$(6 \div 2)(1+2)$ or $6 \div (2(1+2))$ depending on the intended interpretation
#help-28
dusty scaffold
glossy valveBOT
bee
hot herald
to clearly indicate the order where there may be ambiguity
dense edge
but if we go order to operations, that means we follow BEDMAS
Brackets first, so 1+2
then Division, Multiplication (left to right)
so it would be 6 / (2(3))
hot herald
but the intentions of the writer are unclear
dusty scaffold
**bee**
or of course you could write it as a fraction \
$\frac{6}{2(1+2)}$ $\frac{6}{2}(1+2)$ unambiguous
glossy valveBOT
bee
hot herald
take for example
$$1 \div ab$$
do you think the writer intends for you to divide 1 by the whole $ab$, or divide by $a$ then multiply by $b$
glossy valveBOT
ℝamonov
dense edge
do you find a lot of ambiguity in math problems? how often does it come up in your life?
just curious
and when it does, what is the procedure to follow?
dusty scaffold
if there's ambiguity it's not a maths problem, it's a "humans doing maths" problem
dense edge
yes, math is a lot to do with language actually
dusty scaffold
the solution is:
if you produced the ambiguous expression, write it more clearly
if someone else produced it, ask them what they meant
although if there's context to the expression you might be able to infer which interpretation was meant just by the fact that only one possibility makes the context correct
...i don't really have anything else to say about it, ambiguous notation is literally just a result of how humans write stuff
dusty scaffold
i've worked with formalisations of mathematics that have completely unambiguous notation: however the computer interprets the expression is the only correct way to parse it
dusty scaffold
it's kinda like emphasis for words?
i'd say it's more analogous to english sentences that are syntactically ambiguous
dusty scaffold
"police officer jailed for attacking members of the public found dead"
why was the police officer attacking dead people? ("attacking (members of the public found dead)")
or is the story actually claiming that the entire public was found dead? ("members of (the public found dead)")
of course the intended parse is neither of these, it is that the police officer was found dead, after being jailed for attacking (presumably living) members of the public
maths doesn't really have an equivalent to emphasis, every "mathematical sentence" means basically just its literal meaning without any subtext
you can of course as a human make statements about maths that have subtext, but the subtext won't be mathematically relevant in the same way as the literal content of the statement
(for instance the subtext could be false)
vivid forge
hello i have a question regarding the inverse of the matrix D shown in the picture, shouldn't the coefficients of the inverse be 1/2 and not 1/sqrt(2) like in the matrix circled in red?
vivid forge
.close
carmine minnow
$\sin^2(x)=0$ iff $\sin x=0$?
toxic elbow
so in short the screenshot is 0? and ur trying to solve it easier than expansion and simplification?
toxic elbow
zero product property
fleet briar
sin(x) = +- 0, which is just 0
golden obsidian
@sharp flame yo
full forumBOT
<@718461587236716584> yo
golden obsidian
When 21.44 moles of Si reacts with 17.62 moles of N2 how many moles of Si3N4 are formed?
I got
7.1
and limiting factor
Si
for the reactant in excess how many moles are left over at the end of the reaction?
anyone help?
<@&286206848099549185>
obtuse condor
No chemistry my guy
coarse mortar
There is SI3, so you must divide 21.44 by 3
Then for N2, there are 4, so 17.62/2
7.15 and 8.81
golden obsidian
No chemistry my guy
its also maths tho
golden obsidian
7.15 and 8.81
uh
golden obsidian
its not
golden obsidian
thats not even what i asked
golden obsidian
for the reactant in excess how many moles are left over at the end of the reacti...
^
obtuse condor
Ah cool
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coarse mortar
Btw if you havent figured it out yet @golden obsidian , you have to do 2/3 times 21.44 because it is the ratio of Si to N2 to create Si3N4, and subtract the answer from 17.62 to find out how much of N2 will remain.
tacit eagle
how did theyget this answer
full forumBOT
how did theyget this answer
twilit leaf
Is there some context?
vast fossil
You can use logarithms to solve for t in the second equation
tacit eagle
how did theyget this answer
i managed to get 24.6 on this one so dw
but on this other (very similar problem), i got my answer incorrect (bottom)
9.888763537 was my answer, and i rounded up to 9.9
brittle steeple
but on this other (very similar problem), i got my answer incorrect (bottom)
what's your work?
