help-28

[static mesa]

so thats one of the points

[flat mesa]

and they have also highlighted (4,f(4))

[static mesa]

yes

[flat mesa]

you want a secant line with those two points

[static mesa]

oh so it's just one secent line

[flat mesa]

yes

[static mesa]

alright

and I think I got the slop part of that

[flat mesa]

[static mesa]

.close

[full forum]

Channel closed

Closed by @static mesa

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tall turtle]

Solve the triangle

the upside down pi/5 is suppose to be right side up

[terse bone]

you can just solve for the angles knowing that the sum of them is pi and you can just use pythagoras for the side if you dont wana do trigonometry:)

[tall turtle]

for the angles it would be pi/5, 2.5pi/5 and 1.5 pi/5 right?

[terse bone]

thats what i got

[wide wind]

They do, but keep them to integers.

[onyx glen]

why would you write them this way

2.5π/5 is like... legal but it's so cursed

if you want them all over the same denominator put them over 10 or something.

[terse bone]

F = am type beat

[tall turtle]

How about for the angles

I mean sides

Would I need to convert the pi.5 to decimals

[terse bone]

no need just plug the values into the formula and write down whatever you get

[full forum]

@tall turtle Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[solid thunder]

I'm wondering, is there some simple way of transforming the space of graphs to an inner product space?
I've been looking at some stuff related to random walk kernels, but I feel like a really simple example of this kinda thing would be great to start with

[full forum]

@solid thunder Has your question been resolved?

[full forum]

@solid thunder Has your question been resolved?

[gritty rose]

what does "space of graphs" mean

[solid thunder]

well, I've probably not thought about it fully formally, but I more or less meant to say "all graphs, regardless of size"

[gritty rose]

what's your definition of graph

[solid thunder]

(V, E), set of vertices, set of pairs (v_i, v_j) from VxV

• the thingy that allows multigraphs, I can't remember how exactly

E is a multiset ig?
but idm whichever definition tbh

I kinda just wanna wrap my head around how I'd go about cooking up a metric for graphs tbh
like my first thought was take the adjacency matrix and go from there, but I feel like it doesn't work (directly at least?) for different sized graphs, which is why I'd mentioned all graphs specifically

[full forum]

@solid thunder Has your question been resolved?

[full forum]

@solid thunder Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[waxen wing]

can someone please explain how they got this step?

[full forum]

@waxen wing Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quiet hedge]

,rotate

[quiet hedge]

Not sure how to start

[summer echo]

Use the triangle inequality

|w + z| <= |w| + |z|

[quiet hedge]

Ok

How do I apply it

[summer echo]

You have to write a series of < or <= signs starting with |(1 + i)z^3 + iz|

and at the end there should be 3/4

[quiet hedge]

Like this?

Ow I did it

Tysm

.close

[full forum]

Channel closed

Closed by @quiet hedge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[short crest]

is area ABD = area ADC?

If yes, does that work for any triangle?

[summer echo]

That works, because their bases are the same length and their heights are the same

but you only have to find the height and base of AED

[short crest]

why?

[summer echo]

A = 1/2 * b * h

[hollow wharf]

Your argument can work, I can see a solution using just this

Both approaches here should get you to the answer

[short crest]

Why not just... 1/2 area ABC - area EBD 🙂

[summer echo]

Yeah it works

[short crest]

But does that work for any triangle?

[summer echo]

If AB = BC, yes the 24 cm doesn't matter

and D has to be the mid-point

[short crest]

So if AB ≠ BC, it won't work?

[summer echo]

E doesn't matter I think

nvm

[hollow wharf]

E matters

[summer echo]

if would, sorry

[hollow wharf]

But yeah in this case there are so many solutions

[summer echo]

To be clear: D has to be the midpoint of BC, that's it I think

[short crest]

Oh okay, thanks.

.close

[full forum]

Channel closed

Closed by @short crest

Use .reopen if this was a mistake.

[summer echo]

for this to work

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sullen salmon]

how to get this with the following conditions

[stark ruin]

multiply divide by x-1

[sullen salmon]

let me try

i will ping you

[stark ruin]

you just gotta form standard limits

[sullen salmon]

you sure by x-1?

could it be x+1?

[stark ruin]

what im trying to do is make a standard limit

[sullen salmon]

ok

wait

[stark ruin]

which is there for log (1+x)

ok you cant do that yet

first step is write x =1-y

because standard limits only apply when x tends to 0

[sullen salmon]

yes

so we can assume

x= t+1

[stark ruin]

replace x by 1-y

[sullen salmon]

and proceed

[stark ruin]

yeah

y tends to 0

and create standard imits

[sullen salmon]

by l' i am getting -1/pi^2

thats what i want

[stark ruin]

yh

y+ln(1-y)/1+cos(1-y)pi

[sullen salmon]

1-y

should be

1+y?

