help-28

[stiff musk]

given base and height

[torn jolt]

Yes

Oh is the base (-a+a)

[stiff musk]

so length of base = ?

[torn jolt]

0

[stiff musk]

look at the picture, it's obviously not zero

[balmy rose]

and does that make sense?

you are assuming negative lengths exist here

[torn jolt]

Oh 2a

[balmy rose]

visually, you can think about the minus as a direction

2a is good

[torn jolt]

Sorry guys my brain isn't functioning

Ok 1/2(2a)(a)

[stiff musk]

which equals?

[torn jolt]

a^2

[stiff musk]

yep

[torn jolt]

I'll try the circle one myself

[stiff musk]

nice

[torn jolt]

Does this seem right or no

[stiff musk]

yea that's fine

[torn jolt]

1/2 pi r^2 now

[stiff musk]

yep

[torn jolt]

Is 2r^2pi correct

[stiff musk]

wait, you just said 1/2 pi r^2

it can't be both

[torn jolt]

That's my answer after plugging in

[stiff musk]

plugging in what

[torn jolt]

2r

Oh shit

radius

[stiff musk]

no, r is the radius

yea

[torn jolt]

Bro I was right the first time

[stiff musk]

yep you were! 🤣

[torn jolt]

For this part why does 34 have 2 to 2 interval?

What do u mean silly case

Oh so u think they are trying to trick us

[grim skiff]

It's not trying to "trick" you, you should have learned something like this, maybe

[torn jolt]

Oh I see so whenever the range a and b are the same it equals 0

That makes sense

[split swift]

you can view an integral geometrically as the (signed) area between the integrand and the x-axis, between the lower and upper bounds

if the lower and upper bounds are equal, the region has zero width, so zero area, i.e., the integral is zero

[torn jolt]

👌

Thanks for the explanations

a) 3
b) -1
c) 0
d) 5

Idk if b is right

@stiff musk u still on?

Y

We didn't learn that

Oh

So just 3

f(3)-f(6)

F(3)-F(6)

[glossy valve]

..,,

[torn jolt]

-3

?

Ohhh

Why didn't you just tell me its the inverse

-1 -> 1

Ohhh

That makes sense

What if it goes from diferent values

Like a

F(0)-F(-1)

F(1)-F(0) = 5

1-0
0+1

It's the same

So it's just 5 again

0+1

1-0

1 and 1

You don't do keep change change?

-F(-1) Keep change change becomes F(1) right

Ok phew

So you can keep change change right

[torn jolt]

b) 5-5 = 0
c) 0
d) 15

True

I wonder how my teacher expected us to do this without that theorem

This theorem makes it so much easier

Yeah maybe

Bruh

Why is it -5 again

[tepid kite]

yo

I need help

again

Last question

[torn jolt]

Bro

[tepid kite]

I'm being serious

Stop thinking I'm trolling

Ok

Sorry

[torn jolt]

Wait actually

I kinda see what ur saying

Like subtracting the intervals

1-1 for B and -1-0 for A

Ye

Can u tell me what a LHS is

O ok

Yeah that make sense

Wait don't leve yet

[tepid kite]

Are you guys finished?

Ok

Lmk when u are

[torn jolt]

Yeah

Ok

[glossy valve]

..,,

..,,

[tepid kite]

Man I feel bad for Mickey

This is hard

[torn jolt]

Why is that true

[torn jolt]

😢 I remember looking at this kinda stuff two years and thinking is that even math anymore

[tepid kite]

Ong 😂

[torn jolt]

Oh right

Wait yeah that makes sense

[tepid kite]

I'm here struggling in functions only the 2nd day 💀

[torn jolt]

The two areas add up

[torn jolt]

It's ok functions are pretty hard

[tepid kite]

Yea ig

U think u could help me out once ur done?

[torn jolt]

Yeah I get that

[glossy valve]

..,,

[torn jolt]

Yes

Yeah

Can we go to the next q

[tepid kite]

U have one more 💀😭

[torn jolt]

Yeah bro I'm struggling

[tepid kite]

Same 🤣

Alr ima stop disturbing u guys

Good luck with everything

Take care

[torn jolt]

I'll help you after dw @tepid kite

[tepid kite]

Ok thank u

I'll ask the question rn

Till the other guy responds

To help u

Name each polynomial by its degree and number of terms

3gn⁷ - 8d⁶ - 7y⁴s³ - 6z⁷k³ + 9d⁵y4

That's the question

We are doing review rn

[glossy valve]

..,,

[torn jolt]

Yea

Rieman sum?

Like the upper and lower rectangles

What about mid point?

2 4 6

-6 8 30 80

Wait a min

U didnt say f(6)

Ohh

And for the right f(0) is redundent

That's what I mean

Ok but what about midpoint

OH

The middle

f(2) f(4)

Hm

That is a good guess

When is an increasing
function, how does each estimate compare with the actual
value? Explain your reasoning.