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@tacit eagle Has your question been resolved?
tacit eagle
my work is (ln(8/2.2)) / 0.130092 = t
t= 9.888763537 and i rounded up to 9.9 yrs
@brittle steeple
brittle steeple
2.2 instead of 2.12?
teal aurora
i think you are asking way too many questions where you make errors you should be able to spot yourself by just taking 1 minute to look everything over again
during a test for example you cant get sm1 to fheck your work
sour rose
that website is kinda bad tbh, it should just accept approx values instead of taking exact input when u can't give exact input
brittle steeple
isn't that what it's doing
tacit eagle
i think you are asking way too many questions where you make errors you should b...
you right
mb
ty monik, koter
tacit eagle
that website is kinda bad tbh, it should just accept approx values instead of ta...
this was from before
how come they wanted 2.12
but didnt say they wanted it
in that format
sour rose
actually wait, you should've just input 2.12, why did u add 0s
oh ur missing a decimal anyways i didn't notice
brittle steeple
np
teal aurora
i missed it aswell on first read
cause usually they type it where you answer from what i seen
teal aurora
in trillions as in 2.12 trillion
think of trillions as a unit
if sm1 told you to write something out in meters
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inner solstice
what would it be simplified to?
full forumBOT
what would it be simplified to?
frosty geyser
,rccw
glossy valveBOT
astral sinew
torn jolt
can you answer this with step by step explanation
full forumBOT
can you answer this with step by step explanation
torn jolt
<@&286206848099549185>
polar valve
can you answer this with step by step explanation
this is not a "someone does the work for you"-server. you can get help to solve your example yourself.
torn jolt
?
polar valve
?
polar valve
somewhere else, not here.
torn jolt
i dont know where it is tho
pulsar gale
where is the somone does the homework for you server
thats not a server you want to be in
because you wont learn
and when the test comes you wont do so well
or you just wont gain anything from the class
torn jolt
thats a good point
ember shadow
If the problem was asking you to solve $\frac{x}{1} + \frac{1}{x}$, how would you do it?
glossy valveBOT
cwatson
torn jolt
ok so this is my question im getting the answer as 42/9 however google says it is 18 i want to know which one is the right answer and with an explanation
ember shadow
Why don't you explain how you arrived at that answer?
And I can tell you if it's the right approach
torn jolt
i did normal fraction addition i mutiplied the numerator and the denominator of the first term with (2 + root 5 ) ^2 and carried on from there
pulsar gale
i did normal fraction addition i mutiplied the numerator and the denominator of ...
you could easily have messed up an exponent or something else somewhere
there are a lot of numbers going on here
do you have physical work
pulsar gale
I see the issue
(a + b)^n is not the same as a^n + b^n
it would be pretty complicated to expand out (2 + sqrt5)^4
torn jolt
so do you have to use identities
torn jolt
yes
pulsar gale
oh yeah then just do that
torn jolt
ok thanks
ember shadow
FOIL
ember shadow
well yes but I assume he doesn't know the other way
pulsar gale
they said they do
ember shadow
oh, got it
pulsar gale
,w simplify ((2 + sqrt(5))^2) + (1 / ((2 + sqrt(5))^2))
glossy valveBOT
torn jolt
i dont understand this either how did 18 come
and wouldnt evaluating this just give 10
pulsar gale
idk
ember shadow
Are you forgetting to add the 1 from the right term's numerator?
Regardless, a $\sqrt{5}$ term will remain in both the numerator and denominator.
glossy valveBOT
cwatson
torn jolt
oh yea i forgot to add the 1 but when i do im gettin 40.5
ember shadow
What do you get before dividing it out
torn jolt
162/4
ember shadow
That's not correct. As I said, there are terms with sqrt(5) in both numerator and denominator
Check your arithmetic again
torn jolt
after i evaluated the numerator and denominotor terms using identities i got 9 + 4 root 5 and then did fraction addition which would result in mutiplying the both numeraotr and denominot of the first term with that and that would get rid of the square root
ember shadow
The term on the bottom left is correct so far. You are not multiplying things out correctly
What is $(2 + \sqrt{5})^2$?
