#help-28

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drifting dune
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why is there a ± in front of a square root like in the quadratic equation

but when there is a limit there is no ± in front of the square root!!!!

WHY

barren needle
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the square root is defined as positive?

nova basin
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why would you expect a +- to be there ? That's just a random limit, it doesn't stem from the quadratic equation

drifting dune
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idk there is 2 roots

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so

nova basin
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it's not a quadratic equation

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why are you bringing the quadratic formula to this innocent, simple limit ?

drifting dune
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so its only there when it is a quadratic equation?

limber flicker
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I would say when you are solving for a variable that is satisfied by +- x then you have the pm sqrt

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as you solve for when x = -b + blah blah blah

limber flicker
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^^

drifting dune
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so

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if x is on the other side

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?

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with no blah blah blah

tall juniper
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In the middle of the derivation of the quadratic formula we have
(x+b/2a)² = (b²-4ac)/4a²
And when we root both sides we get
x+b/2a = ± √(b²-4ac)/√(4a²)
x+b/2a = ± √(b²-4ac)/2a

jovial wing
tall juniper
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But in the limit nobody rooted both sides, it was just given as is

drifting dune
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so if you root both sides

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?

hallow walrus
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$x^2=a\implies x = \pm\sqrt{a}$, but $x=a\nRightarrow \sqrt{x}=\pm\sqrt{a}$

glossy valveBOT
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kheerii

drifting dune
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hmmm

tall juniper
hallow walrus
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it was just an example of when the plus minus appears and when it doesnt

drifting dune
#

.close

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dark seal
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hello, I have this exercice for practicing distance vectors:
it asks for me the point or points at the straight that are at two of distance from P(-2,2)
this is what the exercice tells me: r: (x - 1) / 2 = (y + 1) / -1, that the distance between the point P and the other points must be 2 (d = 2) and that the point P is P(-2,2)

What I though is to use the formula d = |Ax1 + By1 + C| / sqrt(a^2 + b^2), so first I got the general equation: x + 2y + 1 = 0, moreover, A = 1, B = 2, C = 1
(in what I was trying I supposed there is just 1 point at the line, but I don't know if it is good) the point that is in the line I called it O and then the width betweeen O and P is 2, so | OP | = 2, | OP | = P - O = (Px, Py) - (Ox, Py) = (-2,2) - (Ox, Oy) (this I am not pretty sure if it is right)
and I think aswell that | OP | = sqrt((Px2 - Ox1)^2 + (Py2 - Oy1)^2)

and then I am stucked here, because I don't know how to find the x1 and y1 from the formula distance between a point and a line, should I not use this formula?
how could I continue?

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upbeat relic
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Problem 2....
I see we have to use contradiction to prove it mathematically,but I am not getting it why suppose (0,1/3) or (0,1/5) is not included(subset ) of (0,1) or (0,1/2) and similar for others !??!?

ember shadow
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,rccw

glossy valveBOT
ember shadow
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what specifically is your question? do you know how to form that intersection?

upbeat relic
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As far as i know intersection is the common part of 2 or more sets ,

Now when we are taking n=1,its suppose A1= (0,1)
When n=2
ItsA2= (0,1/2) and so on .
My question why in this case Intersection (0,1/n)
A1's subset A2's subset A3 ...... and so on

Then it wouldn't be null obviously .

ember shadow
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A1 is not subset of A2

upbeat relic
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No A2 is subset of A1....
And A3 is of A2

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And so on ...

ember shadow
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right

nova basin
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take the intersection up to a given N. that should help you understand

ember shadow
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so what is $A_1 \cap A_2$

glossy valveBOT
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cwatson

upbeat relic
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No tell me one thing for example intersection of (0,1) and (0,1/3) is null
But isn't (0,1/3) a subset of (0,1)?

nova basin
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" intersection of (0,1) and (0,1/3) is null " no it's (0, 1/3)

upbeat relic
ember shadow
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what "trouble"?

nova basin
upbeat relic
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Then it is becoming (0,0) hence null ....., I guess .

Not trouble,but the explanation

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Thanks for your time ..... Sir ✅
@ember shadow @nova basin

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spark sundial
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how would i find the confidence interval for this question?? im not quite sure I'm doing the process right (I have a ti-84 calculator I'm using)

i got this question wrong on a test, so don't mind my previous answers and instead look at the second image attached for my process

spark sundial
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please @ me if anyone responds 🙂

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spark sundial
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<@&286206848099549185>

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@spark sundial Has your question been resolved?

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median beacon
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median beacon
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because AT prime is diagonal

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does that mean that the vectors in the basis B prime are eigen vectors?

