#help-28
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I Did solve it but not sure if did it the right way
Please don't occupy multiple help channels.
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$proof that (a1+1)(a2+1)...(ak+1)=n.a1.a2...ak$
Lena
give more context, what even is n?
n ∈ N*
but there in no n term in the LHS
that's just simply not true, e.g. a1 = 3, a2 = 7, then (a1+1)(a2+1) = 4 * 8 = 32, which is not an integer multiple of 21 = 3 * 7
it should be A(n) I presume?
!original
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
Yeah
I think that there is an equation to A(n)
idk what A(n) is, it seems that you may recognise this type of question but I don't
k
@bold hinge show us the entire question pls
Prove that if n satisfies (a1+1)(a2+1)...(ak+1)=n.a1.a2..ak and n=p1*p2..*pi then i=k
k
one min I am helpin another guy
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Hello! Is a scalar field the same as a surface? If not what is the difference.
a scalar field is a function from a surface to the real numbers (just think: the function is the same as an assignment of a number to each point, but the notion of such an assignment is captured by a function)
would the function of the field be the same as a surface?
what do you mean by function of the field
(the point is that in order to have a scalar field you already had to have a surface to begin with)
ok
so lets say we have a surface f(x,y) = x^2 +y^2. I know how to find that
the surface
but how would i then go about plotting the field
i think "f(x,y) = x^2 +y^2" is called a scalar function
On a note i think i might not have gotten here yet in my multivariable class
oh i see what’s happening, here is a bit of pedagogical stuff that you might not know yet: f itself is not the surface. the graph of f is a surface. f is just a scalar function on the plane R^2.
so like
it depends on what you mean by “plot” but usually when people say “plot f” they mean “visualize the graph of f in R^3”
ok
so you’d draw the set of all (x,y,z) in 3d space such that z = x^2+y^2
yes
note that
there are generalizations of what a graph is
that you’re now set up for
just some food for thought
not that it’s important now
but graphs are everywhere!
not exactly sure what you mean - you need to define your own scalar field, there isn’t one given to you.
if you want one example of a scalar field on your surface, you can take the function s(x,y,z)= x+y, and then restrict the domain of s to the surface.
if you meant something else just say
ah I think i falsely infered that for every f and surface there was also a scalar field
ohh okay
i mean for every f there are in fact two things associated to f: first is a scalar field on R^2, given by the point (x,y) being assigned to f(x,y). the second is a surface, the set of all (x,y,z) such that z=f(x,y)
but you don’t get a scalar field automatically on the graph of f from just f alone
you do get one on the plane R^2
but they’re just sort of different things
gotcha
so if i had a R^3 function f, then it would have a surface in R^4 and a scalar field in R^3
and to get the fields i would have to assign a set of points
it would have a different kind of object in R^4, but yes it’s a scalar field in R^3
if you have ever heard the word “manifold” this is related to those
if you want a scalar field, start with a set of points and make a function from those points to R
gotcha
this makes a lot more sense
excited to learn more in my coming lectures
thank you genuinely! You are a bank of cool maths
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Is this correct?
it seems to easy a solution to be accepted like this
I see online calculators rewrite it into polar coordinates first btut the result is the same
Your method is only checking the limit along lines that look like y = mx, it's possible in general that while all those limits are 0, some other curve has a different limit
so we should convert into polar?
Yeah thats a common way
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Although, i forget but checking all y = mx might be enough by some theorem
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first you need to split that into two
so like 4/3 - 4/(3sin^22x)
$ (4/3) \int{\pi /6}{\pi /3} dx - (4/3) \int{\pi /6}{\pi /3} \frac{1}{sin^2(2x)} dx$
Dunno why the bot doesn't work
dam
remove whitespace near dollar sign
$(4/3) \int{\pi /6}{\pi /3} dx - (4/3) \int{\pi /6}{\pi /3} \frac{1}{sin^2(2x)} dx$
فطر
the limits are messed up
the whole thing is wrong
nuh uh, thats wrong
???
$\frac{a}{b+c}\neq\frac{a}b+\frac{a}c$
tada
فطر
mmm ok ok one sec
why does it not
fraction denominator is not linear
he is right I made a tiny rearragement mishap
if it was multiply would it equal ?
no
dam
either way youre onto something
do you know whats $1-\sin^22x=?$
for real
فطر
Dear me
it would equal 1 - (1 -cos4x/2)
well, simpler than that
$\frac{4}{3} \int{\frac{\pi}{6}}{\frac{\pi}{3}} \frac{1}{1 - sin^2(2x)} dx$
Mutty
maybe like cos^2
sir this is not #latex-testing
...!
