#help-28

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stiff quartz
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Hello, say I have a 2d orientation basis matrix, for example the identity matrix, and I have a 2d vector [x, y]. How would I get the angle between the heading direction and the 2d vector.

gritty rose
gritty rose
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okay so you want pi/4 from the matrix?

stiff quartz
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ye

gritty rose
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you can take arcsine and/or arccos of the entries

stiff quartz
gritty rose
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or just take the arccos of that of the normalized dot product of the two vectors

stiff quartz
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the column vector?

gritty rose
stiff quartz
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yea

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so the 2nd column vector represents the y?

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my linear algebra skills are rusty lol

gritty rose
# gritty rose

what don't you understand here? do you not understand the dot product

stiff quartz
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i dont really understand the matrix

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the basis matrix

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I know I can represent the heading angle as a scalar

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but im trying to do it with a 2d basis matrix

gritty rose
stiff quartz
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ye I know the dot product

gritty rose
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why do you need to understand the matrix at all?

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you just need to understand matrix-vector multiplication

stiff quartz
gritty rose
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matrix times vector = vector

stiff quartz
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ye

stiff quartz
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right?

gritty rose
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yes you should be using the formulas that give you the angle

stiff quartz
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i see thank you

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@stiff quartz Has your question been resolved?

stiff quartz
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Im still working on it hold up

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ye it works

#

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mortal owl
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what is 2x^2 + 3x^3

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keen shoal
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common factor

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i mean

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is it = 0?

mortal owl
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honestly I don't know

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I forgot how to do basic mathd

keen shoal
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what are you trying to solve

mortal owl
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nevermind ignore that

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how do I simplify this

wide sundial
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Remove the brackets

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Collect like terms

mortal owl
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okay and

wide sundial
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That’s it

keen shoal
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basic addition and subtraction

mortal owl
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I'll type out my answer and you guys can check if it's right

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-x^2+7x^3 2y^2

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yeah I think I didn't get the idea

wide sundial
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Show your working out

mortal owl
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I made it into 9x^2 y^3 -10x^2 y^3+4x^3 y^2 + 3x^3 y^2

keen shoal
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subtract/add like terms

mortal owl
keen shoal
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looks right

mortal owl
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what is y^3-y^3

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is it 0?

keen shoal
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where is y^3 - y^3

mortal owl
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is it not right

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wait I found out the mistake

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no I didn't

keen shoal
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there’s an x ^2being multiplied with both y^3

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its 9x^2y^3 - 10x^2y^3

mortal owl
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yeah I lost the plot

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I'm not smart enough to understand that statement

keen shoal
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what’s

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x + x

mortal owl
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tell me idk

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2x?

keen shoal
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what’s 1 + 1

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yes

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2x

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now

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what’s xy + xy

mortal owl
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2xy?

keen shoal
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correct

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what’s 9xy - 10xy

mortal owl
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-xy?

keen shoal
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correct

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do you get it now?

mortal owl
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OH

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yeah I realized the mistake

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I seperated them

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the x and y

keen shoal
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yes

mortal owl
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okay ty

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!close

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torn jolt
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@mortal owl i need help with the square root

rugged narwhal
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What’s the question?

mortal owl
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wait what

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crystal delta
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Please don't occupy multiple help channels.

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crystal delta
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HELP PLEASE

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junior geode
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junior geode
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I need help on question 61

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I have (y-1)^2 = -x

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and then im lost

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because no negative square roots on the real plane

viral jasper
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You are correct

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So ask yourself what the domain could be to make the square root not be negative

junior geode
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-x >= 0
x <= 0
Any x equal to or less than zero

viral jasper
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Exactly

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As long as x<=0, you are fine

junior geode
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Alright

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Nearly there

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Just still need to determine how to find the bottom half of the parabola

viral jasper
junior geode
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,w plot(1 + sqrt(-x))

junior geode
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,w plot(1 - sqrt(-x))

junior geode
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I believe graphing would work

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Now the solution makes sense

junior geode
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rugged narwhal
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Did i answer question 5 correctly?

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rugged narwhal
astral sinew
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a doesnt even make sense

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crystal delta
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Bro fr? @viral jasper

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Please don't occupy multiple help channels.

crystal delta
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I asked for help for so long

keen shoal
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you’re not entitled to getting help

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people volunteer to help

stiff musk
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!15min

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Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

stiff musk
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emphasis: Please do not ping or DM individual users about your question.

viral jasper
crystal delta
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I was asking for help for so long I pinged helpers twice and nobody came!

