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[tardy lotus]

How can I even find an approach to solve this?

[thick minnow]

show that it satisfies all the axioms of vector space

I think there are 8 or 10 axioms

[tardy lotus]

Well I don't know what they are and I am also unfamiliar with the notations that they used

[thick minnow]

Then google them or look up some textbook, there is no other way

[deft zodiac]

https://en.m.wikipedia.org/wiki/Vector_space

defn n basic properties

[normal tree]

could probably show the existence of an isomorphism to the standard R+

if you want an interesting way to do it

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@tardy lotus Has your question been resolved?

[tardy lotus]

Can you provide some resources that explains this whole topic. Because I don't have any idea about these type of math

[normal tree]

read this and prove it the normal way first lol

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@tardy lotus Has your question been resolved?

[tardy lotus]

Ok thanks

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[bitter lagoon]

Hi, can someone explain to me how this transformation works?

[bitter lagoon]

This is a follow up on my question from yesterday. Full context can be read here: https://discordapp.com/channels/268882317391429632/486844829209198613/1064976691690221578

How does the sum become the expression

This is another form of the transformation

The proof that they are equal is pretty straight forward imo I just want to know how someone would transform a sum into this

[fading steeple]

Induction, probably

[bitter lagoon]

Is there no other way than to use induction to transform the sum into a form without a sum?

[fading steeple]

You can probably reduce it using combinatorial formulas also

But offhand i don't have paper

[bitter lagoon]

The thing I'm most interested in tbh is how the professor got this exercise. He must've known that they are equal somehow...

Through trial and error perhaps?

[fading steeple]

Or he went to look up Gould's identities

There are a lot of those

There are also books on combinatorial identities

Or identities basically

[bitter lagoon]

Interesting I've never heard of him before

It's an answer good enough for me

Thank you very much

[fading steeple]

You're welcome 🙂

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[timber brook]

$lim x->0+ (1+x)^(1/x)$

[timber brook]

$(1+x)^(1/x)$

[glossy valve]

boda

[timber brook]

could someone help me doing this limit

i check'd the resolution

and for the first step it gets an "e" and an ln that i dont know where it comes from

[hot herald]

consider the sub
u = 1/x

[timber brook]

i'm sure im missing some property

[hot herald]

a definition of e will be applied in one way or another

[timber brook]

im sorry, could you explain it in another way, i guess im missing part of the theory

about that "e"

[hot herald]

look up definitions of e

[timber brook]

ok ill check that out ty

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[digital citrus]

hey, Dose anyone know What math 100 course in college contains of?

[fast peak]

math. for more specifics I would hope that your college has descriptions for the courses

[digital citrus]

it doesnt

[fast peak]

if you just google math 100 course you'll find several lists of topics which are always slightly different

[torn jolt]

or ask the course lecturer, or your student advisor

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[serene sage]

can someone pls help me with this

[rose rain]

question 14?

[serene sage]

13

[rose rain]

completed the square yet?

[shrewd hamlet]

How come u didn’t finish the -b/2a=-3

[serene sage]

not sure what to complete the square of

[shrewd hamlet]

That’ll give u b

No need to complete square

[rose rain]

yeah thats probably better tbh

[serene sage]

so b = 6a?

now i should substitute?

[shrewd hamlet]

We know ‘a’

[serene sage]

how

[glossy valve]

Stephen

[serene sage]

but then why cant we assume b and c to be 1 as well 🤔 thought we were suppoussed to find all the coeff

[shrewd hamlet]

There’s no coefficient of ‘a’ shown in the equation, only ‘b’ and ‘c’ are listed

[serene sage]

ahh okay

[glossy valve]

Stephen

[serene sage]

even in 14, x = -1?

[shrewd hamlet]

a=-1

[serene sage]

kk tysmmm

[shrewd hamlet]

Np

[serene sage]

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[mighty tangle]

Hey,
With this CDF calculation, shouldnt it be F(26)-F(24)?

[mighty tangle]

Because 24 is still within our probability right?

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@mighty tangle Has your question been resolved?

[mighty tangle]

<@&286206848099549185>

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@mighty tangle Has your question been resolved?

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@mighty tangle Has your question been resolved?

[bitter lagoon]

If I understood cumulative distribution functions correctly, with it being defined for a random variable X as $F_X(x) = P(X \leq x)$, the probability of X lying with in the semi-closed interval $\left[a,b\right)$ is $P(a < X \leq b) = F_X(b) - F_X(a)$. In your case you ask for $P(24 \leq X < 26.2)$ which in turn is equal to $P(23 < X \leq 26) = F(26) - F(23)$

[glossy valve]

Cyrol

[bitter lagoon]

The equality follows, as $26 < 26.2$ and $23 < 24$. As 24 is the next bigger value after 23, this fulfills the requirement of your probability calculation, that $24 \leq X < 26.2$

[glossy valve]

Cyrol

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[torn jolt]

Hi!