[stark ruin]

oh yeah

m b

wrong sign

[sullen salmon]

ok

[stark ruin]

i mean

you can do it both ways

either way y tends to 0

[sullen salmon]

i have an idea

since i got

at the den

1+cospi(1+t)

we can multiply and devide by

1-cospi(1+T)

ignore my spelling

[stark ruin]

noneed

u can ust

just

multiply divide

[sullen salmon]

1+t?

[stark ruin]

pi^2(1-y)^2

or whatever you took

[stark ruin]

this works

[sullen salmon]

wait

[stark ruin]

because we want to create

[sullen salmon]

using that

[stark ruin]

1-cos x /x^2

[sullen salmon]

listen i got

wait i will write in desmos

something like this

@stark ruin

[stark ruin]

yes

now multiply divide

by( 1+t)pi

[sullen salmon]

wait i forget a term there

@stark ruin

[stark ruin]

yeah so

multiply divide

by pi(1+t)

[sullen salmon]

done

[stark ruin]

sin terms gone now

and u have a (1+t)piin denom

[sullen salmon]

how?

sin must tends to zero

in this case it is tending towards Pi

[stark ruin]

sin pi

tends toward 0

[sullen salmon]

ik

but the angle

it tends to zero

not the value of sin

[stark ruin]

1+tpi

tends to pi

ahh right

[sullen salmon]

yes

same

i did this

[stark ruin]

idk then 💀 probably wait for someone else

[sullen salmon]

but not ended ip getting

-1/pi^2

then i realised i fucked up

[sullen salmon]

yea

by this ques my teacher has take my all power

🫠

[patent loom]

72 cm^2

[sullen salmon]

huh?

[patent loom]

Midpoint of AB = BC = 24cm

Given

We need AE and ED lengths

[sullen salmon]

bro

ask in help section

its already reserved

[patent loom]

AE=BE=1/2 * AB=1/2 * 24cm=12cm

BD=DC=1/2 * BC=1/2 * 24cm=12cm

Area=(1/2) * base * height

AE is the base value and ED is the height

Area=(1/2) * AE * ED=(1/2) * 12 * 12=72

[sullen salmon]

.close

[full forum]

Channel closed

Closed by @sullen salmon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[compact leaf]

if pair of lines make equal angles $ax^2-2xy+by^2=0$ and $bx^2-2xy+ay^2=0$ then prove that a-2=2 and a+2=0

[glossy valve]

Tita

[unborn pike]

!status

[full forum]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[compact leaf]

1

[unborn pike]

Do you know formula of angle b/w pair of line?

[compact leaf]

yes this one

[unborn pike]

So use this

[compact leaf]

arctan( 2sqrt(4-ab)/(a+b)= arctan(( 2sqrt(4-ba)/(b+a)

@unborn pike

[unborn pike]

Take tan both sides

And simplify it

[compact leaf]

it gives nothing

0=0

[full forum]

@compact leaf Has your question been resolved?

[compact leaf]

@unborn pike

sry for ping

[full forum]

@compact leaf Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[compact leaf]

.reopen

[full forum]

✅

[full forum]

@compact leaf Has your question been resolved?

[unborn pike]

You should send the original question

@compact leaf

[compact leaf]

It is in Hindi

[compact leaf]

.close

[full forum]

Channel closed

Closed by @compact leaf

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[simple crow]

Hello everyone,
I know this is technically physics, but my problem is with the maths. In the attached picture, there is a differential equation (top, green) and then as you can see below it, a change of variables is made (red).
I've tried many times already and I cannot get the simple (blue) equation(i'm new to differential equations).
L, m , k and E are constants.
Thanks!

[full forum]

@simple crow Has your question been resolved?

[full forum]

@simple crow Has your question been resolved?

[full forum]

@simple crow Has your question been resolved?

[full forum]

@simple crow Has your question been resolved?

[full forum]

@simple crow Has your question been resolved?

[trail barn]

rightmost red tells us that $\frac{dr}{dU}=-\frac{L^2}{km}\frac1{U^2}$

chain rule gives $\frac{dr}{d\theta}=\frac{dr}{dU}\cdot\frac{dU}{d\theta}$.

[glossy valve]

Edward II

Edward II

[trail barn]

and so substituting around we have (1): $\frac{dr}{d\theta}=-\frac{L^2}{km}\frac1{U^2}\frac{dU}{d\theta}$

[glossy valve]

Edward II

[trail barn]

we also have from leftmost red (a bit of rearranging and a square) that (2): $\frac{L^2}{m^2r^2}=\frac{U^2k^2}{L^2}$

[glossy valve]

Edward II

[trail barn]

and also (3): $\frac{2k}{mr}=\frac{2k^2U}{L^2}$

[glossy valve]

Edward II

[trail barn]

then substitute into green, (1) is LHS, (2) is 2nd term on RHS, (3) is 3rd term on RHS, and after rearranging everything should cancel out to give you blue

[trail barn]

.

