You should convert the mixed fraction to an improper one first
#help-28
light sonnet
torn jolt
2-1=1?
timid tide
full forumBOT
timid tide
how do I solve this ?
I'm familiar with how you can turn recurring decimals into fractions but idk how to do this one, it says my answer is wrong
full forumBOT
Show your work, and if possible, explain where you are stuck.
timid tide
midnight hamlet
I'm familiar with how you can turn recurring decimals into fractions but idk how...
Simply convert the recurring part (0.x) into fraction, then plus the non-recurring part (4.x), then shift it to the order of magnitude you want (0.4x).
void iris
hi
void iris
i have a qs
does anyone have good suggestions on how i can get a good grade in my as lvl maths exam
m1 and p2
dusky locust
Study
midnight hamlet
For exam it's just study.
For how to get good at math there are other tips.
Although generally advisable, sometimes getting good at math may make you worse at exam by things like distraction or overthinking.
full forumBOT
@void iris Has your question been resolved?
torn jolt
!claim
torn jolt
I'm not sure how to answer this question, surely I'd just do the inverse to find the original function, how would I use the coordinates given?
if you find the antiderivative, youll find infinitely many (+C) solutions that satisfy
Oh wait
you plug in the coordinates to find the specific function
I haven't shown the full question sorry
Oh yes I have nvm#
torn jolt
you plug in the coordinates to find the specific function
As in, sub in the constant "c" at the end, then sub in the coords to find it?
Give me a second
c=-2
f(x)=1-3x^-1+2x^-1
torn jolt
f(x)=1-3x^-1+2x^-1
where did u get this?
So, I subbed in the coords to get "1=0+3+c"
c=-2
no i mean the f
I differentiated
Since that's the opposite of integration
?
?
even if u differentiate thats 3\
[f'(x) = x+3 \implies f(x) = \frac{x^2}{2} + 3x + c, \forall c \in R]
glossy valveBOT
Jester
torn jolt
Oh lord
I think I forgot how to differentiate
x^n=(x/n-1)^n-1
?
differentiate is [(x^n)' =nx^{n-1}]
glossy valveBOT
Jester
torn jolt
anti is [\int x^n dx = \frac{x^{n+1}}{n+1} + c]
glossy valveBOT
Jester
torn jolt
Which do I use here?
since f'(x) is given and you need to find f(x)
u need to find a function that differentiates to x+3
so antiderivative of it
(x^2/2)+3x+c
c=1
So just, (x^2/2)+3x+1?
yea
Thank you
!close
damn
gritty rose
It's .close
wet forum
Hey. I am joking with a friend, and need to get an equation made for a computer program to calculate the number of holes in a hole, based on the number of entrances, assuming every entrance has access to every other one at all times. The equation also only needs to assume there is at least 3 entrances. It should use 2 variables, holes and ent, where holes is the number of holes, and ent is equal to the number of entrances. She gave me this image, saying that every line represents 1 hole.
wet forum
Basically, every possible way to traverse is equal to a hole, where you are unable to leave via the same way you came
torn jolt
if you define it like that then its n choose 2
wet forum
?
torn jolt
n choose 2 is the equation
blissful lake
bruh that looks like among us lower half
torn jolt
n * (n-1) / 2
wet forum
Based on its actual definition, or my given definition
languid holly
Wouldn't he have to calculate combinations of "n holes in 2"?
n entrances**
i mean, every combination of 2 different entrance is a hole
torn jolt
Based on its actual definition, or my given definition
based on your definition of "hole" the equation i gave
wet forum
Maybe my definition wasn't perfectly said, but it actually does
languid holly
then holes= n!/(2(n-2)!)
torn jolt
then holes= n!/(2(n-2)!)
bro thats n choose 2
wet forum
No, nC2 works in my scenarios
Thanks
I am closing it
Does this server have thank counters_
.close
torn jolt
I had a question on quadratic equations getting graphed with vertex form
torn jolt
For example y=2(x+3)^2+6
How does 2 affect it
I know, but does it affect how low and high it goes
it doesnt affect the vertex, only the graph
sharp fable
a affects the stretch right?
torn jolt
Yeah, I'm confused on that
pine osprey
Put the graph into desmos and play around, you will see yourself
torn jolt
Okay
in its vertex form no
I've been shown to use the family function y=x^2 and use the vertex to help to dot from the family function.