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I still need help@

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!

viral jasper
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So why you pinging me specifically? hmmCat

crystal delta
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Because you are in chat which means you saw me pings and ignored them!

viral jasper
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I don't get notified from Helpers ping, and even if I did, I have no obligation to help

crystal delta
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O

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Mm sure

keen shoal
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upload a better picture or type it

empty sapphire
# crystal delta Mm sure

The fact of the matter is that we're here on a volunteer basis, which unfortunately means that

  1. help will not always be available
  2. helpers can and are selective about what they work on
  3. there's not an obligation to help out with a problem if they don't feel like they're up to the task or if they decide there's a personality conflict with a person
  4. Just because someone's a helper doesn't mean they know how to solve problems. For example I help out here mostly with calculus problems and maybe some adv math stuff but I'm super weak on my geometry stuff since I haven't done any of it since like the 6th grade
crystal delta
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O

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Anyway i will be super respectful and post a clearer image

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If anyone can help me It would be amazing this is one of the last problems i need help with before I finish my finals!

viral jasper
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this is your final?

crystal delta
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No it is a homework that I need to finish before I start my finals

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My teacher is cool and he is about to lose his job so he made the final another home work assigment

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professor*

viral jasper
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Wish I could help, but I don't know econ

empty sapphire
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yeah same

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econ is not something i've taken before :/

crystal delta
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dang this is super hard and I find patterns but they always mess up

stiff musk
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i'm no expert on these sorts of questions, but i would first try working out what the balance is on day 14 before the $57.92 purchase is made

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then add the purchase

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then work out the balance on day 23 before the late fee

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then add the late fee

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etc

terse karma
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Yeah

crystal delta
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Ok i will try!

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@crystal delta Has your question been resolved?

crystal delta
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Yea It isn't working

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runic spruce
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runic spruce
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in this step i dont get why 1 + h -1 is important

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because in our formula booklet it just says h

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so i dont get where that comes from?

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@runic spruce Has your question been resolved?

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@runic spruce Has your question been resolved?

robust slate
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The x coordinates of the points are 1 (from point P) and 1+h (some small distance away)

runic spruce
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ohhh

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makes more sense thanks

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calm sun
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calm sun
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can someone help me through this? I don't understand how sir got to that answer

robust slate
glossy valveBOT
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Civil Service Pigeon

robust slate
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Rewrite $\sqrt x$ as $x^{1/2}$

glossy valveBOT
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Civil Service Pigeon

calm sun
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is 2 root x the same as root x?

robust slate
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No

calm sun
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what can root x be re-written as then? x^2?

robust slate
calm sun
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oops I meant 2 root x

robust slate
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$2\sqrt x$ is the same as multiplying $\sqrt x$ by $2$

glossy valveBOT
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Civil Service Pigeon

robust slate
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Take that as you will

calm sun
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ah okay

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so 2x^1/2

terse karma
glossy valveBOT
calm sun
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runic spruce
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for 10b

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runic spruce
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they've let m = that so it remains positive?

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runic spruce
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acc nvm

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faint bobcat
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pls help justify option b

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faint bobcat
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<@&286206848099549185> waited half an hour in other channel for this already no response pls help

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dim compass
#

If $$B=C$$ Can you premultiply A on both sides if $$|A|=0$$

brave blaze
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context...

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?

dim compass
brave blaze
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but what are A, B, C
you didnt define anything

glossy valveBOT
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Calamity

dim compass
brave blaze
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and what |.| means ?

dim compass
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It's sign for determinant of Matrix

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In this case it's determinant of A

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I had this question because when it's AB=AC but |A|=0 you can't get to B=C as A inverse doesn't exist

brave blaze
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If B = C
you can still multiply A on both sides

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its a thing about regularity if I remember

dim compass
dim compass
brave blaze
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but I could be wrong too, so lets wait for someone to confirm

dim compass
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Oh okay!