[torn jolt]

(1x0.5) + (1x0.5) + (2x0.25) + (3x0.25)

i thought that was the approach... I don't understand how two 1/4s morph into a 3/4

[full forum]

@torn jolt Has your question been resolved?

[torn jolt]

PS this relates to expected value

[viral jasper]

Where did you get the extra 1x0.5 from

[snow obsidian]

you mean this step?

[torn jolt]

ohh my bad, i took the two 1 events as seperate, but that's is obviously not correct given that a probability distribution amounts to 1 (0.5 + 0.5)

[torn jolt]

yes this step

me confusie

[snow obsidian]

what is 3 times 1/4

[torn jolt]

but then again, it does state 1/2 + 1/2... i thought that was equivalent to 0.5*1

[viral jasper]

Ah that's a fair mistake. Glad you realized it

[snow obsidian]

there is half a chance to get 1 space

why would you take it 2 times

that would make a 100% probability that you will get 1 space

[torn jolt]

yeah thats what i figured

[viral jasper]

The probably of 1 space is 1/2 because there are two 1/4 chances to get it

[torn jolt]

but in that pic you shared, it has 1/2 + 1/2? isnt that 1? (i.e. 100%)

and what makes for 3/4?

[torn jolt]

isnt that 1/4 though? sorry im sure something that is otherwise clear is flying over my head

[snow obsidian]

$\frac{1}{4} \cdot 3$

[glossy valve]

Shockshwat

[snow obsidian]

what is the value of this

[torn jolt]

UHHHHH

yes 3/4

0.75

[snow obsidian]

ye so theres ur ans

[torn jolt]

yes this is all cleared up now, thank you guys so muchhh

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[wicked oak]

Hi need help clarifying this

[wicked oak]

In 2
I subtract the 180 with the 77 degree so i do this every question like this?

[tight glen]

When you have supplementary angles, and one angle is given. You have to find the other. Then yes. You subtract guven angle from 180 deg

[wicked oak]

Ty

Is this also the case with complementary

Angles

[tight glen]

You subtract the angle given from 90 deg instead of 180

[wicked oak]

Ty

[tight glen]

Np

Good day to you

[wicked oak]

I also have a question

On this one

In the 7x + 2

Im talking about the 4th question

I also add the 2 in the 8x -9 the - 9 part

[tight glen]

Wdym?

[wicked oak]

After that i disregard the 8x -7x

[tight glen]

As in, you have already written 7x+2= 8x-9. You talking about solving for x?

[tight glen]

Disregard?

Wdym?

[wicked oak]

In the first part of the equation once you add the + 2 to the -9

[tight glen]

You don’t add +2 to the -9.

[wicked oak]

Why did it become - 7

[tight glen]

7x+2 = 8x-9

[tight glen]

It did not

Go through it step by step

[tight glen]

That is correct

But I wanted you to solve it yourself

And not show me the solution they have provided

[wicked oak]

Oh i was just asking why did it go from 8x - 9 to 8x - 7

[tight glen]

It is 7x*

They subtracted 7x from both sides of the equation

So as to get rid of it from the left hand side of the equation

[wicked oak]

Oh since they are congruent right?

Wait i think i know

The answer

Oh im dumb lol you told me the answer

So in every question like this

Like 9 + 5 = 8x - 7 i do
14 + 5 = 8x - 9

@tight glen this correct?

Given: AB¯¯¯¯¯¯¯¯≅CD¯¯¯¯¯¯¯¯, AB = (x + 14) cm and CD = 25 cm. What is the value of x?

How do i solve this

[tight glen]

Set the values equal

(x+14 )cm and 25 cm

[wicked oak]

Ok so
Ab = cd

4x + 3 x + 21

Wait i was looking at another question

[wicked oak]

So i do ab = cd

Or
X +14 +25cm

[tight glen]

Equal yes

[tight glen]

Why would you do that?

[wicked oak]

Idk tbh

So once i set it equal what do i do

[tight glen]

You solve for x

[wicked oak]

Ok ry

Ty*

[wicked oak]

Like this?

[tight glen]

Yes. More or less

You should review basic algebra

[wicked oak]

Yep

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@wicked oak Has your question been resolved?

[wicked oak]

Where did they get the +3 in

In 2

[tight glen]

Same idea

LM= FT

So

Set them equal

(2x-3)cm and 11 cm

[wicked oak]

Ik that bit

But*

In here

Where did they get +3

[tight glen]

Added 3 on both sides of the equations

To get rid of it on the left hand side

[wicked oak]

To get rid of 2x?

[tight glen]

2x is 2*x

So to get rid of the multiple of 2 in the 2x, you divide for sides by 2

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[torn jolt]

ik lol

[woeful inlet]

What's wrong?

[torn jolt]

i was tripping

[woeful inlet]

Your answer is correct

[woeful inlet]

Happens

[hybrid oak]

just wanted to confrim

conform

confrim

confirm

[woeful inlet]

You have 3 coordinates/points

So what's the problem?