Like for example, three to the left and six up
But does the 2 effect the up or down
full forumBOT
@torn jolt Has your question been resolved?
vagrant linden
Hey ive been told a gradient vector points in the direction with the slope with the highest accent, it does so like a regular vector where <f_x,f_y> both are weighted and the combination of these weights then points to the direction of greatest increase
My question is, what happens on the graph of xy at the point (0,0). There are two directions that increase equally as much, so how does the gradient work with that? Additionally the gradient vector is <y,x>, at (0,0) it is <0,0> thus it doesnt point anywhere, does it not actually point to the direction with greatest slope?
torn jolt
Hey ive been told a gradient vector points in the direction with the slope with ...
the slope at (0, 0) is 0 at any direction
vagrant linden
what? why is it not greater then 0 on directions that arent axis'
oh thats just how derivatives work, theyre approximations
torn jolt
no derivatives are limits so its 0
vagrant linden
well limits are just approximating it as well tho right
torn jolt
i dont like the word approximation
vagrant linden
because even an infintecimly small step in dxdy would change the slope
what would you call it
torn jolt
?
vagrant linden
but arent limits just approximations?
torn jolt
1 is an approximation of 0.99, 1 is a limit of 0.9, 0.99, 0.99, 0.999, ....
and the limit of 0.9, 0.99, 0.99, 0.999, .. is exactly 1
vagrant linden
but limits are just approaching some value, they never reach it, they then make a guess on what that value is, in this case 1
torn jolt
define reach
vagrant linden
.9,.99,.999 never is equal to 1
torn jolt
yes, but 1 is exactly equal to the limit of the sequence
vagrant linden
but that doesnt mean the graph is equal to 1 there
so the limit is exactly equal to 1
but by zooming into the graph starting from .9,.99 etc we dont have to be 1
which i think shows approximation quite well
torn jolt
but by zooming into the graph starting from .9,.99 etc we dont have to be 1
zoom in any epsilon amount, and ill zoom delta amount closer to it
anyways
vagrant linden
but youll never reach 1
no matter how far you zoom in
i mean think about a graph being undefined at the point 1
its limit can give you .9,.99=1, and zooming into the graph from .9, .99... will let you approximate it to be 1 at the undefined point
but it doesnt actually have to be 1
right?
torn jolt
yes
vagrant linden
so does that show a limits an approximation
torn jolt
but its im not talking about 1 element thats 1
im talking about the whole sequence
and that its limit is 1
vagrant linden
yeah i agree with that, but im saying apply that to a graph at a point and it becomes an approximation
and thats why a derivative at a point can be=0
torn jolt
derivative by definition is a limit so it is exactly what it is
vagrant linden
yeah i agree with that, but im saying apply that to a graph at a point and it be...
but what about this
torn jolt
approximation to what?
vagrant linden
approximation of what the graph is equal to at that point
torn jolt
if the actual value at a point is not its limit then its not continous
vagrant linden
yeah
vagrant linden
but doesnt a limit still chose a value at that point
vagrant linden
well for a non continous point
torn jolt
if its non continuos then yeah it cna be different
but then itll be not differentiable
and you cant have a derivative or a slope
vagrant linden
but then itll be not differentiable
but regardless of that, doesnt that mean a limit is an approximation
for continous graphs its an exact approximation
torn jolt
define approximation
vagrant linden
for non continous points it is just an approximation
torn jolt
for people its something close to it
torn jolt
for non continous points it is just an approximation
but then anything is an approximation of anything, an apple is an approximation of a ferrari
torn jolt
anyways whats ur problem
vagrant linden
i want to know is a limit an approximation, if it is then i can make a decision on what a derivative is
torn jolt
for intuition sure
vagrant linden
but in reality
vagrant linden
idk how that line of logic is spouted
oh
well yeah
it is
its just a bad approximation
something like f(x)= 2x, then f(1)=2, thats not an approximation
torn jolt
and the goodness of the approximation is just the difference?
vagrant linden
well some things have good approximations, some have bad, some are exact values that arent approximations
right?