[trail barn]

oh and substitute for the factor on the LHS as well

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cloud crater]

i dont get why these 4 are not the opposite sign

like sin= 1/2 not -1/2

oh nvm i thought cos was y and sin was x but its the opposite

.close

[full forum]

Channel closed

Closed by @cloud crater

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pliant rivet]

I am just trying to review limits but is symbolab right about this?

[pliant rivet]

Why do we add the 2?

[trail barn]

there's no 2 being added, the + means limit from the right

as in from more than 2

[hot herald]

this is only step one of their work

[trail barn]

(it's giving a hint and saying the right side limit is 1, which is correct)

[hot herald]

and only evaluate of the right side limit

supposedly the left side limit in in part 2

with conclusion in part 3

[pliant rivet]

Yeah dang I didnt realize it was one

The diverges part makes sense I just connected the limit with addition for some reason

Thanks

.close

[full forum]

Channel closed

Closed by @pliant rivet

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[marsh tusk]

A sport club is made of year 9 and year 10 students. Last year there were 30 more year 10 students than year 9 students in the sport club. This year, the total number of members has increased by 10%. The members from year 9 have increased by 20% and the members from year 10 have increased by 5%. How many members does the sport club have this year?

[full forum]

@marsh tusk Has your question been resolved?

[torn jolt]

where do u need help wit

[full forum]

@marsh tusk Has your question been resolved?

[torn jolt]

H

[dire swallow]

a convex hexagon ABCDEF with an interior point P is given. Assume that BCEF is a square and both ABP and PCD are right isoceles triangles with right angle at B and C, respectively. Lines AF and DE intersect at G. Prove that GP is perpendicular to BC

[marsh tusk]

how do you solve it?

idk what to do

[marsh tusk]

!occupied

[full forum]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[torn jolt]

start by assigning variables to the numbers of year 9 and year 10 students last year

then make equations between these 2 variables based on your given information

then solve that system of equations (there should be 2 equations)

[marsh tusk]

idk how to make a equation with the percentages though

i did the year 10 = year 9 + 30

[torn jolt]

ok so

a 10% increase in something means that something + 10% * that something

and that something = 100% of that something

so, if you want, a 10% increase of something = 110% that something

makes sense?

[marsh tusk]

um

kinda?

so wha would that look like as a equation

[marsh tusk]

is it year 10=720 year 9=690

i did y=x+30

1.2x+1.05y=1.1(2x+60)

x is year 9 and y is year 10

[torn jolt]

nope

i don't have the same answer

[torn jolt]

should be 1.1(2x+30) on the RHS btw

[marsh tusk]

huh why

[torn jolt]

because total member = x+y

y = x+30

so x+y = x+(x+30)

=2x+30

[marsh tusk]

oh

so is it

x=30

y=60

[torn jolt]

yes

srry for late response

[marsh tusk]

.close

[full forum]

Channel closed

Closed by @marsh tusk

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tiny flame]

is this correct or nah

[glossy valve]

chef

[onyx glen]

i think the way you're notating this is clunky bc you're not letting yourself use the same set of primes for both sides

the crux of the argument is basically in the exponent on 13 in the prime factorizations of a^3 and 13^2 * x^3

[tiny flame]

yes

[onyx glen]

i think the best way to notate this would be to like

let v_p(n) be the exponent of p in the prime factorization of n, optionally mention that it's equivalent to saying v_p(n) is the highest nonnegative integer k such that p^k divides n

then $v_{13}(a^3) = 3v_{13}(a) = 3v_{13}(x)+2$

[glossy valve]

AnnGhost

[onyx glen]

and we get $3[v_{13}(a)-v_{13}(x)] = 2$, which is clearly impossible as 2 isn't divisible by 3

[glossy valve]

AnnGhost

[tiny flame]

when you say the prime factorization of n, what n are you referring to

just any n in naturals

[onyx glen]

just any n

cause im already using it for both x and a

[tiny flame]

ok i gotta think this over, and ill get back to you, thanks for this

[onyx glen]

btw your proof does hold water, it's just style that you've got issues with

[full forum]

@tiny flame Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[faint bobcat]

here only s and then t pair to be found and not t, s pairs right?