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Even if you can get from B=C to AB=AC when |A|=0, you don't seem to be able to reverse the process

brave blaze
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Yea

dim compass
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So I found this weird

brave blaze
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But if AB = AC implies B=C, it means A is regular on the left

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but I think A must be invertible

dim compass
brave blaze
#

oh its just some words we use in group theory lol

dim compass
brave blaze
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but maybe thats not the correct word in english

dim compass
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Perhaps

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It's my first time hearing word regular, I mean in math

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strange sonnet
#

hello

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strange sonnet
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need some help finding total distance traveled

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if v(t) = 8-2t over [0,0.5]

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what i did was set the equation to 0 and found t = 4

oak shadow
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@strange sonnet

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As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

strange sonnet
#

could you delete that message i would like to work through the problem

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i already know the answer from before hand

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just trying to understand step by step

oak shadow
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The function is linear, with a negative slope of -2. This means that the object is slowing down at a constant rate.
The initial velocity is 8, and the final velocity at t = 0.5 is 7. This means that the object is moving in the negative direction (since the velocity is decreasing), and is still moving in the negative direction at the end of the time interval.
The distance traveled may not be the same as the displacement, since the object changes direction at some point during the interval. If the object changes direction exactly once, then the distance traveled will be the sum of the distances traveled in each direction.

strange sonnet
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okay so i have the value t = 4

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now how would i know which interval is positive and negative?

oak shadow
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You can determine the sign of the velocity function over each subinterval to determine the direction of motion, and therefore the sign of the distance traveled on each subinterval.
For the subinterval [0,4], the velocity function is v(t) = 8 - 2t. This function is positive for t < 4, which means that the object is moving in the negative direction (since the velocity is decreasing). Therefore, the distance traveled on this subinterval will be negative.
For the subinterval [4,0.5], the velocity function is v(t) = 2t - 8. This function is positive for t > 4, which means that the object is moving in the positive direction (since the velocity is increasing). Therefore, the distance traveled on this subinterval will be positive.
So the total distance traveled will be the sum of the absolute values of the distances traveled on each subinterval. The sign of the total distance traveled will be negative, since the distance traveled on the first subinterval is negative.

strange sonnet
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this makes sense

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thank you

#

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scenic wren
#

heyyy

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scenic wren
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i have this proof

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which is not entirely correct

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as far as i know, the fact that f is bounded is important

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any idea which step depends on that?

torn jolt
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wouldn't bounded be used for existence of the integral?

scenic wren
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uhm

torn jolt
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ie, everything is finite

scenic wren
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but aren't there improper integrals?

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where stuff is not finite

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or is that not yet a thing with riemann integrals

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yeah i think you are right

torn jolt
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I cant think of a counterexample rn

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ocean helm
#

Is there a symbol to represent a concatenation of numbers? Like I have X = 1 and Y = 42, and I want to represent the concatenation of X and Y, in a way that X (concatenation annotation symbol) Y = 242

ocean helm
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I have searched but I didn't find anything relevant

upbeat crag
#

draw a line above XY

torn jolt
upbeat crag
#

oh

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i didnt know that

ocean helm
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Ty

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torn jolt
# torn jolt X||Y is a common way to write it

Previous video sets this up: https://youtu.be/-ruC5A9EzzE
Extra on concatenation: https://youtu.be/LgnoYsbI7Uc
More links & stuff in full description below ↓↓↓

We appreciate any help on Patreon - it lets us make a few more and better videos: http://www.patreon.com/numberphile

Matt Parker on Numberphile playlist: http://bit.ly/Matt_Videos
Matt'...

▶ Play video
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vocal coral
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vocal coral
#

how would you do this

torn jolt
#

use a calculator and the unit circle

proud briar
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or… just a calculator

vocal coral
#

could i just do sin 3/4

proud briar
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arcsin(3/4)

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just inverse sine.

vocal coral
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ok but on my test im not allowed a calculator

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so how would i do it

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without

proud briar
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Oh

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Then unit circle then

torn jolt
proud briar
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But considering the correct to three 3 decimals

torn jolt
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unless you are given tables

proud briar
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yeah

vocal coral
torn jolt
#

trig tables

vocal coral
torn jolt
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it depends how detailed your circle is

vocal coral
#

oh

vocal coral
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but in the answers it is a coord pair

torn jolt
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wdym?

vocal coral
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for sin0=3/4

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you can do sin inverse 3/4

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to get the x term

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and i got 0.848

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but idk how to get 2.294

torn jolt
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use the unit circle