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according to this

fast peak
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yes

median beacon
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here it says the eigenvectors are the standard ordered basis

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shouldnt it be B prime

fast peak
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well not of that matrix....

median beacon
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thats what i initally asked tho

fast peak
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they are eigenvector of A_T

median beacon
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oh ok

median beacon
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according to the prop it says the eigenvectors of the basis B in relation to AT

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not AT prime

fast peak
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the prop is using different notation

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in their notation A_T would be T and A_T prime would be A_T

median beacon
fast peak
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I meant what I said

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spring wedge
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what exactly is the simplest form of a number?
so like for a number like 4, is 2+2 simpler than 4? or is it 1 + 1 + 1 + 1?

spring wedge
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recently i asked what was simpler, sqrt(68) or 2sqrt(17) and it was the latter because the number inside of the square root was smaller, i was wondering if this applies with all simplification related stuff, just the smallest version of the thing you're trying to simplify but it's also equivalent

civic basin
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4 is the simplest form of 4

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cause its integer

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sqrt(68) exact value would be in decimal form, so for it to be in the simplest form, you need to write it as smallest number in sqrt as it can be

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and factor out the integer

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like sqrt(4*17) = 2sqrt(17)

spring wedge
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so if it's not a perfect square root, you have to make the number inside of the square root as small as possible?

civic basin
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yes

spring wedge
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but wouldn't the exact value of 2sqrt(17) also be a decimal?

civic basin
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yes, it would be almost exact value as sqrt(68)

light sonnet
spring wedge
light sonnet
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You want to simplify the inside as much as possible

civic basin
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alone

spring wedge
spring wedge
civic basin
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let me know, whats simpler to you?
I will be 10 years old in 34 months.
or
I will be 10 years old in 2 years and 10 months.

light sonnet
spring wedge
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but i've just been doing math on my own to learn about it and i came across this which i don't really understand

light sonnet
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Because take $\sqrt{108} + \sqrt{12}$, first glance, you'd assume that you can't add them because the number under isn't the same but if you simplify it, $\sqrt{108} = 6\sqrt{3}$ and $\sqrt{12} = 3\sqrt{3}$, you'll notice that you can add them

glossy valveBOT
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dldh06

civic basin
spring wedge
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i see

spring wedge
civic basin
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and you can do a lot of more things with 2sqrt(17) than sqrt(68)

spring wedge
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alright

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hoary hound
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hoary hound
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<@&286206848099549185>

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silk rock
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is this correct?

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empty sapphire
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yeah seems right to me

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@silk rock Has your question been resolved?

silk rock
empty sapphire
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oh wait no. The domain should be the same

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.... I think

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you only need to restrict the domain if need be. Like if you had a rational or square root function

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things like that

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but you're passing all real numbers into all real numbers, so you're good fam

silk rock
empty sapphire
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oh wait you're right

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I forgot about that

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it's been a hot minute lol

silk rock
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I'm confused about the domain of a composed function:

Dom(f o g) = {x∈Dom(g) / g(x)∈Dom(f)}

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dim compass
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R={(x,y)|x and y are real numbers and x=wy for some rational number w}

dim compass
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I want to know if the relation is reflexive or not

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The tricky real number that seems problematic is 0

fast peak
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well is x=wx for some rational number w?

dim compass
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I don't know if I should take w to be rational number for granted or not

fast peak
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well for which rational number does it hold

dim compass
fast peak
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x=wx

dim compass
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So w should be 1?

fast peak
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w=1 works

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yes

dim compass
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If any rational number other than w=1 is there

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it doesn't follow x=wx

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So should it be non reflexive?

fast peak
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who cares about other rational numbers. w=1 works

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end of story

dim compass
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Oh

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You're right

fast peak
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"for some rational number" means "at least one"

dim compass
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I see

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Thanks

fast peak
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for x=0 there would be others but for nonzero x there is only w=1

dim compass
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Does that not disobey the question

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That w should be some rational?

fast peak
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it holds for some rational

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who cares whether it also holds for other numbers

dim compass
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In question x can be any real number, so it can be 0 and when it is 0, w=irrational worms

dim compass
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In question it says it hold for some rational number w

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But when we analyse the question it can work for non rational number w as well when x=0

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But you're right from your perspective

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vale karma
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Can anyone help me solving this exercise about complex number, the answer is on the right

wary walrus
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try using the fact that x is a real number if and only if x is its own conjugate

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vale karma
wary walrus
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$z \in \mathbb R , \Leftrightarrow , z = \overline z$

glossy valveBOT
vale karma
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But, how can this affirmattion help me?

wary walrus
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you want (conjugate of z) * (z^2 - 1) to be real

vale karma
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yes

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I have to substitute z=a+bi?

wary walrus
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I guess so because the answer uses this form

vale karma
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but, do I have to do the operations including the i or not?

wary walrus
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what do you mean by that ?

vale karma
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if I have to do this

wary walrus
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I think so

vale karma
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i did it but it has no sense because it's an enormous expression

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dark cobalt
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for i) isnt the answer just 0.9? not sure why we need to calculate anything

dark cobalt
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with P(E) being forgot to submit and
P(H1) = finished work
P(H2) = did not finish

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and for ii) have I done this right?

