but might be too much
#help-28
topaz valley
thorny horizon
topaz valley
eternal agate
hello can someone show me how you would solve this?
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hello can someone show me how you would solve this?
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cursive badger
for this question
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for this question
cursive badger
i would make y=1/x^2
in terms of x
and the integral would be for 1 to 9 right>
?
wintry citrus
yeah
cursive badger
but when i do that my value is only half of the ans
rocky saddle
what is your ans
cursive badger
4
wintry citrus
show your work
rotund birch
you prob took the integral wrong
wintry citrus
4 is right
cursive badger
rotund birch
its 2sqrt(y) and if you take the boundaries as stated above it gives 4
cursive badger
what is the difference between (a) and (b)
full forumBOT
what is the difference between (a) and (b)
brisk obsidian
brisk obsidian
what is the difference between (a) and (b)
a is asking about the blue area and b is asking about the orange area.
brisk obsidian
Which one, a or b?
brisk obsidian
Just so you completely understand what you are doing, you are using the Area formula and integrating with respect to one of the dimensions.
$\int_a^b \underbrace{f(x)}{\text{length}} \cdot \underbrace{dx}{\text{width}}$
glossy valveBOT
Kookiemon
brisk obsidian
For part a, you need to determine an expression for the length.
cursive badger
would i convert x in terms of y?
brisk obsidian
Solving in terms of x or y is often determined by how easy it is to integrate along an interval.
As well as the simplicity of determining the upper and lower bounds.
Anytime you change one or both boundaries, you need to evaluate a different interval.
cursive badger
would the boundaries be 0 and 4?
brisk obsidian
One moment, I'm making a graph so that you can visually see for yourself what I mean.
Once you have looked at that, let me know.
cursive badger
ive checked it out
brisk obsidian
The length in the integral is calculated by subtracting x^2 from 4 - x^2. The boundaries do not change across the entire interval from [-sqrt(2), sqrt(2)].
Do you understand how that length is calculated?
brisk obsidian
So if you were to solve in terms of y, the boundaries change at y=2.
brisk obsidian
You would need to evaluate two separate integrals in terms of y; [0,2] and [2,4].
Do you understand why?
cursive badger
im guessing as they intersect at 2?
brisk obsidian
Well, not just only because they intersect at 2, but mostly because the upper and lower boundaries change.
From [0,2], the boundaries are defined by the function y = 4-x^2 or x = sqrt(4-x).
And from [2,4], the boundaries are defined by the function y=x^2, or x = sqrt(y).
brisk obsidian
No.
What is the length of the horizontal line for x=sqrt(y)?
What is the length of that line?
cursive badger
2sqrty?
glossy valveBOT
Kookiemon
brisk obsidian
And you would have to calculate the expression of length for the interval from [0,2] as well.
This is more work than you need to do.
Because you can just solve one integral if you solve in terms of x.
$\int_{-\sqrt{2}}^{\sqrt{2}}{((4-x^2) - (x^2)) dx}$
glossy valveBOT
Kookiemon
cursive badger
In terms of x?
brisk obsidian
Yes.
cursive badger
Is it not meant to be in terms of y
brisk obsidian
Unless the question specifically asks you to solve in terms of y, you should determine which axis of integration to use based on how easy it would be to solve.
For the blue area, you only need to solve one integral in terms of x and two integrals in terms of y.
Which would be easier?
Is it easier to solve one integral or two integrals?
cursive badger
One
brisk obsidian
Ok, and you can solve a with one integral if you integrate in terms of x.
For part b though, you would have to solve using two integrals because the upper boundary changes.
cursive badger
this question is making my brain explode
brisk obsidian
The two lengths are calculated differently.
So you would have to use two integrals for each length.
brisk obsidian
Yes.
However ...
If you were to solve in terms of y, the boundaries of the length are the same across the entire interval so you would only need one integral.
cursive badger
Tbh can’t be asked to change to y values
brisk obsidian
Well, you will need to learn how to do that eventually.
cursive badger
Ye ig
brisk obsidian
So in terms of x, you would need to use two different integrals.
On the left side, the upper boundary is x^2 and on the right side the upper boundary is 4-x^2.