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or draw sine

vocal coral
vocal coral
torn jolt
vocal coral
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3/4 is not

torn jolt
#

use a calculator

torn jolt
torn jolt
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in which case follow the video

vocal coral
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broken rain
#

why the cos(u) is positive if g = -cos(u) the same with u*cos(u)?

hot herald
#

text book error

#

was this part of a larger question?

broken rain
#

yep

#

I understand why is

umbral dome
#

,w integrate xsin(x)

hot herald
#

show the full thing

umbral dome
#

yeah it's just wrong

broken rain
#

this minus

umbral dome
#

that would reverse the sign then

hot herald
#

well yeh, they had a - in front

broken rain
#

thank you both <3

#

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hot herald
#

so book is actually fine

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sterile ledge
#

im just confused on what this is asking

sterile ledge
#

would A^-1 not always have dim nxn

#

which matches A

fast peak
#

you have to show that A^-1 = q(A) for some polynomial q

#

of degrree k-1 < n

sterile ledge
#

Im not sure where I would start

#

does this have to do with CH theorem?

fast peak
#

more or less

sterile ledge
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buoyant ivy
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wheat sinew
#

find the length and width (they should be the same number) and multiply one of the sides by 0.10

#

then you have your answer

buoyant ivy
#

Huhh

wheat sinew
#

@hot herald i'm wrong?

hot herald
#

yes, you're wrong

buoyant ivy
#

This is what I tried doing

#

I'm certain it's very wrong

hot herald
#

overcomplicating a lot of it

buoyant ivy
hot herald
#

you are told that you have a square garden

buoyant ivy
#

Tfff

#

Square

#

OMFG

wheat sinew
#

so the values are the same

#

all sides are equal in a square

buoyant ivy
#

Why did I think of it as a rectangle bleakkekw

buoyant ivy
wheat sinew
#

so what x what gives you 10,000?

buoyant ivy
#

Yes

hot herald
#

doesn't actually make a difference to the answer if it was a rectangle

buoyant ivy
#

B is the answer right ?

hot herald
#

no

#

your work shown actually seems fine,
just 1 or 2 steps from the result

buoyant ivy
#

Tf

#

You broke my mind

hot herald
#

note that you know w * l
and to find the increase, subtract the original area

buoyant ivy
#

2100

#

Danggg

#

Tysm, I really need to acquire some skill at solving these problems

#

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wheat sinew
#

👍🏾

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pliant finch
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Please don't occupy multiple help channels.

fast peak
#

!status

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fast peak
#

also, what is P

pliant finch
#

Positive integers

#

4

fast peak
#

very handwavy

#

you arent really using the definitions of injective and surjective

#

your argument is based on "same size". but you also need to use that the set is finite.

pliant finch
#

How would you incorperate that

pliant finch
#

cause otherwise idk where to add it

fast peak
#

I'm not sure what the cleanest way to prove this is. I would use induction probably

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pliant finch
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torn jolt
#

try drawing it first

pliant finch
torn jolt
#

that's a good start

pliant finch
#

im not sure it works though cause isint tan from -pi/2<x <pi/2

torn jolt
#

try using suitable linear transformations to get it where you want

pliant finch
#

What like multiplying the bounds?

torn jolt
pliant finch
#

so yeah the bottom one no?

#

$f(\frac{pi}{2} x) = tan x$

glossy valveBOT
#

AKAPROTYPE

torn jolt
#

almost

pliant finch
#

what am I missing

#

What if instead of straching the bounds I reduced the bound of tanx and then said because tan has a bijection over -pi/2 < x < pi/2 it should have one over this interval

#

@torn jolt

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simple plume
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tepid root
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tepid root
#

how do I simplify sqrt(2)/2 into 1/sqrt(2)

#

??

hollow sable
#

Multiply numerator and denominator by sqrt(2)

#

This is known as rationalizing the denominator

tepid root
#

thank you so much

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cosmic crag
#

help with part b pls

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red onyx
#

Rotation by 60 degrees and dilation by a factor of 2 I think

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red onyx
#

And direction flipped

#

@cosmic crag

fathom saddle
#

Definitely have rotation matricies in the back of your mind, they tend to take that diagonal form

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stiff geyser
#

I need help with Task 9, I believe task 8 is related to it but I'm not sure how to do it either can someone help me please

upbeat crag
#

what's "the string"?

stiff geyser
#

I'm not exactly sure myself but I believe its referring to the order of the euler path ACDA for example

#

<@&286206848099549185>

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ionic gate
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ionic gate
#

so i have this question

#

the answer was this

#

why did they do the times thing on the left row

#

and not the top colom?

