#help-28

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clear lily
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ye

round gust
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,w sin(x)=2

glossy valveBOT
round gust
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,w 2 = (e^(ix) - e^(-ix)) / (2i)

glossy valveBOT
round gust
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why do i get different answers

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or how do i get different answers?

clear lily
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i mean are they different

round gust
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idk

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lol

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they are the same]

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@round gust Has your question been resolved?

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placid jackal
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how to differnetiante -2xy

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placid jackal
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?

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do ew take u to be -2x or +2x?

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u*

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we*

vast fossil
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With respect to which variable?

placid jackal
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x

vast fossil
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Then it's -2y

placid jackal
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sry

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i meant implciet diferntaiton

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one sec

vast fossil
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Ah

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Alright

placid jackal
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the -2xy bit

vast fossil
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Then it's -2y - 2xy'

placid jackal
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guy on youtube got this

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woudnt the - and - make a +

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?

vast fossil
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Where is the other - coming from though?

placid jackal
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ohhhh

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yeh shi

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u right

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thanks

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πŸ™‚

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low cradle
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Hi, I have no clue what's going on here i need the area

atomic blade
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Area of what

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Surface area?

low cradle
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Yeah

atomic blade
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Well you don't need the diagonal

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It's a cube with side lengths of a

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What's true about each side of a cube?

low cradle
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I have no clue what's going on here i just got this sent with a note "Finish this by monday" I assumed i need the area but i honestly dont even know

atomic blade
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What's the entire assignment

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It's giving you a formula

low cradle
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That's it this picture and "Finish this by monday" i supposed i need a?
I'm sitting staring at this picture for 2 hours that's my last resort

atomic blade
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Well I can't help you if all you're given a cube with a diagonal

low cradle
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Alright i understand, I'll try to think about it.
Thanks though

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cursive void
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cursive void
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hello can someone help me undrstand this question

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the second part is the hardest for me to understand

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I understand the first part

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dense edge
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dense edge
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Which method do you prefer?

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Left or right

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To find derivative

hallow walrus
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both the methods are equivalent

carmine stratus
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right i'd say, the left will waste time

void widget
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Product rule is easy but both are good and correct

dense edge
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OK

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ivory fern
#

Hey so im misunderstanding how the questions are being asked on my college courses, I'm not asking for the answer, just possibly some help on how to work out or set up certain problems

gritty rose
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@ivory fern Has your question been resolved?

ivory fern
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How many days will we be driving? Remember, for this one there is no such thing as a partial day. (Hint, you will need to look up and use the ROUND function)

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not understanding what is meant by round function and when I look it up i get the code but theres no way its giving me the right answer

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the answer i get is 5.5 days on the road after breaks are taken out and it says to use the round function on that to input the right answer into the spreadsheet

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im having trouble knowing what to ask because i dont want answers, i need to know how to do this stuff in a spreadsheet and I think i get how to code the formulas once i figure out what the formula is like how to work out the problem, i can give you the info used in the assignment but I was thinking if I just post the question then maybe we could use example numbers or something to help me get on the right track

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heres all the questions, to maybe help with context clues and whatnot

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  1. How many gallons of fuel will you need to travel?
  2. What will be the total cost of fuel?
  3. What is the total amount of time we will be spending on breaks, in hours?
  4. What is the total driving time, including breaks?
  5. How many days will we be driving? Remember, for this one there is no such thing as a partial day. (Hint, you will need to look up and use the ROUND function)
  6. How many nights will we need a hotel?
  7. What will the total cost of hotels be for our trip?
  8. While traveling, what is our average miles driven per hour? Don’t forget to include breaks.
  9. How much fuel are we using per hour of drive time during our trip?
  10. How much fuel are we using per day?
  11. How much money are we spending on each day we use fuel and stay in a hotel?
  12. How much money, in fuel, are we spending per hour of drive time?
  13. How much money will our trip cost us in fuel and hotels?
  14. What percent of our total trip cost comes from hotels?
  15. What percent of our total trip cost comes from fuel?
  16. What is the total percent of fuel and hotel percentages? Hint: it must be 100%
  17. How many miles are driven per day, on average?
  18. While Driving, not including breaks, what is our average MPH?
  19. How much, in fuel, does it cost to drive a single mile?
  20. What is your average MPH while traveling, but on a break?
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ive done the first few as you can see where im at (on number 5)

wild sleet
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they mean you have like

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excel or google spreadsheet

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and you can ROUND() things there

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you can just try it

ivory fern
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ok well maybe i cant get help here then, im going to email my instructor about maybe clarifying this so i can work on it tomorrow before its due, I just dont know if I need to round up or down here and if i do either then nothing else im doing makes sense

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thank you anyways for your time and attention

wild sleet
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you never said what's your problem

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it's just a lot of context and you;re saying it doesn;t work out

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maybe it's just me

gritty rose
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Definitely not just uou

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OP has a problem they're working on, and isn't giving it in its original form

wild sleet
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i don't mean the original problem, i mean the exact issue, what result is not appealing and causes the confusion
so it's maybe just me

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if you add 0.5 before round you can ensure that it rounds up

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@ivory fern Has your question been resolved?

ivory fern
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its ok, thank you both

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boreal obsidian
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Your welcome/.