The lower boundary for both is the x-axis so y=0.
fervent meteor
How do you find roots of something like x^7+8x^3-6x^5=0?
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How do you find roots of something like x^7+8x^3-6x^5=0?
waxen yew
Factorize or something right?
fervent meteor
I mean ofc but how
nova wing
Factorize or something right?
yeah, have fun with that 🤣
dapper bane
How do you find roots of something like x^7+8x^3-6x^5=0?
you can factorise x³
indigo ore
Well obviously x=0 is a root, your best guess would be to find another root after factorizing
fervent meteor
I was basically doing a question of binomial and it came down to this , the solution I found of that question in the book it basically never opened the brackets
dusty musk
How do you find roots of something like x^7+8x^3-6x^5=0?
take something common
fervent meteor
severe spear
no, you can use hidden quadratics
indigo ore
x=2 is actually working
severe spear
How do you find roots of something like x^7+8x^3-6x^5=0?
use hidden quadratics
fervent meteor
x=2 is actually working
It's +2,-2,+/- root 2 and 0 work
fervent meteor
use hidden quadratics
What does that mean
severe spear
baaically
waxen yew
we don't use a calculator
why not if it helps right\
dapper bane
bro
fervent meteor
why not if it helps right\
it's not allowed to
sly frigate
this isn''t wrong tho
indigo ore
You do not need a calculator to find out that x=2 is a solution
dapper bane
imagine if you're on a test and you gotta do this equation
severe spear
instead of factorising a horrible equation like that
dapper bane
how are you going to solve it now
sly frigate
factoring that is simple
dapper bane
factoring that is simple
exactly
fervent meteor
I think differentiating without opening the brackets was the better way no point in trying this I guess
severe spear
do x^7 = y^4
sly frigate
take out x^3, and then solve the biquadratic equation
severe spear
x^5 = y^2
dapper bane
there's alot of talking lmao
severe spear
wait holdup
indigo ore
You have $x^7 + 8x^3 - 6x^5 = x^3(x^4 - 6x^2 + 8)$ \
And I assume your best guess is to try simple values (say, up to 2 or 3) for the root of the 4th degree equation, hoping to get back ideally to a second degree equation where you can use common techniques
glossy valveBOT
Fέliχ
sly frigate
I think differentiating without opening the brackets was the better way no point...
it's not a differentiation question
severe spear
didn't see the x^3
sly frigate
it's a simple factoring question
dapper bane
You have $x^7 + 8x^3 - 6x^5 = x^3(x^4 - 6x^2 + 8)$ \\
And I assume your best gu...
subsitute t=x²
fervent meteor
yeah no I ain't doing all that I should have opened the brackets at the first place lol
fervent meteor
it's not a differentiation question
This is a part of a bigger binomial theorum question
I needed to maximum the value of a term
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woven flume
can someone help me find the solution to this ?
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can someone help me find the solution to this ?
woven flume
i should find a soultion for x > 0
worn maple
can someone help me find the solution to this ?
Use sum of arctan formula
worn maple
Use tan of sum of angles formula i.e. tan(a+b)=... and plug a=arctan x and b=arctan 1/x as angles then
In other words: simply apply tan of both sides 🙂
woven flume
isnt like tan(pi/2)=inf?
worn maple
GOOD point lol
worn maple
Ok what I mean
worn maple
Use tan of sum of angles formula i.e. tan(a+b)=... and plug a=arctan x and b=arc...
Do this to find sum of arctan formula
We want a formula for arctan x + arctan y = ...
Idea: use tan(a+b) = ... with a = arctan x and b = arctan y
worn maple
no
Forget about your problem one sec, we need to find a formula for arctan x + arctan y to simplify your expression
woven flume
oh nvm im slow lmao
worn maple
Do this to find sum of arctan formula
We want a formula for arctan x + arctan y ...