#

2 is properly the determent so every thing divided by 2
but they did it for the numbers on the left
how whould you approch this querstioin

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vale glacier
#

hi, how do I show that this limit approaches -inf

worthy coral
#

Replace x with 0

#

And evaluate the result

keen shoal
vale glacier
#

-inf

worthy coral
#

x -> -∞?

vale glacier
#

i forgot how to deal with limits like this, do I just plug in the 0, get -1/0 and then say it equals -inf?

keen shoal
#

-1/0 is undefined

#

not -inf

worthy coral
#

In limits, a/0 = ±∞

vast fossil
#

Generally it would be more accurate to pick something like 0.001 and -0.001

keen shoal
#

0 in the denominator is undefined?

vast fossil
keen shoal
#

exactly

#

the goal is to get rid of the 0 in the denominator

vast fossil
keen shoal
#

hmm

worthy coral
#

You have to evaluate lateral limits

vale glacier
worthy coral
#

That's an option

vast fossil
#

Or inequalities

keen shoal
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vocal coral
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vast fossil
#

If you don't see it, you can substitute for cos(theta)

#

Let's say x = cos(theta)

#

Then the equation becomes 2x^2 - x - 1 = 0

#

Can you solve this now?

vocal coral
vast fossil
#

Right, the answers for x will also be the answers for cos(theta)

#

Yet make sure that x is not outside of [-1, 1]

vast fossil
#

Make sure x is between -1 and 1

#

(Including -1 and 1)

vocal coral
#

ok

#

and also for b is says find theta

rough tundra
#

do a first

#

you'll find b becomes easier

vast fossil
#

You can use arccos for part b

#

After doing part a, like MrFancyu2 suggested

vocal coral
#

and find where cos -1/2 is

vast fossil
#

That's good as well

vocal coral
#

because i got cos(theta)=-1/2

#

and costheta = 1

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ashen bluff
#

I'm using a statistical learning python library called scikit-learn and it has an implentation of Principal Component Analysis for dimensionality reduction. It also an implementation of Incremental Principal Component Analysis whereby the samples can be provided in batches. My understanding of PCA is that the PCs are obtained by performing eigendecomposition on the covariance matrix. I want to understand, which part of this is possible to do in batches?

ashen bluff
#

I want to know for sure that the result of using IPCA will be equal/v.similar to that of PCA.. or at the very least I woud like to know where the drawbacks would be if there are any

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red girder
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red girder
#

how do i do this ?

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sterile heath
#

I asked help with this same question a wee while ago and got good help but i wonder if theres a simpler way to solve. I was told to use a probability tree but I think I can use probability with combinations instead

summer echo
#

Yes you can, note that the probability of at most three kings is 1 - P(all 4 kings)

#

Now find the number of hands with 4 kings and the number of total possible hands

sterile heath
#

the number of hands with all four kings is 48 i think

summer echo
#

Yes, because the last card has 48 options

sterile heath
#

and the possible hands is 52C5

summer echo
#

Yup, so what's P(all 4 kings)?

sterile heath
#

48/52c5

summer echo
#

Now the probability of at most three kings is just 1 - 48/(52C5)

#

Which is really close to 1

sterile heath
#

0.99998 and some more decimals

#

which is 99.998%

summer echo
#

So, you won't ever get 4 kings in your hand

#

Even if you play your entire life

sterile heath
#

just a 0.002% chance

summer echo
#

I think the expected value of games is 50000 before you get 4 kings, but I have to go now

sterile heath
#

thank you

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sinful onyx
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sinful onyx
#

this is a regular tetrahedron, M divides DB perfectly in half

#

i need to find the angle between the line AM and the plane ABC

#

which is the same as the angle between AM and AM', where M' is the orthogonal projection of M onto ABC

#

but how do I know where this projection is

#

<@&286206848099549185>

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#

<@&286206848099549185>

mossy halo
#

ортогональная - это то как она будет лежать на плоскости ABC

#

подожди я нарисую

#

Нет там это не будет половина

#

Это будет 1/4

#

У тетраедара все углы 60?

sinful onyx
#

Только если они принадлежат к одной стороне

mossy halo
mossy halo
sinful onyx
#

Какова мера угла M'AM

mossy halo
#

не знаю

#

наверное 45

#

а нет

#

он вроде 30

#

потому что у тебя треугольник ADC подобен AMK

#

короче фигня

#

короче как-то через углы

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atomic blade
#

Alfred moment

#

Get your own channel

torn jolt
#

The central rectangle of a small carpet in the shape of
mosaic is 5 m by 3 m. Its plain border is a uniform width.
If the total area of ​​the carpet is 24m2, determine the width of the border.

