help-28

[proven jay]

but how i do find it otherwise

[desert steppe]

*tan(m) = x/y

[full forum]

@proven jay Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mighty crescent]

From the graph, you can see the local minimum and local maximum

[strong ferry]

I havent done this before can you elaborate

I need to find out the minimums too

@mighty crescent

[mighty crescent]

Do you know what local minimum and local maximum mean?

[strong ferry]

no

[mighty crescent]

Local maximum is the left one and local minimum is the right one

[strong ferry]

how do I find -1 and 17

I think I see

[mighty crescent]

You substitute into the expression for the function

[strong ferry]

the maximum is over (-1,0) and then I plug in -1 to the function to get the second number

ty ty

what does this mean? @mighty crescent

[empty sapphire]

the maximas are y outputs. You'd find the value by plugging them into the equation above.

In this case something like this

,w 2(-1)^3 - 6(-1)^2 - 18(-1) + 7

[glossy valve]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by mellowdramallama

[empty sapphire]

so that's your relative maximum

[strong ferry]

I got that part

does the part I underlined mean anything?

[empty sapphire]

not really, that's just the graphing window. It's says that the x values are from -5 to 5 with each tick being 1 unit and the y values are form -60 to 60 with each tick being 10 units

[strong ferry]

ah ok thank you

.CLOSE

.closer

.close

[full forum]

Channel closed

Closed by @strong ferry

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[plain fox]

where am i wrong ?

[full forum]

@plain fox Has your question been resolved?

[plain fox]

<@&286206848099549185> pls help

[winter yacht]

Shine some light or retrace your work, it's difficult to comprehend.

[plain fox]

it is clear

[winter yacht]

Wait, sorry

my brightness was low lol

Gtg sorry

[plain fox]

[lusty vector]

i think u can use agp here

[plain fox]

whats agp?

[lusty vector]

arithmetic-geometric progression

[plain fox]

no i need to use binomial

[full forum]

@plain fox Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[plain fox]

.

can someone help me with this?

[mighty crescent]

What if you just solve the quadratic first

[lost lichen]

Hello

Can you help with vector

[mighty crescent]

Please go to an available help channel, like #help-20, and read #❓how-to-get-help

[plain fox]

u mean using quadratic formula?

[mighty crescent]

or by completing the square

[plain fox]

but that i cant use that , i have to use binomial

if i could use those methods , this question was a piece of cake

but i have to use the binomial and stuff

[full forum]

@plain fox Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[civic reef]

can anyone solve?

[full forum]

Please don't occupy multiple help channels.

[narrow helm]

close either this or your previous channel.

[civic reef]

they are both different questions

i'll ask this later after the prev is solved then

.close

[full forum]

Channel closed

Closed by @civic reef

Use .reopen if this was a mistake.

[civic reef]

.close

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

@atomic kayak Has your question been resolved?

[full forum]

@atomic kayak Has your question been resolved?

[atomic kayak]

<@&286206848099549185>

[gilded panther]

yess

[strong galleon]

Can someone please explain this to me?

<@&286206848099549185>

[mighty crescent]

please read #❓how-to-get-help

[full forum]

@atomic kayak Has your question been resolved?

[atomic kayak]

No

[full forum]

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hushed tendon]

Hey

[hushed tendon]

What am I missing here? how did she get to this?

[vast fossil]

It's by definition

[hushed tendon]

what happened to m+1?

[narrow helm]

n+1 can be written as (n + m + 2)-(m+1)

[vast fossil]

Got rewritten as (n + m + 2) - (n + 1)

If you still don't understand, try rewriting the right hand side using the definition (a choose b is equal to a!/((a - b)!b!))

[hushed tendon]

alright thanks

.close

[full forum]

Channel closed

Closed by @hushed tendon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

how do i solve this

[torn jolt]

can you help me

[vast fossil]

Express P_n(-x)

[torn jolt]

it

basically x^k becomes (-x)^k

[vast fossil]

Right, which is the same as (-1)^k x^k

The two (-1)^k's will combine into just 1

So you have $P_n(-x) = \sum_{k=0}^n\frac{1}{k!}x^k$

[glossy valve]

A Lonely Bean

[torn jolt]

what happened to the k!

?

oh

im kind of confused

[vast fossil]

By what exactly?

[torn jolt]

are u saying this

[torn jolt]

is equal to this?

[vast fossil]

Yes, because (-1)^k * (-x)^k = (-1)^k * (-1)^k * x^k = (-1)^2k * x^k = ((-1)^2)^k * x^k = 1^k * x^k = x^k

[torn jolt]

ok fine

makes sense

[vast fossil]

Now it looks like you need to use the formula for multiplying power series together

[torn jolt]

what is the formula

[vast fossil]

$\left(\sum_{k=0}^\infty a_kx^k\right)\left(\sum_{k=0}^\infty b_kx^k\right) = \sum_{k=0}^\infty\left(\sum_{i=0}^na_ib_{n-i}\right)x^k$

[torn jolt]

omg!

[vast fossil]

Oh wait it should be k instead of n

Hold on

[torn jolt]

amen！

[glossy valve]

A Lonely Bean

[vast fossil]

So in this case we have a_k = (-1)^k/k! and b_k = 1/k!