I was trying to make it look cleaner but this bot doesn't recognize integral limits wth
cos^22x
yes
dam so is this wrong
yes
ok
$\frac43\int_{\frac{\pi}6}^{\frac{\pi}3}\frac1{\cos^22x}\dd x$
فطر
now what do you see
The _ 🤦
when do i know to use 1 - cos2x or cos^2x
just see if which is more advantageous
anyway
$\int f(ax+b)\dd x= \frac1a F(ax+b) + C$
فطر
where F is the antiderivative of f
yea
well, have you learned derivative/integral of trigonometry functions?
i did yea
yeah
so its tan
do you know what to do from here now?
yes well done
!done
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Hello
merp
just want to make sure
does the equation of any lines not only work for line, right?!
i mean in example
if we had an y=x^2 as a line
then if there and unknown dot only known for its x=2
then the y point of the dot is x^2
which is 4
then the unknown dot of x=2 is (2,4)
am i right?
ping please!!
point or coordinate
r u just saying if u can plug in the value
What does the sentence mean lol
y=x, y=x^2, and other line equations do not only works for their lines, right?
lol r u saying
idk TvT
does any value of x will make the coordinate be in the line of this??
wait
instead of line u should say idk uh curve or equation cos it’s confusing when u get to higher degrees
Yes
Ok man
oh yeah
instead, TenQ very much!!!!
and its entering function
yet TenQ very much
i will be not easily satisfied with just one answer
see you again!
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Hi
@near umbra Has your question been resolved?
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is the first answer b and second answer A???
or wait it wouldn't be discontinuity woud it?
Can you define discontinuity?
Doesnt look like a good definition
Well that is the problem
If you are not really sure about what a discontinuity is, you can’t solve the problem
You should study first, try solving problems later
Not the opposite
I did study it though like I know removeable ddiscontinuity is when in a function x = a function isn't the same and in jump continuity the function ends and starts at a different point
I thought infinite discontinuity was when a function jsut had a vertical asymptote
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Hello
My questions says a triangle has side lengths of 10 units, 15 units, and 18 units. Please find its area.
would you do heron's?
do you know heron's formula
yes
so i got square root of 21.5 times 11.5 times 6.5 times 3.5
do i round that up to nearest whole number?
because it gives me square root of 5624.9375
if i round up to 5625 i got 75 as my answer
is that the area?
@torn jolt Has your question been resolved?
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what did i do wrong here
i just plugged in 4, so 1-4 which should be -3
and the floor function just gets rid of all decimals, and since there were no decimals here im not sure what i did wrong
what's int(1-x)?
how did it get -4 tho?
-3>-4
,w floor(-3.01)
what integer is less than -3.1?
-3 is an integer, so yes the floor of -3 is -3. but you are taking the limit of this, not just plugging in a number
it says here INT(1-x), you plug in 1-4=-3
you don't plug in 4
that only works if your function is continuous, the floor function isn't continuous
,w plot floor(1-x) on 1 < x< 6
by checking values. your limit is to 4 from the right, so check the function by plugging in 4.1, 4.01, 4.001
the limit tells you what the function is doing around an x-value, not necessarily at that x-value.
i know this way, but i was just trying to see if there was a way to algebraically do it
other then plugging and checking
but thank you
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i dont understand
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
Hi
Need help?
Anything to the power of minus is 1 over the number that has the power
If something has a negative exponent just flip it (from numerator to denominator or denominator to numerator) and make the exponent positive
@torn jolt Has your question been resolved?
(a)^-s = 1/(a^s)
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help me finist this pls
looks like it's basically done...?
then what is R and I()
you have $\lim_{n\to\infty}|x| = |x|$, you need that to be less than 1\
So you have $|x| < 1$ which is the same as $-1<x<1$.
Zybikron
can you find the radius and interval from those two inequalities?
yep
but is it closed or open
test your end points, if x=1 does your series converge? what about if x=-1
it says incorrent to both close and open
why is that
that's how you determine if the end points are included.
yeah but it says incorrect to both
so you didn't actually test them, and just guessed.
yes
the series only converges for one of the end points.
what is the result of the second one
what happens when you raise a negative number to inf
it alternates between -1 and 1.
so und
[-1,1)so why is it that the interval '1' has open paranthesis when the limit converges
and when '-1' und it diverges and closed panathesis?