$P(H_1 | E) = \frac{0.01 \cdot 0.9}{0.01 \cdot 0.9 + 0.5 \cdot 0.1 }$

glossy valveBOT
dark cobalt
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<@&286206848099549185>

thin flint
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90% or 0.9 is the number of students that finish their assignment on time as a percentage of the total, not the number of students that forgot to submit their assignment

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@dark cobalt Has your question been resolved?

dark cobalt
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are you saying H1 and H2 should be forgot to submit and didnt forget to submit?

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or

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the answer to part i should be 0.01 * 0.9 + 0.5 * 0.1

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?

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@thin flint

thin flint
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i'm saying that the prior probability that a student forgets to submit their assignment is different

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it requires a bit of calculation

dark cobalt
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so

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hm

dark cobalt
thin flint
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0,9 completes on time

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so 0,1 doesn;t

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of those who complete on time 1/100 doesn't submit

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forgets

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and half of those who don't complete on time claim to have forgottem

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forgotten

dark cobalt
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yeah

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so those who forget to submit would be the sum of those?

thin flint
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that is what the prior probability would be yes

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that's the starting point

dark cobalt
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so thats the answer to i

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so P(H1) = 0.01 * 0.9 + 0.5 * 0.1

thin flint
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that is the answer to i

dark cobalt
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for ii)

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since it wants

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finished | they forgot

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? @thin flint

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thin flint
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i'm not sure but i don't think so

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i'm not terribly good at this either 😄

dark cobalt
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oh nw :p

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torn jolt
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So I have two planes here, the rainbow one is pythagorean theorem z=sqrt(x^2+y^2) and the blue one is a linear approximation I made. The blue graph matches the rainbow colored one in y=x, however the further away from the line y=x the more discrepancy there is between the blue and rainbow one. How could I transform the blue graph so it matches the rainbow one better.

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Because it is for a specific engineering project its important to keep x and y seperated, so no x*y or sqrt(x y) or anything like that.

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Also, blue and rainbow dont have to match exactly, I just need a pointer in the right direction how I can 'curl' the blue graph a bit

white geyser
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if a linear approximation curves its not linear anymore.

torn jolt
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<@&286206848099549185>

woeful hatch
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hm

woeful hatch
torn jolt
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All thats needed for my project

woeful hatch
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right

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let me just figure out how to restrict geogebra 3d input in x and y

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ok here's my illustration of the equations

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that red thing is the y = x plane

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what did you put in to make your blue plane?

torn jolt
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approximately z = 0.5 * (0.96043x+0.39782y+0.96043y+0.39782x) x c

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adjusted c a bit so it adds up nicely over y=x

woeful hatch
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right

torn jolt
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approximately 1.03, cant find the whole variable

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Its a formula I derived from this algorithm, if its of any help

woeful hatch
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ah, is that why the x and y are split into 2 parts?

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and yes that does help

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are these where your x and y come from?

torn jolt
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yes, basically did it 2 times adding it to eachother

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divided by 2

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to eliminate the min max thing

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but now the <4% deviation is lost

woeful hatch
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my instinct would be to split it into two planes: one for x < y, and one for x >= y.

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to simulate how the curve bends around the z-axis

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not sure about how to curl (as you put it) the graph

torn jolt
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Mm, how would I do that?

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for the project I really need it as one formula, that would be able to be split into 2

woeful hatch
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hold on

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partial derivatives might help

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what are $\frac{\partial z}{\partial x}$ and $\frac{\partial z}{\partial y}$?

glossy valveBOT
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OutOfNosh

woeful hatch
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so it's $\frac{x}{\sqrt{x^2 + y^2}}$, which rules out that idea, since you're not allowed to mix x and y

glossy valveBOT
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OutOfNosh

woeful hatch
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idk

torn jolt
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I got a new idea, but I will try it tomorrow as its late here

woeful hatch
torn jolt
woeful hatch
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i.e. if x >= y, have the formula spit this out, otherwise, spit that out?

torn jolt
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That would not be possible, because the inputs are mechanical

woeful hatch
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but still present it as one formula?

torn jolt
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things would get too complicated unfortunately

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the idea was, z = f(x) + g(y)

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so it needs to be ablle to 'split' like that

woeful hatch
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right, right

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tbh this isn't remotely my area of expertise

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rancid salmon
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Can someone help me solve the question below the scatter plot?

rancid salmon
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<@&286206848099549185>

digital willow
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okay so you have the equation for the scatter plot right

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?

rancid salmon
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no

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im not sure if its correct

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but is it correct?