such as a lambo is a good approximation for a ferrari, while an apple is not, but a ferrari is exactly a ferrari
and thus limits at points are approximations as at some points they are not exact
assuming that non-exactness in one instance means its an approximation, and that that term approximation carries over to all points
its just the approximation is exact at some points
i feel like this is closer to a definition problem
which feels futile
i think im just going to go with my current understanding as i cant see the flaw in it and you havent said its incorrect based on my definitions
.close
full forumBOT
full forumBOT
Available help channel!
torn jolt
anyone know how to fix this issue?
full forumBOT
anyone know how to fix this issue?
torn jolt
i can't seem to find a solution to making it so in the top formula, M= whatever M is not undefined
full forumBOT
Available help channel!
twin wolf
Write $y=\left(x-a-b\right)\left(x-a+b\right)\left(x+a+b\right)$ in expanded form and hence determine the least value of y. Assume that a and b are real constants.
glossy valveBOT
waterr beam
twin wolf
I'm not sure what the question is asking
What does it mean when it says assume a and b are real constants?
onyx glen
it means to assume they are real constants. they are real numbers that are fixed and do not depend on x
twin wolf
does that affect on how i expand it
onyx glen
no
strange though. the minimum value of y as written is definitely -infty
are you sure you did not miscopy the problem
onyx glen
i am not sure what the least value of y means
have you ever solved problems that required you to maximize or minimize a function
fast peak
i am not sure what the least value of y means
if you plug in some value of x then you will get a value y out. so the question is asking what is the smallest value y that you could get from this for all possible options x
twin wolf
have you ever solved problems that required you to maximize or minimize a functi...
i believe so but i didnt understand it very well
twin wolf
if you plug in some value of x then you will get a value y out. so the question ...
is that going to be like any number
fast peak
wdym
it will be some number. assuming a minimum exists
but it might be possible (and here it is) that you can get arbitrarily small values out
twin wolf
but how do you get a number out of just variables like x, a, and b
onyx glen
well ordinarily you would have had an answer in terms of a and b
it is just that this problem is fucked up and in some sense doesn't have an answer
fast peak
can you give us a picture of the whole original problem?
fast peak
and now a minimum does exist
onyx glen
still, expand this.
onyx glen
there are ways to make your own life easier
twin wolf
how so
onyx glen
first two parentheses multiply to ( (x-a)^2 - b^2 )
twin wolf
first two parentheses multiply to ( (x-a)^2 - b^2 )
is this what you mean
onyx glen
what else could i possibly mean lol
twin wolf
by the way i tried to expand it the old fashioned way and i regret it
so thats the first two done?
onyx glen
i would recommend against expanding out (x-a)^2 actually
the second two parentheses, in a similar fashion to the first two, multiply to $((x+a)^2 - b^2)$. so you then have $$y = [(x-a)^2 - b^2][(x+a)^2 - b^2]$$
glossy valveBOT
Ann
twin wolf
i would recommend against expanding out (x-a)^2 actually
but isnt that what the question wants
onyx glen
the question does not say anything explicit about a particular intermediate step in your computation
twin wolf
hm
onyx glen
trust me when i say it is going to be better this way
onyx glen
what does what mean
onyx glen
(x-a)^2 multiplied by (x+a)^2 means (x-a)^2 multiplied by (x+a)^2...
twin wolf
(x-a)^2 multiplied by (x+a)^2 means (x-a)^2 multiplied by (x+a)^2...
should i expand that
twin wolf
so how should i go about multiplying that without expanding
onyx glen
well first off you know like
you could just write $$(x-a)^2(x+a)^2 - b^2(x+a)^2 - b^2(x-a)^2 + b^4$$ and only worry about the product at the next step
glossy valveBOT
Ann
crude gazelle
You ate that fr
onyx glen
You ate that fr
??
crude gazelle
Like you killed that
twin wolf
lkmfao
full forumBOT
@twin wolf Has your question been resolved?
crude gazelle
I know i’m not crazy but a second opinion would be appreciated
atomic venture
what is g(-1)?
crude gazelle
yes🤡
atomic venture
lol happens
atomic venture
you're trying to solve 8x*cos(x)=0?
atomic venture
those are just the solutions
the zeroes of y are all values of x that satisfy y=0
like x=0
would you know how to solve an equation like that?
crude gazelle
So do I set y=0
atomic venture
yeah
crude gazelle
Oh
atomic venture
because y=8x*cos(x)
y=0
hence that
then solve for x
are you able to solve that?