Hold on P_n isn't a power series, it's a polynomial

[torn jolt]

amen...this isnt calculus

[sharp flame]

Wait is this a thing

[vast fossil]

Well the formula for multiplying polynomials is not so different, it's just
[ \left(\sum_{k=0}^n a_kx^k\right)\left(\sum_{k=0}^nb_kx^k\right) = \sum_{k=0}^{2n}\left(\sum_{i=0}^ka_ib_{k-i}\right)x^k ]
As far as I remember

[sharp flame]

💡

[vast fossil]

Yes, multiplication of power series is defined using the convlution too

[sharp flame]

No I meant that pattern

I'll stop channel clogging now

[vast fossil]

What pattern

[sharp flame]

But that's cool

a_(i)a_(n - i)

[vast fossil]

I'll show later why that works

[glossy valve]

A Lonely Bean

[vast fossil]

Anyway here we are gonna have a_k = (-1)^k/k! and b_k = 1/k!

So $P_n(x)P_n(-x) = \sum_{k=0}^{2n}\left(\sum_{i=0}^k\frac{(-1)^i}{i!}\frac{1}{(k-i)!}\right)x^k$

[glossy valve]

A Lonely Bean

[vast fossil]

Hmm

[torn jolt]

amen

[vast fossil]

It looks like we need to consider the cases of k being even or odd

If k is odd, then every ith term gets cancelled with the (k - i)th term

So we look at only even k

I.e., $P_n(x)P_n(-x) = \sum_{k=0}^n\left(\sum_{i=0}^{2k}\frac{(-1)^i}{i!(k-i)!}\right)x^{2k}$

[glossy valve]

A Lonely Bean

[torn jolt]

ok

[vast fossil]

Now you may notice that every ith term in that sum is equal to the (2k - i)th term, we can add them up

Except for the central term, since it is not paired with a term equal to it (since i = 2k - i for that term)

[torn jolt]

ok

[vast fossil]

Eh this doesn't seem to be going anywhere

I'll let you know if I come up with the solution

[torn jolt]

ill ask my professor

[vast fossil]

Oh it's you

[torn jolt]

?

.close

[full forum]

Channel closed

Closed by @mental cedar

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[misty flare]

Hey guys. I need help on how to calculate this

[torn jolt]

Are you aware of sine law

[misty flare]

no

[willow sedge]

if two triangles are equal then ratio of corresponding sides should be equal

[misty flare]

thanks

.close

[full forum]

Channel closed

Closed by @misty flare

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lucid hill]

I want to sort n marbles into n/m bags of m marbles each. The marbles are colored, and there are c(i) marbles of color i. Bags cannot contain more than 1 marble of each color.

How many ways can I do this?

I can do it ignoring colors, but after a while I haven't found a viable solution to exclude color repetitons besides brute force. And I'm dealing with around 50 marbles, so that is not possible.

This is not related to any study or work, so I don't even know if it's possible to find a simpler solution.

[full forum]

@lucid hill Has your question been resolved?

[full forum]

@lucid hill Has your question been resolved?

[full forum]

@lucid hill Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lucid void]

I have this math problem that looks like this. I have to find both solutions for x. I was able to find x = 3 but it says the other solution is x = 7 and I’m not sure how they got that answer. Can anyone explain?

[quaint prawn]

@rare dock snow

[rare dock]

snow

[gritty rose]

Square both sides, isolate the square root, then square again

[vast fossil]

Could you show your work?

[lucid void]

Sure I’ll show what I did to get 3

So here’s how I got 3 and I checked it at the bottom

[gritty rose]

Yea that's wrong

,tex .freshman

[glossy valve]

riemann

[gritty rose]

But also you didn't square the right side

[lucid void]

Oh when I do that I get x = 4 which is wrong

[gritty rose]

Right. It's wrong for two reasons

But somehow they cancelled each other and got the right answer

[gritty rose]

Go back to this

(a+b)^2 = ?

[lucid void]

I should end up with 5x+1 - 3x-5 = 4 right?

[full forum]

@lucid void Has your question been resolved?

[full forum]

@lucid void Has your question been resolved?

[gritty rose]

No

[gritty rose]

You're still making this mistake

[gritty rose]

Answer this

[full forum]

Channel closed

Closed by @lucid void

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[split saffron]

I got this question incorrect, can someone tell me which one of these was the correct answer, and why that is the case?

[split saffron]

The slices are perpendicular to the y axis, so I believe I would take the integral with respect to x, and since it is a square, I think the correct answer would have been the one above what I chose.

.close

[full forum]

Channel closed

Closed by @split saffron

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

hello, could someone explain me this please, is about variations in combinatorics, without repetition

I don't get (n-k+1)

the other part I get it

[restive sigil]

it's basically multiplying k numbers starting from n and going down

[torn jolt]

yes

but I think they answers would be different

[restive sigil]

what do you mean?

[torn jolt]

mm w8

I think there should be a parenthesis like this ((n-k)+1) or is it not necessary?