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oh alr

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yea

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idk why

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yes

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ok..

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a lil

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my teacher never taught us this. just gave it to us

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yea

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cuz of the lune of best fit

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?

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and the points basically touches the line?

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oh

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ok

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shrewd hamlet
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What’s the fastest way to do this?

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shrewd hamlet
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(Solve the system)

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currently doing lagrange multipliers and not having a fun time doing these by hand

normal tree
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have you tried using a computer algebra system lol

shrewd hamlet
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ive searched up system of nonlinear equations solver and the one i tried didnt work

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couldnt find any other decent ones

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do u have a site u can recommend?

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yea i tried symbolab but it didnt work unforuntately

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ye, ill show u

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hmm

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alr imma try

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did some more manual and tried to plug in, still didnt work

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:/

#

wait how would i do the eigenvectors for the nonlinear part

#

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slate ivy
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slate ivy
#

can some one tell me how did we get the red circled part

buoyant gust
slate ivy
#

oh distributivity

#

Alright thanks

buoyant gust
#

So the one became 3(x+y)^2.
And the dy/dx became 3(x+y)^2 dy/dx

So result is 3(x+y)^2 + 3(x+y)^2 dx/dy

#

You get it now?

slate ivy
#

yeah

buoyant gust
#

Alr

slate ivy
#

thx

#

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buoyant gust
#

Np

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dark violet
#

i need help with Equivalent fractions

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dark violet
lapis gate
#

Ok so what have you tried so far?

#

if anything

dark violet
#

yes

lapis gate
#

wym

dark violet
lapis gate
#

I mean to solve it

#

like what steps did you take

dark violet
#

a calculator

#

i was in school

lapis gate
#

Ok well the easiest way in this case is to simplify each fraction as much as you can

#

Do you know how to simplify a fraction? Like what is the simplest way you can write 16/20?

dark violet
#

not really

lapis gate
#

So for 16/20 what is a number can go into both 16 and 20?

dark violet
#

10?

lapis gate
#

Evenly ^

#

Can 10 go into 16 evenly?

dark violet
#

no

lapis gate
#

ok so try a different number xD

dark violet
#

its really not that funny

lapis gate
#

? I'm helping you

lapis gate
#

exactly

#

So you can divide both 16 and 20 by 2 to get an example of an equal fraction

#

so 16/20 can also be written as 8/10

dark violet
#

ok

lapis gate
#

Now how can you reduce 8/10 even more? Is there a number that goes into both?

dark violet
#

2

lapis gate
#

yep 😄 so 8/10 can also be written as 4/5

#

and now you can see there's no way that you can reduce it more

#

so that is the simplest way that you can write it

dark violet
#

i still dont get it

#

i am slow

lapis gate
#

But you understand what I am saying so far right?

#

it's ok don't worry

dark violet
#

kinda

lapis gate
#

Do you understand how we reduced 16/20 to get it to 4/5?

dark violet
#

2

lapis gate
#

No I know but you understood the process right?

dark violet
#

suree

lapis gate
#

Ok awesome

#

So now what you should do is do that for each of the answer options

#

and see which ones also reduce to 4/5

#

So for example, does 2/3 reduce to 4/5?

dark violet
#

no

lapis gate
#

Exactly!

#

What about 12/15?

#

Can you reduce that?

dark violet
#

yes

lapis gate
#

What would you do to reduce it?

dark violet
#

4/5?

lapis gate
#

Yes but how?

#

What did you do to get that?

dark violet
#

3+3+3+3

#

3+3+3+3+3

lapis gate
#

Yep you are right!

#

So you can see how then 16/20 also can equal 12/15?

#

because both of them are the same when they are reduced

dark violet
#

this is too confusing

lapis gate
#

What part is confusing you?

#

You were getting it right 😄

dark violet
#

everthingg

lapis gate
#

Just remember

#

you need to reduce the fraction as small as you can

#

that is the first step

dark violet
#

ok

#

but how do i reduce 3/5

lapis gate
#

That's as small as you can go!

dark violet
#

oh

lapis gate
#

You can't reduce 3 or 5 by anything smaller right?

dark violet
#

wait

lapis gate
#

So that would be your simplified fraction

dark violet
#

let me send a screen shot

lapis gate
#

sure

dark violet
lapis gate
#

Ok so that one is already reduced right?