[hybrid oak]

i cant figure out how to find the equation for the table

[hot herald]

well how did you determine the equation in the previous question

[hybrid oak]

that was line of best fit

[hot herald]

yeh...

and how did you use that line to determine its equation

[hybrid oak]

i forgot

[hot herald]

how do you forget something like that

are you implying that you are now unable to determine equations of any lines?

[woeful inlet]

Doom we always find 2 points on the line and then use the formula. Now the line isn't given and it gave you the 2 points. So how do we solve it?

[hybrid oak]

what are the 2 points

[hot herald]

well in the current question you are essentially given three, you can pick any two you want

[woeful inlet]

They are given in the table

[hybrid oak]

-4 and -3

[woeful inlet]

Yes that's one of the points

[hybrid oak]

4 and -1

[woeful inlet]

That's another point

[hot herald]

and supposedly in the previous question there were even more to choose from, and you were somehow able to get the equation from that

[hybrid oak]

-4 and -3 4 and -1 0 and -2

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[ember tree]

How do u calculate the percentage change between multiple numbers?

[stable plover]

100 x (new - old) / old

[ember tree]

What if there's 6 sets of numbers?

[stable plover]

then your question is unclear

what do you mean by percentage change

[ember tree]

between multiple numbers

1985 and 2010. Specify whether this change is a percent increase or decrease.

[stable plover]

this is the percentage change between two numbers

namely the number of immigrants in 1985 and the number of immigrants in 2010

[ember tree]

https://i.gyazo.com/e7fe2cdadb20527b52f89f01fde7bc21.png

between 1985 and 2010?

[stable plover]

no

which numbers in this list correspond to 1985 and 2010

[ember tree]

Why does it say between then?

[stable plover]

you left out a column

[ember tree]

The top is 1985 and the bottom is 2010

[stable plover]

can you send the whole table?

[hot herald]

general vocab
eg what's the distance between A and B

[ember tree]

https://i.gyazo.com/425ae732139d729141b31a641eee52e8.png

[stable plover]

then the question asks you to find the percentage change between the two numbers 3546 and 35527

[ember tree]

What do you get when you calculate that?

[stable plover]

use the formula

[ember tree]

I'm getting 8.98% which is wrong

[hot herald]

how are you getting 8.98%

[ember tree]

100x3546-35527/35527

[stable plover]

first note the parentheses

second note the order of the two numbers

the question asks for the percentage change between 1985 and 2010

so you should put 3546 as the old value and 35527 as the new value

[ember tree]

Ok, that worked

ty

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[honest swallow]

Triangle

[honest swallow]

Question

[earnest grove]

4 * 9/2 = 6 * BE/2 => 4*9= 6BE => BE= 6

@honest swallow

[honest swallow]

What

[earnest grove]

S = ab/2 right

[honest swallow]

What is s

Sorry I'm not great at maths

So the area of the whole triangle is 6cm squered

[earnest grove]

Area…

[honest swallow]

Is this correct

No it's 18 isn't it

[earnest grove]

Uh yes

[honest swallow]

Cuz 9 times 4 decided by 2

[earnest grove]

That’s right

[honest swallow]

Mk

So from there how I get be

[earnest grove]

If you have S then just put the numbers and find h=BE

h = BE = 2S/AB

[honest swallow]

Ahhhh OK thanks so much XD I'm not smart XDDD

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[restive hawk]

just sort of confused as to how p->q in the first 2 red Ts

as P has false and q has true

but that still ended up with p->q

[ivory cairn]

false premise always results in a true implication

[restive hawk]

so what you’re saying is

suppose i have

a->b

let’s say a if F

therefore b is just true?

[ivory cairn]

no, a -> b is true

[restive hawk]

oh ok

we did not learn that statement in lecture

was just shown the table

so if whatever comes before the —> is false

it will imply whatever is after it?

[ivory cairn]

yep

[restive hawk]

interesting

but that wouldn’t hold for biconditional right

[ivory cairn]

that is correct, because if p is false and q is true, then q-> p is a false implication. So p <-> q is also false

[restive hawk]

right because for biconditional they have the have the same value

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[worn jackal]

Why does this happen?

[hot herald]

what specifically are you referring to

[worn jackal]

Why does a go away and a2 goes up

[hot herald]

wdym

[worn jackal]

Umm

U see how a dissapears

[hot herald]

do you know how to combine fractions through addition, e.g how would you simplify
$$\frac12 + \frac13$$

[worn jackal]

And u put a2 on top

[glossy valve]

ℝamonov

[worn jackal]

Yes is 6

[hot herald]

no

[worn jackal]

Its*

[hot herald]

1/2 +1/3 isn't 6

[worn jackal]

Noo

The 2 become 6 and 3 becomes 6

Then

1 gets multiplyed by 3 and the other one gets multiplyde byy 2

Sow the answer is 5

[hot herald]

no

[worn jackal]