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bright crane
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Someone check my answers and tell if anything is incorrect

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haughty temple
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hello

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haughty temple
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Can someone explain why this is the case?

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How can this subspace may be only part of V yet the third bullet point implies V = span(..)

fast peak
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the definition is separate from that text

ivory cairn
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The bullet points are all the same thing. If v1,...,vn are a spanning set of V then Span(...) = V

fast peak
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that text is only an explanation/comment/... for why you would want this terminology

ivory cairn
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if v1,..., vn are not a spanning set of V, then Span(...) may not be all of V

haughty temple
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Ohh I see I thought the two are directly related

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thank you!

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last scaffold
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how do i find the area of this shape

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onyx glen
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is it supposed to be a semicircle?

flint moon
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Probably

onyx glen
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@last scaffold

last scaffold
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yeah it is

onyx glen
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if so, do you know how to find the area of a whole circle?

last scaffold
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yup

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but because it's in the middle should i not power it by 2?

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or am i dumb

onyx glen
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what's "it"

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i have no idea what you are talking about

last scaffold
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1.9

onyx glen
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"But because 1.9 is in the middle, should I not power 1.9 by 2?"

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is that what you are asking?

last scaffold
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yea

onyx glen
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that question is phrased in such a way as to be unanswerable. there's no "should" in such problems.

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i mean like

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do you have an attempt that you aren't sure about?

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or have you not written anything down yet

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you can either find the area of the (semi)circle directly in terms of its diameter, or first find the radius and do it through that.
neither path is "better" or "more correct" than the other.

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@last scaffold Has your question been resolved?

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runic igloo
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runic igloo
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Hi

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Can someone explain how the horizontal asymptote is y=0

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Isn't the bottom greater than the top therefore making this a slanted asymptote/

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Am I finding the degrees wrong?

gritty rose
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What do you think the degree of a polynomial is

runic igloo
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It's the greatest number or if there's multiple parentheses you add them up

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So like (x-2)^1(x+3)^2 is 3

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x^2+4x+3 is 2

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Because it's greater than 1

gritty rose
runic igloo
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Just an example

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I made up

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Also for the function x^2-5x+6 / x^2-2x-3

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My answer key says that there are 2 x-intercepts

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What is that supposed to mean

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@runic igloo Has your question been resolved?

runic igloo
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No

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I'm confused about the 2 x intercepts part

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Is this in reference to graphong?

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graphing it

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@runic igloo Has your question been resolved?

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serene sage
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serene sage
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can someone pls help me with these

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what does it mean by f(g (1/81) ?

normal tree
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f and g are functions

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g^(-1) is the inverse of g, also a function

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f(g(1/81)) means that you apply g to 1/18 and then you apply f to that result

minor notch
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it basically means that you first solve for g(x) and you get an answer.
then you solve for f(answer).

serene sage
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so by applying g to 1/18, does it mean log_9(1/18)

minor notch
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yes

serene sage
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okay do u think calculator is allowed in this ques?

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or no calc?

light sonnet
normal tree
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I was allowed a calculator on every exam I took in university lol

serene sage
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i'm gonna have a calc section and no calc section

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i'm not sure wether this is solvable without calc or no

normal tree
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it definitely is

light sonnet
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In my opinion, that question would be non calc because it's just applying log concepts and it's a simple enough question to do by hand

minor notch
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i wasn't allowed a calculator in university at all
so for me i can do it

serene sage
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kk, will try attempting it without calc

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tyy

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swift fulcrum
#

Can anyone teach me how to make an equation for 3D planes?

swift fulcrum
#

Where [x, y, z] = [6, βˆ’7,10] + s[1,3, βˆ’1] + t[2, βˆ’2,1]

normal tree
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equations of planes are generally given by $x \cdot n = k$

glossy valveBOT
#

Saccharine

normal tree
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where k is a constant, n is the normal vector

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x is the point that you're testing

swift fulcrum
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What about the equation Ax + By + Cz + D = 0?

normal tree
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that's literally the same as the dot product thing

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suppose n has components [A, B, C]

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then x dot n is literally Ax + By + Cz

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and k = -D

swift fulcrum
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Does n equal to [6, βˆ’7,10] here?

normal tree
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no

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[6, -7, 10] is a point on the plane

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note that a plane can be defined by a single point in space and two vectors on the plane

swift fulcrum
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Wait

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It says in my notes that there is no equations for scalar in 3D..

normal tree
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"no equations for scalar in 3D" this makes no sense on its own

swift fulcrum
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Oh that was for vector mb

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Could you explain this in a easier way please

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Our class when over this superficially

normal tree
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what, planes?

swift fulcrum
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Yea..