crude gazelle
First divide by 8 right
crude gazelle
8x or just 8
crude gazelle
is cos x or y on the unit circle
crude gazelle
so it would be pi/2 and 3pi/2
crude gazelle
so sin is y and cos is x
atomic venture
mhm
crude gazelle
ok that’s easy. the last class i took like this was sophomore year of HS
@atomic venture if you have time for one more
atomic venture
what have you tried?
crude gazelle
nothing i’m just confused
atomic venture
that part is trying to get you to realise all side lengths must be positive
so 42-2x>0
and x>0
crude gazelle
ohhh
atomic venture
to account for all sides
so the domain would be all x that satisfy those conditions
does that makes sense
atomic venture
yeah, you need all the sides to be positive
you cant have a negative length
for 42-2x to be positive, theres an upper limit on what x can be right?
crude gazelle
It can’t be 24
atomic venture
yeah true
crude gazelle
yeah idk either
atomic venture
0 is the correct lower bound though
atomic venture
there it wants you to use some graphing utility to find that
you could probably use desmos
crude gazelle
this is a very strong equation
Idk if that’s right but idk how to get the maximum from that-
i got (7,5488)
I lied
I just had to get the X value
atomic venture
you'd plot that equation in software like desmos
and find the maximum value
in the range you found earlier
crude gazelle
yeah
I’m doing inverse functions now
@atomic venture What does a one-to-one domain mean
atomic venture
ah
basically for every y value there is only one corresponding x value
and vice versa
crude gazelle
Ohhhhh
atomic venture
so like a quadratic wouldn't be a one to one function
atomic venture
mhm
crude gazelle
you’re the best thank you so much
atomic venture
nw :)
full forumBOT
@crude gazelle Has your question been resolved?
weak crater
<@&286206848099549185>
upbeat crag
x+y=40.11
weak crater
Yes
upbeat crag
x=y*0.6
upbeat crag
no i cant give you answers
weak crater
Ok so
weak crater
X+Y0.4=40.11
weak crater
Ok yes
weak crater
Ok
upbeat crag
do you know why i can do that
weak crater
Y*0.4+Y=40.11
upbeat crag
yes
lilac trail
u can do it like x + 40% of x = 40.11
weak crater
Ok then I solve it
upbeat crag
u can do it like x + 40% of x = 40.11
which is basiaclly the same thing
upbeat crag
Ok then I solve it
yes
weak crater
It’s 0.4
lilac trail
typing error
weak crater
How do ya solve it
lilac trail
x+0.4x=40.11
willow sedge
@weak crater How many channels have you occupied
weak crater
Oh
lilac trail
hope i could help you
wicked zephyr
Any way do I strt first step for finding (ii) PQ ?
full forumBOT
Any way do I strt first step for finding (ii) PQ ?
wicked zephyr
<@&286206848099549185>
silver pasture
!15m
full forumBOT
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
full forumBOT
<@&286206848099549185>
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
@wicked zephyr Has your question been resolved?
wicked zephyr
<@&286206848099549185>
full forumBOT
@wicked zephyr Has your question been resolved?
solar drum
I am trying to understand the wording of this question
full forumBOT
I am trying to understand the wording of this question
solar drum
I dont fully understand what the question is asking of me, what are the first few steps to take in answering what this question needs of me
tawdry grove
you have been given a formula to find the angle of elevation (theta) of a rainbow and you have been provided some details
using the details you have been provided, find some extra information that will help you find theta
solar drum
so the formula being Sin α=k*sin(β)
tawdry grove
so the formula being Sin α=k*sin(β)
and you have been given this formula as well which will help you find beta which is what you need
tawdry grove
well, the question wants you to solve for theta
the equation for theta is: θ = 4β-2α
later on, you have been given the value of α
but you havent gotten β
you have also been provided with this formula here: Sin α=k*sin(β)
and you know the value of k, but youre trying to find β
so you plug in your known values, and then solve for β
solar drum
ohh, so once I find sin(β) then I can use sin inverse to find (β)
tawdry grove
exactly
and then you plug that into the equation of θ
to find the angle of elevation
solar drum
okay I see, Ill give it a shot, thank you for explaining it to me. Should I keep this chat open in case I need more help or should I close it and make a new one later?