5/6

Mb

[hot herald]

poor wording by you got the right result

apply the same principle to your question

[worn jackal]

I know i am terrible at explaining

[hot herald]

very poor wording
LCD is 6,
1/2 can be expressed as 3/6
and 1/3 as 2/6
1/2 + 1/3 = 3/6 + 2/6 = 5/6

[worn jackal]

Is not the same

Idk how to deal with it if there is a

[regal copper]

consider that there can be any number in place of a

so treat it how you would treat other numbers

[hot herald]

can you identify the LCM of
1,a,a^2

[worn jackal]

No

[hot herald]

can you identify the LCM of
1, 2, 2^2

[worn jackal]

Just doesn work idk i cant put 1 in front of both a's

[hot herald]

1a = a

don't overthink

can you identify the LCM of
1, 2, 2^2

[worn jackal]

Can u type that with bot idk what that want from me

[hot herald]

can you identify the LCM of
$$1,2,2^2$$

[glossy valve]

ℝamonov

[worn jackal]

2^2

[hot herald]

yes,

what about
$$1, 7, 7^2$$

[glossy valve]

ℝamonov

[worn jackal]

7^2

[hot herald]

what about
$$1, 1234, 1234^2$$

[glossy valve]

ℝamonov

[worn jackal]

But with a's is just confusing

The last one 1234^2

[hot herald]

now similarly what about
$$1,a,a^2$$
apply the $\textbf{same exact idea}$ that you applied for those 3 examples (don't overthink)

[glossy valve]

ℝamonov

[worn jackal]

a^2 but how do i use it the

[hot herald]

the LCM is a^2

well recall what you did with the simpler example with
1/2 + 1/3

I'm trying to get you to realise that the principle is exactly the same

[worn jackal]

Can u use it on example But with a's

[hot herald]

huh?

instead of doing the manipulation to get denominators of 6, use the same idea to get denominators of a^2

$1 = \frac{\text{what?}}{a^2}$

[glossy valve]

ℝamonov

[worn jackal]

1

[hot herald]

no

$1 \redneq \frac{1}{a^2}$

[glossy valve]

ℝamonov

[worn jackal]

Oke sow is a2/a2

[hot herald]

yes

[worn jackal]

Same as 5/5 =1

[hot herald]

$1 = \frac{a^2}{a^2}$

[worn jackal]

Can u solve thjs in spets

[glossy valve]

ℝamonov

[worn jackal]

Dont skip steps like photo math

[hot herald]

similarly
$$\frac5a = \frac{\text{what?}}{a^2}$$

[glossy valve]

ℝamonov

[worn jackal]

I dont know

[hot herald]

recall how you went from
1/2 to 3/6 in that simpler numerical example

and from 1/3 to 2/6

the numerator and denominator can be multiplied by the same amount to get an equivalent fraction

consider what multiplied to a gives a^2
and multiply the numerator and denominator of your fraction by that value

[worn jackal]

But then the answer would be

Sec

[lapis zodiac]

when I fail a math question, how should I practice to get better?

[hot herald]

yeh

[worn jackal]

But here

a^2 goes up

Not just a

The sam principle

[hot herald]

don't forget you had a 1 which is a^2/a^2

[worn jackal]

But then it would be a^3

[hot herald]

why a^3

[worn jackal]

Sec

[hot herald]

applying what we've gone through
$$1 - \frac 5a + \frac{6}{a^2} = \frac{a^2}{a^2} - \frac{5a}{a^2} + \frac{6}{a^2}$$

[glossy valve]

ℝamonov

[worn jackal]

I get it now

Idk why but i was thinking that a from the 2 gets multiplyed with a2 =a3

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[chrome idol]

is the empty set typically considered an interval?

[ivory cairn]

at best, that would depend on context.
I think you could say it's an empty interval, sure.

I would not consider the empty set an interval if we're talking about subsets of {1,2,3}

[chrome idol]

In the context of nested intervals, we had to prove/disprove the intersection of a nested interval is not an interval

either ways, time to argue for marks in office hours

since they did not define what interval is

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[ivory cairn]

you should check your definition of interval first

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[chrome idol]

they did not define it in textbook or in class

[ivory cairn]

it's probably defined somewhere in the book.

check the back appendixes or preface material

if they define something like (a,b) = {x | a < x< b} then i'd see an easy argument that a =/= b in the definition of an interval.

so (a,a) is not an interval

but either way, if you're going to go argue for points back, have something to show you've researched it a little and ask why you lost points

[chrome idol]

thanks

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[orchid kelp]

a) Determine n belongs to the set of natural numbers if the greatest common divisor of the numbers 3n+7 and 2n+6 is n+1
b) Solve the equation in the set of natural numbers: x^2-10x+y+7=0

[orchid kelp]

I need explaination

bc I have an math olympic tmw

and I don t feel ready

[full forum]

@orchid kelp Has your question been resolved?