The estimates are above

Yes

It make sense

The y values are greater

As it f increases

Hi can someone help me

@torn jolt @hollow oracle

Right is better for decreasing slope

Help me @hollow oracle

Yes please

Sorry for causing u trouble

That makes sense

Man integration is hard to get used to

Yeah ik

I just miss doing easy derivatives

Hope so

Thank you so much

.close

[full forum]

Channel closed

Closed by @formal glade

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[storm hill]

kinda confused on what part b is asking

[limpid furnace]

Having no solution basically means the matrix “blows up”

For example, if you end up with x=1 AND x=2

You know there’s something wrong

[storm hill]

yea

im just asking about part b

the matrix has a unique soln if k not equal to 2 or -2

[civic horizon]

i need help with baby work

[storm hill]

so do i just choose a value for k and solve according to that ?

[limpid furnace]

So if you want the matrix to have existing solutions, it needs to “not blow up”

[civic horizon]

plaese save me

[limpid furnace]

You would usually write the values that k doesn’t blow up

Or the “domain”

If you prefer to call it that

[storm hill]

ah i see

[limpid furnace]

You should have done that in A(ii)

So, your answer probably should look like:

For k larger than (some random number I just made up), the matrix has solutions (blah blah blah)
For k equals (some number) the matrix doesn’t have a solution
For k smaller than (some number) the matrix has solution (blah blah blah)

[storm hill]

alright thanks

.close

[full forum]

Channel closed

Closed by @storm hill

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vital inlet]

For this question I got the correct answer however I don’t think my process is right

[vital inlet]

I rewrite the equation with unknowns and plugged in known values

And solved

[limpid furnace]

If it’s a quadratic, it’s in the form ax^2+bx+c

[vital inlet]

Yeah

[limpid furnace]

And you sub in your x

[vital inlet]

So its still possible to solve in the quadratic form?

I just did ax^2 + c

[limpid furnace]

So a+b+c=1
4a+2b+c=10
9a+3b+c=23

I’m sure you can work this out

[vital inlet]

Mk

.close

[full forum]

Channel closed

Closed by @vital inlet

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[drowsy onyx]

idk what to do

[drowsy onyx]

which side am i solving

[full forum]

@drowsy onyx Has your question been resolved?

[full forum]

@drowsy onyx Has your question been resolved?

[drowsy onyx]

.close

[full forum]

Channel closed

Closed by @drowsy onyx

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[queen dagger]

For integral fractions, it has asked me to simplify by using bedmas for order, then use exponent rules and then convert negative exponents via flipping

The question is:

(5a^3b^2)(-2a^-2b)^-3 divided by (-5a^8b-9)^-3

I got as my answer (1)b^19/-30a7, but i dont know if its correct.

[queen dagger]

my work

<@&286206848099549185>

[full forum]

@queen dagger Has your question been resolved?

[queen dagger]

<@&286206848099549185>

[queen dagger]

.close

[full forum]

Channel closed

Closed by @queen dagger

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[craggy prairie]

I just wanted to double check if i got the recipe the right answer

[vapid barn]

Recipe?

There is no recipe here. Just relax.

@craggy prairie

[craggy prairie]

Sorry typo

I just wanted to double check if I got the right answer

Since we’re trying to find Pr(- result | DS) would the answer be 0.4?

@vapid barn

<@&286206848099549185>

[full forum]

@craggy prairie Has your question been resolved?

[inland moth]

yeah

[craggy prairie]

Since it’s a triple test i just 0.4 x 0.4 x 0.4?

[inland moth]

yes

[full forum]

@craggy prairie Has your question been resolved?

Channel closed

Closed by @craggy prairie

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[viral pelican]

Hey! How do I make sure that my intergrals adds a constant in Mathematica when calculating primitive function?

[viral pelican]

Ive used Intergrate[f[t]]

However it does not add a constant when getting primitive funktion

[harsh pilot]

Does this work for you?

Integrate[f[t], t, GeneratedParameters -> C]

[viral pelican]

Yeah, thanks!

[viral pelican]

How do I add conditions to C?

[full forum]

@viral pelican Has your question been resolved?

[copper basalt]

can you help me?

with my question if you are free?

[full forum]

Channel closed

Closed by @viral pelican

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mental patio]

So I could use some help with this problem. I'm not a total newb to math but its been a while since I've done trig.

[craggy tapir]

law of cosine

[sharp lagoon]

[\sohcahtoa]

[glossy valve]

Chai T. Rex

[sharp lagoon]

That's how you can get one of the other sides.

[full forum]

@mental patio Has your question been resolved?

[mental patio]

yeah I think I figured out the other angle but I'm just having a hard time deciding how to figure out the hypotenuse and opposite lengths. So if I'm correct based on this I would wanna do TOA because then I would just do 63 * tan(90) and that would get me the length of the hypotenuse? I am watching a lecture from my teacher right now and he did a similar situation in which the angle was 32 degrees and his hypotenuse was 7ft and so he used cos32 degrees = x/7 but because he didn't have x he multiplied 7 by 32 which gave him 5.94?