You said you didn't know arctan formula, so I gave you the idea to find it
woven flume
so its tan(arctan(x)+arctan(1/x))
woven flume
idfk tbh
glossy valveBOT
SkyTwX
worn maple
Idea:
glossy valveBOT
SkyTwX
worn maple
in the bottom it will be 1-(x*1/x) tho
Please, try to forget about your problem first :p
worn maple
**SkyTwX**
Focus on this problem
woven flume
shouldnt i just take arctan on both sides to isolate alpha and beta?
bc that is equivalent to arctan(a)+arctan(b)
worn maple
shouldnt i just take arctan on both sides to isolate alpha and beta?
exactly
I think you got it, so now you know the formula for the sum of arctan 🙂
worn maple
**SkyTwX**
Meaning we can complete this formula
glossy valveBOT
SkyTwX
worn maple
Now come back to the question, simplify the left hand side term... if you can :p
glossy valveBOT
SkyTwX
worn maple
Do you know limits?
worn maple
Assume we want to find the value for $x=a$
glossy valveBOT
SkyTwX
worn maple
The value of the left hand side
Then we have the following
$f(a)=\mathrm{arc}\tan(a)+\mathrm{arc}\tan\left(\frac{1}{a}\right)=\lim_{x\to a}\left[\mathrm{arc}\tan(x)+\mathrm{arc}\tan\left(\frac{1}{x}\right)\right]$
glossy valveBOT
SkyTwX
worn maple
This is true because of linearity of the limit and continuity of arctan
woven flume
**SkyTwX**
how do i apply that to the problem here
worn maple
First: this allows us to bring a limit
Why bring a limit? Because this allows us somehow to divide by 0 lol
Actually we don't even need to do that but anyway
$\lim_{x\to a}\left[\mathrm{arc}\tan\left(\frac{x+\frac{1}{x}}{1-x\frac{1}{x}}\right)\right]$
glossy valveBOT
SkyTwX
hushed spear
Euh this is overly complicated
worn maple
Yeah clearly
hushed spear
Draw a right triangle with side lengths 1 and x.
Express both angles (using arctan) in terms of x and add them.
worn maple
Yeaaah okay I though of this but negative x made me trippin' but actually it's ok sorry haha
woven flume
the length of the hypotenuse doesnt matter right?
woven flume
no ty 😭
hushed spear
$\lim_{x\to a}\left[\mathrm{arc}\tan\left(\frac{x+\frac{1}{x}}{1-x\frac{1}{x}}\r...
There's an \arctan command
worn maple
$\arctan$
glossy valveBOT
SkyTwX
worn maple
I'm feeling stupid thank you @hushed spear
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Is this right ?
untold zinc
Do u complete the square first then plus the 10 or u plus 10 before u complete the square
sly frigate
Is this right ?
you got it right
sly frigate
Do u complete the square first then plus the 10 or u plus 10 before u complete t...
it doesn't matter
untold zinc
Oh right ok
Wait but if u plus the 10before
Ohhhhh wait I see
Thank you!
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untold zinc
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untold zinc
@sly frigate is this how u do it when u add the 10 before completing the square
untold zinc
Form this question by the way
sly frigate
yes that's right
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merry spoke
f(x) = 1/x
fn Is the derivative that has the order of a non-null natural number n of the function f
Prove that for every non-null natural number n
merry spoke
Can anyone guide me to solve this? I have no idea how to start.
sick prawn
I think induction works
merry spoke
I need to solve it using "Inference backtracking".
Idk if that's the correct name of it, I'm not that good at English.
sick prawn
Ok, induction doesn’t work
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fading steeple
Why does induction not work again? This looks exactly like induction
torn jolt
what is inference backtracking? induction looks exactly like what you need for this problem
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wheat onyx
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dull cargo
Hi, how can solve lim x->0 ( x²/sin²2x) without using L'Hospital
twilit leaf
use the limit fact that lim x->0 a/sina =1
dull cargo
so the reponse is 1/4?
gritty rose
so the reponse is 1/4?
Show how you got this
dull cargo
bc lim x->0 x/sin2x . lim x->0 x/sin2x = 1/2 . 1/2 = 1/4
dull cargo
Show how you got this
that's right?
worthy tree
1/2 = 1/4 ?
worthy tree
that's right?
the final result is 1/4
glossy valveBOT
Mehdi_Moulati
worthy tree
this is correct too?
yes
hollow stag
hollow stag
alright
closed another channel
so i dont even understand about this question
dont know how to do either
onyx glen
what part of this question escapes you?
hollow stag
simply no idea how to do
onyx glen
ok, but do you at least understand what to do?
hollow stag
no clue actually
onyx glen
you are told that a natural number called N is the product of three distinct prime numbers called a, b and c.
do you understand what this means?
hollow stag
no
onyx glen
not ideal, the way you're wording it...
but ok, yeah, sure.
do you know what the word "product" means?