[ivory cairn]

for a)
n+1 divides both terms. So (3n+7)/(n+1) and (2n+6)/(n+1) are both integers.
using the fact that 3n+7 = 3(n+1)+4 and 2n+6 = 2(n+1) + 4
You get (3n+7)/(n+1) = 3 + 4/(n+1) and (2n+6)/(n+1) = 2 + 4/(n+1) are integers

which means 4/(n+1) is an integer

find positive (or non-negative, maybe) values of n

or b)
y = -x^2 + 10x - 7 which is a downward facing parabola. so the only times y would be positive is between the roots.
use the quadratic formula to find the roots, then take the natural number x coordinates between the two roots, and plug them in to get your natural number ordered pairs (x,y)

[orchid kelp]

got it

Thanks a lot

this is a 7 grade (i am over 13)

but I know quadric formula

idk if I am allowed to use it

but wish me luck

thx again

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[gritty rose]

The fuck

14 order polynomial?

[hollow sable]

im reaching but what if you could find some sort of recursion between the number of nested roots

idk tho

[rapid laurel]

ok why is t> sqrt x

[spice orchid]

would help if you showed us what t is equal to

[rapid laurel]

just change of variable

of the six sqrt

[hollow sable]

it says it in the picture

[spice orchid]

well this thing is certainly bigger than sqrt(x) bc the stuff inside the first root is bigger than x

[rapid laurel]

wuttt??? stuff inside the first root?

what stuff are u talking about

[west sequoia]

Think about it in terms of a number

[spice orchid]

t = sqrt(x + stuff)

x + stuff > x since stuff > 0

[rapid laurel]

right

oh

i see

i get it

and we plug t back to the x equation

to get a range for x

very cool

[gritty rose]

just plug the 14th order monic into wolfie

[rapid laurel]

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[median beacon]

need some help plz

starting with a

[spice orchid]

rearrange for n

[median beacon]

chartbit

ahem

sleepy time no?

[spice orchid]

,ti @devout valley

[glossy valve]

The current time for chartbit is 01:11 AM (GMT) on Fri, 20/01/2023, the same as iCaird!

[spice orchid]

yeah go to sleep chartbit

[median beacon]

,ti ΣAC

[glossy valve]

The current time for iCaird is 01:12 AM (GMT) on Fri, 20/01/2023.

[light sonnet]

,ti @spice orchid

[glossy valve]

The current time for iCaird is 01:12 AM (GMT) on Fri, 20/01/2023.
dldh06 is 5 hours behind, at 08:12 PM (EST) on Thu, 19/01/2023.

[median beacon]

LMAO

,ti dldh06

[glossy valve]

The current time for dldh06 is 08:12 PM (EST) on Thu, 19/01/2023.

[median beacon]

o

[devout valley]

I’m like literally in bed haha

[light sonnet]

,ti SA2017

[glossy valve]

This user hasn't set their timezone! Ask them to set it using ,ti --set.

[median beacon]

AHAHAAHAH

get rekt

[devout valley]

See y’all later 🙋‍♀️

[devout valley]

We know your time zone anyway

[median beacon]

or do u

[light sonnet]

It's one of the 24 timezones that the world has

[gritty rose]

You forget half hour time zones in crazy parts of the world

[light sonnet]

They don't count

[acoustic stratus]

theres a 45 minute timezone too i think

[acoustic stratus]

or maybe its a 15 minute one

[median beacon]

^

[median beacon]

hey harper

[spice orchid]

so you just want the smallest n thats bigger than that expression

[acoustic stratus]

yep +0845, +0545, and +1245

[median beacon]

is epsilon a natural num?

it just says >0

[spice orchid]

its real

[median beacon]

what do we let epsilon to be then?

[spice orchid]

you dont let it be anything

[median beacon]

i was gona say 1 but it could be as small as 0.1 etc

[spice orchid]

youre doing this for a general epsilon

[median beacon]

how do we find least n then

[spice orchid]

well if that expression is negative, then the smallest n is 1

otherwise just take the ceiling of that expression

[spice orchid]

(or maybe 0, depends what your convention on the natural numbers is)

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[marsh cloak]

Basically idk how to start it

[weary stirrup]

good you understood what an angle of depression is by drawing that line

have you done solving using SOHCAHTOA

this is what you'd do here since it's a right triangle. the "B" angle is 21 and the angle "A" is 15 degrees

pretty sure you can solve from there

you're solving for the bottom one

[marsh cloak]

https://tenor.com/view/math-hangover-movie-the-alan-gif-18437148

[weary stirrup]

come on now it isn't calculus

but what I meant by the bottom one is the base

that is essentially how far away it is

[marsh cloak]

C - A?