[restive sigil]

not necessary, they mean the same thing

[brave blaze]

(n-k)+1 is the same as n-k+1
what is your point

[torn jolt]

see

this

ignore the R/F

is not the same

[brave blaze]

because you didnt apply the formula well

[torn jolt]

why

[brave blaze]

7x6x3

you wrote this

[torn jolt]

Yes

but it's okay

[brave blaze]

and whats the formula saying ?

[torn jolt]

(n-k+1)

[brave blaze]

before that

[torn jolt]

n (n-1)(n-2)......(n-k+1)

[brave blaze]

yes

so why did you jump from 6 to 3

you forgot something

also its not really 3

[torn jolt]

7x6x5x4x3

?

is not the same

also

I wanted to see how to get only 5

[brave blaze]

if you take k = 3, you have this :
7x6x5

not 7x6x5x4x3

[torn jolt]

but you need a parenthesis

because you could do (n-(k+1)) as well

[brave blaze]

?

n-(k+1) = n-k-1

not the same thing with your formula

dont put parenthesis where there is none

or at least know how it works

[torn jolt]

oh okay, I calculated it like this n-(k+1)

[torn jolt]

I don't have teachers

[brave blaze]

sadge

[torn jolt]

this is why

I come here

[torn jolt]

thanks so much 🙂 I made this mistake that now I will pay attention to, sorry for this stupid error

[brave blaze]

no problemo

[torn jolt]

.close

[full forum]

Channel closed

Closed by @iron swan

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slender pond]

For B why doesn’t reverse chain rule work?

[slender pond]

1b?

[brittle steeple]

reverse chain rule?

[kind jay]

Is that integration by parts?

[brittle steeple]

it would be u-substitution

[slender pond]

Yes I’m supposed to use that

[brittle steeple]

integration by parts is reverse product rule

[kind jay]

U can apply ibp many times, not only once

[brittle steeple]

ye we'll need to see more work to understand what you're trying to do

[slender pond]

Ok

Why does the method I use work on the right but not for the one on the left

@brittle steeple @kind jay

[brittle steeple]

i don't know what your method is

first you have written

y = e^(6x^2-1)

and then later you have written

y = 1/2 * e^(6x^2-1)

you are aware these are different things, right

so y cannot equal them both

[full forum]

@slender pond Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[leaden gust]

Hi, this a practice question and I need help in finding the domain and range with X intercept and y intercept, this might be easy but I’m stuck for the domain is it (0, infinty)?

[quaint prawn]

no

[rough tundra]

why would domain be (0,inf)?

[quaint prawn]

the domain is all of the x-values you can put into the function

[leaden gust]

This is why I’m kinda confused with domains only for this graph

I see

[quaint prawn]

looking at this, can you put in x-values of 0 or below?

[leaden gust]

Yes I think so

[quaint prawn]

you think so? or yes

[leaden gust]

Yes

[quaint prawn]

Yes, you can.

are there any x-values that you can't put in?

[leaden gust]

Yes, any value above 0?

(Idk if I’m right)

[quaint prawn]

why

[leaden gust]

Wait so this graph the thing I’m confused with is it does not touch the X axis I think bcos both the arrows are in y axis as I see it, but I know I’m wrong

[quaint prawn]

why does it matter if it touches the x-axis

but clearly it does not

[leaden gust]

So if it doesn’t touch the X axis at all and the domain should be the values of X axis, does this mean the domain is 0?

[quaint prawn]

nope

[leaden gust]

Oooo so it’s all the values

[quaint prawn]

domain has nothing to do with the x-axis

[leaden gust]

I see

[quaint prawn]

the domain is the set of all x-values you can input into your function

remember what functions do

they take something in (inputs)

and spit something out (outputs)

[leaden gust]

True

[quaint prawn]

so the domain is all of the possible inputs

an easy example is something like
y=x

what can you put into this?

is there any limitations on what x is?

[leaden gust]

Nope

Anything

[quaint prawn]

so the domain is (-inf, inf)

[leaden gust]

From negative to 0 and above

Yep

[quaint prawn]

and another good example is

y=1/x

[leaden gust]

Ooo

[quaint prawn]

can we put everything into this?

or is there something tricky

[leaden gust]

1/c is not a fixed value so it depends on the value of X

So I think we can

Yes

We can

[quaint prawn]

what about x=0

if f(x)=1/x what is f(0)?

[leaden gust]

It’s 1

[quaint prawn]

1/0 = 1?

[leaden gust]

Oh no , it’s 0

My bad

[quaint prawn]

1/0 = 0?

[leaden gust]

Anything divided by 0 is 0

So yes

[quaint prawn]

no

you can't divide anything by zero

[leaden gust]

Wait so no result?

[quaint prawn]

exactly

1/0 is undefined

[leaden gust]

I see

[quaint prawn]

you can't put x=0

so 0 isn't in the domain

[leaden gust]

that’s why I got my answer wrong

Bcos I put 0 as domain

[quaint prawn]

No

[leaden gust]

And 0 cannot be domain

[quaint prawn]

No

The domain of a function, depends on the function

for y=x

[leaden gust]

Yes

[quaint prawn]

x can be 0

0 is in the domain of y=x

but for y=1/x

it is not

it depends on the function

so 0 is in the domain of some functions, and not in the domain of some other functions

[leaden gust]

makes sense so it depends on the function

[quaint prawn]

Yes

[leaden gust]

Got it

[quaint prawn]

Rinz let me show you a quick example of something

[leaden gust]

Yes please

[glossy valve]

Austin

[quaint prawn]

what is the solution of this?