glossy valveBOT
cwatson
glossy valveBOT
cwatson
torn jolt
hold on
ember shadow
To simplify the top part, unless you know Pascal's rule, you can change the $(2 + \sqrt{5})^4$ to $(9 + 4\sqrt{5})^2$, since $x^4 = (x^2)^2$. Do you understand so far? So then you will have to simplify $\frac{(9 + 4\sqrt{5})^2 + 1}{9 + 4\sqrt{5}}$
glossy valveBOT
cwatson
torn jolt
yes this is exactly what i got after evaluting with identities again im still getting 162/4
ember shadow
Stop jumping ahead. Do it step by step. What do you get when multiplying out the term on the top and adding 1?
torn jolt
the top term the (9 + 4root 5 )^2 i evaluated with identities
ember shadow
I don't know what "evaluated with identities" means, but what did you get, then?
torn jolt
it means i solved with identities i got 162 + 72root5
ember shadow
(What "identities"???)
OK, that is the numerator. So you have the numerator and the denominator you got correctly was $9 + 4\sqrt{5}$. How does that reduce to 162/4
glossy valveBOT
cwatson
ember shadow
You are now looking at $\frac{162 + 72\sqrt{5}}{9 + 4\sqrt{5}}$
glossy valveBOT
cwatson
torn jolt
ok this is what i got in my mistake i worte 162 / 4 , checking again im getting 170/4
ember shadow
HOW are you getting those?? There are square roots in both the top and bottom, you can't just "cancel" them if that's how you're approaching it
Please explain your steps
torn jolt
why not you can cancel square root terms like root 5 / root 5
ember shadow
If the entire term was, for example, $\frac{72\sqrt{5}}{4\sqrt{5}}$, then yes you could cancel them. But there is a term being added
glossy valveBOT
cwatson
ember shadow
It's just a standard arithmetic rule
torn jolt
oh youre right but then that would just leave me with 171/4
ember shadow
No, I'm telling you that you can't just cancel things like that
torn jolt
see root5/ rrot 5 evaluates to be 1 right
ember shadow
No, I just said, again, you cannot cancel them like that. Both the numerator and denominator are single expressions, you can't just cancel from one part of the expression
$162 + 72\sqrt{5}$ is a single number. And $9 + 4\sqrt{5}$ is also a single number
glossy valveBOT
cwatson
torn jolt
ok if thats the case how would you further simplify the expression
remember the answer is supposed to be 18
ember shadow
As I suggested before, stop trying to jump ahead to dividing. What are other ways you can simplify arithmetic expressions?
Focus on just the top or bottom, for now
torn jolt
can you just show me the expression rn
ember shadow
$162 + 72\sqrt{5}$
glossy valveBOT
cwatson
ember shadow
simplify that
ember shadow
Guess if you have to, you're not getting a grade here
torn jolt
can you show me the expression the full
ember shadow
I just did, look at the last TeXit picture
ember shadow
As I said, forget about the denominator for now
torn jolt
ok i mean other then that i dont know where to start
ember shadow
What level of math have you learned so far?
glossy valveBOT
cwatson
torn jolt
you cant do that you can only evaluate it
ember shadow
Do you know what factoring means
torn jolt
yes but factoring hre gets you nowhere
ember shadow
That's not true. I wouldn't be asking about it if that were true
torn jolt
(162 + 72sqrt(5))/(9 + 4sqrt(5)) |
ember shadow
How can you factor something from $162 + 72\sqrt{5}$? Just focus on the numerator
glossy valveBOT
cwatson
ember shadow
You can't change the root. It will stay as root 5. But you're getting the right idea with 72
You're not seeing what I'm getting at so let me give you a first step: $162 + 72\sqrt{5} = 2 (81 + 36\sqrt{5})$. Do you understand that?
glossy valveBOT
cwatson
torn jolt
yes
ember shadow
OK, now keep going like that
torn jolt
81 as 9 sqaure 36 as 6 square
ember shadow
That's true but their squares don't matter here.
torn jolt
ye iik that but what else is there to do
ember shadow
I "pulled out" a 2 from both the 162 and 72. Do something similar for the 81 and 36
torn jolt
but 81 and 36 dont have anything in common
ember shadow
Yes, they do. Try some numbers
torn jolt
9
ember shadow
Yes!