[weary stirrup]

you're solving for both CB and CA right?

well now that I think about it it's BA for the second one

you should get started with the first one though

[marsh cloak]

https://tenor.com/view/mona-mona-genshin-impact-mona-genshin-genshin-mona-genshin-impact-gif-23478748

[weary stirrup]

it should become clear to you

it's a right triangle so 90 degrees

and it has angle B which is 21 degrees

180-(90+21) = angle 3

you have a side given to you

which i think is adjacent

so solve from there, you're trying to find opposite

using tan

Tan_ = O/A

[marsh cloak]

man i suck at reading when someone is explaining to me

[weary stirrup]

$Tan21°=\frac{O}{A}$

[glossy valve]

Zyme><SOL

[weary stirrup]

$Tan21°=\frac{O}{30}$

[glossy valve]

Zyme><SOL

[marsh cloak]

i get that part but what triangle am i using? DCA?

[weary stirrup]

first right triangle

work on each individually

[marsh cloak]

DCB?

[weary stirrup]

yes, DCB

$\frac{Tan21°}{1}=\frac{O}{30}$

[glossy valve]

Zyme><SOL

[weary stirrup]

and so on..

you'll get your first distance this way

I'll leave you to get the second one

[marsh cloak]

ok

[weary stirrup]

note* you're solving for opposite since it's the distance

[marsh cloak]

i got the distance for DCB

[weary stirrup]

so if you do anything make sure it has opposite in it

solve for the hypotenuse now

[marsh cloak]

angle 3 for DBA?

[weary stirrup]

to get the adjacent of the second

[weary stirrup]

DCB

[marsh cloak]

oh ok

i got a sussy number

anyway

[weary stirrup]

you can round it

[marsh cloak]

i meant a different sussy

[weary stirrup]

bruh 💀

teacher wilin

[marsh cloak]

💀

[weary stirrup]

you technically don't need that third angle

it's just nice to have

[marsh cloak]

now that I found the opposite

[weary stirrup]

all your angles and all your sides

[marsh cloak]

now I try to find the hypotenuse

[weary stirrup]

find the hypotenuse of DCB

[marsh cloak]

so now I use sin then?

or was it cos 💀

[weary stirrup]

you can use anything aslong as you have one of the two things

[marsh cloak]

gimme a moment while I got find the answer for "AHHHHHHHHHHHHHH"

[weary stirrup]

if you don't understand why you're doing this is because side "DB" in DCB is equal to "DB" in "DBA"

so since you have an angle for "DBA" you only really need a side

to start solving

[marsh cloak]

uhhh

so

like

i did

cos 90 = h/11.5 (prob wrong) and then i did the math and got 0 :/

[weary stirrup]

you shouldn't use 90 as your angle

[marsh cloak]

i'll use 69 then 💀

[weary stirrup]

nah but i think what you did there was right with 90 as your degree

since your solving for DB

[marsh cloak]

then what am i doing wrong???

[weary stirrup]

try $sin90=\frac{30}{H}$

[glossy valve]

Zyme><SOL

[marsh cloak]

oh 💀

ok gimme a sec

i got 30 m

so now i have all three sides from DCB

[weary stirrup]

ok, use 30m and your angle of 15 to find the distance from B to A

[marsh cloak]

so i use to laws or SOH CAH TOA

[weary stirrup]

you found the opposite, you need adjacent

[marsh cloak]

so tan

[weary stirrup]

yeah

use the angle your given

15

[marsh cloak]

uh huh

i got 8 m

[weary stirrup]

do you have an answer sheet

[marsh cloak]

yes

the answer is 34 m

[weary stirrup]

is that the answer?

for which

[marsh cloak]

this question

the one we're doing rn

[weary stirrup]

B to A is 34?

[marsh cloak]

it's asking how far apart are the boats if the observer is 30 m above water level

[weary stirrup]

we obviously did something wrong lol

partly because I'm not 100% focused

[marsh cloak]

💀

😭

i hate this question

[weary stirrup]

it's not hard

I'm just stupid

gimmie a sec

I'll do it and tell you what I did

[marsh cloak]

ok

[weary stirrup]

pretty sure the angle of depression has some relevance here

anyways, does it only say 34?

[marsh cloak]

yes

[weary stirrup]

hm

yeah I can't get it

maybe check with your teacher

[marsh cloak]

my teacher takes 10 years to respond

[weary stirrup]

or a friend, not too sharp with these questions

I ended up getting 29.1 for B to A

which is what I think you got

hold on

you can't use SOHCAHTOA

on that

theres a different thing

the second triangle can't have SOHCAHTOA be used on it

since it isn't right

[marsh cloak]

https://tenor.com/view/mona-mona-genshin-impact-mona-genshin-genshin-mona-genshin-impact-gif-23478748

[weary stirrup]

I'd ping <@&286206848099549185> since I'm just wasting your time at this point lol

[marsh cloak]

ok

<@&286206848099549185>

[weary stirrup]

put your question too

[marsh cloak]

its pinned?

[weary stirrup]

so they can see it, since its burried by text now

[marsh cloak]

pins

[weary stirrup]

oh ok, that works then

[marsh cloak]

while i'm waiting ima just go ask like 3 other servers 💀

[viral jasper]

@marsh cloak do you know trig?