[faint bobcat]

<@&286206848099549185>

[pseudo parcel]

for each number in set S there can be 5 other numbers that can be paired with it

and there are 5 numbers in set S

[faint bobcat]

so how should i solve this

[pseudo parcel]

so

5*5

[faint bobcat]

25]

yes if all were different in both

@pseudo parcel

[pseudo parcel]

ah i didnt read properly

[faint bobcat]

25- repeats

but how to find repeats

[pseudo parcel]

ok

one moment

[faint bobcat]

also should we consider (s,t) and (t,s) pairs both or only (s,t) cos considering both types will be like 50 pairs

[pseudo parcel]

i would say consider s,t

then further consider if its repeating

[faint bobcat]

cool but how you got to know to avoid (t,s) from the question

[pseudo parcel]

consider the cases ig

[faint bobcat]

means like how you recognise that you don't need to find t,s pair too

[pseudo parcel]

so for s = 1, repeating numbers would be t=1,2,3,6. this is the case for s=2,3,6

[faint bobcat]

also iam getting 6 repeats of 25

but answer is 14

not 19

[pseudo parcel]

wdym 6 repeats of 25

[faint bobcat]

the p values im getting twice are 6

2,1 3,1 3,2 6,1 6,2 6,3 \

[pseudo parcel]

ok well another way you could do it is list the possible values of p

i.e. brute force

[faint bobcat]

ya i listed bro

25 values i get

from which i said i found 6 to give same p

[pseudo parcel]

try listing out the numbers again

as a matrix perhaps

then simply remove the repeating numbers

once you remove the repeats you will get 14 unique

[pseudo parcel]

you missed out a few then, check again

[faint bobcat]

oh yes

i missed 2,2 1,8 etc

[faint bobcat]

in table you mean

[pseudo parcel]

yes sorry

table

[faint bobcat]

okay got it

[pseudo parcel]

so x axis is set S and y axis is set T

then just multiply together

[faint bobcat]

yeah

thanks man

[full forum]

@faint bobcat Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[red blade]

yo

[red blade]

I'm trying to prove the contradiction: there exists an m, n s.t that there are an even number of ways of filling a (2m) x (2^n - 1) rectangle with 1 x 2 dominoes

so then, I break it up into the case where the first placed block is uh placed like this

and the second placed block is placed like this

.close

[full forum]

Channel closed

Closed by @red blade

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[open quail]

I have a question

[open quail]

can costheta be rewritten as cos^2theta/costheta

[umbral dome]

not sure how useful that is but sure

[tropic canopy]

provided cos theta is not 0

[full forum]

@open quail Has your question been resolved?

[open quail]

I just needed it for a proof

[open quail]

right ok

thanks

[full forum]

Channel closed

Closed by @open quail

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[atomic kayak]

Help

[full forum]

@atomic kayak Has your question been resolved?

[torn jolt]

hi

!status

[full forum]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[runic tapir]

🆘

[torn jolt]

@atomic kayak are you still here

[full forum]

@atomic kayak Has your question been resolved?

[atomic kayak]

Hi

Im still here.

[full forum]

@atomic kayak Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[grizzled patrol]

Heyy i need a bita help w this problem, cant solve it to save my life

[full forum]

@grizzled patrol Has your question been resolved?

[grizzled patrol]

<@&286206848099549185>

[minor crater]

start with the numerator

what does $1-\cos^2(\theta)$ equal to?

[glossy valve]

artemetra

[grizzled patrol]

sin^2x

[minor crater]

great

now, let's tackle the denominator

what's $\sec(\theta)$ in terms of $\cos$

[glossy valve]

artemetra

[grizzled patrol]

1/cos(theta)

[minor crater]

great, substitute that into $\sec^2(\theta)-1$

[glossy valve]

artemetra

[minor crater]

and then simplify

[full forum]

@grizzled patrol Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[grizzled patrol]

.reopen

[full forum]

✅

[grizzled patrol]

oh mb, thanks for your patience

i was out

[grizzled patrol]

so i can sub sec^2x as 1/cos^2x?

[minor crater]

yes

[plain fox]

like sin^2 + cos^2 = 1
1 + tan^2 = sec^2
which u can rearrange into sec^2 - 1 = tan^2

[minor crater]

or you can go like this, yes

[grizzled patrol]

ohh thanks a ton

really saved me there

i will solve it from here, thanks a ton again!

[full forum]

@grizzled patrol Has your question been resolved?

Channel closed

Closed by @grizzled patrol

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[west crescent]

I only know num 1

And im not sure about the answer hahahahaha

Pls help

If you help you will be rich!!!

Hahahahaha

Pls help

[torn jolt]

the only fastest way i can think of is synthetic division

[torn jolt]

how did you tackle it

[warm vale]

or just regular long division

[west crescent]

Long division hahahaha

[west crescent]

I dont know how 😭

[torn jolt]

https://www.youtube.com/watch?v=FxHWoUOq2iQ

[west crescent]

Thank you

.close

[full forum]

Channel closed

Closed by @west crescent

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wise saffron]

Hello

[wise saffron]

How does this prove a number is prime?

[vernal sleet]

To prove a number like 11 is prime using proof of exhaustion, begin by considering the numbers less than the square root of 11 as potential divisors.

[true hemlock]

Prove by exhaustion means exhausting all the possible cases

[wise saffron]

Alrighty

Ty

.close

[full forum]

Channel closed

Closed by @wise saffron

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[unborn trout]

Any tips on solving this?