So you bring the 9 out front (don't forget the 2 already there) so then what do you have
torn jolt
18(9+4root 5
glossy valveBOT
cwatson
ember shadow
So the whole expression, with the denominator, is $\frac{18(9 + 4\sqrt{5}}{9 + 4\sqrt{5})}$
torn jolt
no way
glossy valveBOT
cwatson
torn jolt
its 18
ember shadow
Yes
torn jolt
dude ty so much
i only recently learned factoring so i dont know many use cases for it
ember shadow
No worries, glad I could help
torn jolt
thanks bye
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cobalt sorrel
how do I write this: one numbers 1/7 is equal to second numbers 1/8
hallow walrus
let the first number be x and the second number be y
then you can write $\frac{x}{7} = \frac{y}{8}$
glossy valveBOT
kheerii
high moat
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glossy valveBOT
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@high moat Has your question been resolved?
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@high moat Has your question been resolved?
high moat
No
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@high moat Has your question been resolved?
tidal reef
i don't think there's a thing called "intersection of 2 points"
i've only ever heard of "intersection of 2 lines" or "point of intersection"
high moat
yes
pulsar gale
Okay very different
What is a and what is b
Cause they each have two plane equations
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faint breach
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@faint breach Has your question been resolved?
brisk parrot
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brisk parrot
I just plug in P(8) right..?
But the answer I get is slightly off from the answer I get in the back of the book
I get 49.48% but the book has 51.5%
OH is it because I'm supposed to plug in P(9) not P(8)?
..it is
.close
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tacit eagle
I tried to find max in my calculator but failed to do so, ti-84 plus ce
onyx glen
show calculator input and output
normal tree
https://education.ti.com/en/customer-support/knowledge-base/ti-83-84-plus-family/product-usage/34845
teal aurora
if you did do it correctly maybe it wants 2400 instead?
glossy valveBOT
teal aurora
oh im dumb
why are all these questions just
reading comprehension
they purposefully make things so weird to answer
tacit eagle
if you did do it correctly maybe it wants 2400 instead?
2400?
tacit eagle
my answers
are correct just gotta use hundreds after the dot
well tbh
im getting strange numbers
everytime
in my calculator
max keeps changing
i do left bound
then right bound
then it gives me
something in between
but tbh
idk how far left and how far right
i should go
to get the "maximum"
making it unto 24,000 or whatever value i understood
just need help getting a consistent max
teal aurora
do you have no computer during test
tacit eagle
bro
teal aurora
only handheld calc?
teal aurora
💀
tacit eagle
true but the skill
is useful
to know how to do
on calc
ulator
since i bought this sht for 100 xd
Press 2nd, then CALC (above the TRACE key). Choose 4: maximum or 3: minimum. The calculator will ask you for a left bound, a right bound, and a guess for the maximum or minimum. You can enter these by using your left and right arrows to move the cursor to a reasonable x-value, then pressing ENTER.
thats nasty bro
"guess left and right bound"
smh
normal tree
yeah that's typical of numerical optimization algorithms
you have to tell them where to search
tacit eagle
idk what max is
is there
another way
to find out
what it is
using
calculator
teal aurora
no most search algorithms need a starting point as saccharine says
actually i wouldnt know ive never used calcs before
but you did get it right
tacit eagle
so at 25, 24000 people?
normal tree
2400
light sonnet
.close
fathom vessel
how would you find m?
full forumBOT
how would you find m?
fathom vessel
.close
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hallow fern
say we want to show that if matrix A^k=0 and if B is similar to A then B^k=0
hallow fern
Since B is similar to A then B=PAP^-1 where P is invertible
then B^k=(PAP^-1)^k
im not sure how to evalute that bracket tho.
Clearly where going to get A^k which is 0 so the whole thing evaluates to 0
just missing the middle step of what to write
is it that (PAP^-1)^k=PA^kP^-1 ?
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quartz gale
is it that (PAP^-1)^k=PA^kP^-1 ?
That’s exactly what the solution
rocky vale
is it that (PAP^-1)^k=PA^kP^-1 ?
That's true because
(P A P^-1)^k
= (P A P^-1) (P A P^-1) (P A P^-1) ...