tawdry grove
keep it open
solar drum
okay
tawdry grove
🙂
solar drum
did I correctly find β
tawdry grove
yep you found it correctly
solar drum
awesome, so after plugging it into the original equation I found that theta roughly = 42.4
tawdry grove
if you did arcsin((sin(59)/1.33) you could also find beta that way and then round it from there
tawdry grove
awesome, so after plugging it into the original equation I found that theta roug...
yep, thats correct
solar drum
if you did arcsin((sin(59)/1.33) you could also find beta that way and then roun...
interesting, so thats basically a quicker version of what I did
tawdry grove
yea and youre also saving yourself from painful rounding, you know how teachers can be sometimes
solar drum
I see, so I would do that instead of seperating it into two steps
solar drum
awesome, thank you very much
tawdry grove
with these questions you just have to read very carefully and use the tools that they have given you to your advantage
solar drum
I see, also, I tried your method in my calculator and I got 44.66 instead of my original answer of 40.3, is the difference because of rounding or did I enter the equation wrong in my calculator
ok i think I see my mistake
I didnt use parenthesis to seperate sin(59)
tawdry grove
sin(59.4)
solar drum
yep, I got the correct answer this time. Thank you again for the help!
tawdry grove
yea no worries
solar drum
.close
brittle sleet
x^2 + ax - 3x + k
has no solution, what is the value of k?
test question and i had no idea how to approach it, ty :)
static heart
Using the quadratic formula b/2a +- 1/2a*sqrt(b^2-4ac), it will have no real roots if b^2-4ac is negative
brittle sleet
i understood that part, but it also asked the value of k.. am lost
hot herald
first set up the inequality applying the above
brittle sleet
(a-3)^2 - 4k under sqrt < 0
full forumBOT
@brittle sleet Has your question been resolved?
modern horizon
(a-3)^2 - 4k under sqrt < 0
you have the answer
brittle sleet
.close
gleaming walrus
Question 12
full forumBOT
Question 12
gleaming walrus
Translation: we consider a line e through (x1,y1,z1) with direction vector R(a1,b1,c1) and a line through f with P2(x2,y2,z2) with direction vector S(a2,b2,c2) Prove that e and f are intersecting if and only if … ≠0
viral jasper
what have you tried
gleaming walrus
i really dont understand how to begin
gleaming walrus
what have you tried
I only know intersecting is when it is parallel and no solutions
viral jasper
I only know intersecting is when it is parallel and no solutions
I think there may be a translation error somewhere. If they're parallel, they'll never intersect
viral jasper
all good
In 3D, you can also have lines that are not parallel but still never intersect
I think they're called skew lines
viral jasper
no worries
gleaming walrus
U know the solution for the excercise?
I dont know what I gotta do and I also gotta learn for a big test tomorrow
viral jasper
What time is it for you right now?
gleaming walrus
20:50
viral jasper
Oh ok
gleaming walrus
U know the answer?
viral jasper
I don't "know" it, but I think we can through it.
viral jasper
Me knowing it wouldn't help you anyway. Stuff like this can't be memorized. The objective is to learn to how to solve problems, so you need to use the tools you have already learned
Let's try proving the forward implication first
gleaming walrus
It would save a lot of time
viral jasper
That is, let's prove "if the lines intersect, then the determinant is nonzero "
viral jasper
If the lines intersect, then there must be some single point that is common to both lines
gleaming walrus
Yeah
viral jasper
How would you find such a point?
gleaming walrus
Idk
viral jasper
Do you know how to find the intersection of two lines in 2D?
gleaming walrus
system?
i think i might just leave this question
i gotta study for the other test
its only 1 dumb question
full forumBOT
@gleaming walrus Has your question been resolved?
bleak mountain
I cannot seem to figure out sin and cos after I've watched vids on the subject
weary terrace
Maybe try to go through some basic questions with solved solutions that might help in understanding it better
bleak mountain
Where do I find solved equations?
weary terrace
just google out trigonometry solved equations there are many good sites I believe
bleak mountain
thanks
hot herald
Where do I find solved equations?
there'd be some in the video guides you watched
bleak mountain
.close
quick cairn
If i substitute a variable in a system of equations, do I mention it when writing the solutions of the system?
torn jolt
do you have an example of what you mean?
quick cairn
do you have an example of what you mean?