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I don't understand why this is in a high school curriculum

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Looks more like calc 3 stuff

normal tree
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it's probably more useful than a lot of other things

swift fulcrum
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I say integrations are more helpful

normal tree
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maybe, not sure

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do you at least know what a plane looks like

swift fulcrum
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A sqaure

normal tree
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no

swift fulcrum
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Rectangle

normal tree
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it's like an infinitely large sheet of paper in 3d space

swift fulcrum
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Ohh

normal tree
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suppose you start at a point on the plane

swift fulcrum
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Ye

normal tree
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suppose you're standing on the plane

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ik it's a stretch but just imagine it

swift fulcrum
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Okay

normal tree
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if you lay down two sticks on the ground, keeping in mind not to make them point in the same direction or opposite directions

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basically they're at some angle between each other that's not 180 degrees or 0 degrees

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you can get to any point on the plane by walking first in the direction of one of the sticks for some distance and then walking in the direction of the second stick for some distance

swift fulcrum
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Okay

normal tree
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flipping that on its side

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you can imagine that a plane can be defined by some starting point

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and the directions of those two sticks

swift fulcrum
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They stretch infinitely

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Right?

normal tree
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no they're just regular sticks

swift fulcrum
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Ok

normal tree
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but I'm talking about the directions of them

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so their length doesn't really matter

swift fulcrum
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Ok

normal tree
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so basically you can come to the conclusion that a starting point and two direction vectors define a plane

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now knowing that, can you tell me why 3 points in space, i.e. a triangle, also defines a plane passing through them?

swift fulcrum
normal tree
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no

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that is nonsense

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"triangular plane" what even is that

swift fulcrum
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wdym by triangle?

normal tree
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I'm asking you why, if someone gives you a triangle in space, there's a planes that passes through it

swift fulcrum
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Because of x, y, and z planes in 3d?

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I'm not sure if I understand correctly

normal tree
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what are x, y, and z planes in 3D?

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if you don't know what words mean or how to use them together

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then use simpler words

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slamming a bunch of words together like linear combinatorics topology theory algebra does not grant them special meaning

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math is not about learning magical spells

swift fulcrum
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What do you mean if there is a plane that passes through a triangle?

normal tree
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I mean that every point in that triangle is on a plane

swift fulcrum
#

Ohh

normal tree
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note that if I give you 4 points in space, there isn't necessarily a plane that goes through all of them

swift fulcrum
normal tree
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what has to be parallel

swift fulcrum
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The plane and triangle

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Or the three points in the triangle has to be in the equation of the plane

normal tree
#

yeah no it doesn't seem like you're absorbing anything

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like the stuff you're asking

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is just nonsense

#
Khan Academy

Learn for free about math, art, computer programming, economics, physics, chemistry, biology, medicine, finance, history, and more. Khan Academy is a nonprofit with the mission of providing a free, world-class education for anyone, anywhere.

#

you should also stop using words that make no sense

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and learn the proper definitions of them

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learn to make precise mathematical statements

swift fulcrum
#

Okay

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I'll go watch that video

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Are these matrices?

normal tree
#

column vectors

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torn jolt
#

V=U+ as for a. a=?

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torn jolt
#

I dont even know where to begin?

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#

@torn jolt Has your question been resolved?

torn jolt
#

no

gritty rose
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Screenshot or take a picture of the question

torn jolt
#

i solved it ty tho

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@hazy escarp Has your question been resolved?

brittle steeple
#

.close

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smoky marlin
#

Can anyone help?

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smoky marlin
#

i dont get it

shut thorn
#

what is $\cos 60$

glossy valveBOT
#

bettim

smoky marlin
#

1/2

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?

shut thorn
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what is $\sin 30$

glossy valveBOT
#

bettim

smoky marlin
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also 1/2

shut thorn
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so now what is $\cos 60 - \sin 30$

glossy valveBOT
#

bettim

smoky marlin
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0?

shut thorn
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yes

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corrct

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so what is any number times 0?

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$x \times 0$ ?

glossy valveBOT
#

bettim

smoky marlin
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ohhhhh

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oh daym

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okay thanks

#

okay quick question how to compute those numbers without calcu

shut thorn
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you're welcome

smoky marlin
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cuz i dont have cot on my calcu

shut thorn
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0, 30, 45, 60 and 90 are standard angles

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$\frac{\cos x}{\sin x} = \cot x$

glossy valveBOT
#

bettim

smoky marlin
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If so then cot is 1?

shut thorn
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x isnt equal nah?