= P A (P^-1 P) A (P^-1 P) A (P^-1 P) A ... P^-1
= P A^k P^-1
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regal glen
for proving a statement, in this case ∀q ∈ Q, ∃r ∈ Q such that q/r ∈ Z.
just because it does not work when r = 0, it doesnt make the statement false right?
because first of all the negation would still be q/r just ∃q ∈ Q. ∀r ∈ Q, q/r ∈ ~Z
regal glen
as the first one is saying, for any value of x, i can pick a y that will work, and that y does not need to work for every single value of x
whilst the second is saying i need to pick a y that works for every single value of x?
fast marlin
waht do they mean by suits?
full forumBOT
waht do they mean by suits?
spice orchid
Spade club heart diamond
fast marlin
so 3 cards of one suit could be either 1 spade, and 1 club, and 1 heart
or would it be 3 spade
for example ^
spice orchid
It means 3 cards have the same suit and 2 cards have another same suit
E.g. 3 spades and 2 hearts
karmic smelt
if red is my current curve and black is the curve i desire, how can i manipulate the red curve to get closer to the black curve?
spice orchid
Very vague, what it is that you have control over?
karmic smelt
Very vague, what it is that you have control over?
yeah sorry, i dont want to overwhelm with information
i have code
that loops over every asterisk
and the return is 0-100
as in the position of the characters
you can see the red function is sort of like an absolute value in a way
spice orchid
Well why don't you just measure the difference between the asterisks and move the relevant direction
Again it's unclear what you have control over and what exactly behaviour you want
limber flicker
u could play around with multiplying values based of their position in the array by a quadratic ax^2 , provided you're trying to go from red to black
karmic smelt
upIncrement = (textIndex-0.5)/textTotal;
downIncrement = (textTotal-textIndex+0.5)/textTotal
const triangle = textIndex < textTotal/2 ? (100*2) * upIncrement : (100*2) * downIncrement;
const rounded = textIndex < textTotal/2 ? (100*2) * upIncrement : (100*2) * downIncrement;
@limber flicker @spice orchid here is the code. textIndex is the index of every asterisk so 1,2,3,4,etc textTotal is the total number of asterisks
triangle is the triangle shape
and i want to modify the rounded variable
since it's pretty clear that the rounded curve is a modified version of the triangle one
karmic smelt
u could play around with multiplying values based of their position in the array...
i was thinking of something like that
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glad whale
Literally how is this wrong??? help please??
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Literally how is this wrong??? help please??
azure grove
i think u need to first rationalise it? I think
azure grove
oh, ye
glad whale
azure grove
0 + (-4/5)i
azure grove
std form is $a+ib, a,b \in \mathbb{R}, i = \sqrt{-1}$
glossy valveBOT
n11
atomic blade
Complex numbers are always a + bi
glad whale
Ah
atomic blade
Which means you need to make a = 0
Because you onow
Mathematics
10/10 would recommend
pulsar gale
lmao
atomic blade
Mathematica on its way to give me 64 + 0.0000000001i for the integration of a polynomial ☠️
verbal musk
where it says "[delta,infinity) if delta>0" why dont they just say (0,infinity)
verbal musk
$[\delta,\infty)\forall\delta>0 = (0,\infty)$
glossy valveBOT
please request a new nickname
rose rain
Sure
ocean lark
Because it doesn't converge uniformly on (0,inf).
ocean lark
I can explain more in-depth after my game
verbal musk
ok
ocean lark
On [delta,infinity) for delta>0, we can see that it converges as justified in the answer, essentially by finding a bound in terms of delta However, what they did won't work on (0,infinity). Why? Because the bound won't work. However you choose n, I can give you an x in (0, inf) such that 1/(1+n^2x)>1/n^2. In specific, I could choose (n-1)/n^2.
it thinks im trying to type in tex :(
oh because i put dollar signs
lucid cobalt
**please request a new nickname**
What can you say about whether these two sets have a least element?
ocean lark
That's an explanation of why their method doesnt imply convergence on (0, inf), i.e. leaving the truth of convergence on (0, inf) up in the air but It looks like the next paragraph is the start of a proof that it actually doesn't converge?
verbal musk
What can you say about whether these two sets have a least element?
delta can be as small as we want tho right?
lucid cobalt
Yes, but you're fixing it as some positive number. The least element will always be delta for that set that's closed below
ocean lark
I mean I don't think having a least element is the property that is a problem here. Like (3,inf) doesnt have a least element, but the given function certainly converges uniformly on there.
lucid cobalt
If your question is "why not just say (0, \infty)" this is I think the best way to see that those are different sets no matter how small you take delta
verbal musk
ok that helps me understand why the sets arent equal
lucid cobalt
I mean I don't think having a least element is the property that is a problem he...