[sharp lagoon]

No, you never use the right angle for SOHCAHTOA.

You have the angle 23.8 degrees.

Which other side do you want to figure out? The hypotenuse or the other leg?

[mental patio]

And I have the other angle at 156.2 degrees and yeah I was watching the video again I think I got a little closer. I did cos(23.8)*63 which got me 14.85 which I think would be the opposite side of the given angle?

[full forum]

@mental patio Has your question been resolved?

[full forum]

@mental patio Has your question been resolved?

[full forum]

@mental patio Has your question been resolved?

[full forum]

@mental patio Has your question been resolved?

[spice knot]

this video walks you through on how to do a problem like this

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[steady rock]

find a & b for -ax^2+4bx-3 for x intercepts 1 and -1. This was multiple choice so i just did substitution, how do i work this out without substitution.

[glacial pasture]

well, if i say f(x)=-ax^2+4bx-3
then f(1)=f(-1)=0

you can solve the two equations youll get from that simultaneously

[steady rock]

okay how do i do that haha

[glacial pasture]

-a+4b-3=0
-a-4b-3=0
-a+4b=-a-4b

b=0

a=-3

[steady rock]

gotcha

gracias

.close

[full forum]

Channel closed

Closed by @steady rock

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[scenic prism]

how do you do tabular integration for this problem?

[scenic prism]

the problem is on the top left corner, my attempt at the problem with tabular method is on the left and the traditional integration by parts method is to the right

[blissful sundial]

Tabular method is really only useful when u have a function where doing multiple derivatives will get it to 0 like a polynomial. So u wouldn’t use it for this problem

[full forum]

@scenic prism Has your question been resolved?

[scenic prism]

thank you

[full forum]

Channel closed

Closed by @scenic prism

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gentle coyote]

given:

[gentle coyote]

that's what I've come to

I could do the other problems, however in this one both there's p-h there, so kinda different

the answer is ||2L||

[full forum]

@gentle coyote Has your question been resolved?

[gentle coyote]

<@&286206848099549185> please!

[polar valve]

add (fp)-f(p) in the numerator, and the split the fraction into a sum of two fractions.

[gentle coyote]

ahhhhh

perfect

thank you

.close

[full forum]

Channel closed

Closed by @gentle coyote

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slate violet]

You need to times the number of passwords per second in 2012 by 2, 8 times

[void swift]

2^8?

[void swift]

how did you get that?

[slate violet]

Doubles every year for 8 years

[slate violet]

Yep

[void swift]

oh

im blid

blind

mb

[slate violet]

Yeahh

[full forum]

@void swift Has your question been resolved?

Channel closed

Closed by @void swift

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[full forum]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[finite stag]

.close

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[woeful fossil]

how to solve this

[woeful fossil]

Look at the image and answer the question below
What number would complete our table?

translated

[full forum]

@woeful fossil Has your question been resolved?

[rough plaza]

there can be many possible answers
we hope that we can find a easy one to solve this question

[rough plaza]

what have you tried so far

[full forum]

@woeful fossil Has your question been resolved?

[woeful fossil]

I tried to see it as a 4x3 magic square but I can't make sense of it. I don't know what mathematical concept to apply here.

[rough plaza]

oh ok, first step for me would be try to break the biggest number down in each column

break down as in breaking it into
something times something

the first one,
90 <-- there are many combinations
so I use the second one to clarify
65 <-- there are only 2 combinations

try work on these first @woeful fossil

[woeful fossil]

oko let me try

[full forum]

@woeful fossil Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pulsar thistle]

pls someone ;-;

[limpid moat]

ponyo !

[pulsar thistle]

yes

[limpid moat]

wow

[full forum]

@pulsar thistle Has your question been resolved?

Channel closed

Closed by @pulsar thistle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[plucky remnant]

How would I find the derivative of this function?

[plucky remnant]

One for x and one for t

[limpid moat]

chain rule

[plucky remnant]

Idk what u is

[limpid moat]

for example, u(x)=i(kx-wt)

[plucky remnant]

And what would y(u) be?

[full forum]

@plucky remnant Has your question been resolved?

Channel closed

Closed by @plucky remnant

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lone crag]

how to solve this continue？

[formal scarab]

partial fractions innit

[full forum]

@lone crag Has your question been resolved?

[still sluice]

7-t^2=(√7-t)(√7+t), use this to split 1/(7-t^2) to the form of A/(√7-t) + B/(√7+t), then solve A and B

[rugged void]

^^

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[rugged void]

well
that was... abrupt

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mental patio]

Thanks I think I solved the problem but this will probably help me on another problem

[lone crag]

ohhh thank you !!

[full forum]

@mental patio Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tiny drum]

need help with 4th question

[tiny drum]

will be helpful if someone tells me its steps of construction

[fervent dove]

three steps

1. draw a straight line, then a line with it at a 75* angle

do you have a compass?