[unborn trout]

Need to use l'hopital rule

[vernal sleet]

To apply L'Hopital's rule to this limit, differentiate the numerator and the denominator separately and then evaluate the limit again.

[unborn trout]

its still an indeterminate form

if i keep differentiating it, it will still remain indeterminate doesnt it? or did i do something wrong

[limpid moat]

derive another time!

trust me

[vernal sleet]

Your solution is correct. If after differentiating once, the form is still indeterminate, try differentiating again until you obtain a determinate form.

[limpid moat]

as i said..

[limpid moat]

now you can simplify!

[unborn trout]

I get 8/27e

is that correct haahaha

[limpid moat]

no

if you simplify you get $\frac{16}{81e^x}$

[glossy valve]

everg

[unborn trout]

ahh i see

since the denominator is infinty, the asnwer will be zero

alright thank you both so much have a nice day 😄

.close

[full forum]

Channel closed

Closed by @unborn trout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

Hi guys please help me I know I shouldn’t ask for solution but I just don’t get it. Isn’t there only 1 HA which is -1? Also I couldn’t do the VA candidate 0 since I didn’t understand how to steerage it to left hand and right hand side??

[torn jolt]

Yea got it

For HA? @elder remnant

I only see 1 HA which is -1 cuz e^2x/-e^2x which i interpret as -1??

[full forum]

@torn jolt Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[primal dove]

Suppose P(x)=5x^2-14x-3 and Q(x)=2x^2-x-k (with k unknown) both contains a common factor of the form (x-a), where a is an integer. Find the value of k.

[primal dove]

dude i just finished a problem earlier, now there's this one where i cant understand again

my brain melting fr

[torn jolt]

do you know polynomial division

[primal dove]

yea

[torn jolt]

okay so

suggestion: divide P(x) by x-a

[primal dove]

wait i divide that?

[torn jolt]

yes

[primal dove]

but how tho its a variable

[limpid moat]

p(x) contain a most two factor (x-a) ...so you r searching k such that a and a' is a root of Q

[torn jolt]

Thing is

there is a fact that helps you

when you know that (x-a) is a factor of P(x), what does that imply when you divide P(x)/(x-a)?

[primal dove]

it just stays that way??

[torn jolt]

what stays?

like, what im trying to tell you

a polynomial can be represented by its factors

do you agree with the above?

[primal dove]

ye..?

[torn jolt]

right

so $P(x)=(x-a)\cdot \hdots$

[torn jolt]

like you know that a is a factor of P(x), with some other unknown factors

so when we perform P(x)/(x-a)

you get this: [
\f{\map P x}{x-a} =\f{(x-a)\cdot\hdots}{(x-a)}
]

[torn jolt]

which means, P(x) divides x-a with no remainder

[limpid moat]

how can you do this pinky screen ?

[torn jolt]

so you know the remainder of this division would be 0

[primal dove]

O ye

[torn jolt]

if you perform your long division, you would be able to recover the value of a using that

so i think i talked enough, so its better you start doing the division instead of having me dump more at you

[primal dove]

so i can get the value of a by doing long division?

[torn jolt]

yeah just do it dw about the variable being there

just do it normally as you would

take a pic after so i can fact check

also, would you prefer speaking in tagalog than english?

[primal dove]

both is fine, i have knowledge gaps on both languages

[torn jolt]

fair

anyhow, try doing the long division on paper then take a pic or something

[primal dove]

alrr

[torn jolt]

remember, the remainder will be 0

[glass crystal]

hello i'm not sure about long division with a parametrized factor like this

its essentially just asking for a root

just find the roots of the two polynomials no?

for the second one they'll depend on k

[torn jolt]

oh i see i misinterpreted the question and took a roundabout way of doing it

sorry for that

[primal dove]

ye idunno how to divide this help

[glass crystal]

if you could just do long division of a polynomial by x-a and find a

you could find any root of any polynomial

degree >5

so just find the roots for both

and try to make match one of the second with one of the first

and solve for k

[primal dove]

i actually dont know how to start with this

[glass crystal]

you dont know how to find the roots of a quadratic?

[primal dove]

i know but like

[glass crystal]

whats the issue?

[primal dove]

i don't understand what ure saying

[glass crystal]

start by finding the roots of both quadratics

then well carry on

[primal dove]

on like, the p(x) and q(x)?

[glass crystal]

yeah the roots of P and Q

the two solutions to P(x) =0

and the two solutions to Q(x)=0

[primal dove]

okay wait

wait so how do i solve q

there's like a k

i got 3 and -1/5 on p

[glass crystal]

ok do the same for q

but keep the result with ks

inside

they will depend on k

[primal dove]

so what do i put for k?

its just k?

[glass crystal]

yeah

keep k for now

[primal dove]

(1±√1+8k)/4??