Yeah I should say no least element but inf is 0 maybe
lucid cobalt
ok that helps me understand why the sets arent equal
Glad we helped
verbal musk
On [delta,infinity) for delta>0, we can see that it converges as justified in th...
ok so basically there is no sequence that allows us to say |f_n(x)| < a_n
instead we have to rely on a dependence on delta
ocean lark
I think you have the idea
verbal musk
.close
fallow jacinth
Im trying to follow the distributing part but I keep getting the wrong answer
glacial pasture
pallid sorrel
u integrated the 0.283 into the first set of brackets
but lost the brackets
x(a+b)(c+d) = (ax + bx)(c+d)
= acx + adx + bcx + bdx
but u did x(a+b)(c+d) = ax + bx(c+d) = ax + bcx + bdx
@fallow jacinth
fallow jacinth
ok I see
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woeful grotto
how do i do this ahah
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how do i do this ahah
onyx glen
what's the question?
onyx glen
... you THINK?
onyx glen
so it does not say what you are asked to find.
woeful grotto
yeah
onyx glen
so in fact there is no question.
short siren
quaint prawn
...
onyx glen
no question no problem.
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outer dust
under the definition of a subspace, would a subspace in r^4 also always go through the origin?
outer dust
like would every line and plane through the origin in r^4 is a subspace of r^4
harsh cedar
m being forced to do this:
Orbo has heated up a 1166 cubic centimetre block of ice, originally at -33 degrees Celsius, to the temperature of 110 degrees Celsius. How much thermal energy was absorbed from this change?
torn jolt
m being forced to do this:
Orbo has heated up a 1166 cubic centimetre block of i...
they really don't give you anything other than this?
$q = mc \Delta T$
glossy valveBOT
hannibal
torn jolt
c = 4.2
harsh cedar
what c = 4.2... ?
torn jolt
specific heat capacity of water
harsh cedar
torn jolt
oh what.
use the explanations that were given to you previously, now that you have this info
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torn jolt
How do u find measure QR
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How do u find measure QR
gritty rose
you can show your work and someone can check
grave elm
I think it’s 23.03 right
I dont think so
devout valley
What’s this here saying?
grave elm
it would be greater than diameter
grave elm
What’s this here saying?
RPS and RPQ I guess
torn jolt
What I did was find circumference and divided by 2 then I found the length of qs and divided by 2 and then I subtracted that from half of the circumference
grave elm
that's the reason why it's incorrect
grave elm
I suggest using trigonometry
torn jolt
Hmm ok
grave elm
See the red diameter? It bisects the 60° angle
torn jolt
Yea
grave elm
so can you find measure of RPQ?
torn jolt
Lol
grave elm
lemme see
torn jolt
Brb
grave elm
Im still getting different results
grave elm
What I did was find circumference and divided by 2 then I found the length of qs...
this should be correct
you probably messed up the calculation
you're like 2 units off
torn jolt
Ok I re did it and got 20.93 for rq
grave elm
seems better now
digital tinsel
Ik that i have to us half angle to find the answer but I'm confused on how exactly to start the answering the question.
cold thicket
Ik that i have to us half angle to find the answer but I'm confused on how exact...
i think its 90/2
then flip it
digital tinsel
i dont think that right this is a trigonometry quesiotion and im sure i have to us half angle identities
feral rain
those formulas invole sin and cos not cosec
harsh carbon
Well make cosec a sine
cold thicket
i dont think that right this is a trigonometry quesiotion and im sure i have to ...
then i think divide it by 180
feral rain
i do understand what you are saying as you get strange decimals
cold thicket
is that geomatry?
harsh carbon
We get that sin(x)=1/4 which is not a standard triangle
digital tinsel
no this is precalc 2
cold thicket
no this is precalc 2
wrong general
lucid cobalt
Shireen - what's the relationship between csc and sin?
feral rain
oooo you could use small angle formulas
as sin(x) = 1/4 is a small angle you could use those to find x and thus your values
or you could use the triangle
digital tinsel
will is sin(x) is 1/4 but im trying to find what sin of (x/2) would i take the 1/4 and divide by 2?