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What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
2
ok i just got to induction im kinda clueless but ik its weak induction and i use base n = 1 or wtv
Which part are you stuck on?
ik how to do part b and c but not a and d
for a, what the question is telling you to do is to prove it directly
how have you done c?
so like substitute 2 into a
for c i think its just i have to prove base case n = 1 is true in original formula without actually solving it yet
No, it’s asking you to say the statement you have to prove, not to prove that the statement is true
okay so like in base case, (formula) must be true when n = 1
In this case, the answer to c is (formula)
thats it?
oh like P(1)
into the formula
for part d after doing (k+1) why do we add (k+1)^2 to both sides?
@stiff summit
idk if im allowed to tag lol
You can
To prove the next case, (k+1)
ok i did the algebra and because the left hand side and right hand side equation equals each other its proven that n = k + 1 is true as well correct?
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so this is my first time doing integrals with polynomials and i don't understand how my teacher did the part circled in purple
why is it 6A + 6B ?
course of A+B =-1 on the left i think
@barren kayak Has your question been resolved?
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Hi! i'm not sure how to use this channel haha, but the thing is i'm a bit desperate with some algebra. Using the expression of the photo, i want to obtain/clear K/N, but since it's not only 1 variable i'm stuck with that 😦 any help would be really welcomed
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<@&286206848099549185> any tip/help? :(((
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@silk island Has your question been resolved?
@silk island Has your question been resolved?
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Why does n! stay the same when finding the derivative of that series?
we are taking the derivative with respect to x
from the perspective of the variable x, n is essentially a constant
Ah I see
Thank you for clarifying again
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Would you be cool with me @ you for questions in these helps channels in the future?
i'm not necessarily always available, but someone who is available will help if you just post the question
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10/BC = 3/5
I have no idea what BC could be. Can I turn it around somehow and get BC alone ?
okay so
whenever you have a fraction equals an fraction
you can do something called cross multiplication
so if 10/BC = 3/5 then 10 * 5 = BC * 3
aka 50 = 3BC
so BC = 50/3
Oogy Boogy
Okay
Hold up
But do I just forget about the 3/5 for now ?
Ohhh wait
Tysm
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Probability theory. The lifetime (in hours) of a certain type of electrical components can be considered as a stochastic variable with the density function f(x) = 0.001e^(-0.001x)x ∈ ℝ^+1. Two such components are interconnected to form a system. Calculate the probability that the lifetime of the system exceeds 100 hours, if a) the components are connected in series.
Is this correct?
The right answer is e^-0.2. But do I go through it in the right way?
Don't really have a teacher to ask 🥲
@strange summit Has your question been resolved?
<@&286206848099549185>
Follow up question.
b) the components are connected in parallel.
Is this correct?
If I don't subtract answer for a) I get 1.8
The right answer is 0.99
<@&286206848099549185> Anyone? 🙃
mind's going brrrrrrrrrrrr
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How do I solve this?
I am not even sure on where to start
I figured I could just try joining BR and RC but that's going to give me 12, which isn't even in the list of options 😭
tangents drawn to a circle from a point are equal in length
what are some theorems related to circle geometry and tangents?
guess you're late to ask that question
Holdup, what if I just draw a line from R to Q, and thus, subtract 4 from 15 which gives me 11 and then add 8 to it which gives me 19, which is also the right answer?
I am not so certain on how this works, but when I was told to draw a line from R to A, I figured why not do R to Q and start from there
We know that BR = BQ. This is from the theorem B-eard mention. Applying this again but on QA and PA we get PA=11. Once again we apply the theorem (I will leave the details to you). https://math.libretexts.org/Bookshelves/Geometry/Elementary_College_Geometry_(Africk)/07%3A_Regular_Polygons_and_Circles/7.03%3A_Tangents_to_the_Circle
think you about this pic
@blissful hill
Oh!
Lemme check.ig out!
OoO, it sure is extensive but I do sorta get an idea!
In any case, @willow sedge, @torn jolt, @tough hazel, and @fossil river - thank you so much for helping out!
While initally it was a bit hard to understand, I actually do understand it now on a better light!
Thank you so much!