[tiny drum]

i said 4th question,the tangent one 🥹

[fervent dove]

oh lmao

[tiny drum]

i need help please i have a test in 3 hours

[fervent dove]

ok, well tell me what a tangent is first

[tiny drum]

a line touching a circle

[fervent dove]

at how many points?

[tiny drum]

two pointa

points

[fervent dove]

not quite

[tiny drum]

yeah it depends

like transverse

tangent

[fervent dove]

a tangent only touches one point

[tiny drum]

common tangent

[tiny drum]

ok

[fervent dove]

is it not just this?

if the lines are parallel, they have to be at the opposite side of the circle

you could also draw them vertically i’m sure

[tiny drum]

wait wait wait

how did u draw the perpendicular

[fervent dove]

oh shit perpendicular

ok well it’s the same thing pretty much

ok wait

draw the circle and split it into its quadrants, then draw a tangent at two of those points

you can use a protractor to ensure it’s at 90*

does that help a bit?

[tiny drum]

so first i draw a 3cm circle then i divide it into 4 quadrants by making perpendicular bisectors???

[fervent dove]

yes, exactly

[tiny drum]

can i draw the tangents any where

[fervent dove]

well they have to be at a 90* angle

you can if you really want to, but i wouldn’t advise it

by splitting it into the quadrants, you get two points at the circle where if you draw two tangents, they will be at 90*

[tiny drum]

yeah alr i got it

[fervent dove]

alright

[tiny drum]

thank you so much!!!

.close

[fervent dove]

no problem

[full forum]

Channel closed

Closed by @tiny drum

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[full forum]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[west quiver]

so the top bit is the answer, I just dont get how we get there

x ^ 1/2 would be sqrt(x)

but this is 1 1/2

oh wait I guess the 1 does not make a difference as exponent here does it?

not sure how it becomes 'x sqrt(x)'

[eager obsidian]

consider x^(1 1/2) first

thats x^(3/2)

which is x(x^(1/2))

[west quiver]

why though

this'd explain where the x up front comes from

so we take the x from 2/2 out, and keep the remainder (1/2) there?

wait itd make sense

u just split it

hold up

.close

[full forum]

Channel closed

Closed by @west quiver

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[left cradle]

How do you solve 4 D?

.close

[full forum]

Channel closed

Closed by @left cradle

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[flint crane]

why does b in asin(b(x-c))+d change the period?

[flint crane]

i understand that f(kx) gets horizontally stretched by a factor of 1/k

but if u wanna change period shouldnt it be asin(bx-c)+d instead (by direct substitution)?

thanks

[summer echo]

What they do is first stretch it, and then translate it

so asin(x) + d would become asin(bx) + d after the stretching

and then asin(b(x - c)) +d after the translation

[flint crane]

ohh

so if i get asked "what transformation from y=cosx to y=cos(2(x+pi/6)) its just horizontally stretch factor 1/2 and pi/6 units left?

do you mind opening your own channel

[pine vine]

sorry

[summer echo]

Yes. (sorry for the late reaction)

[flint crane]

ah thanks

.close

[full forum]

Channel closed

Closed by @flint crane

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

hi

[torn jolt]

but i dont know how i got negative value, and the answer says its 6

[vapid scarab]

could u send a closer image

of the last 3-4 steps

[torn jolt]

sure

[vapid scarab]

Yo nvm I got u

theres 2 formulas

one of them is base 1 = base 2

ie p = q

that u used

and the other one is

[torn jolt]

yea

and theres one more

[vapid scarab]

p+q = n

[torn jolt]

yea

oh

so is that what im supposed to use here

[vapid scarab]

Exactly

it shold give u 3r = 18

r=6

Am I right?

[torn jolt]

yea you are

[vapid scarab]

Nice

[torn jolt]

yea

yay

thanks

!!

.close

[full forum]

Channel closed

Closed by @tawdry kiln

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[topaz junco]

....any clue how to solve this? dont really wanna know the solution ,just a clue, feels so simple but i havent done geometry in like 4-5 years -_-

<@&286206848099549185> sorry for pinging this fast, posted this 3 times by now

[signal temple]

U wanna find out the area of triangle ADE?

[topaz junco]

perimeter of ADE

[signal temple]

Oh

[cunning vessel]

is DE parallel to BC?

[topaz junco]

so any clues? found that IE = EC and ID = DB but thats kind of it

[topaz junco]

yeah

[signal temple]

Ok

[cunning vessel]

If then

AC is 12

AB is 10

[topaz junco]

yeah

lol

(also please just give me a hint, not the whole solution)

[cunning vessel]

And Parameter you want to know is same is AD+AE+ID+IE

this is hint I guess

[topaz junco]

....no, the perimeter is AD +DE + AE ( i can put IE and ID instead of DE but idk whats next)

[cunning vessel]

DE is ID+IE

[topaz junco]

didnt read your message right

-_-

[cunning vessel]

ok

more hint?