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outer pasture
for $g(t)= 4\cos(\frac{\pi}{3}t-\frac{2\pi}{3})+1$ would the Phase shift be $-\frac{2\pi}{3}$?
glossy valveBOT
Astassa
stiff musk
either that or +2pi/3, depending on your convention
outer pasture
ok yeah, i think the formula is $acos(w(t-h))+k$ so that would make the phase shift positive
glossy valveBOT
Astassa
outer pasture
would the horizontal shift be positive 2 instead of -2
tired blade
is that correct
full forumBOT
is that correct
meager dew
it can be simplified further
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@tired blade Has your question been resolved?
tired blade
it can be simplified further
oh ok
ill do that rq
(z-3)^2 @meager dew ?
is that right
meager dew
yes
meager dew
well the function can have a value of 0
so you can plug 3 in
but if you plug in 0 it’s undefined
tired blade
but if you plug in 0 it’s undefined
so z != 0?
meager dew
yes
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tired blade
ohh
meager dew
.reopen
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✅
meager dew
idk if you wanted it to close or not
meager dew
dividing by zero isn’t allowed.
dividing by zero makes it undefined
so -5z cannot equal 0
therefore, as you said, z cannot equal 0
tired blade
therefore, as you said, z cannot equal 0
another question sry lol, and my answer is like that
correct?
pulsar gale
another question sry lol, and my answer is like that
what about n
pulsar gale
ye
pulsar gale
idk
tired blade
ay ty, what about the simplified function itself is it right?
||<@&286206848099549185>|| anyone knows?
pulsar gale
its hard to see since you crossed out the question
pulsar gale
looks good then
torn jolt
Hey! I need help with this problem. I need to use trig identities to solve it. The first thing I did was use the odd identity to write it was sec B ( csc B - sin B)
spice orchid
try writing everything in terms of cos and sin
torn jolt
try writing everything in terms of cos and sin
1/cosB ( 1/sin B - sinB/1)
spice orchid
what are the actual instructions of the question? "solve" is vague rn
torn jolt
Rewrite each expression in terms of at most one trig function (not in the denominator). Indicate the identities being used for all the identity works.
torn jolt
what are the actual instructions of the question? "solve" is vague rn
Sorry, I should have put that. 
spice orchid
okay try and combine into one fraction now
torn jolt
erm
torn jolt
okay try and combine into one fraction now
So distribute?
spice orchid
the inside terms
sorry wasn't clear
combine the stuff in the brackets into one fraction
torn jolt
Just curious, why shouldn't I distribute?
torn jolt
Ok so I got 1 - sin^2 B / cosBsinB
I think I could go further with this though, no?
MAybe use the pythagorean identity?
torn jolt
the numerator could be cos^2B
MY final answer is the cot B
Could you help me with two others?
spice orchid
you went wrong somewhere
spice orchid
correct so far
torn jolt
isnt that just cotB
spice orchid
MY final answer is the cot B
then you must have typoed because you didnt write that here
spice orchid
cotB is correct yeah
torn jolt
Can I get your help with 2 others?
I was able to solve one but I want to make sure im write
I do my best >-<
Still newer to these
spice orchid
sure go for it
torn jolt
For this one I got -secB, but im not sure if it's right
spice orchid
thats right yeah
torn jolt
Yay
Then the next one is
I rewrote the thing in parenthesis as sin^2p
Using pythagorean identity
So then I have sec ^2p(sin^2p)
Should I rewrite them in terms of cosine?
spice orchid
rewrite sec^2(p) in terms of cosine yes
torn jolt
My final answer is tan^2p
spice orchid
yep well done
torn jolt
Thank you! That is half of what I have to do, but I'm going to take a break and work on the other problems tomorrow since they're verifying identities. I truly appreciate your help. I find these types of problems somewhat enjoyable - requires some critical thinking.
.close
brave blaze
Quick check, the expectancy of a multivar random vector returns a vector with the expectancy of each random variable, right ?