[glass crystal]

yeah

so now they ask you to match one of them to the integer root of P

which is 3

it has to be the + version because otherwise you'll get something smaller than 1/4

so you have to solve $\frac{1+\sqrt{1+8k}}{4} =3$

[glossy valve]

Benjamin

[glass crystal]

you get why?

the link between roots and factors

of a polynomial

[primal dove]

Oh

wait so, when i do that, I'll get the value of k??

[glass crystal]

do you get why i tolf you to do that?

[primal dove]

yeaa

[glass crystal]

ok

so now you just need to do it

[primal dove]

wait whats the connect of the lesson factor theorem in this problem then

[glass crystal]

whats factor therorem to you?

[primal dove]

i dont rlly get the definition, our teacher didn't define it well

[glass crystal]

cant you read it somewhere?

in your class material

[primal dove]

ye so, the problem is im dyslexic

im trying tho

[glass crystal]

im sure ill understand even with misspelling unless you havr trouble reading

[primal dove]

ye i do have trouble with reading than spelling

[glass crystal]

ok

so i cant help you much lol it will be the same if i give you a written definition

like you are reading what im szying rn no?

but also idk what exactly your teacher called factor theorem exactly

idk what it actually is

[primal dove]

yea

so the k i got is 15

[glass crystal]

so idk avout factor theorem but the fact we use here

is that if a is a root of a polynomial then (x-a) is a factor of the polynomial

[vast fossil]

They probably meant the root-factor theorem which states that a polynomial is divisible by (x - a) if and only if a is one of its roots

[glass crystal]

and reversely

[vast fossil]

Yeah

[glass crystal]

yeah

[primal dove]

what

[glass crystal]

what what

[vast fossil]

(x - a) is a factor of a polynomial f(x) if and only if f(a) = 0

[primal dove]

but is the solution we used right

i mean its right but

[glass crystal]

yeah but we are trying to explain why we did that since you asked

[glass crystal]

.

[primal dove]

is there also a way where the solution is somehow like this

[glass crystal]

back to long division

oh we could do that aswellsince we know the root

this would be : find the roots of P then pick the integer one (3)

then do long division with (x-3)

or use this theorem i dont know

[primal dove]

o like the a would turn into 3?

[glass crystal]

i probably know it but not by its name i mean

[glass crystal]

since thry say a is an integer and (x-a) is a factor of P then a is a root of P and 3 is the only integer root of P so yes

[primal dove]

how about in Q

[glass crystal]

wdym?

then you know you want (x-3) to be a factor of Q

so apply your theorem i think

[primal dove]

O okiii

[glass crystal]

or do it as we did

using the link between roots and factors

[primal dove]

im gunno consider both because i just need to understand it

[glass crystal]

gl

[primal dove]

tenkyou

this is the last this night, i feel like i bothered 3 tutors so-

.close

[full forum]

Channel closed

Closed by @primal dove

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

why is it n-1 and not just n

if they're saying it loses 7/8 each bounce then on the first bounce it should not rebound to 36

[full forum]

@torn jolt Has your question been resolved?

[full forum]

@torn jolt Has your question been resolved?

[dark frost]

well no... all the bounces act the same

its dropped at an initial height and the first bounce it loses energy

oh yeah

nvm im dumb i agree with you

perhaps your setup of a1 = 36 is incorrect

id say a0 = 36 and the first bounce is a1 = 36 × (7/8) and a2 = 36 × (7/8)² etc etc

[full forum]

@torn jolt Has your question been resolved?

Channel closed

Closed by @full adder

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[final palm]

I have this mixing problem i am trying to set up a system of equations for. I get how to set up the change with the pure water, but i dont get how to do when the pure water is changed to a salt solution

[final palm]

with pure water i got this. it gives it you actually and its right

but im lost on how add the mixture in place of pure water

its a mixture of 2 pounds of salt per gallon

nvm i got it

.close

[full forum]

Channel closed

Closed by @final palm

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[silent cairn]

I tried 0 for the may 1 balance and still got wrong did I miss any steps?

[full forum]

@silent cairn Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wanton mesa]

the answer for d)

they did n*p = 75 x 0.14

which is 10.5

why do you need that?

they said 4 beads is < 10.5 so p(x<=4)

if the value is lower than expected value you do p(x<="value') ? and vice versa?

[full forum]

@wanton mesa Has your question been resolved?

[wanton mesa]

<@&286206848099549185>

[full forum]

@wanton mesa Has your question been resolved?

Channel closed

Closed by @wanton mesa

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lilac junco]

hi

[lilac junco]

im stuck on this part

[slate scarab]

man i wnated to use it

[lilac junco]

these are the theorems that relate to this part i think in the lecture notes

and this is the workings ive done so far

im not really sure how to proceed with answering this next part, i assume its easy but i would like to understand what they are asking better

right now all i know is that y must be >= 0 otherwise the root will be a negative root right?

and its not an IVP yet so im not sure how to proceed

[full forum]

@lilac junco Has your question been resolved?