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Hello
Please I need urgent help
How to solve these kind of questions what is the procedure
<@&286206848099549185>
<@&286206848099549185>
please wait 15 min before pinging helpers
also, there is a link between partial sums and general term of a series, given by $a_N = ...$
rafilou2003
(hint : it's a difference of two partial sums)
The partial sum is just the sum of the first n terms
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Yeah
And you get x from this
ye
X-x is zero bruv
Xd
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Hi
did you have a particular question about this problem
Do I use riemann sum
u dont need to
you can but the question's asking you to compute it geometrically
Sorry I was googling how to spell that word lol
Thank you guys. I got it. It’s just a right triangle right?
yes
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how do you solve this problem?
i've tried factoring equation 1 and divide but it doesn't quite work
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is there any trigonometric indetity that helps me deal with this?
what's your goal with it, is it part of a larger problem you have to solve?
well yes it is,
I try to solve this using lhoptials
but end up with cos(theta/k) = k+2
(sorry dunno how to use latex)
So was wondering if there is a trigonometric idenetity for this
the derivative of sin(theta/k) is not just cos(theta/k)
divide top and bottom by k
ahh that forms a quadratic
L'hopitals rule is overused . teachers should show students how to manipulate limits normally
yes
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especially when calculating the sin(x)/x limit, it's circular reasoning to use l'hopital
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how is this constructed? OD = DA?
hi
hello
there is no numbers
11
no its Plane geometry
i mean theres E which is 90° u js need to find B angle to do 180-90- B angle number = A angle number
okay
and because of that i came here
I cant find B
yea theres like no number
💀
if there was any type of number of angle u coudl find
i would help u
but since there isnt its quite difficult
and im the same gr lvl as u aswell
<@&286206848099549185>
ok ty
this might be solvable i remembered this in gr 10 my math teacher
basically it might have to involve trig
and i dont rmemeber exactly but bascially since its o a
thats toa
tan of sumthing = opposit/adj
is there anything that goes with this
and i rmemeber u could do something with this with a calculator
BEAC = BE baptizes AC
bro im kinda positive on this answer do u think so too
idk
im kinda proud
lots of assumptions
look
no
cus were trynna find A
and since were finding that angle
we put the opposit angle as opp
then the 90° and angle we need to find is adj
and since opp and adj = toa
i may think tan^-1=45 means 45°
so if thats true and right triangle on google says other sides should be 45 each other side along with 90°
@weak shell where did you find this q
its from our math book
then it must have an answer
cus i gave a reasonable answer
no it doesnt have i just checked right know
what
it doesnt have answer sheet?
what textbook r u using do u kno the name of it
what chapter and page and question
yeah just give a sec
im so confident at this one
ik its
partially right
wait
🖌️
if we connect B and C with an invisible line it kind looks like a perfect triangle
no like perfect triangle
ik what you mean
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how do i find the interval
like what is my goal
as t gets smaller y gets smaller and x gets smaller right and vice versa
but i dont understand what "correct" interval means
i mean im getting an answer
@oblique skiff Has your question been resolved?
<@&286206848099549185>
Your answer has $x$ as a function of $y$, so what's the domain of $y^3$, i.e., for which values of $y$ is $y^3$ defined?
bondalton
so the interval is communicating that y cant be less than 0
?
wait so y just gets infinitely smaller but never past zero
is that it? @vital thorn
Yep, it's just that $y$ is never negative or zero because $e^t$ is never negative or zero.
bondalton
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'\
that, or use the product rule
is $0.6te^{-\frac{1}{20}t}$ $y$ or $\odv{y}{x}$?
pnoןɔ
im not sure
could you post the question this came from?
ok i would recommend you follow the product rule here
oh ok
a
.close
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This is what I'm looking at and struggling with; It is a transportation problem start I do not know how they filled in the BVs and NBVs here. I can try to give additional context, but this is what the example problem has that's relevent.
I am very, very far behind in this class and struggling to catch up. You may need to explain this in baby terms to me; I don't really understand what any of this means, but I am trying very hard.
This does not have an assignment tied to it for at least a few days (and I completed part of it that I was able to figure out), so i have time. If anyone has resources that are good to learn from, I would also appreciate those!
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how to differentiate?