[marsh cloak]

yes but this question be hitting diff 💀

[viral jasper]

For sure let's do it in steps

We're given <DBC=21 and <DAC=15.

With me so far?

[marsh cloak]

yes

if i don't say anything from this point then i'm heading to the bathroom but continue 💀

[viral jasper]

Okay so trig time

You know DC=30m and <DBC=21

So which trig identity can you use to find the length CB?

[marsh cloak]

tan

[viral jasper]

yes

So, using tan, what length do you get for CB?

[marsh cloak]

11.5

[viral jasper]

Mind showing your work?

[marsh cloak]

ye one sec

this pic is what i've done so far

[viral jasper]

You got this reversed

O is adjacent leg and 30 is opposite

btw I suggest against using O as a variable name. Looks like 0

[marsh cloak]

ok

x

and then

auck i hate this question 😭

[viral jasper]

and then?

wdym

[marsh cloak]

idk what im doing anymore 😭

[viral jasper]

you were close here

I'm sure you know tangent formula

tan=opposite/adjacent

DC is your opposite leg, and CB is your adjacent leg

We're given DC=30m, and we're assigning CB=x

So you have tan(21)=30/x

Solve for x

[marsh cloak]

so i divide for the tans basically

[viral jasper]

not sure what you mean

If you have an idea, mind writing out the math?

[marsh cloak]

so like

take the 30/tan 21

and the same thing for the tan 15

[viral jasper]

ah

yes

That will give you CB and CA

Then I trust you know how to find the ship distance, BA

[marsh cloak]

yes

thank you

time to be sitting on my chair for the next 2 hours

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[delicate snow]

help

[twilit leaf]

for these ones, we consider whether each is negative, positive, or zero

[delicate snow]

ok

[delicate snow]

for example, for option A f''(-2) is concave up, but for f'(3) how am i meant to know the stationary point

[twilit leaf]

it says in the statement at the top

f(3) is a local maximum which means f'(3) is equal to what number?

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@delicate snow Has your question been resolved?

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[toxic granite]

can y'all help me out with this

idk how to show the steps im very lost

<@&286206848099549185>

[tardy verge]

Use cosine law

[toxic granite]

can you show me how you would solve this question?? its a mock exam for practice. Pleaseee

[tardy verge]

Cosine lA

Do you know what’s cosine law?

[toxic granite]

yes

[tardy verge]

it’s a trigonometry law

then it’s obvious

[toxic granite]

but How do I get all the side lengths first

can you do that part G

plz

plz

[tardy verge]

Can you stop begging my help?

[toxic granite]

ok ok srry

[tardy verge]

You can find the intersection points by equating straight line equations

You first get the coordiantes for each intersection point

[toxic granite]

how would I do the equation part

[polar valve]

Get a Point B with x = 1 -> y = ... ->, Let C (1,2) look at the triangle ABC

[toxic granite]

hmm ok

[tardy verge]

If a point lies on two straight lines, then the x coordinate/y coordinate will be the same

For example

C intersects straight line y=3x+2 and 2x+2y-22=0

[toxic granite]

yea

ok

[tardy verge]

which means if I sub x into both equations, the y obtained form both equations will be the same

[toxic granite]

ok

how would I do the substitutions to solve the equation

2x + (3x + 2) - 22 = 0

would this be correct

[tardy verge]

Sure, that works

But it’s wrong, you forgot the coefficient 2

[toxic granite]

the y

[tardy verge]

You only add (3x+2) once

You must add another one

Because it’s 2y

2y = 2(3x+2)

[toxic granite]

I substituted (3x+2) as y

[toxic granite]

oh ok

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[silk solstice]

this identity is wrong right

isn't it suppsed to be
sin(m+n)θ - sin(m-n)θ

[tulip beacon]

check, plug some random numbers as m, n and theta

m = 2 n = 3 theta = 4, see if they equate

0.156 on left, -0.246 on right

doesnt hold so not true

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[cloud tartan]

hey, can someone spot my mistake? wolfram alpha says its 0

[lavish wren]

positive infinity is 0 because lim (x->∞) 1/x =o

negative infinity dne

[cloud tartan]

so i already know from start on that 1/(anything with n in it) is 0 ?

[lavish wren]

yes, unless you have something in the numerator with the same or greater degree

[cloud tartan]

ok ty! 🙂

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[mellow sun]

f,g n times differentialable functions

show for x e I that...

and b is get the formula 4b from a

[warm abyss]

I guess you have to use product rule and induction here

[mellow sun]

hmm

thats smart

im stupid

[rose rain]

no youre not

also tip when you see things with arbitrary n in naturals

induction is a good thing to try

:sotrue

[mellow sun]

ok

i dont really understand it cause my english is so bad but ok

[rose rain]

its a meme

[mellow sun]

how about b?

