You liar smh it's 4174.54 not 4175.54
Do you see how to solve it?
This is wrong
,w 4,086.69+87.86
Probably some rounding diff but same thing
Oh
Lmao
You just solve for FV setting n=59
The interest payment on that balance by multiplying 2.15%
Add the 2
That too
anyway thanks for the help!
👍
@open zinc, ty for ur efforts
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How many integer values of $x$ satisfies [
\log_5\frac{x^2-7}{216}<\log_6\frac{x^2-7}{125}
]
Mildew
expanding this yields me pretty ugly inequation
i do notice 216 = 6^3, 125 = 5^3 though
but not sure what to do with those information
Hey
First make it, $\log_5 (x^2-7) -\log_6 (x^2-7) < 3(\log_5 6-\log_6 5)$
right, thats also what i got
Monarch of Eternal Night
Now use the log properties
Use change of base rule
This one to convert it to $\frac{log (x^2-7)}{log 5}-\frac{logx^2-7}{log6}<3(\frac{log6}{log5}-\frac{log5}{log6})$
Monarch of Eternal Night
@minor bough
Sure
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To prove the group action is faithful I need to find the associated group homomorphism
normally, if this was finite I'd say it's something like f:F*-> S_n where n is the order of F
but F being a field need not be finite
so where is the associated group homomorphism mapping into?
I think we'd still define it by f_g(s)= g*s
I'm just confused on that distinction
mathematicians are just making up terms now
these terms are pretty standard, last I checked
sadly, idk any group theory
so I cannot clear this doubt 
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this question is driving me crazy i did this four times and im still not getting it right its not even hard aswell its just algebraic manipulation to make x the subject
This is my closest attempt. Where did I go wrong?
the answer is $x = \frac{4p}{1-p^2}$
BOHO
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c is the question?
by definition interquartile range = Q3-Q1
lol
just plug 30
the 11 and 66 is minimum and maximum
and that is how you identify Q1,2,3 in box plot
good luck xd
so Q1 is 28?
im confuzled again
is it (21+35)/2 to find Q1
its not that was my first answer
340000
how did you get that
he's wrong
he's right
what im wondering lmao
the first column of this table represents the numbers at hundred thousands
the second column of this table represents the numbers at ten thousands
it is rounded up
why round up
idk
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no idea how to do this
consider for a, how many ways can exactly 39 of 48 unique eagles survive. What's the probability of each of those arrangements?
i know thats what its asking i just don't know how to find it
which part are you stuck on? the number of possible arrangements or the probability of each arrangement?
alternatively, use the binomial distribution on your calculator, but that's somewhat dependant on what class this is for
I can give you an example for a similar question if that would help?
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3,4 anyone?
how far did you get on your own?
Na it’s like easy but what’s the formula
well you would find the height of the cone using pythagorean then use 1/3h(pi)r^2
For 3 the formula is 1 over 3 base x height
How do we the base
If we have the radius
Ohhhhhh
also, just want to make sure you're aware: slant height and height are two different things
Pythagorean Theorem
How do I do that with js the slant height tho
So I js do 3 squre + 4 squared?
Wait so how do I get the Pythagorean therom
using this image, r^2+h^2=s^2
you have r and s
find h
^ wait js to make sure what does that mean?
which part do you not get?
Wait how will we find the h in the formula if we don’t have it
Btw my bad for the dumb questions shit js confusing
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any ideas?
@main trellis Has your question been resolved?
I don't quite understand the last part of the question because I'm greek
what does T do to the first component of E?
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@pseudo cape Has your question been resolved?
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Need to solve for x
question pls
there is no image
How to find the value of x, I don't know what to do
This channel isn't allowing me to send any more images
Can I send what I've done in dm?
try writing everything in terms of $a = 2^x$ and $b = 5^x$
lgkoo
Yeah, I did that