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torn jolt
#

The central rectangle of a small carpet in the shape of
mosaic is 5 m by 3 m. Its plain border is a uniform width.
If the total area of ​​the carpet is 24m2, determine the width of the border.

#

this is so weird

atomic blade
#

Now you have to get your own channel yourself

#

You locked this channel and it's heading towards its demise

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winged rock
#

help

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winged rock
#

how can u shade this using venn diagram

#

hehe thank u

sinful onyx
#

just shade everything that isn't inside circle C

#

the first () is part of a union with everything that isn't C and a union just adds stuff together

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winged rock
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can u show it?

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frozen portal
#

Hi everyone!!

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frozen portal
#

How would I do this problem?

#

I want to know an intuitive way to do it

#

All I know is that the line of reflection cuts through C/C' because C and C' have the same coordinate

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serene sage
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serene sage
#

how does the first part turn into 1/e?

torn jolt
#

e^(n+1) = e*e^n

serene sage
#

ohhhh

#

thanks, i cant believe i didn't catch that

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next zephyr
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viral jasper
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what have you tried

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harsh cairn
#

on step 2 how did they change -7 to -42

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stuck summit
harsh cairn
#

pls

stuck summit
#

it looks like they multiplied it by the 6 in front of x but i cannot for the life of me understand this

ivory cairn
#

oh that is an awful way to teach factoring

stuck summit
#

this looks like it was scanned in the 90s

harsh cairn
#

did they do it wrong?

stuck summit
#

i dont understand this step at all

light sonnet
ivory cairn
#

they're doing the AC trick of multiply the leading coefficient and constant terms. 6 * 7 = 42

light sonnet
#

So you can have a = 1

stuck summit
#

that works??

light sonnet
#

Which makes factor easier

harsh cairn
#

what

ivory cairn
#

technically.

harsh cairn
#

whats another factor trick?

light sonnet
#

This method

stuck summit
#

wait

#

i understand now

#

this is actually genius wtf

harsh cairn
#

explain pls

light sonnet
#

The video I linked explains it

stuck summit
#

woulda saved me hours of testing combinations of factors

harsh cairn
#

theyve never taught this in class tho

harsh cairn
light sonnet
#

As mentioned, you slide the a coefficient, to do a * c, and then divide to make a = 1

#

Because factoring equations when a = 1 is easier

harsh cairn
#

i just divided the whole thing by 6?

light sonnet
#

No

#

As I suggested, that video will help

harsh cairn
#

ok

harsh cairn
light sonnet
#

Just watch that video, it explains it

harsh cairn
#

ok wait

#

this strat is so good

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lucid oasis
full forumBOT
lucid oasis
#

so if i get infin over infin what does that mean

#

its lopital right?

grand hound
lucid oasis
#

but lopital would just make it infin over infin again rightr?

#

oh wait its infin minus infin over infin

#

so 0

grand hound
#

you would have to continue doing l'hopital

#

sometimes you have to do l'hopital multiple times till it stops being indeterminate

grand hound
#

infinity - infinity is also another indeterminate form

#

here is all the indeterminate forms

sudden yoke
#

i thought 0^0 = 1

olive plaza
sudden yoke
#

if it's in the denominator?

#

what if it's in the numerator

grand hound
#

then it's indeterminate

sudden yoke
#

ah

#

weird

grand hound
#

yeah it's a weird circumstance, if you are taking AP it probably won't show

sudden yoke
#

yeah i'm in bc rn and never had to deal with 80% of that chart

grand hound
#

yeah i also taken it and i haven't seen it

#

however, ive seen it in college

#

so it's good to know if you are doing higher level math

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lucid oasis
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lucid oasis
#

is this solved by a calculator?