#

What about 12/20?

#

Can you reduce that one?

dark violet
#

no

lapis gate
#

Why not?

dark violet
#

wait

#

yes

lapis gate
#

How can you reduce it?

#

by 2 right?

#

or by 4

dark violet
#

yah

#

2

lapis gate
#

both work

dark violet
#

oh

lapis gate
#

so if you reduce it by 2 it would be 6/10 right?

#

now can you reduce 6/10 even smaller?

dark violet
#

yah

lapis gate
#

By 2 again right?

dark violet
#

yah

lapis gate
#

So then you get 3/5

#

So that means that 3/5 is equal to 12/20

dark violet
#

yah

lapis gate
#

Now what about 9/15?

dark violet
#

by 3?

lapis gate
#

yes! So 3/5

#

I think you're understanding more now 😄

#

What about 6/10?

dark violet
#

2

#

3/5

lapis gate
#

yep which is 3/5 again

#

What about 1/2?

dark violet
#

no

lapis gate
#

Exactly

#

so you just solved all of them yourself

dark violet
#

k

lapis gate
#

Do you understand how to answer the question now?

dark violet
#

yah wanna know somthing

lapis gate
#

sure

dark violet
#

i have answered 150 qustions 😭

lapis gate
#

Correctly? or wrong

dark violet
#

mostly wrong like 15 right

lapis gate
#

I think you can do more correct now though

#

You seem to understand it

#

Want to do one more together?

dark violet
#

sure

#

i am doin 2/16

lapis gate
#

Ok first can you reduce that more?

dark violet
#

no

lapis gate
#

Are you sure?

dark violet
#

no

lapis gate
#

What can go into 2 and 16 evenly?

dark violet
#

2

lapis gate
#

exactly

#

so 2/16 = 1/8

#

Which also happens to be one of the choices

dark violet
#

yep

lapis gate
#

What about 2/10?

#

Does that equal 1/8?

dark violet
#

yes

#

brb i neeed to get somtin to drink

#

yo i am back

#

bye

#

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torn jolt
#

what are the quartiles to the box plot?

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torn jolt
#

the numbers in order are

#

12,13,13,14,16,16,18,18,20,22

terse karma
#

What does she say?

torn jolt
#

she says the box plot below shows the distribution of ages

terse karma
#

Did you find the quartiles

torn jolt
#

the box plot is incorrect, and I know the quartiles is wrong but i'm not sure what they are supposed to be

terse karma
#

You have to find Q1 ,median and Q3

torn jolt
#

the median is 16

#

idk how to find quartiles

terse karma
#

Why notblobcry

#

You can get it just like median

torn jolt
#

i'm asking how to find it

terse karma
#

Second quartile is equal to median itself so just find Q1 and Q3

torn jolt
#

i don't understand but ok 😭..

terse karma
#

Righr

#

So we get the mean of 2nd and 3rd number to get Q1

#

What's the 2nd and 3rd number?

torn jolt
#

why would i need the mean?

terse karma
#

Oh yes it's not required to find mean in here

#

It's 2.5 so the Q1 will be just 3rd number itself

torn jolt
#

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torn jolt
#

.open

#

.

#

HLEP

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torn jolt
#

help

#

i need help w all my homework

#

asap

wintry cosmos
#

do you know what a discriminant is?

torn jolt
#

no-

#

i need help with all my work

#

can you help me

#

please

remote tartan
glossy valveBOT
wintry cosmos
torn jolt
#

wtf does that mean

#

????

vast fossil
#

Quadratic formula is lowkey an overkill though

wintry cosmos
#

a, b are the coefficients of x^2 and x respectively and c is the constant

torn jolt
#

im going to cry

#

STOP

#

you arent helping

vast fossil
#

We don't do that here

wintry cosmos
#

*ax^2

vast fossil
torn jolt
#

you say heres a formula but not saying wtf it is

vast fossil
#

Helping =/= Giving away the answers

torn jolt
#

how am i supposed to use a formula when idk what goes where

#

why can't you just google the formula for the discrimannt ? what's so hard about it

vast fossil
glossy valveBOT
#

Stephen

torn jolt
#

"substitute and simplify"

vast fossil
#

So, you haven't been introduced to the quadratic formula yet?

wintry cosmos
#

Standard form → $ax^2 + bx + c \$
Discriminant → $b^2 - 4ac$

glossy valveBOT
torn jolt
#

probably a more instructive answer would be to ask him to figure out the determinant