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in cos it was 60 in sin it was 30

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if it was equal you can use

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for example

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$\frac{\cos 60}{\sin 60} = \cot 60$

glossy valveBOT
#

bettim

shut thorn
#

$\frac{\frac{1}{2}{\frac{\sqrt{3}}{2}} = \cot 60$

glossy valveBOT
#

bettim
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

shut thorn
#

$\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}} = \cot 60$

glossy valveBOT
#

bettim

shut thorn
#

$\frac{\frac{1}{\cancel{2}}}{\frac{\sqrt{3}}{\cancel{2}}} = \cot 60$

glossy valveBOT
#

bettim

shut thorn
#

so

#

$\cot 60 = \frac{1}{\sqrt{3}}$

glossy valveBOT
#

bettim

shut thorn
#

like this

sly frigate
smoky marlin
# shut thorn so

Ohhh i get it now thanks thanks now what about secant and cosecant

sly frigate
#

you could also take the reciprocal of tan45 to find cot45

#

that way you don't have to find each cos and sin

shut thorn
#

$\frac{1}{\cos \theta} = \sec \theta$

glossy valveBOT
#

bettim

shut thorn
#

$\frac{1}{\sin \theta} = \csc \theta$

glossy valveBOT
#

bettim

smoky marlin
#

Now what about this

shut thorn
#

wat is cos?

#

$\cos \theta = \frac{\text adjacent}{\text hypotenuse}$

glossy valveBOT
#

bettim

shut thorn
#

if cos increases, tnen it means the adjacent increases or the hypotenuse decreases

smoky marlin
#

Yepp

shut thorn
#

now look for all the functions that ahve adjacent in numerator or hypotenuse in the denominator

smoky marlin
#

sin has hypotenuse

shut thorn
#

$\tan \theta = \frac{\text opposite}{\text adjacent}$

glossy valveBOT
#

bettim

shut thorn
#

yes

#

sin is correct

smoky marlin
#

im guessing sine?

shut thorn
#

and tan is incorrect

#

but wait

smoky marlin
#

but why u send tan?

shut thorn
smoky marlin
sly frigate
smoky marlin
shut thorn
shut thorn
#

do you know sin and cos graphs?

smoky marlin
#

Nope

shut thorn
#

well to sum up

#

when sin increases, cos decreases

#

like a result

#

remember this

#

now let me come back to the question

#

what is sec?

smoky marlin
shut thorn
#

$\frac{1}{\cos \theta} = \sec \theta$

glossy valveBOT
#

bettim

sly frigate
shut thorn
#

okay

#

consider a triangle

smoky marlin
shut thorn
#

now if theta incrases,

#

now consider the two triangles

sly frigate
#

consider a triangle with a fixed hypotenuse length: to make the cosine value larger, you can do it by making the angle smaller - that way the adjacent will become longer
but when you make the angle smaller, the opposite length becomes smaller
and since sin=opp/hyp with the hyp being a fixed length, sine decreases as cosine increases

smoky marlin
#

:> how did we get here

sly frigate
#

do you understand that
cos increases -> adjacent increases -> opposite decreases -> sine decreases

shut thorn
#

ok in the second triangle, i increased the angle, cosx = a/h
sin x = o/h
we can observe that sin increases as theta increases, and cos decreases as theta increases

sly frigate
#

did you by any change learn about cosine and sine values using a unit circle?

smoky marlin
sly frigate
#

oh well it doesn't really matter here

#

you just need to understand that as cos increases, sine decreases

#

let's go back to this

#

we now know that sine isn't the answer

#

now let's look at secant

#

$\frac{1}{\cos \theta} = \sec \theta$

smoky marlin
glossy valveBOT
sly frigate
#

when the denominator of a fraction increases, does the fraction increase or decrease?

smoky marlin
#

decrease?

sly frigate
#

yes

#

so does secant decrease or increase?

smoky marlin
#

Decrease?

sly frigate
#

good

#

so now we know secant isn't the answer

#

let's look at cosecant

#

$\frac{1}{\sin \theta} = \csc \theta$

glossy valveBOT
sly frigate
#

a few minutes ago we figured out that sine decreases as cosine increases

#

using that, can you determine whether cosecant increases or decreases?

smoky marlin
#

so its also not cosencant

#

cuz if cosine increases then sine decreases and if sine decreases cosecant decreases

sly frigate
#

why so?

#

you just told me that when the denominator increases, the value of the fraction decreases

smoky marlin
#

oh wait

#

wait my brain is not braining

sly frigate
#

lol take your time

smoky marlin
#

if sin decreases that would make cosecant increase

sly frigate
#

yes

#

you can always make up examples to determine the behavior of the fraction

#

e.g. 1/4, 1/3, 1/2, 1/1...