[topaz junco]

i kind of need a hint that i didnt know about :/

[cunning vessel]

you know everything yu need to solve this problem I think

AB=AD+DB

think about what has same length with DB

[topaz junco]

if only i could find AD or DB..... D is not necesarry the midpoint of AB

[cunning vessel]

yes not neccesarrily

what is lengh of AB again?

[topaz junco]

10

[signal temple]

10

[cunning vessel]

is AB=AD+DB?

[topaz junco]

well DB = DI because of the angles DBI and DIB

[topaz junco]

yeah

[signal temple]

It doesn't say that d is mid point

[cunning vessel]

it is just point on AB

[signal temple]

Can u send the question

Is there any more info given?

[cunning vessel]

more direct hint you need?

[signal temple]

If D and E are mid points

[topaz junco]

.....my math teacher kind of came to class and droped that on the board without anything else, i know that DE is pallarel to BC and that its not an isoscel triangle or a right triangle

[signal temple]

Then the sum is done

[topaz junco]

yeah but there is nothing saying that, a friend tried that and the teacher said that they arent the midpoints

[cunning vessel]

D is point on AB. So we can say length of AB is same as sum of length of each AD+DB

and DB=ID

[topaz junco]

yeah

so AD + ID = 10

[cunning vessel]

yes

same for AC

[topaz junco]

so AE + IE = 12

[cunning vessel]

yes

[topaz junco]

the lenght of IE and DI arent equal,right?

[cunning vessel]

yes

dont have to be

[signal temple]

They are not equal yes

[cunning vessel]

it doesnt have to be equal, you can still solve this

[topaz junco]

maybe i forgot some theorem about bisector lines but i just dont see it....

we also got AD/DB = AE/EC, right? brcause of Thales theorem

[cunning vessel]

I dont thimk that info is necesarry though

[topaz junco]

i still dont see it, there doesnt seem to be a way to use sin or cos, or even calculus....

[cunning vessel]

more hint? or would you keep trying?

[topaz junco]

just 1 more hint, tried all day at school -_-

[cunning vessel]

this

[topaz junco]

nooooooo, IT WAS THAT SIMPLE

[cunning vessel]

is it too direct

[topaz junco]

FUUUUUUUUU

so its just 22?

damn

[cunning vessel]

yes

sorry if this was too much for a one hint

[topaz junco]

i just never thought of labeling the lrnght of 2 sides..... wow

[cunning vessel]

I agree, sure not easy to find that at first attempt

[topaz junco]

yeah no problem, kind of gave it away, i was thinking it was something complex like using multiple lines and finding the lenght of each one at a time

thanks for the help, also, how did you see it so fast?

[cunning vessel]

Idk, I might've solved similar question long time ago

[topaz junco]

forgot to do .close

.close

[full forum]

Channel closed

Closed by @topaz junco

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[calm jacinth]

can someone help me understand this

[minor crater]

hint: x=-5

[vapid scarab]

its like the 1s part is given

u use the given value of x to get the value of y

[minor crater]

substitute that and solve for y

[vapid scarab]

the format is (x,y) = (-5, ? )

so u simply find that question mark by substituting the given value of x in that equation

[calm jacinth]

thanks lol

.close

[full forum]

Channel closed

Closed by @calm jacinth

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[clever iris]

is my work correct?

[gritty rose]

No

0 times anything = 0

[clever iris]

which part are u talking about>

[gritty rose]

The part where you have a multiplication by zero

[clever iris]

do u mean v^2 time 0?

ohh i see

so is this the answer?

[gritty rose]

Is V depending on r or is that also a constant?

[clever iris]

i think V is a constant

[gritty rose]

You forgot a factor of (R+r) in the numerator

[clever iris]

i found the darivitive of (R + r)^2

that made it 1

[gritty rose]

Yes. Where did it go

[gritty rose]

Also you forgot a factor of 2

[clever iris]

its still there but -(V^2 R) * 1

[gritty rose]

No that's not how multiplication works

[clever iris]

sorry but i dont understant

[gritty rose]

-V^2 * R * 2* (R+r)

-V^2 * R is a constant multiplying the derivative of (R+r)^2

d/dr(R+r)^2 is just power rule

[clever iris]

oh so i cant make (R+r)^2 = (R + r )(R+r) then find the derivaitve

[gritty rose]

You can but that's a waste of time

Also prone to more algebra mistakes

[clever iris]

oh i see now

thank you

So is this correc

[gritty rose]

Yes

[full forum]

@clever iris Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[white garnet]

how do i factor the quadratic here

[minor crater]

no need to factor it

find the derivative

[white garnet]

don't know how yet, doing what my professor told me to atm

[minor crater]

what did your prof tell you to do

[white garnet]

this

[viral jasper]

ahh derivative with extra steps

[white garnet]

yes

[viral jasper]

!show

[full forum]

Show your work, and if possible, explain where you are stuck.

[white garnet]

i didn't do anything yet really

just trying to factor the quadratic and failing

[viral jasper]

How about try following and the example, actually writing it down, and seeing where you get stuck

[viral jasper]

What are you trying to factor, exactly?