It's the same example we worked on earlier actually
torn jolt
I think the two images you've shown are sufficiently clear as working
quick cairn
Do I just write the values of x,y,z since t disappeared
torn jolt
t is always -1/2
you can drop it in your working
(though if the question asks for it, you should mention it at the end as well)
quick cairn
(though if the question asks for it, you should mention it at the end as well)
The question is solve the following linear system
torn jolt
then you should mention t at the end
quick cairn
Ok... and I still don't understand what u said about introducing parameters when i find an eq 0=0
Can you provide an example please?
quick cairn
Yes i understand that example
But i don't understand what to do when i get 0=0 in a certain row
torn jolt
if you have less equations then unknowns after GE, then you have at least one free variable
and that free variable becomes your param
ember shadow
What does GE stand for?
Gaussian Elimination
torn jolt
torn jolt
And what does free variable mean?
a variable that can be anything
quick cairn
look at example 7 here <https://www.cliffsnotes.com/study-guides/algebra/linear-...
Example 7 is clear but it doesn't mention parameters though 👀
torn jolt
free variable is interchangable with parameter here
z=t is where they defined parameter t
quick cairn
Ok... but what do i set t equal to if i get 0=0??
torn jolt
ignore any 0 rows
quick cairn
ignore any 0 rows
I can only get 0 rows if the row is duplicated right?
torn jolt
yes, linearly dependent is the term for it
quick cairn
In this case E1 and E2 are linearly dependant?
torn jolt
yes
dim compass
Is it correct to write rational number set in set builder form as: Q={x | x=p/q, p and q are integers, q≠0}?
faint pike
$\frac{ | x-2 | }{ x-2 } > 0$
full forumBOT
$\frac{ | x-2 | }{ x-2 } > 0$
glossy valveBOT
Meatball.
faint pike
hey! I am getting 2 cases for this and after solving all of em getting x belongs to all real numbers but the answer is x > 2, some help would be appreciated, thanks
keen violet
hi
woeful hatch
if x > 2, then |x-2| = x-2
keen violet
so you did the existence condition?
woeful hatch
so this expression is just one
faint pike
if x > 2, then |x-2| = x-2
wait wouldnt i get like x-2/x-2 > 0 then 1>0
faint pike
so you did the existence condition?
i am sorry but what exactly is existence condition
faint pike
x - 2 =\ 0
nope
woeful hatch
x<2
in that case, |x-2| = -(x-2), so the whole expression becomes 1
which is less than 0
so the condition is false for x < 2
and obviously the expression is undefined for x = 2
woeful hatch
take a look at this
woeful hatch
only x > 2 gets you |x-2|/(x-2) > 0
ocean flame
I'm having a struggle with matrix and equations. I need to find the X value (x<0) using the Gauss Jordan elimination method knowing that the range of the matrix equals 2. I have tried to do it, but I just don't understand how using that method you can reach a result. Also, english is not my first language so feel free to ask if something is not clear. Thanks!
full forumBOT
I'm having a struggle with matrix and equations. I need to find the X value (x<0...
@ocean flame Has your question been resolved?
ocean flame
<@&286206848099549185>
full forumBOT
@ocean flame Has your question been resolved?
ember shadow
what is the definition of "range"
stiff musk
possible hint: if the rank of A is 2, then what is the determinant of A?
full forumBOT
@ocean flame Has your question been resolved?
modern horizon
too much
maiden lodge
Can you show us your work
modern horizon
pick one
brittle jay
what do i do now
full forumBOT
what do i do now
brittle jay
somehow need to knock the nine down to one of the three
gilded quarry
Ok, use first log(ab) = log(a) + log(b) on log(6)
onyx glen
6^2 = 4 * 9
modern horizon
somehow need to knock the nine down to one of the three
log5 (11 - 6 + 4)
brittle jay
many thanks, i couldnt get my head around it lmao
brittle jay
6^2 = 4 * 9
wait how would the 9 become 4*9 though? would it just be 1.1^2/4?
onyx glen
i didn't say the 9 would "become" 4.9 ...
brittle jay
im sorry im not thinking straight rn
onyx glen
log5 (11 - 6 + 4)
you realize this is wrong as shit right
or rather
not technically wrong, but there's no way to tie that to the problem data
brittle jay
yea i wasn't looking at that one
onyx glen
log(a+b) ≠ log(a) + log(b), etc.
brittle jay
that one made no sense to me
onyx glen
and make no sense it should.
anyway, $9 = \frac{6^2}{4}$ so $\log_5(9) = 2 \log_5(6) - \log_5(4)$ is what i was going for.
glossy valveBOT
Ann
brittle jay
👍
torn jolt
full forumBOT
torn jolt
How would I solve this?