#

for Ti-84

next zephyr
#

LOL I JUS DID THIS

#

or smth similar

next zephyr
#

integral

lucid oasis
#

wdym

#

oh indefinite integral

#

how

#

oh oh oh

#

i know now

#

thakns

next zephyr
#

yeah

lucid oasis
#

.clsoe

#

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next zephyr
lucid oasis
#

thank man you too

next zephyr
#

thx

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dim elm
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dim elm
#

Unsure how to do this

#

I was gonna try replacing it as a1 and a3 and use formulas but I’m kinda tripped up on the algebra equation part about the sequence. I’ve never done that before.

plush egret
#

they give you choices so

#

you could just guess and check

#

probably the most reasonable way to approach this problem

boreal marlin
#

B is the only formula that's correct for a_9

dim elm
#

How do you know?

boreal marlin
#

Replace n for 9 in each formula to check

#

The coefficient of x has to be 16

dim elm
dim elm
#

Plug in the number 9 ?

#

Not 16x-2?

boreal marlin
#

No, that's the value of a_9

#

You're given a_9 and a_11, and multiple choices for a_n, to check which one is correct replace n for 9, also for 11, in each formula

dim elm
#

So then the values are just to be able to see if the formula is correct?

boreal marlin
#

Well, it asks for a_6

#

So once you have a formula that matches you could replace n for 6, but it's already given in each option

dim elm
#

So how would I find the formula for a^n if it wasn’t multiple choice?

smoky root
#

You're told it's an arithmetic sequence, so the difference between consecutive terms is always the same

#

Since your given a_9 and a_11, you can find the difference between them and cut it in half to find the difference between each term

#

then, you can work backwards to find a_0 and come up with the formula

dim elm
#

How would I find that difference? Subtract a^9 from a^11?

smoky root
#

it'll always be a_n = a_0 + n*D

#

other way around

#

a_11 - a_9

dim elm
#

But a^9 and a^11 are kinda far apart so how could U determine the difference after subtraction?

#

Would the answer be a^10 or d? Im a bit confused on that part

smoky root
#

what do you get when you subtract them?

boreal marlin
#

In general you can't know the formula for any sequence

smoky root
boreal marlin
#

You're right, my bad

smoky root
#

np

dim elm
#

When I subtract a^9 from a^11 I get 2x+6?

smoky root
#

good, so since they're two apart, the common difference is half of that, or x+3

dim elm
#

So d=x+3

smoky root
#

yup

boreal marlin
#

Careful with notation, a^n is the nth power of a, not the nth value of the sequence a

smoky root
#

then you can do a little algebra

#

$a_9 = a_0 + 9(x+3)$

glossy valveBOT
dim elm
#

And then youd plug that into the arithmetic sequence formula

smoky root
#

yeah

dim elm
#

Ahhhhh

smoky root
#

but we want to find a_0

dim elm
#

So would it then be a_n okay noted

dim elm
smoky root
#

well, do you have a formula for arithmetic sequences?

#

(I might be using different notation)

dim elm
#

Yes, a_n=a_1 + (n-1)d

smoky root
#

oh, ok

#

I was using

#

a_n=a_0+nd

dim elm
#

Ohhh

smoky root
#

they're equivalent

#

but you'll want to find a_1 then

#

and you can use a_9 to do it

#

since

#

$a_9=a_1 + 8d$

glossy valveBOT
dim elm
#

Ohhhhh okayyyy that makes so much more sense

#

Thanks!!!

smoky root
#

but as the others have said

#

if it's multiple choice, just plugging 9 into all of them is faster, lol

dim elm
#

That’s true honestly. I think my final is multiple choice so I’ll probs just do that but i wanna know just in case lol

smoky root
#

that's good!

dim elm
#

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woeful cave
#

I need to compute in Z13, in the form [k] where 0 <= k <= 12

25^513 + (-2)(9)

woeful cave
#

Im struggling with figuring out how to convert the 25^513

#

i know its something like

#

25= -1(mod)13 but i dont know what to do with that

vast fossil
#

And (-1)^513 = -1

woeful cave
#

so -1 x -18? = 18

#

so is it just [5]

vast fossil
#

-1 - 18 you mean?

woeful cave
#

yea

#

-1-18 so

#

=-19

#

so

#

is that just

#

[6]?

vast fossil
#

-19 + 23 = 4

woeful cave
#

i forgot hwo to convert when its negative

#

why 23?