[lilac junco]

<@&286206848099549185> ik u are busy sorry

hello

[wanton mesa]

uni stuff?

[lilac junco]

ye

[wanton mesa]

idk btw

what course u studiying?

[lilac junco]

maths

[wanton mesa]

cool

yh im pre uni so idk soz

try <@&286206848099549185> again

[hasty wing]

I think you did everything correctly

[lilac junco]

yeah im just stuck on what to do next

[hasty wing]

What more is there to do?

[lilac junco]

i havent done that part yet

[hasty wing]

If you are allowed to have complex solutions, then you don't need to worry about the roots

If you want real solutions, make restrict y

Then draw some graphs

[lilac junco]

so y >=0?

[hasty wing]

yeah

[lilac junco]

thing is though theres just random constants in the solutions

which graph would i be drawing, the initial linear equations i got or the solutions to those

[hasty wing]

Each choice for that constant is a different solution

[lilac junco]

so theres infinite solutions then?

[hasty wing]

That's why it says "representative selection"

Yes

Without initial or boundary conditions

[lilac junco]

so whats the interval? its defined for y>=0 is that it?

[hasty wing]

You have an expression for the solutions in terms of the constants and x

[lilac junco]

yeah

[hasty wing]

Restrict that to be positive and you will get a restriction on x for every choice of c1

[lilac junco]

oh ok

so just solve for c1 basically

?

in each solution

[hasty wing]

I would solve for the restriction on x in terms of c1

Then the interval would be defined for every choice of c1 you could make

If you want to draw a graph for a specific solution, you can choose c1 arbitrarily

[lilac junco]

oh I think i get it

ill try

i wont close this just yet

[hasty wing]

I may or may not be around, but you can always ping if it's been longer than 15min

[lilac junco]

ok thanks

[hasty wing]

(ping helpers not me, to be clear)

[lilac junco]

ive gotten this for the first one

not sure how this helps tbh

oh wait

one sec

let me just sub in for c1

no that was silly

just get 0=0 lmfao

yeah dont really know what to do from here

oh

[hasty wing]

Factor?

[lilac junco]

its just x >= -c1/2

yeah i just went back in my workings

and realised i had it factorised before

and it made it more obvious

the restriction is the same for both

right?

[full forum]

@lilac junco Has your question been resolved?

[lilac junco]

<@&286206848099549185> is this the correct way of phrasing my answer

[hasty wing]

I haven't checked that the restriction is the same for both. But if so, I think the answer is fine

[full forum]

@lilac junco Has your question been resolved?

[full forum]

@lilac junco Has your question been resolved?

Channel closed

Closed by @lilac junco

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wheat garden]

find the absolute maximum value of $y=\sqrt[x]{x}$

[glossy valve]

Jash

[wheat garden]

do you rearrange it so u get y^x=x and then implicitly derive wrt x

[mossy vessel]

That is one method of doing it

another option is very similar is to use logarithmic differentiation

By taking the natural logarithm of both sides:

[wheat garden]

i got y^x *lny=1

wait

(x^1/x)^x*1/xlnx=1

[mossy vessel]

hmmmm

[wheat garden]

lnx=1

[mossy vessel]

there should be a y' somewhere

[wheat garden]

ye i replaced it with 0

[wheat garden]

yo so x=e

y=e^1/e

[gritty rose]

,w min x^(1/x), x>0

[mossy vessel]

you are right, though I don't understand the method you took haha, y = e

[mossy vessel]

maxima

[wheat garden]

y^x * (ln(y) + x(y'/y)) = 1

[glossy valve]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by rie.mann

[mossy vessel]

ahh gotcha

[wheat garden]

and then replaced y’ with 0

then substituted x^1/x for y

[mossy vessel]

I would've just done implicit differentiation on $\ln(y) = \frac{1}{x}\ln(x)$, but whatever worked for you haha

[glossy valve]

Ammardian

[wheat garden]

would you replace x^1/x as e^(lnx/x) otherwise

[full forum]

@wheat garden Has your question been resolved?

Channel closed

Closed by @wheat garden

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[unreal seal]

stuck again

[stiff summit]

can you show your work?

[unreal seal]

yes

[spiral vigil]

b is related to h

[unreal seal]

how so

should i set h = 4 instead of 12

also shouldn't db/dt = 0

[stiff summit]

By similar triangles

[unreal seal]

so i should set up a proportion?

[stiff summit]

What do you mean

[unreal seal]

nvm

is db/dt = 0?

because the size of the base doesn't change or does it

[stiff summit]

The surface area of the water grows as more water enters the pyramid

[unreal seal]

true

you're right about that

[stiff summit]

yes it does, because at the bottom, it’s close to a point, but at the top, it’s the whole base

[unreal seal]

do i have the volume formula correct

[stiff summit]

the volume formula on the first line is correct

[unreal seal]

ok

i was iffy about that

[unreal seal]

is it that 12dh/dt = 7db/dt?