I solved it by plugging in numbers
for the distance and brightness and got D
but i want to know an alternative way
"tec" do you need help?
Excuse me?
modern horizon
lol
onyx glen
"tec" do you need help?
if it wasn't clear from what i said in the channel you opened,
when a person comes here, YES, it does mean they need help. it doesn't make sense to ask.
if they didnt need help why would they open a help channel
torn jolt
mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm
oh
One more try
gooodbye
God you are dumb no shit I need help
modern horizon
<@&268886789983436800>
onyx glen
but i want to know an alternative way
one star has distance d and brightness b, and the other has distance 3d and brightness 2b
onyx glen
well you could like... write down $L_1 = 4\pi d^2 b$ and $L_2 = 4\pi (3d)^2 (2b)$ and then find $\frac{L_2}{L_1}$ perhaps
glossy valveBOT
Ann
onyx glen
$L_2$ not $L^2$ but otherwise yes keep going
glossy valveBOT
Ann
onyx glen
yes
full forumBOT
full forumBOT
Available help channel!
willow wagon
I need help in remainder theorem
full forumBOT
I need help in remainder theorem
torn jolt
yes
bronze magnet
How do I find the concavity of f''(x) = 24x - 6
full forumBOT
How do I find the concavity of f''(x) = 24x - 6
fervent wharf
How do I find the concavity of f''(x) = 24x - 6
Didn't you previously post this?
Have you studied concavity before? Or just saw it in some question?
bronze magnet
I get it
fervent wharf
this post is coaliest of coal
Lol
bronze magnet
this post is coaliest of coal
if its so easy
bronze magnet
Have you studied concavity before? Or just saw it in some question?
do I set it = to 0?
fervent wharf
do I set it = to 0?
Yes
And that is the point of inflection where the concavity changes
fervent wharf
If f''>0 then up if <0 then down
bronze magnet
so 1/2 is concave up? doesnt it have to be between 2 points?
leave me alone ann
.close
grizzled violet
full forumBOT
grizzled violet
I feel so dumb right now becasue i literally did calculus last year 💀
the work is on the paper, its just random notes and what not me trying to solve question 5a
the rest of the assignment is piss easy
potent shale
Just rearrange
grizzled violet
im tryna find the formula for that
potent shale
The length is 4x no matter if you go up and down
grizzled violet
20 = 2.22x i thinkk
potent shale
The height is 3x no matter if you go left and right
so it's simply 3x * 2 + 4x * 2 = 14x
grizzled violet
thats the total without the cut
potent shale
With the cut too
grizzled violet
?
potent shale
You can think of it as if you fold the cuts outside
"fold"
you use the same length
So the rectangle has the same perimeter
think of it
grizzled violet
im so stupid, your right, the answer would be the same with or without cuts theres literally no difference
broooo ohmygoodness
💀
potent shale
yep
grizzled violet
main issue is with question C tho
I cant find the little height for that section in the middle
acc nvm i think i got it
nvm im more lost than ever
@potent shale Would you know how to solve this ?
I got 0.778x as one of my areas of the section on the right side
potent shale
What are you struggling with? the length of the small height?
Lets call it y?
can you write it on the picture
grizzled violet
What are you struggling with? the length of the small height?
yeah thaat lil middle section
potent shale
so you know that 2x = 9 + y right?
grizzled violet
yh
potent shale
and x+y = 18
There you go, two equations, two variables
You already found x, so you can find y actually
grizzled violet
X + Y = 18 ? sorry im like half asleep 12:47am
grizzled violet
yea
potent shale
on the right you have x+y
from the second figure
on the right
But if you want it in terms of x, you can simply use one of these equations
grizzled violet
2x = 9 + y rearranges to some else
potent shale
Yes, these are two equations both are true
Use one of them
You can solve it
you got that x=9 right?
grizzled violet
yea
potent shale
So from the first equation you have 2* 9 = 9 + y
y= 9
From the second equation we have
X+Y =18 = > 9+y=18, y = 9
Anyway, you have y
grizzled violet
I mean I would have just guessed that myself theres no way it was that simple
so confused rn
no way it can be that easy
grizzled violet
because why is the height of the nine below way longer than the middle nine ?
at the sametime they didnt say to scale
but it should be at least remotely similar right
potent shale
They usually do this to throw you off...