[leaden gust]

2x= X, so 2x-x = -x , x=0?

[quaint prawn]

x=0, yes

but what if you took $2x=x$

[glossy valve]

Austin

[quaint prawn]

and divided both sides by x

then you would have

$2=1$

[glossy valve]

Austin

[leaden gust]

True

[quaint prawn]

well this is clearly not true

so how did we get this false statement?

can we not divide by x?

well

since x is 0

you can't divide by 0

otherwise

2=1

and other bad things

[leaden gust]

Yep true if u can’t divide by 0 then it’s 2=1

I see

[quaint prawn]

so how about you try this, what is the domain of $f(x)=\frac{1}{1-x}$

[glossy valve]

Austin

[quaint prawn]

what x-values can you not put in?

[leaden gust]

It cannot be equal to 0

Bcos division by zero is undefined

[quaint prawn]

what cannot be equal to 0

be more specific

[leaden gust]

The 1-x cannot be equal to 0

[quaint prawn]

which means x cannot equal what?

[leaden gust]

0 so we do X=1 and solve for it

But

[quaint prawn]

yeah, so x cannot equal 1

[leaden gust]

X cannot be equal

Yes

So it will be

All real numbers except x =1

[quaint prawn]

yes

which you write like this

[leaden gust]

Phew

[quaint prawn]

(-inf, 1) U (1, inf)

[leaden gust]

Yep got it

[quaint prawn]

great

so back to your question

[leaden gust]

only u could make me understand ngl

Yes

[quaint prawn]

let us continue with the domain here then

what do you think is the domain now

[leaden gust]

Oh yes also the functions are f(-4) and f(3) for that question

[quaint prawn]

Those aren't functions

[leaden gust]

Values

[quaint prawn]

if there is more information though just send a picture please

[leaden gust]

Yes

[quaint prawn]

so I can understand what you mean better

[quaint prawn]

okay so

what it is saying is to evaluate the function at x=-4 and x=3

that is just another one of the things you need to do

[leaden gust]

Yes

[quaint prawn]

but let us take it one step at a time

starting with the domain

[leaden gust]

Yes the domain

[quaint prawn]

What do you think the domain is now?

[leaden gust]

(-inf, 1)

[quaint prawn]

no, the domain of the function in your question

not the example I gave

this is a graph of your function

[leaden gust]

Wait so it has a arrow

Means it can’t be infinite

Right

Nvm its@oppisite

Arrow means infinite

So domain would be

(2,-inf)?

I’m confused about this graph ngl

[quaint prawn]

No, stop for a second, I'll try to explain

[leaden gust]

Yes

[quaint prawn]

your screen is not infinitely large right

so you can't see all of the graph

the arrow just indicates that it keeps going

even though you can't see all of it

because your screen is not big enough

[leaden gust]

True

[quaint prawn]

so all the arrow means, is that the graph keeps going in that direction

even though the graph gets cut off on your screen

Now, as for the domain, remember what we are looking for.

Are there any x-values that you can not put into this function?

If there were, they would not have a cooresponding y-value on the graph

So what do you think is the domain?

[leaden gust]

Then it should be infinite

[quaint prawn]

By infinite, do you mean that we can put all x-values into our function?

[leaden gust]

We can put all values of X in this, yeah

[quaint prawn]

so then the way you write that is:
(-inf, inf)

do you understand?

[leaden gust]

Yes I have better clarity now

I’m not looking at what numbers the arrows are on instead what all they can have values for

So it’s better

[quaint prawn]

Okay great. The next part of your question asks for the range

[leaden gust]

Yes

[quaint prawn]

the range is similar to the domain

so, now you know that the domain is all x-values you can put in

the range is all y-values you can get out

[leaden gust]

Got it

[quaint prawn]

so look at your graph

are there any y-values your graph does not touch?

[leaden gust]

Yep

1

[quaint prawn]

that's true

it also doesn't touch anything below 1 right

[leaden gust]

Yes it does not

So 1 and below

[quaint prawn]

what about 1.5

does it touch 1.5?

[leaden gust]

Oh wait so it’s 2 and above

[quaint prawn]

Do you mean the range is 2 and above?

[leaden gust]

It doesn’t touch 1.5 or 1 or below but it touches 2 to be exact

[quaint prawn]

True

[leaden gust]

So basically the graph is intercepting 2 and going above

[quaint prawn]

it does not touch anything below 2

so the range is 2 or above

right?

[leaden gust]

Yes nothing below 2

Yes

[quaint prawn]

okay

try to write that

in a proper interval

[leaden gust]

So it will be (2, infi)

A question

[quaint prawn]

not quite

[leaden gust]

Do we write infi in front of@the number

[quaint prawn]

the open bracket means that you are excluding 2

it is [2, inf)

meaning that we are including 2

[leaden gust]

Ooo I see

[quaint prawn]

and we write infinity after the 2 because it is larger than 2

[leaden gust]

So always [, to include

[leaden gust]

Got it

[quaint prawn]

to include yes

so rewrite it again

the proper way this time

what is the range?