[white garnet]

.

[white garnet]

i know where i am getting stuck. i just need to factor this

[viral jasper]

I would disagree that you know, because you are not supposed to factor that

[viral jasper]

I again recommend that you try following these steps, while actually writing down the work, and see where you get stuck

[white garnet]

the example problem is the solution i showed above, i am supposed to factor and cancel accordingly

and i am writing it down tf

[viral jasper]

May I see what you've written so far?

[white garnet]

trying to factor

not working

what i said

ignore other stuff

[viral jasper]

Yeah, you are not supposed to factor -4x²-4x+4

[white garnet]

what do i do then

[viral jasper]

Note the example here, what is being calculated

This is for finding the slope of f at x=3. Would you know how to set this up for finding the slope at x=1 then?

[white garnet]

just input x = 1 and f(1) into slope formula, take that limit

[viral jasper]

That is correct. So do you see how to correct your earlier work now?

[white garnet]

no because i just get this and im stuck

[viral jasper]

try simplifying this a bit

[white garnet]

so +8?

[hot herald]

no

how are you getting that

[white garnet]

at the end

[hot herald]

oh, you mean just the -(-4) part?

[white garnet]

ye

[hot herald]

what do you have after simplifying further

[full forum]

@white garnet Has your question been resolved?

Channel closed

Closed by @white garnet

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glacial knoll]

$\lim_{n\to\infty}\ln{\frac{1}{n}}$

[glacial knoll]

How can I solve this?

[full marsh]

Wrap it around $

[glossy valve]

Ñøïr

[glacial knoll]

I amnt really satisfied by wolfram's answer

Compute 'lim(n->∞)ln(1/n)' with the Wolfram|Alpha website (https://www.wolframalpha.com/input/?i=lim(n->∞)ln(1%2Fn)) or mobile app (wolframalpha:///?i=lim%28n-%3E%E2%88%9E%29ln%281%2Fn%29).

[viral jasper]

why not?

[glacial knoll]

Last step explained as

log(1/(large positive number)):
Answer: |
| -∞

[viral jasper]

screenshot pls?

[viral jasper]

That is kinda hand-wavy, yea

[glacial knoll]

Hand-wavy?

Is there any reason infinities used arbitrarily in calculus this way?

like, in definite inegrals its more preferred lim(b->∞) a to b instead of a to ∞ as I see

[viral jasper]

hand-wavy as in "not mathematically rigorous"

[glacial knoll]

There seem to no more satisfactory answer to that

Thank you

.close

[full forum]

Channel closed

Closed by @glacial knoll

Use .reopen if this was a mistake.

[viral jasper]

The most satisfactory answer would be an epsilon limit proof

[glacial knoll]

Actually, thats on me

[viral jasper]

.reopen

[full forum]

✅

[glacial knoll]

Apologies, shared the problematic part instead of original problem

You see I was trying to find convergence of summation

In next question I found this

So it falls to undefined category by ln0

[viral jasper]

oh. Then yes

But what is the original original question?

[glacial knoll]

original question is to show they are divergent or n-th term test is inconclusive

Well, thanks again

.close

[full forum]

Channel closed

Closed by @glacial knoll

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jade radish]

I wrote this but my brain is telling me that this should be isomorphic

like, it's one-to-one and onto, therefore a bijection between the two groups ( really it's the same group and so I don't see why it would ever NOT be isomorphic )

the issue is that our definition of isomorphism is given as this:

where star and circledcirc are the binary operations of G1 and G2, respectively

which in the case of 3.49.a is both addition on the integers

[devout valley]

Yea, as per the way they defined it, you need both bijectivity and being an homomorphism, even if you have the bijectivity bit, you also need that homomorphism part

[devout valley]

There are isomorphisms [and Z as an additive group is isomorphic to itself, e.g. the identity map], but the one here (assumedly phi(x) = x + 1, right?) is not one of them

[jade radish]

ahhh I see

Is the way I went about the problem enough to show that it isn't a isomorphism since the groups themselves are the same, I didn't care to show bijectivity

[devout valley]

Yep, as long as you show you fail at least one thing needed to be an isomorphism, you're good to say it isn't

Doesn't matter if anything else is satisfied or not

[jade radish]

I see, alright

thanks!

.close

[full forum]

Channel closed

Closed by @jade radish

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

I'm so lost on this

[jade radish]

What about this confuses you?

It's saying to set y to be 0 on the left and then solve for x ( or rather, this is how I am interpreting the problem based on the info I have )

so it wants you to solve

[glossy valve]

Juke | ping me if no response

[jade radish]

this

[torn jolt]

Well yeah I know that

Then you get -x(x-2)(x-2)

[jade radish]

okay, in this case so from here what do you think our options are?

how did you get that?