#

the denominator decreases but the fraction value increases

smoky marlin
#

Okay okay now that makes cosecant the answer?

sly frigate
#

yes

#

but you should check tangent

#

just to be sure

#

tan=opp/adj right?

smoky marlin
#

yeh

sly frigate
smoky marlin
#

idk how to explain

sly frigate
#

the denomiator of tangent increases while the numerator decreases

#

that would make tangent decrease

smoky marlin
#

okay okay i get it now thanks

#

okay what about this

#

I dont get the question

sly frigate
#

i gtg now so i'll just sum it up quickly

#

let a=opposite, b=adjacent, c=hypotenuse in a right triangle

#

express all the trignometric values using a, b, c, and then use the pythagorean theorem c^2=a^2+b^2

#

hint: ||divide both sides of c^2=a^2+b^2 by c^2||

smoky marlin
#

How did we go to pythagorean theorem TT

sly frigate
#

oh because a, b, and c are the lengths of a right triangle

smoky marlin
#

WAIT WHAT THE YOUR EXACTLY RIGHT like seriously

sly frigate
#

that's why this is an identity

smoky marlin
sly frigate
#

it works for every right triangle

#

you should memorize this identity- it's a very important one

#

especially when you start learning trignometric functions, cosine and sine laws, etc..

smoky marlin
#

i got the answer but fr i dont get it

#

i got lucky lmao

#

because C^2 over C^2 is 1

sly frigate
smoky marlin
#

Nahhh i have no idea what a unit circle is and what i dont get is how A^2 and B^2 became cos and sin

sly frigate
#

it's only 2 minutes long

smoky marlin
#

Ohhhhhhh now i get why its cos and sin

#

because A and B is opposite and adjacent

#

And opposite over hypotenuse is sin

#

okay i get it now

#

Thankyouuuuu

#

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supple galleon
#

Can I use usub for this?

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scenic wren
#

for what?

tame crag
#

this

scenic wren
#

ahh

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supple galleon
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supple galleon
#

Can I use usub for this

#

<@&286206848099549185>

torn jolt
#

you have to use integration by parts

supple galleon
#

Ok

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supple galleon
#

What do I set U as

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supple galleon
vast fossil
#

That doesn't seem elementary

#

Because even after you do partial fractions

#

You get e^(-ax)/x + e^(-ax)/x^3

supple galleon
onyx glen
#

you'r probably out of luck for integrating this symbolically

#

or maybe not...? hold up

#

,w int exp(-ax)*(1/x + 1/x^3) dx

gritty rose
#

,w int e^(x)/(x+x^3)

onyx glen
#

or did you do a fucky wucky with the fractions

vast fossil
#

Oh, mb

#

Yeah

onyx glen
#

you did do a fucky wucky with the fractions

vast fossil
#

Right, I would rather call it a brain fart though as I had checked the fraction's decomposition in wolframalpha

supple galleon
#

So what do i set u as

onyx glen
#

nothing, you cant take this integral symbolically

vast fossil
#

My point is still there though, you end up integrating e^(-ax)/x and xe^(-ax)/(x^2 + 1)

vast fossil
#

E.g. multiplication, addition, sin, sqrt, so on

#

You will have to define something new in order to express it

supple galleon
#

How would I go about solving it then

fast peak
#

computer

#

or are you supposed to calculate a definite integral. maybe there are some complex analysis tricks for that

supple galleon
#

Idk complex analysis

full forumBOT
#

@supple galleon Has your question been resolved?

supple galleon
#

When solving this integral

#

Since i am solving in terms of A

#

Am I allowed to do what I did on the right side from steps 8-9

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#

@supple galleon Has your question been resolved?

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uncut willow
#

Is -3/2 the evaluation of (-8/27)^(-1/3)

uncut willow
#

oky thanks

#

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verbal harness
#

To solve this would I just do sin‐¹(5/13)? My steps were pythagreon Therom to get side RP which is 13 and then I just did sin

cosmic canopy
#

That seems right

verbal harness
#

Okay thanks

late grail
#

sin = opposite/hypotenuse

verbal harness
#

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verbal harness
#

.reopen

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#

βœ…

verbal harness
#

Does anyone know what I did wrong?

lucid cobalt
#

It's asking for sin P, not the angle measure of P itself

#

You did one step extra

verbal harness
#

So then how do I find sin p?

#

If I do sin(5/13) then I am just left with a decimal

#

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wanton wolf
#

How can I prove this? I am unable to find a way

brittle steeple
#

try combining the fractions

wanton wolf
#

Oh wait

#

Let me try that

#

i did that

#

but i am stuck at 2csc^2 A/ csc^2 A - 1 = 2 sec^2 A

nimble current
#

it might help to convert everything into sines and cosines

wanton wolf
#

yeah i was about to do that

#

because sec and csc can be converted to sine and cosines

#

imma try this

#

alr it worked

#

ty

#

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celest fulcrum
#

Hey, I did this question

full forumBOT
celest fulcrum
#

where did the 25 come from?