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Quick check, the expectancy of a multivar random vector returns a vector with th...
@brave blaze Has your question been resolved?
native imp
Hi can someone help me on these
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@native imp Has your question been resolved?
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@native imp Has your question been resolved?
normal tree
for the first one, what can you say about the relationship between b and theta?
native imp
I have no idea
normal tree
do you know how to do trigonometry in right triangles?
calm tinsel
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grave elm
calculate second derivative, set it =0 and solve for a?
calm tinsel
ok I tried to make the second derivative of it equal to 2 but I realised I still have the x in there
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What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
No
calm tinsel
oh
grave elm
Firstly calculate second derivative, then x=2 ofc
fleet briar
f''(2)=0
brittle axle
Now this one is fucking me up
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Now this one is fucking me up
lavish onyx
Hi
brittle axle
Hi
lavish onyx
Mind that angle 4 equals to the sum of angle 1 and 2
brittle axle
So would it be x+11 +3x+4 = 5x +2?
lavish onyx
Yes
lavish onyx
To what's asked
You have already found the way to find angle 3 yourself
So you got x
Put it
brittle axle
Okay so x=13 then 180=5(13)+2
lavish onyx
Okay so x=13 then 180=5(13)+2
180-5x13+2
brittle axle
Thank you so muchhhhhhh I can finally go to sleep
lavish onyx
You are welcome
brittle axle
Good night ✌️
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torn jolt
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torn jolt
How do I do part a?
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@torn jolt Has your question been resolved?
thick minnow
How do I do part a?
What have you tried so far?
woven horizon
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covert wing
This help channel is occupied
So please remove your question from this help channel and create one for yourself
stoic pivot
Ok thank you
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torn jolt
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torn jolt
help 🥺
torn jolt
Yeah
full forumBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
silver shoal
Guys i have a simple question, not need to open a thread but
short crest
Guys i have a simple question, not need to open a thread but
ask in an open channel
silver shoal
How can i represent a digit of a number from position
brittle steeple
do it anyways lol
short crest
Show your working
torn jolt
Umm okay
silver shoal
How can i represent a digit of a number from position
So i have 1234
How can i represent mathematically i am showing the number 1
,,n_{1} like this ?
glossy valveBOT
Oliver Twist
short crest
just open a new channel bro
torn jolt
Yeah
short crest
OC : CR = 2 : 3
torn jolt
yep
short crest
find CR in terms of c
short crest
aight ping me when you're back
torn jolt
@short crest
short crest
ok
torn jolt
sorry had to open the door
torn jolt
Yeah
short crest
do you know how to find CR?
short crest
no..
torn jolt
😭
torn jolt
yeah
short crest
Let OC = 2x
and CR = 3x
torn jolt
Oh okay
short crest
if 2x = c
x = ?
torn jolt
c/2
torn jolt
c/3?
short crest
no no no
torn jolt
ummm
short crest
if x = c/2
3x or 3 * x = ?
torn jolt
Hello can someone com to help 26
short crest
Hello can someone com to help 26
just wait bro
final wigeon
Don't spam around
short crest
we're in the middle of something here
torn jolt
3/CR
torn jolt
just wait bro
Ok
torn jolt
Uh
torn jolt
yeah
short crest
and we know that x = c/2
torn jolt
why multiplied?
short crest
so 3 time c/2 = 3x
torn jolt
I see thanksss
short crest
ok so OC : CR = 2 : 3 or you can say 2x : 3x,
if 2x = c
3x = ?
torn jolt
3 x c/2?
torn jolt
3 x c/2?
short crest
yes
torn jolt
That makes it 5/2c
short crest
yes
short crest
yes
torn jolt
Thanku sm
short crest
wait what the hell are you supposed to do to find CQ
torn jolt
CR + RQ?
short crest
oh
short crest
yeah exactly, idk how you're supposed to do it given such little information
i am very bad at geometry
torn jolt
Ahh icc
Its okay thou, u helped me alot
Umm help me with the (c) part, i think i can do the b part
short crest
i can.. but i don't know how to show it.. as i said im very bad at geometry
torn jolt
Ohh
torn jolt
Let OC = 2x
and CR = 3x
@short crest why did u put OR as 2x?
short crest
you're welcome, sorry can't help much