[leaden gust]

[2,infi)

Right

[quaint prawn]

good job

yes

[leaden gust]

yes got it

[quaint prawn]

The next part asks about the x-intercepts

[leaden gust]

Yes

[quaint prawn]

that is when the function touches the x-axis

does your function ever touch the x-axis?

[leaden gust]

It does not have X intercepts

Nope

[quaint prawn]

yea

thats correct

[leaden gust]

yes

[quaint prawn]

what about the y intercept

the y intercept is when your function touches the y-axis

does your function ever touch the y-axis?

[leaden gust]

but for y intercepts where it touches the y axis , there is 2

Yes

[quaint prawn]

so the y-intercept is 2

[leaden gust]

Yep

[quaint prawn]

you wrote 2, infinity

but it is only 2

[leaden gust]

Also a question , there can’t be more than 1 y intercepts right?

[leaden gust]

Oh I see for range ?

[quaint prawn]

there can be

no, i am looking at the second picture you sent

[random isle]

yo can someone help me out with interval notation

increasing and decreasing intervals

[quaint prawn]

this channel is occupied, read #❓how-to-get-help and open an available channel

[leaden gust]

Oh yea my bad i wrote that before but now I understand

[quaint prawn]

okay just making sure 👍

[leaden gust]

Now the last question

It asks us about values of functions

[quaint prawn]

yes it asks for f(-4) and f(3)

[leaden gust]

yes

[quaint prawn]

this is saying, what is your function when x=-4, and what is your function when x=3

you should be able to tell by looking at your graph

[leaden gust]

Yep

[quaint prawn]

great, all done then! good work

[leaden gust]

Wait so for -4 it doesn’t touch anything

For the value

Yep other than that we are done

Thank you so much @quaint prawn !

[quaint prawn]

What do you mean? f(-4) is asking for the y-value of your function when x=-4

[leaden gust]

Yes got confused for a second, i got the values it’s correct :DD

[full forum]

@leaden gust Has your question been resolved?

Channel closed

Closed by @leaden gust

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[elfin hound]

Can someone just explain the mapping, domain and range to me? I'm aware of what all three mean but just in this context because I missed the lesson these notes are from.

[elfin hound]

Like why is it X+2 for the mapping and not X-2?

And how they got the domain and range

[white geyser]

are you sure those answers are right

[elfin hound]

its what the teacher did for notes

[white geyser]

are those circles on the original curve hollow or filled in

[elfin hound]

it looks hollow?

idk if thats important tho

i just wanna know why (x-2) makes it move 2 units right and not 2 units left?

[white geyser]

its important because for the domain and range you used brackets, which implies a closed interval ( including end points)

i've never seen mapping used in precalc context, but i assume its because they want the translations to reproduce the old function from the new one?

[elfin hound]

the graph doesn't continue in the sketch so ig it is closed

[white geyser]

if the circles are hollow it should be open interval, since those points aren't defined.

but its hard to tell from the picture

[elfin hound]

i just wanna know the whole x thing

does (x-2) not mean you're - 2 from the original x values?

if not

then does

[white geyser]

x+2 would undo the translation of the transformed function

[elfin hound]

(x+2) make it translate left?

but shouldn't adding make the graph go right? and taking make the graph go left?

thats how the x axis works

[white geyser]

g(x + 2) - 1 = f(x + 2 - 2) - 1 => f(x)

i think thats what they are trying to say, again, ive never seen "mapping" used in precalc, so just a guess.

[elfin hound]

i might as well ask the teacher lmao

i missed the lesson she went over these notes

i understood the earlier parts but this kinda fucked me up

.close

[full forum]

Channel closed

Closed by @elfin hound

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sly grove]

how to convert 1/3 to base 7 (by writing 1/3 as a sum of a geometric sequence)

[severe linden]

Maybe use formula for geoemtric series limit.

[full forum]

@sly grove Has your question been resolved?

[sly grove]

im not sure how to tho

[severe linden]

the limit of a geometric series built with a is 1/(1-a)

you want limit 1/3

equate and solve for a (and hope it ends up being a digit)

[sly grove]

can you give an example? (also i haven't learned limit of geometric series

[severe linden]

$1 + a + a^2 + a^3 + a^4 + \dots = \frac{1}{1 - a}$

[glossy valve]

M8732

[severe linden]

You have learnt geometric series but not this?

[sly grove]

that's right

[severe linden]

odd

but it basically just does what it says.

so we want

I think I said it incorrectly above.

We do not want to solve for a, as a = 1/7

[sly grove]

is there a domain of values for a?

[severe linden]

yes, it only converges between -1 and 1

,wolf 1/(1-1/7)

[glossy valve]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by m8732

[severe linden]

So if we had the number

1.1111111111111111111111111111111111... base 7

it would be 1.1666666... or 7/6

Let's work from here.

[sly grove]

also, there's an example problem (if you want to see it

[severe linden]

I would prefer if we focus on the problem first.