#

here is my work for reference

#

I want to learn how to do this so please dont give me the answer lol

#

Just kinda wanna know how they got the 25

torn jolt
#

-24-1 = -25

celest fulcrum
#

But it wont be -1 its going to be multiplied right

#

because when u solve the 0 the second part becomes -1 while soving the intigral

torn jolt
#

$-8 x e^{-8x}-e^{-8x} = (-8x-1)e^{-8x}$

glossy valveBOT
celest fulcrum
#

but the original just cancles everything out due to the x in the equation

#

oh shell methord?

torn jolt
#

?

torn jolt
celest fulcrum
#

yeah so if u sub in 3

#

it becomes

#

$-8(3)e^{-24}$

glossy valveBOT
celest fulcrum
#

-e^{-24}

#

$-8(3)e^{-24}-e^{-24}$

glossy valveBOT
celest fulcrum
#

3 times 8 would be 25

#

24****

#

so how does it end up with 25?

#

am i missing something

#

oh

#

nvm,

#

i figured it out

#

i was being dumb

#

ty for your help lol

#

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sleek quest
#

is there a ncie and simple way to do this that im not seeing?

sleek quest
#

maybe make some triangles?

celest fulcrum
#

the diagnal lines in the center are equal

#

so

#

one line is

#

$2sqrt(pi)$

glossy valveBOT
celest fulcrum
#

ah well

#

idk how to use this thing

#

but do you get what im saying?

sleek quest
#

anyone??

gritty rose
#

this looks like $\pi$

glossy valveBOT
#

riemann

sleek quest
#

oh

#

i see that

gritty rose
#

Or maybe one for area

#

either way, you have two equations and two unknowns

sleek quest
#

im not sure how i could relate the lengths and widths

gritty rose
sleek quest
#

length is x and width is y

#

x^2+y^2=11

#

x^2=11-y^2

#

x=sqrt(11)-y

#

y=sqrt(11)-x

gritty rose
sleek quest
#

why

gritty rose
#

unless you drew this picture wrong

#

your picture makes it look like $\sqrt{11}$ is the length from the center of the rectangle to C

glossy valveBOT
#

riemann

gritty rose
sleek quest
#

shouldve drawn that better

sleek quest
#

19=xy-sqrt(11)x-sqrt(11)y+11

#

does that work?

#

doesnt seem so friendly

gritty rose
gritty rose
#

,tex $\sqrt{a + b} \neq \sqrt{a} + \sqrt{b}$

glossy valveBOT
#

riemann

hollow sable
full forumBOT
#

@sleek quest Has your question been resolved?

sleek quest
gritty rose
sleek quest
#

hmm

#

so is it x=sqrt(11-y)?

#

@gritty rose

gritty rose
#

go the other way

sleek quest
#

then im not sure what it is

gritty rose
#

use the area of the square to plug into pythagorean theorem

#

xy = ?

sleek quest
#

19

gritty rose
#

correct

#

solve for y (or x, doesn't matter) and plug into the pythagorean equation

gritty rose
sleek quest
#

oh

#

so -sqrt(11)x-sqrt(11)y+11=0

gritty rose
#

no idea how you got that

#

did you solve for y yet?

gritty rose
sleek quest
#

x=19/y

#

sorry

sleek quest
#

i get some really nasty numbers out of that

full forumBOT
#

@sleek quest Has your question been resolved?

sleek quest
#

@gritty rose

#

anyone????

#

<@&286206848099549185>

pulsar gale
sleek quest
pulsar gale
#

or you just messed up somewhere

sleek quest
#

maybeeee

#

i dunno where

sleek quest
#

xy=19

#

because of area

#

x^2+y^2=11

#

due to pythagorean theorem

sleek quest
#

not sure why there are no real roots

#

please ping if you have an answer

pulsar gale
#

x^2 + (19/x)^2 = 11

#

,solve x^2 + (19/x)^2 = 11

#

,w x^2 + (19/x)^2 = 11

glossy valveBOT
pulsar gale
#

@sleek questsometimes that happens

#

maybe they messed up the question

sleek quest
#

maybe

#

what if something cancels out and produces a nice number when we find the perimeter

#

2(x+y)

#

hmmm

#

maybe we're missing something

pulsar gale
#

Which for 19/x is false

sleek quest
#

right

pulsar gale
#

@sleek questso theres no solution, problem solved

sleek quest
#

ok!

#

thanks

#

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dusky drift
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dusky drift
#

how do I first get started with this?

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@dusky drift Has your question been resolved?

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@dusky drift Has your question been resolved?

dusky drift
#

<@&286206848099549185> ?