@hollow stag
hollow stag
Y ik
onyx glen
okay...
so then
you are told that a natural number called N is the product of three distinct prime numbers called a, b and c.
which part of this statement don't you understand?
onyx glen
...oh, is english not your native language?
hollow stag
No
onyx glen
what is your native language?
hollow stag
Chinese
onyx glen
okay, nevermind.
yeah i think this is a language barrier
i don't speak chinese so idk how to overcome it
hollow stag
I checked the answer is 8
But idk how abc come
The smallest number i could think of are 1 3 5 for abc
But its 1×3×5 would be 15
Maybe Ill ask my teacher tmr
Thx for try helping me
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atomic jacinth
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light burrow
I checked the answer is 8
Theres a rule. The number of divisors of an integer is dependent on the prime factorization. Do that first. Then add 1 to the power of that prime(in this case, 1) so everythings 2 in this case. Then you multiply those numbers together. 2^3 = 8
stable plover
$n = p_1^{m_1} p_2^{m_2} \cdots p_k^{m_k}$ has $(m_1+1)(m_2+1)\cdots (m_k+1)$ factors
glossy valveBOT
tushar
hollow stag
Oh
I don't think i have learnt this but this question came from a chapter which is combination and permutation
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delicate walrus
What’s wrong here? How can I fix this, the last bits are completely confusing me, how do I approach if imaginary number appears in the limit approaching side?
clear lily
there shouldnt be any imaginary numbers
are you trying to find the derivative of f(x) = sqrt(x) at x = 1?
delicate walrus
are you trying to find the derivative of f(x) = sqrt(x) at x = 1?
Thats interesting, but there is no slope at sqrt of 1 right?
clear lily
is that a yes?
delicate walrus
I mean no
clear lily
alright so what exactly are you trying to do
delicate walrus
I mean I so stressed aaaaaahhh 😭
delicate walrus
What’s wrong here? How can I fix this, the last bits are completely confusing me...
I can’t approach a limit for this, is that the way it’s supposed to be?
clear lily
is this a derivative?
delicate walrus
😭😭😭
Thankyou kind ser, I can’t focus, maybe I need to take a break and clear my head
delicate walrus
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delicate walrus
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delicate walrus
\
It’s supposed to be 0
As we are multiplying, the outer bracket
Ahh noo
Nvm
Aaaaaa
Correct, thankyou once again
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torn jolt
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torn jolt
Whats wrong?
worthy ferry
torn jolt
Channel occupied
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torn jolt
Simple question, how do I derive $\frac{dr}{dt}$ in $\frac{dV}{dt} = \frac{dA}{dr} \times \frac{dr}{dt}$?
glossy valveBOT
SillyRaccoon
shrewd hamlet
just divide both sides by dA/dr? is that what ur asking?
torn jolt
just divide both sides by dA/dr? is that what ur asking?
Sorry for not clarifying it (in a rush atm)
Translated question: the area of a sphere is increasing with the speed of $28 cm^2$ per minute. At what speed does the sphere volume increase if the radius of the sphere is 6.5 cm?
glossy valveBOT
SillyRaccoon
torn jolt
So we want dV / dt and we have dA / dt, we need dr / dt to proceed with the solution afaik
shrewd hamlet
SA = 4* pi * r^2
torn jolt
That's just the derivative of dV / dt for the sphere?
shrewd hamlet
V = 4 * pi * r^3 / 3
torn jolt
Isn't the derivative for dr / dt supposed to have a time component in the formula?