#

I mean the discriminant

#

nvm i found a site that gives me answers

torn jolt
#

no but it solves answers

#

So

#

solves answers... Hmmm

vast fossil
#

So do you want to get help here or not

#

And by 'help' I mean guidance through the problem

torn jolt
#

what does this mean

torn jolt
#

but it doesnt give tell me how many there are

#

okay. Do you have some ideas

#

the discriminant is 32

#

-32

#

oops

#

but

#

ok

#

negative means none

#

so ?

vast fossil
#

Right, and there are no real solutions when discriminant is negative

#

Yeah

torn jolt
#

Yep

#

what if its positivite

#

its 109

vast fossil
#

Then it has two

wintry cosmos
torn jolt
#

but how do i know if it has one

wintry cosmos
#

this might help

torn jolt
#

im not using that formula-

vast fossil
torn jolt
#

ohh

#

OH

#

OPMG

#

OMG

#

thnka oyu

#

im not done yet

torn jolt
#

what is this-

#

because it says it doesnt have one

wintry cosmos
#

well, find the discriminant

torn jolt
#

IT DOESNT HAVE ONE

vast fossil
#

2y^2 - 7y + 4 = 0 has no real solutions because its discriminant is negative

torn jolt
#

so you lied

#

.

#

if its negative how is it 2 solutions

torn jolt
vast fossil
#

It's 0 solutions when D < 0

torn jolt
#

no one knows what d < 0 means

#

so

vast fossil
#

Who

wintry cosmos
#

d < 0 is no real solutions

vast fossil
wintry cosmos
#

where were we again?

torn jolt
#

i finished discriminants

#

next is

wintry cosmos
torn jolt
#

ya

#

ok i know how to do these-

#

this

#

is what i need help w

wintry cosmos
#

so $f(z)$ is a function and the output is $z^2 - 2z$

glossy valveBOT
wintry cosmos
#

input the given 'z' value into f(z) and you'll get the value

torn jolt
#

ok hold

#

i need to finish this graph

#

ok how do i do the table

wintry cosmos
#

basically just substitute the given 'z' value into 'z^2 - 2z' and fill the table accordingly

torn jolt
#

do you think i can do 8 more of these ixls and finish today

wintry cosmos
#

haha, ig.

#

i'm not sure of your timezone lol

torn jolt
#

its 2

#

pm

wintry cosmos
#

i see

#

it's almost 12 PM here

torn jolt
#

oh

wintry cosmos
#

anyways, i gtg

#

good luck on your learning 👍

torn jolt
#

so is this 0

#

help

#

i

#

.close

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grave elm
#

Would the following be injective map from Q+ to N? I have positive fraction a/b where a and b are coprime, then I would just do a*b to map it to N. Would this be injective?

torn jolt
#

no

#

1/6 ≠ 2/3

torn jolt
#

(I think)

grave elm
#

this is what I found, I just wanted something simpler

grave elm
torn jolt
torn jolt
grave elm
#

ty for help

#

.close

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spiral latch
#

hii

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spiral latch
#

i want to help for fix my question

#

30Z⁴ + 5Y³X⁵ - 3XZ

#

x = 2
y = 3
z = -4

#

my answer is 207.360.000

#

so I wanted to see if it's right

onyx glen
#

,w 30 * (-4)^4 + 5 * 3^3 * 2^5 - 3 * 2 * (-4)

onyx glen
#

nope

torn jolt
spiral latch
#

oh

#

.close

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spiral latch
#

i want to resolve to solve 30Z⁴ + 5Y³X⁵ - 3XZ
x = 2
y = 3
z = -4

rugged heron
#

you want to verify?

drifting dune
#

re solve

rugged heron
#

what does re solve mean in this context im a lil lost

drifting dune
#

he solved it wrong before

spiral latch
#

I did but I didn't get it right, and I'm not getting it right

#

So I wanted to help me solve it right

rugged heron
#

what do you have in mind to solve this?

spiral latch
#

1 minute

torn jolt
spiral latch
#

I'm Brazilian and I'm using the translator sorry

torn jolt
#

ah

#

you just replace x y z with their values what's the problem

rugged heron
#

it is wrong i think

torn jolt
rugged heron
#

this is what they are referring to i believe

spiral latch
torn jolt
torn jolt
rugged heron
torn jolt
spiral latch
#

30 . (-4)^4 + 5 (3^3.2^5) - 3 (2 . ( -4)

#

. is multiplication

#

after that i do

#

30 . 256 + 5 ( 27 . 32 ) - 3 ( 2 . ( -4)

#

is it correct so far?

vital shadow
#

yea

spiral latch
#

after again

#

7680 + 135 . 160 - 6 . 12

#

correct?

vital shadow
#

3*2*(-4) does not equal 6*12

spiral latch
#
  • 72?
vital shadow
#

how so?