[torn jolt]

What do u mean

[torn jolt]

Facetor

Factor

-x(x+4)

[jade radish]

yes that is where u stop

idk where u got (x-2)(x-2) from

[torn jolt]

Wait

Juke

[jade radish]

that's not equal to (x+4)

yo

[torn jolt]

The graph says 2

[jade radish]

what're you talking about

[torn jolt]

Oh fck I was using the numbers from their graph

[jade radish]

oh btw, if you factor -x out the inside should be (x-4) not (x+4)

[torn jolt]

There was someoen else that helped me

[jade radish]

uh okay

[torn jolt]

Yeah I got confused I guess

[jade radish]

Anyways you have -x(x-4)

[torn jolt]

Yeah

[jade radish]

this set to 0

[torn jolt]

0 and 4

[jade radish]

yuh

ez

[torn jolt]

Bounds

[jade radish]

what

wym by bounds

[torn jolt]

I m confused on something else

[jade radish]

okay..

related to this problem?

[torn jolt]

Like in the integral [0-4]

[torn jolt]

Another q

[jade radish]

integral??

[torn jolt]

I understand this one

[jade radish]

you mean interval?

[torn jolt]

Yes

[jade radish]

AH okay

what about the interval

[jade radish]

btw, do you mean [0, -4]?

[torn jolt]

No

[jade radish]

[-4, 0]?

[torn jolt]

[0, 4]

[jade radish]

oh

okay

that one makes sense

[torn jolt]

FTC will be used to find the area for it

I understand it now

[jade radish]

okay!

[torn jolt]

I'm lost on these kinds of questions

45. the integration of x^3 is x^4/4

3^4 is 81

81/4 - 0

81/4 is multiplied by 1/3 (1/b-a) for MVT

But that gave me the wrong answer 🙁

[jade radish]

i don't remember MVT so I can't help ya on this

hopefully somebody else can take a look soon tho !

[torn jolt]

It's just integrating in the interval the only different is it being multiplied by 1/b-a

[full forum]

@torn jolt Has your question been resolved?

[torn jolt]

.close

[full forum]

Channel closed

Closed by @formal glade

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[balmy rose]

!status

[full forum]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[sand shard]

1

[balmy rose]

as we can see, this sub-mobile is in balance

what does this mean?

[sand shard]

the torques are the same?

[balmy rose]

yep

and torque is?

[sand shard]

fr

[balmy rose]

yep, Force times distance

and the force here is the gravitational force F=m*g

[sand shard]

isnt that work

force time distance

[balmy rose]

there is a slight difference

when it comes to torque, the angle also matters
but in this case, it won't make a difference

and yes, the units here are Newton Meters

so Torque and Work have the same units

[sand shard]

doesnt the angle also matter for work

[sand shard]

so i have to change the units to newton and meter?

[balmy rose]

generally, the force and the distance will be vectors. the torque will then be the cross product of these vectors

for the work, it will be W=∫F ds, where s is the way along which the force acts

so they are defined differently
but in most school contexts, they will look similarly

and in our context, torque would be
M = F * r * sin(angle)

but since the angle is 90°, the sin(angle) is just 1

so we get the torque to be F * r

and from this, we can set the torques of two sides equal and solve for the remaining mass

[sand shard]

that problems so annoying then i have to do it so many times and convert them all to newton and meter

[balmy rose]

you dont really have to solve much

[balmy rose]

for example here, on the left we get 2cm * m * g = 4cm * 5g * g

notice that we can just cancel out the g

[sand shard]

dont we have to make it meters

[balmy rose]

so m = 5g * 4/2 = 10g

not really

[sand shard]

why

[balmy rose]

we can also leave the masses in grams

let's say we wanna divide 5 meters by 10 centimeters
then it makes sense to convert

but if we are always dealing with centimeters, then it doesnt really matter

let's say i calculate a time
if i start with minutes and convert that to hours it will be the same if i convert to hours first and then calculate

the key here is to be consistent

as in, we can't add a meter and a centimeter, we should convert first

but here, we can just keep it in cm and g

[sand shard]

oh cuz they not asking for the roque

toruqe

is the answer 36 grams

@balmy rose

[balmy rose]

You mean the end result?

Yeah sounds good

[sand shard]

okk

i have anothe rquesiton

could u check my answer i tried it

teacher doesnt care if use 10 for gravity

[balmy rose]

3.29 looks good

You started wih 80. Should be 8 tho

Also, you avoid rounding mistakes if you only calculate at the very end

So in this case:
8kg * 14cm = m * 34 cm
m = 8kg * 14cm/34cm

And then the calculator gives the result

Also makes it less likely to make logical mistakes

[sand shard]

i undersatnd

thank you

ill do that for the next time

appreciate ur help 🙂

whats ur pfp btw

it looks like a frilled dragon

.close

[full forum]

Channel closed

Closed by @sand shard

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pseudo jay]

Let C be the circle with the equation "x^2 + y^2 - 6y - 16 = 0" and L be its tangent line at (4, 6). Determine the equation of the concave parabola with vertex located at the intercept of L if it is also known that this parabola passes through the intersection of L with the x axis

[pseudo jay]

Sorry, it's on spanish

[full forum]

@pseudo jay Has your question been resolved?