Or did I confuse myself
shrewd hamlet
SA = 4* pi * r^2
this is the formula for surface area
shrewd hamlet
so dA/dt = 8 * pi * r * dr/dt
shrewd hamlet
so 28 = 8 * pi * 6.5 * dr/dt
solve for dr/dt
keep in terms of pi btw
dont change to 3.1415
torn jolt
Obv. we are doing math
shrewd hamlet
so 28 = 8 * pi * 6.5 * dr/dt
do u see what i did here
torn jolt
Correct
shrewd hamlet
so we're solving for dr/dt to plug into our dV/dt equation
torn jolt
In other words, we did: $\frac{dA}{dt} = \frac{dA}{dr} \times \frac{dr}{dt}$ to later replace in $\frac{dV}{dt}$
glossy valveBOT
SillyRaccoon
torn jolt
Did not think of that approach
Thanks!
I now see where I got confused..
I thought of it as $\frac{dA}{dr}$ instead of $\frac{dA}{dt}$
glossy valveBOT
SillyRaccoon
shrewd hamlet
so now dV/dt = 4 * pi * r^2 * dr/dt
torn jolt
The rest is simple
But do we actually know what formula to use when deriving $\frac{dr}{dt}$ or is it just replacing it with something else from another formula?
glossy valveBOT
SillyRaccoon
torn jolt
Just to understand what formula they are referring to when they say dr / dt
shrewd hamlet
not rlly a formula, we're referring to the change in the radius as the time changes
its like chain rule when u differentiate xy and it becomes y + x(dy/dx)
shrewd hamlet
no problem
vast fable
shrewd hamlet
shrewd hamlet
u have to do a period then close
torn jolt
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vast fable
I want a solution to this exam
shrewd hamlet
- #❓how-to-get-help 2. we dont give solutions 3. we dont help on exams LOL
torn jolt
Apparently reactions are a no no
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faint dock
HI i know that if f(x) is an odd function then it's primitive F(x) is even
faint dock
can we say that if f(x) is even that F(x) is odd
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@faint dock Has your question been resolved?
faint dock
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wispy fulcrum
If cos(-t)=-1/5, what would cos(t) be
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If cos(-t)=-1/5, what would cos(t) be
gritty rose
can you use arccos / inverse cosine?
sharp vine
cos(-t) = cos(t)
wispy fulcrum
Is that a theorem or
sharp vine
property of even functions
wispy fulcrum
Then if sin(t) = 4/5 what would sin(pi-t) be
sharp vine
sin(pi - t) = sin(t)
atomic venture
And then sin(-t) = sin(t)
sin(-t) = -sin(t) because it's an odd function
you can see these symmetries on a sine graph or the unit circle
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sour eagle
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sour eagle
I don't know what ive done wrong in part a because I cant solve part b or c
<@&286206848099549185> ?
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torn jolt
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silver valve
Hey could someone look over this and see if there’s any mistakes with this question. I have to make a question for my math assignment and would appreciate if someone would take there time if I have any mistakes or what not
silver valve
It is 3 slides but one question
silver valve
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silver valve
<@&286206848099549185>
tulip sapphire
are you in high school?
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torn jolt
well, 6x3 is definitely not a square
wispy badge
Not math related, but I would also fix up the wording in some places
torn jolt
agreed
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spare condor
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spare condor
may i receive help with this question?
Ive completed part A
which worked out to be dv/dt = k(pi)r^2
but i cant seem to get the right answer for b
ive tried dr/dt=dv/dt * dr/dv
plush egret
ive tried dr/dt=dv/dt * dr/dv
this doesnt look right 
spare condor
it asks for chain rule
plush egret
remember that you want to involve h
well, I guess not remember
h is the quantity of interest here, i think
its why you want to invoke the chain rule
spare condor
wait isnt the question asking for rate of change of the radius
so wouldnt we be looking for dr/dt
plush egret
idk im not being very careful
lemme re-read it
rate of change of the radius
wrt time?
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spare condor
@plush egret do you know what I should do
plush egret
Ah, im playing around with it
Right now I'm checking if you represent volume as a function of radius, and height as a function of radius, then differentiate that equation
spare condor
ok thanks
plush egret
sorry i think I might be too tired.