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loud hull
#

[\frac{d}{dx} = 5(6x+2)(3x^2 +2x + 1)^4 = 4(30x+10)(3x^2 +2x + 1)^3]

glossy valveBOT
#

dopediscorduser

loud hull
#

,w derivative 5(6x+2)(3x^2 +2x + 1)^4

glossy valveBOT
loud hull
#

Where am I going wrong?

rocky saddle
#

ok

rocky saddle
sly frigate
#

!show

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#

Show your work, and if possible, explain where you are stuck.

#

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worn flare
#

@loud hull still need help?

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runic bloom
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runic bloom
#

can’t you just plug in pi/4 for x?

#

and then series of (1/2)^k

#

so geometric

#

a / (1 - r)

#

so 1 / (1 / 2)

#

so why isn’t it 2

#

the key says it’s D

torpid stag
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@runic bloom Has your question been resolved?

runic bloom
#

ah

#

thx

#

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shy tinsel
#

,rotate

glossy valveBOT
shy tinsel
#

!status

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#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
gritty ember
#

1

#

or

#

i dont know how to break down the shape into a cone and cylinder

shy tinsel
#

but you can see that it's a cone and a cylinder right?

gritty ember
#

yea

fringe quiver
#

what is the question?

shy tinsel
#

and you also have some different lengths

gritty ember
#

yes

shy tinsel
#

so what about the cylinder?

gritty ember
#

the cylinder

shy tinsel
#

you already have the height and the diameter for that one

gritty ember
#

yea but what ab the radius for it?

shy tinsel
#

well radius is half of the diameter

gritty ember
#

wait

shy tinsel
#

so you can find the diameter

gritty ember
#

is the diameter 8

shy tinsel
#

yeah that's what it says

gritty ember
#

ohh ok so hald of 8 is 4

shy tinsel
#

yup

#

so now you can find the volume of the cylinder

gritty ember
#

okok so let me solve one sec

#

i got 144

shy tinsel
#

almost

#

it must be 144*pi

gritty ember
#

oh yes

#

144 pi my bad

#

but how do we get 16?

shy tinsel
#

so now you have half of the answer

#

because there is still a cone

#

so what do you know about the cone?

gritty ember
#

the cone has a radius of 4

#

same radius as the cylinder

shy tinsel
#

yup

#

and what about the height?

gritty ember
#

does the height stay as 9??

shy tinsel
#

no

#

you can see that the total height is 12

#

and you also know the height of the cylinder

#

so you can now figure out the height of the cone

gritty ember
#

do we subtract??

shy tinsel
#

yup

gritty ember
#

so we get 3

shy tinsel
#

yup

gritty ember
#

so 3 is fhe heightof the cone

#

and now we do the volume

#

and we get 16

#

and then to get the last blank we just add correct??

shy tinsel
#

yes

gritty ember
#

okayyy

#

what about part b? the third and fourth one

#

bcs ik the first two i know the lateral area im js confused ab the last two

shy tinsel
#

well the base of a cylinder

#

what kind of shape is that?

gritty ember
#

cylinder

#

do we js do the normal area for it??

shy tinsel
#

but the base of it

gritty ember
#

oh

shy tinsel
#

that's just a circle

gritty ember
#

circle??

shy tinsel
#

yea

#

so the area of the base is just the area of the circle

gritty ember
#

ohh

#

so pi radius squared

#

so 16

#

what anout the surface area of the solid??

shy tinsel
#

then you just add them all up

gritty ember
#

ohh

#

wait

#

so

#

OHHHH

#

72+20+16

#

THANK U SOOOOO MUCH

shy tinsel
#

no p roblem

gritty ember
#

:))

#

.close

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#
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#
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urban tiger
#

hi

full forumBOT
urban tiger
#

I’m completely lost rn

#

my notes barely really help me

#

we’re doing rational expressions

real relic
#

send the Q

urban tiger
#

Starting with number 4

#

rn

#

Uh

#

It’s

real relic
#

I can't see the powers clearly

urban tiger
#

7x^3

#

-x^2

#

bottom says 2x^3

#

It’s a really small monitor so I can’t take a clear picture

#

here’s a better one sec

real relic
#

$\frac{7x^3-x^2}{2x^3}$

urban tiger
glossy valveBOT
urban tiger
#

yeah that seems right

real relic
#

do you know how to cancel powers

urban tiger
#

uh I mean I assume just cancel out the x^3 because they match?

real relic
#

yes

real relic
#

and you can also simplify $\frac{x^2}{2x^3}$

glossy valveBOT
shut thorn
#

take $x^2$ common and then cancel

glossy valveBOT
#

bettim

real relic
#

like

shut thorn
urban tiger
#

okay I’m confused

real relic
#

$\frac{7x^3}{2x^3}$-$\frac{x^2}{2x^3}$

urban tiger
#

what are you doing atm with the question

glossy valveBOT
real relic
#

can you simplify each fraction?