[sly grove]

its solution may be reused on this problem (but i dont know how)

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[severe linden]

.reopen

[full forum]

✅

[severe linden]

@sly grove Did you understand my sum?

[sly grove]

this one? 1.1111... = 1 + 1/7 + 1/7^2 .... = 1.1666...?

[severe linden]

yes

and how you use 1/(1-1/7)

to clarify

the 1.16666 is decimal

[sly grove]

1/(6/7) = 7/6

[sly grove]

yup

[severe linden]

Just making sure

wpe are usually not even supposed to give away solutions

Anyway, now we got 7/6

in base 7

How can we get from 7/6 to 1/3 using operations

that do not mess up the base-7 representation in unpredictable ways?

[sly grove]

7/6 = 1 + 1/6, and then get from 1/6 to 1/3?

[severe linden]

🙂

1/6 to 1/3, could it be... a multiplication by 2?

[sly grove]

yeah. how would you go from there to base 7 then?

[severe linden]

Well we know

7/6 = 1.1111111111111111111111111111...

we subtract 1

and then we multiply by 2

Both are not rocket science for either fractions nor base-7

[sly grove]

(1.11111...(7) - 1) *2?

[severe linden]

yes

[sly grove]

ohhhh

0.11111...(7) * 2 = 0.222...(7)?

[severe linden]

Easy, right?

[sly grove]

thank you so much:))

[severe linden]

you are welcome.

I hope the underlaying principles became clear enough.

.close?

[sly grove]

sure

.close

[full forum]

Channel closed

Closed by @sly grove

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rancid gulch]

i got to 11x = x(a+b) + 2(a+b)

[rancid gulch]

im not sure where to go from here

a + b = 11

but what about the second part

2A + 2B = 0 maybe?

idk 😨

[scenic sundial]

how would you do it if it was 11x + 1?

[rancid gulch]

1 = 2a + 2b

i think right

[scenic sundial]

so how would you do it if it was 11x + 0

[astral sinew]

Yes

[rancid gulch]

yay!!

[scenic sundial]

it is

[astral sinew]

(11)x + (0) = (A+B)x + (2A+2B)

Do you see?

[rancid gulch]

yes

but then a = -b right

[scenic sundial]

yep

[rancid gulch]

and so (-b) + b = 11? so 11 !=0 tho

[astral sinew]

Check your factoring

What's the original polynomial

[rancid gulch]

does x^2 +4x + 4 not factor to (x+2)(x+2)

[astral sinew]

Yes

But there's a special thing you have to do with repeated factors

[rancid gulch]

oh no

[astral sinew]

You will write

[rancid gulch]

woops

[astral sinew]

11x/(x^2 + 4x + 4) = A/(x+2) + B/(x+2)²

[rancid gulch]

ohh?

why is that?

[astral sinew]

Might help to use actual numbers if you want the intuition. PFD is basically:
5/6 = 5/(2×3) = A/2 + B/3 = 1/2 + 1/3

[rancid gulch]

also in that case would it be 11x = A/(x+2) + (Bx + C)/(x+2)²

[astral sinew]

Yes

[rancid gulch]

okok

[humble osprey]

huh?

[astral sinew]

11x/(x^2+4x+4) actually

[rancid gulch]

oh yeah

[astral sinew]

Until you clear the denominator

[rancid gulch]

thats what i meant sorry

[humble osprey]

isnt that only for when a quadratic factor cant be broken up into smaller factors (aka it doesnt have real zeros)

[astral sinew]

Repeated roots are special

[humble osprey]

yeah but if they're real theres no need for Bx + C in the nominator

[astral sinew]

There is. Because the denominator is of degree 2

So the numerator can be of degree 1

Hopefully that makes sense q

[rancid gulch]

so what i got after separting everything was
a + b = 0
4a + 2b + c + 4 = 11
2c = 0

so c = 0

4a + 2b + 4 = 11
so 4a + 2b = 7

a = -b

-4b + 2b = 7

[humble osprey]

im pretty sure thats wrong

[rancid gulch]

b = -7/2

[humble osprey]

the case you're talking about is for when there are imaginary roots

with the real ones, A/(x+2) + B/(x+2)^2 is enough

[rancid gulch]

i got it wrong 💀

[humble osprey]

look at number 2

thats what you're supposed to use

[rancid gulch]

ohhh k

why is it a - b?

i mean x - a

[humble osprey]

where?

oh

its random variables, it doesnt matter

[rancid gulch]

ok sorry lol

[humble osprey]

nahh no worries, nothing to apologize for

anyway this is what you're supposed to have now

[rancid gulch]

ahhhh i messing up somewhere even tho im using this one

so i have like 11x = A(x+2)^2 + B(x+2) right

so i expand to 11x = (x^2)(A) + x(4A + B) + (4A + 2B)

wouldnt that mean A = 0 and B = 11 ?

[humble osprey]

wait wait how did you get this

[rancid gulch]

oh wait lol

[humble osprey]

from here, try multiplying both sides by (x + 2)^2

[rancid gulch]

yeah

ok one sec 😭

so its 11x = (a(x+2)^2 + b

[humble osprey]

dont rush, thats how most of those types of mistakes are made 😭

[rancid gulch]

wait

I mean

[humble osprey]

almost

[rancid gulch]

11x = a(x+2) + b

[humble osprey]

yep, you got it :D

[rancid gulch]

thanks 😭

[humble osprey]

you're welcome!