I wonder if riemann is around 
or snow tbh 
can you help with this diff eq problem
🙏
spare condor
😦
plush egret
I just dont understand these steps
I was thinking it was like
a) write a naive diff eq that models the problem
b) use related rates to include the geometry of the problem
c) solve the initial value problem (parameterized)
d) solve for a specific parameter
e) give the specific solution
spare condor
the topic is applications of DE if that helps
plush egret
okay part A so makes sense
topaz valley
plush egret
$v' = \qty( \pi r^2 ) k$
glossy valveBOT
jan Niku
topaz valley
its a cone
plush egret
this seems so reasonable
topaz valley
is the cone pointy side up or down
plush egret
the problem is that it seems too naive to me
plush egret
is the cone pointy side up or down <:thonk:406575732563902485>
its implied pointy down
no one knows why
short siren
is the cone pointy side up or down <:thonk:406575732563902485>
Pointy side down
topaz valley
where does it say
short siren
Evaporation is implying it
topaz valley
but it could by pointy up
plush egret
its not
topaz valley
plush egret
just trust me
plush egret
can we go back to the problem
@spare condor we have summoned a crew u better not leave
spare condor
im here
plush egret
glossy valveBOT
plush egret
lets jump from here
so my thought is
part b doesnt begin with this equation
instead, you wanna work with this
$v(r) = \frac13 \pi r^2 h(r)$
topaz valley
oh radius
glossy valveBOT
jan Niku
short siren
glossy valveBOT
glossy valveBOT
jan Niku
plush egret
then $k=3$
plush egret
glossy valveBOT
plush egret
should be k pi r^2
topaz valley
the pi got absorbed
short siren
Well k can take 3pi
topaz valley
its just constant
glossy valveBOT
topaz valley
you dont know k
glossy valveBOT
jan Niku
plush egret
so $\dd r = \frac{k}{3\pi} \dd t$
glossy valveBOT
jan Niku
plush egret
$r(t) = \frac{kt}{3\pi} + C$
topaz valley
too many constants
glossy valveBOT
jan Niku
plush egret
it doesnt matter
short siren
Let k/3pi = j
plush egret
youre allowed to be paranoid with constants
topaz valley
just absorb them all into k
glossy valveBOT
short siren
k is negative
plush egret
$r(t) = \frac{kt+12\pi}{3\pi}$
glossy valveBOT
jan Niku
topaz valley
better to write it as
short siren
jt +4
plush egret
$r(t) = kt+4$
glossy valveBOT
jan Niku
glossy valveBOT
plush egret
i feel like this is wrong
physically
shouldnt the rate the radius is decreasing change
short siren
k will have a negative value so it's fine
plush egret
that just feels wrong to me
short siren
Ooo can we use the volume to find k?
topaz valley
part d tells you
plush egret
spare condor
btw these are the answer so you can tell if your on the right track
cause im a little lost rn
plush egret
ah geez
plush egret
btw these are the answer so you can tell if your on the right track
c
mfers when the arbitrary constant has a specific form
short siren
plush egret
I'm gonna use their "correct" C to finish D
short siren
So r(6) = 3.5 no?
plush egret
so $r(t) = \frac k3 t + 4$
glossy valveBOT
jan Niku
plush egret
and $h(t) = 3r(t)$
glossy valveBOT
jan Niku
short siren
$r(6) = 3.5 = \frac{k}{3} (6) + 4$
glossy valveBOT
VulcanOne
plush egret
then $v(t) \frac 13 \pi r^2(t) h(t) = \frac{\pi}{3} \qty( \frac k3 t + 4 )^2 3 \qty( \frac k3 t + 4 )$
glossy valveBOT
jan Niku
plush egret
$v(t) = \pi \qty( \frac k3 t + 4 ) ^3$
glossy valveBOT
jan Niku
plush egret
,w expand (2k+4)^3
glossy valveBOT
short siren
plush egret
this way is wrong
plush egret
why 3.5
plush egret
huh?