[rose rain]

more induction

[mellow sun]

i dont understand math memes

math is pain for me

[rose rain]

looks like you are taking analysis

which IS pain

[mellow sun]

i have to unfortunately

hahaha

moore epsillons than the eye can reach

[warm abyss]

Of course it can be proved with more induction (that's actually one of the harder ones at Analysis 1). But I think it needs to follow directly from a🤔

[rose rain]

hmm

constant function?

oh actually

[mellow sun]

there is a clue.it says: find a function f so that f´(x)=c*f(x) with proper factor c

[rose rain]

ooh

yeah I know of one

[mellow sun]

e?

[rose rain]

yup ur close

[mellow sun]

b?xd

[rose rain]

you just have to mess with e^blah blah

to get your correct factor c

[mellow sun]

ok thanks for the help gents ill see what i can do

can i as another question?

[warm abyss]

You can. Idk if I/we can answer

[mellow sun]

great

[rose rain]

if we cant try #real-complex-analysis

[mellow sun]

so i have to use the differential quotient for this one

in a i used the h method

but for b im just to stupid :/

[rose rain]

hmm I wonder if there's a clever way to turn that into a fraction

ah

(im guessing thats what differential quotient means?)

[mellow sun]

this is the differential qoutient sir

[rose rain]

oh definition of differentiability

[mellow sun]

yea

[rose rain]

ok we want to show its differentiable on R*

[mellow sun]

yes sir

without 0

[rose rain]

yeah thats R*

[mellow sun]

ohh

[rose rain]

hmhmhm

[stable plover]

this works pretty quickly with difference of cubes

[rose rain]

ok i assume u got this im popping off to sleep

[mellow sun]

have a great night dear active mental mutilation liker

[warm abyss]

You're right ! Do you know this formula Anan?

[mellow sun]

no

is it binom formula for n=3

?

[warm abyss]

It sais a^3-b^3 = (a-b)(a^2+ab+b^2)

[mellow sun]

ohh

well

oooookay

but how do i use it i have x(1/3

[warm abyss]

Say x^(1/3) is a and (x0)^(1/3) = b

Sorry, typo

[mellow sun]

nppp

okay but what next?

[warm abyss]

What's the denominator then?

[mellow sun]

3

[warm abyss]

3?

https://tenor.com/view/drei-jorge-gonzalez-gif-23175195

[mellow sun]

lol

[warm abyss]

No, normally it is x-x0

[mellow sun]

oh yea

i thought like in the exponent

cause im still wondering how to use that cube formula

[warm abyss]

.

[mellow sun]

but its 1/3...

[warm abyss]

If we do this x = a^3 and x0 = b^3

[mellow sun]

then its just a-b?

[warm abyss]

It's (a-b)/(a^3-b^3) - obviously with limits

[mellow sun]

yes

ah iseee

ok i dont

[warm abyss]

No problem

[mellow sun]

i mean we use formula then cut the a-b ?

[warm abyss]

Yes

Dafür müssen wir aber formell fordern, dass x nicht x0 ist

[warm abyss]

What do you get then?

[mellow sun]

a^2+ab+b^2

[mellow sun]

na klaro

but i have to subtitude it back at some point no?

[warm abyss]

1 over this

[mellow sun]

ohhh

[warm abyss]

Yes 🙂

[mellow sun]

we just use 3rd root of x=a

[warm abyss]

Yes

[mellow sun]

that was my problem

ah noice gg

[warm abyss]

And the 3rd root of b = x0

[mellow sun]

thanks a bunch kohlemaennchen!

[mellow sun]

for sure yes

[warm abyss]

You're welcome

[mellow sun]

.close

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Channel closed

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Use .reopen if this was a mistake.

[full forum]

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[silent sierra]

so I took the log base 2 of both sides

and I have x = (x+3) log_2(3)

but I still have to isolate x on one side right?

[glossy valve]

Stephen

[silent sierra]

Yeah I did that

[shrewd hamlet]

Into what

[silent sierra]

I just move it to the front of the log

(x+3) log_2(3)

or do you want me to make it into 3 to the x power times 3 to the third power?

[shrewd hamlet]

Ye gimme 1 sec, brb

[shrewd hamlet]

Ok yes do this

[silent sierra]

alr

[shrewd hamlet]

What do u get after that

[silent sierra]

2 to the x = 3 to the x times 9

oops

27 I mean

[shrewd hamlet]

Can u write it a lil more clearly

[silent sierra]

2^x = 3^x * (9)

[shrewd hamlet]

What’s 3^3

[silent sierra]

oh yeah meant 27

[glossy valve]

Stephen

[shrewd hamlet]

Now what do you think we shd do

||hint: get all x terms to one side||

[silent sierra]

divide by 3^x?

[shrewd hamlet]

Sure we can do that

So what do we get after that

[silent sierra]

2^x / 3^x = 27

[shrewd hamlet]

Good

Now how can we isolate the x?

[silent sierra]

take the log of both sides

[shrewd hamlet]

Well we need to do something first

How can we combine the 2^x / 3^x

||Hint: power of a quotient rule||