#

3*2 is 6

#

and 6*(-4) is -24

spiral latch
#

oh

spiral latch
#

3.(-4) = 12

#

-12*

vital shadow
#

it doesnt work like that

#

what's 2*2

spiral latch
#

3 ( 2.(-4))

#

3.2

#

and

#

3.-4

spiral latch
vital shadow
#

and 4*3?

spiral latch
#

12

vital shadow
#

yea so 2*2*3 = 12

#

going by your logic, it'd be 2*2 * 2*3 = 4*6

spiral latch
#

6*(-12)

vital shadow
#

you don't need to

spiral latch
#

why

vital shadow
#

what's 3*2

spiral latch
#

6

vital shadow
#

6*4?

spiral latch
#

12

#

no

#

24

vital shadow
#

sry 6*-4

#

-24

spiral latch
#

-24

vital shadow
#

so 3*2*(-4) = -24

#

do you agree?

spiral latch
#

yes

#

in truth no

#

because

#

I think we should first multiply the 3 by the 2 numbers

#

then multiply them

vital shadow
#

that's only for when you add the two

#

like 3*(2+4) = 3*2 + 3*4

spiral latch
#

It is not how it works?

vital shadow
#

no

#

not for multiplication

spiral latch
#

oh

#

sorry

#

so I just multiply the first one?

vital shadow
#

yeah

#

what you did would be like 2+(3+4) = (2+3) + (2+4)

spiral latch
#

no

#

calm

#

I am confused

vital shadow
#

ok nvm, ignore that

spiral latch
vital shadow
#

for now, just know that the picture you sent is incorrect

spiral latch
#

3 ( 2 * -4 )
3 * 2 3 * -4
6 - 12

spiral latch
#

so minus 24?

vital shadow
#

yea

spiral latch
#

7680 + 21600 - 72 - 24

#

correct

vital shadow
#

no

spiral latch
#

waht

#

what

vital shadow
#

u did the same thing here

spiral latch
#

oh

#

real

#

im crazy omg

#

1 minute

#

4320?

vital shadow
#

yea

spiral latch
#

12000 - 94

#

correct?

vital shadow
#

not quite, where does -94 come from

spiral latch
vital shadow
#

it'd be 12000 - (-24) = 12000 + 24 = 12024

#

where did -72 come from?

spiral latch
#

oh

#

idk

#

12000 -24

vital shadow
#

remember that we left out the negative when multiplying for the last term

#

so 12000 - (-24)

spiral latch
#

but there are no parentheses

vital shadow
#

uhh, let's do the last part again

#

-3*2*-4

spiral latch
#

-6 * -4

vital shadow
#

yea so +24

spiral latch
#

so

#

how

spiral latch
vital shadow
#

at first, I left out the "-" in the -3 and just used 3 to multiply instead

#

im sorry for the confusion

spiral latch
#

nothing

#

thanks for helping

#

you're the best

#

.close

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#
Channel closed

Closed by @spiral latch

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atomic vortex
#

so I used partial fractions and got 1/4n - 1/(4(n+4)) but idk what to do from there

atomic vortex
#

I saw a vid and when the dude was doing it he was cancelling values as he was expanding the sum

#

but for me the pattern is something like

#

$\bigg(\frac{1}{4} - \frac{1}{20}\bigg) + \bigg(\frac{1}{8} - \frac{1}{24}\bigg) + \bigg(\frac{1}{12} - \frac{1}{28}\bigg) + \cdots$

torn jolt
#

n+4 means it should repeat every 4 terms

#

so write out a few more terms

glossy valveBOT
#

Calc II Victim

atomic vortex
#

oh I didnt know that

#

let me try

atomic vortex
# torn jolt n+4 means it should repeat every 4 terms

$\bigg(\frac{1}{4} - \frac{1}{20}\bigg) + \bigg(\frac{1}{8} - \frac{1}{24}\bigg) + \bigg(\frac{1}{12} - \frac{1}{28}\bigg) + \bigg(\frac{1}{16} - \frac{1}{32}\bigg) + \bigg(\frac{1}{20} - \frac{1}{36}\bigg) + \bigg(\frac{1}{24} - \frac{1}{40}\bigg) + \bigg(\frac{1}{28} - \frac{1}{44}\bigg) + \bigg(\frac{1}{32} - \frac{1}{48}\bigg) + \cdots$

glossy valveBOT
#

Calc II Victim

atomic vortex
#

so 1/28 did end up cancelling after 4 more

#

same with 1/32

#

and 1/24

#

but

#

what about

#

1/8 and 1/12

#

and 1/16

torn jolt
#

they stay

#

it's a telescoping sum

atomic vortex
#

so I will be left with 1/4 + 1/8 + 1/12 + 1/16

torn jolt
#

yea

atomic vortex
#

holy shit this is acc so cool

atomic vortex
#

what would that mean

#

repeat every 3 terms?