So you won't count on the drawing
Maybe your calculations were wrong, let's check
grizzled violet
7.218x is my area in X
grizzled violet
yeah its a bit weird bro, because do you see the 20 on the left side ? basically i had to do 20/9 = 2.22
2.22x * 2x + 0.778x * x + 2x * x = 7.218 x is the total area
9 = X
potent shale
Why?
grizzled violet
wdym
grizzled violet
because I have to convert the numbers to expression of X
20 is 2.2 times larger than X which equals to nine.
potent shale
I see
But, i think you can do it without converting
Let's check if its correct
You have the upper rectangle = 20x
the mid rectangle = 9*4x
Or maybe it would be easier to use 3x*9
and for the last rectangle 2x * x
potent shale
so in total 41x + 2x^2
if you convert x = 9 to eliminate the square
you get 41x+18x = 59x
grizzled violet
You have the upper rectangle = 20x
how ?
potent shale
For the bottom square you have 2x *x right?
grizzled violet
yeah
potent shale
so its already 18x
The area of this small square
Much larger than you have calculated for the all area
grizzled violet
I guess yeah
potent shale
Now the remaining mid rectangle
3x for the length times 9 for the height
21 x
And the upper rectangle 20x
59x in total
grizzled violet
3x for the length times 9 for the height
but then it will add on area that we already have from the 18x
3x * 9 includes a section of 18x
potent shale
No because i take only the 3x not 4x
Only the length that we did not count
on the left
Check it out with the numbers instead of converting to x
Get a number and then convert to x at the end
grizzled violet
grizzled violet
Get a number and then convert to x at the end
alr
potent shale
No I did the long mid rectangle
Not the small one you drawn
Look on the right figure, you have a length of 3x
Sorry right figure
With the x's
grizzled violet
yeah thats the thing, if u were to do that mid section then it will add on an extra area
because 18x includes a part of that long mid section u know wat I mean ?
grizzled violet
why the whole mid section area what do we do about the other
potent shale
sorry the 21x is a mistake
potent shale
But 9*3 = 27x lol
grizzled violet
yeah thats crazy bro
grizzled violet
I have to get X^2 for the area tho cause remember area is in squared
potent shale
True
grizzled violet
7.218x is my area in X
.
grizzled violet
oh yea alg
potent shale
👍
full forumBOT
@grizzled violet Has your question been resolved?
torn jolt
U can do 3x=20 cuz the value of the side is 20 u can assume the side length is 3x as it is parallel and then solve for X, I might be wrong tho. I’m gonna be honest I’ve never seen a problem like this
potent shale
its not me who needs help
torn jolt
Oh
potent shale
@grizzled violet close
sick canyon
full forumBOT
sick canyon
Could someone either answer a and c or tell me where to find the answers for the specific test
Thanks alot
full forumBOT
@sick canyon Has your question been resolved?
full forumBOT
@sick canyon Has your question been resolved?
full forumBOT
@sick canyon Has your question been resolved?
full forumBOT
@sick canyon Has your question been resolved?
torn jolt
Could someone either answer a and c or tell me where to find the answers for the...
Could you zoom on the question I can't make anything out
What kind of question is it?
gaunt otter
Apply Newton's law on P which gives eqn 2mg-T=2ma put a=5mg/7
for a
Apply Newton's law on Q, which gives T-kmg = kma
for c
full forumBOT
@sick canyon Has your question been resolved?
torn jolt
Hey
terse karma
prove it
torn jolt
Idk where to start
onyx glen
you start by writing your thing properly
did you mean $\frac{\tan(\theta) + \cos(\theta)}{\csc(\theta)}$ or $\tan(\theta) + \frac{\cos(\theta)}{\csc(\theta)}$ on the left?
glossy valveBOT
Ann
onyx glen
actually wait
terse karma
you already know tho 
onyx glen
this is not even true in either interpretation
torn jolt
It’s +cot theta