[spiral vigil]

other way around i think?

[unreal seal]

ok i was thinking that

nvm

ran out of time thanks guys

.closw

.close

[full forum]

Channel closed

Closed by @unreal seal

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tepid elk]

Hi

[tepid elk]

i've been using differential equations and i know how to operate them by treating other variables as constant so if we had two varaible x,y then they would be indepdent of each other

is there any other basic knowledge i should know as a foundation, because i don't understand the reason why we use partial derivatives instead of full derivatives for some equations

is the only reason because we just leave all the other variables as constant

or is there something else to it

sorry if im being confusing

[full forum]

@tepid elk Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[surreal lantern]

please help

[full forum]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[surreal lantern]

2

<@&286206848099549185>

[full forum]

@surreal lantern Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

@kindred spire Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

hey can someone help me with integers

[full forum]

Please don't occupy multiple help channels.

[torn jolt]

hey can someone help me with integers

[glacial pasture]

!onechannel

[full forum]

Please stick to your channel.

[glacial pasture]

.close

[full forum]

Channel closed

Closed by @glacial pasture

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sleek basin]

how do i differentiate qns 3

[willow sun]

what have u tried

[sleek basin]

i’m sort of new so i’m not too sure should i use product rule on here

yeah

i tried to differentiate it normally out

[willow sun]

yes you should apply product rule

[sleek basin]

is it for the 3x and the cos(5x)

and the other one?

[willow sun]

for both

[rare yoke]

What is answer for x³+x

[sleek basin]

something like that?

3cos5x - 15xsin5x-5tan3x

[willow sun]

there will be another term

when you differentiate 5xtan3x

you forgot to differentiate the tan part keeping the x as it is

[sleek basin]

but isn’t tan(3x) = sec^2(3)?

[willow sun]

a 3 will also come out due to chain rule

[sleek basin]

ah ok

but how do we get rid of the sec^2

[willow sun]

why do you want to get rid of it

its a part of your answer

[sleek basin]

the answer don’t have sec^2 tho (qns3)

[willow sun]

i can see it clearly tho

its in the second line

[sleek basin]

o lmao

[willow sun]

the answer spans two lines

[sleek basin]

i dint see haha

mb

[willow sun]

lmao np

[sleek basin]

thanks for your help btw

.close

[full forum]

Channel closed

Closed by @sleek basin

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

Do i need to solve for x?

[willow sun]

no

just look at the graph

[uncut shadow]

Check the graph

[willow sun]

how do you think you can interpret 3x-4>1/2 2^x graphically

[torn jolt]

Uhh

Idk

[willow sun]

3x-4 and 1/2 * 2^x both represent the y coordinates

[torn jolt]

I don't get what the question is asking for

[willow sun]

ok lets understand that first

its asking you

for what values of x will the expression

3x-4

be greater than

the expression 1/2 2^x

[torn jolt]

How can a graph be bigger than another one i don't think i understood it well

Ohh

[willow sun]

now the graph y=3x-4 is nothing but

a figure which shows the values of y

as x varies

with this constraint

[torn jolt]

Can i just check each option one by one?

[willow sun]

no need

[willow sun]

which means

the y coordinate or the height

tells you the value of 3x-4 at different values of x

for example if you draw a vertical line at x=1

and see where it cuts the graph of 3x-4

you will get the value of 3x-4 at x=1

[torn jolt]

Oh ok

[willow sun]

now if you want to compare which one is greater at a particular value of x

3x-4 or 1/2 2^x

you can look at the y coordinate, or the height at that x

is that clear?

[torn jolt]

Yeah i think

[willow sun]

now look at your problem

and the heights that these two graphs

give at different values of x

and observe for what values

is 3x-4 greater than 1/2 2^x

[torn jolt]

Alright

For 2 to 4 right?

This part

[willow sun]

yes

[torn jolt]

Alright ty for the help

.close

[full forum]

Channel closed

Closed by @tired obsidian

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fluid prawn]

Help

[full forum]

@fluid prawn Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sturdy mango]

Convergence or divergence of this series

[sturdy mango]

I set it up with the integral test but now im stuck so im guessing thats not the right way to go about this, what method should i use?

[onyx glen]

the first thing you should check for ANY series that you can't immediately pin down

is whether its terms approach 0

[sturdy mango]

2^n goes to infinity and bottom too right?

[onyx glen]

sure does, but one of these grows SIGNIFICANTLY faster than the other

[sturdy mango]

2^n

[fast peak]

no that is not how fractions work

[onyx glen]

(n+1)/2 = n/2 + 1/2 yes

but its a pretty egregious error youve made just now thinking a/(b+c) = a/b + a/c.

it's like "go back to algebra or maybe pre-algebra" egregious