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what is this question asking
It’s asking which all options are equivalent way to ask
huh
3 of the four statements mean the same thing
or the way .doc put it, are equivalent
so u need to find the odd one out
find the one which is same for all 3, then find the remaining
ohh
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why does the F and T disappear?
and how exactly do u determine if after u distribute the V or Λ, do I write Λ or V next like shown on the circled area
is it cuz I distribute the negation of x and V together and Λ already existed there before the distribution so I just keep it as it is
its an axiom look at the sheet, but if u think abt it right, X OR F is just X because the F doesnt change the outcome, only X does (if that makes sense) same thing for X AND T, the T doesnt affect the result, its completely dependant on X so you can get rid of the AND T
😭 what u doing here
im helping ???
thanks
ohh I see
so no matter the sign whenever F or T is involved I just disregard it
idk how to explain this to u icl 🤣
but that circled one stays the same
that is NOT ❌ true
😭 but isnt that what u said
NO\
u said like x and T or x and F I should remove the T or F
no i didnt
hm
look at the axiom sheet
then when exactly do I remove it
I looked I didnt find anything that was -x V F
pretend not x is x for the axioms
ohh
i cannot believe i have to tell you this
yup
ok ok
we'll see
once grades come back
any other things I need to nkow for boolean
chill, remember what happened last time with u
nono that was just unlucky
anyways
u need
to know
nah not unlucky u made that happen
consistency and contraposition
oh the axioms?
I dont see it anywhere
u need it for a lot of boolean question
oh what does it do
oh wait
its a method to solve
nvm
yeah Ik whats contraposition
wdym
like u know how u have to do the opposite of what the question says for contradiction and contraposition?
so like lets say questions tells u to prove x<a or something and then u use either then do the opposite so it would be a<x or something u know
so how do u do that for boolean algebra
!(P or Q) = !P and !Q, is that what you're asking?
yes
oh wait no
so like lets say I solved this question using contradiction
so over here x A y = F is P and -x V y= -x is Q
!(if P then Q) is just P and !Q
yeah so how would it look like for this question
like does the "and" or "or" symbol change?
or does -x become x?
and y become -y?
x A y = F and -x V y != -x
ohh ok
yeah so it becomes not equals
implies
is that like a relation?
yes
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Could I please get a hand with this
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
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I can't seem to know where to begin with #33, I think I'm stuck midway but I don't even know if I'm doing this correctly 😅
I've been looking on this online, apparently I need to make it so that it turns into an inverse tan, but I just can't seem to reach it
are you familiar with u-substitution?
Yes, I've been trying that for the past few attempts
I just suck at it 😭
I'm inserting the (2x) into the root by squaring it right now but it's probably gonna be my many failed attempts
set u = sqrt 4x^2 -1
Ok
the arctan is going to be from using identities
This is what I've got so far
okay i’m just gonna write this out because i don’t feel like doing latex LOL
what exactly did you get for du?
derivative of u
not quite
you can just use power rule for this and rewrite sqrt (4x^2-1) as
(4x^2-1) ^ 1/2
oh wait you just didn’t move the -1/2 power as a fraction
you’re good
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I'm confused
hm?
are u familiar with double integrals?
yes we just learned about them
so should the bounds for x be 0 to cuberoot 1/27 aka 1/3?
and y is 1/27 to x^3?
@opal isle
for A or B
both?
no
for a i guess
mmm
you cannot get the definite integral as a constant if the bounds for the last integral to evaluate don't have constant bounds
i'm not following
okay hold on
what did u get
x^3/3 - 1/81
yep and that's not an area
u need the outer integral (dy) have constant bounds
the bounds cannot be functions
so that part is the easiest to do
how do i do that?
what is the least value y can take
and the max value it can take
look at the curves
isn't it 0<=y<=1/27
yes
ok imma give you a way to remember this
ok just watch a video prob is the easiest way than looking at static pictures
anyways
remember the last integral should have constant bounds
like if it doesn't, what would be the point of having a definite integral which evaluates to a function and not a number?
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how do i do this? I dont get what theyre doing in the answers either
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suppose we have the function
y = x^2 + sin x
is it possible to find dx/dy?
yeah it is
split the derivative
how do we do that?
oh
dx/dy, not dy/dx
dx/dy = 1/(dy/dx)
^
oh shi
i was thinking of that
but i thought calculus has its own weird ass rules
so i thought it wouldnt apply
anyway, thankyou then
🫶
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''X in the equation''
I have no idea how to solve this thing
Use log
uhhh