short siren
From part d
glossy valveBOT
VulcanOne
short siren
$r(t) = -\frac{1}{12} t + 4$
glossy valveBOT
VulcanOne
plush egret
😌
short siren
We then use this form
plush egret
okay
pizzanub just has to understand everything we did up to here
and can answer the question
short siren
$V = \frac{1}{3} \pi (r(t)^2 h(t))$
glossy valveBOT
VulcanOne
short siren
$h(t) = 3r(t)$
glossy valveBOT
VulcanOne
short siren
$V = \frac{1}{3} \pi (3r(t)^3) = \pi r^3 (t)$
glossy valveBOT
VulcanOne
glossy valveBOT
VulcanOne
plush egret
do you guys know what b is supposed to be
its honestly a really illogical step
i think we side stepped it
its why i was confused so much at first
spare condor
ok I should probably just ingore it then
short siren
**jan Niku**
This is it I guess
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honest cypress
what should I do if there's a reminder in solving division (This is the order of mathematical operation - PEMDAS)
hot herald
depends on what the question wants
is there a specific question with clear instructions where this is coming up?
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pulsar grail
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torn jolt
can someone help me with this Math? I'm at very near to solve this Math but unfortunately, the answer is coming up " 6243 ". The Math is about repeating decimal. The answer is not matching, with the question
gilded lion
can someone help me with this Math? I'm at very near to solve this Math but unfo...
What's the question
torn jolt
What's the question
I have screenshot it
the math is repeating decimal
fraction
and i'm very near to solve it, but the answer in my calculator is showing " 6243 " which is not matching with the question. I hope you understand
torn jolt
they want you to write it as a fraction?
No. I have completed the Math, but the answer is not matching with the question in my calculator. The calculator answer shows " 6243 " but the answer was suppose to come " **6245 **" By the way, this is a repeating decimal fraction Math
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north cargo
does anyone have any idea
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does anyone have any idea
north cargo
no idea how to work with cos - sin
mighty torrent
- sin^2Q?
north cargo
oh plus
mighty torrent
Do you see a way to continue?
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thick jolt
A pipe needs to run from a water main, tangent to a circular fish pond. On a coordinate plane, construct the circular fish pond at a given location and specify your center point and radius. Write your circular fish pond equation. On your coordinate plane, identify the point to represent the location of the water main connection. Construct the pipe so that it is tangent to the fish pond from the water main. Include all steps to creating a tangent line, as discussed in this lesson. Submit your final graph. You may do this by hand, using a compass and straightedge, or using a graphing software program.
Discuss the steps that you used to create your tangent line in #1. What was the most important step? Your discussion should be a minimum of three sentences.
Give an example of tangents in the real world that have not been presented in this lesson. Explain how you know the tangent and the radius in your example are perpendicular.
The client has decided to have a similar circular fish pond constructed in a different location in the yard. On your same coordinate grid, construct a new circular fish pond with a different radius and center from your original circular fish pond. Specify the new center and radius.
Explain how your original fish pond is similar to your new fish pond. Include the translation rule or description of the translation, and show your work for determining the scale factor. Submit your final graph and work.
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A pipe needs to run from a water main, tangent to a circular fish pond. On a coo...
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dark geyser
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torn jolt
I need help
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I need help
torn jolt
Thats what ive answered, am i correct?
And no, this is not assignment its just weekly practise problems
<@&286206848099549185>
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sacred zodiac
Which problem do you need help with? seems to be 4 of them
For 1.2 it was looking for geometric reasoning but yours is more algebraic
1.3 a is fine, b is probably okay but still is looking for geometric solutions
1.4 looks good
torn jolt
For 1.2 it was looking for geometric reasoning but yours is more algebraic
How can i interpret it geometrically?
torn jolt
1.4 looks good
How should i picture problem f)?
torn jolt
1.3 a is fine, b is probably okay but still is looking for geometric solutions
It doesnt say to give geometric explanation, how would u answer that
sacred zodiac
For 1.2 you have two lines going through the origin (all homogeneous systems go through the origin). Either they intersect just at (0,0) or they coincide so infinitely many solutions
torn jolt
OHHH
sacred zodiac
How should i picture problem f)?
Well that line of intersection intersects the plane at a point. So there is one point that lies in teh intersection of all 3 planes
torn jolt
Well that line of intersection intersects the plane at a point. So there is one ...