urban tiger
#

I don’t know what you did to get to that step

shut thorn
#

or just

#

$\frac{x^2(7x-1)}{2x^3}$

real relic
#

All i did was $\frac{a+b}{c} = \frac{a}{c} + \frac{b}{c}$

glossy valveBOT
#

bettim

urban tiger
#

yeah factoring

#

we need to do that

#

that’s what a lot of my questions and examples are

shut thorn
#

$\frac{\cancel{x^2}(7x-1)}{2x^\cancel{3}}$

glossy valveBOT
#

bettim
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

shut thorn
#

so now its

urban tiger
#

but I’m not very good at factoring so I’m confused on what’s the easiest way to determine factoring for bigger numbers

shut thorn
#

$\frac{7x-1}{2x}$

glossy valveBOT
#

bettim

urban tiger
#

yeah

#

you can’t cancel out the x’s further?

#

to get a final answer of 4?

#

ah they’re gone

shut thorn
#

no

#

thats t

urban tiger
#

oh okay

#

so you can only simplify until there’s one value of x left

#

and then you leave it alone

shut thorn
#

you cant simplify further

#

yes

urban tiger
#

okay

#

what really confuses me

shut thorn
#

or you can do $3.5 - \frac{1}{2x}$

glossy valveBOT
#

bettim

urban tiger
#

Is stuff like 5 and 6

#

because I’m not sure how to factor that

#

image sendng

#

this

#

like I know you are supposed to factor it so I can cancel out the common numbers

#

but I’m not sure how to do it

#

the only factoring method I really remember is the Diamond thing

#

where you take a and c, multiply it, and then take b

#

uh like this

#

then you find two numbers that multiply to equal a*c, that also add to equal b

#

If I can figure out the factoring then I think I’m good

#

Cause I know how to cancel out and everything

shut thorn
#

uhm i have no idea about this diamond method

#

can you state which que exactly you want assistance

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#

@urban tiger Has your question been resolved?

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β€’ Show your work, and if possible, explain where you are stuck.
β€’ After 15 minutes, feel free to ping <@&286206848099549185>.
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scenic cedar
#

hello?

full forumBOT
scenic cedar
#

a way to figure out:
what is the chance of hitting the same number, 5 times in a row, on a sixsided dice?

#

<@&286206848099549185>

torn jolt
#

tell me the total number of possibilities/sample space for this question

willow sedge
#

Because every time there is a probability of hitting a number 1/6

torn jolt
#

stop giving answers directly

willow sedge
scenic cedar
#

i mean like in a format?
fx. i used this format to try and figure it out but im not sure.

"this":
β…™ = 16,67%

16,67 : 20 = 0,8335

scenic cedar
#

and then what is it 5 times in a row

#

?

willow sedge
#

in all 5 turns

#

so the probability is just 1/6

scenic cedar
#

ok, but doesnt the probability get lower when it has to be in a row 5 times?

willow sedge
#

No

#

Try to understand

#

There are 6 possible outcomes

scenic cedar
#

yes

willow sedge
#

in each roll

scenic cedar
#

for five turns

willow sedge
#

so regardless of what we got earlier

#

we have probability of 1/6

scenic cedar
#

yes ik for 1 throw it should be 1 / 6 but the chances lower to get all 5 times in a row

willow sedge
#

Let me give you an example
Assume you want to roll a 3 5 times

scenic cedar
#

ok

willow sedge
#

So with the probability of 1/6 you got it in the frrst roll

scenic cedar
#

yes

willow sedge
#

Now lets forget you got a 3

#

So the probability that we again get a 3 just remains 1/6

#

and so on till 5 rolls

scenic cedar
#

i dont think you understand my question..

willow sedge
#

I do my friend

#

TBH I got confused on a similar questions about an year ago and I refused to accept the answer

#

It was what is probabiltiy of getting a 69 twice in cartd numbered from 1 to 100

scenic cedar
#

it just doesnt make sense

willow sedge
#

bruh

#

It'll be 1/100

scenic cedar
#

yea

willow sedge
#

there is a similar concept in your question

scenic cedar
#

can we start over? (sorry) im just gonna translate my text.

#

2 sec

#

whatever, thanks though.

#

πŸ‘

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#

@scenic cedar Has your question been resolved?

#
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β€’ Show your work, and if possible, explain where you are stuck.
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atomic vortex
full forumBOT
atomic vortex
#

for this

#

it has to be

#

wait acc

#

x^2+1 is irreduceable right

#

B/x+4, J/x^2-16, kx+L/x^2+1 , gx+h/(x^2+1)^2

#

oh wait isnt x^2-16 reducable

#

there

#

is that all?

#

or acc

#

what abt

#

M/x-4

#

since I can reduce (x^2-16) to (x-4)(x+4)