[pseudo jay]

<@&286206848099549185> I'm sorry to bother

please help

<@&286206848099549185>

please

help me

[pliant bane]

ok

[pseudo jay]

yo...

[pseudo jay]

<@&286206848099549185>

I have no idea what to do

[ripe fable]

Can you translate it?

[pseudo jay]

Let C be the circumference with the equation "x^2 + y^2 - 6y - 16 = 0" and L be its tangent line at (4, 6). Determine the equation of the concave parabola with vertex located at the intercept of L if it is also known that this parabola passes through the intersection of L with the x axis

here it is

[ripe fable]

Were you able to find the tangent passing through (4,6)?

[pseudo jay]

no

I was sick and didn't went to clases, so i don't know nothing

I was asking if you can guide me

I have some notes an formulas from today

[ripe fable]

Dm them to me I’ll look through them and guide you.

[pseudo jay]

.close

[full forum]

Channel closed

Closed by @pseudo jay

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fallow sage]

help pls

[plush egret]

I don't understand what youve done here

maybe thats a botched sign on the quotient rule there

$\dv t \frac fg = \frac{gf' - fg'}{g^2}$, no?

[glossy valve]

jan Niku

[plush egret]

but you have a + @fallow sage

[fallow sage]

OH

omg little mistakes be the worst

.CLOSE

.close

[full forum]

Channel closed

Closed by @fallow sage

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

https://tenor.com/view/why-isnt-it-posssible-its-just-not-american-psycho-gif-26353597

[torn jolt]

I know its C(31,4) but is there a subtle wording I'm missing that makes that clearer? I got something like this wrong earlier because I just counted lol

.close more of a semantics issue

[full forum]

Channel closed

Closed by @hot tide

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lament rivet]

Hi I’ve done the first 3 steps but not sure how to proceed from here thanks

[torn jolt]

I don't believe there is any more simplification to do, n! grows faster than anything else in the problem, so now assume as n-> ♾️

[lament rivet]

Does that mean it’s infinity/infinity so it tends to 0? Or

[merry thicket]

use l'hopitals rule !!!!!!11!11!

[opal isle]

is 125^n equal to 5^3 * 5^3n ?

[lament rivet]

Omigod it’s only equal to 5^3 x 5^n right

Not 3n

[lament rivet]

I don’t know that yet I will learn it 😭

[opal isle]

it's not 125 x 5 ^n

[lament rivet]

I see now! I haven’t even got the basics down 😭

[torn jolt]

My bad I didn't even look for that

[lament rivet]

Thank you guys

[opal isle]

i dont think (5)^3n that helps a lot for the limit

[gritty rose]

You should divide all terms by n! first

[lament rivet]

Ok I’ll try this now

[torn jolt]

Side note wonderful handwriting

[opal isle]

i mean, (5)^3n helps

but doesn't help you to get rid of inf / inf

[torn jolt]

Doesn't that lim>1?

[opal isle]

no

[torn jolt]

well inf doesn't, but any real number for limit as x->inf does

[lament rivet]

Can I go from step 3 to 4 like this or is this illegal

[opal isle]

yeah its illegal

[lament rivet]

😭

[opal isle]

better if you keep (3) and multiply by 1 (don't change anything)

then rewrite that 1 as 1/n! / 1/n!

see what happens above and below the fraction

[sour egret]

umm isn't there a mistake there

[lament rivet]

Like this?

[lament rivet]

Where 😭 plz tell

[sour egret]

both of these in the denominator are wrong actually

[lament rivet]

I was trying to divide everything by n! But I guess that was not how to do it

😭

[opal isle]

the idea is to multiply that thing by 1

so you still have that thing

[sour egret]

but n!/n! is 1 and you didn't distribute the 5^3

[opal isle]

then you rewrite 1 as 1/n! over 1/n! (a/a = 1)

[lament rivet]

So I multiply everything by this

[opal isle]

yeah, a * 1 = a, shouldn't change anything

[lament rivet]

I didn’t know how to expand the bracket with the factorial 😭

[sour egret]

$\frac{1}{n!}\cdot 5^3\cdot (n! + 125n) = \frac{5^3\cdot n!}{n!} + \frac{125n\cdot5^3}{n!} = 5^3 + \frac{125n\cdot5^3}{n!}$

[glossy valve]

soulgazer

[opal isle]

read the red note pls

okay anyways that way of doing it is also correct

[lament rivet]

Thanks does this look right?

[lament rivet]

Thanks is this right ?

[opal isle]

what happend to the 1/n! above the fraction

[lament rivet]

Is this what’s wrong

[opal isle]

now it is okay

[opal isle]

ignore the black text if it confuses you, but if not it might explain why you distribute the 1/n!

[lament rivet]

Yep i definitely don’t get it 100% rn but will try to learn it

[opal isle]

you remember factorization?

do the opposite step

ab+ac=a(b+c)