Could u draw it on paint pls
Is it like the corner of a room?
sacred zodiac
It doesnt say to give geometric explanation, how would u answer that
If d1 = d2 = 0, this is a homogenoeus system again, it's the same idea as 1.2. You have two planes going through the origin in 3 dimensions. They either intersect in a line or they coincide
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sacred zodiac
.reopen
torn jolt
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torn jolt
If d1 = d2 = 0, this is a homogenoeus system again, it's the same idea as 1.2. Y...
ohhh fff man
thanks alot
sacred zodiac
Is it like the corner of a room?
Think of the xy and yz planes, they intersect along the y axis. Then the y axis intersects the xz plane at only one point!
So yes, corner of a room
torn jolt
Think of the xy and yz planes, they intersect along the y axis. Then the y axis ...
Right, thanks a lot for the help!!
sacred zodiac
no worries!
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loud mortar
Baseball player Babe Didrikson holds the world record for the longest throw (90 meters) by a woman. To answer the following questions, assume that the ball is thrown at an angle of 45.0° above the horizontal, that it travels a horizontal distance of 90 m and that it is caught at the same level from which it was thrown.
A. What is the modulus of the initial velocity of the ball
B. How long does the ball stay in the air?
[a. 29,7 m/s; b. 4,
loud mortar
I have already solved the exercise but the values are not the same and I don't know where I went wrong
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normal tree
I have already solved the exercise but the values are not the same and I don't...
you should show your steps
loud mortar
you should show your steps
normal tree
Can you sorta explain what you're doing there / where those formulae come from?
loud mortar
Vo is the Initial velocity, tvolo is the flight time, and xg is the range
normal tree
okay so where did you get the formulae
normal tree
I don't believe that to be true
for example, when theta = 45 degrees, you have the initial vertical velocity as +vo/sqrt(2), the time of flight is 2vo/(sqrt(2) * g), the initial horizontal velocity is also +vo/sqrt(2), and the product is vo^2/g
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languid perch
$\lim_{x \to 3} \tan \frac{\pi x}{4}$
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$\lim_{x \to 3} \tan \frac{\pi x}{4}$
glossy valveBOT
Willow
sly frigate
Yeah
glossy valveBOT
Result:
-1
Presumably tan = sin/cos
correct
astral sinew
Yeah looks good
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wicked oak
How do i solve n and determine measure
devout valley
cursive badger
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cursive badger
how do i find distance in part d?
light shoal
a bit of calculus if you dont mind
so after 5 seconds, you will have 49(1-e^-2.5)
as velocity
so if you want the distance
then you just find sum of all between 0 and 5 with anti-derivative
which is equal to the anti-derivative of 49-49e^-2.5
cursive badger
do i have to find the integral of v?
light shoal
integral of v on t = 0 and t=5
because the speed is achieved by derivative of distance
and acceleration is achieved by derivative of speed
therefore you can just take integral
light shoal
np
cursive badger
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languid perch
What's the rule of adding square roots like $\sqrt{5} + \sqrt{5}$ = ?
glossy valveBOT
Willow
languid perch
I can't seem to find a good link on this.
glossy valveBOT
riemann
languid perch
Would you happen to have a link on this?
It seems so simple, but I can't locate it on Google.
gritty rose
languid perch
https://youtu.be/83wXAgwcWH0
You see in the thumbnail, they always add a number to the square root
and never only add two square roots alone
but let me check the link to see if it covers the rule you just mentioned
languid perch
yeah, that link also doesn't cover it
languid perch
Maybe this is all you really need
but maybe I should look at what you typed like this:
1a + 1a = 2a
the solution to my problem would then be:
$2\sqrt{5}$
glossy valveBOT
Willow
sly frigate
Because the hypotenuse is 1/2
But it's also the hypotenuse of this red triangle
You know that cos(2theta) would be BC/AB, right?
A cosine value is hypotenuse/adjacent
Oh
That's only when the hypotenuse is 1
So cos(2theta)=BC/AB
subb AB=1/2 into that, and you get
BC=1/2cos(2theta)
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rancid gate
I need help please
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brave blaze
just ask
gritty rose
I need help please
wide nest
😒
rapid laurel
<:JustAsk:371662163489718273>
riemann friend me
proposition(riemann friends me), truth table: riemann friends(true), boki happy. Riemann otherwise(false), boki sad
gritty rose
riemann friend me
you need to stop pinging me. last warning
fast peak