#

like how can u just tell from looking at the denom

#

without drawing out the sum

torn jolt
#

like $\sum_n \frac1{n+1} -\frac1{n+2}$?

glossy valveBOT
atomic vortex
#

yep

torn jolt
#

it repeats every term

atomic vortex
#

oh u j look at the second denom?

#

oh what

#

how

#

did u know

torn jolt
torn jolt
atomic vortex
#

OHhhh

atomic vortex
#

earlier we had (4n) - (4n+4) = 4

#

ohhhhh

#

BROOOo

#

wow

torn jolt
#

yup catthumbsup

atomic vortex
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bro tysm

torn jolt
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(but make sure the numerator is the same)

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yw :D

atomic vortex
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.close

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maiden pike
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maiden pike
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im not sure where to start in this question

torn jolt
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always start out with a diagram

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so u got a diagram of the traingle right

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isoscles has two equal sides

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so it has two sides of 9x + 3

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since the total Perimeter is 30x - 10

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u can subtract 2* (9x+3)

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so then u get the value of the base

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30x - 18x -10 + 6

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12x - 4 is the base

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base to perimeter is 12x - 4 to 30x + 10

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divide by 2 for obht sides to simplify the ratio

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6x - 2 : 15x + 10

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the restriction on x is is it must be +ve

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because if it isn't postive u will get an a negtaive numberr

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and thus a negative premeter which is impossible

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@maiden pike u understand?

maiden pike
torn jolt
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what grade r u in

maiden pike
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11

torn jolt
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year 11

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or age 11

maiden pike
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grade 11

torn jolt
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ahh kk

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where u from

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cuz i am in y12

maiden pike
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oh im canadian

torn jolt
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and this sort of q doesn't come up in our ciriculum

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ahh ok

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i am australian

maiden pike
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thats cool australia tropical

torn jolt
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presonally i would rather be in canada

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that snow and ice omg

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i wish

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anyways let me know if u don't understand what I wrote

maiden pike
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wait

maiden pike
torn jolt
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ok

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let me write it out for u

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i'll draw a diagram

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firstly what are the properties of an isosicles triangle

maiden pike
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okk

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wait

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like 2 equal sides?

torn jolt
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join this

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lmk if u can't access it

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or if u haven't joined yet

maiden pike
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oki gimme a minn

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alr

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torn jolt
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.reopen

maiden pike
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.reopen

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wintry cosmos
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Hello

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You need help in polynomial division?

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!status

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What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
wintry cosmos
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You can do long division like so

torn jolt
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thansk @wintry cosmos

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i am helping her on an online whiteboard

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@maiden pike Has your question been resolved?

wintry cosmos
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ohh lol, I was not aware

torn jolt
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nah all g

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its fine

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torn jolt
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i dont really get this

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devout valley
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What's the definition of eigenvector/values you have?

torn jolt
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idk, i just think i would maybe do Ax = b?

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like reduce [A|x] and that gives an e-vector??

ripe bear
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The definition of an eigenvector of a certain matrix is that which is only scaled and not rotated by the matrix. the given vector is scaled by zero and not rotated. hence it's an eigenvector. the scaling factor is called the eigenvalue of that vector. which in this case is zero.

torn jolt
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how is it scaled by zero? and what does rotated mean?

ripe bear
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it's scaled by zero because applying the matrix gave you the zero vector

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so the outcome is the old vector multiplied by zero.

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mystic cedar
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mystic cedar
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just 1 question
when we have to find R and r

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when it says about the line y = 1
i get confused wheater to subtract the function by 1 or add
how do u know which one to do

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green lily
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green lily
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I let z = a+bi and using that i found "a" by equating real and imaginary components

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however i don't know how to find "b"

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I assume that "Given that this equation has exactly one root" has some significance but idk what

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would completing the square on my real part work?

nova basin
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plugging in the value for a, this becomes a (real-valued) equation in b, which is quadratic. This means you have 0,1,2 real solutions depending on the value of p. There being 1 tells you what p is, and therefore gives you the unique value of p

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Gonna have to go though

green lily
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ah

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could i use the discriminant

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set to 0