#

wouldnt it be 26

vast fossil
#

Oh yeah my bad

#

-19 + 26

#

7

woeful cave
#

ah

#

ok i think i get it

#

coolio

#

thanks

#

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grand kiln
#

a drawer contains 8 black,5 red and 4 blue pencils. assuming you remove them without looking what is the minimum of pencils you should take to ensure that you get at least one of each color? need some help with this question

upbeat crag
#

pigeonhole principle

hot herald
#

think about the worst case scenario

and/or consider if you were able to look,
how could you maximise the amount of pencils you could pick before getting one of each colour

grand kiln
hot herald
#

and what happens after picking pencils only in one colour

grand kiln
hot herald
#

yeh, and after picking all pencils of the same colour, how can you keep picking that avoids getting one of each colour

grand kiln
#

by getting 8 black ones, 5 red, 4 blue ones

hot herald
#

no

#

avoids

#

by picking everything you've have more than one of each coloour

grand kiln
#

so i should pick all the pencils without picking 3 of each color?

hot herald
#

you don't want at least one of each

#

how could you pick them without getting one of each

grand kiln
#

i'll pick 7 black, 4,red,3 blue ones?

hot herald
#

no

#

you'd have 3 of each there and more

#

pick these one at a time

#

the second you've got at least 1 black, red, blue,
you've failed for what i'm trying to get you to consider

grand kiln
#

i'll pick the black ones and red ones or black and blue or red and blue

hot herald
#

now, which of those combinations will require the most picks

grand kiln
#

black and red?

hot herald
#

yes

#

and the pick after that guarantees that you'll have (at least) one of each colour

grand kiln
#

so the minimum picks would be 13?8+5?

hot herald
#

no

#

and the pick after that

#

you'd need one more pick

grand kiln
#

14?

hot herald
#

otherwise you could potentially just have black and red

#

yes

grand kiln
#

so i'll have 8 black ones, 4 red ones and to get all three colors i'll need to pick from 4 blue ones SO i'll just need to pick one. so 14, does this make sense?

hot herald
#

no

#

why are you saying 4 red

grand kiln
#

sorry 5 red

#

my bad

hot herald
#

yes

grand kiln
#

i FINALLY understand, thank you so much!!!!!

#

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slender pond
#

Can someone help me with 6 please

full forumBOT
torn jolt
#

.

slender pond
#

?

torn jolt
#

U already claimed it sry

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vernal haven
#

Hello

full forumBOT
vernal haven
#

Use an appropriate compound angle formula to determine an exact value for tan (19π/
12 ). Do not use a calculator.

Leave your answer in proper radical form, fully simplified.

hallow walrus
#

!status

full forumBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
vernal haven
#

4

hallow walrus
#

show your work

vernal haven
#

hello There

hallow walrus
#

for future reference, you can just send in your work directly

vernal haven
#

Im uploading right now, no problem will do

#

one moment please

hallow walrus
#

if youre having trouble you can just tell me over text your process

vernal haven
hallow walrus
#

,w tan(19pi/12)

hallow walrus
#

looks good

vernal haven
#

Thanks

#

Are you able to assist me on more question

#

@hallow walrus

hallow walrus
#

sure but dont ping me

vernal haven
#

Sorry

#

Prove
2cot20=cot0 - tan0 showing work of good form.

hallow walrus
#

im assuming that's supposed to be theta

#

what have u tried

vernal haven
#

nothing as of yet

hallow walrus
#

what's cot2theta

vernal haven
#

The cotangent of 2θ

hallow walrus
#

...

#

I meant

#

in terms of trigonometric functions

#

with single angles

vernal haven
#

cot(2θ) = (cot²(θ) - 1) / 2cot(θ)

hallow walrus
#

yes

#

so what's 2cot2θ

vernal haven
#

like the solution

hallow walrus
#

what's 2cot2θ

vernal haven
#

The expression 2cot(2θ) represents the value of the cotangent function for an angle that is twice the size of θ.

hallow walrus
#

are you giving these answers from chatgpt

vernal haven
#

no why

#

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torn jolt
#

help

full forumBOT
torn jolt
#

this question

#

CAN SOMONE HELP

#

PLS

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# torn jolt
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
torn jolt
#

6

torn jolt
#

how do I-

#

EVERYTHING

#

like i dont understand it at all

#

and its so bad omg

#

idk

#

like think so

#

but how do u do the question?

#

so i just kinda understand it