[rancid gulch]

so A = 11 and B = -22

YES

IT WORKED

IM SO HAPPY

[humble osprey]

yep, that's correct

:D

[rancid gulch]

.close

[full forum]

Channel closed

Closed by @rancid gulch

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glad whale]

HOw in the world is this wrong??

[scenic sundial]

show your work maybe?

[glad whale]

Ok

[wild sleet]

7/4 + 2/4 is not 11/4

[scenic sundial]

very true

[glad whale]

wait

doesnt the square root of b

turn to b^2

1/2****

[wild sleet]

7/4 + 8/4 is also not 11/4

[scenic sundial]

it is b^(1/2) yes

[glad whale]

ah

thats the mistake i mde then

so it will be so then 1/2 + 5/4

get common denom

so will be 7/4?

[scenic sundial]

where did 5/4 come from?

[glad whale]

oh god im looking at

something else

i mean 7/4

so 7/4 + 1/2

9/4

b^9/4

[scenic sundial]

make sure you have the right parentheses, but yes

[glad whale]

Oh ok

[full forum]

@glad whale Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[patent grotto]

why can -x^2 + x + 6 simplify to (x-3)(x+2) but when its in a function y = -x^2 + x + 6 you cant

[spiral vigil]

you can

[swift fulcrum]

Why not

[patent grotto]

im putting it in online cals

and they say no unless im tripping

[spiral vigil]

show screenshot or something

[spiral vigil]

ask it to factor instead

[patent grotto]

💀 oh you right lmfao

[spiral vigil]

"simplification" is somewhat nebulous

[patent grotto]

i am tripping

thanks

.close

[full forum]

Channel closed

Closed by @patent grotto

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wise seal]

I’m stuck at b. I found the limf(x) by doing g(x)=xf(x)-2x+3/x+2 etc etc but I can’t use this at b

[wise seal]

Or maybe I’m doing something wrong ?? I don’t know

OH nvm

I figured it out

.close

[full forum]

Channel closed

Closed by @wise seal

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

Hello, why are these two formulas for combinations without repetition equal
can someone show me an example like when n = 5 k = 3

[full forum]

@torn jolt Has your question been resolved?

[torn jolt]

<@&286206848099549185>

i dont speak very good spanish

sorry

mm you don't need to, it's just the formulas, but I will translate

Non-repeating combinations
The number of combinations of n elements taken from k and k as well as groupings of the same number of elements is different, at least in one element, is calculated with the following formula:

[torn jolt]

why are these two formulas for combinations without repetition equal
can someone show me an example like when n = 5 k = 3

<@&286206848099549185>

[full forum]

@torn jolt Has your question been resolved?

[torn jolt]

.close

[full forum]

Channel closed

Closed by @iron swan

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dry relic]

A father has his wedding anniversary and birthday on the same day.
The family celebrates with a trip to London. The children pay for the musical and football match for the father. The mother pays the ticket for the football match itself, but gets a ticket for musical by the children. Tickets for the musical cost SEK 2,500 in total, while the tickets for the football match cost SEK 5,400 in total.
together. The plane tickets cost SEK 1,600 per person.

Write an expression for how much each of the children needs to pay.

[dry relic]

I might struggle with converting my expression to LaTex format, but here we go:

The answer, according to the book, is $2500/x + 5400/x+1 + 1600$

[glossy valve]

Seed

[dry relic]

formatting issues... grrr

i personally disgree with the book's expression, though

[elfin stream]

Do $\frac{a}{b}$

[glossy valve]

ItzKraken

[dry relic]

x = amount of children btw

The answer, according to the book is:

$\frac{2500}{x} + \frac{5400}{x+1} + 1600$

grrr

[elfin stream]

Don't put multiple $

[dry relic]

right

[elfin stream]

Only one $ at the start, one at the end

[glossy valve]

Seed

[dry relic]

Perfect, thanks @elfin stream !

Anyways, I disagree with the equation

I believe it rather should be $\frac{2500}{x} + \frac{5400-\frac{5400}{x+2}}{x+1} + 1600$

[glossy valve]

Seed

[elfin stream]

Is the father going to the musical

[dry relic]

yes, atleast in this problem

[elfin stream]

Hmm and so is the mother?

[dry relic]

yes, and she is getting her musical ticket paid by the children

everyone will pay for the 1600 SEK flight ticket,
the 2500 SEK is the cost for everyone to get into the musical. This will be split between the children

5400 is the total cost of the football match. Children split the bill for the tickets that it costs for them and the father, while the mother pays for herself

[dry relic]

if we were to analyse my expression above, we would see that 2500/x is logical, considering that 2500 is the bill for the entire family, which will get split by the amount of children, x

[elfin stream]

Yes

[dry relic]

the +1600 also is logical, since everyone pays for their own flight ticket

1600 is per person

[elfin stream]

Hmm the books answer is correct

[dry relic]

this expression?

[elfin stream]

What does 5400-(5400/(x+2)) represent? Total - the mother's payment right?

[elfin stream]

Where is it written she pays for herself

[dry relic]

yes, we know that 5400 SEK is the total cost for entire family

[elfin stream]

Oh found it

[dry relic]

and we want to make it so that the children split the bill between the ticket cost for them and the father only

[elfin stream]

Yeah

[dry relic]

we need to therefore remove the cost of the mothers ticket from the 5400, and split the difference number that we get between the children

how do we do that? we know that x is the amount of children, and that there is both a father and a mother. This means that 5400/(x-2) tells the cost for each ticket

one ticket costs in other words 5400/(x-2)

[elfin stream]

5400/(x+2) no?

[dry relic]

and the mother pays for herself, so the amount that the children will split between themselves is 5400 minus 5400(x+2), which is the cost for the mother's ticket

The book however says it's just $\frac{5400}{x+1}$ and calls it a day

[glossy valve]

Seed

[dry relic]

it's difficult to claim that the book is wrong though

so i'm unsure

[elfin stream]

They must be then assuming 5400 SEK doesn't include the mothers share

[dry relic]

@elfin stream it might very well be the book's perspective, in which i comment that the problem formatting was vague

because seconds after, another problem appears where it's told that the children pay a total of 3000 SEK, so you're supposed to make an equation

using my method you get no whole x-values

using the book's method you get 5

[full forum]

@dry relic Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[magic rover]

prove that for a,b,x positive integers $\gcd(x^a-1,x^b-1)=x^{\gcd{a,b}}-1$

[glossy valve]

bigpufik

[magic rover]

im trying to use euclidean algorithim

im getting

$\gcd(x^a-1,x^b-1)=\gcd(x^a-1,x^a-x^b)$

[glossy valve]

bigpufik

[magic rover]

i can assume a>b

and try to factor x^b

then

$\gcd(x^a-1,x^b-1)=\gcd(x^a-1,x^a-x^b)=\gcd(x^a-1,x^{a-b}-1)$

[glossy valve]

bigpufik

[magic rover]

then not really sure

.close

[full forum]

Channel closed

Closed by @magic rover

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[prisma flame]

how to solve $$\lim x -> 0 ( x floor(\frac{1}{x}))$$

[glossy valve]

neither

[prisma flame]

i know the so,ution is 1

but idk how to get there

suppose to use basic calculus limit properties

[forest panther]

you can try to give bounds to floor(1/x) if you've seen the squeeze theorem

[full forum]

@prisma flame Has your question been resolved?

Channel closed

Closed by @prisma flame

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[late fable]

'

[late fable]

I don't think this is right

Well I know that it's "right"

according to the book

But I don't think os

It doesn't make sense

Ping if you answer please

[full forum]

@late fable Has your question been resolved?

[late fable]

<@&286206848099549185>

[full forum]

@late fable Has your question been resolved?

[late fable]

<@&286206848099549185> help me

Why aren't you responding

[barren zephyr]

<@&286206848099549185>

Help me

[barren zephyr]

Number 8

[full forum]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[full forum]

Please read #❓how-to-get-help

[light sonnet]

Open your own channel, don't ping helpers as the first message

[full forum]

@late fable Has your question been resolved?

[late fable]

<@&286206848099549185> HELP ME

PLEASE

HELP ME

[late fable]

<@&286206848099549185>

[late fable]

<@&286206848099549185>

[torn jolt]

what do u need

[late fable]

Look at the question

[full forum]

@late fable Has your question been resolved?

[late fable]

@wicked seal

<@&286206848099549185>

Please

awhrre are you

[torn jolt]

Yes

[late fable]

Please

Help

[late fable]

this question

I’m questioning the answer to the question

[torn jolt]

Look at the graph

Look at the control

You notice how hit is similar to the control

[late fable]

I know the answer is right but It doesn’t seem right

[torn jolt]

but when they say "Smahed into" yes responses are higher

[late fable]

Look at the answer choices

None of them say that

[torn jolt]

the one you selected says that

just very

weirdly

[late fable]

Ok

but it doesn’t make sense

[torn jolt]

Basically it's saying that if you use more violent words

[late fable]

That choice doesn’t make sense

[torn jolt]

they are more likely to respond yes

[late fable]

Knowing whichever treatment the subject received

We will always predict no

[torn jolt]

The treatment being the word choice

when you chose "smahed into" they were more likely to respond yes

[late fable]

But that’s not what it’s saying

If it said that

[torn jolt]

It is tho

[late fable]

Then it would be right

Oh wait

[late fable]

yea but we still predict no

Like no matter what word choice

We will always predict no

wdym

[late fable]

why’d you say ?

[torn jolt]

I think you're confusing most likely response with prediction

[late fable]

What

I’m not

I think you are

[full forum]

@late fable Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wispy bay]

Hello, how do I get the 1st term of an arithmetic sequence when I'm given only with the 3rd and 17th term?

[wispy bay]

I've tried using the arithmetic equation but I keep on getting wrong/invalid answers

at a loss here right now

[mighty crescent]

Can you show your work?

[wispy bay]

it's really messy but okay

here I tried substituting the nth term and n with 8

[mighty crescent]

,rotate